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//clc() //f(x) = 0.2 + 25*x - 200*x^2 + 675*x^3 - 900*x^4 + 400*x^5 // for using three point gauss legendre formulae, the intervals have to be changed to -1 and 1 //therefore, x = 0.4 + 0.4 * xd //thus the integral is transferred to //(0.2 + 25*(0.4+0.4*x) - 200*(0.4 + 0.4*x)^2 + 675*(0.4 + 0.4*x)^3 - 900*(0.4 + ...
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## Test drop command set echo set relax drop read <min.fi drop drop read <min.fi read <min.fi drop drop choose min drop read <min.fi read <min.fi drop min2 drop min
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function [x] = usolve(U,b,n) x=zeros(n,1) j=n-1 x(n)=b(n)/U(n,n); for i=1:n-1 U(j,j+1:n)=U(j,j+1:n)/U(j,j) x(j)=b(j)/U(j,j)-U(j,j+1:n)*x(j+1:n); j=j-1 end endfunction function [x] = lsolve(L,b,n) x=zeros(n,1) j=n-1 x(1)=b(1)/L(1,1) for i=2:n ...
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clear ; xdel(winsid()); clc ; exec lbp.sci exec getmapping.sci nb_classe =50; nb_image =8; nb_ima_train = 4; //ona 25 imagette nb_bins =255; Attribut = zeros(nb_ima_train * nb_classe,nb_bins); Attributs_test=zeros(nb_ima_train * nb_classe,nb_bins); attribut_test=zeros(1,nb_bins); comp_train = 1; comp_train_test=1; int...
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//S.H.M r=0.75 //m T=1.2 //sec omega=((2*%pi)/(1.2)) //rad/sec vxmax=0.75*5.236 //m/sec axmax=0.75*5.236^2 //m/sec^2 printf("\nvx(max)=%.3f m/sec\nax(max)=%.3f m/sec^2",vxmax,axmax)
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// Grob's Basic Electronics 11e // Chapter No. 01 // Example No. 1_2 clc; clear; // A dielectric has a positive charge of 12.5*10^18 protons. What is its charge in coulombs? // Given data ec = 12.5*10^18; // Electron charge=12.5*10^18 electrons disp ("This number of electrons is double the charge of...
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//19MCMI07 //Rohan Yadav function y=data_fit_l(x,c) y=exp(c(1)*x)*cos(c(2)*x)+c(3)*sin(x); endfunction function e=myerror(c,z) x=z(1); y=z(2); e=y-data_fit_l(x,c); endfunction xdel(winsid()); clear; clc; x=[1 0.55 1.11 1.66 2.22 ] y=[1 0.47 3.73 2.22 2.61 ] plot(x,y,'ro') z=[x;y]; c0=[2 2 2]'; [copt...
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clc Na=10^17 disp("Na = "+string(Na)+"/cm^3") //initializing value of medium p doping concentration. Nd=10^15 disp("Nd = "+string(Nd)+"/cm^3") //initializing value of light n doping . no=1.5*10^10 disp("no = "+string(no)+"cm^-3") //initializing value of intrinsic carrier concentration. e=1.6*10^-19 disp("e = "+...
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stacksize("max"); //define crystal parameters Lq=0.1; Rq=25; Cq=0.3*10^-12; C0=1*10^-12; //find series resonance frequency ws0=1/sqrt(Lq*Cq); disp(ws0); ws=ws0*(1+Rq^2/2*C0/Lq); fs=ws/2/%pi //find parallel resonance frequency wp0=sqrt((Cq+C0)/(Lq*Cq*C0)); wp=wp0*(1-Rq^2/2*C0/Lq); fp=wp/2/%pi //define frequency rang...
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//Example 3.15:High resistance clc; clear; close; //given data : V1=500;// in V V2=300;// in V t=60;// in sec C=2.5*10^-6;// in F R=t*10^-6/(C*log(V1/V2)); disp(R,"Unknown resistance,R(M-ohm) = ")
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clc;funcprot(0);//EXAMPLE 17.28 // Initialisation of Variables D=0.2;.................//Engine bore in m L=0.25;...............//Engine stroke in m n=2;......................//No of cylinders r=13;......................//Compression ratio fc=14;..................//Fuel consumption in kg/h N=300;....................
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function varargout = iddata(varargin) // Stores plant input-output data // // Calling Sequence // plantData = iddata(yData,uData,Ts) // plantData = iddata([],uData,Ts) // plantData = iddata(yData,[],Ts) // plantData = iddata(yData,uData) // plantData = iddata(yData) // // Parameters // uData : nx1 matrix...
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mu_not=4D-7*%pi a=(3D-2)^2//cross-sectional area La=(20-1.5-1.5)*1D-2//length of flux path in part A mu_r=1000//relative permeability for part A Sa=La/(mu_not*mu_r*a) mprintf("Reluctance of part A=%f*10^4AT/Wb\n",Sa/10^4) Lb=(17+8.5+8.5)*1D-2//length of flux path in part B mu_r=1200//relative permeability fo...
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clc rho_m=840; //kg/m^3 g=9.8; //m/s^2 H=0.03; //m rho=1.2; //kg//m^3 dp=rho_m*g*H; v1=sqrt(2*dp/rho); disp("Velocity =") disp(v1) disp("m/s")
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#------------------------------------------------------------------------------ # Blunders # # Computer Go Test Collection http://www.cs.ualberta.ca/~games/go/ # # $Source: /usr/cvsroot/project_cgtc/blunder.tst,v $ # $Id: blunder.tst,v 1.3 2004/04/28 17:10:39 emarkus Exp $ #--------------------------------------------...
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clc m=12*10^3/3600; // kg/s Rho=815; // kg/m^3 d=0.05; // m e=0.02; d1=50; // m d2=0.038; // m g=9.8; // m v=4*m/Rho/%pi/d^2; f1=1/(2*log10(d1/e)+2.28)^2; L_eq=d1+2*d1*d; H_50mm=4*f1*L_eq*v^2/(d*2*g); v=4*m/(Rho*%pi*d2^2); f2=1/(2*log10(38/e)+2.28)^2; L_eq=d1+2*d1*d2; H_38mm=4*f2*L_eq*v^2/(...
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// find decimal equivalent of binary input and output voltage of the converter // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 20-6, page 762 clear; clc; close; // Given data D0=1;// binary input D1=0;// binary input D2=0;// binary i...
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//Example 5.11 clc disp("Fig 5.25 shows the implementation of given Booolean function with 8:1 miltiplexer.") disp("Implementation table") disp(" D0 D1 D2 D3 D4 D5 D6 D7") disp("A'' 0 1 2 3 4 5 6 7") disp("A 8 9 10 11 12 13 14 15") disp(" 1 1 0 A'' A'' 0 0 A...
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class TestOperateurs public TestOperateurs() {} private integer eval(integer v, string n) { prints(n); prints(" a ete evalue\n"); return(v); } private string boolToString(integer v) { if v then return("vrai"); else ...
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clc; clear all; disp("Heat loss/length") a=0.6;// m b=0.45;//m H=1.5;//m k=0.51;// W/(m*C) tp=105;// degree C ts=5;// degree C x=log(1+H/a); y=H/b; Sfc=2.756*((x^(-.59))*(y^(-.078))); Q=k*Sfc*(tp-ts); disp("W",Q,"Heat loss per meter length, Q =")
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// ============================================================================= // Copyright INRIA 2008 // Copyright DIGITEO 2010 - 2011 // Allan CORNET // ============================================================================= mode(-1); lines(0); function builder_main() TOOLBOX_NAME = "ANN_toolbox"; TOOLBOX_...
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// Exa 1.1 clc; clear; close; // Given data T1 = 25;// in degree C T2 = 100;// in degree C del_T = T2-T1;// in degree C V= 0.7;// barrier potential t 25°C in V del_V = -(2)*del_T;// in mV del_V= del_V*10^-3;// in V V_B = V- abs(del_V);// in V disp(V_B,"(i) When the junction temperature is 100 °C, the barri...
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// Scilab Code Ex6.10: Page-200 (2006) clc; clear; x = 0.38; // Al concentration in host GaAs E_g = 1.424 + 1.266*x + 0.266*x^2; // Band gap of GaAs as a function of x, eV printf("\nThe energy band gap of 38 percent Al doped in GaAs = %5.3f eV", E_g); // Result // The energy band gap of 38 percent Al dope...
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clear //Given B=45.0 Ic=1 //V //Calculation Ib=Ic/B //Result printf("\n The base current for common emitter connection is %0.3f mA",Ib)
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//variable declaration n=4 M=58.5 //Molecular wt. of NaCl N=6.02*10**26 //Avagadro number rho=2180 //density //Calculations a=((n*M)/(N*rho))**(1/3) s=a/2 //Result printf('a=%0.3f*10**-9 metre\n",(a/10**-9)) printf('spacing between the nearest neighbourin...
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PL/SQL Developer Test script 3.0 69 DECLARE c utl_tcp.connection; -- TCP/IP connection to the Web server ret_val pls_integer; BEGIN -- OPTIONS to start ra_session -- PROPFINDs to discover various opaque URIs -- MKACTIVITY to create a transaction -- try: -- for each changed object: -- ...
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//Example 10.2 //page 657 //Control Systems: Principles and Design //M Gopal, Second Edition, Tata McGraw-Hill //Chapter:Compensator design using Bode Plots xdel(winsid())//close all graphics Windows clear; clc; s=poly(0,"s") w=poly(0,'w') G=1/(s^2) zeta=0.45 pm=50 //degrees K=1 G1=syslin('c',K*G) [gm,f...
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//EXAMPLE 4-8 PG NO-230-231 V=25; Vm=0.64; Vn=3.05; R1=5; R2=9.64 I1=(V-R2)/R1 disp('i) CURRENT (I1) is = '+string (I1) +' A '); I2=R2/4; disp('ii) CURRENT (I2) is = '+string (I2) +' A '); I3=(R2-Vn)/10; disp('iii) CURRENT (I3) is = '+string (I3) +' A '...
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0 0 1 1 2 1;2 3 1;1,2 4 2 5 2;4 6 2;2,4 7 2;1,1,1,4 8 2;1,4 9 3 10 3;6 11 3;3,6 12 3;2,6 13 3;1,1,1,1,6 14 3;1,2,1,6 15 3;1,6 16 4 17 4;8 18 4;4,8 19 4;2,1,3,1,2,8 20 4;2,8
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//chapter 4 Ex 37 clc; clear; close; cost1=86; cost2=112; x=poly(0,'x'); y=(cost1-2*x)/3; //equation 1 y=cost2-4*x; //equation 2 for x=1:99 if (cost1-2*x)/3==cost2-4*x break end end y=cost2-4*x; printf("The cost of pen is Rs.%d and that of pencil is Rs.%d",x,y);
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SPLITTeR f {} fILTER xYHy { } fiLTER Nk {X oR jIT Or Ds or o NOT DYD } Y -> jJ grOuper x {mOdULe ba{ w < cfy RdElTA 50m } aGGREgAte COUNt(C.g) aS x ,AVg(aceeKB) as HVO ,joS.vx ,zzn.S } uNgROUPER DuZBk { } gROUPfILter xA {not Hjl ( ) } mErgEr miu { exPOrt uCCY }
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//CHAPTER 6 ILLUSRTATION 4 PAGE NO 177 //TITLE:Turning Moment Diagram and Flywheel //figure 6.4 clc clear //=================== pi=3.141 N=480// speed of the engine in rpm k=.6// radius of gyration in m Cs=.03// coefficient of fluctuaion of speed Ts=6000// turning mo...
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//Part A Chapter 6 Example 4 clc; clear; close; T1=150+273;//K T2=25+273;//K m=1;//kg cp=0.393;//kJ/kgK deltaS_block=-m*cp*log(T1/T2);//kJ/kgK HeatLost_block=-m*cp*(T1-T2);//kJ deltaS_water=-HeatLost_block/T2;//kJ/K deltaS_universe=deltaS_block+deltaS_water;//kJ/K deltaS_universe=deltaS_universe*1000;//J/...
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clc; ID=4*10**-3; IDSS=2*ID; RS=390; VGSQ=-ID*RS; VP=-4.5; RD=2.2*10**3; gm0=(2*IDSS)/(-VP); gm=gm0*(1-(VGSQ/VP)); Av1=-gm*RD; Av2=-gm*RD; Av=Av1*Av2; disp(Av); vi=20*10**-3; vo=Av*vi; disp('mV',vo*10**3,"vo="); Zi=10*10**6; RG=10*10**6; disp('Mohm',Zi*10**-6,"Zi=RG="); Z0=2.2*10**3; RD=2.2*10**3; ...
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function [x1,varargout]= demod (y,fc,fs,method,varargin) //Demodulation for communication systems //Calling Sequences // //x = demod(y,fc,fs,'method') //x = demod(y,fc,fs,'method',opt) //x = demod(y,fc,fs,'pwm',centered) // //Input parameters: // y: Real carrier signal // fc: Carrier frequenc...
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//ques11 disp('To find the inverse laplace transform of the function'); syms s t f=(s+2)/(2*s^2-4*s+13)); il=ilaplace(f,s,t); disp(il);
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// calculate the arrangement of slip gauges clc; Dd=52.215; disp(Dd,'desired value=') Pb=4; disp(Pb,'Protected block=') R=Dd-Pb; disp(R,'Reminder=') Tp=1.005; disp(Tp,'thousand block=') R=R-Tp; disp(R,'Reminder=') Hp=1.010; disp(Hp,'Hunderths block=') R=R-Hp; disp(R,'Reminder=') Ttp=2.20; disp(Ttp,'te...
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clear; clc; Length=4 //in micro-m Width=1 //in micro-m R=1000 //in ohm xj=1*10^-4 //junction depth in cm //Calculation N=Length/Width R0=R/N rho=R0*xj mprintf("Sheet resistance= %i ohm\n",R0) mprintf("average resistivity= %0.3f ohm-cm",rho)
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : CONTROL_FLOW_W -- Unit(s) Under Test: control_flow -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST...
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//EXAMPLE 4-56 PG NO-265 I1=5.92-%i*4.833; V=12+%i*0; Z=V/I1; disp('i) Input Impedance (Z) is = '+string (Z) +' ohm ');
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// Exa 1.5 clc; clear; close; // Given data R_L1 = 1*10^3;// in ohm R_L2 = 0.23;// in ohm R_T = R_L1+R_L2;// in ohm v1 = 10;// in V v2 = 0.7;// in V V_T = v1-v2;// in V I_L = V_T/R_T;// in A disp(I_L*10^3,"The load current in mA is"); V_L = I_L*R_L1;// in V disp(V_L,"The load voltage in V is");
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clc //initialisation of variables W= 2000 //kW m= 2 //kg/s h1= 3023.5 //kJ/kg s2= 5.6106 //kJ/kg K s1= 6.7664 //kJ/kg K //CALCULATIONS h2= h1-(W/m) S=s2-s1 //RESULTS printf (' enthalpy = %.1f kJ/kg',h2) printf (' \n entropy change = %.4f kJ/kg K',S)
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function z = gx(t,x,y) z = x*t - y endfunction function w = gy(t,x,y) w = y*t + x endfunction function [t,x,y] = heun(a,b,h,x0,y0) t = a:h:b n = length(t); x(1) = x0 y(1) = y0 for i = 1:n-1 k1x = gx(t(i),x(i),y(i)) k1y = gy(t(i),x(i),y(i)) k2x = gx(t(i) + h...
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clc clear //input n=6//order of fringe l=0.63*10^-6 //wavelength x=24.8*10^-3 //seperation of bands d=1.5 a=2.7*10^-4 //calculation x=d*(6+1/2)*l/a//distance between centre and sixth fringe w=l*1.6/a//fringe width //output printf("the distance between centre and sixth fringe is %3.3e m",x) printf("\nthe fr...
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clc; pathname=get_absolute_file_path('2_1_soln.sce') filename=pathname+filesep()+'2_1_data.sci' exec(filename) // Solutions: // we know acceleration due to gravity, g=32.2; //ft/s^2 W=(m*g); // Results: printf("\n Results: ") printf("\n The weight of Body is %.0f lb.",W)
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#------------------------------------- # tests of the michi fix_atari routine #------------------------------------- # escape # ------ debug setpos C8 C9 E9 B8 F9 D8 10 debug fix_atari C8 #? [1 C7] debug setpos C1 G7 B2 B1 20 debug fix_atari B1 #? [1 A1] play b e5 30 debug fix_atari B1 #? [1] # counter capture # --...
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clc clear //Input data d=0.2;//The diameter of bore in m L=0.3;//The length of the stroke in m r=5.5;//The compression ratio of the engine N=400;//The speed of the engine in rpm imep=4.5;//The indicative mean effective pressure in bar a=6;//Air to gas by volume CV=12000;//The calorific value of the gas in kJ/...
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function [txt,vnms,vtps,lcount]=ins2sci(lst,ilst,vnms,vtps) // traduit un ensemble d'instructions debutant a l'adresse ilst de la // liste courante lst //! // Copyright INRIA nlst=size(lst) level;level(2)=0; txt=[] while ilst<=nlst then if type(lst(ilst))==15 then [t1,vnms,vtps]=cla2sci(lst(ilst),vnms,vtps) i...
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clear // supprime les anciennes variables clf // supprime la figure avect = 0:0.2:2; // vecteur allant de 0 à 2 avec un pas de 0.2 b=0.1; d=0.05; // déclaration de variables b et d ndate = 0:20; // vecteur allant de 0 à 20 for i = 1:11 // boucle qui va dessiner les variables x(1) = avect(i); // initialise la premiè...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 2 - Pressure and its measurements // Problem 2.22 //Given Data Set in the Problem dens=1000 g=9.81 p0=10.143*10^4 Z=2500 //calculations //1) pressure by hydrostatic law dens0=1.208 p=p0-integrate("dens0*g","z",0,Z) mprint...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 14 Operational Amplifiers Pg no. 431 and 432 clear; clc; //Given A=175000;//open loop voltage gain Zin=1.5D6;//input impedance in ohms Zout=70;//output impedance in ohms Ri=8.2D3;//resistance Ri in ohms Rf=180D3;//feedback resistance in ohms //Solution ...
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//Problem 33.07: For the network shown in Figure 33.32, derive the Th´evenin equivalent circuit with respect to terminals PQ, and hence determine the power dissipated by a 2 ohm resistor connected across PQ. //initializing the variables: rv1 = 5; // in volts rv2 = 10; // in volts thetav1 = 45; // in degrees thet...
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//Chapter-1, Example 1.21, Page 1.49 //============================================================================= clc clear //INPUT DATA V=200;//Terminal voltage in V Ra=0.05;//Armature resistance in ohm Rse=0.03;//Field resistance in ohm N1=1000;//Present speed in rpm N2=800;//Required speed in rpm Ia=4...
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clc clear printf("Example 2.7 | Page number 41 \n\n"); //Find the mep, in kPa, and the indicated power in kW. //Given Data //four-stroke engine x = 3 //number of cylinders y = 1 //engine is single-acting n = 500 //rev/min N = n/2 //cycles/min D = 0.075 //m //bore length L = 0.1 //m //stroke length a = 6...
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// Example 9.7 //Write a multifunction how autometic variables work. funcprot(0); function[]=function1() m=int32(10); //Local Variable disp(m); //First Output endfunction function[]=function2() m= int32(100); //Local Variable function1(); //Calling...
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clear close clc s = poly(0,'s'); G = (1)/(s^3+ 3*s^2 + 2*s); Glin = syslin('c',G); clf(); evans(Glin);
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function [liste_y,liste_t]=RK4(f,y0,N,T) y=y0; liste_y=[y0]; t=0; liste_t=[0]; h=T/N; for k = 1:N k1=h*f(t,y); k2=h*f(t+h/2,y+(k1/2)); k3=h*f(t+h/2,y+(k2/2)); k4=h*f(t+h,y+k3); y=y+(k1/6)+(k2/3)+(k3/3)+(k4/6); t=t+h; liste_y=[liste_y,y]; liste_t=[liste_t,t]; end e...
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//example 10.6 clc; clear; printf('The correct logic expression is : (down-up)''(Qa)(Qb)(Qc)(enable)''');
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clc d=0.0015; //m l=0.15; //m A=%pi*d*l; ts=120; //0C tf=100; //0C h=4500; //W/m^2 0C Q=h*A*(ts-tf); disp("Electric power to be supplied =") disp(Q) disp("W")
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//Ex:6.4 clc; clear; close; R_l=400; V_in=9; V_z=5; P_z_max=0.5; R_s_max=R_l*((V_in/V_z)-1); R_s_min=((V_z*V_in)-V_z^2)/P_z_max; printf("Suitable value of resistor = %d ohm",(R_s_max+R_s_min)/2);
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1_02.sce
//Chapter 1, Problem 2 clc; M=5; //mass in kilogram A=2; //acceleration in m/s2. F=M*A; //calculating the force needed printf("Force = %f N \n\n",F); // displaying the result with unit
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EX5_1.sce
clc;funcprot(0);//Example 5.1 //Initilisation of Variables Tw=30;....//Surface temparature of plate in degrees celcius Ta=300;....//Temparature of air in degrees celcius P=0.06*10^5;...//Pressure of air in bar U=10;....//Velocity of flat plate in m/s K=0.0364;...//Thermal conductivity of air in W/m*K Pr=0.687;.....
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StartingPosition.sci
function [state] = StartingPosition() state = zeros(50, 40); s = size(state); for x = 1:s(1) for y = 1:s(2) if y < SandLine(x) state((s(1) - x + 1), y) = 1; end end end endfunction
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cummax10.sce
//check o/p when too many i/p args are passed to the function v=[8 3 6 ; 7 9 10; 6 2 2]; m=cummax(v,2,'reverse',2); disp(m); //output //!--error 77 //cummax: Wrong number of input argument; 1-6 expected //at line 50 of function cummax called by : //m=cummax(v,2,'reverse',2);
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cholesky.sci
function [C] = cholesky(A) [n,n] = size(A) C = zeros(n,n) for j = 1:n s = A(j,j)-sum(C(j,1:j-1)^2) if(s<=0) then error("Matrice non définie positive"); end C(j,j)=sqrt(s) for i = j+1 : n C(i,j)=1/C(j,j)*(A(i,j)-sum(C(i,1:j-1).*C(j,1:j-1))) ...
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~BivLCM-SR-bfas_oo_vrt_ind-PLin-VLin.tst
THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.273773D+00 ...
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Example9_7.sce
//Example 9.7.refer fig.9.39 clc hfe=60 hie=500 IC=3*10^-3 RB=220*10^3 RC=5.1*10^3 VCC=12 VBE=0.6 format(5) disp(" RB = 200 k-ohm >> hie = 500 ohm") disp("From h-parameter model") beta=hfe Zo=RC Av=(-hfe*RC)/hie disp(" Zi = hie = 500 ohm") disp(" Zo = RC = 5.1 k-ohm") disp(Av," Av =...
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17_3.sce
clc //initialisation of variables p0= 10 //Mpa R= 8.314 //J/mol K T= 30 //C va= 0.02 //m^3/kmol xa= 0.98 //CALCULATIONS p= p0+(R*(273.15+T)*log(xa)/(va*1000)) //RESULTS printf (' Pressure of the phase of pure A= %.2f Mpa',p)
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Ex12_5.sce
clear // // // //Variable declaration s=12411*10**3 //stress(Pa) t=0.0168 //tension e=0.127 //elongation(cm) l=15.24 //length(cm) g=9.8 L=68.04 //load(kg) //Calculation E_eff=s/t //effective modulus(Pa) S=e/l W=E_eff*S A=L*g/W //cross sectional area(m**2) //Result printf("\n effe...
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Ex3_8.sce
// Given:- // State 1 m = 0.9 // mass of air in kg T1 = 300.0 // initial temperature in kelvin P1 = 1.0 // initial pressure in bar // State 2 T2 = 470.0 // final temperature in kelvin P2 = 6.0 ...
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sce
22_03.sce
clear; clc; v=11e3; r=25e6; e=1; xg0=.05*%i; x1=.15*%i; x2=.15*%i; zbase=v^2/r; res=.3; xd=res/zbase; x0=xg0+(3*xd*%i); x=x1+x2+x0; ia0=e/x; ia=3*ia0; iabase=r/(1.7398*v); ia=ia*iabase; ia=fix(ia); printf("the line current for a line to ground fault=%dA",-imag(ia));
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rssq10.sce
//check o/p when too many i/p args are passed to it x=[1 2 3;2 7 4;4 2 5]; r=rssq(x,2,3); disp(r); ////output // !--error 58 //Wrong number of input arguments.at line 3 of exec file called by : ///rssq/rssq10.sce', -1
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//find length of each parallel fillet weld clc //solution //given //ref fig 10.15 b=75//mm//width t=12.5//mm//thickness ft=70//N/mm^2 T=56//N/mm^2 l1=b-t//mm s=12.5//mm //let l2 be length of each parallel fillet for static loading //P=A*ft P=b*t*ft//N//max load P1=0.707*s*l1*ft//N //P2=1.414*s*l2*T=990*l...
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ex_4.sce
// Chapter 10_Fundamentals of the Metal Oxide Semiconductor Field Effect Transistor //Caption_Flat band voltage //Ex_4//page 445 Na=3*10^16 eps=11.7*8.85*10^-14 eps_ox=3.9*8.85*10^-14 e=1.6*10^-19 Qss=10^11 Vtn=0.65 ni=1.5*10^10 //intrinsic carrier concentration phi_ms=-1.13 phi_fp=0.0259*log(Na/ni) xdt...
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voyellestoutesseules1.sce
scenario = "Entraînementaudio XP"; default_font = "Arial Unicode MS"; default_font_size = 33; begin; sound {wavefile { filename = "Sans_titre3.wav"; }; }s5; sound {wavefile { filename = "Sans_titre2.wav"; }; }s66; text { caption = "正式训练开始,我们训练的元音为\n\n /o/(peau) /O/(porc) /é/(fée) /eu/(peu) /oe/(peur)"; fo...
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Ex17_6.sce
//Chapter 17: Antenna Temperature, Remote Sensing and Radar Cross Section //Example 17-4.1 clc; //Variable Initialization tf = 0.693 //Absorption co-efficient (unitless) Te = 305 //Earth temperature (K) Ta = 300 //Satellite antenna temperature (K) //Calculations Tf = (Ta - Te*exp(-tf))/(1-exp(-tf))...
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Ex7_2.sce
clc; //page 344 //Drawing of shear and bending moment diagram printf("Given problem is for drawing diagram, this diagram is drawn by step by step manner.\n "); F_A=-20;//kN, force applied at A F_C=-40;//kN, force applied at C AB=2.5;//m, perpendicular distance between A and B BC=3;//m, perpendicular distance bet...
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Ex4_6.sce
//Ex:4.6 clc; clear; close; V=10;//pk-pk voltage r=1000;//ohms I_pk=V/r;//in Amps I_rms=0.353*I_pk*1000;//milliamps printf("RMS current of 10V peak-peak voltage = %f mA",I_rms);
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Example10_28.sce
/////////Chapter 10 Properties Of Steam ///Example 10.28 Page No:209 ///Enthalpy after throttling //Input data clc; clear; P1=12; //Throttled steam x1=0.96; //Dryness is brottled x2=1; //Constant enthalpy process //From steam table at12 bar ts=188; //In degree celsius hf...
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ex4_7.sce
clc; D=150; // Cylinder Diameter in mm L=200; // Piston stroke in mm C=0.05; // Clearance factor p1=15; // Steam inlet conditions (saturated) in bar p4=1; // Exhaust or back pressure in bar p2=p1; // Constant pressure process p5=p4; // Constant pressure process Vp=(%pi*(D*10^-3)^2*L*10^-3)/4; // Swept volme of ...
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//Executed from scilab using format and system boxes //with the command: // /usr/bin/scilex -nw -nb -f run_wave2d_dx.sce exec("wave2d.sce"); exec("savevtk_xym.sci"); jobname='job1'; //Read input wavetype=1; //travelling nsteps=40; maxamplitude=20; wavenumber(1)=10; wavenumber(2)=5; wavefreq=8; delta(1)=0.01; del...
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clc clear //Input data r=1.4;//Air standard ratio p1=1.25;//Cut off ratio 1 p2=1.50;//Cut off ratio 2 p3=2.00;//Cut off ratio 3 rc=16;//Compression ratio //Calculations n1=(1-((1/rc^(r-1)*(p1^r-1)/(r*(p1-1)))))*100;//Thermal efficiency of the diesel cycle for cut off ratio 1.25 n2=(1-((1/rc^(r-1)*(p2^r-1)/(...
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clear // //Given //Variable declaration L=2.5*1000 //Length in mm w=16.4 //Uniformly distributed load in kN/m I=7.95e7 //Moment of Inertia in mm^4 E=2e5 //Youngs modulus in N/sq.mm //Calculation W=w*L //Total load in N yB=((W*L**3)/(E*I*8)) ...
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errcatch(-1,"stop");mode(2);// Example 6.7, page no-374 rho=1000 h=10 P=rho*h printf("P = %d kg/m^2 = %d kg/cm^2 ",P,P/10000) exit();
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 6 //NOISE clear all; clc; printf("EXAMPLE 6.1(PAGENO 281)"); //given R = 10*10^3//resistance of amplifier in ohms T = 273+27//temperature in kelvin B = (20-18)*10^6//bandwidth k = 1.38*10^-23//boltzman's constant //calculations V_n = sq...
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// Example 17_14 clc;funcprot(0); //Given data P=120;//Plant capacity in MW p_1=150;// bar T_1=600;// °C p_2=0.08;// bar h_i=1000;// Heat transfer coefficient of water side in W/m^2 °C h_o=5000;// Heat transfer coefficient of steam side in W/m^2 °C T_wi=25;// The inlet temperature of water in °C T_wo=35;//The...
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main(){ type myType = array 5 of int; type myType2 = array 10 of myType; if(myType != myType2){ myVar = 0; } else{ myVar = 1; }}
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function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction //calculating current in each line Vl=400//line voltage Vph=Vl/sqrt(3)//phase voltage Ir=8D+3/Vph Iy=6D+3/Vph Ib=...
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//Example 10.13 F=2000;//Force exerted (N) r=2.20*10^-2;//Lever arm (m) net_tau=r*F;//Net torque (N.m) I=1.25;//Moment of inertia (kg.m^2) alpha=net_tau/I;//Angular acceleration (rad/s^2) printf('a.Angular acceleration of the leg =%0.1f rad/s^2',alpha) theta=1;//Angular displacement (rad) omega_0=0;//Initial an...
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clc; //e.g 3.17 mun=3600; mup=1700; k=1.38*10**23; T=300; DP=mup*(T/11600);//answer given in the book is wrong disp('m^2/s',DP*1,"DP="); Dn=mun*(T/11600);//answer given in the book is wrong disp('m^2/s',Dn*1,"Dn="); // test
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load Reg32Bit.hdl, output-file Reg32Bit.out, compare-to Reg32Bit.cmp, output-list time%S1.4.1 in0%B1.16.1 in1%B1.16.1 load%B2.1.2 out0%B1.16.1 out1%B1.16.1; set in0 %B0000000000000000, set in1 %B0000000000000000, set load 0, tick, output; tock, output; set load 1, tick, output; tock, output; s...
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pathname=get_absolute_file_path('10_02.sce') filename=pathname+filesep()+'10_02data.sci' exec(filename) disp("as the applied stress (approx 3513) bar is greater than yield stress but less than ultimate stress of the aluminium rod,it will experience permanent set but will not fracture" )
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function drawobjs(scs_m) nx=size(scs_m) for i=2:nx drawobj(scs_m(i)) end drawtitle(scs_m(1))
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clc P1=1*10^6 //pressure in Pascal h1=3052.1 v1=0.258 s1=7.1251 u1=h1-(P1*10^-3*v1) mprintf("u1=%fkJ/kg\n",u1)//ans vary due to roundoff error s2=s1 sf=1.3027 sg=7.3598 hf=417.54 hg=2675.4 vf=0.001043 vg=1.6940 X2=(s1-sf)/(sg-sf) mprintf("X2=%f\n",X2)//ans vary due to roundoff error h2=(hg*X2)+(1-X2)*hf...
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Example13_4.sce
clear ; clc; // Example 13.4 printf('Example 13.4\n\n'); //Page No. 408 // Solution mol_wt_N2 = 28 ;// Molecular mass of 1 kg mol N2 -[kg] mol_V = 22.42 ;// Molar of ideal gas at standard condition-[cubic metre/kg mol] Tc = 27 ;// Temperature-[degree C] T = Tc + 273 ;//Temperature-[K] P = 100 ;//Pressure-[kPa] //St...
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clc //Chapter3: Modulation //Example3.4, page no 138 //Given Ebb=2e3//DC plate supply Ecc=-500//DC grid bias Ib=67e-3//DC plate current Ic=30e-3//DC grid current Egm=750//RF peak grid voltage Pout=75//RF Power output Ma=0.75//Depth of modulation Paf=(Ma^2*Ebb*Ib)/(2*1)//modulating power required from the aud...
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//Chapter 1: Structure and Bonding //Problem: 5 clc; //Declaration of Constant h = 6.626 * 10 ** -34 // Plank's constant,in J.sec //Declaration of Variables m = 10 * 10 ** -3 // Mass of the ball,in kg v = 10 ** 5 // Velocity of ball,in cm / sec // Solution lamd...
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clear; clc; Sb=30; vb=11; sg=20; p=10; R=6.6; //generator X1=complex(0,.1); X2=complex(0,.1); X0=complex(0,.15); x1=X1*(Sb/sg); x2=X2*(Sb/sg); x0=X0*(Sb/sg); //transformer12 xt1=complex(0,.12); xt2=complex(0,.12); xt0=complex(0,.12); //transmission line vtr=22; Ztr=vtr^2/Sb; Z=complex(1,5); Zpu=Z/...
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// Example 3.33: vo clc, clear t=[0:0.001:12]; vin=10*sin(2*%pi*t/4); // Input voltage in volts // From Fig. 3.73 vint=vin+5; for i=1:length(vint) if vint(i)>0 then // Diode is OFF vo(i)=vint(i); // in volts else break; end end for i=i:length(vint) if vint(i)==-5 t...