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//ship approaching port //refer fig. 14.13 and 14.14 //let west be x and north be y axes //speed in kmph is vBx=25*sind(45) vBy=25*cosd(45) vAx=-15 vAy=0 //Let vr be the relative velocity of B w.r.t. A vrx=17.678-(-15) //kmph vry=17.678 //kmph vr=sqrt((32.678^2)+(17.678^2)) //kmph alpha=atand(17.678/3...
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extracting "~temp.png" extracting "~temp.jpg"
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clear clc //to find average power must be applied by the elevator motor // GIVEN:: //weight of elevator w = 5160//in N //average weight of passenger wp = 710//in N //number of passengers n = 20 //distance between floors sf = 3.5//in meters //time elasped t = 18//in seconds //acceleration due to gra...
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//chapter25 //example25.6 //page552 S=0.01 //mm per volt V=400 // V spot_shift=S*V printf("spot shift = %.3f mm \n",spot_shift)
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///Chapter No 11 Steam Boilers ////Example 11.17 Page No 248 ///Find Actual draught produced in hot gas //Input data clc; clear; mf1=8000; //Average coal consumption in Kg/h ma1=19; //Flue gases formed in Kg/Kg Tg1=270+273; //Average temperature of the chimney in degree celsius Ta1=...
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//Caption:determine_unit_step_and_unit_impulse_response //example 12.11 //page 524 s=%s; syms t; G=sym('8/(s+1)'); H=sym('(1/2*s)'); CL=G/(1+G*H); disp(CL,"C(s)/R(s)="); //for unit step response R(s)=1/s; d=CL*(1/s); disp(d,"C(s)="); c=ilaplace(d,s,t); disp(c,"unit step response,c(t)="); //for unit impulse response R(...
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clc,clear printf('Example 3.3\n\n') I_L1=40 //motor armature current V=250 //rated voltage R_se=0.5 // resistance of series motor N_1=1500;N_2=1200 //initial and final speed E_b1= V - I_L1*(R_se+ 0) //since R_h is zero initially // because E_b = V - I_1*(R_se+ R_h) back emf T2_by_T1 = (N_2/N_1)^2 //lo...
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_salient_cued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds = fa...
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//exa 2.20 clc;clear;close; format('v',6); //F1=0.004*P1^2+2*P1+80;//Rs./hr //F2=0.006*P2^2+1.5*P2+100;//Rs./hr P=250;//MW P1=poly(0,'P1');P2=poly(0,'P2'); dF1bydP1=2*0.004*P1+2; dF2bydP2=2*0.006*P2+1.5; //Let loads are P1 & P-P1 //Economical loading lambda1=lambda2 eqn=2*0.004*P1+2-2*0.006*(P-P1)-1.5; P1=r...
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function [fig] = kiks_gui_monitor() // Ouput variables initialisation (not found in input variables) fig=[]; // Number of arguments in function call [%nargout,%nargin] = argn(0) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------...
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clear; clc; printf("\t Example 5.2\n"); d1=0.1; // diameter of sphere, m T1=303; // environment temp.,K T2=278; // fridge temp., K h=6; //convection coefficient, W/(m^2*K) k=0.603; //thermal conductivity,W/(m*K) a=997.6; // density of water, kg/m^3 c=4180; //heat capacity, J/(kg*K) F=(k/(a*c))*3600/(d...
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//Example 5.4: clc; clear; close; //given data : dIc=100;//in mA Rl=6;//in ohm mv=dIc*Rl*10^-3;//in V pd=mv*dIc;//in mW disp(pd,"(i) power developed in loudspeaker is ,(mW)=") dVc=10;//in V oi=(dVc/dIc)*10^3;//in ohm Rl=6;//in ohm n=sqrt(oi/Rl);//turn ratio of transformer tsv=dVc/n;//om V Il=tsv/Rl;//in A ptr= Il^2*Rl...
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// Example 2.7 clear all; clc; disp('The reactants are Nitrogen and neutron') // The total atomic number of reactants Z_reactant = 7+0; // The total atomic mass number of reactants A_reactant = 14+1; disp('One of the known product is Hydrogen') Z_H = 1; // The atomic number of Hyd...
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clear; clc; printf("\t Example 2.22\n"); //variation in liquid level with respect to time is given below t=[26 185 456 1336 1958 2810 3829 4822 6385] // let Zt-Zo= x; x=[.25 1.29 2.32 4.39 5.47 6.70 7.38 9.03 10.48] i=1; //looping starts while(i<10) y(i)=t(i)/x(i); ...
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clear; clc; //Example - 16.8 //Page number - 580 printf("Example - 16.8 and Page number - 580\n\n"); //Given R = 8.314;//[J/mol*K] - universal gas constant T_f = 273.15;//[K] - Freezing point of water m_water = 100;//[g] - Mass of water m_NaCl = 3.5;//[g] - Mass of NaCl M_wt_water = 18.015;// Molecular weight of wate...
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clear; clc; //Example 13.13 Va=150; Vt=0.026; Ic13=0.2; gm13=Ic13/Vt; printf('\ntransconductance=%.2f mA/V\n',gm13) ro13=Va/Ic13; printf('\noutput resistance=%.2f KOhm\n',ro13) Av2=gm13*ro13; printf('\nvoltage gain=%.2f \n',Av2)
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//chapter 37 //example4 clc //given e=1.6*10^-19 //in coul r=5.1*10^-11 //radius of hydrogen atom in meter m=9.1*10^-31// mass of electron in kg epsilon0=8.9*10^-12 //in coul2/nt-m2 B=2 //in wb/m2 delta_p=(e^2*B*r^2)/(4*m) disp(delta_p,"Change in Orbital dipole moment in amp-m2 is + 0r -")
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clc M_CO2=44; M_H2=2; M_N2=28; M_CH4=16; M_CO=28; // Let volumetric analysis be denoted by V V_CO=0.28; V_H2=0.13; V_CH4=0.04; V_CO2=0.04; V_N2=0.51; Cp_CO=29.27; //kJ/mole K Cp_H2=28.89; //kJ/mole K Cp_CH4=35.8; //kJ/mole K Cp_CO2=37.22; //kJ/mole K Cp_N2=29.14; //kJ/mole K R0=8.314; Cp=V_...
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//====================================================================== // chapter 1 example 10 clc; clear; //input data a = 4; //lattice constant in Å //calculation d = (sqrt(3)*a)/4; //result mprintf('distance between two atoms =%3.3f.Å\n',d); //====================...
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clc;clear; //Example 2.2 //given values V=900;//potential difference in V B=0.01;//uniform magnetic field in Wb/m^2 em=1.76*10^11;//value of e/m in C/kg //calculation v=sqrt(2*em*V); disp(v,'The linear velocity(in m/s) of electron is'); R=v/(em*B); disp(R,'The radius(in m) of the circular path is')
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clc; funcprot(0); //Example 8.1 Lift Equation // Initialisation of variables V = 100*1.467; // Velocity in ft/s alpha =4; S = 250; //Wing Area. rho = 0.00237; // Calculations Cl = 0.649; // From figure 8.8 W = Cl*rho/2*S*V^2; //Results disp(W,"Weight with which an airplan...
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result postfix=[32, x, *, 64, x, *, y, *, +, 32, y, *, 128, x, *, y, *, -, /] (x + 2*x*y) / (y - 4*x*y)
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// Scilab Code Ex3.9:: Page-3.24 (2009) clc; clear; lambda = 6600e-008; // Wavelength of light used, cm a = 0.018; // Width of the slit, cm f = 200; // Focal length of the lens, cm n = 1; // Order for first order diffraction // As a*sin(theta) = n*lambda, a*theta = n*lambda // As theta = lambd...
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clear// //Variable Declaration M=15000 //Maximum bending moment in absolute values in lb.ft S=42 //Sectional Modulus in in^3 //Calculations sigma_max=M*12*S**-1 //Maximum stress in the section in psi //Result printf("\n The maximum Bending Stress in the section is %0.0f psi",sigma_max)
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//finding maxterms and minterms// //example 34// clc //clears the command window// clear //clears// //finding minterms and maxterms// disp('given Y=AC''+A''C') disp('Y=A''C(B+B'')+AC''(B+B'')') disp('Y=A''CB+A''CB''+AC''B+AC''B''') disp('these are the required minterms') disp('the minterms indicate the posit...
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counts = [40 1 9]; len = 11; seq = [1 3 2 1 1 1 3 3 1 1 2 ] code = arithenco(seq,counts); disp(code) dseq=arithdeco(code,counts,len) disp(dseq) disp(seq)
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function do_help while %t do [btn,xc,yc,cwin]=xclick(); if cwin==curwin then [nm,pt,btn]=getmenu(datam,pt) if nm>0 then name=menus(nm) break, else k=getobj(x,[xc;yc]) o=x(k) name=o(5) break end elseif or(windows(find(windows(:,1)<0),2)==cwin) then kwin=...
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function [s]=sylm(a,b) //[s]=sylm(a,b) gives the Sylvester matrix associated to polynomials //a and b, i.e. the matrix s such that: // coeff( a*x + b*y )' = s * [coeff(x)';coeff(y)'] //dimension of s is equal to degree(a)+degree(b) //If a and b are coprime polynomials //(rank(sylm(a,b))=degree(a)+degree(b)) the instru...
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//Simpson's Adaptive Quatrature clc; clear; close(); format('v',10); funcprot(0); deff('[y]=f(x)','y=exp(x)'); a = 0.5; b = 1; h = (b-a)/2; S1 = h*(f(a)+4*f((a+b)/2)+f(b))/3; disp(S1,'S1 : '); S2 = h*(f(a)+4*f((3*a+b)/4)+2*f((a+b)/2)+4*f((a+3*b)/4)+f(b))/6; disp(S2,'S2 : '); err = abs(S2-S1)/15; disp...
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clc // variable initiallitation T1=50 //torque in N-m s=0.3 //slip p=4 //number of poles f=50 //frequency in Hz V=400 //supply voltage in volts Toff=poly(0,'Toff') Ton=0.4*Toff //solution Tratio=0.4 Ns=1500 //synchronous speed in rpm N1=Ns*(1-s) T2=40 //torque in N-m N2=sqrt((T2/T1)*(Ns)^2) Tav=((T1*Ton...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.266469D+00 ...
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function [x,y,typ] =mdaq_pru_reg_set(job,arg1,arg2) pru_reg_desc = ["This block sets MicroDAQ PRU real-time"; "execution unit register."; ""; "input(1) - PRU register value (uint32)"; ""; "PRU register: 0...15"; ""; "Set block parameters:"]; x=[];y=[];typ=[]; select job case...
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// Copyright (c) 2017, Linz Center of Mechatronics GmbH (LCM) http://www.lcm.at/ // All rights reserved. // // This file is licensed according to the BSD 3-clause license as follows: // // Redistribution and use in source and binary forms, with or without // modification, are permitted provided that the followin...
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clc //Chapter15 //Example15.1, page no 533 //Given P_A=0.5// probability of producing symbol 'A' P_B=0.25// probability of producing symbol 'B' P_C=0.25// probability of producing symbol 'C' H=P_A*log2(1/P_A)+P_B*log2(1/P_B)+P_C*log2(1/P_C)// the source entropy mprintf('The source entropy is: %f bits/symbol',H)...
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//root locus s=%s sys=syslin('c',1/(s*(s+2)*(s+1))) clf evans(sys) printf("root loci is symmetical to both axis")
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//Exa 4.12 clc; clear; close; // given : Gt=10 // transmission gain in dB Gr=10 // receiving gain in dB //when frequency=0.3GHz // given : f=0.3 //frequency in Ghz f=0.3*10^9 //frequency in hertz c=3*10^8 //speed of light in m/s lambda=c/f //wavelength in meter d1=1.6 // in Km d1=1.6*10^3 // in meter // ...
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//Script to model influence of uniform e and b field //on charged particle motion exec('lorentz.sce'); exec('bfield.sce'); m=1.6*(10^(-27)); q=1.6*(10^(-19)); dt=5.0*(10^(-9)); it=1:1:1000; //plotid=evstr(x_dialog('plotid ?','1'));; //text=x_dialog('Title?','current'); plotid=1; text='current'; r=zeros(3,1); v=zeros...
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#Heater example #distillation tower condenser is used to preheat distillation tower feed $thermo = VirtualMaterials.NRTL/Ideal/HC / -> $thermo thermo + ETHANOL WATER topVap = Stream.Stream_Material() topVap.In.P = 101.325 topVap.In.VapFrac = 1 topVap.In.MoleFlow = 100 topVap.In.Fraction = 0.85 0.15 cond = Heater.Coo...
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//Example 4.28 //use of flags with unsigned decimal, octal and hexadecimal numbers i = 1234; j = oct2dec('1777'); k = hex2dec('a08c'); printf(":%8u %8o %8x:\n\n", i, j, k); printf(":%-8u %-8o %-8x:\n\n", i, j, k); printf(":%#8u %#8o %#8X:\n\n", i, j, k); printf(":%08u %08o %08X:\n\n", i, j, k);
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Mathe_Labor_Aufgabe1-3.sce
//Aufgabe 1 A = [1 4; 2 5; 3 6]; B = [1 4 0 0; 2 5 0 0; 3 6 0 0]; C = [1 4 1 2 3; 2 5 4 5 6; 3 6 0 0 0]; //Aufgabe 2 D = zeros(5, 10); j = 1; k = 1; for i = 1 : 50 D(j, k) = i; k = k + 1; if (i == 10) j = 2; k = 1; end if (i == 20) j = 3; k = 1...
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9_2.sce
//// //Variable Declaration nb = 5.00 //Number of moles of Benzene, mol nt = 3.25 //Number of moles of Toluene, mol T = 298.15 //Temperature, K P = 1.0 //Pressure, bar R = 8.314 //Ideal Gas Constant, J/(mol.K) //Calculations n = nb + nt xb = nb/n xt = 1. - xb dGmix = n*R*T*(xb*log...
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5_14.sce
clear all; clc; disp("Ex 5_14") disp("Free body diagram is as shown in fig 5-29b") disp("Summing moments about X-direction:") disp("981*0.1-P*0.3*cos30=0") disp("P = 377.6 N") disp("Summing moments about Y-direction:") disp("-981*0.5+A_z*0.8+377.6*0.4=0") disp("A_z = 424.3 N") disp("Summing moments about Z-direction...
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tiProjection.sci
// ----------------------------------------------------------------------- // Etude de la projection perspective, matrices extrinseque et intrinseque // d'une camera. Fonction d'affiche d'un objet apres projection // Module TI, Traitement d'Images // Copyleft (C) 2012-2014 Universite Lille 1 // // This program is free...
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Gausssanspivot.sci
A = [1 2;-3 -1] b = [3;-4] function [x]=Gausssanspivot(A,b) // résout le système Ax=b par [m,n]=size(A);o=length(b); if m~=n | o~=n then, error('probleme de dimensions'), end; // initialisation zero=1.e-16; for k=1:n-1 u=A(k,k:n);pivot=A(k,k);i0=k if abs(pivot)<zero then, error('stop : pivot n...
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ex7_16.sce
// Exa 7.16 clc; clear; close; format('v',6) // Given data Vt = 1;// in V KnWbyL= 10*10^-3;// in A/V^2 V_DD = 5;// in V V_D = 0.1;// in V I_D = Vt*( (V_DD-Vt)*V_D - 1/2*KnWbyL );// in mA R_D = (V_DD-V_D)/(I_D*10^-3);// in ohm R_D= R_D*10^-3;// in k ohm disp(R_D,"The value of R_D in k ohm is : ") V_DS = ...
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//Fluid system - By - Shiv Kumar //Chapter 2 - Impact of Jet //Example 2.30 clc clear //Given Data:- V=40; //Absolute Velocity of Jet, m/s a=0.04; //Cross-sectional area of Jet, m^2 u=40; //Speed of boat, km/hr //Data Used:- rho=1000; ...
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ex1_4.sce
clc; clear all; change = 0.01/100; h = 1e5; // Height rho = 1 // Density of water in gm per cm square g = 980 // Gravity constant in am per square cm deltap = h*g*rho; k = deltap/change; disp('dyne cm^-2',k,'Bulk modulus of sphere is ')
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example5_14.sce
disp('chapter 5 ex5.14') disp('given') disp('Determine the load capacitance') disp('from the data sheet Ro=150ohm') Ro=150 disp('f=600kHz') f=600000 disp('Cs=1/(2*%pi*f*10*Ro)') Cs=1/(2*%pi*f*10*Ro) disp('farads',Cs)
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ex4_20.sce
//Exa 4.20 clc; clear; close; // Given data Q_acb = 84;//in kJ W_acb = 32;// in kJ //Formula Q_acb = del_U+W_acb where del_U = U_b - U_a; del_U = Q_acb - W_acb;// in kJ // Part (a) Path a b d W_abd = 10.5;// in kJ Q_abd = del_U + W_abd;// in kJ disp(Q_abd,"Heat flows into the system along the path a b d in ...
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ex4_32.sce
// Exa 4.32 clc; clear; close; // Given data V_BB = 10;// in V V_BE = 0;// in V R_B = 470;// in kohm R_B = R_B * 10^3;// in ohm I_B = (V_BB - V_BE)/R_B;// in A bita = 200; I_C = bita*I_B;// in A V_CC = 10;// in V R_C = 820;// in ohm V_CE = V_CC - (I_C*R_C);// in V disp("Part (a) : For ideal approximati...
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TemplateSDL.sce
####### INITIATION ####### # Initiation of the scenario and the main PCL-file scenario = "Template"; pcl_file = "TemplatePCL.pcl"; no_logfile = true; # Keep SDL as simple/stupid as possible and # STAY CLEAR OF THE PARALLEL PORT!!! response_matching = simple_matching; response_port_output = true; # To get the Enter ...
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rawToASCII.sce
// script to convert proprietary XRD measurement data into .csv bRes = csvDefault("eol", "linux") files = ls(pwd()) for i = grep(files, '.raw') //set file filter 1 [path,fname,extension]=fileparts(files(i)) printf("\n" + fname + "\n") [fileD, Error] = mopen(files(i...
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Ex5_4.sce
//Example 5_4 clc(); clear; //To find out the power being developed in motor m=200 //units on Kg g=9.8 //units in meters/sec^2 Fy=m*g //units in Newtons vy=0.03 //units in meter/sec P=Fy*vy //units in Watts P=P*(1/746) //units in hp printf("Power developed P=%.5f hp",P)
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FLFloor-Netezza-01.tst
-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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reg.sci
function dout = reg(addr,din) if argn(2) == 1 ftdi('write',[0,addr,0,0]); sleep(15) r = ftdi('read'); dout = 2^8 * r(1) + r(2); else ftdi('write',[1,addr,floor(din/2^8),modulo(din,2^8)]); dout = []; end endfunction
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ATWM1_Working_Memory_MEG_Salient_Uncued_Run2.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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ex10_6.sce
//Page Number: 558 //Example 10.6 clc; //Given sig=5.8D+7; f=10; //GHz h=0.12D-2; //m q=62.8*h*sqrt(f*sig); disp(round(q),'conductor Q of the stripline:');
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example_4_10.sce
clear; clc; disp("--------------Example 4.10---------------") bandwidth = 200*10^3; // 200 kHz //The bandwidth of a low-pass signal is between 0 and f ,where f is the maximum frequency in the signal. // Therefore, highest frequency =200 kHz f = bandwidth; // max frequency sr = 2*f ; // sampling rate = 2*max fre...
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//chapter-7,Example7_10,pg 498 n=10*10^2//scale factor=(1/n) fc=10*10^5//clock frequency N=10//count Tp=(n/fc)*N//time between events printf("time between events\n") printf("Tp=%.4f s",Tp)
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inf = float('inf') plant_pvt_init_data = None T = 720.0 delta_t = 0.5 # HybridConfig initialConfig(initialSet, 2, 0, 0); # Initial Mode initial_discrete_state = [2] # Interval init_Gp = init_Gs; # init_Gp.mul_assign(1.9152); # States # idx 0 1 2 3 4 5 6 7 ...
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clc;funcprot(0);//EXAMPLE 17.9 //page 542 // Initialisation of Variables psi=10*10^6;..............//Modulus of elasticity of 7075-T6 in psi psi1=55*10^6;..............//Modulus of elasticity of Boron fiber in psi psi2=11*10^6;..............//Modulus of elasticity of Typical AL-LI in psi f1=0.6;...............//V...
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 1.6.1\n') //given data //case 1 //a complex number is represented as Z=X+j*Y where j is imaginary //V=3 +j*7 x1=3 y1=7 //calculations r1=sqrt(x1^2+y1^2) if (y1/x1)>0 then theta1=atan(y1/x1) else theta1=%pi-atan(abs(y1/x1)) end th...
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//CHAPTER 4- MEASURING INSTRUMENTS //Example 1 clc; disp("CHAPTER 4"); disp("EXAMPLE 1"); //VARIABLE INITIALIZATION N=10; //number of turns I=5; //in amperes B=500; //flux density in Wb/m^2 ar=15/10000; //area in m^2 //SOLUTION T_d=N*B*I*ar; disp(sprintf("The deflecting torque exerted on...
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//example 8.13 //calculate hydrodynamic earthquake pressure //moment at 50m below water surface clc;funcprot(0); //given c=1; H=100; //heigth of dam hw=100; //heigth of water in reservior FB=1; //free board s=0.15; //slope of upstream face gamma_w=9.81; //unit wei...
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//Example 4.19 close; clc; e=10; //in volts R1=10000; //In ohms R2=10000; //In ohms Ifsd=100*10^-6; //in amperes Range=10; //in volts Sdc=1/Ifsd; //Sensitivity Rs=Sdc*Range; //Multiplier Resistence //Voltage across R2 R=R2*Rs/(R2...
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//Problem 20.16: A 200 kVA rated transformer has a full-load copper loss of 1.5 kW and an iron loss of 1 kW. Determine the transformer efficiency at full load and 0.85 power factor. //initializing the variables: S = 200000; // in VA Pc = 1500; // in Watt Pi = 1000; // in Watt pf = 0.85; // power factor //calc...
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// Exa 5.23 clc; clear; close; // Given data A=10^5; Af= 10^3; // Af= A/(1+A*Bita) Bita= 1/Af-1/A; GDF= 1+A*Bita;// gain densitivity factor disp(GDF,"Gain densitivity factor is : ") // Part (a) when A drops 10 % A_desh= A-A*10/100; Af_desh= A_desh/(1+A_desh*Bita); CorresPer= (Af-Af_desh)/Af*100;// corresp...
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//clc(); clear; //To calculate the wavelength and energy of X-ray beam theta=27.5; //diffraction angle in degrees n=1; //diffracted order h=1; k=1; l=1; H=6.625*10^-34; //plancks constant c=3*10^10; //velocity of light a=5.63*10^-10; //lattice constant in m d=a/(sqrt(h^2...
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//Example 3.37: Insolution resistance of the cable clc; clear; close; v1=200;//volts v2=125;//volts t=30;//seconds cr=t/(log(v1/v2));// v21=100;//volts cr1=t/(log(v1/v21));// y=cr1/cr;// x=10;//mega ohms R=((x/y)-x);//mega ohms disp(R,"resistance is,(M-ohm)=")
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//check o/p when a and b are of unequal length a = [1 2 -1 1]; b = [1 1 2 1 2 2 1 1]; c = cconv(a,b); disp(c); //output //1. 3. 3. 5. 3. 7. 4. 3. 3. -2.220D-16 1.
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clc(); clear; //Given : R = 1; // radius in A N = 5*10^28 ; // atoms/m^3 mu_0 = 4*%pi*10^-7; // permiability of free space in H/m mu_r = 1;//relative permiability m = 9.1*10^-31 // electron mass in kg e = 1.6*10^-19 ; // charge of an electron in C // R = 1*10^-10 m because 1 A = 1.0*10^-10 m chi = -(N*e^2*(...
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// Scilab // disp(%pi); assert_checkequal(2+2,4);
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//Chapter 01: The Foundations: Logic and Proofs clc; clear; mprintf("Propositon p=Michael s PC runs Linux.") mprintf("\n Negation of p is ~p : It is not the case that Michael s PC runs Linux.") mprintf("\n Negation of p is ~p : Michael s PC does not run.Linux")//Negation is opposite of the truth value of the proposit...
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clc// // // //Variable declaration Vy=37*10^-6; //voltage(V) t=10^-3; //thickness(m) Bz=0.5; //magnetic field(wb/m^2) Ix=20*10^-3; //current(A) //Calculation RH=Vy*t/(Ix*Bz); //hall coefficient(m^3/coulomb) //Result printf("\n hall coefficient is %e C-1 m^3",RH)
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clc; Rh=3.66*10**-4; rho=8.93*10**-3; mu=Rh/rho; disp('m^2/V-s',mu*1,"mu="); q=1.6*10^-19; n=1/(q*Rh); disp('/m^3',n*1,"n=");
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clear; clc; disp("--------------Example 3.19---------------") bandwidth=4000; // 4 kHz bits =8; // bits per sample br=2*bandwidth*bits; // formula to calculate bit rate bit_rate=br*10^-3; //multiply with conversion factor printf("The bit rate of the channel is %d kbps.",bit_rate); //display result
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Na=10^17; Nd=10^16; ni=10^10; a=0.0259; //say a=K*T/q V0=a*log(Na*Nd/ni^2); printf('\n The value of V0 is %1.2fV',V0); Va=0.5; b=11.8*8.85*10^-14; q=1.6*10^-19; xp=sqrt(2*b*Nd*(V0-Va)/(q*Na*(Na+Nd))); xn=sqrt(2*b*Na*(V0-Va)/(q*Nd*(Na+Nd))); printf('\n The value of xp is %f*10^-6 cm',xp*10^6); printf('\n Th...
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pathname=get_absolute_file_path('11_01.sce') filename=pathname+filesep()+'11_01data.sci' exec(filename) Cp=Cpmax*(sin(theta))^2; disp(Cp,"Cp=","Cp=Cpmax*(sin(theta))^2","pressure coefficient at point 1 Cp:") printf("\Answer:\n") printf("\n\pressure coefficient at point 1 : %f \n\n",Cp)
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clc; //Example 17.1 //Page No 690 //solution p1=10*10^-3; p2=0.5*10^-3; disp("(a)The power levels, "); P1=10*log10(p1/0.001); disp('dBm',P1,"P = "); P2=10*log10(p2/0.001) disp('dBm',round(P2),"P = "); disp("(b)The difference "); P=10*log10(p1/p2); disp('dBm',round(P),"diff = "); disp("The 10mW power level...
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// Example 3.8, page no-167 clear clc //(a) r1=2500 r2=1500 n=(r1*r2)/(r1-r2) printf("(a)\nn = %d rpm",n) //(b) N=5 r5=n*r1/((r1*(N-1))+n) r5=ceil(r5) printf("\n(b)\nr5=%d",r5)
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clc; pathname=get_absolute_file_path('13_9_soln.sce') filename=pathname+filesep()+'13_9_data.sci' exec(filename) // Solution: // from fig 13-29, // entering moistue content at 80 deg F, moist_in=1.58/1000; //lb/ft^3 // moisture rate which enters the compressor, moist_rate=moist_in*Qc; //lb/min // number of gallons/day...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Laminar Channel Flow 3D homogeneous 2D, P=3, 8x8 Fourier modes (MVM)</description> <executable>IncNavierStokesSolver</executable> <parameters>ChanFlow_3DH2D_MVM.xml</parameters> <files> <file description="Session File">ChanFlow_3DH2D_MVM...
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function []=fun1(plantParam,envParam,outputParam) //[i]=type(plantParam); //Checked possibilities for types //Correct way to print vars //disp(i); envFiles=listfiles([envParam]); //for i=1: y=size(envFiles); disp("Starting simulations"); [referenceFile,err]=mopen(outputParam+"referenceFile.txt","w"); for ...
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//Chapter 3 : Polarization clear; //Variable declaration lamda=6000 //wavelength in Armstrong //Calculations Ie=3/4 Io=1/4 Ratio=Ie/Io //Result mprintf("Ratio of the two intensities Ie:Io is %d or = 3:1",Ratio)
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//Caption:resistance required to be connected in series to reduced speed of machine to 800 rpm (in Ohm) //Exam:2.30 clc; clear; close; V=400;//voltage applied across the motor(in V) R_sh=100;//shunt resistance of motor(in Ohm) I=70;//total current flowing through motor(in Amp) I_sh=V/R_sh;//current flowing thro...
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// Given:- T1 = 294.0 // entry temperature of air in kelvin P1 = 5.1 // entry pressure of air in bars T2 = 352.0 // exit temperature of hot stream in kelvin P2 = 1.0 // exit pressure of hot stream in bars T3 ...
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//example 9.5(b)// clc //clears the screen// clear //clears all existing variables// close c = [0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 ]; //taking the values for a mod - counter q = [0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 0 0 ]; a = [0 1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0 ]; b = [0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 ]; y1=q; y2=...
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clc clear //input r=20;//resistance of coil in ohms l=0.04;//inductance of coil in henry v=240;//supply voltage in volts f=50;//frequency of supply in hertz //calculations xl=2*%pi*f*l;//reactance of coil in ohms z=((r^2)+(xl^2))^0.5;//impedance of coil in ohms i=v/z;//current in amperes cosp=r/z;//cosin...
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clc X =input('Enter X= ') [m n] = size(X) A = X(:,1) E = X(:,1)*X(:,1)' for i=2:n A = A + X(:,i) E = E + X(:,i)*X(:,i)' end mx = A/n disp(mx,"mx= ") E = E/n disp(E,"E= ") C = E - mx*mx' disp(C,'Cov Matrix= ') //Eigen Values and Vectors [V D] = spec(C) disp(V,"Normalised Eigen Vector V= ") ...
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//Chapter-1,Example1_16_1,pg 1-75 Ev=1.08 //average energy required to creaet a vacancy k=1.38*10^-23 //boltzman constant in J/K e=1.6*10^-19 //charge on 1 electron K=k/e //boltzman constan...
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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 3 //example 3.16 //edition 1 //publisher and place:Nelson Engineering clc; clear; Vdc=250; Vs=208;//line to line ac voltage R=3;//system resistance between battery bank and source in ohm Beta=122; Vmax=(sqrt(2)*Vs)/sqrt(3); ...
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<!DOCTYPE SCE> <sce> <project>vocoder.sce</project> <compiler> <option name="libpath" ></option> <option name="libs" >-xl src/common/pack.o</option> <option name="incpath" >src/common</option> <option name="importpath" >src:src/common:src/lp_analysis:src/open_loop:src/closed_loop:src/codebook:src/update:src/p...
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clc; r=50*10^-3; // radius of rotor g=2*10^-3; // air gap length l=10*10^-3; // length normal to radius r B=2.2; // maximum air gap flux density uo=4*%pi*10^-7; // free space permeability // after the derivation of the expression T=(B^2*g*r*l)/uo; printf('Magnitude of torque is %f N-m',T);
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clc clear T1=25+273; //in K T3=1500+273; //in K Qa=900; //in kJ/kg Cv=0.718; G=1.4; T2=T3-(Qa/Cv); r=(T2/T1)^(1/(G-1)); printf('Compression Ratio is %2.1f ',r); printf('\n'); Eff=100*[1-(1/(r^(G-1)))]; printf('Efficiency is %2.1f Percent',Eff); printf('\n'); Px=r^G; //Max Press...
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clear all; clc; disp("Scilab Code Ex 6.22 : ") //Given: sigma_allow_st = 168; //MPa sigma_allow_w = 21; //MPa Est = 200; //GPa Ew = 12; //GPa Iz = 7.93*10^6; //mm^4 A1 = 5493.75; //mm^2 t = 5; //mm h = 100; //mm //Without Board: c = h+t; M1 = (sigma_allow_st*Iz)/(c*10^6); //With Board: bw = 300;/...
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//(Threaded Joints) Example 7.19 //Maximum external force Pmax (kN) Pmax = 10 //Minimum external force Pmin (kN) Pmin = 0 //Assume the stiffness of the bolts to be 1N/mm kb kb = 1 //Calculate the stiffness of the parts kc kc = 3 * kb //Overload percentage load (%) load = 50 //Yield tensile strength of 50C4...
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/////Function :-- lyapchol //////////// ////Lyapunov Equation a =[-1.6602 1.0973; 1.0973 -2.1947 ]; b=[1.5442 ;0]; r=lyapchol(a,b); ////Generalized Lyapunov Equation a =[-1.6602 1.0973; 1.0973 -2.1947 ]; b=[1.5442 ;0]; e=[0.8308 0.5497 ;0.5853 0.9172 ]; r1=lyapchol(a,b,e);
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function [x, y] = pgm13(a, b, n, initialCondition) h = (b-a)/n; y = []; x = []; x(1) = a; y(1) = initialCondition; for i=1:n x(i+1) = x(i) + h; y(i+1) = y(i) + h * pgm14(x(i), y(i)); end endfunction