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3_14_soln.sce
clc; pathname=get_absolute_file_path('3_14_soln.sce') filename=pathname+filesep()+'3_14_data.sci' exec(filename) // Solution: // Pump flow in m^3/s, Q_si=0.0000167*Q; //m^3/s // Diameter of pipe, D_m=D/1000; //m // Area of pipe, A=(%pi*(D_m^2))/4; //m^2 // velocity, v=Q_si/A; //m/s // rounding off the above answer v=f...
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//ques 61 clc disp('to find the assymptote of given curve '); syms x y f=x^2*y^2-x^2*y-x*y^2+x+y+1; //a=degrees(f,x); f1=coeffs(f,x,2); disp('assymptotes parallel to x-xis is given by f1=0 where f1 is :'); disp(factor(f1)); f2=coeffs(f,y,2); disp('assymptotes parallel to y-axis is given by f2=0 and f2 is :');...
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//Example 21.2 //Lagrange Interpolation in Parallel Computing //Page no. 723 clc;close;clear; xi=[-1,0,2,5]; yi=[9,5,3,15]; s=["x=1","n=4","Data:","(-1,9)","(0,5)","(2,3)","(5,15)"] for i=1:4 printf('\tProcessor\t') end printf('\n') for i=1:4 printf('\t N%i\t\t',i) end printf('\n') for i=1:7 ...
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// Problem no 9.10,Page no.240 clc;clear; close; L=3 //m //Length of strut b=0.04 //m //Width of rectangle d=0.10 //m //Depth if rectangle P=100*10**3 //N //Axial thrust w=10*10**3 //N //Uniformly Distributed Load E=210*10**9 //Pa //Calculations A=b*d //m**2 //Area of strut I=b*d**3*12**-1 //m**4 //M.I m=(P*(E*I)...
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// Exa 6.18 format('v',6) clc; clear; close; // Given data I_CBO = 3;//in µA I_CBO= I_CBO*10^-3;// in mA I_C= 15;// in mA // But it is given that I_C= 99.5% of I_E, SO I_E= I_C/99.5*100;// in mA alpha_dc= I_C/I_E; disp(alpha_dc,"The value of alpha_dc is : ") disp(I_E,"The value of I_E in mA is : ")
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function [autovetores, autovalores, inversa]=MethodLeverrierFaddeev(A) [l,c] = size(A) I = eye(l,c) B_i = eye(l,c) C = 0 //armazena valores das matrizes Bk autovetores = 0 //armazena autovetores associados coef = 0 //armazena valores dos coeficientes p coef(1,c+1) = 1 ...
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Example11_3.sce
// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 4: OVERHEAD LINE INSULATORS // EXAMPLE : 4.3 : // Page number 184 clear ; clc ; close ; // Clear the work space and cons...
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8_3.sce
clc //initialisation of variables d=750000//gpd per sq mile v=0.22//ft a=1.27//ft q=0.30//ft d1=365//days p=0.25//ft //CALCULATIONS Q=q*a*d1//mg/sq mile H=p*a*d1//mg/sq mile //RESULTS printf('the results obtained by normal analytical procedures and by Hazen s=% f mg/sq mile',H)
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//To calculate the values of Enthalpy and Entropy of Reaction //Example 9.4 clc; clear; T=[872,973,1073,1173];//Temperatures in Kelvin Kp=[1.8*10^-4,1.8*10^-3,1.08*10^-2,0.0480];//Equilibrium Constant for i=1:4 x(i)=1/T(i);//Defining x-axis of the graph as x=1/T end for i=1:4 y(i)=log(K...
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clc //initialization of new variables clear P=2000 //kg a=4 //cm b=1 //cm d=7 //cm r=3 //cm // calculations A=(a+b)/2*d xbar=(a+b*2)*d/(r*(a+b)) rbar=r+xbar I=b*d^3/12+r*d^3/12 Ixx=I-A*2.8^2 e=Ixx/(rbar*A) f1=P*5.8*(xbar-0.62)/(A*0.62*r) f2=P*5.8*(-d+2.18)/(A*0.62*(5.18+d-2.18)) str=P/A Str_i=f1+str ...
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//************************* Peak Detector ****************************** if (blk_name.entries(bl) =='peakdet_block') then mputl("# PEAK DETECTOR",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) cap_str= ".subckt peak_detector in[0]=net"+string(blk(blk_objs(bl),2))+'_'+ string(ss)+" in[1]=net" + string(blk(...
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clear; clc; disp('Example 5.16'); // aim : To determine the // (a) initial partial pressure of the steam and air // (b) final partial pressure of the steam and air // (c) total pressure in the container after heating // Given values T1 = 273+39;// initial temperature,[K] P1 = 100;// pressure, [MN/m...
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Chapter2_Example1.sce
//Chapter-2, Illustration 1, Page 55 //Title: Gas Power Cycles //============================================================================= clc clear //INPUT DATA P1=0.1;//Pressure of air supplied in MPa T1=308;//Temperature of air supplied in K rv=8;//Compression ratio q1=2100;//Heat supplied in kJ/kg C...
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Ex18_32.sce
// scilab Code Exa 18.32 IFR turbine stage efficiency // part(b) R=0.48; sigma_s=0.6; n_n=0.92; alpha_2=15; // air angle at nozzle exit(from tangential direction) n_st=2*sigma_s*sqrt(n_n*(1-R))*cosd(alpha_2); disp("%",n_st*100,"stage efficiency of the radial turbine is")
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clc; pathname=get_absolute_file_path('5_1_soln.sce') filename=pathname+filesep()+'5_1_data.sci' exec(filename) // Solutions: // Volumetric Displacementis is given by, Vd=(%pi/4)*((Do^2)-(Di^2))*L; //in^3 // Theoretical Flow rate, Qt=(Vd*N)/231; //gpm // Volumetric efficiency, eta_v=(Qa/Qt)*100; //% // Results: printf...
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A=[0 1; -2 -3] U=[1/s] B=[0; 1] phi=inv(s*eye(2,2)-A) X=[1;1] a1=ilaplace(phi(1,1),s,t) a2=ilaplace(phi(1,2),s,t) a3=ilaplace(phi(2,1),s,t) a4=ilaplace(phi(2,2),s,t) S=[a1 a2;a3 a4] disp(S,"%e^(A*t) = ") ZIR=S*X disp(ZIR," ZIR = ") k=phi*B*U b1=ilaplace(k(1,1),s,t) b3=ilaplace(k(2,1),s,t) ZSR=[b1;...
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//example 16.9 //decide whether it is economically feasible to provide canal lining clc;funcprot(0); //given li=2.5; //seepage loss for lined channel p1=25; //wetted perimeter for lined channel t=12; //thickness of concrete lining lf=0.02; //seepage l...
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clear clc n=99 b=3.2 a=1.8 soma=0 function y=f(x) y=200 ./(x+8) endfunction h=(b-a)/n x = a:h:b y = f(x) for i=1:n soma=soma+y(i)+y(i+1) end result=(h/2)*soma
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// Exa 8.4 clc; clear; close; // Given data l=2.5;// in cm l=l*10^-2;// in meter d=1;// in cm d=d*10^-2;// in meter Va= 1000;// in volts theta= 1;// in degree // Formula tand(theta) = l*Vd/(2*d*Va) Vd= 2*d*Va/l*tand(theta);// in volts disp(Vd,"Voltage required across the deflection plates in volts")
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//Variable declaration N=1/60 e=1.6*10**-19 ni=2.5*10**13 b=5*10**13 E=2 //Calculations n=(b+sqrt(2*b**2))/2 mu_p=N/(3*e*ni) mu_i=2*mu_p np=ni**2 p=(ni**2)/n e=1.6*10**-19 E=2 J=(e*E)*((n*mu_i)+(p*mu_p)) //Result printf('mu_p= %0.3f cm**2/V-s \n',(mu_p)) printf('n= %0.3f *10**13/cm**3 \...
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//EXAMPLE 8-13 PG NO-530 Fc=2000; L=0.05; C=1/(16*%pi*%pi*Fc*Fc*L) disp('i) CAPACITOR (C) is = '+string (C) +' F ')
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//Example 8.10;linear synchronous velocity clc; clear; close; f=50;//hz t=0.5;//in meter s=0.25;// vs=2*f*t*(3600/1000);//kmph vc=vs*(1-s);//kmph disp(vs,"linear synchronous velocity in kmph is") disp(vc,"vehicle speed in kmph is")
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// function result = move_sci(b,nonred,max_sci) // Moves matrix b to matrix result with the information on where to move, // decided by the indices of nonred. // The matrix result will have as many rows as b has and max number of columns. // b is augumented with zeros to have nonred number of columns; // The...
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function [mydiffuse]=mydiffuse(jobname,nsteps, nsubsteps, dt, in, concs, sources, sinks) //diffusion system initial values d=in(1); n1=in(2); n2=in(3); n3=in(4); h=in(5); t0=0; t=t0; ddt=dt/nsubsteps printf('sub steps: %d \n', nsubsteps); //smat=zeros(4,nsteps) for ii=1:nsteps printf('...
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clc clear //Initialization of variables Do=2.375 //in hi=1200 Di=2.067 //in km=29.2 h0=1500 L=2.375 //in t1=220 //F t4=140 //F //calculations Re=Do/(Di*hi) R0=Do/(Di*hi) + (Do/12 *log(Do/Di) /(2*km)) + 1/h0 td=Re/R0 *(t1-t4) ti=t4+td Req=1/h0 td2=Req/R0 *(t1-t4) to=t1-td2 //results printf("The tempe...
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* *Testcase IEEE CONVERT FROM/TO FIXED 64 (6), SUBTRACT (5), 11 instr total * SUBTRACT tests - Binary Floating Point * # # Tests five subtraction instructions: # SUBTRACT (extended BFP, RRE) # SUBTRACT (long BFP, RRE) # SUBTRACT (long BFP, RXE) # SUBTRACT (short BFP, RRE) # SUBTRACT (short BFP, RXE) # # ...
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//function fx = fun1(x) // fx = x^3 + 2*x^2 +10*x - 20 //endfunction function fun2(xi) p = poly([-20,10,2,1],"x","coeff"); f = derivat(p); //disp("f(x)= "+p); disp("f(x)/dx ="+f); fxi = horner(f,xi) disp(fxi) endfunction
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.18 //Data given in the Problem b=5 d=1.2 A=b*d dens=1000 g=9.81 //Calculations h=5-0.6*sin(45/180*%pi) F=dens*g*A*h IG=b*d^3/12 H=IG/(A*h)+h //depth of centre of p...
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//Exa 1.9 clc; clear; close; format('v',7); //Given Data : Pmercury=10;//cm of Hg Patm=760;//mm of Hg Patm=1.01325;//bar Pabs=1.2;//bar sg_oil=0.8; sg_water=13.6; sg_mercury=13.6; rho_w=1000;//Kg.m^3 g=9.81;//gravity constant deltaP=Pabs-Patm;//bar deltaP=deltaP*10^5;//N/m^2 //deltaP=rho_o*g*h_o rho...
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//scilab 5.4.1 //windows 7 operating system //chapter 8:Junction Transistors:Biasing and Amplification clc; clear; //given data Rg=1*10^3; //internal resistance in ohms Rl=20*10^3; //Load resistance in ohms hie=1*10^3; //h parameter of the transistor in terms of ohms hre=2.5*10^-4; //h param...
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//clear// //Caption: Program to find Electric Flux density 'D' of a uniform line charge //Example3.1 //page 54 clc; e0 = 8.854e-12; //free space permittivity in F/m rL = 8e-09; //line charge density c/m r = 3; // distance in metre E = Electric_Field_Line_Charge(rL,e0,r); //electric field intensity of line charg...
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function y=f(x) y = (x^2+5*x+1) endfunction x=linspace(-1,8) plot(x, f)
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EX1_36.sce
//EXAMPLE 1-36 PG NO-31 T=0.99425; //TIME disp('i)Time = '+string (T)+' seconds') X=0.37; //DERAVATIVES OF 'I' W.R.T disp('ii)(di\dt) = '+string (X)+' A\sec') LI=0.63; //CURRENT dli=0.37; // deravatives of 'SI' w.r.t disp('iii)(dsi\dt) = '+string (dli)+' Wb-turns\sec') ...
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//************************** VDD Out (Macro block) ***************************** if(blk_name.entries(bl)=='vdd_out') then for ss=1:scs_m.objs(bl).model.ipar(1) mputl("# vdd_out "+string(bl)+" "+string(scs_m.objs(bl).model.ipar(2))+" "+string(ss),fd_w); mputl(".subckt vdd_out in[0]=fb_vddout_net"+st...
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//Initilization of variables M=70 //kg ko=0.4 //m ri=0.45 //m ro=0.6 //m theta=30 //degrees m=35 //kg g= 9.8 //m/s^2 //Calculations I=M*ko^2 //kg-m^2 //Using Equations of motion //Solving the equations by matrix method A=[-1,-m*0.15,0;1,-M*ro,-1;-ri,-I,ro] B=[-m*g;M*g*sind(theta);0] C=inv(A)*B F=C(3) //N...
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Ex2_6.sce
clear // // // //Variable declaration n=4000 //number of lines/cm lamda=5000*10**-8 //wavelength(cm) k=3 //order //Calculation e=1/n sintheta=k*lamda/e costheta=sqrt(1-sintheta**2) dthetabydlamda=k*n/costheta //dispersive power of grating //Result printf...
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Example6_23.sce
clear; clc; // Example: 6.23 // Page: 239 printf("Example: 6.23 - Page: 239\n\n"); // Solution // *****Data******// T = 298;// [K] P = 10*10^5;// [Pa] Tc = 126.2;// [K] Pc = 34*10^5;// [bar] R = 8.314;// [J/mol K] //****************// a = 27*R^2*Tc^2/(64*Pc);// [Pa.m^6/square mol] b = R*Tc/(8*Pc...
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Ex9_2.sce
clear // // //Initilization of Variables L=2000 //mm //Length of square column E=12*10**3 //N/mm**2 //Modulus of Elasticity sigma=12 //N/mm*2 //stress W1=95*10**3 //N //Load1 W2=200*10**3 //N //Load2 FOS=3 //Calculations //From Euler's Formula //P=%pi**2*E*I*(L**2)**-1 .........(1) //Working Load //W=P*(FOS)**-1 ...
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example11_3.sce
//example 11.3 //page 422 clc; funcprot(0); //initialisation of variable P1=10; P2=30; T1=110+460; k=1.4;//const W=10; Cv=0.157;//heat const T2=T1*(P2/P1)^((k-1)/k); H=W*Cv*(T2-T1); disp(H,"Change in Enthalpy(Btu)="); clear
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Ex5_27.sce
//================================================================================= // chapter 5 example 27 clc; clear; //input data Hc1 = 1.41*10^5; //critical fields in amp/m Hc2 = 4.205*10^5; // critical fields in amp/m T1 = 14.1; //temperature in K T2 ...
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TP4.sce
/* Créateur: Jinshan GUO et Anais Debureaux */ exec(fullpath(pwd() + '\TP4.sci'),-1); disp("===========Exo1-Factorisation de Cholesky==========="); A1 = [15 10 18 12;10 15 7 13;18 7 27 7;12 13 7 22]; [C]=cholesky(A1); //Exo1_a disp("Resulat_Exo1(a)_C=",C); disp("Si A1 == A1'':", A1 == A1'); disp("Car A1...
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Ex15_8.sce
// Exa 15.8 clc; clear all; // Given data // Active notch filter Fn=50; //Notch out frequency(Hz) // Solution disp(" Let C=0.047 micro farads"); C=0.047; // micro farads R=1/(2*%pi*Fn*C*10^-6); printf(' The value of R is calculated as %d k Ohms \n',round(R/1000)); disp("For R/2, two 68 k Ohms r...
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Ex3_2.sce
//Example 3.2 //Yielding Criteria for Ductile Metals //Page No. 78 clc;clear;close; sigma00=500; //in MPa sigma_z=-50; //in MPa sigma_y=100; //in MPa sigma_x=200; //in MPa T_xy=30; //in MPa T_yz=0; //in MPa T_xz=0; //in MPa sigma0=sqrt((...
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EX11_1.sce
clc;funcprot(0);//EXAMPLE 11.1 // Initialisation of Variables d=0.1;..................//Cylinder bore in m l=0.12;................//Cylinder stroke in m N=1800;..................//Engine rpm d2=0.028;................//Throat diameter in m Cda=0.8;................//Co efficient of air flow etaV=0.75;................
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11_5.sce
clc //initialisation of variables q=10//ft a=4*%pi//ft p1=q+2//ft p2=62.5*a*p1//lbf s=%pi/64*(4)^2+a*(p1)^2//ft^4 //CALCULATIONS m=a*p1//ft^3 P=s/m//ft F=p2*(P-q)/4//lbf H=p2-F//lbf //RESULTS printf('the total hinge reaction=% f lbf',H)
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example_9.sce
clc clear printf("example 7.9 page number 312\n\n") printf("this is a theoretical question, book shall be referred for solution")
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Ex5_5.sce
//Example 5.5// x=1*10^-3;//m// Using the diffusivity from sample problem 5.3 D=2.98*10^-11;//m^2/s //arrhenius equations a=0.95;//from the figure 5.11 d=(x^2)/((a^2)*(D))// calculating the value of d mprintf("d = %e h",d) b=1;//h //hour c=3.6*10^3;//s //second t=d*(b/c) mprintf("\nt = %f h",t)
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Ex3_26.sce
//Caption:Find the voltage regulation //Exa:3.26 clc; clear; close; KVA=100; Eff_max=0.98; x=0.8; pf=0.8; P_o=x*KVA*1000*pf;//in watts P_i=(P_o-P_o*Eff_max)/(2*Eff_max);//in watts P_cu=P_i/x^2; R_equ=P_cu/(KVA*1000); Z_equ=0.05; X_equ=sqrt(Z_equ^2-R_equ^2); VR=R_equ*pf+X_equ*sqrt(1-pf^2); disp(VR*100,'V...
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clear //Given u=-240.0 R=15.0 //cm u1=1.33 u2=1.5 //Calculation v=1/((((u2-u1)/R)+(u1/u))/u2) //Result printf("\n Position of the image is %0.0f cm",v)
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7_2.sce
clc //initialisation of variables t1=26 //temp in degrees t2=32 //temp in degrees pvs=0.033597 //pressure in bar ps=0.047534 //pressure in bar p=1.013 //pressure in bar a=6.6*10^-4 //CALCULATIONS pv=pvs-(p*a*(t2-t1)) w=(0.622*pv)/(p-pv) phi=pv/ps //RESULTS printf('specific humidity is %2fkg/kg of da',w) p...
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Ex5_4.sce
// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 5 : DIRECT CURRENT MOTORS // Example : 5.4 clc;clear; // clears the console and command history // Given data I = 40; // current in A V_t = 230; // supply in V N = 1100; // speed in...
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8_3.sce
clc //initialisation of variables d= 3 //in P= 2000 //psi s= 20 //strokes //CALCULATIONS Cl= s*d/2 F= P*%pi*d^2/4 stl= (Cl-40)/10 //RESULTS printf ('length of the stop tube= %.f in',Cl) printf (' \n thrust on the rod= %.f lb',F+3) printf (' \n Stop Tube length= %.f stl',stl)
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Ex3_10.sce
//tension in the cable and reaction at a point //refer fig. 3.21 (a),(b)&(c) //Taking moment about A we get T=((25*12*cosd(30))+(10*6*cosd(30)))/(12*sind(15)) //kN //applying equilibrium conditions HA=T*cosd(15) //kN VA=10+25+T*sind(15) //kN RA=sqrt(HA^2+VA^2) //kN alpha=atand(VA/HA) //degree printf("tens...
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Ex9_7.sce
// Given:- // Part(a) etareg = 0.8 // regenerator effectiveness of 80%. // From example 9.4 h1 = 300.19 // in kj/kg h2 = 579.9 ...
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ex_4_30.sce
//Example 4.30//illumination on surface clc; clear; close; format('v',6) ef=17.4;//in mumens/watt dp=1.2;//depreciation factor wlf=1.3;//waste light factor uf=0.4;//utiliazation factor l=50;// in meters b=16;// in meters n=16;// no. of lamps lw=1000;// mscp in watts a=l*b;//arean in m^2 tl=n*lw*ef;///total lumens lwp=(...
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Ex9_3.sce
//Example 9.3 g=9.80;//Acceleration due to gravity (m/s^2) F_o=45*g;//Combined weight of wheelbarrow and load, m*g, (N) l_o=7.50*10^-2;//Output lever arm (m) l_i=1.02;//Input lever arm (m) F_i=F_o*l_o/l_i;//Force to be exerted (N) printf('a.Upward force to be exerted = %0.1f N',F_i) N=F_o-F_i;//Normal force (N) ...
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example11_24.sce
clc // Given that v = 1.8e8 // velocity of space ship away from the earth in m/sec v1 = 2.1e8 // velocity of rocket w.r.t. space ship away from the earth in first case in m/sec v2 = -2.1e8 // velocity of rocket w.r.t. space ship away from the earth in second case in m/sec // Sample Problem 24 on page no. 11.27 printf(...
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function [] = kiks_gui_getlimitlistbox() // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- gl...
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clear //Given d=2*10**-3 //m l=5000*10**-10 //Calculation Z=d**2/l //Result printf("\n Fresnel Distance is %0.3f m",Z)
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function [x,y]=polar_to_cart(r,theta) theta=theta/180*%pi x=r*cos(theta) y=r*sin(theta) endfunction [Ir,Ic]=polar_to_cart(3,30) I=complex(Ir,Ic) Zc=-5*%i Zrl=10+5*%i Ic=Zrl/(Zc+Zrl)*I Vth=Ic*Zc Zth=(Zc*Zrl)/(Zc+Zrl); In=Vth/Zth disp(Zth,In,Vth)
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//Ex4_3 clc ID=10*10^(-3) disp("ID = "+string(ID)+" ampere") // given drain current VDD=(24) disp("VDD= "+string(VDD)+" volts") // Drain voltage VT=(5) disp("VT= "+string(VT)+" volts") // Threshold voltage VGS=(10) disp("VGS= "+string(VGS)+" volts") // gate to source voltage1 KF=ID/(VGS-VT)^2 disp("KF =...
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//decimal to binary conversion// //example 9.c// clc //clears the command window// clear //clears// //decimal to binary conversion// a=dec2bin(624) disp('binary equivalent of decimal number:') disp(a) //answer in binary form//
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//Given that Bdot = 1.4/10^-3 //in T/m w = 3.5*10^-2 //in m v = 750 //in m/s M = 1.8*10^-25 //in kg u = 9.27*10^-24 //in J/T //Sample Problem 41-1 printf("**Sample Problem 41-1**\n") Fz = u*Bdot a = Fz/M t = w/v d = 0.5*a*t^2 printf("The atoms have been deflected %e m", d)
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## Testing merge and unmerge commands set echo read <sample1.fi :31 inspect :31 unmerge :31 inspect :29 inspect :25,:29 merge :29 inspect
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// Scilab code Ex10.13: Pg.468 (2008) clc; clear; e = 1.602e-19; // Electronic charge, C h = 6.616e-34; // Planck's constant, J-s V = 1e-06; // Applied voltage, V f = 2*e*V/h; // Frequency of Josephson current, Hz printf("\nThe frequency of Josephson current = %5.3e Hz or %5.1f MHz", f, f*1e-6); //...
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//Wired Digital Communications : example 9-2 : (pg 407) m=10^7; Pe=10^-6;//error probability a=m*Pe;//average number of errors printf("\naverage number of errors = m*error probability(Pe) \n= %.f",a); mprintf("\n%.f expected bit errors if %.f million bits are recieved",a,a);
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clear ; clc; // Example 24.3 printf('Example 24.3\n\n'); //page no. 728 // Solution Fig. E24.3 // Given m_CO2 = 10 ;// mass of CO2 - [lb] Ti_CO2 = 80 ;// Initial temperature of CO2 - [degree F] Vi = 4.0 ;// Initial volume of CO2-[cubic feet] f_CO2 = 40/100 ;// Fraction of CO2 that convert to liquid finally s_Vi ...
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clc clear //Initialization of variables P=2050 //kPa T=700 //K E=10 //J //calculations Pe=P*10^3 *0.3048^2 /4.4482 /144 Te=T*1.8-460 Ee=E*10^8 /(1055.1) //results printf("Temperature = %d F",Te) printf("\n Pressure = %d lbf/in^2 ",Pe) printf("\n Energy = %.3e Btu",Ee) // tets
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 7.6 //calculation of the speed of vehicle on the turn //given data r=10//radius(in m) of the turn theta=10//angle(in degree) of the bank g=9.8//gravitational acceleration(in m/s^2) of the earth //calculation v=sq...
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// To establish Operating Point & Stability Factor // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 5-4 in page 238 clear; clc; close; // Given Data beta_bjt=50; // Beta Gain of the BJT circuit Vbe=0.7; // Base-Emitter voltage of BJT in V Vcc=2...
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//fonction : 'ResolutionGauss' //paremetre : A une matrcie ,b,un vecteur de reel //retour ; x un vecteur de reel function [x]=ResolutionGauss(A,b) [At,bt]=trigGauss(A,b); x=solsup(At,bt); endfunction
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clear; clc; printf("\t\t\tExample Number 4.5\n\n\n"); // sudden exposure of semi-infinite solid slab to convection // illustration4.5 // solution alpha = 8.4*10^(-5);// [square meter/s] constant Ts = 200;// [degree celsius] initial temperature of of slab Te = 70;// [degree celsius] environment temperature k...
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clc; clear; Nd=2.01*10^7 //Doping level of n-type silicon in cm^-3 Nc=2.8*10^19 //in cm^-3 e=1.6*10^-19 //in J epsilon_r=11.7 //in F/cm epsilon_0=8.85*10^-14 //in F/cm slope=6*10^13 Vbi=0.45 //in V Const=0.026 //constant for kT/e in V //Calculation Nd=2/(e*epsilon_r*epsilon_0*slope) //in cm^-3 phi_n=Cons...
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welcome to my machine projects M1 - Adding Two Numbers M2 - Getting the Area of a Circle using Radius and Diameter M3 - Odd and Even Number Identifier
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//Page Number: 8.12 //Example 8.11 clc; //We use, F=(F1+(F2-1)/G1) //Given FA=1.5; GA=10, //dB GAA=(10^(GA/10)); FB=3; //dB FBB=(10^(FB/10)); GB=15, //dB GBB=(10^(GB/10)); //Case 1: Amp A followed by Amp B F11=FA; F12=FBB; G11=GAA; F1=(F11+(F12-1)/G11); disp(F1,'Gain when Amp A followed by...
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//pathname=get_absolute_file_path('13.12.sce') //filename=pathname+filesep()+'13.12-data.sci' //exec(filename) //Initial pressure(in bar): p1=14 //Initial temperature(in K): T1=400+273 //Number of nozzles: N=16 //Final pressure(in bar): p2=10 //Discharge(in kg/s): m=5 //Nozzle efficiency: nn=0.90 //Inlet...
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//Example 5.5, Page Number 209 //Threshold Current Density clc; //For GaAs Junction l=0.84*(10**-6) //Wavelength in meter w=1.45*(10**13) //Linewidth in Hertz y=3.5*(10**3) //Loss Coefficient per meter n=3.6 //Refractive Index for GaAs q=1 //Quantam Efficiency le=300*(10**-6)//Length in meter d=2*(10**-6) //i...
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#************************************************************ # Scenario of Test # # date : Thu Nov 13 19:08:05 2008 #************************************************************ p3d_sel_desc_name P3D_ENV Test p3d_sel_desc_name P3D_ROBOT superman p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000...
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//Function migration (image list to matrix) for: medianblur //Generated by migrate.cpp //Author: Anirudh Katoch function res = medianblur(varargin) select length(varargin) case 02 then res = il2mat(raw_medianblur(mat2il(varargin(01)), varargin(02))) else error(39) end endfunction
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Name=Fireworks Flick Small PlayerCharacters=player_char BotCharacters=fireworks_target.bot IsChallenge=true Timelimit=60.0 PlayerProfile=player_char AddedBots=fireworks_target.bot;fireworks_target.bot;fireworks_target.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=fireworks_flick.map MapScal...
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-- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protec...
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function y=f(x) //y=x^2-7 //y=x^4-2*x^2-12*x+16*x-40 //y=cos(x)-x //y=(x.*cos(x))./(log(x)) //y=2*x-%e^(-x) //y=%e^(-2*x)+x-1 y=x^3-7*x^2+14*x-6 //y=x^2-1 endfunction //Grafico f(x) x=-10:0.1:10; plot2d(x, f(x)); //muestra grilla xgrid(3,1,7); //Pedir datos al usuario //clc() //a=input...
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//example 5.27 clear; clc; //Given: P1=101.3;//Initial Pressure[KPa] P2=60;//Final Pressure[KPa] He=31.8;//Enthalpy of vaporization[KJ/mol] R=8.314;//Universal gas constant[J/K/mol] T1=353.2;//boiling point of benzene at 101.3KPa[K] //To find the boiling point of b/enzene at 60KPa x=(T1^-1)-(R*0.001*log...
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clc;clear; //Example 5.4 //Mass spectrograph, calculation of linear separation of lines formed on photographic plates //given values E=8*10^4;//electric field in V/m B=.55//magnetic induction in Wb/m*2 q=1.6*10^-19;//charge of ions m1=20*1.67*10^-27;//atomic mass of an isotope of neon m2=22*1.67*10^-27;/...
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clc; clear; printf("\t\t\tChapter8_example7\n\n\n"); // Determinion of the convection coefficient about the ice cube // properties of air at (0 + 70)/2 = 35°F == 495 degree R from appendix table D1 rou= 0.0809; // density in lbm/cu.ft cp=0.240; // specific heat BTU/(lbm-degree Rankine) v= 13.54e-5; // viscosity in s...
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//n=10 //a=0 //b=1 //h=(b-a)/n //x=a:h:b //y=x**2 //k = (1:1:n-1) //l = (0:1:n-1) //yk = (a+(k*(b-a)/n))**2 //yl = (a+((2*l+1)*(b-a)/2*n))**2 //res=((b-a)/6*n)*(a**2+b**2+2*sum(yk)+4*sum(yl)) //Correction : n=10 a=0 b=1 h=(b-a)/n x1 = a+h:h:b-h // (b-a)/n = h, on remplace donc et on a f(a+kh) y1=x1**2 S1 = sum(y1) x2...
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clear; clc; Vs=1.02; Vr=0.9; Z=.1; anglez=80; Cs=(Vs^2)/Z*exp(complex(0,80)); Cr=-(Vr^2)/Z*exp(complex(0,80)); radius=Vs*Vr/Z; Pms=((Vs^2)/Z*cosd(anglez))+(Vs*Vr/Z); dels=180-anglez; Pmr=-(((Vr^2)/Z*cosd(anglez))-(Vs*Vr/Z)); Ps=((Vs^2)/Z*cosd(anglez))-(Vs*Vr/Z*cosd(anglez+15)); Pr=-(((Vr^2)/Z*cosd(anglez))...
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function y=fea(x) y=x^2/4 - sin(x); endfunction function [p1,err,k,y]=secante2(f,p0,p1,delta,max1) //Datos: // f función // p0 y p1 son aproximaciones iniciales a un cero de f // delta : tolerancia , como son números pequeños uso el mismo para todo. // max1 es el número máximo de ...
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clc; funcprot(0); //Example 25.7 //Initializing the variables Vo = 25.3; //Outlet velocity D = 10 ; // Mean hydraulic diameter f = 0.008; // friction factor X = 1000; // Length of road P = 12600; // Absorbing power Va = 300; // Tunnel air flow ...
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function [x,y,typ]=TANBLK_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) [graphics,model]=arg1(2:3); [orig,sz,orient,label]=graphics(1:4) // dly=model(8) xstringb(orig(1),orig(2),['tan'],sz(1),sz(2),'fill') case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutpu...
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V1=1 V2=1 I1=0.0225/0.325*V1 VN=I1/(0.2+0.025) I2=-0.2*VN Y11=I1/V1 Y21=I2/V1 I2=0.025/0.325*V2 VM=I2/(0.1+0.025) I1=-0.1*VM Y12=I1/V2 Y22=I2/V2 A=[Y11,Y12;Y21,Y22] printf("\nA=") disp(A)
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clc //Variable declaration h=2 k=2 l=0 a=450 //Calculations d=a/(sqrt(h**2+k**2+l**2)) //Result printf('d(220) =%0.3fpm\n',(d))
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// Exa 1.24 clc; clear; close; // Given data V_S = 2;// in V R = 100;// in ohm I_D = V_S/R; I_D = I_D * 10^3;// in mA disp("Part (a)") disp(I_D,"The diode current in mA is"); V_K = 0.7;// in V I_D1 = (V_S-V_K)/R; I_D1 = I_D1*10^3;// in mA disp("Part (b)") disp(I_D1,"The diode current in mA is"); R_f = 3...
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clc clear //Input data A=450;//Area of indicator diagram in mm^2 l=60;//Length of indicator diagram in mm s=1.1;//Spring number in bar/mm d=0.1;//Diameter of piston in m L=0.13;//Length of stroke in m N=400;//Operating speed of the engine in rpm //Calculations Av=A/l;//Average height of indicator diagram in...
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//find clc //solution //given d=6//mm Do=75//mm t=350//N/mm^2 G=84*1000//N/mm^2 D=Do-d//mm C=D/d //let W be axial load //neglecting curvature Ks=1+(1/(2*C)) //t=Ks*[8*W*D/(%pi*d^3)]//N/mm^2 W=(t*%pi*d^3)/(8*Ks*D) printf("load acting is,%f N\n",W) dpt=8*W*D^3/(G*d^4)//deflection per turn//mm printf("def...
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//********** 3.0a ********** dac_loc(2,1).entries(1)= '0 8 3 #int[3]'; dac_loc(2,1).entries(2)= '0'; //DAC0 dac_loc(2,2).entries(1)= '0 8 4 #int[4]'; dac_loc(2,2).entries(2)= '1'; //DAC1 dac_loc(2,3).entries(1)= '0 8 5 #int[5]'; dac_loc(2,3).entries(2)= '2'; //DAC2 dac_loc(2,4).entries(1)= '0 9 0 #int[0]'; dac_loc(2,4)...