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clc;clear; //Example 10.3 //given data P1=10; P2=3000; P3=3000; T3=350; P4=10; //from steam tables //at state 1 h1=191.81; v1=0.00101; //at state 2 //s2=s1 //at state 3 h3=3116.1; s3=6.7450; //at state 4 s4=s3; sf=0.6492; sfg=7.4996; hf=191.81; hfg=2392.1; //calculations //part - a win=v1...
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i d like to talk today about the two biggest social trends in the coming century and perhaps in the next 10 000 years but i want to start with my work on romantic love because that s my most recent work what i and my colleagues did was put 32 people who were madly in love into a functional mri brain scanner 17 who were...
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clear; clc; printf("\nEx2.30\n"); //page no.-72 //given del_x=1.1*10^-8;...............//uncertainty in position of electron in m h=1.05*10^-34;................//planck's constant in joule-sec m=9*10^-31;....................//mass of e in kg //By Heisenberg's uncertainty principle, del_v=h/(m*del_x)............
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clc; close(); //page no 235 //prob no. 7.8 delta_f=400; //Hz fm=2000; //Hz B=delta_f/fm; // disp(B,'The modulation index is'); disp('(For B<=2.5 , the signal is NBFM)'); Bt=2*fm; mprintf('The transmission bandwidth Bt= %i Hz ',Bt)
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active_buttons = 5; button_codes = 1,2,3,4,5; begin; picture { box { width = 200; height = 5; color = 255,255,255; }scale; x = 0; y = 0; box { width = 5; height = 20; color = 255,255,255; }choice; x = 0; y = 0; }scale_pic; begin_pcl; int x = 0; loop int responses = response_manager.total_response_...
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//Chapter 11 //Example 11_20 //Page 292 clear;clc; k=5; r=30/2; r1=r+40; er=110*1e-6; s1=k/2/%pi*log(r1/r); s2=0.45; s=s1+s2; n=1; t=55; i=sqrt(t/n/er/s); printf("Thermal resistance of the dielectric of the cable = %.2f thermal ohms per metre length \n\n", s1); printf("Total thermal resistance = %.2f thermal ohms p...
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function rep=x_message(comment,btns) // Copyright INRIA // message - dialogue affichant un message //%Syntaxe // message(comment) //%Parametres //comment : vecteur de chaine contenant le texte du message //%Remarques //Dans l'environnement Xwindow cette macro provoque l'ouverture d'une //fenetre de message. L'utilis...
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//reflected voltage //given clc Vi=50//volts row=0.25//reflection coefficent Vr=Vi*row//the reflected voltage disp(Vr,'the reflected voltage for given reflection coefficent in volts')
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//EXA.3.3.1 clc; clear; close; H=2000 //magnetic field intensity(in A/m) N=500 //no. of turns l=.08*%pi //length of ring (in m) I=H*l/N disp(I,'required current(in A)=')
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//Example 6.5// Power clc; clear; close; //given data : format('v',6) fp=0.024;// flux per pole lf=1.2;// leakage factor fi=fp/lf;// in Wb Z=756;//turns P=4;// number of pole N=1000;// in rpm A=4;//constant E=(fi*Z*N*P)/(60*A);//generated voltage il=1/10;//load current in amperes ish=1/100;//shunt current in amperes ...
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clc //given that l = 1 // width of potential well in angstrom n = 1 // order corresponding to ground state h = 6.63e-34 // Plank constant m = 9.1e-31 // mass of electron in Kg printf("Example 2.21") E = n^2*h^2/(8*m*(l*1e-10)^2) // Calculation of energy in Joule E_eV = E/1.6e-19 // Calculation of energy ...
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s = poly(0,'s'); G = 1/(s^2+3*s+2); // part a scf(0); os = .1; k = 4.397; G1 = k*G/(1+k*G); poles = roots(G1('den')); t_s = mean(-4./(real)); // original closed loop ts t_s = t_s/2; x = -4/t_s; m = 1/(-1*log(os)/(%pi)); x = -8:.01:0; os_line_1 = m.*x; os_line_2 = -1*m.*x; plot(x,os...
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//Example 3.5 // insertion loss clc; clear; close; //given data : n1BYn2=1.48; NA1=0.2; n2theta=(5*%pi)/180; NA2=0.4; eta1=((16*(n1BYn2)^2)/(1+n1BYn2)^4)*(1-((n2theta/(%pi*NA1)))); L_ang1=-10*log10(eta1); eta2=((16*(n1BYn2)^2)/(1+n1BYn2)^4)*(1-((n2theta/(%pi*NA2)))); L_ang2=-10*log10(eta2) disp(L_ang1,"the insertion lo...
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//Use of the disp function. clc disp (10,20,30); disp ([12],3); disp("a",1,"c"); a=ones (2,2); b=rand(3,3,"normal") disp (a, b); deff('[x]=myplus (y, z)','x=y + z')//deff defines inline functions. For detail, see scripts and functions. disp (myplus (10,20)) disp(myplus) // Displays the header of the function...
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//PlotRobotFrame.sci sketch a robot frame structure in 3-D // www.controlsystemslab.com July 2012 function [T]=plotrobotframe(robot,q,varargin) if argn(2)==0 then PlotRobotFrameHelp(); T=[]; else T = _Plot_Robot_Frame(robot,q,varargin); end endfunction ...
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// Scilab Code Ex1.13: Page-1.17 (2009) clc; clear; theta = 45; // Diffraction angle, degrees h = 6.626e-034; // Planck's constant m = 1.67e-027; // Mass of a neutron, kg n = 1; // Order of diffraction k = 1.38e-023; // Boltzmann constant, J/mol/K T = 27+273; // Absolute room temperature, ...
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//Chapter 14 //Example 14_9 //Page 370 clear;clc; v=400; ph_v=230; lr=20*1e3; ly=28.75*1e3; lb=28.75*1e3; ir=lr/ph_v; iy=ly/ph_v; ib=lb/ph_v; //referring to the phasor diagram in the text book xc=ir-iy*cos(30*%pi/180)-ib*cos(30*%pi/180); yc=iy*cos(60*%pi/180)-ib*cos(60*%pi/180); in=sqrt(xc^2+yc^2); printf("\t Ir =...
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clc; B=300; Ib=[0.00002 0.00005]; //Ampere Ic1=B*Ib(1,1); //Ampere Ic2=B*Ib(1,2); //Ampere disp('mA',Ic1*1000,"Ic1="); disp('mA',Ic2*1000,"Ic2=");
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<cmd> ../build/42sh</cmd> <ref> bash</ref> <stdin> echo toto; echo tata; echo titi; echo jojo; echo jiji; echo jaja; echo toto; echo tata; echo titi; echo jojo; echo jiji; echo jaja;echo toto; echo tata; echo titi; echo jojo; echo jiji; echo jaja; echo toto; echo tata; echo titi; echo jojo; echo jiji; echo jaja;echo ...
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// Scilab Code Ex3.24: : Page-3.46 (2009) clc; clear; lambda1 = 5890e-008; // Wavelength of D1 line, cm lambda2 = 5896e-008; // Wavelength of D2 line, cm N = 15000; // No. of lines per inch of grating, lines/inch a_plus_b = 2.54/N; // Grating element, cm n = 2; // Order of diffraction...
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clc // Given that to=0.005//in inch depth of cut V=400//in ft/min cutting speed X=10//in degree rake angle w=0.25//in inch width of cut tc=0.009//in inch chip thickness Fc=125//in lb Cutting force Ft=50//in lb thrust force // Sample Problem on page no. 548 printf("\n # Relative Energies in cutting # \n")...
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//CHAPTER NO.-5 //Example No.5-1-4 , Page No.-211 // Program_to_determine_the_maximum_allowable_power_that_the_transisitor_can_carry Xc=1;//Reactance ft=4*(10^9);//Transit_cut-off_frequency Em=1.6*(10^5);//maximum_electric_field Vx=4*...
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s=%s sys=syslin('c',(k)/(s*(s+1)*(s+2)*(s+3))) evans(sys)
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//Problem 15.09: A coil of inductance 318.3 mH and negligible resistance is connected in series with a 200 ohms resistor to a 240 V, 50 Hz supply. Calculate (a) the inductive reactance of the coil, (b) the impedance of the circuit, (c) the current in the circuit, (d) the p.d. across each component, and (e) the circuit...
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function [s, lowercrossvalue, uppercrossvalue, lowerreference, upperreference]=slewrate(x, varargin) // This function estimate slew rate of bilevel waveform transitions // Calling Sequence // s=slewrate(x) // s=slewrate(x, t) // s=slewrate(x, Fs) // s=slewrate(x, t, 'PercentReferenceL...
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// 08.05.19 // Structure changed // 09.10.11 function M=MixL(varargin) Nargs=length(varargin); M=list(); for I=1:Nargs Da=varargin(I); M(I)=Da; end endfunction
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function MM=unpack(M,blck_szs) //utility function (for use with semidef) MM=[] [mM,nM]=size(M) n=sum(blck_szs) for j=1:nM ptr=1 Mu=[] for ni=blck_szs Mui=[] for l=1:ni Mui(l:ni,l)=M(ptr:ptr+ni-l,j) Mui(l,l:ni)=M(ptr:ptr+ni-l,j)' ptr=ptr+ni-l+1 end Mu=[Mu;matrix(Mui,ni*ni,1)] end MM=[MM,Mu] end
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//example 8.2 //page 290 clc; funcprot(0); //initialisation of variable nu=1.54*10^-6; V=0.1; D=0.02; g=9.81; L=30; Re=V*D/nu; f=64/Re; hf=f*L/D*V^2/2/g; disp(hf,"head loss (m of H20)"); clear
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clear; clc; close; disp("Example 3.1") M0=0.85 //Mach no. a0=300 //speed of sound in m/s m=50 //Air mass flow rate in kg/s //Calculations V0=M0*a0 //Flight speed Dr=m*V0 //Ram drag Dk=Dr/1000 //in kN disp(Dk,"The ram drag for given engine in kN:")
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clc // At 10 bar: From steam table for superheated steam h_sup=3051.2; //kJ/kg T_sup=573; //K T_s=452.9; //K v_g=0.194; //m^3/kg v_sup=v_g*T_sup/T_s; p=10; //bar u1=h_sup-p*v_sup*10^2; //kJ/kg disp("Internal energy of superheated steam at 10 bar= ") disp(u1) disp("kJ/kg") // At 1.4 bar: From steam table...
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//AC Circuits : example 4.49 :(pg 4.37 & 4.38) f=50; I1=4; pf1=0.5; V1=200; I2=5; pf2=0.8; V2=40; Z1=(V2/I2); R=(Z1*pf2); XL1=sqrt((Z1^2)-(R^2)); L1=(XL1/(2*%pi*f)); Z2=(V1/I1); RT=(Z2*pf1); XL2=sqrt((Z2^2)-(RT^2)); L2=(XL2/(2*%pi*f)); Pi=(V1*I1*pf1-(I1^2)*R); printf("\nWith iron core I=4 A pf=0....
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clc clear //initialisation of variables H= 1436.3 //cal mole^-1 d= 0.9999 //g ml^-1 d1= 0.9168 //g ml^-1 P= 1 //atm m= 18.02 //gm R= 1.987 //cal/mole K T= 2 //C //CALCULATIONS V= (P/d)-(P/d1) H1= H*82.05/(m*R) P1= H1*(-T)/(273*V) //RESULTS printf (' pressure required to decrease= %.f atm',P1)
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//Лабораторная работа №11 clc clf() funcprot(0) disp('_______________________________________') disp('y = 3*sin(x)+6*cos(x+3)-1') function y=reshenie(x) y=3*sin(x)+6*cos(x+3)-1 endfunction x=-6:0.1:8; plot2d(x,reshenie(x),axesflag=5),xgrid();scf; x=fsolve([-5;-2;1;4.5;7.5],reshenie) disp(x,'Корни уравнения:...
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clc //Chapter2 //Ex_2.7 //Given n=1.2 To=293 //in kelvin alpha_o=n/To printf("Theoretical value of TCR at 293K is %f which is in well agreement with exprimental value",alpha_o) alpha_o=0.00393 //experimental value n=alpha_o*To disp(n,"Theoretical value of n at 293K is in well agreement with exprimental value"...
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//Exa1.2 clc; clear; close; //given data : FC=25000;//in Rs v=45000;//in Rs s=120000;//in Rs //Part a : Contribution Con=s-v;//in Rs disp(Con,"Contribution in Rs : "); //Part b : Profit Prof=Con-FC;//in Rs disp(Prof,"Profit in Rs : "); //Part c : BEP PVratio=Con*100/s;//in % BEP=FC*100/PVratio;//in Rs ...
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function [mat]=tridiag(A) for i=1:n mat(i,i)=A(i,i); end for (i=2:n) mat(i-1,i)=A(i-1,i); mat(i,i-1)=A(i,i-1); end // facto endfunction function [L,U]=fact(mat) [mat]=tridiag(A); for k=1:n-1 i=k+1:n; mat(i,k)=mat(i,k)/mat(k,k); j=k+1:n; mat(i,j)=mat(...
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clc; clear; f=400 //focal length of lens in cm myu=1.50 //refractive index lambda=5460*10^-6 //wavelength in cm n=5 //fifth bright ring //calculation R=(myu-1)*2*f //radius of curvature in cm D5=sqrt(2*((2*n)-1)*lambda*R) mprintf("The diameter of the fifth bright ring is = %1.2f cm",D5) //The answer pro...
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//pagenumber 427 example 4 clear freque=40*10^3;//hertz frequ1=freque/0.507; disp("upper frequency = "+string((frequ1))+"hertz"); frequ1=freque/1.96; disp("lower frequency = "+string((frequ1))+"hertz");
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clc Vl=400; //Assigning values to parameters Il=34.65; P=14.4*10^3; Vph=Vl; Iph=Il/sqrt(3); Zph=Vph/Iph; t=acosd(P/(sqrt(3)*Vl*Il)) Z=complex(Zph,t); disp("Ohms",Z,"Impedance"); disp("Ohms",real(Z),"Resistance"); disp("Ohms",imag(Z),"Reactance");
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//Example 11_4 clc(); clear; //To findout the specific heat capacity of the metal m=400 //Units in gm c=0.65 //Units in Cal/gm Centigrade tf=23.1 //Units in Centigrade to=18 //Units in Centigrade oil=m*c*(tf-to) //units in cal m1=80 //Units in gm tf=23.1 //Units in Centigrade...
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clc //initialisation of variables v=((3140*%pi*60*60)/(4*4*144))//ft/sec v1=0.852*38.37//ft^3 //CALCULATIONS W=(v/v1)//lb V=(2970*%pi*60*60)/(4*4*144)//ft^3 W1=(V/v1)//lb //RESULTS printf('the weight of steam per hour=% f lb',W) printf('the weight of steam per hour=% f lb',W1)
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//Ex:3.22 clc; clear; close; y=1.2;// operating wavelength in um w=5;// spot size in um x=(2*y)/(%pi*w);// the divergence angle in degree printf("The divergence angle =%f degree", x);
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function response = http_post(host, resource, port, varargin) // This POSTs a request to a resource on host at port. // This will need to use the following functions: // 1. http_header // 2. http_urlencode endfunction
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//Chapter-2,Example2_6_4,pg 2-33 N=3*5000 //number of lines n_l=5000*10^2 //number of lines per meter wavelength=5890*10^-10 //wavelength of light m_max=1/(n_l*wavelength) R_P_max=(m_max)*N pri...
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clear // // // //Variable declaration k=1.000134; epsilon0=8.85*10^-12; //relative permeability(F/m) E=90000; //electric field(N/C) N=6.023*10^26; //avagadro number //Calculations n=N/22.4; p=epsilon0*E*(k-1)/n; //dipole moment(coul-metre) alpha=p/E; //atomic polariz...
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//Chapter 5, Problem 20 clc f=10e6 //frequency in hertz Ls=15e-6 //capacitance in farad Rs=2 //resistance in ohm //calculation Qs=(2*%pi*f*Ls)/Rs Rp=Rs*(1+(Qs^2)) Lp=((1+Qs^2)/Qs^2)*Ls printf("Resistance Rp = %d Kohm\n\n Inductance Lp = %...
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//The concept of multistage Decimation //(a)Single stage decimator Sin=48;Sout=4; fp=1.8; fs=Sout-fp; FT=(fs-fp)/Sin; disp('By using single stage the total filter length is:') L=4/FT //(b)Two-stage decimator Sin=[48 12]; D=[4 3];//decimating factors Sout=[12 4]; fp=[1.8 1.8]; fs=Sout-fp; L1=4*Sin./(fs-f...
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// Variable declaration s_square = 0.25 // mean square error v = 10 // degree of freedom t_thr = 2.228 // theoritical value of t at 0.025 b = 2 r = 3 // Calculation l = [3.07, 2.30;7.17, 5.53;10.80, 7.33] a = l(:,1) b = l(:,2) l1 = [a(1),b(1)] l2 = [a(2),b(2)] l3 = [a(3),b(3)] // Result // first confi...
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clc,clear printf('Example 5.2\n\n') VA=1200*10^3 V_L=6600 R_a=0.25 //armature resistance per phase X_s=5//synchronous reactance per phase I_L=VA/(sqrt(3)*V_L) I_aph=I_L //for star connected load I_a=I_L V_ph=V_L/sqrt(3) //Part(i) phi1=acos(0.8)//and lagging E_ph1= sqrt( (V_ph*cos(phi1)+I_a*R_a)^2+(V_...
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//Eg-5.11 //pg-239 clear clc printf('Theoretical Question\n')
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//(Threaded Joints) Example 7.1 //Refer Fig.7.13 on page 232 //Weight of electric motor P (kN) P = 10 //Yield tensile strength of 30C8 Syt (N/mm2) Syt = 400 //Factor of safety fs fs = 6
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// Grob's Basic Electronics 11e // Chapter No. 05 // Example No. 5_8 clc; clear; // In Fig. 5–18a, suppose that the ammeter M1 reads 16-A instead of 20-A as it should. What could be wrong with the circuit? disp ('Notice that the current I3 is supposed to be 4-A. If R3 is open, this explains why M1 reads a curren...
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//chapter19 //example19.7 //page422 Pc=500 // W m=1 Ps=0.5*m^2*Pc Pt=Pc+Ps printf("sideband power = %.3f W \n",Ps) printf("power of modulated wave = %.3f W \n",Pt)
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clear;lines(0); // Integration of the differential equation // dy/dt=y , y(0)=1, and finds the minimum time t such that y(t)=2 deff('[ydot]=f(t,y)','ydot=y') deff('[z]=g(t,y)','z=y-2') y0=1;ng=1; [y,rd]=ode('roots',y0,0,2,f,ng,g)
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clear;clc function [ X ] = gaussSeidel( A, B ) // Gauss Seidel n = length(B); mensagens = 1; // Estimativa inicial de X e X da iteracao anterior X = zeros(n,1); // Criterios de parada maxIter = 100; minDelta = 10e-10; // Contadores k = 0; delta = 2*minDelt...
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clc //given that E_eV = 0.5// kinetic energy of electron in KeV del_x = 0.4 // Uncertainty in position in nm h = 6.63e-34 // Plank constant m = 9.1e-31 // mass of electron in kg printf("Example 2.12") h_bar = h / (2*%pi) // constant E_J = E_eV*1e3*1.6e-19 p = sqrt(2*m*E_J) // Calculation of momentum in kgm...
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//error clc disp('solution of the given linear differential equation is given by : ');
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//chapter 3 //example 3.24 //page 124 printf("\n") printf("given") f=500;Rs=600;E=8; t=1/(2*f) PW=t; C1=PW/Rs Vo=2*E Vc=(1*Vo)/100;//1% of the Vo Ic=(Vc*C1)/t R1=(2*E)/Ic; printf("suitable value of R1 is %dohm\n",R1)
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syms Wn zeta Kv Ess s=%s; p=poly([8 2 1],'s','coeff'); // characteristic equation z=coeff(p); Wn=sqrt(z(1,1)) zeta=z(1,2)/(2*Wn) Kv=z(1,1)/z(1,2) Ess=1/Kv // Steady state error for unit ramp i/p disp(Ess,"Steady state Error=")
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// Chapter 2_Introduction to the quantum theory of solids //Caption_Density of States //Ex_3//page 63 m=9.11*(10^-31) //mass of electron h=6.625*(10^-34) E=1.6*(10^-19) N=((4*%pi*(2*m)^(1.5))/(h^3))*(E^(1.5))*(2/3) printf('Density of states per unit volume with energies between 0 and 1 eV is %f states per u...
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//Page Number: 42 //Example 1.16 clc; //From given wave equation we can see w=1D+9;//rad/sec bet=30;//rad/m c=3D+8; //m/s u0=1; //let e0=1/(9D+16); vp=w/bet;//m/sec disp('m/s',vp,'Phase velocity:'); e=1/(vp^2*u0); er=e/(e0*u0); disp(er,'Dielectric constant:');
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package main import "flag" func main() { str := flag.String("string", "1234", "string opt usage") size := flag.Int("int", 0, "int opt usage") flag.Parse() _ = str _ = size }
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// 08.08.14 // 08.10.16 // 09.09.25 function Out=CameracoordCurve(Curve) global FocusPoint EyePoint; Out=[]; // 09.09.25 for J=1:size(Curve,1) P=Curve(J,:); Tmp=P-FocusPoint; X1=Tmp(1); Y1=Tmp(2); Z1=Tmp(3); Tmp=EyePoint-FocusPoint; E1=Tmp(1); F1=Tmp(2); G1=Tmp(3); Ca=E1/sqrt(E1^2+F1^2); ...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex8_7.sce. clc; clear; P=300e3; V=500; a=8; p=4; Z=786; theta=5; I=P/V; armature_AT=(1/2)*(I/a)*(Z/(2*p)); //Total AT per pole demagnetizing_AT...
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//Example 2.7 clc; clear; close; //Given data : format('v',5); d=6;//in mm d=d/1000;//in m sigma=0.0755;//N/m //At equillibrium : p*%pi*r^2=sigma*2*%pi*r r=d/2;//in m p=2*sigma/r;//N/m^2 disp(p,"Intensity of pressure in N/m^2 or Pascals : ");
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//fiber optic communications by joseph c. palais //example 3.4 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given lambda=1.32e-6*1e9//wave length in nm lambda0=1.3e-6*1e9//Zero dispersion wave length in nm M0=-0.095//slope at zero dispersion wave length ps/(nm^2xKm) sw=2//spectral width in nm d...
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It is hot. The sky is blue. A little cloud comes looking for you. More cloud come. They bring rain. Sing and dance. It's cool again!
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function p=parallel(r1,r2) p=r1*r2/(r1+r2) endfunction //deactivate voltage source i11=4*6/8 i21=4*2/8 v11=i11*2 v21=1*1 //deactivate current source Req=parallel(2,7) v22=8*Req/(2+Req) v12=v22*(2/(2+5)) v1=v11+v12 v2=v21+v22 disp(v2,v1)
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@relation yeast-5 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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clc // // // //Variable declaration c=3*10**8 delf=3000 //Bandwidth //Calculations lc=(c/delf) //Result printf("\n The coherence length of the laser beam is %0.3f m or 10**5 m",lc)
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//clc() //y1 = x //y2 = exp(-x) for i = 1:6 if i == 1 then x(i) = 0; else x(i) = x(i-1) + 0.2; end y1(i) = x(i); y2(i) = exp(-x(i)); end disp(x,"x = ") disp(y1,"y1 = ") disp(y2,"y2 = ") plot(x,y1); plot(x,y2); xtitle("f(x) vs x","x","f(x)") // from the graph, we get x...
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clc;funcprot(0);//Example 8.13 //Initilisation of Variables Tci=20;......//Inlet temparature of fluid in degrees celcius Tco=90;......//Outlet temparature of fluid in degrees celcius Thi=200;......//Inlet temparature of steam in degrees celcius Tho=100;......//Outlet temparature of steam in degrees celcius U=300;...
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clear; clc; close; Idss = 8*10^(-3); Vp = -4; gmo = 2*Idss/abs(Vp); Id1 = 0; gm1 = gmo*(sqrt(Id1/Idss)); Id2 = Idss/4; gm2 = gmo*(sqrt(Id2/Idss)); Id3 = Idss/2; gm3 = gmo*(sqrt(Id3/Idss)); Id4 = Idss; gm4 = gmo*(sqrt(Id4/Idss)); x = [Id1 Id2 Id3 Id4]; y = [gm1 gm2 gm3 gm4]; yi=smooth([x;y],0.0005)...
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errcatch(-1,"stop");mode(2);//Example 9.17.5 // capacitance ; ; //given data : K=10;// constant C2=35*10^-12; C1=(C2/(K-1))*10^12; disp(C1,"capacitance,C1(pico-farad) = ") exit();
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//Value of P //refer fig. 17.9 (a),(b)and(c) //Let t1 be the time required to bring the system to rest N=1000 //N F=0.2*1000 //N //Applying impulse momentum equation upto stationary condition and leftward motion and solving those equations by trial and error method we get P=645.74 //N printf("Value of P is %....
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disp("The absorption edge of the quantum well structureoccurs at Eg+Ehh1+Ee1"); Ehh1=0.002; Ee1=0.014; Eg=1.424; E=Eg+Ehh1+Ee1; printf('\n The band edge therefore shifts from 1.424eV to %f eV',E); printf('\n'); disp("This corresponds to a blue shift of 10nm");
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// Exa 7.1 clc; clear all; // Given data // Referring to waveform shown in fig 7.50 on page 211 V_attn= 0.5; // Vertical attenuator(V/div) div=3; // No of vertical divisions // Solution // Using equation : Vp-p=(volts/div) * (no. Of div/1); Vp_p=V_attn * div/1 ; printf(' The peak to peak amplitu...
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//example 3 pagenumber 139 clear v=4.3;//volt q=4;//volt dop=10^17;//per cubic centimetre fi0=0.254*log(dop/(5.1*10^10)); fi01=0.407+q+0.55; disp('fi0 = '+string(fi01));
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// Example 12_10 clc;funcprot(0); // Given data T_DB=50.0+273.15;// K T_ref=0+273.15;// K phi=40.0/100;// The relative humidity p_m=0.101;// MPa c_p=1.004;// kJ/(kg.K) // Calculation h_a=c_p*(T_DB-T_ref);// kJ/(kg dry air) // From Table C.1b, p_sat=0.01235;// MPa w=0.622*((phi*p_sat)/(p_m-(phi*p_sat)));/...
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%Generated from '../examples/iocaste/n200.dig'. query(instances(aconcept('Good')), [i1]). concept('Good'). concept('Patricide'). role(hasChild). implies(and([some(arole(hasChild), and([aconcept('Patricide'), some(arole(hasChild), not(aconcept('Patricide')))]))]), aconcept('Good')). implies(aconcept('Goo...
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//Example 1.23 clc disp("Step 1: Identify topology") disp("Here output voltage is sampled and fed in shunt with the input siganl such that, I_s-I_f = I_i, hence topology is voltage shunt feedback") disp("") disp("Step 2 and Step 3: Find input and output circuit") disp("To find input circuit, set Vo = 0. This plac...
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clc; T=2800; // Temperature of combustion in kelvin p=1; // Pressure of combustion in atm // For this reverse reaction at 2800K and 1atm, from Table 15.1 K=44.168; // K=e^3.788; K=sqrt (K); // For stoichiometric equation CO+1/2 O2 = CO2 which is halved // From equation 15.24a and by the iteration process we get t...
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clc; clear all; disp("time and temperature ") L=6/2000;//m rho=7800;// kg/m^3 c=460;// J/(kg.C) k=55;// W/(kgm.C) ti=30;// degree C ta=2150;// degree C t=1100;// degree C Lc=L;// characteristic length Bi=h*Lc/k; if Bi>1 disp("Internal temperature gradients are not small and can not be neglected") end F...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/CPU.tst load CPU.hdl, output-file CPU.out, compare-to CPU.cmp, output-list time%S0.4.0 inM%D0.6.0 instruction%B0.16.0 reset%B2.1.2 outM%D1.6.0 writeM%B3.1.3 add...
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// Example 32_20 clc;funcprot(0); //Given data P=500;// MW F_c=0.45;// Capacity factor F_l=0.6;// Annual load factor Cf=1000*10^6;// Cost of fuel used/year in rupees CC=10000*10^6// Capital cost plant in rupees ID=15/100;// Interest and depriciation // Calculation //(a) MD=(F_c/F_l)*P;// Maximum demand in ...
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tA1 = [0, 1, 0, 0; -1/2, -236/120, 0, 0; 0, 0, 0, 1; 0, 0, -1/2, -236/120]; tA2 = tA1; tA3 = [0, 1, 0, 0; -1/2, -236/120, 0, 0; 0, 0, 0, 1; 1/2, 36/120, -1/2, -236/120]; tA4 = [0, 1, 0, 0; -1/2, -236/120, 0, 0; 0, 0, 0, 1; -1/2, -3.6, -1/2, -236/120]; tA6 = [0, 1, 0, 0; -1/2, -236/120, 0, 0; 0, 0, 0, 1; 1/2, 20/12,...
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//Problem 9.02: At what velocity must a conductor 75 mm long cut a magnetic field of flux density 0.6 T if an e.m.f. of 9 V is to be induced in it? Assume the conductor, the field and the direction of motion are mutually perpendicular. //initializing the variables: l = 0.075; // in m E = 9; // in Volts B = 0.6; /...
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[Read-the-docs-example-5] # Read the docs - example 5 user_indice: {'indice_name': 'my_indice', 'calc_operation': 'max'} in_files: ['tas_day_MPI-ESM-LR_historical_r1i1p1_19500101-19591231.nc', 'tas_day_MPI-ESM-LR_historical_r1i1p1_19600101-19691231.nc', 'tas_day_MPI-ESM-LR_historical_r1i1p1_19700101-19791231.nc', 'tas_...
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clear // l=10 r=100 i=1 f=100 i1=0.5 c=1/(4*(3.14**2)*(r**2)*l) v=i*r z=v/i1 //z=100+jX x=((200**2)-(100**2))**0.5 omega=641.1 //angular frequency in rad/sec f0=omega/(2*3.14) f1=f0-(r/(4*3.14*l)) f2=f0+(r/(4*3.14*l)) printf("\n f0= %0.1f Hz",f0) printf("\n f1= %0.1f Hz",f1) printf("\n f2= %0.1f Hz",f2)
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//Page Number: 216 //Example 4.14 clc; //Given p=40; //mW //Since port 3 is matched x=sqrt(2); s=[1 1 x;1 1 -x;x -x 0]; r1=40; //ohm r2=60; //ohm w=50; //ohm //Reflection coefficients T1=(w-r1)/(w+r1); T2=(r2-w)/(r2+w); //As power is fed into 1 and 2 equally pd=p/2; //Power delivered //Port 1 p1...
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clc;funcprot(0);//EXAMPLE 11.2 // Initialisation of Variables cp=5;.................//Consumption of petrol in kg/h afr = 16;...............//Air fuel ratio Af=2*10^(-6);..............//Fuel orifice area in m^2 z=0.005;................//Distance between tip of jet and level of petrol in float chamber in m spgrp=0...
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clc T=300 //K //a=E-Ef //a=3*k*T //fF(E)=1/(1+exp(E-Ef/kT)) z=exp(3) y=1/(1+z) //y=fF(E) printf('fF(E)=%f\n',y)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc //Initialization of variables T1=1000 //R T2=2000 //R //calculations function y =cp(t) y=9.47 -3.47*10^3 /t + 1.16*10^6 /t^2 endfunction cp2= 1/(T2-T1) *(intg(T1,T2,cp)) //results printf("Specific heat = %.2f Btu/mol R",cp2)
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//exmaple 2.6 clc disp("The circuit is Wien bridge oscillator using op-amp. The gain of the op-amp is") a=1+3 disp(a,"A = 1 + R3/R4 =") disp("So A > 3") disp("This satisfies the required oscillating condition. The feedback is given to non-inverting terminal ensuring the zero phase shift. Hence the circuit will w...