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clc; clear; printf("\t\t\tChapter3_example3\n\n\n"); // Determination of the heat lost through the walls, using the shape-factor method. (b) Repeat the calculations but neglect the effects of the corners; that is, assume only one-dimensional effects through all the walls. k = 1.07; // thermal conductivity of silica br...
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//example(3.16) c=[-5040 13068 -13132 6769 -1960 322 -28 1] p7=poly(c,'x','coeff') roots(p7)
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disp('chapter 5 ex5.12') disp('given') disp('R1=R3=2200ohms') disp('R2=220kohms') disp('Rs=220ohms') Rs=220 R1=2200 R3=2200 R2=220000 disp('R=R2+R3') R=R2+R3 disp('ohms',R) disp('f=600kHz') f=600000 disp('Cs=1/(2*%pi*f*10*R)') Cs=1/(2*%pi*f*10*R) disp('farads',Cs) disp('R=R2||(R1+Rs)') R=R2*(R1+Rs)/(R...
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//Least value of theta to avoid slipping of ladder //refer fig.8.21 //Applying virtual work principle //-0.4*NA*6*cosd(theta)*delta(theta)-200*(-3*sind(theta)*delta(theta))-900*(-5*sind(theta)*delta(theta))+0.25*NB(-6*sind(theta)*delta(theta))=0 NA=1100/(1+0.25*0.4) //N NB=0.4*1000 //N theta=atand(2400/4500) /...
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// Chapter 8_Metal Semiconductor and Semiconductor heterojunctions //Caption_Non ideal effects on the barrier height //Ex_3//page 312 E=6.8*10^4 T=300 e=1.6*10^-19 eps=13.1*8.85*10^-14 delphi=(e*E/(4*%pi*eps))^0.5 xm=(e/(16*%pi*eps*E))^0.5*10^8 printf('Position of the maximum barrier height is %1.0f Angstorm',...
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//chapter 12 //example 12.1 //page 474 printf("\n") printf("given") hfe=50;hie=1*10^3;hib=20;f1=100;Rc=3.3*10^3;Re=Rc; disp(" required capacitance") Xc2=hib; C2=1/(2*3.14*f1*Xc2) disp(" voltage gain with emitter terminal completely bypassed to ground") Av=-(hfe*Rc)/hie disp("voltage gain when f=100") Av=-(...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 14 disp("CHAPTER 8"); disp("EXAMPLE 14"); //shunt generator //VARIABLE INITIALIZATION v_t=220; //in Volts I_l=196; //in Amperes s_loss=720; //stray loss in Watts r_f=55; //shunt field ressitance i...
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clc clear printf("example 6.10 page number 231\n\n") // to find the equilibrium composition P_M = 53.32 //kPa P_W = 12.33 //in kpA P = 40 //IN K pA x = (P - P_W)/(P_M-P_W); printf("liquid phase composition = %f",x) y = P_M*x/P; printf("\n\nvapor phase composition = %f",y)
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clc clear //Input data V1=8 //Intial volume in litre V2=7.8 //Final volume in litre P1=0.7 //Intial Pressure in MPa P2=2.7 //Final Pressure in MPa //Calculations K=(P2-P1)/(log(V1/V2)) //Bulk modulus of liquid in kPa //Output printf('Bulk modulus of liquid is %3.3f kPa',K)
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disp('chapter 11 ex11.9') disp('given') disp('design a single stage bandpass filter') disp('voltage gain Av=1 and a pass band from 300Hz to 30kHz') Av=1 f2=30000 f1=300 disp('select C2=1000pF') C2=1000*10^(-12) disp('Xc2=R2 at f2') disp('R2=1/(2*%pi*f2*C2)') R2=1/(2*%pi*f2*C2) disp('ohms',R2) //use 5.36ko...
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selection=['item1';'item2';'item3']; text=['double-click';'your selection']; button="cancel (optional)"; n=x_choose(selection,text,button)
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x=fscanfMat('z.txt') ; y=fscanfMat('lambda.txt') ; P=fscanfMat('Psdbm.txt') ; x2 = [0:0.2:17.6] ; y2=[1.52:0.001:1.57] ; P2 = P(:,281:4:481) ; fenetre = scf(100001); clf(fenetre,"reset"); Titre = "Directions d''arrivée des signaux (k.d.sin(teta))"; my_handle.figure_name = Titre; xlabel('Lambda (nm)') ; ylabel('Ps (...
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clc // Given that l = 6e-2 // length of laser in meter D = 1e-2 // diameter of laser in meter lambda = 6.944e-7 // wavelength of light in meter d = 3700 // density of aluminium oxide in kg/meter cube Na = 6e+23 // Avogadro number M = 0.102 // molar mass of aluminium oxide in kg/meter cube h = 4.1e-15 // Planck constan...
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//CHAPTER 7 ILLUSRTATION 6 PAGE NO 202 //TITLE:GOVERNORS //FIGURE 7.9 clc clear //=========================================================================================== //INPUT DATA g=9.81// ACCELERATION DUE TO GRAVITY OA=.30// LENGHT OF UPPER ARM IN m AC=.30// ...
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Vector [32,44,55,66].gcd() = 1 Vector [32,44,55,66].extractGcd() = 1
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//Chapter 6 //Example 6.3 //page 201 //To find an approximate load flow solution clear;clc; ///////////////////////////////////////////////////////////////////////////////// //Realdemand Reactive demand Real generation Reactive generation Bus ///////////////////////////////////////////////////////////////...
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function [] = kiks_preferences() // Display mode mode(0); // Display warning for floating point exception ieee(1); global("KIKS_SIM_LIGHT_FEXP","KIKS_SIM_PROX_NOISE","KIKS_K213_NOISE","KIKS_SIM_PROX_EMAX","KIKS_SIM_PROX_EMIN","KIKS_SIM_PROX_EEXP","KIKS_ARENA_DEFAULT_COLOR","KIKS_MOVIENAME","KIKS_MOVIE_QUALITY","KIKS...
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//FICHIER_DE_TEST ADD NAME=bezout.tst,SSI=0 mode(5) //test un=poly(1,'s','c'); zer=0*un; s=poly(0,'s'); [p,q]=bezout(un,s); if norm(coeff([un s]*q-[p 0]))>10*%eps then pause,end [p,q]=bezout(s,un); if norm(coeff([s un]*q-[p 0]))>10*%eps then pause,end [p,q]=bezout(un,un); if norm(coeff([un un]*q-[p 0]))>10*%eps then pa...
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//Caption:Calculate (i)-directivity ,(ii)-coupling, (iii)-isolation //Exa:6.11 clc; clear; close; S_13=0.1; S_14=0.05; C=-20*log(S_13)/log(10); D=20*log(S_13/S_14)/log(10); I=C+D; disp(C,'Coupling (in dB) ='); disp(D,'Directivity (in dB)) ='); disp(I,'Isolation (in dB) =');
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FLAGS='--print UTF-7' STDIN='' STDOUT='\x2b\x2f\x76' STDERR='' EXITVAL='0'
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//resistance at 40 degree a0=0.0043 t1=27 t2=40 R1=1.5 R2=R1*(1+a0*t2)/(1+a0*t1) disp('value of resistance='+string(R2)+ ' ohm')
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// 二次元音響FDTD入門 by Yoshiki NAGATANI 20150525 (http://ultrasonics.jp/nagatani/) - Field Viewer for Scilab 5 h = scf(0); // ウィンドウの準備(新しいウィンドウを開いて h というハンドラに割り当てる) set(h, 'color_map',jetcolormap(64)); // 64 段階の Jet という色マップに設定 interval = 50; // ステップ刻み Nstep = 1000; // 総ステップ数 image_intensity = 2000; //...
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//pagenumber 286 example 3 clear colres=4*10^3;//ohm r1=4*10^3;//ohm rb=20*10^3;//ohm r=1*10^3;//ohm hie=1.1*10^3;//ohm //current gain ri=rb*hie/(rb+hie); curgai=(1/2.04)*(rb/(rb+(hie)))*(-50*colres/(colres+(r1))); disp("current gain = "+string((curgai))); //voltage gain volgai=curgai*r1/r; disp("v...
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// Calculating the log10. y = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; log10res = armaMat("log10",y)
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MARK begin; COMMENT | ************************************************************* | COMMENT | * AUTHOR: Alex Simpson DATE: 30/10/89 * | COMMENT | * * | COMMENT | * SUBJECT: The Diagonalisation Lemma * | COMMENT | * * | COMMENT | * NOTES: Based on the original version by Fausto. ...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 6 Single Staje BJT Amplifiers Pg no. 200 clear; clc; //Given Data //Figure 6.25 VCC=15;//collector supply voltage in volts RE=1.5D3;//emitter resistance in ohms R1=12D3;//divider network resistance R1 in ohms R2=10D3;//divider network resistance R2 in ohms V...
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clc // // // //Variable declaration D=0.04 //Distance from screen lambdaa=5890*10**-10 //Wavelength d=2*10**-3 //Slit separation n=10 //No. of fringes //Calculations x10=(n*D*lambdaa*10**-2)/d //Result printf("\n The position of the 10th fringe is %0....
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clc; //page 194 m1=80;//kg mass of man m2=20;//kg, mass of ladder m=m1+m2;//kg g=9.81;//m/s^2 gravitational acceleration W=-m*g;//N, j C=-0.6*W/3;//N Bz=-0.6*C/1.2;//N By=-0.9*W/1.2;//N printf(" Reaction At B is B= (%.0f) N j +(%.1f N)k\n",By,Bz); printf(" Reaction At C is C= (%.2f) N k\n",C); Ay=-W-B...
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//chapter 3 //example 3.1 //page 73 printf("\n") printf("given") Vf=.7;Rl=500;Vi=22; Vpi=1.414*Vi; disp("Vpi") Vpo=Vpi-Vf; printf(" peak vouput voltage is %3.2fV\n",Vpo) Ip=Vpo/Rl; printf("peak load current is %3.4fA\n",Ip) PIV=Vpi; printf("diode paek reverse voltage %3.2fV\n",PIV)
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//Example(4.14) (pg no.201) B=[1 2 0;2 1 0;0 0 -1] lam = spec(B) norm(B) //Each eigen value of the matrix must have absolute value // no bigger than the norm of that matrix
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function [dfr] = dframefunc() // Calls and initializes dframefunc module // // Syntax // dfr = dframefunc(df) // // Parameters // df: DataFrame input // Returns : dframefunc instance output // // Description // Initializes dframefunc module to access pythonic functions of pan...
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// Problem no 14.4,Page No.329 clc;clear; close; H=10 //m //height od dam a=2 //m //top width b=5 //m //bottom width W=25 //KN/m**3 //weight of mason rho_w=10 //KN/m**3 //density of water //Calculations //Let L=1 m (length of dam) L=1 //weight of dam W2=(b+a)*H*L*W*2**-1 ////Lateral thrust P=rho_w*H**2*L*2**-1 /...
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clear close clc s = poly(0,'s'); G = s^5 - 2*s^4 + 3*s^3- 6*s^2 + 2*s - 4; disp(routh_t(G));
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clc //Given that r_xz = [2,2.8282] // sample Problem 2b Page No. 176 printf("\n \n\n # Problem 2b # \n") r_xz = sqrt (2^2 + (2.8282)^2) r_yz = sqrt (2^2 + (2.8282)^2) printf (" \n Projection of vector r in xz plane is %f", r_xz) printf (" \n projection of vector r in yz plane is %f", r_yz)
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exec("mnluck.sci",2); exec("mnsamp.sci",2); exec("mnprobln.sci",2); exec("numlucksetup.sci",2); exec("numluck.sci",2); function ok=test_mnluck() nsamps=1000; mu=[0.8;-0.5]; Sigma=[4 3;3 5]; x=mnsamp(nsamps,mu,Sigma); luck=mnluck(x,mu,Sigma); problns=mnprobln(x,mu,Sigma); setup=numlucksetup(problns); ...
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// find output voltage,power dissipation // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 24-7, page 962 clear; clc; close; // Given data Vin=15;// input voltage Vz=6.2;// in volts Vbe=0.7;// in volts Rl=40;// in ohms R1=3*10^3;// in ...
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//pathname=get_absolute_file_path('8.06.sce') //filename=pathname+filesep()+'8.06-data.sci' //exec(filename) //Pressure of steam leaving the boiler(in MPa): p1=200 //Temperature(in K): T1=650+273 //Pressure of steam leaving the turbine(in MPa): p4=0.05 //From steam tables: h2=3675.3 //kJ/kg s2=6.6582 //kJ/kg...
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function img_out = seuilMultiple(img, seuil1, seuil2, seuil3) size_X = size(img, 1); size_Y = size(img, 2); img_out = zeros(size_X, size_Y); //tab = [seuil1 seuil2 seuil3 seuil4] for Y = 1:size_Y, for X = 1:size_X, //if img(X, Y) <= seuil1 then //img_out...
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30_01.sce
clear clc k=sqrt(3);//hr^-1 n=1; V=30;//m3 CR=0.12;//kgalc/kgsol density=1000;//kg/m3 //CR in kg/m3 CR=CR*density; CR_opt=CR/2; alcohol_per=CR_opt*100/density;//PErcentage of alcohol printf("\n The Percentage of alchol in cocktail is %f",alcohol_per) //From fig 30.4 kt=1; t=kt/k; t_opt=2*t; v_opt=V/t_op...
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/Knock Back Tracking.sce
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Knock Back Tracking.sce
Name=Knock Back Tracking PlayerCharacters=Ascended Tracking BotCharacters=Long Strafe Bot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Ascended Tracking AddedBots=Long Strafe Bot.bot PlayerMaxLives=0 BotMaxLives=1 PlayerTeam=1 BotTeams=2 MapName=KBTM.map MapScale=5.0 BlockProjectilePredictors=true BlockCheats=true...
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Ex5_6.sce
clc //initialization of variables clear P=10 //tonne E=2*10^6 //kg/cm^2 // calculations // We have to solve linear system Ax=B A=[1 1 1 0 3 1 -3 0 -2 2 0 -E 0 -1 2 -E] B=[P*10^3;0;0;0] x=inv(A)*B W1=x(1,1)/1000 W2=x(2,1)/1000 W3=x(3,1)/1000 th=x(4,1) //results printf('The load taken by each r...
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Ex1_8.sce
clear // res=0.02*(10**-6) l=4000*80*(10**-2) a=0.8*(10**-6) R=(res*l)/(a) printf("\n R= %0.1f ohm",R) power=(230*230)/(80) printf("\n power= %0e W",power)
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EX10_2.sce
//Clearing console clc clear //Intializing variables mg = 20 k = 40 g = 386.4 //Calculating circular frequency w1 = sqrt(k*g/mg) w2 = sqrt(6*k*g/mg) k1 = [1 1;2 -0.5] f1 = [1;0.5] k2 = [27.8 68.1;2*27.8 0.5*68.1] f2 = [0;0] //Solving for constants in equations of motion u1=linsolve(k1,-f1) u2=linsolve(k2,-f2) fi1 =...
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ex1_22.sce
V=20; //Assigning values to different parameters I=1.5; R1=10; R2=15; R3=15; V10=R1*I; Vab=V-V10; I1=Vab/R2; I2=Vab/R3; I3=I-I1-I2; R=Vab/I3; disp("Ohms",R,"Value of unknown resistance");
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Example1_25.sce
//Example 1.25 clc disp("Step 1: Identify topology") disp("By making Vo = 0, feedback current becomes zero. Hence it is a voltage sampling. The feedback is fed in shunt with the input signal and thus the topology is voltage shunt feedback") disp("") disp("Step 2 and Step 3: Find input and output circuit") disp("T...
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Ex1_26.sce
//Chapter1,Ex1.26,Pg1.29 function [current1] = voltagetocurrent(voltage1) resistance1=R current1=voltage1/resistance1 endfunction function[voltage2]=currenttovoltage(current2) resistance2=R voltage2=current2*resistance2 endfunction clc; disp("Refer to the figure shown in the question") R=5 //...
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VIPsmallCircle.sce
//convolution of VIP with a small aperature //display the image F = (imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\VIP.png")); f=scf(); imshow(F); isoview(); //G = (imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\circleAp.png")); nx = 128; ny = 128; x = linspace(-1,1,nx); y = linsp...
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Example3_3.sce
// Computation of mass from moles clear; clc; printf("\t Example 3.3\n"); moles=0.356;//moles of Zn mass=moles*65.39;//mass of Zn, g, 1 mole=65.39 g printf("\t the mass of Zn is : %4.1f g\n",mass); //End
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example1_14.sce
// To find limiting error // Modern Electronic Instrumentation And Measurement Techniques // By Albert D. Helfrick, William D. Cooper // First Edition Second Impression, 2009 // Dorling Kindersly Pvt. Ltd. India // Example 1-14 in Page 16 clear; clc; close; // Given data // let I = X_1 +/- Y_1 // R =...
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sadiku_5_2.sce
clear; clc; format('v',12); ps=10^-7; u=2; w=0.1; t=5; I=ps*u*w; Q=I*t*10^9; disp(Q,'charge(in nC) collected in 5 sec=');
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example5_sce.sce
//chapter 20 //example 20.5 //page 9 printf("\n") printf("given") R1=25*10^3;R2=2.7*10^3;C1=3*10^-6;Vg=.8;Vd1=8;Vs=115;f=60; Vc1=Vd1+Vg //assume the average charging voltage is Vac=1.414*Vs E=.636*Vac //average charging Ic=E/(R1+R2) //charging time t=(C1*Vc1)/Ic T=1/f q=(t*360)/T disp(" concudtion angle...
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EX29_6.sce
// Grob's Basic Electronics 11e // Chapter No. 29 // Example No. 29_6 clc; clear; // Find the exact value of Av. Also, find Vout. // Given data rl = 909; // Load resistance=909 Ohms re = 3.35; // Internal emitter resistance=3.35 Ohms Vin = 1; // Input voltage=1 Volts(p-p) Av = rl/(re+r...
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ex5_6.sce
// Exa 5.6 format('v',5) clc; clear; close; // Given data // Vo = -R_L*Io = ( (-R_L*Rc)/(Rc+R_L+(1/SC)) )*h_fe*Ib; R_C = 4;// in k ohm R_L = 2;// in k ohm R = R_C+R_L;// in k ohm R= R*10^3;// in ohm C_L = 10;// in µF C_L = C_L * 10^-6;// in F // Vo/Ib =Aos/(S+(1/R*C_L)); f_L = 1/(2*%pi*R*C_L);// in Hz di...
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1_A_6.sce
e0=8.85E-12 er=1 A=%pi*(1/200)^2 d=150/1000000 C=er*e0*A/d E=1/1000 v=sqrt(2*E/C) disp(v) E=2/1000000 v=100 er=2*E/(v^2)/C disp(er)
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Ex1_1.sce
// Example No.1.1. // Page No.28. clc;clear; t = 0.15*10^(-2);//Thickness of the quartz crystal -[m]. Y = 7.9* 10^(10);//Young's modulus of quartz -[N/m^2]. d = 2650;//Density of quartz -[kg/m^3]. f = (1/(2*t))*(sqrt(Y/d));//'f' is fndamental frequency of vibration. f = f*10^(-6);//fundamental frequency of v...
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6_3.sce
// 4*6 inch wood beam dimension // 4*0.5 inch steel beam dimension M = 60 ; // Moment in k-in E1 = 1500 ; // in Ksi E2 = 30000; // in Ksi b = 4; // width of crosssection in inch // Transformed Section n = E2/E1 ; // Modular ratio b1 = n*4 ; // Increased width of transformed cross section // Neutral axis h1 = ((3*4*6)+(...
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2_20.sce
clc,clear printf('Example 2.20\n\n') P=4, I_a1= 50, N_1=2000, V=230 //phi_1 is proportioanl to total ampere-turns produced by field coils //phi_1 (prop.) I_a1*P*n (prop.) 200*n (1) //After reconnection, phi_2 proportional to ampere turns divided as follows //phi_2 (pr...
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xdync.sci
// function [Y,degY,X,degX,B,degB,A,degA] = xdync(N,degN,D,degD,C,degC,gap) // given coefficient matrix in T1, primary redundant row information sel, // solves XD + YN = C // calling order changed on 16 April 2005. Old order: // function [B,degB,A,degA,Y,degY,X,degX] = xdync(N,degN,D,degD,C,degC,gap) function...
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Chapter1_Example34.sce
//Chapter-1, Example 1.21, Page 1.49 //============================================================================= clc clear //INPUT DATA Pi=8800;//Input power in W Ra=0.5;//Armature resistance in ohm No=1260;//Speed of the motor at no load in rpm V=240;//Line voltage in V Pm=18800;//Gross mechanical power...
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clc // // // //Variable declaration A=50/1.4 //Amplitude which is A=(50f/1.4*W**2) Amax=50 //Max Amplitude which is Amax=(50f/W**2) //Calculations Rat=A/Amax //Result printf("\n The Value of A/Amax is %0.2f ",Rat)
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function X = idframe(Output,Input,Ts,Unit,Start,End) [lhs,rhs] = argn(0) n = size(Output,'r'); if(rhs<4) Unit = 'Seconds' Start = 0 End = []; end if(rhs==6) if(End~=null) Start = End - Ts*(n-1) end end X = struct('Output'...
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//Initilization of variables d=500 //mm wo=0 //rpm w=300 //rpm t=20 //s t1=2 //s //Calculations alpha=(2*%pi*(1/60)*(w-wo))/t //rad/s^2 w1=wo+alpha*t1 //rad/s v=(d/(2*1000))*w1 //m/s a_n=(d/(2*1000))*w1^2 //m/s^2 a_t=(d/(2*1000))*alpha //m/s^2 a=sqrt(a_n^2+a_t^2) //m/s^2 theta=acosd(a_n/a) //degrees //Res...
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clear //variable declaration //summation of all horizontal forces is zero & vertical forces is zero. //Let the left support C be at a distance x metres from A. P1=(30) //vertical down load at A,KN Pu=(6) //uniform distributed load over whole span,KN/m,(20m of span) P...
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Name=yamasho2 PlayerCharacters=Ascended Tracking BotCharacters=Long Strafe Bot.bot IsChallenge=true Timelimit=90.0 PlayerProfile=Ascended Tracking AddedBots=Long Strafe Bot.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=ascended90_far.map MapScale=5.0 BlockProjectilePredictors=true BlockCheats=false...
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clc //given data A=500 // annual amount invested each year in rs i=9 // interest rate in % n=6 // time in years F=A*(((1+i/100.0)**n)-1)/(i/100.0) // future amount in rs printf("The Future amount will be Rs %.0f ",F)
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function [Q] = dyn_getAtt(X) Q = X(7:10,:); endfunction
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//Exa2.3 clc; clear; close; //given data LatheCost=200;//in Rs/hour grinderCost=150;//in Rs/hour //given data for Design A HoursOfLathe=16;//in hours/1000Unit HoursOfGrinder=4.5;//in hours/1000Unit TotalCostA=LatheCost*HoursOfLathe+grinderCost*HoursOfGrinder;//in Rs/1000unit disp(TotalCostA*100000/1000,"Tota...
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exec('./OuvertureC.sce',-1) exec('./ErosionC.sce',-1) function [NonVide] = VerificationImage(Img) [x,y]=size(Img) NonVide=%F for i=2:x-1 for j=2:y-1 if (Img(i,j)==1) NonVide=%T end end end endfunction function [ImgS] = SqueletteAntuejoul(Img) ...
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clc clear //Input data p=(1.01*10^5)//Standard atmospheric pressure in N/m^2 K=(16*10^10)//Bulk modulus in N/m^2 dp=(p-10^2)//Change in pressure in N/m^2 //Calculations dvv=(dp/K)//Change in volume to initial volume fv=(dvv/10^-7)//Fractional change in the volume *10^-7 //Output printf('The change in volu...
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//To calculate the dielectric constant of material N = 3*10^28; //density, atoms/m^3 alpha_e = 10^-40; //electronic polarizability, Farad-m^2 epsilon0 = 8.854*10^-12; epsilon_r = 1+(N*alpha_e/epsilon0); //dielectric constant of material printf("dielectric constant of material is %5.3f",epsilon_r);
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clc // one value of e is done Gs=2.75 A=30.68 Ms=128 p=1 Hs=Ms/(A*Gs*p) H=2.540 Hv=H-Hs e=Hv/Hs printf('the value of e for give values = %f',e)
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function g=f(x) k=1; for x=0:0.5:10 t=x^2+exp(-2*x); if(t>0) r(k)=t; end k=k+1; end g=(r); endfunction
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// Modified by Minho Kim (9 Oct 2014) load Encoder4Way.hdl, output-file Encoder4Way.out, compare-to Encoder4Way.cmp, output-list in%B1.4.1 out%B2.2.2; set in %B0001, eval, output; set in %B0010, eval, output; set in %B0100, eval, output; set in %B1000, eval, output;
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////Variable Declaration dGfFe = 0.0 //Std. Gibbs energy of formation for Fe (S), kJ/mol dGfH2O = -237.1 //Std. Gibbs energy of formation for Water (g), kJ/mol dGfFe2O3 = -1015.4 //Std. Gibbs energy of formation for Fe2O3 (s), kJ/mol dGfH2 = 0.0 //Std. Gibbs energy of formation for Hydrogen (g), ...
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//Exa 7.2 clc; clear; close; //given data : delVDS=1.5;//in Volt delID=120;//in uA delID=120*10^-6;//in A rd=delVDS/delID;//in Ohm disp(rd*10^-3,"AC drain resistance of JFET in Kohm : ");
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//Example 6_4 clc(); clear; //To find the recoil velocity of the gun vgf //As we know that Momentum before = Momentum after //((m*vb0)+(M*vg0))=((m*vbf)+(M*vgf)) // As vb0=vg0=0 printf("The recoil velocity of the gun is Vgf=-(m/M)*Vbf")
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//chapter 23 Ex 8 clc; clear; close; n1=50; n2=10; ans1=log10(n1) mprintf("The value of log %d to base %d is %.3f",n1,n2,ans1);
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clear clc x=poly([0],'x') A=[1 1 3;1 3 -3;-2 -4 -4] disp("eigen values of A are ") spec(A) disp("let ") a=4.2568381; b=0.4032794; c=-4.6601175; disp("hence,the characteristic equation is (x-a)(x-b)(x-c) ") p=(x-a)*(x-b)*(x-c) disp("inverse of A= ") inv(A)
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clc; p=5; //atm v=1; //volume in litres t=293; //Kelvin R=0.0821; //constant in atm-l/mole-K n=(p*v)/(R*t); //calculating n disp(n,"n = "); //displaying result m=n*32; //moles of O2 disp(m,"Moles of O2 = "); //displaying result d=m/v; //cal density disp(d,"Density in g/litre = "); //...
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//Example 8.7 clc; // Define the polynomial s=poly(0,"s"); p=8+4*s+4*s^2+2*s^3+2*s^4+s^5; // Calculate the routh of above polynomial r=routh_t(p); S=roots(p); disp(r,"Routh array="); disp(S,"Roots="); A=r(:,1); c=0; x=0; for i=1:5 x=A(i,1); if x<0 c=c+1; end end if(c>=1) then ...
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//Example 5.2: Coulomb sensitivity clc; clear; close; //given data : C=1.5*10^-6;// in F V=15;// in V d1=20;// in cm Q=C*V; Sb=(d1/Q)*10^-5; disp(Sb,"Coulomb sensitivity,Sb(mm/micro-C)")
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x = -3.8 format(25) for i = 1:3 esp1 = cos(sqrt(x^2 + 1)) - sin(x) esp2 = ((-1*sin(sqrt(x^2 + 1)) * x)/(sqrt(x^2 + 1))) - cos(x) x = x - (esp1/esp2) disp(x) end
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clc clear //input r1=10;//resistance of first coil in ohms l1=0.05;//inductance of first coil in henry v1=150;//limit of voltage drop across of first coil in volts v=240;//supply a.c. voltage in volts f=50;//frequency of supply in hertz a=40;//angle by which current lags the combined circuit after adding anot...
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// Compute Average lighting current clc; clear; q=20; t=(10)*(10^-3); // Coulomb's Law I=q/t; disp('amperes',I,'The Average Lightning current =')
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// SAMPLE PROBLEM 7/6 clc;funcprot(0); // Given data m=70;// The mass of bent plate in kg omega=30;// rad/s x_A=0.125;// m y_A=0.100;// m x_B=0.075;// m y_B=.150;// m d_x=0.0375;// m d_y=0.125;// m d_z=0.075;// m // Calculation // Part A m_A=x_A*y_A*m;// kg m_B=x_B*y_B*m;// kg I_xxA=((m_A/12)*(y_A^2+x...
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// Exa 2.3 //TO find Offered Load. clc; clear all; B=0.05; //Blocking(5%) CL=3000; //Carried Load in CCS //Solution //Offered Load=Carried Load/(1-Blocking); OL=CL/(1-B); //Offered Load in CCS printf('Offered load is %d CCS \n',round(OL)); printf(' Overflow is %d CCS \n',round(OL)-CL);
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clc; Cp=1.1; // Specific heat of combustion gas in kJ/kg K T3=1600; // Initial temperature of combustion gas in Kelvin T4=1150; // Final temperature of combustion gas in Kelvin p1=0.1; // Pressure at inlet of boiler in MPa p2=8;// Pressure at outlet of boiler in MPa T2=600; // Temperature at outlet of boiler in d...
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//Crank travel(in degrees) Tc=25; //Speed(in rpm) N=2500; //API(in degree) API=30; //Coefficient of velocity Cd=0.875 //Injection pressure(in bar) pinj=150; //Combustion chamber pressure(in bar) pcyl=40; //Power developed(in kW) P=25; //Specific fuel consumption(in kg/kWh) bsfc=0.3;
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clc Nd=10^16 disp("Nd = "+string(Nd)+" /cm^3") //initializing value of donor ion concentration. Vms=-1.12 disp("Vms = "+string(Vms)+" V") //initializing value of metal semiconductor work function difference. Er=3.9 disp("Er = "+string(Er)) //initializing value of relative dielectric permittivity constant . Eo=8...
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//Example13.6 // Determine the frequency response of the astable multivibrator circuit clc; clear; close; Vsat = 2.5 ; VT = 0.7 ; // The frequency of the astable multivibrator is //f = (1/(2*R*C*log((Vsat+VT)/(Vsat-VT)))); disp('The frequency of the astable multivibrator is= 0.87/RC ');
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoPolDelay(In,Delay_ps) // Polarization Delay // // Calling Sequence // Out=SSSoPolDelay(In,Delay_ps) // // Parameters // In : Optical Input // Delay_ps : Delay of the X-pol...
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// Exa 3.10 clc; clear; close; // Given data V1 = 18;// in V V2 = 270;// in V R = 1;// in K ohm R = R*1000;// in ohm V = (V1*R)/(V2+R);// in V disp(V,"The open circuit voltage in volts is"); if V>=10 then disp("The zener diode is operating in the breakdown region.") end
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clc(); clear; // To determine the specific heat of air p = 14.7; // Pressure in psi. Tb = 68; // Dry bulb temperature in F Tw = 50; // Wet bulb temperature in F // In the enthalpy-specific heat diagram, the isotherm 50F in the supersa...
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//Section-14,Example-2,Page no.-PC.30 //To calculate pressure exerted using ideal gas equation and Vanderwalls equation. clc; n=5 R=8.314 T=300 V=1*10^-3 P_1=((n*R*T)/V) disp(P_1,'Required pressure using ideal gas equation(Nm^-2)') a=0.1378 b=0.0318*10^-3 P_2=(((n*R*T)/(V-n*b))-((a*n^2)/(V^2))) disp(P_2,'Re...
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clear; clc; printf("\nEx2.41\n"); //page no.-87 //given h=6.6*10^-34;..........//planck's constant in J-sec m=9*10^-31;.........//mass of electron in kg w=6.4*10^-19;.........//work function in joule nu=10^15;.............//frequency in hertz v=sqrt((2*(h*nu-w))/m)............//velocity in m/sec printf("\...
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function [orbits]=Bifur(Map,NbrItiCalc,XO,Aini,Afin,Etap,NbrItiGraph) orbits=[] if ~isdef('Map','local')... then Map=orb end; if ~isdef('Aini','local')... then Aini=0 end; if ~isdef('Afin','local')... then Afin=-2 end; if ~isdef('Etap','local')... ...
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//Example 1.18 // wavvelength of light clc; //given data : b=.5D-2;//distace between succesive fringes in m u=1.4;//refractive index of cellophane a=10;//angle of wedge in sec a=a*%pi/(60*60*180);//to convert in radian w=2*u*a*b; w=w*1D10;//to convert in A disp(w,"wavelength of light used in A") //note: Pi ...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 7 //Properties of Solutions //Example 2 clear; clc; //Given: V = 0.1; //volume of mixture required (m^3) Ve = 0.03; //volume of alcohol Vw = 0.07; //volume of water de = 789; //density of ethanol (kg/m^3) dw = 997; //density of water (kg/m...