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// // printf("\n case 1') ir=3.415 fr=4.415 n=0//anchor point outside c=0 sc=16 //1cm^2=16m^2 h=10000 ag=0.16*h am=ag/sc printf("\n A= %0.3f square centimeters",am) m=am/(fr-ir) printf("\n M= %0.3f ",m) printf("\n case 2') fr_ir=2.25 c=21.22 n=1 a1=m*(fr_ir-10+c) printf("\n required area is %0.3f square c...
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// Exa 2.30 clc; clear; close; format('v',6) // Given data Vin = 10;// in V V1 = 2;// in V // Vin-V_C+V1 = 0; V_C = Vin+V1;// in V //During positive half cycle the output voltage Vout = Vin-V_C;// in V disp(Vout,"During positive half cycle the output voltage in V is"); Vin = -10;// iin V V1 = 12;// in V ...
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//Problem 7.01: //initializing the variables: C = 1; P = 1; //calculation: F = C - P + 2 printf("\n\nResult\n\n") printf("\n the number of degrees of freedom is %.0f",F)
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function qdot=lowpass(q,t) R=100; C=.01; V=sin(100*t)+sin(t); qdot=V/R-q/(R*C); endfunction
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pathname=get_absolute_file_path('9_6.sce') filename=pathname+filesep()+'9_6_data.sci' exec(filename) //Fuel consumed mf=(P/k)*bsfc //Volume flow rate of fuel Vf=mf/(N/2)*(1/Pf)*10^6 //Change in volume dv=Kcomp*(Vpb+Vin+Vpl)*(p2-p1) //Plunger displacement volume Vp=dv+Vf //Pump work Wp=0.5*(p2-p1)*10^5*dv*10...
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function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction j=%i //voltage V is taken as reference phasor Z1=5+10*j//impedance of inductive branch Z2=10-15*j//impedance of capacitive branch I=20//total current V=I/mag(1/Z1+1/Z2) mprintf("Applied voltage=%f V\n",V) //calculating power fa...
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clc; close; clear; mprintf('For 1st model:\n\n'); mprintf(' Total delay=T1\n'); mprintf(' T1=Rinv*C1+(Rinv+Rtg)*C2+(Rinv+2*Rtg)*C3\n'); mprintf(' Rinv=R and Rtg=R\n'); mprintf(' C1=(3*Ceff*W)+(Cg*W)+(2*Ceff*W)\n'); mprintf(' C2=(Cg*W*2)+(6*Ceff*W)\n'); mprintf(' C3=(4*Ceff*W)+(Cg*W)+(3*f*Cg*W)\n'); mpri...
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clc clear //INPUT DATA Ri=1.5//refractive index of thin film of glass n=30//number of fringes of sodium light is observed across the field of view t=0.018*10^-3//thickness of glass film in m //CALCULATION w=((2*(Ri-1)*t)/n)/10^-7//wavelength of the light used in m *10^-7 //OUTPUT printf('The wavelength of ...
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//Graphical// //Example 5.1.2 //Determination of N-point DFT //Plotting Magnitude and Phase spectrum clear; clc; close; L = 10; // Length of the sequence N = 10; // N -point DFT for n =0:L-1 x(n+1) = 1; end //Computing DFT and IDFT X = dft(x,-1) x_inv =abs(dft(X,1)) //Computing Magnitude and Phase Sp...
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//variable initialization interval_s=1 //time difference between two events in frame s (second) interval_sdash=4 //time difference between two events in frame s' (second) separation_s=0 //s...
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clc; clear; sw=64;//lb/ft^3; specific weight of water h=10;//ft a=3;//ft b=3;//ft //shape is triangular, hence hc=h-(a/3) hc=h-(a/3); A=(0.5*a*b);//ft^3; area of the right angled triangle fres=sw*hc*A;//lb Ixc=b*(a^3)/36; Ixyc=b*(a^2)*(b)/72; //according to the coordinate system taken yc=hc and xc=0 yres...
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//Scilab Code for Example 5.1 of Signals and systems by //P.Ramakrishna Rao //Discrete Time Fourier Transform of //x[n]= (a^abs(n)) 0<a<1 clear; clc; close; // DTS Signal a = 0.5; //0<a<1 max_limit = 10; n = -max_limit+1:max_limit-1; x = a^abs(n); // Discrete-time Fourier Transform Wmax = 2*%pi; ...
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func void Mission_Part1() var int nNode; var int ctID; { nNode := s_PNodeNULL(); nNode := p_AddCheckPoint (nNode, [1428, 164, -2403], 10, 0, 1, "Brief\part7.sc"); nNode := p_AddCheckPoint (nNode, [1170, 184, -4260], 10, 1, 0, "Brief\part6.sc"); /* nNode := p_AddCheckPoint (nNode, [2161, 170, -384...
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//Initilization of variables //here forces will be defines as matrices along with their co-ordinates //Force in N and co-ordinates in mm F1=[30 200 300] F2=[10 400 200] F3=[20 200 500] F4=[50 400 500] //Calculations //solving as system of linear equations A=[1 1 1;-600 -600 0;0 600 600] B=[F1(1)+F2(1)+F3(1)+...
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//acids and bases// //example 2.6// V1=50;//volume of Hcl in ml// V2=30;//volume of NaOH in ml// N1=1;//normality of Hcl// N2=1;//nomality of NaOH// V=V1+V2;//total volume of mixure of solutions// a=100;//percentage of ionization// N=(N1*V1-N2*V2)/V; printf('The normality of resultant solution is %fg.equivalen...
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//For 5 inch nominal pipe line, diameter D: Di=5.047; //Length of pipeline(in feet): L=6; //Operatng spped (in rpm): N=1750; //Water level abovepump centreline(in feet): h=3.5; //Temperature 1 of water(in Farenheit): T1=80; //Temperature 2 of water (in Farenheit): T2=180; //Volume flow rate of water(in gpm)...
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//Find (a) Av ¼ vds=vi; (b) Zin; (c) Zo looking back through the drain-source //terminals, and (d) Ai ¼ ii=iL. //Example 7.3 page no 208 clear clc Rl=14*10^3 rds=40*10^3 Rf=5*10^6 gm=1*10^-3 Av=((Rl*rds*(1-Rf*gm))/(Rf*rds+Rl*rds+Rl*Rf)) printf("\n The value of Av=%0.3f ",Av) Zin=(Rf/(1-Av))/1000 printf("\n ...
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//Example 2.6 (b) c=3*10^8; //velocity of light, m/s V= 0.5*c; //velocity of electron and positron, m/s y= 1/sqrt(1-(V/c^2)); //gamma, for relativistic momentum m=0.511/c^2; //MeV K= 2*y*m*V; //difference in momentum of both photons L= 2*y*m*c; //conservation of energy, sum of momentum of both photons p...
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function matrix = computeMatrix(mat) numRows = size(mat, 1) for i = 1:1:numRows if(mat(i, i) == 0 & i < numRows) then mat([i, i+1], :) = mat([i+1, i], :) end if(mat(i, i) <> 1) then mat(i, :) = mat(i, :)/mat(i, i) end prevNext = [1:(i-1) (i+1):numRows] mat(prevNext, :) = (-mat(prevNext, i)...
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Example_7_13.sce
//A Textbook of Chemical Engineering Thermodynamics //Chapter 7 //Properties of Solutions //Example 13 clear; clc; //Given: P = 20; //pressure in bar //Function for fugacity of component 1 function [y] = f1(x1); y = (50*x1)-(80*x1^2)+(40*x1^3) endfunction //To determine fugacity fugacity coeff...
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Ex4_13.sce
clear all; clc; disp("The specific speeds for all three options can be calculated") N_sa=3600*(500^0.5)/(350^0.75) printf("Nsa= %0.0f rpm*(gpm^0.5)/(ft^0.75)",N_sa) N_sb=4320*(500^0.5)/(350^0.75) printf("\nNsb= %0.0f ",N_sb) N_sc=3600*((500^0.5)/(175^0.75)) printf("\nNsc= %0.0f",N_sc) disp("From figur...
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Ch05Ex5.sce
// Scilab code Ex5.5: Pg:217 (2008) clc;clear; Lambda = 5e-05; // Wavelength of spectral line, cm n = 2; // Second order principal maxima theta = 30; // Direction of principal maxima, degree aplusb_inv = sind(theta)/(n*Lambda); // Number of lines in one cm of grating where a is the width of slit and b...
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10_01.sce
//Example No. 10_01 //Fitting a Straight Line //Pg No. 326 clear ;close ;clc ; x = poly(0,'x') X = 1:5 Y = [ 3 4 5 6 8 ]; n = length(X); b = ( n*sum(X.*Y) - sum(X)*sum(Y) )/( n*sum(X.*X) - (sum(X))^2 ) a = sum(Y)/n - b*sum(X)/n disp(b,'b = ') disp(a,'a = ') y = a + b*x
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4_7.sce
clc //Initialization of variables w1=100 //lbm w2=2 //lbm h1=127 //B/lbm h2=125 //B/lbm hc=401 //B/lbm //calculations ht1=w1*h1 ht2=w2*h2 ht3=(w1+w2)*hc Q=ht3-ht1-ht2 //results printf("Heat liberated = %d B/sec",Q)
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Ex25_4.sce
//chapter25 //example25.4 //page544 S=20 // kilo ohm per volt V_range=10 // V V=20 // V R=10 // kilo ohm R_meter=S*V_range R_equi=R+R*R_meter/(R+R_meter) I=V/R_equi V_reading=I*R*R_meter/(R+R_meter) printf("voltage read by multimeter = %.3f V \n",V_reading) // answer in book is 9.88V but accurate an...
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test_11.sce
// Test #11 : For complex vector inputs exec('./zpklp2mb.sci',-1); [z,p,k,n,d]=zpklp2mb([2*%i,4*%i],[4*%i,7.6*%i],1,0.2,[0.3 0.4]); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. - 0.8743054 0.9021130 //n=-0.9021130 0.8743054 - 1. //k=0.2733954 - 0.0862473i //p=0.4602843 + 0.838068...
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Ex14_16.sce
clear all; clc; disp("Scilab Code Ex 14.16 : ") //Given: I = 175.8*10^-6; //m^4 E = 200*10^6; //kN/m^2 Ra = 1;//kN l_ab = 3; //m l_bc = 6; //m //Virtual Work Equation: m1 = -1; //*x1 M1 = -2.5; //*x1^3 m2 = -0.5; //*x2 x10 = 0; x11 = l_ab; I1 = integrate('m1*M1*(x1^4)','x1',x10,x11); x20 = 0;...
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13_03.sce
clear clc //Bed voidage v=0.4; //Superficial velocity of fluid(cm/s) u=1.2; l=90;//length(cm) //Variance(sec^2) of output signals sigma1_sqr=39;sigma2_sqr=64; dsigma_sqr=sigma2_sqr-sigma1_sqr; //In dimensionless form t=l*v/u; sigmatheta_sqr=dsigma_sqr/t^2; //Dispersion number d=sigmatheta_sqr/2; printf("...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 6 Single Staje BJT Amplifiers Pg no. 204 clear; clc; //Given Data B=190;//current gain of single transistor //Solution Bac=B^2;//current gain of superbeta transistor if B is the gain of each of the employed transistor printf("Bac = %d",Bac);
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00REMESSA1 COBRANCA 00000000000000008911Condominio BLABLA 237237BRADESCO 200521 MX0000000 ...
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Ex11_1.sce
//Ex11_1 Pg-536 clc Vcc=15 //supply voltage in V R1=2*10^(3) //resistor R1 in ohm R2=470 //resistor R2 in ohm Rc=680 //collector resistor in ohm Rl=2.7*10^(3) //load resistor in ohm Re=220 //emitter resistor Idc=Vcc/(Rc+Re) //saturation current printf("(1) Idc_sat = %.1f mA \n",Idc*1e3) DCload=Rc //Dc ...
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16_2.sci
//16.2 clc; disp('For star connection') Zph=(12^2+5^2)^0.5; Eph=440/(3^0.5); Iph=Eph/Zph; Il=Iph; printf("\nLine current=%.2f A",I1) P_total=(3^0.5)*440*Il*12/(Zph*1000); printf("\nTotal Power=%.2f kW",P_total) disp('For Delta connection') Zph=(12^2+5^2)^0.5; Eph=440; Iph=Eph/Zph; Il=Iph*(3^0.5); print...
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10.sce
clc r1=0.06; //m r2=0.12; //m r3=0.16; //m k_A=0.24; //W/m 0C k_B=0.4; //W/m 0C h_hf=60; //W/m^2 0C h_cf=12; //W/m^2 0C t_hf=65; //0C t_cf=20; //0C L=60; //m Q=2*%pi*L*(t_hf-t_cf)/(1/h_hf/r1 + log(r2/r1)/k_A + log(r3/r2)/k_B + 1/h_cf/r3); disp("Rate of heat loss =") disp(Q) disp("W")
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load And2Bit.hdl, output-file And2Bit.out, output-list a0 a1 b0 b1 out0 out1; set a0 0, set a1 0, set b0 0, set b1 0, eval, output; set a0 0, set a1 0, set b0 0, set b1 1, eval, output; set a0 0, set a1 0, set b0 1, set b1 0, eval, output; set a0 0, set a1 0, set b0 1, set b1 1, eval, output; set a0 0, set a1 1, s...
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EX6_8.sce
// Example6.8 // determine the common mode rejection ratio CMRR clc; clear; close; // R2/R1 = 10 ; // R4/R3 = 11 ; // the output of the difference amplifier is given by // Vo = (((R4)/(R3+R4))*(((1+(R2/R1))*VI2))-((R2/R1)*VI1)); // putting R1 R2 R3 R4 value in above equation we get Vo as // Vo =(121/12)...
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//Ex19_19 Pg-965 clc hex='C5E2' //hexadecimal input dec=hex2dec(hex) //decimal output bin=dec2bin(dec) //binary output disp("The binary equivalent of C5E2 is") disp(bin)
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Ex7.2.sci
function y=locus1(z) s=%s H=syslin('c',1+(1/(s*(s+1)*(s+2)))); evans(H,z) printf("The branches of root locus starts with K=0 and poles s=0,-1,-2") printf("Since there is no open loop zero the branches terminate at infinity") y=0; endfunction
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//Ex_7_7 clc; clear; close; format('v',6); //given data : Beta=100;//unitless VBE=0.7;//V VCC=10;//V //(a) VE=-0.7;//V disp("For the circuit in fig(a)"); VE=-0.7;//V(Constant voltage) R1=10;//kohm R2=10;//kohm IE=(VCC+VE)/R2;//mA IB=IE/(Beta+1);//mA VC=VCC-R1*1000*(IE-IB)/1000;//V disp(VE,"Constant vo...
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clc mu_n=600 disp("mu_n = "+string(mu_n)+"cm^2(Vs)^-1") //initializing value of channel mobility kbT = 0.026 disp("kbT = "+string(kbT)+"eV") //initializing value of kbT at 300K apsilen = 11.9*8.85*10^-14 disp("apsilen = "+string(apsilen)+"F/cm") //initializing value of relative permitivity e = 1.6*10^-19 disp(...
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clc; funcprot(0); //Example 8.11 Absolute Coefficients with metric units // Initialisation of variables S = 35; V = 40; alpha = 4; rho = 0.125; // Calculations Cl = 0.76; // Value of Cl from fig 8.10 L = Cl*(rho/2)*S*V^2; //Results disp(L,"Required Lift (Kg):");
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//pathname=get_absolute_file_path('18.09.sce') //filename=pathname+filesep()+'18.09-data.sci' //exec(filename) //Operating temperatures(in K): T1=-15+273 T2=25+273 h2=1317.95 //kJ/kg s2=4.4809 //kJ/kg.K h3=99.94 //kJ/kg s3=0.3386 //kJ/kg.K h9=-54.51 //kJ/kg s9=-0.2132 //kJ/kg.K h4=h3 s8=s3 s4=0.3855 //kJ/...
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clc clear //Input data I=5;//Indicated power developed by single cylinder of 2 stroke petrol engine M=6.5;//Mean effective pressure in bar d=0.1;//Diameter of piston in m //Calculations A=(3.14*d^2)/4;//Area of the cylinder LN=(I*1000*60)/(M*10^5*A);//Product of length of stroke and engine speed S=2*LN;//Ave...
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clc;clear; //Example 23.1 //calculation of relative permittivity //given values E=1000;//electric field in V/m P=4.3*10^-8;//polarization in C/m^2 e=8.85*10^-12;//permittivity in F/m //calculation er=1+(P/(e*E)); disp(er,'relative permittivity of NaCl is ');
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//example 10.12 clc clear //pro= ('Enter the value to whic counter should progress:'); pro =11; // given input q=1; aa=pro; for i=1:4 //converting the given number in to binary x=modulo(aa,2); b(q)=x; aa=aa/2; aa=floor(aa); q=q+1; end bi=' '; // then print...
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 7.6 A=[2 0 4;-1 1 -2;2 3 3] disp(inv(A))
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clear; clc; uts=14740; a=538.4; E=7000; wc=1.805; p=100; l=335; alpha=19.3*10*(-6); fs=2; n=4; ds=3.35; d=(1+2*n)*ds; wh=(2/3)*d*p; //a). wr=sqrt((wc+wh)^2 + wh^2); T=(uts/fs); //bl=breaking load=uts fs=factor of safety printf("The maximum working stress is:%.2f kgf",T); sag=wr*l*l/(8*T); pr...
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//chapter 1 //example 1.16 //page 48,figure 1.59 Ie=400*10^-6; Bmin=80;Bmax=120; //Ie=Ie1+Ie2 for identical transistor Ie1=Ie2 Ie1=Ie/2 Ie2=Ie/2 IB1max=Ie1/(1+Bmin) IB2max=Ie2/(1+Bmin) IBmax=(IB1max+IB2max)/2; disp(IBmax)//largest input bais current IB1min=Ie1/(1+Bmax) IB2min=Ie2/(1+Bmax) IBmin=(IB1min+...
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// scilab Code Exa 18.29 Centrifugal compressor with vaned diffuser T01=310; // in Kelvin p01=1.103; // Initial Pressure in bar dh=0.10; // hub diameter in m d2=0.55; // impeller diameter in m c1=100; // Velocity of air at the entry of inducer c3=c1; // Velocity of air at diffuser exit shi=1.035; // power inp...
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yF = 50; xF = 0; vF = 20; t = 12 xB = [80, 90, 99, 108, 116, 125, 133, 141, 151, 160, 169, 179, 180] yB = [0, -2, -5, -9, -15, -18, -23, -29, -28, -25, -21, -20, -17] for i = 1: t+1 if i>12 then disp("Target escaped...") else Distance = sqrt(((yB(i)-yF)**2)+((xB(i)-xF)**2)) xF = (xF + vF*((xB(i)-xF...
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import elist.elist as elel from xdict.jprint import pobj,pdir from locs import * blk = creat_root_block((0,0),(5,5),(2,2)) get_pt_zone(blk,(0,0)) == 'zetl' get_pt_zone(blk,(5,0)) == 'zebl' get_pt_zone(blk,(5,5)) == 'zebr' get_pt_zone(blk,(0,5)) == 'zetr' get_pt_zone(blk,(-1,-1)) == 'zotl' get_pt_zone(blk,(6,-1)) == 'z...
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clear; clc; r1=.95; r2=.92; r3=.98; r4=.88 R=r1*r2*r3*r4; mprintf("\nNet system reliability = %.4f ",R);
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.33 // Page 272 printf("Example 5.33, Page 272 \n \n"); // solution // basis 1 kmol of SO2 reacted a = 22.036-24.771-.5*(26.026) b = (121.624-62.948-.5*11.755) c = (-91.876+44.258-.5*(-2.343)) d = (24.369-11.122-.5*(-.562)) ...
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//Example 6.9// current and phase angle errors clc; clear; Is=5;//IN AMPERES Ip=100;//primary current in amperes VA=20;//BURDEN xr=4;// mmfc=0.18;//mmf for core loss in AT Ep=VA/Ip;//voltage across primary winding d= atand(1/xr);//secondady phase angle in degree csd= cosd(d); sd=sind(d); Kt=20;// Knom=20 ...
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//Solution 2-6 WD=get_absolute_file_path('2_07_solution.sce') datafile=WD+filesep()+'2_07_example.sci' clc; exec(datafile) //conversion h = h /100; //from [cm] to [m] deltaP = rho * g * h deltaP = deltaP / 10**5; //conversion from [N/m^2] to [atm] printf("The pressure at top of water column is less than atm pressure b...
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s = poly(0, 's'); //Time Dt = 0.001; //time intervall t = 0:Dt:2; //Parameters from system identification part Kg = 0.1752; //q in slides xi = 1; o_n = 10.52; //Transfer function, look in 6 lecture. LM = Kg/(s ^ 2 / o_n ^ 2 + 2*xi/o_n * s + 1); G = syslin('c', LM); y = csim('step', t, G); //Controller Kc = 10; C =...
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BASELINE = baseline_watering.bsl DELAY UNTIL 1-04:30:00 WHENEVER smoist[0] < 450 and not already_watered WAIT wpump FOR 720 # Wait 12 minutes for water pump to be on SET already_watered = True WAIT not wpump FOR 13 # Turn pump off before 13 seconds have elapsed # Wait an hour for both moisture sensors to be ...
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 17.2 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given b=62.5e-6;//Outer radius of silica fiber in m R=30e-3;//Radius of the circular loop formed by the fiber in m lambda=633e-9;//Wavelength in m ...
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errcatch(-1,"stop");mode(2);//Example 1_19 ; ; //To find the diameter of 20th ring D4=0.4 //units in cm D12=0.7 //units in cm D20=sqrt(2*(D12^2-D4^2)+D4^2) printf("The diameter of the 20th dark ring is %.4f cm",D20) exit();
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//Exa11 clc; clear; close; //given data rho_i=2*10^-3; //in ohm-m (there is miss printed in this line in the book) sigma_i=1/rho_i; miu_e=0.3;// in m^2/V-s miu_h=0.1;// in m^2/V-s e=1.6*10^-19; // in C // Formula sigma_i=nita_i*e*(miu_e+miu_h) nita_i=sigma_i/(e*(miu_e+miu_h)); disp("Carrier density is : "...
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//C-Exercise22 //Jurain Kahl //Nattawut Phanrattinon funcprot(0); exec("CompFin_2019_SS_BS_Price_Int.sce") //computes the initial price of European call options with identicall maturity T and strikes K = (K1, ..., Kn) function V0 = BS_EuCall_FFT (S0, r, sigma, T, K, R, N, M, kappa1) //model parameters delta and ka...
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function I = ajeita(I) // I = I - min(I); I = I / max(I); I = round(I*255+1); endfunction
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//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 310 clear; clc; //Given VCC=15;//collector supply voltage in volts RC=2.2D3;//collector resistance in ohms RE=470;//emitter resistance in ohms R1=33D3;//divider network resistance R1 in ohms R2=10D3;//divider network r...
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function gaussian_elimination(a,b) [m,n]=size(a); if m~=n then error('Matrix A must be square matrix'); abort; end b=b'; [r,c]=size(b); if m~=r then error('Incompatible orders of A and b'); abort; end a=[a b]; for j=1:n-1 ...
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//Exa:1.33 clc; clear; close; I_f=100;//in amperes V=220;//in volts N=1000;//in rpm T_f=V*I_f/(2*%pi*N/60);//Full load torque (N-m) E_bf=V;//Back emf (in volts) V_a=V+E_bf;// Voltage across armature (in volts) I_b=2*I_f;//braking current R=(V_a/I_b);//in ohms disp(R,'Value of external resistance (in ohms)='...
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//chapter 7 //example 7.1 //Calculate the capacitance of capacitor and charge on the plates //page 187 clear; clc; //given A=100; // in cm^2 (cross-sectional area) d=1; // in cm (seperation between plates) Eo=8.85E-12; // in F/m (absolute permittivity) V=100; // in V (potential difference) //calculate A=A*1...
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// Scilab code Exa4.7.3: To determine the fission power produced by one microgram of Fm-256 : Page 190 (2011) N = 6.023e+023/256*10^-6; // Number of nuclei in 1ug of Fm-256 t_h = 158*60; // Half life of Fm-256, s D_c = log(2)/t_h; // Decay constant, s^-1 F_r = N*D_c; // Fission rate, fissions/s E = 220*1.6e-013; ...
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//Calculate the minimum clearance of conductor and water clear; clc; //soltion //given W=1.5;//kg/m//Line conductor wieght L=500;//meter//span of the line T=1600;//kg//max allowable tension T1=30;//m//height of the tower 1 T2=90;//m//height of the tower 2 h=T2-T1;//m//difference in the between support printf...
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errcatch(-1,"stop");mode(2);//Initialisation of variables l=3e-3//vibrating length E=8e10//young modulus d=2500//kg per m3 N=(1/(2*l))*sqrt(E/d) printf('frequency is %e Hz \n',N) exit();
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// Example 9.2 // Computation for VCEQ and re' for case(a),o/p overall gain, gain,i/p resistance, overall current gain & o/p resistance for case(b),minimum value of Ce for case(c)// // Page no.370 clc; clear; close; //Given data hFE=100; hfe=150; Rc_A=2.2*10^3; VBB=2.79; VBEQ=0.7; Rb=7.67*10^3; Re1=0; Re2=2.2*10^3; V...
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<?xml version="1.0" encoding="utf-8"?> <test> <description> Process 2D vorticity output </description> <executable python="true">bfs_vort.py</executable> <parameters></parameters> <files> <file description="Session File">bfs_tg.xml</file> <file description="Session File">bfs_tg.fld</file> <...
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clc; // page no 126 // prob no 3.10 f_car=8*10^6;f_mod1=2*10^3;f_mod2=3.5*10^3; //Signal is LSB hence o/p freq is obtained by subtracting f_mod from f_car f_out1=f_car-f_mod1; disp('MHz',f_out1/(10^6),'The o/p freq f_out1 is '); f_out2=f_car-f_mod2; disp('MHz',f_out2/(10^6),'The o/p freq f_out1 is ');
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clear; clc; //1. create and Display Office Topology NameOfNetwork='office Topology';// Name of your network NumberOfNodes=input("Enter number of nodes");//Number of Nodes in the network ConnectionEndingNode=[1 2]; //Ending Nodes of the connection lines ConnectionStartingNode=[1 2];//Ending Nodes of the...
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//Chapter-1,Example1_2_8,pg 1-16 V=0.2 //volume of oil A=10^4 //area t=V/A //Thickness of oil film r=0 //for normal incidence n=1 //for 1st dark band wavel...
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clear // // // //Variable declaration n1=1.53 //Core refractive index delta=0.0196 //relative refractive index difference //Calculation NA=n1*sqrt(2*delta) //numerical aperture thetaa=asin(NA)*180/%pi //acceptance angle(degrees) //Result printf("\n numerical aperture is %0.3f ",NA) printf("\n...
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// Scilab code Ex1.2: : Pg:19 (2008) clc; clear; V = 100; // potential difference, volt Lambda = 12.25/sqrt(V); // de Broglie wavelength, angstorm printf("\nThe de-Broglie wavelength of an electron = %5.3f angstorm", Lambda); // Result // The de-Broglie wavelength of an electron = 1.225 angstorm
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clc //to calculate relative intensities //Imax/Imin=(a1+a2)^2/(a1-a2)^2+105/95 //(a1+a2)/(a1-a2)=1.051 //we get a1/a2=40 a1=40 //a1=40*a2 a2=1 disp("the ratio of the intensities of interfering sources is I1/I2=a1^2/a2^2="+string(a1^2/a2^2)+"unitless") //answer is given in terms of ratio in the book
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//Example 16_5 clc(); clear; //To find the work done in carrying a proton and for an electron q=1.6*10^-19 //Units in C vab=9 //Units in V work=q*vab //Units in J printf("The work done in carrying proton is=") disp(work) printf("Joules\n") q=-1.6*10^-19 //Units in C work=q*vab //Units in J...
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clc; clear; //Example 2.41 //Given rho=9000 //kg/cubic meter Cp=0.38 //kJ/(kg.K) Cp=Cp*1000 //J/kg.K k=370 //W/(m.K) T0=483 //K T_inf=373 //K delta_T=40 //K T=T0-delta_T //K t=5 //time in [minutes] t=t*60 //[seconds] //A=2A.....Two faces //V=A.2x //2x=thickness of slab=30 mm=0.03 m ...
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clc; clear all; disp("Ingot velocity ") D=10/100;//m Diameter of cylindrical ingot L=30/100;//m ti=1250;// degree C t=800;// degree C ta=90;// degree C k=40;// W/m.C h=100;// W/m^2.C a=1.16*10^(-5);//m^2/s Lc=D*L/(4*L+2*D);//m Lc Bi=h*Lc/k; disp(Bi,"Bi =") //(t-ta)/(ti-ta)=exp(-a*h*As*tau/(k*V)) //h*As/...
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mu_not=4D-7*%pi Ns=400//no. of turns on search coil N=1000//no. of turns of wire on solenoid M=mu_not*Ns*N*25D-4/80D-2 mprintf("Mutual inductance of arrangement=%f mH\n",M*1000) //di/dt=200 e=-M*200 mprintf("emf induced in search coil=%f V",e)
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clc; printf("\n Example 4.3\n"); Q=50; //volumetric flow rate of methane P=101.3e3;//Given Pressure T1=288;//Given Temperature d=0.6;//Diameter of pipeline l=3e3;//length of the pipe line R_R=0.0001;//Relative roughness P2=170e3;//Pressure at which methane is to be discharged T2=297;//Temperature at which ...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 1: Electromechanical Fundamentals // Example 1-4 clear; clc; close; // Clear the work space and console. // Given data v = 1.5; // v = velocity in m/s with which the conductor is moving l = 0.4;...
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// Exa 1.25 clc; clear; close; // Given data R1= 1;// in kΩ R2= 0.47;// in kΩ V_o1 = 0.7;// in V disp(V_o1,"The value of Vo1 in V is"); V_o2 = 0.3;// in V disp(V_o2,"The value of Vo2 in V is"); I1 = (20-V_o1)/R1;// in mA I2 = (V_o2-V_o1)/R2;// in mA I = I1 + I2;// in mA disp(I,"The current in mA is");
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//Example No. 4.4 clc; clear; close; format('v',6); //Given Data : T=110;//min Tdash=150;//min t=30;//min tdash=45;//min theta_f=50;//degree C //theta=theta_f-(theta_f-theta1)*exp(-t/T) //theta1=theta*exp(-tdash/Tdash); theta=(theta_f-theta_f*exp(-t/T))/(1-exp(-tdash/Tdash)*exp(-t/T));//degreeC disp(th...
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// Scilab Code Ex10.2: Page-507 (2011) clc;clear; q1 = 1e-009; // Charge at first corner, C q2 = 2e-009; // Charge at second corner, C q3 = 3e-009; // Charge at third corner, C d = 1;....// Side of the equilateral triangle, m theta = 30;....// Angle at which line joining the observation point to the sour...
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//chapter 19 //example 19.27 //page 883 printf("\n") printf("given") Rw=.1;f=1*10^6;Lp=19.5*10^-6;Rl=1.2*10^3;Vcc=30;Idc=12.3*10^-3; QL=(2*3.14*f*Lp)/Rw Qp=Rl/(2*3.14*f*Lp) B=f/Qp Il=(.707*Vp)/(2*3.14*f*Lp) Pl=(Il)^2 *Rw Pi=(Vcc*Idc)+Pl n=(Po/Pi)*100
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//Example 4.24 //Use of field width and precision specification with string output line = input("Enter string(upto 12 characters): ", "string"); printf("%10s % 15s %15.5s %.5s", line, line, line, line);
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// PG (21) deff('[y]=f(x)','y = x^3-3*x^2+3*x-1') xset('window',0); x=-0:.01:2; // defining the range of x. y=feval(x,f); a=gca(); a.y_location = "origin"; a.x_location = "origin"; plot(x,y) ...
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m = mode(); mode(-1); // the position error between the current and final positions for the end effector // // CPosition: Cartesian coordinates of the current position. // FPosition: Cartesian coordinates of the end point. function result = F1(CPosition, FPosition) try positions = [CPosition; FPosition];...
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// Exa 6.13 clc; clear; close; // Given data V_S = 1.7;// in V R_S = 0.51;// in kohm R_S= R_S*10^3;// in ohm V_DD = 18;// in V R_D = 2*10^3;// in ohm V_GS = -1.7;// in V V_P = - 4.5;// in V I_DQ = V_S/R_S;//in A disp(I_DQ*10^3,"The value of I_DQ in mA is"); V_GSQ = -V_S;// in V disp(V_GSQ,"The value of V...
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z = %z; syms n z1;//To find out Inverse z transform z must be linear z = z1 X =z^2/((z-(1/4))*(z-(1/2))) X1 = denom(X); zp = roots(X1); X1 = z1^2/((z1-(1/4))*(z1-(1/2))) F1 = X1*(z1^(n-1))*(z1-zp(1)); F2 = X1*(z1^(n-1))*(z1-zp(2)); h1 = limit(F1,z1,zp(1)); disp(h1,'h1[n]=') h2 = limit(F2,z1,zp(2)); disp(h2,...
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//Optoelectronics and Fiber Optics Communication by C.R. Sarkar and D.C. Sarkar //Example 2.2 //OS = Windows 7 //Scilab version 5.5.2 clc; clear; //given n1=1.48;//core refractive index of a step-index fiber delta=0.015;//relative index difference between the core and cladding lamda=85*10^-8;//wavelength ...
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//Example 1_2 page no:23 clc; //given //solving a sub part voltage = 500;//in v current = 32;//in A arm_res = 0.4;//in ohm fl_win_res = 250;//in ohm rpm = 450; field_current = 2; input_pow = (voltage*current)/1000; arm_current = current - field_current; //when running at 600rpm rpm1 = 600; k_phi = (voltag...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <!DOCTYPE AUTOTEST> <AutoTest version="2.0.0" wavetype="5"> <Pulse>Pulse 4</Pulse> <Title>12V Class C</Title> <Organization>IVECO</Organization> <Standard>16-2103 2007</Standard> <Item>5.2.8.1 Test pulse 4a</Item> <system> <PowerSys...
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clc; clear; unit_cell_edge_x=(2) //intercept of x unit_cell_edge_y=(-3) //intercept of y unit_cell_edge_z=(6) //intercept of z //calculations Reciprocal_x=1/unit_cell_edge_x //reciprocal value of miller index x Reciprocal_y=1/unit_cell_edge_y //reciprocal value of miller index y Reciprocal_z=1/unit_cell_edge_...
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//chapter 2 //may june 2013 //Aem=Gdmax*lamda^2/4*pi; printf("\n"); Gdmax=1.5;//for half wave dipole f=10^9; c=3*10^8; lamda=c/f; Aem=(Gdmax*(lamda)^2)/(4*(%pi)); printf("the effective aperture is %gm^2",Aem);
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function [x,y,t]=getoutputs(o) execstr('[x,y,t]='+o(5)+'(''getoutputs'',o)')
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//Problem 1.2 h1=0.75 //atm pressure in term of mercury w=9810 w1=13.6*w //specific weight of mercury Patm=w1*h1 w2=15000 h2=3 // p=w2*h2 // gauge pressure Pabs=Patm+p disp(p,"gauge pressure(N/m2)") disp(Pabs,"absolute pressure(N/m2)")
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//Variable declaration Id=1.6 //drain current(mA) Vgs=-3 //gate to source voltage(V) Id1=.4 //drain current(mA) Vgs1=-4 //gate to source voltage(V) Vp=-5 //peak voltage(V) by solving equations 1.6=Idss(1+3/Vp)^2 and .4=Idss(1+4/Vp)^2 Idss=10 ...
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//Initilization of variables W=100 //lb lo=4 //ft theta=45 //degrees g=32.2 //ft/s^2 l=8/3 //ft //Calculations //Taking moment about point O and equating it to zero alpha=(W*(lo*0.5)*cosd(theta))/((W/g)*(l)*2) //rad/s^2 //Summing forces in the t direction Ot=(W*cosd(theta))-((W/g)*lo*0.5*alpha) //lb //Work D...