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Exa_3_12.sce
//Exa 3.12 clc; clear; close; format('v',5); //Given Data : T1=24+273;//K T2=10+273;//K Q1=1500;//kJ/min Q1=Q1/60;//kW COP_ideal=T1/(T1-T2); ActualCOP=COP_ideal*30/100; W=Q1/ActualCOP;//kW disp(W,"Power required in kW : "); //Answer is wromg in the book as calculation for Q1 is wrong.
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clc; //page no 648 //prob no. 17.9 //A pulse magnetron with avg power=1.2kW & peak power=18.5kW & 1 pulse is generated every 10ms Pavg=1.2*10^3;Pp=18.5*10^3;Tt=10*10^-3; //Determination of duty cycle D=Pavg/Pp; disp(D,'The duty cycle is'); //Determination of length of pulse Ton=D*Tt; disp('sec',Ton,'The lengt...
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clc //initialisation of variables Q= 1100 //cuses i= 1/1800 C= 95 n= 1.5 //CALCULATIONS d= ((Q*sqrt(3600)/C)/(n+0.6))^0.4 b= 0.6*d ht= b+2*(n*d) //RESULTS printf ('Depth = %.2f ft ',d) printf ('\n Bottom width = %.2f ft ',b) printf ('\n Top width = %.2f ft ',ht)
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clc clear dib=[5 12 6.8 7.4 23 15 18 48 12 14 23 22 29 15 9.3 15 13 16 22 19 35 30 35 33 30 35; 13 20 14 16 15 8.1 11 50 5.1 5.5 16 15 22 5.6 5.3 11 18 19 23 20 36 31 36 34 22 39; 23 34 29 24 8.6 4.9 4.1 4.1 14 8.5 3.1 2.4 7.4 12 13 13 22 23 15 18 20 17 18 19 9.3 23; 16 27 23 14 23 13 14 14 17 11 7.4 8.1 13 6.3 9.8 4....
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// calculating static error and static correction clc; disp('calculating static error and static correction') Am = 0.000161; At = 0.159*10^-3; e=Am-At; disp(e,'Static error(m3/s)='); Sc=-e; disp(Sc,'Static Correction(m3/s)=');
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01genTestDistribs.sce
clear all; rand("seed",123456); rand("uniform"); X=rand(20,1); X=1 + X*(10-1); rand("654321"); rand("normal"); // Générer le bruit epsilon=rand(20,1); epsilon=epsilon*8.0; d1true=10 + 100*X; d1 = d1true + epsilon; d2true = 10+100*X - 4.9*X^2; d2= d2true + epsilon; // Save d1 save("d1.dat", "X", "d1"); // Save ...
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Chapter2_Example22.sce
clc clear //INPUT DATA //C8H18+12.5(O2+3.773N2)=8 CO2 +9 H2O +47.16 N2 ;//FUEL COMPOSITION n=60.66;//number of moles of air //CALCULATIONS n1=8+9+47.16;//number of moles of air and product xs= 15.14/1;//air fuel ratio xs1=1/xs;//fuel air ratio Mr=(1/n)*(114.15+59.66*28.96);//Molecular weights of reactants M...
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12_4.sce
clc //initialisation of variables p=60//in h=20//percent a=1000//ft h1=40//percent c=0.5//ft p1=14.3//ft p2=6.1//ft d=11.7*10^-2//ft //CALCULATIONS P=p2/p1//ft D=d*p//ft //RESULTS printf('the air valve with a discharge the change in slop=% f ft',D)
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6_1.sce
clear; clc; // Illustration 6.1 // Page: 324 printf('Illustration 6.1 - Page: 324\n\n'); // solution //*****Data*****// // n-heptane - a n-octane - b T1 = 303; // [K] P = 1; // [bar] D = 0.6; W = 0.4; zf = 0.5; // Parameters for componenr 'A' Tc_a = 540.3; // [K] Pc_a = 27.4; // [bar] A_a...
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// ne s'affiche pas, matrice trop grosse // Test avec la matrice suivante : K3 = [ 11 -1 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 -1 -1 -1 0 0 0 0 0 0 0 0 0 -1 -1 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 -1 -1 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0...
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// Example 2.14 clc; clear; close; // Given data format('v',6); Vpp= 3;// output voltage in V del_t= 4;// in µs del_V= 90*Vpp/100-10*Vpp/100;// in V // Required slew rate, SR= del_V/del_t;// in V/µs disp(SR,"The required slew rate in V/µs is : ");
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//calculate constants of equivalent circuit of line clear; clc; //soltion //FUNCTIONS function [z]=rxr(A,B)//Function for the multiplication in rectangular form z(1)=A(1)*B(1) z(2)=A(2)+B(2) endfunction function [z]=rdr(A,B)//Function for the division in rectangular form z(1)=A(1)/B(1) z(2)...
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clc; //page 365 //problem 6.4 //Given energy per bit Eb = 0.01 Eb = 0.01; //Given fundamental frequency is fb = 8 KHz fb = 8*10^3; //No of symbols M = 16 M = 16; N = log2(M); BW_BPSK = 2*fb; disp('Bandwidth for BPSK is '+string(BW_BPSK)+'Hz'); BW_QPSK = fb; disp('Bandwidth for QPSK is '+string...
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even odd.sci
disp("Input 10 number:") n = 10 //number of inputs for i=1:n x(i) = input('') end even_sum = 0 //variable for all the sum of even nos. even_count = 0 //count for even numbers recorded odd_sum = 0 //variable for all the sum of odd nos. odd_count = 0 //count for even numbers recorded for i=1:n if modulo(x(i),2)...
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Final Project.sce
clear; clc; //***************************************Taking Input From the user to know which Application he/she would like to perform********************************************* n=x_dialog('1. A 2 digit number recongnization 2. AC Remote (on/off) || Enter any Number:','1') //*********************************...
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EX3_14.sce
// Exa 3.14 format('v',6) clc; clear; close; // Given data v = 1/(20 * 10^-6);// in cm/sec E = 10;// in V/cm Mu= v/E;// in cm^2/V-sec disp(Mu,"The mobility of minority charge carrier in cm^2/V-sec is ");
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Ex21_2.sce
//Ex21_2 Pg-1068 clc disp("Refer to figure 21.12") R1=20000 //timing resistor R1 in ohm R2=R1 //timing resistor R2 in ohm C=0.1*10^(-6) //capacitance in farad tau=0.69 //time constant tHIGH=tau*(R1+R2)*C //time output that will remain high printf(" Time output = %.2f msec",tHIGH*1e3)
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//Exa 4.3 clc; clear; close; //Investment proposal A : P1=-10000;//in Rs P2=3000;//in Rs P3=3000;//in Rs P4=7000;//in Rs P5=6000;//in Rs i=18;//in % per annum //Formula : (P/F,i,n) : 1/((1+i/100)^n) PW_A=P1+P2*1/((1+i/100)^1)+P3*1/((1+i/100)^2)+P4*1/((1+i/100)^3)+P5*1/((1+i/100)^4);//in RS disp(PW_A,"The ...
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// Scilab code Ex5.7: Pg.209 (2008) clc; clear; e = 1.6e-19; // Charge on electron, C h_cross = 1.055e-034/e; // Reduced plank's constant, eV-s c = 3e+17; // Velocity of light, nm/s E = 0.511e+06; // Energy of electron, eV L = 0.1; // Length of box, nm E_z = (h_cross*c)^2/(2*E*L^2); // Zero poi...
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// Example 3_9 clc;funcprot(0); // Given data v=10;// The volume of the tank in m^3 rho_s0=3.0;// The initial salt density in kg/m^3 t=0;// Time in s Q=0.01;// The volume flow rate in m^3/s // Calculation // (b) // V=Q*t; V=v*log(2);// printf("\nThe volume of fresh water,V=%0.3f m^3",V);
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clc; m=18; // mass flow rate of air in kg/s p1=3.6; // Pressure of fluid at inlet of turbine in MPa T1=800; // Temperature of fluid at inlet of turbine in Kelvin V1=100; // Velocity of fluid at inlet of turbine in m/s V2=150; // Velocity of fluid at outlet of turbine in m/s W=3.6; // Power output of turbine in M...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv // aux functions to sum of absolute errors // it is necessary to install the "diffcode" package using ATOMS in Scilab // smooth functions according to Go...
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ns=0.035; ps=ns*10^3; disp("the value (in ps) is"); disp(ps); mus=ns*10^(-3); disp("the value (in μs) is"); disp(mus);
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clc clear //INPUT DATA nv=0.8;//volumetric efficiency in percentage vc=3;//clearence volume in litre p2=8;//air compressor pressure in bar p1=0.98;//air compressor pressure in bar //CALCULATIONS vs=12.085/(1-nv);//stroke volume in m^3 d=((vs/1000)*4/3.14)^(1/3);//cylinder length in m //OUTPUT printf('(i)...
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// Example 6.12;//Cavity length and longitudinal modes clc; close; clear; h=0.87*10^-6;//Wavelength in meter n=3.6;//refractive index df=278;//frequency sepration in Gega Hertz C=3*10^8;//Speed of light in m/s L=(C/(2*n*df*10^9))*10^4;//Length of cavity in cm q=(2*n*L*10^-2)/(h);//Number of logitudinal modes ...
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// 10.11.13 function Out=Flattenlist(varargin) Out=list(); for N=1:length(varargin) D=varargin(N); if type(D)~=15 Out($+1)=D; else for I=1:length(D) Ds=D(I); Tmp=Flattenlist(Ds); Out=lstcat(Out,Tmp); end; end; end; endfunction;
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clc cp=1.005; //kJ/kg K T_A=333; //K T_B=288; //K p_A=140; //kPa p_B=110; //kPa //h=cp*T //v/T=0.287/p ds_system=integrate('cp/T', 'T', T_A, T_B) + integrate('0.287/p', 'p', p_A, p_B); ds_surr=0; ds_universe=ds_system+ds_surr; disp("change in entropy of universe = ") disp(ds_universe) disp("kJ/kgK") disp(...
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errcatch(-1,"stop");mode(2); A=[3 2 2;1 3 1;5 3 4] C=[3 4 2;1 6 1;5 6 4] disp("AB=C -->B=inv(A)*C") B=inv(A)*C exit();
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//Transport Processes and Seperation Process Principles //Chapter 1 //Example 1.6-1 //Introduction to engineering principles and units //given data //heat reqd= mCp)(delta T) //a) 298-673K m=3;//m is given as 3 g mol H1= m*29.68*(673-298);//for N2 at 673K Cp=29.68 J/g mol K //b) 298-1123K H2=m*31*(1123-298);/...
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// example:-11.7,page no.-625. // program to design an amplifier to have a gain of 11 dB at 4 GHZ. s11=0.75*expm(%i*(-120)*%pi/180); s21=2.5*expm(%i*(80)*%pi/180); s12=0; s22=0.6*expm(%i*(-70)*%pi/180); Gsmax=1/(1-abs(s11)^2); Gsmax=10*log10(Gsmax); Glmax=1/(1-abs(s22)^2); Glmax=10*log10(Glmax); Go=abs(s21)^2...
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clear// //Variables hie = 1100.0 //hie (in ohm) hre = 2.5 * 10**-4 //hre hfe = 50.0 //Current gain hoe = 24.0 * 10**-6 //hoe (in Ampere per volt) rL=10.0*10**3;RL=10.0*10**3; RS = 1.0 * 10**3 //Sourc...
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clc;clear; //Example 4.15 //given data E=75;//in Cal/day //calculation Ereduced=E*365; //The metabolizable energy content of 1 kg of body fat is 33,100 kJ Ec=33100; mfat=Ereduced/Ec*4.1868; disp(mfat,'weight this person will lose in one year in kg')
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//Example 1_2 page no:21 clc; I8=20/8; I15=(2.5*11)/(11+28); V28=0.71*28; V19=2.5*19; emf=V28+V19;//calculating the emf disp(I8,"the current flowing through 8 ohm resistor is (in A)"); disp(I15,"the current flowing through 15 ohm resistor is (in A)"); disp(V28,"the voltage across 28 ohm resistor is (in V)"); ...
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clear;lines(0); A=diag([-0.9,-2,2,0.9]);X=rand(A);A=inv(X)*A*X; [U,d]=schur(A,'c'); A1=U'*A*U; spec(A1(1:d,1:d)) //stable cont. eigenvalues [U,d]=schur(A,'c'); A1=U'*A*U; spec(A1(1:d,1:d)) //stable disc. eigenvalues
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// Given:- // Analysis // State 1 is the same as in Example 8.3, so h1 = 3348.4 // in kj/kg s1 = 6.6586 // in kj/kg.k // State 2 is fixed by p2  2.0 MPa and the specific entropy s2, ...
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//Ex 3.2 clc;clear;close; Vin=2.5;//mV R1=2;//kohm Rf=200;//kohm G=-Rf/R1;//Gain Vo=G*Vin/1000;//V disp(Vo,"Output Voltage(V) : ");
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// Implementation of example 6.5 // Basic and Applied Thermodynamics by P.K.Nag clc clear T1 = 473; //K T2 = 293; //K T3 = 273; //K //let Q1 be any constant Q1 = 1; Q2 = Q1*T2/T1; W = (T1 - T2)*Q1/T1; //COP = T2/(T2 - T3) = Q'/W Q2_ = T2/(T2 - T3) * (T1 - T2)/T1 * Q1; MF = (Q2 + Q2_)/Q1; //multiplica...
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// Returns a new optimal camera matrix // // Calling Sequence // new_cameraMatrix = initCameraMatrix2D(Size,objectPoints,imagePoints,ImageSize_width,ImageSize_height,aspectRatio); // // Parameters // Size : Number of vectors of calibration points and its projections // 0bjectPoints : This is a vector of vector of cal...
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// Scilab Code Ex9.2 Specific heat of copper from Debye temperature: Page-311(2010) h = 6.626e-034; // Planck's constant, joule second k = 1.38e-023; // Boltzmann constant, joule/mol/kelvin T = 30; // Given temperature, kelvin N = 6.023e+023; // Avogadro's number R = N*k; // Universal gas constant, ...
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//Ex 2.10 page 73 clc; clear; close; R=10;// ohm L=0.1;// H delta_i=20/1000;// A Vs=230;// V4 f=50;// Hz theta=45;//degree delta_t = L*delta_i/Vs; // s delta_t = delta_t*10**6;// micro s printf('Minimum gate pulse width = %.1f micro s',delta_t)
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mode(2);errcatch(-1,"stop");driver("GIF"); //determine the voltage sin wave f=50 V=50 Vm=V*1.414 w=2*3.14*f t=(0:0.1:5*%pi)'; plot2d1('onn',t,[5*sin(t)]) disp('voltage equation v=70.7sin(314)t') xinit('/home/fossee/Downloads/tbc_graphs/Engineering_Basics_T._Thyagarajan_1853/Ex4_2');xend();exit();
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//Chapter 7,Example 7.6 Page 228 clc clear e0 = 50 x = 50 R = 6 Z = 400 v = 3*10^5 //(i)Value of the voltage wave when it has travelled through a distance of 50 km pow = (-1/2)*(6/400)*50 e = e0*exp(pow) //(ii)The power loss and the heat loss PL = e^2*1000/Z // power loss t = x/v i0 = e0*1000/Z HL = -x*i0*Z*(exp(-0.75)...
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//To plot different types of histograms in a graphics window d=rand(1,10000,'normal'); // the Gaussian random sample subplot (2,2,1); histplot (20, d); xtitle ("Normalised Histogram"); subplot (2,2,2); histplot (20, d, normalization=%f); xtitle ("Regular Histogram"); subplot (2,2,3); histplot (20, d, style=5);...
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clc disp("Example 2.3") printf("\n") printf("Given") disp("Capacitance used is 20uF") disp("Voltage is v=50*sin(200*t)") C=20*10^-6; // Given that v=50*sin(200*t); vamp=50; t=0:0.001:0.015; //q=C*v qamp=vamp*C q=qamp*sin(200*t) //i=C*d/dt(v) //d/dt(sin 200t)=200*cos t iamp=C*vamp*200; i=iamp*cos(200*t) ...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 7: PARALLEL OPERATION // Example 7-11 clear; clc; close; // Clear the work space and console. // Given data // writing supply voltage in exponential form as follows // %pi/180 for degrees to radi...
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//Electric Drives:concepts and applications by V.subrahmanyam //Publisher:Tata McGraw-Hill //Edition:Second //Ex1_12 clc; clear; Sf=0.04;//Full load slip in % I=5;//Current in A Tst=(I)^2*Sf; x=((2/I)*100)^(1/2); T=(2/I)^2*(I)^2*Sf; disp(T,"Torque in Nm is:")
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// Scilab code Ex14.4: Pg 513 (2005) clc; clear; m = 1; // Mass of Uranium taken, kg Q = 208; // Disintegration energy per event, MeV A = 235; // Mass number of Uranium N = (6.02e+23*m)/A; // Number of nuclei E = N*Q; // Disintegration energy, MeV printf("\nThe total energy released if %1d kg of Urani...
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clc // Example 4.6.py // Consider a 15 deg half angle wedge at zero angle of attack in a Mach 3 flow of // air. Calculate the drag coefficient. Assume that the pressure exerted over the // base of the wedge, the base pressure, is equal to the free stream pressure. // Variable declaration M1 = 3.0 // ups...
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clc // Given That r = 10/7 // ratio of nth ring diameter for two media // Sample Problem 43 on page no. 1.55 printf("\n # PROBLEM 43 # \n") R = (1/r)^2 // calculation for the ratio of refractive index of media printf("\n Standard formula used \n mu1/mu2 = D2/D1. \n") printf("\n the ratio refractive index of media = %...
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load Resta.hdl, output-file Resta.out, output-list s%B1.16.1; set al %B1001011010110101, set ah %B1010110101101101, set bl %B0010110100101011, set bh %B0101101010010110, eval;
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clc; l=0.5; // length of conductor lying along Y-axis B=1.2; // Flux density along the X-axis v=2; // velocity of conductor //e=Blv; for maximum induced emf all the three quantities should be perpendicular to each other e=B*l*v; printf('Maximum induced EMF in conductor is %f V',e);
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// Example no 6.1 // To compute the carrier power, percentage of total power in carrier power and power in each sideband. // Page no. 260 clc; clear all; // Given data PAM=10*10^3; // Power of transmitted AM signal k=0.6; ...
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//Example 9.7// cavity gain clc; clear; close; x=0.5;// y=(1-(sqrt(x)))/(1+sqrt(x));// g=(y/(1-y)^2);// disp("cavity gain is "+string(g)+"/(sqrt(R1*R2))")
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function fig_handle=pkgBuildFrame() fig_handle = figure('dockable','off',.. 'figure_name','Scilab Atoms Package Creator',.. 'tag','pkgMainWindow',.. 'figure_size',[600,600],.. 'menubar_visible','off',.. 'toolbar_visible','off',.. 'infobar_visible','on',.. 'resize','on',.. 'visible','off',.. 'layout'...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat transfer, Seventh Edition, Frank Kreith, Raj M Manglik and Mark S Bohn, Chapter 10, Example 2") //density of saturated liquid in kg/m^3 rho_l=962; //gravitational acceleration in m/s^2 g=9.8; ...
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//Chapter-5,Example 3,Page 122 clc(); close(); t=[75 119 183] //time in minute V=[24.20 26.60 29.32] //volume of alkali used V_0=19.24 V_a=42.03 k=(2.303 ./t).*log10((V_a-V_0)./(V_a-V)) printf('values of k') disp(k) printf('since k values are fairly constant by putting in 1nd order rate...
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// Exa 2.1 clc; clear; // Given // A wien bridge oscillator under consideration R = 55*10^3; // Resistance in Ohms // R = R1 = R2 ... given C = 800*10^-12; // Capacitor in Farad // C = C2 = C1 .. given // Solution f = 1/(2*%pi*R*C) ; printf(' The frequency of oscillations = %.1f Hz \n',f);
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5_9.sce
//Example 5.9 //Modified Newton Raphson Method //Page no. 165 clc;clear;close; deff('x=f(x)','x=exp(x)-3*x-sin(x)') deff('x=f1(x)','x=exp(x)-3-cos(x)') printf('n\txn\t\t\f(xn)\t\tf1(xn)\t\tXn+1\t\tError\n') printf('--------------------------------------------------------------------------------------------------...
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//Example 6.2, page 126 clc k=1/.5 v=1/.2 v1=-4-5 p=-2*k s1=-(1/v1) m=-(5/v1) printf("The power is %f D", p) printf("\n The position of image is formed at %f m",s1) printf("\n The magnification of image is %f cm",m)
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//Chapter 3, Example 3.5, page 74 clc //Initialisation No=1 //index of refraction N1=1.3*10**-7 h=20 //height //Calculation wc=asin(((4*No)/((4*No)+((h**2)*N1)))) //critical angle //Results printf("Critical angle = ...
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//developed in windows 8 operating system 64bit //platform Scilab 5.4.1 //example 26_2w clc;clear; //Given Data press_a=100*10^3; //Pressure at point a (Unit: Pascal) press_b=100*10^3; //Pressure at point b (Unit: Pascal) press_d=200*10^3; //Pressure at point c (Unit: Pascal) press_c=200*10^3; //Pre...
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load GameOfLife.asm, output-file gliderLeft.out, compare-to gliderLeft.cmp, output-list RAM[132]%D1.8.1 RAM[133]%D1.8.1 RAM[134]%D1.8.1 RAM[164]%D1.8.1 RAM[165]%D1.8.1 RAM[166]%D1.8.1 RAM[196]%D1.8.1 RAM[197]%D1.8.1 RAM[198]%D1.8.1; set PC 0, set RAM[99] 4, // set number of generations set RAM[100] 0, // set start...
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//Design a cellular system for PCS system using QPSK modulation Smin = -91.4; fc = 1800; ht = 50; ahr = -4.53; d = 1; Gt = 12; Gr = 0; Lft = 1; Lfr = 1; fm = 10.5; Lp = 69.55 + 26.16*log10(fc) - 13.83*log10(ht) - ahr + (44.9 - 6.55*log10(ht))*log10(d) ; Pt = Smin - (Gt+Gr) + (Lft + Lfr + fm) + Lp; di...
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clc //initialisation of variables pe= 126 //ft ve=16//ft/sec g= 32.2 //ft/sec^2 w= 62.3 //lbf/ft^3 Q= 64 //ft^3/sec n= 0.79 vo= 8 //ft/sec h= 9 //ft nh= 0.82 //CALCULATIONS H= pe+(ve^2/(2*g))+13 Ps= H*w*Q*n/550 W= pe+(ve^2/(2*g))+4-((vo^2/(2*g))-h) W1= nh*H dh= W-W1 nm= n/nh e= Ps*((1/nm)-1) //RESULT...
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detectPeopleInVideo.sci
function detectPeopleInVideo(input_file, output_file) opencv_detecPeopleInVideo(input_file, output_file) endfunction
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clc; clear all; disp("temperature at interfaces") L=0.16;//m thickness of slab qg=1.2*10^(6);// W/m^3 k=180;// W/(m*C) t1=120;// degree C t2=t1; tw=t1; A=1;//m^2 x=L/2; tmp=(qg/(2*k))*(L-x)*x+tw; Qmp=qg*A*x; gradTmp=-Qmp/(A*k); disp("degree C",tmp,"temperature at mid plane tmp = ") disp("W/m^2",Qmp,"he...
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//variable initialization S1=0 L1=2 J1=2 g1=1 S2=1 L2=3 J2=4 g2=5/4 B=0.25 //magnetic field (T) mu=5.79*10^-5; //mass (eV/T) //(i) E1=4*g1*mu*B; ...
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1;e;0 1;- p1;-;s;-;2;0;- digOutItem 1 status
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clear // // //Initilization of Variables P=250*10**6 //N-mm/sec //Power transmitted n=100 //rpm q_s=75 //N/mm**2 //Shear stress //Calculations //From Equation of Power we have T=P*60*(2*%pi*n)**-1 //N-mm //Torsional moment //Now from torsional moment equation we have //T=j*q_s*(d/2**-1)**-1 //After substituting va...
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//clear// //Caption:Program to find the maxima and minma electric field //Example13.2 //page443 clc; clear er1 = 4; ur1 = 1; er2 = 9; ur2 = 1; eo = 8.854187*10^-12; uo = 4*%pi*10^-7;//free space permittivity and permeability u1 = uo*ur1; //permeability of medium 1 u2 = uo*ur2; //permeability of medium 2 e1 = eo*er1; /...
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example22_4.sce
//Chapter 22 //Example 22_4 //Page 531 clear;clc; mva=10; kv=6.6; x=(100-85); v_ph=kv*1000/sqrt(3); i=mva*1e6/sqrt(3)/kv/1000; min_fc=0.2*i; emf=0.15*v_ph; r=emf/min_fc; printf("Full load current = %.2f A \n\n", i); printf("Minimum fault current which will operate the relay = %.2f A \n\n", min_fc); printf("Voltage ...
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//Importing Drive Cycle data=csvRead("track1.csv"); Drive.time=data(3:470,1); Drive.values=data(3:470,2); //Importing Grade data value=csvRead("Grade Data.csv") Grade.time=value(3:470,1) Grade.values=value(3:470,2)
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ex1_12.sce
errcatch(-1,"stop");mode(2);//Caption:Find the average value of emf induced across the feild terminals //Exa:1.12 ; ; P=4;//no of poles N=4*250;//No.of turns Phy_1=40*P*10^-3;//In Webers Phy_2=5*P*10^-3;//In Webers t=0.1;//in seconds e=N*(Phy_1-Phy_2)/t; disp(e,'average value of emf induced across the feild...
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errcatch(-1,"stop");mode(2);// Exa 1.6 ; ; // Given data T = 287;// in degree C T = T + 273;// in K disp(T,"The temperature on absolute scale in K is"); exit();
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Ex2_8.sce
//Chapter 2 //page no 59 //given clc; clear ; Br_Si=1.79*10^-15; //Recombination coefficient for Si Br_Ge=5.25*10^-14; //Recombination coefficient for Ge Br_GeAs=7.21*10^-10; //Recombination coefficient for GeAs Br_InAs=8.5*10^-11; //Recombination coefficient fo...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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clear; clc; close; disp("Example 5.4") M0=1.4 //from normal shock table p=0.9582 //p=pt2/pt0 M1=M0 //from isentropic table: A=1.115 //A=A1/Acr A11=1.1 //A11=Ax/A1 Af=A11*A //from normal shock table for M>1 Mx=1.56 //from normal table p1=0.91 //p=pt2/pt0 p2=p disp(p,"(a)The best backpressure :") disp(...
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//signals and systems //time domain analysis of discreet time systems //convolution clear; close; clc; n=(0:14); x=4^-n; a=[1 -0.6 -0.16]; b=[5 0 0]; y=filter(b,a,x); clf; plot2d3(n,y); xlabel('n'); ylabel('y[n]');
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//============================================================= //Chapter 5 example 27 clc; clear all; //variable declaration //V = (5*sin(theta))+(0.6*sin(3*theta))\ a = 5; b = 0.6; rd = 35; //resistance in Ω ra = 30; //resistance in Ω //calculati...
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// 08.07.11 function Out=Xyzax3data(Xrange,Yrange,Zrange) J=mtlb_findstr(Xrange,'='); Tmp=evstr(part(Xrange,J+1:length(Xrange))); Px=[Tmp(1),0,0]; Qx=[Tmp(2),0,0]; J=mtlb_findstr(Yrange,'='); Tmp=evstr(part(Yrange,J+1:length(Yrange))); Py=[0,Tmp(1),0]; Qy=[0,Tmp(2),0]; J=mtlb_findstr(Zrange,'='); Tmp=e...
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// Exa 4.25 clc; clear; close; format('v',5) // Given data R1 = 4;// in M ohm R2 = 2;// in Mohm R_G = (R1*R2)/(R1+R2);// in Mohm Zin = R_G;// in Mohm disp(Zin,"The input impedance in Mohm is"); R_S = 2.5;// in k ohm R_S = R_S * 10^3;// in ohm R_L = 25;// in k ohm R_L = R_L * 10^3;// in ohm g_m = 2500;//...
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// Example 18.16, page no-470 clear clc E=600*10^3 //V/m eps=8.854*10^-12 //F/m epsr=6 p=eps*(epsr-1)*E printf("Polarisation produced in NaCl is %.3f *10^-5 C.m^-2",p*10^5)
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//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 7 //Scilab version- 6.0.0 //Example 3.1.2 clc; clear; //given //case 1 n1=1.48;//Refractive index of the core for silica fiber n2=1.46;//Refractive index of the cladding for silica fiber //case 2 n3=1.495;//Refr...
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eliminacaoGauss.sci
function solucaoSistema = refinamento(matriz, solucaoSistema, vetorIndependente, tolerancia, iteracoes) residuo = vetorIndependente - (matriz * solucaoSistema); erro = norm(residuo, 'inf'); tolerancia = (0.5 * 10 ** (2 - tolerancia)); // algarismos de significancia [l, u] = lu(matriz);...
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10_8.sce
clear; clc; close; Vio = 1.2*10^(-3); R1 = 2*10^(3); Rf = 150*10^(3); Vo = Vio*((R1+Rf)/R1); disp(Vo,'Output offset voltage(Volts) = ');
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clear; clc; disp('Example 1.13'); // Given values V = 230; // Voltage, [volts] W = 4; // Power of heater, [kW] // solution // using equation P=VI I = W/V; // current, [K amps] mprintf('\n The current taken by heater is = %f amps \n',I*10^3); // End
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clc; clear; e=[1 -1 -1 -1;-1 -1 -1 1]; x=[1 1 -1 -1;1 -1 -1 -1;-1 -1 -1 1;-1 -1 1 1]; w=e/2; m=size(x,"r"); p=size(e,"r"); for i=1:m //for the input vector for j=1:p //for example vector net(i,j)=w(j,:)*x(i,:)'+m/2; end for j=1:p-1 if net(i,j)>net(i,j+1) n...
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// Example 7.10 // Calculation of Wattmeter Readings // Assuming phase_a= 0; V_ab_m= 780; // Line voltage phase_ab= 30; // in degree I_a_m=30; // in Amphere phase_a=-36.9;//in degree V_cb_m= 780; phase_cb=90; I_c_m=30; phase_c=83.1; x_ab=V_ab_m*cos(phase_ab*(%pi/180)) y_ab=V_ab_m*sin(phase_ab*(%pi/180)) V_...
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//example-21.5. //page no-633 //given //volume V=0.01 //m^3 //frequency f=50 //Hz //area of loop A=600 //J/m^2 //as we know that //A=mu*Bmax^16 //also power loss is given by //P=mu*Bmax^16*f*V //so P=A*f*V //watt printf ("the power loss due to hysteresis is %f W",P)
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clc //Chapter 11:Power amplifiers //example 11.4 page no 475 //given Pt=4//max power dissipation in watt Idmax=1.5//max drain current in amp Vcc=48//supply voltage P_t=(4*%pi*Pt)/(Vcc*Idmax)//the normalised max transistor dissipation disp('from figure 11.21 it is found that maximum possible conduction angle is ...
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aaa bbb ccc config.info.default (289 B) mnemonics.txt (13.1 kB) begin transaction (level = 1) aaa bbb ccc config.info.default (289 B) mnemonics.txt (13.1 kB) ddd eee fff rollback transaction (level = 1) aaa bbb ccc config.info.default (289 B) mnemonics.txt (13.1 kB) aaa bbb ccc config.info.default (289 B) mnemonics.txt...
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gsort.sci
// test de gsort : a Finir pour ind ds le cas 'l' // a faire ensuite marcher pour vecteur complexes N=3,P=2 a=int(10*rand(N,P)); [a1,ind]=gsort(a,'g'); uu=maxi(abs(a(ind)-matrix(a1,N*P,1))) [a1,ind]=gsort(a,'r'); uu=0.0;for i=1:N,uu=uu+maxi(abs(a(i,ind(i,:))-a1(i,:)));end [a1,ind]=gsort(a,'c') ; ...