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// Find Vgs,operating region,Id,Rd // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 6-13 in page 288 clear; clc; close; // Given data Vdd=10; // Drain voltage in in V Vds=6; // Drain-source voltage in V K=0.2*10^-3; // Constant in mA/V^2 Vt=1;...
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//Example 9.7.b //find watt-hour efficiency clc; clear; close; I=30;// in amperes t=6;// in hours Vt=2;// terminal voltage Ic=40;// in amperes tc=5;// in hours Vc=2.5;// in volts Who=I*t*Vt;// watt hour output of the battery Whi=Ic*tc*Vc;// watt hour input of the battery nWh=(Who/Whi)*100;// ampere hour efficiency disp...
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// Updated(24-7-07) // 7.2 H = trfu(1,[1 -1 0],-1); w = -5:0.4:5; fre = w/(2*%pi); nyquist(H,fre); xset('window',1) nyquist(H) xset('window',2) w = -1.3:0.3:3.3; fre = w/(2*%pi); fre = -0.557:0.02:0.557; fre = 0.01:0.01:1; nyquist(H,fre);
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// Example 6.6 //overall power conversion efficiency clc; clear; close; Pc=200*10^-6;//Optical power in Watt If=25;//forward current in milli Ampere Vf=1.5;//forward voltage in Volts P=If*10^-3*Vf;//power in Watt npc=((Pc/P));//overall power conversion efficiency disp(npc*100,"overall power conversion effic...
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function [stk,txt,top]=sci_home() // Copyright INRIA txt=[] set_infos('home ignored',1) txt=[txt; '// home'] stk=list(' ','-2','0','0','1')
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function [f1]=function1(x,f1) f1=(x(1,1)*x(1,1)-x(2,1)*x(2,1)-1); endfunction function [f2]=function2(x,f2) f2=(x(1,1)*x(2,1)*x(2,1)*x(2,1)-x(2,1)-3); endfunction function [der11]=derivative11(x,der11) der11=(2*x(1,1)); endfunction function [der12]=derivative12(x,der12) der12=(2*x(2,1)); endfuncti...
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// Example 7.7, page no-272 clear clc Ta= 40 //Antenna Noise temperature Ti=290 //Reference temperature in K T=50 // Effecitve input noise temperatuire Tf=Ti L=(Ta-Tf)/(T-Tf) L=ceil(L*10^4)/10^4 printf("Loss factor = %.4f = %.3f dB",L,10*log10(L))
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//Exa:1.34 clc; clear; close; P_o=17.6*1000;//in watts Eff=0.8;//Efficiency V=220;//in volts I_f=P_o/(V*Eff);//in amperes I_af=I_f;//in amperes R_a=0.1;//in ohms N=1200;//in rpm T_f=P_o/(2*%pi*N/60);//Full load torque (N-m) E_bf=V-I_af*R_a;//Back emf (in volts) V_a=V+E_bf;// Voltage across armature (in vol...
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//All the quantities are expressed in SI units p0 = 30*101000; //reservoir pressure T0 = 3500; //reservoir temperature R = 520; //specific gas constant gam = 1.22; //ratio of specific heats ...
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// ************** Ejecucion metodo golden ************** clear all; clc; // Solucion del problema de optimizacion function fx = funcion(x) g=9.81, v0=55, m=80, c=15, z0=100; fx = -(z0 + (m/c)*(v0+(m*g/c))*(1-exp(-(c/m)*x))-(m*g/c)*x) endfunction xlow = 0, xup = 4, niter = 20; [xlow, x2, fx2, x1, f...
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% ---------------------------------------------------------------------- % $Id: ofsf.tst 469 2009-11-28 13:58:18Z arthurcnorman $ % ---------------------------------------------------------------------- % Copyright (c) 2006-2009 Andreas Dolzmann and Thomas Sturm % -------------------------------------------------------...
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// Scilab Code Ex5.2 : Percentage transmission of polarized light: Page-113 (2010) I0 = 1; // For simplicity, we assume the intensity of light falling on the second Nicol prism to be unity, watt per metre square theta = 30; // Angle through which the crossed Nicol is rotated, degrees I = I0*cosd(90-theta)^2; ...
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//Example 15.7// prt=24.4*10^-9;//ohm m //room temperature value of restivity a=0.0034;//C^-1 //temperature coefficient of restivity t=200;// degree C //tempertaure tn=20;//degree C //room temperature p=(prt)*(1+a*(t-tn)) mprintf("p = %e ohm m",p) s=1/p mprintf("\ns = %e ohm^-1 m^-1",s)
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clc // Given that p = 1000 // power of lamp in W d = 2 // distance of a point from lamp in meter e0 = 8.85e-12 // electric permittivity of space mu0 = 1.2567e-6 // magnetic permittivity of space c = 3e8 // speed of light in meter/sec // Sample Problem 31 on page no. 10.48 printf("\n # PROBLEM 31 # \n") s = p / (4 * %p...
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function q=matris_max_min_topla(a); maxa=max(a); mina=min(a); q=mina+maxa; endfunction
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//n = 100; data = [10:10:100] for n = data i=n/10 A=rand(n,n); B=rand(n,n); tic(); C3B= matmat3b(A,B); times1(i) = toc() tic(); C2B= matmat2b(A,B); times2(i) = toc() tic(); C1B= matmat1b(A,B); times3(i) = toc() tic(); Cnorm=A*B; times4(i) = toc() end subplot(2,2,1),plot(data,times1,"r"),subplot(2...
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clc; clear; rand('seed',0); N = [8,2,2]; M = read_csv('D:\Boring Stuff\Study Material\Sem VI\Artificial Intelligence\Lab\Assignment 5\emg.csv',[],[],"double"); P = read_csv('D:\Boring Stuff\Study Material\Sem VI\Artificial Intelligence\Lab\Assignment 5\emg.csv',[],[],"double"); x = M(1:40,2:9)'; t = M(:,10:11)';...
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//Example 11// Ch 2 clear all clc close phi1=0; phi3=10; phir=[phi1;phi3]; sl=[1.25 -0.014;-0.014 0.8381]; //elements of global stiffness matrix sr=-[-0.7786 -0.4571;-0.4571 -0.3667];//elements of global stiffness matrix phil=inv(sl)*sr*phir printf('value of potentials at the nodes are %f \n',phil)
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//Example 3.43:resistance clc; clear; close; Q=100.5;//ohms M=300;//ohms S=0.0045;//ohms x=(Q/M)*S;//ohms r=0.1;//ohms m=300.25;//micro ohms q=100.6;//ohms y=((r*m)/(r+m+q));//ohms z=((Q/M)-(q/m));//ohms R=x+(y*z);//milli ohms disp(R*10^3,"unknown resistance is ,(milli-ohm)=")
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// Exa 2.20 clc; clear; close; // Given data R1= 500;// in ohm R2= 615;// in ohm R3= 100;// in ohm delR1ByR1= 1; delR2ByR2= 1; delR3ByR3= 0.5; // Part(i) R4=R1*R2/R3;// in ohm disp(R4,"Unknown resistance in ohm") delR4ByR4= delR1ByR1+delR2ByR2+delR3ByR3; disp(delR4ByR4,"Relative limiting error of unknown...
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//Example number 2.1, Page number 2.33 clc;clear;close // Variable declaration I=1/2 // unitless // Calculation theta1=acos(1/sqrt(2))*(180/%pi) // radian theta2=acos(-1/sqrt(2))*(180/%pi) // radian // Result printf("theta=%.f degrees",theta1) printf("\ntheta=%.f degrees",theta2) printf("\n\n The value of theta can...
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clc clear //Input data P1=1;//Initial pressure of a 3 stage compressor in bar P4=40;//Final pressure in bar T1=293;//Initial temperature in K n=1.3;//Polytropic index V1=15;//Air delivered per minute in m^3/min //Calculations W=((3*n)/(n-1))*P1*10^5*V1*(((P4/P1)^((n-1)/(3*n)))-1);//Work done by the compresso...
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clear; clc; //Example - 13.5 //Page number - 442 printf("Example - 13.5 and Page number - 442\n\n"); //This problem involves proving a relation in which no mathematics and no calculations are involved. //For prove refer to this example 13.5 on page number 442 of the book. printf(" This problem involves provi...
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clc clear disp("Example 8.10") printf("\n") disp("convert the following decimal to binary numbers") disp("a)47.8125 b)100.0001 c)29.3749") //given decimal number i=1;x=1 dec=47.8125 //separating integer part IP=floor(dec) IP1=IP //separating decimal part DP=modulo(dec,1) //storing each integer digit in ...
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clc // Given that d = 180 // Bore in mm L = 200 // Stroke in mm Bp = 245 // Brake power in kW N = 1500 // Speed in rpm mep = 8 // Mean effective pressure in bar m_f = 70 // Fuel consumption in kg/h cv = 42 // Heating value of fuel in MJ/kg m_h = 0.12 // Fraction of hydrogen content by mass m_a = 26 // Air con...
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clc;funcprot(0);//Example 1.12 //Initilisation of Variables T1=323;.........//Temparature of blackbody before heated in K T2=373;.........//Temparature of blackbody after heated in K s=5.67*10^-8;.......//Stefan-Boltzmannconstant //Calculations e=s*(T2^4-T1^4);........//Increse in emmissive power in W/m^2 disp(e...
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction //c...
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sigma_cbc=7//in MPa sigma_st=275//in MPa lx=6//in m ly=7//in m D=lx*10^3/35//in mm D=180//assume, in mm W1=(D/10^3)*25//self-weight, in kN/m W2=0.5//floor finish, in kN/m W3=1//partitions, in kN/m W4=5//live load, in kN/m W=W1+W2+W3+W4//in kN/m a=ly/lx //panels I, II, V and VI belong to case 4 and panels II...
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function [] = printInit() for i = 1:1:9 x = [i i]; y = [0 10]; plot(x,y); end for i = 1:1:10 y = [i i]; x = [0 10]; plot(x,y); end // for i = 1:sizesnake // [x0 y0] = getCord(snake_head(1, i)); // [x1 y1] = getCord(snake_tail(1, i)); // ...
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//Example 22.4 B=1.50;//Magnetic field strength (T) l=5*10^-2;//Length of wire (m) I=20;//Current (A) theta=90;//Angle between I and B (deg) F=I*l*B*sind(theta);//Force (N) printf('Force on the wire = %0.2f N',F) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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function [c] = connected(X) c = 0; i = 1; j = 2; a = size(X); while(j > i) if X(i,j) == 0 j = j + 1; else X(i,:) = X(i,:) | X(j,:); X(:,i) = X(:,i) | X(:,j); X(j,:) = []; X(:,j) = []; a(1) = a(1) - 1; end if (j > a(1)) & (i < a(1)) j = i + 2; ...
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//to find the number of plates required clc P=20//lb/in^2 u=0.07//friction coefficient N=3600//rpm H=100//hp r1=5//in r2=0.8*r1//given A=%pi*(r1^2-r2^2)//the area of each friction surface W=A*P//total axial thrust on plates M=(1/2)*u*W*(r1+r2)//friction moment for each pair of contacts T=H*33000*12/(2*%pi*N)...
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//Example 1.15<a> // Find wheather the following signal is periodic or not x3(n)=2*e^(%i*(t+%pi/4)) clc; t=-21:21; x=2*exp(%i*(t+%pi/4)); f=1/(2*%pi); N=1/f; disp('samples',N,'(b)the given signal is not periodic');
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clc //initialisation of variables clear f=0.0025 l=100//ft d=0.5 p1=200//lb/in^2 p2=120//lb/in^2 T1=600//f w1=0.95//lb/ft^3 g=32.2//ft/sec^2 nT1=580//f nw1=0.87//lb/ft^3 //CALCULATIONS k=f*l/d v1=19.5*sqrt(T1) pd1=w1*v1*v1/(144*2*g) np1=p1-pd1 nv1=18.5*sqrt(nT1) nT2=0.97*nT1 W=0.87*%pi*d*d*nv1/4...
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clear; clc; l=10; D=1.25; dia=1.213e-2; Cab=.01206/log10(D/(dia/2)) C=l*Cab; Cn=2*C; mprintf("Capacitance between 2 conductors= %.4f e-6F/km\n", C); mprintf("Capacitance between conductor and neutral= %.4f e-6F/km\n", Cn);
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//clc(); clear; //To calculate refractive index of material of the core NA=0.39; //numerical aperture delta=0.05; //fractional index change A=sqrt(2*delta); n1=NA/A; printf("refractive index of the core is %f",n1);
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//example 21.1 //calculate //total installed capacity //load factor //plant factor //utilization factor clc;funcprot(0); //given c=10000; //capacity of each generator; n=3; //number of generator l1=12000; //initial load on plant l2=26000; //final load on...
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//AC Circuits : example 4.42 :pg(4.32 & 4.33) PR=1000; VR=200; Pcoil=250; Vcoil=300; R=((VR^2)/PR); I=(VR/R); r=((Pcoil/(I^2))); Zcoil=(Vcoil/I); XL=sqrt((Zcoil^2)-(r^2)); RT=(R+r); ZT=sqrt((RT^2)+(XL^2)); V=(ZT*I); printf("\nPR=1000 W \nVR=200 V \nPcoil=250 W \nVcoil=300 V \nPR=(VR^2/R)"); printf("\nR=%....
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function[Q]=SRB(Tr,Pr,omega) B0=0.083-(0.422/(Tr^1.6)); diffr_B0=0.675/(Tr^2.6);//dB0/dTr B1=0.139-(0.172/(Tr^4.2)); diffr_B1=0.722/(Tr^5.2);//dB0/dTr Q=-Pr*(diffr_B0+(omega*diffr_B1)); funcprot(0); endfunction
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errcatch(-1,"stop");mode(2);//Caption:Determine Primary resistance referred to secondary and secondary resistance referred to primary and total resistance of transformer referred to primary. //Exam:3.21 ; ; V_1=2000;//Primary voltage at no load or full load(in Volts) V_2=220;//Secondary voltage at no load (in Vo...
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pathname=get_absolute_file_path('20_4.sce') filename=pathname+filesep()+'20_4data.sci' exec(filename) clear for i=1:8 I(i)=B(i)*y(i)*y(i); end Ixx=sum(I); P=(-Sy/Ixx); qb1(1)=0,qb2(1)=0; for i=2:3 qb1(i)=P*B(i+1)*y(i+1) +qb1(i-1); qb2(i)=(P*B(i+5)*y(i+5) +qb2(i-1)); end qb1(4)=qb1(2); qb2(4)=...
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//Ex1_4 clc; //Given: wavelength=10^-10; m=9.1*10^-31; h=6.626*10^-34; //solution: p=h/wavelength; e=p*p/(2*m); // energy in J e1=e/(1.6*10^-19);// energy in eV printf("The energy in eV is = %f ",e1)
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clc //Example 14.11 //Install Symbolic toolbox //Calculate f(inf) syms s t ; disp('Given function is f(t)=1-exp(-a*t)') u=laplace(1) v=laplace(exp(-2*t)) F=u-v x=s*F //From final value theorem y=limit(x,s,0) disp(y,'f(inf)=')
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//Page Number: 194 //Example 4.3 clc; //Given c=3D+8; //m/s a=2.286;//cm a1=a/100;//m b=1.024;//cm b1=b/100;//m f=10D+9;//hz sig=6D+7; u=4D-7*%pi; w=2*%pi*f; eet=377; //Shortest cavity length lamc=2*a1;//m fc=c/lamc;//hz lam=c/f;//m lamg=lam/sqrt(1-(fc/f)^2);//m sc=lamg/2;//m disp('cm',sc*100,'Sho...
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clc //For air at 20 0C and 75% R.H p_vs=0.0234; //bar phi=0.75; p_t=1.0132; cp=1.005; t_db=20; //0C p_v=phi*p_vs; t_dp=15 + (16-15)*(0.01755-0.017)/(0.0182-0.017); W=0.622*p_v/(p_t-p_v); h_g=2538.1; //kJ/kg h_vapour=h_g + 1.88*(t_db - t_dp); h1=cp*t_db + W*h_vapour; disp("(i) Relative humidity ...
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clc //initialisation of variables Tn= 0.820 Tn1=0.450 A= 426.1 A1= 91 //CALCULATIONS l= Tn*A l1= Tn1*A1 L= l+l1 //RESULTS printf ('A0 for acetic acid= %.1f ',L)
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#************************************************************ # Scenario of JidoRef # # date : Wed Oct 20 15:18:24 2010 #************************************************************ p3d_sel_desc_name P3D_ENV JidoRef p3d_sel_desc_name P3D_ROBOT HUMAN_ACHILE p3d_set_robot_steering_method Linear p3d_set_robot_curren...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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clc //initialisation of variables T= 290 //K xa= 0.4 xb= 0.6 P= 600 //kPa V= 60 //L R= 8.314 //J/mol K Mp= 44 //kg/kmol Mb= 58.12 //kg/kmol vp= 0.00171 //m^3/kg vb= 0.00166 //m^3/kg na= 0.1 //kmol nb= 0.15 //kmol V1= 0.04000 //m^3 xa= 0.4 np= 2 Vc= 0.1 //m^3 //CALCULATIONS Pasat= %e^(14.435-(2255/T)...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map2202" Width="13" Height="9" CellSize="40" BackgroundSize="1" Background="13plus.png"> <Cell Name="墓碑" X="2" Y="1" /> <Cell Name="枯树" X="6" Y="1" /> <Cell Name="幽灵-右" X="7" Y="1" arg0="3" arg1="1.00" /> <Cell Name="枯树" X="11" Y="1" /> <Cell Name="出生点" X...
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// Example 4.3: Region of operation, Node currents and voltages clc, clear betaf=100; // Current gain disp("Let us assume that the transistor is in active region."); VBE_active=0.7; // in volts // From Fig. 4.19 VCC=10; // in volts VBB=5; // in volts RB=100e3; // in ohms RE=2e3; // in ohms RC=2e3; // in ohms ...
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//<f>=%pps(p,s) // %pps(p,s) calcule la puissance s_ieme (negative) d'une matrice //de polynomes. //l'exposant s doit etre entier. //les puissances entieres positives sont definies en fortran. //! if s>-1 then error(43),end if int(s)<>s then error('%pps: integer power only'),end [m,n]=size(p) if m<>n then error(43),e...
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clc; clear all; v=0.86e6;//velocity of electron in m/s m=9.1e-31;// Mass of electron in Kg e=1.6e-19;// Charge of electron k=1.38e-23;//boltzmann constant Ef=m*v*v/2;//fermi energy Tf=Ef/k;//The fermi temperature disp('K',Tf,'The fermi temperature is:')
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clear; clc; funcprot(0); //given data D = 30;//tip diameter in m CL = 0.8;//lift coefficient J = 5.0; l = 1.0;//chord length in m Z = 3;//number of blades r_R = [0.2 0.3 0.4 0.6 0.8 0.9 0.95 1.0]; n = 8; //Calculations //iterating to get values of induction factors a = 0.1;//inital guess anew = 0; a_ =...
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//chapter 16 //example 16.12 //page 705 printf("\n") printf("given") fs=1*10^6;Rs=700;C1=1000*10^-12;C2=100*10^-12;R1=1*10^6;R2=10*10^3;Rs=700;Vdd=5; Ct=(C1*C2)/(C1+C2) disp(" at resonance Xl=Xct 2*pi*f*L=1/2*pi*f*Ct") L=1/(((2*3.14*fs)^2)*Ct) ip=Vdd/(R1+R2+Rs) Pd=(((.707*ip)^2)*Rs)*10^9; printf(" peak power dissipa...
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//Caption:In a single phase transformer Calculate the secondary terminal voltage at full load. //Exam:3.17 clc; clear; close; V_1=2000;//Primary voltage at no load or full load(in Volts) V_2=400;//Secondary voltage at no load (in Volts) K=V_2/V_1;//Ratio of transformation R_1=5;//Primary resistance(in Ohm) R_2...
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clc// // // //Variable declaration h=6.62*10^-34; //planck's constant(J sec) c=3*10^8; //velocity of light(m/sec) Eg=1.43*1.6*10^-19; //energy gap(J) //Calculation lamda=h*c*10^6/Eg; //wavelength of radiation(micro m) //Result printf("\n wavelength of radiation is %0.3f micro m",lamda)
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function y = meuFatorial(x) a=1 for i=1:1:x a=a*i; end y=a; endfunction
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//EX3_2 PG-3.15 clc disp("Refer to the figure-3.8 shown") Vin=0;//cut-in voltage for an ideal diode is zero Rf=0;//forward resistance for an ideaal diode is zero disp("For an ideal diode") Vm=15; Vdc=-Vm/%pi; printf("\n DC output voltage is %.2f V\n ",Vdc) disp("-ve sign indicates that voltage is negative wrt ...
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//EXAMPLE 2-9 PG NO-65 t1=0.0025; //time t2=0.005; //time t3=0.01; //time i1=10*314.16*cos(314.16*t1); //i1 is derivatives of i wrt t; disp('i) Current = '+string ...
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//ques-34.25 //Calculating concentration of a substance clc EC=14000;//molar absorptivity l=1;//thickness (in cm) A=0.85;//absorbance C=A/(EC*l); printf("The concentration of the given substance is %.7f M.",C);
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// Scicos // // Copyright (C) INRIA - Masoud Najafi <masoud.najafi@inria.fr> // Serge Steer <serge.steer@inria.fr> 1993 // Habib Jreij 1993 // // This program is free software; you can redistribute it and/or modify // it under the terms ...
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clc //initialisation of variables Re= -4 //KN Rh= -6 //KN Ro= 2 //KN x1= 1 //m x2= 3 //m x3= 5 //m x4= 4 //m //CALCULATIONS Rb= (Ro*x1-Re*x2-Rh*x3)/8 Rav= (-Ro*x1-Re*x3-Rh*x2)/8 Rah= Ro Fcf= (Rav+Re)/cosd(45) Fcd= (-Re*x1-Rav*x4-Ro*x1)/x1 Fef= (Rav*x2+Ro*x1)/x1 //RESULTS printf ('Rb= %.1f KN',Rb) prin...
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//Example 7.12, page no-443 clear clc i2=150 i1=125 m=(i2-i1)*100/i1 printf("Moisture percentage = %d%%",m)
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//Example 5_3_u1 clc(); clear; //To find the intercepts along the Y and Z axes a=0.121 //units in nm b=0.184 //units in nm c=0.197 //units in nm //Given miller indices are (2,3,1) OA_OB=3/2 OA_OC=1/2 OB=(2/3)*b //units in nm OC=2*c //units in nm printf("The Intercepts along th...
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clc;clear; //Example 3.9 //part a disp('Part a'); //given values P=200; x=0.6; //from Table A-5 T=120.21; uf=504.50; ufg=2024.6; //calcualtions u=uf+(x*ufg); disp(T,'temperature in Celcius '); disp(u,'internal energy in kJ/kg'); disp('saturated liquid–vapor mixture at a pressure of 200 kPa'); ...
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// ==================================================================== // Allan CORNET // DIGITEO 2008 - 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== test_path = fullfile(xls_getRootPath(...
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//===================================================================================== //Chapter 12 example 16 clc;clear all; //variable decalaration R4 = 1000; //resistance in Ω C3 = 50*10^-12; //capacitance in F A = 314*10^-4; //area in m**2 D = 0.3*10^-2; //thickness in m er ...
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clear; clc; close; Ra = 10*10^(3); C = 0.1*10^(-6); Thigh = 1.1*Ra*C; disp(Thigh,'Period of output waveform = ')
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backend = Backend.x86 backend.ralloc = backend.ralloc or Ralloc.color Ld.rtend = "" --- don't need the run-time system Test.trust_exe = 1 Test.source = "lcc" Test.asmdir = Test.asmdir or "lcc/x86" Test.outdir = Test.outdir or "lcc/output" Test.files = { { source="8q.c--", } , { s...
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clear; clc; close; disp("Example 4.4") m=50 //air mass flow in kg/s mf=1 // fuel mass flow in kg/s tae=0.88 //turbine adiabatic efficiency pe=45*10^6 //shaft power in Watt cp4=1156 // in J/kg.K Tt4=1390.0197 // in K pt4=1.92 //units in MPa cp5=cp4//specific heat mt=m+mf//total mass gm=1.33 //gamma ht5=cp4...
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//page 98 clc;funcprot(0);//EXAMPLE 4.6 // Initialisation of Variables n=2;........//No. of Atoms present per cell in BCC a0=2.866*10^-8;.....//The lattice parameter of BCC iron in cm rho1=0.994*10^15;.......//Planar density of (112)BCC in atoms/cm^2 //CALCULATIONS a=sqrt(2)*a0^2;.........//Area of BCC iron in c...
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clear; clc; // Illustration 7.7 // Page: 454 printf('Illustration 7.7 - Page: 454\n\n'); // solution //*****Data*****// Ff = 1.89; // [cubic m/min] Fs = 2.84; // [cubic m/min] t = 2; // [min] //*****// printf('Illustration 7.7(a) - Page: 454\n\n'); // Solution(a) Q = Ff+Fs; // [total flow rate,...
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//Mclaurin Expansion n = 5; a = 0.1; expvalue = 1.0; currentTerm = 1.0; for i=1:n currentTerm = currentTerm * a / i; expvalue(i+1) = expvalue(i) + currentTerm; end trueVal = exp(a); error = abs(trueVal - expvalue);
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clc //initialisation of variables v= 100 //ft/sec u= 40 //ft/sec a= 25 //degrees g= 32.2 //ft/sec^2 vr= 66 //ft/sec a1= 20 ///degrees a2= 8 //degrees r= 0.14 //CALCULATIONS A= atand(v*sind(a)/(v*cosd(a)-u)) A1= atand(r) v1= vr*sind(A1)/sind(a1) W= (v^2-v1^2)/(2*g) e= (v^2-v1^2)*100/v^2 //RESULTS print...
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// **** Purpose **** // calculate the direct product // **** Variables **** // A: nxn, real or complex // <= matrix A // B: nxn, real or complex // <= matrix B // C: nxn, real or complex // => A direct prod of B // **** Version **** // 05/01/2014 // **** Comment **** function [C]=PIL_dirprod(A,B) A_dim=size(A); B_di...
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clc;funcprot(0);//Example 2.15 //Initilisation of Variables d=0.03;....//diameter of uranium steel rod in m qg=50000000;....//heat generated rate in W/m^2 Tw=120;....//surface temparature of uranium steel rod in degrees celcius K=30;....//thermal conductivity of uranium steel rod in W/m*K //calculations R=d/2;....
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clc //initialization of variables l = 200 // Length of the tower in cm d = 60 // diameter of the tower Lf = 300 // Liquid flow in cc/sec Kx = 2.2*10^-3 // dominant transfer co efficient in liquid in cm/sec //Calculations A = %pi*60*60/4 // Area of the cross section in sq cm L = Lf/A // Liquid flux in cm^2/se...
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// Exa 2.17 clc; clear; close; // Given data R1= 200;//in ohm R2= 100;//in ohm R3= 50;//in ohm del_R1ByR1= 5; del_R2ByR2= 5; del_R3ByR3= 5; // Part (i) when the resistance are connected in series Rse= R1+R2+R3;// in ohm disp(Rse,"Equivalent resistance when connected in seried in ohm"); LimError= R1/Rse*de...
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//find the compression of the piston rod clc //solution //given d=50//mm//diameter of rod l=600//mm//length of rod D=400//mm//diameter of piston p=0.9//(N/mm^2)//maximum steam pressure E=210*10^3//(N/mm^2)//young's modulus pi=3.14 A=(pi/4)*D^2//(mm^2)//area of cross section of piston P=A*p//N//max load acti...
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6_1.sce
clc //initialisation of variables d= 3.880 //g l^-1 M= 208.3 //gm P= 1 //atm R= 0.08205 //cal/mol K T= 473.1 //K //CALCULATIONS d1= M*P/(R*T) d2= (d1-d)/d Kp= d2^2/(1-d2^2) Kc= Kp/(R*T) //RESULTS printf (' Kc = %.3e moles l^-1',Kc)
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//Données graphe aléatoire NPE=2; //Nombre de paramètres environnementaux (déchets) //Choix d'un jeu de paramètres de lois gamma ks=[25 35]; //Shape parameters mu=[6 7]; //Moyennes Beta=ks./mu; //Rate parameters NQ=7; //Nombre de quantiles extraits + 1 Q=zeros(NPE,NQ-1); for i=1:NPE for l=1:(NQ-1) ...
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Chapter23_example17.sce
clc clear //Input data Vs=0.0015//Stroke volume in cu.m rc=5.5//Volume compression ratio p2=8//Pressure at the end of compression stroke in kg/cm^2 T2=350+273//Temperature at the end of compression stroke in K p3=25//Pressure in kg/cm^2 x=(1/30)//Fraction of distance travelled by piston pa=1/16//Petrol air mix...
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// Variable Declaration E_c = 100.0 //Safe working stress(kV/cm) rms V = 130.0 //Operating voltage(kV) rms d = 1.5 //Diameter of conductor(cm) // Calculation Section ln_D = 2*V/(E_c*d)+log(d) D = exp(ln_D) thick_1 = (D-d)/2 //Insulation thickness(cm) d_2 = 2*V/E_c D_2 = 2.718*d_2 ...
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example16_9.sce
clc // Given that d1= 0.534*10^3 // densiy of Li in kg/m^3 d2= 0.971*10^3 // densiy of Na in kg/m^3 d3= 0.86*10^3 // densiy of K in kg/m^3 w1 = 6.939 // atomic weight of Li w2 = 22.99 // atomic weight of Na w3 = 39.202 // atomic weight of K h = 6.62e-34 // Planck constant in J sec m = 9.1e-31 // mass of an electron i...
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pathname=get_absolute_file_path('7_1.sce') filename=pathname+filesep()+'7_1data.sci' exec(filename) D=(E*t^3)/(12*(1-v^2)); X=(16*q0/(D*%pi^6))/(((1/a^2)+(1/b^2))^2); X1=(16*q0/%pi^4)*((1/a^2)+(v/b^2))/(((1/a^2)+(1/b^2))^2); X2=(16*q0/%pi^4)*((v/a^2)+(1/b^2))/(((1/a^2)+(1/b^2))^2); function[w]=f(x,y),//taking fi...
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//Example 1.23 // distance between rings clc; clear; //given data : R1=100;//radii of curvature in cm R2=R1;// given w=5400D-8;// wavelength of light in m n1=5;// order of ring for case one r1=sqrt(n1*w/((1/R1)+(1/R2)));//radii of curvature in cm n2=15;// order of ring for second case r2=sqrt(n2*w/(1/R1+1/R2)...
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2 Ray Ground Propogation Model.sce
clc clear Fc = input("Enter Frequency in Hz: ") E = input("Enter Electric Field in v/m: ") GrdB = input("Enter Gain of Receiver Antenna in dB: ") d = input("Enter distance between Transmitting and Receiving Antenna in meters: ") c = 3*10^8 lambda = c/Fc disp("Wavelength in meters: ") disp(lambda) Gr = 10^(Grd...
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delta=.9957; function [xrec]=reciever(quant,delay) xrec=quant+delay; // xrec=bin2dec(bit)*delta+x_i+delay; endfunction function [xrec]=reciever_bin(bit,delay,x_i) // xrec=qua+delay; xrec=bin2dec(bit)*delta+x_i+delay; endfunction //indicator=1; function [bit]= delMod(x_high,x_low) ...
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Ex2_14.sce
clear // //kcl is applied to the circuit and the eqns obtained are solved using cramer's rule printf("\n the voltages of nodes 1 and 3 are 50.29 and 57.71 respectively") //i3=v/r printf("\n current through 16 ohm resistor is 1.64A")
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// Procedure to split a polynomial into good and bad factors, as discussed in Sec. 9.5. The factors that have roots outside unit circle or with negative real parts are defined as bad. // 9.12 // function [goodpoly,badpoly] = polsplit3(fac,a) // Splits a scalar polynomial of z^{-1} into good and bad // factors. I...
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function [x,y,typ]=macrocab_out(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1); case 'getinputs' then [x,y,typ]=standard_inputs(arg1); case 'getoutputs' then [x,y,typ]=standard_outputs(arg1); case 'getorigin' then [x,y]=standard_origin(arg1); case 'set' the...
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Example_4_15.sce
//Example 4.15 clear; clc; //Given Cpw=75.42;//heat capacity of water in J K^-1 mol^-1 T=263; //temperature in K P=1;//pressure in atm Cpi=37.20;//heat capacity of ice in J K^-1 mol^-1 delHf=6008;// latent heat of fusion in J mol^-1 mp=273;//melting point of water in K n=1;//moles of ice taken //To calc...
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6_11.sce
clc //initialisation of variables h=0.5//lb p1=2.5//lb/in^2 p2=100//lb/in^2 t=250//Degree C pv=1.3//constant pt=0.5457*p2//lb/in^2 t1=18//degree C h1=32//C.H.U/lb h2=151//C.H.U/lb D=0.887//in V1=sqrt(2*32.2*1400*h1)//ft/sec V2=sqrt(2*32.2*1400*h2)//ft.sec s1=8.74//ft^3 s2=140.8//ft^3 T1=0.687//in T1=1....
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13_7.sce
clear clc //Example 13.7 disp('Example 13.7') s = %s; num = 4; den = (5*s+1); delay=1; w = 0.001:0.002:10*%pi; LF = "loglog" // Warning: Change this as necessary Gv=2;Gm=0.25;Gc=1; G1 = num/den*Gc*Gm*Gv; G1m = horner(G1,%i*w); //G1m denotes magnitude G1p = phasemag(G1m)-delay*w*180/%pi; //G1p denotes phase xset...
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//Ex10_2 clc; // Given: E=1.1;// in MeV M=65;// molecular weight of zinc //Formula: // Er=(536*E^2)/M // Solution: Er=(536*E^2)/M; printf("The energy of recoil of Zinc atom is = %f eV", Er)
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// Problem no 7.2,Page no.184 clc;clear; close; P=295 //KW //Power N=100 //R.p.m sigma_s=80 //MPa //shear stress //Calculations T_mean=((P*60000)*(2*%pi*N)**-1) //N*m //T_max=T_mean=(%pi*D**3*sigma_s)*16**-1 D=((T_mean*16)*(%pi*sigma_s*10**6)**-1)**0.333 //m //Diameter of solid shaft //For hollow shaft //I_p_h=...
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// Scilab code Exa9.7 : : Page-392 (2011) clc; clear; h_cut = 1.0545e-34; // Reduced Planck's constant, joule sec R = 1.2e-15; // Distance of closest approach, metre m = 1.67482e-27; // Mass of the nucleon, Kg // For O-17 for A = 17:60 // Mass numbers if A == 17 then omega_O = ...
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//Example 7.17 // strain clc; clear; close; //given data : n=4; Rg=200; // in ohm Rsh=100*10^3; // in ohm Gf=2; // gauge factor e=Rg/(n*Gf*(Rg+Rsh)); // case 1 -when the calibration switch is closed, the read out gives a reading of 140 division D=e/140; //case 2 - when the strain gauge is loaded, the strain S=D*220*10^...