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clear //Given me=9.11*10**-31 //Kg lp=1.813*10**-4 vp=3 //Calculation mp=me/(lp*vp) //Result printf("\n The particles mass is %0.3f *10**-27 Kg. The particle is proton",mp*10**27)
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// This code helps you generate k-point for band struncture calculation. // << Variables >> // [lat_const]: 1x1, real // => lattice constant. primitive vectors will all multipile this constant. // [pri_vect]: 3x3, real // => primitive vectors in row form // [k_path_red]: nx3, real // => k-path divided points in reduced...
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clear; clc; //Caption:Minimum value of coupling capacitance for a given FET //Given Value Ry=1;//in K Rg=1;//in M Ri=1;//in K hOE=1/40;//in K^-1 //fL=1/(2*%pi*(ro+ri)*Cb)<=10 //Ro>1/hOE=40K ro=Rc=1K. Rb>Ri=1K then ri=1K ro=1000;//in ohm ri=1000;//in ohm Cb=1/(2*%pi*10*(ro+ri)); disp('pF',Cb*...
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//chapter2.example.4// //core refractive index=n1,cut off value of V parameter for single mode operation=Vc,radius=a,cladding refractive index=n2,relative index difference between core and cladding=d,cut off wavelength=lc// clc clear Vc=2.405; n1=1.46; d=0.0025; a=5*(10^-6);//in metres// h=sqrt(2*d); x=(2*%pi*...
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//Example 6-27// //Reduce by Variable Mapping// clc //clears the console// clear //clears all existing variables// disp('Z=A''B''CDE+A''BC''DE''+A''BCD+AB''CD''F+ABC''D''+ABCD''') disp('Converting the 6 variable minterms to 4 variable minterms') disp('m7-E+E'';m14-F+F''') disp('Result Z= A''CDE+A''BDE''+ABD''+...
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clear clc T=303;//in K m2=10;//mass of solute in gm m1=80;//mass of solute acetone in gm P1=271;//in torr P2=283;//in torr M1=58;//in gm/mol M2=((m2*M1)/(((P2-P1)/P2)*m1))-((M1*m2)/m1) printf('M2=%.1f gm/mol',M2) //page 39
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clear //Given u=4*3.14*10**-7 //T/A m n=20 I=12 //A r=0.1 //m //Calculation B=u*n*I/(2*r) //Result printf("\n Magnetic field at the centre of coil is %0.1f *10**-3 T",B*10**3)
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clc //initialisations r=8.3//j/mol/k J=4.2//j/cal T=273 m=2//gm //CALCULATIONS ke=(3*r*T/(2*m*J)) //results printf(' ke of one gm of hydrogen= % 1f calories',ke)
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// problem 8.5 d=0.05 V=20 y=120 x=180-y g=9.81 p1=1000 w=g*p1 a=3.142*d*d/4 F=(w*a*V*V*(1+cosd(x)))/(g) disp(F,"force in N exerted by the water jet")
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clc // Given that Bp = 110 // Brake power in kW n_m = 0.8 // Mechanical efficiency of the engine m_f = 50 // Fuel required for engine in kg/h r_f = 5 // Reduced engine friction in kW printf("\n Example 20.7\n") Ip = Bp/n_m Fp = Ip-Bp Fp_n = Fp-r_f Ip_new = Bp + Fp_n m_f_new = Ip_new * m_f/ Ip s_f = m_f- m_f...
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errcatch(-1,"stop");mode(2);// Example 10.13, page no-276 e=1.6*10^-19//C ni=2.4*10^19 //m^-3 mue=0.39//m^2/V-s muh=0.19//m^2/V-s sig=ni*e*(mue+muh) printf("The conductivity of Ge at 300 K is %.2f per Ohm-m",sig) exit();
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CellID CellName CompType MountType Verified NoPins GlueX GlueY AssemblyX AssemblyY Height TimeStamp History Description ...
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printf("\t example 8.1 \n"); printf("\t approximate values are mentioned in the book \n"); T1=358; // inlet hot fluid,F T2=100; // outlet hot fluid,F t1=90; // inlet cold fluid,F t2=120; // outlet cold fluid,F W=49600; // lb/hr w=233000; // lb/hr printf("\t 1.for heat balance \n"); printf("\t for oil \n"); c=...
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clear; clf; // read from file filename = pwd() + "\case-studies\week-3\exp_data.txt"; data = fscanfMat(filename); // constant variables frequency = 0.1; // Hz omega = 2 * %pi * frequency; sigma_0 = 6; // MPa E = 3; // elastic modulus (MPa) eta = 5; // viscosity (MPa/s) dt = 0.29; // can reach 0.4 for 4th order Run...
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//Chapter 3,Example 3.1 Page 104 clc clear R1 = 75 //ohms R2 = 2600 //ohms C1 = 25 // nF C2 = 2.5 //nF alpha = (10^9/2)*(1/(R2*C1)+1/(R1*C1)+1/(R1*C2)) beeta = (1/2)*sqrt(4*alpha^2-4*10^18/(R1*R2*C1*C2)) t1 = (1/(2*beeta))*log((alpha+beeta)/(alpha-beeta)) K = 0.7/(t1*(alpha-beeta))+1 t2 = K*t1 printf (" alpha = %e \n...
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# camera: eye, center, up, fovy, width, height camera 0 3 8 0 1 0 0 1 0 45 1024 1024 # recursion depth depth 5 # background color background 0 0 0 # global ambient light ambience 0.2 0.2 0.2 # light: position and color light 20 50 0 0.5 0.5 0.5 light 50 50 50 0.5 0.5 0.5 light -50 50 50 0.5 0.5 0.5 # ...
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clear; clc; // Stoichiometry // Chapter 3 // Material Balances Without Chemical Reaction // Example 3.5 // Page 62 printf("Example 3.5, Page 62 \n \n"); // solution m= 100 //[kg] original mixture (basis) A = 27.8 //[kg] B = 72.2 //[kg] // let x and y be uper and lower layer amounts // total mixtu...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Rao, R Ramesh, and Shankar Narasimhan. 1996. //“Comparison of Techniques for Data Reconciliation of Multicomponent Processes.” //Industrial & Enginee...
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clc // Given that E = 100 // strength of electric field in V/m B = 1e-3 // magnetic field in tesla // Sample Problem 9 on page no. 6.24 printf("\n # PROBLEM 9 # \n") v = E / B printf("\n Standard formula used \n v = E / B. ") printf("\n The drift of the guiding center = %e m/sec",v)
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clc //initialisation of variables T= 300 //F T1= 50 //F s= 0.17*10^-8 //Btu/hr ft^2 R^4 e1= 0.93 A= 10 //in F= 1 //CALCULATIONS A1= 10*(40/(12*10)) q= A1*F*e1*s*((T+460)^4-(T1+460)^4) //RESULTS printf ('Heat loss from the conduit by radiation = %.f Btu/hr per ft',q)
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//Example 3_12 clc;clear;funcprot(0); // Given values dV=90-0;//Change in velocity in km/h dt=10;// s b_1=2;// m b_2=0.6// m; g=9.81;// m/s^2 a_z=0;// m/s^2 // Calculation a_x=(dV/dt)/3.6;// The acceleration of the truck in m/s^2 theta=atand(a_x/(g+a_z));// degree // Case 1: gradZ_s1=(b_1/2)*tand(theta)...
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PL/SQL Developer Test script 3.0 18 -- Created on 10/06/2015 by YURISHO declare -- Local variables here percent_count number := 0; cursor cPublisher is SELECT DISTINCT publisher FROM book; begin -- Test statements here for publisher_rec in cPublisher loop percent_count := percent_count + Package.Boo...
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clear;lines(0); deff('y=f(x1,x2)','loc=1;y=a*x1+x2-loc') vars=macrovar(f)
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//Initilization of variables //length matrix L1=[0,4,6] //m //Bending moment matrix B=[0,400,0] //N.m //Shear force plotting //Here the left side and right side lengths are considered as close as 4 to keep up with right and left distinctions L=[0,3.999,4,5.99998,6] S=[100,100,-200,-200,0] //Calculations cum Result subp...
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// Equilibrium hole concentration in Si // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 1-17 in page 48 clear; clc; close; // Data given n_0=10^17; // Free electron concentration /cm^3 n_i=1.5*10^10; // Constant of calculation // Calculation ...
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// Example 7.2, page no-161 clear clc r=1.85*10^-10//m t=3*10^-14//s m=9.11*10^-31//Kg e=1.6*10^-19//C a=r*(4/sqrt(3)) ne=2/a^3 rho=m/(ne*t*e^2) printf("Resistivity of copper is %.3f*10^-8 Ohm-m",rho*10^8)
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//Example 10.8 //Picard Method //Page no. 313 clc;clear;close; deff('y=f(x,y)','y=x^2-y') y(1)=1; for i=1:5 y(i+1)=y(1)+integrate('f(x,y(i))','x',0,0.2) printf('\n y%g = %g\n',i,y(i+1)) end
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function [x,y,typ]=IFTHEL_f(job,arg1,arg2) x=[];y=[];typ=[] select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; x(3)(11)=[-1 -1]...
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ScreenName String 'Join Game Lobby' ImplName String 'NULL SCREEN' ElementChunkArray Int 12 ScreenElementType Int 0 ImplName String 'Game Lobby Backdrop' TabIndex Int 1 Selectable Bool False Enabled Bool True ReferenceArea Rect( 0, 0, 800, 600 ) # left,top,right,bottom ScreenElementType Int 1 ImplName String 'Open Ship...
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// Scilab Code Ex 1.4 Lattice constant of a unit cell: Page-9 (2010) M = 58.5; // Atomic weight of NaCl, gram per mole d = 2180D+03; // Density of rock salt, per metre cube n = 4; // No. of atoms per unit cell for an fcc lattice of NaCl crystal N = 6.023D+23; // Avogadro's No. // Volume of the unit...
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// Calculate the difference in two diameters clc; x=20/12; L=50-10; lem=0.6; d=(L*lem)/(2*x); disp(d,'difference in diameters of the rollers(micro-meter)')
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// Exa 2.6 clc; clear; close; format('v',6) // Given data V_BEsat = 0.8;// in V V_BEact = 0.7;// in V V_CEsat = 0.2;// in V V_CC = 10;// in V Beta = 100; V = 5;// in V R_B = 50* 10^3;// in ohm R_E = 2* 10^3;// in ohm R_C = 3* 10^3;// in ohm //Applying KVL to input loop, V = R_B*I_B + V_BEact + I_C*R_E ...
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//Example 8.15 // clc; clear; close; //given data : B=5*10^6;// in Hz Ts=10;// in ns Td=4;// in ns a=9;// in ns/km b=2;// in ns/km l=6;// in km Tn=a*l;// in ns Tc=b*l;// in ns Ts_max=(0.35/B)*10^9; disp(Ts_max,"T system_maxmum,(ns) = ") Tsys=1.1*sqrt(Ts^2+Tn^2+Tc^2+Td^2); disp(Tsys,"T system,(ns) = ") //answer is wron...
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//chapter20 //example20.2 //page437 V_NL=30 // V regulation=1 // since regulation=((V_NL-V_FL)/V_FL)*100, we get V_FL as V_FL=100*V_NL/(100+regulation) printf("full load voltage = %.3f V \n",V_FL)
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clc function vl=f(t), vl=300*sin(1000*t), endfunction; //Defining functions R=20; //Assigning values to parameters w=1000; Z=R/cos(%pi/4); Xc=sqrt(Z*Z-R*R); Xl=2*Xc; L=Xl/w; C=1/(w*Xc); disp("Henry",L,"Inductance Value"); disp("Farad",C,"Capacitance Value");
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// chapter14 // example14.18 // page 313 f=200 // Hz Ro=10d3 // ohm, transistor output impedence Zi2=2.5d3 // ohm, input impedence of next stage // since Ro=2*%pi*f*Lp, making Lp as subject we get Lp=Ro/(2*%pi*f) // since Zi2=2*%pi*f*Ls, making Ls as subject we get Ls=Zi2/(2*%pi*f) printf("primary ind...
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clc; clear; //part a a=[3 2;-1 2]; b1=18; b2=2; disp(determ(a),"The determinant for part(a)=") //part b a=[1 2;1.1 2]; b1=10; b2=10.4; disp(determ(a),"The determinant for part(b)=") //part c a1=a*10; b1=100; b2=104; disp(determ(a1),"The determinant for part(c)=")
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//to determine excitation emf, torque angle,stator current, pf, max power, kVAR delivered clc; j=sqrt(-1); P=10000; V=400; Ia=P/(sqrt(3)*V); pf=.8; phi=acosd(pf); Iaa=Ia*complex(cosd(-phi),sind(-phi)); Vt=V/sqrt(3); X=16; Ef=Vt+j*X*Iaa; disp(abs(Ef),'excitation emf(V)'); dl=atand(imag(Ef)/real(Ef)); dis...
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@Harness: scheduler @$X: a->a+x @$Y: a->a+y @$Z: a+x->b @Input: a @Output: b @Result: X,Z
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//Example 6.1// Terminal voltage clc; clear; close; //given data : format('v',7) Z=440;// number of lap N=900;// revolutions in rpm fi=0.07;//fluxin Wb P=4;// number of pole A=4;//constant Ia=50;// armature current in Amperes E=462;//voltage in V E=(P*fi*Z*N)/(60*A);//general voltage in volts R=0.002;// resistance in...
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//Graphical// //Implementation of Equation 2.1.6 in Chapter 2 //Digital Signal Processing by Proakis, Third Edition, PHI //Page 45 clear; clc; close; L = 4; //Upperlimit n = -L:L; x = [zeros(1,L),1,zeros(1,L)]; a=gca(); a.thickness = 2; a.y_location = "middle"; plot2d3('gnn',n,x) xtitle('Graphical Repre...
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clc clear //input r=20;//resistance of an inductor in ohms x=15;//reactance of an inductor in ohms v=250;//supply voltage in volts //calculations z=((r^2)+(x^2))^0.5;//magnitude of impedance in ohms phi=(180/%pi)*atan(x/r);//phase angle in degrees i=v/z;//current magnitude in amperes //output mprintf('...
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clc; clear all; disp("heat transferred per meter") ta=15+273;//K air temperature ts=605+273;//K plate temperature U=6.5;// m/s velocity of air x=0.35;//m distance tf=(ts+ta)/2;// mean film temperature rho=0.614;//kg/m^3 cp=1046;//J/kg.K k=0.04593;// W/m.C mu=29.7*10^(-6);//kg/m.s Pr=0.675;, Re=rho*U*x/mu; ...
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clc; disp('case a'); // as per the data taken from Ex 1_3 rlg=24.948*10^5; // air gap reluctance for example 1_3(a) rlc=12.474*10^5; // iron core reluctance for example 1_3(a) rl=rlg+rlc; // net reluctance N=500; // Number of turns L=(N^2/rl)*1000; printf('Inductance for case a is %f mH\n',L); disp('case b');...
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clear; clc; //Example 17.7 Vcc=1.7; Re=0.008;//mohm Rc=0.008;//mohm Vy=0.4; Vbe=0.7; Vor=Vcc//logic 1 Vor=Vcc-Vy//logic 0 Vr=1.5; iE=(Vr-Vbe)/Re; printf('\nemitter current=%.2f microA\n',iE) iR=Vy/Rc; printf('\nmaximum current in Rc =%.2fmicroA\n',iR) iD=iE-iR; printf('\ncurrent through the diode=%.2f m...
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clc f=50 //Assigning values to parameters vl=440 p=1500 t=acos(0.2) vph=vl/sqrt(3) il=p/(sqrt(3)*vl*p*cos(t)) iph=il zph=vph/iph zph1=5.17+%i*25.3 [res]=real(zph1) [xl]=imag(zph1) l=xl/(2*%pi*f) disp("ohms",res,"The resistive circuit constant is") disp("ohms",l,"The inductive circuit ...
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// problem 7,9 Q=0.3 D=1.5 N=0.02 A=3.142*D*D/(4*2) p=3.142*D/2 m=A/p i=((Q*N)/(A*(m^0.6666)))^2 disp(i,"the slope of the sewer")
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clc; clear; alpha=0.01 //wedge angle in radian lambda=6000*10^-10 //wavelength in m n=10 //the fringe observed //calculation x=((2*n-1)*lambda)/(4*alpha) mprintf("The distance at which the 10th fringe will be obtained from the edge of the wedge is = %1.2e m",x)
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err_getUnsatCore3.tst
; get-unsat-core after an assertionset command (set-option :produce-unsat-cores true) (set-logic QF_UF) (assert true) (check-sat) (push 1) (get-unsat-core)
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// Exa 2.4 format('e',9) clc; clear; close; // Given data V = 30;//applied forward voltage in V R_L = 3;//load resistance in k ohm R_L = R_L * 10^3;// in ohm Imax = V/R_L;// maximum diode current in A Imax = Imax * 10^3;// in mA slope = -1/R_L;// in mho plot([V,0],[0,Imax]); xlabel("V_F in volts"); ylabe...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 7.6 //Caption : Program to Find the state of Steam at Discharge & Mass Rate of Flow //Given Values P1=8600;//[KPa] T1=773.15;//[K] //values of Enthalpy and...
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clc pathname=get_absolute_file_path('7_7_2.sce') filename=pathname+filesep()+'772.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") u2=sqrt(2*32.174*(-F-g*deltaZ/32.174)) Vdot=u2*%pi*(ID/2)^2 /144 t=V*0.1337/(Vdot*60) print...
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//Ex11_11 clc Vop_p = 7//peak to peap output voltage Vip_p = 100*10^-3//peak to peap input voltage Av = Vop_p/Vip_p disp("Av = output voltage/input voltage") disp(" = "+string(Av))//voltage gain
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// ErturkMe - Copyright 2011 - 2022 // http://erturk.me // ierturk@ieee.org // See license.txt thispath = get_absolute_file_path("demPMSM.dem.sce"); xcos(thispath+"/demPMSM.xcos"); clear thispath;
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// Exa 6.13 clc; clear; close; // given data fL=200;//in Hz fH=1;//in KHz AFBP=4;//unitless //for LP section design //assume C=0.01 uF C=0.01;//in uF R=1/(2*%pi*fH*1000*C*10^-6);//in ohm disp("For low pass section design component values are :"); disp(R/1000,"Value of R in Kohm is :") disp(C,"Value of C ...
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2_7.sce
clc //initialisation of variables h= 6.8 //in of mercury sm= 13.6 ssw= 1.026 g= 32.2 //ft/sec^2 //CALCULATIONS V= sqrt(2*g*h*(sm-ssw)/12)*3600/5280 //RESULTS printf ('speed of submarine = %.1f miles per hour ',V)
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// Exa 4.19 clc; clear; close; format('v',6) // Given data R1 = 50;// in ohm L = 318;// in mH L = L * 10^-3;// in H R2 = 75;// in ohm C = 159;// in µF C =C * 10^-6;// in F V = 230;// in V f = 50;// in Hz XL= 2*%pi*f*L;// in ohm Z1= R1+XL*%i;// in ohm I1= V/Z1;// in A XC= 1/(2*%pi*f*C);// in ohm Z2= R2...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex3_19.sce clc; clear; //Below values are taken from the given circuit (fig.3.27) Z1=complex(6,0); Z2=complex(10,15); Z3=complex(6,-3); Zs=(Z1*Z2)/(Z1+Z2)+Z3; Vs=...
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// Exa 3.17 clc; clear; close; // Given data E= 1.5;// in V R1addRm= 10;// addition of R1 and Rm in kohm Rx= 0; R=R1addRm+Rx;// in kohm R=R*10^3;// in ohm I= E/R;//meter FSD current in amp // At 0.8 FSD Im= 0.8*I;// in amp R= E/Im;// in ohm R=R*10^-3;// in kohm Rx= R-R1addRm;//in kohm disp(Rx,"Unknown...
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Ejercicio3.sci
function [m,b] = createmat() // Autores: Hector E. Gomez Morales // Funcion que una matriz a partir de los datos del problema x = [1.02; 0.95; 0.87; 0.77; 0.67; 0.56; 0.44; 0.30; 0.16; 0.01] y = [0.39; 0.32; 0.27; 0.22; 0.18; 0.15; 0.13; 0.12; 0.13; 0.15] n = size(x, 'r') m = ones(n, 5) b = ones(n, 1) for i=1:n m(i,...
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// Example 10.5 /// Given Z=R+iXl; i.e Z= 10+i10 R=10; // Resistance Xl=10; // Inductance f=50; // Frequency L=Xl/(2*%pi*f); // Value of Inductor disp(' The Value of Resistor is = '+string(R)+' Ohm'); disp(' T...
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8_5_2.sce
clc //initialisation of variables s= 0.9 v= 5 //ft/sec l= 10 //ft di= 0.5 //in n= 100 u= 0.002 //lbfsec/ft^2 w= 62.3 //lbf/ft^3 g= 32.2 //ft/sec^2 //CALCULATIONS dp= 8*u*v*l/(di/2)^2 hf= dp*144/(s*w) hk= v^2/(2*g) ht=hf+hk P= s*w*n*v*%pi*ht*di^2/(144*4*550) //RESULTS printf (' horse-power required = %....
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//oznaczenia: //y(1) <--> Zajace //y(2) <--> Rysie function [prawa_strona] = F(t,y) prawa_strona(1)= a*y(1)-b*y(1)*y(2) prawa_strona(2)= c*y(1)*y(2)-d*y(2) endfunction //Wartosci poczatkowe Z0=100; //poczatkowa liczba zajacy R0=10; //poczatkowa liczba rysi //Parametry a=0.1; b=0.01; c=0.002; d=0.05; //Czas...
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Linear Regression.sci
// Macro script for linear regression -- Scilab // Function to get coefficients for a line fit to features x given target y function [a,b] = linearRegressionTrain(x,y) // Extracting the least square mean of that function and displaying [a, b] = nanreglin(x, y); endfunction // Function to predict the target for ...
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clear;lines(0); s=poly(0,'s'); p=[s,s*(s+1)^2,2*s^2+s^3]; [pgcd,u]=gcd(p); p*u
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// This GUI file is generated by guibuilder version 4.2.1 ////////// f=figure('figure_position',[324,17],'figure_size',[965,700],'auto_resize','on','background',[33],'figure_name','Graphic window number %d','dockable','off','infobar_visible','off','toolbar_visible','off','menubar_visible','off','default_axes','on','v...
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clear // Variable declaration T_d1=23// The dry bulb temperature in °C T_w=5// The temperature of water in °C H=50// % saturation n_s=0.7// Saturation efficiency in % x_a=0.0089// Moisture content in kg/kg x_b=0.0054// Moisture content in kg/kg // Calculation //(a) printf("\n (a) By construction on the chart ( Figure...
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clear; clc; C1=integrate('x^2','x',1,0);//for y=0=z C2=0;// as (az.ay)=0 C3=integrate('x^2 -1','x',0,1); C4=integrate('-y-y^2','y',1,0); C=C1+C2+C3+C4; disp(C);
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clc k = 1/4 // return time to cutting ratio l = 900 + 2*75 // length of stroke in mm v = 6 // cutting stroke in m/min f = 2 // feed mm/stroke w = 600 // breadth in mm N = (v*1000)/(l*1.25) // r.p.m N = round(N) time = w/(f*N) // min printf("\n Time required for shaper to complete one cut = %d min" ,time )
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//Example 6.3 clc; clear; close; format('v',5); //Given data : g=9.81;//constant h=102;//mm H=105;//mm Cv=sqrt(2*g*h)/sqrt(2*g*H); disp(Cv,"Coefficient of velocity : ");
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///Chapter No 11 Steam Boilers ////Example 11.6 Page No 233 ///Enthalpy of superheated steam //Input data clc; clear; ms=6000; //Boiler produce of steam Kg/h P=25; //Boiler pressure in bar Tsup=350; //Boiler temperature in degree celsius Tw=40; ...
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//chapter8,Example8_12,pg 193 //for brightest spot R1=sqrt(b*lam) R1=0.05 lam=5*10^-5 bb=(R1^2)/lam//brightest spot //for darkest spot bd=(R1^2)/(2*lam)//darkest spot printf("position of brightest spot\n") printf("b=%.2f cm",bb) printf("\nposition of darkest spot\n") printf("b=%.2f cm",bd)...
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7.sci
clc; clear all; disp("Boundary layer thickness") x=1.2;//m distance from the leading edge of plate v=15.4*10^(-6);//m^2/s kinematic viscocity U=2.8;//m/s velocity of air Re=U*x/v;// Reynold's number disp("Blasius solution") delta1=5*x*1000/(Re)^0.5;//mm disp("mm",delta1,"Maximum thickness of boundary la...
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//Chapter 01: The Foundations: Logic and Proofs clc; clear; p="Maria learns discrete mathematics" q="Maria will find a good job" mprintf("Let p=%s \n Let q=%s",p,q) mprintf("\np->q is : If %s then %s",p,q) //p->q p implies q means If p then q. mprintf("\np->q is also expressed as :%s when %s",q,p)
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clear // // //Initilization of Variables L=6000 //mm //Length of circular shaft d1=100 //mm //Outer Diameter d2=75 //mm //Inner Diameter R=100*2**-1 //Radius of shaft T=10*10**6 //N-mm //Torsional moment G=80*10**3 //N/mm**2 //Modulus of Rigidity //Calculations J=%pi*32**-1*(d1**4-d2**4) //mm**4 //Polar Modulus /...
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Chapter3_Exampl18.sce
clc clear //INPUT DATA p1=101.325;//Pressure in kN/m^2 t1=303;//Temperature in K g=1.4;//constant cp=1.005;//specific pressure in kJ/kgK cv=0.718;//specific volume in kJ/kgK R=0.287;//gas constant in kJ/kgK r=2.5;//cut off ratio v2=0.1;//clearance volume in m^3/kg //CALCULATIONS v1=R*t1/p1;//volume at s...
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clc; T1=-30+273;//K T2=32+273;//K COP=T1/(T2-T1); eff=0.75; acctual_COP=eff*(COP); Q=5;//kW W=Q/acctual_COP; disp("required powar input is:"); disp("kW",W);
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load Mux4Way16.hdl, output-file Mux4Way16.out, compare-to Mux4Way16.cmp, output-list w%B1.16.1 x%B1.16.1 y%B1.16.1 z%B1.16.1 sel%B2.2.2 out%B1.16.1; set w 0, set x 0, set y 0, set z 0, set sel 0, eval, output; set sel 1, eval, output; set sel 2, eval, output; set sel 3, eval, output; set w %B0001001000110100, set ...
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exec("swigtest.start", -1); // OUTPUT [a, b] = output2(); checkequal(a, 1, "[a, b] = output2(): a"); checkequal(b, 2, "[a, b] = output2(): b"); [ret, a, b] = output2Ret(); checkequal(ret, 3, "[a, b] = output2Ret(): b"); checkequal(a, 1, "[a, b] = output2Ret(): a"); checkequal(b, 2, "[a, b] = output2Ret(): b"); [c, ...
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function fcontour2d(xr,yr,f,nz,style,strf,leg,rect,nax) // deff('[z]=surf(x,y)','z=x**2+y**2'); // fcontour(surf,-1:0.1:1,-1:0.1:1,10); // //! [lhs,rhs]=argn(0); if rhs=0,s_mat=['deff(''[z]=surf(x,y)'',''z=x**3+y'');'; 'fcontour2d(-1:0.1:1,-1:0.1:1,surf,10,1:10,'"011"','" "',[-1,-1,1,1]*1.5);']; ...
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// Scilab Code Ex17.2 Variation of critical magnetic field with temperature for tin Page-537 (2010) T_c = 3.69; // Critical temperature of superconducting transition, kelvin B_c0 = 3e+5/(4*%pi); // Critical magnetic field intensity to destroy superconductivity at zero kelvin, tesla B_cT = 2e+5/(4*%pi); // C...
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// Método iterativo para resolução de sistemas de equações lineares // Precisa de um chute inicial function x = Gauss_Seidel(a,b,x0,N,tol) n = size(a,1) x = zeros(n,1) sol = %F for iteracao = 1:N for i = 1:n soma=0 for j = 1:i-1 soma = soma + a...
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clear; clc; z11=10;z22=12;z12=5;z21=5; deltaz=(z11*z22)-(z12*z21); y11=z22/deltaz; printf("The y-parameters are:\n"); printf("-y11 = %f mho\n",round(y11*10^4)/10^4); y22=z11/deltaz; printf("-y22 = %f mho\n",round(y22*10^4)/10^4); y12=-z12/deltaz; printf("-y12 = %f mho\n",round(y12*10^3)/10^3); y21=y12; prin...
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//example-21.8 //page no-634 //given //frequency f=50 //Hz //mass m=50 //kg //density rho=7500 //kg/m^3 //volume of material V=m/rho //m^3 //hysteresis loop area A=150 //m^2 //scale factor //1 cm=0.008 Wb/m^2 on y-axis and 1cm=20 A/m on x-axis //energy lost during each cycle E=A*0.008*20*10^4 //J/...
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BEGIN MESSAGES DE_EMPPID_included USING DE_EMPPID_included_urn:nhs-itk:services:201005:SendCDADocument-v2-0_template WITH NULL SOAPWRAP SOAPACTION urn:nhs-itk:services:201005:SendCDADocument-v2-0 END MESSAGES BEGIN TEMPLATES DE_EMPPID_included_urn:nhs-itk:services:201005:SendCDADocument-v2-0_template TKW_ROOT/contrib...
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// Exa 6.22 clc; clear; close; // Given data T = 20;// in degree C H1 = 3039;// Enthalpy in kJ/kg H2 = 2725;// Enthalpy of 1kg dry saturated steam H_sup = H1-H2;// superheat of 1kg of steam in kJ/kg H= 2621.4;// heat required for 1kg or water in kJ m = H_sup/H;// in kg disp(m,"Quantity of water in kg is");
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// Scilab code Exa11.12 : : Page-539 (2011) clc; clear; e = 1.6e-19; // Charge of an electron, C R = 9.144; // Radius, metre m_p = 1.67e-027; // Mass of the proton, Kg E = 3.6*1.6e-13; // Energy, joule L = 3.048; // Length of the one synchrotron section, metre T = 3; ...
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// Example 4.26;//Bifringence and differnce between the propogation constt. clc; clear; close; Lb=0.05;//Birefringent Coherence over length in meter h=0.5;//wavelength in micro meter df=1;//spectral width in nano meter Bf=((h*10^-6)/(Lb));//modal bifringence Lbc= (((h*10^-6)^2)/(Bf*df*10^-9));//COHERENCE LENGT...
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function [df] = qcut() // Calls and initializes qcut function // // Syntax // df = qcut() // // Parameters //df: qcut input // // Description //The pandas documentation describes qcut as a “Quantile-based discretization function.” This basically means that qcut tries to divide up the...
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//To determine the specific energy consumption //Page 376 clc; clear; W=400; G=1; a=1.5; //Acceleration Ta=30; //Acceleration Time Tf=36; //Free running Period Tc=25; //Coasting Period B=2.6; r=45; RI=10/100; //Rotational Inertia Effect Eff=75/100; // Overall Efficieny g=9.81; //Accleration due to gravit...
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clc clear //Input data V=24800//Potential difference applied in V n=1//Order of diffraction l=1.54*10^-10//Wavelength of X-ray beam in m q=15.8//Glancing angle in degrees //Calculations d=((n*l)/(2*sind(q)))/10^-10//Interplanar spacing in m lmin=12400/V//Minimum wavelength of X-rays emitted in angstroms q...
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function [h,x]= meshe(a,b,N) h = (b-a)/N; for i=1:N+1 x(i) = a +(i-1); end endfunction function [y]=f(x) y = x^3-3*x^2+2; endfunction function [E,Iapp] = trapezoid(a,b,N,Iex) [h,x] = meshe(a,b,N); Iapp = 0; for k=1:N Iapp = Iapp + (f(x(k)) + f(x(k+1))); end Iapp = (...
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// generated by builder.sce: Please do not edit this file // ------------------------------------------------------ smcube_block_path=get_absolute_file_path('win_loader.sce'); libsmcube_link_num = link(smcube_block_path+'release/libsmcube_block.dll',['smcube_block'],'c'); clear smcube_block_path;
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lines(0); ilib_verbose(0); ierr = exec('loader.sce', 'errcatch'); if ierr <> 0 then disp(lasterror()); exit(ierr); end example_Init(); // This example shows how to use C++ functions with STL lists arguments // Here, STL lists are converted from/to Scilab matrices (SWIG_SCILAB_EXTRA_NATIVE_CONTAINERS is not defined...
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function func(a) lam=poly(0,'lam'); lam=lam charmat=a-lam*eye(3,3); disp(charmat,"the characteristic matrix is"); charpoly=poly(a,'lam'); disp(charpoly,"the characteristic polynomial is:"); lam=spec(a); disp(lam,"the eigen values of A are"); endfunction function[x,lam]=eigenvect...
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//***************************************************************** // animation of a spring pendulum //***************************************************************** // function to create rotation matrix function M=rot(a) M=[cos(a),sin(a);-sin(a),cos(a)]; endfunction // constants n=40; // number of ...
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// //given l=10,b=15, a1=l*b ir=0.686 fr=9.976 n=2 m=100 marea=150//measured area c=(marea/100)+10.710 area=m*c printf("\n area of zero circle is %0.3f square centimeters',area)