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function [e1,e2,e3,e4,e5,e6,e7,e8,e9,e10,.. e11,e12,e13,e14,e15,e16,e17,e18,e19,e20,.. e21,e22,e23,e24,e25,e26,e27,e28,e29,e30,.. e31]=%grae(i,f) [lhs,rhs]=argn(0) if rhs<>2 then error(39), end if type(i)<>10 then error('The name of the element of the graph-list must be a string'), end l=prod(size(i)) if lhs<>l then...
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//Chapter-8,Example 7,Page 196 clc(); close(); Ksp=3.45*10^-11 //solubility product of CaF2 //Ksp = [Ca+2]*[F-]^2 //Ksp = [S]*[2*S]^2 S = nthroot(Ksp,3)/4 printf('the solubility of CaF2 is S = %.7f mole/litre',S) //mistake in textbook
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//Page Number: 652 //Example 12.6 clc; //Given Z0=50; //ohm p=2.4; L=0.313; x=2*%pi*L; y=tan(x); Zl=(Z0*(1+(p*p*%i)))/(p+(p*%i)); T=(Zl-Z0)/(Zl+Z0); p=sqrt((real(T))^2+(imag(T))^2); disp(p,'Reflection coefficient:');
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// The equation 8*x^3-12*x^2-2*x+3==0 has three real roots. // the graph of this function can be observed here. xset('window',0); x=-1:.01:2.5; // defining the range of...
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// Example 4.27;//Maximum bit rate clc; clear; close; L=10;//Length in Km Dt2=600*10^-12;//Birefringent in second per kilometer B=(0.9)/(Dt2*L*10^3);// Btm= round((B/0.55)*10^-3);// maximum bit rate in kilo bit per second disp(Btm,"maximum bit rate in kilo bit per second")
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exec RungeKutta4.sci; //Los valores del metodo se toman como vectores horizontales function z = f(t,u) z(1,1)=-4*u(1,1)-2*u(1,2)+cos(t)+4*sin(t); z(1,2)=3*u(1,1)+u(1,2)-3*sin(t); endfunction function z = yex(t) z(:,1)=(2 .* exp(-t')) - (2 .* exp(-2*t')) + sin(t'); z(:,2)=(-3 .* exp(-t')) +...
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function [sr]=%lss_r_p(s,p) // sr=%lss_r_p(s,p) <=> sr=s/p // s : syslin list // p : polynomial matrix //! // Copyright INRIA sr=s/tlist(['lss','A','B','C','D','X0','dt'],[],[],[],p,[],[])
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function II3_res = fis_II3(inVector, inCodes) // аргументы: входной вектор числовых значений и массив строк-имен переменных f_II3=newfls("m"); // тип Мамдани f_II3.name="fisII3"; f_II3.TNorm="min"; // and f_II3.SNorm="max"; // or f_II3.Comp="one"; // not f_II3.defuzzMethod="centroide"; // центр тяже...
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load('/home/willane/Downloads/p2STD/xa_10_1.sod') x1=x_a load('/home/willane/Downloads/p2STD/xa_26_1.sod') x2=x_a load('/home/willane/Downloads/p2STD/xa_43_1.sod') x3=x_a X = [x1 x2 x3] //concatenação dos sinais Xt=fft(X) //cálculo da transformada de fourier nXt = length(Xt) //calcula o tamanho do sinal Xutil = ...
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//clc() A = [6,15,55;15,55,225;55,225,979]; sl = 0 l11 = (det(A(1,1)))^(1/2); //for second row l21 = (det(A(2,1)))/l11; l22 = (det(A(2,2)) - l21^2)^(0.5); //for third row l31 = (det(A(3,1)))/l11; l32 = (det(A(3,2)) - l21*l31)/l22; l33 = (det(A(3,3)) - l31^2 - l32^2)^(0.5); L = [l11,0,0;l21,l22,0;l31,l32,l33]...
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// Grob's Basic Electronics 11e // Chapter No. I // Example No. I_13 clc; clear; // Find the reciprocals for the following powers of 10: (a) 10^5 (b) 10^-3. // Given data A = 10^5; // Variable 1 B = 10^-3; // Variable 2 C = 1/A; disp (C,'The reciprocal of 10^5 is') disp ('i.e 10^-5') D = 1...
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//to find no of poles, slip and freq of rotor currents at full load, motor speed at twice of full load clc; n_s=600; f=50; P=120*f/n_s; disp(p,'no of poles'); n=576; s=(n_s-n)/n_s; disp(s,'slip'); f2=s*f; n_r=s*n_s; disp(n_r,'rotor speed wrt rotating field(rpm)'); ss=f2*s; n=(1-ss)*n_s; disp(n,'motor sp...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 8: BRAKING // EXAMPLE : 8.2 : // Page number 806 clear ; clc ; close ; // Clear the work space and console // Given data ...
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z1=20+%i*50; z2=15+%i*35; z3=-%i*10; z=z1+z2+z3; disp("total series impedance (in Ω) is"); disp(z);
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function [frq,db,phi]=repfreq(sys,fmin,fmax,pas) pas_def='auto'; l10=log(10); [lhs,rhs]=argn(0) //discretization //-compat type(sys)<>15 retained for list/tlist compatibility if type(sys)<>15&type(sys)<>16 then error(97,1),end; flag=sys(1); if flag(1)='r' then dom=sys(4),else dom=sys(7),end if dom==[]|dom==0 then er...
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//Example 4.1.b // power lost clc; clear; close; //given data : I=11; // current in A V1=55; // voltage in V V2=220; // voltage in V V=V2-V1; R=V/I; P=I^2*R; disp(P,"power lost,P(W) = ")
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 7, Example 11") //Liquid sulphur di oxide in a saturated state flows inside a L=5m long tube and D=25mm internal diameter with a mass flow rate(mdot) of 0.15 kg/s....
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//7th term of the series 3,6,12,.... clear; clc; close; //in the series r=2, so using the formula // nth term=a*r^(n-1) a=3;n=7;//given data term7=3*(2)^(7-1); mprintf("\n the seventh term of the series is %i",term7)
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clc; clear; printf("\t\t\tChapter8_example2\n\n\n"); // Determination of heat lost through the glass per unit area // properties of air at 22 + 273 = 295 K = 300 K(approx) and 273 K from appendix table D1 rou= [1.177 1.295]; // density in kg/cu.m cp= [1005 1005.5]; // specific heat in J/(kg*K) v= [15.68e-6 12.59e-6];...
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clc // Given that fringe_width = 9e-4 // fringe width in meter a = 0.1 // distance of bi prism from slit in meter b = 0.9 // distance of bi prism from screen in meter lambda = 5.896e-7 // wavelength of light in meter // Sample Problem 14 on page no. 1.45 printf("\n # PROBLEM 14 # \n") D = a + b // calculation ...
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printf('Antes de ingresar los valores asegurese de acomodar las ecuaciones tal que los valores de las diagonales sean los mas altos'); A=input("Ingrese la matriz de coeficientes ann A = ") B=input("Ingrese el vector de valores bn B = ") n = length(B) x = zeros(1, n) x_ant = x Er=1 while abs(Er)>10^-4 for i=...
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//EXAMPLE 5-31 PG NO-326; V=25; R1=50; R2=40; R3=10; I=(V/(R1+((R2*R3)/(R2+R3))))*(R3/(R2+R3)); disp('i) Current (I) is = '+string (I) +' A ');
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//Chapter-1,Example1_14_9,pg 1-61 n=4 //for FCC structure //the interplanar spacing of plane h=1 k=1 l=1 d=2.08*10^-10 //distance A=63.54 //atomic weight of Cu N=6.023*10^26 //...
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L = 6 ; // Span of the beam in ft P = 10800 ; // Pressure acting in lb c = 2 ; // in ft b = 2; // Width of cross section of the beam in inch h = 6; // Height of the cross section of the beam in inch x = 9 ; // in inch Ra = P/3 ; // Reaction at point at A V = Ra ; // Shear force at section mn M = Ra*x ; // Bend...
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//Determine appropriate values of RS and RD. //Solved Example Ex4.8 page no 120 clear clc Rs=750 //kΩ printf("\n Rs = %0.2f K ohm",Rs) Vdd=24 //V Vdsq=15 //V Idq=0.002 //mA Rd=((Vdd-Vdsq-(Idq*Rs))/Idq)/1000 printf("\n Rd = %0.2f K ohm",Rd)
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clc; v=343; //velocity in m/sec vs=20; //velocity in m/sec fs=500; //original frquency f1=(fs*v)/(v-vs); //doppler effect disp(f1,"Percieved frequency in Hz = "); //diplaying result
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//EX13_16 PG-13.10 clc clear printf("conversion of octal no 475.25 to its decimal equivalent =") N=(4*8^2)+(7*8^1)+(5*8^0)+(2*8^(-1))+(5*8^(-2)); printf(" %.5f",N)
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errcatch(-1,"stop");mode(2);//Example 4.2.1: peak amplitude ; ; //given data : format('v',7) E_rms=230;//in V Ep=sqrt(2)*E_rms; disp(Ep,"peak amplitude,Ep(V) = ") exit();
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//Initilization of variables d=0.09 //m //diametre of the right circular cylinder h=0.12 //m //height of the cyinder W=10 //N // self weight of the bar l=0.24 //m //length of the bar //Calculations theta=atand(h/d) // angle which the bar makes with the horizontal Lad=sqrt(d^2+h^2) //m // Lad is the length of the...
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errcatch(-1,"stop");mode(2); syms n disp('1+2+3+4+5+6+7+....+n+.....=') p=1/n*(1/n+1)/2 disp(limit(p,n,0)); exit();
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function y = fun(d) y = d.^2 - 8 endfunction function j = der(h) j = 2*h endfunction //plot(k, fun(k)) //plot(k, zeros(1, length(k))) function [raiz, erro, iteracoes] = newtoton(x0, p) x = x0 - fun(x0)/der(x0) er = abs((x-x0)/x) inter = 0 while(er>=10^-p) x0 = x ...
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clc clear printf("example 6.11 page number 232\n\n") printf("this is a theoritical question, book shall be referred for solution")
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clc; //Example 7.6 //Page No 261 //solution K=0.75; fcp=500; K1=1.5; fcf=500; vm=2; fm=2; Vm=4; Fm=1; //(a) disp("(a) FM Modulator "); m=(vm*K1)/fm; disp(m,"m = "); disp("PM Modulator "); m1=vm*K; disp(m1,"m = "); disp("Since the modulation indexes are same the output spectrum is also the same, which is in ...
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// Theory and Problems of Thermodynamics // Chapter 7 // Thermodynamic Relations // Example 12 clear ;clc; //Given data T1 = 373.15 // normal boiling point of water in K T2 = 423.15 // boiling point of water on hill in K h_fg_1 = 2257 // latent heat of vaporizat...
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// Exercise F4 // ------------ // Solve the y= -5*x + 5*(t^2)+2*t equation with 0<=x<=2 and x0 = 1/3 with the improved Euler method // --------------------------------------------------------- function [k,t,x]=eulercor(a, b, n, x0) // k is the step, t the margin and x is the vector with the approaches h=(b...
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clear clc //Example 10.10 disp('Example 10.10') s=%s; Gp=1/(5*s+1); Gm=1/(s+1); Gv=1/(2*s+1); Ys=Gv*Gp*Gm Routh=routh_t(Ys,poly(0,"Kc")); // produces routh table for polynomial 1+Kc*Ys disp(Routh) K1=roots(numer(Routh(3,1))); K2=roots(numer(Routh(4,1))); mprintf('K lies between %f and %f for system to be stable', ...
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//Exa 11.2 clc; clear; close; //Given data : rho=5*10^14*10^-2;//ohm-m l=5*1000;//m r1=2.5;//m r2=r1+1;//m R_ins=rho/(2*%pi*l)*log(r2/r1);//ohm disp(R_ins/10^6,"Insulation resistance of cable(Mohm) :");
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// Example 7.14 clc; clear; close; // Given data format('v',5); f_H= 200;// in Hz f_L= 2*10^3;// in Hz C= 0.05*10^-6;// in F // For low-pass filter, R_desh= 1/(2*%pi*f_H*C);// in Ω R_desh= R_desh*10^-3;// in kΩ disp("The value of R'' is : "+string(R_desh)+" kΩ ( Approx. 20 kΩ)") // For high-pass filter, R...
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clc // // // //Variable declaration mu=1.4 //Refractive index cosr=0.8631 t=0.01*10**-3 //thickness lambda1=4000*10**-10 //Wavelength 1 lambda2=5000*10**-10 //Wavelength 2 //Calculations n1=(2*mu*t*cosr)/lambda1 n2=(2*mu*t*cosr)/lambda2 deln=(n1)-(n2) //Result printf("\n The number of dark...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Equal16.tst load Equal16.hdl, output-file Equal16.out, compare-to Equal16.cmp, output-list a%B1.16.1 b%B1.16.1 out%B3.1.3; set a %B0000000000000000, ...
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//all the quantities are expressed in SI units ratio = 12; //contraction ratio of wind tunnel nozzle Cl_max = 1.3; //maximum lift coefficient of the model S = 0.56; //wing planform area of the model L_max = 4448.22; //maximum lift force that can be measured by the mechanical balance rho_in...
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// Initiization of variables theta=30 // degrees // ange made by the ball against the wall e=0.50 // Calculations // The notations have been changed // Resolving the velocity v as, v_x=cosd(theta) v_y=sind(theta) V_y=v_y // from coefficient of restitution reation V_x=-e*v_x // Resultant velocity V=sqrt(V_x^...
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clc // Given That d = 1.5e11 // separation between earth and sun in meter power_sun = 3.8e26// power radiated by sun in W c = 3e8 //Sample Problem 7 Page No. 82 printf("\n # Problem 7 # \n ") s = power_sun /(4 * %pi * (d^2)) //calculation of Energy received per unit surface area per unit time p = s / c // calc...
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clc; clear; n1=input("Enter the value of Refractive Index n1:") n2=input("Enter the value of Cladding Refractive n2:") NA1=sqrt((n1*n1)-(n2*n2)) delta=((n1*n1)-(n2*n2))/(2*(n1*n1)) NA2=n1*sqrt(2*delta) Acceptance_angle1 =asind(NA1) Acceptance_angle2 =asind(NA2) disp("NA1",NA1) disp("NA2",NA2) disp('Acceptanc...
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clc; P=2400;//N, Vertical Force applied at D AB=2.7;//m, perpendicular distance between A and B BE=2.7;//m, perpendicular distance between E and B BK=1.5;//m, perpendicular distance between B and K AJ=1.2;//m, perpendicular distance between A and J EF=4.8;//m, perpendicular distance between E and F BD=3.6;//m, p...
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clc clear A=[6 -2 1; -2 7 2; 1 2 5] b=[11 5 -1] D=[6 0 0; 0 7 0; 0 0 -5] L=[0 0 0; -2 0 0; 1 2 0] U=[0 -2 1; 0 0 2; 0 0 0] DI=inv(D) printf('For Jacobi method, we need to compute the eigen value of this matrix') B=DI*(L+U) disp(B) T=spec(B) disp(T) printf(' Magnitude of Largest eigenvaue is %f',abs(T(2,1))...
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N = 1000 exec("scriptTrousCompl.sce",-1) function y=freqT(n) y = zeros(1,n) for i = 1:N k = T(n) y(k) = y(k) + 1 end y = y / N endfunction function y=loitheoY(n) y = zeros(1,n) for k = 1:n y(k) = (k-1) / prod(1:k) end endfunction clf() //n = input('n = ?') argument...
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//clc(); clear; //To calculate the glancing angle lambda=0.071*10^-9; //wavelength in m //miller indices of diffraction plane h=1; k=1; l=0; a=0.28*10^-9; //lattice constant in m n=2; d=a/sqrt((h^2)+(k^2)+(l^2)); disp(d); theta=asind((n*lambda)/(2*d)); printf("glancing angle in degrees is");...
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//Finding the third force F //Assume that the third force F makes an angle theta with x-axis //Resolving the forces we get //F*cosd(theta)=-225.9...(1) //N //F*sind(theta)=-408.9...(2) //N //Then (2)/(1) gives theta=atand(-408.9/-225.9) //degree F=sqrt(225.9^2+408.9^2) //N printf("The third force is F=%.1f ...
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// example 4.3 // find the linear interpolation polinomial // using disp('f(2)=4'); disp('f(2.5)=5.5'); // 1)lagrange interpolation, P1=legrangeinterpol (2,2.5,4,5.5) // 2)aitken's iterated interpolation, P1=aitkeninterpol (2,2.5,4,5.5) // 3) newton devided differance interpolation, ...
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function mOutput = GetSags(mPoints, spParams) //Generates an array of sag values given an array of [u, v] points //And surface parameter structure defining general polynomial freeform surface format('e', 16); //Build Polynomial Terms sPolynomialTerms = ''; iNM = size(spParams.mPolyCoef); ...
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function [stk,nwrk,txt,top]=f_maxi(nwrk) //!purpose // Scilab maxi function translation //! txt=[] select rhs case 1 then s2=stk(top) if lhs==1 then if s2(3)=='0' then fun='ivmax',else fun='dvmax',end nwrk=dclfun(nwrk,fun,s2(3)) out=callfun([fun,mulf(s2(4),s2(5)),s2(1),'1'],s2(3)) stk=list(out,'0',...
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clc //initialisation of variables u= 80 //ft/sec n= 62 r= 1/4 v= 11 //ft^3 w= 62.3//lbf/ft^3 p= 2 //lbf/in^2 //CALCULATIONS uw= u*n/(r*v*w) R= v*w*(uw/u)^2 P= r^2*p/R //RESULTS printf (' water velocity= %.f ft/sec',uw) printf (' \n pressure drop= %.5f lbf/in^2 per ft',P)
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 11.4w //calculation of the separation between the particles under mutual attraction //given data mA=1//mass(in kg) of particle A mB=2//mass(in kg) of particle B R=1//initial distance(in m) between the two particles ...
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clear// //Variables RC = 250.0 * 10**-12 //Time constance (in seconds) Vomax = 50.0 //Maximum output voltage (in volts) tau = 0.05 * 10**-6 //time (in seconds) //Calculation alpha = Vomax / RC //alp...
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//Jhon Sebastian Cano Ruiz - 1556156 clc() A = input("Ingrese la matriz en el formato [# # # ; # # # ; # # #]: ") b = input("Ingrese el vector columna b en el formato [# ; # ; #]: ") errorLimite= input("Digite el límite de error deseado: "); limiteIteracion= input("Ingrese un maximo de iteraciones: "); iteracion=...
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PL/SQL Developer Test script 3.0 71 declare v_sal emp.sal%TYPE; --税率 v_s NUMBER(7, 3); --速算扣除数 v_ss NUMBER(7, 3); --总税率 v_toaltax NUMBER(11, 4) := 0; --所在级别 v_level NUMBER(1); --创建游标查询数据 CURSOR currsor_emp --查出员工工资 IS SELECT SAL, TO_CHAR(HIREDATE, 'yyyy') as yea...
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function newtonraphsonMd(f,df,d2f,x0,tol,it); //f es la función que se ingresara entre comillas //x0 es un punto //df es la primera derivada de la función que ese insertara entre comillas //d2f es la segunda derivada de la función que ese insertara entre comillas //tol es la tolerancia //it es el numero maximo de ite...
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function b = fir2(n, f, m, grid_n, ramp_n, window_in) funcprot(0); rhs= argn(2); if rhs < 3 | rhs > 6 error("Wrong Number of input arguments"); end //verify frequency and magnitude vectors are reasonable t = length(f); if t<2 | f(1)~=0 | f(t)~=1 | or(diff(f)<0) error ("fir2: frequency m...
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//Exa 2.13 clc; clear; close; //Given Data : format('v',8); disp("Assumptions : "); disp("Power to be transmitted is the same(say, P watts)"); disp("Length of the line is the same(say, l meters)"); disp("Losses in the line are the same(say, W watts)"); //I=P/V;//in Ampere //a=2*I^2*R=2*(P/V)^2*rho*l/W;//in m...
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//Section-1,Example-1,Page no.AC-265 //To calculate the amount of lime required for softening of given hard water sample. clc; V_1=5000 //Given solution of hard water A_1=72 //Amount of MgSO4(ppm) M_F1=100/120 //Multiplication factor C_Eq= A_1*M_F1 //CaCO3 equivalent L_R=(74/100)*C_Eq*V_1*10^-3 disp(L...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex12_2.sce clc; clear; z=complex(6,8); Vl=110; printf("\nPhase current of the load: Magnitude \t Angle(deg) \n") I_YR=complex(Vl*cosd(0),Vl*sind(0))/(z); I_BY=co...
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//Ex 5.3 page 185 clc; clear; close; Vs=400;//V alfa=0.25;// duty cycle delta_I=10;// A L=0.5;// H R=0;// ohm Vo=alfa*Vs;//V //Vo+L*di/dt=Vs -- putting dt=Ton & di=delta_I Ton=delta_I/((Vs-Vo)/L)*1000;// ms T=Ton/alfa;// ms f=1/T*1000;//Hz printf('\n chopping frequency = %d Hz',f)
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getd ('../../libs/'); //CHARGEMENT IMAGES img_origine_v2 = readpbm("Gliese 581d V2.pbm"); img_origine = readpbm("Gliese 581d.pbm"); //===============IMG V2=============== scf(1); title("Image : Gliese 581d V2 bruitée"); display_gray(img_origine_v2); //HISTOGRAMME IMAGE NON DEBRUITE scf(2); title("histogramme image ...
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// Grob's Basic Electronics 11e // Chapter No. 03 // Example No. 3_15 clc; clear; // How much current is needed for a 24 Ohms Resistor that dissipates 600 W? // Given data R = 24; // Resistance=24 Ohms P = 600; // Power=600 Watts I = sqrt(P/R); disp (I,'The Current I in Amps')
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function z=f(x,y) z=1-x^2-y^2 endfunction R=linspace(0,.1,4); X=[]; x=1; for r=R // [x,err]=fsolve() end //manual od fsolve // Draw a circle of radius 1 according to its cartesian equation: plotimplicit "x^2 + y^2 = 1" xgrid(color("grey"),1,7) isoview
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clc //page 39 mass=30;// kg W=mass*9.81;// N, Weight of package alpha=15;//degree alpha=alpha*%pi/180;// Conversion into radian F=W*sin(alpha);//N printf("F= %.2f N",F);
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clc //initialisation of variables q=60//cfs D=4//ft w=0.177//ft s=0.59//ft h=4.0//ft d1=1.0//ft v=0.90//ft d1=0.42//ft h1=6.0//ft h2=1.5//ft dl=1.3//ft p=0.41//ft u=0.8//ft u1=3.2//ft y=0.45//ft //CALCULATIONS H=s*D//ft d2=d1*D//ft V=v*D//ft P=p*D//ft D1=y*D//ft //RESULTS printf('the critical de...
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load Zxg.hdl, output-file Zxg.out, compare-to Zxg.cmp, output-list a%B2.16.1 b%B2.1.2 out%B2.16.1; set a %B0000000000000000, set b 0, eval, output; set a %B0000000000000000, set b 1, eval, output; set a %B1111111111111111, set b 0, eval, output; set a %B1111111111111111, set b 1, eval, output;
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 8 // Condensation and Boiling // Example 8.5 // Page 337 printf("Example 8.5, Page 337 \n \n"); D = 0.02 ; // [m] l = 0.15 ; // [m] T = 500+273 ; // [K] Tc = -196+273 ; // [K] e = 0.4; s = 5.670*10^-8; // Film boiling will occur...
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A = [2,1]; b = 5; mu = 10; u = [1;1;1]; x = [1.3;2.4]; v = 0; function y = f(x) y = (x(1)-3)^4 - x(2)^2; endfunction function y = fprim(x) fp1 = 4*(x(1)-3)^3; fp2 = 2*x(2); y = [fp1;fp2]; endfunction function gDesig = g(x) g1 = x(1)^2 + x(2)^2 - 25; g2 = x(1)-x(2) + 1; g3 = -x(1); gDe...
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// sum 23-5 clc; clear; m=1100; V=65*5/18; t=4; r=0.22; mb=12; C=460; S=0.5*V*t; //Total kinetic energy TE=K.E(vehicle)+K.E(rotating parts). TE=((0.5*m*(V^2))+(0.1*0.5*m*(V^2))); E=TE/4; w=V/r; theta=S/r; T=E/theta; delT=E/(mb*C); // printing data in scilab o/p window printf("S is %0.2f m ",S); ...
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// Example 4.1:Link Length clc; clear; close; alpha = 0.5;//Attenuation loss in dB/Km Pi=1.5;//input power in milli watt Po=2//Output power in micro watt L=(10/alpha)*(log10((Pi*10^-3)/(Po*10^-6)));// Link Length in Km disp(L,"Length in Km")
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clc clear //INPUT DATA p1=1;//initial pressure in bar pd=30;//delivery pressure in bar t1=288;//temperature in K n=1.3;//index of copression //CALCULATIONS p21=sqrt(p1*pd);//Intermediate pressure in bar v121=(p21/p1)^(1/n);//volume ratio t21=t1*(p21/p1)^((n-1)/n);//temperature in K v212=t21/t1;//volume rat...
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//Section-6,Example-5,Page no.-P.48 //To calculate the quantity of ethyl alcohol required. clc; dl_Tf=10 //(K) K_f=1.86 //(Kkgmol^-1) M_w=62 d=1 //density (assumption) V=10 //Volume(L) M=V*d W=((dl_Tf*M*M_w)/K_f)*10^-3 disp(W,'Quantity of ethyl alco...
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//Key: //f(x) : Objective Function //ci(x)'s : Constraints //Variable Declaration: function [a] = f(x) a = -2.0*x(1) - 1.6*x(2) endfunction //Calculation X = [16820,1152] //Result: printf("Maximum Profit is $ %.0f /day or $ %f /year",-f(X),-365*f(X))
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clc clear //Conditions at 10 bar P1=10; //in bars Hg=2778.1; //in kJ/kg Tsat=179.9+273; //Temperature in K Vg=0.194; //in m^3/kg //Conditions at 10 bar and 300 Celcius Cps=2.1; Tsup=300+273; H1=Hg+(Cps*(Tsup-Tsat)); V1=Vg*(Tsup/Tsat); U1=H1-(P1*100*V1); printf('The I...
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errcatch(-1,"stop");mode(2);//Caption:Find the efficiency //Exa:4.4 ; ; //From Exa:4.3 V_2=230;//in Volts Z_1=4+%i*12; I_s=75*(cosd(30)+%i*sind(30));//in Amperes a=10;//transformation ratio E_1=2282.87*(cosd(2.33)+%i*sind(2.33));//in Volts E_2=228.287*(cosd(2.33)+%i*sind(2.33));//in Volts I_p=7.5*(cosd(30...
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s=%s syms K J f K=60; // given J=10; // given p=K/J q=K/J+(f/J)*s+s^2 G=p/q; disp(G,"Qo(s)/Qi(s)=") zeta=0.3; // given cof1=coeffs(q,'s',0) // on comparing the coefficients Wn=sqrt(cof1) cof2=coeffs(q,'s',1) // 2*zeta*Wn=cof2 f/J=2*zeta*Wn r=s^2+f/J s=s^2+f/J+K/J H=r/s; disp(H,"Qe(s)/Qi(s)=")
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function[P]=NEWTON(X,Y,x) P=Y(1) n=length(X) for i=2:n A=0 for j=1:i w=1 for k=[1:j-1,j+1:i] w=w*(X(j)-X(k)) end A=A+Y(j)/w end _X=1 for l=1:i-1 _X=_X*(x-X(l)) end P=P+A*_X end endfunction //Исходные данные X=[0,%pi/4,%pi/2,3*%pi/2] Y=[1,1.4,1,-1] x1=[%pi/6,...
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//Example 26.1 d_o=60;//Object distance (cm) d_i=2;//Image distance (cm) h_o=1.2*10^-2;//Object height (cm) h_i=-h_o*d_i/d_o;//Image height (cm) printf('Size of the image on the retina = %0.2e cm',h_i) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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// Example 2.14 clc; clear; close; // Given data Q= -40;// in kJ/kg W= -80;// in kJ/kg E= Q-W;// change in internal energy in kJ/kg disp(E,"Change in internal energy in kJ/kg is : ") disp("Thus internal energy of the working substance increases ")
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function coord = pixelMissionA1(img, pixelValue) size_X = size(img, 1); //On récupère la longueur de l'image à modifier. size_Y = size(img, 2); //On récupère la largeur de l'image à modifier. img_out = zeros(size_X, size_Y); //On crée une matrice nulle qui va contenir l'image modifiée (ici une matrice ...
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// chapter 3 // example 3.17 //page 150, figure 3.53 Ri=%inf;Ro=0; Aol=%inf; Vb=0;//b is virtually ground Vout=1;// let us assume //input current of op-amp is zeroas R=%inf I1=(Vb-Vout)/100000 If2=I1; Va=((10000)/(100000))*(Vb-Vout) //at node A Iin=I1+If1 // (Vin-Va)/10*10^3=(Va-Vb)/10*10^3 + (Va-Vo)/100*10...
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// // $Id$ // // Copyright (C) 2008 Antoine Blais, Antoine Drouin // // This file is part of paparazzi. // // paparazzi is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2, or (at yo...
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//Example 5.46 //Newton's Divided Difference Interpolation //Page no. 192 clc;close;clear; x=[3,3.6,3.8] y=[0.13515,0.83059,0.26253]; deff('y=f1(x1,x2,y1,y2)','y=(y2-y1)/(x2-x1)'); deff('y=f2(x1,x2,x3,y1,y2,y3)','y=(f1(x2,x3,y2,y3)-f1(x1,x2,y1,y2))/(x3-x1)'); function [x]=f(x1,x2,x3,y1,y2,y3) x=(x1+2*x2+...
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clc; P=200000; // rated power output of transformer E1=11000; // primary side voltage E2=400; // secondary side voltage // initialising the results of the open circuit test performed on l v side Vo=400; // open circuit voltage in V Io=9; // no load current in A Po=1500; // core loss in W // initialising the res...
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// Scilab code Ex11.1: Pg.483 (2008) clc; clear; R0 = 1.2; // Quantum mechanical correction, fm A_He = 4; // Atomic mass number of Helium A_U = 238; // Atomic mass number of Uranium R_He = R0*(A_He)^(1/3); // Nuclear radius of Helium, fm R_U = R0*(A_U)^(1/3); // Nuclear radius of Uranium, fm prin...
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// Public domain script. loi_de_X = 1/6*ones(1,6); loi_de_Y = loi_de_X; subplot(2,1,1); bar(1:6, loi_de_X); loi_de_2_des = convol(loi_de_X, loi_de_Y); subplot(2,1,2); bar(2:12, loi_de_2_des);
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clc; clear; printf("\n Example 6.1"); d_o=25e-3;//Diameter of orifice printf("\n\n Given:\n Diameter of orifice = %d mm",d_o*1e3); d_p=75e-3;//Diameter of pipe printf("\n Diameter of pipe = %d mm",d_p*1e3); flow_o=300e-6;//Flow rate through pipe printf("\n Flow rate through pipe = %d m^3/s",flow_o*1e6); Meu_...
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clc; clear; //Example 4.18 sigma=5.67*10^-8 ; //[W/(sq m.K^4)] T1=813; //[K] T2=473; //[K] e1=0.87; e2=0.26; D1=0.25 ;//[m] D2=0.3; //[m] Q_by_a1=sigma*(T1^4-T2^4)/(1/e1+(D1/D2)*(1/e2-1)) //[W/ sqm] printf("\n Heat transfer by radiaiton is %d W/sq m",Q_by_a1);
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//Chapter 2:Dynamics of Electric Drives //Example 2 clc; //Variable Initialization J=10 //moment of inertia of the drive in kg-m2 mprintf("Passive load torque during steady state is : Tl=0.05*N in N-m") mprintf("\nAnd load torque : T=100-0.1*N in N-m ") mprintf("\nLoad torque when the direction is reversed...
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errcatch(-1,"stop");mode(2);//Example 6_7_u1 ; ; //To calculate the no of photons emitted by the ruby laser p=1 //units in Watts lamda=694.3 //units in nm lamda=lamda*10^-9 //units in meters h=6.63*10^-34 //units in m^2 kg s^-1 c=3*10^8 //units in meter/se...
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@relation pima @attribute 'preg' real[0.0,17.0] @attribute 'plas' real[0.0,199.0] @attribute 'pres' real[0.0,122.0] @attribute 'skin' real[0.0,99.0] @attribute 'insu' real[0.0,846.0] @attribute 'mass' real[0.0,67.1] @attribute 'pedi' real[0.0,2.42] @attribute 'age' real[0.0,81.0] @attribute 'class' {tested_negative,tes...
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function ps(arr, fs) playsnd(arr, fs); endfunction
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clc //Initialization of variables GCO2=-394 //kJ/mol GCO=-137 //kJ/mol GO2=0 //calculations deltaG=2*GCO2-2*GCO+GO2 //results printf('Standard reaction gibbs energy = %d kJ/mol',deltaG)
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exec("alaqiltest.start", -1); if add(7, 9) <> 16 then alaqiltesterror(); end if do_op(7, 9, funcvar_get()) <> 16 then alaqiltesterror(); end exec("alaqiltest.quit", -1);
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20 1:0.06666666666666667 10:1.0 13:2.0 14:1.0 19:0.1111111111111111 28:0.25 41:1.0 52:0.09090909090909091 54:1.0 56:0.5 63:0.5 65:0.5 76:0.3333333333333333 83:0.03508771929824561 99:0.3333333333333333 155:2.0 187:0.3333333333333333 542:1.0 1045:1.0 1124:1.0 20 1:0.26666666666666666 13:1.0 19:0.1111111111111111 41:1.0 5...