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//Problem 13.19: Determine by successive conversions between Th´evenin and Norton equivalent networks a Th´evenin equivalent circuit for terminals AB of Figure 13.46(a). Hence determine the current flowing in the 200 ohm resistance. //initializing the variables: V1 = 10; // in volts V2 = 6; // in volts R1 = 2000;...
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//最適ロバストサーボ Ae=[0 1 0;0 -1 1;0 0 0]; be=[0;0;1]; ce=[1 0 0]; re=1; Qe=ce'*ce; Be= inv(re)*be*be'; Pe=ricc(Ae,Be,Qe,'cont'), spec(Pe) ke=-inv(re)*be'*Pe; Z=[0 1 0;0 -1 1;1 0 0]; k=ke*inv(Z); k1=[k(1) k(2)], k2=k(3)
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clear; clc; printf("\t Example 5.1\n"); //dry bulb temperature=50 and wet bulb temperature=35 Tg=50; //dry bulb temperature=50 To=0; //refrence temperature in degree celcius Mb=28.84; //average molecular weight of air Ma=18; ...
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clc,clear printf('Example 7.15\n\n') diameter_shaft = 14 length_shaft=30 Surface_area_shaft =%pi* length_shaft * diameter_shaft thickness_coating = 1.5/10 density_Ni= 8.9 Mass_Ni= Surface_area_shaft * thickness_coating*density_Ni ECE_Ni=0.000304 //gram/C electricity_required= Mass_Ni/ECE_Ni printf('Theo...
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syms K; s=%s; G=syslin('c',25(s+1)/(s+5)); p=K; q=s^2+s; J=p/q; F=G*J; T=F/(1+F); // Closed loop transfer function disp(T,"C(s)/R(s)") // sensitivity w.r.t K = dT/dK*K/T S=(diff(T,K))*(K/T) disp(S,"Sensitivity")
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//To calculate the ratio of the seperation between successive lattice planes h1 = 1; k1 = 0; l1 = 0; //for (100) plane x1 = sqrt(h1^2+k1^2+l1^2); h2 = 1; k2 = 1; l2 = 0; //for (110) plane x2 = sqrt(h2^2+k2^2+l2^2); h3 = 1; k3 = 1; l3 = 1; //for (111) plane x3 = sqrt(h3^2+k3^2+l3^2); //d = a/sqrt(...
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//determine the inductance of the coil R=6 V=250;//volts I=1.5;//amps Z=V/I;//impedance f=60;//hetrz X=sqrt(Z^2-R^2) L=X/(2*%pi*f) disp('inductance of coil='+string(L)+ 'henry')
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P=5000 Vt=215 n=1000 Ra=0.4 Ia=P/Vt Eag=Vt+Ra*Ia Eam=Vt-Ra*Ia newn=Eam/Eag*n/1.1 disp(newn)
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// chapter 10 // example 10.2 // Estimate peak and rms value of load voltage // page-699-700 clear; clc; // given E=600; // in V (line voltage) f=50; // in Hz (supply frequency) Ls=1.46; // in mH (inductance per phase) I_L=28; // in A (load current) p=6; // number of pulses alpha1=0,alpha2=30, alpha3=60; // in degrees ...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Pulse>CUSTOM WAVE</Pulse> <Title>Waveform 3</Title> <Organization>GM</Organization> <Standard>GMW3172 2010</Standard> <Item>9.2.17 Crank Pulse Capability and Durability</Item> <voltage>14</voltage> <count>49...
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// Grob's Basic Electronics 11e // Chapter No. 27 // Example No. 27_11 clc; clear; // If Vz=10 V, calculate Iz. // Given data Vin = 25; // Input voltage=25 Volts Vz = 10; // Zener voltage=10 Volts Rs = 1*10^3; // Source Resistance=1 kOhms Iz = (Vin-Vz)/Rs; disp (Iz,'The Zener Current in ...
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function [y]=ishigami(x,a,b,c) y = sin(a) + 7 * sin(b)^2 + 0.1 * c^4 * sin(a) endfunction
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clc // Given that lambda = 6.058e-7 // wavelength of light in meter L = 0.2 // coherence length in meter // Sample Problem 3 on page no. 1.40 printf("\n # PROBLEM 3 # \n") printf("\n Standard formula used \n f = c/lambda. \n") line_width = (lambda ^ 2) / L//calculation for line width f_spread = (3 * 10 ^ 8) / ...
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function [A] = cipherReplaceSpecial(A) // Replaces 'a' with 'b' in the cipher A [m,n] = size(A); if m < 1 disp('Cipher is empty') else for i = 1:m for j = 1:n A(i,j) = A(i,j) + 64; end end end endfunction
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// Exa 4.25 clc; clear; close; // Given data R_F = 5;// in k ohm R_G = 1;// in k ohm R1 = 10;// in k ohm R2 = 20;// in k ohm A = (1 + ((2*R_F)/R_G))*(R2/R1); disp(A,"The gain of instrumentaion amplifier is");
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clear; clc; //Example7.3[Cooling of Plastic Sheets by Forced Air] //Given:- T_p=95;//Temp of plastic Sheet[degree Celcius] T_air=25;//Temp of air[degree Celcius] v=3;//Velocity of flowing air[m/s] L=0.6;//Length of plastic sheet[m] w=1.2;//width[m] k=0.02808;//[W/m.degree Celcius] Pr=0.7202;//Prandtl Number...
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clc; p02=6; // Inlet pressure in bar T02=900; // Inlet temperature in kelvin p0fs=1; // Outlet pressure in bar eff_isenT=0.85; // insentropic efficiency of turbine alpha_2=75; // Nozzle outlet angle in degree u=250; // Mean blade velocity in m/s Cp=1.15*10^3; // Specific heat in J/ kg K r=1.333; // Specific hea...
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clc; clear; clf; function y = line(m,c,st,et,dt) t = st:dt:et; y = m*t + c; endfunction y = line(1,0,0,10,1); plot2d3(y); xgrid(2); xlabel("T", "fontsize", 5); ylabel("X", "fontsize", 5); title("Line Function", "fontsize", 4); //Following code is not important plot(y)
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//Example 4.1, Page number 4.32 clc;clear;close // variable declaration r1 = 2; // in radians r2 = 3; // in radians d1 = 4; // Converting from mm to radians d2 = 6; // Converting from mm to radians // calculations D = (r2-r1)/(d2*10**3-d1*10**3) // Diverg...
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clear; clc; close; Vi_rms = 12; Rl = 4; Vcc = 25; Vi_p = sqrt(2)*Vi_rms; Vl_p = Vi_p; Po_ac = (Vl_p^2)/(2*Rl); Il_p = Vl_p/Rl; Idc = (2/%pi)*(Il_p); Pi_dc = Vcc*Idc; Pq = (Pi_dc-Po_ac)/2; n = (Po_ac/Pi_dc)*100; disp(Po_ac,'Output power(Watts) = '); disp(Pi_dc,'Input power(Watts) = '); disp(Pq,...
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اِسْتَصْدَرَ تَسْتَصْدِرْنَ V;2;PL;FEM;IPFV;IND;ACT كِيلُومِتْرٌ كِيلُومِتْرٌ N;SG;NDEF;NOM الْعَمِيق عُمُقًا ADJ;PL;MASC;NDEF;ACC اِسْتِقَامَةٌ الِاسْتِقَامَةَ N;SG;DEF;ACC فِكْرَةٌ الْفِكْرَة N;SG;DEF;INFM مِعًى أَمْعَاءً N;PL;NDEF;ACC رَمَادٌ الْأَرْمِدَةِ N;PL;DEF;GEN ضَاعَ يَضِيعُونَ V;3;PL;MASC;IPFV;IND;ACT السُّ...
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//Variable Declaration i=98.6328 //Angle(degrees) e=0.0011501 //eccentricity n=14.23304826 //Mean Motion(1/day) a=7192.3 //Semimajor axis(km) K1=66063.1704 //Known constant(km^2) //Calculation n0=(2*180*n) //Mean Motion (deg/sec) K=(n0*K1)/((a**2)*((1-e**2)**2)) //Constant (deg/day) w=-K*cos(i*3.14...
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//Chapter 16,Example 10,page 564 //Determine the from and tail times clear clc n = 12 C1 = 0.125*10^-6/n // micro F C2 = 0.001*10^-6 // micro F R1 = 70*n // ohm R2 = 400*n // ohm // beased on figure 16.15 theta = sqrt(C1*C2*R1*R2) neta = 1/(1+R1/R2+C2/C1) a = R2*C1/(2*theta*neta) // alpha T2 = 7*theta*10^6 T1 = T2/25 p...
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function d=%r_diag(a,k) // %r_diag - implement diag function for rational matrix ,.. // Copyright INRIA [lhs,rhs]=argn(0) if rhs==1 then k=0,end [m,n]=size(a('num')) if m<>1&n<>1 then d=syslin(a('dt'),diag(a('num'),k),diag(a('den'),k)) else mn=max(m,n) den=ones(mn,mn) den=den-diag(diag(den,k))+diag(a('den'),k)...
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//[r]=%snr(l1,l2) //%snr(l1,l2) correspond a l'operation l1<>l2 ou l1 est une matrice de scalaire // et l2 une fraction rationnelle //! r=degree(l2(2))==0&degree(l2(3))==0 if r then r=coeff(l2(2))./coeff(l2(3))==l1,end r=~r //end
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// Exa 7.12 clc; clear; close; // Given data I_D = 500;// in mA V_GS = 3;// in V R_DS = 2;// in ohm V_DD = 20;// in V R1 = 1;// in kohm R1 = R1 * 10^3;// in ohm V_out = (R_DS/(R1+R_DS))*V_DD;// in V disp(V_out,"The output voltage in V is");
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//to calculate the a).diversity factor b).avg load and laod factor of each consumer c).avg load and load factor of combined load. //postfix 1,2...4 shows the consumers. clc; //for consumer1 avg_load1=1; //load in kwatt max_dem1=5; //demand in kwatt dem1_at8=5; ...
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//To Determine the distance at which the regulator must be located //Page 472 clc; clear; //Terms from previous example TVDpu=0.0776; //Total Voltage Drop VRRpu=1.035; //Setting Voltage of Regulator l=10;//Length of the Feeder //Primary voltages for various cases VPpua=1.01; VPpub=1.00; s1=poly(0,'s1')...
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// Exa 5.18 clc; clear; close; format('v',6) // Given data Vo = 36;// in V Vi = 0.028;// in V A = Vo/Vi; Vf = 1.2; Vo = 100; Beta = Vf/Vo; // Gain with feedback Af = A/(1+(A*Beta)); Vs = Vi;// in V // Output voltage Vo =Af*Vs;// in V disp(Vo,"The output voltage in V is"); //Df =D/(1+(A*Beta)); DbyDf ...
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clc clear //Input data m=0.04//Mass of stone in kg vi=25//Initial velocity in m/s vf=0//Final velocity in m/s yi=0//Initial height in m //Calculations Ui=(m*9.81*yi)//Initial potential energy in J Ki=(1/2)*m*vi^2//Initial kinetic energy in J Etotal=(Ui+Ki)//Total energy in J h=(Etotal/(m*9.8))//Maximum hei...
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# camera: eye, center, up, fovy, width, height camera 0 3 8 0 1 0 0 1 0 45 1024 1024 # recursion depth depth 5 # background color background 0 0 0 # global ambient light ambience 0.2 0.2 0.2 # light: position and color light 20 50 0 0.5 0.5 0.5 light 50 50 50 0.5 0.5 0.5 light -50 50 50 ...
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clc a=30 Ka1=(1-sind(a))/(1+sind(a)) a=35 Ka2=(1-sind(a))/(1+sind(a)) //at z=0 so T0=0 //atz=3 To=3*16 Ta1=Ka1*To Ta2=Ka2*To // At z=6 To=3*16+3*(18-9.81) Ta2=Ka2*To Pa =(1/2)*3*16+3*13.0+ (1/2)*3*36.1 z= (24 *(3+3/3)+39.0*(3/2)+54.15*(3/3))/Pa printf('The force per unit length of the wall = %f kN/m\...
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clc //initialization of new variables clear sigma=5 //m^2/s x0=1 y0=1 //(x0,y0) location of source x=0 y=-1 //calculations u=sigma/(2*%pi)*(x-x0)/((x-x0)^2+(y-y0)^2) w=sigma/(2*%pi)*(y-y0)/((x-x0)^2+(y-y0)^2) //results printf('u = %.3f m/s',u) printf('\n w = %.3f m/s',w)
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function [db,phi]=dbphi(repf) // Copyright INRIA phi=phasemag(repf); db=20*log(abs(repf))/log(10);
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//All the quantities are expressed in SI units b = 30*%pi/180; //oblique shock wave angle M1 = 2.4; //upstream mach number //from figure 9.9, for these value of M and beta, we have theta = 6.5*%pi/180; Mn_1 = M1*sin(b); //upstream mach ...
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//Finding magnetising current //Example 15.27(pg. 409) clc clear a=0.01//crosssectional area of ring in m^2 Uo=4*(%pi)*(10^-7)//absolute permeability lf=1.25//leakage factor Ur=400//permeability N=175//no of turns phig=0.8*(10^-3)//flux through air gap in Wb Bg=phig/a//Flux density in air gap in Wb/m^2 Hg=Bg...
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funcprot(0) clf() f0 = 30 function ret = x(t) ret = exp(-sigma)*cos(2*%pi*f0*t) endfunction function ret = tfx(f) ret = ((sigma*((sigma^2)+4*(%pi^2)*((f-f0).^2)).^(-1)) + (sigma*((sigma^2)+4*(%pi^2)*((f+f0).^2)).^(-1)))/2 endfunction t = -100:0.1:100 f = t // Ex 1. subplot(411); sigma = 5 plot(tfx(f), "r")...
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[0,600]x[0,400] S (20,40) (100,50) S (50,30) (100,200) S (10,100) (200,70) S (10,300) (300,370) S (50,5) (70,290) S (60,390) (80,100) S (10,390) (120,250) S (90,200) (200,220) S (150, 180) (300,60) S (100, 70) (290, 80) S (120,20) (170, 370) S (160,380) (220, 40) S (210, 50) (470,20) S (250,30) (330,330) S (200,300) (4...
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// Exa 5.12 clc; clear; close; // Given data gm=75;// in A/V Rs= 1;// in kohm Rs= Rs*10^3;// in ohm R_E= 1;// in kohm R_E= R_E*10^3;// in ohm rpi= 1;// in kohm rpi= rpi*10^3;// in ohm hie=rpi; Io= -gm; Vi= Rs+R_E+rpi; Gm= Io/Vi; disp(Gm,"Value of Gm is : ") Bita=-R_E; disp(Bita,"Value of Bita is : "...
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array <int> finalSeq[432] = {35,68,57,33,17,25,56,41,23,36,67,67,2,51,13,61,22,12,5,47,47,48,48,49,69,29,2,8,10,5,25,28,11,64,40,13,72,54,7,57,25,38,6,57,31,15,51,51,15,8,8,66,66,8,54,35,35,14,6,6,31,31,27,63,3,1,37,15,26,65,31,47,61,12,33,27,68,28,30,50,50,18,53,3,28,23,9,19,63,45,22,22,66,42,42,7,59,10,41,7,14,66,23,...
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mu_not=4D-7*%pi //calculating flux density at centre of coil B=mu_not*I/(2*R) I=50 R=4D-2 B=mu_not*I/(2*R) mprintf("Flux density at centre of coil=%f*10^-6 Wb/m^2(Tesla)\n", B*10^6) //calculating flux density perpendicular to plane of coil at a distance of 10 cm from it z=10D-2 B=mu_not*I*R^2/(2*(R^2+z^2)^1.5...
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//Example 4.16. clc format(6) I=5*10^-3 T=300 disp("Forward resistance of a PN junction diode, rf = (eta*VT)/I where VT = T/11600 and eta = 2 for silicon") disp("Therefore, rf = 2*(T/11600) / 5*10^-3") eta=2 //for silicon rf=600/(11600*5*10^-3) disp(rf," rf(ohm) = ")
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//Griewank function function z=f(x, y) z = (x^2)/50 + (y^2)/50 - (cos(x)+1)*(cos(y/sqrt(2))+1); endfunction //plotting x = linspace(-15,15,100); y = linspace(-15,15,100); z = feval(x,y,f); surf(x,y,z); //simulated annealing algo x = -1.2; y = 1; //initial solution T = 2.5; //initial temperature iter...
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// Exa 5.10 clc; clear; close; format('v',6) // Given data h_ie = 1.5;// in ohm h_fe = 100; h_re = 3 * 10^-4; h_oe = 25 * 10^-6;// in mho V_CC = 20;// in V R1 = 50 * 10^3;// in ohm R2 = 5 * 10^3;// in ohm R_C = 5 * 10^3;// in ohm R_L = 10 * 10^3;// in ohm R_S = 1;// in k ohm Ri= 1.4*10^3;// in ohm R_B...
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clear; clc; // Illustration 7.12 // Page: 252 printf('Illustration 7.12 - Page: 252\n\n') // solution //****Data****// Tempg1 = 32;// [OC] Tempw1 = 28;// [OC] //******// H1 = 90;// [kJ/kg] H1_prime = 72;// [kJ/kg dry air] H2_prime = 163.6;// [kJ/kg dry air] deff('y = f17(H2)','y = (H2-H1)-(H2_prime...
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clc clear //INPUT DATA Ef=2.1*1.6*10^-19//The fermi energy level in potassium at a particular temperature in J m=9.11*10^-31//mass of electon in Kg h=6.625*10^-34//plank's constant in m^2 Kg/sec //CALCULATION nc=(((8*m)/(h*h)*Ef)^(3/2)*(3.14/3))/10^28//ThE Number of free electrons per unit volume in potassium ...
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//Caption: Tests of Hypotheses Concerning variances //Two tailed Chi-square Tests Concerning Single Population Variance //Test 2: Ho: Var >= k and H1: Var <k //Example8.30 //Page284 clc; Var = 0.64; //popualtion variance of the weight of the cement bags in Kg n = 8;// sample size S2 = 0.36;//sample variance o...
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//Ex19_14 Pg-963 clc disp("Conversion of decimal number 0.85 base to its octal equivalent ") a=[0.85] //0.75 value in textbook is wrong z=modulo(a,1) d=0 for i=1:10//converting the values after the decimal point into octal z=z*8 q=floor(z) d=d+q/(10^i) if z>=1 then z=z-q end ...
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#************************************************************ # Scenario of garching # # date : 2012 #************************************************************ p3d_sel_desc_name P3D_ENV garching p3d_sel_desc_name P3D_ROBOT human1 p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.00...
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clc d=figure('position',[0,0,650,400]); d.figure_name='Лабораторная работа №23'; set(d,'BackgroundColor',[1,0.9,0.9]); str1=uicontrol(d,'style','text','position',[25,350,100,30],'string','Введите а:'); edit1=uicontrol(d,'style','edit','position',[25,300,100,30],'string','1'); str2=uicontrol(d,'style','text','positio...
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//Ex5.21,Pg5.23 clc; //Given x=1 and pf=1 we obtain the first equation //With x=0.5 and pf=1 we obtain the second equation A=[1 1;1 0.25] B=[52.2;26.1] W=A\B printf("\n Copper loss=%.1f kW \n",W(2)) printf("\n Iron loss=%.1f kW \n",W(1)) //Now if x=0.6 and pf=1 n= (0.6*600*1/((0.6*600*1)+W(1)+((0.6^2)*W(2))))...
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// Scilab code Ex5.9: Pg:218 (2008) clc;clear; Lambda = 5000; // Wavelength of spectral line, Angstorm theta = 30; // Direction of principal maxima, degree d_theta = 0.01; // Angular separation between two wavelengths, radians d_Lambda = Lambda*cotd(theta)*d_theta; // Difference in two wavelengths, ang...
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//refer Fig.1.11 in the textbook //applying KVL over loops ABEFA and BCDEB, I2=3.5*I1; -2*I1+7*I2=10 a=[3.5 -1;-2 7] b=[0;10] i=inv(a)*b I1=i(1,1) I2=i(2,1) I=I2-I1 mprintf("Current through 8 ohm resistance=%f A from E to B", I)
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// Questo modello si riferisce ad un asse vincolato // con fulcro al centro. // L'ingresso è l'angolo Teta desiderato // Lo stato è dato da Angolo, Velocità angolare e Accelerazione angolare A=[ -1,0,0; -1,-1,0; -1,-1,-1 ]; B=[1;1;1]; n=100; T=[0:n-1]; IN=T./n; Teta(1:n)=20; //Teta=10*sin(T*(2*%pi/250)); X0...
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//Chapter-1, Example 1.2, Page 18 //============================================================================= clc; clear; //INPUT DATA l1=20;//length in cm for first case l2=0.4;//length in cm for second case w=0.1;//width in cm t=0.4;//thickness in cm p=1.7*10^-6//resistivity of copper in ohm cm a1=0.1*0...
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//Chapter-5, Example 5.15, Page 192 //============================================================================= clc clear //INPUT DATA Ti=250;//Temperature of aluminium slab in degree C Tc=50;//Convective environment temperature in degree C h=500;//Heat transfer coefficient in W/m^2.K x=0.05;//Depth of ...
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// Given :- // Part (a) etat = 0.85 // given efficiency // From the solution to Example 8.3, the following specific enthalpy values are known, in kJ/kg h1 = 3348.4 h2s = 2741.8 h3 = 3353.3 h4s = 2428.5 h5 = 173.88 h6 = 181.94 // Calculations h2 = h1...
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//Exa 6.5 clc; clear; close; //Given Data: f=10;//in GHz f=f*10^9;//in Hz BWFN=10;//in degree c=3*10^8;//Speed of light in m/s lambda=c/f;//in meter //Part (a): d=140*lambda/BWFN;//in meter disp(d,"Diameter of a parabolic Antenna in meter : "); //Part (b): HPBW=58*lambda/d;//in degree disp(HPBW,"3-dB Bea...
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2011-2011 - DIGITEO - Bruno JOFRET // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The ter...
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// Three-Phase Circuits :example 6.10 :(pg 6.16) P=1500*10^3; pf=0.85; VL=2.2*10^3; phi=acosd(pf); IL=P/(sqrt(3)*VL*pf); Iph=IL/sqrt(3); AC=Iph*pf; RC=Iph*sind(phi); IAC=IL*pf; IRC=IL*sind(phi); printf("\nP=1500kW \npf=0.85 (lagging) \nVL=2.2kV"); //For Delta-connected load printf("\nP=sqrt(3)*VL*IL*cos(ph...
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//Example 28.1 delta_t_0=1.52*10^-6;//Proper time for life of the muon (s) c=3*10^8;//Speed of light (m/s) v=0.950*c;//Velocity of muon (m/s) Gamma=1/sqrt(1-v^2/c^2); delta_t=Gamma*delta_t_0;//Elasped time as measured by Earth-bound observer (t) printf('Life of the muon as measured by Earth-bound observer = %0.2e...
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clc kBT=0.026 disp("kBT = "+string(kBT)+"eV") //initializing value of multiplication of boltzmann constant and 300K temperature mo = 9.1*10^-31 disp("mo = "+string(mo)+"kg") //initializing value of mass of electron m=0.08*mo disp("m = "+string(m)+"kg") //initializing value of mass of electron in InAlAs T = 300 ...
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//example 5.6 clc; funcprot(0); // Initialization of Variable R1=22;//resistance V1=56;//voltage V2=2;//voltage //calculation I=(V1-V2)/R1; disp(I,"current in mA") R2=V2/I; disp(R2*1000,"resistance2 in ohm:") printf('pick R2=R3=820ohm R1=R4=22 kohm') clear()
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PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_ciudad(pciudad => :pciudad, p_recordset => :p_recordset); end; 2 pciudad 1 Heredia 5 p_recordset 1 <Cursor> 116 0
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1032 cd .. 1033 ls 1034 ls -a 1035 cd .git/ 1036 ls 1037 cd .. 1038 ls 1039 cat HW7.iml 1040 ls 1041 rm HW7.iml 1042 ls 1043 ls -a 1044 cd .idea/ 1045 ls 1046 cd .. 1047 ls 1048 ls -a 1049 rm HW7.iml 1050 ls 1051 rm -rf .idea 1052 ls 1053 ls -a 1054 ls 1055 git add --a...
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/* Code à vérifier le résultat dans un fichier .sce */ funcprot(0); exec(fullpath(pwd() + '\Exo_pre.sci'),-1); T = [0,1,3,4]; cc = [1 2 1;4 1 -1;1 -4 1]; clf(); [t1,z1] = trace(10,T,cc); subplot(2,2,1); plot(t1,z1); xtitle("Figure1 N=10"); [t2,z2] = trace(100,T,cc); subplot(2,2,2); plot(t2,z2); xt...
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//Exa 2.38 clc; clear; close; format('v',7); //Given Data : mdot=0.5;//kg/s p1=1.4;//bar rho1=2.5;//kg/m^3 u1=920;//kJ/kg C1=200;//m/s p2=5.6;//bar rho2=5;//kg/m^3 u2=720;//kJ/kg C2=180;//m/s Qdot=-60;//kW Z21=60;//m g=9.81;//gravity constant h21=u2-u1+(p2*10^5/(rho2*1000)-p1*10^5/(rho1*1000));//kJ...
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function [x,y]=standard_origin(o) graphics=arg1(2); orig=graphics(1) x=orig(1);y=orig(2);
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//Example 1.2 //Program to find Range of a Resistor so as to satisfy manufacturer's Tolerances //Colour Band Sequence: GRAY, BLUE, GOLD, GOLD clear; clc ; close ; A=8;//NUMERICAL CODE FOR BAND GRAY B=6;//NUMERICAL CODE FOR BAND BLUE C=-1;//NUMERICAL CODE FOR BAND GOLD D=5;//TOLERANCE VALUE FOR BAND GOLD i.e. 5...
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.7 // Page 123 printf("Example 4.7, Page 123 \n \n"); // solution m = 100//[kg] Tallow m1 = 3*403*m/890 // [kg] m2 = 92*m/890 printf("(a) \n \n NaOH required = "+string(m1)+" kg \n \n \n(b) \n \n...
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//Exa 1.18 clc; clear; close; //given data : f=20;//in MHz f=f*10^6;//in Hz le=100;//in m c=3*10^8;//speed of light in m/s lambda=c/f;//in m Rr=160*(%pi*le/lambda)^2;//in ohm disp(Rr/1000,"Radiation Resistance in KOhm : ");
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errcatch(-1,"stop");mode(2);//Example 2.5(c) ; ; R1=15*10^3;//From the result of Example 2.4 Romin=50*10^6; emax=R1/Romin; p=emax/4; pper=p*100; printf("Resistance tolerance Required=%.5f percent",pper); exit();
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function s1=%r_i_r(i,j,s1,s2) // %r_i_r(i,j,s1,s2) insertion s2(i,j)=s1 //! // Copyright INRIA [lhs,rhs]=argn(0) if rhs==3 then [s1,s2]=sysconv(j,s1) [n1,n2]=size(s2('den')) n=s2('num');n(i)=s1('num'), d=ones(n);d(1:n1,1:n2)=s2('den');d(i)=s1('den') else [s1,s2]=sysconv(s1,s2) [n1,n2]=size(s2('den')) n=s...
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clc clf // --------- PLOT SIGNAL -------- function plot_signal(x, n, pos, name, dotColor) subplot(3,2, pos) indice = linspace(0, length(x) - 1, length(x)) indice = indice - n + 1; plot2d3(indice, x) config = gca() config.x_location = "origin"; config.data_bounds = [ -5 -5; 5 10]; ...
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//chapter13 //example13.15 //page289 printf("i) Class A amplifier means that it raises voltage level of signal and its \nmode of operation is such that collector current flows for whole input signal. \n \n") printf("ii) Audio voltage amplifier means it raises voltage level of audio signal \nand its mode of operat...
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clc; clear all; Eg = 1.8*1.609e-19; // Bandwidth of given LED h = 6.626e-34; // Planck's Constant c = 3e8; lambda = ((h*c)/Eg)*1e6; disp('um',lambda,'The wavelength of light emitted from LED is')
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s=0 C = 0 M = eye(295,295) for k=1:295; s=s+M(k,1:k)*M(1:k,k); C = C + (k - 1) end
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//EXAMPLE 1-2 PG NO 18 R=0.69; //RESISTANCE P=2.83*10^-8; //PRO L=60; //LENGTH OF CABLE a=(P*L)/R; disp('i) a = '+string (a)+' m^2'); D=[(4*a)/%pi]^0.5; //DIAMETER disp('i) DIAMETER = '+string (D)+' mm');
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clc //Initialization of variables h1 = 36/12 //ft h2 = 6/12 //ft h3 = 9/12 //ft SgOIL = 0.9 SgHg = 13.6 yH2O = 62.4 // lb/ft^3 // Calculations Dair = -(SgOIL)*(yH2O)*(h1+h2) + (SgHg)*(yH2O)*(h3) Pgage = Dair/144 // psi //results printf("the pressure reading in the gauge is %.2f psi",Pgage)
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<?xml version="1.0" ?> <TestCase name="rrp1" version="5"> <meta> <create version="10.0.0" buildNumber="10.0.0.431" author="admin" date="11/09/2017" host="inbasdpc10722" /> <lastEdited version="10.0.0" buildNumber="10.0.0.431" author="admin" date="11/09/2017" host="inbasdpc10722" /> </meta> <id>1CCCE6DFC52D11E7...
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clc // Given that lambda = 5450 // Wavelength in angstrom mu = 1.5 // Refractive index of material n = 3 // order of fringe // Sample Problem 16 on page no. 100 printf("\n # PROBLEM 16 # \n") printf("\n Standard formula used \n (mu - 1)*t = n*lambda\n") t = n*lambda*1e-10/(mu-1) // Calculation of thickness o...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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k=input("Enter the number of cases:") function y=f(x) y=((gamma(n/2+d/2)*n)*((n/d)*x)^((n/2-1))/((gamma(n/2)*gamma(d/2)*d)*(1+(n/d)*x)^(n/2)+d/2)) endfunction for i=1:k d=input('Enter the d value:') n=input('Enter the n value:') x=1:2:100; y=feval(x,f) xlabel('N') ylabel('D') title("GRAPH OF F-DISTRIBUTION")...
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// Test # 4 : Input Argument #2 is of complex type exec('./allpasslp2mb.sci',-1); [n,d]=allpasslp2lp(0.3,%i); //!--error 10000 //Wo must be real ,numeric and scalar //at line 37 of function allpasslp2lp called by : //[n,d]=allpasslp2lp(0.3,%i)
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S=[1,2,3,4,5,6]; //sample space for the rolling of a die A=[2,4,6]; //event that an even number occurs B=[1,3,5]; //event that an odd number occurs C=[2,3,5]; //event that a prime number occurs disp(union(A,C),'sample space for the event that an even or a prime number occurs')...
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//Example 5.13 clc;clear;close; format('v',5); G=4000;//MW R=2;//Hz/p.u.MW////Speed regulation constant H=5;//sec C=600;//MW//Capacity theta=40;//degree///Power angle f=50;//Hz disp("Part(a)"); T=C/G*cosd(theta);//sec omega0=sqrt([2*%pi*f*T/H-(f/4/R/H)^2]);//radian/sec disp(omega0,"Frequency of oscillation(...
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clc //initialization of variables clear w=64 //kg H=60 //cm b=40 //cm h=5 //cm E=0.12*10^6 //kg/cm^2 Es=2*10^6 //kg/cm^2 // for part (a) and (b) I=b*h^3/12 del=4*w*120^3/(E*I) P=w*(1+sqrt(1+(2*H/del))) str=P*240*6/(b*h^2) printf('part (a) and (b)') printf('\n Maximum stress in wood = %d kg/cm^2',str) pr...
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clc clear //Initialization of variables kp=1.09 kp2=0.154 feed=[ 1 5 0 0 0 ] //calculations x=poly(0,"x") vec=roots(kp/4^4 /4 *(1-x)*(5-2*x)^2 *(6+2*x)^2 -x^5) x=vec(5) pro=feed- [x 2*x -x -4*x 0] y=poly(0,"y") vec2=roots(kp2*(0.273-y)*(0.727-y)*(7.454+2*y)^2 - 4*y^2 *(2.908+2*y)^2 *4) y=vec2(4) pro2=pro-...
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clc //code uses userdefined function complexstring function s=complexstring(a) if imag(a)>=0 then s=sprintf('%g+%gi',real(a),imag(a)) else s=sprintf('%g%gi',real(a),imag(a)) end funcprot(0) endfunction //dc test Vdc=13.8 //dc voltage in volts Idc=13 //di...
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clc clear //INPUT DATA l=20;//Stroke in cm d=15;//Bore in cm N=400;//speed in rpm Rc=22;//compression ratio p1=101.325;//Pressure in kN/m^2 t1=303;//temperature in K n1=1.3;//no of cycles n2=1.35;//no of cycles g=1.4;//constant cp=1.005;//specific pressure cv=0.718;//specific volume R=0.287;//gas constnat...
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// perceptron: function description function y = perceptron(W, b, X) u = W * X + b; u(u >= 0) = 1; u(u < 0) = 0; y = u; endfunction
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pathname=get_absolute_file_path('17_7.sce') filename=pathname+filesep()+'17_7_data.sci' exec(filename) //Brake mean effecive pressure(D and L remain same as previous problem) pbm=(P*60000)/(0.25*%pi*D^2*L*N*0.5)*10^-5 //Torque developed by the engine T=(P*60000)/(2*%pi*N) printf("\n\nRESULTS\n\n") printf("\nBra...
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clc //to calculate skin depth f=10^8 //frequency sigma=3*10^7 //conductivity of the medium muo=4*%pi*10^-7 //permeability of free space del=sqrt(2/(2*%pi*f*sigma*muo)) disp("skin depth is del="+string(del)+"m")
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clc //Initialization of variables x=poly(0,"x") //calculations y=6*x^2 -6*x+1 z=roots(y) //results printf("For stability, s must be greater than %.2f and less than %.2f and must be less than 1",z(1),z(2))
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function f=%rxr(s1,s2) // %rxr(r1,r2)=r1.*r2 r1,r2 rationals //! [s1,s2]=sysconv(s1,s2) [num,den]=simp(s1(2).*s2(2),s1(3).*s2(3)) f=tlist(['r','num','den','dt'],num,den,s1(4))
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clear; clc(); xdel(winsid()); function [tm, tmBis, tr5, depassement] = cara(y, t, K) tr5 = max([t(max(find(y>=(1.05*K)))), t(max(find(y<=(0.95*K))))]); tm = t(min(find(y>=0.9*max(y))))- t(max(find(y<=0.1*max(y)))); tmBis = t(min(find(y>=K))); depassement = ((max(y)-K)/K)*100; endfunction function [wc0...
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// //given BB_AB=248+(15/60) BB_BC=326+(15/60) BB_CD=46+(0/60) BB_DE=38+(15/60) BB_EA=147+(45/60) FB_AB=68+(15/60) FB_BC=148+(45/60) FB_CD=224+(30/60) FB_DE=217+(15/60) FB_EA=327+(45/60) //(a) includedA=-FB_AB+BB_EA includedB=-FB_BC+BB_AB includedC=BB_BC-FB_CD includedD=360-(171+(15/60)) exteriorD=FB_DE-BB_CD exte...
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//Ex19_6 Pg-959 clc dec=9 //decimal input bin=dec2bin(dec) //binary output disp("The binary equivalent of 9 is") disp(bin)
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clc xold=zeros(4,1); xnew=zeros(4,1); p=5 i=0 while(1) xnew(1)=((0.3*xold(2)+0.6*xold(3)+1.8)/3) xnew(2)=((0.6*xold(1)+0.6*xold(3)+10.8)/6) xnew(3)=((1.6*xold(2)+6.4*xold(4)-8)/8) xnew(4)=((0.2*xold(1)+0.6*xold(2)-0.4*xold(3)+3)/2) erro_rel=(max(abs(xnew-xold)))/(max(abs(xnew))); xold=xnew i=i+1 if(erro...