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//Chapter-3,Example3_2,pg 3_6 Vifs=4.095 n=12 Qe=Vifs/(((2^n)-1)*2) printf("quantisation error\n") printf("Qe=%.5f V",Qe)
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7_9.sce
clear; clc; printf("\t\t\tExample Number 7.9\n\n\n"); // heat transfer across horizontal air gap // Example 7.9 (page no.-346) // solution a = 0.2;// [m] side length of plate d = 0.01;// [m] seperation between two plates p = 101325;// [Pa] pressure of air R = 287;// [] universal gas constant T1 = 100;// [...
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exp_6.sce
Xn = input("Enter the value of Xn "); i_x= input("Enter the range of Xn "); Hn = input("Enter the value of Hn "); i_h= input("Enter the range of Hn "); exec("E:\scilab\work_17BIT009\exp_6_fun.sce"); [Yn,In] = exp_6_fun(Xn,i_x,Hn,i_h); figure(1); subplot(3,1,1); plot2d3(i_x,Xn); xlabel('n'); ylabel('Xn')...
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ex1_12.sce
// Exa 1.12 clc; clear; close; // Given data E = 20;// in V V_D1 = 0.7;// in V V_D2 = 0.7;// in V V2 = E - V_D1 - V_D2;// in V R1 = 3.3*10^3;// in ohm R2 = 5.6*10^3;// in ohm I2 = V2/R2;// in A I2 = I2*10^3;// in mA disp(I2,"The current through resistor R2 in mA is "); I1 = V_D2/R1; I1 = I1 * 10^3;// in...
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gridgain.log.tst
[14:14:22,515][INFO ][main][GridListenActorSelfTest] >>> _____ _ _______ _ >>> / ___/____(_)___/ / ___/___ _(_)___ >>> / (_ // __/ // _ / (_ // _ `/ // _ \ >>> \___//_/ /_/ \_,_/\___/ \_,_/_//_//_/ >>> >>> ---==++ IN-MEMORY BIG DATA ++==--- >>> ver. x.x.x-DDMMYYYY >>> Copyri...
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clc; //Example 20.7 //page no 276 printf("\n Example 20.7 page no 276\n\n"); //refer to illustrative Example 20.5 //(1) //we have to calculate minimum air ventilation flow rate into the room containing 10 ng/m^3 of a toxic chemical //ng means nanograms rV=250//chemical generated in the laboratory,ng/min c_o=10...
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2020-04-09T02:43:26.499817
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exp10_14pp.sce
clear clc disp("example10.14") a1=5000;b1=450;c1=0.5;//for system 1 e1=0.02;e2=-0.02//error a1c=a1*(1-e1);b1c=b1*(1-e1);c1c=c1*(1-e1) a2c=a1*(1-e2);b2c=b1*(1-e2);c2c=c1*(1-e2) tl=200 function [co]=cost(a,b,c,p) co=a+b*p+c*p^2 endfunction p11=(b2c-b1c+2*c2c*tl)/(2*(c1c+c2c)) p22=tl-p11 totco=cost(a1c,b...
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2020-04-09T02:43:26.499817
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ex3_11.sce
// Example 3.11, page no-99 clear clc theta_l=30 //earth station's location 30°W longitude theta_s=50 //satellite's location 50°W longitude theta_L=60 //earth station's location 60°N latitude r=42164 // orbital radius of the satellite in km R=6378 //Earth's r...
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sci
OraclePG.sci
function[F, G, ind] = OraclePG(qc, ind) // Si ind = 2, on calcule seulement F if ind == 2 then F = 1/3*(q0+B*qc)'*(r .* (q0+B*qc) .* abs(q0+B*qc)) + pr'*Ar*(q0+B*qc) ; // Si ind = 3, on calcule seulement G elseif ind == 3 then G = B'*Ar'*pr + B'*(r.*(q0+B*qc).*abs(q0+B*qc)); ...
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macrocab_pfet1.sce
style.fontSize=12; style.displayedLabel="<table> <tr> <td><b>G<br>S</b></td> <td align=center>pFET1</td> <td align=left><b>D</b></td> </tr> </table>"; pal11 = xcosPalAddBlock(pal11,"macrocab_pfet1",[],style);
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sce
22.sce
clc clear //Input data T=300+273 //Static Temperature in K C=200 //Velocity in m/s Cp=1005 //Specific heat capacity at constant pressure in J/kg-K //Calculation To=T+(C^2/(2*Cp)) //Stagnation Temperature in K C_max=sqrt(2*Cp*To) //Maximum possible velocity obtained by air in m/s //Output printf('Maximum...
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solution4_19.sce
//Obtain path of solution file path = get_absolute_file_path('solution4_19.sce') //Obtain path of data file datapath = path + filesep() + 'data4_19.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the permissible stresses for steel parts sigmat (N/mm2) sigmat = Syt/fs //Calculate the ...
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ex8_20.sce
// Exa 8.20 clc; clear; close; // Given data R_f = 200;// in kΩ R_i = 30;// in kΩ V_i = 0.1;// in V V_im = 0.5;// in V Vo_min = -((R_f/R_i)*V_i);// in V disp(Vo_min,"The minimum output voltage in V is"); Vo_max = -((R_f/R_i)*V_im);// in V disp(Vo_max,"The minimum output voltage in V is"); disp("The output ...
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/2825/CH2/EX2.7/Ex2_7.sce
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sce
Ex2_7.sce
//Ex2_7 Pg-88 clc disp("Relaxation time in terms of mobility is given by") disp(" t=m*u/e") printf("\n\n Taking effective mass of electron an holes in consideration,\n relaxation time is given by \n") disp(" t=m_star*u/e") disp("(a) foe electrons,m_star = 0.259*m_0") m0=9.1*10^(-31) ue=0.135 //mo...
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2020-04-09T02:43:26.499817
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37,975,407
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sce
E18_2.sce
clc //Initialization of variables function [coefs]=regress(x,y) coefs=[] if (type(x) <> 1)|(type(y)<>1) then error(msprintf(gettext("%s: Wrong type for input arguments: Numerical expected.\n"),"regress")), end lx=length(x) if lx<>length(y) then error(msprintf(gettext("%s: Wrong size for both input arguments: sa...
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/td.sce
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Neucrede/Dummy
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refs/heads/master
2021-06-18T00:47:59.632096
2021-03-31T09:19:08
2021-03-31T09:19:08
179,017,060
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sce
td.sce
td = [1.1786885 1.2666667 3.952459 2.3217391 4.1098361 -0.3565217 6.3918033 5.2434783 5.0934426 2.4028986 2.3786885 2.3623188 1.847541 2.6463768 0.942623 6.9884058 0.9819672 4.3913043 1.847541 8.0028986 3.6180328 7.3942029 1.2770492 6.2173913 4....
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eti-walis/Travel-Agencies-Database
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2023-08-19T04:17:54.751162
2021-09-30T16:28:16
2021-09-30T16:28:16
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tst
test_delete_station_procedure.tst
PL/SQL Developer Test script 3.0 4 begin -- Call the procedure delete_stop_procedure(delAddress => :delAddress); end; 1 delAddress 1 JerusalemBenGurion15 5 0
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hnizdil/it3105-image-processing
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2009-10-26T10:51:57
2009-10-26T10:51:57
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sce
recog_momcom.sce
getf('functions.sci'); // // get reference images and do the threshold // // function for converting ascii to pgm function fnames = patt_ascii_to_pgm(patt) clr = 'red'; path = 'recog/'; fnames = list(); for i = 1 : 3 fname = path + patt + string(i) + '.' + clr; pgm_from_ascii(fname, [128 128]); fnames($+1) ...
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sce
5_4.sce
clc //initialisation of variables L= 200 //m D= 18 //m h= 6 //m w= 10 //KN/m //CALCULATIONS L2= L/(sqrt((D-h)/D)+1) H= w*L2^2/(2*D) Tmax= sqrt((w*L2)^2+H^2) alphamax= atand(w*L2/H) printf ('L2= %.1f m',L2) printf (' \n H=%.1f KN',H) printf (' \n Tmax=%.1f KN',Tmax) printf (' \n alphamax=%.1f degrees',alph...
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FOSSEE/Scilab-TBC-Uploads
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//Page Number: 8.12 //Example 8.10 clc; //Given K=1.38D-23; B=40D+6; Tant=600; //Kelvin Trec=3000; //Kelvin G=80; //dB GG=(10^(G/10)); //Input noise power from antenna Nant=K*Tant*B; //W disp('W',Nant,'Nant='); Nrec=K*Trec*B; //W disp('W',Nrec,'Nant='); Nout=(Nant+Nrec)*GG; disp('W',Nout,'...
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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2013 - Scilab Enterprises - Antoine ELIAS // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The...
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//Example 23.5 Np=50;//Number of loops in the primary Vp=120;//Primary voltage (V) Vs=100*10^3;//Secondary voltage (V) Ns=Np*Vs/Vp;//Number of loops in the secondary printf('a.Number of loops in the secondary coil = %0.2e',Ns) Ip=10;//Current in the primary coil (A) Is=Ip*Np/Ns;//Current in the secondary coil (A...
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clc; clear all; disp("heat transfer coefficient") s=20/1000;//m side of channel L=2.5;//m length of channel U=4.5;//m/s tb=30;// degree C ts=70;// degree C rho=995.7;// kg/m^3 k=0.6175;// W/m.C v=0.805*10^(-6);// m^2/s Pr=5.42; Prs=2.55;// Pr at 70 degree C Deq=4*s*s/(4*s)//m Re=U*Deq/v Nu=0.021*Re^0.8*P...
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clc(); clear; // To calculate the lowest energy of electron n1=1; n2=1; n3=1; //values in lowest energy h=6.62*10^(-34); M=9.1*10^-31; //mass in kg L=0.1; //side in nm L=L*10^-9; //side in m n=(n1^2)+(n2^2)+(n3^2); E1=(n*h^2)/(8*M*L^2); //energy in j E1eV=E1/(1.6*10^-19); //energy in eV pri...
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//Example number 3.3, Page number 3.33 clc;clear;close // Variable declaration T=1.2 // in s V=7500 // in m^3 // Calculation A=(0.16*V)/T // in m^2 // Result printf("Total absorpttion = %.f m**2 of O.W.U.",A)
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// Pulse Response to impulse response (Freq Domain) converter. // Imports pulse response from HSpice *.tr files and // computes impulse response in frequency domain file // // // Use for bus simulations from Intel // // // (c)2009 L. Rayzman // Created : 04/03/2009 // Last Modified: 04/03/2009 - Initi...
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// Grob's Basic Electronics 11e // Chapter No. 27 // Example No. 27_12 clc; clear; // If R L increases to 250 Ohms, calculate the following: Is, Il, Iz, and Pz. // Given data Vin = 25; // Input voltage=25 Volts Vz = 7.5; // Zener voltage=7.5 Volts Rl = 250; // Load Resistance=250 Ohms Is = ...
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//Find the capacitance of a varactor diode clear; clc; //soltion //given C=5;//pf//capcitance of varactor diode at V=4V V=4;//V K=C*sqrt(4); //When bias voltage is increased upto 6 V Vn=6;//V//new bias voltage Cn=K/(sqrt(Vn)); printf("Capacitance (At 6 V ) = %.3f pf",Cn);
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//Section-9,Example-4,Page no.-E.6 //To calcuate the pH of unknown solution. clc; R=8.314 T=298 F=96500 E=0.4188 E_ref=0.2415 pH=(E-E_ref)/((2.303*R*T)/F) disp(pH,'pH of the unknown solution')
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//example 3.7(a)// clc //clears the screen// clear //clears existing variables// disp('when V(i)=0, the transistor T(1) is operating at point B') t=5; //input voltage as given in question// x=0; V=t-x; //output voltage in volts// disp('here V(o)(in volts)=') disp(V)
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//xor_clk_sr = [0 1 0 0 0 0 linspace(0,0,32)]; // 1st //xor_clk_sr = [0 1 0 1 0 0 linspace(0,0,32)]; // 2nd xor_clk_sr = [0 1 0 1 0 1 linspace(0,0,32)]; // 3rd XOR output xor_data_sr = [1 1 linspace(0,0,36)]; xor_in=[ linspace(1.9,1.9,6) linspace(2.1,2.1,8) linspace(2.1,2.1,8) linspace(2.1,2.1,8) linspace(2.1,2.1,8)...
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//Example 11-3 Flow of Hot Oil over a Flat Plate T = 40 //temperature of hot oil [C] L = 5 //length of flat plate [m] V = 2 //free stream velocity of oil [m/s] rho = 876 //density of oil at 40 C [kg/m^3] nu = 2.485 * 10**-4 //kinematic viscosity of oil at 40 C [m^2/s] Re_cr = 5 * 10**5 //critical Reynold's number
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//Chapter 3, Example 3.4 clc R1=25 //resistance in ohm R2=400 //resistance in ohm //To solve simultaneous equation by converting them into matrices form a=[R1 -2;R2 -8] b=[50;3200] x=a\b //Results printf("Voc = %d V\n",x(1)) //display voltage Voc printf("R = %d Oh...
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//Example 7.12 //Transformation of Thermal System from state description xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ // State space model of Thermal System s=%s; F=[-7 -12; 1 0]; G=[1;0]; H=[1 2]; J=0; sys=syslin('c',F,G,H,J) ...
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clear x=[0 1 2 3 4 7]'; y=[1 3 4 6 5 7]'; n=size(x,1); M=[n sum(x) sum(x) sum(x.^2)] b=[sum(y) sum(x.*y)] a=inv(M)*b; XX = 0:0.1:10; YY = a(1)+a(2)*XX; plot(XX, YY, 'b') plot(x,y,'r*');xgrid
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clc // Given that lambda = 5890 // wavelength of light in angstrom a = 1 // Diameter of aperture in cm // Sample Problem 36 on page no. 176 printf("\n # PROBLEM 36 # \n") printf(" Standard formula used \n") printf(" theta = 1.22*lambda/a \n") theta = 1.22*lambda*1e-10/(a*1e-2) // Calculation of resolving limi...
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function [Q,M,rk]=fullrf(A,tol) //[Q,M,rk]=fullrf(A) //Full rank factorization : A=Q.M //with range(Q)=range(A) and ker(M)=ker(A), //Q full column rank , M full row rank // rk = rank(A) = #columns(Q) = #rows(M) //F.D. //! [lhs,rhs]=argn(0) na1=norm(A,1); if rhs==1 then tol=sqrt(%eps);end if na1 < 1.d-10 then Q=[];M=[];...
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clear; clc; printf("\t Example 7.8\n"); s1=20.51; //solubility at 10 degree per 100 gm of water w2=277.85; //molecular weight of FeSO4.7H2O //let x be the quantity of Na2CO3.10H2O x=poly([0],'x'); //calc. x the weight of crystal t=roots(900*.4-.5465*x-(900-x)*20.5/120.5...
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@relation yeast-1 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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N=1500//speed in rpm E1=300//hysteresis losses //E1=k1*N k1=E1/N E2=150//eddy current losses //E2=k2*N^2 k2=E2/N^2 E=E1+E2//total iron losses //when iron losses are reduced to half //k1*N1+k2*N1^2=.5*E //solving for N1 N1=(-k1+sqrt(k1^2-4*k2*(-.5*E)))/(2*k2) mprintf("Total iron losses will be halved if sp...
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host("make"); link('libtdll.dll",'doit','c'); [a,b]=fort('doit',1,1,'d',2,2,'d','sort',1,2);
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clear; clc; //page no. 17 r1 = 0.25;// radius of cylinder in feet l = 2;//length of cylnider in feet r2 = 0.30;// radius of co-axial cylinder in feet mu = 0.018;//lb-sec/ft^2 torque = 0.25;// in ft-lb dv_dy1 = torque/(4*%pi*mu*r1^2);//velocity gradient at radius = 0.25 in fps/ft dv_dy2 = torque/(4*%pi*mu*r2^...
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A = [ 5 -3 0 ; 3 -9 1 ; 0 1 -7 ]; B = [ 5 ; 2 ; 4 ]; X = A\B; disp("Currents = "); disp(X); P = [31 -6 ; -6 41]; Q = [75 ; 90]; R = P\Q; disp("Voltages VA and VB = "); disp(R);
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//Exam:14.3 clc; clear; close; R_Cu=1.8*10^(-8);//resistivity of pure copper at room temperature R_CuNi=7*10^(-8);//resistivity of Cu 4% Ni alloy at room temperature R_Ni=(R_CuNi-R_Cu)/4;//resistivity due to Impurity scattering per % of Ni disp(R_Ni,'resistivity due to impurity scattering per percent of Ni in ...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 12.5 //Caption : Program to Calculate the Heat transfer rate in th evaporator M_LiCl=42.39; M_H2O=18.015; T1=298.15;//[K] T2=405.15;//[K] //Step a m_LiCl...
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//Example 8.5.2 //Calculate the rain attenuation clc clear Upfreq=17.80 //17.80Ghz //Polarization=vertical kv=0.0510 av=1.0927 elevationangle=45 hs=0.05 hr=4.00 R=63 latitude=25 Ls=((hr - hs)/(sind(elevationangle))) printf("The slant path length is %f km",Ls) Lg=Ls*c...
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scenario = "1 back Visual - non-verbal"; no_logfile = false; scenario_type = trials; response_matching = simple_matching; default_background_color = 128, 128, 128; default_text_color = 200,200,200; default_font_size = 40; active_buttons = 2; button_codes = 1,2; write_codes = true; pulse_width = 10; pcl_file = "1 ba...
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clear all; clc; d = 7/8;//diameter of the bar in inches l = 10;//length in feets P = 6;;//axial pull in tons E = 13000;//modulus of elsticity in tons/in^2 m = 4; A = 0.25*%pi*d^2;//in in^2 V = 0.25*%pi*d^2*l*12;//volume in cub.inches p = P/A;//in tons/in^2 e = p/E; del_l = e*l*12;//stretchof the bar in inche...
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clc //initialisation of variables a=0.51//mm f=0.1//m-kg //CALCULATIONS N=a/(a+b)//mm //RESULTS printf('the numberator and denominator of the right side=% f mm',N)
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// find closed-loop total harmonic distortion // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 19-4, page 714 clear; clc; close; // Given data R1=10^2;// in ohms from the given figure Rf=3.9*10^3;// in ohms from the given figure Avol=10...
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// scilab Code Exa 4.3 Calculations on Steam Turbine Plant p1=82.75; // Turbine Inlet Pressure in bar T1=510; // Turbine Entry Temperature in Degree Celsius pc=0.042; // Condenser Pressure in bar H=3420; n_e=0.85; gamma=1.4; n_st1=0.85; p2=22.75; // for regenerative cycle hs(1)=121.4; // from steam tab...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>AInflow Inlet Condition, P=5</description> <executable>PulseWaveSolver</executable> <parameters>AInflow.xml</parameters> <files> <file description="Session File">AInflow.xml</file> </files> <metrics> <metric type="L2" id=...
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// Delete figures, memory and screen xdel(winsid()); clear; clc function y = fun2fit(x, c) y = c(1)* cos(c(2)*x+c(3)) + c(4); endfunction // This is how we define the error to be minimized. // Function leastsq iterates through this error until it's // not posible to reduce it any more. function e = myerror(c, x, ...
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//to calculate net power op,eff,line current and pf clc; j=sqrt(-1); Zs=(1/3)*(.3+j*6); phi=atand(imag(Zs)/real(Zs)); Vt=400/sqrt(3); Ef=600/sqrt(3); a=sqrt(Vt^2+Ef^2-2*Vt*Ef*cosd(phi)); Ia=a/abs(Zs);disp(Ia,'line current(A)'); B=acosd((Vt^2+a^2-Ef^2)/(2*Vt*a)); phi=90-(90-atand(imag(Zs)/real(Zs)))-B;disp...
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//Example 7_6 clc(); clear; //To find out the rotation rate at=8.6 //units in meters/sec^2 r=0.2 //units in meters alpha=at/r //units in rad/sec^2 t=3 //units in sec wf=alpha*t //units in rad/sec printf("The rotation rate is wf=%d rad/sec",wf) //In textbook answer is printed wrong as 129 rad/sec b...
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//Chapter 13, Problem 7, figure 13.37 clc; E1=10; //e.m.f source 1 R1=2; //resistor 1 R3=5; //resistor 2 R2=8; //resistor 3 R=10; //resistor 4 I1=E1/(R1+R2); V2=I1*R2; r=R3+((R1*R2)/(R1+R2)); I=V...
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clc; N=1000; // speed of dc series motor v=250; // supply from mains i=50; // current drawn from mains r=0.6; // armature + field resistance rg=4.4; // additional resistance // field flux is proportional to armature current Ea1=v-i*r; // counter EMF at 1000 rpm // Ea2=v-(n2/20)*(r+rg) where Ea2 is counter EMf a...
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//ques12 //Using Generalized Charts to Determine Pressure clc //(a) R=0.5956;//Gas constant for a given substance in psia.ft^3/lbm.R Pcr=3200;//Critical Pressure in psia Tcr=1164.8;//Critical Temp in R v=0.51431;//specific volume in ft^3/lbm T=600;//Temperature in F //so P=1000;//Pressure in psia from Table A...
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clc clear //input f=0.15 //focal length u=0.2 //distance of object //calculation x=(1/-f)-(1/u)//lens formula y=1/x m=y/u//linear magnification //output printf("the position of image is %3.3f m",y) printf("\n linear magnification is %3.3f hence image is diminished",m)
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//Example 1.13// resolution clc; clear; close; //given data : D=1/9999; F=9.999; R=D*F; disp(R*10^3,"resolution,R(mv) = ")
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//Chapter 1: Structure and Bonding //Problem: 21 clc; // Solution v_n = 2 * 5 // number of valence e- in nitrogen v_co = 4 + 6 // number of valence e- in CO mprintf("The Number of valence electrons in N2 is %d\n", v_n) mprintf(" The Number of valence electrons in CO is %d", v_co)
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//dsing sleeve and cotter joint clc //solution //given P=60*10^3//N ft=60//N/mm^2 t=70//N/mm^2 fc=125//N/mm^2 pi=3.14 //let d be diameter of rods //P=A*ft //P=(p1/4)*d^2*ft printf("the dia of cotter jont is,%f mm\n",sqrt((P*4)/(pi*ft))) printf("the standard dia of cotter jont is d=26mm\n") d=36//mm //let...
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// Example 34_8 clc;funcprot(0); //Given data a=[5 4 2 1 0.5];// Load in kW b=[200 4000 2000 1000 1560];// No of hours at load CV_c=28000;// kJ/kg Cc=350;// Cost of coal in Rs./ton CV_d=36000;// kJ/kg Cd=1200;// Cost of diesel oil in Rs./ton Ci_s=18500;// Capital investment for steam plant in Rs/kW Ci_d=1700...
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R=1.987;//universal gas constant// T1=293;//initial temperature in kelvin// T2=303;//Final temperature in kelvin// K1=6.68*10^-3;//rate constant corresponding to T1 in per min// K2=1.31*10^-2;//rate constant corresponding to T2 in per min// E=(2.303*R*T1*T2*log10(K2/K1))/(T2-T1);//energy of activation in Kcal per ...
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//To find diameter and number of collars clc //Given: d2=300/1000,r2=d2/2 //m W=200*1000 //N N=75 //rpm mu=0.05 p=0.3 //N/mm^2 P=16*1000 //W //Solution: //Calculating the angular velocity of the shaft omega=2*%pi*N/60 //rad/s //Calculating the total frictional torque transmitted T=P/omega //N-m //Calculat...
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clc //initialisation of variables a=27.6//sq ft h=1.37//ft d=1.53*(27.9)^0.38*(1.36)^0.24//ft //CALCULATIONS R=d/4//ft A=(%pi*d^2)/4//sq ft //RESULTS printf('The diameter hydraulics radius and area of the hydraulically equivalent circular conduit=% f sq ft',A)
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// TODO: fix cyclic chains of snakes and ladders global ladder_top global ladder_bottom ladder_top = rand(1, sizeladder); ladder_top = ladder_top .* (85) + 15; ladder_bottom = zeros(1, sizeladder); idx = 0; for i = ladder_top idx = idx + 1; ladder_bottom(1, idx) = rand() * (i - 10) + 5; end for i = 1:sizela...
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clear all; clc; disp("Scilab Code Ex 12.10 : ") //Given: E = 200*10^6; //kN/m^2 I = 17*10^-6;//mm^4 l_ac = 2; //m l_cF = 4; //m l_Fb = 2; //m l_cb = 6; //m l_aF = 6; //m l_ab = 8; //m F = 16; //kN R_b = (F*l_cb)/l_ab; R_a = F - R_b; mc = R_a*l_ac; mf = R_b*l_Fb; theta_ca = (0.5*l_ac*mc)/(E*I); ...
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//chapter 10 // example 10.5 // page 351 R1=20 Vin=12; Vout=0;//worst case for masimum power across R1 VR1=Vin-Vout; disp(VR1) PR1=VR1^2/R1; disp(PR1)//watt
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clc //Initialization of variables pKa=4.88 C=0.01 //M pKw=14 //calculations pKb=pKw-pKa Kb=10^(-pKb) x=(sqrt(C*Kb)) pOH=-log(x) pH=14-pOH f=x/C //results printf("fraction protonated = %.1e",f) printf("\n 1 molecule in about %d",1/f)
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//clear commands clear; xdel(); clc; clf(); //write vectors x=[-0.442671 0.359050 -0.104953 0.802850 0.515488 0.119297 -0.067232 -0.934263 -0.397992 0.221656 0.574816 -0.812922 0.412275 0.318949 0.546983 0.935423 0.801874 0.360454 0.451766 0.152806 -0.704398 -0.383526 0.943968 0.477523 -0.828303 0.675832 -0.01126...
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//*********************************************************************// // Author : Asmita Bhar //*********************************************************************// function varargout = Minimum(image, varargin) [lhs,rhs] = argn(0); if rhs<1 then error(msprintf("Not enough input arguments")); end if rhs>9 ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 5 Example 17") Q12=1000;//heat added during process 1-2 in KJ Q34=800;//heat added during process 3-4 in KJ T1=500;//operating temperature for process 1-2 T3=40...
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h3 = 882; h2 = 1034; h6 = 998; h1 = 1008; v1 = 0.084; h4 = h3-h1+h6; h5 = h4; t4 = 25+273; disp("kJ/kg",h6-h5,"Refrigeration effect is") m = 10; w = (m*14000)/((h6-h5)*3600); // in kg/s disp("kg/s",w,"Refrigerant flow rate is") v1 = 0.084; VFR = w*3600*v1; // in kg/h ve = 0.8; // volumetric efficiency CD = ...
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//5.4 clc; To=1/2000; T=1/50; //Rn=1/(1+n^2*(To/T)^2) R1=1/(1+1^2*(To/T)^2); R3=1/(1+3^2*(To/T)^2); R5=1/(1+5^2*(To/T)^2); R7=1/(1+7^2*(To/T)^2); R11=1/(1+11^2*(To/T)^2); R13=1/(1+13^2*(To/T)^2); PE3=(R3-1/1)*100; printf("Percentage error for the production of 3rd harmonics=%.2f",PE3) PE5=(R5-1/1)*100; pr...
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//clear// //Caption: Program to find the torque and force acting on each side of planar loop //Example9.4 //page 271 clc; ax = sym('ax'); ay = sym('ay'); az = sym('az'); I = 4e-03; //current in Amps B = [0,-0.6,0.8]; //Magentic Field acting on current loop in Tesla L1 = [1,0,0]; //length along x-axis L2 = [...
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UNDEF : @,@ ASSLOA END ---1 -ALONG : IN STATE 1 POSIT 1 NOT FOUND ---2 -HAPPEN: CANNOT ALLOCATE STRING, STRHIB=2, FSYM=2 ---3 -EMITT : SYMBOL 3 IN STATE 3 NOT FOUN...
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//chapter18 //example18.7 //page406 Vcc=50 // V Np=5 Ns=1 R=50 // ohm R_ac=(Np/Ns)^2*R Po=Vcc^2/R_ac printf("ac load = %.3f ohm \n",R_ac) printf("maximum load power = %.3f W \n",Po)
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clc; s =%s; for k = 12:4:20 G = syslin('c',k/(s^2+8*s+k)); disp(G); den = denom(G); coef = coeff(den); Wn = sqrt(coef(1,1));disp(Wn,"Natural Frequency = "); zeta = coef(1,2)/(2*Wn);disp(zeta,"Daming ratio = "); if(zeta==1) printf("system is critically damped"); else if(zeta>1) printf("overdamped...
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Total index levels = 0 Total number of nodes = 2 Total number of items = 5 Dumping level #0 [Node 0] flags = 3, dge_link = -1 lft_link = -1, rgt_link = -1 Item #0, data = aaa, link = -1 Item #1, data = aaa, link = -1 Item #2, data = aaa, link = -1 Item #3, data = aaa, link = -1 Item #4, data = aaa, link = -1
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<?xml version="1.0" encoding="utf-8"?> <test> <description>3D channel flow, Prismatic elements, P=6</description> <executable>IncNavierStokesSolver</executable> <parameters>Prism_channel_m6_dealiasing.xml</parameters> <files> <file description="Session File">Prism_channel_m6_dealiasing.xml</file...
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# Heat exchanger test units SI $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + WATER # lets have some streams for this test hotInlet = Stream.Stream_Material() coldInlet = Stream.Stream_Material() hotOutlet = Stream.Stream_Material() coldOutlet = Stream.Stream_Material() hotInlet2 = Stream.Stream_Mate...
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // libbackdoor_c_path = get_absolute_file_path('loader.sce'); // // ulink previous function with same name...
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//Example 8.12 clear; clc; //Given T1=1225;//initial temperature in K T2=1200;//final temperature in K R=8.314;//gas constant in J K^-1 mol^-1 delHo=216.7;//standard enthalpy of the reaction in kJ K1=0.00328;//equillibrium constant at temperature T1 //To determine equillibrium constant,delSo and delGo at t...
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// Example 13.4 //Write a function to insert a given item before a specified node known as //key node. funcprot(0); //Create the list function [List]=create(list1) global List; // Create the current node list1.number=input("Input a number(Type -999 to end); "); if list1.num...
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clear; clc; Zin=36;Zt=500;f=40;x=0.97 Zo=sqrt(Zin*Zt); A=10^(Zo/276); lo=300/f; l1=lo*x/4; printf("-The characteristic impedance of the transmission line = %f ohms\n",round(Zo)); printf("-The spacing between the conductors shud be %f times the radius of the conductor\n",round(A)); printf("-The length of the qu...
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clear; clc; //Example13.14[Radiation Heat Transfer in a Cylindrical Furnace] //Given:- Ts=600;//Wall Temperature[K] d=5,H=5;//Diameter and Height of cylindrical furnace Tg=1200,eg=0.45;//Average gas temperature and average emissivity of the combustion gases Pc=0.10,L=3,Pw=0.16;//From Previous examples //Solut...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>NS, Couette flow, mixed bcs, FRDG advection and LFRDG diffusion, MODIFIED</description> <executable>CompressibleFlowSolver</executable> <parameters>Couette_FRDG_LFRDG_adiabatic.xml</parameters> <files> <file description="Session File">Co...
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//Find the inductance of a 3 phase line(triangle) clear; clc; //soltion //given r=1;//cm//radius of the conductor re=r*exp(-1/4); d1=600;//cm//spacing of the triangular shaped system d2=700;//cm//spacing of the triangular shaped system d3=800;//cm//spacing of the triangular shaped system L=0.2*log(((d1*d2*d3)...
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//chapter6,Example6_11,pg 124 ni=2.5*10^13 e=1.6*10^-19 un=3900 up=1900 sigin=ni*e*(un+up)//intrinsic conductivity //1 donor atom/10^8 Ge atom dropped rhoGe=4.42*10^22//no. of Ge atom/cc Nd=rhoGe/10^8 sigex=Nd*e*un//extrinsic conductivity printf("extrinsic conductivity\n") printf("sigex...
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//function myscijob() a=rand(5,5); b=rand(5,1); A=sparse(a); [h,rk]=lufact(A); x=lusolve(h,b); res=a*x-b fprintfMat('myscitest.dat',x); exit(); //endfunction
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//Problem 24.01: Determine the values of the resistance and the series-connected inductance or capacitance for each of the following impedances:(a)(12 + i5)ohm (b)-i40 ohm (c)30/_60° ohm (d)2.20 x 10^6 /_-30° ohm. Assume for each a frequency of 50 Hz. //initializing the variables: z1 = 12 + %i*5; z2 = -40*%i; r3 ...
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// Exa 8.9 clc; clear; close; // Given data C = 0.82;// in kg H2 = .12;// in kg O2 = 0.02;// in kg a = C/12; b = H2/2; y = (32*(a+(0.5*b))-O2)/0.23; disp(y,"Minimum quantity of air in kg is");
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% Test cases for definite integration. int(x/(x+2),x,2,6); int(sin x,x,0,pi/2); int(log(x),x,1,5); int((1+x**2/p**2)**(1/2),x,0,p); int(x**9+y+y**x+x,x,0,2); % Collected by Kerry Gaskell, ZIB, 1993/94. int(x^2*log(1+x),x,0,infinity); int(x*e^(-1/2x),x,0,infinity); int(x/4*e^(-1/2x),x,0,infi...
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//developed in windows 8 operating system 64bit //platform Scilab 5.4.1 //example 23_1w clc;clear; //Given Data temp=373.15;//Temperature at steam point (Unit Kelvin) press=1.5*10^4;//Pressure at steam point(Unit Pascal) //calculation ptr=(273.16*press)/temp;//Calculation of pressure at triple point of wate...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function s = Source(M) x1 = ones(M,1); y = 0:M-1; s = zeros(2*M,M) for i = 1:M x = (i-1)*x1; for m = 1:M s(2*m-1,i) = x(m); s(2*m,i) = y(m); end end s = m...
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clear //Given //From example 5.8 W = 4.0 //N/m - The force distribution L = 3 // m - The length of the force applied M = W*L/8.0 // KN.m The moment due to force distribution o = 30 // the angle of force applied to horizontal l = 150.0 //mm length of the crossection b = 100.0 //mm - width of the crossection // ...