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clc; clear all; er=1.0024;//relative permittivity N=2.7e25;//no of atoms e0=8.85e-12;//permittivity of vacume xe=e0*(er-1)/N;//polarisability of argon atom disp('F m^2',xe,'polarisability of argon atom is:')
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clc disp("Example 12.5") printf("\n") printf("Given") disp("The system ABC is DELTA connected") disp("Maximum line voltage is 339.4V") disp("The three impedances are 10(0 deg),10(30 deg),15(-30 deg)") ZABmag=10;ZABph=0; ZBCmag=10;ZBCph=30; ZCAmag=15;ZCAph=-30; //Let maximum line voltage is Vmax Vmax=339....
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function [a] = diffDiv(t, y) // diffDiv([1, 3, 4.5,5, 6], [1, 5, 3, 7, -1]) // calcule a, les différences divisées. On a : // - t est un vecteur de taille n+1 contenant les t_i. // - y est un vecteur de taille n+1 contenant les valeurs aux t_i. // Le polynôme p s'écrit : // p(t) =...
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//Chapter 02:Basic Structures: Sets, Functions, Sequences, Sums and Matrices clc; clear; j=[] s=[] i=0 upj=input("Enter the upper limit for the inner summation:"); lowj=input("Enter the lower limit for the inner summation:"); upi=input("Enter the upper limit for the outer summation:"); lowi=input("Enter the lower lim...
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//EXAMPLE 27.12 //ARMATURE clc; funcprot(0); //Variable Initialisation P=4;.....//Total number of poles N=1500;...//Speed in rpm Ia=150;.........//Current in Amperes Cs=64;.........//Total number of commutator segments Wb=1.2;.......//Brush span in segments L=0.05;........//Inductance of each armature in ...
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//Ex:4.4 clc; clear; close; V_rms=240;//in Volts V_pk=1.414*V_rms; printf("Peak voltage of %d V RMS voltage = %f V",V_rms,V_pk);
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# Wait a minute before starting, to give agent a chance to initialize DELAY FOR 60 #DELAY UNTIL 1-07:00:00 # Wait until 7am before starting to test BASELINE = smoist_up.bsl #INTERFERENCE = smoist_up.inf WHENEVER smoist[0] < 450 WAIT wpump FOR 60 # Wait one minute for water pump to be on WAIT not wpump F...
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clc; clear all; T = 300; // Temperature in kelvin c = 3e8;// Velocity of air h = 6.626e-34; // Plancks constant k = 1.38e-23; // Boltzmanns constant e = 1.602e-19; // Charge of an electron lambda = 5000e-10; // Wavelength of light in meters r = exp(((h*c)/(k*T*lambda))); // Temporary variable t = (1/(r-1)); //...
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//Chapter 14: Water Treatment //Problem: 5 clc; //Initialisation of Variables wt1 = 32.4 //in mg/L for Ca(HCO3)2 wt2 = 29.29 //in mg/L for Mg(HCO3)2 wt3 = 13.5 //in mg/L for CaSO4 //Solution wt1_eq = wt1 * 100 / 162. wt2_eq = wt2 * 100 / 146. wt3_eq = wt3 * 100 / 136. temp_h = wt1_eq + wt2_eq /...
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/*Este programa especifica um exemplo de declaração e invocação de uma função de soma com argumentos de entrada e de saída variáveis, a qual recebe argumentos de entrada, realiza a soma desses argumentos e devolve o valor do resultado. Nota-se que os argumentos de saída variáveis são especificados por uma lista. *...
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//Example 2.7.9;//series resistance and power dissipation clc; clear; close; //given data : format('v',7) vr=12;//in volts t=50;//in micro seconds d=0.2;//duty cycle pd=5;//power dissipation in watts Ig=poly(0,"Ig"); p=-5+1.5*Ig+8*Ig^2;// x=roots(p);// rg=(vr-(1.5+8*x(2,1)))/(x(2,1));//resistance in ohms pg=d*pd;//aver...
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function outputVoltage = helperHarmonicDistortion(inputVoltage) //helperHarmonicDistortionADC Helper function for HarmonicDistortionExample.m //Calling Sequence // outputVoltage=helperHarmonicDistortionAmplifier(inputVoltage) //Description //Analizing the harmonic distortion of a weakly non-linear system in the prese...
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// Example 10.25, page no-285 clear clc sig=6.22*10^7//per ohm-m n=5.9*10^28//m^3 e=1.6*10^-19//C mu=sig/(n*e) printf("The mobility of electrons in Si is %.2f*10^-3 m^2/V-s",mu*10^3)
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// Variable declaration n = 16 // sample size Mean = 3.42 // sample mean std_dev = 0.68 // standard deviation // Calculation // t(0.025) = 2.131 t = 2.131 y1 = Mean - t*(std_dev / sqrt(n)) // lower limit of range y2 = Mean + t*(std_dev / sqrt(n)) /...
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clc clear xdel(winsid()) // Close all existing figures // Scilab Computer Vision tutorial: drawing objects, geometrical analysis scicv_Init(); function plot_mat(img, desc) figure() matplot(img) title(desc) endfunction // ----------> DRAWING OBJECTS <---------- // Canvas for drawing: use...
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// 2.21 clc; th1=30; th2=60; th0=th1+th2/2; Rth1=4.8; Rth2=6.2; Rth0=5.5; ath0=(1/Rth0)*(Rth2-Rth1)/(th2-th1); printf("\n alpha at o degree= %.4f /degree C ",ath0) disp('5.5[1+0.0085(th-45)]')
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close(); clear; clc; //Three resistances in parallel 'R1', 'R2', 'R3', Voltage source 'V' R1 = 5; //ohm R2 = 10; //ohm R3 = 20; //ohm V = 100; //V //(a) //current through R1 'I1' I1 = V/R1; //A //current through R2 'I2' I2 = V/R2; //A //current through R3 'I3' I3 = V/R3; //A mprintf("Current through ...
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//3.11 clc; R=10; RL=R+R/2; i1=400/15; i2=i1; i3=i1; Irms_load=(1/(2*%pi)*(i1^2*2*%pi/3+(i1/2)^2*4*%pi/3))^0.5; printf("RMS value of the load current = %.3f A", Irms_load) Po=i1^2*R*3; printf("\nOutput power = %.2f W", Po) Iavg_thy=1/(2*%pi)*(i1*%pi/3+(i1/2*2*%pi/3)); printf("\nAverage thyristor current = %...
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local input = require("frontend/input") local scene = {} local currentIndex = {1,1} local previousIndex = {} local grid local cfg = cine.serialize.load("frontend/config.lua") local sw,sh = love.window.getDimensions() local font = cine.sourceFont.new("frontend/Roboto-Bold.ttf",cfg.fontSize[3]*(sh/100)) local layer = ci...
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COMMENT | ************************************************************* | COMMENT | * AUTHOR: R.W. Weyhrauch DATE: around 1978 | COMMENT | * | COMMENT | * SUBJECT: Peano/ Robinson arithmetic (with SS) | COMMENT | * | COMMENT | * NOTES: See Prolegomena paper in AI Journal 1980 (ap...
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//chapter 4 Ex 39 clc; clear; close; hens=50; goats=45; camels=8; numFeet=224; numKeepers=numFeet-((goats*4+camels*4+hens*2)-(hens+goats+camels)); mprintf("The total number of keepers are %d",numKeepers);
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//Variable declaration: //From example 13.4: h1 = 548.0 //Steam enthalpy at the entry and exit to the boiler (kJ/kg) h2 = 3989.0 //Steam enthalpy at the entry and exit to the turbine (kJ/kg) h3 = 2491.0 //Steam enthalpy at the entry and exit to th...
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// Scilab Code Ex 10.10 Electron mobility inside conductors : Page-346 (2010) e = 1.6D-19; // Electronic charge, in C m = 9.1D-31; // Eelctronic mass, in kg res = 1.54D-8; // Electrical resistivity of silver, in ohm metre E = 100; // Electric field applied along the length of the wire, V/m n ...
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3^3 + 4^3 + 5^3 = 6^3 6^3 + 8^3 + 10^3 = 12^3 9^3 + 12^3 + 15^3 = 18^3 7^3 + 14^3 + 17^3 = 20^3 12^3 + 16^3 + 20^3 = 24^3 18^3 + 19^3 + 21^3 = 28^3 15^3 + 20^3 + 25^3 = 30^3 18^3 + 24^3 + 30^3 = 36^3 14^3 + 28^3 + 34^3 = 40^3 6^3 + 32^3 + 33^3 = 41^3 21^3 + 28^3 + 35^3 = 42^3 3^3 + 36^3 + 37^3 = 46^3 27^3 + 30^3 + 37^3...
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clc; RL=8; VP=16; P=(VP^2)/(2*RL); disp('W',P,"P=");
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//example 2.1(b)// clc //clears the screen// clear //clears all existing variables// a=hex2dec('1E') b=hex2dec('F3') c=a+b; d=dec2bin(c); e=dec2hex(c); disp(c, ' addition of given numbers in decimal form = ') disp(d, ' addition of given numbers in binary form = ') disp(e, ' addition of given numbers in hexa...
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// Exa 1.3 clc; clear; close; // Given data format('v',9) V_CC= 12;// in volt V_EE= 12;// in volt V_BE= 0.7;// in volt R_C= 10;// in k ohm R_C= R_C*10^3;// in ohm R_E= 10;// in k ohm R_E= R_E*10^3;// in ohm R_B= 20;// in k ohm R_B= R_B*10^3;// in ohm Bita_dc= 75; // Part (i) //Ignoring V_BE I_T= V_EE/...
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aaa=imread("cat.jpeg") bbb=imread("lenaj.jpeg") ccc=imread("lenab.bmp") ddd=imread("lenat.tif") eee=imread("rect.jpg") aa=circle(aaa,100, 200, 50, 10, 10, 10, 1, 0, 0) bb=circle(bbb, 100, 200, 50, 10, 10, 10, 8, 0, 0) cc=circle(ccc, 100, 200, 50, 10, 10, 10, 4, 0, 0) dd=circle(ddd, 100, 200, 50, 10, 10, 10, 6, 0, 0) e...
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//example 1 //Balancing the Combustion Equation clear clc Mair=28.97 //Molar mass of air in kg/kmol x=8 //no. of moles of CO2 in products y=9 //no. of moles of H2O in products z=7.5 //no. of moles of O2 in products w=75.2 // no. of moles of N2 in products NMair=20*4.76*29 //mass of air in kg NMc=8*12 //mass o...
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//Example 5.1 // frequency clc; clear; close; //given data : N=45; // count t=10; // gate period in ms f=(N/(t*10^-3))*10^-3; disp(f,"frequency,f(k-Hz) = ")
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errcatch(-1,"stop");mode(2);//// exec("1.3data.sci"); //CA = 0.1*CA0; V = (v0/k)*log(1/0.1); disp("V =") disp(V) disp ("dm^3") exit();
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/* Sa se calculeze jacobianul si hessianul functiilor in punctul indicat: f(x,y)= x^2+y^2-1 x^3-y (x,y)=(1,2) */ deff('q=fct(p)', ['x=p(1)','y=p(2)','q(1)=x.^2+y.^2-1','q(2)=x.^3-y']) p=[1,2] [J,H]=numderivative(fct,p)
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clear// //Variable Declaration P=300 //Point Load in N R_a=100 //Reaction at A in N R_c=200 //Reaction at C in N E=12 //Youngs Modulus in GPa L1=2 //Length of the load from A in m L2=1 //Length of the load from C in m b=0.04 //Width of the CS of the beam in m h=0.08 //Depth of the CS of the beam in m //C...
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//pathname=get_absolute_file_path('6.08.sce') //filename=pathname+filesep()+'6.08-data.sci' //exec(filename) //Dryness fraction: x=0.10 //Pressure(in MPa): p=0.15 //From steam tables:(at 0.15 MPa): hf = 467.11 hg = 2693.6 vf = 0.001053 vg = 1.1593 sf = 1.4336 sg = 7.2233 //Enthalpy(in kJ/kg): h=hf+x*(h...
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errcatch(-1,"stop");mode(2);//Ex:2.10 ; ; printf("Resistance = 330 ohms with 2%% tolerance"); exit();
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//(4.10) An industrial process discharges gaseous combustion products at 478K, 1 bar with a mass flow rate of 69.78 kg/s. As shown in Fig. E 4.10, a proposed system for utilizing the combustion products combines a heat-recovery steam generator with a turbine. At steady state, combustion products exit the steam gener...
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//pathname=get_absolute_file_path('16.01.sce') //filename=pathname+filesep()+'16.01-data.sci' //exec(filename) //Bore diameter(in m): d=0.24 //Stroke length(in m): l=0.36 //Compression ratio: r=6 //Speed(in rpm): N=120 //Index of polytropic process: n=1.3 //Index for adiabatic process: n1=1.4 //Pressure ...
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//EX4_2 Pg-4.14 clc printf("When beta_dc=50 ") beta_dc=50; alpha_dc=beta_dc/(1+beta_dc); printf("\n alpha_dc=%.4f \n\n",alpha_dc) printf(" When beta_dc=190 ") beta_dc=190; alpha_dc=beta_dc/(1+beta_dc); printf("\n alpha_dc=%.4f \n\n",alpha_dc) printf(" When alpha_dc=0.995 ") alpha_dc=0.995; beta_dc=alpha_dc/...
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//Ten-Seng Guh tg2458 //COMS 4281 Intro to Quantum Computing //Homework 1 Programming Part args = sciargs() numargs = size(args, 2) if (numargs == 8) then j = strtod(args(6)) k = strtod(args(7)) m = strtod(args(8)) else //default values for j,k, and m disp("Incor...
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clear //Given uw=1.33 uo=1.20 //Calculation // uow=uw/uo sinr=(sin(30*3.14/180.0))/uow r=asin(sinr)*180/3.14 //Result printf("\n Angle of refraction in water is %0.1f degree",r)
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close; clear ; clc; //% Read in original RGB image. srcRgbImage = imread('steg_s.png'); //% Extract color channels. srcRedChannel = srcRgbImage(:,:,1); //% Red channel srcGreenChannel = srcRgbImage(:,:,2); //% Green channel srcBlueChannel = srcRgbImage(:,:,3); //% Blue channel //% Create an all black channel. allBlack ...
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clear //Given a=10**6 //J/s E=200*10**6*1.6*10**-19 //Calculation N=a/E //Result printf("\n Number of fission per second is %0.2f *10**16 ",N*10**-16)
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//example(3.14) c=[-3 1 0 1] p3=poly(c,'y','coeff') roots(p3)
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// Example 18.6, page no-463 clear clc N=2.7*10^25//m^-3 d=0.384*10^-9//m eps=8.854*10^-12 alfe=4*%pi*eps*d^3 epsr=(1+(2*N*alfe)/(3*eps))/(1-(N*alfe)/(3*eps)) printf("The dielectric constant of Ar is %.8f",epsr)
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//To calculate the increase in Internal Energy in the process //Example 26.1 clear; clc; delQ=418;//Heat given to the gas in Joules delW=40;//Work done by the gas in Joules delU=delQ-delW;//formula for finding increase the internal energy printf("Increase in Internal Energy=%.f joule",delU);
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function [r]=%sor(l1,l2) //%sor(l1,l2) constant==rational //! r=degree(l2(2))==0&degree(l2(3))==0 if r then r=coeff(l2(2))./coeff(l2(3))==l1,end
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clc //Intitalisation of variables clear v= 1 //cc p= 1.013*10^6 //dyne cm^-2 r= 4.184*10^7 //ergs //CALCULATIONS W= v*p/r //RESULTS printf ('Work done = %.4f cal',W)
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// Exa 5.2 // To calculate reuse factor for AMP and GSM systems. clc; clear all; S_IAMP=18;// S/I ratio in dB S_IGSM=12;// S/I ratio in dB PPL=4; // propogation path loss coefficient //solution // Using Equation 5.16 on page no 132, we get N_AMP=(1/3)*((6*10^(0.1*S_IAMP))^(2/PPL));//reuse factor for AMPS...
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//Finding of Cappilary rise //Given d=0.03*10^-2; //Diameter in meter st=0.0735; //Surface Tension in N/m x=0; //contact angle in degree w=1000*9.81; //To Find h=(4*st)*cos(x)/(w*d); h1=h*10^2; disp(h); disp("Capillary rise ="+string(h)+" meter"); disp("Ca...
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//ex1 //Pressure of Saturated Liquid in a Tank clc Psat=70.183;//saturated pressure @90C using steam table A-4 in kPa printf('From steam table Psat @ 90 C = %.3f kPa',Psat); vsat=0.001036;//saturated specific volume @90C in m^3/Kg m=50;//mass in kg V=m*vsat;//Volume of tank in m^3 printf('\n Total Volume of Tan...
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//addition of harmonic motion //Exa_2_11 clc; clear; close; A=sqrt((10+15*cos(2))^2 + (15*sin(2))^2); alpha=atand((15*sin(2))/(10+15*cos(2))); disp("x(t)=R*%e^(i*(omega*t+alpha))"); disp("where "); disp(A,"A ="); disp(alpha,"alpha =");
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCI...
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a b b a s আ ব ্ ব া স a b d u l r a p h i k আ ব দ ু ল র ফ ি ক a b e r d a r e আ ব ে র ড ে য় া র a b e r d e e n আ ব ে র দ ি ন a b h a i p u r অ ভ য় প ু র a b u k a l a m আ ব ু ক া ল া ম a c h a l p u r অ চ ল প ু র a c t u n অ ্ য া ক ট ু ন a d a i r আ দ ে র a d e c c o অ ্ য া ড ে ক ো a d i r o n d a c k আ দ ি র ো ন ্ ...
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errcatch(-1,"stop");mode(2);//Initialisation of variables c=3e10 //eauating m=2*mo and cancelling we get v=sqrt(.75*c^2)// cm per s printf('required velocity is %e cm per sec \n',v) exit();
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//Exa 4 clc; clear; close; //given data : inINV=100000;//initial investment in Rs. and equal for all projects //Project A : cash in flows of 1st,2nd,3rd,4th and 5th years CIF1=30000;//in Rs. CIF2=30000;//in Rs. CIF3=30000;//in Rs. CIF4=30000;//in Rs. CIF5=30000;//in Rs. //Project A : Cummulative cash in flo...
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function d=g_tril(a,k) // g_tril - implement tril function for sparse matrix, rationnal matrix ,.. [lhs,rhs]=argn(0) if rhs==1 then k=0,end select type(a) case 1 then d=tril(a,k) case 2 then d=tril(a,k) case 4 then [m,n]=size(a) i=find(tril(ones(a),k)) a=matrix(a,m*n,1) d=emptystr(m*n,1) d(i)=a(i) d=mat...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-3,Example 4,Page 49 //Title:Mass ratio //================================================================================================================ clear clc //INPUT U=2000;//specific internal energy o...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 33 // read it as example 32 in the book on page 2.86 clc; disp("CHAPTER 2"); disp("EXAMPLE 33"); //VARIABLE INITIALIZATION r1=20; //in Ω r2=30; // r3=40; // l1=0.5; ...
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//Ex 3.11 //MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS PROGRAM clear; clc ; close ; syms n; a=0.5; //assume constant value x =(a)^n; X1= symsum (x,n ,0, %inf ); a=2; //assume constant value X2= symsum (x,n ,0, %inf ); if (X1<=%inf) disp('Hence Summation < infinity. Given System is Stable f...
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=(round(sd*100)/100) dms=[d m sd] endfunction a=26.0/60+51.0/3600;//angle in degrees p=56.0/60+5.1/3600//polar distance //calculation H=aco...
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//Determine the output of the motor. clc; clear; eff=80/100; V=220; I=8; // Power Equation P=V*I P=V*I;// Input Power Pout=eff*P;// Output Power disp('watts',Pout,'The output power of the motor =')
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// Copyright 2012 Manolo Venturin, EnginSoft S.P.A. // // Licensed under the Apache License, Version 2.0 (the "License"); // you may not use this file except in compliance with the License. // You may obtain a copy of the License at // // http://www.apache.org/licenses/LICENSE-2.0 // // Unless ...
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// scilab Code Exa 18.24 Calculation on an axial compressor cascade beta1=51; beta2=9; alpha_1=7; // air angle at rotor and stator exit u=100; // test section velocity of air in m/s cx=u/(tand(alpha_1)+tand(beta1)); w1=cx/cosd(beta1); alpha2=atand(tand(alpha_1)+tand(beta1)-tand(beta2)) c2=cx/cosd(alpha2); ...
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clc,clear printf('Example 4.7\n\n') P=400 //power absorbed in watts phi=acos(0.05) //power factor angle f=40*10^6 //frequency in hertz k_0=8.854*10^-12 //permittivity of free space k=5 //relative permittivity of wood A=200*10^-4 //area of cross section of plate in m^2 t=0.02 //thickness in m C=k_0*k*A/t //...
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//Example 1.32// expression of output clc; clear; close; //I1=2*sin(2*t)+0.2*cos(8*t);// //I1=2*sin(2*t)-0.2*sin(8*t+%pi);// w=2;// t=0.15;//secomds r=1/(sqrt(1+(w*t)^2));// mo=w*r;//magnitude pf=atand(w*t);//degree //Io=mo*sin(2*t-16.7);//output x=0.2 w1=8;// t=0.15;//secomds r1=1/(sqrt(1+(w1*t)^2));// mo1=x*r;//magni...
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clc;clear; //Example 15.3 //calculation of binding energy //given values Mp=1.00758;//mass of proton in amu Mn=1.00897;//mass of nucleon in amu M=4.0028;//mass of Helium nucleus in amu amu=931.4;//amu in MeV //calculation E1=(2*Mp+2*Mn-M)*amu;//total binding energy disp(E1,'Binding energy in MeV is'); E...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, Subsonic Cylinder, WeakDG advection, Implicit solver</description> <executable>CompressibleFlowSolver</executable> <parameters>CylinderSubsonic_WeakDG_Implicit.xml</parameters> <files> <file description="Session File">CylinderSubs...
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clear; clc; r1=3e6; x=10; r=150e6; rb=9e6; x1=x*rb/r1; xc=inv(2*inv(x1)); xt=rb*100/r; x=(inv(inv(xt)-inv(xc)))-5; printf("the reactance that should be added= %d percent",x);
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// Example 24_26 clc;funcprot(0); //Given data T_1=303;// K p_1=0.9;// bar p_2=4.5;// bar T_3=1000+273;// K p_3=1.1;// bar e=0.8;// Effectiveness of heat exchanger n_c=0.85;// Isentropic efficiency of compressor n_t=0.80;// Isentropic efficiency of turbine m_a=5;// kg/sec C_p=1.005;// kJ/kg.K r=1.4;// Sp...
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//Example 9.1 // current clc; clear; close; //given data : n=20; // dry cells of emf E=1.5; // emf in volts R=5; // external resistance in ohm r=0.5; // internal resistance in ohm I=(n*E)/(R+(n*r)); disp(I,"current flowing,I(A) = ")
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function y=f(x) y=2./(x+8) endfunction function integral=Trapezio(a,b,n) h=(b-a)/n x=a:h:b y=f(x) I=y(1) for i=2:n I=I + 2*y(i) end integral=(h/2)*(I+y(n+1)) endfunction integral=Trapezio(1.8,3.2,10) n=((10^5)*(4./(1.8+8)^3)*((b-a)^2))/12 n=70
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function draw_system (an, bm, opt) loadXcosLibs(); scs_m = scicos_diagram(); scs_m.props.title = "Diagram"; if (opt == 0) then index = 0 // x(n) index = index + 1 scs_m.objs(index) = CONST("define"); scs_m.objs(index).graphics.exprs = "x(n)"; scs...
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clc; clear all; t = 0.5e-2; // Thickness in meters r = 2650; // Density in Kg per cubic meters p=1;//for fundamental vibration Y = 7.9e10; // Youngs modulus in Newton per square meter f = (p/(2*t))*sqrt(Y/r);//The fundamental frquency disp('Hz',f,'The fundalmental frquency is ')
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//Keyword matrix for the example Fig 2.18 // Move scilab to current file directory [u,t,n] = file() n = strcat(n) file_name = basename(n)+fileext(n) file_name = strcat(file_name) ind=strindex(n,file_name) path = part(n,1:ind-1) chdir(path) exec("Chapter_2.sci",-1) key = "PLAYFAIREXAMPLE" mat = playfa...
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//example-22.11 //page no-674 //given //depth of penetration at 3K is 39.8 nm and at 7.1 K is 1730 A T1=3 //K T2=7.1 //K dp1=39.6*10^-9 //m dp2=1730*10^-10 //m //as we know that depth of penetration and temp are related as //(dp(T)/dp(T0))=1/(1-t^4/Tc^4) //so we get //at 3K //let dp(T0)=dp0 //dp0=sqrt(...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Transient Growth (Modified Arnoldi): Backward-facing step</description> <executable>IncNavierStokesSolver</executable> <parameters>bfs_tg.xml</parameters> <files> <file description="Session File">bfs_tg.xml</file> <file description="Ses...
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// Exa 3.5 clc; clear; close; format('v',5) // Given data R_L = 1.2;// in k ohm R_L = R_L * 10^3;// in ohm Vi = 16;// in V R = 1;// in k ohm R = R * 10^3;// in ohm // The value of V_L V_L = (R_L*Vi)/(R+R_L);// in V disp(V_L,"The value of V_L in V is"); V_Z = 10;// in V // The value of V_R V_R = Vi-V_L...
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//Ex3.6.1.;calculate: solar altitude anglr,Incident angle,Collector efficiency //Solar declination :delta n=1 delta=23.45*sin((360/365)*(284+n)); printf(" Solar declination delta=%f degree",delta); fie=22;//degree //solar hour angle ws=0,(at mean of 11:30 and 12:30) ws=0; //Solar altitude anglr alpha is given...
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//Example 1_7 clc; clear;close; //Given data i_latch=40*10^-3;//A t=40*10^-6;//s Vdc=90;//V R=25;//ohm L=0.5;//H //Solution : i=Vdc/R*(1-exp(-R*t/L));//A disp("Current in the circuit is "+string(i)+" A, it is less than latchig current, the thyristor will not turn on."); R=Vdc/(i_latch-i);//ohm disp("Ma...
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function sp=g_round(a) [ij,v,mn]=spget(a) sp=sparse(ij,round(v),mn)
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clc; V=230;//supply current Pout=15000;//output voltage Ra=0.2;//armature circuit resistance Rse=0.1;//resistance of series field winding Nf=1000;//shunt field turns per pole //Data for magnetization curve at 1500 rpm If_=[0 0.2 0.4 0.6 0.8 1.02 1.15 1.32 1.56 1.92 2.4];//field current at 1500 rpm Ea=[6 40 80 1...
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ಹೋಗು V;MASC;PL;3;FUT ಆಗು V;PL;1;FUT ಸಾಯಿಸು V;NEUT;PL;3;FUT ಕೊಡು V;FEM;POT;SG;3 ನಡೆ V;POT;PL;2 ಆಗು V;SG;1;POS ಆಗಮಿಸು V;IMP;PL;1 ಘೂಕ N;NOM;PL ಕರೆ V;MASC;SG;3;FUT ತೊಳೆ V;NEUT;PL;3;FUT ಕೆಮ್ಮು V;NEUT;PL;3;FUT ಕೇಳು V;PL;2;PRS ಸಾಯಿಸು V;FEM;PL;3;PST ಕಾಪಾಡು V;NEUT;SG;3;FUT ಕೆಮ್ಮು V;SG;2;POS ಪುಷ್ಕರಿಣಿ N;GEN;SG ಹಾಡು V;NEUT;PL;3 ಆ...
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clc //initialisation m=2//kg T=273//k r=8314.3//j/mol/k //CALCULATIONS c=sqrt(3*r*T/m) Ti=(4*c*c*m/(3*r)) C=Ti-273 //results printf(' temperature at which rms speed will double is= % 1f c',C)
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//===================================================================================== //Chapter 12 example 22 clc;clear all; //variable declaration f1 = 2*10^6; //frequency from second data in Hz f2 = 1*10^6; //frequency from first data in Hz C1 = 230*10^-12; //capacitance in F C2 =...
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//Example 14.8 //Gauss Legendre Two Point Rule //Page no. 472 clc;close;clear; deff('y=f(x)','y=1/(x+3)') s=integrate('f(x)','x',-1,1) printf('By Direct Method, I = %g',s) s=f(-1/sqrt(3))+f(1/sqrt(3)) printf('\n\n By Gauss-Legendre 2 point rule, I = %g',s)
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///Chapter No 11 Steam Boilers ////Example 11.16 Page No 247 ///Find Theoretical draught produced in water //Input data clc; clear; hw=1.9; //Drauhgt water in cm Tg=290+273; //Temp of flue gases in degree celsius Ta=20+273; //Ambient temp in degree celsius ma=22; //Flue gases...
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clc;funcprot(0);//Example 8.6 //Initilisation of Variables Th=120;.....//saturation temparature of vapour in degrees celcius Tci=30;......//Initial temparature of cooling liquid in degrees celcius mc=1;....//Mass flow rate of liquid in kg/s Tco=65;......//Outer temparature of cooling liquid in degrees celcius hfg...
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//EXAMPLE 26.5 //SHORT SHUNT COMPOUND GENERATOR clc; funcprot(0); //Variable Initialisation I=30;.............//Load current in Amperes V=220;.............//Terminal voltage in Volts Rsh=200;............//Resistance of shunt field in Ohms Ra=0.05;...........//Resistance of armature in Ohms Rse=0.30;..........
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//EXAMPLE 3-14 PG NO 182-183 X=[400+%i*0 -6+%i*0,-200-%i*346.410 6-%i*0]; Y=[12+%i*0 -6+%i*0,-6+%i*0 6-%i*8]; I1=52.31-%i*7.120; I2=37.957-%i*14.23; Ia=I1; disp('i) CURRENT (Ia) is in rectangular form = '+string (Ia) +' A '); Ib=I2-I1; disp('i) CURRENT (Ib) is in rectangular form ...
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//Example 6.1 clc; clear; close; format('v',5); //Given data : Do=25;//mm Dc=20;//mm H=85;//mm x=335;//mm y=350;//mm a=%pi/4*Do^2;//m^2 ac=%pi/4*Dc^2;//m^2 Cc=ac/a; disp(Cc,"Coefficient of contraction : "); Cv=sqrt(x^2/4/H/y); disp(Cv,"Coefficient of velocity : "); Cd=Cc*Cv; disp(Cd,"Coefficient of di...
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getf('fox_rabbit.sce'); x=ode([22;500],0,[0:.01:10],fox_rabbit); //set("figure_style","new") //create a figure subplot(211) plot2d([0:.01:10],x') xtitle('Fox and Rabbit History','Years','Population'); subplot(212) plot2d(x(1,:),x(2,:)) xtitle('Fox and Rabbit Interaction','Foxes','Rabbits');
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//check o/p when i/p is of type char y=['a' 'a' 'b' 'a']; f=armcov(y,3); disp(f); //output //!--error 10000 //length of input vector should be greater than 3/2 times of the input order of the model //at line 7 of function armcov called by : //f=armcov(y,3); //corresponding MATLAB o/p //Error using arpest //...
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clear; clc; printf("\n Example 5.1"); //Basis 1 kg of solids feed_rate_solid = 1.33; //Mass rate of feed of solids in kg/sec U = 1.5; //Mass rate of solids in the underflow in kg/sec Y = [5.0 ; 4.2; 3.7 ; 3.1; 2.5]; printf("\n concentration(Y) (kg water/kg solids):\n"); printf("%.1f\n",Y); pri...
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//Obtain path of solution file path = get_absolute_file_path('solution10_11.sce') //Obtain path of data file datapath = path + filesep() + 'data10_11.sci' //Obtain path of function file funcpath = path + filesep() + 'functions10_11.sci' //Clear all clc //Execute the data file exec(datapath) exec(funcpath,[-1]) //Calcu...
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clc; RC=12*10**3; RL=4.7*10**3; R1=33*10**3; R2=4.7*10**3; IC=1*10**-3; hiemin=1*10**3; hiemax=5*10**3; hfemin=70; hfemax=350; hie=sqrt(hiemin*hiemax); disp('kOhm',hie*10**-3,"hie="); hfe=sqrt(hfemin*hfemax); disp('Ohm',hfe*1,"hfe=");//answer printed in the book is wrong Ri=hie; a=(R1*R2)/(R1+R2); Ris=(Ri*a)/(Ri+a); d...
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clc //initialisation of variables clear t1=593 //temparature in k p2=1.05 //pressure in bar p1=7 //pressure in bar cp=1.005 p3=3.696 //pressure in bar r=0.287 //kj/kgk a=6.25*10^-4 g= 32.2 //ft/sec^2 R= 8.314 //CALCULATIONS t2=t1*(p2/p1)^((g-1)/g) c2=44.72*(cp*(t1-t2))^(0.5) rho2=p2*100/(r*t2) m2=rho2...