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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdProject_Diff1D Segment Modified basis P=6 Q=7</description> <executable>StdProject_Diff1D</executable> <parameters>4 6 7</parameters> <metrics> <metric type="L2" id="1"> <value tolerance="1e-12">1.32975e-14</value> ...
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-- VectorCAST 20.sp1 (05/27/20) -- Test Case Script -- -- Environment : COMPOUND_FAILS -- Unit(s) Under Test: manager -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:REMOVED_CL_PREFIX TEST.S...
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// Scilab Code Ex9.4: Page-9.26 ; (2004) clc;clear; ni = 2.4e+19; // Carrier concentration at room temperature mu_e = 0.39; // Mobility of electron; m^2V^-1s^-1 e = 1.6e-19; // Electronic charge, C mu_h = 0.19; // Mobility of holes, m^2V^-1s^-1 sigma = ni*e*(mu_e+mu_h); // Conductivity, mho.m^-1 r...
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clc //initialisation of variables p=120//lb/in^2 ts=264//degree C T1=(273+130.6)//F v=0.0171//ft^3/lb L1=518.4//lb T2=(273+171.9)//F L2=487.4//lb Cp=0.48//lb L=0.0894/Cp//lb Ts=T2*1.205//degree ta=536-273//Degree C T=649.9//C.H.U S=131.2//C.H.U w=(144*40)/1400*(10.49-v)//C.H.U C=T-S//C.H.U I=C-w//C.H.U...
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 5.28 clc; clear; s=poly(0,'s')//defines s as poly nomial variable h=syslin('c',(1/(s*(s^2+6*s+10))))//the given transfer function assigned to variable h assume K=1 scf(...
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clc;funcprot(0);//EXAMPLE 11.5 // Initialisation of Variables afr=15;.....................//Air fuel ratio p1=1;.........................//Atmospheric pressure in bar p2=0.8;.......................//Pressure at venturi throat in bar pd=30;....................//Pressure drop to air cleaner in mm of Hg rhohg=13600;...
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clc clear //INPUT DATA V=475//volume of hall in m^3 a1=0.025//absorbtion coefficient for wall in O.W.U a2=0.02//absorbtion coefficient for the ceiling in O.W.U a3=0.55//absorbtion coefficient for the floor in O.W.U S1=200//The wall area of the room in m^2 S2=100//The floor area of the room in m^2 S3=100//The c...
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function [F1]=crossover(Pa1,Pa2,a,b) //crossing over de deux individus n=length(Pa1); F1=zeros(1,n);M=zeros(1,n); for i=a:b do t=Pa1(1,i); M(1,t)=t; end; //matrice M d'arret pour la boucle while for k=a:b do F1(1,k)=Pa1(k); end; // liste F1 contenant la sequence de Pa1 entre a et b cont=1; f=findeur(Pa2,Pa1...
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// Complex variable s = poly(0, 's'); // // System values // M = 0.02; // Kg // Gravity g = 9.81; // m/s¨2 // Wheels r = 0.021; // m m = 0.019; // Kg Jw = 1/2*m*r^2; // Motor Max_speed = 260; // rpm gear_ratio = 50; Istall = 0.36; // [A] Vstall = 6; // [V] Tstall = 5*10*...
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//X: Abscisas. //Y: Imagenes f(x). //P: Polinomio de Newton. //n: Numero de puntos. //n-1: Grado del polinomio. function[P]=newton(X,Y) n=length(X); for j=2:n, for i=1:n-j+1,Y(i,j)=(Y(i+1,j-1)-Y(i,j-1))/(X(i+j-1)-X(i)); //Realizo las diferencias divididas end end x=poly(0,"x"); //Defino un poli...
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//example 3.1 clc; clear; disp("we can minimize the given equation as:"); disp('Y = AB'' + AB = A(B'' + B)'); disp('Therefore, Y = A(1) = A'); disp('this says that output Y equals to A, so all we hve to do is connect a wire between input A and output Y.');
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V1 = complex(10); V2 = complex(10*cos(-%pi/3),10*sin(-%pi/3)); Z1 = complex(1,1); Z2 = complex(1,-1); Z3 = complex(1,2); //By appling the nodal analysis we get the following equation: //Va((1/Z1)+(1/Z2)+(1/Z3)) = (V1/Z1) + (V2/Z2) Y = (1/Z1)+(1/Z2)+(1/Z3); Va = (1/Y)*((V1/Z1) + (V2/Z2)); //voltage of node a ...
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function [R, lags] = moc_xcorr (X, Y, maxlag, scale) // Compute correlation R_xy of X and Y for various lags k: // Calling Sequence // [R, lag] = moc_xcorr (X [, Y] [, maxlag] [, scale]) // Description // // Compute correlation R_xy of X and Y for various lags k: // // R_xy(k) = sum_{i=1}^{N-k}{x_i y_{i-k}}/(N...
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// Example 3.7, page no-165 clear clc //(a) R1=120 R2=120 R3=120 R4=120 Rg=100 C=(R1*R2*R4)+(R1*R3*R4)+(R1*R2*R3)+(R2*R3*R4)+(Rg*(R1+R4)*(R2+R3)) C=C/10^7 printf("(a)\nC=%.3f*10^7",C) E=10 F=E*R3*R1*2*10^3/(C*10^7) printf("\nF = %.1f *10^3 A/mm = %.1f mA/mm",F,F) //(b) Fe=2*10^-4 E=10 DeltaE=Fe*E/...
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// page no 310 // example 10.1 // BCD TO BINARY // BCD into its binary equivalent. // given BCD no is 72 clc; a=72; x=modulo(a,10); // seperating the units digit printf('Unpacked BCD1 ') disp(dec2bin(x,8)); a=a/10; // seperating the tens place digit a=floor(a); printf('\n \n Unpac...
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function value = sme(ratings,users,items) nr = size(ratings,1); value = 0; for i = 1:nr value = value + (ratings(i,3) - users(:,ratings(i,1))'*items(:,ratings(i,2)))^2; end endfunction
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clc //initialisation of variables t=240//F p=4//lb R=53.35//f t1=460//F l=0.6931//ft lb //CALCULATIONS W=p*R*(t1+t)*l//ft-lb //RESULTS printf('the work done=% f ft-lb',W)
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function signal =PrepAudioForProcessing(signal, SamplingFreq) signal = DownSampleTo3675(signal, SamplingFreq); endfunction function signalat3675 = DownSampleTo3675(signal, SamplingFreq) select SamplingFreq case 44100, signalat3675 = DownSample(signal, 12); case 22100, signalat3675 = DownSample(s...
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errcatch(-1,"stop");mode(2);//Caption:Find (a)Equivalent rotor current (b)Stator current (c)Power factor (d)Stator input (e)Rotor input (f)Efficiency //Exa:11.13 ; ; V=440//Voltage supplied(in volts) f=50//frequency(in hertz) Z_s=1.5+(%i*3)//Stator impedance per phase(in ohms) Z_r=1.6+(%i*1)//Rotor impedance p...
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syms s TF=8/(s^2+4*s+8) Mp=25 //given omegaN=sqrt(8) disp(omegaN,"omegaN = ") zeta=4/(2*omegaN) disp(zeta,"zeta = ") omegaD=omegaN*(sqrt(1-zeta^2)) Tp=%pi/omegaD disp(Tp," Tp = ") disp(%e^(-%pi*zeta/sqrt(1-zeta^2))," Mp = ") disp(4/(zeta*omegaN)," Ts = ")
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clc// // // //Variable declaration V=20*15*5; //volume(m^3) T=3.5; //time(s) A=950; //surface area(m^2) //Calculation sigma_as=0.165*V/T; //total absorption in the hall(OWU) ac=sigma_as/A; //average absorption coefficient //Result printf("\n total absorption in the hall is %0.3f...
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//chapter 3 Ex2 clc; clear; close; n1=5/8; n2=7/12; n3=13/16; n4=16/29; n5=3/4; V=[n1 n2 n3 n4 n5]; V=gsort(V,'lc','i'); mprintf("%.2f < %.2f< %.2f < %.2f < %.2f",V(1),V(2),V(3),V(4),V(5));
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//Find current and voltage of sending end and percentage regulation clear; clc; //soltion //given R=0.1425*200;//ohm//total resistance X=0.49*200;//ohm//reactance Y=8*10^-4;//S//total susecptance Vrl=132*1000;//V pf=0.8;//power factor P=50*10^6;//MVA Vr=round(Vrl/sqrt(3)); Ir_=(P/(sqrt(3)*Vrl)); Ir=Ir_*com...
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function [C,b,m]= HammingEncode(m3,m2,m1,m0) //Caption:Hamming Encoding //H(7,4) //Code Word Length = 7, Message Word length = 4, Parity bits =3 //function for XOR gate function [value] = xor(A,B) if(A==B) value = 0; else value = 1; end endfunction //Getting Messa...
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clc //ex16.4 V_T=240; //dc supply voltage R_A=0.065; //armature resistance R_F=10; //field resistance R_adj=14; //adjustable resistance n=1200; //speed in rpm P_rot=1450; //rotational power loss T_out=250; //hoist torque I_F=V_T/(R_F+R_adj); //field current //E_A at I_F...
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// Exa 4.30 clc; clear; close; format('v',6) // Given data R = 4;// in ohm L = 0.5;// in H V = 100;// in V f = 50;// in Hz X_L = 2*%pi*f*L;// in ohm X_C = X_L;// in ohm // X_C = 1/(2*%pi*f*C); C = 1/(X_C*2*%pi*f);// in F C = C * 10^6;// in F disp(C,"The value of capacitance in µF is"); I = V/R;// in A] ...
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//Buck Boost Converter Script File Rm=5.1; //Resistance L=2.2e-04; //Inductance C=8200e-06; //Capacitance Fsw = 200e03; // Switching Frequency
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//Section-14,Example-1,Page no.-PC.80 //To calculate K_p at 1000 K clc; T_1=925 T_2=1000 K_p925=18.5 dl_H=-71.09*10^3 R=8.314 //ln(K_p1000)/(K_p925)=(dl_H/R)*((1/T_1)-(1/T_2)) K=((dl_H)/R)*((1/T_1)-(1/T_2)) K_p1000=(%e^(K))*18.5 disp(K_p1000,'K_p at 1000 K')
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//ques-2.2 //Calculating percentage of hydrogen and Higher calorific value clc C=90;//Percentage of Carbon in coal O=3;//Percentage of Oxygen in coal S=0.5;//Percentage of Sulphur in coal NCV=8490.5;//Net calorific value (in kcal/kg) //HCV=NCV+0.09*H*587; //HCV=(8080*C+34500*(H-O/8)+2240*S)/100; //Solving for ...
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-chain [[-2,-1,3,1],[-3,0,6,1],[-3,-2,4,2],[-3,-1,6,2]] [3,4,5,6] 3 1 [[-2,-1,3,1],[-3,0,6,1],[-3,-2,4,2],[-3,-1,6,2]],det=1 [3,4,5,6], chain 8 => [11,27,15,29] => [25,86,31,88] => [45,199,53,201] => [71,384,81,386] => [103,659,115,661] => [141,1042,155,1044] => [185,1551,201,1553] => [235,2204,253,2206]
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// Exa 7.6 format('v',7);clc;clear;close; // Given data verticaltangencies = 2;// vertical tangencies horizontaltangencies = 5;// horizontal tangencies f_H = 1;// frequency in kHz // f_V/f_H = horizontaltangencies/verticaltangencies; f_V = (horizontaltangencies/verticaltangencies)*f_H;//unknown frequency of vert...
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clc //initialisation of variables Q= 140 //cuses w= 62.4 //lb/ft^3 l= 140 //ft P= 70 //percent k= 1.6 v= 3*10^8 //CALCULATIONS rv= k*v HP= Q*l*w*(P/1000)/550 //RESULTS printf ('Required size of reservoir = %.1e ft^3 ',rv) printf ('\n horsepower = %.f h.p ',HP)
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load('data') fs=128 t=0:1:6000-1 t=t/128 m1 = ( data(:,1)-mean( data(:,1) ) ) m2 = ( data(:,2)-mean( data(:,2) ) ) for(i = 33:6000) mm1(i) = mean(m1(i-32:i)) mm2(i) = mean(m2(i-32:i)) end figure subplot(3,1,1) plot2d(t, mm1) subplot(3,1,2) plot2d(t, mm2) subplot(3,1,3) plot2d(t, da...
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function [] = sgrid(zeta,wn,col) // sgrid() // sgrid(Z,Wn) // sgrid('new') // Copyright INRIA [lhs,rhs]=argn(0) if rhs < 3 ; col=3;end if rhs==0 then [a,limits]=xgetech() wmax = 10 .^(floor(log10(max(abs(limits))))); wn= 0:1:10; zeta = linspace(0,1,10); end if rhs==1 then if type(zeta)<>10 then write(%io(2),...
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//Example 1.4 vol_stack=6*3*0.5;//Volume of a stack of 100 bills(in^3)=length(in)*width(in)*height(in) n_stacks=(1*10^12)/(1*10^4);//Number of stacks=(1 trillion $)/(dollars in a stack of 100$ bills) area=100*50*(3/1)*(3/1)*(12/1)*(12/1);//Area of football field (in^2)=length(yards)*width(yards)*conversion sq.yards ...
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//Example 17.16// Ic=5;//mA //Collector Current Ve=5;//mV // Emitter Voltage Ic1=50;//mA //Collector Current Ve2=25;//mV //Emitter voltage a=log(Ic1/Ic)//(Taking antilog to remove the exponential term) //mprintf("a = %f mV",a) b=(Ve2-Ve)//(Subtracting the terms) //mprintf("b = %i ",b) B=b/a //(Dividing the ...
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//Initilization of variables //Here the integration is indefinite hence it will be computed manually and entered W=10 //lb l=4 //ft w=2 //rad/s g=32.2 //ft/s^2 //Calculations //Part (a) wf=1.5 //rad/s t=sqrt(((W/g)*(l*w*l))-((W/g)*(l*wf*l))) //s //Part (b) //Applying conservation of angular momentum r=((W/g...
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clc; Vgs=-5; Vgg=Vgs; Idss=0.016; Vgsoff=-8; Id=Idss*(1-(Vgs/Vgsoff))^2; Vdd=10; Rd=2200; VDS=Vdd-Id*Rd; disp('V',Vgs,"Vgs=") disp('mA',Id*1000,"Id=") disp('V',VDS,"VDS=")
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 3.6 //Caption : Program To find (a)Kinetic energy Change (b)change in temperature //Given values n=1;//Molar Rate(mol/s) D=5;//inner Diameter(cm) R=83.1...
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OraclePH.sci
function [F,G,H,ind] = OraclePH(qc,ind) //AdTInv = inv(AdT); //B = [-AdTInv*AdC;eye(n-md,n-md)] //q0 = [AdTInv*fd;zeros(n-md,1)] v = q0+B*qc; u = r.*v.*abs(v); F = %nan; G = %nan; H = %nan; if ind==2 then F = 1/3*sum(u.*v)+sum(pr.*(Ar*v)); elseif ind==3 then G = ...
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// Chapter 10 example 4 //------------------------------------------------------------------------------ clc; clear; // Given data f = 10*10^9; // operating frequency in Hz f_us = 100*10^3; // upsweep freq f_ds = 100*10^3; // downsweep freq Tus = 5*10^-3; // u...
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clc clear //Page number 470 //Input data t=0;//The given temperature in degree centigrade E=5.64*10^-21;//The mean kinetic energy of molecules of hydrogen in J R=8.32;//Universal gas constant in J/mole-K //Calculations T=t+273;//The given temperature in K N=(3/2)*(R/E)*(T);//Avogadros number //Outp...
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errcatch(-1,"stop");mode(2);//Exam:15.4 ; ; N_a=1.1*10^20;//acceptor density in atoms/m3 n_i=2.5*10^19;//concentration of majority carrier per m3 n_p=(n_i^2)/N_a;//intrinsic density R=n_p/n_i;//Ratio of n_p and n_i disp(R,'n_p/n_i='); exit();
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9_21.sce
clc //initialisation of variables R= 1.987 //cal mole^-1 K^-1 T= 2000 //K dH= 117172 //cal mole^-1 H= -43 //cal mole^-1 n= 2 H1= -56.12 //cal mole^-1 //CALCULATIONS K= 10^(-(1/(2.303*R))*((dH/T)+n*H-H1)) //RESULTS printf ('equilibrium constant= %.1e ',K)
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// Scilab code Ex5.19: Pg:229 (2008) clc;clear; t = 5; // width of the base of the prism, cm Lambda = 5000; // wavelength, angstrom D = 200; // Rate of change of refractive index with wavelength, per cm RP = t*D; // Resolving power of a prism d_Lambda = Lambda/(D*t); // Smallest difference in wavel...
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clc // Given that d = 200 // Diameter of focussed laser beam in micro meter T_m = 3400 // Melting temperture of tungsten in °C k = 2.15 // Thermal conductivity of tungsten in W/cm-°C p_a = 10 // Percentage of beam absorbed // Sample Problem 16 on page no. 401 printf("\n # PROBLEM 6.16 # \n") H = 2*k*T_m/(d*10^-4) I = H...
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errcatch(-1,"stop");mode(2);// Example 1.2, page no-23 Rs=30 R=1000 luponw=R/Rs printf('L upon W =100/3') printf("\n1kohm resistor can be fabricated by using a pattern of 100 mil* 3 mil") exit();
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p=1010011; r=1; figure; //plot (10,y); x=length(p); for y=1:7 if(z==1) then plot((r*5):(r*5)+5,2,"*"); else plot((r*5):(r*5)+5,1,"*"); end r=r+5; end
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clear stacksize('max') //K= ? //коэффициент кросс релаксации // ? N=7.8e+26;//концентрация активных ионов //? beta0 = K*N0; //K*N0 // c //? W31 = ?; // A31 //см^-3 //? W32 = ?; // A32 //см^-3 //? W21 = ?; //см^-3 //ок? h = 6.62e-34; //постоянная планка//? c=3e8; //скорость света //ок //sigma_a_pump = ?;//поглощение на...
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// Exa 4.4 format('v',7); clc; clear; close; // Given data format('v',11) V_A= 20;// in V R_D= 5;// in kΩ R_D= R_D*10^3;// in Ω I= 0.8;// in mA I=I*10^-3;// in A i_D= I/2;// in A unCox= 0.2;// mA/V^2 unCox= unCox*10^-3;// in A/V^2 WbyL= 100; // Formula i_D= 1/2*unCox*WbyL*V_OV^2 V_OV= sqrt(2*i_D/(unCox...
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//Transport Processes and Seperation Process Principles //Chapter 13 //Example 13.4-3 //Membrane Seperation Processes //given data //nomenclature similar to previous problem xf=0.5; theta=0.2;//fraction cut p1=20;//pressure selected for use ph=80;//pressure selectred for use alphas=10; xom=(xf*(1+(alphas-1)*...
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//signals and systems //Inverse Lapalce Transform //(a) X(S) = (7s-6)/s^2-s-6 Re(s)>-1 s =%s ; syms t ; [A]=pfss((7*s-6)/((s^2-s-6))); //partial fraction of F(s) F1 = ilaplace(A(1),s,t) F2 = ilaplace(A(2),s,t) //F3 = ilaplace(A(3),s,t) F = F1+F2; disp(F,"f(t)=")
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//Example 15_8 clc(); clear; //To show using lines of force that a charge suspended with in cavity induces an equal and opposite charge on surface printf("Lines of force come out of positive charge q suspended in cavity.\nCavity \nsurface must possess a negative charge since lines of force go and terminate on q.\nT...
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//scilab 5.4.1 //Windows 7 operating system //chapter 20 Cathode Ray Oscilloscope clc clear e=1.6*10^-19//e=charge of an electron Va=1000//Va=potential difference in volts m=9.11*10^-31//m=mass of an electron v=sqrt((2*e*Va)/m)//v=axial velocity of an electron l=2*10^-2//l=axial length of deflecting plates in ...
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%Generated from '../examples/happy/happy.dig'. query(instances(aconcept('Happy')), [i1]). concept('Happy'). concept('Pretty'). concept('Clever'). role(hasChild). implies(some(arole(hasChild), and([some(arole(hasChild), aconcept('Clever')), some(arole(hasChild), aconcept('Pretty'))])), aconcept('Happy')). ...
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exec("swigtest.start", -1); s = 2000; s = test1(s+1); s = test2(s+1); s = test3(s+1); s = test4(s+1); if s <> 2004 then swigtesterror(); end exec("swigtest.quit", -1);
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// Example 6.4 B=0.9; // Megnetic Flux Density N=4000; // No.Of turns mo=4*%pi*10^-7; // Permeability of free Space Hc=820; // Megnetic Field Strength for Core lc=0.22; // Length of Circuit Ac=50*10^-6; // Area of Circuit Fc=Hc*lc; ...
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// Test # 4 : When either Input Argument #1 or #2 is of complex type exec('./allpassbpc2bpc.sci',-1); [n,d]=allpassbpc2bpc([0.4*%i,0.7],[0.2,0.5]); //!--error 10000 //Wo must be real, numeric and must contain only 2 elements //at line 36 of function allpassbpc2bpc called by : //[n,d]=allpassbpc2bpc([0.4*%i,0.7],...
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//a is a collection of points function lagrange(a) [row,col] = size(a); for i = 1:row l(i) = 1 end for i = 1:row for j = 1:row if j~=i l(i) = l(i) * poly(a(j,1) , "x")/(a(i,1) - a(j,1)) end end end out = [] P = 0 for i ...
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// 2(n^2+5) clear; clc; close; mprintf("the first five terms of the sequence are: \n"); for n=1:5 disp(2*(n^2+5)) end
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//Example 3.1 //Program to Compute the DFT of a Sequence x[n]=[1,1,0,0] //and IDFT of a Sequence Y[k]=[1,0,1,0] clear; clc ; close ; x = [1,1,0,0]; //DFT Computation X = fft (x , -1); Y = [1,0,1,0]; //IDFT Computation y = fft (Y , 1); //Display sequence X[k] and y[n] in command window disp(X,"X[k]="); di...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 1 Example # 1.10 ") //diameter of pipe in m d = 0.5; //Epsilon is given as epsilon = 0.9; //sigma(constant) in SI units is sigma = 0.000000...
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// Example 4.28;//Pulse Spreadning clc; clear; close; L=100;// Length in Km Tpmd=0.5*sqrt(L);// pulse broadning in pico second disp(Tpmd,"pulse broadning in pico second is ")
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main array[2] a; var i; { let i <- 0; while i < 2 do let a[i] <- call inputnum(); let i <- i + 1 od; call outputnum(a[0]); call outputnum(a[1]) }.
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servers.cloud.int.foo42 bla.protocol_counter.foo tcpconns.42-remote.foo servers.cloud.int.foo.bar.apps.events.meh foo.bar.whatever-average abLaH bFoO
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//example 4.1 clc; funcprot(0); FS=4; q=110*2; Nq=90; Ny=50; Gamma=110; m1=0.34; B=2.5; L=2.5; H=1.5; phi=35; m2=0.45; Fqs=1-0.34*B/L; Fys=1-0.45*B/L; qu=q*Nq*Fqs+1/2*Gamma*Ny*Fys*B; Qall=qu*B^2/FS; disp(Qall,"bearing load in lb");
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//Example 7.9 // NEP and specific detectivity clc; clear; close; //given data : h=6.63*10^-34; c=3*10^8; Id=9*10^-9;// in A e=1.6*10^-19; eta=60/100; lamda=1.3*10^-6;// in m A=100*50*10^-12;// in m^2 NEP=(h*c*sqrt(2*Id*e))/(eta*e*lamda); disp(NEP,"NEP,(W) = ") D=sqrt(A)/NEP; disp(D,"Specific detectivity,(MHz^(-1/2) W^-...
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clear; clc; // Illustration 2.4 // Page: 99 printf('Illustration 2.4 - Page: 99\n\n'); // solution // Mass Transfer into a Dilute Stream Flowing Under Forced Convection in a Circular Conduit n = 6; // [number of variables] // Variables Symbols Dimensions // Tube diameter ...
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clear; clc; close; R1 = 39*10^(3); R2 = 3.9*10^(3); Re = 1.5*10^(3); Rc = 4*10^(3); Vcc = 18; Vbe = 0.7; Beta = 140; Rth = R1*R2/(R1+R2); Eth = R2*Vcc/(R1+R2); Ib = (Eth - Vbe)/(Rth + (Beta+1)*Re); Ic = Beta*Ib; Vce = Vcc - Ic*(Rc+Re); disp(Ic,'Collector current(Amperes) in :'); disp(Vce,'Vce(Volts)...
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//Example 33.1 d=10^-15;//Range of the strong nuclear force (m) c=3.0*10^8;//Speed of light (m/s) delta_t=d/c;//Time during which the pion exists (s) h=6.63*10^-34;//Planck's constant (J.s) delta_E=h/(4*%pi*delta_t);//Energy uncertainity from Heisenberg uncertainty principle (J) delta_E=delta_E*1/(1.6*10^-13)//E...
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clc(); clear; //To determine the number of guided modes NA=0.25; //numerical apperture lambda=0.75; //wavelength in micro metres a=25; //core radius i.e 50/2=25 f=(2*%pi*a*NA)/lambda; //normalised frequency Ng=(f^2)/2 ...
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//example-20.5 //page no-597 //given //area of plate A=10*10*10^-6 //m^2 //capacitance C=10^-9 //F //distance between the plates d=2*10^-3 //m //contant E0=8.854*10^-12 //F/m //dielectric constant Er=C*d/(E0*A) printf ("the cielectric constant of the crystal is %f",Er)
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//chapter21 //example21.4 //page468 R=10d3 // ohm C=2.2d-6 // F V1=0 // V V2=10 // V t1=0 // sec t2=0.4 // sec Eo=R*C*(V2-V1)/(t2-t1) printf("output voltage = %.3f V \n",Eo)
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clear; Q1 = [0.1:0.1:300, 300:-0.2:0.2, 0.2:0.02:10, 10:0.1:400, 400:-1:293]; Q2 = [0:0.1:899.9]; Q3 = [exp(-Q2/100+4.5)]; Q4 = [sin(-Q2)]; Q5 = [0.1:0.1:100, 100:-0.1:0.1, 0.1:0.1:100, 100:-0.1:0.1,0.1:0.1:100, 100:-0.1:0.1,0.1:0.1:100, 100:-0.1:0.1,0.1:0.1:100]; bigX = zeros(5*9000, 15); for i = 1:9000 q1 =...
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function Xi = genererRandNormale(moyenne,sigma, iter) Xi = grand(iter,1,'nor',moyenne,sigma); endfunction
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// Grob's Basic Electronics 11e // Chapter No. 22 // Example No. 22_9 clc; clear; // An RC circuit has a time constant of 3 s. The capacitor is charged to 40 V. Then C is discharged. After 6 s of discharge, how much is Vr? // Given data RC = 3; // RC time constant=3 Sec t = 6; // Discharge time=6 Se...
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//Example 6-5 Power Generation and Wind Loading of Wind Turbine D = 9 //diameter of wind turbine blade [m] V_1 = 11 //minimum speed for power generation [m/s] Wdot_act = 0.4 //Actual power generated by turbine [kW] beta1 = 1 //momentum flux correction factor rho = 1.22 //density of air [kg/m^3]
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clc //Chapter8 //Example8.1, page no 313 //Given //a L=1.2*10^-3//distributed inductance C=0.05*10^-6//distributed capacitance Zo=sqrt(L/C)//Characteristic Impedance mprintf('The characteristic Impedance is Zo= %f ohm',Zo) Wo=1// Assumedfor ease of calculation G=%i*sqrt(L*C)*Wo mprintf('\nPropagation consta...
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// Example 7_1 clc;funcprot(0); // Given data T_L=70.0;// °F T_H=4000.0;// °F // Solution n_T_max=(1-((T_L+459.67)/(T_H+459.67)))*100;// The maximum possible thermal efficiency of this engine in % printf('\nThe maximum possible thermal efficiency of this engine,(n_T)_max=%2.1f percentage',n_T_max);
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//Example 4.6 clc disp("kVA = 1200, V_L = 6600 V, R_a = 0.25 ohm, X_s = 5 ohm") disp("Now kVA = sqrt(3)*V_L*I_L*10^-3") il=1200/(sqrt(3)*6600*10^-3) format(7) disp(il,"Therefore, I_L(in A) =") disp("Therefore, I_aph = 104.97 A ... as star connected.") disp("This is its full load current") vph=...
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clc //Intitalisation of variables clear Ma= 153.8 //gms Mb= 169.9 //gms pa= 114.9 //mm pb= 238.3 //mm //CALCULATIONS xa= (1/Ma)/((1/Ma)+(1/Mb)) xb= 1-xa Pa= pa*xa Pb= pb*xb Pt= Pa+Pb //RESULTS printf ('PA = %.1f mm',Pa) printf ('\n PB = %.1f mm',Pb) printf ('\n Total vapour pressure = %.1f mm',Pt)
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function y = troiscorps(t,r,m) x1 = r(1:2);x2 = r(5:6);x3 = r(9:10); d1 = (x3-x2) / norm(x3-x2)^3; d2 = (x1-x3) / norm(x1-x3)^3; d3 = (x2-x1) / norm(x2-x1)^3; y(1:2) = r(3:4); y(5:6) = r(7:8); y(9:10) = r(11:12); y(3:4) = m(2) * d3 - m(3) * d2; y(7:8) = m(3) * d1 - m(1) * d3; y(11:12) = m(1) * d2 - m(2) * d1; end...
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function [x,iter] = falsaposicao(a, b, p, n) x=a iter=0; Er=10; while (Er>10^(p)) & (iter<n) xold = x x=a-(fx(a)*(b-a))/(fx(b)-fx(a)) Er= abs((x-xold)/x) if (fx(a)*fx(x)<0) then b=x else a=x end iter=iter+1 end endfunction
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clear; clc; printf("\t\t\tExample Number 8.21\n\n\n"); // influence of convection on solar equilibrium temperature // Example 8.21 (page no.-455) // solution T_surr = 25+273;// [K] surrounding temperature sigma = 5.669*10^(-8);// [W/square meter K^(4)] h = 10;// [W/square meter] heat transfer coefficient /...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // APPENDIX C : REVIEW OF BASICS // EXAMPLE : C.3 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA X_pu = 12/100 ; // Leakage reactance in pu kV_B_HV = 345 ; // HV ...
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 8.2.1\n') //given data E=1.96*10^11//youngs modulus in N/m^2 m=5//mass of rotor in kg d=0.01//dia of shaft in m I=(%pi/64)*d^4///moment of area in m^4 l=0.4//bearing span in m e=0.02//distance of CG away from geometric centre of rotor in mm N=30...
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//chapter 6 example 9// clc clear //electron transit time=tf,bandwidth=Bm,photoconductive gain=G,// tf=8*(10^-12);//in seconds// G=60; Bm=(1/(2*%pi*tf*G))*(10^-8); printf("\n maximum 3dB bandwidth=%f MHz\n",Bm)
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function out=iz(x) d=size(x); u=min(d); tr=0; for k=1:1:u; tr=tr+x(k,k); end out=tr; endfunction
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function c=cvet() n=getdate(); rand("seed",n(10)); c=round(1+rand(1)*15); if c==4 then c=5; end endfunction xg=[0 0 3 3 5 5 6 6 8 6 6 8 8 6]; yg=[0 5 5 0 5 0 0 5 5 5 3 3 0 0]; x=0; y=0; xs=1; ys=1; xm=10*max(xg); ym=10*max(yg); vx=0; //n=getdate(); rand("seed",n(10)); c=round(1+rand(1)*8); f=figure(); f.figure_p...
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//Example 8.10 //Cascaded lattice realization of IIR Transfer Function clear; clc; z=%z; P3z= -0.2 + 0.18/z + 0.4/(z^2) + 1/(z^3); D3z= 1 + 0.4/z + 0.18/(z^2) - 0.2/(z^3); A3z=P3z/D3z; p1=coeff(numer(P3z)); p=mtlb_fliplr(p1); disp(mtlb_fliplr(p),'The coefficients ofnumerator are = '); d1=coeff(numer(D3z-1)); d=mtlb_fl...
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// Exa 2.14 clc; clear; close; // given : f=100 // frequency in MHz f=100*10^6 // frequency in Hz v_0=3*10^8 // speed of light in m/s // formula : Gamma=%i*omega*sqrt(mu_0*epsilon_0)=%i*omega/v_0 =(%i*2*pi*f)/v_0 Gamma=%i*2*%pi*f/v_0 //propagation constant disp(Gamma,"propagation constant in m^-1:") funcprot...
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//Obtain path of solution file path = get_absolute_file_path('solution10_5.sce') //Obtain path of data file datapath = path + filesep() + 'data10_5.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the permissible shear stress for the spring tau (N/mm2) tau = (50/100)*Sut //Calculate the Wahl fa...
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clc clear for k=1:10 K=k if k>2 & k<=8 then continue//pass control to line 2 end disp(K) end