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clc disp("Example 2.45") printf("\n") disp("Find the capacitor value for half wave rectifier") Vdc=20 f=60 RL=500 r=0.1/(2*sqrt(3)) c=1/(2*sqrt(3)*r*f*RL) printf("Capacitor value =\t%e farad\n",c)
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//Finding of Discharge //Given rho=1000; d=0.05; P=1226.25; //To Find A=(%pi/4)*d^2; V=P/(rho*A); V1=sqrt(V); Q=A*V1; disp("Discharge ="+string(Q)+" m^3/sec");
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A = eye(405,405) for j = 1:405 for i = 1:405 if(abs(i - j) > 1) A(j,i) = 1 else A(j,i) = 0 end end end function [L,A,C] = fatoraLU(A) n = size(A,1) L = eye(n,n) C = 0 for j = 1:n-1 for i = j+1:n L(i,j) = A(i,j)/A(j,j) ...
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5 ~~~~~~~~~~~~~~~~~~~~~~~~~~ 374
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clc //initialisation of variables C0= 0.357 H1= 30.5 //ft H2= 5 //ft w= 62.4 // lb/ft^3 D= 20 g= 112 // lb/ft^3 //calculations G= g-w FS= D*G/(C0*w*(H1-H2)) //results printf ('safety factor = % 2f ',FS)
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clear all; clc; disp("Ex 8_3") //Using the eqautions of equilibrium and eqautions of friction and after simplifyig, we get a qaudratic equation: mu_s^2-4.419*mu_s+1=0 //solving the above equation for mu_s: //coefficients of the quadratic equation a=1 b=-4.619 c=1 d=sqrt(b^2-(4*a*c)) mu_s1=((-b)+d)/(2*a) mu_s2=((-b)-d)/...
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i1=4-1 // KCL at node 1 disp(i1,"i1=") v1=i1*1 v12=1*1 v2=v1-v12 i2=v2/1 i3=1-i2 //KCL at node 2 Vs=v2-1*i3 //KVL disp(Vs,"Vs=")
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clc clear Ms=7.5; //kg/kg of coal P=11; //in bar Tf=70; //in C Eff=0.75; //Efficiency FOE=1.15; //Factor of Evaporation Cps=2.1; //in kJ/kg K Hfw=293; //in kJ/kg H=(FOE*2257)+Hfw; //At 11 bar Hg=2781.7; //in kJ/kg Tsat=184.1; //in C Tsup=((H...
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disp('The given matrix is:') a=[1 1 1;2 2 2;3 3 3] disp(a,'A=') disp('A is not invertible because its columns are linearly dependent.') disp('Hence, 0 is an eigenvalue of matrix A.')
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clc //initialisation of variables v= 8.867*10^13 //sec^-1 u= 1.628*10^-24 //gms //CALCULATIONS k= (%pi*2*v)^2*u //RESULTS printf (' force constant = %.2e dyne cm^-1',k)
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function [b, r] = deconv (y, a) // calling sequence: // [b,r]= deconv (y, a) // Deconvolve two vectors. // // [b, r] = deconv (y, a) solves for b and r such that // y = conv (a, b) + r. // // If y and a are polynomial coefficient vectors, b will // contain the coefficients of the polynomial quotient and r will be // a ...
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clc // Given that l = 1e-10 // width of box in m e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg c = 3e8 // speed of light in m/sec h = 6.63e-34 // Planck constant in J-sec // Sample Problem 19 on page no. 15.31 printf("\n # PROBLEM 19 # \n") printf("Standard formula used \n") printf(" ...
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// Example 3.22, page no-147 clear clc Vi=0.6 Vi1=0.6 Vi2=0.6 R1=10*10^3 Rf=20*10^3 RL=2*10^3 I1=Vi/R1 I1=I1*1000 Av=1+Rf/R1 printf('Av=%d',Av) Vo=Av*Vi printf('\nVo=%.1f V',Vo) IL=Vo/RL IL=IL*1000 printf('\nI1=%.1f mA',IL) //By Kirchhoff's current law Io=I1+IL printf('\nIo=%.2f mA', Io)
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// Example 4.3:Number of the modes clc; clear; close; format('v',6) h= 0.85;// Wavelenght in micrometers a= 50;// Core radius in micrometers NA=0.17;// v1=(2*%pi*a*NA)/h; m2= round((v1^2)/2); disp(m2,"Number of modes")
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errcatch(-1,"stop");mode(2);//Example 9.14.2 // time interval ; ; format('v',7) vdv=2;//volts per division in micro seconds/div n=2;//no. of divisions Tint=vdv*n;//peak to peak voltage in volts disp(Tint,"time interval in micro seconds is") exit();
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// Variable Declaration P_i = 0.75 //Pre-fault power(p.u) f = 50.0 //Frequency(Hz) H = 6.0 //Value of H for finite machine(sec) x_G = 0.2 //Reactance of machine(p.u) x_T = 0.1 //Reactance of transformer(p.u) x_L = 0.4 //Reactance of line(p.u) V = 1.0 //Voltage of infinite ...
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health index pri rep docs.count docs.deleted store.size pri.store.size green aggstats-2013-01 12 1 1843406 301578 1.4gb 749.7mb green aggstats-2013-03 12 1 4499021 14779 2.8gb 1.4gb green aggstats-2012-11 12 1 821800 5307 593mb ...
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clc clear printf("example 8.7 page number 367\n\n") //to find the flow rate in an orifice density_of_water = 1000; //in kg/m3 viscosity = 1*10^-3; //in Pa-s pipe_diameter = 250; //in mm orifice_diameter = 50; // in mm density_of_mercury = 13600; // in mm manometer_height = 242; ...
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//Chapter 07: Discrete Probability clc; clear; s_total_msg=2000 //spam messages total spam_msg=250 //occurrence of 'Rolex' in spam nspam_msg=5 //occurrence of 'Rolex' in not know to be spam ns_total_msg=1000//not spam messages total threshold=0.9 p=spam_msg/s_total_msg q=nspam_msg/ns_total_msg r=p/(p+...
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Ex9_2.sce
clc// // // //Variable declaration d=5*10^-6; //thickness(m) Dc=3.4*10^-3; //diffusion coefficient(m^2 S-1) //Calculation tow_diff=d^2/(2*Dc); //time taken(s) //Result printf("\n time taken is %0.1f *10^-9 s",tow_diff*10^9)
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//To calculate the mass of melted Ice //Example 25.3 clear; clc; m=0.2;//mass of a piece of ice in kg at 25 degree Celsius s=4200;//specific heat capacity of water in J/kg-k t1=25;//Initial Temperature in Celsius t2=0;//Final Temperature in Celsius Q=m*s*(t1-t2);//formula for finding the heat L...
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Ex5_11.sce
clc; VS=6; R1=330; R2=470; VD=0.7; RT=R1+R2; I=(VS-0.7)/RT; disp('mA',I*10**3,"I=");
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Ex15_21.sce
//Variable declaration: a1 = 0.00044 //Term 'a' for U_clean a2 = 0.00089 //Term 'a' for U_dirty //Calculation: Rs = a2 - a1 //Resistance associated with the scale hs = 1.0/Rs //Scale film coefficient (Btu/h.ft^2..) //Result: printf("The scale film coefficie...
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ch6_31.sce
clear; clc; V=230;//per phase V_ml=sqrt(3)*sqrt(2)*V; f=50; w=2*%pi*f; a1=60; L=0.015; i_cp=(sqrt(3)*V_ml/(w*L))*(1-sind(a1)); printf("circulating current=%.4f A",i_cp);
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effdsql.tst
CREATE OR REPLACE PROCEDURE dynsql_efficiency (counter IN INTEGER) IS cursor_id INTEGER; exec_stat INTEGER; BEGIN /* || Approach 1: Open, parse, execute and bind and close || for each new variable. */ PLVtmr.capture; FOR i IN 1..counter LOOP cursor_id := DBMS_SQL.OPEN_CURSOR; DBMS...
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fibonacciRecursivo.sce
function f = fibonacciRecursivo(n) tic(); select n case 0 then f = 1 case 1 then f = 1 else f = fibonacciRecursivo(n-1) + fibonacciRecursivo(n-2) end t = toc(); disp(t); endfunction
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Ex17_2.sce
clc // Given that e=1.6*10^-19 //Charge on electron in Coulomb ni=4*10^19 // number of electron per unit volume for Si at 423 K (m^-3) //Values of m_e and m_h are deduced from graphs at page No.689 m_e=0.06 //Mobility of electron in m^2/V-s m_h=0.022 // Mobility of holes in m^2/V-s printf(" Example 1...
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NNID_Ex_3_11.sce
clc //Chapter 3:Network noise and intermodulation distortion //example 3.11 page no 88 //given ensqr=8*10^-16//noise voltage insqr=9*10^-25//rms noise current Rs=sqrt(ensqr/insqr)//sourse resistance k=1.38*10^-23//Boltzmmans constant T=290//tempreture F=(ensqr+insqr*Rs^2+4*k*T*Rs)/(4*k*T*Rs)//amplifier noise f...
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TIA.sce
//************************* TIA ****************************** if (blk_name.entries(bl) =='TIA') then for ss=1:scs_m.objs(bl).model.ipar(1) mputl("# TIA",fd_w); tia_str= ".subckt TIA_blk in[0]=net"+string(blk(blk_objs(bl),2))+'_1 out[0]=net"+string(blk(blk_objs(bl),2+numofip))+'_'+string(ss)+" #TIA_fgota_...
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//Example number 3.9, Page number 3.35 clc;clear;close // Variable declaration lamda_L1=39.6*10**-9 // in m lamda_L2=173*10**-9 // in m T1=7.1 // in s T2=3 // in s // Calculations x=(lamda_L1/lamda_L2)**2 // in kg/m^2 Tc4=(T1**4)-((T2**4)*x)/(1-x) // in K Tc=(Tc4)**(1/4) // in K printf("Tc = %0.4f K",Tc) printf("\n...
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ATWM1_Working_Memory_MEG_Salient_Uncued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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Example_4_13.sce
//Example 4.13 A random sample of 100 articles taken from alarge batch of article contains 5 defective article clc; clear; n=100; p=5/100; q=1-p; N=2646; SE=sqrt((p*q)/n); disp((p-2.05*SE),"to",(p+2.05*SE),"The 96% confidence limits for Pare ",N,"Population size N",n,"Sample size"); S_E=sqrt(p*q/(n))*sqrt((N-...
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3.sce
clc clear //input n=7//order of fringe l=0.63*10^-6 //wavelength x=24.8*10^-3 //seperation of bands d=1.5 //calculation a=n*d*l/x//slit seperation //output printf("the slit seperation is %3.3e m",a)
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CoSaMp.sce
function cj=contribution(R,dj) cj=abs(dj'*R)/norm(dj) endfunction function y=contriblist(R,D,s) [N,M]=size(D) CJ=[] for i=1:M CJ=[CJ,contribution(R,D(:,i))] end indices=1:length(CJ) [B,k]=gsort(CJ,"g","d") y=k(1:2*s) endfunction function y=cosamp(D,K,x,s) [N,M]=size(D) ...
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clc; vl=400; // line voltage z=10+7.5*%i; // load impedance per phase disp('For star connected load'); vp=vl/sqrt(3); // phase voltage ip=vp/abs(z);// phase and line current are same in the case of star connected load an=atand(-imag(z),real(z)); pf=cosd(an); P=sqrt(3)*vl*ip; pa=sqrt(3)*vl*ip*pf; pr=-sqrt(3)...
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// Example 7.4 r=0.75*10^-2; // Radius of Solenoid A=%pi*r*r; // area of Solenoid N=900; // No,of turns l=0.3; // Length of Solenoid mo=4*%pi*10^-7; // Permeability of free Space L=(N*N*mo*A)/l; // Formula of Induction of a Coil I=5; //...
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Ex24_10.sce
// Initilization of variables l=1 // m // length of the simple pendulum g=9.81 // m/s^2 // Calculations // Let t_s be the time period when the elevator is stationary t_s=2*%pi*sqrt(l/g) /// seconds // Let t_u be the time period when the elevator moves upwards. Then from eqn 1 t_u=2*%pi*sqrt((l)/(g+(g/10))) // se...
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// Scilab Code Ex12.11: Page-452 (2014) clc; clear; T = 110; // Half life of F-18, min f_remain = 0.01; // Fraction of the F-18 sample remained t = -log(0.01)/(log(2)*60)*T; // Time taken by the F-18 sample to decay to 1 percent of its initial value, h printf("\nThe time taken for 99 percent of the F-18 s...
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exec("poisson2d.sce",-1) function u = func(x,y) u = cos(x+y) - cos(x-y) endfunction function u = gauss(x,y) r2 = x**2 + y**2 u = exp(-0.5*r2) endfunction Nx = 50 Ny = 50 x = linspace(-%pi,%pi,Nx) y = linspace(-%pi,%pi,Ny) u0 = zeros(Nx,Ny) // set BC u0(1,:) = 0.0 u0(:,1) = 0.0 u0(Nx,:) = 0.0 u0(:,Ny) = 0.0 /...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 3: Methods of Analysis // Example 3 - 1 clear; clc; close; // // Given data I1 = 5.00; I4 = 10.00; R2 = 4.00; R3...
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spliTTER IG {} fILtEr RRv { } FilTER Y {nOt P Or nj } V -> YC GROUper k {MoDUlE MmGzI{ } MoDULE Y{ fAv < UAKXT DEltA 56 YT < R RdelTA 5 } aggRegATE UX } UngRoupEr N { } GrouPFiLteR aFaw {} meRGeR n { MoDule T { braNches vIs } MODUle Q { BrAncHEs n } MoDule x { bRaNCheS c, z, mQ } ExpOrT Fpr }
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// Example 2_15 clc;funcprot(0); // Given data v_A=0.3;// m/s // Calculation // Solution (I). // v_A=y_A,v_B=y_B v_B=-(2*v_A)/3;// m/s printf("\nThe velocity of B,v_B=%0.1f m/s",v_B); // Solution (II). v_B=abs((2/3)*v_A);// m/s printf("\nThe velocity of B,v_B=%0.1f m/s (upward)",v_B);
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function [x,y,t]=getoutputs(o) // Copyright INRIA execstr('[x,y,t]='+o(5)+'(''getoutputs'',o)')
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// Example 2.8.b: Calculate stability factor Beta=100;//Common emitter D.C. Current gain S=1+Beta ; disp (S,"The Stability factor")
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//calculate the circuit current u=1//for air gap F=1.5e-3//flux A=9e-4 //area B=F/A H=B/(4*3.14*10^-7*u) l=4e-3//air gap S=H*l//amps turns in air gap l=4e-3//air gap u1=800// for iron gap A1=750e-6 B1=F/A1 H1=B1/(4*3.14*10^-7*u1) l1=270e-3 S1=H1*l1 u2=1000//for P,Q,R H2=B/(4*3.14*10^-7*u2) Ip=135e-3...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1308" Width="13" Height="13" CellSize="40" BackgroundSize="1" Background="11plus.png"> <Cell Name="房子" X="2" Y="1" /> <Cell Name="房子" X="3" Y="1" /> <Cell Name="房子" X="4" Y="1" /> <Cell Name="房子" X="5" Y="1" /> <Cell Name="房子" X="6" Y="1" /> <Cell Na...
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clear;lines(0); x=rand(10,10,'uniform') rand('normal') rand('info') y=rand(x,'normal');
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 10 : PROTECTIVE EQUIPMENT AND TRANSMISSION SYSTEM PROTECTION // EXAMPLE : 10.4 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA z_l = 0.2 + %i * 0.7 ; /...
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function [child,st]=pkgFindObj(tag,parent) // same as findobj, but only compute it on the given parent frame // usefull if 2 frames have uicontrol with the same tag value if argn(2) == 1 if exists('gcbo') parent = pkgGetRootHandle(gcbo) else parent=gcf() end end st = %f child=[] if...
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clc m_O2=4; //kg m_N2=6; //kg p=4*10^5; //Pa T=300; //K M_O2=32; M_N2=28; m=10; //kg disp("(i) The mole fraction of each component") n_O2=m_O2/M_O2; n_N2=m_N2/M_N2; x_O2=n_O2/(n_O2+n_N2); disp("x_O2=") disp(x_O2) x_N2=n_N2/(n_N2+n_O2); disp("x_N2=") disp(x_N2) disp("(ii) The average molecular...
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disp('to check if the polynomials span R3') disp('placing the coordinate vectors of the polynomial into the columns of a matrix') a=[1 -3 -4 1;-3 5 5 0;5 -7 -6 1] disp(a,'A=') disp('performing row operations') a(2,:)=a(2,:)+3*a(1,:) a(3,:)=a(3,:)-5*a(1,:) disp(a) a(3,:)=a(3,:)+2*a(2,:) disp(a) disp('the four ...
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//Problem 10.16: //initializing the variables: c = 0.25 mo = 0.35 w = 0.15 in = 0.25 ql = 0.05 co2 = 0.118 co = 13; // in ppm o2 = 0.104 NHVc = 14000; // in Btu/lb NHVmo = 25000; // in Btu/lb NHVw = 0; // in Btu/lb NHVin = -1000; // in Btu/lb //calculation: NHV = c*NHVc + w*NHVw + mo*NHVmo + in*NHVin...
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// Function Name: expmatSym // Returns the Matrix exponential of the input matrix(symmetric/hermitian matrix). // Calculating the expmatSym. inputMat = [-1.2, 1, 1.9; -4, 2.6, 5; -2.3, 8, -7]; result = armaMatFunc("expmatSym",inputMat)
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clear// //Variables L = 150.0 * 10**-6 //Inductance (in Henry) C = 100.0 * 10**-12 //Capacitance (in Farad) //Calculation fo = 0.159 / (L * C)**0.5 //Resonant frequency (in Hertz) //Result printf("\n The resonant frequency is %0.1f MHz.",fo * 10**-6)
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//clear// clear; clc; //Example 25.2 //Solution cbyc0 =0.05; u0 = 58; //[cm/s] Dv = 0.37; //[m^2/g] c0 = 365; //[ppm] S = 1194; //[m^2/g] T = 25; //[C] rho_b = 0.461; //[g/cm^3] P = 737; //[mm Hg] M = 74.12; //[g/mol] eps = 0.457; t = 1:0.5:8.5; t(4) = 2.4; t(5) = 2.8; t(6) = 3.3; cbyc0 =[0.005,0.01,...
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clc;clear;close; n=3 disp("Enter matrix A") for i=1:n for j=1:n a(i,j)=input("Enter") end end disp('matrix is ') disp(a) a(2,:)=a(2,:)-(a(2,1)/a(1,1))*a(1,:) a(3,:)=a(3,:)-(a(3,1)/a(1,1))*a(1,:) disp(a) a(3,:)=a(3,:)-(a(3,2)/a(2,2))*a(2,:) disp(a) a(1,:)=a(1,:)/a(1,1) a(2,:)=a(2,:)/a(2,2...
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//Problem 3.10: A carbon resistor has a resistance of 1 kohms at 0°C. Determine its resistance at 80°C. Assume that the temperature coefficient of resistance for carbon at 0°C is 0.0005/°C //initializing the variables: R0 = 1000; // in ohms T0 = 0; // in °C T1 = 80; // in °C a0 = -0.0005; // in per°C pi = 3.14...
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/* Resolução Retroativo, por Mateus de Assis Tal solução foi explicada e desenvolvida em sala de aula Disciplina de Computação Numérica - ECT2401 */ function x = ResRet(A,b) //resolução retroativa com matriz A e vetor independente b [l,c] = size(A) //quantidade de linhas e colunas da matriz A f...
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//EXAMPLE 2.21.A clc; x1=100; x=integrate('3*t','t',0,x1); disp(x); disp('valid for t>=0');
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//Chapter 2 //Example 2_15 //PAge 30 clear;clc; fc=1e3; ugpd=4e3; cv=1e4; n_alternator=0.96; n_mech=0.95; //specific fuel consumption printf("(i)\t Specific fuel consumption = %.2f kg/kWh \n\n", fc/ugpd); //overall efficiency heat_per_day = fc*cv; e=ugpd*860; printf("\t\t Electrical output in heat units per day =%3...
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// mode(-1); lines(0); // DEMO START data_path = SCI+'/contrib/OpenPR-0.0.2/etc/data/heart_scale'; [label_vector, instance_vector] = readsparse(data_path); model = svmtrain(label_vector, instance_vector, '-c 1 -g 0.07'); disp("svm model:") disp(model) // DEMO END
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//check o/p when i/p is of type 'char' a='character'; y=peak2peak(a); disp(y); //output // 19.
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clear; clc; Vr=132e3/sqrt(3); P=50e6; pf=.8; Irm=P/(3*Vr) pfa=-1* acos(pf); Ir=complex(Irm *pf, Irm * sin(pfa)); A=complex(.98*cosd(3), .98*sind(3)); B=complex(110*cosd(75), 110*sind(75)); Vs=(A*Vr)+(B*Ir); V=abs(Vs) vs=V*sqrt(3)*1e-3; mprintf("\n\n\n(a)\nSending End Voltage= %.1f kV", vs) phi1=at...
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int main(void) { int a, b; a+++ ++b; }
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clc //Example 13.4 disp('Given') disp('L1=0.4H L2=2.5H k=0.6 i1=4i2=20*cos(500t-20)mA') L1=0.4;L2=2.5;k=0.6; disp('a)') t=0; i2=5*cos(500*t-(20*%pi)/180) printf("i2(0)=%3.2f mA \n",i2) disp('b)') M=k*sqrt(L1*L2) //v1(t)=L1*d/dt(i1)+M*d/dt(i2) v1=-L1*20*500*10^-3*sin(500*t-(20*%pi)/180)-M*5*500*10^-3*sin(500...
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// //areas a1=2050,a2=8400,a3=16300,a4=24600,a5=31500, h=5 printf("\n according to trapezoidal rule') v1=(h/2)*(a1+a5+2*(a2+a3+a4)) printf("\n volume = %0.3f meter cube",v1) printf("\n according to prismoidal rule') v2=(h/3)*(a1+a5+4*(a2+a4)+2*(a3)) printf("\n volume = %0.3f meter cube",v2)
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function M=%hm_imag(M) // Copyright INRIA M('entries')=imag(M('entries'))
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// Exa 2.28 clc; clear; close; // Given data format('v',13) Eg= 0.72;// in eV Ef= Eg/2;//in eV K= 8.61*10^-5;// in eV/K T=300;//in K nc= 1; n= 1+%e^((Eg-Ef)/(K*T)); ncBYn= nc/n; disp(ncBYn,"The fraction of the total number or electrons is : ")
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//chapter 12 //example 12.2 //page 477 printf("\n") printf("given") Vcc=24;Ve=5;Vce=3;Rl=120*10^3;Vbe=.7 Rc=Rl/10 Vrc=Vcc-Vce-Ve Ic=Vrc/Rc Re=Ve/Ic//use 3.9Kohm standard value to make Ic littel less than design level Re=3.9*10^3; R2=10*Re I2=(Ve+Vbe)/R2 R1=(Vcc-Ve-Vbe)/I2
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clc clear //Input data p1=1//Initial pressure in kg/cm^2 T1=15+273//Initial temperature in K p2=5.5//Pressure after compression in kg/cm^2 T3=750+273//Temperature at the entrance of turbine in K v=225//Speed in m/s x=70//Percentage in=75//Isentropic efficiency of compressor in percent Cp=0.24//Specific heat a...
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COMMENT | ************************************************************* | COMMENT | * AUTHOR: Paolo Pecchiari | COMMENT | * | COMMENT | * SUBJECT: EVAL TEST | COMMENT | * | COMMENT | * GETFOL VERSION: September 1990 | COMMENT | * | COMMENT...
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# interface { ifname le0; mtu 1500; } ipv4 { src 1.1.1.1; dst 2.2.2.2; tcp { seq 12345; ack 0; sport 9999; dport 23; flags S; data { value "abcdef"; } ; } } send { via 10.1.1.1; }
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function []= bfs() r=10 c=10 a = grand(r,c,"uin",0,1) a(1:(r+1):(r*r)) = 0 for(i=1:r) for(j=1:c) a(i,j) = a(j,i) end end disp(a) vis = 0 while(vis == r) for (j = 1:r) a1 =a(j,(1:$)) disp(a1) l1= find(a1...
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disp("Part a"); v=120; p=60; r=18; i=v/r; disp("the initial inrush of current (in A) is"); disp(i); disp("Part b"); i1=p/v; disp("the steady operating current (in A) is"); disp(i1); disp("Part c"); r1=v/i1; disp("the hot resistance (in Ω) of the lamp is"); disp(r1);
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PL/SQL Developer Test script 3.0 18 declare t_time1 TIMESTAMP := CURRENT_TIMESTAMP; t_time2 TIMESTAMP := CURRENT_TIMESTAMP - 0.000123; v_result varchar2(120); begin -- Call the function /* v_result := sgm.pa_utl.time_get_vdiff(time1 => t_time1, time2 => t_time2); DBM...
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// Scilab Code Ex8.3: Page-285 (2014) clc; clear; delta_E = 2e-003; // Energy difference for the 3p subshell of sodium, eV h = 6.62e-034; // Planck's constant, Js e = 1.602e-019; // Energy equivalent of 1 eV, J c = 3.00e+008; // Speed of light in vacuum, m/s lambda = 589.3; // Wavelength of spectra...
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//Example 1_43 clc(); clear; //To find the thickness of the soap film lemda=7000 //units in angstroam lemda=7000*10^-8 //units in cm u=1.33 n=2 t=(((2*n)+1)*(lemda/2))/(2*u) printf("Thickness of the soap film is %.8f cm",t)
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function [npl,nzr,ngn]=bilt(pl,zr,gn,num,den) //[npl,nzr,ngn]=bilt(pl,zr,gn,num,den) //macro for calculating the gain poles and zeros //which result from a bilinear transform or from //a biquadratic transform. Used by the macros iir //and trans //Note: ***This macro is not intended for general use*** // pl :input po...
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function [s]= trompette(fp,fm,Fe,d,m0) // fp -> hauteur, d-> durée, m0-> amplitude du sinus modulant Te=1/Fe; // temps echantillonage x=[0:Te:d]; //axe temps m=[0:Te:d]; // amplitude constante au cours du temps n=length(m); for i=1:n m(i)= m0; end f=[0:Te:d]; // frequ...
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clc // Given that f = 4 // Focal length of telescope objective in m d = 100 // Diameter of lens of telescope in inch lambda = 5000 // mean wavelength of light in angstrom // Sample Problem 33 on page no. 175 printf("\n # PROBLEM 33 # \n") printf(" Standard formula used \n") printf(" theta = 1.22*lambda/a \n...
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function [dboutput] = db(X, SignalType, R) //dboutput = db(X) converts the elements of the vector or matrix X to decibels (dB). The elements of X are voltage measurements across a resistance of 1 ohm. //dboutput = db(X,SignalType) specifies the signal type represented by the elements of X as 'voltage' or 'power'. The...
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<?xml version="1.0" encoding="utf-8" ?> <Scene> <Sprite Translate="X:-853.000000 Y:0.000000 Z:0.000000" Scale="X:1.000000 Y:1.000000 Z:1.000000" FileName="bg01.jpg" ImageArea="L:0.000000 T:0.000000 R:853.000000 B:480.000000" ZOrder="-10000" Opacity="1.00" MoveSpeed="0.00" /> <Sprite Translate="X:-0.500000 Y:0.0...
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clear; clc; //Example - 3.18 //Page number - 112 printf("Example - 3.18 and Page number - 112\n\n"); //Given T_1 = 300;//[K] - Temperature at entry P_1 = 100;//[kPa] - Pressure at entry P_2 = 900;//[kPa] - Pressure at exit R = 8.314;//[J/mol*K] - Universal gas constant // (a) // Reversible adiabatic ...
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clc clear x=[3.2 2.7 1 4.8 5.6] y=[22 17.8 14.2 38.3 51.7] for i=1:1:5 X=[x(1,i) y(1,i)] disp(X) end P31=(3-x(1,2))*(3-x(1,3))*(3-x(1,4))*(3-x(1,5))*y(1,1)/((x(1,1)-x(1,2))*(x(1,1)-x(1,3))*(x(1,1)-x(1,4))*(x(1,1)-x(1,5))); P32=(3-x(1,1))*(3-x(1,3))*(3-x(1,4))*(3-x(1,5))*y(1,2)/((x(1,2)-x(1,1))*(x(1,2)-x(1,3...
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//Example 1_35 clc; clear;close; //Given data: Vdc=100;//V L=0.1*10^-3;//H C=10*10^-6;//F Vc=100;//V t_off_thyristor=25*10^-6;//s IL=10;//A t_off=Vc*C/IL;//s disp("T_off is "+string(t_off)+" seconds. It is greater than thristor turn off time, so it is sufficient for communication.") Ip=Vdc*sqrt(C/L);//A ...
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// The equation x^3-17==0 has three real roots. // the graph of this function can be observed here. xset('window',7); x=-5:.001:5; // defining the range of x. deff('[y...
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//Variable declaration: h_out = 390.0 //Enthalpy of the fluid that exits from the evaporator (kJ/kg) h_in = 230.0 //Enthalpy of the fluid that enters the unit (kJ/kg) //Calculation: QC = h_out - h_in //Heat absorbed by the evaporator (kJ/kg) //Result: printf("The hea...
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//Exa:2.18 clc; clear; close; //Given: Pt=100;//in Watts m=0.25;//depth Pmax=100//maximum power transmission capable Pc=Pt/(1+(m^2)/2); printf("\n\n\t carrier power = %f W ",Pc); printf("\n\n\t sidebands have the remaining %f W ",Pmax-Pc);
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example418.sce
//Example 4.18 clc; syms s; I=(2*s+3)/((s+1)*(s+3)); i=ilaplace(I); io=limit(i,t,0); disp(io,'INITIAL VALUE OF i(t)');
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/MemoryAccess/PushNTest/PushNTest.tst load PushNTest.asm, // load PushNTestManual.asm, output-file PushNTest.out, compare-to PushNTest.cmp, // SP ...
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//example 2.3a pg.no.14 clear;clc;close; n=-2:2; x1=[4 -2 4 -6 0]; x2=0.5*x1//x[n] x3=0.5*[x1(length(x1):-1:1)];//x[-n] xe=(x2+x3);//even part xo=(x2-x3);//odd part a=gca(); a.thickness=2; a.x_location="middle"; a.y_location="middle"; plot2d3('gnn',n,xe,rect=[-4 -6 4 6]) xtitle('graphical representation of even part of...
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testarrondis.sce
floor(1.3),ceil(1.3),round(1.3),int(1.3) floor(-1.3),ceil(-1.3),round(-1.3),int(-1.3) floor(1.6),ceil(1.6),round(1.6),int(1.6) floor(-1.6),ceil(-1.6),round(-1.6),int(-1.6) // compute the quotient of a euclidean division by rounding floor(10/6) // quotient 10-6*floor(10/6) // remainder pmodulo(10,6) // r...
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1_2.sce
clc; clear; g=9.8;//m/s^2; acceleration due to gravity m=68.1;//kg c=12.5;//kg/sec; drag coefficient count=2; v(1)=0; disp(v(1),"v(m/s)=",0,"Time(s)=") for i=2:2:12 v(count)=v(count-1)+(g-c*v(count-1)/m)*(2); disp(v(count),"v(m/s)=",i,"Time(s)=") count=count+1; end disp(g*m/c,"v(m/s)=","infinity","Time(s)="...
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clear; clc; close; f = 1000; T = 1/f; C = 0.1*10^(-6); R = 100*10^(3); //between t1-->t2 vo_1 = 5; Vc = 25; //between t2-->t3 Rth = 0; Eth = 5; vo_2 =35; tau = R*C; discharge_time = 5*tau; //between t3-->t4 vo_3 = 5; disp(vo_1,'output voltage during t1-->t2 : '); disp(vo_2,'output voltage during t2...
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time_frequency_tool_test.sce
//-- To change the default directory, // create scilab.ini file at C:\Users\USER\Documents // with a statement such as: // chdir "C:\yugo\statistics" //-- To execute a script file like this, type: // exec("time_frequency_tool_test.sce") // in console or press Ctrl+L on Scinotes //--- To make the graph wind...
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ATWM1_Working_Memory_MEG_Nonsalient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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example7_5.sce
clear; clc; //Example7.5[Heat Loss from a Steam Pipe in Windy Air] d=0.1//diameter of pipe[m] Ts=110;//Temp of ecternal surface of pipe[degree Celcius] Ta=10;//Temp of air[degree Celcius] va=8;//Velocity of air[m/s] Tf=(Ts+Ta)/2;//Film temperature[degree Celcius] k=0.02808;//[W/m.degree Celcius] Pr=0.7202;//...
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Mul16.tst
load Mul16.hdl, output-file Mul16.out, compare-to Mul16.cmp, output-list ip1%B1.16.1 ip2%B1.16.1 out%B1.16.1; set ip1 %B0000000000000010, set ip2 %B1111111111111101, eval, output; set ip1 %B1111111111111101, set ip2 %B1111111111111100, eval, output; set ip1 %B0000000000000011, set ip2 %B0000000000000...