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// Example 2.11 clear all; clc; // Given data T_C = 38; // Given temeperature in celsius //The temperature in Kelvin T_K = T_C+273.15; T_0 = 293.61; // The temperature in kelvin equivalent to 0 deg celsius kT = 0.0253; // The term 'kT' in...
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clc //Initialization of variables D = 850 //kg/m^3 R = (0.06/0.10)^2 Qs = 0.005 // m^3/s Ql = 0.05 // m^3/s A2 = (%pi)*(0.06^2)/4 // m^2 // Calculations Ds = (Qs^2)*(D)*(1 - R^2)/(2*(A2)^2) // N/m^2 Dl = (Ql^2)*(D)*(1 - R^2)/(2*(A2)^2) // N/m^2 // results printf (" the pressure differnce range is %.2f kPa...
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// chapter 9 // example 9.28 // Design an OTT-filter // page-662 clear; clc; // given E_L=230; // in V (output voltage) f=50; // in Hz I_L=1.5; // in A (load current) Edc=40; // in V (source voltage) // calculate W_D=2*%pi*f; // calculation of design radian frequency Z_L=E_L/I_L; // calculation of load impedence Z_D=ab...
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//Problem 28.09: A series R–L–C circuit is connected to a 0.2 V supply and the current is at its maximum value of 4 mA when the supply frequency is adjusted to 3 kHz. The Q-factor of the circuit under these conditions is 100. Determine the value of (a) the circuit resistance, (b) the circuit inductance, (c) the circuit...
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//LUD Decomposititon clc clear close A=[] L=[] n=input("Enter order of matrix:") for i=1:n for j=1:n printf("Enter a number for a(%d %d):",i,j) A(i,j)=input(""); end end disp("The matrix is") disp(A) //Forward elimination for i=1:n for j=i:n if(i==j)then ...
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// Example 18.2, page no-460 clear clc r=0.12*10^-9//m eps=8.854*10^-12 alf=4*%pi*eps*r^3 printf("The electronic polarisability of an isolated Se is %.4f * 10^-40 F m^2",alf*10^40)
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000046 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x0000007a ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x0e 0x92 st -X, r0 0x2: 0x0a 0x92 st -...
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clc //Example 14.21 //Design of cone clutch with given mean diameter //------------------------------------------------------------------------------ //Given Data: //power to be transmitted P=20000//Watts //speed N=600//rpm //Mean diameter Dm=0.2//m //Mean radius Rm=Dm/2 //Taper of cone a=1/15 alpha=at...
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//chapter2,Example2_2,pg 22 V1=5//input-1 V2=5//input-2 V12=50*10^-3//difference input Vo=2//output voltage acc=0.01//accuracy Ad=(Vo/V12)//diffrential gain //error at the output should be less than (2/100)V or 20mV.if common mode gain is the only source of error then err=Vo*acc//error Acm=(...
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<scriptConfig name="das_test" script="das_test"> <params> <param name="das.sim.sample_interval" type="int">1000</param> <param name="das.sim.chan_4_label" type="string" /> <param name="das.sim.chan_1_label" type="string">1</param> <param name="das.sim.chan_2_label" type="string">2</param> <param n...
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clear clc RT_F=0.05913;//in V m_LHC=0.01;// gamma_LHC=0.383;// m_RHC=1.0;// gamma_RHC=0.042;// Ecell=-(RT_F*log10((m_LHC*gamma_LHC)/(m_RHC*gamma_RHC)));// printf('Ecell=%.4f V',Ecell) //page 525
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clc; clear; e=1; x1=.15*%i; x2=.15*%i; ia1=e/(x1+x2); a=1*%e^(%i*(120*%pi/180)); b=a^2; ia2=-ia1; ia=(b-a)*ia1; iap=e/x1; c=real(ia)/imag(iap); mprintf("the ratio to line to line fault to three phase fault=%f",c);
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## DO NOT EDIT! Generated automatically from test/ieee1788-constructors.itl ## by the Interval Testing Framework for IEEE 1788. ## https://github.com/nehmeier/ITF1788/tree/92558f7e942665a78f2e883dbe7af52320100fba ## ## ## Test Cases for interval constructors from IEEE Std 1788-2015 ## ## Copyright 2016 Oliver Heimli...
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clc f = 0.2 // feed in mm/rev. N = 800 // spindle speed in rev./min. d = 10 // doameter of hole in mm mrr = %pi*(d^2)*f*N/4 // metal removal rate in mm^3/min. mrr = mrr/60 // mm^3/s p = 0.5*mrr // cutting power from table 14.2 in watts omega = 2*%pi*N/60 // rpm T = p/omega // torque in N.m printf("\n MRR = %0....
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function [maximus, maximus2, maximus2val] = get_max_values_range(data, step, fstart, N) j=1; k=1; start_f = 125; end_f = 255; for i=fstart:step:N-step [maximum, index] = max(data(i:i+step-1)); f = index + i - 1; newf = f; while newf < start_f newf = newf *...
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clear; clc; a=90; R=10; P=5000; V_s=sqrt(P*R*4*%pi/(2*3)/((%pi-%pi/2)+(sind(2*a))/2)); V_ph=V_s/sqrt(3); printf("per phase voltage, V_ph=%.2f V",V_ph); I_or=sqrt(P*R); V_s=I_or*2*%pi/(sqrt(2)*3*(1+cosd(a))); V_ph=V_s/sqrt(3); printf("\nfor constant load current"); printf("\nV_ph=%.1f V",V_ph);
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errcatch(-1,"stop");mode(2);//Ex19_2 Pg-958 bin='11101'; //binary input dec=bin2dec(bin) //decimal output disp("The decimal equivqlent of 11101 is") disp(dec) exit();
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//Load Raw Points from File plPoints = csvRead("data\geometry\POINTS_16001_160409.csv", ","); //Load Point file plPoints(:,1) = -plPoints(:,1); //Flip Point X-values to correspond with cutting on the left side of SPDT machine (CCW rotation) plPoints = plPoints($:-1:1,:); //Reverse the order of the points
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// Test #8: When numerator and denominator have differents lengths exec('./tf2ca.sci',-1); [d1,d2,b]=tf2ca([0.03 -0.5 -0.5 0.03],[1 2.4 -33); //!--error 10000 //Both the vectors must be of equal length //at line 49 of function tf2ca called by : //[d1,d2,b]=tf2ca([0.03 -0.5 -0.5 0.03],[1 2.4 -33]
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clear // // // //Variable declaration a=100*10**-6 NA=0.3 //numerical aperture(m) lamda=850*10**-9 //wavelength(m) //Calculation V_number=(2*%pi**2*a**2*NA**2/lamda**2) //number of modes printf("\n total number of modes is %0.3f",2*V_number) //Result
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clear; clc; disp("--------------Example 3.9--------------") fl=0; // 0kHz fh=4; // 4kHz // example explanation printf("Figure shows a nonperiodic composite signal. It can be the signal created by a microphone or a telephone set when a word or two\nis pronounced. In this case, the composite signal cannot be period...
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//Fluid Systems - By Shiv Kumar //Chapter 17- Dimensional and Model Analysis //Example 17.4 //Theoritical Problem to Find expression for Drag Force.
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Ex4_15.sce
clc // initialization of variables mdots=100 // mass flow rate of sodium in kg/s Ts1=450 // inlet temperature of sodium in degree celsius Ts2=350 // exit temperature of sodium in degree celsius Cp=1.25 // specific heat of sodium in KJ/kg.*C Tw1=20 // inlet temperature of water in degree celsius Pw=5000 // inlet ...
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//Example 7.59b //Z transform of x[n]=(a^-n)u[-n-1] clc; syms a n z; x=(a^-n); X=symsum(x*(z^-n),n,-%inf,-1);
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clc clear //input data T1=333 //Inlet temperature in K D=0.05 //inner duct diameter in m f=0.005/4 //frictional factor L=5 //Length of the pipe in m Pt=101 //Exit pressure in kPa, Pt=P2 Since flow is choked M2=1 //Mach number at exit since pipe is choked k=1.4 //Adiabatic constant R=0.287 //Gas constant i...
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// Exa 5.6 clc; clear; // Given // A stationary Lissajous pattern Vy = 6 ; // max value on vertical axis Vx = 5; // max value on horizontal axis fx = 1500; // horizontal input frequency(Hz) // Solution // fy/fx = No of pts the target meets per bottom(x-axis)/No of pts the target meets per bottom(y-ax...
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clc // Given that lambda = 1.24e-10 // wavelength of X-ray in A x1 = 1 // coordinate on x axis of first plane y1 = 0 // coordinate on y axis of first plane z1 = 0 // coordinate on z axis of first plane x2 = 1 // coordinate on x axis of second plane y2 = 1 // coordinate on y axis of second plane z2 = 0 // coordinate on...
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//Example 12.10 rho=1.29;//Density from table (kg/m^3) v=40;//Speed (m/s) L=7.40*10^-2;//Characteristic length (m) eta=1.81*10^-5;//Viscosity from table (Pa.s) N_R_v=(rho*v*L)/eta;//Reynolds number printf('Reynolds number = %0.2e (object in fluid)',N_R_v) //Openstax - College Physics //Download for free at http...
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Infinite Impulse Response (IIR) Butterworth Filter.sce
clear n=5;//order ftype='lp';//lowpass fdesign='butt';//butterworth frq=[0.35 0];//[fh fl] delta=[0 0];//change in amplitude Hz=iir(n,ftype,fdesign,frq,delta);//transfer func [Hf fr]=frmag(Hz,100)//hf=value,fr=divisions plot(fr,Hf)//plotting of graph(x,y) xtitle('Frequency Response','Frequency','Magnitute');//...
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// Anti windup control (AWC) of IBM Lotus Domino server, studied in Example 9.16 on page 357. It can be used for the follwoing situations: with and without saturation, and with and without AWC. // 9.18 exec('pp_im2.sci',-1); exec('desired.sci',-1); exec('zpowk.sci',-1); exec('cosfil_ip.sci',-1); exec('polsplit3...
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clc; clear all; disp("temperature of cheese leaving") m=800;//kg/h D=100/1000;//m L=1.75;//m ts=95;//degree C t1=15;//degree C rho=1150;//kg/m^3 cp=2750;//J/kg.C mu=22.5;//kg/m.s k=0.421;//W/(m.C) A=3.1416*(D^2)/4; U=(m/3600)/(rho*A);// m/s Re=(m/3600)*D/(A*mu); Pr=mu*cp/k; X=(D/L)*Re*Pr; X Nu=3...
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function [img, RbandVal, GbandVal, BbandVal]=imgdisplay1(fname,RGB,path) stacksize('max') // Output variables initialisation (not found in input variables) img=[]; // Display mode mode(-1); // Display warning for floating point exception ieee(1); //fname='inputimage'; //RGB='RGB.txt'; //win4pix='win4pix.txt'; if(is...
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// Chapter 3 example 4 //------------------------------------------------------------------------------ clc; clear; // Given data RmsVmax = 100; // max value of RMS vtg RmsVmin = 25; // min value of RMS vtg Zl = 300; // load impedance in ohm // Calculations VSWR = RmsVmax/...
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//chapter4 //example4.3 //page69 Vm=1000 // V rp=500 // ohm Rl=4500 // ohm Im=Vm/(rp+Rl) // in A Idc=Im/%pi // in A Idc_mA=Idc*1000 // in mA Irms=Im/2 // since ac current is equal to rms current Irms_mA=Irms*1000 // in mA W=Irms^2*(rp+Rl) // in watts printf("dc ammeter reading = %.3f A or %.3f mA \n",...
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//=========================================================================== //chapter 6 example 5 clc;clear all; //variable declaration Rm = 2; //instrument coil resistance in Ω V = 250; //full-scale reading in V R...
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//Example number 3.4, Page number 3.34 clc;clear;close // Variable declaration V=12*10**4 // in m^3 A=13200 // in m^2 x=2 // The absorption become 2*A of open window // Calculation T1=(0.16*V)/A // Sabine's formula T2=(0.16*V)/(x*A) // in s Td=T1-T2 // in s // Result printf("T1 = %0.2f second",...
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// Examle 4.11 // From the diagram (4.14) Req=2+{(12*4)/(12+4)}+4; // Equivalent resistance (for 4.14a ) v=36; // Voltage source i=v/Req; // Current supply by the voltage source I=i*(12/(12+4)); ...
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// sum 3-10 clc; clear; G=38*10^3; d=10; P=5*10^3; A=%pi*d^2/4; sig=P/A; deld=0.0002; //Let the lateral strain be E1 E1=deld/d; v=2*deld*G/(sig-(2*deld*G)); E=2*G*(1+v)*10^-3; // printing data in scilab o/p window printf("v is %0.4f ",v); printf("\n E is %0.3f kN/mm^2 ",E);
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//Power P, Voltage V, Armature Resistance Ra,Field Resistance Rf //Total mechanical and core losses Pc close(); clear; clc; P = 100;//kW V = 230;//V Ra = 0.05;//ohm Rf = 57.5;//ohm Pc = 1.8;//kW If = V/Rf; Il = P*1000/V; Ia = Il+If; total_losses = If^2*Rf+Ia^2*Ra+Pc; Pi = P + total_losses/1000; n = P/Pi*...
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EX15_2.sce
//Finding of Speed of Sound waves //Given k=1.4; R=287; T=293; //To Find C=sqrt(k*R*T); C1=C*(18/5); disp("Speed of Sound waves ="+string(C1)+" Km/hr");
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("2*x + 12*x^2 + 32*x^3 + 32*x^4 - 32*y^4 - 3*z - 1").getHighTerms("x") = + 32*x^3, + 32*x^4 ("2*x + 12*x^2 + 32*x^3 + 32*x^4 - 32*y^4 - 3*z - 1").getHighTerms("y") = + 0, - 32*y^4 ("2*x + 12*x^2 + 32*x^3 + 32*x^4 - 32*y^4 - 3*z - 1").getHighTerms("z") = + 0, - 3*z
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Ex8_8.sce
clc clear P1=1; P2=10; Vs=0.014; n=1.3; V1=3; FAD=3; W=[n/(n-1)]*[P1*100*V1/60]*[((P2/P1)^((n-1)/n))-1]; printf('Power required= %2.1f kW',W); printf('\n'); RPM=FAD/Vs; printf('Rotational Speed= %2.0f rpm',RPM); printf('\n');
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clc; clear; function yp=f(x,y) yp=[y(2);-16.1*y(1)]; endfunction x=0:0.1:4 y0=[0.1 0]; sol=ode(y0,0,x,f); count=1; disp(sol) for i=1:2:81 a(count)=sol(i); b(count)=sol(i+1); count=count+1; end plot(x,a) plot(x,b,".-") h1=legend(["y1,y3","y2,y4"]) xtitle("y vs x","x","y") function yp=g...
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Ex5_6.sce
//Ex:5.6 clc; clear; close; I_c=1.5;//in A I_b=50*10^-3; V_ce=6;//volts hfe=I_c/I_b; P=I_c*V_ce; printf("hfe required = %d",hfe); printf("\n collector power dissipation = %d W",P);
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solution3_3.sce
//Obtain path of solution file path = get_absolute_file_path('solution3_3.sce') //Obtain path of data file datapath = path + filesep() + 'data3_3.sci' //Clear all clc //Execute the data file exec(datapath) printf('\nMaximum diameter of hub is: %f mm\n',(Dh + Uh)) printf('\nMinimum diameter of hub is: %f mm\n...
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example2_18.sce
// Calculate forward currents for voltages // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 2-18 in page 98 clear; clc; close; // Given data Vt=0.026; // Thermal voltage at room temperature in eV V=[0.1 0.2 0.3]; // Given voltages in V // Cal...
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7_2.sce
clc; //page no. 289 // prob no. 7.2 // In the given problem fm=30;// in KHz fs=44.1;//sampling rate in KHz fa=fs-fm;// audible frequency disp('KHz',fa,'The audible frequency is');
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TestHexTileSeq.tst
566769707=6 1191281444=3 1557219254=1 1854083915=1 25562286=1 710084632=3 565750963=0 1459925108=5 236938571=0 1860957759=5 1724402076=3 980256184=5 221507525=-2 1957337308=-1 1196621866=0 887770454=0 491728531=-1 1006831199=4 371995505=-1
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exp15_1pp.sce
clc clear disp('example 15.1') a=0.1 //plate area b=3 //flux density d=0.5 //distence between plates v=1000 //average gas velosity c=10 //condectivity e=b*v*d ir=d/(c*a) //internal resistence mapo=e^2/(4*ir) //maximum power output printf("E=%dV \ninternal resistence %.1fohm \nmaximum power output %...
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22_4.sce
clear//Variables VBB = 2.7 //Base voltage (in Volts) RB = 40.0 //Base resistance (in kilo-ohm) VCC = 10.0 //Supply voltage (in volts) RC = 2.5 //Collector resistance (in kilo-ohm) VBE = 0.7 //Emitter-to-...
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exa_7_5.sce
// Exa 7.5 clc; clear; close; // Given data V1= 6.2;// in V V2= 0.6;// in V V3= 0.6;// in V Vout= V1-V2-V3;// in V disp(Vout,"The output voltage in volts is : ")
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Chapter12_example5.sce
clc clear //Input data W=2.2//Work function of sodium in eV h=6.625*10^-34//Plancks constant in J.s c=3*10^8//Velocity of light in m/s e=1.6*10^-19//Charge of electron in Columbs //Calculations v=(W*e)/h//Frequency in Hz l=(c/v)/10^-10//The threshold wavelength in angstroms //Output printf('The threshold...
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EX5_15.sce
//chapter 5 //example 5.15 //page 450 clear; clc; disp("example 5.15"); L=8000; //load La=5000; pf=0.8; phi=acosd(pf); printf("\ntan phi= %f\n",tand(phi)); disp("FOR ALTERNATOR A"); pf_a=0.9; phi_a=acosd(pf_a); printf("\ntan phi_a= %f\n",tand(phi_a)); disp("reactive load=active load*tan phi"); dis...
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videowithpicturew.sce
response_matching = simple_matching; begin; trial { video { filename = "video_main.avi"; }; time = 1000; video { filename = "video_test.avi"; }; time = 5000; picture { ellipse_graphic { ellipse_height = 50; ellipse_width = 50; height = 1000; width = 1000; color = 255,0,0; }; x = 0; y ...
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example7_7.sce
v1=9; v2=12; i=100*10^(-3); v=v2-v1; r=v/i; disp("the value of the resistor (in Ω) is"); disp(r); p=v*i; disp("power rating (in W) of the required resistor is"); disp(p);
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Horizontal Inside Flick.sce
Name=Horizontal Inside Flick PlayerCharacters=Flick Player BotCharacters=Flick Start C.bot;Flick Start L.bot;Flick Start R.bot;Flick Target C.bot;Flick Target L01.bot;Flick Target L02.bot;Flick Target L03.bot;Flick Target L04.bot;Flick Target L05.bot;Flick Target R01.bot;Flick Target R02.bot;Flick Target R03.bot;Flic...
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Example1_25.sce
clc // Given That a=12e-5// slit width in cm lambda1=5.89e-5// wavelength in cm lambda2=5.896e-5//wavelength in cm n=2// for second order spectrum //Sample Problem 25 Page No. 56 printf("\n # Problem 25 # \n") printf(" \n Standard formula used \n lambda / d_lambda = n*N \n\n") d_lambda = lambda2-lambda1 gra...
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Example_11_11.sce
//Example 11.11 clear; clc; printf("\tExample 11.11\n"); // F is feed // D is distillate // W is waste // S is sidestream F=100; S=10; //Mass fractions of CCl4 in various streams xf=0.5; xd=0.95; xw=0.05; xs=0.8; // D + W = 100-10 // 0.95D + 0.00W = 50-8 A=[1,1;0.95,0.05];...
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Ex11_4.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 4") T1=(-30+273);//temperature of air at beginning of compression in K T3=(27+273);//temperature of air after cooling in K r=8;//pressure ratio Cp=1....
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Ex7_9.sce
// Theory and Problems of Thermodynamics // Chapter 7 // Thermodynamic Relations // Example 9 clear ;clc; //Given data T = 273.15 // temperature water in K den_i = 916 // density of ice at 0` C in kg/m^3 den_w = 1000 // density of water at 0` C in kg/m^3...
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clc; funcprot(0); //Example 14.4 //Initializing the variables Za_Zb = 16; Za_Zc = 24; f = 0.01; l1 = 120; l2 = 60; l3 = 40; d1 = 0.12; d2 = 0.075; d3 = 0.060; g = 9.81; //Calculations A = [%pi*d1^2/4 %pi*d2^2/4 %pi*d3^2/4] function[z] = Coeff(l,d) z = 4*f*l/(d*2*g); endfunction function[f] = ...
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clc; // Chapter 2 Switched communication systems //Example 2.3,page no 125 //given C=6000//Tatol no of call in busy hour SC=5000//no of subscribers CR=C/SC//busy hour calling rate mprintf('Busy hour calling rate is:%f \n',CR) T=2.5/60//avarage duration of calls in hours A=C*T//rate of traffic flow mprintf('...
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// Scilab Code Ex19.7: Page-962 (2011) clc; clear; H_c0 = 2e+005; // Critical field for niobium at 0 K, A/m H_cT = 1e+005; // Critical magnetic field for superconducting niobium at 5 K, A/m T = 8; // Temperature at which lead loses its superconducting state, K // As H_cT = H_c0*(1-(T/T_c)^2), solving...
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//Calculate the ampere turns for each commutating pole //Chapter 2 //Example 2.25 //page 135 clear; clc; disp("Example 2.25") P=8;..........................//pole Z=107;.........................//generator with slots Ia=1000;.....................//current containing in amperes Bag=0.32;....................../...
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Name=Orbmonk 1v1 invulnerable PlayerCharacters=OrbMonk BotCharacters=Shinji Bot.bot;Racer Bot.bot;Random Bot Watcher Assassins.rot IsChallenge=true Timelimit=60.0 PlayerProfile=OrbMonk AddedBots=Random Bot Watcher Assassins.rot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=kovaim1.map MapScale=1.0 Bloc...
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clc P=100 h=20.35 *10^-2 l=20 w= 8*P*h/l^2 printf('Weight of the tape = %f N/m',w)
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clc //initialisation of variables T= -40 //C v= 217.4 //cm^3 r= 8.8 // atm deg^-1 m= 18 //gms //CALCULATIONS H= (273+T)*(-v*m/1000)*r*(1.987/82.05) //RESULTS printf (' Increase in enthalpy = %.f cal mole^-1',H-1)
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//Example 9.1 clear; clc; Vref=2; R1=20*10^3; R2=30*10^3; Vos=5*10^(-3); IB=250*10^(-9); Rpar=(R1*R2)/(R1+R2); VN=Rpar*IB; Vneti=Vos+VN; VT=(1+(R2/R1))*(Vref-Vneti); printf("Worst Case Error=%.f mV",Vneti*10^3);
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//Problem 22.04: The stator of a 3-phase, 4-pole induction motor is connected to a 50 Hz supply. The rotor runs at 1455 rev/min at full load. Determine (a) the synchronous speed and (b) the slip at full load. //initializing the variables: p = 4/2; // number of pairs of poles f = 50; // in Hz nr = 1455/60; // in r...
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//Transmission Lines : example 12-9 : (pg 599) j=%i; RL=120;//load resistance from smith chart ZL=75+j*50;//load impedance Z0=50;//characteristic impedance a=75/Z0; y=50/Z0;//normalized load impedance z=2.4;//normalized z at a point that is purely resistive ar=z*Z0;//actual resistance x=sqrt(Z0*RL); printf("\...
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function [r] = kLED(ref,n,action) // Ouput variables initialisation (not found in input variables) r=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); //KLED Send led command to Khepera // //kLED(ref,n,action) // Set the led number n to OFF (action=0), ON (action=1), // or c...
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//Solution 11-5 WD=get_absolute_file_path('11_05_solution.sce'); datafile=WD+filesep()+'11_05_example.sci'; clc; exec(datafile) //unit conversions V = V / 3.6; //from [km/h] to [m/s] //(a) W = m * g; //weight of aircraft [N] //from total weight = lift force minimum velocity is given by V_min1 = sqrt(2 * W /(rho_ground ...
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//Chapter 5:Dc Motor Drives //Example 13 clc; //Variable Initialization //Ratings of the separately excited motor V=200 // rated voltage in V N=875 // rated speed in rpm Ia=150 // rated current in A Ra=0.06 // armature resistance in ohms Vs=220 // source voltage in V f=50 // frequency of the source vol...
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// Exa 2.18 clc; clear; close; // Given data Vt= 1;// in V unCox= 120;// in µA/V^2 unCox= unCox*10^-6;// in A/V^2 L1=1;// in µm L2=L1;// in µm I_D= 120;//in µA I_D= I_D*10^-6;//in A V_GS1= 1.5;//in V V_G2= 3.5;// in V V_S2= 1.5;// in V V_DD= 5;// in V V_D2= 3.5;// in V // Formul I_D= 1/2*unCox*W/L*(V...
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//Ex_7_9 clc; clear; close; format('v',6); //given data : VEE=5;////V VCC=-5;////V VE=1;////V RB=20;//kohm RE=5;//kohm RC=5;//kohm VBE=0.7;////V VB=VE-VBE;///V IB=VB/RB;///mA IE=(VEE-VE)/RE;//mA IC=IE-IB;//mA VC=VCC+IC*RC;//V Beta=IC/IB;//Current gain Alfa=IC/IE;//Current gain disp(VB,"VB(V) : "); ...
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//Chapter 17 //Example 17_6 //Page 408 clear;clc; kva1=3000; kva2=4500; x1=7; x2=8; rc=150*1e6/1000; kvatr=7500; xt=7.5; bv=3300; base=7500; printf("Let base kVA be 7500 kVA \n"); per_x1=x1*base/kva1; per_x2=x2*base/kva2; per_xt=xt*base/kvatr; r_ab=per_x1*per_x2/(per_x1+per_x2); c=base*100/r_a...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//pathname=get_absolute_file_path('1.02.sce') //filename=pathname+filesep()+'1.02-data.sci' //exec(filename) //Diameter of the vessel(in m): d=30*10^-2 //Accelertion due to gravity(in m/s^2): g=9.78 //Atmospheric pressure(in Pa): p=76*(10^-2)*13550*g //Area: a=(%pi*d^2)/4 //Effort required: F=p*a printf("\...
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// Example 11.6, Page No-466 clear clc Vr=10 R=10*10^3 I1=Vr/(2*R) I1n=I1*1000 printf('\nI1= %.1f mA', I1n) I2=I1/2 I2n=I2*1000 printf('\nI2= %.2f mA', I2n) I3=I1/4 I3n=I3*1000 printf('\nI3= %.2f mA', I3n) Io=I1+I2+I3 Ion=Io*1000 printf('\nIo= %.3f mA', Ion) Vo=-1*Io*R printf('\nOutput Voltage V...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 4 : DIRECT CURRENT MACHINES // EXAMPLE : 4.2 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA p = 8; // Number of the poles in Dc machi...
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//This scilab script is to compute the solution of a nonlinear function with initial //guess x_0 clear clc //The nonlinear equation for which solutions are sought exec functwovar.sci; //Initial guess for the solution t0 = [0;0]; //Computation of solution using fsolve y_result = fsolve(t0,functwovar); //Display t...
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clc; clear all; V = 12000; // Volume of the room in cubic meters T = 1.5; // Reverberation time in seconds a = 0.4; // Absorption coefficient of interior surface in sabine per square meter s = (0.163*V)/(a*T);//The total surface area disp('m^2',s,'The total surface area is') // Wrong answer printed in textbook....
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function [y] = deflexionBarra(x) w0 = 2.5; E = 50000; I = 30000; L = 600; y = (w0/(120*E*I*L))*(-x.^5+2*L^2*x.^3-L^4*x); endfunction
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clc //Initialization of variables ax=1.5 //m/s^2 g=9.81 //m/s^2 //calculations alpha=atand(ax/g) //results printf("The interface is inclined at %.2f degrees with the horizontal",alpha)
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// chapter 6 // example 6.9 // fig. Ex.6.9 // Find average output current and power delivered // page-299-300 clear; clc; // given E=230; // in V (voltage supply) f=50; // supply frequency alpha=%pi/4; // in radian (firing angle) R=10; // in ohm (load resistance) L=10; // in mH Ec=120; // in V (capacitor voltage) // c...
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//Scilab Code for Example 1.4 of Signals and systems by //P.Ramakrishna Rao //Determine whether the given signal is periodic or not //x(t)=cos(7*t)+sin(4*t) clc; clear; syms t; x=sin(4*t)+cos(7*t); disp(x,'x(t)'); t=0:1/12:12 x=sin(4*t)+cos(7*t); t=0:1/12:12; plot(t,x); title('x(t)'); xlabel('Time in seco...
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function [output] = initCameraMatrix2D(list_size,in2,in1,width,cols,ratio) [output] = opencv_initCameraMatrix2D(list_size,in2,in1,width,cols,ratio) endfunction
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function [msg] = pblib_set(msg, field_name, value) //pblib_set // function [msg] = pblib_set(msg, field_name, value) // // Sets a value in the proto message msg and updates the has_field hash table. BEWARE: // This function potentially makes a full copy of your msg because it gets modified. I // have no idea ...
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//Example 2.4 v_0=0;//Initial velocity (km/h) v_f=30;//Final velocity (km/h) delta_t=20;//Time period (s) delta_v=v_f-v_0;//Change in velocity (km/h) delta_v=delta_v*10^3/3600;//Change in velocity (m/s) a=delta_v/delta_t;//Acceleration (m/s^2) printf('Average acceleration = %0.3f m/s^2',a) //Acceleration is pos...
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//Chapter 15, Problem 19 clc; I=100e-6; V=2e-3; //supply voltage f=200e3; //frequency L=50e-6; //inductance in henry R=V/I; //resistance in ohm C=1/((2*%pi*f)^2*L); ...
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clear; clc; close; V1 = 8; R1 = 2*10^3; I1 = 10*10^(-3); Il = V1/R1; Vo = -I1*R1; disp(Il,'Il(Amperes) = '); disp(Vo,'Vo(Volts) = ');
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//[stk,nwrk,txt]=%rc2for(nwrk) // genere le code relatif a la concatenation en ligne des matrices //! rhs=evstr(op(3)) nl='0';typ=0 for k=1:rhs sk=stk(top-rhs+k) typ=maxi(typ,evstr(sk(3))) nl=addf(nl,sk(4)) end nc=sk(5) typ=string(typ) [out,nwrk,txt]=outname(nwrk,typ,nl,nc) lout=length(out) nl1='0' for k=1:rhs ...
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clc; //Example 23.9 //page no 344 printf("Example 23.9 page no 344\n\n"); //the bottom of a ship,moving in water rho=1000//density of water v=12//velocity of boat,m/s L=20//length,m W=5//width ,m meu=1e-3//viscosity R_e=rho*v*L/meu//reynolds no printf("Reynolds no R_e=%f ",R_e); //from reynolds no flow is ...
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//ramanujan's method //example 2.23 //page 47 clc;clear;close; deff('y=f(x)','1-2*((3/2)*x+(1/4)*x^2-(1/48)*x^4+x^6/1440-x^8/80640)'); a1=3/2,a2=1/4,a3=0,a4=1/48,a5=0,a6=1/1440,a7=0,a8=-1/80640; b1=1; b2=a1; b3=a1*b2+a2*b1; b4=a1*b3+a2*b2+a3*b1; b5=a1*b4+a2*b3+a3*b2; b6=a1*b5+a2*b4+a3*b3; b7=a1*b6+a2*b5+a3*...
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//EXAMPLE 6.14 //Inverse Z-transform clear; clc; z = %z; num=z*(z+2); den=(z-0.2)*(z+0.6); H=num/den; elts=factors(den); disp(elts); //solving Partial Fractions, we get: Hz = 2.75/(1-(0.2)/z) - 1.75/(1+(0.6)/z); disp(Hz); //disp(h = 2.75*(0.2^n) - 1.75*(0.6^n)*u(n)); h1= ldiv(2.75*z,(z-(0.2)),10) disp(h1/2.75,'h1 = ');...
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function [diffusem]=diffusem(nsteps, nsubsteps, dt, dif,in, concs, sources, sinks,inconsts) //diffusion system initial values //d=in(1) //d passed as a vector 1 diffusion constant for each species n1=in(1); n2=in(2); n3=in(3); h=in(4); nspecies=in(5); t0=0; //concs, sources and sinks are list...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.304582D+00 ...