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L=[1:5] // values from 1 to 5 U=[1:2:10] // values from 1 to 10 (increment by 2) V=[5:-1:1] // negative step linspace(1,5,3) // 3 values equally spaced linspace(1,5,5) // 5 values equally spaced logspace(-2,6,5) // logarithmic spacing
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errcatch(-1,"stop");mode(2);disp('To find the eigenvalue of matrix A') disp('A=') a=[2 7;7 2] disp(a) disp('Eigen values of A are:') disp(spec(a)) exit();
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Voff=0.5; Vp2=0.9-0.24-Voff; printf('\n The value of Vp2 is %fV',Vp2); disp("d-d0=sqrt(Єs*Vp2/(q*Nd))"); c=12.2*8.854*10^-14; //say c=Єs q=1.6*10^-19; Nd=10^18; a=sqrt(c*Vp2/(q*Nd)); printf('\n The value of (d-d0) is %fA',a*10^8); Vg=0.7; d=153.9*10^-8; ns=c*(Vg-Voff)/(q*d); printf('\n The value of ns is %...
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errcatch(-1,"stop");mode(2);//// exec("2.2data.sci"); CA0=(yA0*P0)/(R*T0); FA0 = CA0*v0; V = FA0*X*(1/-rA) disp("FA0 =") disp(FA0) disp("mol/s") disp("V =") disp(V) disp ("dm^3") exit();
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//<f>=%ras(f,m) // %ras(f,m) calcule la somme d'une matrice de fractions rationnelles //et d'une matrice de scalaires ou la somme d'un systeme dynamique //decrit par sa matrice de transfert et d'un gain constant. //Cette macro correspond a l'operation f+m //! if sum(size(m))=-2 then m=m*eye(f(3)); end; f(2)=f(2)+m.*...
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//Example 2.2 //Program to calculate //(a) NA //(b) Solid Acceptance Angle //(c) Critical Angle at the core-cladding interface clear; clc ; close ; //Given data n1=1.46; //CORE REFRACTIVE INDEX delta=0.01; //RELATIVE REFRACTIVE INDEX DIFFERENCE //Numerical Aperture NA=n1*sq...
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clc clear all A=imread("H:\IVP\blobs.png"); A=double(A) a=find(A==255) A(a)=1; W=[1 1 1;1 1 1;1 1 1] a1=find(W==1) count=length(a1); [r c]=size(A); E=zeros(r,c); O=zeros(r,c); for i=2:r-1 for j=2:c-1 t=sum(A(i-1:i+1,j-1:j+1).*W) if(t==count) E(i,j)=1; else E(i,j)=0; ...
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function [x,y,typ]=ANDLOG_f(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[] select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1;...
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// chapter 7 , Example 7.10 , pg 214 T1=300 //temperature (in K) e=1.6*10^-19 //charge of electron (in C) k=1.38*10^-23 //Boltzmann constant (in J/K) T2=330 //temperature (in K) E1=0.3 // E1=(Ec-Ef_300) (in eV) E2=(E1*T2)/T1 //E2=(Ec-Ef_330) (in eV) printf("At 330 K the Fer...
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ӏэпапсӏэ ӏэпапсӏэм N;ERG;SG;DEF губчъо губчъохэмэ N;ERG;PL;DEF азэнаджапӏ азэнаджапӏэхыу N;LGSPEC1;PL аргъэй аргъэйэ N;NDEF;SG блэгъожъ блэгъожъэхыу N;LGSPEC1;PL хэтэрыкӏ хэтэрыкӏэхэмэ N;ERG;PL;DEF ӏашӏу_ӏушӏу ӏашӏу_ӏушӏум N;ERG;SG;DEF шъхьэӏух шъхьэӏухэхэ N;NDEF;PL кӏьэнлъэ кӏьэнлъэу N;LGSPEC1;SG мэхъагьэ мэхъагьэм AD...
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clear; clc; V_t=72; I_a=200; r_a=0.045; N=2500; k=(V_t-I_a*r_a)/N; E_a=k*1000; L=.007; Rm=.045; Rb=0.065; R=Rm+Rb; T_a=L/R; I_mx=230; I_mn=180; T_on=-T_a*log(-((V_t-E_a)/R-I_mx)/((I_mn)-(V_t-E_a)/R)); R=Rm; T_a=L/R; T_off=-T_a*log(-((-E_a)/R-I_mn)/((I_mx)-(-E_a)/R)); T=T_on+T_off; f=1/T; printf("...
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exec("statUSA.sce", -1) scf (1) ; clf ; subplot(2,2,1) plot (YGUV (: , 1 ) , YGUV (: , [2 3]) ) legend (["chômage (%)" , "croissance (%)"] , 3) subplot(2,2,2) plot (YGUV ( : , 2 ) , YGUV (:, 3 ) ) xtitle ("Évolution historique croissance / chômage", "Croissance", "Chômage") subplot(2,2,3) plot (YGUV ( : , 2 ) , YGU...
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T1=337.9 //K T2=473 //K Tc=513.2 //K
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//Ex19_18 Pg-965 clc hex='9AF' //hexadecimal input dec=hex2dec(hex) //decimal output bin=dec2bin(dec) //binary output disp("The binary equivalent of 9AF is") disp(bin)
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//Example 4.5// b=0.286;//nm // repeat distance between the adjacent atoms t=2;// degree //Given a=1;// rad c=57.3;//degree D=b/(t*(a/c)) mprintf("D = %f nm",D)
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tab= read("fer",100,101) for i=1:50 clf a=string(double(i*16/100)) plot2d(tab(i,:),rect=[0,285,101,296],style=2) xtitle("Température à "+a+" sec, barre de fer","x","T(K)") sleep(100) end plot2d(tab(50,:),rect=[0,285,101,296],style=2) xtitle("Température à "+string(a)+" sec, barre de fer ","x","T(K)"...
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//Discrete Time Fourier Transform of //x[n]= 1 , abs(n)&lt;=M1 clear; clc; close; // DTS Signal M1 = 2; n = -M1:M1; x = ones(1,length(n)); Wmax = 2*%pi; K = 4; k = 0:(K/1000):K; W = k*Wmax/K; XW = x* exp(-sqrt(-1)*n'*W); XW_Mag = real(XW); W = [-mtlb_fliplr(W), W(2:1001)]; // Omega from -Wmax to Wmax XW_Mag = [m...
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function [L,fe]= play2(d) // N -> liste notes, R-> liste temps notes N=['do','do','do','re','mi','re','do','mi','re','re','do']; N=['do','do','si','si','do','do','la','mi','mi','sol#','sol#','la']; //N=['do','re','mi','fa','sol','la','si']; //N=['do','do','do','do','do','do','re']; N1=[1:12]; n=...
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Signals_Ex_1_11_Pg_39.sce
clear ; clc ; close ; //Chapter1 //Example1.11(1), page no 39 //Given T = 10; //time Tau Tg = -T/2 :0.1: T/2; // time period for given Gate Function -tau/2 to tau/2 G_t0 = 1; //Magnitude of Gate Function (A) G_t = G_t0* ones (1, length (Tg));// Gate function G(t) f = -%pi: %pi / length (Tg): %pi ; Dw = 0.1; ...
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//Chapter 18, Problem 1 clc; v=120; //dc supply c=15e-6; //capacitance in farad r=47e3; //resistance in ohms taw=r*c; //time constant t1=taw; vcta= v*(1-%e^(-1*t1/taw)); vct = v/2; t = 0:0.1:10 vc = v*(1-%e^(-1*t/taw)); plot(t,vc) xtitle("capaci...
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function [] = kiks_settimescale(tscale) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- glo...
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2_19.sce
clear clc dia=2.5e-2 d=3 r=dia/2 r1=.7788*r c=exp(%i *2*%pi/3) b=exp(%i *-2*%pi/3) k=2 Dab=d Dac=2*d Dbc=d Dca=2*d La=round(k*(log(1/r1) + log(1/Dab)*b + log(1/Dac)*c)*1e3)/1e4 Lb=round(k*(log(1/Dab) + log(1/r1)*b + log(1/Dbc)*c)/b*1e3)/(1e4) Lc=round(k*(log(1/Dac) + log(1/Dbc)*b + log(1/r1)*c)...
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example39.sce
clear clc function [x]=C(a,b) x=factorial(a)/(factorial(b)*factorial(a-b)) endfunction disp('probability of 8 heads and 4 tails in 12 trials=p(8)=C(12,8)*(1/2)^8*(1/2)^4=') C(12,8)*(1/2)^8*(1/2)^4 disp('the expected no. of such cases in 256 sets =256*p(8) =') 256*(495/4096)
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//Section-2,Example-1,Page no.-CS.52 //To find the throwing power of the plating bath solution in a Haring-Blum cell. clc; x_1=6.6 x_2=4 w_1=52 w_2=55 A=x_1/x_2 B=w_2/w_1 P_th=((100*(A-B))/(A+B-2)) disp (P_th,'Percentage throwing power')
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givens.man.tst
clear;lines(0); A=[3,4;5,6]; U=givens(A(:,1)); U*A
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Ex5_1.sce
clear // // // //Variable declaration E_EF=0.5 //fermi energy(eV) FE=1/100 //probability Kb=1.381*10**-23 //boltzmann constant(J/k) x=6.24*10**18 //Calculation KB=Kb*x y=E_EF/KB T=y/log(1/FE) //temperature(K) //Result
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clc; close(); clear(); //page no 476 //prob no. 14.5 L=320*10^-9; //H/m C=90*10^-12; //F/m v=1/sqrt(L*C); mprintf('The velocity of propagation is, v = %.3f 10^8 m/s \n',v*10^-8);
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testIK.sce
IK_target_RLeg_real = [0.069828271865844727, 0.23262149095535278, 0.35102164745330811]; //the foothold for the ith leg, in the leg attachment frame //disp(IK_target_RLeg); //HR Leg l1 = 0.1; l2 = 0.15; l3 = 0.3; xOff = [1 0 0]*0.15/2; yOff = [0 1 0]*0.3/2; offset_i = - xOff - yOff; orient = [-0.7022104 -0.4188790 ...
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//time required for wave to travell //given clc L=1.2d-6//H/m C=12.5d-12//F/m leng_line=2//length of the line in meter t=sqrt(L*C)*leng_line//time required for the wave to travell in seconds t=round(t*1d+12)/1d+12///rounding off decimals disp(t*1d+9,'the time required for wave to travell in nanoseconds')//nsec ...
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7_3.sce
clc,clear printf('Example 7.3\n\n') V_L=6600 P_out=500*10^3 eta=83/100 //efficiency R_a=0.3,X_s=3.2 //armature resistance and synchronous reactance Z_s=complex(R_a,X_s) //synchronous impedance theta=(%pi/180)*phasemag(Z_s) //phasemag returns the angle in degrees not radians phi=acos(0.8) //leading V_ph=V_L...
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//Example 7.35 In calculating a certain cost of living index number the following weights were used clc; clear; I=[32 54 47 78 58]; W=[15 3 4 2 1]; Avg=sum(I.*W)/sum(W); disp(100+Avg,"Cost of living index",Avg,"Average percentage increase for all groups taken together",I,"Average % Increase in Price");
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clc pathname=get_absolute_file_path('5_4_2.sce') filename=pathname+filesep()+'542.sci' exec(filename) printf("All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") Tr=T/Tc Pr=P/Pc Vrideal=V*Pc/(n*R*Tc) printf(" \n Tr= %f",Tr) printf(" \n Pr= %f",Pr) prin...
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dif3.sce
//Programa: dif3.m //Modelo de Difusão //Fronteiras Constantes + Pulso Quadrado clear; N = 30; //Número de Nós L = 1; //Comprimento [m] D = 1; //input('D = '); //Coeficiente de Difusão xmin = 0; xmax = L; //[m] dx = (xmax - xmin)/(N-1); //Passo [m] xp = linspace(xmin,xmax,N); //[m] up = 0*xp; //posterior: u(k+1) u...
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//pagenumber 115 example 21 clear resacu=1*10^-6;//ampere voltaf=150*10^-3;//volt w=8.62*10^-5; voltag=0.026;//volt u=300;//kelvin uw=u*w; resist=(uw)/((resacu)*exp(voltaf/voltag)); disp("resistance at 150mvolt = "+string((resist))+"ohm");//correction in the book
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// polar plot of a linear system // repf = spolarplot(G,omega) // G: linear sytem and omega:is frequency in rad/s // repf: is the complex frequency response function repf = spolarplot(G,omega) f = omega /2/%pi; repf = repfreq(G,f); r = abs(repf); theta = atan(imag(repf),real(repf)); polarplot(theta,r,style ...
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clc clear printf("Example 12.2 | Page number 416 \n\n"); //Find the stoichiometric air for combustion of (a)Carbon (b)Hydrogen (c)Sulphur //Given data //Molar masses of O2,H2,N2,C and S respectively MO2 = 32 //g/mol MH2 = 2 //g/mol MN2 = 28 //g/mol MC = 12 //g/mol MS = 32 //g/mol //Part(a) printf("Part(a)\n...
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function [output] = lab2uint8(pstData) a = opencv_lab2uint8(pstData); d = size(a); for i=1:d output(:,:,i) = a(i); end endfunction
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//Problem 20.24: An a.c. source of 24 V and internal resistance 15 kohm is matched to a load by a 25:1 ideal transformer. Determine (a) the value of the load resistance and (b) the power dissipated in the load. //initializing the variables: tr = 25; // teurn ratio V = 24; // in Volts R1 = 15000; // in Ohms Rin ...
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//example 3.7 // this program needs kmap.sci and noof.sci clc; disp('The kanaurgh map for given truth table will be :'); disp(' C''D'' C''D CD CD'''); //displaying the given kmap disp('A''B'' 1 0 0 0'); disp('A''B 0 0 0 0'); disp('AB x x x x'); disp('AB'' 0 0 ...
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//example 7.3 clc; funcprot(0); // Initialization of Variable Id=500;//load current i=134;//mA D=.42;//duty cycle //calculation Ip=Id+i/2; Im=Id-i/2; I1=((D/3)*(Ip^2+Im*Ip+Im^2))^.5; disp(I1,"rms current in mA:") printf('by trapezium method') I2=D^.5*Id; disp(I2,"rms current in mA:") printf('by rectangle...
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@relation monk-2 @attribute A1 integer[1,3] @attribute A2 integer[1,3] @attribute A3 integer[1,2] @attribute A4 integer[1,3] @attribute A5 integer[1,4] @attribute A6 integer[1,2] @attribute Class{0,1} @inputs A1,A2,A3,A4,A5,A6 @outputs Class @data 1 1 1 1 1 1 1 1 1 1 0 ? 1 ? 1 1 1 1 0 1 0 ? 0 0 0 1 0 ? 0 ? 0 ? 1 ? 1 1...
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ScreenName String 'Fleet File Dialog Screen' ImplName String 'Dialog Screen' ElementChunkArray Int 10 ScreenElementType Int 0 ImplName String 'Front End Dialog Screen Backdrop' TabIndex Int 8 Selectable Bool False Enabled Bool True ReferenceArea Rect( 69, 169, 603, 420 ) # left,top,right,bottom ScreenElementType Int 1...
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//Chapter-11, Example 11.1, Page 480 //============================================================================= clc clear //INPUT DATA Tsat=100;//Saturation temperature of water in degree C p1=957.9;//Density of liquid in kg/m^3 Cpl=4217;//Specific heat in J/kg.K u=(279*10^-6);//Dynamic viscosity in N.s/...
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// // 09.02.27 // 10.04.25 function Out=Setwindow(varargin) global XMIN XMAX YMIN YMAX Nargs=length(varargin); if Nargs==0 Out=[XMIN,XMAX,YMIN,YMAX]; disp(Out); return; end; if Nargs==1 Dt=varargin(1); if type(Dt)==1 Dt=list(Dt); end; Xm=%inf; XM=-%inf; Ym=%inf; YM=-%in...
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clear; clc; printf("\t\t\tProblem Number 6.13\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.13 (page no. 255) // Solution //From equation,cv=R/(k-1) , R=8.314/32; //constant of proportionality //kJ/kg*K //The molecular weight of oxygen is 32 k=1.4 //for oxygen //given //k=cp/cv cv=R/(k-1); //Specific he...
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//Example 1_7 page no:25 clc; I5=4; I6=1; V=30; R6=6; V6=24; V10=50; I10=I5+I6; Vc=-V6; V1=V10-Vc; disp(I10,"the current through 10 ohm resistance is (in A)"); Vs=I10-V+Vc;//calculating the source voltage disp(Vs,"the source voltage Vs is (in V)");
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// To Determine the subtransient current in the alternator , motor and the fault clear clc; Ib=50*1000/(sqrt(3)*13.2);// base current (amps.) Vf=12.5/13.5;// the Prefault Voltage (p.u) Xf=(%i*.3)*(%i*.2)/(%i*.5);// Fault impedence(p.u) If=.9469/(Xf);//Fault current (p.u) Ifl=30*1000/((sqrt(3)*12.5*.8));//full lo...
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Nij = [68 56 32; 52 72 20]; n= sum(Nij); Ni = zeros(2,1); Mj = zeros(3,1); for i= 1:2 for j= 1:3 Ni(i) = Ni(i) + Nij(i,j); end end for j= 1:3 for i= 1:2 Mj(j) = Mj(j) + Nij(i,j); end end NM = ones(2,3); for i=1:2 for j=1:3 NM(i,j)= Ni(i)*Mj(j); end end ...
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.5 // Page 121 printf("Example 4.5, Page 121 \n \n"); // solution m=100 //[kmol] (basis) dry mixed gas // x = kmol of water gas // y =kmol of producer gas // overall material balance : // x+y =...
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clc; //ex3.6 Vave=26.8; //Volt RL=20000; //Ohm Iave=Vave/RL; //Ampere//from v=r*i disp('mA',Iave*1000,"Iave=");
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function rect=pol2rect(rho,theta) rect=rho.*cos(theta)+(%i)*rho.*sin(theta); endfunction
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function [s]= instru_vent(fp,fm,Fe,d,m0) // f0 -> hauteur, d-> durée, m0-> amplitude Te=1/Fe; // temps echantillonage pi=3.14159; x=[0:Te:d]; //axe temps a=0.03; //excursion du vibrato fv=2; // fréquence du vibrato m=[0:Te:d]; // amplitude constante au cours du temps n=length(m)...
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// Exa 3.2 format('v',5) clc; clear; close; // given data Vin= 5;// in V V_LED= 2;// in V Rs= 470;// in Ω Vs= Vin-V_LED;// in V // When supply voltage is 5 V, the LED current I= Vs/Rs;// in A I= I*10^3;// in mA disp(I,"When supply voltage is 5 V, the LED current in mA is : ") Vin= 10;// in V Vs= Vin-V_LE...
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clc clear //Input data N=6000;//Number of particles in a system e=3;//The number of energy states with equal spacing n1=3000;//Number of particles in the lower level n2=2500;//Number of particles in the middle level n3=500;//Number of particles in the upper level n11=3001;//Number of particles in the lowe...
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function OneDIndx = Convert2DIndexTo1D(rowNum, colNum, numberOfCols) OneDIndx = rowNum * numberOfCols + colNum; endfunction
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//Exa 1.31 clc; clear; close; f1=factorial(4) // factorial of 4 f2=factorial(6) // factorial of 6 disp(f1,"factorial of 4 is:") disp(f2,"factorial of 6 is:")
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//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 21 clc; //Declaration of Variables Kc = 0.5 // mole square litre square T = 400 // K R = 0.082 // litre atm per degree per mole // Solution Kp = Kc * (R * T) ** (-2) mprintf("The given equilibrium is\n") mprintf(" N2...
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function[avt1_nt1, avt1_nt2, op_nt1, op_nt2, ge_nt1_indexu, ge_nt2_indexu, ge_nt1_indexu_low, ge_nt2_indexu_low] = nodal_test2(Qnt1, Q2nt1, jac_row, runsize, zr_nt_nodal, varargin) [lhs, rhs] = argn(0); if rhs > 5 then is_multiple = varargin(1); else is_multiple = 0; end //Nodal test...
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// f = ab ^ x // ln(f) = ln(a) + xln(b) // ln(f) = a0 + x * a1 // a = e^a0 // b = e^a1 function xr = mmqPolinomial(x, y, grau) for i = 1 : (grau + 1) for j = 1 : (grau + 1) A(i, j) = sum( x .^ (j + i - 2)) end end for i = 1 : (grau + 1) b(i) = sum(y .* (x .^ (i - 1))) end xr = A\...
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-- VectorCAST 6.4c (02/03/16) -- Test Case Script -- -- Environment : LIBC -- Unit(s) Under Test: abort1 abs atof atoi atol bLib memchr memcmp memcpy memmove memset ns16550 qsort rand random random_r strcat strchr strcmp strcpy strlcat strlcpy strlen strncat strncmp strncpy strpbrk strspn strtod strtok strtok_r str...
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function ply2vtk() // Convert a PLY file to VTK format. // // Syntax // PointCloud(plyFileName,vtkFileName,"ply2vtk") // // Parameters // plyFileName : input file of ply format // vtkFileName : output file of vtk format // // Description // Input file is an PLY format which is them transformed to VTK format ...
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<f:for each="{extension.plugins}" as="plugin"> plugin.{extension.shortExtensionKey}_{plugin.key} { view { # cat=plugin.{extension.shortExtensionKey}_{plugin.key}/file; type=string; label=Path to template root (FE) templateRootPath = EXT:{extension.extensionKey}/Resources/Private/Templates/ #...
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s=%s; s=poly(0,'s'); t=[0:0.05:10]; syms Kv; g=(Kv/(s*(0.5*s+1))); // given Kv=20 Kv=20; g=(20/(s*(0.5*s+1))); G=syslin('c',g) fmin=0.01; fmax=100; subplot(2,2,1) bode(G) subplot(2,2,2), plot2d(t,csim('step',t,G)) //bode(G,fmin,fmax) //show_margins(G) xtitle("uncompensated system") [gm,freqGM]=g_...
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//Chapter 1,Example1.24,Pg1.27 clc; disp("Refer to the figure shown in the problem") I1=5/2 //The 3ohms resistance gets shorted hence current flows only through the 2 ohms resistor I2=2 printf("\n I1=%.1f A \n",I1) printf("\n I2=%.0f A \n",I2) Vab=2*I1-8+5*I2 printf("\n Vab=%.0f V \n",Vab)
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// This code calculated the reduced BZ, i.e. c3 goes to infinite. clear; clc; exec(PiLib); //Parameters ================================== a_vec=[.. 5.992718 0.000000 0.000000 2.996359 5.189846 0.000000 2.996359 1.729949 4.893033]; // original lattice vectors c_conv=[1 0 0; 0 1 0; 0 0 1]; // co...
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// Example 4_8 clc;funcprot(0); // Given data phi_e=120;// V R=144;// ohm t=1.50;// h // Solution // (a) i_e=phi_e/R;// A W_12=-phi_e*i_e*t;// The electrical current work in W.h // (b) W_ec=-phi_e*i_e;// W printf('\n(a)The electrical current work,W_12=%3.0f W.h \n(b)The electrical power consumption,W_elec...
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// Ex3_7 clc; // Given: B=11.009305; C1=12; C2=11.001433; p=1.0078; n=1.0087; Al=26.981535; Si1=27.976927; Si2=26.986705; // Solution: m1=(B+p-C1);//(a) E1=m1*931;// of last proton in C in MeV printf("\n The binding energy for the last proton in 12C is = %f MeV",E1) m2=(C2+n-C1);//(b) E2=m2*931;...
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// Exa 6.11 clc; clear; close; // Given data V_DD= 20;// in V R1= 2.1*10^6;// in Ω R2= 270*10^3;// in Ω R_D= 4.7;// in kΩ R_S= 1.5;// in kΩ I_DSS= 8;// in mA V_P= -4;// in V V_G= V_DD*R2/(R1+R2);// in V // V_GS= V_G-R_S*I_D (as Vs= I_D*R_S) and // I_D= I_DSS*(1-V_GS/V_P)^2;// in A // I_D= I_DSS*(1-(V...
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clc; s = poly(0,'s');//defines a polynomial po = syslin('c',10/(s^5+2*s^4+3*s^3+6*s^2+5*s+3));//defines a transfer function m = denom(po);//extraction of the denominator polynomial of the transfer function co = coeff(m);//extraction of the coefficients of the denominator polynomial n = length(co); syms eps ; f...
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clc;clear; //Example 7.21 //given data T=100+273;//in K Q=-600; Tb=25+273;//in K //calculation dSsys=Q/T; disp(dSsys,'entropy change of water in kJ/K'); // Sin - sout + Sgen = dSsystem Sgen= -Q/Tb + dSsys; disp(Sgen,'total entropy generation in kJ/K')
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//Example 3.30.A clc; syms s t; x=laplace(3*t); y=laplace(1); z=x*y; f=ilaplace(z); disp(f);
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// Capt ion : Hamming Encoding //H( 7 , 4 ) //Code Word Length = 7 , Mes sage Word l e n g t h = 4 , //Pa r i t y b i t s =3 // c l e a r ; close ; clc ; // Ge t t ing Mes sage Word m3 = input ( ' Ent e r the 1 b i t (MSb) o f me s sage word ' ); m2 = input ( ' Ent e r the 2 b i t o f me s sage word ' ); ...
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## Test dissection of multiproject repo branchify project1/trunk project1/branches/* project1/tags * branchmap :project1/trunk:heads/master: :project1/tags:tags: :project1/branches:branches: set testmode read <multigen.svn branch project2 delete prefer git write -
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s = 100 rand("seed") n=10; U=rand(n,n);//Ici on génère une matrice carée avec des nombre aléatoires UL=tril(U);//On prend la partie triangulaire inferieur de la matrice A //On aura une matrice triangulaire inferieur UU=triu(U);//On va prend la partie triangulaire superieur de la matrice A //O...
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clc SB=10000000 //rating of transformer VL1B=230000 //voltage rating IL1B=SB/(sqrt(3)*VL1B) mprintf("ILIB=%fA\n",IL1B) VL2B=4160 IL2B=SB/(sqrt(3)*VL2B) mprintf("IL2B=%fA\n",IL2B) //star delta connected mprintf("Rated kVA=SB/1000=%fkVA\n",SB/1000) mprintf("Rated 11=I1B=ILIB=%fA\n",IL1B) mprintf("Rated I2=I2B=...
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; @Harness: simplifier ; @Purpose: "Test variants of all instructions" ; @Result: PASS adc r0, r0 add r0, r0 adiw r24, 0 and r0, r0 andi r16, 0 asr r0 bclr 0 bld r0, 0 brbc 0, 0 brbs 0, 0 brcc 0 ...
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clear; clc; close; disp("given system is y[n]-a*y[n-1]=x[n]"); disp("taking fourier transform H(w)=Y(w)/X(w)=1/(1-a*e^-j*w)"); //impulse response n=-10:10; w=-3:0.01:3; a=.5; Hw=ones(1,length(w))./(1-a*%e^(-%i*w)); h=(1/2*%pi)*Hw*exp(%i*w'*n); disp("impulse response is a^n*u[n]") plot2d3(n,h); plot(n,h,'...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.17(PAGENO 221)"); //given V_m = 5//modulating voltage f_m = 20*10^3//modulating frequency V_c = 10//carrier voltage f_c = 100*10^6//carrier frequency delta_f = 2*10^3//frequeny deviati...
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clc; clear; Na=10^15 //doping densities in cm^-3 Nd=10^17 //in cm^-3 V=0.5 //in V e=1.6*10^-19 //in J nn0=10^17 //in cm^-3 ni=1.5*10^10 //in cm^-3 Si_bandgap=1.1 //bandgap of silicon in eV Const=0.0259 //constant value for kT/e in J //Calculation //a) pn0=ni^2/nn0 //in cm^-3 pn=pn0*exp((V)/Const) //b...
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clear;lines(0); global a b c a=1;b=2;c=3; who('global') clearglobal b who('global')
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// chapter 2 // example 2.11 // Fig. E2.11 // Calculate shortest fault clearance time // page-54-55 clear; clc; // given Vm=120; // in V (sinosoidal ac supply) integration=15; // in a^2.s (integral of square of current) // calculate t=integration/Vm^2; // calculation of fault clearance time t=t*1E3; // changing unit fr...
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clear //Given l = 400 //mm - Length b = 300 //mm - breath F = 20 //KN _ the force applied on the beam F_d = 0.75 //KN-m - The force distribution d = 2 //mt - the point of interest from the free end //calculations //From moment diagram M = F*d - F_d*d*1 I = b*(l**3)/12 //mm4 - Bending moment diagram...
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//Example6.22 // To determine the output voltage clc; clear; close; Vin = 2 ; R2 = 20*10^3 ; R1 = 2*10^3 ; // the output voltage of follower Vo1 is Vo1 = Vin ; disp('the output voltage of follower Vo1 is = '+string(Vo1)+ ' V'); // the output voltage of an inverting amplifier Vo = -(R2/R1)*Vo1 ; disp('Th...
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ScreenName String 'Loading Ship Model Dialog Screen' ImplName String 'Dialog Screen' ElementChunkArray Int 3 ScreenElementType Int 0 ImplName String 'Loading Dialog Backdrop' TabIndex Int 4 Selectable Bool False Enabled Bool True ReferenceArea Rect( 262, 222, 647, 372 ) # left,top,right,bottom ScreenElementType Int 2 ...
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//Example 12.2 //Find the probability of the problem. disp('The sample space in this case is:-'); disp('(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)'); disp('(2,1) (2,2) (3,3) (4,4) (5,5) (6,6)'); disp('(3,1) (2,2) (3,3) (4,4) (5,5) (6,6)'); disp('(4,1) (2,2) (3,3) (4,4) (5,5) (6,6)'); disp('(5,1) (2,2) (3,3) (4,4) (5,5)...
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// Scilab Code Ex2.32:: Page-2.22 (2009) clc; clear; b = 1; // For simplicity assume fringe width to be unity, cm S = 3*b; // Fringe shift, cm lambda = 5890e-008; // Wavelength of light used, cm mu = 1.6; // Refractive index of the mica sheet // As S = b/lambda*(mu-1)*t, solving for t t = S*lambda/(...
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// Chapter 13_Optical Devices //Caption_Quantum efficiency //Ex_9//page 628 n2=3.666 //index of refraction in GaAs n1=1 //index of refraction in air T=((n2-n1)/(n2+n1))^2 //reflection coeffucient printf('The reflection coefficient at semiconductor- air interface ius %1.2f',T)
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#header default_background_color = 255, 255, 255; default_text_color = 0, 0, 0; #nužno za TMS response_logging = log_active; write_codes=true; pulse_width=1; #nuzno za press for pause active_buttons=2; response_matching=simple_matching; begin; #SDL kod picture{ text{ caption="+"; font_size=48; }; x=0; y=0; ...
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 2 // Heat Conduction in Solids // Example 2.8 // Page 47 printf("Example 2.8, Page 47 \n\n") // The bar will have two dimensional variation in temperature // the differential equation is subject to boundary conditions x1 = 0; // [cm] ...
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//Page Number: 372 //Example 7.4 clc; //Given Gr=3D-4; //mho Ge=3D-5; //mho Ploss=200D+3; //W V0=22D+3; //V I0=28; //A //(i) Circuit effciency n=1/(1+(Gr/Ge)); disp('%',n*100,'Circuit effciency:'); //(ii) Electronic effciency ne=1-(Ploss/(V0*I0)); disp('%',ne*100,'Electronic effciency:');
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// Example 7.5 clc; clear; close; // Given data format('v',5); alpha= 1.414;// passband C= 0.01*10^-6;// in F (assume) fc= 1*10^3;// in Hz dc_gain= 6; R= 1/(2*%pi*C*fc);// in Ω R= R*10^-3;// in kΩ disp("The value of R is : "+string(R)+" kΩ (standard value 15 kΩ)"); R= 15;// in kΩ Af= 3-alpha;// and Af= 1+...
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//Exa 1.3 clc; clear; close; //Given data : format('v',5); n1=1.52;//refractive index //Formula : sin(theta_c)=n2/n1; theta_c=73.2;//in Degree n2=n1*sind(theta_c); disp(n2,"Refractive Index of another medium : ");
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// Scilab code Exa11 : : Page 180 (2011) E = 4e+06; // Energy lost in the scintillator, eV N_pe = E/10^2*0.5*0.1; // Number of photoelectrons emitted G = 10^6; // Gain e = 1.6e-019; // Charge of the electron, C Q = N_pe*G*e; // Charge collected a...
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// **** Purpose **** // calculate the two-particle CG coefficients of LS and JJ coupling // **** Variables **** // [L1,S1,ML1,MS1,L2,S2,ML2,MS2,J1,J2,J,MJ]: integer or half-integer // <= the quantum numbers // [coup]: char, 'ls', 'jj' // <= specify the type of coupling // [CG]: 1x1, real or complex // => cg coefficient...
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(unwatch all) (clear) (dribble-on "textpro.out") (batch "textpro.bat") (dribble-off) (clear) (open "textpro.rsl" textpro "w") (load "compline.clp") (printout textpro "textpro.bat differences are as follows:" crlf) (compare-files textpro.exp textpro.out textpro) (close textpro)