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// Exa 1.3 clc; clear; close; // Given data G=-10; Ri= 100;// in kohm R1= Ri;// in kohm R1=R1*10^3;// in ohm // Formula G=-R2/R1 R2= R1*abs(G);// ohm disp(R1*10^-3,"Value of R1 in kohm is : ") disp(R2*10^-6,"and value of R2 in Mohm is : ")
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//Example 8// Ch 12 clc; clear; close; // given data a=2; b=5.3; alpha=(b/a)^0.33; r1=1.385;//radii of intersheaths in cm r2=1.92;//radii of intersheaths in cm r=1;//conductor radius in cm ri=2.65;//sheath of inside radius in cm V=66;//voltage in kv Vpeak=66*sqrt(2)/sqrt(3);//peak voltage V2=Vpeak/(1+1/a...
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s=poly(0,'s'); F=syslin('c',[1/((1+s)*s*(0.1*s+1))]) //without k fmin=0.1; //Min freq in Hz fmax=20; //Max freq in Hz scf(1);clf; bode(F,fmin,fmax); //Plots frequency response of ope...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 21") disp("Hydraulic efficiency, etah, is given by") disp("etah = Power given to runner/Water Power available") disp(" = m ...
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clc //initialization of varaibles HV=4344 //B/lb xC=56 //lb R=1.986 T=530 //R MC=56 //g/mol //calculations HR=xC*HV Eb=-HR -R*T*(2-3) HV=-Eb/MC //results printf("COnstant volume heating value = %d B/lb ",HV)
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clc; a=1; c={6.31-2-(2*1.95)}/2 d=0.03+(0.79*30) tds=a+c+d; C=a/tds*100 O=c/tds*100 N=d/tds*100 disp(N,O,C,"analysis by volume is:");
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*Testcase ilc sysclear archmode z r 60=00020000000000000000000000000000 r 70=0002000000000000000000000000DEAD r 1A0=00000001800000000000000000000200 r 1D0=00000001800000000000000000000220 r 200=41F00C0041200021EB110240002FEB9B r 210=0248002FAD440000A72C0002B2B20060 r 220=D213F000008C41F0F020D5010...
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//Example 5.2 //Program to Determine Dynamic Input Resistance of the Transistor at //the point: Ie=0.5 mA and Vcb= -10 V. clear; clc ; close ; //From the Input Characteristics dIe=(0.7-0.3)*10^(-3); //A dVeb=(0.7-0.62); //V //Calculation ri=dVeb/dIe; //Dynamic Input Resistance at Vcb= -10 V //Displaying The...
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//************************** VDD IN Analog ***************************** if(blk_name.entries(bl)=='vdd_i') then chgnet_dict=[chgnet_dict;'net'+ string(blk(blk_objs(bl),2+numofip))+"_..",'vcc '] chgnet_tf=%t; end
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function [rep]=xdialog(labels,vali) // if typeof(labels)<>'character'; write(%io(2),'First arg must be a string vector'); return;end if typeof(vali)<>'character'; write(%io(2),'Second arg. must be a string vector');return;end [m,n]=size(labels); [m1,n1]=size(vali); if n<>1, write(%io(2),'First arg. must be a column ve...
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//Section-1,Example-2,Page no.-AC.437 clc; E_m=3.4 V_m=0.7 E_f=69 V_f=0.3 A_c=250*10^-6 E_c=((E_m*V_m)+(E_f*V_f)) disp (E_c,'longitudinal modulus of elasticity(GPa)') Q_c=60*10^6 A_c=250*10^-6 P_c=Q_c*A_c //P_c=P_f+P_m disp(P_c,'Load carried by composite phases(P_c)') P=((E_f*V_f)/(E_m*V_m)) /...
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// Resuelve el sistema lineal Ax=b con el método de gauss_seidel // comenzando desde x con una tolerancia de eps // con un máximo de iteraciones maxIter // Además muestra la cantidad de iteraciones realizadas si se llegó a la condición de parada function x = gauss_seidel(A, b, x, eps, maxIter) n = size(A, 1) xN...
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clear// //Variables R = 1000.0 //Resistance (in ohm) sig = 5.8 * 10**7 //Conductivity in (Siemen per meter) d = 10**-3 //diameter (in meter) E = 10 * 10**-3 //Eletric field (in Volt per meter) //Calculation l = R *sig...
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//Ex 2.3 page 68 clc; clear; close; m=16;// V/A (gradient) t_on=4;// us IG=500;// mA VS=15;// V VG=m*IG/1000;// V //Load line equation //VG=VS-IG*RS RS=(VS-VG)/(IG/1000) ;// ohm Pg=VS*(IG/1000)**2 ; // W printf('Gate power dissipation = %.f W',Pg) printf('\n Resistance to be connected = %.f ohm',RS)
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// Example 6.22.3 page 6.73 clc; clear; beta0=1.85d7; T=293; //temperature k=1.38d-23; //Boltzman constant Ea=0.9*1.6d-19; theta=0.65; //thershold betar=beta0*%e^(-Ea/(k*T)); t=-log(theta)/betar; printf("\nDegradation rate is %.2e per hour.\nOperating lifetime is %.1e hour.",betar,t); //answe...
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// Ex8_6 clc; // Given: ma1=3321;// counts in 3 min mb1=2862;// counts in 2 min mab1=4798;// counts in 2 min m=1080;// counts in 30 min muk1=5126;// counts in 2 min // Solution: ma=ma1/3; mb=mb1/2; mab=mab1/2; mbc=m/30; muk=muk1/2; t1=(ma+mb-mab-mbc)/(mab^2-ma^2-mb^2);// in min t2=t1*60;// in seconds ...
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clc,clear //example 1.7 //To find values of all trigonometric functions for 60 degree //take an equilateral triangle of side 2 and divide it by half //all 3 angles of equilateral triangle are same as 60 degree //the bisector of angle is also the perepndicual bisector of oppsoite side // Thus, A=60 B=30 C=90 in ...
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// Scilab code Ex6.8: Pg 211 (2005) clc; clear; c = 1; // Assume speed of light to be unity, m/s L = 0.200; // Width of the potential well, nm h_cross = 197.3; // Reduced Planck's constant, eV.nm/c^2 m = 511e+03; // Mass of an electron, eV/c^2 U = 100; // Height of potential well, eV delta...
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Ex15_5.sce
clc epsilonox=3.9 epsilonnitride=7 dnitride=1.5*(epsilonnitride/epsilonox) disp(dnitride,"dnitride in nm is= ")
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# flat Dutch.X11 - 4*m + 2*m^2 + 42 # flat Dutch.X11 16*m - m^2 + 21 # flat Dutch.X11 16*m + m^2 - 21 # flat Dutch.X11 4*m + 2*m^2 + 42 # merg Dutch.X11 - 4*x_y_z + 2*x_y_z^2 + 42 # merg Dutch.X11 16*x_y_z - x_y_z^2 + 21 # merg Dutch.X11 16*x_y_z + x_y_z^2 - 21 # merg Dutch.X11 4*x_y_z + 2*x_y_z^2 + 42 # orig...
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6_3.sci
// calculating the maximum output voltage clc; Sa=10; disp(Sa, 'saturation voltage=') Vom=Sa; disp(Vom,'maximum output voltage')
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pathname=get_absolute_file_path('26_3.sce') filename=pathname+filesep()+'26_3data.sci' exec(filename) clear Tr=T*L1/2; mu=(8*G*t/(A*E*(b+a)))^0.5; L=L1/2; k1=((T*(b-a)*10^3)/(8*a*b*G*t)); k2=1/(mu*cosh(mu*L)); k3=((4*(b-a))/(a*b*(b+a))); k4=(2*T*(10^3)/(a*b*G*t*(b+a))); function[th]=f(z) w=(k1*((k2*sinh...
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8_2.sce
//Example 8.2 //Page no. 309 //Given Cp=50 //tpd, plant capacity T1=135 //C, Temp. T2=40 //C temp. T3=30 //C temp. dt1=(T1-T2) //C hot end temp. dt2=(T2-T3) //C cold end temp. //Properties of ethylbenzene rho1=840 //kg/m^3, density cp1=2.093 //kj/kg K , ...
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Ex8_12.sce
clc clear D=0.2; L=0.3; Vs=(22/7)*(1/4)*D*D*L; Vc=0.04*Vs; V3=Vc; P2=9; P1=1; n=1.3; V4=V3*[(P2/P1)^(1/n)]; V1=Vs+Vc; W=[n/(n-1)]*[P1*100]*[V1-V4]*[((P2/P1)^((n-1)/n))-1]; R=0.287; T1=15+273; Md=[P1*(V1-V4)*100]/[R*T1]; Wpkg=W/Md; printf('Word done per kg: %3.2f kJ/kg of air',Wpkg); printf('\n'); ...
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clc;funcprot(0);//EXAMPLE 7.1 // Initialisation of Variables D=20.3;................//Diameter in cm L=30.5;.................//Length in cm N=300;................//Engine rpm eta=78;.................//Efficiency in percentage afr=4/1;.................//Air Fuel Ratio //Calculations StV = ((%pi)/4)*((D/100)^2)...
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//Example 7_4_u2 clc(); clear; //To find the charge in the minority carrier concentration ni=9.65*10^9 //units in cm^-3 nno=10^14 //units in cm^-3 //Before illumination pno=ni^2/nno //units in cm^-3 //After illumination tp=2 //units in us tp=tp*10^-6 //units in sec gl=(10^13/10...
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// Problem no 10.1,Page No.249 clc;clear; close; //Consider Equilibrium of joint A //As there are no Load applied at A members AC and AB have nothing to Balance //So they are null members F_AB=0 F_AC=0 //Consider Equilibrium of joint B //Applying the summation of horizontal forces we get F_DB=4*(cos(45*%pi*180**-...
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example8_6.sce
// To find the resistance R1 and R3 in fig 8-8 // example 8-6 in page 207 clc; // Given data R4=5e+3; L1=100e-3; Ls=500e-3; Rs=270; R3=1e+3; // resistances in ohm and inductances in henry //calculation printf("R3=%d K-ohm\n",R4*L1/(Ls*1000)); printf("R1=%d ohm",Rs*R3/R4); //result //R3=1 K-ohm //R1=54 ohm
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//chapter 4 //example 4.9 //Show that given angles are successive order of difraction and find spacing constant //page 79 clear; clc; //given lambda=0.586; // in Angstrom (wavelength of X-rays) n1=1, n2=2, n3=3; // orders of diffraction theta1=5+(58/60); // in degree (Glancing angle for first order of diffract...
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Ex1_21.sce
clc // Variable Initialization Vm=230//Supply Voltage in Volts Ra=0.75//Combined Field and Armature circuit resistance in Ohm N=1300 //Motor speed in Rpm V=210//Rated voltage of motor in Volts a=45//firing angle in Degree Kaf=0.03 //Constant in N-m/A^2 Kres=0.075 //Constant in V-s/Rad //Solution //For semi...
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//pathname=get_absolute_file_path('16.13.sce') //filename=pathname+filesep()+'16.13-data.sci' //exec(filename) //Pressures(in bar): p1=1 p10=20 //Temperatures(in K): T1=300 T5=T1 T9=T1 //Clearance: C=0.04 //Bore(in m): D=0.30 //Stroke(in m): L=0.20 //Index of compression: n=1.25 //Gas constant(in kJ/k...
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10_8.sce
clear; clc; printf("\t\t\tExample Number 10.8\n\n\n"); // effects of off-design flow rates for exchanger in example 10-7 // Example 10.8 (page no.-537-538) // solution // we did not calculate the oil flow in example 10-7 but can do so now from q = 193;// [kW] c_oil = 1.9;// [J/kg degree celsius] heat capac...
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ques11.sce
clc disp('for roles theorem F9x) should be differentiable in (a,b) and f(a)=f(b)'); disp(' Here f(x)=sin(x)/e^x'); disp(''); syms x y=sin(x)/%e^x; y1=diff(y,x); disp(y1); disp('putting this to zero we get tan(x)=1 ie x=pi/4'); disp('value pi/2 lies b/w 0 and pi. Hence roles theorem is verified');
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clc; clear; close; Wn1=400;//in nm Wp1=400;//in nm Wn2=200;//in nm Wp2=800;//in nm Vdd=1.8;//in volts Vtp=0.5;//in volts Vtn=0.5;//in volts Ep=24;//in volts En=6;//in volts X1=sqrt((Wn1*Ep)/(Wp1*En)); Vs1=(Vdd+(X1*Vtn)-Vtp)/(1+X1); X2=sqrt((Wn2*Ep)/(Wp2*En)); Vs2=(Vdd+(X2*Vtn)-Vtp)/(1+X2); disp(Vs1,'Vs ...
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//Example 7.8, page no-441 clear clc D=80 W=66.5 //(a) printf("(a)\nThe intersection point of DB temperature 80°F and WB temperature 66.5°F \nlines on the relative humidity curve for 50%%.\n RH = 50%% ") //(b) printf("\n(b)\nFrom the point of intersection of the dry and wet bulb curves, move left \nhorizontally...
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clc m_a=20; //kg/s T1=300; //K T3=1000; //K rp=4; //rp=p2/p1 cp=1; //kJ/kg K y=1.4; T2=T1*(rp)^((y-1)/y); T4=T3-T2+T1; //p5/p4=(p5/p3)*(p3/p4) //let p3/p4=r1 r1=(T3/T4)^(y/(y-1)); //r2=p5/p4; r2=1/4*r1; P_ratio=1/r2; //Pressure ratio of low pressure turbine disp("Pressure ratio of low pressure turb...
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//find the efficiency of following rivet joints clc //solution //given t=6//mm d=20//mm ft=120//N/mm^2 T=90//N/mm^2 fc=180//N/mm^2 p=50//mm pi=3.14 Pt=(p-d)*t*ft//N//tearing resistance of plate Ps=(pi/4)*d^2*T//N//shearing resistance of rivet Pc=d*t*fc//N//crushing resistance of rivet P=p*t*ft//N//strengt...
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//example 9.7 //page 320 clc; funcprot(0); //initialisation of variable epsilon=0.025;//roughness L=500; pi=3.14; g=9.81; Q=0.1; S=5.43/100; K=Q/sqroot(S); //solving for D deff('y=f(D)','y=3.14/4*sqroot(2*9.81)*(2*log10(D/0.025)+1.14)*D^2.5-.3'); [x]=fsolve(0.1,f); disp(x,"diameter(m):"); clear
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// Example 5.19 : To select values of capacitance required R_B=100000; // (ohm) r_pi=2500; // (ohm) R_C=8000; // (ohm) R_L=5000; // (ohm) R_sig=5000; // (ohm) B=100; // beta value g_m=0.04; // (A/V) r_pi=2500; //(ohm) f_L=100; // (Hz) r_e=25; // (ohm) R_C1=R_B*r_pi/(R_B+r_pi)+R_sig; // Resistance seen by C_C...
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//Chapter 8, Problem 3 clc; F=1.92; l=400*10^-3; B=1.2; I=F/(B*l); printf("Current = %f A\n\n\n",I); printf("If the current flows downwards, the direction of its"); printf(" magnetic field due to the current alone will be clockwise when viewed from above.\n"); printf("The lines of flux will reinforce (i.e. str...
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// Scilab code Ex8.3: Pg 258 (2008) clc; clear; E = 110; // Value of d.c. voltage supply, volt L = 1.5; // Inductor value, henry R = 220; // Value of series resistor, ohm // Part (a) di_dt = E/L; // The initial rate of change of current through inductor, H printf("\nThe initial rate of change of cu...
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clear all; clc; disp("Scilab Code Ex 3.5 : ") //Given: //Refer to the graph of shear stress-strain of titanium alloy. x_A = 0.008; //rad - x co-ordinate of A y_A = 360; //MPa - y co-ordinate of A height = 50;//mm l = 75; //mm b = 100; //mm //Calculations: //Shear Modulus: G = y_A/x_A; //Proporti...
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function r=mtlb_all(a) // Copyright INRIA if type(a)==4 then a=bool2s(a);end if size(a,1)==1|size(a,2)==1 then r=and(a) else r=and(a,1) end
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clear clc //Lista de exercício 3 - 3º Tarefa //Dados pi = %pi r = 0.001; // raio da esfera em metros rho = 7850; //densidade do aço em kg/m^3 g = 9.8; //m/s^2 m = (4/3)*pi*(r^3)*7850 // massa em kg R=1;//Raio da circunferencia geradora //Condições iniciais s0 = -1/10; v0 = 0; S0 = [s0;v0]; //Espaço de estados function ...
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//example 6.2 clear; clc; //Given: T=500;//Temperature[K] P=100;//Pressure[atm] a=3.61;//van der waals constant for CO2[atm.L^2.mol^-2] b=0.0429;//van der waals constant for CO2[L.mol^-1] R=0.082;//Universal gas constant[atm.K-1.mol^-1] //To find the molar volume of CO2 x=b+(R*T/P); y=a/P; z=a*b/P; p...
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clc //Initialization of variables Hv=539.6 //cal/g T=273.2+100 //K //calculations Kb=1.987*T^2 /(1000*Hv) //results printf("Molal elevation constant = %.3f deg /mole /kg",Kb)
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clear all; clc; //This numerical is Ex 2_2S,page 30. //The value given in the book for N_m is 1315,but on calculating the true value is found out to be 1304.35 P_ho=22.4//hydraulic output power Q=0.14//flow rate at best efficiency point g=9.8 rho=998 H_p=97.5 N=600 delta_pm=P_ho/Q printf("Value of dischar...
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//clc() //Ss = solid flow rate, Pwaterin = 25;//% Pwaterout = 5;//% X1 = Pwaterin/(100 - Pwaterin);//kg water/kg dry air X2 = Pwaterout/(100 - Pwaterout);//kg water/kg dry air //form humidity chart, Y2 = 0.015;//kg water/kg dry air Y1 = 0.035;//kg water/kg dry air m = 1;//kg of dry air //Ss * X1 + Y2 = Ss * X...
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clc //initialisations ht=65//cm h0=-5//cm t=273//c //CALCULATIONAS h100=h0+(100*(ht-h0)/t) l=(1+(t/273)) H=(ht-(h0*l))/(l-1) printf(' temperature= % 1f cm',H)
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//Example_a_6_1 page no:233 clc; Vmag=250; Vang=100; Imag=15; Iang=30; theta=100-30; pf=cosd(theta); active_power=(Vmag/sqrt(2))*(Imag/sqrt(2))*pf; reactive_power=(Vmag/sqrt(2))*(Imag/sqrt(2))*sind(theta); apparent_power=(Vmag/sqrt(2))*(Imag/sqrt(2)); disp(pf,"the power factor is "); disp(active_power,"the ...
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// Scilab code Ex1.9: Pg:21 (2008) clc;clear; h = 6.62e-034; // Planck's constant, joule-sec c = 3e+008; // Velocity of light, m/s m_0 = 9.1e-031; // Rest mass of an electron, kg m = 1836*m_0; // Mass of a proton, kg E = m_0*c^2; // Energy of an electron, joule // Since (1/2)*m*v^2 = 81.9e-015, s...
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// Scilab code Exa4.7.4: To determine the power produced by 100 milligram of Cf-252 : Page 191 (2011) N = 6.023e+023/252*0.1; // Number of nuclei in 100mg of Cf-252 t_h = 2.62*365*24*3600; // Half life of Cf-252, s D_c = log(2)/t_h; // Decay constant, s^-1 F_r = N*D_c; // Fission rate, fissions/s E = 210*1.6e-01...
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clear; n=3; es=0.5*(10^(2-n)); x=0.5; f(1)=1; //first estimate f=e^x=1 ft=1.648721; //true value of e^0.5=f et(1)=(ft-f(1))*100/ft; ea(1)=100; i=2; while ea(i-1)>=es f(i)=f(i-1)+(x^(i-1)) //(factorial(i-1)); et(i)=(ft-f(i))*100/ft; ea(i)=(f(i)-f(i-1))*100/f(i); i=i+1; end for j=1:i-1 ...
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b = chdir('C:\Users\work\OneDrive\Documents\SciLab\lab_v2') exec('ADC.sce') n = 1 fs = 22050 quant_levels = linspace(-1, 1, 10) //Task 1 recorded_data = ADC(n, quant_levels, fs) f = figure(1) // set figure's number clf // clear figure plot(recorded_data) gca.data_bounds = [0,-2; fs,2] xlabel('Samples') ylabel('Amplit...
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clc; h=0.78; //height in m g=9.8; //gravitational constant in m/sec square v=0.5; //velocity in m/sec t=sqrt((2*h)/g); //calculating t disp(t,"Time required in sec = "); //displaying result s=v*t; //calculating distance disp(s,"Horizontal distance in m = "); //displaying result
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//Example number 5.10, Page number 88 clc;clear; close; //Variable declaration delta_x=10**-8; //length of box(m) m=9.1*10**-31; //mass(kg) h=6.626*10**-34; //plank constant //Calculation delta_v=h/(m*delta_x)/10**3; //uncertainity in velocity(km/s) //Result printf("uncertainity in velocity is %.1f km/s"...
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function [img, lowResPath, highResPath] = getPhoto(path) img = imread(path); f = createWindow(); imdisplay(img,f); // set(f,'layout','border'); i = uicontrol(f,'style','image','string',path,'position',[20,20,200,200],'scrollable','on'); disp(size(img)); endfunction
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function ask(node) disp(node); if (node(2) == 'ENDPOINT') disp('Result: ' + node(1)); else disp(node(1)); res = input('','string'); if (part(res,1) == 'y') ask(node(2)) else ask(node(3)) end end endfunction a = "Does the conflict involve a Warwaw Pact or other Soviet allied ...
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//// //Varialble Declaration gama = 71.99e-3 //Surface tension of water, N/m r = 2e-5 //Radius of xylem, m theta = 0.0 //Contact angle, rad rho = 997.0 //Density of water, kg/m3 g = 9.81 //gravitational acceleration, m/s2 H = 100 //Height at top of redwood tree, m //C...
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//used under linux //tdp=getenv('SCILAB_HOME')+'/share/scilab/contrib/iome_toolbox/loader.sce'; tdp='/usr/share/scilab/contrib/iome_toolbox/loader.sce'; //following used under windows //tdp=getenv('SCILAB_HOME')+'/contrib/iome_toolbox/loader.sce'; exec(tdp); elist=iome('localhost',8080,0); addparamdouble('f1',27,elist...
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//chapter-10 page 490 example 10.12 //============================================================================== clc; clear; D=3;//dimension of a paraboloid in m f=3*10^9;//frequency (S band) in Hz c=3*10^8;//Velocity of light in m/sec //CALCULATION w=c/f;//wave length in m BWFN=140*(w/D);//BeamWidth b...
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// This GUI file is generated by guibuilder version 4.2.1 ////////// f=figure('figure_position',[400,50],'figure_size',[640,480],'auto_resize','on','background',[33],'figure_name','Graphic window number %d','dockable','off','infobar_visible','off','toolbar_visible','off','menubar_visible','off','default_axes','on','vis...
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e=input("Bedrag in euros: "); t=input("Wisselkoers: "); d=e*t; disp("Het bedrag in dollar: "+string(d)) printf("Het bedrag is %f dollar",d)
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//Ex:2.14 clc; clear; close; printf("Two 100 ohm resistor of 1 W");
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exec('Bernauli.sci', -1) //Given that density_Ethanol = 791 //in kg/m^3 A1 = 1.20*10^-3 //in m^2 A2 = A1/2 //Pressure in narrower section is lesser deltaP = -4120 //in N/m^2 //Sample Problem 15-8 printf("**Sample Problem 15-8**\n") A = [A1, A2] density = density_Ethanol h = 0 V = fsolve([0, 1], Berna...
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clc //ex1.7 R_1=10; R_2=5; V_R_2=15; //voltage across R_2 a=0.5; i_y=V_R_2/R_2; //current across R_2 i_x=i_y*2/3; //current across R_1, by applying KCL at the top end of the controlled source V_x=i_x*R_1; //ohm's law V_s=V_x+V_R_2; //KVL around the periphery of the circuit disp(V_s,'...
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//Power required// pathname=get_absolute_file_path('10.12.sce') filename=pathname+filesep()+'10.12-data.sci' exec(filename) //From given graph, for maximum delivery condition, Q=48.5gpm. //Volume of oil per revolution delivered by the pump(in in^3/rev): vc=Qe/N*231 //Volumetric Effciency of pump at max flow: Ef...
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//qscatter exec('v.sce'); exec('f.sce'); exec('u.sce'); exec('tdl.sce'); exec('sigma.sce'); exec('numerov.sce'); //partial wave analysis of scattering deltah=0.01; nsteps=200; global m global hb m=938*10^9; hb=6.59*10^(-13); //2m/hb^2=6.12meV^-1(sigma)^-2 sig=zeros(nsteps); for i=1:nsteps e=i*0.05; k=sqrt(2*m*...
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//EXAMPLE 2-84 PG NO 121-122 L=0.01; //Inductance C=0.04*10^-6; //Capacitor Fo=1/[2*%pi*(sqrt(L*C))]; disp('i) Resonant Frequency (Fo) is = '+string (Fo) +' Hz '); Z=50; R=Z; V=100; Io=V/R; disp('ii) Current (Io) is = '+string...
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function ydot = f(t,y) ydot=[a-y(2)*y(2)-1;1 0]*y endfunction a=1;y0=[1;0];t0=0;instants = 0:0.02:20; y=ode(y0,t0,instants,f); plot2d(y(1,:),y(2,:),style=-1,rect=[-3,-3,3,3],nax=[10,2,10,2]) xtitle('Van der pol')
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// Exa 5.2 clc; clear; close; // Given data Rf= 12;// in k ohm Rs1= 12;// in k ohm Rs2= 2;// in k ohm Rs3= 3;// in k ohm Vi1= 9;// in volt Vi2= -3;// in volt Vi3= -1;// in volt Vout= -Rf*[Vi1/Rs1+Vi2/Rs2+Vi3/Rs3];// in volt disp(Vout,"Output voltage in volt");
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//// //Variable Declaration t1by2 = 2.05e4 //Half life for first order decomposition of N2O5, s x = 60. //percentage decay of N2O5 //Calculations k = log(2)/t1by2 t = -log(x/100)/k //REsults printf("\n Rate constant of the reaction: %4.3e 1/s",k) printf("\n Timerequire for 60 percent d...
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//=========================================================================== //chapter 3 example 17 clc; clear all; //variable declaration R1 = 500; //resistance in Ω R2 = 615; //resistance in Ω R3 = 100; //resistance in Ω dR1 = 1; //limiting error(dR1/R1) in % dR2 ...
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clc; clear; //The size of retinal image x : x = ((17 * 10)/50); disp(x,'The size of the retinal image (in mm) is ');
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// Question 3 function [l, m]=factorisation_cholesky(D, SD) // arg: la diagonale et la sous-diagonale d’une matrice M symétrique définie // positive et tridiagonale. // return: deux vecteurs l (diagonale) et m (sous-diagonale) issus de // la matrice résultante de la factorisation de cholesky....
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//pathname=get_absolute_file_path('3.17.sce') //filename=pathname+filesep()+'3.17-data.sci' //exec(filename) //Initial pressure(in MPa): pi=0.5 //Initial volume(in m^3): vi=0.5 //Final pressure(in MPa): pf=1 //Atmospheric pressure(in Pa): patm=1.013*10^5 //Adiabatic index of compression for H2: rH2=CpH2/(Cp...
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// Partial fraction expansion for Example 4.29 // 4.9 // z^2 + 2z // G(z) = -------------------- // (z + 1)^2 (z - 2) exec('respol.sci',-1); exec('flip.sci',-1); num = [1 2 0]; den = convol(convol([1 1],[1 1]),[1 -2]); [res,pol] = respol(num,den)
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// ReOrderStateEqns > findRow > filt // MinKer > polyRank // IpolishLeftAnn > rowcmprI // gauss > RowManipulatePlusIs // function that takes first input a vector v1 of indices (assumed distinct integers), // and second input v2 of what is required from within v1. // and gives two outputs: one is v1 with just ...
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pathname=get_absolute_file_path('8_3.sce') filename=pathname+filesep()+'8_3data.sci' exec(filename) A=t*(2*a +b); Ixx=2*a*t*(b/2)^2 +(t*b^3)/12; Iyy=(2*t*a^3)/12; I0=Ixx+Iyy; J=(2*a*t^3)/3 +(b*t^3)/3; tau=(t*a^3 *b^2)/24; Px=(%pi^2 *E*Ixx/L^2);//PCR(xx) Py=(%pi^2 *E*Iyy/L^2);//PCR(yy) Pth=(A/I0)*(G*J +(%pi^2...
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clc; clear; lambda=0.180*10^-9 //wavelength in m R=1.097*10^7 // in m^-1 //calculation Z_star=sqrt(4/(3*lambda*R)) mprintf("The Z_star is = %d\n",Z_star) Z=(Z_star+1) mprintf("Since Z which is the atomic number is = %d,the element is Cobalt",Z) ...
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//************************* Algorithmic ADC ****************************** if (blk_name.entries(bl) =='Algo_ADC') then mputl("# Algorithmic ADC ",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) adc_str= ".subckt Algo_ADC in[0]=net"+string(blk(blk_objs(bl),2))+'_'+ string(ss)+" in[1]=clk_A in[2]=clk_R in[3]...
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//time domain analysis of continuous time systems //Convolution Integral of input x(t) = (e^-t).u(t)and g(t) =(e^-2*t)u(t) clear; close; clc; Max_Limit = 10; t = 0:0.001:10; for i=1:length(t) g(i) =(exp(-2*t(i))); end x= exp(-(t)); y = convol(x,g) figure a=gca(); plot2d(t,g) xtitle('Impulse Res...
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clear; close; clc; T0=4; w0=%pi/2; y=[1 0 0 0]; n=-8:7; x=[]; for i=1:length(n)/T0 x=[x y]; end plot2d3(n,x); plot(n,x,'r.'); xtitle('x[n]','n') for k=-9:9 c(k+10)=0; for n=0:3 c(k+10)=c(k+10)+ (1/4)*(y(n+1))*(%e)^(%i*w0*k*n); end end k=-9:9; figure plot2d3(k,abs(c)); plot...
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//Base-64 encoding mapping table disp("Base-64 encoding mapping table") [u,t,n] = file() n = strcat(n) file_name = basename(n)+fileext(n) file_name = strcat(file_name) ind=strindex(n,file_name) path = part(n,1:ind-1) chdir(path) //Get function to create encoding table exec("Chapter_6.sci",-1) enc =...
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clear; clc; Pr=.24; Vr=.55; del=asind(Pr/Vr); a=gca(); a.auto_scale="off"; a.data_bounds=[0,0.3;1.5,1]; xlabel("Voltage"); ylabel(" ReactivePower"); V=[0:.01:5]; Q=((V)^2)+(V*cosd(del)); plot(V,Q); q=.38; v=.95; Qr=((220^2)*q)/60; Vrr=v*220; mprintf("Critical power = %.3f MVAR and Critical voltage = %....
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idct1.sci
function y = idct1(x,n) funcprot(0); rhs=argn(2) if (rhs<1 | rhs>2) then error("Wrong number of input arguments.") end select(rhs) case 1 then y=callOctave("idct",x) case 2 then y=callOctave("idct",x,n) end endfunction
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curl "localhost/recipes/rate.php?username=lmitchell&author_name=nloison"
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clc,clear printf('Example 3.2\n\n') //no load I_noload=2.5 //No load current V=440 R_a=1.2,R_sh=550//resistance of armature and shunt field windings no_load_input=V*I_noload I_sh=V/R_sh I_a_noload=I_noload-I_sh no_load_armature_copper=(I_a_noload^2)*R_a constant_losses=no_load_input-no_load_armature_coppe...
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jac_flowsheet_residuals.sci
function [At, varargout] = jac_flowsheet_residuals(flow_full,temp_full, flow, temp, coef ) //****************************************************************************** // Data Reconciliation Benchmark Problems From Literature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} ...
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vmm6x2.sci
function [x,y,typ]=vmm6x2(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x...
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consulta_por_segundo_apellido.tst
PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_segundo_apellido(psegundo_apellido => :psegundo_apellido, p_recordset => :p_recordset); end; 2 psegundo_apellido 1 Marx 5 p_recordset 1 <Cursor> 116 0
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4_optimizacion.sce
function y=banana(x) y = 100*(x(2)-x(1)^2)^2 + (1-x(1))^2; endfunction opt = optimset ( "TolX" , 1.e-2 ); [x , fval , exitflag , output] = fminsearch ( banana , [-1.2 1] , opt )
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// Scilab Code Ex9.1: Page-9.24 ; (2004) clc;clear; ni = 2.37e+19; // Carrier concentration at room temperature mu_e = 0.38; // mobility of electron; m^2V^-1s^-1 e = 1.6e-19; // electronic charge, C mu_h = 0.18; // mobility of holes; m^2V^-1s^-1 sigma = ni*e*(mu_e+mu_h); // conductivity, mho.m^-1 ...
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// example 6.3 // solution to the given IVP disp('du/dt= A*u'); // u=[u1 u2]'; A=[-3 4 ;-2 3]; // given B=[1 0;0 1]; // identity matrix; [x,lam] = geigenvectors(A,B); // hence; disp('u=c1*%e^t*x(:,1)+c2*%e^-t*x(:,2)'); disp('u1=c1*%e^t+c2*%e^-t*2') d...
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ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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clear; clc; printf("\t\t\tExample Number 6.2\n\n\n"); // heating of water in laminar tube flow // illustration6.2 // solution Tw = 60;// [degree celsius] temperature of water d = 0.0254;// [m] diameter of tube R = 287;// [] gas constant u = 0.02;// [m/s] velocity of water Tw = 80;// [degree celsius] tempe...
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fwData = read(get_absolute_file_path("LoadData.sce") + "..\Data\FwElectrical.txt", 10, 2); rvData = read(get_absolute_file_path("LoadData.sce") + "..\Data\RvElectrical.txt", 10, 2);
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//Example 5.36 //Secant Method //Page no. 204 clc;clear;close; a=8670;c=10^-8;t2=1.4*10^-4; deff('x=f(x)','x=-t2+log((1-2*x/a)/(2-x/a))*(a*x*c)/(a+x)') printf('n\txn\t\tf(xn)\t\tXn+1\t\tf(Xn+1)\t\tXn+2\t\tError\n') printf('----------------------------------------------------------------------------------------...