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ex18_9.sce
errcatch(-1,"stop");mode(2);// Example 18.9, page no-465 E=1000//V.m^-1 P=4.3*10^-8 //C.m^-2 eps=8.854*10^-12 //F.m^-1 epsr=1+P/(eps*E) printf("The relative permittivity of NaCl is %.2f",epsr) exit();
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cv = 0.718; T2 = 500; T1 = 300; m = 1; T0 = 300; // Case (a) Sua = cv*log(T2/T1); Ia = T0*Sua; disp("kJ/kg",Ia,"The irreversibility in case a is") // Case (b) Q = m*cv*(T2-T1); T = 600; Sub = Sua-(Q/T); Ib = T0*Sub; disp("kJ/kg",Ib,"The irreversibility in case b is")
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//****************************** ADC ********************************** if(blk_name.entries(bl)=='adc') then ONchip_ADC=1; adc_loc_idx = adc_loc_idx +1; fd_io= mopen (fname+'.pads','a+'); // DEDICATED PADS code for ss=1:scs_m.objs(prime_ops(s)).model.ipar(1) mputl("# ota_buf"...
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fitting in a parabola.sce
//FITTING A CURVE IN PARABOLA num=input("no. of points=") x=[] y=[] for i=1:num x(i)=input("x:") y(i)=input("y:") end x_sum=0 y_sum=0 x_sq_sum=0 x_y_sum=0 x_cu_sum=0 x_sq_y_sum=0 x_qua_sum=0 for j=1:num x_sum=x_sum+x(j) y_sum=y_sum+y(j) x_sq_sum=x_sq_sum+x(j)*x(j) x_y_sum=x_y_sum+x(j)*y(j) ...
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clc // // // //Variable declaration lambdaa=5000*10**-8 //Wavelength N=40000 //Grating lines de=12.5*10**-5 //Diffraction element //Calculations RPmax=((de*N)/lambdaa) //Result printf("\n The Maximum resolving power is %i or 10**5",RPmax)
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test_joystick.SCI
displayname=root.displays.getmembers.get(0).name; codeblock readtextfile(ScriptDir+"\TOOLS.sci"); sf=T_scene_create; sss=T_getscene; myviewport=T_getviewport; vp=myviewport; vp.camerapos=point(10,15,40); vp.cameradir=vecnorm(point(10,15,0)-vp.camerapos); vp.cameraupdir=vector(0,1,0); vp.enableusernav...
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gallery_no_override.sce
Camera 115.699996948 63.540000916 129.500000000 -0.104099371 0.977739513 -0.182177961 105.998748779 59.343551636 112.521316528 18.427069 Materials 55 0.639200 0.592200 0.572500 0.126800 0.122400 0.120800 12.600000 0.443100 0.525500 0.023530 0.000000 0.000000 0.000000 20.000000 0.639200 0.592200 0.572500 0.126800 0.1224...
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RK_Ariel_e_Pedro_Coelho_v4.sce
//RUNGE-KUTTA DE 4ª ORDEM - ARIEL E PEDRO COELHO (GRUPO 8) - MÉTODOS NUM. EQ. DIF. //IPRJ-UERJ 2019/1 PROF. GRAZIONE DE SOUZA //Limpeza de variáveis e do console clc; clear; clearglobal; //Variáveis globais global('t','q','i'); t(1) = 0; //Valor inicial de ...
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11_8_2.sce
clc //initialisation of variables l= 9 //ft g= 32.2 //ft/sec^2 Q= 160 A= 21*%pi //CALCULATIONS d= 6/(l*2*g*(A/Q)^2-1.5) //RESULTS printf ('diameter = %.2f ft',d) //ANSWER GIVEN IN THE TEXTBOOKIS WRONG
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//pagenumber 306 example 28 clear re=4*10^3;//ohm r1=4*10^3;//ohm hie=1.1*10^3;//ohm resist=10*10^3;//ohm hfe=50; rb=10*10^3;//ohm r=1*10^3;//ohm colres=5*10^3;//ohm //(1) current gain ri=rb*hie/(rb+hie); curgai=(1/2.04)*((rb)/(rb+hie))*((-hfe*colres)/(colres+r1)); disp("current gain = "+string((curgai...
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// Example 6.8: Ri, AVs clc, clear IC=0.2e-3; // in amperes bta=125; Rs=2e3; // in ohms RE=100; // in ohms RC=5e3; // in ohms VT=25e-3; // Voltage equivalent to temperatue at room temperature in volts gm=IC/VT; // in mho r_pi=bta/gm; // in ohms Ri=r_pi+(1+bta)*RE; // in ohms AVs=-bta*RC/(Rs+r_pi+(1+bta)*RE);...
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// Exa 3.20 (Miss printed as example 3.17) clc; clear; close; format('v',7) // Given data V_E = 1;// in V V_BE = 0.7;// in V R_C = 1;// in k ohm Beta = 180; V_CC = 12;// in V V_CEQ = 6;// in V // Applying KVL into collector circuit, V _CC - I_C*R_C - V_CEQ = 0 or I_C = (V_CC-V_CEQ)/R_C;// i...
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clc; clear; sg=0.65; l1=0.75;//ft l2=0.5;//ft //0.5 ft =z1(max) //0.5=0.75*(ay(max)/g) aymax=(0.5*32.2)/0.75;//ft/s^2 disp("ft/s^2",aymax,"The max acceleration that can occur before the fuel level drops below the transducer=")
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8.sce
clc u=0.1; // Ns/m^2 d=0.1; //m R=0.05; // m Rho=900; //kg/m^3 v_max=2; // m/s v=v_max/2; // m/s disp("At the pipe wall (r =R), therefore, the shear stress is"); Tw=-2*u*v_max/R; disp(Tw); disp("N/m^2"); disp("The negative sign indicates that the shear stress is in the opposite direction to flow."); d...
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BitToBus16.tst
load BitToBus16.hdl, output-file BitToBus16.out, compare-to BitToBus16.cmp, output-list in%B2.1.2 out%B1.16.1; set in 0, eval, output; set in 1, eval, output;
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function[w,y,e,J]=aalms(x,dn,mu,M) N=length(x); y=zeros(1,N); w=zeros(1,M); printf('N=%d\n', N); for n=M:N x1=x(n:-1:n-M+1); disp(w) disp(x1) y(n)=w*x1'; e(n)=dn(n)-y(n); w=w+2*mu*e(n)*x1; printf('n=%d, dn(n)=%f, y(n)=%f, e(n)=%f\n', n, dn(n), ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART I : GENERATION // CHAPTER 7: TARIFFS AND ECONOMIC ASPECTS IN POWER GENERATION // EXAMPLE : 7.14 : // Page number 77 clear ; clc ; close ; // Clear the work space and ...
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//Test file corresponding to 8 valid inputs and 2 invalid inputs //This will function even if we introduce an invalid input, as the pin features a validity bit called enable (en) load Encoder83.hdl, output-file Encoder83.out, //compare-to Encoder83.cmp, output-list x0%B3.1.3 x1%B3.1.3 x2%B3.1.3 x3%B3.1.3 x4%...
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// Chapter 13_Optical Devices //Caption_Photo conductor //Ex_5//page 611 mup=480 mun=1350 L=100*10^-4 //length of photoconductor A=10^-7 //cross sectional area tau_p=10^-6 //minority carrier lifetime V=10 //applied voltage tn=L^2/(mun*V) //photoconductor gain is G=(tau_p/tn)*(1+(mup/mun)) printf('...
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/* *rc2poly *Convert reflection coefficient to prediction filter polynomial *Syntax: *a = rc2poly(k) *[a, efinal] = rc2poly(k, r0) * * *Desciption: *a = rc2poly(k) converts the reflection coefficients k corresponding to the lattice structure to the *prediction filter polynomial a, with a(1) = 1. The output a...
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clear; clc; //page no. 127 p_A = 0; p_B = 0; p_C = 0; p_D = 0; //velocity heads V1 = 15.28;//fps V2 = 16.78;//fps V3 = 15.50;//fps V4 = 16.50;//fps q = sqrt(2*32.2)*integrate('h^(1/2)','h',3.771,4.229); printf('V_A = %.2f fps,\n V_B = %.2f fps,\n V_C = %.2f fps,\n V_D = %.2f fps',V1,V2,V3,V4); pri...
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clc //Initialization of variables Hr=178 //kJ/mol Sr=161 //J/K mol //calculations T=Hr*10^3 /Sr //results printf("Decompostion temperature = %.2e K",T)
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clc //to calculate thickness //mass absorption coefficient mum of an absorber is related with linear absorption coefficient mu and density of the material rho is given by //mu=rho*mum=2.7*0.6=1.62 cm^-1 mu=1.62 //if initial intensity Io of the X-ray beam is reduced to I in traversing a distance x in absorber I=Io*...
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//Copyright INRIA files=G_make(['/tmp/ext10c.o'],'ext10c.dll'); link(files,'ext10c','C'); //passing a parameter to ext10c routine by a list: param=[0.04,10000,3d+7]; y=ode([1;0;0],0,[0.4,4],list('ext10c',param))
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//Variable declaration r=0.052*10**-9; //radius(m) B=3; //flux density(Wb/m**2) e=1.6*10**-19; m=9.1*10**-31; //mass(kg) //Calculation delta_mew=e**2*r**2*B/(4*m); //change in magnetic moment(A m**2) //Result printf('change in magnetic moment is %0.3f *10**-29 Am**2 \n',(delta_mew*10**...
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// Some crazy language blah blah blah Test to see if branch1 tracking is working quick test for changes sldkfj lkjsdf sdflkj loiiowejkljjkl 334fsd slksdjf
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disp('Performing GE.') a = [2 1 -1 ; -3 -1 2 ; -2 1 2] disp('The coefficient matrix is:') disp(a) b = [8 ; -11 ; -3] function GE(a, b) c = [a b] disp('The augmented matrix is:') disp(c) l21 = c(2,1) / c(1,1) disp('R2 = R2 - ' + string(l21) + '*R1') c(2,:) = c(2,:) - l21*c(1,:) dis...
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// 08.05.18 // Structure changed // 09.10.11 function TF=Member(A,L) if Mixtype(L)>1 N=Mixlength(L); else N=length(L); end for I=1:N Tmp=Op(I,L); if A==Tmp TF=%t return end end TF=%f endfunction
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//(Manufacturing Considerations in Design) Example 3.1 //Refer Fig. 3.25 on page 70 //Basic diameter of bush Db mm Db = 20 //Refer tables 3.2 and 3.3a for tolerances of H6-e7 fit //Upper deviation for bush Ub mm Ub = 0.013 //Lower deviation for bush Lb mm Lb = 0.000 //Basic diameter of crank pin Dc mm Dc = ...
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//Ex_2_21 clc; clear; close; format('v',4); //given data : N=500;//turns A=0.01;//m^2(Area of cross section of poles) l=0.5;//m(mean length) mu0=4*%pi*10^-7;//permeability of air mu_r=1000;///relative permeability g=9.8;//gravitational acceleration W=200;//kg F=W/2;//kg F=F*g;//N B=sqrt(F*2*mu0/A);//Wb/m...
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// Given:- Tnot = 299 //in kelvin etac = .8 //compressor efficiency of 80 percent mdot = .08 //mass flow rate in kg/s //analysis //State 1 is the same ...
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clear;lines(0); // //Example of how to use the fsfirlin macro for the design //of an FIR filter by a frequency sampling technique. // //Two filters are designed : the first (response hst1) with //abrupt transitions from 0 to 1 between passbands and stop //bands; the second (response hst2) with one sample in each //...
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## Copyright (C) 2006-2017 John W. Eaton ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later vers...
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clear // // //Initilization of Variables L=3000 //mm //Length of column W=800*10**3 //N //Load a=1*1600**-1 //Rankine's constant FOS=4 //Factor of safety sigma=550 //N/mm**2 //stress //Calculations //Effective Length l=L*2**-1 //mm //Let d1=outer diameter & d2=inner diameter //d1=5*8**-1*d2 //M.I //I=%pi*64**-1*...
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//Chapter-1,Example1_3_3,pg 1-16 A=63.5 //atomic weight of Cu N=6.023*10^23 //Avogadro's number n=4 //FCC structure r=1.28*10^-8 //atomic radius of Cu //for FCC a=4*r/(sqrt(2)) ...
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clc;clear; //Example 16.8 //given data T=15; P=92; //from Table A-4 Pv=1.7057; //calculations yv=Pv/P; disp(yv,'mole fraction of water vapor at the surface'); yw=1-yv; yw=round(yw) disp(yw,'mole fraction of water in the lake')
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// Scilab Code Ex12.10 : Page-608 (2011) clc; clear; e = 1.6e-19;....// Charge on anlectron, C m = 9.1e-31;....// Mass of the electron, kg r = 5.1e-11;....// Radius of the electronic orbit, m B = 2.0;....// Applied magnetic field, weber per metre-square delta_pm = e^2*r^2*B/(4*m); printf("\nThe change in the mag...
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clc t = 0:0.000001:0.002; deff('y=u(t)','y=1*(t>=0)'); y =0.02*(u(t) - u(t-0.002)); figure a=gca() subplot(111) plot2d(t,y,5,rect=[0 0 0.004 0.03]) xtitle('i vs t','t in ms','i in mA') syms s //For t<=0 ms v=0 //For the region in the rectangular pulse i.e 0<t<=2 ms v=integ(s^0,s)*4000 //For t>2 ms v=8...
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//Chapter 7, Problem 4 clc; B=1.2; //Magnetic flux density H=1250; //Magnetic field strength uo=4*%pi*10^-7; //permeability of free space ur=B/(uo*H); //Calculating relative permeability printf("Relative permeability = %f",ur);
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clear D=500.0 //diameter of the wheel d=200.0 //diameter of axle W=5000.0 //effort VR=(2*D)/(D-d) //Velocity Ratio Efficiency=0.6 MA=Efficiency*VR //Mechanical advantage P = W/MA //Effort printf("\n Effort is %0.3f N",P)
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Ex2_1.sce
//Ex_2_1 clc; clear; close; format('v',6); //given data : LTsc=1.6;//H(Series cumulative) LTd=0.4;//H(differentially) L1=0.6;//H M=(LTsc-LTd)/4;//H(Mutual Inductance) L2=LTsc-2*M-L1;//H K=M/sqrt(L1*L2);//Coupling Coefficient disp(M,"Mutual Inductance(H)"); disp(K,"Coupling Coefficient");
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ch4ex31.sce
//signals and systems //Unilateral Laplace Transform:Solving Differential Equation //example 4.17 s= %s; syms t; // Re s>-1 [A] = pfss(1/((s+1)*(s+5))); F1 = ilaplace(A(1),s,t) F2 = ilaplace(A(2),s,t) //F3 = ilaplace(A(3),s,t) F = F1+F2 disp(F) //-5< Re s <-2 [B] = pfss(-1/((s+2)*(s+5))); G1 = ilaplace(B...
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Ex7_3.sce
//chapter-7 page 279 example 7.3 //============================================================================== clc; clear; Pi=2.5;//Incident Power from one directional coupler in mW Pr=0.15;//Reflected Power from other directional coupler in mW //CALCULATION p=sqrt(Pr/Pi);//Reflection Coefficient S=((1+p...
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r1=1; r2=1.2; r=r1+r2; v=10; disp("Part a"); v1=v*r2/r; disp("the maximum voltage (in V) is"); disp(v); disp("the minimum voltage (in V) is"); disp(v1); disp("Part b"); v2=v*(r1/2+r2)/r; disp("the volatge (in V) is"); disp(v2);
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clear; clc; printf("Example 10.3\n"); P=101.3e3; //pressure of the operating column T=295; //Temperature of the operating column P_A=7e3; //partial pressure of ammonia x=1e-3; //=(y1-y2)Thickness of stationary gas film D=2.36e-5; //Diffusivity of ammonia C_A=(1/22.4)*(273/T)*(P_A/P);//=(C_A1-C_A2)Concentr...
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load('/home/willane/Downloads/p2STD/xa_10_1.sod') x1 = x_a load('/home/willane/Downloads/p2STD/xa_26_1.sod') x2 = x_a load('/home/willane/Downloads/p2STD/xa_43_1.sod') x3 = x_a x = [x1 x2 x3] Xf = fft(x) N = length(x) fs=35000 //taxa de amostragem periodo = 1/fs t = linspace(0,N/264600,N) function sinal_amostr...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map3102" Width="13" Height="11" CellSize="40" BackgroundSize="2" Background="_t.png"> <Cell Name="出生点" X="1" Y="1" /> <Cell Name="树" X="4" Y="1" /> <Cell Name="树" X="5" Y="1" /> <Cell Name="树" X="6" Y="1" /> <Cell Name="树" X="7" Y="1" /> <Cell Name="出生点...
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clc //Given that r1 = 1.5e8 // distance of Earth from Sun in km t1 = 1 // let // sample problem 12 page No. 305 printf ("\n\n\n # Problem 12 # \n") printf ("\n Standard formula used T^2 = k* r^3") t2 = 29.5 * t1// calculation of time period of Saturn r2 = r1 * (t2 / t1) ^ (2/3) //calculation of distance of s...
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7_3.sce
clear clc disp('Exa-7.3'); //for l=0; // employing the formula for probability distribution similarly as done in Exa-7.2 Pr1= integrate('(1/8)*((4*x^2)-(4*x^3)+(x^4))*%e^(-x)','x',0,1); //x=r/ao; similrly limits between 0 and 1. Pr2=integrate('(1/24)*(x^4)*(%e^-x)','x',0,1); ...
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clear // //eqns are obtained from the figure and are solved for currents i1=6.89 i2=3.89 i3=-2.12 i=2*(i2-i1) printf("\n current supplied by dependent source is= %0.1f A",i) power=6*i1 printf("\n power supplied by voltage source is= %0.1f W",power)
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a2.sce
clc; clear; //for i=1:1:5 m1=input('Under Mod - Index: '); m2=input('Perfect Mod - Index:'); m3=input('Over Mod - Index: '); //MESSAGE SIGNAL Am=10; fm=40; t=0:0.000001:0.25 mt=Am*sin(2*%pi*fm*t); subplot(5,1,1); plot(t,mt); xtitle('Message signal','time','Amplitude'); //CARRIER SIGNAL Ac=10; fc=300; t=0:0.000001:0...
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stacksize('max'); C=2*10^-12; L=5*10^-9; R=20; Z0=50; //f=[10^7:10^8:10^11]; //define frequency range f_min=10e6; //lower frequency limit f_max=100e9; // upper frequency limit N=100; // number of points in the graph f=f_min*((f_max/f_min).^((0:N)/N)); // compute frequency points on log scale w=2*%pi.*f...
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clear; clc; disp('Example 7.4'); // aim : To determine // the dryness fraction of steam // Given values P1 = 2;// initial pressure, [MN/m^2] t = 350;// temperature, [C] P2 = .28;// final pressure, [MN/m^2] // solution // at 2 MN/m^2 and 350 C,steam is superheated because the saturation temperatu...
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zaka=zĭ V;POT zaka=zĭ V;HAB zaka=zĭ V;PFV u+tooˀ V;POT u+tooˀ V;PFV u+tooˀ V;HAB asa V;PFV asa V;HAB asa V;POT u+zûˀu=zhibi V;PFV u+zûˀu=zhibi V;POT u+zûˀu=zhibi V;HAB u+s+ialda V;PFV u+s+ialda V;POT u+s+ialda V;HAB tuyí V;POT tuyí V;PFV tuyí V;HAB zhuuˀn V;HAB zhuuˀn V;PFV zhuuˀn V;POT kayí V;HAB kayí V;POT kayí V;PFV...
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//Ex3_11 clc TJmax=175 disp("TJmax= "+string(TJmax)+ " degree celsius") //maximum allowed junction temperature theta=0.1 disp("theta= "+string(theta)+ " degree celsius/mW ") //thermal resistances b/w junction to ambient change_T=TJmax-25 //temperature difference PDmax=change_T/theta disp("at 25 degree celsius...
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//clear// //Caption:Program to determine the cutoff frequency for the first waveguide mode(m=1) //Example14.1 //page 499 clear; clc; er1 = 2.1; //dielectric constant of teflon material er0 = 1; //dielectric constant of air d = 1e-02; //parallel plate waveguide separation in metre C = 3e08; //free space velocit...
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//(a)Impulse invariant design s=%s;z=%z; HS=1/(s+1); H1s=horner(HS,3*s/%pi) H1z=%pi/3*z/(z-%e^(-%pi/3)) //Modified inmpulse invariant design HZ=z/(z-1/%e); HMZ=0.5*(z+1/%e)/(z-1/%e);//modified transfer function H1Z=HZ/horner(HZ,1) HM1Z=HMZ/horner(HMZ,1) f=0:0.05:0.5; HZ1=horner(HZ,exp(%i*2*%pi*f')); HMZ1=ho...
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% Test of CANTENS.RED % % Authors: H. Caprasse <hubert.caprasse@ulg.ac.be> % % Version and Date: Version 1.1, 15 September 1998. %---------------------------------------------------------------- off errcont; % Default : onespace ?; wholespace_dim ?; global_sign ? ; signature ?; % answers to the 4 ...
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a a m o d t 阿 莫 特 a a r s 阿 尔 斯 a b b a t e 阿 巴 特 a b b o u d 阿 布 德 a b e g g 阿 贝 格 a b e r d e e n 阿 伯 丁 a b e r n 阿 本 a b i g a i l 阿 比 盖 尔 a b i j a h 阿 拜 甲 a b p l a n a l p 阿 普 拉 纳 尔 普 a b r u z z o 阿 布 鲁 佐 a c h a t z 阿 卡 兹 a c h e r o n 阿 克 龙 a c k l e n 阿 克 伦 a c k l e y 阿 克 利 a c l a n d 阿 克 兰 a c o c a 阿 克 卡 ...
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任意極配置.sce
//”CˆÓ‹É”z’u A=[1 0;0 2]; b=[1;1]; poles=[-2,-3]; k_=ppol(A,b,poles); k=-k_ spec(A+b*k)
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13_b.sce
//hex to decimal conversion// //example 13.b// clc //clears the command window// clear //clears// x='B3D8' a=hex2dec('B3D8') disp('the result in decimal form:') disp(a)
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//Ex:8.14 clc; clear; close; ni=0.15;// internal quantam efficiency vf=2.0;// forward voltage in volts i_f=15*10^-3;// forward current in amp x=25;// acceptance angle in degree pi=vf*i_f;// input power in Watt po=ni*pi;// output power in Watt NA=(sin(x*3.14/180)); nc=NA^2;// numerical aperture pf=nc*po;// o...
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// Example 5.4, page no-175 clear clc //multiplication of two signals gives AM with frequency component(wc-wm) and (wc+wm) and its BW is 2wm bw=0.5/100 //bw is 0.5% of carrier freq. wc=2/bw printf("Wc = %.0fWm",wc)
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Example9_18.sce
clear; clc; // Example: 9.18 // Page: 364 printf("Example: 9.18 - Page: 364\n\n"); // Solution //*****Data******// n1 = 0.7;// [moles of helium] n2 = 0.3;// [moles of argon] R = 8.314;// [J/mol K] T = 273 + 25;// [K] //******************// n = n1 + n2;// [total moles] x1 = n1/n;// [mole fraction ...
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PAM.sce
E_b=1:0.1:10; d=2*E_b; N=1; U=0; y=d/sqrt(N/2); P_e=qfunc(y); plot(E_b,P_e); xlabel("Amplitude"); ylabel("Probability"); title("BER of PAM");
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//Initilization of variables F1=25 //lb F2=25 //lb L1=14 //in L2=20 //in //Calculations C=F1*L1 //lb-in M=-F2*L2 //lb-in //Result clc printf('The twisting couple is:%f lb-in\n',C) //lb-in printf('The bending moment is:%f lb-in',M) //lb-in
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example12_34.sce
clc // Given that E = 4.18 // energy of alpha particle in Mev n = 12 // no. of particle enter the chamber per sec E_ = 40 // required energy of an ion pair in ev e = 1.6e-19 // charge on an electron in C // Sample Problem 34 on page no. 12.45 printf("\n # PROBLEM 34 # \n") R = n * E * 10^6 // in eV N = R / E_ i = N * ...
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Antennagain=5 Pt=113 Gt=10^(Antennagain/10) EIRP=Pt*Gt//effective isotrophic radiated power r=11*10^3 Pd=EIRP/(4*%pi*r*r)//power density printf('\nEIRP=%.1f W',EIRP); printf('\npower density= %.f nW/m^2',Pd*10^9)
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ex_4_6b.sce
clear; clc; syms n z; x1=(1/2)^n; X1=symsum(x1*(z^-n),n,-%inf,-1) x2=3^-n; X2=symsum(x2*(z^-n),n,0,%inf) X=X1+X2 z=%s; XX=%s; XX=-z/(z-.5)+z/(z-(1/3)); plzr(XX) a=denom(XX) b=roots(a) i=1; for theta=0:1/50:360 rx(i)=b(1)*cos(theta); ry(i)=b(1)*sin(theta); i=i+1; end plot(rx,ry) i=1; f...
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MetodoNewtonComOrdem.sce
//Método de Newton para f(x) = x^3 - 4*x^2 + 5*x -2 x = 1.0731000001 for i = 1:1000 x = x - (x^3 - 4*x^2 + 5*x -2)/(3*x^2 - 8*x + 5) end disp(x)
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// Exa 2.24 clc; clear; close; // Given data e = 1.6*10^-19;// in C Miu_e = 7.04*10^-3;// in m^2/volt-sec n = 5.8*10^28;// number of electron/m^3 m = 9.1*10^-31; E_F = 5.5;// in eV Torque = (Miu_e/e)*m;// in sec disp(Torque,"Relaxtion time in sec is"); Rho = 1/(n*e*Miu_e);// in ohm cm disp(Rho,"Resistivit...
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// chapter 9 // example 9.8 // find intrinsic carrier density and conductivity at 300K in germanium // page 275 clear; clc; M=72.6; // atomic mass of germanium P=5400; // in Kg/m^3 (density) ue=0.4; // in m^2/V-s (mobility of electrons) uh=0.2; // in m^2/V-s (mobility of holes) Eg=0.7; // in eV (Band gap) m=...
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load CustomTest.asm, output-file CustomTest.out, compare-to CustomTest.cmp, output-list RAM[20]%D0.2.0 RAM[41]%D0.2.0 RAM[61]%D0.2.0 RAM[51]%D0.2.0 RAM[31]%D0.2.0 RAM[40]%D0.2.0 RAM[60]%D0.2.0 RAM[50]%D0.2.0 RAM[30]%D0.2.0 RAM[21]%D0.2.0 RAM[22]%D0.2.0 RAM[23]%D0.2.0 RAM[...
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C=[] t=[] // função que descreve o modelo do fermentador function g=fermenter(V) to=0 Co=[5;0;V(2);0] function [f]=fun(t,C,V) Ks=23.587; Ki=103.502; Pmax=201.443; ms=0.272; kd=0.054;betamix=2.201; n=0.365; a=2.6; b=-0.282 mumax=2.305*exp(-61.786/V(1))+-15.326*exp(-152.713/V(1)) Yx...
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function r = evalpoly(p,x) //------------------------------------------------------------ // Function: evalpoly - evalutes a polynomial at a given value // // Input: p - a polynomial or a vector with coeff (a0, a1, a2,..) // x - a number // Output: r - the value of the polynomial evaluated at x //---------------...
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void main(void) { struct { int x; } a; a. }
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//Example 6.8(d) clear; clc; Vs=13; A=10; ft=1*10^6; SR=0.5*10^6; f=2*10^3; Vommax=SR/(2*%pi*f); if Vommax>Vs then Vimmax=Vs/A; printf("Useful Input Amplitude Range is Vim<=%.2f V",Vimmax);
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clc; Vt=1; // m^3 d_t=1; // m C_d=0.6; d_o=0.02; // m g=9.8; // m/s^2 a_o=%pi*(d_o)^2/4; A=%pi*(d_t)^2/4; H1=4*Vt/%pi/(d_t)^2; t=A/C_d/a_o*sqrt(2*H1/g); disp("Total drainage is found to take ") disp(t) disp(" seconds");
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clc h1 = 3230.9 // Enthalpy of steam at turbine inlet in kJ/kg s1 = 6.69212// Entropy of steam at turbine inlet in kJ/kgK V1 = 160 // Velocity of steam at turbine inlet in m/s T1 = 400 // Temperature of steam at turbine inlet in degree Celsius h2 = 2676.1 // Enthalpy of steam at turbine exit in kJ/kg s2 = 7.3549...
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6_4.sce
//Ratio of speeds of a generator and motor clc; clear; V=250; Il=80; Ra=0.12; Rf=100;// Field Resistance Ish=V/Rf;// Field Current Ia1=Il+Ish;// Machine Current genrated Ia2=Il-Ish;// Motor Current taken by the motor E=V+(Ia1*Ra);// Generator Induced EMF Eb=V-(Ia2*Ra);// Motor Operating EMF //...
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//ques-2.22 //Calculating weight of air theoretically required and weight of dry flue gas per kg of fuel and weight of air actually used clc C=624;//weight of carbon in coal (in g) H=41;//weight of hydrogen in coal (in g) O=69;//weight of oxygen in coal (in g) N=12;//weight of nitrogen in coal (in g) S=8;//weigh...
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// calculate output across load resistor // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 10-6, page 331 clear;clc; close; // Given data B=200; re=180;// in ohms R1=10*10^3;// in ohms R2=2.2*10^3;// in ohms Rc=3.6*10^3;// in ohms Vg=50*10^-3;// in ...
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clc; //Example 25.2 //Page No 1018 //solution Pt=1000; fb=50*10^6; Tb=(1/fb); disp('s',Tb*10^1,"Tb = "); Eb=Pt*Tb; disp('J',Eb,"Eb = "); disp("Expressed as a log with 1 Joule as the reference, "); eb=10*log10(Eb); disp('dBJ',eb,"Eb = ") disp("It is common to express Pt in dBW and Eb in dBW/bps. Thus, "); p...
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//Given that La = 1 //(say) Ld = 2.0*La ka = 1 //(say) kd = 5.0*ka T1 = 25 //in degree C T2 = 20 //in degree C T5 = -10 //in degree C //Sample Problem 19-6 printf("**Sample Problem 19-6**\n") //The rate of thermal conduction will be same through (a) & (d) //ka*A*(T2-T1)/La = kd*A*(T5-T4)/Ld T4 = T5 - ka*(T2-T1)/La...
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//Example 9.5:diverter resistance clc; clear; close; format('v',6) nf=1;// n2=1.25*nf;// of=1;// of2=nf/n2;// isef=1;// ise2=0.66667;// ia2=(1/ise2);// idiv=ia2-ise2;// rdiv=ise2/idiv;// disp(rdiv*100,"diverter resistance required as percentage of the field resistance is") //answer is wrong in the textbook
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clear; clc; disp(' Example 14.7'); // aim : To determine // the power required to drive the vane pump // given values m_dot = 1;// air capacity, [kg/s] rp = 2;// pressure ratio P1 = 1*10^5;// intake pressure, [N/m^2] T1 = 273+70;// intake temperature, [K] Gama = 1.4;// heat capacity ratio rv = .7;// vo...
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clear;lines(0); ieee(1);1/0 ieee(2);1/0,log(0)
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// this code test the asser visu // given as an input to Andreis function // for step computing //------------- LOAD The Files ---------------------// path=get_absolute_file_path("scilab-src"); disp('HOME:'+path), getd(path + "src/graphisme"); // pour charger un repertoire en entier getd(path + "src/transformation")...
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//Chapter-5, Example 5.18, Page 202 //============================================================================= clc clear //INPUT DATA Ti=30;//Initial temperature of the slab in degree C q=(2*10^5);//Constant heat flux in W/m^2 k=400;//Thermal conductivity in W/m.K a=(117*10^-6);//Thermal diffusivity in...
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//chapter-2,Example2_2,pg 54 aFe=16.65 aAg=2.86 bFe=-0.095 bAg=0.017 aFe_Ag=aFe-aAg bFe_Ag=bFe-bAg a=aFe_Ag b=bFe_Ag Tn=-(a/b) t=100 EFe_Ag=(a*t)+0.5*(b*(t^2)) printf("neutral temp. of Fe-Ag thermocouple\n") printf("Tn=%.3f deg. C",Tn) printf("\nthermo e.m.f of thermocouple\n")...
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// Scilab code Ex9.5: Pg.381-382 (2008) clc; clear; delta_E = 4.77e-04*1.6e-19; // Energy difference, J l = 0; // Rotational level h_cross = 1.055e-34; // Reduced plank's constant, J-s I = h_cross^2/delta_E; // Moment of inertia, ev-s^2 m_1 = 12; // Mass of C, u m_2 = 16; // Mass of O, u mu = ...
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clc; clear; function z=u(x,y) z=x^2+x*y-10 endfunction function z=v(x,y) z=y+3*x*y^2-57 endfunction x=1.5; y=3.5; e=[100 100]; while e(1)>0.0001 & e(2)>0.0001 J=[2*x+y x; 3*y^2 1+6*x*y]; deter=determ(J); u1=u(x,y); v1=v(x,y); x=x-((u1*J(2,2)-v1*J(1,2))/deter); y=y-((v1*...
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//Example 1.18.2: voltage of the capacitor clc; clear; close; format('v',7) r=15;//in ohms l=12;///inductance in mH c=8;//capacitance in micro farads v=100;//in volts t=((%pi)/(sqrt((1/(l*10^-3*c*10^-6))-(r^2/(4*(l*10^-3)^2)))));// time in seconds vc= v*(1-cosd(t/(sqrt(l*10^-3*c*10^-6))));//in volts disp(vc,"the capaci...
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clc; clear; format('v',11); f=1*10^9; c=3*10^8; //velocity of light in air. lemda=c/f; T=1/f; disp("E=-2*sin(2*%pi*z/0.3)","At t=T/4,equation of electric field is "); Zmax1=(%pi/2)*0.3/(2*%pi); Zmax2=(5*%pi/2)*0.3/(2*%pi); Zmax3=(9*%pi/2)*0.3/(2*%pi); Zmin1=(3*%pi/2)*0.3/(2*%pi); Zmin2=(7*%pi/...
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// Program to plot using polarplot function theta= 0:.01:3*%pi; polarplot(sin(2*theta),cos((2*theta))) xtitle('Using polarplot')
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function [v3] = concatenar(v1,v2) for i = 1:length(v1) v3(i) = v1(i) end for i = 1:length(v2) v3(i + length(v1)) = v2(i) end endfunction
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clear// //Variables IE = 10 //Emitter current (in milli-Ampere) alpha = 0.987 //common base current gain //Calculation IC = alpha * IE //Collector current (in milli-Ampere) IB = IE - IC //Base current (in milli-Ampere) //Result ...
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s=%s; syms k H=syslin('c',1+(k/(s*(s+1)*(s+2)))) evans(H,5) d=derivat(H) p=numer(d) a=roots(p) // a=breakaway point disp(a,"breakaway ppoint=")
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Name=psalmflick Strafing Tracking Precise PlayerCharacters=Player BotCharacters=target.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Player AddedBots=target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot;target.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0;0;0;0;0 PlayerTeam=1 BotTeams=0;0;0;0;0;0...
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...