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n=input("Number of input pattern"); x=[] c=1; for i=1:n a=input("Enter a pattern"); x=cat(1,x,a) end wtmat=input("Enter wight matrix"); for i=1:n net=0; for j=1:length(wtmat); net=net+wtmat(j)*x(i,j); end r=sign(net); for j=1:length(wtmat) delt...
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/* Cities Codes Amesterdam 1 Athens 2 Berlin 3 Bern 4 Brussels 5 Budapest 6 Copenhagen 7 Stockolm 8 Helsinki 9 Lisbon 10 London 11 Madrid 12 Oslo 13 Paris 14 Porto 15 Rome 16 Vienna 17 Frankfurt 18 */ //Data nCities = 17 visit_duration = [2 2 3 1 3 ...
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x=[0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100 102 104 106 108 110 112 114 116 118 120 122 124 126 128 130 132 134 136 138 140 142 144 146 148 150 152 154 156 158 160 162 164 166 168 170 172 174 176 178 180]; y=[234...
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clc clear //Input data R1=0.06;//Thickness of material layer in m R2=0.12;//Thickness of the two insulating materials in m R3=0.16;//Thickness of material layers with pipe in m K1=0.24;//Thermal conductivity of one layer in W/mC K2=0.4;//Thermal conductivity of another layer in W/mC L=60;//Length of the pipe in...
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clear // // //Initilization of Variables D_s=20 //mm //Diameter of steel D_Ci=20 //mm //Internal Diameter of Copper t=5 //mm //THickness of copper bar P=100*10**3 //N //Load E_s=2*10**5 //N/mm**2 //modulus of elasticity of steel E_c=1.2*10**5 //N/mm**2 //Modulus of Elasticity of Copper //Calculations A_s=%pi*4**-1*...
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//Scilab Code for Example 4.3 of Signals and systems by //P.Ramakrishna Rao //x(t)=A*cos w0*t*gate(t/T) //T=1/2*fo //fo=0.5 Hz clear; clc; //Fourier Transform A=1; T=0.5; fo=1/(2*T); Wo=2*%pi*fo; for f=-20:1:20; X(f+21)=A*integrate('cos(Wo*t)*cos(2*%pi*f*t)','t',-0.25,0.25); end disp(X,'X(0)-->X(20)'); ...
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clc L=882.1 // in m a = 65*10^(-7)//in ()1 degree F)^-1 Tm=65 To=84 Ct= L * a * (Tm-To) l1=100 k1=2+1/6 l2= 150 k2=4+12/60 l3=50 k3=1+1/10 l4=200 k4=7+48/60 l5=300 k5=3 l6=82.1 k6=5+1/6 Cs= l1*(1-cosd(k1))+l2*(1-cosd(k2))+l3*(1-cosd(k3))+l4*(1-cosd(k4))+l5*(1-cosd(k6))+l6*(1-cosd(k6)) TC=Ct-Cs CL=L+...
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clc; funcprot(0); // Initialization of Variable d=62.4;//displacement in mm H=250.0;//height of datum m r=115.4;//image distance in mm //calculation h=H*d/r; disp(h,"height of chimney in m") clear()
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// Exa 5.1 clc; clear; close; // Given data R = 10;// in k ohm R = R * 10^3;// in ohm C = 0.001;// in µF C = C * 10^-6;// in F f_c = 1/(2*%pi*R*C);// Hz f_c = f_c * 10^-3;// in kHz disp(f_c,"Cutoff frequency in kHz is"); R_F = 100;// in k ohm R1 = 10;// in k ohm A_F = 1+(R_F/R1); disp(A_F,"The passband v...
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clc M=30 //molar mass for ethane in kg/kmol Tc=305.43 //temperature in kelvin Pc=4.884 //pressure in MPa P=70 //pressure in bar Pr=(P*10^5)/(Pc*10^6) mprintf("Pr=%f\n",Pr)//ans vary due to roundoff error M1=7 //mass of ethane present in kg Moles=(M1/M)*1000 //moles of ethane mprintf("Moles of ethane=%fmol\n",M...
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exec('platesD.sci') exec('Doolittle.sci') filas=5 [A b] = platesD(filas,1,1) disp('Ejercicio c:') printf('A:\n') disp(A) printf('\n') printf('b:\n') disp(b) printf('\n') rA = rank(A) rAb = rank([A b]) [n _n] = size(b) if(rA == rAb) if(rA == n) printf('Determinado\n') // Solución por Doolitle lu = Dooli...
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//Graphical// //Example 11.6.1 //Design of wiener filter of Length M =2 clear; close; clc; M =2; //Wiener Filter Length Rdx = [0.6 2 0.6] //Cross correlation matrix between the desired input sequence and actual input sequence C = Rdx(M:$) //Right sided sequence To_M = toeplitz(C) Rxx = [0.6 1 0.6] //Auto cor...
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clear //Given a=10 b=2 c=3 //Calculation Vce=a-b Ic=c-b Ro=Vce/Ic //Result printf("\n The output resistance is %0.3f k ohm",Ro)
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// Example 7.9;//overall power clc; clear; close; Pdc=300*10^-6;//d.c. power in watt f=20*10^6;//frequency in hertz Ti=5*10^-9;//recombination life time in nano second Pe=(Pdc*sqrt(1+(2*%pi*f*Ti)^2))*10^6; disp(Pe,"overall power in micro watt")
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calibSimplexMeanSquares_11:58:13.350 AM 07-juin-2013.sci
ms=[];incomemean=[];bref=[];bnorm=[]; ms(1)=4.837358271377804E7; incomemean(1)=17000; bref(1)=12000; bnorm(1)=30000; ms(2)=4.8155241393382326E7; incomemean(2)=17000; bref(2)=13000; bnorm(2)=30000; ms(3)=5.092290478630149E7; incomemean(3)=17000; bref(3)=12000; bnorm(3)=31000; ms(4)=1.8876618021012735E7; incomemean(4)=18...
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clc clear mprintf("entre com o primeiro nº")
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// Scilab Code Ex3.10: Page-106 (2013) clc; clear phi = 2.36; // Work function of sodium, eV N_A = 6.02e+023; // Avogadro's number e = 1.6e-019; // Energy equivalent of 1 eV, J I = 1e-008; // Intensity of incident radiation, W/Sq.m K = 1.00; // Kinetic energy of the ejected photoelectron, eV rho =...
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//Ex 5.1 clc; clear; close; format('v',5); V1=2;V2=3;V3=4;V4=5;//V R1=10;R2=15;R3=22;R4=50;//kohm Rf=10;//kohm Vout=-Rf/R1*V1-Rf/R2*V2-Rf/R3*V3-Rf/R4*V4;//V disp(Vout,"Output voltage of the circuit(V)");;
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function r=%r_n_r(l1,l2) //%r_n_r(l1,l2) <=> l1<>l2 for rational matrices //! // Copyright INRIA r=l1('dt')<>l2('dt') if ~r then r=l1('num')<>l2('num')|(l1('den')<>l2('den')&l1('num')<>0) end
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//Example 1_16 page no:33 clc; R1=5 R2=6 R3=3 R4=3 R5=10 R6=6 R7=2 R8=4 V=100; R9=1/((1/(R7+R8))+(1/R6));//calculating the resistances R10=1/((1/(R3+R4))+(1/R2)); Rt=1/((1/13)+(1/8)); It=V/Rt; I8=20.2*(13/(13+8)); I13=20.2*(8/(13+8)); I5=I8; I10=I13; I4=3.845; I3=6.25; Va=I3*3; Vb=I4*4; Vab=Va-Vb...
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clear; clc; //Example3.8[Heat Loss through an Insulated Steam Pipe] //Given:- T_steam=320;//[degree Celcius] T_surr=5;//[degree Celcius] k_iron=80;//Thermal conductivity of cast iron[W/m.degree Celcius] k_insu=0.05;//Thermal conductivity of glass wool insulation[W/m.degree Celcius] h_out=18;//Covection heat t...
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//Fluid Systems - By Shiv Kumar //Chapter 17- Dimensional and Model Analysis //Example 17.21 //To Find the Ship Velocity and Propulsive Force in the Prototype. clc clear //Given Data:- //For Model, Lm=1; //Length of Model, m Vm=0.7; //Speed in the Model, m/s F...
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clear// //Case a : //Variables R = 8.0 //Resistance (in ohm) P1 = 60.0 //Power (in watt) //Calculation I1 = (P1/R)**0.5 //Current (in Ampere) //Case b : //Variables R = 8.0 //Resistance (in ohm) P2 = 120.0 //Power (in watt) //Calculation I2 = (P2/...
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//Example 6_8 clc(); clear; //To determine the velocity of the third piece momentumbefore=0 //units in kg meter/s m=0.33 //units in Kgs vz=momentumbefore/m printf("The Z component of velocity is Vz=%d meters/sec\n",vz) m=0.33 //units in Kgs v0=0.6 //units in meters/sec vy=-(m*v0)/m //interms of...
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//=========================================================================== //chapter 7 example 5 clc;clear all; //variable declaration f = 50; //frequency in Hz L = 5*10^-3 //inductance V = 100; //voltage in V I = 10; //current in A R1 = 3000; //resistance in Ω //calculations x = ((2*%pi*f*L...
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//Engineering and Chemical Thermodynamics // Example 3.13 //Page no:137 clear ; clc ; //Given Ws_real = -2.1 ; //[MW] Ws_rev = -2.8 ; // [MW] n_tur = Ws_real / Ws_rev ; disp(" Example: 3.13 Page no : 137") ; printf("\n Isentropic efficiency of turbine = %.2f %%", n_tur * 100);
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clc //Chapter7 //Ex_12 //Given Eo=8.85*10^-12//F/m2 Er=1000 D=3*10^-3 //in m V=5000 // in V d=200*10^-12 //in m/V L=10*10^-3 //in mm A=%pi*(D/2)^2 F=Eo*Er*A*V/(d*L) disp(F,"Force required to spark the gap in Newton is")
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[[i= partials/header ]] [[i= partials/navbar ]] <div class="container"> <div class="flex row product"> <div class="container center productImg"> <img src="/assets/img/products/defaultImage.svg" alt="img"> <input type="text" name="image" placeholder="defaultImage.svg" disabled...
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clc; clear; disp("efficiency(n)=(useful power/total power)*100%"); disp(" =total sideband power/(total sideband power+carrier power)*100%"); syms m Pc N=[((m^2)*Pc/2)/(Pc*(1+(m^2)/2))]; disp("*100% ",N); disp("----------------------------------------------------------------"); m=0.7 //modulation index...
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//init clear; clf; //define function //positive definite? function [ispos] = isPos(X) ev = spec(X); ispos = "POSITIVE"; for i = ev', if real(i) < 0.0 then ispos = "NON-POSITIVE"; end, end endfunction //parameters of th...
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// Function Name: normalize // Return its normalised version, has been normalised to have unit p-norm(3rd parameter) // Calculating the normalize inputMat = [ 1, 2, 3; 4, 5, 6; 7, 8, 10;] result = armaMatFunc("normalize",inputMat)
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//Scilab Code for Example 6.1 of Signals and systems by //P.Ramakrishna Rao //Sampling of signal clc; clear f n X X_delta w; fs=200; for f=-200:200 X(f+201)=5*[delta(f-75)+delta(f+75)]; end figure(1); f=-200:200; plot2d3(f,X,-2); title('X(f)'); xlabel('---> f'); w=1; n=-1; for f=-275:275 X...
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function [best_fit, best_individual]=bestFitness(populacao) pop_fit = fitnessFunction(populacao); best_fit=pop_fit(1); best_individual=1; for i=2:length(pop_fit) if(pop_fit(i)>best_fit) best_fit = pop_fit(i); best_individual=i; end end disp("Be...
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clc; //From table 14.2 at 25 oC and 1 atm for C8H8 del_Ho=-2039.7; // LHV in MJ/kmol // Combustion equation is C3H8+ 5O2 +18.8N2 → 3CO2 +4H2O +18.8N2 // From table 14.3 h333_C3H8=2751; // h333_h298 of C3H8 in kJ/kmol h333_O2=147; // h333_h298 of O2 in kJ/kmol h333_N2=145; // h333_h298 of N2 in kJ/kmol h1333_CO2...
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// // This help file was automatically generated from hrtFrameCommand.sci using help_from_sci(). // PLEASE DO NOT EDIT // mode(1) // // Demo of hrtFrameCommand.sci // //========= E N D === O F === D E M O =========// // // Load this script into the editor // filename = "hrtFrameCommand.sce"; dname = get_absolute_file_...
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//given u=160,g=10,h=240 clear clc close //using the formulae "h=u*t-(g*t^2)/2" u=160; g=10; h=240; t=poly(0,'t'); r=(240-u*t+(g*t^2)/2)//u*t-(g*t^2)/2-h=0 a=5;b=-160;c=240;//from equation we get these values //using the formulae - solution of quadratic equation ax^2+bx+c=0 t=(-b+sqrt(b^2-4*a*c))/(2*a);...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 9 //Chemical Reaction Equilibria //Example 9 clear; clc; //Given: //Reaction: N2(g) + 3H2(g) --> 2NH3(g) To = 298; //temperature in K T = 700; //(K) R = 8.314; //ideal gas constant Hf = -46100; //standard heat of formation (J/mol) Gf = -1...
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//clear// clear; clc; //Example 5.1 // Given mu = 0.004; //[kg/m-s] D = 0.0779;// [m] rho = 0.93*998; //[kg/m^3] L = 45; //[m] //For fittings, form Table 5.1 sum_Kf = 0.9 + 2*0.2; //From Eq.(4.29), assuming alpha_a = 1, // since pa = pb, and Va_bar = 0 //A = Vb_bar^2/2 + hf = g*(Za-Zb) A = 9.80665*...
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// Example 7.5.2 page 7.24 clc; clear; R=0.6; //responsivity Pin=15; //optical power in microwatt Ip=R*Pin; //computing photocurrent printf("\nPhotocurrent generated is %d microAmpere.",Ip);
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clc //initialisation of variables dq=-80 dv=0.091*10^-6//m^3 p=1.013*10^5//n/m^2 //CALCULATIONS du=dq-(p*dv/46) //results printf(' \n change in internal energy= % 1f cal',du)
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//exa 1.7 clc;clear;close; format('v',9); dmax=40;//MW//Maximum demand CF=0.5;//Capacity Factor UF=0.8;//Utilisation Factor LF=CF/UF;///Load Factor disp(LF,"(a) Load Factor : "); C=dmax/UF;//MW//Plant Capacity disp(C,"(b) Plant Capacity(MW) : "); RC=C-dmax;//MW//Reserve Capacity disp(RC,"(c) Reserve Capacity...
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//example 3.1 clear; clc; //given: V1=14;//initial volume of cylinder in m3 V2=9;//final volume of cylinder in m3 P=2000;//pressure during the operation in N/m2 U=(-6000);//internal energy of the system in J //to find energy transfered in form of heat: W=-P*(V2-V1);//work done during the operation in J ...
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clear // // // //Variable declaration h=6.63*10^-34; //planck's constant(J-sec) m=1.673*10^-27; //mass of proton(kg) v=10^4; //velocity of proton(m/sec) V1=100; //potential difference in 1st case(V) V2=10000; //potential difference in 2nd case(V) V3=6400; //potential dif...
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m=36;//kg acc=7;//ft/sq sec
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clc; //page no 420 //problem no 12.4.2 //a binary unipolar waveform with following specifications are given A=4;//max value of received signal voltage Vn=0.5;//rms noise voltage Vth=2;//Threshold voltage for the comparator Pbe=1/2 * b;// bit error probability disp(Pbe,'The bit error probability');
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function [keys, values] = http_urldecode(URL) // This function converts a URL-encoded set of key-value pairs to a // pair of Scilab vectors corresponding to the keys and values respectively endfunction
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clear; clc; printf("\t\t\tExample Number 7.12\n\n\n"); // heat transfer across evacuated space // Example 7.12 (page no.-351-352) // solution E = 0.06;// emmisvity of polished aluminium plate d = 0.025;// [m] seperation between plates p = 101325*10^(-6);// [Pa] pressure of air between plates T1 = 100;// [de...
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//Example 7.7: Acceleration, Coasting and Braking periods clc; clear; close; //given data : S=1.6;// in km Va=40;// in km/h V1=64;// in km/h alfa=2.0;//in km/p/sec Beta_c=0.16;// in km/h/sec Beta=3.2;// in km/h/sec t1=V1/alfa;// in sec disp(t1,"Duration of Acceleration,t1(sec) = ") T=(S*3600)/Va;// in sec // Formula: T...
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//Example 4.3, Page Number 158 //The Function fpround(dependency) is used to round a floating point number x to n decimal places clc; d=0.2*(10**-3) //Chip Diameter in meter d1=1 //Distance in Meter l=550*(10**-9 ) //Wavelength in Meter q=0.001 //External Quantum Efficiency i=50*(10**-3) //Operational Current ...
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clc; //Example 10.8 //Page No 418 //solution s=8; //(a) disp("(a)With the 7 bit PCM,"); b=7; r=s*b; disp('kbps',r,"line speed = "); //(b) disp("(b)With the 8 bit PCM, "); b1=8; r1=s*b1; disp('kbps',r1,"line speed = ");
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear; //example 6.3 //calculation of series resistance ,damping resistance and maximum output voltage of the generator //given data n=8//number of stages C=0.16*10^-6//value of condenser(in farad) Cl=1000*10^-12//value of load capacitor (...
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// Csae study: Chapter-8, Page No:253 // 2.Processing of a customer list CUSTOMERS=10; printf(" Input names and telephone numbers\n"); printf(" [Names must have First,Second and Last_name]\n"); for i=1:CUSTOMERS //Read data [first_name(i),second_name(i),surname(i),...
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clc; F=50-30; //force in lb w1=50; //weight in lb w2=30; //weight in lb m=(w1+w2)/g; //calculating mass disp(m,"Mass in slugs = "); //displaying result a=F/m; //Newton's Law disp(a,"Accelaration in ft/sec square = "); //displaying result
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//chapter8,Example8_9,pg 184 alpha=((%pi*10)/(60*60*180))//converting into radian B=0.5//fringe width u=1.4 lam=2*B*alpha*u printf("wavelength of light used\n") printf("lam=%.12f m",lam)
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clc //initialisation of variables P= 10 //atm Kp= 0.1719 //CALCULATIONS a= sqrt(Kp/(10+Kp))*100 //RESULTS printf (' percentage = %.f percent',a)
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clc clear x=5 z=26 iter=5 bob=1000 se=zeros(1,iter) vo=zeros(1,iter) a=zeros(1,z) cap=[288 95 115 133 107 22 34 186 190 33 56 100 90 82 143 68 166 44 73 72 60 68 15 8 20 29] tim=[0 12 6.2 5.6 27 17 20 44 18 16 23 24 34 11 9 11 11 13 17 14 30 25 30 28 27 33; 12 0 5.2 9.9 39 29 32 52 29 27 34 36 46 23 20 23 15 18 24 21 3...
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//<f>=%ssr(m,f) // %ssr(m,f) soustrait la matrice de fractions rationnelles f a la //matrice de scalaires m. //Cette macro correspond a l'operation m-f //! [t,n2,d2]=f(1:3), if sum(size(m))=-2 then m=m*eye(d2); end; [n2,d2]=simp(m.*d2-n2,d2) f=list(t,n2,d2,f(4)) //end
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clear; clc; //Example 2.10 printf("Example 2.10") A= 1 //sq m x1=0.15 x2=0.01 x4=0.15 T1=973 //[K] T2=288 //[K] dT=T1-T2 //[K] //Thermal conductivities k1=1.75 k2=16.86 k3=0.033 k4=5.23 //in absence of air gap,sum of thermal resistances sR=(x1/k1*A)+(x2/k2*A)+(x4/k4*A) Q= dT/sR printf("Heat los...
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[a]=ex13f([1,2,3]+%i*[4,5,5]); if norm(a-2*[1,2,3]-%i*[4,5,5]*3) > %eps then pause,end [a]=ex13f([1,2,3]); if norm(a-2*[1,2,3]) > %eps then pause,end
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#************************************************************ # Scenario of radiateur # # date : Wed Nov 24 14:33:26 2004 #************************************************************ p3d_sel_desc_name P3D_ENV radiateur p3d_sel_desc_name P3D_ROBOT radiateur p3d_set_robot_steering_method Linear p3d_set_robot_curre...
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clc //given Tb=27 Tc=30 Td=24 Te=21 k=Te*Tb/(Tc*Td)//k=Nd/Ne //by applying componendo and dividendo, using Ne=0 and reducing we get a=(1-k)//where a = Nd/Na b=1/a printf("\nThe ratio of the speed of driving shaft to the speed of driven shaft\n\nNa/Nd = %.2f",b)
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clear; clc; // Example: 9.10 // Page: 354 printf("Example: 9.10 - Page: 354\n\n"); // Solution //*****Data******// x1 = 0.3;// [mole fraction of component 1 in the mixture] x2 = 0.7;// [mole fraction of component 2 in the mixture] phi1 = 0.7;// [fugacity coeffecient of component 1 in the mixture] phi2...
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//Exa 6.7 clc; clear; close; //given data L=3;// in m delta=0; hx='10*x^(-1/4)' // (a) Average heat transfer coefficient h=1/L*integrate(hx,'x',delta,L); disp("(a) Average heat transfer coefficient is : "+string(h)+" W/m^2K") // (b) Heat transfer rate A=3*.3;// in m^2 Tp=170;// plate temp. in degree C T...
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// // // clear; clc; getd('../lib'); getd('.'); // exemplo do livro Algoritmos Numéricos, 2a. ediçao x = [ 1.2 2.5 3.0 4.1 6.2 7.1 8.8 9.5]; y = [ 6.8 6.1 9.9 9.7 12.1 17.9 18.0 21.5]; [b1 b0 r2 s2] = reglin_simples(x, y, %T); x_reg = linspace(0,10,1000); y_reg = b1*x_reg + b0; plot(x, y, 'g.'); plot(x_reg, y_reg...
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xlyu V;HAB;1 xlyu V;PFV;1 xlyu V;PFV;3 xlyu V;HAB;3 xlyu V;PROSP;2 xlyu V;PROSP;1 xlyu V;HAB;2 xlyu V;PROG;3 xlyu V;PROSP;3 xlyu V;PROG;2 xlyu V;PROG;1 xlyu V;PFV;2 lya V;PROG;2 lya V;PROSP;1 lya V;PROG;1 lya V;PFV;3 lya V;HAB;3 lya V;HAB;1 lya V;PROSP;2 lya V;PROSP;3 lya V;HAB;2 lya V;PFV;2 lya V;PROG;3 lya V;PFV;1 jl...
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clc u_m = 0.8 // mean velocity in m/s D = 5 // Diameter in cm v = 4.78e-7 // dynamic coefficient of viscosity Pr = 2.98 // Prantl number K = 0.66 // Thermal conductivity in W/mK l = 3 // length of pipe in m tw = 70 // Wall temperature tf = 50 // mean water temperature printf("\n Example 18.9\n") Re = u_m*D*1e...
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// Calculation function ans = f1(x1,x2) ans = 6*exp(-2*x1-3*x2) endfunction // (A) x1 limit- (0,1) x2 limit- (0,1) p1 = feval([0,1],[0,1],f1) p = p1(2) // Result printf ( "P(x1<1 and x2<1): %.3f",p) // Note : Answer may vary because scilab use feval function and it calculates differently.
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//Chapter-5,Example5_15_5,pg 5-44 //for an electron e=1.6*10^-19 //electron charge m_e=9.1*10^-31 //mass of an electron L=10^-9 //width of well h=6.63*10^-34 //Plank's consta...
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disp('Vectors u an v are:') u=[-1;2] v=[4;6] disp(v,u) disp('Projection of v on u=(u.v)/(v.v)') a=u'*v b=u'*u p=a/b disp(p,'=')
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disp('Division Algorithm') a=4461; //dividend b=16; //divisor r=modulo(a,b) //remainder k=fix(a/b) //quotient j=b*k+r //dividend=divisor*quotient+remainder a=-262; //dividend b=3; //divisor k=fix(a/b) //remainder r=modulo(a,b) //quotient j=b*k+r //dividend=divisor*quotient+remainder disp(...
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// problem 2.11 d=4 h=4 s=0.6 s1=1 h1=s*h/s1 v=3.142*d*d*0.25*h1 x=h1/2 cog=h/2 h2=cog-x a=3.142*d*d*d*d/64 bm=a/v mh=bm-h2 disp(mh,"metacentric height in m,negative sign indicte that cylinder is in unstable equilibrium")
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// @Harness: verifier // @Purpose: "Test for arity mismatch in subroutine calls" // @Result: "ArityMismatch @ 8:8" architecture arity_02 { external subroutine a(x: int): void; subroutine b(): void { a(); } }
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clc clear //Input data //Data from combustion chart p=[1,33,33,1]//Pressure of air fuel mixture in kg/cm^2 T=[65,600,1450,725]//Temperature of air fuel mixture in K V=[16,1.23,3.45,16]//Volume in m^3/kg U=[11.8,110,295,140]//Internal energy in kcal/kg H=[22.7,150,395,225]//Enthalpy in kcal/kg S=[0.068,0.068,0....
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function [rectMat]=boundingRect(points) rectMat=opencv_boundingRect(points); endfunction
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// Chapter9 // Page.No-444 // Example_9_11 // Design of voltage regulator // Given clear;clc; Vo_min=5; // Min output voltage in volt Vo_max=12; // Max output voltage in volt Vref=1.25; // Reference voltage in volt Iadj=100*10^-6; // Adjustment pin current in ampere R1=240; // Assumption R2_min=R1*(Vo_min-Vr...
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//find clc //solution //given L=500//mm Nm=900//rpm Nc=200//rpm T=5000//N-m Tmax=1.25*T vr=Nm/Nc //Dp+Dg=(L*2)...eq1 //Dg=vr*Dp....eq2 //usieng eq1 and eq2 Dp=182//mm Dg=4.5*Dp/1000//m v=%pi*Dg*Nc/60//m/s Cv=3/(3+v) fog=140 //yg=.175-(0.841/Tg)=0.175-0.841*m/Dg...Tg=Dg/m //yg=0.175-0.001m Wt=2*Tmax/...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 10.15\n\n\n"); // Chapter 10 : Refrigeration // Problem 10.15 (page no. 539) // Solution //THE HEAT PUMP T1=70+460; //70F=70+460 R //Energy flows into the system at reservoir at constant temperature T1(unit:R) //from problem 10.1 T2=32+460; //32F=32+4...
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//Section-14,Example-4,Page no.-PC.77 //To calculate pressure of CO. clc; K_p=4*10^-2 Kbar_p=2 p_CO=sqrt(K_p*Kbar_p) disp(p_CO,'Required pressure of CO')
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// Sp_Example 3.4 clear; clc; close; format('v',6); // Given data Nr=4;//poles La=10.7;//in mH Lu=1.5;//in mH i=7;//in A q=3;//phase //Calculations lambda_a=La*10^-3*i;//in Wb/T lambda_u=lambda_a;//in Wb/T i2=lambda_u/Lu/10^-3;//in Ampere Wm=(i2-i)*lambda_u/2;//in Jooules disp(Wm,"Energy conversion ...
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function [x,fval] = fseminf(fun,x0,ntheta,seminfcon,w,s,A,b,Aeq,beq,lb,ub) fsinfObjfun = fun fsinfStartpoint = x0 intervals = w samplespace = s fsinfA = A fsinfb = b fsinfAeq = Aeq fsinfBeq = beq fsinflb = lb fsinfub = ub [v,t1,t2] = seminfcon(fsinfStartpoint,[0 0]) //d...
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//EXAMPLE 3-24 PG NO-189 W1=-1200; W2=3400; P=W1+W2; disp('iv) Power (P) is = '+string (P) +' W '); X=[sqrt(3)*(W2-W1)]/P; disp('iv) (tan (Q)) is = '+string (X) +' ');
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 12 Example 9") T1=(1200+273);//temperature of body in K T2=(600+273);//temperature of black surrounding in K epsilon=0.4;//emissivity of body at 1200 degree celc...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 8: BRAKING // EXAMPLE : 8.3 : // Page number 810 clear ; clc ; close ; // Clear the work space and console // Given data ...
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clc // Given that V_Cd=-0.403 //Half Cell Potential of Cd++|Cd in volt V_Ni=-0.250 //Half Cell Potential of Ni++|Ni volt C_Ni=10^-3 C_Cd=0.5 n=2 //Net electron exchange in Redox reaction printf(" Example 16.1\n") printf("\n Part A:") dV=V_Ni-V_Cd // Potential difference in volts printf("\n Standard C...
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// Scilab code Ex3.10: Pg 90-91 (2008) clc; clear; C_1 = 6e-06; //Capacitance, F C_2 = 4e-06; //Capacitance, F V = 150; // Supply voltage, V // Part (a) // The reciprocal of the resulting capacitance of capacitors connected in series is the sum of the reci...
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//Example 2.13 (a) //MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS PROGRAM //Z- transform of (-1/5)^n u(n)+5(1/2)^(-n)u(-n-1) clear; clc ; close ; syms n z; x1 =(-1/5)^n ; X1= symsum (x1 *(z^(-n)),n ,0, %inf ); x2 =(1/2)^(-n); X2= symsum (5* x2 *(z^(-n)),n ,0, %inf ); X = (X1 -X2); //Display the result in comman...
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// Exa 5.9 clc; clear; close; format('v',6) // Given data W1 = 300;// in kW W2 = 100;// in kW V_L= 2000;// in V Eta= 90/100; P = W1+W2;// in kW disp(P,"The power input in kW is"); // tan(phi) = sqrt(3)*((W1-W2)/(W1+W2)); phi = atand(sqrt(3)*((W1-W2)/(W1+W2))); pf = cosd(phi);// power factor disp(pf,"The ...
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s = poly(0,'s'); k1_range = [.001, .01, .1, 1]; t = 0:.1:75; steps = zeros(length(t), length(k1_range)); impulses = zeros(length(t), length(k1_range)); for i = 1:length(k1_range) k1 = k1_range(i) k2 = k1/5; G = (s+k1)/(s+k2); G = syslin('c',G); steps(:, i) = csim('step', t, G); impu...
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ieee-sqrts.tst
* *Testcase ieee-sqrts.tst: IEEE Square Root, Convert From/To Fixed *Message Testcase ieee-sqrts.tst: IEEE Square Root, Convert From/To Fixed *Message ..Includes SQUARE ROOT (5), CONVERT FROM/TO FIXED 32 (6), 11 instr total * * SQUARE ROOT tests - Binary Floating Point * # # Tests five square root instructions: # SQU...
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//Finding the values of the Snubber Circuit for a thyristor cicuit //Example 7.4(Page No- 340) clc clear //given data dv = 100;//V/us; I_TD = 100;//A R = 5;//Ohm L = 0;//H Ls = 0; fs = 2*10^3;//Hz Vs = 200;//V //part(a) Rs = Vs/I_TD; Cs = ((0.632*R*Vs)/(100*(R+Rs)^2)); printf('(a) Rs : %d Ohm',Rs); pr...
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clc; // page no 680 // prob no 18_4 T_sky=120;// Sky temp expressed in K L_dB=2;// antenna feedline loss L=10^(L_dB/10); // the noise temp is given as Ta=((L-1)*290 + T_sky)/L; disp('K',Ta,'Noise temperature is' );
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---------------------------------------------------------------------------------------- --Create View CREATE OR REPLACE VIEW tblDecisionTreeMulti_VW AS( SELECT OBSID, VARID, NUM_VAL AS Value FROM tblDecisionTreeMulti); -- Execute Stored Procedure -- note: alter table column VAL to VALUE in tblDTData. SELECT '***** E...
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isEpipoleInImage.sci
function [isepi, varargout ] = isEpipoleInImage(fundamental_matrix, imagesize) // Find whether image contains epipole. // // Calling Sequence // isepi = isEpipoleInImage(F, imagesize) // [isepi, epipole] = isEpipoleInImage(F, imagesize) // // Parameters // F : A 3 * 3 fundamental matrix computed from stereo images. It ...
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example18_8.sce
clc // Given that r = 0.6e-10 // radius of the atom N = 28e26 // no. of electron in per m^3 mu_ = 4 * %pi * 1e-7 // magnetic permeability of space Z = 2 // atomic no. of helium m = 9.1e-31 // mass of an electron in kg e = 1.6e-19 // charge on an electron in C // Sample Problem 8 on page no. 18.24 printf("\n # PROBLEM...
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clc,clear printf('Example 5.19\n\n') VA=2000*1000 V_L=11000,V_ph=V_L/sqrt(3) R_a=0.3,X_s=5 //armature resistance and synchronous reactance //case (i) phi=acos(0.8) //lagging I_L=VA/(sqrt(3)*V_L) , I_a=I_L E_ph = sqrt((V_ph*cos(phi)+I_a*R_a)^2 +(V_ph*sin(phi)+ I_a*X_s)^2) //Using E_ph = sqrt((V_ph*cos(ph...
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## DO NOT EDIT! Generated automatically from test/libieeep1788_tests_num.itl ## by the Interval Testing Framework for IEEE 1788. ## https://github.com/nehmeier/ITF1788/tree/92558f7e942665a78f2e883dbe7af52320100fba ## ## Copyright 2013-2015 Marco Nehmeier (nehmeier@informatik.uni-wuerzburg.de) ## Copyright 2015-2016 Ol...
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//5.5 clc; emf_std_cell=1.0183; emf_cell=70/50*emf_std_cell; printf("e.m.f. of the cell=%.2f V",emf_cell) V_read=1.35; V_cal=1.32379; error_voltmeter_percent=((V_read-V_cal)/V_cal)*100; printf("\nPerentage error of the voltmeter=%.2f",error_voltmeter_percent)