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clc // Given That x = 2.948e-5 // distance moved by movable mirror in meter n = 100 // no. of fringes cross the field of view // Sample Problem 51 on page no. 1.58 printf("\n # PROBLEM 51 # \n") lambda = 2*x/n // calculation for wavelength of monochromatic light printf("\n Standard formula used \n lambda = 2*x/n. \n") printf("\n Wavelength of monochromatic light = %f A.",lambda * 1e10)
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clc //initialization of variables w1=2 //lbm w2=1 //lbm P=30 //lbm/in^2 T=60+460 //R //calculations R1=35.1 R2=55.1 Rm=(w1*R1+w2*R2)/(w1+w2) vm=(w1+w2)*Rm*T/(144*P) p1=w1*R1*T/(144*vm) p2=w2*R2*T/(144*vm) //results printf("Gas constant of the mixture = %.1f lb/in^2",Rm) printf("\n Volume of the mixture = %.1f ft^3",vm) printf("\n Partial pressure of CO2 = %.1f lb/in^2",p1) printf("\n Partial pressure of N2 = %.1f lb/in^2",p2)
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clc clear //Input data Z=70;//Vaccum gauge reading in cm of Hg Pa=101.325;//Atmospheric pressure in kPa d=13.6*10^3;//Density of Hg in kg/m^3 g=9.81;//Gravity in m/sec^2 //Calculations Pv=(d*g*Z)/10^5;//Vaccum pressure in kPa Pab=Pa-Pv;//Absolute pressure in kPa //Output printf('Absolute pressure Pab = %3.4f kPa ',Pab)
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function [stk,txt,top]=sci_subplot() // Copyright INRIA txt=[] if rhs==1 then if isnum(stk(top)(1)) then m=evstr(stk(top)(1)) p=modulo(m,10) n=modulo((m-p)/10,10) m=round((m-p-10*n)/100) j=int((p-1)/n) i=p-1-n*j rect=[i/n,j/m,1/n,1/m] i=string(i);j=string(j),n=string(n);m=string(m) e='xsetech('+lhsargs([i+'/'+n,j+'/'+m,'1/'+n,'1/'+m])+')' stk=list(e,'0','0','0','0') else stk=list('mtlb_subplot('+stk(top)(1)+')','0','0','0','0') end elseif rhs==0 then stk=list('xsetech([0 0 1 1])','0','0','0','0') else i=gettempvar(1) j=gettempvar(2) p=stk(top)(1) m=stk(top-2)(1) n=stk(top-1)(1) if stk(top-1)(2)=='2' then n='('+n+')',end if stk(top-2)(2)=='2' then m='('+m+')',end txt=j+' = int(('+p+'-1)/'+n+');'+i+' = '+p+'-1-'+n+'*'+j e='xsetech('+lhsargs([i+'/'+n,j+'/'+m,'1/'+n,'1/'+m])+')' stk=list(e,'0','0','0','0') top=top-2 end
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// Example 34_16 clc;funcprot(0); //Given data CC_kw=15000;// Capital cost/kW installed TP=2200;// Total power of the diesel power plant in kW AOC=600000;//Annual operating costs in rupees FC=100000;// Fixed cost in rupees VC=200000;// Variable cost in rupees AMC=FC+VC;// Annual maintainence costs in rupees Cf=0.8;// Cost of fuel per kg in rupees Clo=40;// Cost of lubricating oil per kg in rupees CV=40000;// kJ/kg cf=0.5;// Consumption of fuel in kg/kWh clo=1/400;// Consumption of lubricant oil in kg/kWh MD=1600;// Maximum demand in kW F_l=45/100;//Load factor //Calculation CC=ceil (TP*CC_kw);// Capital costof the plant in rupees/ year; I=ceil(CC*(15/100));// Interest on capital AE=ceil(MD*F_l*8760);// Annual energy generated in kWh/year F_c=ceil(cf*AE);// kg/year Fc=ceil(F_c*Cf);// Cost of fuel in rupees per year Lc=ceil(clo*AE);// Lubrication consumption in kg /year CLO=ceil(Clo*Lc);//Cost of lubricant oil Rs/year TFC=ceil(I+FC);// Total fixed cost in kg/year TRC=ceil(Fc+Lc+VC+AOC);// Total running cost in Rs/year Tc=ceil(TFC+TRC);// Total cost in Rs/year Gc=(Tc/AE);// Generation cost in Rs/kWh. printf('\nThe annual energy generated=%0.1e kWh/year \nThe cost of generation=Rs.%0.2f/kWh',AE,Gc); // The answer provided in the textbook is wrong
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//Section-8,Example-1,Page no.-IC.9 //To calculate the lattice energy of NaCl crystals from the given data. clc; N_o=6.023*10^23 A=1.748 Z1=1 //Z+ Z2=1 //Z- e=1.602*10^-19 e_o=8.854**10^-12 r_o=0.2814*10^-9 n=8 U_c=((-N_o*A*Z1*Z2*e^2)/(4*%pi*e_o*r_o))*(1-(1/n)) disp(U_c,' Lattice energy of NaCl crystals(kJ/mol)')
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//Exa 4.2 clc; clear; close; format('v',8); //Given Data : T1=290+273;//Kelvin T2=8.5+273;//Kelvin Q1=300;//KJ //Case 1 : Q2=-215;//KJ sigmaQbyT=Q1/T1+Q2/T2 disp(sigmaQbyT,"(i) Q1/T1+Q2/T2 = "); disp("It is less than zero. Cycle is irreversible") //Case 2 : Q2=-150;//KJ sigmaQbyT=Q1/T1+Q2/T2 disp(sigmaQbyT,"(ii) Q1/T1+Q2/T2 = "); disp("It is equal to zero. Cycle is reversible"); //Case 3 : Q2=-75;//KJ sigmaQbyT=Q1/T1+Q2/T2 disp(sigmaQbyT,"(iii) Q1/T1+Q2/T2 = "); disp("It is greater than zero. Cycle is impossible.");
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//chapter 7 //Example 7.8 //Page 187 //directZbus clear;clc; //Given Impedances Z10 = %i*1.2; Z21 = %i*0.2; Z23 = %i*0.15; Z13 = %i*0.3; Z30 = %i*1.5; //1*1 bus Zbus = Z10; disp('1X1 bus impedance matrix with bus 1 and reference bus') disp(Zbus) //to establish bus 2 [m,n] = size(Zbus) for i = 1:m for j = 1:n Zbus(2,i) = Zbus(i,j); Zbus(i,2) = Zbus(i,j) end end Zbus(2,2) = Z10 + Z21; disp('After establishing bus 2') disp(Zbus) //to establish bus 3 with impedance connecting it to bus 1 [m,n] = size(Zbus) for i = 1:m for j = 1 Zbus(3,i) = Zbus(i,j); Zbus(i,3) = Zbus(i,j); end end Zbus(3,3) = Z10 + Z13; disp('Connecting a impedance between bus 3 and 1') disp(Zbus) //to add an impedance from bus 3 to reference [m,n] = size(Zbus) for i = 1:m for j = 1:n Zbus(4,i) = Zbus(i,j); Zbus(i,4) = Zbus(i,j) end end Zbus(4,4) = Zbus(3,3) + Z30; disp('After adding impedance from bus 3 to reference') disp(Zbus) [m1,n1] = size(Zbus); Z_new = zeros(m1-1,n1-1); for c = 1:m1-1 for d = 1:n1-1 Z_new(c,d) = Zbus(c,d) - ((Zbus(c,4)*Zbus(4,d)) / Zbus(4,4)); end end disp('After elemination of 4th row and column') disp(Z_new) //to add the impedance between buses 2 and 3 Z_new(1,4) = Z_new(1,2) - Z_new(1,3); Z_new(2,4) = Z_new(2,2) - Z_new(2,3); Z_new(3,4) = Z_new(3,2) - Z_new(3,3); Z_new(4,1) = Z_new(1,4); Z_new(4,2) = Z_new(2,4); Z_new(4,3) = Z_new(3,4); Z_new(4,4) = Z23 + Z_new(2,2) + Z_new(3,3) - 2*Z_new(2,3); disp('After adding impedance between buses 2 and 3') disp(Z_new) [m1,n1] = size(Z_new); Zbus_new = zeros(m1-1,n1-1); for c = 1:m1-1 for d = 1:n1-1 Zbus_new(c,d) = Z_new(c,d) - ((Z_new(c,4)*Z_new(4,d)) / Z_new(4,4)); end end disp('The Bus Impedance Matrix is') disp(Zbus_new)
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// Example 2.18 page no-72 clear clc //(a) sigma=100 //Ohm-cm e=1.6*10^-19 //c mup=1800 //cm^2/V-sec ni=2.5*10^13 // /cm^3 printf("\n(a)\nAs it is p-type semiconductor, p>>n.") pp=sigma/(e*mup) n=ni^2/pp printf("\nPp=%.2f*10^17 holes/cm^3\nn=%.1f*10^9 electrons/cm^3",pp/10^17,n/10^9) //(b) mun=1300 sig=0.1 n1=1.5*10^10 n2=sig/(mun*e) p1=(n1^2)/n2 printf("\n\n(b)\nn=%.2f*10^14 elecrons/cm^3\np=%.2f*10^5 holes/cm^3",n2/10^14,p1/10^5)
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clc; //step1 Vcc=20; //volt R2=20000; //ohm R1=150000; //ohm Vb=20*(R2/(R2+R1)); //Volt Ve=Vb-0.7; //volt Re=2200; //ohm Ie=Ve/Re; //Ampere re=0.025/Ie; //ohm Rc=12000; //ohm RL=50000; //ohm rc=(Rc*RL)/(Rc+RL); //ohm Av=rc/re; disp('',Av,"Av=");//The answers vary due to round off error
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function [r]=%p_o_l(l1,l2) //r=%p_o_l(l1,l2) <=> r=(l1==l2) list==polynomail //! // Copyright INRIA r=%f
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DEFINE CHANNEL (CS) + CHLTYPE (RCVR) + TRPTYPE (TCP) + REPLACE
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//Example 3_5 clc; clear;close; //Given data: V=200;//V R=10;//in ohm L=20;//mH C=100;//pF f=50;//Hz //Solution : Z1=R+%i*(2*%pi*f*L*10^-3-1/(2*%pi*f*C*10^-6));//ohm Z3=R+%i*(3*2*%pi*f*L*10^-3-1/(3*2*%pi*f*C*10^-6));//ohm Z5=R+%i*(5*2*%pi*f*L*10^-3-1/(5*2*%pi*f*C*10^-6));//ohm Z7=R+%i*(7*2*%pi*f*L*10^-3-1/(7*2*%pi*f*C*10^-6));//ohm Z9=R+%i*(9*2*%pi*f*L*10^-3-1/(9*2*%pi*f*C*10^-6));//ohm I=4*V/%pi/abs(Z1);//A Irms=I/sqrt(2);//A disp(Irms,"RMS load current(A)"); Ip=sqrt((4*V/%pi/abs(Z1))^2+(4*V/3/%pi/abs(Z3))^2+(4*V/5/%pi/abs(Z5))^2+(4*V/7/%pi/abs(Z7))^2+(4*V/9/%pi/abs(Z9))^2);//A disp(Ip,"Peak value of load current(A)"); Ih=sqrt(Ip^2-I^2)/sqrt(2);//A disp(Ih,"RMS harmonic current(A)"); hd=sqrt(Ip^2-I^2)/I;//harmonic distortion disp(hd*100,"Harmonic distortion(%)"); Irms_load=Ip/sqrt(2);//A Pout=Irms_load^2*R;//W disp(Pout,"Total output power(W)"); Pout_com=Irms^2*R;//W(fundamental component) disp(Pout_com,"Fundamental component of power(W)"); Iavg_in=Pout/V;//A disp(Iavg_in,"Average input current(A)"); Ip_thy=Ip;//A disp(Ip_thy,"Peak thyristor current(A)");
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clear; clc; l=270; T=1800; w=1; h=90-30; ap=30; x=(l/2)-T*h/(w*l); x1=-x+l/2; sag1=w*x1*x1/(2*T); sag2=w*x*x/(2*T); hob=w*(l-x)^2/(2*T); clearance=ap+sag1-sag2; printf("The clearance between the conductor and water at point m is:%.2f m",clearance);
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//Example_a_7_1 page no:269 clc; R=2; C=-2*%i; L1=8*%i; L2=6*%i; V=5/(0.5+(1/L1)+(1/(4*%i))); Vmag=sqrt(real(V)^2+imag(V)^2); Vang=atand(imag(V)/real(V)); Vabmag=Vmag*6/4; Vabang=Vang; disp(Vabmag,"the magnitude of voltage across AB is (in V)"); disp(Vabang,"the angle of voltage across AB is (in degree)"); Iamag=Vmag/2; Iaang=Vang-(-90); disp(Iamag,"the magnitude of short circuited current through terminals AB is (in A)"); disp(Iaang,"the angle of short circuited current through terminals AB is (in degree)");
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/08/FunctionCalls/SimpleFunction/SimpleFunctionVME.tst load SimpleFunction.vm, output-file SimpleFunction.out, compare-to SimpleFunction.cmp, output-list RAM[0]%D1.6.1 RAM[1]%D1.6.1 RAM[2]%D1.6.1 RAM[3]%D1.6.1 RAM[4]%D1.6.1 RAM[310]%D1.6.1; set sp 317, set local 317, set argument 310, set this 3000, set that 4000, set argument[0] 1234, set argument[1] 37, set argument[2] 9, set argument[3] 305, set argument[4] 300, set argument[5] 3010, set argument[6] 4010, repeat 10 { vmstep; } output;
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make.tst
include ../etc/Makefile BIN_NAME = tst_pufa OBJ_LIB = ${WORKDIR}/lib/libtst.a ${WORKDIR}/lib/libcomm.a ${WORKDIR}/lib/libpufa.a EXECOBJ = ${WORKDIR}/bin/${BIN_NAME}.out LINKRULE = ${CC} -o ${EXECOBJ} ${OBJ_LIB} -L${WORKDIR}/lib -ltst -lcomm -lpufa TARGETS = ${EXECOBJ} all:${TARGETS} ${EXECOBJ}: ${OBJ_LIB} ${LINKRULE} clean: @- rm -f ${TARGETS} ${CLEANFILES}
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// SAMPLE Pr_BOBLEM 7/5 clc;funcprot(0); // Given data omega=3;// rad/s p=8;// rad/s gamma=30;// degree y=0.300;// m z=0.120;// m // Calculation // Velocity omega=[0,0,3];// rad/s r_B=[0,0.350,0];// m v_B1=det([omega(2),omega(3);r_B(2),r_B(3)]);// m/s v_B2=-det([omega(1),omega(3);r_B(1),r_B(3)]);// m/s v_B3=det([omega(1),omega(2);r_B(1),r_B(2)]);// m/s v_B=[v_B1,v_B2,v_B3];// m/s // Note that k*i=J=jcos(gamma)-ksin(gamma),K*j=-i*cos(gamma) and K*k=i*sin(gamma) r_AB=[0,y,z];// m // omega*r_AB=3K*(yj+zk); omegaintor_AB=(-(omega(3)*(y*cosd(gamma))))+(omega(3)*(z*sind(gamma)));// m/s p=[0,8,0];// rad/s v_rel1=det([p(2),p(3);r_AB(2),r_AB(3)]);// m/s v_rel2=-det([p(1),p(3);r_AB(1),r_AB(3)]);// m/s v_rel3=det([p(1),p(2);r_AB(1),r_AB(2)]);// m/s v_rel=[v_rel1,v_rel2,v_rel3];// m/s v_A=v_B(1)+omegaintor_AB+v_rel(1);// m/s printf("\nThe velocity of point A,v_A=%0.4fi m/s",v_A); // Acceleration a_B1=det([omega(2),omega(3);v_B(2),v_B(3)]);// m/s^2 a_B2=-det([omega(1),omega(3);v_B(1),v_B(3)]);// m/s^2 a_B3=det([omega(1),omega(2);v_B(1),v_B(2)]);// m/s^2 a_B=[a_B1,a_B2,a_B3];// m/s^2 a_B=[0,((a_B(2)*(cosd(gamma)))),-(a_B(2)*(sind(gamma)))];// m/s^2 omegadot=0;// m/s^2 // Assume O=omega*(omega*r_A/B) O=[0,((omega(3)*omegaintor_AB*(cosd(gamma)))),-omega(3)*(omegaintor_AB*(sind(gamma)))];// m/s^2 // Assume O_1=2*omega*v_rel O_1=[0,((2*omega(3)*v_rel(1)*(cosd(gamma)))),-2*omega(3)*(v_rel(1)*(sind(gamma)))];// m/s^2 a_rel1=det([p(2),p(3);v_rel(2),v_rel(3)]);// m/s^2 a_rel2=-det([p(1),p(3);v_rel(1),v_rel(3)]);// m/s^2 a_rel3=det([p(1),p(2);v_rel(1),v_rel(2)]);// m/s^2 a_rel=[a_rel1,a_rel2,a_rel3];// m/s^2 a_A=[(a_B(1)+(omegadot*r_AB(1))+O(1)+O_1(1)+a_rel1),(a_B(2)+(omegadot*r_AB(2))+O(2)+O_1(2)+a_rel2),(a_B(3)+(omegadot*r_AB(3))+O(3)+O_1(3)+a_rel3)];// m/s^2 a_A=norm(a_A);// m/s^2 printf("\nThe acceleration of point A,a_A=%1.2f m/s",a_A); // Angular Acceleration // Note that k*i=J=jcos(gamma)-ksin(gamma),K*j=-i*cos(gamma) and K*k=i*sin(gamma) omega=[3,8];// rad/s (K,j)(k*j=-i*cos(gamma)) alpha=[0+(-omega(1)*omega(2)*cosd(gamma))];// (i) rad/s^2 printf("\nThe angular acceleration of the disk,alpha=%2.1fi rad/s^2",alpha);
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// Example 5.2.2 clc; clear; n1=1.47; //refractive index of fiber n=1; //refractive index of air d=40d-6; //core diameter y=4d-6; //lateral dispalcement a=d/2; //computing core radius eta_lateral = (16*(n1/n)^2)/(%pi*(1+(n1/n))^4)*(2*acos(y/(2*a))-(y/a)*(1-(y/(2*a))^2)^0.5); //computing eta_lateral with air gap loss=-10*log10(eta_lateral); //computing loss when air gap is present eta_lateral1=(2*acos(y/(2*a))-(y/a)*(1-(y/(2*a))^2)^0.5)/%pi; //computing eta_lateral without air gap loss1=-10*log10(eta_lateral1); //computing loss when air gap is not present printf("\nloss with air gap is %.2f dB.\nloss with no air gap is %.2f dB.\n Thus we can say that loss reduces considerably if there is no air gap.",loss,loss1); //answer in the book for loss with air gap is 0.91dB, deviation of 0.01dB.
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//EXAMPLE 3.2.C clc; Syms s t w=2; laplace(cosh(w*t),t,s)
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7_6.sce
clc //initialisation of variables g=32.2 h=25//ft f=0.01 d=1//m d1=12//in pi=22/7 //CALCULATIONS k=(4*f*2000/d)+1 v=sqrt(2*g*h/k) k1=4*f/d l1=((d1*2*g)/(v*v))-1 l=l1/k1 dis=pi*d*v/4 //results printf (' Discharge through pipe= %.2f ft^3/sec ',dis)
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ex23_7.sce
//23.3 p=30//in cm f=10//in cm x=(1/f)-(1/p) q=1/x M=-(q/p) disp("part a") disp(q,"The position of final image in cm=") disp(M,"The magnification=") p=5//in cm f=10//in cm x=(1/f)-(1/p) q=1/x M=-(q/p) disp("part b") disp(q,"The position of final image in cm=") disp(M,"The magnification=")
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function varargout = frd(varargin) // Stores frequency and response data // // Calling Sequence // plantData = frd(respData,frdData,Ts) // Parameters // frdData : nx1 matrix of non-decreasing frequency points // respData : nx1 matrix of the frequency response // Ts : non-negative real number // plantData : frd type module // Description // It is a frd type module that stores the frequency and response data with sampling time Ts. The time unite is in second and frequency unit rad/sec. // Examples // frdData = 0:1024 // frdData=frdData'; // respData = rand(1024,1) // Ts = 0.1 // plantData = frd(frdData,respData,Ts) // Authors // Ashutosh Kumar Bhargava, Bhushan Manjarekar [lhs,rhs] = argn(0) if rhs < 2 || rhs > 4 then errmsg = msprintf(gettext("%s: Wrong numbers of input arguments."), "frd"); error(errmsg) end frequency = varargin(1) freqUnit = 'rad/TimeUnit' if ~iscolumn(frequency) then errmsg = msprintf(gettext("%s: frequency must be a finite column vector."), "frd"); error(errmsg) end respData = varargin(2) // pause if size(frequency,'r') <> size(respData,'r') then errmsg = msprintf(gettext("%s: input output matrix dimension must be equal."), "frd"); error(errmsg) end if rhs == 2 then Ts = 0 elseif rhs >2 then Ts = varargin(3) end if Ts < 0 || size(Ts,'*') <> 1 || typeof(Ts) <> 'constant' then errmsg = msprintf(gettext("%s: Sampling time must be a scalar non negative real number."), "frd"); error(errmsg) end // saving the spectrum value if rhs == 4 then spect = varargin(4) else spect = [] end // / matching its dimensions if ~size(spect) then elseif size(frequency,'r') <> size(spect,'r') then errmsg = msprintf(gettext("%s: Numbers of power spectra must be equal to the numbers of frequency."), "frd"); error(errmsg) end TUnit = 'seconds' t = tlist(['frd','Frequency','FrequencyUnit','ResponseData','Ts','TimeUnit','Spect'],frequency,freqUnit,respData,Ts,TUnit,spect) varargout(1) = t endfunction // overloading function %frd_p(varargin) myTlist = varargin(1) f = fieldnames(myTlist) freqData = myTlist.Frequency tempRespData= myTlist.ResponseData for jj = 1:size(tempRespData,'c') respData = tempRespData(:,jj) mprintf("\t -------------------------") mprintf("\n") mprintf("\t Frequency \t Response") mprintf("\n") mprintf("\t -------------------------") mprintf("\n") for ii = 1:length(myTlist.Frequency) temp = '' if real(respData(ii))>=0 then temp = temp + ' ' end temp = temp + string(real(respData(ii))) // temp = string(real(respData(ii))) if imag(respData(ii)) > 0 then temp = temp +"+" end if ~imag(respData(ii)) then else temp = temp + string(imag(respData(ii))) +"i" end // temp = temp + string(imag(respData(ii))) + " i" mprintf("\n\t %f \t %s",freqData(ii),temp)// real(respData(ii)),imag(respData(ii))) end mprintf("\n\n") end if ~myTlist.Ts then mprintf("\n Continuous Domain frequency response.") else mprintf("\n Sampling Time = "+string(myTlist.Ts)+" "+myTlist.TimeUnit) mprintf("\n Discrete Domain frequency response.") end endfunction
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// Ex2_7 clc; // Given: h=6.6262*10^-34;// in J.s f=17.24*10^6;// in Hz/T m=5.05*10^-27;// in J/T // Solution: E=h*f; g=E/(m) printf("The nuclear g factor for P is = %f",g)
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// Example 2.5 format('v',6) clc; clear; close; // given data Vin= 15;// in V V_K= 0.7;// in V R_L= 10;// in kΩ R_L= R_L*10^3;// in Ω // The output voltage Vout= Vin-V_K;// in V // The current I= Vout/R_L;// in A // The power dissipation of the diode P= V_K*I;// in W I=I*10^3;// in mA P= round(P*10^3);// in mW disp(Vout,"The output voltage in volts is : "); disp(I,"The current in mA is : "); disp(P,"The power dissipation of the diode in mW is : ")
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// Scilab Code Ex16.9: Page-604(2014) clc; clear; H0 = 71; // Hubble cinstant, km/s per Mpc tau = 1/H0*1e+006*3.26*9.46e+012/3.16e+007; // The upper limit of the age of the universe, y printf("\nThe upper limit of the age of the universe = %4.2e y", tau); // Result // The upper limit of the age of the universe = 1.37e+010 y
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//Chapter 9 Ex 9 clc; clear; close; x=(2^(1/4)-1)*((2^(3/4))+(2^(1/2))+(2^(1/4))+1); mprintf("The value of the expression is %.0f",x);
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clear //Given A=0.9 Ie=1 //mA //Calculation Ic=A*Ie Ib=Ie-Ic //Result printf("\n Base current is %0.3f mA",Ib)
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clear Z0 = 376.730313668; h = 0.2e-3; w = 0.2e-3; t = 0.035e-3; er = 4.4; weff = w + ( t/%pi ) * log( 4 *exp(1) / ( sqrt( ( t/h ).^2 + (t/(w*%pi+1.1*t*%pi ) ).^2 ))) * ( er+1) / (2*er); X1 = 4*( 14 * er + 8 )/( 11*er )*h/weff; X2 = sqrt( 16*(h/weff).^2*( ( 14*er+8 )/(11*er)).^2 + ( er +1 )/( 2*er ) * %pi*%pi ) Z = Z0 / ( 2*%pi *sqrt( 2* ( 1 +er ) ) ) * log ( 1 + 4*h/weff *( X1 +X2) )
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//Chapter 11: Broadband and Frequency-Independent Antennas //Example 11-7.1 clc; //Variable Initialization gain_dbi = 7.0 //Gain (dBi) bandwidth = 4 //Relative bandwidth (unitless) s_lambda = 0.15 //Spacing (lambda) k = 1.2 //Scale constant (unitless) //Calculation alpha = atan((1-1/k)/(4*s_lambda))*180/%pi //Apex angle (degrees) n = round(log(bandwidth)/log(k)) //Number of elements(unitless) n =n + 1 n =n + 2 //Number of elements considering conservative design (unitless) //Result mprintf("The apex angle is %.1f degrees",alpha) mprintf("\nThe number of elements is %d", n)
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(x^3 + x^2*y + y^2).derivative("x", 3) = 6
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//Chapter 20, Problem 4, Fig.20.7 clc; Vl=415; //3-phase supply Pr=24000; //resistance in ohm Py=18000; //resistance in ohm Pb=12000; //resistance in ohm Vp=Vl/sqrt(3); //phase voltage Ir=Pr/Vp; //current in each line Iy=Py/Vp; Ib=Pb/Vp; //calculating current in the neutral conductor Irh=cos(90*%pi/180); Iyh=cos(330*%pi/180); Ibh=cos(210*%pi/180); Irv=sin(90*%pi/180); Iyv=sin(330*%pi/180); Ibv=sin(210*%pi/180); Ih=(Ir*Irh)+(Iy*Iyh)+(Ib*Ibh); Iv=(Ir*Irv)+(Iy*Iyv)+(Ib*Ibv); In=sqrt(Ih^2+Iv^2); printf("(a) Ir = %d A\n\nIy = %d A\n\nIb = %d A\n\n",Ir,Iy,Ib); printf("(b) The three line currents are shown in the phasor diagram of Fig. 20.8.\n"); printf("Since each load is resistive the currents are in phase with the phase voltages and are hence mutually displaced by 120◦."); printf("\nIn = %f A\n",In);
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// Example 3_4 clc;funcprot(0); // Given data V=90;// km/h C_D=0.2;// The drag coefficient rho=1.23;// The density of air in kg/m^3 A=2.3;// m^2 // Calculation V=V*(1000/3600);// The velocity in m/s F_D=(1/2)*rho*(V^2)*A*C_D;// The drag force in N W=F_D*V;// The work done in W Hp=W/746;// The required horse power in hp printf("\nThe required horse power,Hp=%1.2f hp",Hp);
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// Example 18.10, page no-466 clear clc epsr=1.0024 N=2.7*10^25 //atoms.m^-3 eps=8.854*10^-12//F.m^-1 alfe=eps*(epsr-1)/N printf("The polarisability of argon atom is %.1f * 10^-40 F m^2",alfe*10^40)
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//Find Elastic Strain Energy //Ex:6.4 clc; clear; close; v=0.31;//poisson's ratio bv=.25*10^-9;//burger's vector in m ri=1.1*10^-9;//in m r0=10^5*bv;//in m sm=45*10^9;//shear modulous in n/sqm gb_2=sm*bv^2; u_ed=(gb_2/(4*3.14*(1-v)))*log(r0/ri); disp(u_ed,"Elastic Strain Energy of Edge dislocation (in J/m) = "); u_sd=(gb_2/(4*3.14))*log(r0/ri); disp(u_sd,"Elastic Strain Energy of Screw dislocation (in J/m) = "); r=u_ed/u_sd;//ratio disp(r,"Ratio of energies of edge dislocation over screw dislocation = ");
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//Chapter 04:Number Theory and Cryptography clc; clear all; //To find the quotient and remainder dividend=101 divisor=11 quotient=int(dividend/divisor) //To find quotient remainder=modulo(dividend,divisor) //To find remainder dividend_a=(divisor *quotient)+remainder //To find dividend mprintf("The quotient when %d is divided by %d is %d = %d div %d and the remainder is %d = %d mod %d",dividend,divisor,quotient,dividend,divisor,remainder,dividend,divisor)
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// Initilization of variables s=1 // m mu=0.192 // coefficient of static friction g=9.81 // m/s^2 // Calculations // The maximum angle of the inclined plane is given as, theta=atand(3*mu) // degree a=(2/3)*g*sind(theta) // m/s^2 // by solving eq'n 4 v=sqrt(2*a*s) // m/s // Let the acceleration at the centre be A which is given as, A=g*sind(theta) // m/s^2 // from eq'n 1 // Results clc printf('(a) The acceleration at the centre is %f m/s^2 \n',A) printf('(b) The maximum angle of the inclined plane is %f degree \n',theta)
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// Scilab code Ex3.19: Pg 101-102 (2008) clc; clear; C = 270e-12; // Capacitance, F A = 60e-04; // Cross-sectional area of plate, m^2 E = 350e03; // Dielectric strength, V/m epsilon_r = 2.1; // Relative pemittivity epsilon_o = 8.854e-12; // Permittivity of free space // Part (a) // Since formula for capacitance, C = ((epsilon_o)*(eplison_r)*A)/d, solving for d d = ((epsilon_o)*(epsilon_r)*A)/C; // Thickness of dielectric, m // Part (b) // Since E = V/d, solving for V V = E*d; // Maximum possible working voltage, V printf("\nThe thickness of Teflon sheet required = %5.4f mm", d/1e-03); printf("\nThe maximum possible working voltage for the capacitor = %5.1f V", V); // Result // The thickness of Teflon sheet required = 0.413 mm // The maximum possible working voltage for the capacitor = 144.6 V
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clc // initialization of variables clear b=10 //mm M=1 t=50 //mm rho=5 //mm h=25 //mm c=60 //mm SF=4.0 //part (a) S_cc=2.8 q=0.94 S_ce=1+q*(S_cc-1) // M is not known. take it as unity S_n=3*M*t/(2*h*(c^3-t^3)) S_e=S_ce*S_n printf('part (a)') printf('\n Effective stress = %.1e M',S_e) //part (b) S_max=172 //MPa S_w=S_max/SF M=S_w/S_e printf('\n part (b)') printf('\n M =%.1f N.m',M/10^3)
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, quasi 1D nozzle, stagnation inflow bc</description> <executable>CompressibleFlowSolver</executable> <parameters>Nozzle_Quasi1D_P6.xml</parameters> <files> <file description="Session File">Nozzle_Quasi1D_P6.xml</file> </files> <metrics> <metric type="L2" id="1"> <value variable="rho" tolerance="1e-12">3.87376</value> <value variable="rhou" tolerance="1e-12">3.89851</value> <value variable="E" tolerance="1e-12">790564</value> </metric> <metric type="Linf" id="2"> <value variable="rho" tolerance="1e-12">1.22627</value> <value variable="rhou" tolerance="1e-12">2.95978</value> <value variable="E" tolerance="1e-12">250372</value> </metric> </metrics> </test>
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//Ex4_4 clc A = 4*10^-6 W = 1.5*10^-6 apsilent_r = 16//for germanium apsilent_not = 8.85*10^-12//permitivity in vaccum disp("A = "+string(A)+"m_sq")//cross sectional are disp("W = "+string(W)+"m")//width of depletion layer disp("apsient_r = "+string(apsilent_r))//relative permittivity disp("CT = apsilent*A/W")//transition capacitance disp(" = "+string(apsilent_r*apsilent_not*A/W)+"F") // note: units given in textbook in the solution for cross sectional area and width are misprinted.
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clc;// in-built fuction routh_t can be used to generate the routh table s = poly(0,'s'); tf = syslin('c',10/(s^5+7*s^4+6*s^3+42*s^2+8*s+56)); deno = denom(tf); coef = coeff(deno); routh = [coef([6,4,2]);coef([5,3,1])]; // we will get a row of all zeroes T = routh(2,:)/7; coef1 = coeff(T); // auxillary polynomial s^2+6*s+8 generation second = poly([coef1(3) 0 coef1(2) 0 coeff(1)],"s","coeff");disp(second); aux = derivat(second);//auxillary polynomial len = coeff(aux); routh = [routh;len(4) len(2) 0]; disp(routh); t = routh(2:3,1:3); det1 = det(t(1:2,1:2))/t(2,1); det2 = -(t(1,1)*t(2,3)-t(2,1)*t(1,3))/t(2,1); routh = [routh;-det1 det2 0]; t1 = routh(3:4,1:2); det3 = det(t1(1:2,1:2))/t1(2,1); routh = [routh;-det3 0 0]; t2 = routh(4:5,1:2); det4 = det(t2(1:2,1:2))/t2(2,1); routh = [routh;-det4 0 0]; disp(routh) c = 0; for k = 1:length(coef) if(routh(k,1)<0) c =c +1; end end if(c>=1) printf("system is unstable") else printf("system is stable,hence no poles in RHP") end
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//Chapter-2, Illustration 4, Page 58 //Title: Gas Power Cycles //============================================================================= clc clear //INPUT DATA rv=9.5;//Compression ratio P1=100;//Air pressure in kPa T1=290;//Air temperature in K V1=600*(10^-6);//Volume of air in m^3 T4=800;//Final temperature in K R=287;//Universal gas constan in J/kg.K Cv=0.718;//Specific heat at constant volume in kJ/kg.K y=1.4;//Ratio of specific heats //CALCULATIONS T3=T4*(rv^(y-1));//Temperature at the end of constant volume heat addition in K P2=P1*(rv^y);//Pressure at point 2 in kPa T2=T1*(rv^(y-1));//Temperature at point 2 in K P3=P2*(T3/T2);//Pressure at point 3 in kPa m=(P1*1000*V1)/(R*T1);//Specific mass in kg/s Q=m*Cv*(T3-T2);//Heat transferred in kJ n=(1-(1/rv^(y-1)))*100;//Thermal efficiency Wnet=(n*Q)/100;//Net workdone in kJ MEP=Wnet/(V1*(1-(1/rv)));//Mean effective pressure in kPa //OUTPUT mprintf('Maximum pressure of the cycle is %3.2f kPa \n Maximum temperature of the cycle is %3.1f K \n Amount of heat transferred is %3.2f kJ \n Thermal efficiency is %3.1f percent \n Mean effective pressure is %3.1f kPa',P3,T3,Q,n,MEP) //==============================END OF PROGRAM=================================
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//Example 10 Page No: 1.86 //given inb1=22e-6;//A inb2=26e-6;//A //determine input offset current input base current i1=inb2-inb1; i2=(inb2+inb1)/2; format(10); disp('Input offset current = '+string(i1*10^6)+' μA'); disp('Input base current = '+string(i2*10^6)+' μA');
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//Soultion 3-02 WD=get_absolute_file_path('3_02_solution.sce'); datafile=WD+filesep()+'3_02_example.sci'; clc; exec(datafile) h = h / 1000; //converting height of Hg column from [mm] to [m] P = rho * g * h; //Basic pressure eqaution [Pa] P = P / 1000; //result printf("Atmospheric pressure is %1.1f kPa", P);
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//example(3.17) c=[51200 0 -39712 0 7392 0 -170 0 1 ] p8=poly(c,'x','coeff') roots(p8) xset('window',0); x=-11:01:11; // defining the range of x. deff('[y]=f(x)','y=x^8-170*x^6+7392*x^4-39712*x^2+51200'); //defining the cunction y=feval(x,f); a=gca(); a.y_location = "origin"; a.x_location = "origin"; plot(x,y) // instruction to plot the graph title(' y =x^8-170*x^6+7392*x^4-39712*x^2+51200')
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// Scilab Code Ex 11.10: Page-568 (2011) clc;clear; function s = sine(x) s = x - x^3/factorial(3) + x^5/factorial(5) - x^7/factorial(7) + x^9/factorial(9); endfunction function s = cosine(x) s = 1 - x^2/factorial(2) + x^4/factorial(4) - x^6/factorial(6) + x^8/factorial(8); endfunction k = 1; // For simplicity assume constant of proportionality to be unity, units for theta = 1:1:45 alpha = k*cosd(theta); b = k*sind(theta); if alpha == b then phi = atand(b/alpha); break; end end //printf("\nThe phase difference between electric and magentic field vectors = %4.2f rad", phi); // Result // The skin depth of an EM-wave in Al = 0.000010 m
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function [r, allrates] = irr(cf) //IRR Internal rate of return. // // R = IRR(CF) // [R, ALLRATES] = IRR(CF) // // Inputs: // CF - A vector containing a stream of periodic cash flows. The // first entry in CF is the initial investment. If CF is a // matrix, each column of CF is treated as a separate cash-flow // stream. // // Outputs: // R - An internal rate of return associated to CF. If CF is a // matrix, then R is a vector whose entry j is an internal rate // of return for column j in CF. // // Optional Outputs: // ALLRATES - A vector containing all the internal rates of return // associated to CF. If CF is a matrix, then ALLRATES is also a // matrix, with the same number of columns as CF, and one fewer // row, and column j in ALLRATES contains all the rates of return // associated to column j in CF (including complex-valued rates). // // Conventions: // * If one or multiple (warning if multiple) strictly positive rates // are found, R is set to the minimum // * If no strictly positive rates, but one or multiple (warning if // multiple) non-positive rates are found, R is set to the maximum // * If no real-valued rates are found, R is set to NaN (no warnings) // // Examples: // // 1) A simple investment with a unique positive rate of return // // Suppose an initial investment of $100,000 is made, and the following // cash flows represent the yearly income realized by the investment: // // Year 1 $10,000 // Year 2 $20,000 // Year 3 $30,000 // Year 4 $40,000 // Year 5 $50,000 // // To calculate the internal rate of return on the investment, use // // r = irr([-100000 10000 20000 30000 40000 50000]) // // which returns r = 12.01%. If the cash flow payments were monthly, // the resulting rate of return would be multiplied by 12 for the // annual rate of return. // // 2) Multiple rates of return // // Consider now a project with the following cash flows: // // CF = [-1000 6000 -10900 5800]. // // Suppose the market rate is 10%. // We first call IRR with a single output argument: // // R = irr(CF). // // It displays a warning ("Warning: Multiple rates of return") and // returns a 100% rate of return. The 100% rate on the project looks // very attractive. However, there was a warning. So call IRR again, // but this time with two output arguments: // // [R, ALLRATES] = irr(CF). // // The rates of return (in ALLRATES) are -4.88%, 100%, and 204.88%. // Though some of these rates are lower and some higher than the // market rate, any of these rates can be used to get a consistent // recommendation on the project (see [2]), but we recommend to simply // switch to a present value analysis in these kinds of situations. // To check the present value of the project, use PVVAR: // // PV = pvvar(CF,0.10). // // The second argument is the 10% market rate. The present value is // -196.0932, negative, so the project is not desirable. // // It is strongly recommended to always complement the use of IRR with a // present value analysis, using PVVAR. Some cash-flow streams have a // unique positive internal rate of return, as in Example (1). However, // all cash-flow streams have a multiplicity of rates of returns (some of // which are negative, or complex-valued). Hazen [2] explains how any of // these rates can be used to get a recommendation on the project that is // consistent with the present value analysis (therefore, all rates of // return are valid and consistent). Yet, using the present value directly // is a simpler way to accomplish the same goal when the rates of return, // as in Example (2), do not have a straightforward interpretation. // // It is good practice to always call IRR with two output arguments, and // to check the values of all the rates of return, especially when a call // to IRR displays a warning about multiple rates. // // See also MIRR, XIRR, PVVAR. // // References: // [1] Brealey and Myers. Principles of Corporate Finance. Chapter 5. // [2] Hazen, G. A New Perspective on Multiple Internal Rates of // Return. The Engineering Economist, 2003, Vol. 48-1, pp. 31-51. // // Copyright 1995-2006 The MathWorks, Inc. // $Revision: 1.8.2.5 $ $Date: 2010/10/08 16:43:29 $ oneRateOut = %T; [rowcf,colcf] = size(cf); if rowcf == 1 [rowcf,colcf] = size(cf'); cf = cf(:); end multrates = zeros(1,colcf); r = zeros(1,colcf); allrates = zeros(rowcf-1,colcf); for loop = 1:colcf // loop over all cash-flow streams coef = roots(cf($:-1:1,loop)'); // Find roots of polynomial rates = ((1)./coef) - 1; // Compute corresponding rates // Preferred rates are real-valued and positive ind = find(real(rates) > 0 & abs(imag(rates)) < 1e-6); nind = length(ind); if (nind==1) // One single positive rate r(loop) = real(rates(ind)); elseif (nind > 1) // Multiple positive rates; flag stream id and return min rate multrates(loop) = 1; r(loop) = min(real(rates(ind))); else // Get indices of any other real rates, if any (must be <= 0) ind = find(abs(imag(rates)) < 1e-6); nind = length(ind); if (nind==1) // One non-positive rate r(loop) = real(rates(ind)); elseif (nind > 1) // Multiple non-positive rates; flag stream id and return max rate multrates(loop) = 1; r(loop) = max(real(rates(ind))); else // No real rates; return NaN r(loop) = NaN; end end allrates(:,loop) = rates(:); end // for loop endfunction
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//chapter-15,Example15_4,pg 512 We=7.6*10^-5//speed od gyro L=490 d=0.094 c=3*10^8 delphi=7.69*10^-5//phase shift lam=((2*%pi*L*d*We)/(c*delphi))//wavelength of laser light printf("wavelength of laser light\n") printf("lam=%.11f m",lam)
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//********** 3.0 ********** dac_loc(1,1).entries(1)= '9 0 1 #int[1]'; dac_loc(1,1).entries(2)= '2'; //DAC2 dac_loc(1,2).entries(1)= '9 0 2 #int[2]'; dac_loc(1,2).entries(2)= '3'; //DAC3 dac_loc(1,3).entries(1)= '8 0 5 #int[5]'; dac_loc(1,3).entries(2)= '0'; //DAC0 dac_loc(1,4).entries(1)= '9 0 3 #int[3]'; dac_loc(1,4).entries(2)= '4'; //DAC4 dac_loc(1,5).entries(1)= '9 0 4 #int[4]'; dac_loc(1,5).entries(2)= '5'; //DAC5 dac_loc(1,6).entries(1)= '9 0 5 #int[5]'; dac_loc(1,6).entries(2)= '6'; //DAC6 dac_loc(1,7).entries(1)= '10 0 0 #int[0]'; dac_loc(1,7).entries(2)= '7'; //DAC7 dac_loc(1,8).entries(1)= '10 0 1 #int[1]'; dac_loc(1,8).entries(2)= '8'; //DAC8 dac_loc(1,9).entries(1)= '10 0 2 #int[2]'; dac_loc(1,9).entries(2)= '9'; //DAC9 dac_loc(1,10).entries(1)= '9 0 0 #int[0]'; dac_loc(1,10).entries(2)= '1'; //DAC1 dac_loc(1,11).entries(1)= '10 0 3 #int[3]'; dac_loc(1,11).entries(2)= '10'; //DAC10 dac_loc(1,12).entries(1)= '10 0 4 #int[4]'; dac_loc(1,12).entries(2)= '11'; //DAC11 //********** 3.0 ********** dac_buf_loc(1,1).entries='10 0 5 #int[5]'; dac_buf_loc(1,2).entries='11 0 0 #int[0]'; dac_buf_loc(1,3).entries='11 0 1 #int[1]'; dac_buf_loc(1,4).entries='11 0 2 #int[2]'; //********** 3.0 ********** gpin_loc(1,1).entries(1)='13 0 1 #int[1]'; gpin_loc(1,1).entries(2)='0'; //west GPIO proc to arrat gpin_loc(1,2).entries(1)='13 0 2 #int[2]'; gpin_loc(1,2).entries(2)='1'; //west gpin_loc(1,3).entries(1)='13 0 3 #int[3]'; gpin_loc(1,3).entries(2)='2'; //west gpin_loc(1,4).entries(1)='13 0 4 #int[4]'; gpin_loc(1,4).entries(2)='3'; //west gpin_loc(1,5).entries(1)='13 0 5 #int[5]'; gpin_loc(1,5).entries(2)='4'; //west gpin_loc(1,6).entries(1)='14 0 0 #int[0]'; gpin_loc(1,6).entries(2)='5'; //west gpin_loc(1,7).entries(1)='14 0 1 #int[1]'; gpin_loc(1,7).entries(2)='6'; //west gpin_loc(1,8).entries(1)='14 0 2 #int[2]'; gpin_loc(1,8).entries(2)='7'; //west gpin_loc(1,9).entries(1)='14 0 3 #int[3]'; gpin_loc(1,9).entries(2)='8'; //west gpin_loc(1,10).entries(1)='14 0 4 #int[4]'; gpin_loc(1,10).entries(2)='9'; //west gpin_loc(1,11).entries(1)='14 0 5 #int[5]'; gpin_loc(1,11).entries(2)='10'; //west gpin_loc(1,12).entries(1)='15 1 0 #int[0]'; gpin_loc(1,12).entries(2)='11'; //west gpin_loc(1,13).entries(1)='15 1 1 #int[1]'; gpin_loc(1,13).entries(2)='12'; //west gpin_loc(1,14).entries(1)='15 1 2 #int[2]'; gpin_loc(1,14).entries(2)='13'; //west gpin_loc(1,15).entries(1)='15 1 3 #int[3]'; gpin_loc(1,15).entries(2)='14'; //west gpin_loc(1,16).entries(1)='15 1 4 #int[4]'; gpin_loc(1,16).entries(2)='15'; //west //********** 3.0 ********** adc_locin(1,1).entries='5 0 5 #int[5]'; //adc in 0 adc_locin(1,2).entries='6 0 0 #int[0]'; //adc in 1 //********** 3.0 ********** adc_loc(1,1).entries='7 0 2 #int[2]'; //adc out0 0 adc_loc(1,2).entries='7 0 1 #int[1]'; //adc out0 1 adc_loc(1,3).entries='7 0 0 #int[0]'; //adc out0 2 adc_loc(1,4).entries='6 0 5 #int[5]'; //adc out0 3 adc_loc(1,5).entries='6 0 4 #int[4]'; //adc out0 4 adc_loc(1,6).entries='6 0 3 #int[3]'; //adc out0 5 adc_loc(1,7).entries='6 0 2 #int[2]'; //adc out0 6 adc_loc(1,8).entries='6 0 1 #int[1]'; //adc out0 7 adc_loc(1,9).entries='8 0 4 #int[4]'; //adc out1 0 adc_loc(1,10).entries='8 0 3 #int[3]'; //adc out1 1 adc_loc(1,11).entries='8 0 2 #int[2]'; //adc out1 2 adc_loc(1,12).entries='8 0 1 #int[1]'; //adc out1 3 adc_loc(1,13).entries='8 0 0 #int[0]'; //adc out1 4 adc_loc(1,14).entries='7 0 5 #int[5]'; //adc out1 5 adc_loc(1,15).entries='7 0 4 #int[4]'; //adc out1 6 adc_loc(1,16).entries='7 0 3 #int[3]'; //adc out1 7 //********** 3.0 ********** iopad_loc(1,13).entries='1 0 3 #'; //west iopad_loc(1,14).entries='2 0 3 #'; //west iopad_loc(1,9).entries='3 0 0 #'; //west iopad_loc(1,10).entries='3 0 3 #'; //west iopad_loc(1,11).entries='4 0 0 #'; //west iopad_loc(1,12).entries='4 0 3 #'; //west iopad_loc(1,1).entries='9 0 0 #'; //west iopad_loc(1,2).entries='11 0 0 #'; //west iopad_loc(1,3).entries='12 0 0 #'; //west iopad_loc(1,4).entries='12 0 3 #'; //west iopad_loc(1,5).entries='13 0 0 #'; //west iopad_loc(1,6).entries='13 0 3 #'; //west iopad_loc(1,7).entries='14 0 0 #'; //west iopad_loc(1,8).entries='14 0 3 #'; //west iopad_loc(1,15).entries='1 15 0 #'; //east iopad_loc(1,16).entries='1 15 3 #'; //east iopad_loc(1,17).entries='2 15 0 #'; //east iopad_loc(1,18).entries='2 15 3 #'; //east iopad_loc(1,19).entries='3 15 0 #'; //east iopad_loc(1,20).entries='9 15 3 #'; //east iopad_loc(1,21).entries='9 15 0 #'; //east iopad_loc(1,22).entries='10 15 3 #'; //east iopad_loc(1,23).entries='10 15 0 #'; //east iopad_loc(1,24).entries='11 15 3 #'; //east iopad_loc(1,25).entries='11 15 0 #'; //east iopad_loc(1,26).entries='12 15 0 #'; //east iopad_loc(1,27).entries='15 1 5 #'; //south iopad_loc(1,28).entries='15 1 2 #'; //south iopad_loc(1,29).entries='15 2 5 #'; //south iopad_loc(1,30).entries='15 2 2 #'; //south iopad_loc(1,31).entries='15 3 5 #'; //south iopad_loc(1,32).entries='15 4 2 #'; //south iopad_loc(1,33).entries='15 11 5 #'; //south iopad_loc(1,34).entries='15 12 2 #'; //south iopad_loc(1,35).entries='15 12 5 #'; //south iopad_loc(1,36).entries='15 13 2 #'; //south iopad_loc(1,37).entries='15 13 5 #'; //south iopad_loc(1,38).entries='15 14 2 #'; //south iopad_loc(1,39).entries='15 14 5 #'; //south iopad_loc(1,40).entries='13 0 1 #int[1]'; //west GPIO proc to arrat iopad_loc(1,41).entries='13 0 2 #int[2]'; //west iopad_loc(1,42).entries='13 0 3 #int[3]'; //west iopad_loc(1,43).entries='13 0 4 #int[4]'; //west iopad_loc(1,44).entries='13 0 5 #int[5]'; //west iopad_loc(1,45).entries='14 0 0 #int[0]'; //west iopad_loc(1,46).entries='14 0 1 #int[1]'; //west iopad_loc(1,47).entries='14 0 2 #int[2]'; //west iopad_loc(1,48).entries='14 0 3 #int[3]'; //west iopad_loc(1,49).entries='14 0 4 #int[4]'; //west iopad_loc(1,50).entries='14 0 5 #int[5]'; //west iopad_loc(1,51).entries='15 1 0 #int[0]'; //west iopad_loc(1,52).entries='15 1 1 #int[1]'; //west iopad_loc(1,53).entries='15 1 2 #int[2]'; //west iopad_loc(1,54).entries='15 1 3 #int[3]'; //west iopad_loc(1,55).entries='15 1 4 #int[4]'; //west iopad_loc(1,56).entries='15 1 5 #int[5]'; //south GPIO array to proc iopad_loc(1,57).entries='15 2 0 #int[0]'; //south iopad_loc(1,58).entries='15 2 1 #int[1]'; //south iopad_loc(1,59).entries='15 2 2 #int[2]'; //south iopad_loc(1,60).entries='15 2 3 #int[3]'; //south iopad_loc(1,61).entries='15 2 4 #int[4]'; //south iopad_loc(1,62).entries='15 2 5 #int[5]'; //south iopad_loc(1,63).entries='15 3 0 #int[0]'; //south iopad_loc(1,64).entries='15 3 1 #int[1]'; //south iopad_loc(1,65).entries='15 3 2 #int[2]'; //south iopad_loc(1,66).entries='15 3 3 #int[3]'; //south iopad_loc(1,67).entries='15 3 4 #int[4]'; //south iopad_loc(1,68).entries='15 3 5 #int[5]'; //south iopad_loc(1,69).entries='15 4 0 #int[0]'; //south iopad_loc(1,70).entries='15 4 1 #int[1]'; //south iopad_loc(1,71).entries='15 4 2 #int[2]'; //south iopad_loc(1,72).entries='15 12 5 #int[5]'; //Vg _array_gate sel iopad_loc(1,73).entries='0 11 2 #int[2]'; //Vg _array_gate sel iopad_loc(1,74).entries='9 15 3 #int[3]'; //east Analog_memory_Vout<0> iopad_loc(1,75).entries='0 12 5 #int[5]'; //north Analog_memory_pbias<0> iopad_loc(1,76).entries='4 15 1 #int[1]'; //east Analog_memory_nbias<0> iopad_loc(1,77).entries='14 15 5 #int[5]'; //east mem_in<0> iopad_loc(1,78).entries='15 11 4 #int[4]'; //south am clk iopad_loc(1,79).entries='0 6 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,80).entries='0 6 3 #int[3]'; //north barrel_shiftter_out<0> iopad_loc(1,81).entries='0 6 2 #int[2]'; //north barrel_shiftter_out<0> iopad_loc(1,82).entries='0 6 1 #int[1]'; //north barrel_shiftter_out<0> iopad_loc(1,83).entries='0 6 0 #int[0]'; //north barrel_shiftter_out<0> iopad_loc(1,84).entries='0 5 5 #int[5]'; //north barrel_shiftter_out<0> iopad_loc(1,85).entries='0 5 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,86).entries='0 5 3 #int[3]'; //north barrel_shiftter_out<0> iopad_loc(1,87).entries='0 5 2 #int[2]'; //north barrel_shiftter_out<0> iopad_loc(1,88).entries='0 5 1 #int[1]'; //north barrel_shiftter_out<0> iopad_loc(1,89).entries='0 5 0 #int[0]'; //north barrel_shiftter_out<0> iopad_loc(1,90).entries='0 4 5 #int[5]'; //north barrel_shiftter_out<0> iopad_loc(1,91).entries='0 4 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,92).entries='0 4 3 #int[3]'; //north barrel_shiftter_out<0> iopad_loc(1,93).entries='0 4 2 #int[2]'; //north barrel_shiftter_out<0> iopad_loc(1,94).entries='0 4 1 #int[1]'; //north barrel_shiftter_out<0> iopad_loc(1,95).entries='0 4 0 #int[0]'; //north barrel_shiftter_out<0> iopad_loc(1,96).entries='0 3 5 #int[5]'; //north barrel_shiftter_out<0> iopad_loc(1,97).entries='0 3 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,98).entries='0 3 3 #int[3]'; //north barrel_shiftter_out<0> iopad_loc(1,99).entries='0 3 2 #int[2]'; //north barrel_shiftter_out<0> iopad_loc(1,100).entries='0 3 1 #int[1]'; //north barrel_shiftter_out<0> iopad_loc(1,101).entries='0 3 0 #int[0]'; //north barrel_shiftter_out<0> iopad_loc(1,102).entries='0 2 5 #int[5]'; //north barrel_shiftter_out<0> iopad_loc(1,103).entries='0 2 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,104).entries='0 2 3 #int[3]'; //north barrel_shiftter_out<0> iopad_loc(1,105).entries='0 2 2 #int[2]'; //north barrel_shiftter_out<0> iopad_loc(1,106).entries='0 2 1 #int[1]'; //north barrel_shiftter_out<0> iopad_loc(1,107).entries='0 2 0 #int[0]'; //north barrel_shiftter_out<0> iopad_loc(1,108).entries='0 1 5 #int[5]'; //north barrel_shiftter_out<0> iopad_loc(1,109).entries='0 1 4 #int[4]'; //north barrel_shiftter_out<0> iopad_loc(1,110).entries='0 1 3 #int[3]'; //north barrel_shiftter_out<31> iopad_loc(1,111).entries='0 1 2 #int[2]'; //north barrel_shiftter_in<0> iopad_loc(1,112).entries='0 1 1 #int[1]'; //north barrel_shiftter_in<0> iopad_loc(1,113).entries='0 1 0 #int[0]'; //north barrel_shiftter_in<0> iopad_loc(1,114).entries='1 0 0 #int[0]'; //east barrel_shiftter_in<0> iopad_loc(1,115).entries='1 0 1 #int[1]'; //east barrel_shiftter_in<0> iopad_loc(1,116).entries='1 0 2 #int[2]'; //east barrel_shiftter_in<0> iopad_loc(1,117).entries='1 0 3 #int[3]'; //east barrel_shiftter_in<0> iopad_loc(1,118).entries='1 0 4 #int[4]'; //east barrel_shiftter_in<0> iopad_loc(1,119).entries='1 0 5 #int[5]'; //east barrel_shiftter_in<0> iopad_loc(1,120).entries='2 0 0 #int[0]'; //east barrel_shiftter_in<0> iopad_loc(1,121).entries='2 0 1 #int[1]'; //east barrel_shiftter_in<0> iopad_loc(1,122).entries='2 0 2 #int[2]'; //east barrel_shiftter_in<0> iopad_loc(1,123).entries='2 0 3 #int[3]'; //east barrel_shiftter_in<0> iopad_loc(1,124).entries='2 0 4 #int[4]'; //east barrel_shiftter_in<0> iopad_loc(1,125).entries='2 0 5 #int[5]'; //east barrel_shiftter_in<0> iopad_loc(1,126).entries='3 0 0 #int[0]'; //east barrel_shiftter_in<0> iopad_loc(1,127).entries='3 0 1 #int[1]'; //east barrel_shiftter_in<0> iopad_loc(1,128).entries='3 0 2 #int[2]'; //east barrel_shiftter_in<0> iopad_loc(1,129).entries='3 0 3 #int[3]'; //east barrel_shiftter_in<0> iopad_loc(1,130).entries='3 0 4 #int[4]'; //east barrel_shiftter_in<0> iopad_loc(1,131).entries='3 0 5 #int[5]'; //east barrel_shiftter_in<0> iopad_loc(1,132).entries='4 0 0 #int[0]'; //east barrel_shiftter_in<0> iopad_loc(1,133).entries='4 0 1 #int[1]'; //east barrel_shiftter_in<0> iopad_loc(1,134).entries='4 0 2 #int[2]'; //east barrel_shiftter_in<0> iopad_loc(1,135).entries='4 0 3 #int[3]'; //east barrel_shiftter_in<0> iopad_loc(1,136).entries='4 0 4 #int[4]'; //east barrel_shiftter_in<0> iopad_loc(1,137).entries='4 0 5 #int[5]'; //east barrel_shiftter_in<0> iopad_loc(1,138).entries='5 0 0 #int[0]'; //east barrel_shiftter_in<0> iopad_loc(1,139).entries='5 0 1 #int[1]'; //east barrel_shiftter_in<0> iopad_loc(1,140).entries='5 0 2 #int[2]'; //east barrel_shiftter_in<0> iopad_loc(1,141).entries='5 0 3 #int[3]'; //east barrel_shiftter_in<0> iopad_loc(1,142).entries='5 0 4 #int[4]'; //east barrel_shiftter_in<0> iopad_loc(1,143).entries='13 0 0 #int[0]'; //east dco_clk
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clc //initialisation of variables d1= 4 //ft d2= 2 //ft h1= 50 //ft h2= 45 //ft g= 32.2 //ft/sec^2 //CALCULATIONS r= (d1^2/d2^2) v1= sqrt((h1-h2)*2*g/(r^2-1)) Q= v1*%pi*d1^2/4 //RESULTS printf ('discharge through pipe= %.2f cubic feet per second ',Q)
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//clc() Nflue = 100;//kmoles NCO2 = 9.05; NCO = 1.34; NO2 = 9.98; NN2 = 79.63; PCO2F = 9.2;//% ( Feed ) PCOF = 21.3;//% PH2F = 18;//% PCH4F = 2.5;//% PN2F = 49;//% //Taking carbon balance, F = (NCO2 + NCO )/ ( (PCO2F + PCOF + PCH4F)/100); //Nitrogen balance gives, Nair = (NN2 - F*PN2F/(100) )* 100 / 79; R = Nair/F; disp(R,"(a)molar Ratio of air to fuel = ") Oexcess = NO2 - NCO / 2; Pexcess = Oexcess *100/ (Nair*21/100 - Oexcess); disp("%",Pexcess,"(b)Percent excess of air = ") NN2F = F * PN2F / 100; PN2F = NN2F *100/ NN2; disp("%",PN2F,"(c)Percent of nitrogen in the flue gas that came from fuel = ")
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// Function to round a floating point number x to n decimal places function [f]= fpround(x,n) f=round(x*10^n)/10^n; endfunction
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//[stk,nwrk,txt,top]=%log2for(nwrk) // //! txt=[] iop=evstr(op(2)) s2=stk(top);s1=stk(top-1);top=top-1 if s2(2)='2' then s2(1)='('+s2(1)+')',end if s1(2)='2' then s1(1)='('+s1(1)+')',end stk=list(s1(1)+ops(iop,1)+s2(1),'1') //end
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//water// //page 1.90 example 5// clc volume_hardwater=15000//in litres// volume_NaCl=120//Volume of NaCl in litres// Wt_per_Litre=30//% NaCl consumed by zeolite bed// total_wt=Wt_per_Litre*volume_NaCl//total gms NaCl consumed by zeolite bed// CaCO3_equivalent=total_wt*50/58.5//in terms of (gms/lit)// H=CaCO3_equivalent/volume_hardwater//Hardness of water(gms/lit)// Hardness=H*1000//Hardness of water(mg/lit) or ppm// printf("\nHardness of water sample is %.1f ppm",Hardness);
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clc Psat = 3.973 // Saturation pressure in MPa vf = 0.0012512 // specific volume of fluid in m^3/kg vg = 0.05013 // Specific volume of gas in m^3/kg hf = 1085.36 // Specific enthalpy of fluid in kJ/kg hfg = 1716.2 // Latent heat of vaporization in kJ/kg sf = 2.7927 // Specific entropy of fluid in kJ/kgK sfg = 3.2802 // Entropy change due to vaporization in kJ/kgK mf = 9 // Mass of liquid in kg V = 0.04 // Volume of vessel in m^3 // at T = 250 uf = 1080.39 //Specific internal energy in kJ/kg ufg = 1522// Change in internal energy due to vaporization in kJ/kg printf("\n Example 9.5") Vf = mf*vf // volume of fluid Vg = V-Vf // volume of gas mg = Vg/vg // mass of gas m = mf+mg // mass if mixture x = mg/m // quality of steam v = vf+x*(vg-vf) // specific volume of mixture h = hf+x*hfg // enthalpy of mixture s = sf+(x*sfg) // entropy of mixture u = h-Psat*1e6*v*1e-03 // Internal energy of mixture u_ = uf+x*ufg // Internal energy at 250 degree Celsius printf("\n The pressure is %f MPa",Psat) printf("\n The total mass of mixture is %f kg",m) printf("\n Specific volume is %f m3/kg",v) printf("\n Enthalpy is is %f kJ/kg",h) printf("\n The entropy is %f kJ/kg K",s) printf("\n The internal energy is %f kJ/kg",u) printf("\n At 250 degree Celsius, internal energy is %fkJ/kg",u_) //The answer provided in the textbook is wrong //The answers vary due to round off error
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function [y, xm]= rceps(x) //Produce the cepstrum of the signal x, and if desired, the minimum phase reconstruction of the signal x. //Calling Sequence //[y, xm] = rceps(x) //Parameters //x: real or complex vector input //Produce the cepstrum of the signal x, and if desired, the minimum phase reconstruction of the signal x. If x is a matrix, do so for each column of the matrix. //Examples // f0 = 70; Fs = 10000; # 100 Hz fundamental, 10kHz sampling rate // a = poly (0.985 * exp (1i*pi*[0.1, -0.1, 0.3, -0.3])); # two formants // s = 0.005 * randn (1024, 1); # Noise excitation signal // s(1:Fs/f0:length(s)) = 1; # Impulse glottal wave // x = filter (1, a, s); # Speech signal in x // [y, xm] = rceps (x .* hanning (1024)); # cepstrum and min phase reconstruction funcprot(0) lhs= argn(1) rhs= argn(2) if(rhs <1 | rhs> 1 ) error("Wrong number of Input Arguments"); end if(lhs<2 | lhs>2) error("Wrong number of Output Arguments") end [y,xm]= callOctave("rceps",x); endfunction
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N=100000; clf x=rand(1,N); u=1+4*rand(1,N); mu=sum(u)/N mu1=mean(u) clf x=-2+4*rand(1,N); y=-2+4*rand(1,N); plot(x,u,".") clf x=-2+4*rand(1,N); y=-2+4*rand(1,N); I=find((x.^2+y.^2)<=1); plot(x(I),y(I),".") //find retourne le vecteur des indices i pour lesquels x(i) est "vrai" clf x=-2+4*rand(1,N); y=-2+4*rand(1,N); I=find((x.^2+y.^2)<=1); pi=(length(I)/N)*16 clf x=rand(1,N); y=rand(1,N); a=min(x,y); b=max(x,y)-min(x,y); c=1-max(x,y); I=find(a+b>c & a+c>b & b+c>a); p=length(I)/N plot(x(I),y(I),".") clf x=ceil(rand(1,N)*6); mx=mean(x) mx1=sum(x)/N mx2=cumsum(x)./[1:N]; plot([1:N],mx2)
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//Example 7_5 clc(); clear; //To find the angular acceleration and angular velocity of one wheel vtf=20 //units in meters/sec r=0.4 //units in meters wf=vtf/r //units in rad/sec vf=20 //units in meters/sec v0=0 //units in meters/sec^2 t=9 //units in sec a=(vf-v0)/t //units in meters/sec^2 alpha=a/r //units in rad/sec^2 printf("Angular accelertion is a=%.2f meters/sec^2\n",a) printf("Angular velocity is alpha=%.2f rad/sec^2",alpha)
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Ex10_6.sce
// chapter 10 // example 10.6 // calculate frequency of EM waves // page 314 clear; clc; // given V=8.50; // in micro V (voltage across Josephson junction ) e=1.6E-19; // in C (charge of electron) h=6.626E-34; // in J/s (Planck’s constant) //calculate V=V*1E-6; // changing unit from V to microVolt v=2*e*V/h; // calculation of frequency of EM waves printf('\nThe frequency of EM waves is \tv=%1.3E Hz',v); // Note: the answer in the book is wrong due to calculation misatke
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21_21.sce
//Problem 21.21: A 200 V, d.c. shunt-wound motor has an armature resistance of 0.4 ohm and at a certain load has an armature current of 30 A and runs at 1350 rev/min. If the load on the shaft of the motor is increased so that the armature current increases to 45 A, determine the speed of the motor, assuming the flux remains constant. //initializing the variables: Ia1 = 30; // in Amperes Ia2 = 45; // in Amperes Ra = 0.4; // in ohm n1 = 1350/60; // in Rev/sec V = 200; // in Volts //calculation: //The relationship E proportional to (Phi*n) applies to both generators and motors. For a motor, //E = V - (Ia*Ra) E1 = V - (Ia1*Ra) E2 = V - (Ia2*Ra) //The relationship, E1/E2 = Phi1*n1/Phi2*n2, applies to both generators and motors. Since the flux is constant, Phi1 = Phi2 Phi2 = Phi1 n2 = E2*Phi1*n1/(Phi2*E1) printf("\n\n Result \n\n") printf("\n the speed of the motor is %.2f rev/sec ",n2)
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clc clear //input data P=330//Power output from the turbine is kW H=70//Head of operating turbine in m N=750//Speed of the turbine in rpm nH=0.94//Hydraulic efficiency n0=0.85//Overall efficiency FR=0.15//Flow ratio BR=0.1//Breadth ratio D1D2=2//Ratio inner and outer diameter of runner g=9.81//Acceleration due to gravity in m/s^2 dw=1000//Density of water in kg/m^3 //calculations Cr1=FR*(2*g*H)^(1/2)//Flow velocity at inlet in m/s Q=(P*10^3)/(dw*g*H*n0)//Discharge at outlet in m^3/s D1=(Q/(nH*3.1415*BR*Cr1))^(1/2)//Runner inlet diameter in m b1=BR*D1//Height of the runner vanes at inlet in m U1=(3.1415*D1*N)/60//Runner tip speed at inlet in m/s Cx1=(nH*g*H)/(U1)//Velocity of whirl at inlet in m/s a11=atand(Cr1/Cx1)//Guide blade angle in degree b11=atand(Cr1/(Cx1-U1))//Runner vane angle at inlet in degree D2=D1/D1D2//Runner outlet diameter in m U2=(3.1415*D2*N)/60//Runner tip speed at outlet in m/s Cr2=Cr1//Flow velocity at outlet in m/s b22=atand(Cr2/U2)//Runner vane angle at outlet in degree b2=D1*b1/D2//Width at outlet in m //output printf('(a)Flow velocity at inlet is %3.2f m/s\n(b)Discharge at outlet is %3.3f m^3/s\n(c)Runner inlet diameter is %3.3f m\n(d)Height of the runner vanes at inlet is %3.4f m\n(e)Guide blade angle is %3.2f degree\n(f) Runner vane angle at inlet is %3.2f degree\n Runner vane angle at outlet is %3.2f degree\n(g)Runner outlet diameter is %3.4f m\n(h)Width at outlet is %3.4f m\n(i)Runner tip speed at inlet is %3.2f m/s\n(j)Velocity of whirl at inlet is %3.f m/s',Cr1,Q,D1,b1,a11,b11,b22,D2,b2,U1,Cx1)
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Ex2_13.sce
// Example 2.13 clear all; clc; // Given data rho_NaCl = 2.17; // Density of Sodium Chloride(NaCl) in gram/cm^3 // From standard data table NA = 0.6022*10^24; // Avogodro number M_Na = 22.99; // Atomic weight of Sodium(Na) M_Cl = 35.453; // Atomic weight of Chlorine(Cl) M_NaCl = M_Na+M_Cl; // Molecular weight of Sodium Chloride(NaCl) // Calculation N = rho_NaCl*NA/M_NaCl; // As in NaCl, there is one atom of Na and Cl N_Na = N; N_Cl = N; // Result printf(" Atom density of Sodium and Chlorine = %5.4E molecules/cm^3 \n",N);
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c_pass2.sci
function cpr=c_pass2(bllst,connectmat,clkconnect,cor,corinv) // cor ; correspondance table with initial block ordering // // bllst: list with nblk elts where nblk denotes number of blocks. // Each element must be a list with 12 elements: // 1- function name (in string form if fortran routine) // 2- vector of number of inputs // 3- vector of number of ouputs // 4- vector of number of clock inputs // 5- vector of number of clock outputs // 6- vector (column) of continuous initial condition // 7- vector (column) of discrete initial condition // 8- vector (column) of real parameters // 9- vector (column) of integer parameters // 10- string: 'z' if zero-crossing, // 'l' logical // 11- vector of size <number of clock outputs> including // preprogrammed event firing times (<0 if no firing) // or [for backward compatibility] // boolean vector: i-th entry %t if initially output is fired // 12- boolean vector (1x2): 1st entry for dependence on u, 2nd on t // // connectmat: nx4 matrix. Each row contains, in order, the block // number and the port number of an outgoing scicopath, // and the block number and the port number of the target // ingoing scicopath. // // clkconnect: same as connectmat but for clock scicopaths. // // define some constants // Copyright INRIA show_trace=%f if show_trace then disp('c_pass1:'+string(timer())),end if bllst==list() then message(['No block can be activated']) cpr=list() ok=%f; return end clkptr=1,cliptr=1,typ_l=[],dep_ut=[] nblk=size(bllst) //take care of the heritage [bllst,inplnk,outlnk,clkptr,cliptr,inpptr,outptr,.. dep_ut,typ_l,typ_r,typ_m,tblock,typ_cons,ok]=mini_extract_info(bllst,.. connectmat,clkconnect) if show_trace then disp('c_pass20:'+string(timer())),end //if ~ok then // heritage block ! [outoin,outoinptr]=conn_mat(inpptr,outptr,inplnk,outlnk) [clkconnect,exe_cons]=pak_ersi(connectmat,clkconnect,dep_ut,typ_r,.. typ_l,outoin,outoinptr,tblock,typ_cons,clkptr) //end if show_trace then disp('c_pass21:'+string(timer())),end done=%f while ~done //replace all synchro (l) blocks recursively [clkptr,cliptr,typ_l,dep_ut,typ_m]=make_ptr(bllst,clkptr,cliptr,typ_l,.. dep_ut,typ_m) if show_trace then disp('c_pass3001:'+string(timer())),end clkconnect=cleanup(clkconnect) if show_trace then disp('c_pass3011:'+string(timer())),end [ok,done,bllst,connectmat,clkconnect,typ_l,typ_m,corinv]=paksazi(bllst,.. connectmat,clkconnect,corinv,clkptr,cliptr,typ_l,typ_m,dep_ut) if show_trace then disp('c_pass300011:'+string(timer())),end if ~ok then cpr=list() return end end if show_trace then disp('c_pass31:'+string(timer())),end //extract various info from bllst [lnkptr,inplnk,outlnk,clkptr,cliptr,inpptr,outptr,.. xptr,zptr,rpptr,ipptr,xc0,xd0,rpar,ipar,dep_ut,.. typ_z,typ_s,typ_x,typ_m,funs,funtyp,initexe,labels,.. bexe,boptr,blnk,blptr,ok]=extract_info(bllst,.. connectmat,clkconnect) if ~ok then cpr=list() return, end if ~or(typ_x) & or(typ_z) then message(['For using treshold, you need to have' 'a continuous system with state in your diagram.'; 'You can include DUMMY CLSS block (linear palette)' 'in your diagram.']); cpr=list() ok=%f; return end if show_trace then disp('c_pass41:'+string(timer())),end //form a matrix which gives destinations of each block [outoin,outoinptr]=conn_mat(inpptr,outptr,inplnk,outlnk) [evoutoin,evoutoinptr]=synch_clkconnect(typ_s,clkconnect) // if show_trace then disp('c_pass50:'+string(timer())),end // // discard duplicate calls to the same block port // and group calls to different ports of the same block // to compute execution table and its pointer. [ordptr1,execlk,execlk0,execlk_cons]=.. discard(clkptr,cliptr,clkconnect,exe_cons) clkconnect=[];exe_cons=[] if show_trace then disp('c_pass501:'+string(timer())),end // Set execution scheduling tables [ordptr,ordclk,cord,iord,oord,zord,critev,ok]=scheduler(inpptr,.. outptr,clkptr,execlk,execlk0,execlk_cons,ordptr1,outoin,outoinptr,.. evoutoin,evoutoinptr,typ_z,typ_x,typ_s,bexe,boptr,blnk,blptr); if ~ok then cpr=list() return, end if show_trace then disp('c_pass51:'+string(timer())),end //form scicos arguments izptr=ones(nblk+1,1) ztyp=0*ones(typ_z) ztyp(typ_z)=1 simtp=['scs','funs','xptr','zptr','izptr','inpptr','outptr','inplnk',.. 'outlnk','lnkptr','rpar','rpptr',.. 'ipar','ipptr','clkptr','ordptr','execlk','ordclk','cord','oord',.. 'zord','critev','nb','nblk','ztyp','ndcblk','subscr','funtyp',.. 'iord','labels'] subscr=[] ncblk=0;nxblk=0;ndblk=0;ndcblk=0; sim=tlist(simtp,funs,xptr,zptr,izptr,.. inpptr,outptr,inplnk,outlnk,.. lnkptr,rpar,rpptr,ipar,ipptr,clkptr,.. ordptr,execlk,ordclk,cord,oord,zord,.. critev(:),size(typ_z,'*'),ztyp,nblk,ndcblk,subscr,funtyp,iord,labels); //initialize agenda [tevts,evtspt,pointi]=init_agenda(initexe,clkptr) if show_trace then disp('c_pass61:'+string(timer())),end statetp=['xcs','x','z','iz','tevts','evtspt','pointi','outtb'] outtb=0*ones(lnkptr($)-1,1) iz0=[] state=tlist(statetp,xc0,xd0,iz0,tevts,evtspt,pointi,outtb); cpr=list(state,sim,cor,corinv) if show_trace then disp('c_pass71:'+string(timer())),end ///////////////////////////////////////////////////////////////////// function [ordptr2,ordclk,cord,iord,oord,zord,critev,ok]=.. scheduler(inpptr,.. outptr,clkptr,execlk,execlk0,execlk_cons,ordptr1,outoin,outoinptr,.. evoutoin,evoutoinptr,typ_z,typ_x,typ_s,bexe,boptr,blnk,blptr); // nblk=size(typ_x,1) if execlk0<>[] then //compute cord t_var_blk=execlk0(:,1) wec=zeros(1,nblk) wec(t_var_blk')=execlk0(:,2)' vec=-ones(1,nblk) vec(t_var_blk)=0*t_var_blk' // time varying blocks [r,ok]=new_tree2(vec,outoin,outoinptr,dep_ut) cord=[r,wec(r)'] else cord=[] end // //compute iord if execlk_cons<>[] then vec=-ones(1,nblk) no_tu_dep=execlk_cons(:,1) wec=zeros(1,nblk) wec(no_tu_dep')=execlk_cons(:,2)' vec(no_tu_dep)=0*no_tu_dep' [r,ok]=new_tree2(vec,outoin,outoinptr,dep_ut) iord=[r,wec(r)'] else iord=[] end // if ~ok then message('Algebraic loop detected; cannot be compiled.'); ordptr2=[],ordclk=[],cord=[],iord=[],oord=[],zord=[],critev=[] return, end ordclk=[] ordptr2=ordptr1 for o=1:clkptr(nblk+1)-1 vec=-ones(1,nblk); wec=zeros(1,nblk); vec(execlk(ordptr1(o):ordptr1(o+1)-1,1)')=.. zeros(execlk(ordptr1(o):ordptr1(o+1)-1,1))'; wec(execlk(ordptr1(o):ordptr1(o+1)-1,1)')=.. execlk(ordptr1(o):ordptr1(o+1)-1,2)'; [r,ok]=new_tree2(vec,outoin,outoinptr,dep_ut) if ~ok then message('Algebraic loop detected; cannot be compiled.'); ordptr2=[],ordclk=[],cord=[],iord=[],oord=[],zord=[],critev=[] return, end // r=[r,wec(r)'] ordptr2(1+o)=size(r,1)+ordptr2(o) ordclk=[ordclk;r] end if ordptr1<>ordptr2 then disp("serious bug,report");pause;end //ordptr=[ordptr1,ordptr2]; zord=cord oord=cord n=size(cord,1) vec=-ones(1,nblk); vec(cord(:,1))=0; // [ext_cord,ok]=new_tree3(vec,dep_ut,typ_s); typp=zeros(typ_s);typp(typ_s)=1 [ext_cord,ok]=new_tree3(vec,dep_ut,typp); if ~ok then disp('serious bug, report.');pause;end ext_cord=ext_cord(n+1:$); for iii=n:-1:1 i=cord(iii,1) fl=%f fz=%f // if typ_s(i) then fz=%t;fl=%t; end for ii=[outoin(outoinptr(i):outoinptr(i+1)-1,1)',.. evoutoin(evoutoinptr(i):evoutoinptr(i+1)-1,1)'] //ii est un block affecte par changement de sortie du //i-eme block de oord // if ii<=nxblk | ii>nb then fz=%t;end if typ_z(ii) then fz=%t;end if typ_x(ii) then fl=%t;end if fl&fz then break,end //si ii est un block integre (continu avec etat) //il faut garder i // for l=iii+1:n //si ii est un block qu'on a decide de garder //il faut garder i if or(ii==[zord(iii+1:$,1)',ext_cord]) then fz=%t; end if or(ii==[oord(iii+1:$,1)',ext_cord]) then fl=%t; end // if fl&fz then break,end // end if fl&fz then break; end end //mettre a zero si block doit etre supprimer if ~fl&~typ_x(i) then oord(iii,1)=0; end if ~fz&~typ_z(i) then zord(iii,1)=0; end end //supprimer les blocks a supprimer oord=oord(oord(:,1)<>zeros(oord(:,1)),:); zord=zord(zord(:,1)<>zeros(zord(:,1)),:) //critev: vecteur indiquant si evenement est important pour tcrit //ordclk_fut et ordptr3 sont l'analogue de ordclk et ordptr2 sauf //pour le fait que la dependance en temps n'est pas pris en compte. //Donc les blocks indiques sont des blocks susceptibles de produire //des discontinuites quand l'evenement se produit // 1: important; 0:non n=clkptr(nblk+1)-1 //nb d'evenement //a priori tous les evenemets sont non-importants critev=zeros(n,1) for i=1:n fl=%f for hh=ordptr1(i):ordptr1(i+1)-1 jj= ordclk(hh,1) //block excite par evenement i if ~(ordclk(hh,2)==0) then for ii=[outoin(outoinptr(jj):outoinptr(jj+1)-1,1)',.. evoutoin(evoutoinptr(jj):evoutoinptr(jj+1)-1,1)'] //block excite par block excite par evenement i //si il est integre, i est important if typ_x(ii) | typ_z(ii) then fl=%t;break; end end end if fl then break;end end if fl then critev(i,1)=1; end end function [ord,ok]=tree3(vec,dep_ut,typ_l) //compute blocks execution tree ok=%t nb=size(vec,'*') for j=1:nb+2 fini=%t for i=1:nb if vec(i)==j-1&typ_l(i)<>-1 then if j==nb+2 then message('algebraic loop detected');ok=%f;ord=[];return; end if typ_l(i)==1 then fini=%f; kk=bexe(boptr(i):boptr(i+1)-1)'; else kk=[]; for ii=blnk(blptr(i):blptr(i+1)-1)' if vec(ii)>-1 & (dep_ut(ii,1) | (typ_l(ii)==1)) then fini=%f; kk=[kk ii]; end end end vec(kk)=j*ones(kk) ; //disp(vec) end end if fini then break;end end [k,ord]=sort(-vec); ord(find(k==1))=[]; function [okk,done,bllst,connectmat,clkconnect,typ_l,typ_m,corinv]=.. paksazi(bllst,connectmat,clkconnect,corinv,clkptr,cliptr,.. typ_l,typ_m,dep_ut) okk=%t nblk=length(bllst) nblkorg=nblk if ~or(typ_l) then done=%t; return end change=%f for lb=find(typ_l) indx=find(clkconnect(:,3)==lb) if indx==[] then message(['A synchro block is inactive';'cannot be compile']); okk=%f;return end if or(clkconnect(indx,1)==lb) then message(['Algebraic loop detected';'on activation links']); okk=%f;return end nn=size(indx,'*') if nn>=2 then indxo=find(clkconnect(:,1)==lb) indy=find(connectmat(:,3)==lb) if size(indy,'*')>1 then disp('Synchro block cannot have more than 1 input') end for k=2:nn clkconnect(indx(k),3)=nblk+1; bllst(nblk+1)=bllst(lb); corinv(nblk+1)=corinv(lb); tmp=clkconnect(indxo,:); yek=ones(tmp(:,1)) clkconnect=[clkconnect;[yek*(nblk+1),tmp(:,[2 3 4])]] nblk=nblk+1 end onn=ones(nn-1,1) connectmat=[connectmat;.. [onn*connectmat(indy,[1 2]),[nblkorg+1:nblk]',onn]] change=%t nblkorg=nblk end end if change then done=%f;return; end // clkconnecttmp=clkconnect; clkconnect=clkconnecttmp(find(clkconnecttmp(:,1)<>0),:); clkconnect0=clkconnecttmp(find(clkconnecttmp(:,1)==0),:); bclkconnect0=clkconnect0(:,[1 3]); con0=zeros(clkconnect0(:,1)); texeclk0=bclkconnect0(find(bclkconnect0(:,1)==0),2); con=clkptr(clkconnect(:,1))+clkconnect(:,2)-1; [junk,ind]=sort(-con);con=-junk; clkconnect=clkconnect(ind,:); // bclkconnect=clkconnect(:,[1 3]); boptr=1; bexe=[]; for i=1:nblk r=bclkconnect(find(bclkconnect(:,1)==i),2); bexe=[bexe;r]; boptr=[boptr;boptr($)+size(r,1)]; end // bconnectmat=connectmat(:,[1 3]); blptr=1; blnk=[]; for i=1:nblk r=bconnectmat(find(bconnectmat(:,1)==i),2); blnk=[blnk;r]; blptr=[blptr;blptr($)+size(r,1)]; end // tclkconnect=clkconnect(~typ_l(clkconnect(:,1)),:); tcon=clkptr(tclkconnect(:,1))+tclkconnect(:,2)-1; texeclk=tclkconnect(:,[3 4]); ordptr1=1; for i=1:clkptr($)-1 tmp=find(tcon<=i); if tmp==[] then ordptr1(i+1)=ordptr1(i); else ordptr1(i+1)=max(tmp)+1; end end // clkconnect=[clkconnect0;clkconnect]; con=[con0;con]; // pointer=[]; for o=0:clkptr($)-1 if o==0 then texeclki=texeclk0; else texeclki=texeclk(ordptr1(o):ordptr1(o+1)-1,1);end if texeclki<>[] then vec=-ones(1,nblk); vec(texeclki')=zeros(texeclki)'; // [r,ok]=new_tree3(vec,dep_ut,typ_l); typ_lm=zeros(typ_l);typ_lm(typ_l)=1;typ_lm(typ_m)=-1; [r,ok]=new_tree3(vec,dep_ut,typ_lm); if ~ok then message('Algebraic loop detected; cannot be compiled.'); bllst=[];connectmat=[];clkconnect=[];typ_l=[];corinv=[] okk=%f;done=%t;return, end pointer=find(con==o) for bl=r if typ_l(bl) then mod=bllst(bl);mod(10)='s',bllst(bl)=mod,typ_l(bl)=%f pointer=pointer(find(clkconnect(pointer,3)<>bl)); yek=ones(pointer'); clkconnect(pointer,:)=.. [yek*bl,yek,clkconnect(pointer,[3 4])]; //connect all the event outputs of the logical block to .... for bl_out=2:clkptr(bl+1)-clkptr(bl) clkconnect=[clkconnect;[yek*bl,bl_out*yek,clkconnect(pointer,[3 4])]]; end // ok=%f,return else pointer=pointer(find(clkconnect(pointer,3)<>bl)) end end end if pointer<>[] then warning('problem1');pause;end end; // if or(typ_l) then warning('problem2');pause;end // okk=%t;done=%t; function [ordptr1,execlk,clkconnectj0,clkconnectj_cons]=.. discard(clkptr,cliptr,clkconnect,exe_cons) if exe_cons<>[] then clkconnectj=exe_cons mma=maxi(clkconnectj(:,2))+1 con=mma*(clkconnectj(:,1))+clkconnectj(:,2) [junk,ind]=sort(-con);con=-junk clkconnectj=clkconnectj(ind,:) // discard duplicate calls to the same block port if size(con,'*')>=2 then clkconnectj(find(con(2:$)-con(1:$-1)==0),:)=[] end // group calls to different ports of the same block. clkconnectj=[clkconnectj(:,1),2^(clkconnectj(:,2)-ones(clkconnectj(:,2)))] clkconnectj=int(clkconnectj) con=clkconnectj(:,1) clkconnectj_cons=[] if size(con,'*')>=2 then iini=[find(con(2:$)-con(1:$-1)<>0),size(clkconnectj,1)] else iini=1 end for ii=iini clkconnectj_cons=[clkconnectj_cons;[clkconnectj(ii,1),.. mysum(clkconnectj(find(clkconnectj(:,1)==clkconnectj(ii,1)),2))]] end else clkconnectj_cons=[] end clkconnecttmp=clkconnect clkconnect=clkconnecttmp(find(clkconnecttmp(:,1)<>0),:) clkconnect0=clkconnecttmp(find(clkconnecttmp(:,1)==0),:) if clkconnect0<>[] then clkconnectj=[clkconnect0(:,3),clkconnect0(:,4)] // con=cliptr(clkconnectj(:,1))+clkconnectj(:,2)-ones(clkconnectj(:,2)) mma=maxi(clkconnectj(:,2))+1 con=mma*clkconnectj(:,1)+clkconnectj(:,2) // [junk,ind]=sort(-con);con=-junk clkconnectj=clkconnectj(ind,:) // discard duplicate calls to the same block port if size(con,'*')>=2 then clkconnectj(find(con(2:$)-con(1:$-1)==0),:)=[] end // group calls to different ports of the same block. clkconnectj=[clkconnectj(:,1),2^(clkconnectj(:,2)-ones(clkconnectj(:,2)))] clkconnectj=int(clkconnectj) con=clkconnectj(:,1) clkconnectj0=[] if size(con,'*')>=2 then iini=[find(con(2:$)-con(1:$-1)<>0),size(clkconnectj,1)] else iini=1 end for ii=iini clkconnectj0=[clkconnectj0;[clkconnectj(ii,1),.. mysum(clkconnectj(find(clkconnectj(:,1)==clkconnectj(ii,1)),2))]] end else clkconnectj0=[] end con=clkptr(clkconnect(:,1))+clkconnect(:,2)-1 [junk,ind]=sort(-con);con=-junk clkconnect=clkconnect(ind,:) // ordptr1=1 for i=1:clkptr($)-1 tmp=find(con<=i) if tmp==[] then ordptr1(i+1)=ordptr1(i) else ordptr1(i+1)=max(tmp)+1 end end execlk=[] new_ordptr1=1 if show_trace then disp('c_pass50001:'+string(timer())),end for j=1:clkptr($)-1 if ordptr1(j)<>ordptr1(j+1) then clkconnectj=[clkconnect(ordptr1(j):ordptr1(j+1)-ones(ordptr1(j+1)),3),.. clkconnect(ordptr1(j):ordptr1(j+1)-1,4)] // con=cliptr(clkconnectj(:,1))+clkconnectj(:,2)-ones(clkconnectj(:,2)) mma=maxi(clkconnectj(:,2))+1 con=mma*clkconnectj(:,1)+clkconnectj(:,2) [junk,ind]=sort(-con);con=-junk clkconnectj=clkconnectj(ind,:) // discard duplicate calls to the same block port if size(con,'*')>=2 then clkconnectj(find(con(2:$)-con(1:$-1)==0),:)=[] end // group calls to different ports of the same block. clkconnectj=[clkconnectj(:,1),2^(clkconnectj(:,2)-ones(clkconnectj(:,2)))] clkconnectj=int(clkconnectj) con=clkconnectj(:,1) clkconnectjj=[] if size(con,'*')>=2 then iini=[find(con(2:$)-con(1:$-1)<>0),size(clkconnectj,1)] else iini=1 end for ii=iini clkconnectjj=[clkconnectjj;[clkconnectj(ii,1),.. mysum(clkconnectj(find(clkconnectj(:,1)==clkconnectj(ii,1)),2))]] end else clkconnectjj=[] end execlk=[execlk;clkconnectjj] new_ordptr1=[new_ordptr1;new_ordptr1($)+size(clkconnectjj,1)] end ordptr1=new_ordptr1 function a=mysum(b) if b<>[] then a=sum(b), else a=[], end function [lnkptr,inplnk,outlnk,clkptr,cliptr,inpptr,outptr,.. xptr,zptr,rpptr,ipptr,xc0,xd0,rpar,ipar,dep_ut,.. typ_z,typ_s,typ_x,typ_m,funs,funtyp,initexe,labels,.. bexe,boptr,blnk,blptr,ok]=extract_info(bllst,.. connectmat,clkconnect) ok=%t nbl=length(bllst) clkptr=zeros(nbl+1,1);clkptr(1)=1 cliptr=clkptr;inpptr=cliptr;outptr=inpptr; //clkptr=1;cliptr=1; //inpptr=1;outptr=1; xptr=1;zptr=1; rpptr=clkptr;ipptr=clkptr; //rpptr=1;ipptr=1; // xc0=[];xd0=[];rpar=[];ipar=[]; fff=ones(nbl,1)==1 dep_ut=[fff,fff];typ_z=fff;typ_s=fff;typ_x=fff;typ_m=fff; initexe=[]; funs=list(); funtyp=zeros(typ_z) labels=[] // // for i=1:nbl ll=bllst(i) if type(ll(1))==15 then funs(i)=ll(1)(1) funtyp(i,1)=ll(1)(2) else funs(i)=ll(1); funtyp(i,1)=0; end if funtyp(i,1)>999 then if ~c_link(funs(i)) then x_message(['A C or Fortran block is used but not linked'; 'You can save your compiled diagram and load it'; 'This will automatically link the C or Fortran function']) end end inpnum=ll(2);outnum=ll(3);cinpnum=ll(4);coutnum=ll(5); // inpptr(i+1)=inpptr(i)+size(inpnum,'*') outptr(i+1)=outptr(i)+size(outnum,'*') cliptr(i+1)=cliptr(i)+size(cinpnum,'*') clkptr(i+1)=clkptr(i)+size(coutnum,'*') // xc0=[xc0;ll(6)(:)] xptr(i+1)=xptr(i)+size(ll(6),'*') if funtyp(i,1)==3 then //sciblocks xd0k=var2vec(ll(7)) else xd0k=ll(7)(:) end xd0=[xd0;xd0k] zptr(i+1)=zptr(i)+size(xd0k,'*') // if funtyp(i,1)==3 then //sciblocks rpark=var2vec(ll(8)) else rpark=ll(8)(:) end rpar=[rpar;rpark] rpptr(i+1)=rpptr(i)+size(rpark,'*') if type(ll(9))==1 then ipar=[ipar;ll(9)(:)] ipptr(i+1)=ipptr(i)+size(ll(9),'*') else ipptr(i+1)=ipptr(i) end // typ_z(i)=ll(10)=='z' typ_s(i)=ll(10)=='s' typ_x(i)=ll(6)<>[] typ_m(i)=ll(10)=='m' dep_ut(i,:)=(ll(12)(:))' // if ll(5)<>[] then ll11=ll(11) prt=find(ll11>=zeros(ll11)) nprt=prod(size(prt)) initexe=[initexe;.. [i*ones(nprt,1),matrix(prt,nprt,1),matrix(ll11(prt),nprt,1)]]; end if size(ll)>=13 then if type(ll(13))==10 then labels=[labels;ll(13)(1)] else labels=[labels;' '] end else labels=[labels;' '] end end clkconnect=clkconnect(find(clkconnect(:,1)<>0),:); con=clkptr(clkconnect(:,1))+clkconnect(:,2)-1; [junk,ind]=sort(-con);con=-junk; clkconnect=clkconnect(ind,:); // bclkconnect=clkconnect(:,[1 3]); boptr=1; bexe=[]; for i=1:nbl r=bclkconnect(find(bclkconnect(:,1)==i),2); bexe=[bexe;r]; boptr=[boptr;boptr($)+size(r,1)]; end // bconnectmat=connectmat(:,[1 3]); blptr=1; blnk=[]; for i=1:nbl r=bconnectmat(find(bconnectmat(:,1)==i),2); blnk=[blnk;r]; blptr=[blptr;blptr($)+size(r,1)]; end // [ok,bllst]=adjust_inout(bllst,connectmat) nlnk=size(connectmat,1) inplnk=zeros(inpptr($)-1,1);outlnk=zeros(outptr($)-1,1);ptlnk=1; lnkbsz=[] for jj=1:nlnk ko=outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1) ki=inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1) if ko<>0 & ki<>0 then if ko>ki then outlnk(outlnk>ko)=outlnk(outlnk>ko)-1 outlnk(outlnk==ko)=ki inplnk(inplnk>ko)=inplnk(inplnk>ko)-1 inplnk(inplnk==ko)=ki ptlnk=-1+ptlnk lnkbsz(ko)=[] elseif ki>ko outlnk(outlnk>ki)=outlnk(outlnk>ki)-1 outlnk(outlnk==ki)=ko inplnk(inplnk>ki)=inplnk(inplnk>ki)-1 inplnk(inplnk==ki)=ko ptlnk=-1+ptlnk lnkbsz(ki)=[] end elseif ko<>0 then inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1)=ko elseif ki<>0 then outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1)=ki else outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1)=ptlnk inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1)=ptlnk lnkbsz=[lnkbsz;bllst(connectmat(jj,1))(3)(connectmat(jj,2))] ptlnk=1+ptlnk end end lnkptr=cumsum([1;lnkbsz]) //store unconnected outputs, if any, at the end of outtb unco=find(outlnk==0); if unco==[] then return;end siz_unco=0 for j=unco m=maxi(find(outptr<=j)) n=j-outptr(m)+1 siz_unco=maxi(siz_unco,bllst(m)(3)(n)) end lnkptr=[lnkptr;lnkptr($)+siz_unco] outlnk(unco)=maxi(outlnk)+1 function [outoin,outoinptr]=conn_mat(inpptr,outptr,inplnk,outlnk) outoin=[];outoinptr=1 nblk=size(inpptr,1)-1 for i=1:nblk k=outptr(i):outptr(i+1)-1 ii=[] for j=outlnk(k)' ii=[ii,find(inplnk==j)] end outoini=[];jj=0 for j=ii m=maxi(find(inpptr<=j)) n=j-inpptr(m)+1 outoini=[outoini;[m,n]] jj=jj+1 end outoinptr=[outoinptr;outoinptr($)+jj] outoin=[outoin;outoini] end function [clkptr,cliptr,typ_l,dep_ut,typ_m]=.. make_ptr(bllst,clkptr,cliptr,typ_l,dep_ut,typ_m) nblk0=size(clkptr,'*') nbl=size(bllst) if nbl<nblk0 then return; end i=nblk0;ll=bllst(i) cliptr1=zeros(nbl-nblk0,1);clkptr1=cliptr1; cliptr1(1)=cliptr($)+sum(ll(4)) clkptr1(1)=clkptr($)+sum(ll(5)) typ_l1=cliptr1==1;dep_ut1=[typ_l1,typ_l1]; typ_l1(1)=ll(10)=='l';typ_m1(1)=ll(10)=='m';dep_ut1(1,:)=ll(12); j=1 for i=nblk0+1:nbl j=j+1 ll=bllst(i) cliptr1(j)=cliptr1(j-1)+sum(ll(4)) clkptr1(j)=clkptr1(j-1)+sum(ll(5)) typ_l1(j)=ll(10)=='l' typ_m1(j)=ll(10)=='m' dep_ut1(j,:)=ll(12) end cliptr=[cliptr;cliptr1] clkptr=[clkptr;clkptr1] typ_l=[typ_l;typ_l1] typ_m=[typ_m;typ_m1] dep_ut=[dep_ut;dep_ut1]; function [ord,ok]=tree2(vec,outoin,outoinptr,dep_ut) //compute blocks execution tree ok=%t; nb=size(vec,'*'); for j=1:nb+2 fini=%t for i=1:nb if vec(i)==j-1 then if j==nb+2 then message('algebraic loop detected');ok=%f;ord=[];return; end // kk=[]; for k=outoinptr(i):outoinptr(i+1)-1 ii=outoin(k,1); if dep_ut(ii,1)&vec(ii)>-1 then fini=%f; // kk=[kk ii]; vec(ii)=j; end end // vec(kk)=j*ones(kk) ; end end if fini then break;end end [k,ord]=sort(-vec); ord(find(k==1))=[]; ord=ord(:) function [ok,bllst]=adjust_inout(bllst,connectmat) nlnk=size(connectmat,1) for hhjj=1:length(bllst) for hh=1:length(bllst) ok=%t for jj=1:nlnk nout=bllst(connectmat(jj,1))(3)(connectmat(jj,2)) nin=bllst(connectmat(jj,3))(2)(connectmat(jj,4)) if (nout>0&nin>0) then if nin<>nout then bad_connection(corinv(connectmat(jj,1)),connectmat(jj,2),nout,.. corinv(connectmat(jj,3)),connectmat(jj,4),nin) ok=%f;return end elseif (nout>0&nin<0) then ww=find(bllst(connectmat(jj,3))(2)==nin) bllst(connectmat(jj,3))(2)(ww)=nout ww=find(bllst(connectmat(jj,3))(3)==nin) bllst(connectmat(jj,3))(3)(ww)=nout elseif (nin>0&nout<0) then ww=find(bllst(connectmat(jj,1))(3)==nout) bllst(connectmat(jj,1))(3)(ww)=nin ww=find(bllst(connectmat(jj,1))(2)==nout) bllst(connectmat(jj,1))(2)(ww)=nin elseif (nin==0) then ww=bllst(connectmat(jj,3))(3)(:) if mini(ww)>0 then if nout>0 then if sum(ww)==nout then bllst(connectmat(jj,3))(2)(connectmat(jj,4))=nout else bad_connection(corinv(connectmat(jj,3))) ok=%f;return end else bllst(connectmat(jj,3))(2)(connectmat(jj,4))=sum(ww) ok=%f end else nww=ww(find(ww<0)) if norm(nww-nww(1),1)==0 & nout>0 then bllst(connectmat(jj,3))(2)(connectmat(jj,4))=nout k=(nout-sum(ww(find(ww>0))))/size(nww,'*') if k==int(k) then bllst(connectmat(jj,3))(3)(find(ww<0))=k else bad_connection(corinv(connectmat(jj,3))) ok=%f;return end else ok=%f end end elseif (nout==0) then ww=bllst(connectmat(jj,1))(2)(:) if mini(ww)>0 then if nin>0 then if sum(ww)==nin then bllst(connectmat(jj,1))(3)(connectmat(jj,2))=nin else bad_connection(corinv(connectmat(jj,1))) ok=%f;return end else bllst(connectmat(jj,1))(3)(connectmat(jj,2))=sum(ww) ok=%f end else nww=ww(find(ww<0)) if norm(nww-nww(1),1)==0 & nin>0 then bllst(connectmat(jj,1))(3)(connectmat(jj,2))=nin k=(nout-sum(ww(find(ww>0))))/size(nww,'*') if k==int(k) then bllst(connectmat(jj,1))(2)(find(ww<0))=k else bad_connection(corinv(connectmat(jj,1))) ok=%f;return end else ok=%f end end else //case where both are negative ok=%f end end if ok then return, end end message('Not enough information to determine port sizes'); for jj=1:nlnk nout=bllst(connectmat(jj,1))(3)(connectmat(jj,2)) nin=bllst(connectmat(jj,3))(2)(connectmat(jj,4)) if nout<=0&nin<=0 then ninnout=under_connection(corinv(connectmat(jj,1)),connectmat(jj,2),nout,.. corinv(connectmat(jj,3)),connectmat(jj,4),nin) if ninnout==[] then ok=%f;return;end if ninnout<=0 then ok=%f;return;end bllst(connectmat(jj,1))(3)(connectmat(jj,2))=ninnout bllst(connectmat(jj,3))(2)(connectmat(jj,4))=ninnout end end end function ninnout=under_connection(path_out,prt_out,nout,path_in,prt_in,nin) // alert for badly connected blocks // path_out : Path of the "from block" in scs_m // path_in : Path of the "to block" in scs_m //! lp=mini(size(path_out,'*'),size(path_in,'*')) k=find(path_out(1:lp)<>path_in(1:lp)) path=path_out(1:k(1)-1) // common superbloc path path_out=path_out(k(1)) // "from" block number path_in=path_in(k(1)) // "to" block number if path==[] then hilite_obj(scs_m(path_out)) if or(path_in<>path_out) then hilite_obj(scs_m(path_in)),end ninnout=evstr(dialog(['Hilited block(s) have connected ports '; 'with sizes that cannot be determiend by the context'; 'what is the size of this link'],'1')) hilite_obj(scs_m(path_out)) if or(path_in<>path_out) then hilite_obj(scs_m(path_in)),end else mxwin=maxi(winsid()) for k=1:size(path,'*') hilite_obj(scs_m(path(k))) scs_m=scs_m(path(k))(3)(8); scs_show(scs_m,mxwin+k) end hilite_obj(scs_m(path_out)) if or(path_in<>path_out) then hilite_obj(scs_m(path_in)),end ninnout=evstr(dialog(['Hilited block(s) have connected ports '; 'with sizes that cannot be determiend by the context'; 'what is the size of this link'],'1')) for k=size(path,'*'):-1:1,xdel(mxwin+k),end scs_m=null() unhilite_obj(scs_m(path(1))) end function [clkconnect,exe_cons]=pak_ersi(connectmat,clkconnect,.. dep_ut,typ_r,typ_l,outoin,outoinptr,tblock,typ_cons,clkptr) //add every event to the time event because time includes all events all_out=[] for k=1:size(clkptr,1)-1 if ~typ_l(k) then kk=[1:(clkptr(k+1)-clkptr(k))]' all_out=[all_out;[k*ones(kk),kk]] end end all_out=[all_out;[0,0]] //add time event if needed ind=find(tblock) ind=ind(:) for k=ind' clkconnect=[clkconnect;[all_out,ones(all_out)*[k,0;0,0]]] end if show_trace then disp('c_pass4444:'+string(timer())),end ind1=find(typ_cons) ind=[ind;ind1(:)] exe_cons=[ind,zeros(ind)] vec=-ones(1,nblk); vec(ind)=0 [r,ok]=new_tree4(vec,outoin,outoinptr,typ_r) exe_cons=[exe_cons;r] if show_trace then disp('c_pass4445:'+string(timer())),end [clkr,clkc]=size(clkconnect); mm=maxi(clkconnect)+1; cll=clkconnect(:,1)*mm+clkconnect(:,2); [cll,ind]=sort(-cll); clkconnect=clkconnect(ind,:); cll=[-1;-cll;mm]; ii=find(cll(2:$)-cll(1:$-1)<>0) for k=1:size(ii,'*')-1 oo=[ii(k):ii(k+1)-1] vec=-ones(1,nblk); vec(clkconnect(oo,3))=0 [r,ok]=new_tree4(vec,outoin,outoinptr,typ_r) m=size(r,1) r=[clkconnect(ii(k),1)*ones(m,1),clkconnect(ii(k),2)*ones(m,1),r] clkconnect=[clkconnect;r] end if show_trace then disp('c_pass4446:'+string(timer())),end function [r,ok]=tree4(vec,outoin,outoinptr,typ_r) //compute blocks which inherit ok=%t; nb=size(vec,'*'); r=[]; for j=1:nb-1 fini=%t for i=1:nb if vec(i)==j-1 then for k=outoinptr(i):outoinptr(i+1)-1 ii=outoin(k,1); if (vec(ii)>-1)|typ_r(ii) then fini=%f; vec(ii)=j; end if typ_r(ii) then r=[r;outoin(k,:)] end end end end if fini then break;end end function [bllst,inplnk,outlnk,clkptr,cliptr,inpptr,outptr,.. dep_ut,typ_l,typ_r,typ_m,tblock,typ_cons,ok]=mini_extract_info(bllst,.. connectmat,clkconnect) ok=%t nbl=length(bllst) clkptr=zeros(nbl+1,1);clkptr(1)=1 cliptr=clkptr;inpptr=cliptr;outptr=inpptr; //clkptr=1;cliptr=1;inpptr=1;outptr=1; fff=ones(nbl,1)==1 dep_ut=[fff,fff];typ_l=fff;typ_r=fff;typ_cons=fff;typ_m=fff; tblock=fff //dep_ut=[];typ_l=[];typ_r=[];typ_cons=[] //tblock=[] // specifies blocks that must be connected to time event. // for i=1:nbl ll=bllst(i) inpnum=ll(2);outnum=ll(3);cinpnum=ll(4);coutnum=ll(5); // if cinpnum==[]&ll(10)<>'z' then // this block inherits ok=%f typ_r(i)=~ll(12)(2) tblock(i)=ll(12)(2) //if block depends on time but has no event input port if ~ll(12)(2) then //inherits from the inputs cinpnum=ones(inpnum) bllst(i)(4)=cinpnum //XXXXXXXXXXXXXXXXXXXXX end // else tblock(i)=ll(12)(2);typ_r(i)=%f end inpptr(i+1)=inpptr(i)+size(inpnum,'*') outptr(i+1)=outptr(i)+size(outnum,'*') cliptr(i+1)=cliptr(i)+size(cinpnum,'*') clkptr(i+1)=clkptr(i)+size(coutnum,'*') // typ_l(i)=ll(10)=='l';typ_m(i)=ll(10)=='m';dep_ut(i,:)=(ll(12)(:))'; typ_cons(i)=[cinpnum==[]&inpnum==[]&~ll(12)(2)] // end if show_trace then disp('c_pass22222222:'+string(timer())),end //' nlnk=size(connectmat,1) inplnk=zeros(inpptr($)-1,1);outlnk=zeros(outptr($)-1,1);ptlnk=1; for jj=1:nlnk ko=outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1) ki=inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1) if ko<>0 & ki<>0 then if ko>ki then outlnk(outlnk>ko)=outlnk(outlnk>ko)-1 outlnk(outlnk==ko)=ki inplnk(inplnk>ko)=inplnk(inplnk>ko)-1 inplnk(inplnk==ko)=ki ptlnk=-1+ptlnk elseif ki>ko outlnk(outlnk>ki)=outlnk(outlnk>ki)-1 outlnk(outlnk==ki)=ko inplnk(inplnk>ki)=inplnk(inplnk>ki)-1 inplnk(inplnk==ki)=ko ptlnk=-1+ptlnk end elseif ko<>0 then inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1)=ko elseif ki<>0 then outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1)=ki else outlnk(outptr(connectmat(jj,1))+connectmat(jj,2)-1)=ptlnk inplnk(inpptr(connectmat(jj,3))+connectmat(jj,4)-1)=ptlnk ptlnk=1+ptlnk end end //store unconnected outputs, if any, at the end of outtb unco=find(outlnk==0); if unco==[] then return;end outlnk(unco)=maxi(outlnk)+1 function [evoutoin,evoutoinptr]=synch_clkconnect(typ_s,clkconnect) nblk=size(typ_s,'*') evoutoin=[];evoutoinptr=1 for i=1:nblk if typ_s(i) then dd=clkconnect(clkconnect(:,1)==i,3) else dd=[] end evoutoin=[evoutoin;dd] evoutoinptr=[evoutoinptr;evoutoinptr($)+size(dd,'*')] end function clkconnect=cleanup(clkconnect) mm=maxi(clkconnect)+1 cc=clkconnect(:,4)+mm*clkconnect(:,3)+clkconnect(:,2)*mm^2+.. clkconnect(:,1)*mm^3 [cc1,ind]=sort(-cc) clkconnect=clkconnect(ind,:) ind=find(cc1(2:$)-cc1(1:$-1)==0) clkconnect(ind,:)=[] function [r,ok]=new_tree2(vec,outoin,outoinptr,dep_ut) dd=zeros(dep_ut);dd(dep_ut)=1; [r,ok2]=sci_tree2(vec,outoin,outoinptr,dd) ok=ok2==1 function [r,ok]=new_tree3(vec,dep_ut,typ_l) dd=zeros(dep_ut);dd(dep_ut)=1; //ddd=zeros(typ_l);ddd(typ_l)=1; [r2,ok2]=sci_tree3(vec,dd,typ_l,bexe,boptr,blnk,blptr) r=r2' ok=ok2==1 function [r,ok]=new_tree4(vec,outoin,outoinptr,typ_r) nd=zeros(size(vec,'*'),(max(outoin(:,2))+1)); ddd=zeros(typ_r);ddd(typ_r)=1; [r1,r2]=sci_tree4(vec,outoin,outoinptr,nd,ddd) r=[r1',r2'] ok=%t
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t=[0:0.01:5*%pi]; A=5; wc=2; Vm=A.*squarewave(t); Vc=A.*sin(wc.*t); Vp=Vm.*Vc; subplot(3,1,1); plot(t,Vm,'black'); subplot(3,1,2); plot(t,Vc,'black'); subplot(3,1,3); plot(t,Vp,'black');
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//Section-3,Example-1,Page no.-EC.19 //To calculate the BOD of the sample. clc; DO_b=840 DO_i=230 ml_ad=80 //ml. of sample after dilution ml_bd=50 //ml. of sample before dilution BOD=((DO_b-DO_i)*(ml_ad/ml_bd)) disp (BOD,'Biological Oxygen Demand (ppm)')
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//Caption: Scilab code for Edge Detection using Different Edge detectors //[1]. Sobel [2].Prewitt [3].Log [4].Canny //Fig7.27 //page389 close; clc; a = imread('E:\DIP_JAYARAMAN\Chapter7\sailing.jpg'); a = rgb2gray(a); c = edge(a,'sobel'); d = edge(a,'prewitt'); e = edge(a,'log'); f = edge(a,'canny'); ShowImage(a,'Original Image') title('Original Image') figure ShowImage(c,'Sobel') title('Sobel') figure ShowImage(d,'Prewitt') title('Prewitt') figure ShowImage(e,'Log') title('Log') figure ShowImage(f,'Canny') title('Canny')
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// Scilab code Ex3.16 : Pg:121 (2008) clc;clear; R = 20; // Radius of curvature of the spherical surface, cm mu = 1.5; // Refractive index of the material h = 5; // First height of the incident ray from the principal axis, cm delta_f_h = h^2/(2*mu*(mu - 1)*R); // Spherical aberration of the spherical surface, cm printf("\nFor h = %d, the Spherical aberration of the spherical surface = %4.2f cm", h, delta_f_h); h = 7; // Second height of the incident ray from the principal axis, cm delta_f_h = h^2/(2*mu*(mu - 1)*R); // Spherical aberration of the spherical surface, cm printf("\nFor h = %d, the Spherical aberration of the spherical surface = %4.2f cm", h, delta_f_h); // Result // For h = 5, the Spherical aberration of the spherical surface = 0.83 cm // For h = 7, the Spherical aberration of the spherical surface = 1.63 cm
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function lcaNewMonitorValue // Check if monitored PVs need to be read, i. // // Calling Sequence // //[flags] = lcaNewMonitorValue(pvs, type) // // Description // // Check if monitored PVs need to be read, i.e, if fresh data are // available (e.g., due to initial connection or changes in value and/or // severity status). Reading the actual data must be done using [1]lcaGet. // // Parameters // // pvs // Column vector (in matlab: m x 1 cell- matrix) of m strings. // // type // (optional argument) A string specifying the data type to be used // for the channel access data transfer. The native type is used by // default. See [2]here for more information. // // Note that monitors are specific to a particular data type and // therefore lcaNewMonitorValue will only report the status for a // monitor that had been established (by [3]lcaSetMonitor) with a // matching type. Using the ``native'' type, which is the default, // for both calls satisfies this condition. // // flags // Column vector of flag values. A value of zero indicates that no // new data are available - the monitored PV has not changed since // it was last read (the data, that is, not the flag). A value of // one indicates that new data are available for reading (lcaGet). // // NOTE: As of labCA version 3 the flags no longer report error // conditions. Errors are now reported in the [4]standard way, // i.e., by aborting the labCA call. Errors can be caught by the // standard scilab try-catch-end construct. The [5]lcaLastError // routine can be used to obtain status information for individual // channels if lcaNewMonitorValue fails on a vector of PVs. // // See also [6]lcaNewMonitorWait. // // Examples // //try and(lcaNewMonitorValue(pvvec)) // vals = lcaGet(pvvec) //catch // errs = lcaLastError() // handleErrs(errs) //end // __________________________________________________________________ // // // till 2018-02-28 // //See also // // lcaGet 1. lcaGet // lcaGet 2. lcaGet // lcaSetMonitor 3. lcaSetMonitor // Error 4. Error // lcaLastError 5. lcaLastError // lcaNewMonitorWait 6. lcaNewMonitorWait endfunction
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clc //Given that lambda1 = 6560 // wavelength in Angstrom n1 = 1 // transition state no n2 = 2 // transition state no n3 = 3 // transition state no. //Sample Problem 14 page No. 141 printf("\n\n\n # Problem 14 # \n") printf("\n Standard formula Used \n\n For Balmer Series \n 1/lambda = R*(1-(1/n)^2) \n\n For Lyman series \n 1/lambda = R*((1/2)^2 -(1/n)^2)") lambda2 = (n2^2 * n1^2) *(n3^2 - n2^2) /( (n2^2 - n1^2) * (n3^2 * n2^2)) * lambda1 //calculation of Wavelength of first line of Lyman series printf ("\n \nWavelength of first line of Lyman series is %f Angstrom. ", lambda2 )
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//Exa 4.9 clc; clear; close; // Given data Vin=5;// in V R1= 1;// in kΩ R1= R1*10^3;// in Ω CF= 0.1;// in µF CF= CF*10^-6;// in F f= 1;// in kHz f= f *10^3;// in Hz T= 1/f;// in sec delta_Vout= Vin*T/(2*R1*CF);// in V disp(delta_Vout,"The maximum change in output voltage in volts is : ") S= 2*%pi*f*Vin;// in V/sec disp(S*10^-6,"The minimum slew rate required in V/micro-sec is : ")
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16_15.sce
clc; delta_t=277-17; d=0.15; alpha=1.32*(delta_t/d)^0.25; disp("heat transfer coefficient="); disp("W/m^2 K",alpha);
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test2-10.tst
main var i, r; function pow(b, e); var t; { if e == 0 then return 1 fi; if e == 1 then return b fi; let t <- call pow(b, e / 2); let t <- t * t; if 2 * (e / 2) != e then let t <- t * b fi; return t }; function sumpow(b, n); var i, s; { let s <- 0; let i <- 0; while i <= n do let s <- s + call pow(b, i); let i <- i + 1 od; return s }; { call outputnum(call sumpow(2, 10)); call outputnum(call sumpow(3, 7)); call outputnum(call sumpow(5, 3)) }.
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Ex16_4.sce
// chapter 16 // example 16.4 // Determine dc supply voltage and charging current // page-997 clear; clc; // given num_cell=18; // number of cells AH_output=90; // in AH (AH output per cell) T=10; // in Hrs charging_time=8; // in Hrs AH_efficiency=85; // in % V_cell=2.4; // in V (voltage per cell) r=0.1; // in ohm (internal resistance of battery) // calculate // since AH_efficiency=AH_output/AH_input, therefore we get AH_input=AH_output/(AH_efficiency/100); // calculation of input AH per cell // since AH_input=charging_current*charging_time, therefore we get charging_current=AH_input/charging_time; // calculation of charging current V_total=num_cell*V_cell; // calculation of total terminal voltage of 18 cells V_drop=r*charging_current; // calculation of voltage drop across internal resistance Edc=V_total+V_drop; // calculation of dc supply voltage printf("\nThe charging current is \t %.2f A",charging_current); printf("\nThe dc supply voltage is \t %.3f V",Edc); // Note: the answers vary slightly due to precise calculation
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Ex18_18.sce
//Initilization of variables m=50 //kg vo=4 //m/s vf=8 //m/s t=6 //s g=9.8 //m/s^2 r=0.8 //m u=0.25 //coefficient of friction I=30 //kg-m^2 //Calculations Na=m*g //N F=u*Na //N //Angular Speeds wo=vo/r //rad/s wf=vf/r //rad/s //Applying impulse momentum theorem mb=(I*wf+m*vf*r-I*wo-m*vo*r+F*r*t)/(vo*r+g*r*t-vf*r) //kg //Result clc printf('The mass of block B is %f kg',mb)
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ex1_64.sce
//Exa:1.64 clc; clear; close; T_L=600;//in N-m T_m=450;//in N-m N=600;//in rpm w_o=2*%pi*N/60;//in rad/sec s=0.08;//slip w=s*w_o;//in rad/sec K=w/T_m;//Torque constant J=(-10/K)/log(0.25);//in Kg-m^2 J_m=10;//in Kg-m^2 J_F=J-J_m; disp(J_F,'Moment Of Inertia Of Flywheel (in Kg-m^2)=');
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Chapter9_example1.sce
clc clear //Input data t=0.2//Thickness of film in micro m r=1.25//Refractive index of liquid w=[4000,5000]//Range of wavelength in Angstrom q=35//Angle observed in degrees //Calculations u=asind(sind(q)/r)//Angle of reflection in degrees w1=(2*t*10^-6*r*cosd(u))/10^-10//Wavelength in Angstrom w2=w1/2//Wavelength in Angstrom //Output printf('Wavelength absent in reflected light is %i Angstrom',w2)
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Ex8_10.sce
//Ex8_10 clc fo=150 disp("fo= "+string(fo)+" Hz")//Central frequency of band pass filter BW=15 disp("BW= "+string(BW)+" Hz")// Upper cut-off frequency or 3-dB bandwidth Q=fo/BW // Quality factor disp("Q= "+string(Q)) C=0.05*10^(-6) // Choosing value of capacitor same as in book disp("C="+string(C)+"farad") R=sqrt(2)/(2*%pi*fo*C) disp("R=sqrt(2)/(2*%pi*fo*C)="+string(R)+ " ohm") // resistance value for filter design Am=5-(sqrt(2)/Q) // formulae disp("Am=5-(sqrt(2)/Q)="+string(Am)) // Midband gain Abp=Am/(5-Am) disp("Abp=Am/(5-Am)="+string(Abp)) // Central frequency gain
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exmp2_28.sce
//Example 2.28 clc leq=500+5000+600 format(5) disp(leq,"L_eq(in uH) = L1 + L2 + 2M =") f=(1/(2*%pi*sqrt(150*6100*10^-18)))*10^-3 format(9) disp(f,"f(in kHz) = 1 / 2*pi*sqrt(C*L_eq) =")
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GeoProver.tst
# GeoProver test file for Maple, created on Jan 18 2003 read("GeoProver.mpl"): read("supp.mpl"): with(geoprover): interface(prettyprint=0): # Example Arnon # # The problem: # Let $ABCD$ be a square and $P$ a point on the line parallel to $BD$ # through $C$ such that $l(BD)=l(BP)$, where $l(BD)$ denotes the # distance between $B$ and $D$. Let $Q$ be the intersection point of # $BF$ and $CD$. Show that $l(DP)=l(DQ)$. # # The solution: vars_:=List(x1, x2, x3); # Points A_:=Point(0,0); B_:=Point(1,0); P_:=Point(x1,x2); # coordinates D_:=rotate(A_,B_,1/2); C_:=par_point(D_,A_,B_); Q_:=varpoint(D_,C_,x3); # polynomials polys_:=List(on_line(P_,par_line(C_,pp_line(B_,D_))), eq_dist(B_,D_,B_,P_), on_line(Q_,pp_line(B_,P_))); # conclusion con_:=eq_dist(D_,P_,D_,Q_); # solution gb_:=geo_gbasis(polys_,vars_); result_:=geo_normalf(con_,gb_,vars_); # Example CircumCenter_1 # # The problem: # The intersection point of the midpoint perpendiculars is the # center of the circumscribed circle. # # The solution: parameters_:=List(a1, a2, b1, b2, c1, c2); # Points A_:=Point(a1,a2); B_:=Point(b1,b2); C_:=Point(c1,c2); # coordinates M_:=intersection_point(p_bisector(A_,B_), p_bisector(B_,C_)); # conclusion result_:=List( eq_dist(M_,A_,M_,B_), eq_dist(M_,A_,M_,C_) ); # Example EulerLine_1 # # The problem: # Euler's line: The center $M$ of the circumscribed circle, # the orthocenter $H$ and the barycenter $S$ are collinear and $S$ # divides $MH$ with ratio 1:2. # # The solution: parameters_:=List(a1, a2, b1, b2, c1, c2); # Points A_:=Point(a1,a2); B_:=Point(b1,b2); C_:=Point(c1,c2); # coordinates S_:=intersection_point(median(A_,B_,C_),median(B_,C_,A_)); M_:=intersection_point(p_bisector(A_,B_), p_bisector(B_,C_)); H_:=intersection_point(altitude(A_,B_,C_),altitude(B_,C_,A_)); # conclusion result_:=List(is_collinear(M_,H_,S_), sqrdist(S_,fixedpoint(M_,H_,1/3))); # Example Brocard_3 # # The problem: # Theorem about the Brocard points: # Let $\Delta\,ABC$ be a triangle. The circles $c_1$ through $A,B$ and # tangent to $g(AC)$, $c_2$ through $B,C$ and tangent to $g(AB)$, and # $c_3$ through $A,C$ and tangent to $g(BC)$ pass through a common # point. # # The solution: parameters_:=List(u1, u2); # Points A_:=Point(0,0); B_:=Point(1,0); C_:=Point(u1,u2); # coordinates M1_:=intersection_point(altitude(A_,A_,C_),p_bisector(A_,B_)); M2_:=intersection_point(altitude(B_,B_,A_),p_bisector(B_,C_)); M3_:=intersection_point(altitude(C_,C_,B_),p_bisector(A_,C_)); c1_:=pc_circle(M1_,A_); c2_:=pc_circle(M2_,B_); c3_:=pc_circle(M3_,C_); P_:=other_cc_point(B_,c1_,c2_); # conclusion result_:= on_circle(P_,c3_); # Example Feuerbach_1 # # The problem: # Feuerbach's circle or nine-point circle: The midpoint $N$ of $MH$ is # the center of a circle that passes through nine special points, the # three pedal points of the altitudes, the midpoints of the sides of the # triangle and the midpoints of the upper parts of the three altitudes. # # The solution: parameters_:=List(u1, u2, u3); # Points A_:=Point(0,0); B_:=Point(u1,0); C_:=Point(u2,u3); # coordinates H_:=intersection_point(altitude(A_,B_,C_),altitude(B_,C_,A_)); D_:=intersection_point(pp_line(A_,B_),pp_line(H_,C_)); M_:=intersection_point(p_bisector(A_,B_), p_bisector(B_,C_)); N_:=midpoint(M_,H_); # conclusion result_:=List( eq_dist(N_,midpoint(A_,B_),N_,midpoint(B_,C_)), eq_dist(N_,midpoint(A_,B_),N_,midpoint(H_,C_)), eq_dist(N_,midpoint(A_,B_),N_,D_) ); # Example FeuerbachTangency_1 # # The problem: # For an arbitrary triangle $\Delta\,ABC$ Feuerbach's circle (nine-point # circle) is tangent to its 4 tangent circles. # # The solution: vars_:=List(x1, x2); parameters_:=List(u1, u2); # Points A_:=Point(0,0); B_:=Point(2,0); C_:=Point(u1,u2); P_:=Point(x1,x2); # coordinates M_:=intersection_point(p_bisector(A_,B_), p_bisector(B_,C_)); H_:=intersection_point(altitude(A_,B_,C_),altitude(B_,C_,A_)); N_:=midpoint(M_,H_); c1_:=pc_circle(N_,midpoint(A_,B_)); Q_:=pedalpoint(P_,pp_line(A_,B_)); # polynomials polys_:=List(on_bisector(P_,A_,B_,C_), on_bisector(P_,B_,C_,A_)); # conclusion con_:=is_cc_tangent(pc_circle(P_,Q_),c1_); # solution gb_:=geo_gbasis(polys_,vars_); result_:=geo_normalf(con_,gb_,vars_); # Example GeneralizedFermatPoint_1 # # The problem: # A generalized theorem about Napoleon triangles: # Let $\Delta\,ABC$ be an arbitrary triangle and $P,Q$ and $R$ the third # vertex of isosceles triangles with equal base angles erected # externally on the sides $BC, AC$ and $AB$ of the triangle. Then the # lines $g(AP), g(BQ)$ and $g(CR)$ pass through a common point. # # The solution: vars_:=List(x1, x2, x3, x4, x5); parameters_:=List(u1, u2, u3); # Points A_:=Point(0,0); B_:=Point(2,0); C_:=Point(u1,u2); P_:=Point(x1,x2); Q_:=Point(x3,x4); R_:=Point(x5,u3); # polynomials polys_:=List(eq_dist(P_,B_,P_,C_), eq_dist(Q_,A_,Q_,C_), eq_dist(R_,A_,R_,B_), eq_angle(R_,A_,B_,P_,B_,C_), eq_angle(Q_,C_,A_,P_,B_,C_)); # conclusion con_:=is_concurrent(pp_line(A_,P_), pp_line(B_,Q_), pp_line(C_,R_)); # solution sol_:=geo_solve(polys_,vars_); result_:=geo_eval(con_,sol_); # Example TaylorCircle_1 # # The problem: # Let $\Delta\,ABC$ be an arbitrary triangle. Consider the three # altitude pedal points and the pedal points of the perpendiculars from # these points onto the the opposite sides of the triangle. Show that # these 6 points are on a common circle, the {\em Taylor circle}. # # The solution: parameters_:=List(u1, u2, u3); # Points A_:=Point(u1,0); B_:=Point(u2,0); C_:=Point(0,u3); # coordinates P_:=pedalpoint(A_,pp_line(B_,C_)); Q_:=pedalpoint(B_,pp_line(A_,C_)); R_:=pedalpoint(C_,pp_line(A_,B_)); P1_:=pedalpoint(P_,pp_line(A_,B_)); P2_:=pedalpoint(P_,pp_line(A_,C_)); Q1_:=pedalpoint(Q_,pp_line(A_,B_)); Q2_:=pedalpoint(Q_,pp_line(B_,C_)); R1_:=pedalpoint(R_,pp_line(A_,C_)); R2_:=pedalpoint(R_,pp_line(B_,C_)); # conclusion result_:=List( is_concyclic(P1_,P2_,Q1_,Q2_), is_concyclic(P1_,P2_,Q1_,R1_), is_concyclic(P1_,P2_,Q1_,R2_)); # Example Miquel_1 # # The problem: # Miquels theorem: Let $\Delta\,ABC$ be a triangle. Fix arbitrary points # $P,Q,R$ on the sides $AB, BC, AC$. Then the three circles through each # vertex and the chosen points on adjacent sides pass through a common # point. # # The solution: parameters_:=List(c1, c2, u1, u2, u3); # Points A_:=Point(0,0); B_:=Point(1,0); C_:=Point(c1,c2); # coordinates P_:=varpoint(A_,B_,u1); Q_:=varpoint(B_,C_,u2); R_:=varpoint(A_,C_,u3); X_:=other_cc_point(P_,p3_circle(A_,P_,R_),p3_circle(B_,P_,Q_)); # conclusion result_:=on_circle(X_,p3_circle(C_,Q_,R_)); # Example PappusPoint_1 # # The problem: # Let $A,B,C$ and $P,Q,R$ be two triples of collinear points. Then by # the Theorem of Pappus the intersection points $g(AQ)\wedge g(BP), # g(AR)\wedge g(CP)$ and $g(BR)\wedge g(CQ)$ are collinear. # # Permuting $P,Q,R$ we get six such {\em Pappus lines}. Those # corresponding to even resp. odd permutations are concurrent. # # The solution: parameters_:=List(u1, u2, u3, u4, u5, u6, u7, u8); # Points A_:=Point(u1,0); B_:=Point(u2,0); P_:=Point(u4,u5); Q_:=Point(u6,u7); # coordinates C_:=varpoint(A_,B_,u3); R_:=varpoint(P_,Q_,u8); # conclusion result_:=is_concurrent(pappus_line(A_,B_,C_,P_,Q_,R_), pappus_line(A_,B_,C_,Q_,R_,P_), pappus_line(A_,B_,C_,R_,P_,Q_)); # Example IMO/36_1 # # The problem: # Let $A,B,C,D$ be four distinct points on a line, in that order. The # circles with diameters $AC$ and $BD$ intersect at the points $X$ and # $Y$. The line $XY$ meets $BC$ at the point $Z$. Let $P$ be a point on # the line $XY$ different from $Z$. The line $CP$ intersects the circle # with diameter $AC$ at the points $C$ and $M$, and the line $BP$ # intersects the circle with diameter $BD$ at the points $B$ and # $N$. Prove that the lines $AM, DN$ and $XY$ are concurrent. # # The solution: vars_:=List(x1, x2, x3, x4, x5, x6); parameters_:=List(u1, u2, u3); # Points X_:=Point(0,1); Y_:=Point(0,-1); M_:=Point(x1,x2); N_:=Point(x3,x4); # coordinates P_:=varpoint(X_,Y_,u3); Z_:=midpoint(X_,Y_); l_:=p_bisector(X_,Y_); B_:=line_slider(l_,u1); C_:=line_slider(l_,u2); A_:=line_slider(l_,x5); D_:=line_slider(l_,x6); # polynomials polys_:=List(is_concyclic(X_,Y_,B_,N_), is_concyclic(X_,Y_,C_,M_), is_concyclic(X_,Y_,B_,D_), is_concyclic(X_,Y_,C_,A_), is_collinear(B_,P_,N_), is_collinear(C_,P_,M_)); # constraints nondeg_:=List(x5-u2,x1-u2,x6-u1,x3-u1); # conclusion con_:=is_concurrent(pp_line(A_,M_),pp_line(D_,N_),pp_line(X_,Y_)); # solution sol_:=geo_solveconstrained(polys_,vars_,nondeg_); result_:=geo_eval(con_,sol_); # Example IMO/43_2 # # The problem: # # No verbal problem description available # # The solution: vars_:=List(x1, x2); parameters_:=List(u1); # Points B_:=Point(-1,0); C_:=Point(1,0); # coordinates O_:=midpoint(B_,C_); gamma_:=pc_circle(O_,B_); D_:=circle_slider(O_,B_,u1); E_:=circle_slider(O_,B_,x1); F_:=circle_slider(O_,B_,x2); A_:=sym_point(B_,pp_line(O_,D_)); J_:=intersection_point(pp_line(A_,C_), par_line(O_, pp_line(A_,D_))); m_:=p_bisector(O_,A_); P1_:=pedalpoint(J_,m_); P2_:=pedalpoint(J_,pp_line(C_,E_)); P3_:=pedalpoint(J_,pp_line(C_,F_)); # polynomials polys_:=List(on_line(E_,m_), on_line(F_,m_)); # constraints nondegs_:=List(x1-x2); # conclusion con_:=List(eq_dist(J_,P1_,J_,P2_), eq_dist(J_,P1_,J_,P3_)); # solution sol_:=geo_solveconstrained(polys_,vars_,nondegs_); result_:=geo_simplify(geo_eval(con_,sol_)); quit;
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Ex21_3_1.sce
clc //initialization of variables d =1000 // kg/m^3 h = 30 // W/m^2-C-sec Hvap = 2300*10^3 // J/kg T = 75 // C Ti = 31 // C l = 0.04 // m epsilon = 0.36 c = 3600 // sec/hr t1 = (Hvap/h)*(1/(T-Ti))*(l*epsilon*d)// sec t = t1/c // in hr //Results printf("The time taken for drying is %.f hr",t)// answer wrong in textbook
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clc;clear;close // FOR ANY SYSTEM AX=B & FOR ANY NO. OF EXPERIMENTS A=input("enter the matrix") disp(A,'A='); Y=input("enter the column matrix") disp(Y,'Y='); X=((A'*A)^-1)*(A'*Y); //FROM NORMAL EQ. disp(X,'X='); M=X(1,1); C=X(2,1); disp(M,'M='); disp(C,'C='); disp('The line of best fit is Y=MT+C');
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//find sending end voltage and current and power and efficiency clear; clc; //soltion //FUNCTIONS function [z]=rxr(A,B)//Function for the multiplication of rectangular z(1)=A(1)*B(1) z(2)=A(2)+B(2) endfunction function [a]=r2p(z)//Function for rectangular to polar a=z(1)*complex(cosd(z(2)),sind(z(2))) endfunction //given P=50*10^6;//VA Vrl=110*1000;//V pf=0.8//power factir Vr=[Vrl/sqrt(3) 0]; Ir=[P/(sqrt(3)*Vrl) -acosd(pf)]; A=[0.98 3]; B=[110 75]; C=[0.0005 80]; D=[0.98 3]; Z1=rxr(A,Vr); Z2=rxr(B,Ir); AV=r2p(Z1); BI=r2p(Z2); Vs=AV+BI; theta1=atand((imag(Vs)/real(Vs))); printf("Sending end voltage= %.0f V\n",abs(Vs)); Y1=rxr(C,Vr); Y2=rxr(D,Ir); CV=r2p(Y1); DI=r2p(Y2); Is=CV+DI; theta2=atand(imag(Is)/real(Is)); printf("Magnitude of sending end current= %d A\n",abs(Is)); phis=theta2-theta1; Ps=3*abs(Vs)*abs(Is)*cosd(phis); printf("Sending end power=%.1fMW\n",floor(Ps/10^5)/10); Pr=P*pf; n=Pr*100/(floor(Ps/10^5)*10^5); printf("Transmission Efficiency= %.1f percent",n); //The value of voltage is 87427 V
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# # Makefile.tst # Created: Mon Jan 8 07:33:59 2001 by tek@wiw.org # Revised: Tue Jun 26 20:53:10 2001 by tek@wiw.org # Copyright 2001 Julian E. C. Squires (tek@wiw.org) # This program comes with ABSOLUTELY NO WARRANTY. # $Id$ # # TESTTOOLS=./tests/test-set GENERATEDTESTS=./tests/memcptst ./tests/imagetst ./tests/colortst TESTS=./tests/test-set.sh PROFILES= check: $(TESTTOOLS) $(TESTS) $(GENERATEDTESTS) profile: $(PROFILES) $(TESTS) $(PROFILES): libdentata.a ./$@ $(GENERATEDTESTS): %: %.o libdentata.a $(CC) $(CFLAGS) -o $@ $< $(LDFLAGS) -ldentata ./$@ $(TESTTOOLS): %: %.o libdentata.a $(CC) $(CFLAGS) -o $@ $< $(LDFLAGS) -ldentata testsclean: $(RM) ./tests/*~ ./tests/*.o testsdistclean: testsclean $(RM) $(GENERATEDTESTS) $(TESTTOOLS) # EOF Makefile.tst
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Ex10_12.sce
// Variable declaration alpha = 0.05 n = 400 chi_sq_thr = 16.919 // Calculation q = [22.4,42.8,65.2,74.8,69.2,52.8,34.8,20.0,10.0,8.0] // list of expected frequency p = [18,47,76,68,74,46,39,15,9,8] // list of entries chi_sq_prt = 0 for i = 1:10 chi_sq_prt = chi_sq_prt + (p(i)-q(i))^2/q(i) end // Result printf ( "Practical chi square value: %.3f",chi_sq_prt) if(chi_sq_thr > chi_sq_prt) then printf ( "null hypothesis can not be rejected") printf ( "Poisson distribution provides a good fit at level alphha=0.05") else printf ( "null hypothesis must be rejected") printf ( "Poisson distribution does not provide a good fit at level alphha=0.05") end
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Example2_1b.sce
exec('Example2_1a.sce', -1) clc //Sample Problem 2-1b printf("\n**Sample Problem 2-1b**\n") time = distance_covered / velocity //in hr delta_t = time + next_time /60 //in hr printf("Time interval from the begining of the drive to the arrival at the station is %f hr", delta_t)
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/812/CH3/EX3.04/3_04.sce
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FOSSEE/Scilab-TBC-Uploads
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//temperature and pressure// pathname=get_absolute_file_path('3.04.sce') filename=pathname+filesep()+'3.04-data.sci' exec(filename) //Assuming temperature varies linearly with altitude: //Temperature gradient(in F/ft): m=(T1-T2)/(z2-z1) //Value of g/(m*R): v=g/m/R/32.2 //Pressure at Vail Pass(in inches of Hg): p12=p1*((T2+460)/(T1+460))^v //Percentage change in density: pc1=(p12/p1*(T1+460)/(T2+460)-1)*100 //Assuming density is constant: //Pressure at Vail Pass(in inches of Hg): p22=p1*(1-(g*(z2-z1)/(R*32.2)/(T1+460))) //Percentage change in density: pc2=0; //Assuming temperature is constant: //Pressure at Vail Pass(in inches of Hg): p32=p1*%e^(-g*(z2-z1)/(R*32.2)/(T2+460)) //Percentage change in density: pc3=(p32/p1*(T1+460)/(T1+460)-1)*100 //For an adiabatic atmosphere: p42=p1*((62+460)/(80+460))^(k/(k-1)) //Percentage change in density: pc4=(p42/p1*(T1+460)/(T2+460)-1)*100 printf("\n\nRESULTS\n\n") printf("\n\n1) If temperature varies linearly with altitude\n\n") printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p12) printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc1) printf("\n\n2) If density is constant\n\n") printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p22) printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc2) printf("\n\n3) If temperature is constant\n\n") printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p32) printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc3) printf("\n\n4) For an adiabatic atmosphere\n\n") printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p42) printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc4)
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/models/complexity_1000/Applied_Thermodynamics_and_Engineering/CH7/EX7.2/7_2.sce
43751b0616b2e18f8ae6d44f1a24b97d3bfc6f0d
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apelttom/20-semester_PhD_thesis
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refs/heads/master
2018-12-26T22:03:38.510422
2018-12-14T20:04:11
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7_2.sce
clc; //part I %H2=0.494; %CO=0.18; %CH4=0.2; %C4H4=0.02; %O2=0.004; %N2=0.062; %CO2=0.04; O_H2=%H2/2; O_CO=%CO/2; O_CH4=%CH4*2; O_C4H4=%C4H4*6; O_O2=-%O2*1; C_CO=%CO; C_CH4=%CH4; C_C4H8=4*%C4H4; C_CO2=%CO2; H_H2=%H2; H_CH4=2*%CH4; H_C4H8=4*%C4H4; O_Tot=O_C4H4+O_CH4+O_CO+O_H2+O_O2; C_Tot=C_CO+C_CH4+C_C4H8+C_CO2; H_Tot=H_H2+H_CH4+H_C4H8; AF=O_Tot/0.21; disp(AF,"stoichiometric A/F ratio is:") //partII actual_AF=AF+0.2*AF; Ass_N2=0.79*actual_AF; Exs_O2=(0.21*actual_AF)-O_Tot; N2_Tot=Ass_N2+%N2; Tot_wet=H_Tot+C_Tot+Exs_O2+N2_Tot; Tot_dry=C_Tot+Exs_O2+N2_Tot; C_dry=(C_Tot)/Tot_dry*100; O_dry=(Exs_O2)/Tot_dry*100; N_dry=(N2_Tot)/Tot_dry*100; C_wet=(C_Tot)/Tot_wet*100; O_wet=(Exs_O2)/Tot_wet*100; N_wet=(N2_Tot)/Tot_wet*100; H_wet=(H_Tot)/Tot_wet*100; disp("Analysis by volume of the wet product of CO2,H2O,O2,N2 respectively is:"); disp(N_wet,O_wet,H_wet,C_wet) disp("Analysis by volume of the dry product of CO2,O2,N2 respectively is:"); disp(N_dry,O_dry,C_dry)
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/2609/CH4/EX4.9/ex_4_9.sce
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FOSSEE/Scilab-TBC-Uploads
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ex_4_9.sce
////Ex 4.9 clc; clear; close; format('v',5); I2=1;//mA Rf=4.7;//kohm //Case 1st I1=500;//micro A Vout1=-I1*10^-6*Rf*10^3;//V disp(Vout1,"For 500 micro A current, Output Voltage(V)"); //Case 2nd I2=1;//mA Vout2=-I2*10^-3*Rf*10^3;//V disp(Vout2,"For 1 mA current, Output Voltage(V)"); deltaVout=Vout2-Vout1;//V disp(deltaVout,"Variation in Output Voltage(V)");
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/data/out/LoadAndVerify.sce
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MaxRCC/TDB32
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refs/heads/master
2022-01-06T08:46:25.206207
2018-09-03T18:41:17
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clf; clear all; //str = 'Pos_0.txt'; str = 'Pos_3.txt'; //str = 'tbOutData.txt'; tbdata = csvRead(str,ascii(9), [], 'string'); fs = 250000; [n m]=size(tbdata); data= bin2dec(tbdata); mat = [] N = length(data)/61; for k=0:N-1 beam = data(k*61+1: (k+1)*61) - 2^17; mat = [mat abs(beam)] end D = 512 mat = mat(:,48:1024); [x,y] = size(mat) t = 0:1/fs:(y-1)/fs; theta = -30:1:30; t = t*1000; mat = mat./max(mat); mat = D*mat; mat = int(mat) scf(0) plot3d(theta,t,mat) h=get("hdl") //get handle on current entity (here the surface) a=gca(); //get current axes a.rotation_angles=[35,-30]; a.box="off" //a.grid=[1 1 1]; //make grids a.axes_visible="on"; //axes are hidden a.axes_bounds=[.2 0 1 1]; f=get("current_figure"); //get the handle of the parent figure //f.color_map=bonecolormap(512) //f.color_map=coppercolormap(512); //f.color_map=hotcolormap(128); f.color_map=jetcolormap(D); //change the figure colormap h.color_flag=1; //color according to z h.color_mode=-1; //remove the facets boundary h.color_flag=1; //color according to given colors //h.data.color=[1+modulo(1:400,64),1+modulo(1:400,64)]; //shaded h.color_flag=1; outstr = str + '.svg' xs2svg(0, outstr) //csvWrite(mat', "angle0.txt");
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/opgaves/vpw-pizzabonnen+/inputs.sce
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pizzas0 = [] bonnen0 = [] pizzas1 = [4813,1719,3762,9829,6090,4,2511,7053,2252,1708,487,8406,9927,6621,7305,2112,8230,6189,2691,8394,964,6144,7224,5138,9654,4833,3985,4846,1301,7094,5873,4544,3873,5177,1674,9210,9359,6573,6267,9117,3432,7815,8318,2343,853,1392,8598,8925,6933,4256,250,4136,7105,3898,4725,3122,788,4864,5203,3932,4495,8877,8865,4409,6169,9491,1240,9652,6698,4558,2314,4093,834,3370,8911,7580,1177,3794,7786,6511,5348,4691,551,5543,9365,3487,7395,5449,1905,6811,5229,6843,1120,480,897,3253,1216,2209,1525,7174,6600,6140,2474,3504,9516,8684,1023,929,2969,2129,1715,8037,2787,9575,7170,3946,6829,8458,2941,1057,7689,6026,1086,2918,1066,4963,8237,228,8421,3760,5140,7161,7481,1442,999,9959,5866,6627,3922,1004,3476,1067,1999,5185,3050,8722,8693,3597,7321,2897,8617,5618,3753,1610,2250,2890,8144,3832,9776,8084,7083,1460,8978,4988,434,7780,986,5510,276,2091,4415,7344,1314,3466,4420,8574,5852,4140,7294,9988,7790,7238,1649,2855,6462,1412,7501,243,7679,8921,899,5954,3236,7580,4586,3511,6449,8872,2176,6017,2687,9745,8769,6851,2977,7108,6621,6751,9361,8060,9814,2505,1427,4941,2266,816,1752,4130,4682,5422,9784,9491,2833,7857,7223,6211,388,8874,7043,2301,7232,7872,4879,8020,9190,3227,2829,2311,611,926,2674,1532,2254,1668,5313,3672,4304,2384,3317,6308,7547,9222,8141,4218,8881,5006,6268,2284,6644] pizzas1=[pizzas1,1207,3131,7927,1412,861,6761,242,496,7280,1109,1990,4593,4553,7891,1811,4889,4571,1351,4839,3202,645,6734,5098,9942,136,2850,5350,4631,4637,7578,5599,7356,8535,9870,1745,6195,928,1532,5525,3546,3829,7696,1793,8737,3175,1022,6309,4221,4607,6997,8590,5623,6053,3880,1463,3429,1722,7165,3263,5610,3,6493,5018,5086,8133,4936,3051,880,7680,2770,3726,5859,9629,5907,8290,3429,2149,883,7394,3077,470,1761,991,3256,2205,4250,8625,3026,3802,6903,4168,2205,2215,2360,9245,5285,2020,9319,733,2907,8400,2418,5030,3545,3776,8737,6682,2680,5375,9059,6056,7876,4933,4571,7194,1093,1393,7309,399,4238,6512,5022,4001,5868,9987,1574,5827,6986,8434,8343,6796,5945,2802,996,8218,5985,3003,8808,3697,2325,695,9164,6290,5827,4385,8838,6801,6967,6070,4189,5958,6519,6264,9338,4879,168,6230,4553,5363,3270,1438,2663,5099,9388,1660,1198,483,5000,9669,7555,3817,9776,9116,6921,8054,3920,8541,6961,2009,7618,9318,4853,6645,6090,1735,5075,9295,420,1739,1546,282,988,3485,6030,9221,3580,7184,2807,2190,8532,8753,5811,1366,4782,8298,4875,9647,5583,9730,9954,6518,5421,6116,9641,6366,2410,5113,8334,3262,3348,1527,1261,1031,9350,8397,4405,7001,8575,8365,9032,5045,8196,492,4243,5291,8111,3790,4626,3557,6871,1295,2313,2968,1795,7321,7967,5045,8946,5749,6862,2616,7992,899,3080,6445,5130,1595,2060,6047,7662,1374,145,116,7162,3306,7204,213,156,2372,3621,5040,2281,358,9047,1987,5239,7635,1367,2238,902,2535,2534,95,2691,4915,5892,9591,2970,2697,2235,7327,7270,5636,3930,3816,1265,9891,3449,6955,2773,6598,9904,1068,8276,8039,6748,531,1078,787,7988,9059,9209,9178,3117,5628,8787,7774,1982,2953,1142,2248,3402,5025,3942,6799,7852,8375,7996,5596,6399,6211,2889,6532,1117,1621,7105,4815,7787,5079,3259,551,478,7107,6411,9005,4385,8169,7328,3682,4250,1803,7412,7057,4211,7327,2436,5979,9630,7028,5940,2923,5156,3099] pizzas1=[pizzas1,2940,2021,1457,1902,2942,7864,6868,8000,8019,9094,9450,1362,581,5050,266,7795,1421,2736,9906,628,7850,6386,6957,606,5136,7599,1786,7180,2431,1897,8802,4926,9845,9590,3633,4004,6907,9981,9459,9634,5460,6281,8184,2045,7651,9943,1838,9487,2657,6204,8143,2368,2193,4891,79,2138,2101,9225,6633,9913,663,9840,2619,5134,4702,5749,2844,9056,6204,7990,6423,8743,572,2635,4697,8119,4184,4770,6885,5999,2701,743,8578,7104,6564,7132,9610,8398,4274,982,7410,6122,4710,6626,633,3291,5393,9920,7380,5571,7816,8368,6792,8928,6628,4292,8484,8478,7470,9488,8629,8530,7595,378,5971,2838,6933,6602,3987,9575,5832,3172,8201,7008,6074,83,4699,394,836,413,8061,7940,7060,5432,4769,4176,2983,857,3735,3331,8621,341,56,5005,7277,3109,2110,2453,764,1397,6655,2969,5078,4091,7665,8301,6049,4635,2437,5211,8947,41,9276,1046,7757,7848,5863,8736,3052,6242,4251,1660,369,6795,1006,3471,7951,1373,7273,4919,8612,2793,7263,5304,8113,7105,910,2406,8104,8377,4231,2534,916,276,6518,5736,9563,8865,5372,8429,4344,2455,7685,1118,5145,9867,45,186,5969,7070,4741,4677,5939,5081,7277,7430,1577,1319,5423,3579,6079,3796,7797,225,1913,4723,5741,4215,5763,7961,3162,3249,5333,6543,1404,7079,2404,6724,3336,7839,8858,6469,7824,7976,2997,8032,3932,8810,7947,1416,5295,9625,183,7684,2686,2948,1575,6726,4056,9097,7199,9774,4472,3229,8409,128,7668,3262,7686,9177,7094,8484,4445,2977,5717,4265,4591,3474,49,1650,2000,8047,937,777,2432,1493,9792,5076,4447,6339,2925,7588,4009,8581,7156,7075,772,4581,8022,2961,5954,3124,4481,9100,5179,96,4033,9292,8712,6880,1739,8940,1682,2886,3291,4880,5722,9897,7035,143,6989,8699,8091,9462,6772,9704,9589,2907,7672,4843,3949,3689,2708,9048,5947,972,6558,4752,7968,2935,7888,4269,9003,6038,8235,5166,4947,2199,5958,9879,8203,9930,1371,7874,8503,2488,9051,1390,440,2911,8304,1145,6539,6474,4581,3895,1202,6414,1275,7825,453,648,3351,6577,3115,8245,2745,1709] bonnen1 = [ 3,2; 7,1; 1,3; 3,3; 7,1; 9,1; 0,4; 5,0 ] pizzas2 = [2082,680,8965,175,9025,7761,7662,1767,8559,8067,9968,5103,4137,9380,4366,4035,3284,4696,491,8978,631,1513,3581,8094,1323,4853,8561,519,2898,5172,3498,4677,6576,4642,9335,7885,987,9008,9513,1790,6288,6543,3898,8774,1983,5442,3993,9568,6637,4732,4281,8170,489,751,1845,2848,9845,2505,2345,7366,7743,4214,9112,2716,9552,1364,6734,4293,2385,9203,979,9510,5341,435,9461,7948,6821,8104,4360,5244,7654,6392,8490,8542,2473,2862,8526,2377,7004,9130,1764,6332,9844,2352,1438,6329,7366,4912,7213,805,1869,2123,7236,8821,2222,7505,441,3009,4445,5766,9741,9802,7868,9460,2112,9813,2758,2242,737,5113,2874,9523,1277,7324,8382,5662,3088,8607,374,1100,6638,1570,7379,1258,5713,466,8375,3824,3249,8382,8533,6993,3090,1557,1337,7018,4158,3605,8462,3132,302,9438,9638,6915,6825,2009,6960,3736,7058,9862,1975,7876,8882,1925,4470,8780,5219,8167,9437,2189,5345,9372,7230,7356,1198,3726,8147,4729,1396,5014,6958,9336,4634,2290,4351,8298,7773,3311,6574,809,8377,8352,9153,354,4418,9186,198,6718,8776,3673] bonnen2 = [2,9;5,3;2,9;5,3;5,3;2,9;2,9;2,9;5,3;2,9;2,9;5,3;5,3;5,3;2,9;5,3;2,9;5,3] pizzas3 = [145,749,706,209,747,909,378,274,316,895,580,428,754,650,900,866,481,829,761,250,732,813,554,128,172,372,862,778,697,10,119,806,192,76,881,116,902,154,620,518,663,728,804,463,785,862,55,160,350,634,536,699,925,200,913,990,758,848,926,123,805,750,390,611,325,304,459,710,644,502,303,639,771,957,743,763,289,995,516,218,414,873,281,831,847,928,34,164,966,234,953,973,928,106,233,678,537,160,246,566] bonnen3 = [3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;10,5] pizzas4 = [145,749,706,209,747,909,378,274,316,895,580,428,754,650,900,866,481,829,761,250,732,813,554,128,172,372,862,778,697,10,119,806,192,76,881,116,902,154,620,518,663,728,804,463,785,862,55,160,350,634,536,699,925,200,913,990,758,848,926,123,805,750,390,611,325,304,459,710,644,502,303,639,771,957,743,763,289,995,516,218,414,873,281,831,847,928,34,164,966,234,953,973,928,106,233,678,537,160,246,566] bonnen4 = [3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;3,1;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;5,2;10,5;10,5;10,5;10,5;10,5;10,5;10,5;10,5;10,5;10,5]
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//Exa 5.13.9 clc; clear; close; //Given data bita = 100; V_CE = 0.2;//in V V_BE = 0.8;// in V R_C= 500;// in Ω R_B= 44*10^3;// in Ω R_E= 1*10^3;// in Ω V_CC= 15;// in V V_GE= -15;// in V // Applying KVL to collector circuit // V_CC-V_GE - I_Csat*R_C-V_CE-I_E*R_E=0, but I_Csat= bita*I_Bmin and I_E= 1+bita I_Bmin= (V_CC-V_GE-V_CE)/(R_C*bita+(1+bita)*R_E);// in A // Applying KVL to the base emitter circuit // V_BB-I_Bmin*R_B-V_BE-I_E*R_E + V_CC=0 V_BB= I_Bmin*R_B + V_BE + (1+bita)*I_Bmin*R_E-V_CC;// in V disp(I_Bmin*10^3,"The value of I_B(min) in mA is : ") disp(V_BB,"The value of V_BB in volts is : ")
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// Exa 4.1 clc; clear; close; // Given data p = 1.0;// in MPa p = p * 10^6;// in N per m^2 del_v = 1.5;// in m^3 per min del_v = del_v * 60;// in m^3 per h W = p * del_v;// in J W = W * 10^-6;// in MJ disp(W,"Work done by the pump upon the water in MJ");
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Chapter5_Example7.sce
//Chapter-5, Illustration 7, Page 255 //Title: Air Compressors //============================================================================= clc clear //INPUT DATA D=0.2;//Bore in m L=0.3;//Stroke in m r=0.05;//Ratio of clearance volume to stroke volume P1=97;//Pressure at entry in kN/(m^2) P4=P1;//Pressure at point 4 in kN/(m^2) T1=293;//Temperature at point 1 in K P2=550;//Compression Pressure in kN/(m^2) P3=P2;//Pressure at point 3 in kN/(m^2) n=1.3;//Adiabatic gas constant N=500;//Speed of compressor in rpm Pa=101.325;//Air pressure in kN/(m^2) Ta=288;//Air temperature in K //CALCULATIONS x=(n-1)/n;//Ratio DV=(3.147*L*(D^2))/4;//Difference in volumes in m^3 V3=r*DV;//Clearance volume in m^3 V1=V3+DV;//Volume at point 1 in m^3 V4=V3*((P3/P4)^(1/n));//Volume at point 4 in m^3 Vs=V1-V4;//Effective swept volume in m^3 EVs=Vs*N;//Effective swept volume per min Va=(P1*EVs*Ta)/(Pa*T1);//Free air delivered in (m^3)/min nV=((V1-V4)/(V1-V3))*100;//Volumetric effciency T2=T1*((P2/P1)^x);//Air delivery temperature in K t2=T2-273;//Air delivery temperature in oC W=(n*P1*(V1-V4)*(((P2/P1)^x)-1))*N/((n-1)*60);//Cycle power in kW Wiso=P1*V1*(log(P2/P1));//Isothermal workdone P=(n*P1*V1*(((P2/P1)^x)-1))/(n-1);//Cycle power neglecting clearance niso=(Wiso/P)*100;//Isothermal efficiency //OUTPUT mprintf('Free air delivered is %3.3f (m^3)/min \n Volumetric efficiency is %3.0f percent \n Air delivery temperature is %3.1f oC \n Cycle power is %3.0f kW \n Isothermal efficiency is %3.1f percent',Va,nV,t2,W,niso) //==============================END OF PROGRAM=================================
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function [r,ind]=aplat(l,r) //flattens a list. If l is constant it puts it in a list //ind contains the list structure // Copyright INRIA if type(l)==1|type(l)==5 then r=list(l);ind=-1;return;end n=size(l) [lhs,rhs]=argn(0) if rhs==1 then r=list(),nr=0,end ind=list() i=0 nind=0 for li=l i=i+1 if type(li)==15 then [r,ind1]=aplat(li,r) ni=size(ind1) for j=1:ni,nind=nind+1;ind(nind)=[i,ind1(j)];end nr=size(r) else nr=nr+1 r(nr)=li nind=nind+1 ind(nind)=i end end
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Ex5_18.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 5 Example 18") T1_a=800;//temperature of reservoir a in K T1_b=700;//temperature of reservoir b in K T1_c=600;//temperature of reservoir c in K T2=320;//temperature of sink in K W=20;//work done in KW Q2=10;//heat rejected to sink in KW disp("let heat supplied by reservoir at 800 K,700 K,600 K be Q1_a , Q1_b , Q1_c") disp("here Q1-Q2=W") disp("so heat supplied by source(Q1)=W+Q2 in KW") Q1=W+Q2 disp("also given that,Q1_a=0.7*Q1_b.......eq 1") disp("Q1_c=Q1-(0.7*Q1_b+Q1_b)") disp("Q1_c=Q1-1.7*Q1_b........eq 2") disp("for reversible engine") disp("Q1_a/T1_a+Q1_b/T1_b+Q1_c/T1_c-Q2/T2=0......eq 3") disp("substitute eq 1 and eq 2 in eq 3 we get, ") disp("heat supplied by reservoir of 700 K(Q1_b)in KJ/s") disp("Q1_b=((Q2/T2)-(Q1/T1_c))/((0.7/T1_a)+(1/T1_b)-(1.7/T1_c))") Q1_b=((Q2/T2)-(Q1/T1_c))/((0.7/T1_a)+(1/T1_b)-(1.7/T1_c)) disp("so heat supplied by reservoir of 800 K(Q1_a)in KJ/s") disp("Q1_a=0.7*Q1_b") Q1_a=0.7*Q1_b disp("and heat supplied by reservoir of 600 K(Q1_c)in KJ/s") disp("Q1_c=Q1-1.7*Q1_b") Q1_c=Q1-1.7*Q1_b disp("so heat supplied by reservoir at 800 K(Q1_a)") Q1_a disp("so heat supplied by reservoir at 700 K(Q1_b)") Q1_b disp("so heat supplied by reservoir at 600 K(Q1_c)") Q1_c=-Q1_c disp("NOTE=>answer given in book for heat supplied by reservoir at 800 K,700 K,600 K i.e Q1_a=61.94 KJ/s,Q1_b=88.48 KJ/s,Q1_c=120.42 KJ/s is wrong hence correct answer is calculated above.")
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sce
exa_1_12.sce
// Exa 1.12 clc; clear; close; // Given data V_D1=0.7;// in volt V_D2=V_D1; V_BE= 0.7;// in volt Bita= 100; R3=180;// in ohm V_EE= 15;// in volt V_CC=15;// in volt R_C=470;// in ohm V_B3= -V_EE+V_D1+V_D2;// in volt V_E3= V_B3-V_BE;// in volt I_E3= (V_E3-(-V_EE))/R3;// in amp // Part (i) I_CQ= I_E3/2;// in amp I_CQ= I_CQ*10^3;// in mA I_CQ= ceil(I_CQ); I_E=I_CQ; disp(I_CQ,"Quiescent current in mA") V_CEQ= V_CC + V_BE - I_CQ*10^-3*R_C;// in volt disp(V_CEQ,"Value of V_CEQ in volt"); re_desh= 26/I_E;// in ohm // Part(ii) A_d = R_C/(re_desh); disp(A_d,"Differential Voltage gain"); // part(iii) R_in1= 2*Bita*re_desh;// in ohm disp(R_in1*10^-3,"Input resistance in k ohm");