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clear; clc; printf("\n Example 2.2\n"); // String insertion. s="auto";...............//1st string or character array. x="mobile";...............//2nd string or character array. z=s+x;..........//concatenation of 2 strings. printf("\tstring s="); disp(s); printf("\tstring x="); disp(x); printf("\tconcatenated string z="); disp(z);........//dispalying concatenated string.
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clear // // // //Variable declaration N=6.02*10**26 //Avagadro Number n=8 //number of atoms a=5.62*10**-10 //lattice constant(m) M=72.59 //atomic weight(amu) //Calculation rho=n*M/(a**3*N) //density(kg/m**3) //Result
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//Example 2.1 // NA ,angles and pulse broadning clc; clear; close; format('v',9 ) disp("part (a)") n1=1.5;//core refrative index n2=1.48;//claddin refractive index a=100/2;//radius in micro meter na=1;//air refrative index NA=sqrt(n1^2-n2^2);//numerical aperture disp(NA,"numerical aperture is") disp("part (b)") am=(asind(NA));// tm=asind(NA/n1);// tc=asind(n2/n1);// disp(am,"angle in degree is (αm)") disp(tm,"angle in degree is (Om)") disp(tc,"angle in degree is(Φc)") disp("part (c)") c=3*10^8;//speed of light in m/s dtl=((n1/n2)*(n1-n2)/c);//pulse broadning per unit length disp(dtl,"pulse broadning per unit length in sm^-1")
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ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.268492D+00 2 -0.147873D-02 0.211473D-02 3 -0.489459D-02 -0.855111D-03 0.393875D+00 4 -0.151137D-02 -0.618116D-04 -0.192970D-02 0.347601D-02 5 -0.134384D-02 0.368126D-04 0.206304D-02 0.746187D-04 0.352973D-02 6 0.904082D-03 0.247710D-04 -0.103239D-03 -0.122153D-04 -0.211316D-03 7 0.160761D-02 -0.279283D-04 -0.177985D-03 -0.680529D-05 0.235804D-03 8 0.196969D-03 0.945759D-04 -0.108814D-02 0.124828D-03 0.208188D-04 9 -0.425060D+00 0.211415D-01 0.400550D+00 -0.654718D-03 0.569136D-01 10 -0.361370D+00 -0.340545D-03 0.217110D+00 -0.230361D-02 0.165086D+00 11 -0.246230D+00 0.414167D-02 -0.333779D-01 0.654590D-02 -0.477824D-02 12 -0.148318D+00 -0.909303D-03 -0.119636D+01 0.557656D-01 -0.286384D-01 13 0.154384D+00 0.125550D-02 -0.799888D-02 0.410154D-02 0.198343D-01 14 0.133524D+00 -0.774451D-02 -0.454539D+00 0.204597D-01 -0.137601D-01 15 -0.224644D+01 -0.294356D-01 -0.295709D+00 -0.457382D-02 -0.867764D-01 16 -0.201096D-01 -0.733386D-02 0.134365D-01 -0.905398D-03 0.353195D-03 17 0.467435D-02 0.114137D-03 -0.192588D-02 0.116862D-03 -0.362659D-03 18 -0.439713D+00 -0.134231D-01 0.125577D+00 -0.250038D-01 -0.717341D-01 19 -0.793156D-01 -0.316111D-02 -0.122656D-01 0.946993D-02 -0.374516D-02 20 0.453864D+00 -0.142890D-01 -0.313927D+01 -0.302560D-01 0.282843D-01 21 0.684045D-01 0.265608D-02 -0.594019D-02 0.204075D-02 0.694238D-02 22 0.211472D-02 0.635864D-04 0.616929D-02 0.364590D-03 0.116659D-03 23 0.922255D-02 0.383885D-02 -0.419896D-01 -0.132870D-01 -0.442687D-03 24 0.177393D-02 0.283732D-03 0.261974D-02 -0.987364D-03 -0.392662D-04 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 0.529153D-03 7 0.617844D-03 0.426584D-02 8 0.833115D-04 -0.972193D-04 0.169113D-02 9 -0.178143D-01 -0.370705D-01 -0.101939D-01 0.357302D+02 10 -0.126934D-01 0.167045D-01 -0.528494D-02 0.213360D+01 0.163588D+02 11 -0.121162D-01 -0.197887D-01 0.610473D-02 0.231947D+01 0.199876D+00 12 0.301402D-02 -0.945023D-02 0.167409D-01 -0.599606D+00 -0.794965D+00 13 0.391591D-01 0.112174D+00 -0.272362D-03 -0.203517D+01 0.172219D+01 14 0.123668D-01 0.339031D-01 0.142322D+00 -0.139758D+01 0.373901D+00 15 0.134986D-01 -0.193625D-01 0.262556D-01 0.208488D+01 -0.336871D+01 16 -0.920818D-03 -0.242679D-02 -0.685236D-03 0.604478D+00 -0.154059D-01 17 -0.125951D-04 0.739879D-04 -0.162068D-03 -0.120527D+00 -0.359652D-01 18 -0.156549D-01 -0.464231D-01 -0.707592D-01 -0.864052D+01 -0.815880D+00 19 -0.130096D-01 0.386176D-02 -0.127846D-02 -0.901338D+00 -0.711785D+00 20 -0.157115D-01 0.257936D-01 -0.934463D-01 0.584794D+01 0.216127D+01 21 0.109148D-01 -0.884088D-02 0.176745D-02 0.106719D+01 0.901427D+00 22 0.707324D-04 0.237190D-04 0.296884D-03 0.439363D-01 -0.104438D-01 23 0.278950D-03 0.118261D-02 -0.443054D-03 -0.357393D-01 0.843209D-01 24 0.179565D-04 -0.270664D-04 -0.154161D-03 -0.745962D-02 -0.756755D-02 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 0.268766D+02 12 0.770335D+00 0.126117D+03 13 -0.419131D+01 0.255364D+01 0.113132D+02 14 -0.388568D+01 -0.765402D+00 0.260222D+01 0.567741D+02 15 -0.181595D+01 0.149847D+01 -0.260165D+01 0.290990D+01 0.184882D+03 16 0.256140D+00 -0.144409D+00 -0.157841D+00 -0.164911D+00 0.160223D+01 17 0.291818D-01 0.736533D-01 0.162461D-02 0.561427D-02 -0.875724D+00 18 -0.188267D+01 -0.496108D+01 -0.170610D+01 -0.102972D+02 0.205979D+01 19 0.372373D+00 -0.232757D+01 -0.142691D+01 0.150750D+01 -0.203792D+01 20 0.250118D+01 -0.175219D+02 -0.368536D+01 -0.159262D+02 0.107200D+02 21 0.888380D-01 0.248250D+01 0.123160D+01 -0.156997D+01 0.113863D+01 22 -0.339821D-01 0.459320D-01 -0.547410D-03 0.396347D-01 -0.311117D-01 23 0.699723D-02 -0.310708D+00 0.747182D-01 0.191577D+00 0.271250D+00 24 0.229130D-01 -0.123993D+00 -0.141607D-02 -0.911273D-01 -0.223438D-01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 0.343071D+00 17 -0.211273D-01 0.109376D-01 18 -0.528833D+00 0.895186D-02 0.173067D+03 19 0.391275D-01 0.221636D-01 0.331549D+01 0.460431D+01 20 0.380968D+00 -0.498512D-01 -0.230328D+02 0.349213D+01 0.511738D+03 21 -0.292867D-01 -0.255914D-01 0.440693D-01 -0.428540D+01 -0.340652D+01 22 -0.108291D-02 0.430609D-03 -0.765370D+00 -0.181899D-01 0.125437D+00 23 -0.474043D-02 -0.287322D-02 -0.494688D+00 -0.376275D-01 0.465689D+01 24 -0.119281D-02 -0.480803D-03 0.232847D+00 -0.147718D-01 -0.248747D+01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 0.493161D+01 22 -0.180111D-01 0.703809D-02 23 0.294974D-02 -0.509094D-02 0.606194D+00 24 -0.111267D-02 -0.223976D-02 -0.319994D-01 0.249333D-01 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 1.000 2 -0.062 1.000 3 -0.015 -0.030 1.000 4 -0.049 -0.023 -0.052 1.000 5 -0.044 0.013 0.055 0.021 1.000 6 0.076 0.023 -0.007 -0.009 -0.155 7 0.048 -0.009 -0.004 -0.002 0.061 8 0.009 0.050 -0.042 0.051 0.009 9 -0.137 0.077 0.107 -0.002 0.160 10 -0.172 -0.002 0.086 -0.010 0.687 11 -0.092 0.017 -0.010 0.021 -0.016 12 -0.025 -0.002 -0.170 0.084 -0.043 13 0.089 0.008 -0.004 0.021 0.099 14 0.034 -0.022 -0.096 0.046 -0.031 15 -0.319 -0.047 -0.035 -0.006 -0.107 16 -0.066 -0.272 0.037 -0.026 0.010 17 0.086 0.024 -0.029 0.019 -0.058 18 -0.065 -0.022 0.015 -0.032 -0.092 19 -0.071 -0.032 -0.009 0.075 -0.029 20 0.039 -0.014 -0.221 -0.023 0.021 21 0.059 0.026 -0.004 0.016 0.053 22 0.049 0.016 0.117 0.074 0.023 23 0.023 0.107 -0.086 -0.289 -0.010 24 0.022 0.039 0.026 -0.106 -0.004 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 1.000 7 0.411 1.000 8 0.088 -0.036 1.000 9 -0.130 -0.095 -0.041 1.000 10 -0.136 0.063 -0.032 0.088 1.000 11 -0.102 -0.058 0.029 0.075 0.010 12 0.012 -0.013 0.036 -0.009 -0.018 13 0.506 0.511 -0.002 -0.101 0.127 14 0.071 0.069 0.459 -0.031 0.012 15 0.043 -0.022 0.047 0.026 -0.061 16 -0.068 -0.063 -0.028 0.173 -0.007 17 -0.005 0.011 -0.038 -0.193 -0.085 18 -0.052 -0.054 -0.131 -0.110 -0.015 19 -0.264 0.028 -0.014 -0.070 -0.082 20 -0.030 0.017 -0.100 0.043 0.024 21 0.214 -0.061 0.019 0.080 0.100 22 0.037 0.004 0.086 0.088 -0.031 23 0.016 0.023 -0.014 -0.008 0.027 24 0.005 -0.003 -0.024 -0.008 -0.012 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 1.000 12 0.013 1.000 13 -0.240 0.068 1.000 14 -0.099 -0.009 0.103 1.000 15 -0.026 0.010 -0.057 0.028 1.000 16 0.084 -0.022 -0.080 -0.037 0.201 17 0.054 0.063 0.005 0.007 -0.616 18 -0.028 -0.034 -0.039 -0.104 0.012 19 0.033 -0.097 -0.198 0.093 -0.070 20 0.021 -0.069 -0.048 -0.093 0.035 21 0.008 0.100 0.165 -0.094 0.038 22 -0.078 0.049 -0.002 0.063 -0.027 23 0.002 -0.036 0.029 0.033 0.026 24 0.028 -0.070 -0.003 -0.077 -0.010 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 1.000 17 -0.345 1.000 18 -0.069 0.007 1.000 19 0.031 0.099 0.117 1.000 20 0.029 -0.021 -0.077 0.072 1.000 21 -0.023 -0.110 0.002 -0.899 -0.068 22 -0.022 0.049 -0.693 -0.101 0.066 23 -0.010 -0.035 -0.048 -0.023 0.264 24 -0.013 -0.029 0.112 -0.044 -0.696 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 1.000 22 -0.097 1.000 23 0.002 -0.078 1.000 24 -0.003 -0.169 -0.260 1.000
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//function for calculating the energy level function[energy]=F(j) energy=a*j*(j+1); endfunction //variable initialization m=1.6738*10^-27; //mass of hydrogen atom (kg) r=0.74*10^-10; //intermolecular distance of hydrogen molecule (meter) h=1.054*10^-34; //Planck's constant (joule second) e=1.6*10^-19; //Charge of electron (coulombs) //calculation of rotational energy levels mu=m/2; //reduced mass of hydrogen atom (kg) I=mu*r^2; //moment of inertia of molecule (kg meter^2) a=h^2/(2*I*e); //constant (eV) E0=F(0); //energy of level 0 (eV) E1=F(1); //energy of level 1 (eV) E2=F(2); //energy of level 2 (eV) E3=F(3); //energy of level 3 (eV) printf("\nE0 = %.0f\nE1 = %.2e eV\nE2 = %.2e eV\nE3 = %.2e eV",E0,E1,E2,E3);
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// Scilab Code Ex9.11: Page-468 (2011) clc;clear; alpha = 3.5;....// Attenuation of the optical fibre, dB/km Pi = 0.5;....// Input power of optical fibre, mW L = 4;.... // Distance through the optical wave transmits through the fibre, km // As alpha = 10/L*log10(Pi/Po), solving for Po Po = Pi/exp(alpha*L*2.3026/10); // Output power of optical fibre, mW printf("\nThe output power of optical fibre = %4.1f micro-watt", Po/1e-003); // Result // The output power of optical fibre = 19.9 micro-watt
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clear all; clc; printf("\n Example 11.19"); //Data from fig. 11.42 a = [0 0.02 0.04 0.06 0.08 0.1 0.2 0.4 0.6 0.8 1.0]; b = [0.75 0.62 0.60 0.57 0.55 0.52 0.45 0.30 0.18 0.09 0]; //a = (R-Rm)/(R+1) //b = [(n+1)-(nm+1)]/(n+2) R = [0.92 1.08 1.25 1.75 2.5 3.5 5.0 7.0 9.0]; n = [28.6 22.8 16.9 13.5 11.7 10.5 9.8 9.2 8.95]; plot(n,R); xtitle("Plot of R vs n","n","R"); printf("\n Derivative calculated from the graph"); d = [110.0 34.9 9.8 3.8 1.7 0.6 0.4 0.2 0.05]; i=1; while i <=9 s = R(i)+1 - (n(i)+7.72)/d(i); if s <=0.0001 then Ropt = R(i); printf("\n Ropt = %.2f",Ropt); break; end i=i+1; end printf("\n R is approximately %.1f percent of the minimum reflux condition",1.25/0.866666666*100);
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//Steven McHale //Tsunami Model //Shallow-Water Wave Equation //Crank-Nicholson Discretization clear; //clf; clc; // Constants g = 9.81; u0 = 0; v0 = 0; b = 0; h0 = 5030; // Define the x domain //ni = 151; ni=41; xmax = 100000; dx = xmax/(ni-1); x = [0:dx:xmax]; // Define the y domain //nj = 151; nj=41; ymax = 100000; dy = ymax/(nj-1); y = [0:dy:ymax]; tmax = 15; // Define the wavespeed wavespeed = u0 + sqrt(g*(h0 - b)); // Define time-domain dt = 0.68*dx/wavespeed; //t = [0:dt:tdomain]; t=[1:dt:tmax]; courant = wavespeed*dt/dx; // Build empty u, v, b matrices u=zeros(length(x), length(y), length(t)); v=zeros(length(x), length(y), length(t)); b=zeros(length(x), length(y)); // Define h h=zeros(length(x), length(y), length(t)); h(:,:,1) = 5000; h((45000/100000*(length(x)-1)+1):floor(55000/100000*(length(x)-1)+1),(45000/100000*(length(y)-1)+1):floor(55000/100000*(length(y)-1)+1),1) = 5030; //Define b for i = 1:length(x) if x(i) > 20001 b(:,i) = 0; elseif x(i) < 20000 b(:,i) = 5000/20000*(20000-x(i)); end end // Employ Lax for n=1:(length(t)-1) for i=2:(ni-1) for j=2:(nj-1) u(i,j,n+1) = ((u(i+1,j,n) + u(i-1,j,n) + u(i,j+1,n) + u(i,j-1,n))/4)... - 0.5*(dt/dx)*((u(i+1,j,n)^2)/2 - (u(i-1,j,n)^2)/2)... - 0.5*(dt/dy)*(v(i,j,n))*(u(i,j+1,n) - u(i,j-1,n)) - 0.5*g*(dt/dx)*(h(i+1,j,n)-h(i-1,j,n)); v(i,j,n+1) = ((v(i+1,j,n) + v(i-1,j,n) + v(i,j+1,n) + v(i,j-1,n))/4)... - 0.5*(dt/dy)*((v(i,j+1,n)^2)/2 - (v(i,j+1,n)^2)/2)... - 0.5*(dt/dx)*(u(i,j,n))*(v(i+1,j,n) - v(i-1,j,n)) - 0.5*g*(dt/dy)*(h(i,j+1,n)-h(i,j-1,n)); h(i,j,n+1) = ((h(i+1,j,n) + h(i-1,j,n) + h(i,j+1,n) + h(i,j-1,n))/4)... - 0.5*(dt/dx)*(u(i,j,n))*((h(i+1,j,n)-b(i+1,j)) - (h(i-1,j,n)-b(i-1,j)))... - 0.5*(dt/dy)*(v(i,j,n))*((h(i,j+1,n)-b(i,j+1)) - (h(i,j-1,n)-b(i,j-1)))... - 0.5*(dt/dx)*(h(i,j,n)-b(i,j))*(u(i+1,j,n)- u(i-1,j,n))... - 0.5*(dt/dy)*(h(i,j,n)-b(i,j))*(v(i,j+1,n) - v(i,j-1,n)); end end // Define Boundary Conditions u(1,:,n+1) = 2.5*u(2,:,n+1) - 2*u(3,:,n+1) + 0.5*u(4,:,n+1); u(length(x),:,n+1) = 2.5*u(ni-1,:,n+1) - 2*u(ni-2,:,n+1) + 0.5*u(ni-3,:,n+1); u(:,1,n+1) = 2.5*u(:,2,n+1) - 2*u(:,3,n+1) + 0.5*u(:,4,n+1); u(:,length(y),n+1) = 2.5*u(:,nj-1,n+1) - 2*u(:,nj-2,n+1) + 0.5*u(:,nj-3,n+1); v(1,:,n+1) = 2.5*v(2,:,n+1) - 2*v(3,:,n+1) + 0.5*v(4,:,n+1); v(length(x),:,n+1) = 2.5*v(ni-1,:,n+1) - 2*v(ni-2,:,n+1) + 0.5*v(ni-3,:,n+1); v(:,1,n+1) = 2.5*v(:,2,n+1) - 2*v(:,3,n+1) + 0.5*v(:,4,n+1); v(:,length(y),n+1) = 2.5*v(:,nj-1,n+1) - 2*v(:,nj-2,n+1) + 0.5*v(:,nj-3,n+1); h(1,:,n+1) = 2.5*h(2,:,n+1) - 2*h(3,:,n+1) + 0.5*h(4,:,n+1); h(length(x),:,n+1) = 2.5*h(ni-1,:,n+1) - 2*h(ni-2,:,n+1) + 0.5*h(ni-3,:,n+1); h(:,1,n+1) = 2.5*h(:,2,n+1) - 2*h(:,3,n+1) + 0.5*h(:,4,n+1); h(:,length(y),n+1) = 2.5*h(:,nj-1,n+1) - 2*h(:,nj-2,n+1) + 0.5*h(:,nj-3,n+1); end
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//Part B Chapter 4 Example 15 clc; clear; close; l=3;//m d1=85;//mm d2=65;//mm A=1*0.5;//m^2 Pw=2200;//N/mm^2 LG=Pw*A//N(Total Wind load at G) M=LG*(3+0.25)//Nm(Max BM on pipe) T=LG*(0.5+0.5);//Nm I=%pi/64*(d1^4-d2^4);//mm^4 Z=I/42.5;//mm^3 Zp=2*Z;//mm^3 sigma_b=M*1000/Z;//N/mm^2 tau_s=T*1000/Zp;//N/mm^2 disp("Maximum bending stress is "+string(sigma_b)+" N/mm^2"); disp("Maximum shear stress is "+string(tau_s)+" N/mm^2");
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//Example 3.4 //Frequency response xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ //(a) Frequency response of 1/(s+k) k=1; fmin=1e-2; fmax=1e2; // Transfer function s=poly(0,'s'); sysH=syslin('c',1/(s+k)) //Frequency response for k=1 //Note that - magnitude plot semilog plot unlike log-log plot in the book. bode(sysH,fmin,fmax) title('Frequency response for k=1','fontsize',3) //------------------------------------------------------------------ //(b) Response to u=sin(10*t); t=0:0.02:10; u=sin(10*t); y=csim(u,t,sysH); figure, plot(t,y) //Title, labels and grid to the figure exec .\fig_settings.sci; // custom script for setting figure properties title('Complete transient response','fontsize',3) xlabel('Time (sec.)','fontsize',2) ylabel('Output','fontsize',2) //phase lag figure, plot(t,y) plot(t,u,'r') zoom_rect([9 -1 10 1]) exec .\fig_settings.sci; // custom script for setting figure properties title('Phase lag between output and input','fontsize',3) xlabel('Time (sec.)','fontsize',2) ylabel('Output, Input','fontsize',2) h=legend('y(t)','u(t)') h.legend_location = "in_upper_right" h.fill_mode='off' // time lag w=find(t>=9.4 & t<=10); T=t(w); Y=y(w); U=u(w); wu=find(U==max(U)) wy=find(Y==max(Y)) //Responses plot2d3(T(wy),Y(wy)) plot2d3(T(wu),U(wu)) delta_t=T(wu)-T(wy); //time lag sec. xstring(9.64,-0.1,"$\delta t$",0,0) xarrows([9.58;9.72], [0;0], 0.7, 1) xarrows([9.72;9.58], [0;0], 0.7, 1) t=get("hdl") disp(abs(delta_t), "Time lag of output in sec. is") disp(abs(delta_t)*10, "Phase lag of output in radians is") //------------------------------------------------------------------
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//calculates// s=%s; G=syslin('c',20/(s*(s+4))) H=0.35; y=G*H; S=1/(1+y); disp(S,"1/(1+G(s)*H(s))") //given w=1.2 w=1.2 s=%i*w S=horner(S,s) //calculates value of S at s a=abs(S) disp(a,"sensitivity of open loop") F=-y/(1+y) disp(F,"(-G(s)*H(s))/(1+G(s)*H(s))") S=horner(F,s) //calculates value of F at s b=abs(S) disp(b,"sensitivity of closed loop")
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// Camera parameters vfrom = [25 25 21]; vto = [23 25 0]; vup = [0.2 0.8 0.6]; fcamwidth = 47; istep = 1; sname='testsim3'; cam=struct('camfrom',vfrom,'camto',vto,'camup',vup,'camwidth',fcamwidth); settings=struct('step',istep,'name',sname); metadata.author='MikeG'; metadata.sdate=date(); metadata.platform='felix'; metadata.desc='Collab viewer example'; metadata.name='collabtestsim3'; elist=list(2); elist(1)='localhost'; //elist(1)='10.0.16.99'; elist(2)=8080; elist(3)=0;
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//Variable declaration n1 = 4 // Total operators n2 = 3 // Total Machines n3 = 8 // Test specimens for each pair //Calculation Total_pairs = n1*n2 Total_specimens = n1*n2*n3 //Results printf ( "Total Pairs : %.f ",Total_pairs) printf ( "Total Test specimens : %.f",Total_specimens)
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<<<<<<< HEAD //isminphase Determine whether filter is minimum phase or not // Description : It determines whether the given system function is minimum phase system or not . Minimum phase system means all zeros of transfer function will be inside the unit circle in z-plane , also poles mustbe within unit circle for stability and causality //Syntax //flag = isminphase(b,a) //flag = isminphase(sos) //flag = isminphase(...,tol) // b and a are the vectors containing numerator and denumerator coefficients respectively //tol, tolerance is used to determine when two numbers are close enough to be considered equal. //Example : of minimum phase system //flag = isminphase([1 -0.3 0.02],1) //Output // flag = // // 1. ======= >>>>>>> 6bbb00d0f0128381ee95194cf7d008fb6504de7d //Author: Parthasarathi Panda //parthasarathipanda314@gmail.com function ismin=isminphase(varargin) [nargout,nargin]=argn(); if (nargin==2) then a=varargin(1); b=varargin(2); if type(a)~=1 | type(b)~=1 then error('check input type'); end v=size(a); if length(v)>2 then error('check input dimension'); end v=size(b); if length(v)>2 then error('check input dimension'); end [n,k]=size(a); if k==1 then a=a'; elseif n~=1 then error('check input dimension'); end [n,k]=size(b); if k==1 then b=b'; k=n; elseif n~=1 then error('check input dimension'); end elseif (nargin==1) then sos=varargin(1); if type(sos)~=1 then error('check input dimension'); end v=size(sos); if length(v)>2 then error('check input dimension'); end if v(2)~=6 then error('no. of columns must be 6'); end a=1;b=1; for i=[1:v(1)] a=convol(a,sos(i,1:3)); b=convol(b,sos(i,4:6)); end else error('no. of inputs not matching'); end poly_a=inv_coeff(a); poly_b=inv_coeff(b); z=inv_coeff([1,0]); gc=gcd([poly_a,poly_b]); [r,den]=pdiv(poly_b,gc); [r,num]=pdiv(poly_a,gc); <<<<<<< HEAD maxpole=max(abs(roots(den))); maxzero=max(abs(roots(num))); if length(b)==1 then if length(a)==1 then ismin=1; elseif maxzero<1 then ismin=0; else ismin=1; end elseif maxpole>1 then if length(a)==1 then ======= maxpole=min(abs(roots(den))); maxzero=min(abs(roots(num))); if length(a)==1 then if length(b)==1 then ismin=1; elseif maxzero>1 then ismin=1; else ismin=0; end elseif maxpole>1 then if length(b)==1 then >>>>>>> 6bbb00d0f0128381ee95194cf7d008fb6504de7d ismin=1; elseif maxzero>1 then ismin=1; else ismin=0; end else ismin=0; end endfunction
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// Example 5.12:corner frequency and maximum GAIN clc; clear; close; Vcc=10;// Colector voltage in volts Beta= 100; Rc=1;// Collector resistance in killo ohms Rs=600;//SERIES RESISTANCE IN OHMS Re=0.2;// in kilo ohms R1= 50;// in kilo ohms R2= 10;// in kilo ohms Vbe=0.7;// Base to emitter voltage in volts C1=1;//capacitance in micro farad Vth=Vcc * (R2/(R1+R2)); // vOLTAGE AT BASE Rth= (R1*R2)/(R1+R2); Ib=((Vcc-Vbe)/((Rth+(1+Beta)*Re)*10^3))*10^5;//in micro ampere Icq= Beta*Ib*10^-3;//in milli ampere Vt=26;//volate at room termprature in milli volts gm= (Icq/Vt)*10^3;//transconductance in milli ampere per volts rpi= (Beta*Vt*10^-3)/(Icq*10^-3);//resistance Rb=Rth;//base resistance in killo ohms x=(rpi+(1+Beta)*Re*10^3);// y=(Rs+Rb*10^3);// ts=((x*y)/(x+y))*C1*10^-3;//in milli second fl= (1/(2*%pi*ts*10^-3));//corner frequency in hertz Ri=(x*Rb*10^-3)/(Rb+x*10^-3);// Av= ((gm*10^-3*rpi*Rc*10^3)*Rb*10^3)/((Ri+Rs*10^-3)*10^3*(x*10^-3+Rb)*10^3); disp (fl,"corner frequency in hertz is") disp(Av,"maximum gain is")
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#$Id: pdbboxes 232 2015-05-04 12:44:10Z Lukas_Tutkus $ 93.962 97.136 44.179 inputs/1AXC.pdb
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//example 6.2.1 //calculate power level at op of transponder //variables clc clear pearth = 500 gain = 105 backoff = 3 outputpower = 40 BWStA = 15 BWStB = 10 BWStC = 5 Pt = 20 EIRPa = 3.0 EIRPb = 4.8 EIRPc = 7.8 PtindB=10*log10(outputpower) - backoff printf("Power of tansponder is %fdBW \n",PtindB) BWt = BWStA + BWStB + BWStC PtA = 10*log10((BWStA/BWt)*Pt) PtB = 10*log10((BWStB/BWt)*Pt) PtC = 10*log10((BWStC/BWt)*Pt) printf("Transponder power output allocated to StA is %f dBW \n",PtA) printf("Transponder power output allocated to StB is %f dBW\n",PtB) printf("Transponder power output allocated to StC is %f dBW\n",PtC) PinA = PtA - gain PinB = PtB - gain PinC = PtC - gain printf("Transponder input power for StA signal is %f dBW\n",PinA) printf("Transponder input power for StB signal is %f dBW\n",PinB) printf("Transponder input power for StC signal is %f dBW \n",PinC) Pte = 10*log10(250) PStA = Pte - EIRPa PStB = Pte - EIRPb PStC = Pte - EIRPc printf("The Earth Station A transmit power is %f dBW \n",PStA) printf("The Earth Station B transmit power is %f dBW \n",PStB) printf("The Earth Station C transmit power is %f dBW\n",PStC)
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//Example 2.7// a=sqrt(3);// Given //By formula b=1;//Given r=a-b disp(r)
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clc; pathname=get_absolute_file_path('3_8_soln.sce') filename=pathname+filesep()+'3_8_data.sci' exec(filename) // Solution: // The required piston area, A=round(F_load/p); //in^2 // The necessary pump flow rate, Q=((A/144)*S)/t; //ft^3/s Q_gpm=Q*449; //gpm // The Hydraulic Horsepower delivered to cylinder, HHP=(p*Q_gpm)/1714; //HP // rounding off the above answer HHP=fix(HHP)+(fix(floor((HHP-fix(HHP))*10))/10); //HP // The output horsepower delivered by cylinder to load, OHP=HHP*eta; //HP // Results: printf("\n Results: ") printf("\n The Required piston area is %.0f in^2.",A) printf("\n The necessary pump flow rate is %.1f gpm.",Q_gpm) printf("\n The Hydraulic Horsepower delivered to cylinder is %.1f HP.",HHP) printf("\n The output horsepower delivered by cylinder to load is %.1f HP.",OHP)
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clear all clc close iload=5*1e-3;//Load current in A //Capacitances of Cockcroft-Waltobn type voltage tripler in F C1=0.01*1e-6; C2=0.05*1e-6; C3=0.10*1e-6; f=50;//frequency in Hz Vs=100*1e3//Supply voltage in V //Ripple voltage in V dv=iload/f*(2/C1+1/C3) printf('Ripple voltage in V %f',dv) //Voltage drop in V Vdrop=iload/f*(1/C2+1/C1+1/(2*C3)) printf('Voltage drop in V %f',Vdrop) //Average output voltage in V V_av=3*sqrt(2)*Vs-Vdrop printf('Avarage voltage in V %f',V_av) //Ripple factor in percentage RF=Vdrop/(3*Vs*sqrt(2))*100 printf('Ripple voltage in percentage %f',RF)
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clc clear //Initialization of variables Co=0.1 Co2=14.1 Cb=0.646 //calculations Q2=Co/(Co+Co2) *Cb*10160 //results printf("Heat loss = %d Btu per lb of fuel",Q2)
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// Example 24_12 clc;funcprot(0); //Given data P=10;// Power plant capacity in MW T_1=300;// K T_4=960;// K e=0.7;// The effectiveness of regenerator n_c=0.8;// Isentropic efficiency of compressor n_t=0.90;// Isentropic efficiency of turbine n_com=0.96;// Combustion efficiency n_m=0.95;// Mechanical efficiency n_g=0.95;// Generation efficiency CV=40000;// kJ/kg C_pa=1;// kJ/kg.K r=1.4;// Specific heat ratio Cf_t=4000;// Cost of fuel in Rs./tonne Oc=3000;// All other charges in rupees Q=90;// Heat developed in combustion chamber in % //Calculation p_r=(n_c*n_t*(T_4/T_1))^(r/(2*(r-1)));// Pressure ratio T_2a=T_1*(p_r)^((r-1)/r);// K T_2=((T_2a-T_1)/n_c)+T_1;// K T_5a=T_4*(1/p_r)^((r-1)/r);// K T_5=T_4-(n_t*(T_4-T_5a));// K m_a=(P*1000)/((C_pa*((T_4-T_5)-(T_2-T_1)))*n_com*n_g); T_3=T_2+(e*(T_5-T_2));// K m_f=(m_a*C_pa*(T_4-T_3))/(CV*n_com*(Q/100));// kg/sec Cf=((m_f*3600)/1000)*Cf_t;// Cost of fuel in Rs./hr Tc=Cf+Oc;// Total cost in Rs/hr Ce=Tc/(P*1000);// Cost of energy generated in Rs/kWh m=m_a/m_f;// Air-fuel ratio printf('\nThe cost of energy generated=Rs.%0.2f/kWh',Ce); // The answer vary due to round off error
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clear clc Co=1;k=1;t=1;//given //Scheme A //For mixed flow reactor //t=(Co-C1)/KC1^2 C1=(-1+sqrt(1-4*t*(-Co)))/2*t; //For the plug flow reactor //t=1/k(1/C2-1/C1) C2=C1/(1+k*t*C1); printf("\n Conversion for flow scheme A is %f",C2) //Scheme B //For plug flow C3=Co/(1+k*t*Co); //For mixed flow reactor C4=(-1+sqrt(1-4*t*(-C3)))/2*t; printf("\n Conversion for flow scheme B is %f",C4) //Scheme C,D,E //Using exit age distribution fn for 2 equal plug-mixed flow reactor system,using fig 12.1 t_bar=2; in=1000; C5=integrate('(2/t_bar)*(exp(1-2*t/t_bar))/(1+Co*k*t)','t',t_bar/2,in); printf("\n Conversion for flow scheme C,D,E is %f",C5)
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clc(); clear; //To calculate the pitch of the helix and radius of trajectory v=2*10^6; //speed in m/s teta=30; //angle at which proton enters at the origin of coordinate system B=0.3; //magnetic field in iT vp=v*sind(teta); //v(perpendicular component) vpa=v*cosd(teta); //v(parallel component) m=1.67*10^-27; //mass of proton q=1.6*10^-19; p=(vpa*2*%pi*m)/(q*B) //pitch of the helix described by the proton R=((m*vp)/(q*B))*10^2 //radius of the trajectory printf("the pitch of the helix is %f m and radius of trajectory is %f cm",p,R)
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clc //initialisation de=5.52*10^-21//j k=1.38*10^-23 //CALCULATIONS t=de/(2*k) //results printf(' \n temperature of system= % 1f k',t)
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//Example 2_9_u1 clc(); clear; //To calculate resolving power in second order //We have e*sin(theta)=k*lamda //We have e*0.2=k*lamda ->1 //And e*0.3=(k+1)*lamda ->2 //Subtracting one and two 3*0.1=lamda lamda=5000 //units in armstrongs lamda=lamda*10^-8 //units in cm e=lamda/0.1 //units in cm width=2.5 //units in cm N=width/e respower=2*N printf("Resolving power is %.f",respower)
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex9_7.sce. clc; clear; //input data are taken from example 9.5 V=1+%i*0; Xd=1.0; Xq=0.6; pf=0.8; theta=acosd(pf); Ia1=pf-%i*sind(acosd(pf)); Ia=1.0; //phase magnitude of Ia printf("\n (a)") //lagging power factor tan_del=(Ia*Xq*cosd(theta))/(V+(Ia*Xq*sind(theta))); del=atand(real(tan_del)); Ef_dash=((V+(Ia*Xq*sind(theta)))^2+(Ia*Xq*cosd(theta))^2)^(1/2); Ef=real(Ef_dash)+(Ia*sind(theta+del)*(Xd-Xq)); reg=((Ef-V)/1.0)*100; printf("\n Voltage Regulation for 0.8 lagging power factor=%d percentage \n",reg) printf("\n (b)") tan_del=(Ia*Xq*cosd(theta))/(V-(Ia*Xq*sind(theta))); del=atand(real(tan_del)); Ef=((V-(Ia*Xq*sind(theta)))^2+(Ia*Xq*cosd(theta))^2)^(1/2); reg=((Ef-V)/1.0)*100; printf("\n Voltage Regulation for 0.8 leading power factor=%2.0f percentage",reg)
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clear; //clc(); // Example 15.7 // Page: 405 printf("Example-15.7 Page no.-405\n\n"); //***Data***// printf(" Our system consists of Au and H2O.\n"); // So N = 2;// Number of the species // If there is no chemical reaction, then Q = 0; //So C = N - Q;// Number of the components printf(" If no compound is formed, then number of the components in the system are \n C = N - Q = 2 - 0 = %0.0f\n\n",C); // However, if there is also a chemical reaction // Au + H2O = AuH2O // so n = 3;// Number of the species q = 1;// Number of the reactions // Thus, we have c = n - q;// Number of the components printf(" If there is also a chemical reaction, viz.\n Au + H2O = AuH2O \n"); printf(" the number of the components in the system are\n C = N - Q = %0.0f\n\n",c); printf(" The number of the components is independent of the existence or nonexistence of such compounds of questionable existence. ");
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// 08.07.11 function Ang=Thetadegree() global THETA; Ang=THETA*180/%pi; endfunction
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errcatch(-1,"stop");mode(2); //Initialization of variables ratio=0.99 E=3.19e5 //lb/in^2 //calculations pd=-E*log(ratio) //ersults printf("Pressure difference = %d psi",pd) exit();
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS // EXAMPLE : 1.5 : // Page number 682 clear ; clc ; close ; // Clear the work space and console // Given data V = 400.0 // IM voltage(V) f = 50.0 // Frequency(Hz) I_s = 5.0 // Full voltage starting current in terms of full load current T_s = 2.0 // Full voltage starting torque in terms of full load torque tap = 65.0 // Auto-tranformer tapping(%) // Calculations V_ph = V/3**0.5 // Phase voltage(V) V_ph_motor = tap/100*V_ph // Motor phase voltage when auto-transformer is used(V) I_ph_motor = tap/100*I_s // Motor phase current in terms of full load current I_1 = tap/100*I_ph_motor // Line current from supply in terms of full load current T = (tap/100)**2*T_s // Starting torque in terms of full load current V_applied = V_ph/2**0.5 // Voltage to be applied to develop full-load torque(V) I_line = V_applied/V_ph*I_s // Line current in terms of full load current // Results disp("PART IV - EXAMPLE : 1.5 : SOLUTION :-") printf("\nCase(i): Motor current per phase = %.2f*I_fl ", I_ph_motor) printf("\nCase(ii): Current from the supply, I_1 = %.2f*I_fl ", I_1) printf("\nCase(iii): Starting torque with auto-transformer starter, T = %.3f*T_fl ", T) printf("\nVoltage to be applied if motor has to develop full-load torque at starting, V = %.f V", V_applied) printf("\nLine current from the supply to develop full-load torque at starting = %.2f*I_fl ", I_line)
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// Conversion to current source and nodal analysis clc; clear; // Nodal Equations // 1.5*Va-0.5*Vb+0*Vc=5 // 0.5*Va-1.5*Vb+0.5*Vc=0 // 0*Va-0.5*Vb+1*Vc=0 Y=[1.5 -0.5 0;0.5 -1.5 0.5; 0 -0.5 1]; // Admittance matrix I=[5;0;0]; V=inv(Y)*I; Va=V(1); Vb=V(2); Vc=V(3); Vab=Va-Vb; disp('V',Va,'Voltage at node A =') disp('V',Vb,'Voltage at node B =') disp('V',Vc,'Voltage at node C =') disp('V',Vab,'The voltage across AB in the circuit =') disp('A',Vab/2,'The current in branch AB in the circuit =')
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//caption:stability_using_Nyquist_criterion //example 12_23_i //page 535 clf(); s=%s; s1=-s; disp("for K=0.1") g=(0.1*(s+10)*(s+40))/(s*(s+1)*(s+4)); g1=(0.1*(s1+10)*(s1+40))/(s1*(s1+1)*(s1+4)); GH=syslin('c',g); GH1=syslin('c',g1); nyquist(GH); nyquist(GH1); //mtlb_axis([-1.5 0.2 -0.3 0.3]); xtitle('Nyquist plot of (0.1*(s+10)*(s+40))/(s*(s+1)*(s+4))') figure; show_margins(GH,'nyquist') disp("since the point(-1+%i0) is not encircled clockwise by Nyquist plot ,so N=0 and P=0") N=0;//no. of encirclement of -1+%i0 by G(s)H(s) plot anticlockwise P=0;//no. of poles of G(s)H(s) with positive real part Z=P-N;//np.of zeros of 1+G(s)H(s)=0 with positive real part disp(Z,"Z=") disp("as Z=0,there are no roots of closed loop characterstics eq having positive real part, hence system is stable.")
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clc //metodo de newton //funcao juros compostor function y = modelo(x) y=0.04+(x)/(1-x)*sqrt(2*3.5/(2+x)); endfunction //funcao principal function x = newton(x0, prec, cont_max) cont=0; x=x0; e=1;//maior erro x_old=x0; while (e>=10^(-prec) & cont<=cont_max) x_antes=x_old; x_old=x; x=x_old - (modelo(x_old)*(x_antes-x_old)/(modelo(x_antes)-modelo(x_old))); e=abs(x-x_old)/x; cont=cont+1; end endfunction //entrada x=newton(0.5, 3, 10)//nao entra com o a entrada da funcao secundaria(derivada e funcao)
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BigVectorArray.parseRecurrence("a(n) +(-2*n+1)*a(n-1) +2*(-n+1)*a(n-2)=0") vname=a_0, k=0, kmax=0, kmin=0, poly=a_0 + a_1 + 2*a_2 - 2*a_1*n - 2*a_2*n vname=a_1, k=-1, kmax=0, kmin=-1, poly=a_0 + a_1 + 2*a_2 - 2*a_1*n - 2*a_2*n vname=a_2, k=-2, kmax=0, kmin=-2, poly=a_0 + a_1 + 2*a_2 - 2*a_1*n - 2*a_2*n shift by 0 create bva[4] bva[3]=1, vector=[1], poly=a_1 + 2*a_2 - 2*a_1*n - 2*a_2*n bva[2]=1 - 2*n, vector=[1,-2], poly=2*a_2 - 2*a_2*n bva[1]=2 - 2*n, vector=[2,-2], poly=0 bva[0]=0 result= [[0],[2,-2],[1,-2],[1]]
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clear clc //This is a theorotical Qn printf("Its a theorotical Question")
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// Example 1-1 in page 8 // Given data clc; phi=500*10^-8;// one maxwell=10^-8 Wb, phi=total flux Area=(2.54*10^-2)^2;// area in m^2, cross section is one inch and 1inch=2.54cm // Calculation B=phi/Area; //flux density(B) in tesla printf("total flux density=%.2f mT",B*1000); // Result // the toatal flux density is 7.75 mT
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//Section-1,Example-2,Page no.-AC.163 //To find the weight of air actually supplied per m^3 of the gas. clc; M_w=28.97 V=300*(100/21)*(150/100) //Volume of air reqd. for 1m^3 of gas using 50% excess air(L) W=V*(1/22.4)*M_w disp(W,'weight of air actually supplied per m^3 of the gas.(gm)')
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//Caption:Design Schmitt circuit components R1,R2,R3,R4 and R5 //Ex6.5 clc; clear; close; u=3//Upper trigger voltage(in volts) Ib=500//Max base current(in nA) Vf=0.7//Forward diode voltage(in volts) Vk1=-2//Voltage(in volts) Vcc=15//Collector voltage(in volts) Vk2=-Vk1 i=Ib*0.1 R2=u*1000/i I=u/R2 Vo=Vcc-1 Vr1=Vo-u R1=Vr1/I I4=100*i Va1=Vk1+Vf Vee=-Vcc V4=Va1-Vee R4=V4*1000/I4 Va2=Vk2+Vf V5=Va2-Va1 R5=V5*1000/I4 R3=(Vcc-Va2)*1000/I4 disp(R5,R4,R3,R2,R1,'R1,R2,R3,R4,R5(in kilo ohm)=')
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//Chapter 2,Ex2.29,Pg 2.33 clc; disp("Refer to the figure shown in the diagram") A=[1 0 0;-1 3 -1;-2 -5 10] B=[60;12;24] V=A\B printf("\n Voltage across the 100 ohms resistor=%.2f V\n",V(3))
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clc;funcprot(0);//EXAMPLE 16.7 // Initialisation of Variables M=56;.........//Molecular Weight of Polyethylene P=0.88;........//Measured density of PolyethyleneInitial P1=0.915;........//Measured density of Polyethylene Final Pa=0.87;........//Density of Amorphous Polyethylene //Caluculations Pc=M/(7.42*4.95*(2.55*10^-24)*6.02*10^23);...........//Density of complete Crystalline polymer Cp1= ((Pc/P)*((P-Pa)/(Pc-Pa)))*100;..................//Crystallinity of Polyethylene initial Cp2= ((Pc/P1)*((P1-Pa)/(Pc-Pa)))*100;................//Crystallinity of Polyethylene final disp(Pc,"Density of Crystalline polymer:") disp(Cp1,"Crystall. of Polyethylene initial:") disp(Cp2,"Crystall. of Polyethylene final:")
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function y = f(x) // Função cuja derivada deseja ser estimada y = exp(x) + sin(x) endfunction // Derivada recuada com dois pontos function D = recuada(x, h) D = (f(x)-f(x-h))/h endfunction function D = avancada(x,h) D = (f(x+h)-f(x))/h endfunction function D = centrada(x,h) D = (f(x+h)-f(x-h))/2*h endfunction function D = derivadaSegunda(x,h) D = (f(x+h)-2*f(x)+f(x-h))/(h^2) endfunction
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a=0.01; b=0.02; N=8124; I0=124; R0=30; S0=N-I0-R0; t=0:0.01:200; x0y0=[S0;I0;R0]; function dxdy=x_der(t,x) dxdy(1)=0; dxdy(2)=-b*x(2); dxdy(3)=b*x(2); endfunction x=ode(x0y0, 0, t, x_der); function dxdy=y_der(t,x) dxdy(1)=-a*x(1); dxdy(2)=a*x(1)-b*x(2); dxdy(3)=b*x(2); endfunction y=ode(x0y0, 0, t, y_der); plot(t,y); h1=legend(['Возможные больные';'Заболели';'Вылечились']);
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//find clc //solution //given D=150//mm R=75//mm d=50//mm r=25//mm p=0.8//N/mm^2 N=100//rpm u=0.015 W=p*%pi*[R^2-r^2]//N printf("load to be supported is,%f N\n",W) T=(2/3)*u*W*[(R^3-r^3)/(R^2-r^2)]//N-mm P=2*%pi*N*T/60000 printf("power loast in friction is,%f W\n",P)
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function egauss(A,b) M=[A b]; [n m]=size(M); j=2; for j=1:n kolom=abs(M(:,j)); [nilai,ind]=max(kolom(j:n)); indeks=ind+j-1; if kolom(j) < nilai then M=tukar(M,indeks,j); end, for i=j+1:n M(i,:)=-M(i,j)/M(j,j)*M(j,:)+M(i,:); end, end nA=M(1:n,1:n); nB=M(:,n+1); solusix=subbalik(nA,nB); disp('Matriks M');disp(M); disp('Solusi X');disp(x); endfunction function hasil=tukar(M,indeks,j) sementara=M(j,:); M(j,:)=M(indeks,:); M(indeks,:)=sementara; hasil=M; endfunction function nilai=subbalik(A,b) [m,n]=size(A); x(n)=b(n)/A(n,n); for k=n-1:-1:1 jum=0; for j=k+1:n jum=jum+A(k,j)*x(j); end, x(k)=(b(k)-jum)/A(k,k); end nilai=x; endfunction
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clc ; clear ; xdel ( winsid () ) ;//xdel(0)//xdel() R=2000; r=200; j=sqrt(-1); C=0.1*10^-6; for i=1:100000 k(i)=log10(i) f=i; w=2*3.1414*f; w1=1/(r*C); pre_emp(i)=(R/r)*20*log10(sqrt(1+(w/w1)^2)) de_emp(i)=-20*log10(sqrt(1+(w/w1)^2)) end subplot(211) plot(k,pre_emp); title("Pre emphasis"); xlabel('log f'); ylabel('Gain (dB)') subplot(212) plot(k,de_emp); title("De emphasis"); xlabel('log f'); ylabel('Gain (dB)')
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//Example9.7 // determine the lock range of the FSK demodulator clc; clear; close; Vcc = 12 ; Fvco = 0.25*Vcc ; f = 200*10^3 ; // KHz // the total time period of VCO t = 1/f ; disp('The total time period of VCO is = '+string(t)+ ' sec '); // In VCO the capacitor charging and discharging time period are equal ,so the total time period of tringular and square wave forms can be written as 2*t ; // the charging or discharging time of capacitor tcap = t/2 ; disp('The charging or discharging time of capacitor is = '+string(tcap)+ ' sec '); // the voltage swing of VCO for 12 V supply Fvco = 0.25*Vcc ; disp('The voltage swing of VCO for 12 V supply is = '+string(Fvco)+ ' V '); // The lock range of PLL //FL = (1/2*%pi*f)*(Fvco/tcap); FL = (3/(2*%pi*f*tcap)); disp('The lock range of PLL FL is = '+string(FL)+ ' Hz '); // the capture range fcap = sqrt(f*FL); disp('The capture range is = '+string(fcap)+ ' Hz ');
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//====================================== // Exercise 1: the surface Ekman layer //====================================== //Author: Jochen Kaempf, 2015 (update) f = gcf(); scf(0); f.figure_size = [400,400]; in = read("uvprof1.dat",-1,3); // read data file nz = 500; z = in(1:nz,1); u = in(1:nz,2); v = in(1:nz,3); time = 0.0; dt = 2.0; x = z; y = z; x(1:nz) = 0; y(1:nz) = 0; for n = 1:125 // animation loop time = n*dt; // predict displacement of virtual floats for i = 1:nz; x(i) = x(i)+dt*u(i); y(i) = y(i)+dt*v(i); end; drawlater; clf(); // draw graph frame plot2d(0,0,-1,"031"," ",[-40,-40,40,40]); ax = gca(); ax.font_size = 3; // draw floats nzz = 100; for i = 1:nz r = (nzz-i+1)/nzz*1.5; r = max(r,0.3); d = r/2; // float size changes with depth xfarc(x(i)-d,y(i)+d,r,r,0,360*64) p1=gce(); //get handle on current entity p1.foreground=0; p1.thickness=1; p1.fill_mode = "on"; p1.line_mode = "on"; end; // draw wind direction xarrows([0 0],[0 40],100,5); p2=gce(); p2.mark_foreground=4; p2.thickness=3; p2.arrow_size=30; // draw flow vectors every 10 m for i = 1:10:91 xarrows([0 x(i)],[0 y(i)],40,2) p3=gce(); p3.mark_foreground=1; p3.thickness=1; p3.arrow_size=20; p3.segs_color = 1 ; end; xgrid(1); // draw grid p4=gce(); p4.mark_foreground=1; p4.thickness=1; xstring(-5, -39,"x (m)"); // draw x label txt=gce(); txt.font_size = 3; xstring(-39, 0,"y (m)"); // draw y label txt=gce(); txt.font_size = 3; title("Time = "+string(int(time))+" secs","fontsize",3); // draw title drawnow; // save frames as sequential GIF files //if n < 10 then // xs2gif(0,'ex100'+string(n)+'.gif') //else // if n < 100 then // xs2gif(0,'ex10'+string(n)+'.gif') // else // xs2gif(0,'ex1'+string(n)+'.gif') // end //end end; // end reference for animation loop
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# A000000 generated by Sequence # Table of n, a(n) for n = 0..9 0 1 1 9 2 3 3 15 4 6 5 78 6 24 7 132 8 51 9 699
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 5: MECHANICAL DESIGN OF OVERHEAD LINES // EXAMPLE : 5.5 : // Page number 199 clear ; clc ; close ; // Clear the work space and console // Given data w_w = 1.781 // Wind pressure on conductor(kg/m) w_i = 1.08 // Weight of ice on conductor(kg/m) D = 6.0 // Maximum permissible sag(m) s = 2.0 // Factor of safety w_c = 0.844 // Weight of conductor(kg/m) u = 7950.0 // Ultimate strength(kg) // Calculations w = ((w_c+w_i)**2+w_w**2)**0.5 // Total force on conductor(kg/m) T = u/s // Allowable maximum tension(kg) l = ((D*2*T)/w)**0.5 // Half span(m) L = 2.0*l // Permissible span between two supports(m) // Results disp("PART II - EXAMPLE : 5.5 : SOLUTION :-") printf("\nPermissible span between two supports = %.f metres \n", L) printf("\nNOTE: ERROR: Horizontal wind load, w_w = 1.781 kg/m, not 1.78 kg/m as mentioned in problem statement")
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function [txt,trad]=m2sci(lst,nam,Imode,Recmode) // translate matlab syntax to scilab //%Parameters // lst : list, represents the interpreted code of the matlab function given by macr2lst // nam : nam of the scilab function to generate // txt : character string column vector: the text of resulting scilab function //! //%Main variables // vnms : nx2 matrix of strings, each row contains the matlab and scilab name of // a refered matlab variable // vtps : a list, each entry is a list(?,?,?,?) // Copyright INRIA [lhs,rhs]=argn(0) if rhs==1 then nam=lst(1),end if rhs<=2 then Imode=%t,end if rhs<=3 then Recmode=%f,end //sci_min=sci_mini //sci_max=sci_maxi lst=mmodlst(lst) lcount=1;level=[0,0]; quote='''' // sciparam() //stack of named variables // add input variable in the defined variables inputs=lst(3) macrhs=size(inputs,2) vnms=[], vtps=list() for k=1:macrhs if or(inputs(k)==killed(1)) then vnms=[vnms;['%'+inputs(k),inputs(k)]], else if funptr(inputs(k))<>0 then vnms=[vnms;['%'+inputs(k),inputs(k)]], inputs(k)='%'+inputs(k), else vnms=[vnms;[inputs(k),inputs(k)]], end end if Imode then r=askfortype(inputs(k)) if r<>[] then vtps($+1)=r else vtps($+1)=list('?','?','?',0) end else vtps($+1)=list('?','?','?',0) end end, // add predefined variable in the defined variables if find(vnms(:,2)=='i')==[] then vnms=[vnms;['%i','i']], vtps($+1)=list('1','1','1',0) end if find(vnms(:,2)=='j')==[] then vnms=[vnms;['%i','j']], vtps($+1)=list('1','1','1',0) end vnms=[vnms;['%nan','NaN']], vtps($+1)=list('1','1','1',0) vnms=[vnms;['%nan','nan']], vtps($+1)=list('1','1','1',0) vnms=[vnms;['%inf','Inf']], vtps($+1)=list('1','1','1',0) vnms=[vnms;['%inf','inf']], vtps($+1)=list('1','1','1',0) if find(vnms(:,2)=='pi')==[] then vnms=[vnms;['%pi','pi']], vtps($+1)=list('1','1','1',0) end if find(vnms(:,2)=='eps')==[] then vnms=[vnms;['%eps','eps']], vtps($+1)=list('1','1','1',0) end outputs=lst(2) maclhs=size(outputs,2) for k=1:maclhs if funptr(outputs(k))<>0 then vnms=[vnms;['%'+outputs(k),outputs(k)]] vtps($+1)=list('?','?','?',0) outputs(k)='%'+outputs(k) end end bot=size(vtps) // translate sciexp=0 [crp,vnms,vtps]=ins2sci(lst,4,vnms,vtps) dcl=[] //add special code // nargin & nargout if find(vnms(:,1)=='nargin'|vnms(:,1)=='nargout') then dcl='[nargout,nargin] = argn(0)' end //Initial value of lhs arguments ini=emptystr() for k=outputs if find(inputs==k)==[] then ini=ini+k+'=[];',end end if ini==emptystr() then ini=[],end //info on macros variables n=size(vtps) info=[] for k=1:n m=string(vtps(k)(2)) n=string(vtps(k)(3)) tp=string(vtps(k)(1)) info=[info; '// '+part(vnms(k,2),1:24)+' size :'+part(m+' x '+n,1:12)+' type: '+tp]; end //write(%io(2),info,'(a)') //add the function header hdr='function '+lhsargs(outputs)+'='+nam+rhsargs(vnms(1:macrhs,1)); txt=[hdr;ini;dcl;crp(1:$-1)] // generate associated translation function //if nam=='script' then // f=fnam+'.sce' // trad=[ // 'function [stk,txt,top]=sci_'+fnam+'()' // 'stk=list(''exec('''+sci2exp(f)+''')'',''0'',''?'',''?'',''?'')'] if batch then trad=[ 'function [stk,txt,top]=sci_'+fnam+'()' 'stk=list(''exec('+fnam+')'',''0'',''?'',''?'',''?'')'] else trad=[ 'function [stk,txt,top]=sci_'+nam+'()' 'RHS=[]' 'for k=1:rhs' ' RHS=[stk(top)(1),RHS]' ' top=top-1' 'end' 'top=top+1'] if maclhs==0 then trad=[trad; 'stk=list('+sci2exp(nam)+'+rhsargs(RHS),''0'',''?'',''?'',''?'')'] elseif maclhs==1 then k1=find(outputs(1)==vnms(:,2)); if k1<>[] then k1=k1(1); w=strcat([sci2exp(vtps(k1)(2)),sci2exp(vtps(k1)(3)),sci2exp(vtps(k1)(1))],',') else w='''?'',''?'',''?''' end trad=[trad; 'stk=list('+sci2exp(nam)+'+rhsargs(RHS),''0'','+w+')'] else w=[] for k=1:maclhs k1=find(outputs(k)==vnms(:,2)); if k1<>[] then k1=k1(1); w=[w;strcat([sci2exp(vtps(k1)(2)),sci2exp(vtps(k1)(3)),sci2exp(vtps(k1)(1))],',') ] ; else w=[w;'''?'',''?'',''?'''] end end w(1)='w=['+w(1);w($)=w($)+']'; trad=[trad; '// w(i,1) is the ith output argument type' '// w(i,2) is the ith output argument row dimension' '// w(i,2) is the ith output argument column dimension' w] // sci2exp(w,'w')] trad=[trad; 'if lhs==1 then' ' stk=list('+sci2exp(nam)+'+rhsargs(RHS),''0'',w(1,1),w(1,2),w(1,3))' 'else' ' stk=list()' ' for k=1:lhs' ' stk(k)=list('+sci2exp(nam)+'+rhsargs(RHS),''-1'',w(k,1),w(k,2),w(k,3))' ' end' 'end'] end end
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errcatch(-1,"stop");mode(2);//Caption:Determine the value of resistance //Exa:2.28 ; ; V=220;//in volts R_a=0.1;//in ohms N_1=800;//in rpm N_2=520;//in rpm I_a1=20;//in ampers E_1=V-(I_a1*R_a);//in volts E_2=N_2*E_1/N_1;//in volts R_A=-(E_2-V+I_a1*R_a)/20; disp(R_A,'Additional resistance(in ohms)='); exit();
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clear;lines(0); W1=ssrand(2,2,5);trzeros(W1) //call trzeros roots(det(systmat(W1))) //roots of det(system matrix) s=poly(0,'s');W=[1/(s+1);1/(s-2)];W2=(s-3)*W*W';[nt,dt,rk]=trzeros(W2); St=systmat(tf2ss(W2));[Q,Z,Qd,Zd,numbeps,numbeta]=kroneck(St); St1=Q*St*Z;rowf=(Qd(1)+Qd(2)+1):(Qd(1)+Qd(2)+Qd(3)); colf=(Zd(1)+Zd(2)+1):(Zd(1)+Zd(2)+Zd(3)); roots(St1(rowf,colf)), nt./dt //By Kronecker form
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#SDL scenario = "GetInput"; pcl_file = "GetInputPCL.pcl"; begin; picture { text {caption = " ";}t_Info1; x=0; y = 100; text {caption = " ";}t_Info2; x=0; y = 0; } p_Info;
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//Chapter-2,Example 2_10,Page 2-34 clc() //Given Data: lam=6*10^-7 //Wavelength of light a=0.02*10^-2 //width of slit (a=d) f=2 //distance between screen and slit //Calculations: //We know, a*sin(theta)=m*lam, here m=1 theta=asin(lam/a)*180*60/%pi //angular position in first minima (1 degree=60 minutes) printf('Total angular width is = %.2f minutes \n \n',2*theta) x=f*lam/a //separation between central maxima and first minima printf(' Linear width is = %.6f m \n',2*x)
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// Scilab code Exa4.5.2: To calculate Q-value for the reaction : Page 183 (2011) M_Cf = 252.081621; // Mass of califronium, amu M_Cm = 248.072343; // Mass of curium, amu M_He = 4.002603; // Mass of alpha particle, amu Q = [M_Cf-M_Cm-M_He]*931.49; // Q-value, MeV printf("\nThe Q-value for the reaction : %4.2f MeV", Q) // Result // The Q-value for the reaction : 6.22 MeV
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A = [ 3 4 6 7 10]; B= [-20 5 15 24]; disp(variance(A), "The sample variance of A is") disp(variance(B), "The sample variance of B is")
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const const1 = 11; type t1 = array 20 of int; var v2 : t1; void sym1 () { const const1 = 33; PRINT SYMBOL TABLE }
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// A program to directly writing and reading a matrix to/from a file. A = rand (4,3); fprintfMat ("MatrixA.txt", A, "%lg"); B = fscanfMat ("MatrixA.txt", "%lg"); disp(B);
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clc; //page 718 //problem 13.15 //Bit interval T = 1/10^6 = 10^-6 sec T = 10^-6 //White Noise Power Spectral Density n/2 = 10^-9 W/Hz n = 2*10^-9 //Power required Ps = Eb/T, where Eb = energy per bit //For information system feedback system Eb = n Ps = n/T disp('power required for information system feedback system is '+string(Ps)+' Watt') //For optimal system Ps = (0.69 * n)/T Ps = (0.69 * n)/T; disp('power required for optimal system is '+string(Ps)+' Watt')
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//Example No. 7.10.3 clc; clear; close; format('v',6); N=25;//no. of turns Vrms=150;//µV(emf induced) f=500;//kHz(tuned frequency) A=0.5^2;//m²(Area of loop) theta=0;//degree(angle) c=3*10^8;//m/s////Speed of light lambda=c/(f*10^3);//m(Wavelength) Erms=lambda/(2*%pi*A*N*cosd(theta))*Vrms*10^-6;//V/m(maximum emf induced) disp(Erms*10^3,"Field strength in mV/m : ");
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// Example 34_31 clc;funcprot(0); //Given data P=2500;// kW MD=1600;// Maximum load in kW F_l=0.48;// Load factor CC_s=15000;// Initial cost of Ic=18000;// Installation cost in Rs./kW I=15/100;// Interest on capital Mc=200000;// Maintainence cost in Rs./year Tlo=850000;// Total labour and other consumables in Rs./year Fc=7;// Fuel cost in Rs./kg Lc=30;// Lubricating oil cost in Rs./kg F=0.25;// Fuel consumed in kg/kWh O=0.025;// Oil consumed in kg/kWh //Calculation CC=P*Ic;// Capital cost of the plant in rupees I=CC*I;// Interest on capital in rupees E_g=MD*F_l*8760;// Energy generated per year in kWh Cf=F*E_g*Fc;// Cost of fuel in Rs./year Cl=O*E_g*Lc;// Cost of Lubricating oil in rupees Tfc=I+Mc;// Total fixed cost in rupees Trc=Cf+Cl+Tlo;// Total running cost in rupees Tc=Tfc+Trc;// Total cost in rupees Gc=Tc/E_g;// Generation cost in Rs./kWh printf('\nThe cost of generation=Rs.%0.2f/kWh',Gc); // The answer provided in the textbook is wrong
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clc; //Exampkle 14.5 //page no 157 printf("Example 14.5 page no 157\n\n"); //air is transported through a circular conduit MW=28.9//molecular weight of air R=10.73//gas constant T=500//temperature P=14.75//pressure,psia //applying ideal gas law for density rho=P*MW/(R*T)//density rho=0.08//after round off meu=3.54e-7//viscosity of air at 40 degF //assume flow is laminar q=8.33//flow rate ,ft^3/s L=800//length of pipe,ft P_1=.1//pressure at starting point P_2=.01//pressure at delivery point D=[(128*meu*L*q)/(%pi*(P_1-P_2)*144)]^(1/4)//diameter printf("\n pipe diameter D=%f ft",D); //check the flow type meu=1.14e-5 R_e1=4*q*rho/(%pi*D*meu)//reynolds no //printf("\n reynolds no R_e=%f ",R_e); //from R_e we can conclude that laminar flow is not valid P_drop=12.96//pressure drop P_1-P2 in psf f=0.005//fanning friction factor g_c=32.174 D=(32*rho*f*L*q^2/(g_c*%pi^2*P_drop))^(0.2)//diamter from new assumption //strat the second iteration with the newly calculated D k=0.00006/12//roughness factor K_r=k/D//relative roughness C_f=1.321224 R_e_n=4*q*rho/(%pi*D*meu)//new reynolds no //printf("\n new reynolds no R_e=%f ",R_e); f_n=0.0045//new fanning friction factor D=[((8*rho*f_n*L*q^2)/(g_c*%pi^2*P_drop))^(0.2)]*C_f//final calculated diameter because last diameter is same with this printf("\nD=%f ",D); //iteration may now be terminated S=%pi*(D^2)/4//cross sectional area of pipe v=q/S//flow velocity printf("\n flow velocity v=%f ft/s",v);//printing mistake in book in the value of meu in the formula of D is first time that's why this deviation in answer
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function A = insertion_sort(A) n = length(A); for(i = 2:n) t = A(i); j = i; while((j > 1) & (A(j-1) > t)) A(j) = A(j-1); j = j-1; end A(j) = t; end endfunction
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// (4.3) Steam enters a converging–diverging nozzle operating at steady state with p1 = 40 bar, T1=  400C, and a velocity of 10 m/s. The steam flows through the nozzle with negligible heat transfer and no significant change in potential energy. At the exit, p2 = 15 bar, and the velocity is 665 m/s. The mass flow rate is 2 kg/s. Determine the exit area of the nozzle, in m2. //solution //variable initialization p1 = 40 //entry pressure in bar T1 = 400 //entry temperature in degree celcius V1 = 10 //entry velocity in m/s P2 = 15 //exit pressure in bar V2 =665 //exit velocity in m/s mdot = 2 //mass flow rate in kg/s //from table A-4 h1 = 3213.6 //specific enthalpy in in kj/kg h2 = h1+((V1^2-V2^2)/2)/1000 //from table A-4 v2 = .1627 //specific volume at the exit in m^3/kg A2 = mdot*v2/V2 printf('the exit area of the nozzle in m^2 is \n\t A2 = %e',A2)
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clc; clear; //----------------- // Question 2 // Part a s = poly(0, 's'); G = 10 / (s* (s+2) * (s+4)); Gs = syslin('c', G); K = 10; Cs = K * Gs /. syslin('c', 1, 1); disp("Transfer function for K = 10"); disp(Cs); disp("=================================================="); // Part b K = 0:0.1:100; scf(); for i=1:size(K, 2) k = K(i); Cs = k * Gs /. syslin('c', 1, 1); [z, p, _p] = tf2zp(Cs); plot(real(p), imag(p), 'b*', 'LineWidth', 2); end xlabel("Real Axis", 'fontsize', 3); ylabel("Imaginary Axis", 'fontsize', 3); title(["Locus of poles of", "$\frac{10K}{10K + 8s + 6s^2 + s^3}$"], "fontsize", 4); xs2png(gcf(), "Q2b.png"); // ------------------------ // Part c K_critical = -1; for i=1:size(K, 2) k = K(i); Cs = k * Gs /. syslin('c', 1, 1); [z, p, _p] = tf2zp(Cs); rp = real(p); if rp(1) > 0 || rp(2) > 0 || rp(3) > 0 K_critical = k; break; end end disp("Estimated Critical Value of K"); disp(K_critical); // ------------------------ // Part d
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// chapter 16 // example 16.16 // What will be the firing angle and output power available // page-1051 clear; clc; // given f=50; // in Hz neta=60; // in % T=0.24; // in s (repition period) // calculate // part (i) can not be solved // since T=0.24 s represents 12 cycles at 50 Hz or T=24 half cycles, therefore T=24; // since Pload/Pmax=N/24, therefore N1=1, N2=24 Pload1=N1/T; Pload2=N2/T; printf("The available power range from %.2f %% of Pmax (N=%.f) to %.f %% of Pmax (N=%.f) varying in steps of %.2f %% of Pmax",Pload1*1E2,N1,Pload2*1E2,N2,Pload1*1E2);
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//Example 2.21://consumer monthly bill ,power factor and average cost per unit clc; clear; close; format('v',9) kwh=125000;// kvarh=100000;// kvah=sqrt(kwh^2+kvarh^2);//kVAh kw=180;// kvar=125;// mkva=sqrt(kw^2+kvar^2);//kVA pkva=15;//rupees pkvah=0.1;//reupees tmb=pkva*mkva+pkvah*kvah;//in Rs disp(tmb,"total monthly bill in Rs") pf=kwh/kvah;//power factor d=30;//days t=24;//hours a day lf=((kwh/(d*t))/kw);//load factor avcp=tmb/kwh;//in paisa disp(pf,"power factor is") disp(lf,"load factor is") disp(avcp*100,"average cost per unit (kWh) in paisa is") //total monthly bill and load factor is calculated wrong in the book
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//chapter1,Example1_5,pg 482 //with input voltage exceding 2Vd,diodes conduct and the voltage divider circuit with diodes can allow only a Vi given by Vi=2Vd printf("\ninput voltage to amplifier\n") printf("\nVi=2Vd")
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//Example 9.11.refer fig.9.55 clc format(6) VCC=10 RB=470*10^3 RE=3.3*10^3 beta=100 RS=1*10^3 RL=50 re=22.4 VBE=0.7 IB = (VCC-VBE) / (RB + ((1+beta)*RE)) x1=IB*10^6 disp(x1,"From fig.9.55, IB(uA) = (VCC-VBE) / (RB + (1+beta)*RE)") format(5) IE=(1+beta)*IB x2=IE*10^3 disp(x2," IE(mA) = (1+beta)*IB =") rL=(RE*RL)/(RE+RL) disp(rL,"The load resistance of the emitter follower is rL(ohm) = RE || RL =") // answer in textbook is wrong x=(1+beta)*(re+rL) Zi=(RB*x)/(RB+x) x3=Zi*10^-3 disp(x3," Zi(k-ohm) = RB || (1+beta)(re+rL) =") y=(50/(22.4+50))*((7.13*10^3)/((1*10^3)+(7.3*10^3))) // answer in textbook is wrong disp(y," VL / VS = (rL/re+rL)(Zi/Rs+Zi) =")
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//lubricants// //example 3.7.9.A// clc wt_oil=1.55//weight f oil saponified(gms)// blank=20//volume blank titration reading(ml)// back=15//volume back titration reading(ml)// volume=blank-back//volume of alcoholic KOH consumed(ml)// normality_KOH=0.5//normality of KOH // S=volume*normality_KOH*56/wt_oil//formula for saponification value// printf("\nSaponification value of oil is %.2f mgs KOH",S);
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clc clear cd='C:\Users\Álvaro\Google Drive\0 mestrado mecatronica\2017.2\INTRODUÇÃO À IDENTIFICAÇÃO DE SISTEMAS\2 unidade trabalho\Kalman 2D'; FILE='dados_sensor_GPS.txt'; data = read(FILE, -1, 3); total_points = size(data,"r"); t = data(1:total_points,1); x = data(1:total_points,2); y = data(1:total_points,3); tempo = 1 dt= t(tempo)-0; // variacao tempo //erro esperado de sinal do satelite Uk= 6; Ek= 36; /////////MATRIZES DE COVARIANCIA////////// Rk = [0.1 0; 0 0.1]; //covariancia Qk = [0.003 0;0 0.003]; //covariancia PesoR=1; PesoQ=1000; Hk = [cos(32) 0; sin(32) 0]; // modelo de obrservacao Xkant = [0 ; 0]; //X anterior Pkant = [0.1 0;0 0.1]; //P anterior /////////PREDICAO////////// Phi = [1 dt; 0 1]; // modelo de transicao de estados Xk = Phi*Xkant; // X predicao Pk = Phi*Pkant*Phi' + Qk; // predicao covariancia /////////ATUALIZACAO DE DADOS////////// yk = [(([x(tempo),y(tempo)]))']; //coleta dados ykest=[(Hk*Xk)]; // dados estimados erro_estimacao(:,tempo)=yk(:,tempo)-ykest(:,tempo); /////////CORRECAO////////// Kk = Pk*Hk'*inv(Hk*Pk*Hk' + Rk); //ganho de kalman Xkest = Xk + Kk*erro_estimacao; // X correcao Pkest = (eye(2,2) - Kk*Hk)*Pk; // P correcao /////////CALCULO DA VELOCIDADE ESTIMADA////////// Vkest=[Xkest(1,tempo)/dt;Xkest(2,tempo)/dt] // velocidade Vreal=[(yk(1,tempo))/dt;(yk(2,tempo))/dt]; vel=[sqrt(((Vkest(1,tempo)))^2 +(Vkest(2,tempo))^2)]; /////////Atualizacao Vars. Auxs.////////// Pkant=Pkest; Xkant = Xkest(:,tempo); for tempo = 2:total_points dt= t(tempo)- t(tempo-1); // variacao tempo /////////PREDICAO////////// Phi = [1 dt; 0 1]; // atualizacao modelo Xk = Phi*Xkant; // predicao X Pk = Phi*Pkant*Phi' + Qk; // predicao variancia /////////ATUALIZACAO DE DADOS////////// yk = [yk, ([x(tempo),y(tempo)])'];//coleta dados ykest=[ykest, (Hk*Xk)]; erro_estimacao=[erro_estimacao,yk(:,tempo)-ykest(:,tempo)]; /////////CORRECAO////////// Kk = Pk*Hk'*inv(Hk*Pk*Hk' + Rk); // ganho de kalman Xkest = [Xkest ,Xk + Kk*erro_estimacao(:,tempo)]; // correcao X Pkest= (eye(2,2) - Kk*Hk)*Pk; //(eye(2,2) - Kk*Hk)*Pk; /////////Atualizacao Vars. Auxs.////////// Pkant=Pkest; Xkant = Xkest(:,tempo); /////////CALCULO DA VELOCIDADE ESTIMADA////////// Vkest=[Vkest, [(Xkest(1,tempo)-Xkest(1,tempo-1))/dt;(Xkest(2,tempo)-Xkest(2,tempo-1))/dt]]; Vreal=[Vreal, [(yk(1,tempo)-yk(1,tempo-1))/dt;(yk(2,tempo)-yk(2,tempo-1))/dt]]; vel=[vel, sqrt(((Vkest(1,tempo)))^2 +(Vkest(2,tempo))^2)]; /////////MATRIZES DE COVARIANCIA////////// Qk = [(variance(Vkest(1,:)-Vreal(1,:))) 0; 0 (variance(Vkest(2,:)-Vreal(2,:)))]/PesoQ; Rk = [(variance(erro_estimacao(1,:))) 0; 0 (variance(erro_estimacao(2,:)))]/PesoR; end ////Primeira janela//// figure(1) f=get("current_figure") ; f.figure_size=[1000,800]; subplot(311) title('Longitude X'); plot(x,'r'); set(gca(),"auto_clear","off") plot(ykest(1,:),'g'); set(gca(),"auto_clear","on") hl=legend(['Longitude';'Longitude Calculada'],[-4]); subplot(312) title('Latitude Y'); plot(y,'r'); set(gca(),"auto_clear","off") plot(ykest(2,:),'g'); set(gca(),"auto_clear","on") h2=legend(['Latitude';'Latitude Calculada'],[-4]); subplot(313) title('Erro de estimação'); plot(erro_estimacao(1,:),'g') set(gca(),"auto_clear","off") plot(erro_estimacao(2,:),'r') set(gca(),"auto_clear","on") h3=legend(['Erro Longitude';'Erro Latitude'],[-4]); ////Segunda janela//// figure(2) f2=get("current_figure") ; f2.figure_size=[1000,800]; subplot(211) title('Latitude x Longitude'); plot(ykest(1,:),ykest(2,:), 'b'); plot(x,y, 'r'); h1=legend(['Kalman';'Real'],[-4]); subplot(212) title('Velocidade estimada'); plot(vel, 'g'); h2=legend(['m/s'],[-4]);
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x=[1321, 246544, 312134] y=[1320, 246545, 312100] disp(norm(x-y, 1)) disp(norm(x-y, 2)) disp(norm(x-y, %inf))
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//(14.6) Carbon monoxide at 25C, 1 atm enters a well-insulated reactor and reacts with the theoretical amount of air entering at the same temperature and pressure. An equilibrium mixture of CO2, CO, O2, and N2 exits the reactor at a pressure of 1 atm. For steady-state operation and negligible effects of kinetic and potential energy, determine the composition and temperature of the exiting mixture in K. //solution //The overall reaction is //CO + .5O2 + 1.88N2 -------> zCO + (z/2)O2 + (1-z)CO2 + 1.88N2 p =1 //in atm pref = 1 //in atm //solving equations K = (z/(1-z))*(z/(5.76+z))^.5 and z*deltahbarCO + (z/2)*deltahbarO2 + (1-z)*deltahbarCO2 + 1.88deltahbarN2 + (1-z)*[hfbarCO2-hfbarCO]= 0 z = .125 T = 2399 //in kelvin printf('the temperature of the exiting mixture in kelvin is: %f',T) printf('\ncomposition of the equilibrium mixture, in kmol per kmol of CO entering the reactor, is then 0.125CO, 0.0625O2, 0.875CO2, 1.88N2.')
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 1.5 //6*6 matrix in which aij is given by //(1) least common multiple of i and j A=[1 2 3 4 5 6;2 2 6 4 10 6;3 6 3 12 15 6;4 4 12 4 20 12;5 10 15 20 5 30;6 6 6 12 30 6]; mprintf('6*6 matrix in which aij is given by ') mprintf('\n(1) least common multiple of i and j') disp(A) //(2) greatest common divisor of i and j B=[1 1 1 1 1 1;1 2 1 2 1 2;1 1 3 1 1 3;1 2 1 4 1 2;1 1 1 1 5 1;1 2 3 2 1 6]; mprintf('\n(2) greatest common divisor of i and j') disp(B)
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_logo.sci"); createvar(menu); JoystickUseForNavigation(false); function startup() { sf=T_scene_create; sf=root.SC.Universe; sss=T_getscene; myviewport=T_getviewport; myviewport.CameraPos=point(0,0,1); myviewport.CameraDir=vector(0,0,-1); myviewport.FocalDistance=1; myviewport.NearClipPlane=0.1; myviewport.FarClipPlane=20; screensizey=2*tan(myviewport.aperture/2); screensizex=screensizey*myviewport.aspectratio; logoframe=sf.addsubframe("Logoframe"); logoframe.transf.translate(vector(0.2*screensizex,-0.3*screensizey,0)); logoframe.transf.scale(0.06); logoframe.transf.rotate(vector(0,1,0),deg2rad(-45)); createlogo(logoframe); menu=T_createmenu; root.SC.Universe.MenuFrame.color=color(0.75,0.75,0.75); root.SC.Universe.MenuFrame.BlendType=BlendTransparent; root.mousedampingfactor=0.25; root.SC.Universe.MenuFrame.EnabeMouseArrow(point(0.5,0.5),point(0,0),point(1,0.995),0.03); root.framerate=60; myviewport.EnableUserStop=false; root.showcontrols=true; menu.sizex=0.3; menu.Color=color(1,1,1,1); dirstack=list; dirstack.add(ScriptDir); while dirstack.size>0 do { curdir=dirstack(dirstack.size-1);dirstack.del(dirstack.size-1); curparent=curdir; if curparent==ScriptDir then curparent=""; if FileIsPresent(curdir+"\menu.txt") then { content=readtextfile(curdir+"\menu.txt"); while content!="" do { line=content.split("~n"); id=line.split(";"); name=line;if name=="" then name=id; found=false; if id=="-" then { menu.add(curparent,"-"); found=true; } if FileIsPresent(curdir+"\"+id+".SCI") then { menu.add(curparent,Translate(name),curdir+"\"+id+".SCI"); found=true; } if not(found) and ID.Length>0 then { if FileIsPresent(curdir+"\"+id+"\menu.txt") then { dirstack.add(curdir+"\"+id); menu.add(curparent,Translate(name),curdir+"\"+id); } } } } if false then { dirlist=GetFileList(curdir+"\*.*",true); foreach dir in dirlist do if (dir!=".") and (dir!="..") and (dir(0)!="_") then { dirstack.add(curdir+"\"+dir); name=dir; if name.find("_")>=0 then name.split("_"); menu.add(curparent,Translate(name),curdir+"\"+dir); } filelist=GetFileList(curdir+"\*.SCI",false); foreach file in filelist do { if file(0)!="_" then { name=file;name=name.split("."); if name.find("_")>=0 then name.split("_"); menu.add(curparent,Translate(name),curdir+"\"+file); } } } } } startup; while true do { if menu.WasModified then { st=menu.SelectID; menu.visible=false; root.Viewports.main.FadeColor=Color(0,0,0,1); render; if FileIsPresent(st) then { # try { ExecuteScript(st,""); # } } startup; menu.SelectID=st; output(st); } render; }
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//Example 5.23 clc;clear;close; format('v',7); Z=1.5+%i*2.5;//ohm V=11;//kV P=20;//MW pf=0.8;//power factor theta=acosd(pf); I=P*1000/sqrt(3)/V/pf;// I=I*expm(%i*-theta*%pi/180);//A Vdrop=I*Z;//V Vboost=Vdrop;//V disp(Vboost,"Voltage boost needed at station A(V)");
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//Example 8.40 clc disp("Excitation table") disp("Present State Next State Flip-flop Inputs") disp(" QC QB A+ B+ J_A K_A J_B K_B") disp(" 0 0 1 1 1 X 1 X") disp(" 0 1 0 0 0 X X 1") disp(" 1 0 0 1 X 1 1 X") disp(" 1 1 1 0 X 0 X 1") disp("") disp("K-map Simplification") disp(" For J_A") disp(" B'' B") disp("A'' 1 0") disp("A X X") disp("J_A = B''") disp("") disp(" For K_A") disp(" B'' B") disp("A'' X X") disp("A 1 0") disp("K_A = B''") disp("") disp(" For J_B") disp(" B'' B") disp("A'' 1 X") disp("A 1 X") disp("J_B = 1") disp("") disp(" For K_B") disp(" B'' B") disp("A'' X 1") disp("A X 1") disp("K_B = 1") disp("")
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figure; plot2d3(x1) a=gca() ;//get the current axes a.box="on"; a.data_bounds=[0,0;720,26]; const=m1*ones(1,720); plot(const) figure; plot2d3(x2) a=gca() ;//get the current axes a.box="on"; a.data_bounds=[0,0;720,26]; const=m2*ones(1,720); plot(const)
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3_2_Chip_Operating_Temperature.sce
clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 3.2 Page 107 \n'); //Example 3.2 // Chip Operating Temperature Tf = 25+273; //[K] - Temperature of Fluid Flow L=.008; //[m] - Thickness of Aluminium k=239; // [W/m.K] Effective Thermal Conductivity of Aluminium Rc=.9*10^-4; //[K.m^2/W] Maximum permeasible Resistane of Epoxy Joint q=10^4; //[W/m^2] Heat dissipated by Chip h=100; //[W/m^2.k] - Thermal Convectivity from chip to air //Temperature of Chip //q=(Tc-Tf)/(1/h)+(Tc-Tf)/(Rc+(L/k)+(1/h)) Tc = Tf + q*(h+1/(Rc+(L/k)+(1/h)))^-1; printf("\n\n Temperature of Chip = %.2f degC",Tc-273); printf("\n Chip will Work well below its maximum allowable Temperature ie 85 degC") //END
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//Variable declaration: k = 0.022 //Thermal conductivity of glass wool (Btu/h.ft. F) T1 = 400 //Inside wall temperature ( F) T2 = 25 //Outside wall temperature ( C) L = 3/12 //Length of insulation cover (ft) //Calculation: T_2 = T2*(9/5)+32 //Outside wall temperature in fahrenheit scale ( F) QbyA = k*(T1-T_2)/L //Heat flux across the wall (Btu/h.ft^2) //Result: printf("The heat flux across the wall is : %.1f Btu/h.ft^2 .",QbyA)
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//Chapter 13 //Example 13_28 //Page 343 clear;clc; v1=250; v2=250; l1=35; l2=20; r1=v1^2/l1/1000; r2=v2^2/l2/1000; I=(v1+v2)/(r1+r2); V1=I*r1; V2=I*r2; printf("Resistance of load on the +ve side = %.3f ohm \n\n", r1); printf("Resistance of load on the -ve side = %.3f ohm \n\n", r2); printf("Circuit current = %.2f A \n\n", I); printf("Voltage across +ve outer and middle wire = %.1f V \n\n", V1); printf("Voltage across -ve outer and middle wire = %.1f V \n\n", V2);
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clear clc XA=0.35; FAo=2000;//mol/hr eA=3;k=96; CAo=0.1; W=((1+eA)*log(1/(1-XA))-eA*XA)*(FAo/(k*CAo)); printf("\n The amount of catalyst(kg) needed in a packed bed reactor is %f",W)
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; @Harness: disassembler ; @Result: PASS section .text size=0x0000000e vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x00000042 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x78 0x94 sei 0x2: 0x08 0x94 sec 0x4: 0x38 0x94 sev 0x6: 0x18 0x94 sez 0x8: 0x68 0x94 set 0xa: 0x58 0x94 seh 0xc: 0x28 0x94 sen start .data:
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clc; p1=1; // Pressure of air at inlet of compressor in bar T1=30; // Temperature of air at inlet of compressor in degree celcius p2=12; // Delivery pressure of air in bar T2=400; // Temperature of air at inlet of compressor in degree celcius V2=90; // Velocity of air at exit in m/s w=3740; // Power input to compressor in kW k=1.4; // Index of reversible adiabatic process Cpo=1.0035; // Specific heat at constant pressure in kJ/kg K wa=Cpo*(T2-T1)+V2^2/2000; // Actual specific work input m=w/wa; // Mass flow rate of air T2s=(T1+273)*(p2/p1)^((k-1)/k);// Isentropic discharge temperature ws=Cpo*(T2s-(T1+273))+V2^2/2000; // Isentropic work eff_com=ws/wa; // Isentrpic efficiency disp ("%",eff_com*100,"Isentrpic efficiency of compressor =","K",T2s,"Isentropic discharge temperature = ");
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// exa 8.2 Pg 228 clc;clear;close; // Given Data Fmin=60;// N Fmax=140;// N d=3;// mm Dm=18;// mm Sut=1430;// MPa C=Dm/d;// spring index Kw=(4*C-1)/(4*C-4)+0.615/C;// Wahl's correction factor Ks=1+0.5/C;// Shear Stress factor Fm=(Fmax+Fmin)/2;// N Fa=(Fmax-Fmin)/2;// N tau_m=Ks*(8*Fm*C)/(%pi*d**2);// MPa tau_a=Kw*(8*Fa*C)/(%pi*d**2);// MPa Ses_dash=0.22*Sut;// MPa Sys=0.45*Sut;// MPa //tau_m/Sys+tua_a/Ses_dash*(2-Ses_dash/Sys)=1/n n=1/(tau_m/Sys+tau_a/Ses_dash*(2-Ses_dash/Sys));// factor of safety printf('\n factor of safety = %.2f',n)
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Ex2_9.sce
//Example 2_9 clc(); clear; //To calculate the resolving power and grating element sintheta1=0.3 sintheta2=0.2 lamda=5000 //units in A e=(lamda/(sintheta1-sintheta2))*10^-8 //units in cm width=2.5 //units in cm n=width/e //units in cm resolvingpower=2*n printf("Grating element is e=%.5f cm\n",e) printf("Resolving power=%d",resolvingpower)
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tst-scheddownasup_service.tst
description = count scheduled service downtime as uptime logfile = scheddownasup_service.log global_vars { include_soft_states = 0 } scheduled service downtime as uptime { start_time = 1202684400 end_time = 1202770800 host_name = testhost service_description = PING scheduled_downtime_as_uptime = 1 correct { TIME_OK_SCHEDULED = 3600 TIME_OK_UNSCHEDULED = 75600 TIME_WARNING_SCHEDULED = 0 TIME_WARNING_UNSCHEDULED = 7200 } } host in scheduled downtime, service as uptime { start_time = 1202684400 end_time = 1202770800 host_name = testhost2 service_description = PING scheduled_downtime_as_uptime = 1 correct { TIME_OK_SCHEDULED = 3600 TIME_OK_UNSCHEDULED = 75600 TIME_WARNING_SCHEDULED = 0 TIME_WARNING_UNSCHEDULED = 7200 } } host in scheduled downtime, service as uptime, 2 services { start_time = 1202684400 end_time = 1202770800 host_name = testhost2 service_description { testhost;PING testhost2;PING } scheduled_downtime_as_uptime = 1 correct { TIME_OK_SCHEDULED = 3600 TIME_OK_UNSCHEDULED = 75600 TIME_WARNING_SCHEDULED = 0 TIME_WARNING_UNSCHEDULED = 7200 } }
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//Chapter 23,Ex 2.23,Pg2.29 clc; disp("Refer to the diagram given in the question") A=[4 -2;-2 3] B=[5;4] V=A\B printf("\n Va=%.2f V\n",V(1)) printf("\n Vb=%.2f V\n",V(2))
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questao2.sce
function y=v(r) y = 3.*(1 - r./4).^(1./7) endfunction function y=Q(r) vr = 3.*(1 - r./4).^(1./7) y = 2.*(%pi).*r.*vr endfunction a = 0 b = 4 //h = (b-a)./m h = 0.025 x1 = a x2 = x1 + h x3 = b //R = (h./3).*(Q(x1) + 4.*Q(x2) + Q(x3)) R = h.*(Q(a) + 4.*Q((a+b)./2) + Q(b)) disp(R)
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// Example 4.23.a;//TOTAL RMS Pulse broadning clc; clear; close; M=250;//dispersion parametr picosecond per nano meter per kilometer Sa=50;//spectral width in nm NA=0.3;//nUMERICAL aPERTURE n1=1.45;// Core refractibve index C=2.998*10^8;//Speed of light in m/s L=1;//length in Km Sm=M*L*Sa*10^-3;//rms pulse broadning due to material dispersion Ss=(L*10^3*NA^2)/(4*sqrt(3)*C*n1)*10^9;//Pulse broadning due to intermodal dispersion in ns/Km St=sqrt(Sm^2+Ss^2);// Total broadning disp(Ss,Sm,St,"Total broadning ns per Km is")
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P10_angular_displacement_of_flywheel.sce
clc //Example 7.10 //Angular displacement of flywheel //------------------------------------------------------------------------------ //Given data //Moment of Inertia J=0.125 //kg-m^2 //Torsional stiffness Kt=1.176 // N-m/rad //Torque To=0.6 //N-m //frequency w=4 //rad/s //Damping couple Ct=0.4 //N-m res10=mopen(TMPDIR+'10_angular_displacement_of_flywheel.txt','wt') mfprintf(res10,'(a) Torsional amplitude of vibration is given by:\n') mfprintf(res10,'\ttheta=To/sqrt((Kt-Jw2)^2+(Ct*w^2)^2)\n\n') //Torsional amplitude: theta=To/sqrt((Kt-(J* w^2))^2 + (Ct* w)^2 ) mfprintf(res10,'\ttheta=%0.4f rad\n\n',theta) //Maximum Damping couple Cmax=Ct*w*theta mfprintf(res10,'(b) Maximum damping couple= Ct*w*theta = %0.4f N-m\n\n',Cmax) mfprintf(res10,'(c)Phase angle phi =\n\ttan(phi)=(Ct*w)/(Kt-J*w^2)\n') //Phase angle phi=atand((Ct*w)/(Kt- J* w^2)) mfprintf(res10,'phi=%0.3f degrees',180+phi) //Adding 180 to make it positive angle mclose(res10) editor(TMPDIR+'10_angular_displacement_of_flywheel.txt') //------------------------------------------------------------------------------ //-----------------------------End of program-----------------------------------
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clc; //Example 24.3 //Page No 988 disp("Given: Noise bandwidth is 10MHz"); //solution f=10*10^6; disp("Substituting in equation 24-16 yields, "); N=-174+(10*log10(f)); disp('dBm',N,"N = "); disp("If the minimum C/N requirement for a receiver "); Cmin=24+N; disp('dBm',Cmin,"N = "); disp("For a system gain of 113.35dB, it would require a minimum transmit carrier power(Pt) of ") Pt=113.35+Cmin; disp('dBm',Pt,"N = ");
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clc fc = 55000 // fixed cost in Rs vc = 45 // variable cost per piece in Rs sp = 100 // selling price per piece in Rs p = (vc/sp)*100 // percentage of variable cost to pm = 100 - p // profit margin bep = ((55000/55)*100)/100 // Break even point printf("\n Break even point = %d pieces" , bep)
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SxP_InteViewer_v1.51.sce
// ====================== S-params Converter ==================== // // (Semi)Intelligent Differential S-param Viewer // // (c)2014 L. Rayzman // // // // // GUI interface based on UICONTROL2 GUI demo // // Created : 02/25/2014 // Last Update : 03/18/2014 - Added user interaction in case can't guess // port mapping // 06/23/2014 - Updates against 5.5.0 // - Broke the code structure into multiple files // for ease of management // - Removed unwrapping since it has been // natively introduced into 5.5.0 // - Renamed port mapping modes // odd -> odd/even // even -> sequential // 07/18/2014 - Corrected issue with plot of miniscule // values // Corrected issue of plotting in impedance=50ohm // after plotting renormilized to another impedance // // // TODO: Debug group-delay calculation to deal with phase discontinuities // resulting in large GD steps // ==================================================================== // ==================================================================== clear; stacksize(200*1024*1024); exec("SxP_InteViewer_Utilities_v1.01.sci"); // Supporting functions/includes /////////////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////////////// global SxPversion; SxPversion=1.51; //Main code verision SxPExecName="SxP_InteViewer_v1.51.sce"; // Top level script file name // // THINGS FOR FILES // global frefsparam; frefsparam = emptystr(); // Filename of inputfile global spreffreqs; spreffreqs=[]; // Inputfile frequency points vector sprefdata=[]; // Inputfile S-param matrix data // // THINGS FOR SPARAM DATA // global spdata; spdata=[]; // Converted s-param matrix data global numofports; global numofreqs; numofports=0; // Number of ports numofreqs=0; // Number of frequencies entries_choice=emptystr(); // Text matrix that describes available entries to view entry_idx=0; // // // THINGS FOR PROCESSING/DISP OF SPARAM DATA // global smapmode; smapmode=0; // SxP mapping mode // 0 ==> Unable to guess/unknown // // 1 ==> 1-------- 2 (Odd/Even Mapping) // 3-------- 4 // // // 2 ==> 1 ------- n/2+1 (Sequential Mapping) // 2 ------- n/2+2 (Canonical form for mode conversion) smixmode=0; // Output matrix mode // 1 => SDD // 2 => SDC // 3 => SCD // 4 => SCC bDetIl=%t; // Insertion loss detection flag /////////////////////////////////////////////////////////////////////////////// // THINGS FOR GUI/PLOTS gui_frame_w = 300; // Frame width gui_frame_h = 500; // Frame height gui_margin_x = 15; // Horizontal margin between each element gui_margin_y = 15; // Vertical margin between each element gui_padding_x = 10; // Horizontal padding between each element gui_padding_y = 10; // Vertical padding between each element gui_button_w = 100; // Button width gui_button_h = 30; // Button height gui_defaultfont = "arial"; // Default font gui_subframe_font_size = 12; // Title font size (rotation angle, colormap,...) gui_text_font_size = 11; // Text font size global diff_mode_fig; // Diff mode selector GUI ID global diff_mode_fig_idx; global diff_mode_fig_handles; diff_mode_fig_handles.dummy = 0; diff_mode_fig_idx=0; global main_GUI_fig; // Main GUI ID global main_GUI_fig_idx; global main_GUI_handles; main_GUI_handles.dummy = 0; main_GUI_fig_idx=1; global plot_fig; // Plot Figure ID global plot_fig_idx; plot_fig_idx = 2; /////////////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////////////// /////////////////// // Get Scilab Version /////////////////// version_str=getversion(); version_str=tokens(version_str,'-'); version_str=tokens(version_str(2),'.'); version(1)=msscanf(version_str(1), '%d'); version(2)=msscanf(version_str(2), '%d'); if (version(1)<5) then error("Invalid Scilab version. Version 5.5 or greater is required"); if getscilabmode()=="NW" then sleep(2000); quit; end; elseif (version(2) < 5) then error("Invalid Scilab version. Version 5.5 or greater is required"); if getscilabmode()=="NW" then sleep(2000); quit; end; end /////////////////// // Setup files/directories // Read touchstone files // Get user input /////////////////// // // Read input file // // frefsparam=uigetfile("*.s*p", "", "Please choose S-parameters file"); if frefsparam==emptystr() then messagebox("Invalid source file selection. Script aborted", "","error","Abort"); if getscilabmode()=="NW" then sleep(2000); quit; else abort end; end disp(strcat(["Info: Begin loading touchstone file " frefsparam])); [spreffreqs,sprefdata] =sptlbx_readtchstn(frefsparam); disp("Info: Finished loading touchstone file"); numofports=size(sprefdata,1); //Find number of ports if numofports < 4 then messagebox("Only 4-port or larger S-parameters are allowed. Script aborted", "","error","Abort"); if getscilabmode()=="NW" then sleep(2000); quit; else abort end; end if modulo(numofports,2) <> 0 then messagebox("Only even port-count S-parameters are allowed. Script aborted", "","error","Abort"); if getscilabmode()=="NW" then sleep(2000); quit; else abort end; end if modulo(numofports,4) <> 0 then messagebox("Only even number of mixed-mode ports are currently allowed. Script aborted", "","error","Abort"); if getscilabmode()=="NW" then sleep(2000); quit; else abort end; end numofreqs=size(sprefdata,3); //Find number of frequency points /////////////////// // Estimate the port mapping /////////////////// // // Check Odd/Even mapping // // TempM=[]; for i = 1:numofports/2 // Copy to a temp for k=1:numofreqs TempM(k)=sprefdata(2*i-1, 2*i,k); end // Check the criteria // Take derivative and Check that average slope value is positive if (abs(TempM(1)) < 0.9) then bDetIl = %f; break; end end TempM=[]; // // If not odd/even mapping, check seq // // if ~bDetIl then bDetIl=%t; for i = 1:numofports/2 // Copy to a temp for k=1:numofreqs TempM(k)=sprefdata(i,i+numofports/2,k); end // Check the criteria // Take derivative and Check that average slope value is positive if (abs(TempM(1)) < 0.9) then bDetIl = %f; break; end end if bDetIl then smapmode=2; // If got to here, then it is sequential mapping end else smapmode=1; // If found all alreday, then it was odd/even mapping end clear TempM; // // Report Mapping // // if smapmode==0 then // Ask user to select mode // exec("SxP_InteViewer_DiffModeSelGUI_v1.sci", 2); // <==== FANCY VERSION DIDN'T WORK smapmode=x_choices('',list(list('Port map mode:',1,['Odd/Even','Sequential']))); end if smapmode==1 then disp("Info: Odd/Even differential port mapping found") disp("Info: Applying port remapping") elseif smapmode==2 then disp("Info: Sequential differential port mapping found") else messagebox("Unable to determine differential port mapping. Script aborted", "","error","Abort"); if getscilabmode()=="NW" then sleep(2000); quit; else abort end; end ///////////////////////////// // // Perform port remapping // as necessary // ///////////////////////////// spdata=zeros(numofports,numofports, numofreqs); if smapmode==1 then R=zeros(numofports,numofports); k=zeros(1,numofports); // Create row permuation matrix and index vector R(1,1)=1; R(numofports,numofports)=1; k(1)=1; k(numofports)=numofports; for i=2:numofports-1 if i<= numofports/2 then //lower ports -> odd R(i,2*i-1)=1; else //upper ports -> even R(i,(i-numofports/2)*2)=1; end k(i)=modulo(i-1,2)*(numofports/2)+ceil(i/2); end for i=1:numofreqs // Set port order to sequential mapping (canonincal) form // First port spdata(:,1,i)=R*sprefdata(:,1,i); // Second through second to last port for j=2:numofports-1 // Apply row permutation matrix on original column // and put into new column spdata(:,k(j),i)=R*sprefdata(:,j,i); end // Last port spdata(:,numofports,i)=R*sprefdata(:,numofports,i); end sprefdata = spdata; clear R; clear k; end ///////////////////////////// // // Perform Mode conversion // ///////////////////////////// disp("Info: Performing mode conversion") spdata=SE2MM_CONV(sprefdata); clear sprefdata; /////////////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////////////// ///////////////////////////// // // Evoke GUI controls // ///////////////////////////// exec("SxP_InteViewer_MainGUI_v1.1.sci"); sleep(100); show_window(main_GUI_fig_idx); /////////////////////////////////////////////////////////////////////////////// ///////////////////////////////////////////////////////////////////////////////
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//Network Theorem 1 //page no-3.47 //example3.41 //calculation of Vth disp("Removing the variable resistor RL from the network:"); disp("I2-I1=4");....//equation 1 disp("Applying KVL at the outerpath:"); disp("-6*I1-5*I2=2");....//equation 2 A=[-1 1;-6 -5]; B=[4 2]' X=inv(A)*B; disp(X); disp("I1 = -2 A"); disp("I2 = 2 A"); disp("Writing Vth equation,"); a=-2; v=8-a; printf("\nVth = %.f V",v); //calculation of Rth disp("replacing the voltage source with short circuit and current source by an open circuit "); x=(v*1)/(v+1); printf("\nRth = %.2f Ohm",x); //calculation of RL disp("For maximum power transfer"); printf("\nRth = RL =%.2f Ohm",x); //calculation of Pmax m=(v^2)/(4*x); printf("\nPmax = %.2f W",m);
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hystdiff_c.sci
function block=hystdiff_c(block,flag) if flag==1 in_out_num = block.ipar(1); //Vectorized row_vec_io = 1:in_out_num; // Row vector for input & output block.outptr(1)(row_vec_io)=block.x(row_vec_io); //Output elseif flag==0 //variables and ODE block.xd(row_vec_io)= block.inptr(1)(row_vec_io) end endfunction
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Example_5_4.sce
//Diffusion Coefficient Determination clear; clc; printf("\tExample 5.4\n"); T=550+273; //in K D0=1.2*10^-4; //Temperature independent preexponential in m^2/s Qd=131000; //Activation energy in J/mol-K R=8.31; //Universal Gas constt D=D0*exp(-Qd/(R*T)); printf("\nDiffusion coefficient is %.1f * 10^-13 m^2/s\n",D/10^-13); //End
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Example43_3.sce
// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 5: ELECTRIC TRACTION-SPEED TIME CURVES AND MECHANICS OF TRAIN MOVEMENT // EXAMPLE : 5.3 : // Page number 778-779 clear ; clc ; close ; // Clear the work space and console // Given data speed = 25.0 // Scheduled speed(kmph) D = 800.0/1000 // Distance between 2 stations(km) t = 20.0 // Time of stop(sec) V_m_per = 20.0 // Maximum speed higher than(%) beta = 3.0 // Retardation(km phps) // Calculations t_total = D*3600/speed // Total time of run including stop(sec) T = t_total-t // Actual time for run(sec) V_a = D/T*3600 // Average speed(kmph) V_m = (100+V_m_per)*V_a/100 // Maximum speed(kmph) alpha = 1/((7200.0*D/V_m**2*((V_m/V_a)-1))-(1/beta)) // Value of acceleration(km phps) // Results disp("PART IV - EXAMPLE : 5.3 : SOLUTION :-") printf("\nRate of acceleration required to operate this service, α = %.2f km phps", alpha)