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Ex1_4.sce
// Ex1_4 Page:12 (2014) clc; clear; c = 3e+08; // Speed of light in vacuum, m/s delta_tau = 2.6e-08; // Mean lifetime of an unstable particle at rest, s d = 20; // Distance travelled by the unstable particle before it decays, m v = poly(0, "v"); // Declare the speed variable v = 1/sqrt(roots(d^2*v - (d/c)^2 - delta_tau^2)); // Speed of the particle in Lab frame from Time Dilation relation, m/s printf("\nThe speed at which the unstable particle 20 m distance before decaying = %3.1e m/s", v); // Result // The speed at which the unstable particle 20 m distance before decaying = 2.8e+08 m/s
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//Example 19.4 d=2.5*10^-2;//Distance between plates (m) E=3*10^6;//Maximum electric field (V/m) V_AB=E*d;//Maximum voltage (V) printf('Maximum voltage = %d kV (approx)',V_AB/1000) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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function [] = kiks_arena_add_mask(xpos,ypos,color,theRadius) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- // TODO: cache downsampled matrixes global("KIKS_ROUND_COLORMASK_CELL","KIKS_ROUND_MASK_CELL","KIKS_ROUND_MASK","KIKS_MMPERPIXEL","KIKS_ARENA_MASK","KIKS_ARENA_COLORMASK"); r = mtlb_a(floor(mtlb_double(theRadius)/mtlb_double(KIKS_MMPERPIXEL))*2,1); if mtlb_logic(r,">",100) then error("Object too large"); end; //eval(sprintf(''global KIKS_ROUND_MASK_%d KIKS_ROUND_MASK_COLOR_%d;if isempty(KIKS_ROUND_MASK_%d), KIKS_ROUND_MASK_%d=kiks_scale(KIKS_ROUND_MASK,r,r);KIKS_ROUND_MASK_COLOR_%d=KIKS_ROUND_MASK_%d*color;end;binary_mask=KIKS_ROUND_MASK_%d;color_mask=KIKS_ROUND_MASK_COLOR_%d;'',r,r,r,r,r,r,r,r)); if isempty(KIKS_ROUND_MASK_CELL(r).entries) then // !! L.14: Unknown function kiks_scale not converted, original calling sequence used KIKS_ROUND_MASK_CELL = cell(); KIKS_ROUND_MASK_CELL(r).entries = kiks_scale(KIKS_ROUND_MASK,r,r); KIKS_ROUND_COLORMASK_CEL = cell(); KIKS_ROUND_COLORMASK_CEL(r).entries = mtlb_double(KIKS_ROUND_MASK_CELL(r).entries)*mtlb_double(color); end; binary_mask = KIKS_ROUND_MASK_CELL(r).entries; color_mask = KIKS_ROUND_COLORMASK_CEL(r).entries; minx = mtlb_s(floor(mtlb_double(xpos)/mtlb_double(KIKS_MMPERPIXEL)),floor(mtlb_double(theRadius)/mtlb_double(KIKS_MMPERPIXEL)));// xpos - object radius miny = mtlb_s(floor(mtlb_double(ypos)/mtlb_double(KIKS_MMPERPIXEL)),floor(mtlb_double(theRadius)/mtlb_double(KIKS_MMPERPIXEL)));// ypos - object radius maxx = mtlb_a(floor(mtlb_double(xpos)/mtlb_double(KIKS_MMPERPIXEL)),floor(mtlb_double(theRadius)/mtlb_double(KIKS_MMPERPIXEL))); maxy = mtlb_a(floor(mtlb_double(ypos)/mtlb_double(KIKS_MMPERPIXEL)),floor(mtlb_double(theRadius)/mtlb_double(KIKS_MMPERPIXEL))); KIKS_ARENA_MASK(mtlb_imp(miny,maxy),mtlb_imp(minx,maxx)) = mtlb_a(mtlb_double(KIKS_ARENA_MASK(mtlb_imp(miny,maxy),mtlb_imp(minx,maxx))),mtlb_double(binary_mask)); KIKS_ARENA_COLORMASK(mtlb_imp(miny,maxy),mtlb_imp(minx,maxx)) = mtlb_a(mtlb_double(KIKS_ARENA_COLORMASK(mtlb_imp(miny,maxy),mtlb_imp(minx,maxx))),mtlb_double(color_mask)); endfunction
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clc; clear all; f = 2.87e3; //Fundalmental frquency in Hz/m r = 2660; // Density in Kg per cubic meters Y = 4*f^2*r;//The Youngs modulus of he quartz cystal disp('N/m^2',Y,'The Youngs modulus of he quartz cystal is ') f1 = 1200e3; // Frequency of vibration in Hertz t = (1/(2*f1))*sqrt(Y/r);//The thickness of the crystal disp('m',t,'The thickness of the crystal is ')
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function bisectionMethod(funExp,x_lower,x_upper) allowedPercentError = 0.0005; //allowed percent error percentError = 100; //percent error x_temp = 0; //temporary storage for x if (x_lower > x_upper) then //if x_lower is greater than x_upper then swap it x_temp = x_upper; x_upper = x_lower; x_lower = x_temp; end x = x_lower; y = x_upper; midpoint = y; if (isValid(funExp,x,y) == 1) then while (1) //loop infinitely until break is found //----------------------- midpoint = y; xAns = evstr(funExp); //check percentError percentError = ((midpoint-x)/midpoint)*100; //calculate percent error if percentError <= allowedPercentError then break; end //------------------------ //if percent error is still not enough get midpoint midpoint = (x+y)/2 x_temp = x; x=midpoint; midpointAns = evstr(funExp); x = x_temp; //------------------------ if xAns == 0 then midpoint = x; break; end if (xAns * midpointAns)<0 then x_upper = midpoint; else x_lower = midpoint; end, x = x_lower; y = x_upper; end disp(midpoint,"Answer"); else disp("No answer."); end endfunction; function [isValid] = isValid(funExp,x_lower,x_upper) x = x_lower; x_lower = evstr(funExp); x = x_upper; x_upper = evstr(funExp); if (x_lower * x_upper) > 0 then isValid = 0; else isValid = 1; end endfunction;
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clear //Given m=9*10**9 r=0.707 q=5*10**-6 //Calculation // E=m*q/r**2 //along AO E2=m*q/r**2 //along BO E3=m*q/r**2 //along OD E11=E+E2 E12=E2+E3 I=(2*E11*r)*10**-4 //Result printf("\n Electric field at the centre of the sphere is %0.2f *10**4 N/C",I)
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clc(); clear; // To calculate mew and n RH=3.66*10^-4; e=1.6*10^-19; rho_n=8.93*10^-3; n=1/(RH*e); mew_e=RH/rho_n; printf("n per m^3 is"); disp(n); printf("mew_e is %f m^2/V",mew_e);
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//7.13 clc; Vm=400*2^0.5/(3^0.5); Vf=3*3^0.5*Vm/%pi; Rf=250; If=Vf/Rf; Kt=1.33; Ia=50; w=2*%pi*1200/60; Vb=Kt*w*If; Ra=0.3; Va=Vb+Ia*Ra; alph_a=acosd(Va/Vf); printf("Firing angle of converter in the armature circuit=%.3f degree",alph_a)
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mcr.sci
function [z,flag]=mcr(y,phi,m,lbd0,psi) //<z,flag>=mcr(y,phi[,m[,lbd0[,psi]]]) // // Resolution MC ou MCR pour l'identification // du model d'un systeme sous forme d'entree-sortie : // // y(n) = phi'(n) . z + e(n) // // Estimation recursive de z minimisant le critere // quadratique d'erreur entre l'entree relle y et son estime. // // y : vecteur reel ou complexe des donnees. // phi : vecteur reel ou complexe des observations. // psi : vecteur reel ou complexe des observations de la // variable instrumentale. // m : denomination entiere de la methode MCR utilisee // = 0 MC ordinaire // = 1 MCR multiplicatif simple. // = 2 MCR a facteur d'oubli constant. // = 3 MCR a facteur d'oubli exponentiel. // lbd0 : initialisation du facteur d'oubli dans l'intervalle ]0,1[. // z : vecteur parametre a estimer z. // flag : test de convergence // = 1 convergence correcte // = 0 convergence forcee (/ au nombre d'echantillons disponibles) //! [o,i]=argn(0); if i < 2 then error(58); end; // // Controle sur le type des entrees // if i >= 1 then if type(y) <> 1 then error(53,1); end; if i >= 2 then if type(phi) <> 1 then error(53,2); end; if i >= 3 then if type(m) <> 1 then error(53,3); end; if i >= 4 then if type(lbd0) <> 1 then error(53,4); end; if i >= 5 then if type(psi) <> 1 then error(53,5); end; end; end; end; end; end; // // Controle sur la validite des entrees // [o,i]=argn(0); y=testvec(y,'l'); select i case 2 then psi=phi; m=0; to=1; case 3 then psi=phi; select m case 0 then to=1; case 1 then to=1; case 2 then lbd0=0.8; to=lbd0; case 3 then lbd0=0.8; to=lbd0; else error(36,3); end; case 4 then psi=phi; to=lbd0; if to <= 0 then error(36,4); end; if to > 1 then error(36,4); end; if m <= 1 then error(36,3); end; if m > 3 then error(36,3); end; case 5 then K=maxi(size(y)); sphi=size(phi); spsi=size(psi); if norm(sphi - spsi) <> 0 then error(89,2); end; if sphi(1,1) <> K then error(5); end; if spsi(1,1) <> K then error(5); end; to=lbd0; if to <= 0 then error(36,4); end; if to > 1 then error(36,4); end; if m = 0 then error(36,3); end; if m > 3 then error(36,3); end; else error(58), end; // // Initialisations // K=maxi(size(y)); tphi=size(phi); dim=tphi(1,2); // if m=0 then mphi=phi' * phi; th=inv(mphi) * (phi' * y'); flag=1; else P1p=1000 * norm(phi) * eye(dim,dim); th1p=0 * ones(dim,1); th =0 * ones(dim,1); dis=1000; mu=1/to; s=1D-10; // flag=1; n=1; z=[]; while dis > s e=y(n) - phi(n,:) * th1p; num=P1p * psi(n,:)'; den=(1/mu) + phi(n,:) * P1p * psi(n,:)'; G=num/den; P= (1/to) * (eye(P1p) - G*phi(n,:)) * P1p; th= th1p + G * e; dis=abs(1 - norm(th1p)/norm(th)); if n = K-1 then dis=0; flag=0; end; th1p=th; P1p=P; if m=3 then to=lbd0 * to + (1-lbd0); mu=1/to; end; n=n+1; // z=<z th>; end; // while end; z=th';
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// example 7.5 // solve the boundary value problem u''=u+x; // u(x=0)=u(0)=0; u(x=1)=u(4)=0; h=1/4; // we know; u''=(u(j-1)-2*u(j)+u(j+1))/h^2; // 1) second order method; x=0:1/4:1; u0=0; u4=0; u1_3 = rand(1,3) u=[u0 u1_3 u4]; // hence; disp('(u(j-1)-2*u(j)+u(j+1))/h^2=u(j)+x(j)') // for j=1,2,3; disp('for j=1 -16*u0+33*u1-16*u2=-.25') disp('for j=2 -16*u1+33*u2-16*u3=-.50') disp('for j=3 -16*u2+33*u3-16*u4=-.75') // hence solving for u1,u2,u3) , u1=-.034885; u2=-.056326; u3=-.050037; disp(x); disp(u); // 2) numerov method; x=0:1/4:1; u0=0; u4=0; u=[u0 u1 u2 u3 u4]; // since according to numerov method we get the following system of equations; disp('(191*u(j-1)-394*u(j)+191*u(j+1)=x(j-1)+10*x(j)+x(j+1)') // for j=1,2,3; disp('for j=1 191*u0-394*u1+191*u2=3') disp('for j=2 191*u1-394*u2+191*u3=6') disp('for j=3 191*u2-394*u3+191*u4=9') // hence solving for u1,u2,u3 , u1=-.034885 u2=-.056326 u3=-.050037 disp(x); disp(u);
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//Chapter 5 //Example 5.2 //Page 103 //example1inpu clear;clc; //Given l = 230 ; //in mi f = 60 ; //in Hz P = 125e6 ; //in W V = 215e3 ; //in V //From Table A.1 and A.2 for 30ft Rook //z = R + i(Xa + Xd) z = 0.1603 + %i * (0.415+0.4127); //From Table A.1 and A.3 for 30ft Rook y = %i * [1e-6 / ( 0.0950 + 0.1008)] //Calculations yl = sqrt(y*z)*l; Z_c = sqrt(z/y); V_r = V / sqrt(3); I_r = P / (sqrt(3)*V); cosh_yl = cosh(real(yl)) * cos(imag(yl)) + %i * sinh(real(yl)) * sin(imag(yl)); sinh_yl = sinh(real(yl)) * cos(imag(yl)) + %i * cosh(real(yl)) * sin(imag(yl)); //Per Unit calculations Base_impedance = V^2 / P; Base_current = P / (sqrt(3)*V); Z_c_pu = Z_c / Base_impedance; V_r_pu = (V / sqrt(3)) / (V / sqrt(3)); I_r_pu = (P / (sqrt(3)*V)) / Base_current; V_s_pu = V_r_pu * cosh_yl + I_r_pu * Z_c_pu * sinh_yl; I_s_pu = I_r_pu * cosh_yl + V_r_pu * sinh_yl / Z_c_pu; Line_voltage = abs(V_s_pu)*V / 1000; Line_current = abs(I_s_pu)*Base_current; printf("\n\n Sending end line voltage = %.1f V \n\n",Line_voltage) printf("\n\n Sending end line current = %.1f A \n\n",Line_current)
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//Example 14-5 clc;clear; // Properties rho_a=1.20;// kg/m^3 rho_w=998;// kg/m^3 n=1750; alpha_1=0; alpha_2=40; r_1=0.04;// m r_2=0.08;// m b_1=0.052;// m b_2=0.023;// m v=0.13;// m^3/s g=9.81// m/s^2 // Calculation V_1n=(v/(2*%pi*r_1*b_1)); V_1t=0;//since alpha_1=0 V_2n=(v/(2*%pi*r_2*b_2)); V_2t=V_2n*tand(40); omega=(2*%pi*n)/60; H=((omega/g)*((r_2*V_2t)-(r_1*V_1t))); H_wc=H*(rho_a/rho_w)*1000;// mm bhp=(rho_a*g*v*H); printf('The required brake horsepower,bhp=%0.1f W\n',bhp);
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// Exa 5.7 clc; clear; close; // Given data f_c = 1;// in kHz f_c = f_c * 10^3;// in Hz C2 = 0.0047;// in µF C2 = C2 * 10^-6;// in F C3 = C2;// in F C = C2;// in F R2 = 1/(2*%pi*f_c*C);// in ohm R2 = R2 * 10^-3;// in k ohm R3= R2;// in kohm // Let R1=30;// in kohm R_F= R1*0.586;// in kohm disp(floor(R2),"The value of R2 and R3 in kΩ is : ") disp(R1,"The value of R1 in kΩ is : ") disp(R_F,"The value of R_F in kΩ is : ") disp("The standard value of R_F is 20 kΩ")
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errcatch(-1,"stop");mode(2);//Chapter 12 //page no 432 //given ; all; Pt1=-18; //in dBm for 50/125 micron fiber Pt2=-10; //in dBm for 100/125 micron fiber Pd=Pt1-Pt2; printf("\n Additional Power = %0.0f dBm",Pd); exit();
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//Gas Stoichiometry clear; clc; printf("\t Example 5.13\n"); R=0.0821;//universal Gas constant, L.atm/K.mol T=312;//temp in K V=2.4*10^5;//volume, L P1=7.9*10^-3;//pressure initial in atm P2=1.2*10^-4;//pressure final in atm Pdrop=P1-P2;//pressure drop, atm n=Pdrop*V/(R*T);//moles of Co2 reacted Li2CO3=73.89;//mol. mass of Li2CO3, g mLi2CO3=n*Li2CO3;//mass of Li2CO3, g printf("\t the mass of Li2CO3 formed is : %4.1f *10^3 g\n",mLi2CO3*10^-3); //End
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/* Mohamad Fahrio Ghanial Fatihah 140810190005 */ function jacoby() clear; clc; printf('\nProgram Penyelesaian SPL dengan Metode Iterasi Jacoby\n') printf('Ubah SPL menjadi matriks [A][X]=[H]\n') printf('Masukkan SPL dalam bentuk matriks\n'); A = input('Masukkan elemen matriks A : '); H = input('Masukkan elemen matriks H : '); x0 = input('Masukkan nilai awal x0 : '); y0 = input('Masukkan nilai awal y0 : '); z0 = input('Masukkan nilai awal z0 : '); x = (H(1,1)-A(1,2)*y0-A(1,3)*z0)/A(1,1); y = (H(2,1)-A(2,1)*x0-A(2,3)*z0)/A(2,2); z = (H(3,1)-A(3,1)*x0-A(3,2)*y0)/A(3,3); i = 1; galatx = abs((x-x0)/x); galaty = abs((y-y0)/y); galatz = abs((z-z0)/z); tol = 0.000001; printf('iterasi-%d ->\t x = %.4e\t y = %.4e\t z = %.4e\n', i, x, y, z); printf('galatx = %.4e\t galaty = %.4e\t galatz = %.4e\n\n', galatx, galaty, galatz); i=2; while (galaty > tol && galatx > tol && galatz > tol) xtemp = x; ytemp = y; ztemp = z; x = (H(1,1)-A(1,2)*ytemp-A(1,3)*ztemp)/A(1,1); y = (H(2,1)-A(2,1)*xtemp-A(2,3)*ztemp)/A(2,2); z = (H(3,1)-A(3,1)*xtemp-A(3,2)*ytemp)/A(3,3); printf('iterasi-%d ->\t x = %.4e\t y = %.4e\t z = %.4e\n', i, x, y, z); galatx = abs((x-xtemp)/x); galaty = abs((y-ytemp)/y); galatz = abs((z-ztemp)/z); printf('galatx = %.4e\t galaty = %.4e\t galatz = %.4e\n\n', galatx, galaty, galatz); i = i + 1; end i = i - 1; printf('\nIterasi terhenti pada iterasi ke-%d\n', i); printf('Jadi Penyelesaian SPL tersebut adalah:\n x = %.4e\t y = %.4e\t z = %.4e', x, y, z); endfunction
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 6, Example 1") disp("From saturated steam tables, enthalpy of saturated vapor at 2 MPa:") disp("Enthalpy in kJ/kg") h1 = 2799.5 hg = h1 disp("Entropy in kJ/kgK") s1 = 6.3409 sg = s1 disp("Since the expansion is isentropic, s1 = s2: i.e., s1 = s2 = 6.3409 = sf2 +x2sfg2, where x2 is the dryness fraction after isentropic expansion, sf2 is the entropy of saturated liquid at 0.2MPa, sfg2 is the entropy of vaporization at 0.2 MPa. Using tables:") x2 = (sg - 1.5301)/5.5970 disp("h2") hf2 = 504.7; hfg2 = 2201.9; disp("h2 in kJ/kg") h2 = hf2+x2*hfg2 disp("Using the energy equation:C2 in m/s") C2 = (2*(h1-h2)*1000)^0.5
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// Author: Benjamin Fradet // To execute with Scilab 5.5.1 exec('generateMarkovSeq.sci', -1); exec('generateHMMSeq.sci', -1); exec('viterbi.sci', -1); exec('baumWelch.sci', -1); exec('forwardBackward.sci', -1); // preprocessing // read csv file data = csvRead('processedDataset.csv'); n = size(data, 1); // remove header line data(1, :) = []; // remove strings columns data(:, [3, 5]) = []; weatherIndex = 4; pressureIndex = 2; stateIndex = 3; // matrix is now day of year, temperature, humidity, pressure, precipitation, // cloud level, weather, pressure type // weather is coded as follows: // 1 = Cloudy // 2 = Rain // 3 = Snow // 4 = Sunny weathers = [1; 2; 3; 4]; // pressure type is coded as follows: // 1 = Low pressure // 2 = High pressure pressures = [1; 2]; nSeq = 15; // computes the intial probabilities // computes the probabilities of each type of weather pCloudy = size(data(data(:, weatherIndex) == 1, :), 1) / n; pRain = size(data(data(:, weatherIndex) == 2, :), 1) / n; pSnow = size(data(data(:, weatherIndex) == 3, :), 1) / n; pSunny = size(data(data(:, weatherIndex) == 4, :), 1) / n; disp(pCloudy, 'cloudy: '); disp(pRain, 'rain: '); disp(pSnow, 'snow: '); disp(pSunny, 'sunny: '); initialProbsWeather = [pCloudy; pRain; pSnow; pSunny]; // computes the probabilites of each state normalPressure = 1013.25; pLow = size(data(data(:, pressureIndex) <= normalPressure, :), 1) / n; pHigh = 1 - pLow; initialProbsPressure = [pLow; pHigh]; // multinomial model // generates a 15 long sequence of weather types with the multinomial model disp(samplef(nSeq, weathers, initialProbsWeather), 'multinomial sequence: '); // Markov model // computes the transition matrix p // Cloudy = 1 cloudyIndices = find(data(:, weatherIndex) == 1); nCloudy = length(cloudyIndices); weathersAfterCloudy = data(cloudyIndices + 1, weatherIndex); cloudyToCloudy = length(weathersAfterCloudy(weathersAfterCloudy == 1)) / nCloudy; cloudyToRain = length(weathersAfterCloudy(weathersAfterCloudy == 2)) / nCloudy; cloudyToSnow = length(weathersAfterCloudy(weathersAfterCloudy == 3)) / nCloudy; cloudyToSunny = length(weathersAfterCloudy(weathersAfterCloudy == 4)) / nCloudy; // Rain = 2 rainIndices = find(data(:, weatherIndex) == 2); rainIndices = rainIndices(1:length(rainIndices) - 1); nRain = length(rainIndices); weathersAfterRain = data(rainIndices + 1, weatherIndex); rainToCloudy = length(weathersAfterRain(weathersAfterRain == 1)) / nRain; rainToRain = length(weathersAfterRain(weathersAfterRain == 2)) / nRain; rainToSnow = length(weathersAfterRain(weathersAfterRain == 3)) / nRain; rainToSunny = length(weathersAfterRain(weathersAfterRain == 4)) / nRain; // Snow = 3 snowIndices = find(data(:, weatherIndex) == 3); nSnow = length(snowIndices); weathersAfterSnow = data(snowIndices + 1, weatherIndex); snowToCloudy = length(weathersAfterSnow(weathersAfterSnow == 1)) / nSnow; snowToRain = length(weathersAfterSnow(weathersAfterSnow == 2)) / nSnow; snowToSnow = length(weathersAfterSnow(weathersAfterSnow == 3)) / nSnow; snowToSunny = length(weathersAfterSnow(weathersAfterSnow == 4)) / nSnow; sunnyIndices = find(data(:, weatherIndex) == 4); nSunny = length(sunnyIndices); weathersAfterSunny = data(sunnyIndices + 1, weatherIndex); sunnyToCloudy = length(weathersAfterSunny(weathersAfterSunny == 1)) / nSunny; sunnyToRain = length(weathersAfterSunny(weathersAfterSunny == 2)) / nSunny; sunnyToSnow = length(weathersAfterSunny(weathersAfterSunny == 3)) / nSunny; sunnyToSunny = length(weathersAfterSunny(weathersAfterSunny == 4)) / nSunny; pMarkov = [cloudyToCloudy, cloudyToRain, cloudyToSnow, cloudyToSunny; ... rainToCloudy, rainToRain, rainToSnow, rainToSunny; ... snowToCloudy, snowToRain, snowToSnow, snowToSunny; ... sunnyToCloudy, sunnyToRain, sunnyToSnow, sunnyToSunny]; disp(pMarkov, 'transition matrix: '); // generates a markov sequence disp(... generateMarkovSeq(pMarkov, initialProbsWeather, nSeq), 'markov sequence: '); // Hidden Markov model // Low pressure = 1 lowIndices = find(data(:, pressureIndex) <= normalPressure); nLow = length(lowIndices); weathersLow = data(lowIndices, weatherIndex); pLowCloudy = length(weathersLow(weathersLow == 1)) / nLow; pLowRain = length(weathersLow(weathersLow == 2)) / nLow; pLowSnow = length(weathersLow(weathersLow == 3)) / nLow; pLowSunny = length(weathersLow(weathersLow == 4)) / nLow; // High pressure = 2 highIndices = find(data(:, pressureIndex) > normalPressure); nHigh = length(highIndices); weathersHigh = data(highIndices, weatherIndex); pHighCloudy = length(weathersHigh(weathersHigh == 1)) / nHigh; pHighRain = length(weathersHigh(weathersHigh == 2)) / nHigh; pHighSnow = length(weathersHigh(weathersHigh == 3)) / nHigh; pHighSunny = length(weathersHigh(weathersHigh == 4)) / nHigh; // computes the probs to change states high/low pressures lowIndices = lowIndices(1:length(lowIndices) - 1); pressuresAfterLow = data(lowIndices + 1, pressureIndex); lowToLow = length(pressuresAfterLow(pressuresAfterLow <= normalPressure)) / ... nLow; lowToHigh = length(pressuresAfterLow(pressuresAfterLow > normalPressure)) / ... nLow; pressuresAfterHigh = data(highIndices + 1, pressureIndex); highToLow = length(pressuresAfterHigh(pressuresAfterHigh <= normalPressure)) ... / nHigh; highToHigh = ... length(pressuresAfterHigh(pressuresAfterHigh > normalPressure)) / nHigh; // transition matrix transitionHMM = [lowToLow, lowToHigh; ... highToLow, highToHigh]; // emission matrix emissionHMM = [pLowCloudy, pLowRain, pLowSnow, pLowSunny; ... pHighCloudy, pHighRain, pHighSnow, pHighSunny]; // generates a hidden markov sequence [weatherSeq stateSeq] = ... generateHMMSeq(transitionHMM, emissionHMM, initialProbsPressure, nSeq); disp(weatherSeq, 'generated hmm weather sequence: '); disp(stateSeq, 'generated hmm hidden state sequence: '); // model exploitation // posterior state probabilities of an emission sequence posteriors = forwardBackward(data(1:10, weatherIndex), initialProbsPressure, ... transitionHMM, emissionHMM); disp(posteriors, 'posterior state probabilities: '); // most probable path: // given the weathers for a whole year, tries to find the sequence of states // associated (high or low pressure) [path stateMatrix] = viterbi(data(:, weatherIndex), transitionHMM, emissionHMM); // actual state vector actualState = data(:, stateIndex); probaError = sum(actualState == path') / n; disp(probaError, ... 'proba of error between the most likely path and the real path: '); disp(path(1:10), 'most probable state path: '); disp(actualState(1:10)', 'real state path: '); disp(stateMatrix(1:4, :), 'positions states matrix: '); // to compute: proba of error between the most probable path and real pressures // learning of the model disp(initialProbsWeather, 'lambda weather: '); disp(initialProbsPressure, 'lambda pressure: '); tMatrix = zeros(2, 2); eMatrix = zeros(2, 4); l = 0; nIter = 20; for i = 1:nIter [tmpTMatrix tmpEMatrix tmpL] = baumWelch(data(:, weatherIndex), ... initialProbsPressure, ... 10e-8, 1000); tMatrix = tMatrix + tmpTMatrix; if abs(tmpL) > abs(l) l = tmpL; eMatrix = tmpEMatrix; end end tMatrix = tMatrix ./ nIter; disp(tMatrix, 'learned transition matrix: '); disp(transitionHMM, 'empirical transition matrix: '); disp(eMatrix, 'learned emission matrix: '); disp(emissionHMM, 'empirical emission matrix: ');
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//Example 5_13_u1 clc(); clear; //To determine the crystal structure and indices of plane and lattice parameter of the material theta21=20.7 //units in degrees theta22=28.72 //units in degrees theta23=35.36 //units in degrees theta24=41.07 //units in degrees theta25=46.19 //units in degrees theta26=50.90 //units in degrees theta28=55.28 //units in degrees theta29=59.4 //units in degrees theta1=theta21/2 //units in degrees theta2=theta22/2 //units in degrees theta3=theta23/2 //units in degrees theta4=theta24/2 //units in degrees theta5=theta25/2 //units in degrees theta6=theta26/2 //units in degrees theta8=theta28/2 //units in degrees theta9=theta29/2 //units in degrees //sin^2(theta) values sin1=(sin(theta1*%pi/180))^2 sin2=(sin(theta2*%pi/180))^2 sin3=(sin(theta3*%pi/180))^2 sin4=(sin(theta4*%pi/180))^2 sin5=(sin(theta5*%pi/180))^2 sin6=(sin(theta6*%pi/180))^2 sin8=(sin(theta8*%pi/180))^2 sin9=(sin(theta9*%pi/180))^2 //sin^2(theta)/0.0308 values temp1=sin1/sin1 temp2=sin2/sin1 temp3=sin3/sin1 temp4=sin4/sin1 temp5=sin5/sin1 temp6=sin6/sin1 temp8=sin8/sin1 temp9=sin9/sin1 h2k2l21=temp1*2 h2k2l22=temp2*2 h2k2l23=temp3*2 h2k2l24=temp4*2 h2k2l25=temp5*2 h2k2l26=temp6*2 h2k2l28=temp8*2 h2k2l29=temp9*2 //(h,k,l) values are determined such that the sum h^2+k^2+l^2=temp value in that manner hence we have to select the (h,k,l) values //(h,k,l) values hkl1=110 //As h^2+k^2+l^2=2 hkl2=200 //As h^2+k^2+l^2=4 hkl3=211 //As h^2+k^2+l^2=6 hkl4=220 //As h^2+k^2+l^2=8 hkl5=310 //As h^2+k^2+l^2=10 hkl6=232 //As h^2+k^2+l^2=12 hkl8=321 //As h^2+k^2+l^2=14 hkl9=400 //As h^2+k^2+l^2=16 printf("unit cell Dimensions for peak 1 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is %.2f\n",theta21,hkl1,ceil(h2k2l21) ) printf("unit cell Dimensions for peak 2 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is %.2f\n",theta22,hkl2,ceil(h2k2l22) ) printf("unit cell Dimensions for peak 3 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is%.2f\n",theta23,hkl3,ceil(h2k2l23)) printf("unit cell Dimensions for peak 4 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is %.2f\n",theta24,hkl4,ceil(h2k2l24)) printf("unit cell Dimensions for peak 5 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is%.2f\n",theta25,hkl5,ceil(h2k2l25)) printf("unit cell Dimensions for peak 6 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is%.2f\n",theta26,hkl6,ceil(h2k2l26)) printf("unit cell Dimensions for peak 7 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is %.2f\n",theta28,hkl8,ceil(h2k2l28)) printf("unit cell Dimensions for peak 8 when 2*theta=%.1f is (%d) where sin^2(theta)/0.0308 is %.2f\n",theta29,hkl9,ceil(h2k2l29)) printf("The material corresonds to bcc structure\n") //Consider peak no 8 where theta=29.71 lamda=0.07107 //units in nm d400=lamda/(2*sin(theta9*(%pi/180))) //units in nm a=d400*sqrt(ceil(h2k2l29)) //units in nm printf("Lattice parameter of the material a=%.4fnm",a)
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//Example 1_8 clc; clear; close; format('v',6); //given data : //6*I1-3*I2=2 from mesh 1 //-6*I1+14*I2=4 from mesh 2 A=[6 -3;-6 14];//coefiicient matrix B=[2;4];//coefiicient matrix X=A^-1*B;//Matrix multiplication I1=X(1);//A I2=X(2);//A disp(I1,"Current in 2ohm & 4ohm resistor(A)"); disp(I2,"Current in 3ohm & 5ohm resistor(A)"); I6ohm=I1-I2;//A(Current in 6ohm resistor) disp(I6ohm,"Current in 6ohm resistor(A)");
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clc //initialisation of variables r=10000//ft l=400000//people q=1000000//mgd w=100//gpcd w1=150//gpcd m=50//percent g=1.5//ft h1=2.32//cfs h2=139//cfs d=12//ft c=100//ft l=10.8//ft l2=0.85//ft l1=1000//ft //CALCULATIONS a=r*w/q//mgd b=l*w1/q//mgd a1=a*g//mgd b1=b*g//mgd D=d*sqrt(h1/%pi)//in D1=d*sqrt(h2/%pi)//in L=l/l1//ft L1=l2/l1//ft //RESULTS printf('the higher loss of head in small conduits at equal velocity=% f ft',L1)
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//clear// //Caption: Program to calculate link rise time //Example8.3 //page 291 clear; clc; close; t_tx = 15e-09; //transmitter rise time t_mat = 21e-09; //material dispersion related rise time t_mod = 3.9e-09; //rise time resulting from modal dispersion t_rx =14e-09; //receiver rise time tsys = sqrt(t_tx^2+t_mat^2+t_mod^2+t_rx^2) disp(tsys*1e09,'link rise time in nano seconds tsys =') //Result //link rise time in nano seconds tsys = 29.617731
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// Scilab Code Ex4.1: Page-233 (2008) clc; clear; c = 3e+008; // Speed of light in vacuum, m/s v = 3e+004; // Speed of earth, m/s d = 7; // Effective length of each path, m lambda = 7000e-010; // Wavelength of light used, m n = 2*d*v^2/(lambda*c^2); // Fringe shift printf("\nThe expected fringe shift = %3.1f", n); // Result // The expected fringe shift = 0.2
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// Scilab Code Ex9.14: Probability of electron moving in 1D box : Page-207 (2010) a = 2e-010; // Width of 1D box, m x1 = 0; // Position of first extreme of the box, m x2 = 1e-010; // Position of second extreme of the box, m P = integrate('2/a*(sin(2*%pi*x/a))^2', 'x', x1, x2); // The probability of finding the electron between x = 0 and x = 1e-010 printf("\nThe probability of finding the electron between x = 0 and x = 1e-010 = %3.1f", P); // Result // The probability of finding the electron between x = 0 and x = 1e-010 = 0.5
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// Calculating the normcdf y = [1,2,3,4,5,6,7,8] res = armaClust("normcdf",y)
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//chapter 6 Ex 5 clc; clear; close; Atotal=36; Btotal=44; avgA=40; avgB=35; avg=(Atotal*avgA+Btotal*avgB)/(Atotal+Btotal); mprintf("The average weight of whole class is %.2f kilograms",avg);
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clear; clc; rating=25e6; vb=11e3; x=.16/4; faultMVA=rating*1e-6/x; mprintf("the fault MVA from method 1=%dMVA",faultMVA); //method 2 Ifault=1/(x*%i); Ib=rating/(sqrt(3)*vb); Isc=Ib*25; MVA=sqrt(3)*vb*Isc/1e6; mprintf("\n the fault MVA from method 2=%dMVA",MVA);
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//Exa 1.15 clc; clear; close // given data Tf=80;// in degree C I=200;// in amp h=4000;// in W/m^2degree C rho=70*10^-6; L=100;// in cm R=0.1;// in ohm d=3;// in mm d=d*10^-3; As= %pi*d; //Formula I^2*R= h*As*(Tw-Tf) Tw= I^2*R/(h*As)+Tf; disp(Tw,"Central temperature of the wire in °C")
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// chapter 9 // example 9.3 // fig. 9.5 // Determine rms load current at fundamental frequency, rms value of load current, power output and average supply current // page-550 clear; clc; // given Edc=220; // in V (dc source) R=10; // in ohm L=10; // in mH C=52; // in uF f=400; // in Hz // calculate L=L*1E-3; // changing unit from mH to H C=C*1E-6; // changing unit from uF to F X_L=2*%pi*f*L; // calculation of inductive reactance X_C=1/(2*%pi*f*C); // calculation of inductive reactance I=0; // intialisation of variable for rms load current // since Impedence offered to the nth harmonic component Zn=sqrt(R^2+(n*X_L-X_C/n)^2) printf("\nn\t\tZn\t\t\tIn"); for n=1:2:9 Zn=sqrt(R^2+(n*X_L-X_C/n)^2); // calculation of Impedence offered to the nth harmonic component En=0.9*Edc/n; // calculation of rms value of the nth harmonic component of the output voltage In=En/Zn; // calculation of rms value of nth harmonic component of the current printf("\n%.f\t\t%.2f ohm\t\t%.3f A",n,Zn,In); I=I+In^2; end I=sqrt(I); printf("\n\nThe rms value of load current is \t I=%.2f A",I); P0=I^2*R; // calculation of output power Iav=P0/Edc; // calculation of average supply current printf("\n\nThe output power is \t\t\t P0=%.2f W",P0); printf("\n\nThe average supply current is \t\t Iav=%.2f A",Iav); // Note: The answer varies slightly due to precise calculation
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filtres.sci
function cny =canny(image) image = nb(image) cny = edge(image,'canny') endfunction function y = bonus(x) [nl,nc]=size(x) y = []; for i=2:nl-1 for j=2:nc-1 y(i,j)=(x(i,j)+x(i+1,j+1)-x(i,j+1)-x(i-1,j+1)-x(i+1,j)-x(i-1,j)-x(i+1,j-1)-x(i,j-1)-x(i-1,j-1)) end end endfunction function flou = gaussien(image) G = fspecial('gaussian',27,3); flou = imfilter(image,G); endfunction function hrztl = horizontal(image) [x,y,c] = size(image) for i = 1 : x/2+1 for j = 1 : y hrztl(i,j,:) = matrix(image(x-i+1,j,:),1,c) hrztl(x-i+1,j,:) = matrix(image(i,j,:),1,c) end end endfunction function hv = horivertical(image) [x,y,c] = size(image) for i=1:x for j=1:y/2+1 hv(i,j,:)=matrix(image(x-i+1, y-j+1,:),1,3) hv(x-i+1, y-j+1,:)=matrix(image(i,j,:),1,3) end end endfunction function vrtcl = vertical(image) [x,y,c] = size(image) for i = 1 : x for j = 1 : y/2+1 vrtcl(i,j,:) = matrix(image(i,y-j+1,:),1,c) vrtcl(i,y-j+1,:) = matrix(image(i,j,:),1,c) end end endfunction function img = nb(image) r = image(:,:,1) g = image(:,:,2) b = image(:,:,3) img = imlincomb(0.299,r,0.587,g,0.114,b) endfunction function ngtf = negatif(image) ngtf = 255 - image endfunction function prwt =prewitt(image) image = nb(image) prwt = edge(image,'prewitt') endfunction function sbl =sobel(image) S = fspecial('sobel'); sbl = imfilter(image,S); endfunction function rouge =red(image) Blanc = uint8(zeros(image(:,:,1))) rouge = image(:,:,1) rouge(:,:,2) = Blanc rouge(:,:,3) = Blanc endfunction function vert =green(image) Blanc = uint8(zeros(image(:,:,1))) vert(:,:,1) = Blanc vert(:,:,2) = image(:,:,2) vert(:,:,3) = Blanc endfunction function bleu =blue(image) Blanc = uint8(zeros(image(:,:,1))) bleu(:,:,1)= Blanc bleu(:,:,2)= Blanc bleu(:,:,3)= image(:,:,3) endfunction function cyn =cyan(image) Blanc = uint8(zeros(image(:,:,1))) cyn(:,:,1) = Blanc cyn(:,:,2) = image(:,:,2) cyn(:,:,3) = image(:,:,1) endfunction function violet =purple(image) Blanc = uint8(zeros(image(:,:,1))) violet(:,:,1) = image(:,:,1) violet(:,:,2) = Blanc violet(:,:,3) = image(:,:,1) endfunction function jaune =yellow(image) Blanc = uint8(zeros(image(:,:,1))) jaune(:,:,1) = image(:,:,1) jaune(:,:,2) = image(:,:,1) jaune(:,:,3) = Blanc endfunction
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clc //Chapter1 //Ex_1.2 //Given R=8.314 // in J/mol/K T=27 //in degree celcius T=T+273 //in Kelvin M_at=14 //in g/mol //From Kinetic Theory V_rms=sqrt((3*R*T)/(2*M_at*10^-3)) disp(V_rms,"rms velocity of Nitrogen molecule in atmosphere at 300K in m/s is") V_rmsx=V_rms/sqrt(3) disp(V_rmsx,"rms velocity in one direction in m/s is")
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<cmd> ../build/42sh</cmd> <ref> bash</ref> <stdin> echo true || echo false && ! echo maarek && echo joseph </stdin>
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//Exa 7.6 clc; clear; close; format('v',5); //Given data : Ph=3;//phase r=10.4/2;//mm r=r/10;//in cm d=2.5;//meter d=d*100;//in cm t=21;//degree C T=t+273;//K b=73.6;//cm-Hg mo=0.85; mv_l=0.7; mv_g=0.8; go=21.21;//kV/cm : assumed del=3.92*b/T;//Air density factor //Formula : Vdo=go*del*mo*r*log(d*100/r);//kV Vdo=go*del*mo*r*log(d/r);//kV Vdo_line=sqrt(3)*Vdo;//kV Vvo=go*del*mv_l*r*(1+.3/sqrt(del*r))*log(d/r);//kV Vvo_line_local=Vvo*sqrt(3);//kV(rms) disp(Vvo_line_local,"Line to line visual critical voltage for local corona(kV-rms) : ") Vvo_line_general=Vvo_line_local*mv_g/mv_l;//kV(rms) disp(Vvo_line_general,"Line to line visual critical voltage for general corona(kV-rms) : ") //Note : Answer in the book is not accurate.
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// Example 1.3 // SAMPLE PROGRAM 1: PRINTING A MESSAGE //Printing Begins printf("I see,I remember") //Printing using printf() function //Printing ends //We can also print a message using disp() function in scilab disp("I see,I remember") //Printing using disp() function
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gpio_in_fixloc.sce
//****************************** GPIO In Fix location ******************************* if (blk_name.entries(bl) =='gpio_in_fixloc') then GPIO_IN_check=1; gpin.entries=[] gi_idx2=size(evstr(scs_m.objs(bl).model.opar(1)), "r"); fd_io= mopen (fname+'.pads','a+'); // DEDICATED PADS code for ii = 1:gi_idx2 if scs_m.objs(bl).model.rpar(2) == 1 then gpin(1,1).entries(1,ii)= strtod(gpin_loc(loc_num,scs_m.objs(bl).model.rpar(3+ii-1)).entries(2)); mputl('net'+ string(blk(blk_objs(bl),2+numofip)) + "_"+ string(ii) +' ' + gpin_loc(loc_num,scs_m.objs(bl).model.rpar(3+ii-1)).entries(1),fd_io); else gpin_loc_idx = gpin_loc_idx +1; gpin(1,1).entries(1,ii)= strtod(gpin_loc(loc_num,gpin_loc_idx).entries(2)); mputl('net'+ string(blk(blk_objs(bl),2+numofip)) + "_"+ string(ii) +' ' + gpin_loc(loc_num,gpin_loc_idx).entries(1),fd_io); end end mclose(fd_io); genarb_gpin = gpin(1,1).entries(1,:); exec("~/rasp30/prog_assembly/libs/scilab_code/genarb_gpin_compile.sce",-1); genarb_gpin_compile(scs_m.objs(bl).model.opar(1),scs_m.objs(bl).model.rpar(1),genarb_gpin,0); // regen = 0 end
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ex4.sce
//ques4 //calculating amount of water vapour condensed on cooling clear clc //from example 3 w1=0.0255;//w1=w, humidity ratio at initial temperature ma=108.6;//mass of air in kg P=100;//kPa net pressure //at 5 C mixture is saturated so Pv2=Pg2 Pg2=0.8721; Pv2=Pg2; w2=0.622*Pv2/(P-Pg2); mc=ma*(w1-w2); printf('Mass of vapour condense = %.3f kg \n',mc);
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//Example number 1.10, Page number 1.38 clc;clear;close //Variable declaration lamda=5893; // in micron n=3 // unitless d_lamda=6 // in micron //Calculation N=(lamda)/(n*d_lamda) // number of rulings //Result printf("N = %0.1f",N) printf("\nThe number of rulings needed is 328. This is the minimum requirement.")
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function [x,y,typ] = mdaq_mem_write(job,arg1,arg2) mem_write_desc = ["This block writes data to MicroDAQ memory."; "Block with mdaq_mem_get function can be used "; "to get data from Standalone and Ext model."; ""; "Set block parameters:"]; x=[];y=[];typ=[]; select job case 'set' then x=arg1 model=arg1.model; graphics=arg1.graphics; exprs=graphics.exprs; while %t do try [ok,start_idx,data_size,vec_size,overwrite,exprs]=.. scicos_getvalue(mem_write_desc,.. ['Start index:'; 'Size'; 'Vector size:'; 'Overwrite:'],.. list('vec',1,'vec',1,'vec',1,'vec',1),exprs) catch [ok,start_idx,data_size,vec_size,overwrite,exprs]=.. getvalue(mem_write_desc,.. ['Start index:'; 'Size:'; 'Vector size:'; 'Overwrite:'],.. list('vec',1,'vec',1,'vec',1,'vec',1),exprs) end; if ~ok then break end //~16MB = 16 000 000B = 4 000 000 floats max_index = 4000000; if data_size == -1 then data_size = max_index - start_idx; end if start_idx < 1 | start_idx > max_index then ok = %f; message("Incorrect start index. Shared memory is idexing from 1 to "+string(max_index)); end if data_size < 1 | data_size > (max_index-start_idx) then ok = %f; message("Incorrect size (max "+string(max_index-start_idx)+")"); end if overwrite > 1 | overwrite < 0 then ok = %f; message("Use values 0 or 1 to set increment option."); end if ok then [model,graphics,ok] = check_io(model,graphics, vec_size, [], 1, []); graphics.exprs = exprs; model.rpar = []; model.ipar = [(start_idx-1);data_size;vec_size;overwrite]; model.dstate = []; x.graphics = graphics; x.model = model; break end end case 'define' then vec_size = 1; start_idx = 1; data_size = 100; overwrite = 0; model=scicos_model() model.sim=list('mdaq_mem_write_sim',5) model.in=-1 model.in2=-2 model.out=[] model.evtin=1 model.rpar=[]; model.ipar = [(start_idx-1);data_size;vec_size;overwrite]; model.dstate=[]; model.blocktype='d' model.dep_ut=[%t %f] exprs=[sci2exp(start_idx);sci2exp(data_size);sci2exp(vec_size);sci2exp(overwrite)] gr_i=['xstringb(orig(1),orig(2),['''' ; ],sz(1),sz(2),''fill'');'] x=standard_define([4 3],model,exprs,gr_i) x.graphics.in_implicit=[]; x.graphics.exprs=exprs; end endfunction
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//Ex2_1 clc; //Given: f=19;// atomic mass no. of F a=197;// atomic mass no.of Au p=239;// atomic mass no. of Pu //solution:(a) m1=f/(6.02*10^23); Rf=1.4*(f^(1/3))*10^-13;// in cm V1=1.3333*3.14*(Rf)^3; df=m1/(V1*10^14);// density in 10^14 g cm^-3 printf("\n The density nucleus of F(19) in 10^14 g cm^-3 is = %f ",df) //(b) m2=a/(6.02*10^23); Ra=1.4*(a^(1/3))*10^-13;// in cm V2=1.3333*3.14*(Ra)^3; da=m2/(V2*10^14);// density in 10^14 g cm^-3 printf("\n The density nucleus of Au(197) in 10^14 g cm^-3 is = %f ",da) //(c) m3=p/(6.02*10^23); Rp=1.4*(p^(1/3))*10^-13;// in cm V3=1.3333*3.14*(Rp)^3; dp=m3/(V3*10^14);// density in 10^14 g cm^-3 printf("\n The density nucleus of P(239) in 10^14 g cm^-3 is = %f ",dp) // Note: The density for Au(197) is not calculated correctly in the textbook.
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//find b1 in fig 5.24 clc //solution //given P=80000//N ft=70//N/mm^2//stress //b=3*t //A=b*t //A=3t*t //P=ft*A //t^2=80000/210 t=sqrt(80000/210)//mm b=3*t//mm ////when the link is shown by dotted line, it will be subjected to direct stress as we;; as bending stress //A1=b1*t //fo=P/A //fo=P/(b1*t) //fb=M/Z//=P*e/(t*b1^2) //f=fo+fb//total stress //f=P/(t*b1)*[(6*e/b1)+1] //70=(80000/(20*b1))*[4] b1=16*10^3/70//mm printf("the thickness is,%f mm\n",t) printf("the width is,%f mm\n",b) printf("the new width is,%f mm\n",b1)
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// Grob's Basic Electronics 11e // Chapter No. 07 // Example No. 7_1 clc; clear; // Three 50 Ohms resistors R1, R2 and R3 are in series across an applied voltage of 180 V. How much is the IR voltage drop across each resistor? // Given data R1 = 50*10^3; // Resistor 1=50k Ohms R2 = 50*10^3; // Resistor 2=50k Ohms R3 = 50*10^3; // Resistor 3=50k Ohms Vt = 180; // Applied Voltage=180 Volts R = R1 // R = R1 = R2 = R3 Rt = R1+R2+R3; V = Vt*(R/Rt); disp (V,'The Voltage Drop across each Resistor in Volts')
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function [vtps_n,vnms_n]=updatevtps(nv_old,vtps_n,vtps_1,vnms_n,vnms_1) //add new variables // Copyright INRIA for k=nv_old+1:size(vtps_1) if find(vnms_1(k,1)==vnms_n(:,1))==[] then vnms_n=[vnms_n;vnms_1(k,:)] vtps_n($+1)=vtps_1(k) end end for k=1:min(size(vtps_n) , size(vtps_1)) for l=1:3 if vtps_n(k)(l)<>vtps_1(k)(l) then vtps_n(k)(l)='?' end end end
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clc;funcprot(0);//Example 8.7 //Initilisation of Variables Tci=50;......//Inlet temparature of water in K Thi=500;......//Inlet temparature of oil in K mc=25;....//Flow rate of water in kg/s mh=20;.....//Flow rate of oil in kg/s U=1;..........//Overall heat transfer coefficient in W/m^2C A=40;....//Area of tube in m^2 Cph=2.5;....//Specific heat of oil in kJ/kgK Cpc=4.2;....//Specific heat of water in kJ/kgK //calculations Ch=mh*Cph;....//Heat capacity of hot fluid by counter flow kW/K Cc=mc*Cpc;....//Heat capacity of cold fluid by counter flow kW/K R=Ch/Cc;.....//Resistance NTU=(U*A)/Ch;....//Number of transfer units E=(1-exp(-NTU*(1-R)))/(1-(R*exp(-NTU*(1-R))));.....//Effectiveness in counter flow Tho=-((E*(Thi-Tci))-Thi);.....//Outer temparature of oil in counter flow arrangement in K Tco=((E*(Thi-Tci))/(Cc/Ch))+Tci;.....//Outer temparature of water in counter flow arrangement in K Ep=(1-exp(-NTU*(1+R)))/(1+R);.....//Effectiveness in counter flow Thop=-((Ep*(Thi-Tci))-Thi);.....//Outer temparature of oil in counter flow arrangement in K Tcop=((Ep*(Thi-Tci))/(Cc/Ch))+Tci;.....//Outer temparature of water in counter flow arrangement in K Eg=0.52;.....//Effectiveness from the graph of in counter flow from graph Thog=-((Eg*(Thi-Tci))-Thi);.....//Outer temparature of oil in counter flow arrangement in K Tcog=((Eg*(Thi-Tci))/(Cc/Ch))+Tci;.....//Outer temparature of water in counter flow arrangement in K Epg=0.48;.....//Effectiveness from the graph of in parallel flow Thopg=-((Epg*(Thi-Tci))-Thi);.....//Outer temparature of oil in counter flow arrangement in K Tcopg=((Epg*(Thi-Tci))/(Cc/Ch))+Tci;.....//Outer temparature of water in counter flow arrangement in K disp("(i)By calculations") disp(Tho,"Outer temparature of oil in counter flow arrangement in K:") disp(Tco,"Outer temparature of water in counter flow arrangement in K:") disp(Thop,"Outer temparature of oil in parallel flow arrangement in K:") disp(Tcop,"Outer temparature of water in parallel flow arrangement in K:") disp("By graph") disp(Thog,"Outer temparature of oil in counter flow arrangement in K:") disp(Tcog,"Outer temparature of water in counter flow arrangement in K:") disp(Thopg,"Outer temparature of oil in parallel flow arrangement in K:") disp(Tcopg,"Outer temparature of water in parallel flow arrangement in K:")
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//Generates a Test wavfile for testing our filters //Contains a wav file with three sine waves //Now it's easy to check if a sine is filtered or not! t = [0: 0.000001: 1]; sin_500Hz = 0.3*sin(2*%pi*500*t); sin_1000Hz =0.3*sin(2*%pi*1000*t); sin_5000Hz =0.3* sin(2*%pi*5000*t); testsign = sin_500Hz +sin_1000Hz + sin_5000Hz; wavwrite(testsign, 'SCI/modules/sound/demos/TripleSin.wav');
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clc // initialization of variables // The reaction equation is //CaHb + c(O2+3.76N2)---> 10.4CO2 + 1.2CO + 2.8O2 + 85.6N2 + dH2O // using atomic balancing // C:a=10.4+12 //N:3.76c=85.6 //O:2c=20.8+1.2+5.6+d //H:b=2d // Solving these equations using matrix A=[1 0 0 0;0 0 3.76 0;0 0 2 -1;0 1 0 -2] B=[11.6;85.6;27.6;0] x=A\B a=x(1) b=x(2) c=x(3) d=x(4) // substituing these values in reaction equation //C11.6H37.9 + 21.08(O2+3.76N2)---> 11.6CO2 + 18.95H2O + 79.26N2 %theoriticalair=22.8*100/21.08 // theoritical air excessair=%theoriticalair-100 printf("The excess air is %i %%",excessair)
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clear; clc; disp('Example 11.5'); // aim : To determine // (a) the intermediate pressure // (b) the indicated power output // (c) the steam consumption of the engine // given values P1 = 1400;// initial pressure, [kN/m^2] x = .9;// dryness fraction P5 = 35;// exhaust pressure k = .8;// diagram factor of low-pressure cylindaer L = 350*10^-3;// stroke of both the cylinder, [m] dhp = 200*10^-3;// diameter of high pressure cylinder, [m] dlp = 300*10^-3;// diameter of low-pressure cylinder, [m] N = 300;// engine speed, [rev/min] // solution // taking reference Fig.11.13 Ahp = %pi/4*dhp^2;// area of high-pressure cylinder, [m^2] Alp = %pi/4*dlp^2;// area of low-pressure cylinder, [m^2] // for equal initial piston loads // (P1-P7)Ahp=(P7-P5)Alp deff('[x]=f(P7)','x=(P1-P7)*Ahp-(P7-P5)*Alp'); P7 = fsolve(0,f);// intermediate pressure, [kN/m^2] mprintf('\n (a) The intermediate pressure is = %f kN/m^2\n ',P7); // (b) V6 = Ahp*L;// volume of high-pressure cylinder, [m^3] P2 = P1; P6 = P7; // using P2*V2=P6*V6 V2 = P6*V6/P2; // [m^3] V1 = Alp*L;// volume of low-pressure cylinder, [m^3] R = V1/V2;// expansion ratio Pm = P1/R*(1+log(R))-P5;// effective pressure of low-pressure cylinder, [kn/m^2] Pm = k*Pm;// actual effective pressure, [kN/m^2] ip = Pm*L*Alp*N*2/60;// indicated power, [kW] mprintf('\n (b) The indicated power is = %f kW\n',ip); // (c) COV = V1/ R;// cut-off volume in high-pressure cylinder, [m^3] V = COV*N*2*60;// volume of steam admitted/h // from steam table vg = .1407;// [m^3/kg] AV = x*vg;// specific volume of admission steam, [m^3/kg] m = V/AV;// steam consumption, [kg/h] mprintf('\n (c) The steam consumption of the engine is = %f kg/h\n',m); // End
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//Area of indicator diagram(in mm^2) Area=2000; //Length of indicaor diagram(in mm) l=100; //Deflection of pointer(in bar/mm) d=2/10; //Stroke of the engine(in m) L=0.1; //Bore of the engine(in m) D=0.1; //Speed of the engine(in rpm) N=1000; //Mechanical effciency nm=0.75;
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<?xml version="1.0" encoding="utf-8"?> <test> <description>NS, Manufactured Compressible Poiseuille's flow to test IP</description> <executable>CompressibleFlowSolver</executable> <parameters>MMS_Compressible_Poiseuille_testIP.xml</parameters> <files> <file description="Session File">MMS_Compressible_Poiseuille_testIP.xml</file> </files> <metrics> <metric type="L2" id="1"> <value variable="rho" tolerance="1e-12">1.71095e-06</value> <value variable="rhou" tolerance="1e-12">1.25767e-04</value> <value variable="rhov" tolerance="1e-12">3.98104e-04</value> <value variable="E" tolerance="1e-12">5.19340e-01</value> </metric> <metric type="Linf" id="2"> <value variable="rho" tolerance="1e-12">4.63915e-06</value> <value variable="rhou" tolerance="1e-12">5.07214e-04</value> <value variable="rhov" tolerance="1e-12">1.43833e-03</value> <value variable="E" tolerance="1e-12">1.26429e+00</value> </metric> </metrics> </test>
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade -- secret or copyright law. Dissemination of this information or reproduction of this material is -- strictly forbidden unless prior written permission is obtained from Fuzzy Logix, LLC. -- Functional Test Specifications: -- -- Test Category: Basic Statistics -- -- Test Unit Number: FLCountPos-Netezza-01 -- -- Name(s): FLCountPos -- -- Description: Aggregate function which returns the count of positive values -- -- Applications: -- -- Signature: FLCountPos(pX DOUBLE PRECISION) -- -- Parameters: See Documentation -- -- Return value: BIGINT -- -- Last Updated: 07-03-2017 -- -- Author: Kamlesh Meena -- -- BEGIN: TEST SCRIPT --.run file=../PulsarLogOn.sql --.set width 2500 SELECT COUNT(*) AS CNT, CASE WHEN CNT = 0 THEN ' Please Load Test Data!!! ' ELSE ' Test Data Loaded ' END AS TestOutcome FROM fzzlSerial a; -- BEGIN: POSITIVE TEST(s) ---- Positive Test 1: Count of 0.0 * Value, Results should be 0 --- Compare query output with 0, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 0 THEN 'BasicStat-FT-FLCountPos-01P1: PASSED' ELSE 'BasicStat-FT-FLCountPos-01P1: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.SerialVal * -0.0) AS CNTPos, COUNT(*) AS CNT FROM fzzlSerial a WHERE a.SerialVal <= 10) AS a; ---- Positive Test 2: Count of -1.0 * Value, Results should be 0 --- Compare query output with 0, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 0 THEN 'BasicStat-FT-FLCountPos-01P2: PASSED' ELSE 'BasicStat-FT-FLCountPos-01P2: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.SerialVal * -1.0) AS CNTPos, COUNT(*) AS CNT FROM fzzlSerial a WHERE a.SerialVal <= 10) AS a; ---- Positive Test 3: Count of Value - 1e4, Results should be 100000 - 1e4 --- Compare query output with 100000 - 1e4, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 100000 - 1e4 THEN 'BasicStat-FT-FLCountPos-01P3: PASSED' ELSE 'BasicStat-FT-FLCountPos-01P3: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.SerialVal - 1e4) AS CNTPos, COUNT(*) AS CNT FROM fzzlSerial a WHERE a.SerialVal <= 100000) AS a; ---- Positive Test 4: Multiple a very small number, Results should be 10 --- Compare query output with 10, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 10 THEN 'BasicStat-FT-FLCountPos-01P4: PASSED' ELSE 'BasicStat-FT-FLCountPos-01P4: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.SerialVal * 1e-100) AS CNTPos, COUNT(*) AS CNT FROM fzzlSerial a WHERE a.SerialVal <= 10) AS a; ---- Positive Test 5: Multiple a very large number, Results should be 10 --- Compare query output with 10, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 10 THEN 'BasicStat-FT-FLCountPos-01P5: PASSED' ELSE 'BasicStat-FT-FLCountPos-01P5: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.SerialVal * 1e100) AS CNTPos, COUNT(*) AS CNT FROM fzzlSerial a WHERE a.SerialVal <= 10) AS a; -- END: POSITIVE TEST(s) -- BEGIN: NEGATIVE TEST(s) ---- Negative Test 1: No data, should return 0 --- Compare query output with 0, if true then return "passed", otherwise, return "failed" SELECT a.CNTPos AS CNTPos, CASE WHEN a.CNTPos = 0 THEN 'BasicStat-FT-FLCountPos-01N1: PASSED' ELSE 'BasicStat-FT-FLCountPos-01N1: FAILED' END AS TestOutcome FROM ( SELECT FLCountPos(a.RandVal) AS CNTPos, COUNT(*) CNT FROM fzzlSerial a WHERE a.SerialVal <= -1) AS a; ---- Negative Test 2a: Invalid Data Type: Input VarChar --- Output error, FLCountPos doesn't not exist, Good SELECT FLCountPos(a.City) FROM tblCustData a; ---- Negative Test 2b: Invalid Data Type: Input VarChar --- Output error, FLCountPos doesn't not exist, Good SELECT FLCountPos(CAST (a.RandVal AS VARCHAR(30))), COUNT(*) FROM fzzlSerial a WHERE a.SerialVal <= 10; -- END: NEGATIVE TEST(s) \time -- END: TEST SCRIPT
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deuxpi = 2 * 3.1415926536; # 6.2831853072 rayon = 3*8; # 24 circonference = deuxpi * rayon; # 150.796447373 circonference
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// Exa 3.9 clc; clear; close; // Given data V_Z = 20;// in V R_L = 1.2;// in K ohm R_L = R_L * 10^3;// in ohm R = 220;// in ohm I_ZM = 60;// in mA I_ZM= I_ZM*10^-3;// in A Vi_min = (R_L + R)/R_L*V_Z;// in V disp(Vi_min,"The minimum value of Vi in V is"); V_L= V_Z;// in V I_L= V_L/R_L;// in A Vi_max= (I_ZM+I_L)*R+V_Z;// in V disp(Vi_max,"The maximum value of Vi in V is");
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//Chapter-5,Example 5_9,Page 5-28 clc() //Given data: //We have alpha particle,neutron,proton and electron. //To find: shortest wavelength printf('We know, lam=h/sqrt(2*m*E) //de Broglie wavelength \n \n') //Wavelength is inversely proportional to mass of particle for constant energy printf(' i.e., Wavelength is inversely proportional to mass of particle for constant energy. \n \n') printf(' We have alpha particle,neutron,proton and electron. \n \n') //AS,alpha particle has highest mass.Thus it will have shortest wavelength. printf(' Out of above, alpha particle has highest mass. \n \n') printf(' Hence it will have shortest wavelength. \n \n')
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//Example 4.27 //use of flags with integers and floating point numbers i = 123; x = 12.0; y = -3.3; printf(": %6d %7.0f %10.1e: \n\n", i, x, y); printf(": %-6d %-7.0f %-10.1e: \n\n", i, x, y); printf(": %+6d %+7.0f %+10.1e: \n\n", i, x, y); printf(": %-+6d %-+7.0f %-+10.1e: \n\n", i, x, y); printf(":%7.0f %#7.0f %7g %#7g:", x, x, y, y);
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clc; close(); clear(); //page no 608 //prob no. 19.6 code=[0 1 0 1 1 0]; t=[0:.01:2] //for x-axis a=[sin(2*%pi.*t)] //for y-axis y=[] x=[] for i=1:length(code) if code(i)==1 then a=-a; end y=[y a] x=[x 2*%pi.*(t+2*(i-1))] end clf plot(x,y) a=gca(); // Handle on axes entity a.x_location = "origin"; a.y_location = "origin"; xtitle('DPSK used to encode 010110','Time','amplitude') xgrid
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filter_definition_zeroHoldEverySecond.sce
// Second order linear state space system derived from a transfer function // with natural frequency 1Hz = 6.28 rad/s , damping 0.9 , // sample rate of 50Hz // // x_n = A*x + b*u // y = c*x + d*u // // Matlab code: // fcm_tf = tf(2*pi*2*pi,[1, 2*0.9*2*pi,2*pi*2*pi]) // fcm_ss = ss(fcm_tf) // fcm_dis = ss(c2d(fcm_tf, 1/50,'matched')) // x_init = (eye(size(fcm_dis.a))-fcm_dis.a)\fcm_dis.b T_0 = 10; //0.1Hz T_1 = 2; //0.5Hz T_2 = 0.2; //5Hz T_3 = 0.0125; //80Hz k_T0 = 0.5; k_T1 = 1; k_T2 = 0.1; k_T3 = 3; tau_T0 = 15; //in i, not in t(i) T_missingSample = 2; // in i, not in t(i) f_dscr = 50; //Hz t = 0:0.02:20; t25hz = 0:0.04:20; u = zeros(1,1001); s=poly(0,'s'); tf = (4*%pi*%pi)/(s^2 + 2*0.9*2*%pi*s + 4*%pi*%pi); ss50hz = syslin('c', tf); ss50hz_dscr = dscr(ss50hz, 1/f_dscr); //0.02 ss25hz = syslin('c', tf); ss25hz_dscr = dscr(ss25hz, 2/f_dscr); //0.04 for i = 1:1001 u(i) = sin(t(i)*2*%pi/T_0)*k_T0; u(i) = u(i) + sin(t(i)*2*%pi/T_1)*k_T1; u(i) = u(i) + sin(t(i)*2*%pi/T_2)*k_T2; u(i) = u(i) + sin(t(i)*2*%pi/T_3)*k_T3; end flt50hz = dsimul(ss50hz_dscr,u); //every second sample substituted by zero hold for i = 1:1001 if (modulo(i,T_missingSample) == 0) then u_zh(i) = u(i-1); else u_zh(i) = u(i); end end flt50hz_zh = dsimul(ss50hz_dscr,u_zh'); //flt50hz = flts(u,ss50hz_dscr); //same as above //only every second sample fed to 25hz filter for i = 1:501 u25hz(i) = u(2*i - 1); end flt25hz = dsimul(ss25hz_dscr,u25hz'); //normalize by removing lowest frequency: for i = 1:(1001 - tau_T0) norm_flt50hz(i+tau_T0) = flt50hz(i+tau_T0) - sin(t(i)*2*%pi/T_0)*k_T0; end scf(1); clf(); plot(t,flt50hz(:),'b-'); plot(t,u(:),'g-'); plot(t,flt50hz_zh(:),'r-'); plot(t25hz,flt25hz(:),'y-'); //plot(t,norm_flt50hz(:),'y-'); xtitle("filter 50Hz"); axis = gca(); axis.data_bounds = [0 -2; 20 2];
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//(2.5) A silicon chip measuring 5 mm on a side and 1 mm in thickness is embedded in a ceramic substrate. At steady state, the chip has an electrical power input of 0.225 W. The top surface of the chip is exposed to a coolant whose temperature is 20 degree Celcius . The heat transfer coefficient for convection between the chip and the coolant is 150 W/m2 K. If heat transfer by conduction between the chip and the substrate is negligible, determine the surface temperature of the chip, in degree Celcius. // solution //variable initialization s=5*(10^-3); //measurement on a side in meter wdot = -.225 //power input in watt Tf = 293 //coolant temprature in kelvin h = 150 //heat transfer coefficient in w/m2 k A = s^2; //surface area Tb = ((-wdot/(h*A)) + Tf - 273) ; //surface temperature in degree printf('the surface temperature of the chip in degree celcius is:\n\t Tb = %f',Tb);
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//Example 6.14 clc clear x = [1 3 4 6]; y = [-3 0 30 132]; n = length(x); Y = 0; X = poly(0, "X"); //X = 5; for i = 1:n t = x; t(i) = []; p = 1; for j = 1:length(t) p = p * (X-t(j))/(x(i)-t(j)); end Y = Y + p*y(i); end Y5 = horner(Y,5); disp(Y5,"y(5) = ")
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// Chapter 10_Fundamentals of the Metal Oxide Semiconductor Field Effect Transistor //Caption_Work function //Ex_2//page 437 phi_m=3.2 //work function for Al-Si junction xi=3.25 //oxide electron affinity Eg=1.11 ni=1.5*10^10 //intrinsic carrier concentration Na=10^14 phi_fp=0.0259*log(Na/ni) phi_ms=phi_m-(xi+Eg/(2)+phi_fp) printf('Metal semiconductor work function difference is %1.2f V',phi_ms)
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#************************************************************ # Scenario of Ikea # # date : Mon Sep 27 17:34:24 2010 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT HUMAN_ACHILE p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.600000 -1.630000 0.760000 -0.060000 0.830000 59.620000 0.000000 0.000000 14.540000 -30.350000 9.770000 7.740000 25.700000 22.460000 24.390000 98.000000 34.110000 -148.270000 -8.210000 -76.970000 30.000000 -4.790000 -34.400000 0.000000 -100.420000 0.000000 4.320000 -80.930000 8.000000 84.360000 0.000000 0.000000 0.000000 4.760000 -83.140000 -0.210000 94.570000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT ROBOT_PR2 p3d_set_robot_steering_method R&S+linear p3d_set_robot_radius 0.300000 p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.810000 -0.490000 0.000000 0.000000 0.000000 -95.000000 0.000000 7.170000 -16.600000 51.550000 18.580000 107.360000 -126.240000 0.000000 -46.520000 0.000000 0.000000 0.000000 0.000000 -0.810000 25.760000 -1.520000 -49.880000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.810000 -0.490000 0.000000 0.000000 0.000000 -95.000000 0.000000 -52.650000 -24.240000 51.550000 18.580000 107.360000 -126.240000 0.000000 -46.520000 0.000000 0.000000 0.000000 18.190000 -48.580000 -2.500000 -75.980000 -36.020000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_constraint p3d_fixed_jnt 1 5 0 1 51.550000 0 p3d_constraint p3d_fixed_jnt 1 6 0 1 18.580000 0 p3d_constraint p3d_fixed_jnt 1 7 0 1 107.360000 0 p3d_constraint p3d_fixed_jnt 1 8 0 1 -126.240000 0 p3d_constraint p3d_fixed_jnt 1 9 0 1 0.000000 0 p3d_constraint p3d_fixed_jnt 1 10 0 1 -46.520000 0 p3d_constraint p3d_fixed_jnt 1 11 0 1 0.000000 0 p3d_constraint p3d_fixed_jnt 1 1 0 6 1.810000 -0.490000 0.000000 0.000000 0.000000 -95.000000 0 p3d_sel_desc_name P3D_ROBOT Lampe p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.220000 -1.270000 0.770000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT Assiette p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.020000 -1.470000 0.787611 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT Pommes p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.442478 -1.622419 0.762537 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT Verre p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.800000 1.900000 0.940000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT Tabouret p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.460000 -0.150000 0.000000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT sailLamp1 p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.060000 -0.690000 2.950000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT sailLamp2 p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.060000 -0.390000 2.950000 0.000000 0.000000 0.000000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_sel_desc_name P3D_ROBOT sailLamp3 p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 1.060000 -0.090000 2.950000 0.000000 0.000000 -19.300000 p3d_set_robot_goto 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 p3d_set_camera_pos 1.668182 -0.861277 0.709835 2.505719 6.001935 0.935000 0.000000 0.000000 1.000000 0.000000
fc0ba58e2f993ae4e0cd01377c1012ea6506316b
449d555969bfd7befe906877abab098c6e63a0e8
/2219/CH3/EX3.16/Ex3_16.sce
6e2aa3e0a9d09687c3beca9689e496cbd6190139
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FOSSEE/Scilab-TBC-Uploads
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refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
37,975,407
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856
sce
Ex3_16.sce
// Chapter 3 example 16 //------------------------------------------------------------------------------ clc; clear; // Given data a = 7.2 ; // width of waveguide in cm b = 3.4; // narrow dimension of waveguide in cm c = 3*10^10; // free space velocity of EM wave in cm/s f = 2.4*10^9; // frequency in Hz // Calculation lamda = c/f // free space wavelength in cm lamda_c = 2*a // cutoff wavelength in cm lamda_g = lamda/sqrt(1 - (lamda/lamda_c)^2); // guide wavelength in cm vp = (lamda_g * c)/lamda // phase velocity in cm/s vg = c^2/vp; // group velocity in cm/s // Output mprintf('Group velocity = %3.1e cm/s\n Phase Velocity = %3.1e cm/s',vg,vp); //------------------------------------------------------------------------------
b495adc7def470b83f0041786c57ebdbf531996f
449d555969bfd7befe906877abab098c6e63a0e8
/3871/CH3/EX3.13/Ex3_13.sce
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no_license
FOSSEE/Scilab-TBC-Uploads
948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1
7bc77cb1ed33745c720952c92b3b2747c5cbf2df
refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
37,975,407
3
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sce
Ex3_13.sce
//=========================================================================== //chapter 3 example 13 clc;clear all; //variable declaration R1 = 1000; //resistance in Ω R2 = 500; //resistance in Ω eR1 = 1; //error resistance eR2 = 1; //error resistance //calculations R = (R1*R2)/(R1+R2); //resistance in Ω X = R1*R2; Y = R1+R2; dX = (eR1+eR2); //error in X //dY = (dR1/Y)+(dR2/Y); //dY = (R1/Y)*(dR1/R1)+((R2/Y)*(dR2/R2) dY = ((R1/(Y))*(eR1))+((R2/(Y))*(eR2)); //error in Y eP = dX+dY; //percentage error in equivaent parallel resistance in % e = R*(eP/(100)); //error(maximum ossible) in equivalent parallel resistance in Ω //result mprintf("percentage error = %3.2f percentage",eP); mprintf("\nerror in equivalent parallel resistance = %3.2f Ω",e);
53e2c6e816ae77c000f4b95263dfe31c4d6392c6
8bc1ab9f1d4165ad25962a8bb841b4e0cc161537
/midproject/test/SBB.TST
4881568af83a83e8eabe25667943db0018cff657
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hyeonjang/scheme-simulation
95779f08da760d726106ce403709f217d5a4a008
45190c9a30ddf8d646500060e75f7e6d14157ecd
refs/heads/master
2023-01-07T05:14:31.351706
2020-11-19T15:57:18
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[2] (load "mbase/sbb.m") Model of type atomic-models with name SBB made. Processor of type simulators with name S:SBB made. OK [3] ;;;first inning (send sbb inject 'pitch 'fiz 5) state s = state s = (5 NONE FIZ 0 0 0 0 5)state s = ()() [4] (send sbb int-transition) state s = state s = (5 NONE FIZ 0 1 0 0 5)state s = ()() [5] (send sbb int-transition) state s = state s = (5 1ST FIZ 0 0 0 0 5)state s = ()() [6] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 0 0 0 5)state s = ()() [7] (send sbb int-transition) state s = state s = (5 3RD FIZ 0 0 0 1 5)state s = ()() [8] (send sbb int-transition) state s = state s = (5 3RD FIZ 0 1 0 1 5)state s = ()() [9] (send sbb int-transition) state s = state s = (5 1ST FIZ 0 0 0 2 5)state s = ()() [10] (send sbb int-transition) state s = state s = (5 1ST FIZ 0 1 0 2 5)state s = ()() [11] (send sbb int-transition) state s = state s = (5 1ST-2ND FIZ 0 0 0 2 5)state s = ()() [12] (send sbb int-transition) state s = state s = (5 1ST-2ND FIZ 0 1 0 2 5)state s = ()() [13] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 0 0 2 5)state s = ()() [14] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 1 0 2 5)state s = ()() [15] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 2 0 2 5)state s = ()() [16] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 0 1 2 5)state s = ()() [17] (send sbb int-transition) state s = state s = (5 2ND-3RD FIZ 0 1 1 2 5)state s = ()() [18] (send sbb int-transition) state s = state s = (5 3RD FIZ 0 0 1 3 5)state s = ()() [19] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 0 1 5 5)state s = ()() [20] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 1 1 5 5)state s = ()() [21] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 2 1 5 5)state s = ()() [22] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 0 2 5 5)state s = ()() [23] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 1 2 5 5)state s = ()() [24] (send sbb int-transition) state s = state s = (5 3RD FIZ 0 0 2 5 5)state s = ()() [25] (send sbb int-transition) state s = state s = (5 3RD FIZ 0 1 2 5 5)state s = ()() [26] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 0 2 7 5)state s = ()() [27] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 1 2 7 5)state s = ()() [28] (send sbb int-transition) state s = state s = (5 2ND FIZ 0 2 2 7 5)state s = ()() [29] (send sbb int-transition) state s = state s = (INF PASSIVE FIZ 0 0 3 7 5)state s = ()() [30] (send sbb output?) output y = output y = OUT 7#(((|#!STRUCTURE| . CONTENT)) OUT 7) [31] ;;; second inning (send sbb inject 'pitch 'foz 5) state s = state s = (5 NONE FOZ 0 0 0 7 5)state s = ()() [32] (send sbb int-transition) state s = state s = (5 2ND FOZ 0 0 0 7 5)state s = ()() [33] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 0 7 5)state s = ()() [34] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 1 0 7 5)state s = ()() [35] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 1 0 7 5)state s = ()() [36] (send sbb int-transition) state s = state s = (5 1ST FOZ 0 0 0 8 5)state s = ()() [37] (send sbb int-transition) state s = state s = (5 1ST FOZ 0 1 0 8 5)state s = ()() [38] (send sbb int-transition) state s = state s = (5 1ST FOZ 1 1 0 8 5)state s = ()() [39] (send sbb int-transition) state s = state s = (5 1ST FOZ 1 2 0 8 5)state s = ()() [40] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 0 0 8 5)state s = ()() [41] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 1 0 8 5)state s = ()() [42] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 0 0 0 8 5)state s = ()() [43] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 1 0 0 8 5)state s = ()() [44] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 0 9 5)state s = ()() [45] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 0 0 9 5)state s = ()() [46] (send sbb int-transition) state s = state s = (5 1ST FOZ 0 0 0 10 5)state s = ()() [47] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 0 0 10 5)state s = ()() [48] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 1 0 10 5)state s = ()() [49] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 1 1 0 10 5)state s = ()() [50] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 2 1 0 10 5)state s = ()() [51] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 3 1 0 10 5)state s = ()() [52] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 0 0 0 10 5)state s = ()() [53] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 0 11 5)state s = ()() [54] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 0 0 11 5)state s = ()() [55] (send sbb int-transition) state s = state s = (5 3RD FOZ 2 0 0 11 5)state s = ()() [56] (send sbb int-transition) state s = state s = (5 2ND FOZ 0 0 0 13 5)state s = ()() [57] (send sbb int-transition) state s = state s = (5 2ND FOZ 1 0 0 13 5)state s = ()() [58] (send sbb int-transition) state s = state s = (5 2ND FOZ 1 1 0 13 5)state s = ()() [59] (send sbb int-transition) state s = state s = (5 2ND FOZ 1 2 0 13 5)state s = ()() [60] (send sbb int-transition) state s = state s = (5 2ND FOZ 0 0 1 13 5)state s = ()() [61] (send sbb int-transition) state s = state s = (5 2ND FOZ 1 0 1 13 5)state s = ()() [62] (send sbb int-transition) state s = state s = (5 2ND FOZ 2 0 1 13 5)state s = ()() [63] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 1 13 5)state s = ()() [64] (send sbb int-transition) state s = state s = (5 1ST FOZ 0 0 1 14 5)state s = ()() [65] (send sbb int-transition) state s = state s = (5 1ST FOZ 1 0 1 14 5)state s = ()() [66] (send sbb int-transition) state s = state s = (5 1ST FOZ 2 0 1 14 5)state s = ()() [67] (send sbb int-transition) state s = state s = (5 1ST FOZ 2 1 1 14 5)state s = ()() [68] (send sbb int-transition) state s = state s = (5 1ST FOZ 3 1 1 14 5)state s = ()() [69] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 0 1 14 5)state s = ()() [70] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 0 0 1 15 5)state s = ()() [71] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 1 0 1 15 5)state s = ()() [72] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 1 16 5)state s = ()() [73] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 1 1 16 5)state s = ()() [74] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 1 1 16 5)state s = ()() [75] (send sbb int-transition) state s = state s = (5 3RD FOZ 2 1 1 16 5)state s = ()() [76] (send sbb int-transition) state s = state s = (5 3RD FOZ 2 2 1 16 5)state s = ()() [77] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 2 16 5)state s = ()() [78] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 1 2 16 5)state s = ()() [79] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 1 2 16 5)state s = ()() [80] (send sbb int-transition) state s = state s = (5 1ST FOZ 0 0 2 17 5)state s = ()() [81] (send sbb int-transition) state s = state s = (5 1ST FOZ 1 0 2 17 5)state s = ()() [82] (send sbb int-transition) state s = state s = (5 1ST FOZ 2 0 2 17 5)state s = ()() [83] (send sbb int-transition) state s = state s = (5 1ST FOZ 3 0 2 17 5)state s = ()() [84] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 0 2 17 5)state s = ()() [85] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 0 0 2 17 5)state s = ()() [86] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 1 0 2 17 5)state s = ()() [87] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 2 0 2 17 5)state s = ()() [88] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 3 0 2 17 5)state s = ()() [89] (send sbb int-transition) state s = state s = (5 1ST-3RD FOZ 0 0 2 18 5)state s = ()() [90] (send sbb int-transition) state s = state s = (5 1ST-3RD FOZ 1 0 2 18 5)state s = ()() [91] (send sbb int-transition) state s = state s = (5 1ST-3RD FOZ 2 0 2 18 5)state s = ()() [92] (send sbb int-transition) state s = state s = (5 1ST-3RD FOZ 3 0 2 18 5)state s = ()() [93] (send sbb int-transition) state s = state s = (5 1ST-2ND FOZ 0 0 2 19 5)state s = ()() [94] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 0 0 2 19 5)state s = ()() [95] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 1 0 2 19 5)state s = ()() [96] (send sbb int-transition) state s = state s = (5 2ND-3RD FOZ 2 0 2 19 5)state s = ()() [97] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 0 2 20 5)state s = ()() [98] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 1 2 20 5)state s = ()() [99] (send sbb int-transition) state s = state s = (5 3RD FOZ 0 2 2 20 5)state s = ()() [100] (send sbb int-transition) state s = state s = (5 3RD FOZ 1 2 2 20 5)state s = ()() [101] (send sbb int-transition) state s = state s = (INF PASSIVE FOZ 0 0 3 20 5)state s = ()() [102] (send sbb output?) output y = output y = OUT 20#(((|#!STRUCTURE| . CONTENT)) OUT 20) [103] ;;; third inning (send sbb inject 'pitch 'siz 5) state s = state s = (5 NONE SIZ 0 0 0 20 5)state s = ()() [104] (send sbb int-transition) state s = state s = (5 NONE SIZ 0 1 0 20 5)state s = ()() [105] (send sbb int-transition) state s = state s = (5 NONE SIZ 0 2 0 20 5)state s = ()() [106] (send sbb int-transition) state s = state s = (5 1ST SIZ 0 0 0 20 5)state s = ()() [107] (send sbb int-transition) state s = state s = (5 1ST SIZ 0 1 0 20 5)state s = ()() [108] (send sbb int-transition) state s = state s = (5 1ST SIZ 0 2 0 20 5)state s = ()() [109] (send sbb int-transition) state s = state s = (5 1ST SIZ 1 2 0 20 5)state s = ()() [110] (send sbb int-transition) state s = state s = (5 1ST SIZ 2 2 0 20 5)state s = ()() [111] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 0 0 0 20 5)state s = ()() [112] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 0 1 0 20 5)state s = ()() [113] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 0 2 0 20 5)state s = ()() [114] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 0 0 1 20 5)state s = ()() [115] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 0 1 1 20 5)state s = ()() [116] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 1 1 1 20 5)state s = ()() [117] (send sbb int-transition) state s = state s = (5 1ST-2ND SIZ 1 2 1 20 5)state s = ()() [118] (send sbb int-transition) state s = state s = (5 2ND-3RD SIZ 0 0 1 21 5)state s = ()() [119] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 0 1 23 5)state s = ()() [120] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 1 1 23 5)state s = ()() [121] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 0 1 25 5)state s = ()() [122] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 1 1 25 5)state s = ()() [123] (send sbb int-transition) state s = state s = (5 2ND SIZ 1 1 1 25 5)state s = ()() [124] (send sbb int-transition) state s = state s = (5 2ND SIZ 1 2 1 25 5)state s = ()() [125] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 0 2 25 5)state s = ()() [126] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 1 2 25 5)state s = ()() [127] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 0 2 27 5)state s = ()() [128] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 1 2 27 5)state s = ()() [129] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 2 2 27 5)state s = ()() [130] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 0 2 29 5)state s = ()() [131] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 1 2 29 5)state s = ()() [132] (send sbb int-transition) state s = state s = (5 2ND SIZ 0 2 2 29 5)state s = ()() [133] (send sbb int-transition) state s = state s = (INF PASSIVE SIZ 0 0 3 29 5)state s = ()() [134] (send sbb output?) output y = output y = OUT 29#(((|#!STRUCTURE| . CONTENT)) OUT 29) [135] (transcript-off) 
5eaf1df020ccb05800cf955eac7584f01f29d7ba
8217f7986187902617ad1bf89cb789618a90dd0a
/source/2.5/tests/examples/pinv.man.tst
39c92ae6b1d2d5c610bdb2bd6ad6e3e3e02a83dd
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clear;lines(0); A=rand(5,2)*rand(2,4); norm(A*pinv(A)*A-A,1)
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// A simple JSON Writer function JSON = JSONWrite(Struct) endfunction
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LucasHattoriCosta/Poli
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metodo_de_euler_melhorado.sce
clc clear //Condições iniciais s0=0; vs0=1; S0=[s0,vs0]; g=9.78; m=0.033; c=0.01; t0=0; tf=5; teta=(%pi)/6; ro=1.2; Cd=0.3; A=0.0003; //Passo de integração h=0.5; dt=h; t=t0:dt:tf; function dS=f(t,S) ds1=S(2); ds2=g*sin(teta)-(S(2)**2)*(ro)*(Cd)*(A)*(0.5)/(m); dS=[ds1;ds2]; endfunction //Método de Euler melhorado final=length(t)-1; Evs(1)=vs0; Es(1)=s0; Et(1)=t0; Evs2(1)=0-(g*sin(teta)-(vs0**2)*(ro)*(Cd)*(A)*(0.5)/(m))*(dt/2); for i=1:final Evs2(i)=Evs(i)-(g*sin(teta)-(Evs(i)**2)*(ro)*(Cd)*(A)*(0.5)/(m))*(dt/2); Evs(i+1)=Evs(i)+(g*sin(teta)-(Evs2(i)**2)*(ro)*(Cd)*(A)*(0.5)/(m))*(dt); Et(i+1)= dt +Et(i); Es(i+1)=Es(i)+(g*sin(teta)-(Evs2(i)**2)*(ro)*(Cd)*(A)*(0.5)/(m))*(dt); end scf(0) xtitle('Euler:Posição s (m) por tempo para h= '+string(h)+' e para vs0='+string(vs0)); plot(Et,Es,'y') scf(1) xtitle('Euler: Velocidade Vs (m/s)por tempo (s) para h = '+string(h)+' e para vs0 = '+string(vs0)); plot(Et,Evs,'y')
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// Example 1.9 clear; clc; close; format('v',7); // Given data R2=0.04;//in ohm X2=0.2;//in ohm //Calculations R2dash=X2;//in ohm (for Tm=Tst) //formula : R2dash=R2+rex Rex=R2dash-R2;//in ohm/phase disp(Rex,"(i) External resistance required in ohm/phase : "); disp("For Tst=Tm/2, Tm=k*E2^2/2/X2 and Tst=k*E2^2*R2/(R2^2+X2^2)"); disp("This gives a polynomial for value of R2dash."); P=[1 -4*X2 X2^2];//R2dash^2-4*X2*R2dash+X2^2=0 R2dash=roots(P);//in ohm disp(R2dash,"Value of R2dash(ohm) are ") disp(R2dash(2),"But R2dash cant be greater than X2, R2dash(ohm) is : "); Rex=R2dash(2)-R2;//in ohm/phase disp(Rex,"(ii) External resistance required in ohm/phase : ");
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/Swisscom_Virtualization_Suite/Tests/tcSendMsgsToQueue.tst
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tcSendMsgsToQueue.tst
<?xml version="1.0" ?> <TestCase name="tcSendMsgsToQueue" version="5"> <meta> <create version="10.0.0" buildNumber="10.0.0.431" author="admin" date="01/24/2017" host="U272282" /> <lastEdited version="10.0.0" buildNumber="10.0.0.431" author="admin" date="01/24/2017" host="U272282" /> </meta> <id>615B447DE22411E695CED6D520524153</id> <Documentation>Put documentation of the Test Case here.</Documentation> <IsInProject>true</IsInProject> <sig>ZWQ9NSZ0Y3Y9LTEmbGlzYXY9MTAuMC4wICgxMC4wLjAuNDMxKSZub2Rlcz0zNTY0Nzg1NTA=</sig> <subprocess>false</subprocess> <initState> </initState> <resultState> </resultState> <Node name="publish_Msgs" log="" type="com.itko.lisa.messaging.jms.JmsSendReceiveStep" version="1" uid="69E14618E22411E695CED6D520524153" think="500-1S" useFilters="true" quiet="false" next="end" > <onExNode>abort</onExNode> <JmsSendReceiveOperation> <OperationInfo> <Name>msg</Name> </OperationInfo> <SendOperation> <OperationInfo> <Name>msg</Name> </OperationInfo> <Destination> <AssetInfo type="javax.jms.Destination" hashcode="-1780350255"><Url>config://dest-3D6044CE22A11E695CED6D520524153</Url> </AssetInfo> <Ref> </Ref> </Destination> <ReplyTo> <Automatic>true</Automatic> </ReplyTo> <Producer> <Automatic>true</Automatic> </Producer> <RuntimeScope>NONE</RuntimeScope> <Message> <PayloadInfo type="javax.jms.Message"></PayloadInfo> <JMSTextMessage> <Payload> <PayloadInfo type="java.lang.String"></PayloadInfo> <String> <Content>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;&#13;&#10;&lt;soapmsg&gt;&#13;&#10; &lt;soapenv:Envelope xmlns:soapenv=&quot;http://schemas.xmlsoap.org/soap/envelope/&quot; xmlns:osit=&quot;http://tibco.swisscom.com/ns/OsiTaskTibco/&quot;&gt;&#13;&#10; &lt;soapenv:Header /&gt;&#13;&#10; &lt;soapenv:Body&gt;&#13;&#10; &lt;osit:wfmStateOsi&gt;&#13;&#10; &lt;taskHeader&gt;&#13;&#10; &lt;osiId&gt;ALL:SUB:10000173833243&lt;/osiId&gt;&#13;&#10; &lt;oeOrderId&gt;5-433867539103&lt;/oeOrderId&gt;&#13;&#10; &lt;requestId&gt;OX.CoPE++cope:cid:4367803##0967160775863972160232552871293144021602@@5-5JBDH4RH&lt;/requestId&gt;&#13;&#10; &lt;appId&gt;100296&lt;/appId&gt;&#13;&#10; &lt;srIntegrationId&gt;SBL:5-433867447070&lt;/srIntegrationId&gt;&#13;&#10; &lt;customerId&gt;88830773&lt;/customerId&gt;&#13;&#10; &lt;/taskHeader&gt;&#13;&#10; &lt;wfmState&gt;&#13;&#10; &lt;stateCode&gt;10&lt;/stateCode&gt;&#13;&#10; &lt;stateText&gt;New&lt;/stateText&gt;&#13;&#10; &lt;stateDate&gt;2016-12-22T12:23:06+01:00&lt;/stateDate&gt;&#13;&#10; &lt;/wfmState&gt;&#13;&#10; &lt;orderedMaterial&gt;&#13;&#10; &lt;matNr&gt;10240230&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;5&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/orderedMaterial&gt;&#13;&#10; &lt;orderedMaterial&gt;&#13;&#10; &lt;matNr&gt;11004399&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;6&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/orderedMaterial&gt;&#13;&#10; &lt;orderedMaterial&gt;&#13;&#10; &lt;matNr&gt;10240230&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;75&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/orderedMaterial&gt;&#13;&#10; &lt;installedMaterial&gt;&#13;&#10; &lt;matNr&gt;10240230&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;5&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/installedMaterial&gt;&#13;&#10; &lt;installedMaterial&gt;&#13;&#10; &lt;matNr&gt;11004399&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;6&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/installedMaterial&gt;&#13;&#10; &lt;installedMaterial&gt;&#13;&#10; &lt;matNr&gt;10240230&lt;/matNr&gt;&#13;&#10; &lt;quantity&gt;1&lt;/quantity&gt;&#13;&#10; &lt;positionNumber&gt;75&lt;/positionNumber&gt;&#13;&#10; &lt;deliveryMode&gt;20&lt;/deliveryMode&gt;&#13;&#10; &lt;/installedMaterial&gt;&#13;&#10; &lt;/osit:wfmStateOsi&gt;&#13;&#10; &lt;/soapenv:Body&gt;&#13;&#10; &lt;/soapenv:Envelope&gt;&#13;&#10;&lt;/soapmsg&gt;</Content> </String> </Payload> </JMSTextMessage> </Message> </SendOperation> <ReceiveOperation> <Disabled>true</Disabled> <OperationInfo> <Name>msg</Name> </OperationInfo> <Destination> <AssetInfo type="javax.jms.Destination" hashcode="-2087201431"><Url>config://dest-5E8D1E20C8F811E6958400059A3C7A00</Url> </AssetInfo> <Ref> </Ref> </Destination> <Consumer> <Automatic>true</Automatic> </Consumer> <Timeout>30</Timeout> <PrepareOnly>false</PrepareOnly> <RuntimeScope>NONE</RuntimeScope> </ReceiveOperation> <ClientCorrelationScheme> <Disabled>true</Disabled> <OperationInfo type="javax.jms.Message"></OperationInfo> <JmsClientMidCid> <OperationInfo> <Name>msg</Name> </OperationInfo> </JmsClientMidCid> </ClientCorrelationScheme> </JmsSendReceiveOperation> <onTimeoutNode>abort</onTimeoutNode> </Node> <Node name="end" log="" type="com.itko.lisa.test.NormalEnd" version="1" uid="615B4483E22411E695CED6D520524153" think="0h" useFilters="true" quiet="true" next="fail" > </Node> <Node name="fail" log="" type="com.itko.lisa.test.Abend" version="1" uid="615B4481E22411E695CED6D520524153" think="0h" useFilters="true" quiet="true" next="abort" > </Node> <Node name="abort" log="" type="com.itko.lisa.test.AbortStep" version="1" uid="615B447FE22411E695CED6D520524153" think="0h" useFilters="true" quiet="true" next="" > </Node> </TestCase>
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# (8*t + 1)^3 = 2 * m^2 + n^2 ? 0 1 1 3^6 = 2 * (2*5)^2 + (23)^2 proper representation by 10^2 + 23^2 = 2 * (2^2*3)^2 + (3*7)^2 = 2 * (2*3^2)^2 + (3^2)^2 [3] 2 17^3 = 2 * (2*17)^2 + (3*17)^2 = 2 * (2*19)^2 + (3^2*5)^2 proper representation by 38^2 + 45^2 [2] 3 5^6 4 3^3*11^3 = 2 * (2*11)^2 + (11*17)^2 = 2 * (2^4*3)^2 + (3*59)^2 = 2 * (2*3*11)^2 + (3*5*11)^2 = 2 * (2^3*11)^2 + (11*13)^2 = 2 * (2*3*17)^2 + (3*41)^2 = 2 * (2^2*29)^2 + (5*19)^2 proper representation by 116^2 + 95^2 = 2 * (2^2*3*11)^2 + (3*11)^2 = 2 * (2*67)^2 + (5)^2 proper representation by 134^2 + 5^2 [8] 5 41^3 = 2 * (2^2*5)^2 + (3^2*29)^2 proper representation by 20^2 + 261^2 = 2 * (2^2*41)^2 + (3*41)^2 [2] 6 7^6 7 3^3*19^3 = 2 * (2^3*3)^2 + (3*11*13)^2 = 2 * (2*3*19)^2 + (3*7*19)^2 = 2 * (2^2*43)^2 + (5*71)^2 proper representation by 172^2 + 355^2 = 2 * (2^2*3*19)^2 + (3*5*19)^2 = 2 * (2*7*19)^2 + (11*19)^2 = 2 * (2*139)^2 + (5^2*7)^2 proper representation by 278^2 + 175^2 = 2 * (2*3*7^2)^2 + (3*37)^2 = 2 * (2^4*19)^2 + (19)^2 [8] 8 5^3*13^3 9 73^3 = 2 * (2*3^2*23)^2 + (5*43)^2 proper representation by 414^2 + 215^2 = 2 * (2*3*73)^2 + (73)^2 [2] 10 3^12 = 2 * (2*3*11)^2 + (3*241)^2 = 2 * (2*3^3*5)^2 + (3^3*23)^2 = 2 * (2^2*3^4)^2 + (3^4*7)^2 = 2 * (2^2*5*23)^2 + (7*47)^2 proper representation by 460^2 + 329^2 = 2 * (2*3^5)^2 + (3^5)^2 = 2 * (2^3*3^2*7)^2 + (3^2*17)^2 [6] 11 89^3 = 2 * (2*89)^2 + (3^2*89)^2 = 2 * (2*5*47)^2 + (3^3*19)^2 proper representation by 470^2 + 513^2 [2] 12 97^3 = 2 * (2*3^2)^2 + (5*191)^2 proper representation by 18^2 + 955^2 = 2 * (2*3*97)^2 + (5*97)^2 [2] 13 3^3*5^3*7^3 14 113^3 = 2 * (2^2*113)^2 + (3^2*113)^2 = 2 * (2^2*211)^2 + (3^3*5)^2 proper representation by 844^2 + 135^2 [2] 15 11^6 = 2 * (2*3^2*5^2)^2 + (7*167)^2 proper representation by 450^2 + 1169^2 = 2 * (2*3*11^2)^2 + (7*11^2)^2 = 2 * (2^2*3*7*11)^2 + (11*23)^2 [3] 16 3^3*43^3 = 2 * (2*3*13)^2 + (3*487)^2 = 2 * (2*3*43)^2 + (3*11*43)^2 = 2 * (2*5*43)^2 + (31*43)^2 = 2 * (2*5*71)^2 + (11*97)^2 proper representation by 710^2 + 1067^2 = 2 * (2^2*5*43)^2 + (19*43)^2 = 2 * (2^2*3*79)^2 + (3*197)^2 = 2 * (2^3*5^3)^2 + (383)^2 proper representation by 1000^2 + 383^2 = 2 * (2^3*3*43)^2 + (3*43)^2 [8] 17 137^3 = 2 * (2^3*101)^2 + (3^2*5^3)^2 proper representation by 808^2 + 1125^2 = 2 * (2^3*137)^2 + (3*137)^2 [2] 18 5^3*29^3 19 3^6*17^3 = 2 * (2*3*17)^2 + (3*17*37)^2 = 2 * (2*3*43)^2 + (3*619)^2 = 2 * (2^4*17)^2 + (17*109)^2 = 2 * (2^3*53)^2 + (5*359)^2 proper representation by 424^2 + 1795^2 = 2 * (2^2*3^2*13)^2 + (3^2*197)^2 = 2 * (2^2*3^2*17)^2 + (3^2*11*17)^2 = 2 * (2*3^3*17)^2 + (3^4*17)^2 = 2 * (2*3^3*19)^2 + (3^5*5)^2 = 2 * (2^7*3^2)^2 + (3^2*107)^2 = 2 * (2^3*3^2*17)^2 + (3^2*5*17)^2 = 2 * (2^2*17*19)^2 + (17*29)^2 = 2 * (2^2*331)^2 + (5^2*11)^2 proper representation by 1324^2 + 275^2 = 2 * (2*3*13*17)^2 + (3*5*17)^2 = 2 * (2*3*223)^2 + (3*11)^2 [14] 20 7^3*23^3 21 13^6 22 3^3*59^3 = 2 * (2^3*19)^2 + (5*7*67)^2 proper representation by 152^2 + 2345^2 = 2 * (2*3*59)^2 + (3*13*59)^2 = 2 * (2^2*3*7*11)^2 + (3*653)^2 = 2 * (2*499)^2 + (5*13*29)^2 proper representation by 998^2 + 1885^2 = 2 * (2*11*59)^2 + (5^2*59)^2 = 2 * (2^3*3*59)^2 + (3*7*59)^2 = 2 * (2*3*269)^2 + (3*193)^2 = 2 * (2^2*7*59)^2 + (5*59)^2 [8] 23 5^3*37^3 24 193^3 = 2 * (2*3*193)^2 + (11*193)^2 = 2 * (2*3^2*97)^2 + (5*11*19)^2 proper representation by 1746^2 + 1045^2 [2] 25 3^3*67^3 = 2 * (2^3*67)^2 + (41*67)^2 = 2 * (2^2*3*67)^2 + (3*13*67)^2 = 2 * (2^5*3*11)^2 + (3*809)^2 = 2 * (2*3*211)^2 + (3*739)^2 = 2 * (2*11*67)^2 + (29*67)^2 = 2 * (2^2*5^2*19)^2 + (13*73)^2 proper representation by 1900^2 + 949^2 = 2 * (2*5*197)^2 + (599)^2 proper representation by 1970^2 + 599^2 = 2 * (2*3*5*67)^2 + (3*67)^2 [8] 26 11^3*19^3 = 2 * (2*19)^2 + (3*19*53)^2 = 2 * (2*11*41)^2 + (3*11*83)^2 = 2 * (2^3*5*23)^2 + (3^3*101)^2 proper representation by 920^2 + 2727^2 = 2 * (2^2*13*19)^2 + (3*19*47)^2 = 2 * (2^3*11*19)^2 + (3^2*11*19)^2 = 2 * (2*5*173)^2 + (3^2*197)^2 proper representation by 1730^2 + 1773^2 = 2 * (2^2*11*47)^2 + (3*11*23)^2 = 2 * (2*5*11*19)^2 + (3*11*19)^2 [8] 27 7^3*31^3 28 3^6*5^6 = 2 * (2*5^4)^2 + (5^3*23)^2 = 2 * (2^2*3*5^3)^2 + (3*5^3*7)^2 = 2 * (2*3^2*5^3)^2 + (3^2*5^3)^2 [3] 29 233^3 = 2 * (2*233)^2 + (3*5*233)^2 = 2 * (2*23*29)^2 + (3^2*5*67)^2 proper representation by 1334^2 + 3015^2 [2] 30 241^3 = 2 * (2*3*241)^2 + (13*241)^2 = 2 * (2*3^2*5*29)^2 + (13*47)^2 proper representation by 2610^2 + 611^2 [2] 31 3^3*83^3 = 2 * (2^2*83)^2 + (47*83)^2 = 2 * (2*5*53)^2 + (7*19*29)^2 proper representation by 530^2 + 3857^2 = 2 * (2*7*83)^2 + (43*83)^2 = 2 * (2*3*7*31)^2 + (3*13*89)^2 = 2 * (2^3*5*47)^2 + (11*263)^2 proper representation by 1880^2 + 2893^2 = 2 * (2^3*3*83)^2 + (3*11*83)^2 = 2 * (2*3*5*83)^2 + (3*7*83)^2 = 2 * (2^2*3*229)^2 + (3*193)^2 [8] 32 257^3 = 2 * (2^2*257)^2 + (3*5*257)^2 = 2 * (2^2*643)^2 + (3^2*5*43)^2 proper representation by 2572^2 + 1935^2 [2] 33 5^3*53^3 34 3^3*7^3*13^3 35 281^3 = 2 * (2*5*43)^2 + (3^3*173)^2 proper representation by 430^2 + 4671^2 = 2 * (2*5*281)^2 + (3^2*281)^2 [2] 36 17^6 = 2 * (2^3*3*17)^2 + (7*17*41)^2 = 2 * (2^2*3^2*5*19)^2 + (863)^2 proper representation by 3420^2 + 863^2 = 2 * (2^2*3*17^2)^2 + (17^2)^2 [3] 37 3^9*11^3 = 2 * (2^2*3*11)^2 + (3*5*11*31)^2 = 2 * (2*3^3*11)^2 + (3^3*11*17)^2 = 2 * (2*3^2*37)^2 + (3^2*13*43)^2 = 2 * (2^2*3^2*31)^2 + (3^2*541)^2 = 2 * (2^4*3^4)^2 + (3^4*59)^2 = 2 * (2^2*11*31)^2 + (11*431)^2 = 2 * (2*859)^2 + (5*17*53)^2 proper representation by 1718^2 + 4505^2 = 2 * (2*3^4*11)^2 + (3^4*5*11)^2 = 2 * (2^3*3^3*11)^2 + (3^3*11*13)^2 = 2 * (2*3*11*41)^2 + (3*11*103)^2 = 2 * (2*3^4*17)^2 + (3^4*41)^2 = 2 * (2*3*479)^2 + (3*17*61)^2 = 2 * (2^3*379)^2 + (5*13*43)^2 proper representation by 3032^2 + 2795^2 = 2 * (2^2*3^3*29)^2 + (3^3*5*19)^2 = 2 * (2^5*3^2*11)^2 + (3^2*5^2*11)^2 = 2 * (2*3^2*11*17)^2 + (3^2*11*19)^2 = 2 * (2*11*157)^2 + (11*139)^2 = 2 * (2^2*3^4*11)^2 + (3^4*11)^2 = 2 * (2^3*3*149)^2 + (3*263)^2 = 2 * (2*3^3*67)^2 + (3^3*5)^2 [20] 38 5^3*61^3 39 313^3 = 2 * (2^2*3^2*71)^2 + (5*839)^2 proper representation by 2556^2 + 4195^2 = 2 * (2^2*3*313)^2 + (5*313)^2 [2] 40 3^3*107^3 = 2 * (2*3*179)^2 + (3*43^2)^2 = 2 * (2^2*3*107)^2 + (3*17*107)^2 = 2 * (2*5*163)^2 + (11*479)^2 proper representation by 1630^2 + 5269^2 = 2 * (2*3*5*107)^2 + (3*11*107)^2 = 2 * (2^2*5*167)^2 + (17*193)^2 proper representation by 3340^2 + 3281^2 = 2 * (2^5*107)^2 + (29*107)^2 = 2 * (2^3*3*13^2)^2 + (3*139)^2 = 2 * (2*19*107)^2 + (107)^2 [8] 41 7^3*47^3 42 337^3 = 2 * (2^2*3^2*47)^2 + (5*7*163)^2 proper representation by 1692^2 + 5705^2 = 2 * (2^2*3*337)^2 + (7*337)^2 [2] 43 3^3*5^3*23^3 44 353^3 = 2 * (2^3*353)^2 + (3*5*353)^2 = 2 * (2^3*547)^2 + (3^2*5*53)^2 proper representation by 4376^2 + 2385^2 [2] 45 19^6 = 2 * (2*3*19^2)^2 + (17*19^2)^2 = 2 * (2^2*3*17*19)^2 + (7*19*31)^2 = 2 * (2*3^2*5*53)^2 + (17*73)^2 proper representation by 4770^2 + 1241^2 [3] 46 3^6*41^3 = 2 * (2^2*3^3*5)^2 + (3^5*29)^2 = 2 * (2*3^2*41)^2 + (3^2*19*41)^2 = 2 * (2^4*3*41)^2 + (3*41*53)^2 = 2 * (2*5^2*43)^2 + (19*337)^2 proper representation by 2150^2 + 6403^2 = 2 * (2*31*41)^2 + (41*149)^2 = 2 * (2^3*3*113)^2 + (3*1987)^2 = 2 * (2*5*307)^2 + (13*431)^2 proper representation by 3070^2 + 5603^2 = 2 * (2^5*3*37)^2 + (3*1667)^2 = 2 * (2*3^2*5*41)^2 + (3^2*13*41)^2 = 2 * (2^2*3^3*41)^2 + (3^4*41)^2 = 2 * (2*3^2*251)^2 + (3^2*11*31)^2 = 2 * (2*3^2*271)^2 + (3^2*181)^2 = 2 * (2^3*3*5*41)^2 + (3*11*41)^2 = 2 * (2*41*61)^2 + (11*41)^2 [14] 47 13^3*29^3 48 5^3*7^3*11^3 49 3^3*131^3 = 2 * (2^3*3*43)^2 + (3*2551)^2 = 2 * (2^2*3*131)^2 + (3*19*131)^2 = 2 * (2^4*131)^2 + (5*11*131)^2 = 2 * (2^2*1051)^2 + (5*19*53)^2 proper representation by 4204^2 + 5035^2 = 2 * (2*17*131)^2 + (5*7*131)^2 = 2 * (2*3*13*61)^2 + (3*7*11*17)^2 = 2 * (2*7*389)^2 + (5^2*47)^2 proper representation by 5446^2 + 1175^2 = 2 * (2*3*7*131)^2 + (3*131)^2 [8] 50 401^3 = 2 * (2*5*7*73)^2 + (3^2*389)^2 proper representation by 5110^2 + 3501^2 = 2 * (2*7*401)^2 + (3*401)^2 [2] 51 409^3 = 2 * (2^2*3^2*5^2)^2 + (11*743)^2 proper representation by 900^2 + 8173^2 = 2 * (2^2*3*409)^2 + (11*409)^2 [2] 52 3^3*139^3 = 2 * (2^2*139)^2 + (61*139)^2 = 2 * (2*3*149)^2 + (3*7*401)^2 = 2 * (2^3*3*139)^2 + (3*17*139)^2 = 2 * (2*13*139)^2 + (7^2*139)^2 = 2 * (2*7*317)^2 + (5*1151)^2 proper representation by 4438^2 + 5755^2 = 2 * (2^2*3*443)^2 + (3*31*43)^2 = 2 * (2*3*7*139)^2 + (3*5*139)^2 = 2 * (2^3*739)^2 + (5*17*19)^2 proper representation by 5912^2 + 1615^2 [8] 53 5^6*17^3 = 2 * (2*5^3*17)^2 + (3*5^3*17)^2 = 2 * (2*5^3*19)^2 + (3^2*5^4)^2 [2] 54 433^3 = 2 * (2*3*433)^2 + (19*433)^2 = 2 * (2*3^2*337)^2 + (5*19*29)^2 proper representation by 6066^2 + 2755^2 [2] 55 3^6*7^6 = 2 * (2*5*7^3)^2 + (7^3*23)^2 = 2 * (2^2*3*7^3)^2 + (3*7^4)^2 = 2 * (2*3^2*7^3)^2 + (3^2*7^3)^2 [3] 56 449^3 = 2 * (2*449)^2 + (3*7*449)^2 = 2 * (2*5*263)^2 + (3^2*7*139)^2 proper representation by 2630^2 + 8757^2 [2] 57 457^3 = 2 * (2^2*3^2*73)^2 + (5*13*139)^2 proper representation by 2628^2 + 9035^2 = 2 * (2^2*3*457)^2 + (13*457)^2 [2] 58 3^3*5^3*31^3 59 11^3*43^3 = 2 * (2^2*11*43)^2 + (3*7*11*43)^2 = 2 * (2*7*149)^2 + (3^3*5*73)^2 proper representation by 2086^2 + 9855^2 = 2 * (2^4*11*23)^2 + (3*7*11*37)^2 = 2 * (2*7^2*43)^2 + (3*5*13*43)^2 = 2 * (2^2*1291)^2 + (3^2*5*7*23)^2 proper representation by 5164^2 + 7245^2 = 2 * (2^3*19*43)^2 + (3*5*7*43)^2 = 2 * (2*7*11*43)^2 + (3^2*11*43)^2 = 2 * (2*7*11*47)^2 + (3*11*31)^2 [8] 60 13^3*37^3 61 3^3*163^3 = 2 * (2*3*11*43)^2 + (3*3347)^2 = 2 * (2^3*3*163)^2 + (3*19*163)^2 = 2 * (2*3*5*163)^2 + (3*17*163)^2 = 2 * (2^2*3*479)^2 + (3*2377)^2 = 2 * (2*5*23*29)^2 + (17*311)^2 proper representation by 6670^2 + 5287^2 = 2 * (2^2*11*163)^2 + (23*163)^2 = 2 * (2*23*163)^2 + (13*163)^2 = 2 * (2^3*5*191)^2 + (19*23)^2 proper representation by 7640^2 + 437^2 [8] 62 7^3*71^3 63 5^3*101^3
5d34d1ed14c45d02d99ae1a931e23842738bf950
449d555969bfd7befe906877abab098c6e63a0e8
/1076/CH16/EX16.4/16_4.sce
f1fa4e6116e25079dcd75eadc2a61f4d17138a00
[]
no_license
FOSSEE/Scilab-TBC-Uploads
948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1
7bc77cb1ed33745c720952c92b3b2747c5cbf2df
refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
37,975,407
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398
sce
16_4.sce
clear clc l=300 l1=120 l3=120 l2=l-l1-l3 U=.25 Ic1=40 Id1=60 r=.1/100 r1=l1*r; r2=l2*r r3=l3*r Va=300 Vb=300 dV=abs(Va-Vb) Ia=(dV+(r1*.5*U*l1)+(r2*.5*U*l2)+(r3*.5*U*l3)+(r2*(Ic1+U*l1))+(r3*(Ic1+U*l1 +Id1+U*l2)))/(r1+r2+r3) I=Ic1+Id1+(U*l) Ib=I-Ia Vc=Va-(Ia-.5*U*l1)*r1 Vd=Vb-((Ib-.5*U*l3)*r3) mprintf("IA= %.1f A, IB=%.1fA, Vc=%.2f V, Vd=%.2f V", Ia, Ib, Vc,Vd)
24679cb2c53a1ffd079e0fc3e237ee4127f4e3f7
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/2579/CH5/EX5.8/Ex5_8.txt
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FOSSEE/Scilab-TBC-Uploads
948e5d1126d46bdd2f89a44c54ba62b0f0a1f5e1
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refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
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Ex5_8.txt
//Ex:5.8 clc; clear; close; ht=100;// transmeter height in m hr=50;// receiver height in m d=1.4142*(sqrt(ht)+sqrt(hr));// max range in miles printf("The max range = %f miles", d);
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/Project 2/Experiments/FURIA-C/results/FURIA-C.vowel-10-1tra/result2s0.tst
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no_license
nickgreenquist/Intro_To_Intelligent_Systems
964cad20de7099b8e5808ddee199e3e3343cf7d5
7ad43577b3cbbc0b620740205a14c406d96a2517
refs/heads/master
2021-01-20T13:23:23.931062
2017-05-04T20:08:05
2017-05-04T20:08:05
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute F6 real[-1.537,1.403] @attribute F7 real[-1.293,2.039] @attribute F8 real[-1.613,1.309] @attribute F9 real[-1.68,1.396] @attribute Class{0,1,2,3,4,5,6,7,8,9,10} @inputs TT,SpeakerNumber,Sex,F0,F1,F2,F3,F4,F5,F6,F7,F8,F9 @outputs Class @data 1 2 7 7 5 4 10 10 6 6 9 8 6 6 0 0 5 5 8 8 4 6 3 3 5 5 0 0 9 9 10 10 5 4 10 5 6 6 1 1 4 4 5 5 10 10 3 2 0 0 8 8 6 6 8 10 3 3 0 0 7 6 3 3 4 4 4 4 7 8 3 3 4 4 10 5 6 6 1 1 2 2 10 10 1 1 1 9 5 8 7 7 9 9 2 2 9 9 6 6 7 7 3 3 5 5 8 8 1 1 3 3 7 7 4 4 7 7 8 8 2 2 4 4 2 2 7 7 9 9 4 4 9 9 8 8 2 2 2 2 10 8 0 0 9 9 10 8 7 8 5 5 6 6 1 1 3 3 10 10 0 0 8 8 6 6 6 4 0 0 3 5 4 4 9 1 1 1 9 9 8 8 5 4 0 0 2 1 2 2 0 0 1 1 2 2 8 8
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youndoldman/FuzzyEnergy
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2021-06-21T02:54:57.234859
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//Solution 12-4 WD=get_absolute_file_path('12_04_solution.sce'); datafile=WD+filesep()+'12_04_example.sci'; clc; exec(datafile) //unit conversions P_i = P_i * 10**6; //from [MPa] to [Pa] c_p = c_p * 10**3; //from [kJ/kg.K] to [J/kg.K] T_i = T_i + 273; //from [C] to [K] A = A * 10**-4; //from [cm^2] to [m^2] R = R * 10**3; //from [kJ/kg.K] to [J/kg.K] P_b = P_b * 10**6 //from [MPa] to [Pa] T_0i = T_i + V_i**2 / (2 * c_p); //stagnation temperature P_0i = P_i * (T_0i / T_i)**(k / (k-1)); //stagnation pressure //As flow is assumed isentropic T_0 = T_0i; P_0 = P_0i; P_crit = 0.5283; //critical pressure ratio for air from table 12-2 //(a) for i=1:1:2 P_back = P_b(i) / P_0; //back pressure ratio printf("\nFor back pressure of %1.2f Pa\n", P_b(i)); if P_back >= P_crit then P_t = P_b(i); //exit pressure equals back pressure printf("The flow is not chocked\n"); Ma_t = sqrt(((1 / P_back)**((k -1) / k) - 1) * 2 / ( k - 1)); //Mach number T_t = (1 + (k - 1) / 2 * Ma**2)**-1 * T_0; //Temperature at throat of nozzle rho_t = P_t / (R * T_t); //from ideal gas equation V_t = Ma_t * sqrt(k * R * T_t); //air velocity mdot = rho_t * A * V_t; else printf("The flow is chocked\n"); Ma = 1; mdot = A * P_0 * sqrt(k / (R * T_0)) * (2 / (k + 1))**((k+1) / (2*(k - 1))); end printf("The mass flow rate of air through the nozzle is %1.2f kg/s", mdot); end
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//Jet of water //refer fig. 14.18 and 14.19 //time taken to move a horizontal distance of 5m t=5/20 //sec //During this period vertical downward velocity gained by water (Vw) Vw=0+(9.81/4) //Horizontal component of velocity of plate (HCp) HCp=0 //Vertical component of velocity of plate (VCp) VCp=1 //m/sec //relative velocity of water w.r.t. plate vry=Vw-VCp //m/sec vrx=20 //m/sec vr=sqrt((20)^2+(1.453)^2) //m/sec alpha=atand(1.453/20) //degree printf("\nvr=%.2f m/sec\nalpha=%.2f degree",vr,alpha)
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as other speakers have said it s a rather daunting experience a particularly daunting experience to be speaking in front of this audience but unlike the other speakers i m not going to tell you about the mysteries of the universe or the wonders of evolution or the really clever innovative ways people are attacking the major inequalities in our world or even the challenges of nation states in the modern global economy my brief as you ve just heard is to tell you about statistics and to be more precise to tell you some exciting things about statistics and that s that s rather more challenging than all the speakers before me and all the ones coming after me one of my senior colleagues told me when i was a youngster in this profession rather proudly that statisticians were people who liked figures but did n t have the personality skills to become accountants and there s another in joke among statisticians and that s how do you tell the introverted statistician from the extroverted statistician to which the answer is the extroverted statistician s the one who looks at the other person s shoes but i want to tell you something useful and here it is so concentrate now this evening there s a reception in the university s museum of natural history and it s a wonderful setting as i hope you ll find and a great icon to the best of the victorian tradition it s very unlikely in this special setting and this collection of people but you might just find yourself talking to someone you d rather wish that you were n t so here s what you do when they say to you what do you do you say i m a statistician well except they ve been pre warned now and they ll know you re making it up and then one of two things will happen they ll either discover their long lost cousin in the other corner of the room and run over and talk to them or they ll suddenly become parched and or hungry and often both and sprint off for a drink and some food and you ll be left in peace to talk to the person you really want to talk to it s one of the challenges in our profession to try and explain what we do we re not top on people s lists for dinner party guests and conversations and so on and it s something i ve never really found a good way of doing but my wife who was then my girlfriend managed it much better than i ve ever been able to many years ago when we first started going out she was working for the bbc in britain and i was at that stage working in america i was coming back to visit her she told this to one of her colleagues who said well what does your boyfriend do sarah thought quite hard about the things i d explained and she concentrated in those days on listening do n t tell her i said that and she was thinking about the work i did developing mathematical models for understanding evolution and modern genetics so when her colleague said what does he do she paused and said he models things well her colleague suddenly got much more interested than i had any right to expect and went on and said what does he model well sarah thought a little bit more about my work and said genes he models genes that is my first love and that s what i ll tell you a little bit about what i want to do more generally is to get you thinking about the place of uncertainty and randomness and chance in our world and how we react to that and how well we do or do n t think about it so you ve had a pretty easy time up till now a few laughs and all that kind of thing in the talks to date you ve got to think and i m going to ask you some questions so here s the scene for the first question i m going to ask you can you imagine tossing a coin successively and for some reason which shall remain rather vague we re interested in a particular pattern here s one a head followed by a tail followed by a tail so suppose we toss a coin repeatedly then the pattern head tail tail that we ve suddenly become fixated with happens here and you can count one two three four five six seven eight nine 10 it happens after the 10th toss so you might think there are more interesting things to do but humor me for the moment imagine this half of the audience each get out coins and they toss them until they first see the pattern head tail tail the first time they do it maybe it happens after the 10th toss as here the second time maybe it s after the fourth toss the next time after the 15th toss so you do that lots and lots of times and you average those numbers that s what i want this side to think about the other half of the audience does n t like head tail tail they think for deep cultural reasons that s boring and they re much more interested in a different pattern head tail head so on this side you get out your coins and you toss and toss and toss and you count the number of times until the pattern head tail head appears and you average them ok so on this side you ve got a number you ve done it lots of times so you get it accurately which is the average number of tosses until head tail tail on this side you ve got a number the average number of tosses until head tail head so here s a deep mathematical fact if you ve got two numbers one of three things must be true either they re the same or this one s bigger than this one or this one s bigger than that one so what s going on here so you ve all got to think about this and you ve all got to vote and we re not moving on and i do n t want to end up in the two minute silence to give you more time to think about it until everyone s expressed a view ok so what you want to do is compare the average number of tosses until we first see head tail head with the average number of tosses until we first see head tail tail who thinks that a is true that on average it ll take longer to see head tail head than head tail tail who thinks that b is true that on average they re the same who thinks that c is true that on average it ll take less time to see head tail head than head tail tail ok who has n t voted yet because that s really naughty i said you had to ok so most people think b is true and you might be relieved to know even rather distinguished mathematicians think that it s not a is true here it takes longer on average in fact the average number of tosses till head tail head is 10 and the average number of tosses until head tail tail is eight how could that be anything different about the two patterns there is head tail head overlaps itself if you went head tail head tail head you can cunningly get two occurrences of the pattern in only five tosses you ca n t do that with head tail tail that turns out to be important there are two ways of thinking about this i ll give you one of them so imagine let s suppose we re doing it on this side remember you re excited about head tail tail you re excited about head tail head we start tossing a coin and we get a head and you start sitting on the edge of your seat because something great and wonderful or awesome might be about to happen the next toss is a tail you get really excited the champagne s on ice just next to you you ve got the glasses chilled to celebrate you re waiting with bated breath for the final toss and if it comes down a head that s great you re done and you celebrate if it s a tail well rather disappointedly you put the glasses away and put the champagne back and you keep tossing to wait for the next head to get excited on this side there s a different experience it s the same for the first two parts of the sequence you re a little bit excited with the first head you get rather more excited with the next tail then you toss the coin if it s a tail you crack open the champagne if it s a head you re disappointed but you re still a third of the way to your pattern again and that s an informal way of presenting it that s why there s a difference another way of thinking about it if we tossed a coin eight million times then we d expect a million head tail heads and a million head tail tails but the head tail heads could occur in clumps so if you want to put a million things down amongst eight million positions and you can have some of them overlapping the clumps will be further apart it s another way of getting the intuition what s the point i want to make it s a very very simple example an easily stated question in probability which every you re in good company everybody gets wrong this is my little diversion into my real passion which is genetics there s a connection between head tail heads and head tail tails in genetics and it s the following when you toss a coin you get a sequence of heads and tails when you look at dna there s a sequence of not two things heads and tails but four letters as gs cs and ts and there are little chemical scissors called restriction enzymes which cut dna whenever they see particular patterns and they re an enormously useful tool in modern molecular biology and instead of asking the question how long until i see a head tail head you can ask how big will the chunks be when i use a restriction enzyme which cuts whenever it sees g a a g for example how long will those chunks be that s a rather trivial connection between probability and genetics there s a much deeper connection which i do n t have time to go into and that is that modern genetics is a really exciting area of science and we ll hear some talks later in the conference specifically about that but it turns out that unlocking the secrets in the information generated by modern experimental technologies a key part of that has to do with fairly sophisticated you ll be relieved to know that i do something useful in my day job rather more sophisticated than the head tail head story but quite sophisticated computer modelings and mathematical modelings and modern statistical techniques and i will give you two little snippets two examples of projects we re involved in in my group in oxford both of which i think are rather exciting you know about the human genome project that was a project which aimed to read one copy of the human genome the natural thing to do after you ve done that and that s what this project the international hapmap project which is a collaboration between labs in five or six different countries think of the human genome project as learning what we ve got in common and the hapmap project is trying to understand where there are differences between different people why do we care about that well there are lots of reasons the most pressing one is that we want to understand how some differences make some people susceptible to one disease type 2 diabetes for example and other differences make people more susceptible to heart disease or stroke or autism and so on that s one big project there s a second big project recently funded by the wellcome trust in this country involving very large studies thousands of individuals with each of eight different diseases common diseases like type 1 and type 2 diabetes and coronary heart disease bipolar disease and so on to try and understand the genetics to try and understand what it is about genetic differences that causes the diseases why do we want to do that because we understand very little about most human diseases we do n t know what causes them and if we can get in at the bottom and understand the genetics we ll have a window on the way the disease works and a whole new way about thinking about disease therapies and preventative treatment and so on so that s as i said the little diversion on my main love back to some of the more mundane issues of thinking about uncertainty here s another quiz for you now suppose we ve got a test for a disease which is n t infallible but it s pretty good it gets it right 99 percent of the time and i take one of you or i take someone off the street and i test them for the disease in question let s suppose there s a test for hiv the virus that causes aids and the test says the person has the disease what s the chance that they do the test gets it right 99 percent of the time so a natural answer is 99 percent who likes that answer come on everyone s got to get involved do n t think you do n t trust me anymore well you re right to be a bit skeptical because that s not the answer that s what you might think it s not the answer and it s not because it s only part of the story it actually depends on how common or how rare the disease is so let me try and illustrate that here s a little caricature of a million individuals so let s think about a disease that affects it s pretty rare it affects one person in 10 000 amongst these million individuals most of them are healthy and some of them will have the disease and in fact if this is the prevalence of the disease about 100 will have the disease and the rest wo n t so now suppose we test them all what happens well amongst the 100 who do have the disease the test will get it right 99 percent of the time and 99 will test positive amongst all these other people who do n t have the disease the test will get it right 99 percent of the time it ll only get it wrong one percent of the time but there are so many of them that there ll be an enormous number of false positives put that another way of all of them who test positive so here they are the individuals involved less than one in 100 actually have the disease so even though we think the test is accurate the important part of the story is there s another bit of information we need here s the key intuition what we have to do once we know the test is positive is to weigh up the plausibility or the likelihood of two competing explanations each of those explanations has a likely bit and an unlikely bit one explanation is that the person does n t have the disease that s overwhelmingly likely if you pick someone at random but the test gets it wrong which is unlikely the other explanation is that the person does have the disease that s unlikely but the test gets it right which is likely and the number we end up with that number which is a little bit less than one in 100 is to do with how likely one of those explanations is relative to the other each of them taken together is unlikely here s a more topical example of exactly the same thing those of you in britain will know about what s become rather a celebrated case of a woman called sally clark who had two babies who died suddenly and initially it was thought that they died of what s known informally as cot death and more formally as sudden infant death syndrome for various reasons she was later charged with murder and at the trial her trial a very distinguished pediatrician gave evidence that the chance of two cot deaths innocent deaths in a family like hers which was professional and non smoking was one in 73 million to cut a long story short she was convicted at the time later and fairly recently acquitted on appeal in fact on the second appeal and just to set it in context you can imagine how awful it is for someone to have lost one child and then two if they re innocent to be convicted of murdering them to be put through the stress of the trial convicted of murdering them and to spend time in a women s prison where all the other prisoners think you killed your children is a really awful thing to happen to someone and it happened in large part here because the expert got the statistics horribly wrong in two different ways so where did he get the one in 73 million number he looked at some research which said the chance of one cot death in a family like sally clark s is about one in 8 500 so he said i ll assume that if you have one cot death in a family the chance of a second child dying from cot death are n t changed so that s what statisticians would call an assumption of independence it s like saying if you toss a coin and get a head the first time that wo n t affect the chance of getting a head the second time so if you toss a coin twice the chance of getting a head twice are a half that s the chance the first time times a half the chance a second time so he said here i ll assume that these events are independent when you multiply 8 500 together twice you get about 73 million and none of this was stated to the court as an assumption or presented to the jury that way unfortunately here and really regrettably first of all in a situation like this you d have to verify it empirically and secondly it s palpably false there are lots and lots of things that we do n t know about sudden infant deaths it might well be that there are environmental factors that we re not aware of and it s pretty likely to be the case that there are genetic factors we re not aware of so if a family suffers from one cot death you d put them in a high risk group they ve probably got these environmental risk factors and or genetic risk factors we do n t know about and to argue then that the chance of a second death is as if you did n t know that information is really silly it s worse than silly it s really bad science nonetheless that s how it was presented and at trial nobody even argued it that s the first problem the second problem is what does the number of one in 73 million mean so after sally clark was convicted you can imagine it made rather a splash in the press one of the journalists from one of britain s more reputable newspapers wrote that what the expert had said was the chance that she was innocent was one in 73 million now that s a logical error it s exactly the same logical error as the logical error of thinking that after the disease test which is 99 percent accurate the chance of having the disease is 99 percent in the disease example we had to bear in mind two things one of which was the possibility that the test got it right or not and the other one was the chance a priori that the person had the disease or not it s exactly the same in this context there are two things involved two parts to the explanation we want to know how likely or relatively how likely two different explanations are one of them is that sally clark was innocent which is a priori overwhelmingly likely most mothers do n t kill their children and the second part of the explanation is that she suffered an incredibly unlikely event not as unlikely as one in 73 million but nonetheless rather unlikely the other explanation is that she was guilty now we probably think a priori that s unlikely and we certainly should think in the context of a criminal trial that that s unlikely because of the presumption of innocence and then if she were trying to kill the children she succeeded so the chance that she s innocent is n t one in 73 million we do n t know what it is it has to do with weighing up the strength of the other evidence against her and the statistical evidence we know the children died what matters is how likely or unlikely relative to each other the two explanations are and they re both implausible there s a situation where errors in statistics had really profound and really unfortunate consequences in fact there are two other women who were convicted on the basis of the evidence of this pediatrician who have subsequently been released on appeal many cases were reviewed and it s particularly topical because he s currently facing a disrepute charge at britain s general medical council so just to conclude what are the take home messages from this well we know that randomness and uncertainty and chance are very much a part of our everyday life it s also true and although you as a collective are very special in many ways you re completely typical in not getting the examples i gave right it s very well documented that people get things wrong they make errors of logic in reasoning with uncertainty we can cope with the subtleties of language brilliantly and there are interesting evolutionary questions about how we got here we are not good at reasoning with uncertainty that s an issue in our everyday lives as you ve heard from many of the talks statistics underpins an enormous amount of research in science in social science in medicine and indeed quite a lot of industry all of quality control which has had a major impact on industrial processing is underpinned by statistics it s something we re bad at doing at the very least we should recognize that and we tend not to to go back to the legal context at the sally clark trial all of the lawyers just accepted what the expert said so if a pediatrician had come out and said to a jury i know how to build bridges i ve built one down the road please drive your car home over it they would have said well pediatricians do n t know how to build bridges that s what engineers do on the other hand he came out and effectively said or implied i know how to reason with uncertainty i know how to do statistics and everyone said well that s fine he s an expert so we need to understand where our competence is and is n t exactly the same kinds of issues arose in the early days of dna profiling when scientists and lawyers and in some cases judges routinely misrepresented evidence usually one hopes innocently but misrepresented evidence forensic scientists said the chance that this guy s innocent is one in three million even if you believe the number just like the 73 million to one that s not what it meant and there have been celebrated appeal cases in britain and elsewhere because of that and just to finish in the context of the legal system it s all very well to say let s do our best to present the evidence but more and more in cases of dna profiling this is another one we expect juries who are ordinary people and it s documented they re very bad at this we expect juries to be able to cope with the sorts of reasoning that goes on in other spheres of life if people argued well except possibly for politics but in other spheres of life if people argued illogically we d say that s not a good thing we sort of expect it of politicians and do n t hope for much more in the case of uncertainty we get it wrong all the time and at the very least we should be aware of that and ideally we might try and do something about it thanks very much
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//determine the transfer function of the transformer coupled network printf("syms R1 R2 C2 C1 L1 L2 M L3 \n G=s^3*R2*C1*C2*M/(((s^2*C2*(L3+L2))+1+s*R2*C2)*(S^2*L1*C1+s*C1*R1+1)-M^2*s^4*C1*C2)\n Transfer function=G")
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/2417/CH7/EX7.14/Ex7_14.sce
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Ex7_14.sce
//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.14\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.14 (page no. 338) // Solution //To solve this probelm,it is necessary to determine the properties of the saturated mixture 90 F.If the air is saturated at 90 F,the partial pressure of the water vapor is found directly from the Steam Tables as 0.6988 psia,and the specific volume of the water vapor is 467.7 ft^3/lbm of vapor. printf("The partial pressure of the dry air is %f psia\n",14.7-0.6988); //the mixture is at 14.7 psia R=1545/28.966; //gas constant of dry air=1545/Molecular weight T=90+460; //temperature of dry air //Unit:R pdryair=14.0; //psia //pressure of dry air //Applying the ideal gas equation to the air, vdryair=(R*T)/(pdryair*144); //volume of dry air //ft^3/lbm //1 in^2=144 Ft^2 //the mass of dry air in the 467.7 ft^3 container printf("The mass of dry air in the 467.7 ft^3 container is %f lbm\n",467.7/vdryair); //To obtain relative humidity(phy),it is necessary to determine the mole fraction of water vapor for both the saturated mixture and the mixture in question. //The saturated mixture contains 1 lbm of water vapor or 1/18.016 moles =0.055 mole of water vapor and (467.7/vdryair)/28.966=1.109 moles of dry air. //For the saturated mixture, the ratio of moles of water vapor to moles of mixture is 0.055/(0.055+1.109)=0.0477 //For the actual mixture,the moles of water vapor per pound of dry air is 0.005/18.016=0.000278 and 1 lbm of dry air is 1/28.966=0.0345 mole.So,the mole of water vapor per mole of mixture at the conditions of the mixture is 0.000278/(0.0345+0.000278)=0.00799 //From the defination of relative humidity, printf("The relative humidity of the mixture is %f \n",(0.00799/0.0477)*100); //Because the mole ratio is also the ratio of the partial pressures for the ideal gas,phy can be expressed as the ratio of the partial pressure of the water vapor in the mixture to the partial pressure of the water vapor at saturation.Therefore, printf("The partial pressure of the vapor at saturation is %f psia\n",(0.00799/0.0477)*0.6988); printf("And the partial pressure of the dry air in the mixture is %f psia\n",14.7-((0.00799/0.0477)*0.6988)); //14.7-The partial pressure of the vapor at saturation //The dew point temperature is the saturation temperature corresponding to the partial pressure of the water vapor in the mixture.So, printf("The dew point temperature corresponding to %f psia is 39F\n",(0.00799/0.0477)*0.6988);
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/797/CH3/EX3.3.e/3_03_example.sci
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3_03_example.sci
//Example 3-03 Gravity Driven flow in IV bottle rho = 1020 //density of IV fluid [kg/m^3] h_bottle1 = 1.2 //height of bottle for blood pressure balance P_gauge2 = 20 //gauge pressure required for sufficient flow rate g = 9.81 //gravitational acceleration [m^2/s]
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/978/CH11/EX11.3/Example11_3.sce
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Example11_3.sce
//chapter-11,Example11_3,pg 505 R1=0//resistance C=0.1*10^-6//capacitance f=1*10^3//frequency L=(1/((2*%pi*f)^2))*(1/C)//inductance printf("inductance of circuit\n") printf("L=%.6f H ",L)
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/tests/kmctr-hw.tst
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kmctr-hw.tst
*Testcase KMCTR fc0 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000000 # LA R0,0 R0->function code 0 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=41200000 # LA R2,FO R2->first operand r 20C=41400000 # LA R4,SO R4->second operand r 210=41500000 # LA R5,SOL R5->second operand length r 214=41600000 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block * r 580=F0703838000000000000000000000000 # Expected result * runtest .1 *Compare * Display parameter block r 500.10 *Want F0703838 00000000 00000000 00000000 *Done *Testcase KMCTR bad sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=4100003f # LA R0,63 R0->function code 63 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=41200000 # LA R2,FO R2->first operand r 20C=41400000 # LA R4,SO R4->second operand r 210=41500000 # LA R5,SOL R5->second operand length r 214=41600000 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block *Program 6 runtest .1 *Done *Testcase KMCTR fc1 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000001 # LA R0,1 R0->function code 1 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500008 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500008 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=0001020304050607 # Parameter block r 600=1011121314151617 # First operand r 700=2021222324252627 # Second operand r 800=3031323334353637 # Third operand * r 680=ACCE8C43F1F6EFBB # Expected result * runtest .1 *Compare * Display parameter block r 600.8 *Want ACCE8C43 F1F6EFBB r 608.8 *Want 00000000 00000000 * Expected result *Done *Testcase KMCTR fc2 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000002 # LA R0,2 R0->function code 2 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500008 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500008 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 600=1011121314151617 # First operand r 700=2021222324252627 # Second operand r 800=3031323334353637 # Third operand * r 680=DDEB7099FF49EFED # Expected result * runtest .1 *Compare * Display parameter block r 600.8 *Want DDEB7099 FF49EFED r 608.8 *Want 00000000 00000000 * Expected result *Done *Testcase KMCTR fc3 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000003 # LA R0,3 R0->function code 3 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500008 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500008 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=1011121314151617 # Parameter block r 600=1011121314151617 # First operand r 700=2021222324252627 # Second operand r 800=3031323334353637 # Third operand * r 680=C53B7B40838457C8 # Expected result * runtest .1 *Compare * Display parameter block r 600.8 *Want C53B7B40 838457C8 r 608.8 *Want 00000000 00000000 * Expected result *Done *Testcase KMCTR fc9 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000001 # LA R0,X'01' R0->function code 1 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=41000009 # LA R0,X'09' R0->function code 9 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500008 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500008 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 600=1011121314151617 # CV r 700=2021222324252627 # First operand r 800=3031323334353637 # Expected result * r 680=ACCE8C43F1F6EFBB # Expected result * runtest .1 *Compare * Display parameter blocks r 600.8 *Want ACCE8C43 F1F6EFBB r 900.8 *Want 20212223 24252627 *Done *Testcase KMCTR fc10 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000002 # LA R0,X'02' R0->function code 2 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=4100000A # LA R0,X'0A' R0->function code 10 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500008 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500008 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 520=2021222324252627 # Parameter block r 600=1011121314151617 # CV r 700=2021222324252627 # First operand r 800=3031323334353637 # Expected result * r 680=DDEB7099FF49EFED # Expected result * runtest .1 *Compare * Display parameter blocks r 600.8 *Want DDEB7099 FF49EFED r 900.8 *Want 20212223 24252627 *Done *Testcase KMCTR fc11 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000003 # LA R0,X'03' R0->function code 3 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=4100000B # LA R0,X'0B' R0->function code 11 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500008 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500008 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 520=202122232425262728292A2B2C2D2E2F # Parameter block r 600=1011121314151617 # CV r 700=2021222324252627 # First operand r 800=3031323334353637 # Expected result * r 680=C53B7B40838457C8 # Expected result * runtest .1 *Compare * Display parameter blocks r 600.8 *Want C53B7B40 838457C8 r 900.8 *Want 20212223 24252627 *Done *Testcase KMCTR fc18 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000012 # LA R0,18 R0->function code 18 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500010 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500010 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 600=101112131415161718191A1B1C1D1E1F # First operand r 700=202122232425262728292A2B2C2D2E2F # Second operand r 800=303132333435363738393A3B3C3D3E3F # Third operand * r 680=23D3E19EEEA74DD7AAFEE59B19E096EE # Expected result * runtest .1 *Compare * Display parameter block r 600.10 *Want 23D3E19E EEA74DD7 AAFEE59B 19E096EE *Done *Testcase KMCTR fc19 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000013 # LA R0,19 R0->function code 19 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500010 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500010 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=1011121314151617 # Parameter block r 600=101112131415161718191A1B1C1D1E1F # First operand r 700=202122232425262728292A2B2C2D2E2F # Second operand r 800=303132333435363738393A3B3C3D3E3F # Third operand * r 680=4804D24C513D7B6F130879534F3FAFB1 # Expected result * runtest .1 *Compare * Display parameter block r 600.10 *Want 4804D24C 513D7B6F 13087953 4F3FAFB1 *Done *Testcase KMCTR fc20 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000014 # LA R0,20 R0->function code 20 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=4120f600 # LA R2,FO R2->first operand r 20C=4140f700 # LA R4,SO R4->second operand r 210=41500010 # LA R5,SOL R5->second operand length r 214=4160f800 # LA R6,TO R6->third operand r 218=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 21C=4120f900 # LA R2,FO R2->first operand r 220=4140f600 # LA R4,SO R4->second operand r 224=41500010 # LA R5,SOL R5->second operand length r 228=4160f800 # LA R6,TO R6->third operand r 22C=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 230=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 600=101112131415161718191A1B1C1D1E1F # First operand r 700=202122232425262728292A2B2C2D2E2F # Second operand r 800=303132333435363738393A3B3C3D3E3F # Third operand * r 680=C2552CA9DEF1C2F675244C301403E4A6 # Expected result * runtest .1 *Compare * Display parameter block r 600.10 *Want C2552CA9 DEF1C2F6 75244C30 1403E4A6 *Done *Testcase KMCTR fc26 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000012 # LA R0,X'12' R0->function code 18 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=4100001A # LA R0,X'1A' R0->function code 26 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500010 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500010 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 520=202122232425262728292A2B2C2D2E2F # Parameter block r 600=101112131415161728292A2B2C2D2E2F # CV r 700=202122232425262728292A2B2C2D2E2F # First operand r 800=303132333435363738393A3B3C3D3E3F # Expected result * r 680=23D3E19EEEA74DD7AAFEE59B19E096EE # Expected result * runtest .1 *Compare * Display parameter blocks r 600.8 *Want 23D3E19E EEA74DD7 r 900.8 *Want 20212223 24252627 *Done *Testcase KMCTR fc27 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000013 # LA R0,X'13' R0->function code 19 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=4100001B # LA R0,X'1B' R0->function code 27 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500010 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500010 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 520=202122232425262728292A2B2C2D2E2F # Parameter block r 530=303132333435363738393A3B3C3D3E3F # Parameter block r 600=101112131415161718191A1B1C1D1E1F # CV r 700=202122232425262728292A2B2C2D2E2F # First operand r 800=303132333435363738393A3B3C3D3E3F # Expected result * r 680=4804D24C513D7B6F130879534F3FAFB1 # Expected result * runtest .1 *Compare * Display parameter blocks r 600.8 *Want 4804D24C 513D7B6F r 900.8 *Want 20212223 24252627 *Done *Testcase KMCTR fc28 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000014 # LA R0,X'14' R0->function code 20 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=B9280000 # PCKMO Encrypt DEA Key r 20C=4100001C # LA R0,X'1C' R0->function code 28 encrypt r 210=4110f500 # LA R1,PB R1->parameter block address r 214=4120f600 # LA R2,FO R2->first operand r 218=4140f700 # LA R4,SO R4->second operand r 21C=41500010 # LA R5,SOL R5->second operand length r 220=4160f800 # LA R6,TO R6->third address r 224=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 228=4120f900 # LA R2,FO R2->first operand r 22C=4140f600 # LA R4,SO R4->second operand r 230=41500010 # LA R5,SOL R5->second operand length r 234=4160f800 # LA R6,TO R6->third operand r 238=B92D6024 # KMCTR R2,R6,R4 Cipher message with counter r 23C=12ee077eB2B20300 # LPSWE WAITPSW Load enabled wait PSW r 300=00020001800000000000000000000000 # WAITPSW Enabled wait state PSW * r 500=000102030405060708090A0B0C0D0E0F # Parameter block r 510=101112131415161718191A1B1C1D1E1F # Parameter block r 520=202122232425262728292A2B2C2D2E2F # Parameter block r 530=303132333435363738393A3B3C3D3E3F # Parameter block r 600=101112131415161718191A1B1C1D1E1F # CV r 700=202122232425262728292A2B2C2D2E2F # First operand r 800=303132333435363738393A3B3C3D3E3F # Expected result * r 680=C2552CA9DEF1C2F675244C301403E4A6 # Expected result * runtest .1 *Compare * Display parameter blocks r 600.10 *Want C2552CA9 DEF1C2F6 75244C30 1403E4A6 r 900.10 * Expected results *Want 20212223 24252627 28292A2B 2C2D2E2F *Done
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// Chapter 5 additional Example 11 //============================================================================== clc; clear; //input data // (311) plane in simple cubic lattice h = 3; // miller indice k = 1; // miller indice l = 1; // miller indice a = 2.109*10^-10 // lattice constant in m // Calculations dhkl = a/sqrt((h^2)+(k^2)+(l^2)); // interplanar distance // Output mprintf('d = %3.3e m',dhkl); //==============================================================================
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errcatch(-1,"stop");mode(2);; ; a=2*10^-3,b=6*10^-3,t=10^-3,l=2,c=5.8*10^7; Ri=l/(c*%pi*a*a); Ro=l/(c*%pi*((b+t)^2-b^2)); Rdc=Ro+Ri; disp(Rdc*10^3,'Resistance in mOhm'); exit();
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clc; clear all; disp("average HT coefficient") D=2/100;//m diameter of tube tf=30;//degree C m=2940;//kg/h ts=100;// degree C L=5;//m k=0.12;//W/m.C cp=2000;//J/kg.K v=5.14*10^(-6);// m^2/s rho=850;//kg/m^3 m1=m/3600;//kg/s As=%pi*D^2/4; U=m1/(As*rho)//m/s Pr=v*rho*cp/k ReL=10^3*ceil(U*D/v/10^3) Nu=0.023*(ReL^0.8)*Pr^(1/3) h=Nu*k/D; disp("W/m^2.C",h,"Average heat transfer coefficiet h =")
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clear; //clc(); // Example 13.3 // Page: 352 printf("Example-13.3 Page no.-352\n\n"); //***Data***// P = 10;//[MPa] given pressure T = 250;//[C] Temperature // Let the total number of moles in the feed be one, then n_T_0 = 1;//[mol] n_CO = 0.15;//[mol] n_CO2 = 0.08;//[mol] n_H2 = 0.74;//[mol] n_CH4 = 0.03;//[mol] // The two simultaneous reactions taking place are // CO + 2*H2 = CH3OH // CO2 + H2 = CO + H2O // Let us denote the first reaction by 1 and the second reaction by 2 // and K_i = (K/K_v)*[P/(1 atm)]^(-summation(v_i)) // and that summation(v_i) = V_i // Then from the table 13.C (page 353) as reported in the book, we have V_1 = -2; V_2 = 0; K_1 = 49.9;// For the first reaction K_2 = 0.032;// For the second reaction // Now let v_i denotes the stoichiometric coefficient of species 'i', then v_CO_1 = -1; v_H2_1 = -2; v_CH3OH_1 = +1; v_CO2_2 = -1; v_H2_2 = -1; v_CO_2 = +1; v_H2O_2 = +1; // Let e_1 = the moles of CO reacted in reaction 1 and e_2 = the moles of CO2 reacted in reaction 2. // Now mol fractions of each of the species in the equilibrium is // y_CO = (n_CO+v_CO_1*e_1+v_CO_2*e_2)/(n_T_0+e_1*V_1+e_2*V_2) = (0.15-1*e_1+1*e_2)/(1+e_1*(-2)+e_2*(0)) = (0.15 - e_1 + e_2)/(1 - 2*e_1) // similarily // y_H2 = (n_H2+v_H2_1*e_1+v_H2_2*e_2)/(n_T_0+e_1*V_1+e_2*V_2) = (0.74 - 2*e_1 - e_2)/(1 - 2*e_1) // y_CH3OH = (n_CH3OH+v_CH3OH_1*e_1+v_CH3OH_2*e_2)/(n_T_0+e_1*V_1+e_2*V_2) = (0 + e_1)/(1 - 2*e_1) // y_CO2 = (n_CO2+v_CO2_1*e_1+v_CO2_2*e_2)/(n_T_0+e_1*V_1+e_2*V_2) = (0.08 - e_2)/(1 - 2*e_1) // y_H2O = (n_H2O+v_H2O_1*e_1+v_H2O_2*e_2)/(n_T_0+e_1*V_1+e_2*V_2) = (0 + e_2)/(1 - 2*e_1) // Now putting the values in the expression of the equilibrium constant of the reactions, for the reaction 1 we have // K_1 = ((0 + e_1)/(1 - 2*e_1))/(((0.15 - e_1 + e_2)/(1 - 2*e_1))*((0.74 - 2*e_1 - e_2)/(1 - 2*e_1))^(2)) // K_2 = (((0.15 - e_1 + e_2)/(1 - 2*e_1))*((0 + e_2)/(1 - 2*e_1)))/(((0.08 - e_2)/(1 - 2*e_1))*((0.74 - 2*e_1 - e_2)/(1 - 2*e_1))) // e = [e_1 e_2] // Solving the two given simultaneous equations,we have function[f]=F(e) f(1) = ((0 + e(1))/(1 - 2*e(1)))/(((0.15 - e(1) + e(2))/(1 - 2*e(1)))*((0.74 - 2*e(1) - e(2))/(1 - 2*e(1)))^(2)) - K_1; f(2) = (((0.15 - e(1) + e(2))/(1 - 2*e(1)))*((0 + e(2))/(1 - 2*e(1))))/(((0.08 - e(2))/(1 - 2*e(1)))*((0.74 - 2*e(1) - e(2))/(1 - 2*e(1)))) - K_2; funcprot(0); endfunction // Initial guess: e = [0.109 0]; y = fsolve(e,F); e_1 = y(1); e_2 = y(2); // So, percent conversion of CO2 is given as // (moles of CO2 reacted)/(moles of CO2 fed) i.e. c_CO2 = e_2/(n_CO2)*100; // Number of moles of CO Formed by the second reaction is 0.032 // So, percent conversion of CO is given as c_CO = e_1/(n_CO + 0.032)*100; printf(" Percent conversion of CO is %f%%\n",c_CO); printf(" Percent conversion of CO2 is %f%%",c_CO2);
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V;FRML;PL;2;NEG;PRS көмeктeсу V;SG;1;PST көмeктeсу V;PROG;PL;1;PRS көмeктeсу V;PRF;PL;2;INFM;PST көмeктeсу V;PROG;FRML;PL;2;NEG;PRS көмeктeсу V;PL;1;PST көмeктeсу V;PROG;FRML;PL;2;PST көмeктeсу V;PL;3;NEG;PRS көмeктeсу V;PROG;SG;2;INFM;PST көмeктeсу V;PRF;SG;1;NEG;PST көмeктeсу V;PRF;FRML;SG;2;NEG;PST көмeктeсу V;SG;2;INFM;PST көмeктeсу V;SG;3;NEG;PST сaлу V;FRML;SG;2;NEG;PST сaлу V;FRML;SBJV;PL;2;FUT сaлу V;PL;2;NEG;INFM;PST сaлу V;FRML;IMP;PL;2 сaлу V;FRML;SBJV;SG;2;FUT сaлу V;FRML;IMP;SG;2 сaлу V;FRML;PL;2;NEG;PRS сaлу V;SBJV;PL;2;INFM;FUT сaлу V;SG;1;NEG;PST сaлу V;FRML;PL;2;PRS сaлу V;SBJV;SG;2;INFM;FUT сaлу V;PROG;SG;1;NEG;PRS сaлу V;PL;3;PST сaлу V;PROG;PL;1;NEG;PRS сaлу V;PRF;PL;1;PST сaлу V;PL;1;NEG;PRS сaлу V;PROG;SG;2;NEG;INFM;PRS сaлу V;PROG;FRML;PL;2;PST сaлу V;PL;2;INFM;PST сaлу V;PROG;PL;1;PRS сaлу V;PROG;PL;3;NEG;PRS сaлу V;PL;3;NEG;PRS сaлу V;FRML;IMP;PL;2;NEG сaлу V;PROG;PL;2;NEG;INFM;PRS сaлу V;SG;3;PST сaлу V;SBJV;SG;3;FUT сaлу V;SBJV;PL;1;FUT сaлу V;SG;1;PRS сaлу V;PL;1;PRS сaлу V;PL;3;PRS сaлу V;PROG;SG;3;NEG;PRS сaлу V;PRF;SG;3;NEG;PST сaлу V;FRML;SG;2;NEG;PRS сaлу V;PRF;FRML;SG;2;NEG;PST сaлу V;PROG;FRML;PL;2;NEG;PST сaлу V;PROG;SG;1;NEG;PST сaлу V;PRF;PL;2;INFM;PST сaлу V;PROG;SG;1;PRS сaлу V;PL;3;NEG;PST сaлу V;PRF;FRML;SG;2;PST сaлу V;PRF;PL;3;NEG;PST сaлу V;PROG;SG;2;INFM;PRS сaлу V;PROG;SG;1;PST сaлу V;PROG;SG;2;NEG;INFM;PST сaлу V;PROG;PL;2;NEG;INFM;PST сaлу V;PRF;SG;3;PST сaлу V;PROG;PL;1;NEG;PST сaлу V;PROG;FRML;PL;2;PRS сaлу V;PRF;SG;1;PST сaлу V;PROG;SG;3;PRS сaлу V;SG;3;NEG;PRS сaлу V;PROG;PL;3;PST сaлу V;FRML;IMP;SG;2;NEG сaлу V;PROG;FRML;SG;2;NEG;PRS сaлу V;PROG;PL;3;PRS сaлу V;PRF;SG;1;NEG;PST сaлу V;SG;3;NEG;PST сaлу V;PRF;SG;2;INFM;PST сaлу V;IMP;SG;2;NEG;INFM сaлу V;SG;2;INFM;PST сaлу V;SG;2;NEG;INFM;PST сaлу V;SG;3;PRS сaлу V;PL;2;NEG;INFM;PRS сaлу V;PRF;SG;2;NEG;INFM;PST сaлу V;FRML;SG;2;PST сaлу V;PRF;PL;2;NEG;INFM;PST сaлу V;PROG;FRML;SG;2;NEG;PST сaлу V;FRML;PL;2;NEG;PST сaлу V;IMP;PL;2;INFM сaлу V;SG;2;NEG;INFM;PRS сaлу V;PROG;SG;3;PST сaлу V;PRF;PL;3;PST сaлу V;PROG;SG;3;NEG;PST сaлу V;PROG;SG;2;INFM;PST сaлу V;PROG;PL;1;PST сaлу V;PROG;PL;3;NEG;PST сaлу V;PROG;PL;2;INFM;PST сaлу V;SBJV;PL;3;FUT сaлу V;PROG;PL;2;INFM;PRS сaлу V;FRML;PL;2;PST сaлу V;FRML;SG;2;PRS сaлу V;PRF;FRML;PL;2;PST сaлу V;PL;1;PST сaлу V;IMP;SG;2;INFM сaлу V;SG;1;NEG;PRS сaлу V;SBJV;SG;1;FUT сaлу V;PROG;FRML;SG;2;PST сaлу V;PL;1;NEG;PST сaлу V;SG;2;INFM;PRS сaлу V;SG;1;PST сaлу V;IMP;PL;2;NEG;INFM сaлу V;PRF;PL;1;NEG;PST сaлу V;PROG;FRML;SG;2;PRS сaлу V;PROG;FRML;PL;2;NEG;PRS сaлу V;PRF;FRML;PL;2;NEG;PST сaлу V;PL;2;INFM;PRS oйлaу V;PROG;SG;2;INFM;PRS oйлaу V;SBJV;PL;1;FUT oйлaу V;PRF;PL;3;NEG;PST oйлaу V;SBJV;SG;3;FUT oйлaу V;PL;2;NEG;INFM;PRS oйлaу V;PROG;PL;2;NEG;INFM;PST oйлaу V;SG;1;NEG;PST oйлaу V;PROG;FRML;PL;2;PRS oйлaу V;PROG;FRML;SG;2;NEG;PRS oйлaу V;FRML;IMP;SG;2 oйлaу V;PROG;PL;3;NEG;PST oйлaу V;PL;3;NEG;PRS oйлaу V;PROG;SG;3;PRS oйлaу V;PROG;SG;3;PST oйлaу V;FRML;IMP;SG;2;NEG oйлaу V;PROG;FRML;SG;2;PST oйлaу V;FRML;SBJV;PL;2;FUT oйлaу V;FRML;IMP;PL;2 oйлaу V;SG;1;PST oйлaу V;PRF;PL;2;NEG;INFM;PST oйлaу V;SG;1;PRS oйлaу V;PROG;SG;1;PRS oйлaу V;FRML;PL;2;NEG;PRS oйлaу V;IMP;PL;2;NEG;INFM oйлaу V;PL;1;NEG;PRS oйлaу V;PROG;PL;1;NEG;PRS oйлaу V;PROG;PL;2;INFM;PST oйлaу V;PRF;FRML;PL;2;PST oйлaу V;PRF;PL;3;PST oйлaу V;PROG;SG;3;NEG;PST oйлaу V;SG;3;PRS oйлaу V;PROG;PL;3;PRS oйлaу V;PROG;SG;2;INFM;PST oйлaу V;PL;1;PRS oйлaу V;PROG;SG;3;NEG;PRS oйлaу V;PROG;PL;3;NEG;PRS oйлaу V;PRF;PL;1;NEG;PST oйлaу V;FRML;SG;2;PST oйлaу V;PROG;FRML;PL;2;PST oйлaу V;PL;1;NEG;PST oйлaу V;SG;3;PST oйлaу V;SBJV;PL;3;FUT oйлaу V;PRF;FRML;PL;2;NEG;PST oйлaу V;PRF;PL;1;PST oйлaу V;PRF;SG;1;NEG;PST oйлaу V;IMP;SG;2;NEG;INFM oйлaу V;FRML;SG;2;NEG;PST oйлaу V;PROG;PL;1;PST oйлaу V;PROG;SG;1;NEG;PRS oйлaу V;SBJV;PL;2;INFM;FUT oйлaу V;PROG;SG;2;NEG;INFM;PST oйлaу V;PRF;SG;3;PST oйлaу V;SBJV;SG;1;FUT oйлaу V;PROG;SG;1;NEG;PST oйлaу V;PROG;FRML;PL;2;NEG;PST oйлaу V;FRML;SG;2;PRS oйлaу V;IMP;SG;2;INFM oйлaу V;PROG;FRML;SG;2;PRS oйлaу V;PROG;FRML;PL;2;NEG;PRS oйлaу V;PROG;SG;1;PST oйлaу V;PL;3;PRS oйлaу V;PROG;PL;3;PST oйлaу V;FRML;IMP;PL;2;NEG oйлaу V;SG;2;NEG;INFM;PRS oйлaу V;SG;3;NEG;PRS oйлaу V;SG;2;INFM;PRS oйлaу V;PRF;PL;2;INFM;PST oйлaу V;PL;2;NEG;INFM;PST oйлaу V;FRML;PL;2;PRS oйлaу V;PRF;SG;1;PST oйлaу V;PROG;FRML;SG;2;NEG;PST oйлaу V;PRF;FRML;SG;2;PST oйлaу V;SG;3;NEG;PST oйлaу V;IMP;PL;2;INFM oйлaу V;PRF;SG;2;NEG;INFM;PST oйлaу V;PRF;FRML;SG;2;NEG;PST oйлaу V;FRML;SBJV;SG;2;FUT oйлaу V;PROG;SG;2;NEG;INFM;PRS oйлaу V;PROG;PL;2;INFM;PRS oйлaу V;PROG;PL;1;NEG;PST oйлaу V;PROG;PL;2;NEG;INFM;PRS oйлaу V;PRF;SG;3;NEG;PST oйлaу V;FRML;PL;2;PST oйлaу V;SG;2;NEG;INFM;PST oйлaу V;PL;3;NEG;PST oйлaу V;PL;3;PST oйлaу V;PL;1;PST oйлaу V;PROG;PL;1;PRS oйлaу V;FRML;SG;2;NEG;PRS oйлaу V;PL;2;INFM;PST oйлaу V;SBJV;SG;2;INFM;FUT oйлaу V;FRML;PL;2;NEG;PST oйлaу V;SG;2;INFM;PST oйлaу V;SG;1;NEG;PRS oйлaу V;PL;2;INFM;PRS oйлaу V;PRF;SG;2;INFM;PST aзaйту V;SG;1;NEG;PRS aзaйту V;SG;1;NEG;PST aзaйту V;IMP;PL;2;INFM aзaйту V;PROG;PL;1;NEG;PST aзaйту V;SBJV;PL;3;FUT aзaйту V;PROG;PL;3;NEG;PST aзaйту V;SBJV;SG;2;INFM;FUT aзaйту V;PROG;SG;2;INFM;PST aзaйту V;FRML;PL;2;NEG;PST aзaйту V;PL;3;NEG;PRS aзaйту V;FRML;PL;2;PST aзaйту V;FRML;SG;2;NEG;PRS aзaйту V;SBJV;PL;1;FUT aзaйту V;FRML;PL;2;PRS aзaйту V;PL;2;NEG;INFM;PRS aзaйту V;PROG;SG;3;NEG;PRS aзaйту V;FRML;SBJV;SG;2;FUT aзaйту V;PL;3;NEG;PST aзaйту V;PROG;SG;2;NEG;INFM;PST aзaйту V;PROG;PL;1;PRS aзaйту V;PROG;FRML;SG;2;NEG;PRS aзaйту V;FRML;SBJV;PL;2;FUT aзaйту V;PL;1;NEG;PRS aзaйту V;PROG;FRML;PL;2;PRS aзaйту V;PRF;FRML;PL;2;PST aзaйту V;FRML;IMP;SG;2;NEG aзaйту V;PRF;PL;3;PST aзaйту V;PRF;SG;3;NEG;PST aзaйту V;SG;3;NEG;PST aзaйту V;PRF;FRML;SG;2;PST aзaйту V;PRF;FRML;PL;2;NEG;PST aзaйту V;FRML;IMP;PL;2 aзaйту V;PRF;PL;3;NEG;PST aзaйту V;PL;1;PRS aзaйту V;PROG;SG;2;NEG;INFM;PRS aзaйту V;FRML;PL;2;NEG;PRS aзaйту V;PRF;SG;1;PST aзaйту V;PROG;PL;3;NEG;PRS aзaйту V;SG;3;NEG;PRS aзaйту V;PROG;FRML;PL;2;NEG;PST aзaйту V;PL;3;PST aзaйту V;PRF;SG;2;INFM;PST aзaйту V;SG;2;INFM;PST aзaйту V;PL;1;NEG;PST aзaйту V;PL;2;INFM;PST aзaйту V;PROG;PL;1;NEG;PRS aзaйту V;PRF;PL;1;PST aзaйту V;PROG;SG;1;PST aзaйту V;PROG;PL;3;PRS aзaйту V;FRML;SG;2;PST aзaйту V;PROG;PL;2;INFM;PRS aзaйту V;PL;3;PRS aзaйту V;PROG;PL;2;INFM;PST aзaйту V;PROG;FRML;SG;2;NEG;PST aзaйту V;PROG;SG;3;NEG;PST aзaйту V;PRF;SG;3;PST aзaйту V;PROG;SG;3;PRS aзaйту V;PROG;FRML;SG;2;PST aзaйту V;SBJV;SG;3;FUT aзaйту V;SG;3;PRS aзaйту V;PL;2;INFM;PRS aзaйту V;PRF;PL;2;NEG;INFM;PST aзaйту V;PROG;SG;1;NEG;PRS aзaйту V;PROG;PL;2;NEG;INFM;PST aзaйту V;PROG;PL;2;NEG;INFM;PRS aзaйту V;PRF;SG;1;NEG;PST aзaйту V;PRF;FRML;SG;2;NEG;PST aзaйту V;SBJV;SG;1;FUT aзaйту V;PROG;FRML;PL;2;NEG;PRS aзaйту V;PROG;SG;1;PRS aзaйту V;PL;1;PST aзaйту V;PL;2;NEG;INFM;PST aзaйту V;IMP;SG;2;INFM aзaйту V;FRML;SG;2;PRS aзaйту V;FRML;IMP;PL;2;NEG aзaйту V;FRML;SG;2;NEG;PST aзaйту V;PROG;SG;3;PST aзaйту V;IMP;SG;2;NEG;INFM aзaйту V;SG;3;PST aзaйту V;PROG;FRML;PL;2;PST aзaйту V;PROG;FRML;SG;2;PRS aзaйту V;PROG;SG;1;NEG;PST aзaйту V;PROG;PL;3;PST aзaйту V;PROG;PL;1;PST aзaйту V;IMP;PL;2;NEG;INFM aзaйту V;SG;1;PST aзaйту V;SG;2;NEG;INFM;PST aзaйту V;PROG;SG;2;INFM;PRS aзaйту V;SG;2;INFM;PRS aзaйту V;PRF;PL;2;INFM;PST aзaйту V;SG;1;PRS aзaйту V;SBJV;PL;2;INFM;FUT aзaйту V;SG;2;NEG;INFM;PRS aзaйту V;PRF;SG;2;NEG;INFM;PST aзaйту V;PRF;PL;1;NEG;PST aзaйту V;FRML;IMP;SG;2 жымию V;PROG;SG;2;NEG;INFM;PST жымию V;SG;3;PST жымию V;PROG;PL;2;NEG;INFM;PST жымию V;PROG;FRML;PL;2;PRS жымию V;FRML;SBJV;PL;2;FUT жымию V;PL;2;INFM;PRS жымию V;FRML;IMP;SG;2 жымию V;PROG;PL;1;NEG;PST жымию V;FRML;SG;2;PST жымию V;PRF;PL;1;PST жымию V;PRF;SG;3;NEG;PST жымию V;SG;3;NEG;PRS жымию V;PL;1;NEG;PST жымию V;PRF;FRML;PL;2;PST жымию V;FRML;SG;2;PRS жымию V;IMP;PL;2;INFM жымию V;FRML;SG;2;NEG;PST жымию V;PRF;PL;3;NEG;PST жымию V;SG;3;NEG;PST жымию V;PROG;SG;2;NEG;INFM;PRS жымию V;PROG;FRML;PL;2;PST жымию V;PROG;PL;3;PST жымию V;FRML;PL;2;NEG;PST жымию V;PL;2;NEG;INFM;PRS жымию V;PROG;SG;3;NEG;PST жымию V;SG;2;NEG;INFM;PRS жымию V;SBJV;SG;3;FUT жымию V;PROG;PL;2;NEG;INFM;PRS жымию V;PL;3;PST жымию V;PL;3;NEG;PST жымию V;PRF;PL;2;INFM;PST жымию V;PROG;FRML;PL;2;NEG;PRS жымию V;PL;1;PRS жымию V;PROG;FRML;PL;2;NEG;PST жымию V;FRML;IMP;PL;2 жымию V;PROG;FRML;SG;2;NEG;PRS жымию V;SBJV;PL;2;INFM;FUT жымию V;SG;1;PRS жымию V;PROG;PL;3;NEG;PRS жымию V;FRML;SBJV;SG;2;FUT жымию V;PRF;SG;1;PST жымию V;IMP;SG;2;INFM жымию V;PL;2;NEG;INFM;PST жымию V;PROG;FRML;SG;2;PST жымию V;SG;1;NEG;PST жымию V;PROG;PL;2;INFM;PST жымию V;PROG;SG;3;NEG;PRS жымию V;PROG;PL;3;NEG;PST жымию V;PRF;SG;2;INFM;PST жымию V;SG;1;NEG;PRS жымию V;FRML;PL;2;PRS жымию V;SG;2;NEG;INFM;PST жымию V;SG;2;INFM;PRS жымию V;PROG;FRML;SG;2;PRS жымию V;PRF;SG;2;NEG;INFM;PST жымию V;PL;1;PST жымию V;SBJV;SG;1;FUT жымию V;SG;1;PST жымию V;PROG;SG;2;INFM;PST жымию V;PROG;SG;3;PRS жымию V;PL;2;INFM;PST жымию V;PRF;SG;3;PST жымию V;PL;3;NEG;PRS жымию V;SBJV;SG;2;INFM;FUT жымию V;PROG;PL;1;PRS жымию V;PRF;PL;2;NEG;INFM;PST жымию V;FRML;IMP;SG;2;NEG жымию V;PROG;PL;1;PST жымию V;FRML;PL;2;PST жымию V;IMP;SG;2;NEG;INFM жымию V;SG;3;PRS жымию V;SG;2;INFM;PST жымию V;SBJV;PL;3;FUT жымию V;PRF;PL;1;NEG;PST жымию V;IMP;PL;2;NEG;INFM жымию V;PROG;PL;3;PRS жымию V;SBJV;PL;1;FUT жымию V;PROG;SG;1;NEG;PRS жымию V;PRF;FRML;SG;2;PST жымию V;PROG;SG;3;PST жымию V;PROG;SG;1;NEG;PST жымию V;PROG;PL;2;INFM;PRS жымию V;PRF;FRML;SG;2;NEG;PST жымию V;PROG;FRML;SG;2;NEG;PST жымию V;PROG;PL;1;NEG;PRS жымию V;PRF;PL;3;PST жымию V;FRML;PL;2;NEG;PRS жымию V;PROG;SG;2;INFM;PRS жымию V;FRML;SG;2;NEG;PRS жымию V;PRF;FRML;PL;2;NEG;PST жымию V;PL;1;NEG;PRS жымию V;PRF;SG;1;NEG;PST жымию V;FRML;IMP;PL;2;NEG жымию V;PROG;SG;1;PRS жымию V;PROG;SG;1;PST жымию V;PL;3;PRS жуу V;PROG;PL;3;PST жуу V;FRML;IMP;PL;2 жуу V;PRF;SG;1;PST жуу V;FRML;PL;2;NEG;PST жуу V;PROG;FRML;PL;2;NEG;PST жуу V;IMP;SG;2;INFM жуу V;PL;1;NEG;PST жуу V;PROG;PL;2;NEG;INFM;PST жуу V;SG;1;NEG;PST жуу V;FRML;SG;2;NEG;PST жуу V;SBJV;PL;1;FUT жуу V;PRF;PL;1;PST жуу V;SBJV;SG;3;FUT жуу V;PROG;FRML;SG;2;NEG;PST жуу V;PRF;PL;2;INFM;PST жуу V;SG;2;INFM;PRS жуу V;PL;2;NEG;INFM;PST жуу V;PROG;SG;2;NEG;INFM;PRS жуу V;PRF;PL;3;NEG;PST жуу V;PROG;FRML;SG;2;PRS жуу V;PL;1;PST жуу V;FRML;IMP;SG;2 жуу V;PRF;PL;1;NEG;PST жуу V;PROG;PL;2;INFM;PRS жуу V;PRF;FRML;SG;2;PST жуу V;PROG;FRML;PL;2;NEG;PRS жуу V;PROG;PL;3;NEG;PST жуу V;PL;2;INFM;PST жуу V;PRF;PL;3;PST жуу V;FRML;PL;2;PRS жуу V;PROG;PL;2;NEG;INFM;PRS жуу V;PROG;FRML;SG;2;NEG;PRS жуу V;PROG;SG;3;PRS жуу V;PRF;FRML;PL;2;NEG;PST жуу V;SG;1;PST жуу V;SG;3;NEG;PRS жуу V;PROG;SG;2;INFM;PRS жуу V;IMP;SG;2;NEG;INFM жуу V;FRML;IMP;PL;2;NEG жуу V;PL;3;PST жуу V;PRF;FRML;SG;2;NEG;PST жуу V;PROG;FRML;PL;2;PRS жуу V;PRF;SG;3;PST жуу V;SG;3;PRS жуу V;SBJV;PL;2;INFM;FUT жуу V;PROG;FRML;PL;2;PST жуу V;IMP;PL;2;INFM жуу V;PROG;SG;1;PRS жуу V;PROG;SG;2;NEG;INFM;PST жуу V;PRF;PL;2;NEG;INFM;PST жуу V;PROG;PL;3;NEG;PRS жуу V;FRML;SG;2;PST жуу V;PROG;SG;3;NEG;PRS жуу V;PROG;SG;1;PST жуу V;SG;1;PRS жуу V;SG;3;PST жуу V;PROG;SG;2;INFM;PST жуу V;PRF;SG;1;NEG;PST жуу V;SBJV;SG;1;FUT жуу V;IMP;PL;2;NEG;INFM жуу V;PL;3;NEG;PRS жуу V;SG;1;NEG;PRS жуу V;PL;3;NEG;PST жуу V;SG;2;NEG;INFM;PST жуу V;PL;1;NEG;PRS жуу V;PRF;FRML;PL;2;PST жуу V;PL;2;NEG;INFM;PRS жуу V;PL;2;INFM;PRS жуу V;FRML;PL;2;NEG;PRS жуу V;PROG;PL;1;PST жуу V;PROG;SG;3;NEG;PST жуу V;PROG;PL;1;NEG;PRS жуу V;PRF;SG;2;NEG;INFM;PST жуу V;SBJV;PL;3;FUT жуу V;PROG;PL;1;PRS жуу V;FRML;SBJV;SG;2;FUT жуу V;SBJV;SG;2;INFM;FUT жуу V;FRML;SBJV;PL;2;FUT жуу V;PROG;FRML;SG;2;PST жуу V;PROG;SG;3;PST жуу V;PROG;PL;2;INFM;PST жуу V;SG;2;NEG;INFM;PRS жуу V;PL;1;PRS жуу V;PRF;SG;2;INFM;PST жуу V;FRML;IMP;SG;2;NEG жуу V;PL;3;PRS жуу V;PRF;SG;3;NEG;PST жуу V;FRML;PL;2;PST жуу V;FRML;SG;2;NEG;PRS жуу V;PROG;PL;3;PRS жуу V;SG;3;NEG;PST жуу V;PROG;PL;1;NEG;PST жуу V;SG;2;INFM;PST жуу V;PROG;SG;1;NEG;PST жуу V;PROG;SG;1;NEG;PRS жуу V;FRML;SG;2;PRS бoлып қaлу V;PL;3;PRS бoлып қaлу V;PROG;PL;2;INFM;PRS бoлып қaлу V;PL;1;NEG;PST бoлып қaлу V;PL;1;PST бoлып қaлу V;PL;2;NEG;INFM;PST бoлып қaлу V;SG;3;NEG;PST бoлып қaлу V;PROG;FRML;PL;2;NEG;PRS бoлып қaлу V;IMP;SG;2;INFM бoлып қaлу V;PRF;FRML;SG;2;NEG;PST бoлып қaлу V;PL;3;NEG;PST бoлып қaлу V;PROG;PL;3;PST бoлып қaлу V;PROG;FRML;SG;2;PST бoлып қaлу V;PROG;PL;3;NEG;PRS бoлып қaлу V;PROG;SG;1;NEG;PRS бoлып қaлу V;IMP;PL;2;NEG;INFM бoлып қaлу V;SG;1;PST бoлып қaлу V;FRML;SG;2;PST бoлып қaлу V;PROG;SG;2;INFM;PST бoлып қaлу V;SG;3;PST бoлып қaлу V;SG;1;NEG;PST бoлып қaлу V;SG;2;INFM;PST бoлып қaлу V;PROG;FRML;SG;2;PRS бoлып қaлу V;FRML;SBJV;PL;2;FUT бoлып қaлу V;FRML;IMP;SG;2;NEG бoлып қaлу V;PROG;PL;2;NEG;INFM;PRS бoлып қaлу V;FRML;IMP;SG;2 бoлып қaлу V;PROG;SG;3;PRS бoлып қaлу V;PROG;SG;1;PRS бoлып қaлу V;PROG;SG;1;NEG;PST бoлып қaлу V;PL;3;PST бoлып қaлу V;PRF;PL;1;NEG;PST бoлып қaлу V;PROG;PL;3;NEG;PST бoлып қaлу V;SG;2;NEG;INFM;PRS бoлып қaлу V;FRML;IMP;PL;2 бoлып қaлу V;SBJV;SG;2;INFM;FUT бoлып қaлу V;SG;1;PRS бoлып қaлу V;PROG;PL;3;PRS бoлып қaлу V;PRF;SG;1;NEG;PST бoлып қaлу V;PRF;FRML;SG;2;PST бoлып қaлу V;PROG;PL;1;PST бoлып қaлу V;PRF;SG;3;NEG;PST бoлып қaлу V;PROG;FRML;PL;2;NEG;PST бoлып қaлу V;PROG;SG;2;INFM;PRS бoлып қaлу V;SG;1;NEG;PRS бoлып қaлу V;PROG;FRML;PL;2;PRS бoлып қaлу V;PL;2;INFM;PRS бoлып қaлу V;PL;3;NEG;PRS бoлып қaлу V;PROG;SG;2;NEG;INFM;PRS бoлып қaлу V;PRF;FRML;PL;2;PST бoлып қaлу V;IMP;PL;2;INFM бoлып қaлу V;FRML;SG;2;NEG;PRS бoлып қaлу V;FRML;PL;2;PST бoлып қaлу V;IMP;SG;2;NEG;INFM бoлып қaлу V;PL;1;PRS бoлып қaлу V;SG;2;INFM;PRS бoлып қaлу V;FRML;PL;2;NEG;PRS бoлып қaлу V;FRML;SBJV;SG;2;FUT бoлып қaлу V;SBJV;PL;3;FUT бoлып қaлу V;PRF;PL;3;PST бoлып қaлу V;PRF;FRML;PL;2;NEG;PST бoлып қaлу V;FRML;IMP;PL;2;NEG бoлып қaлу V;SBJV;PL;2;INFM;FUT бoлып қaлу V;SBJV;SG;1;FUT бoлып қaлу V;PROG;SG;3;PST бoлып қaлу V;PRF;SG;3;PST бoлып қaлу V;PROG;PL;2;INFM;PST бoлып қaлу V;PL;1;NEG;PRS бoлып қaлу V;FRML;SG;2;NEG;PST бoлып қaлу V;SG;3;PRS бoлып қaлу V;PROG;FRML;PL;2;PST бoлып қaлу V;SBJV;PL;1;FUT бoлып қaлу V;PROG;PL;1;NEG;PRS бoлып қaлу V;SBJV;SG;3;FUT бoлып қaлу V;PRF;SG;2;NEG;INFM;PST бoлып қaлу V;PRF;PL;3;NEG;PST бoлып қaлу V;PROG;PL;1;PRS бoлып қaлу V;PRF;PL;1;PST бoлып қaлу V;PROG;SG;3;NEG;PST бoлып қaлу V;PROG;FRML;SG;2;NEG;PST бoлып қaлу V;PROG;FRML;SG;2;NEG;PRS бoлып қaлу V;PROG;SG;2;NEG;INFM;PST бoлып қaлу V;FRML;PL;2;PRS бoлып қaлу V;PRF;PL;2;INFM;PST бoлып қaлу V;SG;3;NEG;PRS бoлып қaлу V;PL;2;NEG;INFM;PRS бoлып қaлу V;FRML;PL;2;NEG;PST бoлып қaлу V;PROG;PL;1;NEG;PST бoлып қaлу V;PRF;PL;2;NEG;INFM;PST бoлып қaлу V;PL;2;INFM;PST бoлып қaлу V;PROG;PL;2;NEG;INFM;PST бoлып қaлу V;PRF;SG;1;PST бoлып қaлу V;SG;2;NEG;INFM;PST бoлып қaлу V;PROG;FRML;SG;2;NEG;PRS бoлып қaлу V;FRML;SG;2;PRS бoлып қaлу V;PROG;PL;2;NEG;INFM;PRS бoлып қaлу V;PROG;SG;3;NEG;PRS бoлып қaлу V;PROG;SG;1;PST бoлып қaлу V;PROG;PL;2;INFM;PRS бoлып қaлу V;PRF;SG;2;INFM;PST бoлып қaлу V;PROG;PL;3;PRS бoлып қaлу V;PROG;FRML;PL;2;PRS бoлып қaлу V;PROG;SG;3;NEG;PRS бoлып қaлу V;PROG;FRML;SG;2;PRS бoлып қaлу V;PROG;SG;1;PRS aйту V;PROG;PL;3;NEG;PRS 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V;PRF;FRML;SG;2;NEG;PST ұстaу V;PRF;FRML;PL;2;NEG;PST ұстaу V;PROG;PL;3;NEG;PRS ұстaу V;SG;3;NEG;PRS ұстaу V;PROG;PL;1;NEG;PRS ұстaу V;PRF;SG;2;NEG;INFM;PST ұстaу V;PRF;PL;3;PST ұстaу V;SG;3;PRS ұстaу V;FRML;SBJV;PL;2;FUT ұстaу V;SBJV;SG;1;FUT ұстaу V;SBJV;PL;3;FUT ұстaу V;PROG;FRML;SG;2;PST ұстaу V;FRML;PL;2;NEG;PST ұстaу V;PROG;SG;3;NEG;PST ұстaу V;PROG;PL;2;INFM;PRS ұстaу V;SBJV;SG;2;INFM;FUT ұстaу V;PROG;FRML;PL;2;PST ұстaу V;SG;1;NEG;PST ұстaу V;IMP;PL;2;INFM ұстaу V;PROG;SG;3;NEG;PRS ұстaу V;PRF;SG;3;NEG;PST ұстaу V;PL;2;NEG;INFM;PRS ұстaу V;PROG;PL;2;INFM;PST ұстaу V;PRF;PL;3;NEG;PST ұстaу V;PROG;SG;3;PRS ұстaу V;PROG;FRML;SG;2;PRS ұстaу V;PROG;PL;2;NEG;INFM;PRS ұстaу V;PL;2;INFM;PST ұстaу V;PL;1;NEG;PST ұстaу V;PROG;FRML;PL;2;NEG;PST ұстaу V;IMP;PL;2;NEG;INFM ұстaу V;FRML;IMP;PL;2;NEG ұстaу V;PRF;PL;1;PST ұстaу V;PROG;PL;3;PRS ұстaу V;PL;3;NEG;PRS ұстaу V;SG;2;NEG;INFM;PRS ұстaу V;SG;3;PST ұстaу V;SBJV;PL;2;INFM;FUT ұстaу V;PL;2;INFM;PRS ұстaу V;PROG;PL;3;NEG;PST ұстaу 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пaйдaлaну V;PL;3;NEG;PST пaйдaлaну V;PRF;SG;3;NEG;PST пaйдaлaну V;FRML;SG;2;PST пaйдaлaну V;PL;3;PRS пaйдaлaну V;PRF;FRML;PL;2;PST пaйдaлaну V;SG;2;NEG;INFM;PST пaйдaлaну V;PROG;FRML;PL;2;PST пaйдaлaну V;FRML;SG;2;NEG;PRS пaйдaлaну V;PRF;PL;3;PST пaйдaлaну V;FRML;PL;2;PST пaйдaлaну V;PROG;SG;2;INFM;PRS пaйдaлaну V;PROG;FRML;PL;2;NEG;PRS пaйдaлaну V;SG;3;NEG;PRS пaйдaлaну V;SG;2;INFM;PST пaйдaлaну V;SBJV;PL;3;FUT пaйдaлaну V;IMP;SG;2;INFM пaйдaлaну V;FRML;IMP;SG;2;NEG пaйдaлaну V;FRML;SG;2;NEG;PST пaйдaлaну V;PROG;PL;2;INFM;PRS пaйдaлaну V;PL;2;INFM;PST пaйдaлaну V;PL;1;PRS пaйдaлaну V;FRML;IMP;SG;2 пaйдaлaну V;PROG;PL;1;NEG;PST пaйдaлaну V;PRF;FRML;PL;2;NEG;PST пaйдaлaну V;PL;3;PST пaйдaлaну V;PROG;PL;1;NEG;PRS пaйдaлaну V;PRF;SG;1;PST пaйдaлaну V;SBJV;SG;3;FUT пaйдaлaну V;PROG;PL;1;PRS пaйдaлaну V;PRF;SG;2;NEG;INFM;PST пaйдaлaну V;PROG;SG;3;NEG;PRS пaйдaлaну V;SG;3;PST пaйдaлaну V;PROG;SG;2;INFM;PST пaйдaлaну V;PROG;SG;2;NEG;INFM;PRS пaйдaлaну V;PROG;SG;1;PRS пaйдaлaну V;PRF;FRML;SG;2;PST пaйдaлaну V;PROG;SG;3;NEG;PST пaйдaлaну V;PROG;PL;1;PST пaйдaлaну V;PL;2;INFM;PRS пaйдaлaну V;IMP;PL;2;INFM пaйдaлaну V;PROG;SG;3;PST пaйдaлaну V;PL;1;NEG;PST пaйдaлaну V;SG;2;INFM;PRS пaйдaлaну V;PL;2;NEG;INFM;PST пaйдaлaну V;PROG;FRML;PL;2;NEG;PST пaйдaлaну V;PROG;FRML;SG;2;PST пaйдaлaну V;SG;3;NEG;PST пaйдaлaну V;FRML;PL;2;NEG;PRS пaйдaлaну V;PROG;SG;1;NEG;PST пaйдaлaну V;PROG;FRML;SG;2;PRS пaйдaлaну V;SBJV;SG;2;INFM;FUT пaйдaлaну V;PROG;SG;1;PST пaйдaлaну V;PL;1;PST пaйдaлaну V;PRF;SG;2;INFM;PST пaйдaлaну V;PRF;PL;1;PST пaйдaлaну V;SG;2;NEG;INFM;PRS пaйдaлaну V;SBJV;PL;2;INFM;FUT пaйдaлaну V;PRF;SG;1;NEG;PST пaйдaлaну V;FRML;IMP;PL;2 пaйдaлaну V;PROG;PL;3;NEG;PRS пaйдaлaну V;PRF;PL;2;INFM;PST пaйдaлaну V;SG;3;PRS пaйдaлaну V;PRF;SG;3;PST пaйдaлaну V;PROG;PL;2;NEG;INFM;PRS
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2.sce
clc // p_a-p_b=-1/2*rho*C^2*(1/R_A^2-1/R_B^2) rho_w=1000; // kg/m^3 g=9.81; // m/s^2 h=0.0115; // m rho=1.22; // kg/m^3 R_A=0.4; // m R_B=0.2; // m C=sqrt(rho_w*g*h*2/(rho*(1/R_B^2-1/R_A^2))); m=rho*C*R_B*integrate('1/R','R', R_B, R_A); disp("Mass flow rate =") disp(m) disp("kg/s")
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Exp4_8.sce
//Example 4.8 clc disp("V_L = 230 V, R_a between lines = 1.8 ohm") disp("(V_oc)_line = 230 V, I_scc = 12.5 A for same I_f = 0.38 A") disp("The value of open circuit e.m.f is always line value unless and until specifically mentioned to be a phase value") disp("Therefore, Z_s = (V_oc)_ph / (I_scc)_ph |for same I_f") voc=230/sqrt(3) format(7) disp(voc," (V_oc)_ph(in V) =") zs=132.79/12.5 disp(zs,"Therefore, Z_s(in ohm/phase) =") disp("R_a between lines = 1.8 ohm") disp("For star connection, R_a between the terminals is 2 R_a per ph") disp("Therefore, 2R_a per ph = 1.8") disp("Therefore, R_a per ph = 0.9 ohm") xs=sqrt((10.623^2)-(0.9^2)) format(7) disp(xs,"Therefore, X_s(in ohm/phase) = sqrt(Z_s^2 - R_a^2) =") disp("Now regulated is asked for I_a = 10 A") disp("Now : The value of Z_s is calculated for I_s = 12.5 A and not at I_s = 10 A. It will be different for I_s = 10 A. But in this problem the test results are not given hence it is not possible to sketch the graphs to detemine Z_s at I_a = 10 A. So value of Z_s calculated is assumed to be same as I_a = 10 A") disp("(i) For 0.8 lagging p.f.") vph=230/sqrt(3) format(7) disp(vph,"V_ph(in V) = V_L/sqrt(3) =") disp("I_a = 10 A") disp("cos(phi) = 0.8 so sin(phi) = 0.6") disp("(E_ph)^2 = (V_ph*cos(phi)+I_a*R_a)^2 + (V_ph*sin(phi)+I_a*X_s)^2") eph=(((132.79*0.8)+(10*0.9))^2)+(((132.79*0.6)+(10*10.585))^2) p=sqrt(eph) format(8) disp(p,"Therefore, E_ph(in V) = ") regu=((218.39-132.79)/132.79)*100 format(6) disp(regu,"Therefore, %Regulation(in percentage) = (E_ph-V_ph / V_ph)*100 =") disp("(ii) For 0.8 leading p.f.") disp("(E_ph)^2 = (V_ph*cos(phi)+I_a*R_a)^2 + (V_ph*sin(phi)+I_a*X_s)^2") eph=(((132.79*0.8)+(10*0.9))^2)+(((132.79*0.6)-(10*10.585))^2) p=sqrt(eph) format(8) disp(p,"Therefore, E_ph(in V) = ") regu=((118.168-132.79)/132.79)*100 format(6) disp(regu,"Therefore, %Regulation(in percentage) = (E_ph-V_ph / V_ph)*100 =")
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/3754/CH27/EX27.15/27_15.sce
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27_15.sce
clear// //Variables Pcdc = 10.0 //Power rating of amplifier (in watt) n = 0.785 //Maximum overall efficiency //Calculation PT = 2 * Pcdc //Total power dissipation of two transistors (in watt) Poac = (PT * n) / (1-n) //Maximum power output (in watt) //Result printf("\n Maximum power output is %0.2f W.",Poac)
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Ex4_7.sce
//Chapter 04:Number Theory and Cryptography clc; clear all; function dec_hex(num) rem=[] i=1 len=0 while num >0 rem(i)=pmodulo(num,16) num=int(num/16) i=i+1 len=len+1 end disp("Hexadecimal Equivalent:") for i=len:-1:1 select rem(i) case 10 then disp('A') case 11 then disp('B') case 12 then disp('C') case 13 then disp('D') case 14 then disp('E') case 15 then disp('F') else disp(rem(i)) end end endfunction inp=input("Enter the decimal number:") dec_hex(inp)
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/764/CH8/EX8.18.b/solution8_18.sce
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solution8_18.sce
//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) then v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution8_18.sce') //Obtain path of data file datapath = path + filesep() + 'data8_18.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the diamater of the rivet from shear consideration ds (mm) ds = sqrt((P * 1000 * 4)/(%pi * n * tau)) dsround = ceil(ds) //Calculate the diameter of the rivet from crushing consideration dc (mm) dc = sqrt((P * 1000)/(n * t * sigmac)) dcround = ceil(dc) //Choose appropriate diameter value d (mm) if (ds > dc) then d = ds dround = ceil(d) else d = dc dround = ceil(d) end //Calculate the width of the band from tensile consideration w (mm) w = ((n/2) * dround) + ((P * 1000)/(t * sigmat)) wround = round_five(w) //Calculate the margin m (mm) m = 1.5 * dround mround = round_five(m) //Calculate the pitch of the rivets p (mm) p = wround - (2 * mround) //Calculate the transverse pitch pt (mm) pt = p //Print results printf('\nDiameter of the rivet(d) = %f or %f mm\n',d,ceil(d)) printf('\nWidth of the band(w) = %f or %f mm\n',w,wround) printf('\nTransverse pitch of the rivets(pt) = %f mm\n',pt)
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3_1.sce
clc //Initialization of variables V=1 //ft^3 m=30 //lbm //calculations v=V/m vf1=0.01665 vfg1=32.38 //ft^3/lbm x1=0.000515 uf1=169.92 ufg1=904.8 u1=uf1+x1*ufg1 vfg=0.0216 vfg2=0.4240 v2=v x2=0.0277 uf2=538.4 ufg2=571 u2=uf2+x2*ufg2 Q=m*(u2-u1) //results printf("Heat transfer = %d Btu",Q)
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6_3w.sce
//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 6.3w //calculation of the maximum value of mass of the block //given data mus=.2//coefficient of static friction between the block and the table M=2//mass(in kg) of one block g=10//gravitational acceleration(in m/s^2) of the earth //calculation N=M*g//normal force //T=m*g tension in the string (1) //fs=mus*N frictional force (2) //f=T from equlibrium equation of 2 kg block (3) //from above equations,we get m=(mus*N)/g printf('the maximum value of mass of the block is %3.2f kg',m)
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10_28.sce
clear clc S=30 SF=1000 V1=33 V2=132 Z1=V1*V1/S I2=S*1e6/(sqrt(3)*V2*1e3) x1g=%i*S/SF x2g=x1g*2/3 x0g=x1g/3 r0g=60/Z1 z0g=r0g+x0g xt=%i *.1 X1=xt+x1g X2=xt+x2g X0=xt FMVAa=round(abs(S/X1)*100)/100 IFa=abs(1/X1)* I2 mprintf("\n(a)3 phase fault Fault MVA=%.2f MVA, Fault Current=%.2f A",FMVAa,IFa) IFb=abs(3/(X1+X2+X0))* I2 FMVAb=IFb * sqrt(3) * V2 * 1e-3 mprintf("\n(b)single line to ground fault Fault MVA=%.2f MVA, Fault Current=%.2f A",FMVAb,IFb) IFc=abs(sqrt(3)/(X1+X2))* I2 FMVAc=IFc * sqrt(3) * V2 * 1e-3 mprintf("\n(c)L-L Fault MVA=%.2f MVA, Fault Current=%.1f A",FMVAc,IFc) IFd=abs(1/(X1+(X2*X0/(X2+X0))))* I2 FMVAd=IFd * sqrt(3) * V2 * 1e-3 mprintf("\n(d)L-L-G fault Fault MVA=%.2f MVA, Fault Current=%.2f A",FMVAd,IFd)
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/623/CH22/EX4.5.7/U4_C5_7.sce
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U4_C5_7.sce
//variable initialization ch=12400 //product of speed of light and Plank's constant (eV*Å) Rch=13.6 //product of speed of light, Plank's constant and R (eV) z=23 //atomic no. of vanadium lembda=24 //wavelength of L absorption edge (Å) //calculation El=ch/(lembda*10^3); //binding energy of L electron (KeV) Ek=((3/(4*10^3))*Rch*(z-1)^2)+El; //binding energy of K electron (KeV) printf("\nBinding energy of K-electron = %.2f KeV",Ek);
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clc com =-1; error_number = 999; while (error_number <> 0) com = com+1; try %serial_port=openserial(com,"9600,n,8,1"); catch disp(['Não pode ler serial']) end [error_message,error_number]=lasterror(%t) disp("ERROR") disp(error_message) disp(error_number) if com == 10 then break end end disp("SUCESSO") disp("COM"+string(com)) //closeserial(%serial_port); //com = 3; //try // %serial_port=openserial(com,"9600,n,8,1"); //catch // disp(['Não pode ler serial']) //end //[error_message,error_number]=lasterror(%t) //disp("ERROR") //disp(error_message) //disp(error_number) //disp(error_number==0) //closeserial(%serial_port);
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 5 : INDUCTION MACHINES // EXAMPLE : 5.22 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA Wsc = 1000; // Power at Blocked Rotor test in Watts Vsc = 56; // Voltage at Blocked Rotor test in Volts Isc = 18; // Current at Blocked Rotor test in Amphere Woc = 52; // Power at No-load test in Watts Voc = 220; // Voltage at No-load test in Volts Ioc = 2.6; // Current at No-load test in Amphere m = 3; // Total Number of phase in Induction Motor p = 4; // Total number of Poles of Induction Motor V = 220; // Operating voltage of the Induction motor in Volts f = 50; // Frequency in Hertz s = 0.05; // Slip R = 0.65; // Per phase stator Resistance in Ohms // CALCULATIONS Vph = Voc/sqrt(3); // Per phase Voltage in Volts Wo = Woc/m; // Per phase No-load loss in Watts theta_0 = acosd(Wo/(Voc*Ioc*sqrt(3))); // No-load power factor angle in degree VSC = Vsc/sqrt(3); // Per phase locked rotor Voltage in Volts WSC = Wsc/m; // Per phase locked rotor loss in Watts theta_sc = acosd(WSC/(VSC*Isc)); // No-load power factor angle in degree ISC = Isc*(Voc/Vsc); // locked rotor current at full Voltage in Amphere Re = WSC/Isc^2; // Resistance in Ohms R1 = R*1.1; // Per phase AC stator Resistance in Ohms R_2 = Re - R1; // Per phase rotor Resistance in Ohms Zsc = VSC/Isc; // Per phase impedance in Ohms Xs = sqrt((Zsc^2)-(Re^2)); // Leakage Reactance in Ohms I_2 = (Voc/sqrt(3))/sqrt((R1+(R_2/s))^2+(Xs^2)); // Current in Amphere pf = cosd(atand(Xs/(R1+(R_2/s)))); // Power Factor Ws = 2*%pi*((120*f/p)*(1/60)); // Rotational Speed in Radians per Seconds Pg = (3*(abs(I_2)^2*R_2))/s; // 3-phase air gap power or Rotor intake Power in Watts T = Pg/Ws; // Torque in Newton-Meter // CALCULATIONS OR DATA OBTAINED FROM CIRCLE DIAGRAM FIGURE 5.35 and PAGE NO:-303 OA = 2.60; // Correspounding Current in Amphere at 87' from Y-axis (from Circle diagram) OE = 70.70; // Correspounding Current in Amphere at 55' from Y-axis (from Circle diagram) OP = 17.77; // Current in Amphere (from Circle diagram) OV = Voc/sqrt(3); // Phase Voltage in No-load test or value obatined from circle diagram in Volts PK = 11.6; // Correspounding Value from Circle diagram JK = 0.8; // Correspounding Value from Circle diagram PJ = 10.8; // Correspounding Value from Circle diagram PM = 11.6; // Correspounding Value from Circle diagram Pir = 3*OV*PK; // Total Rotor intake in Watts Plr = 3*OV*JK; // Total Rotor loss in Watts Po = 3*OV*PJ; // Total Mechanical power output in Watts T_c = (3*OV*PK)/Ws; // Total Torque in Newton-Meter s_c = JK/PK; // Slip obtained from Circle diagram s_pc = 100*s_c; // Slip in percentage eta = 100*(PJ/PM); // Eifficiency in Percentage // DISPLAY RESULTS disp("EXAMPLE : 5.22 : SOLUTION :-"); printf("\n (a) Input line current, I2 = %.2f A \n",I_2) printf("\n (b) Power Factor, Pf = %.3f \n",pf) printf("\n (c) Torque, T = %.2f Nm \n",T) printf(" \n Verification Results from Circle Diagram :-\n"); printf("\n (a) Efficency, eta = %.2f Percent \n",eta) printf("\n (b) slip, s = %.3f = %.f percent \n",s_c,s_pc) printf("\n (c) Torque, T = %.2f Nm \n",T_c)
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function [stk,txt,top]=sci_unix() // Copyright INRIA txt=[] if lhs==1 then V1=gettempvar(1) V1=gettempvar(2) txt=['['+V1+','+V2+'] = '+'unix_g('+stk(top)(1)+')'; 'disp('+V1+')'] stk=list(V1,'0','1','1','1') else stk=list(list('unix_g('+stk(top)(1)+')','-1','?','1','10'),.. list('unix_g('+stk(top)(1)+')','-1','1','1','1')) end
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//Book Name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 7 //example 7.7 //edition 1 //publisher and place:Nelson Engineering clc; clear; V=480;//terminal voltage in volt p=2;//number of poles fst=60;//frequency in hertz f=50;//decreased frequency in Hz Xeq=4;//inductive reactance in ohm R1=0.2;//stator resistance in ohm R2=0.3;//rotor resistance reffered to stator in ohm Td=60;//driving constant load torque in Nm n=3500;//speed of the motor in rpm ns=(120*f)/p;//synchronous speed in rpm Vs=V/sqrt(3); rps=ns/60; omegas=(2*%pi*rps); s=(Td*omegas*R2)/V^2; n=ns*(1-s);//the new motor speed at 50Hz in rpm mprintf("\nThe new motor speed at 50Hz is %f rpm",n) I2st=Vs/sqrt((R1+R2)^(2)+Xeq^(2));//starting current in A Xeqnew=(f/fst)*Xeq;//inductive reactance at 50Hz I2stnew=Vs/sqrt((R1+R2)^(2)+Xeqnew^(2));//starting current at 50Hz in A mprintf("\nThe starting current at 50Hz is %f A",I2stnew)
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Zg=50; //generator impedance Zo=75; //intrinsic impedance Zl=40; //line impedance Vg=5; //generator voltage Ts=(Zg-Zo)/(Zg+Zo); //reflection coefficient at source To=(Zl-Zo)/(Zl+Zo); //reflection coefficient at load temp=1-(To^2); temp1=(1-Ts)^2; temp2=(1-Ts*To)^2; Pin=((Vg)^2*temp1*temp2)/(8*Zo*temp); //input power Pl=Pin; //power delivered to the load disp("Watts",Pl,"The Power delivered to the load is same as that at the input-->");