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clc,clear //Example 6.17 //to express an equation in polar coordinates RHS=9 ; //Note that LHS is basically an equation of circle //But at any instant , it is numberically same as 9 LHS_numerically=RHS ; r=sqrt(LHS_numerically) ; printf('The equation in terms of polar coordinates is : r =%.0f',r)
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//check o/p when null vector is passed as i/p X = [0 0 0 0 0 0]; [a] = rc2poly(X) disp(a) //output // 1. 0. 0. 0. 0. 0. 0.
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//Frequency Modulation : Transmission : example 5-6 : (pg 218) d=75*10^3; fi=30*10^3; fi1=15*10^3; d1=1*10^3; fi2=100; fi3=2*10^3; a=d/fi; b=d/fi1; c=d1/fi2; d=d1/fi3; DR=d1/fi3; //part(a) printf("\nThe maximum deviation in broadcast FM is 75 kHz"); printf("\nmf = %.f",a);//for fi=30kHz printf("\nFor fi ...
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A=testmatrix('magi',5) B = A(2:3, 1:5) C = [A; B]
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2017 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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function [t00,txx,txy,txz,tyy,tyz,tzz,alp]=initgrobj(nx,ny,nz,time,par1,par2,x,y,z,r,alp) // [t00,txx,txy,txz,tyy,tyz,tzz,alp]=initgrobj(nx,ny,nz,time,par1,par2,x,y,z,r) // Initialise gij for set of parts moving // Assume alp shifted by -2GM/r // numobjects // location of object // velocity of ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// Example 2.5.a: Calculate Common Emitter D.C. Current gain alfa=0.950;//Common base D.C. Current gain beta= (alfa/(1-alfa)); disp(beta,"Common Emitter D.C. Current gain")
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clc clear all N=31 n=-15:15 h=(1/4)*sinc(n*3.14/4) w=0.54+0.46*cos(2*3.14*n/(N-1)) //whm = window('hm', N); figure(1) plot2d3(n,h) a=gca(); a.x_location="origin" a.y_location="origin" title('Impulse response of the Desired Filter') xlabel('Discrete Time') ylabel('Impulse Response') figure(2) plot2d3(n,w) a=gca(); a...
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format(25) x = [3 4]' y = 3 ./ x n = length(x) plot(x, y, 'ro-'); xgrid // Matriz de Vandermonde for i = 1:n V(i,j) = x(i)^(j - 1) end end //Interpolação X = 3 + (28 / 100) // Ponto para fazer a intepolação a = inv(V) * y p = 0 for k = 1:n p = p + a(k) * X.^(k - 1) end plot(X, p, 'b.-'); xgrid dis...
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clc //initialisation of variables M= 50. //gm T= 98. //C Mw= 75. //gm T1= 19. //C Tm= 27. //C Mc= 123. //gm SH= 0.1 //cal gm^-1 C^-1 Qinst= 6.5 //cal //CALCULATIONS c= (Mc*SH+Mw+Qinst)/(M*(T-Tm)) //RESULTS printf ('Mean specific heat of the metal sample= %.4f cal/C gm',c) //The answer given in textbook is...
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clear; clc; //Example13.13[Effective Emissivity of Combustion Gases] d=5,H=5;//Diameter and height of cylindrical furnace[m] T=1200;//Temp of gases[K] P=2;//Pressure[atm] yN2=0.8,yH2O=0.08,yO2=0.07,yCO2=0.05;//Volumetric Composition //Solution:- Pc=yCO2*P;//[atm] Pw=yH2O*P;//[atm] disp("atm",Pw,"and","atm",...
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clc // Given that m_0 = 1.6e-27 // mass of proton in kg KE = 500 // kinetic energy of electron in MeV c = 3e8 // speed of light in m/sec // Sample Problem 27 on page no. 54 printf("\n # PROBLEM 27 # \n") printf(" Standard formula used \n") printf("\n E = m*c^2 \n") del_m = KE*1e6*1.6e-19/c^2 // change in mass of proto...
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clc clear printf("example 5.15 page number 207\n\n") //to find the amount of vapor and liquid and amount of heat transfer F = 5000 //in kg/hr xF = 0.01 xL = 0.02; L = F*xF/xL; V = F-L; printf("L = %f Kg/hr\n V = %f kg/hr",L,V) TF= 303 //in K hF = 125.9 //in KJ/kg T1 = 373.2 //in K Hv = 2676...
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clc //to calculate value of Temperature Bc=105*10^3 //magnetic field in amp/m Bo=150*10^3 //critical field of the metal in amp/m Tc=9.2 //critical temperature of the metal in K T=Tc*sqrt(1-(Bc/Bo)) disp("value of temperature is T="+string(T)+"K")
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// problem 4.10 r=5 h1=5 d=0.08 a=0.005 h2=h1-2 Cd=0.6 g=9.81 z=((2*r*((h1^1.5)-(h2^1.5)))/3)-((((h1^2.5)-(h2^2.5)))/5) T=(z*2*3.142)/(Cd*a*((2*g)^0.5)) disp(T,"time in seconds to lower the level by 2m")
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//acids and bases// //example 2.9// M=0.001;//molarity of benzoic acid// N=M;//normality of benzoic acid// V=1/N; K=7.3*10^-5;//dissociation constant of benzoic acid// a=sqrt(K*V);//since benzoic acid is very weak// printf('the degree of ionization of the solution is %f',a); H=N*a; printf('\n The H+ concentrat...
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//Example 5.5 clc //clears the command window clear //clears all the variables format('v',18) //increasing the precision n=...
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clear // // //Initilization of Variables d=750 //mm //Diameter of water supply pipes h=50*10**3 //mm //Water head sigma=20 //N/mm**2 //Permissible stress rho=9810*10**-9 //N/mm**3 //Calculations //Pressure of water P=rho*h //N/mm**2 //Stress //sigma=p*d*(2*t)**-1 //After further simplifying t=P*d*(2*sigma)**-1 //m...
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// ==================================================================== // Allan CORNET // DIGITEO 2008 - 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== test_path = fullfile(xls_getRootPath(...
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function [value] = kLinLight(ref) // Ouput variables initialisation (not found in input variables) value=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); reply = kTurret(ref,2,"L"); // !! L.3: Matlab function sscanf not yet converted, original calling sequence used [value,count,...
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//CHAPTER 6 _ PRESSURE AND SOUND MEASUREMENT //Caption : Sound Measurement // Example 10// Page 370 Lp1=75 //('enter the sound level first machine=:') Lp2=77 //('enter the sound level second machine=:') Lp3=79 //('enter the sound level third machine=:') disp("Since the noise levels are incoherent,the total ...
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function rfeq = get_equalization_signal(respfreq) //EQUALIZACAO x = gsort(respfreq); x = x(length(respfreq)-3); a = (max(respfreq)-min(respfreq))/x; b = max(respfreq)-a*x; rfeq = (respfreq-b)/a; endfunction
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clear; clc; disp('Example 4.9'); // aim : To determine // the specific volume // Given values t = 325; // temperature, [C] P = 2; // pressure, [MN/m^2] // solution // from steam table at given t and P vf = .1321; // [m^3/kg] tf = 212.4; // saturation temperature, [C] mprintf('\n The specifi...
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clc //Initialization of variables A=140 //in^2 P=48 //lb/in^2 mu=3.78*10^-7 g=32.2 G=100 //lb/s p=80 //lb/in^2 T=65+460 //R k=1.4 R=1715 //calculations Rh=A/P /12 R1=G*4*Rh/ (mu*g*A/144) R2=R1 f=0.0083 gam1=p*g*144/(R*T) V1=G*144/gam1/A c=sqrt(k*R*T) M1=V1/c M2=1/sqrt(k) D=4*Rh L= ((1-M1^2 /M2^2)/...
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function [r] = solve(ns) // Geef %t terug indien ns een semimagisch vierkant is, // %f indien niet. r = %t // numbercount for (num = 1:9) numcount = 0 for (i = 1:size(ns,"r")) for (j = 1:size(ns,"c")) if (ns(i,j) == num) then n...
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//Chapter-11 example 4 //============================================================================= clc; clear; PW = 1.5*10^-6;//pulse width in sec PRF = 2000//per second //Calculations Dc = PW*PRF;//duty cycle //Output mprintf('Duty Cycle is %e',Dc); //==========end of program=======================...
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clc; clear all; E=1000;//applied electrical field P=4.3E-8;//polarisation e0=8.854e-12;//permittivity of vacume er=1+(P/(E*e0));//relative permittivity of NACl disp('',er,'relative permittivity of NACl is:')
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//Example 2.34 clc funcprot(0); printf("Enter the value of radius:"); radius=scanf("%d"); pi=3.141593; circumference = 2 * pi * radius; area = pi* radius*radius;
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//CHAPTER 10- THREE-PHASE INDUCTION MACHINES //Example 7 disp("CHAPTER 10"); disp("EXAMPLE 7"); //VARIABLE INITIALIZATION P=4; //number of poles f=50; //in Hz r2=0.1; //rotor resistance in Ohms X2=2; //standstill reacta...
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function [Inn,X,Gbar]=colinout(G) [Innt,Xt,Gbart]=rowinout(G'); Inn=Innt';X=Xt';Gbar=Gbart';
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b=300//width, in mm d=600//effective depth, in mm fck=15//in MPa fy=500//in MPa Xc=0.456*d//in mm Mu=0.36*fck*b*Xc*(d-0.416*Xc)/10^6//in kN-m Ast=round(0.36*fck*b*Xc/0.87/fy)//in sq mm mprintf("Moment of resistance of the beam=%f kN-m\nSteel required=%d sq mm", Mu,Ast)
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load qn3.hdl, output-file qn1.out, output-list x0%B3.1.3 x1%B3.1.3 output-list s0%B3.1.3 s1%B3.1.3 s2%B3.1.3 output-list y0%B3.1.3 y1%B3.1.3 y2%B3.1.3 y3%B3.1.3; output-list y4%B3.1.3 y5%B3.1.3 y6%B3.1.3 y7%B3.1.3; output-list z0%B3.1.3 z1%B3.1.3 z2%B3.1.3 z3%B3.1.3; output-list z4%B3.1.3 z5%B3.1.3 z6%B3.1.3 z7%...
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#------------------------------------------------------------------------------ # Endgame # # Computer Go Test Collection http://www.cs.ualberta.ca/~games/go/ # # $Source: /usr/cvsroot/project_cgtc/endgame.tst,v $ # $Id: endgame.tst,v 1.5 2004/05/15 04:07:45 mmueller Exp $ #---------------------------------------------...
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A=read("C:\Users\GUSTAVO\Desktop\Matriz.txt",4,4) for i=1:4 soma=0 cont=0 for j=1:4 soma = soma + abs(A(i,j)) end if (soma == 0.0) then printf("Linha %d \n",i) cont = cont + 1 else printf("Linha não nula \n") end end printf("Número de linhas nulas: %g...
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Ex7_5.sce
clc T=300//K Na=10^16// cm^-3 Nd=10^15// cm^-3 e=1.6*10^-19// eV epsilon0=8.85*10^-14// F/m epsilons=11.7 Vbi=0.635// V Vr=5// V C=((e*(epsilons*epsilon0)*Na*Nd)/(2*(Vbi+Vr)*(Na+Nd)))^0.5 A=10^-4// cm^2 C=C*A disp(C,"the value of c with cross section area in F is")
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ex6_27.sce
// Exa 6.27 clc; clear; close; // Given data V_DD = 15;// in V R_D = 10;// in kohm R_D = R_D * 10^3;// in ohm I_D = V_DD/R_D;// in A disp(I_D*10^3,"The drain current in mA is"); V_D = V_DD - I_D*R_D;// in V disp(V_D,"The drain voltage in V is");
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Ex21_10.sce
clear // Variable declaration T_d=23// The dry bulb temperature in °C H=40// % saturation SH=36// The sensible heat to be removed in kW LH=14// The latent heat in kW // Calculation // Plotting on the chart ( Figure 21.10 ) from 23°C/40% and using the ratio R=SH/(SH+LH) printf("\n The process line meets the saturation ...
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EX16_9.sce
// Grob's Basic Electronics 11e // Chapter No. 16 // Example No. 16_9 clc; clear; // Determine the capacitance and tolerance for the capacitor in Fig. 16–15. disp ('The dots in the top row are read from left to right in the direction of the arrow. In the bottom row, they are read in the reverse order from right ...
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Example8_2.sce
//Base to base collector leakage current Icbo close(); clear; clc; Beta = 100; Icbo = 5*10^(-6); //Part(a) Ib = 0; Iceo = (Beta+1)*Icbo; //Part(b) Ib = 40*10^(-6); Ic = Beta*Ib + (Beta+1)*Icbo; mprintf('(a):Iceo = %0.0f micro A \n(b):Ic = %0.3f mA',Iceo*10^(6),Ic*1000);
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program1_PES2UG19CS301.sce
clc;clear; A = [2,5,1;4,8,1;0,1,-1], b = [0;2;3]; disp("Matrix before Gaussian Elimination: ") disp(A); Ab = [A b]; a = Ab; n = 3; for i = 2:n for j=2:n+1 a(i,j) = a(i,j) - a(1,j)*a(i,1)/a(1,1); end a(i,1) = 0; end for i=3:n for j=3:n+1 a(i,j) = a(i,j)-a(2,j)*a(i,2)/a(2,2); end a...
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15_22.sce
clear; clc; //Example - 15.22 //Page number - 545 printf("Example - 15.22 and Page number - 545\n\n"); //Given T = 25;//[C] // At 50 C P_1_sat = 7.866;//[kPa] P_2_sat = 3.140;//[kPa] // G_E/(R*T) = 1.4938*x_1*x_2/(1.54*x_1 + 0.97*x_2) // The excess Gibbs free energy expression can be written as // x...
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stacksize('max'); mode(-1) //exec('/usr/share/scilab/contrib/sivp/loader.sce'); getd; //cd '/home/priya/Desktop/img-disp-scilab-1'; fname='quickbird.jpg'; win4pix='win4pix.txt'; //RGB=evstr(x_dialog('RGB bands ?','1 1 1')); //subsetrow=evstr(x_dialog('Enter Row Start and Row End for subset image ','70 180')); //subset...
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mylu3b.sci
function [L,U] = mylu3b(A) n=size(A,1); q=size(1,n); row = [1:n]; for k=1:n-1 [piv,ind]=max(abs(A(k:n,k))); ind = k-1+ind; q(1,k)=row(1,ind); if(ind~=k) new = A(ind,:); A(ind,:)=A(k,:); A(k,:)=new; ro...
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HackALU.tst
load HackALU.hdl, output-file HackALU.out, output-list x%B1.16.1 y%B1.16.1 zx%B3.1.3 nx%B3.1.3 zy%B3.1.3 ny%B3.1.3 f%B3.1.3 n0%B3.1.3 out%B1.16.1 zr%B3.1.3 ng%B3.1.3; //x=12345, y= 6789, out = 0 set x %B0011000000111001, set y %B0001101010000101, set zx 1; set nx 0; set zy 1; set ny 0; set f 1; set n0 0; ...
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example_10_6.sce
clear; clc; disp("--------------Example 10.6---------------") //words x1=[0 0 0 0 0]; x2=[0 1 0 1 1]; x3=[1 0 1 0 1]; x4=[1 1 1 1 0]; //function to find Hamming distance function [d]=hamming_distance(x,y) xd=bitxor(x,y); d=num_of_ones(xd); endfunction function [count]= num_of_ones (d)// function to...
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exa6_4.sce
// Example 6-4 // Root locus clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; // exec("rootl.sci"); s = %s; D = s*(s + 0.5)*(s^2 + 0.6*s + 10); H = syslin('c',1,D); disp(roots(D),'open loop poles ='); rootl(H,[-6 -6; 6 6],'Root locus of G(s) = 1/(s*(s + 0.5)...
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Ex5_6.sce
// Example 5_6 clc;funcprot(0); // Given data T_H=500;// K T_L=300;// K P_1=80*10^3;// Pa v_4=10;// m^3/kg R=287;// J/kg.K k=1.4;// The specific heat ratio // Calculation n=(1-(T_L/T_H))*100;// % T_1=T_L;// K T_2=T_H;// K v_1=(R*T_1)/P_1;// m^3/kg v_2=v_1*(T_1/T_2)^(1/(k-1));// m^3/kg T_4=T_L;// K T_3...
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EX6_1.sce
//Chapter 6, Example 6.1, page 186 clc //Initialisation c=3*10**8 //speed of light f=400*10**6 //frequency in Hz l1=15*10**3 //distance in m l2=15*10**3 //distance in m l=30*10**3 ...
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11_5.sce
clc; clear; format('v',11); S=10^6; Z0=377; E=sqrt(S*Z0); H=E/Z0; disp(E,"The magnitude of the electric field vector,E(in V/m)="); disp(H,"The magnitude of the magnetic field vector,H(in A/m)=");
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6_4_1.sce
//chapter_no.-6, page_no.-260 //Example_no.6-4-1 clc; //(a) Calculate_the_strong_potential_w(inv)_for_strong_inversion kt=26*(10^-3); Na=3*(10^17); Ni=1.5*(10^10); wsinv=2*kt*log(Na/Ni); disp(wsinv,'the_strong_potential_w(inv)_for_strong_inversion(volts)'); //(b)Calculate_the_insulator_Capacitance eir=4; ei=8.854...
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ch12_12.sce
clear; clc; V_s=400; V_ml=sqrt(2)*V_s; V_f=3*V_ml/%pi; R_f=300; I_f=V_f/R_f; T_e=60; k=1.1; I_a=T_e/(k*I_f); N=1000; w_m=2*%pi*N/60; r_a=.3; V_t=k*I_f*w_m+I_a*r_a; a=acosd(V_t*%pi/(3*V_ml)); printf("firing angle=%.3f deg",a); N=3000; w_m=2*%pi*N/60; a=0; V_t=3*V_ml*cosd(a)/%pi; I_f=(V_t-I_a*r_a)...
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Ex1_17.sce
clear all; clc; disp("Scilab Code Ex 1.17 : ") //Given: d_ac= 20; //mm area_ac = %pi*(d_ac/2)^2; //Area = (%pi\4)d^2 area_al = 1800; //mm^2 d_pins = 18; //mm area_pins = %pi*(d_pins/2)^2; st_fail_stress = 680; //MPa al_fail_stress = 70; //MPa shear_fail_pin = 900; //MPa fos = 2; //Factor of safety l_ab ...
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Example27_4.sce
//Given that l = 1.2*10^-2 //in meter b = 1.2*10^-2 //in meter h = 15*10^-2 //in meter resistivityIron = 9.68*10^-8 //in ohm.m //Sample Problem 27-4(1) printf("**Sample Problem 27-4(1)**\n") R1 = resistivityIron*h/(l*b) printf("The resistance of the block is equal to %eOhm\n", R1) //Sample Problem 27-4...
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bow.19_4.tst
19 24:0.5 31:0.2 45:1.0 52:0.5 95:0.4 131:1.0 212:0.5 239:0.2 259:0.07142857142857142 260:1.0 576:1.0 980:0.25 1176:1.0 2219:1.0 3606:1.0 4731:1.0 19 24:0.25 31:0.4 81:0.5 86:0.5 193:0.034482758620689655 328:0.2 448:1.0 477:0.14285714285714285 767:1.0 799:0.14285714285714285 980:0.25 3633:1.0 4176:1.0 5189:1.0 19 8:0.0...
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//Ex3_8 clc VCC=20 disp("VCC = "+string(VCC)+" volts") // collector supply voltage RL=2*(10^3) disp("RL= "+string(RL)+ " ohm") //resistance R1=100*(10^3) R2=R1 disp("R1 =R2= "+string(R1)+ " ohm") //resistance VBE=(0.7) disp("VBE = "+string(VBE)+" volts") // base-emitter voltage BF=100 disp("BF = "+strin...
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//check o/p when i/p is a vector and the dimension along with the direction is mentioned v=[3 5 2 1 6 3 7 8 1]; m=cummax(v,2,'reverse'); disp(m); //output // column 1 to 7 // // 8. 8. 8. 8. 8. 8. 8. // // column 8 to 9 // // 8. 1.
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//Chapter 13 //Example 13_9 //Page 319 clear;clc; x=200; l=300; i=0.75; r=0.00018; v=250; vd=i*r*(l*x-x^2/2); printf("Voltage drop = %.1f V \n\n", vd); printf("Voltage at a distance %d m from supply end = %.1f V \n\n", x, v-vd); p=i^2*r*l^3/3; printf("Power loss in distributor = %.2f W \n\n", p);
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//Problem 4.02: //initializing the variables: mdt = 0.15; // in kg/sec v = 420; // in m/sec //calculation: vxin = v vxout = 0 vyin = 0 vyout = v Fxgc = mdt*(vxout - vxin) Fygc = mdt*(vyout - vyin) Fres = (Fxgc^2 + Fygc^2)^0.5 theta = (atan(Fygc/Fxgc))*180/%pi + 180 printf("\n\nResult\n\n") printf("\...
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clc clear //Initialization of variables gam=0.0765 //lb/ft^3 l=40 //ft w=16 //ft d=8 //ft z=6 //ft BG=1 //ft //calculations I=1/12 *l*w^3 V=l*w*z IVG=I/V - BG MB=I/V //results printf("I/V -BG = %.2f ft ",IVG) if IVG >0 then printf("\n Barge is stable") else printf("\n The barge is unstable")...
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clc //initialisation of variables V= 1.2 //m^3 M= 2350 //Kg w= 0.086 G= 2.71 W= 1000 //kg/m^3 //calculations R= M/V D= M/((1+w)*V) e= (G*W/D)-1 n= e/(e+1) S= (w*G/e)*100 v= (M-(M/(1+w)))/W //results printf ('moist density = % f kg/m^3 ',R) printf ('dry density = % f kg/m^3 ',D) printf ('void ratio = % ...
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//Convolving 2 seq in discrete time domain without convol func clc ; clear ; close ; x=input('ENTER THE FIRST SEQUENCE x(n): '); m=length(x); h=input('ENTER THE SECOND SEQUENCE h(n): '); n=length(h); //x(n) p=0:1:m-1; subplot(3,2,1), a = gca(); a.x_location = "origin"; a.y_location = "origin"; plot2...
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s=%s ; //create state equation of the following matrix TFcont=syslin ('c',(s+6)/(s^2+5*s+6)) SScont=tf2ss(TFcont ) [Ac ,Bc ,U, ind ]=canon( SScont ( 2 ) , SScont ( 3 ) ) disp(Ac,"MAtrix A=") disp(Bc,"MAtrix B=")
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clc //Initialization of variables v2=36 //fps beta=150 //degrees u=60 //fps rho=1.94 Qd=0.0218 V1=100 //fps gam=62.4 g=32.2 //calculations v2s=v2*sind(beta) v2c=u+v2*cosd(beta) V2=34 //fps alpha=32 //degrees Fx=rho*Qd*(v2c-V1)*(V1-u) Fy=-rho*Qd*(V1-u)*v2s Fx2=rho*Qd*V1*(v2c-V1) HPin=gam*Qd*V1*(V1^2 /(...
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clear ; clc; printf("\t Example 9.6\n"); T1=628; //saturated temp.of water, K a=13996; //desity difference,kg/m^3 s=0.418; //surface tension,kg/s^2 Hfg=2925*1000; //latent heat,J/kg a2=4; //density of mercury, kg/m^3 Qmax=0.149*a2^0.5*Hfg*(9.8*a*s)^0.25/10^7-.015; ...
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// Example 8_5 clc;funcprot(0); // Given data Q=5;// The flow rate of water through a pipe in gal/min q=10*10^3;// kW c_p=4.18;// The specific heat in J/kg.K rho=1*10^3;// The density of water in kg/m^3 // Calculation Q=(Q*3.785*10^-3)/60;// The flow rate of water through a pipe in m^3/s deltaT=q/(rho*Q*c_p*...
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//ques2 //Entropy Generation during Heat Transfer Processes clear clc //(a)Sink at 500K Qsource=-2000//heat of source in kJ Qsink=2000//heat of sink in kJ Tsource=800//temperature of source in K Tsink=500//temperature of sink in K Ssource=Qsource/Tsource//entropy of source in kJ/K Ssink=Qsink/Tsink//entropy o...
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// Group_13: Bhargava B // Surya K // S K Savant // Question: // Let x(n) be the 13-point Barker sequence // x(n) = {+1, +1, +1, +1, +1, -1, -1, +1, +1, -1, +1, -1, +1}. // Determine the auto-correlation of the above sequence. // // Function to find auto_correlation of x //Barker NOT WORK...
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// Exa 2.2 Determining the infinitesimal stage efficiencies p1=1.02; // Initial Pressure in bar T1=300; // Initial Temperature in K // part(a) T2=315; // Final Temperature in K gamma=1.4; // Specific Heat Ratio g=9.81; // Gravitational acceleration in m/s^2 sg=1; // Specific Gravity of air delp=(1500)*(0.00...
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function [B] = transpose(m, n, A) B = zeros(m, n); B = A'; disp('The marix is ', A) disp('Transposed matrix is ') endfunction
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13_4_1.sce
clc //initialisation of variables u1= 0.5 //ft^3/sec b= 5 //ft w= 4 //ft g= 32.2//ft/sec^2 //CALCULATIONS u= u1*12*12/(b*w) s= sqrt(g*w/12) F= u/s r= 0.5*(sqrt(1+8*F^2)-1) y= r*w yc= (((w*y*(y+w)))/2)^(1/3) //CALCULATIONS printf (' critical depth= %.2f in',yc)
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pathname=get_absolute_file_path('6_16b.sce') filename=pathname+filesep()+'6_16b_data.sci' exec(filename) R_Cmax=(Pf*P*746/W)-0.8776*sqrt(W/(D*S*Cdo))*(1/(L_Dmax)^1.5)//(R/C)max printf("\Answer:\n") printf("\n\Maximum Rate of climd for CP-1: %f m/s\n\n",R_Cmax)
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clear clc DelH2m_f=10;//molar heat of fusion in kJ/mol T1=298.15;//temperature in K T2=353.35;//freezing temperature in K R=8.314;//in J/Kmol X=(10^-(((DelH2m_f*10^3)/R)*((1/T1)-(1/T2))));//solubility of napthalene printf('X=%.4f',X) //solution is wrong //There are some errors in the solution given in textbo...
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// current is 2A //120V i=2; v=120; // v=I*R where R is the resistance in Ohms r=v/i; disp("r=") disp(r) units='Ohms' r=[string(r) units]; disp(r)
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// Exa 5.15 clc; clear; close; format('v',6) // Given data Af = 100; Vi = 0.6;// in V Vo =Af*Vi;// in V Vi = 50;// in mV Vi = Vi * 10^-3;// in V // Internal gain of amplifier, A = Vo/Vi; disp(A,"The value of A is : "); B= ((A/Af)-1)/A; disp(B,"The value of B is");
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clc mo = 9.1*10^-31 disp("mo = "+string(mo)+"kg") //initializing value of mass of electron m_star=0.067*mo disp("m_star=0.067*mo = "+string(m_star)+"kg") //initializing value of appropriate mass in the conduction band for GaAs apsilen = 13.2*8.85*10^-14 disp("apsilen = "+string(apsilen)+"F/cm") //initializing val...
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//=========================================================================== //chapter 10 example 13 clc; clear all; //variable declaration P = 1000; //resistance in arm AB in Ω Q = 100; //resistance in arm BC in Ω R = 200; //resistance in arm BD in Ω Si1 = 10; //sensitivity Si2 = 5; //sensitivity ...
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clc; clear all; disp("Laminar air flow") L=2;//m length of plate U=5;//m/s velocity of air rho=0.815;//kg/m^3 density of air k=0.03025;// W/(m.C) Pr=0.6965;// Prandlt number Ts=120;// degree C Ta=40;// degree C v=2.107*10^(-5);//m^2/s kinematic viscosity Re=U*L/v;// Reynold's number Nu=0.664*(Re^0.5)*...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS // EXAMPLE : 1.24 : // Page number 706 clear ; clc ; close ; // Clear the work ...
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//determine the nyquist rate //8.1(b) clc; clear all; //x(t)=sin2(200*pi*t) //x(t)=0.5-0.5cos(400*pi*t) wp=400; F1=wp/2; Fs=2*F1; disp('Nyquist Rate='); disp(Fs);
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 3.3.2\n') //given data m=10 //mass of solid in Kg Kr=3000 //stiffness of natural rubber in N/m Kf=12000 //stiffness of felt in N/m Cr=100 //damping coefficient of natural rubber in N-sec/m Cf=330 //damping coefficient of felt in N-sec/m //calcu...
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// run it this way: // $ scilab-adv-cli -f grayplot-cam.sce -args cameradisplacementfile clear; exec('peak_detect.sci'); funcprot(0); // peaks() is redefined args= sciargs(); temp=csvRead(args(5), ascii(9), 'double'); threshold_ratio= 32; sample_window= 120; // FFT sample_window window sample_time= 10; // s freq_samp...
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Whois Server Version 2.0 Domain names in the .com and .net domains can now be registered with many different competing registrars. Go to http://www.internic.net for detailed information. Domain Name: MANGATRADERS.COM Registrar: GODADDY.COM, LLC Whois Server: whois.godaddy.com Referral URL: http://registr...
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function [rep,stat]=unix_g(cmd) //unix_g - shell command execution //%Syntax //rep=unix_g(cmd) //%Parameters // cmd - a character string // rep - a column vector of character strings //%Description // cmd instruction (sh syntax) is passed to shell, the standard output // is redirected to scilab variable rep. //%Exam...
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//Programming Example 7.14 //factorial of an integer using recursion function[] = main() //read in the integer quantity printf("n = "); n=scanf("%d"); //calculate and display the factorial printf("n! = %d\n", Factorial(n)); endfunction function[f] = Factorial(n) ...
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15_04.sce
//Problem 15.04: //initializing the variables: A = 10; B = 100000; //calculation: // Since there are two contributing factors to the cost model, one may write the \n following equation for the profit, P //P = A(t - tc) - B/(TH - t); TH = 500 tc = 100 //For breakeven operation, set P = 0 so that //(t - tc...
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moth-flame-o.sce
clear clc exec('objective.sce'); disp("RUNNING...") rand('seed',getdate('s')) POPSIZE = 50 DIM = 2 UPPER = 100 LOWER = -100 MAXITER = 50 b=1 MOTH = rand(POPSIZE,DIM).*(UPPER-LOWER)+LOWER FIT = F1(MOTH) [BESTFIT IND] = min(FIT) GBESTPOS = MOTH(IND,:) GBESTFIT = BESTFIT // SORT MOTH BASED ON FITNESS AND STORE SORTE...
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CandidateSelector expand width=4 base=5 exponent=3 left=4 right=0 fileName=data/prewrob3.sub.man chain8 [[3,-3,0,3],[3,0,3,0],[-1,3,2,-3],[2,1,3,-1]] det=0 [71,-14,-70,-23] [186,3,-184,-59] [372,6,-368,-118] [744,12,-736,-236] [1488,24,-1472,-472] [2976,48,-2944,-944] [5952,96,-5888,-1888] [11904,192,-11776,-3776] [23...
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clc rho=924; //kg/m^3 g=9.81; //m/s^2 H=2; //m d=2; //depth in m p=rho*g*H; a=d*H; F=p*a/2; disp("Total force exerted over the wall =") disp(F) disp("N")
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 5.7\n\n\n"); // Chapter 5 : Properties Of Liquids And Gases // Problem 5.7 (page no. 192) // Solution //Using Table 2 ans a quality of 80%(x=0.8),we have //at 120 psia x=0.8; sf=0.49201; //saturated liquid entropy //Unit:Btu/lbm*R sfg=1.0966; //Evap...
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//Example 4.5 clc; clear; close; format('v',8); //Given data : S1=1.2;//sp. gravity S2=13.6;//sp. gravity w=1000;//kg/m^3 h2=50/1000;//m h1=200/1000;//m pa=w*(S2*h1-S1*h2);//kg/m^2 disp(pa,"Pressure in the pipe in kg/m^2: "); disp(pa*9.81,"Pressure in the pipe in Pa: ");
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errcatch(-1,"stop");mode(2);; all; Ef=5.51 //in eV E=(3/5)*Ef;//The average energy of a free electron in silver at 0k disp(+'eV',E,'The average energy of a free electron in silver at 0k =') exit();
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//Example 1 with a simple C code f1=['#include <math.h>' 'void fooc(double c[],double a[],double *b,int *m,int *n)' '{' ' int i;' ' for ( i =0 ; i < (*m)*(*n) ; i++) ' ' c[i] = sin(a[i]) + *b; ' '}']; m...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Moving Frame of Reference test </description> <executable>IncNavierStokesSolver</executable> <parameters>Moving_reference_frame.xml</parameters> <files> <file description="Session File">Moving_reference_frame.xml</file> <file descri...