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//Obtain path of solution file path = get_absolute_file_path('solution7_6.sce') //Obtain path of data file datapath = path + filesep() + 'data7_6.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the direct shear force on each bolt Dshear (N) Dshear = (P * 1000)/N //Assume the core cro...
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// Exa 1.21.7 clc; clear; close; // Given data lembda = 1.54;// in Å lembda= lembda*10^-8;// in cm At = 63.54;// atomic weight density = 9.024;// in gm/cc n = 1; N_A = 6.023*10^23; m = At/N_A;// mass a =(density*m)^(1/3);// in cm h = 1; k = 0; l = 0; d = a/(sqrt( ((h)^2) + ((k)^2) + ((l)^2) ));// in cm ...
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clc;funcprot(0);......//Example 4.3 //Initialization of variables L=4;........//Vertical height of the plate in m q=800;..........//Solar radiation in W/m^2 alpha=1;......//100% absorptivity Ta=30;.......//Atmospheric temperature in degree celsius g=9.81;....//Gravitational constant Pr=0.697;......//Prandlt no ...
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clc; Vgs=-5:-5:-20;//Id=Idss*(1-(Vgs/Vgso))^2 Vgso=-20; Idss=12*10**-3; Id=Idss*(1-(Vgs/Vgso))^2; disp('mA',Id*10**3,"Id="); y=0:1:12; x=0:-5:-20; a=gca() //get the current axes a.box="off"; a.y_location="right"; plot2d(Vgs,Id); xlabel("Gate-to-source voltage (VGS)"); ylabel("Drain current ID(mA)");
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 24 clc; disp("CHAPTER 7"); disp("EXAMPLE 24"); //10kVA 2500/250 V single phase transformer //VARIABLE INITIALIZATION va=10000; v1=2500; //primary voltage in Volts v2=250; //secondary voltage in Volts R1=4.8; ...
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function save_super(x) // given a super block definition x save_super creates a file which contains // this super block handling macro definition x1=x(1);nam=x1(2); nin=0;nout=0;clkin=0;clkout=0; for k=2:size(x) o=x(k) if o(1)=='Block' then select o(5) case 'IN_f' then nin=nin+1 case 'OUT_f' th...
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//chapter 13 //example 13.7 //page 565 printf("\n") printf("given") hfe=100;Vbe=.7;Ic1=1*10^-3;Ic2=Ic1;Ic3=Ic2;Ic4=Ic3;Vee=10;Vce=3;Acl=33; disp("different resistor value of circuit") R1=Vbe/((10*Ic1)/hfe) R3=(Vee-Vbe)/(Ic1+Ic2) Vr2=Vee+Vbe-Vce R4=Vr2/Ic1 R2=R4; R7=(Vr2-Vbe)/(Ic3+Ic4) R8=Vee/Ic3 R6=6.8*10...
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clc; C_d=0.6; d_o=0.05; // m g=9.8; // m/s^2; R=2; // H1=1.5; // a_o=%pi*d_o^2/4; t=%pi/C_d/a_o/sqrt(2*g)*(4/3*R*H1^(3/2)-2/5*H1^(5/2)); disp("The time to drain the tank is found to be ") disp(t); disp("seconds");
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// Example 6.12;//bandwidth clc; clear; close; tr=10;//in ns bw=(0.35/tr);//in MHz disp(bw*10^3,"bandwidth in MHz is")
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clc // Given that d=1//in inch Diameter of the hole T=(1/8)//in inch thickness of the sheet // Sample Problem on page no. 396 printf("\n # Calculation of Punch Force# \n") UTS=140000//in psi Ultimate Tensile Strength of the titanium alloy Ti-6Al-4V L=3.14*d//total length sheared which is the perimeter of ...
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// Given:- T1 = 300.00 //temperature in state 1 in kelvin P1 = 1.00 //pressure in state 1 in bar P2 = 2.00 //pressure in state 2 in bar R = 287.00 //gas constant of air in SI units // Ca...
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clc clear //Initialization of variables short=2 //ft apart=3 //ft long=4 //ft T1=2260 //R T2=530 //R sigma=0.1714 //calculations A1=short*long ratio=short/apart disp("from curve 3") F=0.165 Q12=A1*F*sigma*((T1/100)^4 -(T2/100)^4) //results printf("Net exchange of radiation = %d Btu/hr",Q12) disp("The a...
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//Chapter 3, Example 3.12, page 105 clc //Initialisation L=13200 //L parameter in m H=10240 //H parameter Re=6370000 //actual redius of earth ht=30 //height in m hr=2...
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main begin int l; int r; int i; int j; int k; int[] array; boolean changed; boolean flag; array = new int [10]; array[0] = 123; array[1] = 12; array[2] = 13; array[3] = 23; array[4] = 3; array[5] = - 3; array[6] = 412; array[7] = 12345; array[8] = 2; array[9] = 0; do begin ...
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// Example 4.15.4 page 4.38 clc; clear; tau01=10; //pulse broadning ns/mm L1=0.1; //length in kilometer tau02=20; //pulse broadning ns/m L2=1; //length in kilometer tau03=2000; //pulse broadning ns/m L3=2; //length in kilometer tau1=10d-9/1d-6; tau1=tau1*L1; Bopt1=1/(2*tau1); ...
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// Exa 13.5 clc; clear all; // Given data Input=6.3; // V Output=5.2; // V Range= 9.5; // inches // Solution // 0.5 inches core displacement produces 5.2 V // Therefore, a 0.45 inch movement produces voltage as V1=0.45*5.2/0.5; // Similarly - 0.30 inches core movement produces voltage as V2=-0.30...
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//clc(); clear; //To compute the polarisation A=6.45*10^-4; //area of capacitor plates in m^2 d=2*10^-3; //capacitor plates seperation in m V=12; //potential in V epsilonr=5.0; //dielectric constant N=6.023*10^23; //avagadro number in mol inverse epsilon0=8.85*1...
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clc //initialisation of variables h=0.72//percent t=80//F p=14.9//psia w=0.622//ft q=0.5069//ft //CALCULATIONS Pact=h*q//Psia S=w*(Pact/(p-Pact))//lb vapor per lb dry air //RESULTS printf('The specific humidity and also its dew point temperature=% f lb vapor per lb dry air',S)
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inf = float('inf') # sampling time delta_t = 1.0 # pvt simulator state required for initializing the simulator plant_pvt_init_data = None ############################# # P1: Property Description ############################# # Rectangular bounds on initial plant states X0[0, :] <= X <= X0[1, :] initial_set = [[0.0]...
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//find.. clc //soltuion //given d=2.6//m n=15 B=22.5 q=2.967//rad u=0.28 T=960//N m=1.5//kg/m //let N be speed v=sqrt(T/(3*m))//m/s N=(v*60)/(%pi*d)//rpm printf("rpm is,%f rpm\n",N) //for max power trans Tc=T/3 T1=T-Tc //log(T1/T2)=u*q*cosec(%pi/180*B)=0.9435 T2=T1/8.78// P=(T1-T2)*v*n//W printf("t...
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc., USA,pp 436. //Chapter-3 Ex3.2.a Pg No. 96 //Title:Residence time for four STR's in series //======================================================================================== clear clc //INPUT X_A=0.95;//Given conversion t_batch=6;/...
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x f(xs) 1.646582 2.284632 1.898332 2.590988 0.473665 0.590169 1.877802 2.566896 1.012773 1.405433 0.388689 0.469060 0.733454 0.980569 1.216137 1.703616 0.247892 0.281092 0.126748 0.135272 1.349299 1.891069 0.306961 0.357751 1.038700 1.444150 0.635985 0.831911 0.196191 0.216911 1.688834 2.337742 0.5369...
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//clc() F1 = 6*1000;//L/s BOD1 = 3 * 10^-5;//g/L BOD2 = 5 * 10^-3;//g/L V = 16 * 10^3;//m^3/day v = V * 10^3 / (24 * 3600);//L/s //Let BOD of the effluent be BODeff, BODeff = (BOD2 * (F1 + v) - BOD1 * F1) / ( v ); disp("g/L",BODeff,"BOD of the effluent of the plant = ")
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clear // // //Initilization of Variables //Let y be the yield stress y=250 //N/mm**2 //yield stress FOS=1.75 //Factor of safety P=140*10**3 //N //compressive Load D=101.6 //mm //External diameter //Calculations p=y*(FOS)**-1 //N/mm**2 //Permissible stress A=P*p**-1 //mm**2 //Area of hollow tube //Let d be the int...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex9_6.sce. clc; clear; P=500e3; Vl=3.3e3 Il=P/(sqrt(3)*Vl); Vph=Vl/sqrt(3); Iph=Il; Rph=0.4; Xsyn=4.2; printf("\n (a)") pf=1; //unity Ef=((Vph+...
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clear; clc; // Example: 5.13 // Page: 168 printf("Example: 5.13 - Page: 168\n\n"); // Solution //*****Data*****// m = 80;// [mass of Argon, g] T1 = 300;// [K] T2 = 500;// [K] Cv = 0.3122;// [kJ/kg K] //**************// Mw = 40;// [Molecular Weight of Argon] n = m/Mw;// [moles] deltaS = n*Cv*log(...
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//Caption:transfer_function // example 3.2.13 //page 49 // we have defined parallel and series function which we are going to use here //exec parallel.sce; //exec series.sce; syms G1 G2 G3 G4 H1 H2; //shift the summing point after block H2 towards right of block H2 //shift the summing point after block H1 towar...
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load Bonus.hdl, output-file Bonus.out, // output file compare-to Bonus.cmp, // compare file output-list in%B1.4.1 load%B2.1.2 red%B2.1.2 green%B2.1.2 yellow%B3.1.3; // does a full 0-15 cycle without load/in testing. set in %B0000, set load 0, output; // 0 tick, tock, output; // 1 tick, tock, ou...
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// Example 6-10 // Design of parallel compensation by root locus clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; // exec("plotresp.sci"); function [G,C] = getsystem(K) G = 20 / ( s*(s+1)*(s+4) + K*s ); //open loop system C = syslin('c',G /. 1); // closed ...
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clear; clc; //Example - 16.11 //Page number - 584 printf("Example - 16.11 and Page number - 584\n\n"); //Given R = 8.314;//[J/mol*K] - Universal gas constant T = 25 + 273.15;//[K] - Surrounding temperature den_water = 1000;//[kg/m^(3)] - Density of water m_water = 100;//[g] - Mass of water m_C12H22 = 5;/...
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clear() clc() //Decode ole file, extract and open Excel stream [fd,SST,Sheetnames,Sheetpos] = xls_open('WLTP-DHC-12-07e.xls'); //Read second data sheet [Value,TextInd] = xls_read(fd,Sheetpos(2)); //close the spreadsheet stream mclose(fd); //load WLTP time and speed values in structure WLTC.time = Value(8...
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//Example 7.42b clc; function[za]=ztransfer(sequence,n) z=poly(0,'z','r') za=sequence*(1/z)^n' endfunction x=[1,2,3,4,5,0,7]; n1=-3:length(x)-4; X=ztransfer(x,n1); funcprot(0);
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//find string efficiency clear; clc; //soltion //given V1=poly(0,"V1"); V2=poly(0,"V2"); V3=poly(0,"V3"); V=poly(0,"V"); //Since wC is common so its cancelled function x=%c_sign(a) x = '1.05*V2/1.2' + a + '0.05*V3/1.2' endfunction printf("V1="); disp(sign('+')); function x=%c_sin(...
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function [p,h] = bisection(f,a,b,nmax,tol) h = []; // histórico de convergencia |f(p_n)| < tol fa = f(a); fb = f(b); if (abs(fa) < tol) then disp("La raíz es a"); p = a; return; end if (abs(fb) < tol) then disp("La raíz es b"); p = b; return; ...
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//Example 9.9 // Natural response of a Phase-Shift Oscillator // Continued from textbook example 9.7 C=2*10^-6; R=100; L=10*10^-3; K=poly(0,'K'); // Variable gain K alpha=(R/(2*L))*(L/(R^2*C)+1-K); omega_0=sqrt(2/(L*C)); K=roots(alpha); alpha=horner(alpha,K) // Since this is the case of underdamped response ...
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//Problem 8.02: A conductor carries a current of 20 A and is at rightangles to a magnetic field having a flux density of 0.9 T. If the length of the conductor in the field is 30 cm, calculate the force acting on the conductor. Determine also the value of the force if the conductor is inclined at an angle of 30° to the ...
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clc; clear all; disp("Heat loss rate") ti=350;// degree C to=50;// degree C k=1.5;// W/(m*C) x=0.3;// m l=4.5;//m b=3.75;//m h=3;//m Ai=2*(l*b+l*h+b*h);//m^2 y=4*(l+b+h);// length of edges Sfce=y; Sfcc=0.15*x; Am=Ai+Sfce*.54*x+8*Sfcc*x; Am disp("m^2") Q=k*Am*(ti-to)/x; disp("W",Q,"rate of heat loss ...
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disp("the function define b/w n=0 to n=N ") xn=input("enter x(n):"); n=1:length(xn); M = length(xn); sum=0; for i=1:1:M sum=sum+xn(i); y(i)=sum/(M+1); end figure(1) subplot(2,1,1); plot2d3(n,xn); xlabel("n"); ylabel("x(n)"); title("x(n)----->n"); subplot(2,1,2); plot2d3(n,y); xlabel("n"); yl...
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function E = escalona(I, ex, ey) // ESCALONA_ // I: matriz de intensidade // ex: escalonamento vertical // ey: escalonamento horizontal // // Uso: // I = imread('figura.jpg'); // E = escalona(I, 0.5, 2); // imshow(E, []) // [m n] = size(I); //for i=1:m // for j=1:n // a(i,j) = i*ex; // b(i,j) = ...
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function [y] = f(x); y = x ^ 2; //inserir aqui a função //1/(1+x); //x * %e ^ (x/2); //log(1 + x) / log(%e); //x^2; //%e ^ x ^ 2; endfunction; function y = trapezio(x0, x1, n) h = (x1 - x0) / n; soma = f(x0) + f(x1); for k = 1 : n - 1 soma = soma + 2 * f(x0 + k * h); end; y = (h / 2) * soma; en...
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a=1 theta=0:%pi/64:2*%pi; r=a*(1-cos(theta)) polarplot(theta,r) r=a*sin(theta) polarplot(theta,r)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Example 5.32 //Regula Falsi, Newton Raphson and Mullers Method //Page no. 201 clc;clear;close; deff('x=f(x)','x=x^5-3.7*x^4+7.4*x^3-10.8*x^2+10.8*x-6.8') deff('x=f1(x)','x=5*x^4-4*3.7*x^3+3*7.4*x^2-21.6*x+10.8') //newton raphson printf('n\txn\t\t\f(xn)\t\tf1(xn)\t\tXn+1\t\tError\n') printf('------------------...
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clc; m=0.91/0.52; //cal molality disp(m*0.5,"Moles = "); //displaying result disp(300/(m*0.5),"Molecular Mass = "); //displaying result
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function result1= estimator1(X) result1= X(1); //result2= mean(X); endfunction function result2= estimator2(X) //result1= X(1); result2= mean(X); endfunction
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//problem 1.5 h1=0.05 h2=0.1 s1=0.8 s2=13.6 w=9810 p=s2*h2*w //pressure at balance line p1=s1*h1*w pf=p-p1 disp(pf, "pressure in pipe(N/m2)")
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//scilab 5.4.1 //Windows 7 operating system //chapter 14 Integrated Circuits and Operational Amplifiers clc clear R1=10*1000//R1=resistance in ohms R2=100//R2=resistance in ohms R3=10*1000//R3=resistance in ohms R4=10*1000//R4=resistance in ohms R5=10*1000//R5=resistance in ohms //Since the voltage gains of t...
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clc clear //Input data d=10^-3;//The diameter of a steel wire in m t=20;//The difference in the temperature in degree centigrade y=2*10^11;//The youngs modulus of a steel wire in newtons/m^2 a=12*10^-6;//The coefficient of linear expansion of steel wire in per degree centigrade pi=(22/7);//Mathematical constant...
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//Example 8.2 //Page 389 //Refer figure 8.2 on page 385 disp('The attenuation of single-mode fibre operating at 1300nm is approximately 0.35dB/km. Thus,') Pin=42//input power = 42dB A=0.35 LL=(Pin/A)//Loss Limit disp('Using 250 Gbps-km as BDP of a silica single-mode fiber, the chromatic dispersion limit i...
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// PG (18) xT = 1/3 xA = 0.333 abs(xT-xA) // Error //-------------------------------- xT = 23.496 xA = 23.494 abs(xT-xA) // Error //-------------------------------- xT = 0.02138 xA = 0.02144 abs(xT-xA) // Error
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// fun1 => a function name // y => return value function y = fun1 (x) y = x + 2 endfunction // using of functions a = 10 b = fun1(a) disp(b) disp(fun1(10)) function y = fun2 (x) z = x**2 y = z + 1 endfunction disp(fun2(10)) // 101 // function of two arguments function z = calcu...
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clc //initialisation of variables clear T= 1000 //C j= 1.5 Q= 35840 //cal I= 743*10^-40 //g cm^2 w= 214 //cm^-2 Kf= 0.184 //RESULTS printf ('Equilibrium constant = %.3f ',Kf) //NO SOLUTION IS GIVEN TO SOLVE Kf //INCOMPLETE SOLUTION IN THE TEXTBOOK
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//Chapter 19, Problem 4 clc; Ri=1000; //input resistance Rf=2000; //feedback resistance Vi1=0.4; //input voltage 1 Vi2=-1.2; //input voltage 2 V01=(-Rf/Ri)*Vi1; //output voltage 1 V02=(-Rf/Ri)*Vi2; //output voltage 2 ...
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#************************************************************ # Scenario of Ikea # # date : Fri Jan 6 10:53:02 2012 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT Tabouret p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000...
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// Example 3_8 clc;clear;funcprot(0); // Properties rho=1000;// The density of lake water through out g=9.81;//The acceleration due to gravity in m/s^2 // Given values s=8;// m b=1.2;//m h_c=s+b/2; // m // Calculation P_ave=(rho*g*h_c)/1000;// kN/m^2 printf('The average pressure on the door,P_ave=%0.1f k...
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ammoniak ammoniakens N;GEN;DEF;SG ammoniak ammoniaks N;GEN;INDF;SG ammoniak ammoniaken N;NOM;DEF;SG ammoniak ammoniak N;NOM;INDF;SG automation automations N;GEN;INDF;SG automation automationen N;NOM;DEF;SG automation automationens N;GEN;DEF;SG automation automation N;NOM;INDF;SG borste borsten N;NOM;DEF;SG borste borst...
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// This code is to plot the planar pseudo density of the output from gpaw. clear; clc; xdel(winsid()); PD_folder='C:\Users\pipidog\Dropbox\My Project\Density_Plot\nt_store\' PD_name='nt' Plane_fix=[3,13]; // Code Start ================= PD_dim=read(PD_folder+PD_name+'_dim.txt',3,1); PD_data=zeros(PD_dim(1),PD_dim(2),...
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// ShiftRegisterPISO16.tst load ShiftRegisterPISO16.hdl, output-file ShiftRegisterPISO16.out, compare-to ShiftRegisterPISO16.cmp, output-list time%S1.4.1 in%B2.1.2 load%B2.1.2 out%B2.1.2 set in 1, set load 0, tick, output; tock, output; set in 1, set load 1, tick, output; tock, output; set in 1, set load 1, tick,...
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> file_raw -text blob "Hello World!" 2ccdb4c72e6c263e1dc3e5c6617bad479d267546ced55f88d6b6e4527d2e8da8 > file_raw -text blob "This is a test." 90a1a46903f42ddf0386a9c12fd67a6c109285bb8b3117ee83ed222fd0040ad3 > file_raw -text list "2ccdb4c72e6c263e1dc3e5c6617bad479d267546ced55f88d6b6e4527d2e8da8 hello\n90a1a46903f42dd...
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clc; clear; //Example 3.20 m_dot=2250 //Mass flow arte in [kg/h] Cp=3.35 //Specific heat in [kJ/(kg.K)] dT=316-288.5 //Temperature drop for oil [K] Q=Cp*m_dot*dT //Rate of heat transfer in [kJ/h] Q=round(Q*1000/3600) //[J/s] or[W] Di=0.04 //Inside diameter [m] Do=0.048 //Outside diamter in [m] h...
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//Example 1 Page 78 clc clear //The function f cannot be linear.If it were, we would have delta f=m*deltax// disp(-4/2,'the ratio deltag/deltax is the same each time namely -4/2=') disp('hence g is linear with slop m=-2.By the table g(0)=3 hence b =3') disp('g(x)=-2x+3'); x=[0 2 4 6 8 10 12]// taking the x value...
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//Below is the system identification and design s = %s A = 17.09 T = 11.92643 h_s = 1//0.86 //Proportional Controller //k_s = 1 //some rndm number //Lead Controller k_s = 2.8*(s+0.3986)/(s+3.5868) gN = A gD = s*(1+s*T) g_s = gN/gD //plzr(g_s) g_sCL = 2.5*(g_s*k_s)/(1+g_s*h_s*k_s) g =...
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//Example 16.7, Page no 603 clc E=0.129//in Mev x=931//uc^2 Del_E=(E)**2/(2*x*191) printf("\n The value of delta E is %e ev",Del_E*10**6) h=6.6*10^-16//ev-sec T=1.4*10^-10//sec Tou=h/T printf("\n The value of Tou is %e ev",Tou)
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clear clc; rad=1.81; Dist1=6*100; Dist2=Dist1; Dist3=12*100; Reff=.7788*rad; Dist=(Dist1*Dist2*Dist3)^(1/3); L = .4605 * log10(Dist/Reff); mprintf("L=%.4f mH/km",L);
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// page no 321 // example no 10.2 // ADDITION OF PACKED BCD NUMBERS clc; a=77; b=48; x=modulo(a,10); y=modulo(b,10); z=x+y; if z>9 then f=z+6; printf('After addition BCD1 is: ') disp(dec2bin(f)); printf('MSB of this sequence is the carry generated after addition. \n \n') else pri...
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clc h1 = 3023.5 // Enthalpy of steam at state 1 in kJ/kg s1 = 6.7664 // Enthalpy of steam at state 1 in kJ/kgK s2 = s1 // Isentropic process s3 = s1 //Isentropic process s4 = s1 //Isentropic process t_sat_20 = 212 // Saturation temperature at 20 bar in degree Celsius t_sat_1 = 46 // Saturation temperature at 1 bar in ...
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clear // //given ns=1000 //synchronous speed calculated using similar formulas as above N=960 //speed of the motor at full load s=0.04 //slip r2=0.15 a=1.5 x2=1 rres=r2*a**2 rrea=x2*a**2 e2=220/(3**0.5) //case a torque at full load //tfl=((3*s*rres)*(e2**2)*60)/(2*3.14*1000)*((rres**2)+((s*rrea)**2)) printf("\n torque=...
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//clear// //Caption:Program to Calculate NORMALIZED FREQUENCY 'V' and Numerical Aperture //Example2.3 //Page 58 clear; close; clc; a = 25e-06; Lambda =1300e-09; V = 26.6; Numerical_Aperture = V*Lambda/(2*%pi*a) disp(Numerical_Aperture,"Numerical Aperture is"); disp(M = (V^2)/2,'Total number of modes M ente...
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//Eg-11.11 //pg-493 clear clc //The function to be integrated is deff('out = func(in)','out = 8.168*in*(1-in/2.5)^0.17') a = 0; b = 2.5; //Limits of integration //Taking the values of w and x from the table 11.3 //The value of the subscripts is increased by 1 because the index 0 is not valid. w...
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// Examle 16.19 V=220; // Supply voltage Ia=22; // Armature currernt Ra=0.45; // Armature resistance E1=V-(Ia*Ra); // Generated emf disp(' Generated emf = '+string(E1)+' Voltage'); N1=700; // Speed of motor in Shunt N2=45...
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clc //initialisation of variables p=20//psia t=240//F v=6//cu ft p1=80//psia v2=2.23//cu ft h=144//ft t1=778//F w=53.35//ft lb t2=700//F w1=0.1715//lb //CALCULATIONS W=(h*(p1*v2-p*6))/(1-1.4)//ft-lb U=-(W/t1)//Btu W1=(h*p*v)/(w*t2)//lb T=t2*(p1/p)^0.2857//R U2=W1*w1*(T-t2)//Btu //RESULTS printf('The ...
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clear all; clc; disp("Scilab Code Ex 9.6 : ") //Given: sigma_x = -20; //MPa sigma_y = 90; //MPa tou_xy =60; //Mpa //Orientation of Element: theta_s2 = atan(-(sigma_x - sigma_y)/(2*tou_xy)); theta_s2 = theta_s2/2; theta_s1 = %pi + 2*theta_s2; theta_s1 = theta_s1/2; //Maximum in plane Shear Stress: ...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 2 - Pressure and its measurements // Problem 2.2 //Given Data Set in the Problem d_ram=20/100 d_plunger=3/100 F_ram=30*10^3 //Calculations A_plunger=%pi/4*d_plunger^2 A_ram=%pi/4*d_ram^2 //We know that,Pressure on plunger =...
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clc // Given that Z = 79 // atomic no. of element b = 1 // a constant a = 2.468e15 // a constant in per sec c = 3e8 // speed of light in m/sec // Sample Problem 16 on page no. 20.12 printf("\n # PROBLEM 16 # \n") printf("Standard formula used \n ") printf(" nu = a*(Z-b)^2 ........Moseley law \n") f = a * (Z - b)^2 lam...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 12 Example 5") T1=25;//room temperature in degree celcius T4=2;//winter outside temperature in degree celcius h1=10;//heat transfer coefficient on inner window s...
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//Variable declaration: h = 24.0 //Plant operating hour per day (h/day) d = 350.0 //Plant operating day per year (day/yr) //Calculation: N = h*d //Operating hours per year (h/yr) //From example 9.1: Q = 8545.0 //Rate of energy loss (Btu/h) Qy = ...
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//Chapter 10_Special Purpose Amplifiers //Caption : Class B Power Amplifier //Example10.3: A class-B audio power amplifier has a supply voltage of abs(Vcc)=15V. The closed loop gain Av=50 and the amplifier has to deliver 10W of power into an 8 ohm load.Find: //a)the peak output voltage swing //b)the peak output cu...
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describe('dashboardView', () => { it('should contain view tag', () => { const vnode = App.Views.Account.Admin.dashboardView.view(); expect(vnode.tag).toBe('view'); }); });
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//Function to standardize the dimensions funcprot(0) function stddim(x) x=x*(10^3) std=[1 2 3 4 5 6 8 10 12 15 18 20 24 26 30:5:400] n=length(std) for i=1:n if (x<std(i)) then y=std(i) break else continue end end y=y*(1...
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// Example 5.16:fb clc; clear; close; rpi=2;//resistance in killo ohms Cpi=1.8;//capacitance in pico farad Cmu=0.12;//capacitance in pico farad fb=(1/(2*%pi*rpi*10^3*(Cpi+Cmu)*10^-6));//frequency in mega hertz disp(fb,"frequency in mega hertz")
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a . g . p . เ อ จ ี พ ี a a g a a r d อ า ก า ร ์ ด a b a b a อ า บ า บ า a b e l l เ อ เ บ ิ ล a b e r n a t h y แ อ เ บ อ ร ์ แ น ็ ต ท ี ่ a b i g a i l แ อ บ ิ เ ก ล a b s เ อ บ ี เ อ ส a c h e r o n แ อ ็ ก เ ค ร ิ น a c h r o m a t i c l e n s อ ะ โ ค ร ม า ต ิ ก เ ล น ส ์ a c k e r m a n แ อ ็ ก เ ค อ ร ์ เ ม ...
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// Example 10.3 R=120; // Resistance Xc=250; // Capacitve Reactance Q=-64.4; // Phase Angle I=0.9+%i*0; // Current Z=R-%i*Xc; // Impedance disp(' The Impedance is = '+string(Z)+' or ('+string(abs(Z))+' <...
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clc; //page no 122 //prob no. 3.9 // refer fig 3.14 // from spectrum we can see that each of the two sidebands is 20dB below the ref level of 10dBm. Therefore each sideband has a power of -10dBm i.e. 100uW. power_of_each_sideband = 100; Total_power = 2* power_of_each_sideband; disp('uW',Total_power,'The total po...
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clear // // // //Variable declaration r=0.1249 //radius(nm) n=2 //number of atoms //Calculation a=4*r/sqrt(3) //unit cell edge length(nm) V=a**3 //volume of unit cell(nm**3) v=4*n*%pi*r**3/3 //volume of atoms in unit cell(nm**3) fv=V-v //free volume per unit cell(nm**3) ...
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//Example 1.17: Addition of two signed numbers -5 and -4 clc; x=bitcmp(5,4) //finds complement of 5 y=1; u=x+y //1 is added to the complement l=bitcmp(4,4) //finds complement of 5 m=1; n=l+m //1 is added to the complement z=n+u; r = dec2bin(z); // binary equivalent of decimal number disp('The binary number is...
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//(Cylinders and Pressure Vessels) Example 22.8 //Inner diameter of the tube D1 (mm) D1 = 50 //Outer diameter of the tube D2 (mm) D2 = 75 //Outer diameter of the jacket D3 (mm) D3 = 100 //Internal pressure on the compound tube Pi (MPa) Pi = 35 //Young's modulus of the of the tube E (N/mm2) E = 207000
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//Exa 5.3 clc; clear; close; //Given data : l=15;//km P=5;//MW V=11;//kV f=50;//Hz pf=0.8;//power factor cos_fi_r=pf; sin_fi_r=sqrt(1-cos_fi_r^2); L=1.1;//mH/Km VR=V*1000/sqrt(3);//V I=P*1000/sqrt(3)/V/cos_fi_r;//A LineLoss=12/100*P*10^6;//W R=LineLoss/3/I^2;//ohm X=2*%pi*f*L*10^-3*l;//ohm/phase VS=VR...
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clc; clear; P0=2/3; //P(X=0) P1=2/3; //P(Y=0) H_x=0.919; H_y=0.919; H_b=0.919; //Hb(2/3) //since X,Y pair is uniformly distributed on three values H_xy=log2(3); // H(X,Y) H_xdivy=H_xy-H_y; //H(X/Y)=H(X,Y)-H(Y) I_xdivy=H_x-H_xdivy; //I(X,Y)=H(X)-H(X/Y) disp(I_xdivy,"I(X,Y)=");
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// Example A-6-16 // Design of lag lead compensator clear; clc; xdel(winsid()); //close all windows mode(0); // please edit the path // cd "/<your code directory>/"; // exec("rootl.sci"); // exec("plotresp.sci"); s = %s; G = syslin('c',10,s * (s + 2) * (s + 8)); Kv = 80; // desired velocity constant R = ...
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Name=PGTI Curved PlayerCharacters=pistol Launchman BotCharacters=Pigeon3.bot IsChallenge=true Timelimit=60.0 PlayerProfile=pistol Launchman AddedBots=Pigeon3.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=boxer1spawn_curved.map MapScale=4.0 BlockProjectilePredictors=true BlockCheats=true InvincibleP...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/CPU.tst load CPU.hdl, output-file CPU.out, compare-to CPU.cmp, output-list time%S0.4.0 inM%D0.6.0 instruction%B0.16.0 reset%B2.1.2 outM%D1.6.0 writeM%B3...
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//Exa 1.14 clc; clear; close; format('v',7); //Given Data : R0=2.8;//ohm t0=0;//degree C R1=3.8;//ohm t1=100;//degree C R2=5.8;//ohm\ //R=R0*(1+alfa*t) alfa=(R1/R0-1)/t1; t2=(R2/R0-1)/alfa;//degree C disp(t2,"Temperature at R2 in degree C : ");
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//Exa:1.43 clc; clear; close; P_o=37.5*1000;//in Watts N=750;//in rpm Eff=0.9;//Efficiency V_L=400;//in Volts pf=0.85;//Power Factor R_b=2.5;//in ohms T_f=P_o*60/(2*%pi*N);//in N-m I_L=P_o/(sqrt(3)*V_L*pf*Eff);//in Amperes I_b=V_L/(sqrt(3)*R_b);//in Amperes T_E=T_f*I_b/I_L;//in N-m T_i_total=T_f+T_E;//in ...
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clc clear //input data N=3600//Running speed of blower in rpm Dt=0.2//The rotor tip diameter in m Dh=0.125//The rotor hub diameter in m P1=1.013//The atmospheric pressure in bar T1=298//The atmospheric temperature in K m=0.5//Mass flow rate of air in kg/s db=20//The turning angle of the rotor in degree b1=55...
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// Loose 8-5-8 encoder // on a backpropagation network without biases, with SuperSAB // (Note that the tight 8-3-8 encoder will not work without biases) // (The 8-4-8 encoder have proven very difficult to train on SuperSAB) rand('seed',0); // network def. // - neurons per layer, including input N = [8,5,8]; // inp...
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// Example 3.1: (i) maximum output power (ii) maximum collector efficiency (iii) power rating of the transistor clc, clear; Vcc=10; // collector supply voltage in volts Icq=200; // zero-signal collector current in milli-ampere Rl=2; // load resistance in ohm alfa=5; // turn ratio Pout=(Vcc*(Icq*10^-3))/2; Pin=(V...
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// Exa 3.19 clc; clear; close; format('v',6) // Given data R = 12;// in k ohm Vin = 6.3;// in V V_Z = 4.8;// in V I = (Vin-V_Z)/R*10^3;// in mA I_Z = 5;// in mA // Maximum value of load current, I_Lmax = I - I_Z;// in mA I_Z = 100;// in mA // Minimum value of load current, I_Lmin = I - I_Z;// in mA disp...
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w3 = 2.3; w1 = 1.0; w2 = w3-w1; h1 = 2950.0; // At 0.8MPa, 0.95 dry x = 0.95; hf = 721.11; hfg = 2048; h2 = hf + (x*hfg); h3 = ((w1*h1)+(w2*h2))/w3; // Interpolation H = [2769.1 2839.3]; T = [170.43 200]; t3 = interpln([H;T],2790); s3 = 6.7087; s4 = s3; x4 = (s3-1.7766)/5.1193; h4 = 604.74+(x4*2133.8); V4 = sqrt(2000*...
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type x = array 100 of void; main () { }