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//Part B Chapter 4 Example 7 clc; clear; close; M=2.5*1000;//Nm T=3.5*1000;//Nm Te=sqrt(M^2+T^2)//Nm Me=(M+sqrt(M^2+T^2))/2//Nm tau_max=400*10^6;//N/m^2 d1=(Te*16/%pi/tau_max)^(1/3)*1000;//mm sigma=750*10^6;//N/m^2 d2=(Me*32/%pi/sigma)^(1/3)*1000;//mm d=max(d1,d2);//mm disp("Suitable diameter is "+string(r...
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Component : kt-two-step-verification add this line for get language data ------------------- @Input() selectedLanguage : any; (current line Number : 17) ------------------- add two line in "sendLoginCode" function (current line Number : 76) ------------------------- const countryCode = this.phoneForm.value.phone.c...
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clear; //clc(); // Example 7.1 // Page: 134 printf("Example-7.1 Page no.-134\n\n"); //***Data***// T = 220+459.67;//[R] Temperature in Rankine P = 500;//[psia] Pressure R = 10.73;//[(psi*ft^(3)/(lbmol*R))] Gas constant // We will follow the method 'a' as the book has given the multiple methods to solve ...
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//example 14.1.e// clc //clears the screen// clear //clears all existing variables// disp('type of column decoder is 1 to 7 decoder')
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clear // // //Initilization of Variables //Bar-A d1=30 //mm //Diameter of bar1 L=600 //mm //length of bar1 //Bar-B d2=30 //mm //Diameter of bar2 d3=20 //mm //Diameter of bar2 L2=600 //mm //length of bar2 //Calculations //Area of bar-A A1=%pi*4**-1*d1**2 //Area of bar-B A2=%pi*4**-1*d2**2 A3=%pi*4**-1*d3**2 //let...
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//Example 5.4(b) clear; clc; R1=10*10^3; R2=100*10^3; CMRRdB=57;//refer curve of fig.5A.6 at 10 kHz CMRRrec=10^(-(CMRRdB/20));//Reciprocal of CMRR delvi=10; delvp=(R2/(R1+R2))*delvi; delVos=CMRRrec*delvp; dcgain=1+(R2/R1); delvo=dcgain*delVos; printf("Typical change in vo=%.3f V",del...
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//EXAMPLE 7-16 PG NO-473 Zoc1=40; Zsc1=36.67; Zi1=sqrt((Zoc1*Zsc1)); disp('i) IMPEDANCE (Zi1) is = '+string (Zi1) +'ohm '); Zoc2=30; Zsc2=27.5; Zi2=sqrt((Zoc2*Zsc2)); disp('ii) IMPEDANCE (Zi2) is = '+string (Zi2) +'ohm '); TETA=1/tanh(0.9167); disp('iii) (TETA) is = '+string ...
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(unwatch all) (clear) (dribble-on "Actual//dfrulcmd.out") (batch "dfrulcmd.bat") (dribble-off) (clear) (open "Results//dfrulcmd.rsl" dfrulcmd "w") (load "compline.clp") (printout dfrulcmd "dfrulcmd.bat differences are as follows:" crlf) (compare-files "Expected//dfrulcmd.out" "Actual//dfrulcmd.out" dfrulcmd) (close dfr...
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s=%s Max_Limit = 10; h = ones(1,Max_Limit); N2 =0:length(h)-1; for t = 1: Max_Limit x(t)= exp(-(t -1)); end N1 =0:length(x)-1; y = convol(x,h)-1; N = 0:length(x)+ length(h)-2; figure a= gca(); plot2d (N2 ,h) xtitle ( ' Impul s e Re spons e ' , ' t ' , ' h ( t ) ' ); a. thickness = 2; figure a= gca (...
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//To calculate the dielectric displacement V = 10; //potential, V d = 2*10^-3; //plate seperation, m E = V/d; //electric field, V/m epsilon_r = 6; epsilon0 = 8.85*10^-12; D = epsilon0*epsilon_r*E; //dielectric displacement, C/m^2 printf("dielectric displacement in C/m^2 is"); disp(D);
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function y = f0(t, u) y = sin(u + t) endfunction function y = f1(t, u) y = u*t endfunction function y = fm1(t, u) y = 10 - t^2 endfunction function y = fm2(t, u) y = 12 - t^2 endfunction function y = fm5(t, u) y = sin(u + t + 5) endfunction function y = fm6(t, u) y = cos(u + 11) endfunction...
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clear clc //initialisation of variables d= 40 //lb/ft^2 w= 4 //ft h= 6 //ft l= 12 //ft //CALCULATIONS W= w*h*d*l V= W/64 D= V/(w*l) //RESULTS printf ('Volume of water displaced = %.f ft^3',V) printf ('\n Depth of immersion = %.2f ft',D) printf ('\n Centre of buoyancy = %.2f ft from base',D)
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clc //ex15.5 M_r=6000; //relative permeability M_o=4*%pi*10^-7; //permeability of free space w_r=3*10^-2; //width of rectangular cross-section d_r=2*10^-2; //depth of rectangular cross-section N=500; //number of turns of coil B_gap=0.25; //flux density gap=0.5*10^-2; //air gap...
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//Chapter-5, Example 5.16, Page 175 //============================================================================= clc clear //INPUT DATA R=10;//resistance in ohms L=0.1;//inductance in Henry C=150;//capacitor in uf V=200;//voltage in V f=50;//frequency in hz //CALCULATIONS Xc=1/(2*%pi*f*C*10^-6);//Capaciti...
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clear// //Variables IE = 12.0 //Emitter current (in milli-Ampere) beta = 140.0 //common emitter current gain //Calculation IB = IE / (1 + beta) //Base current (in milli-Ampere) IC = IE - IB //Collector current (in milli-Ampere) ...
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clc; m=0.001; //mass in kg c=3*10^8; //velocity in m/sec p=10^8; //power in Watt t=24; //time in hr/day E=m*c*c; //Eintstein equation disp(E,"Energy in Joule = "); //displaying result M=(p*3600*t)/E; //calculating mass of U required m=E/(7822*4185); //calculating mass of coal requi...
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//pathname=get_absolute_file_path('9.07.sce') //filename=pathname+filesep()+'9.07-data.sci' //exec(filename) //Ratio of pressure: rp=1.35 //Flow rate through compressor(in kg/s): m=50 //Overall efficiency: no=0.90 //Initial pressure(in bar): p1=1 //Initial temperature(in K): T1=313 //Adiabatic index of com...
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//Chapter 18 //Example 18_14 //Page 449 clear;clc; mva=10; kv=11; g=[%i*1.2 %i*0.9 %i*0.4]; f=[%i*1 %i*1 %i*3]; Er=kv*1000/sqrt(3); printf("Phase enf of R phase = %d V \n", Er); printf("(i) Total impedance to any sequence current is sum of generator and feeder impedances of that sequence currents \n"); for i=1:3 ...
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丁 格 d i n g e r 万 尼 v a n n i 万 尼 瓦 尔 v a n n e v a r 丘 克 c u k o r 丘 普 卡 c h u p k a 丘 特 尔 c h u t e r 丘 罗 c u r o e 丹 吉 洛 d a n g e l o 丹 特 斯 d a n t e s 丹 西 d a n c y 乌 切 洛 u c c e l l o 乌 尔 维 林 u l v e l i n g 乌 特 里 奇 u t t r i d g e 乌 皮 特 u p i t 乔 卡 比 j o c a b y 乔 基 姆 j o a c h i m 乔 德 宁 j o r d e n i n g 乔 斯 林 ...
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//Ex13_20 PG-13.11 clc clear printf(" Conversion of decimal number 37 to its binary equivalent =") a=[37]; x=dec2bin(a); printf("%s",x)
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This is David Iyoboyi
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// Scilab Code Ex2.12:: Page-2.13 (2009) clc; clear; lambda = 5893e-008; // Wavelength of light used, cm y1 = 10; // Distance of biprism from the source, cm y2 = 100; // Distance of biprism from the screen, cm D = y1 + y2; // Distance between slits and the screen, cm b = 3.5e-02; // Fringe width of the int...
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ex7_1.sce
errcatch(-1,"stop");mode(2); syms x disp(integ(tan(x)^5,x)) exit();
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clear //Given L=130*10**-3 //H I1=20 //mA I2=28 //mA t=140.0*10**-3 //S //Calculation l=I2-I1 e=(-L*l)/t //Result printf("\n Magnitude of induced e.m.f is %0.2f *10**-3 V",e) printf("\n Direction oppose the increase in current")...
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style.fontSize=12; style.displayedLabel="<table> <tr> <td align=center><b>in1<br>in1</b></td> <td align=center>In2In_x1</td></tr></table>"; pal10 = xcosPalAddBlock(pal10,"in2in_x1",[],style);
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7_5.sce
clc //initialisation of variables p=1.01325 //pressure in bar pv=0.020 //pressure in bar at 21 degrees temp ws=0.0154 //kg/kg of da w=0.0123 //kg/kg of da vs=0.86 //under 21 degrees temp m*m*m/kg w1=0.0074 //CALCULATIONS pa=p-pv sr=w/ws rho=1/vs avc=0.0163-w1 //RESULTS printf('partial pressure of vapour a...
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Ex11_4.sce
clc// // // //Variable declaration H=10^4; //magnetic field(amp/m) chi=3.7*10^-3; mew0=4*%pi*10^-7; //Calculation M=chi*H; //magnetisation of material(A/m) B=mew0*(M+H); //flux density(T) //Result printf("\n magnetisation of material is %0.3f A/m",M) printf("\n flux density is %0.4f wb/m^2",B...
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// Example 6.26 //MAXIMA SCILAB TOOLBOX //Z transform of (n+1)*a^n*u(n) clear ; clc ; syms a n z ; x1 =(a)^n ; X1 = symsum(x1*(z^(-n)),n,0,%inf); X2 = -z*(diff (X,z,1)) ; X = X1 + X2; disp (X , 'Z−transform of(n+1)*a^n*u(n) is X = ');
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//Example 6.6, page 237 clc h=10^-34//in j-s m=10^-30//in kg a=10^-14//in m c=3*10^8//in m/s E=((%pi*h)^2)/(2*m*a*a) printf("\n Energy is %e J ",E) //convert to ev e=E/(1.6*10^-19) printf("\n Energy is %e ev ",e) //Answer difference is due to round off E1=(%pi*c*h)/a printf("\n Zero level Energy is %e J ",E1) e1=E1/...
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//Initilization of variables W1=4 //lb W2=2 //lb t2=0.04 //s W3=-2 //lb t3=0.02 //s t=3 //s g=32.2 //ft/s^2 //Calculations //Algebraic sum of two areas A=t2*W2+t3*W3 //lb-s //Using Impulse Momentum Theorem v=(A*g)/W1 //ft/s //Result clc printf('The spped after 3s is %f ft/s',v)
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PrismRefraction.SCI
codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\Physics\Optics\_Optics.sci"); SetOpticFrame(T_scene_create); sss=T_getscene; vp=T_getviewport; vp.CameraPos=point(0,0,10); vp.CameraDir=vector(0,0,-1); vp.FocalDistance=10; vp.NearClipPlane=0.1; vp.FarClipPlane=20; sss.ambientlight...
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example9_22.sce
//clc() xf = 500 * 10^-6; xp = 50 * 10^-6; xb = 1600 * 10^-6; //F - Feed water rate, B - blow down rate, S - high pressure steam, P - process stream rate // total balance, F = P + B // Solid balance, F * xf + P * xp = B * xb //eliminating P, we get, F * xf + (F - B)*xp = B * xb //let F/B be X X = (xb + xp)/(xf...
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//Example 3_24 clc; clear; close; format('v',6); //given data : Z1=10+%i*12;//ohm Z2=12-%i*10;//ohm V=230;//V f=50;//Hz Z=Z1*Z2/(Z1+Z2);//ohm I=V/Z;//A Imag=abs(I);//A Iang=atand(imag(I)/real(I));//degree disp(Iang,Imag,"Total current drawn, magnitude(A) & Angle(degree) are"); pf=cosd(Iang);//Power Facto...
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LoadPlanetMoonsKepler.SCI
function LoadPlanetMoonsKepler(planframe,filename) { filecontent=readtextfile(filename); filecontent.split("~n"); moonsframe=planframe.Inclin.AddSubFrame("MoonsFrame"); moonorbitsframe=planframe.Inclin.AddSubFrame("MoonOrbitsFrame"); while filecontent.length>0 do { line=filecontent.split(...
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// Scilab Code Ex2.14 Ratio of masses of a proton and an electron: Pg:54 (2008) RH = 1.09678e+07; // Rydberg constant for hydrogen, per metre RHe = 1.09722e+07; // Rydberg constant for helium, per metre MH_m_ratio = (RH - 1/4*RHe)/(RHe - RH); // Ratio of mass of a proton to that of an electron printf("\nTh...
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//clear// clear; clc; //Example 24.4 //Given msdot = 2800; //[lb/h] Xa = 0.15; Xb = 0.005; Ti = 80; //[F] To = 125; //[F] Thb = 260; //[F] Hb = 0.01; //[lb water/lb dry air] G = 700; //[lb/ft^2-h] Cps = 0.52; //[Btu/lb-F] //Solution //Counter current operation will be used. //Assuming Nt = 1.5; //...
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clear $th = VirtualMaterials.Advanced_Peng-Robinson / -> $th th + WATER pipe = PipeSegment.PipeSegment() cd /pipe.In P = 300 kPa T = 300.0 K Fraction = 1.0 MoleFlow = 1000.0 cd /pipe.Out #P = 200.0 #T = 300.0 cd / pipe.Diameter = 0.1 pipe.Length = 20.0 pipe.Roughness = 0.0001 pipe.Elevation0 = 0.0 pipe.Elevation...
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//simplify a/(a-b) - a^2/(a^2-b^2) clear; clc; close; //as, (a^2-b^2)=(a+b)(a-b),substitute it. mprintf("\n the fraction is :\n") ans=string('ab/((a+b)(a-b))')
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clc; //e.g 28.1 fo=22*10**3;; C=2*10**-9; L=((0.159/fo)^2)/C; disp('H',L*1,"L=");
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clc; T=700;// Exhaust gas temperature in degree celcius p=120;// Exhaust gas pressure in kPa Cpo=1.089; // Specific heat at constant pressure in kJ/kg K R=0.287; // characteristic gas constant in kJ/kg K p0=100; // Pressure of Surroundings in kPa T0=30; // temperature of Surroundings in degree celcius Cvo=Cpo-R...
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//example 10 //mass flow rate clear clc dt=185 //time period in seconds over which there is incrrease in volume dV=0.75 //increase in volume in 0.75 in m^3 V=dV/dt //volume flow rate in m^3/s P=105 //pressure inside gas bell kPa T=21 //temperature in celsius R=0.1889 //ideal gas constant in kJ/kg-K m=P*V/(R...
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d = 0.02 ; // diameter in m t = 0.008 ; // thickness in m A = %pi*d*t ; // shear area P = 110000 ; // prassure in Newton A1 = (%pi/4)*(d^2); // Punch area t_aver = P/A ; // Average shear stress disp("Pa",t_aver,"Average shear stress in the plate is ") s_c = P/A1 ; // compressive stress disp("Pa",s_c,"Average c...
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// scilab Code Exa 14.3 upstream guide vanes beta2=86; // rotor blade air angle at inlet in degree dh=0.3; // hub diameter in m dt=0.6; // tip diameter in m N=960; // rotor Speed in RPM phi=0.245; // flow coefficient T1=316; // in Kelvin p1=1.02; //Initial Pressure in bar R=287; n_o=0.647; // overall Efficien...
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// method-of-lines solution to the 1-D Buckley-Leverett equation // constants and parameters pathway = pwd() + '\'; g = 9.807; // gravitational acceleration, m/sec^2 u_w = 8.9e-4; // viscosity, Pa*sec u_n = 8.9e-4; rho_w = 1000.0; // density, kg/m^3 rho_n = ...
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clc;clear; //Example 5.8 //given data P1=0.8; P2=0.12; //from Table A-12 //sat. liq at P1 T1=31.31; h1=95.47; //since process is insentropic and at P2 h2=h1; hf=22.49; hg=236.97; T2=-22.32; //calculations x2=(h2-hf)/(hg-hf); disp(x2,'the final state is'); dT=T2-T1; disp(dT,'temperature drop in ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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errcatch(-1,"stop");mode(2);//Exa 1.6 ; ; //given data lambda=1.539;//in Angstrum theta=22.5;//in degree n=1;//order unitless d=n*lambda/(2*sin(theta*%pi/180));//in Angstrum disp(d,"Interpolar distance in Angstrum : ") exit();
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//9.4 clc; n=1000/5; Ie=0.7*1000/100; Tp=1; n=200; Ts=200; R_actual=Ts+(7/5); Error_ratio=(200-R_actual)*100/R_actual; printf("Ratio error=%.2f percent",Error_ratio) Ts=200-(0.5*200/100); n=199/1; R_actual=Ts+(7/5); Error_ratio=(200-R_actual)*100/R_actual; printf("\nRatio error=%.2f percent",Error_ratio)
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xdel(winsid());//fechar janelas de figuras clear();//limpar memória clc();//limpar console t0 = 0; delta_t = 0.001; final_time = 10; t = (0:delta_t:final_time); t = t' ifinal=size(t);ifinal=ifinal(1); sampling_rate = 0.5 ratio = sampling_rate/delta_t; y = zeros(ifinal); u = zeros(ifinal); entradac = 2*ones(ifinal,1)...
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//***impulse function *** n = -10:10; delta =(n==0); subplot(4,1,1); stem(n,delta,'.'); //***unit step function*** step =(n>=0); subplot(4,1,2); stem(n,step,'.'); //***ramp function*** ramp=n.*(n>0); subplot(4,1,3); stem(n,ramp,'.');
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clc; v=250; // rated voltage of shunt motor p=15000; // rated power of motor nm=0.88; // maximumu efficiency of motor n=700; // speed of motor rf=100; // resistance of shunt field i=78; // current drawn by mains f=0.8; // fraction of rated output being delivered l=((1/nm)-1)*f*p; // total losses // at maximum ...
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//Example 5.1 //Calculate the rate of heat loss . //Given T1=65 //C, furnace temp. T2=25 //C, ambient temp. h=1.5 //m, height of door w=1 //m, width of door Tf=(T1+T2)/2 //c, average air film temp. //Properties of air at T...
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clc; clear all; //chapter 4 //page no 123 //example 4.6 L=4*10^-6; //Henry C=9*10^-12; //Farad R=20*10^3; //ohm f0=1/(2*%pi*sqrt(L*C)); //frequency in Hz mprintf('(a) The resonant frequency is f0=%.2f MHz\n',f0*10^-6) Q=R*sqrt(C/L) mprintf(' (b) The Q is %i\n',Q); B=f0/Q; mprintf(' (c) The 3-dB...
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// Example 4.9, page no-154 clear clc p=100 //Antenna power in W pd=10 //Power Density in mW/m^2 d=1000 //distance in m p2=10000 // New antenna power directivity=10*log10(p2/p) printf("Directivity (in dB)= %d dB",directivity)
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clc clear //input v=415;//3 phase supply voltage in volts f=50;//supply frequency in hertz //system is loaded with three star connected coils and three star connected resistors ic=10;//current taken by each of the coils in amperes lagging by 60 degrees ir=8;//current taken by each of the resistors in amperes ...
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clc clear //INPUT DATA T=2.223;//Time taken for 1 oscillation in sec L=1.228;//Length of the pendulum in m //CALCULATIONS g=((4*3.14^2*L)/(T^2));//Acceleration due to gravity in m.s^-2 //OUTPUT mprintf('The acceleration due to gravity is %3.2f m s^-2',g)
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//Calculate the sag clear clc; sf=5;//Factor of safety d=.95;// conductor dia(cm) Ws=4250/sf;// working stress(kg/cm_2) A=%pi*(d^2)/4;// area (cm_2) Wp=40*d*(10^-2);//wind pressure (kg/cm) W=sqrt((.65^2) +(.38^2));// Total effective weight(kg/m) T=850*A;// working tension (kg) c=T/W; l=160; d=l^2/(8*800); ...
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a = --- b = --- while --- m = (a+b)/2 if --- then a = m else b = m end end
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// EXAMPLE (PG 87) // f(x) = (x-1.1)^3 * (x-2.1) c = [2.7951 -8.954 10.56 -5.4 1] p4=poly(c,'x','coeff') roots(p4) deff('[y]=f(x)','y=(x-1.1)^3*(x-2.1)') xset('window',0); x=0:.01:3; // defining the range of x. y=feval(x,...
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//clear// //Caption:Direct Sequence Spread Coherent BPSK //Figure 9.4:Generation of waveforms in DS/BPSK spread spectrum transmitter clear; close; clc; t = 0:13; N = 7; wt = 0:0.01:1; bt = [1*ones(1,N) -1*ones(1,N)]; ct = [0,0,1,1,1,0,1,0,0,1,1,1,0,1]; ct_polar = [-1,-1,1,1,1,-1,1,-1,-1,1,1,1,-1,1]; mt = bt...
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clear; clc; disp("--------------Example 21.4---------------") // display the example printf("The traceroute program is used to find the route from the computer voyager.deanza.edu to the server fhda.edu.\nThe following shows the result:\n\n"); printf("$ traceroute fbda.edu\ntraceroute to fbda.edu (153.18.8.1),30 h...
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function res = qp_kaiser (nb, at, linear) //Computes a finite impulse response (FIR) filter for use with a quasi-perfect reconstruction polyphase-network filter bank. //Calling Sequence //qp_kaiser (nb, at, linear) //qp_kaiser (nb, at) //Parameters //nb: Number of bands //at: Attenuation //linear: When not zero, minim...
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//Problem 12.02: //initializing the variables: xEtOH = 0.3; // mol% ethanol //calculation: xwater = 1 - xEtOH printf("\n\nResult\n\n") printf("\n the liquid mole fractions is %.2f ",xwater)
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errcatch(-1,"stop");mode(2);//Caption:Find (a) the breakdown slip (b) the breakdown torque (c) power developed by the motor //Exa:9.5 ; ; //Refer to data of Exa9.4 R_1=0.1;// in ohms R_2=0.2;// in ohms X_1=0.15;// in ohms X_2=0.25;// in ohms w_s=125.66;//rad/sec V_1=120;//in Volts s_b=R_2/sqrt(R_1^2+(X_1+X...
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//determine (a) VGSQ, (b) IDQ, and (c) VDSQ. //Example 4.23 page no 130 clear clc Idss=10 //mA Vgsq=-1.34 //V Vp0=4 //V Rs=2 //kΩ Vdd=15 //V Rd=500 //kΩ Idq=Idss*((1+(Vgsq/Vp0))^2) Vdsq=Vdd-Idq*10^-3*(Rs*10^3+Rd) printf("\n Idq=%0.2f mA" ,Idq) printf("\...
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clc // Given that r = 2 // ratio of kinetic energy of body to its rest mass // Sample Problem 12 on page no. 11.22 printf("\n # PROBLEM 12 # \n") printf(" Standard formula used \n") printf(" m = m_0/((1-v^2/c^2)^1/2) \n KE = (m-m_0)*c^2 \n ") v = 3e8 * sqrt(1 - (1 / (r + 1))^2) printf("\n Velocity of particle is %f c...
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<<<<<<< HEAD // Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Li...
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TIME 120000 * PENNSEARCH VERBOSE ALL ON TIME 120000 0 PENNSEARCH CHORD join 0 TIME 10000 1 PENNSEARCH CHORD join 0 TIME 10000 2 PENNSEARCH CHORD join 1 TIME 10000 3 PENNSEARCH CHORD join 2 TIME 10000 5 PENNSEARCH CHORD join 0 TIME 10000 4 PENNSEARCH CHORD join 3 TIME 20000 0 PENNSEARCH CHORD ringstate TIME 10000 0...
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<scriptConfig name="LFRT" script="FRT"> <params> <param name="eut.offset_current" type="string">0,0,0</param> <param name="eut.offset_voltage" type="string">0,0,0</param> <param name="frt.high_pwr_value" type="float">0.9</param> <param name="frt.repetitions" type="int">3</param> <param name="eut.s...
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clc // Given that l=12//in inch Length of block w=4//in inch width f=0.01//in inch/tooth feed d=1/8//in inch depth of cut D=2//in inch diameter of cutter n=20//no. of teeth N=100//in rpm spindle rotation Vt=8//in inch/minute axial speed of the tool // Sample Problem on page no. 600 printf("\n # Materi...
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//to find the stiffness of the governor spring clc //given w=3//lb W=15//lb g=32.2 r2=2.5/12//ft N2=240//rpm w2=N*%pi/30 F2=w*w2^2*r2/g a=4.5//in b=2//in sleevelift=0.5 r1=r2*12+a*sleevelift/b//the increase of radius for a scleeve lift is 0.5 in N1=1.05*N2 F1=(N1/N2)^2*(r1/(r2*12))*F2 //a) at minimum ra...
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clc; p1=100; // Pressure at inlet in kPa T1=30; // Temperature at inlet in degree celcius V1=0; // Velocity at inlet in m/s p2=350; // Pressure at outlet in kPa T2=141; // Temperature at exit in degree celcius V2=90; // Velocity at exit in m/s p0=100; // Pressure of Surroundings in kPa T0=30; // temperature of ...
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// Exa 6.26 clc; clear; close; // Given data x1 = 0.95; P1 = 9;// in bar P1= P1*10^2;// in kN/m^2 h_f1 = 743;// in kJ/kg h_fg1 = 2030;// in kJ/kg V = 0.204;// in m^3 x2 = 0.544 P2 = 5;// in bar P2= P2*10^2;// in kN/m^2 h_f2 = 640;// in kJ/kg h_fg2 = 2108;// in kJ/kg H_wet1 = h_f1 + (x1*h_fg1);// in kJ/k...
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//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 8 //Scilab version- 6.0.0 //Example 9.1.1 clc; clear ; //given lambdap=850;//Peak wavelength in nm n=0.01;//quantum efficiency is 1% Ep=1248/lambdap;//energy of photon in eV I=50;//current supposed to be in mA P...
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//Example 18.11 clc rl=(10/(200*10^-3)) // in ohm c2=11.4/0.02 format(4) c=sqrt(570) // in uF disp(rl," RL(ohm) =") disp(" 0.02 = 5700 / L*C1*C2*50 = 114 / L*C1*C2") disp("If we assume L = 10 mH and C1 = C2 = C, we have") disp(" 0.02 = 114 / L*C^2 = 11.4 / C^2") disp(c2," C^2 =") disp(c,"there...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 1, Example 8") //Let us suppose //Velocity of the model, Vm //Length of the model, Lm = 160mm //Length of the prototype Lp = 1000mm ...
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//clear// //Caption: To find optimum decision threshold //Example7.1 //Page 258 clear; clc; close; bon = 1; boff =0; sigma_on = 1; sigma_off = 1; Q = (bon-boff)/(sigma_on+sigma_off) Vth = bon-Q*sigma_on disp(Q,'Q parameter value =') disp(Vth,'optimum decision threshold Vth =') //Result //Q parameter va...
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the LDI (load immediate) instruction" ; @Result: "r16 = 42" start: ldi r16, 42 end: break
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clc clear //Input data v1=0.3;//Velocity of the pump plunger in m/s l=0.575;//The length of the fuel pipe in m A=1/20;//The cross sectional area of pipe to the plunger cylinder a=1/40;//The area of nozzle hole to the pipe p1=27.6;//Initial pressure in the line in bar p2=27.6;//The compression pressure of the ...
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#header default_background_color = 128, 128, 128; write_codes = true; pulse_width = 5; active_buttons = 2; button_codes = 1, 255; no_logfile = false; ############################################################################### #SDL portion of code begin; # in SDL array { LOOP $i 50; $k = '$i + 1'; bitmap {...
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//Example 12.2 r1=0.9*10^-2;//Radius of garden hose (m) A1=%pi*r1^2;//Cross-sectional area of hose (m^2) Q=0.5;//Flow rate (L/s) Q=Q/10^3;//Flow rate (m^3/s) v1=Q/A1;//Speed of water in the hose (m/s) printf('a.Speed of water in the hose = %0.2f m/s',v1) r2=0.25*10^-2;//Radius of nozzle (m) A2=%pi*r2^2;//Cross-...
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clc; clear; function yp=predprey(t,y) yp=[1.2*y(1)-0.6*y(1)*y(2);-0.8*y(2)+0.3*y(1)*y(2)]; endfunction t=0:0.1:20; y0=[2 1]; sol=ode(y0,0,t,predprey); count=1; for i=1:2:401 x(count)=sol(i); z(count)=sol(i+1); count=count+1; end plot(t,x) plot(t,z) xtitle("y vs t", "t","y") clf(); pl...
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Rp=600 Rs=50 W=2*%pi*400*10^6 Q=sqrt(Rp/Rs-1) Xs=Q*Rs Xp=Rp/Q Cs=1/W/Xs Lp=Xp/W Ls=Xs/W Cp=1/W/Xp printf("\nQ=%.4f\nXs=%.4f ohm\nXp=%.4f ohm\nCs=%.2e F\nLp=%.3e H\nLs=%.3e H\nCp=%.2e F",Q,Xs,Xp,Cs,Lp,Ls,Cp)
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function [classe]=classifieur(attributs_normalises,img_gris,moyenne,ecart_type,num_classe) [aire,perimetre,longueur,largeur]=AttributsForme(img_gris); res=[aire,perimetre,longueur,largeur]; for i=1:4 res(i)=(res(i)-moyenne(i))./ecart_type(i); end for app = 1:20 //distance(app)=sum(a...
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E0 = 1/(36*%pi*10^9); //permitivity in free space k = 4*%pi*E0 ; q1 = 1; // charge on the first particle in coulombs q2 = 1; // charge on the second particle in coulombs d = 1; // distance between the particles in meter F = (q1*q2)/(k*d^2); //force between the two particles in newtons disp(F, "force in fre...
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a=100;//cross section dimention,given,in mm b=200;//cross section dimention,given,in mm t=5;//thickness,given,in mm L=3000;//length,given,in mm E=200000;//given,in N/mm^2 G=0.36*200000;//given,in N/mm^2 P=-100*10^3;//load,given,in N
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clear //Given h=6.62*10**-34 //J c=3*10**8 //m/s l=4.0*10**-7 //m //Calculation E=((h*c)/l)/1.6*10**-19 p=h/l //Result printf("\n Value of energy is %0.1f ev",E*10**38) printf("\n Momentum of photo...
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//Chapter 6, Problem 10 clc id=-2e-3 //drain current in ampere vds=-8 //drain to source voltage vcc=-14 //supply voltage vs=2.1 //source voltage vp=5 //pinch-o...
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//Example 7.1 //Program to Calculate //(a)Collector Current //(b)Collector-to-Emitter Voltage clear; clc ; close ; //Given Circuit Data Vcc=9; //V Rb=300*10^3; //Ohms Rc=2*10^3; //Ohms Beeta=50; //Calculation Ib=(Vcc)/Rb; Ic=Beeta*Ib; Icsat=Vcc/Rc; Vce=Vcc-Ic*Rc; //Displaying The Results in Command Win...
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// Exa 21.1 clc; clear all; // Given data Emax=20; //Max value of variable(mA) Emin=4;//Min value of variable(mA) Em=13;//Measured value of variable Eref=10;//Set(ref) point of variable(mA) // Solution //Ep=(Em-Eref)/(Emax-Emin)*100; // Percentage error from page no.(703) //Therefore Ep=(Em-Eref)/(Emax...
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// this code computes the order and the half-power point of Butterworth filter // //lpf_specs = [-1.4161988,-1.,1.,1.4161988]; //bpf //lpf_specs_bsf = [-1.2394869,-1.,1.,1.2394869]; //bsf //delta = 0.15; //W_p = lpf_specs(3); //W_s = lpf_specs(4); // //D1 = (1/(1-delta)^2)-1; //D2 = (1/(delta^2))-1; //numerat...
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//Ex10_9 clc A = 150//gain of amplifier beta = 0.05//feedback ratio disp("A = "+string(A)) disp("beta = "+string(beta)) Af = A/(1+beta*A)//gain with negative feedback disp("Af = A/(1+beta*A) = "+string(Af)) fL = 20*10^3//lower 3dB frequency fU = 160*10^3//upper 3dB frequency disp("fL = "+string(fL)+"Hz") dis...
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x f(xs) 0.676985 0.198647 -0.631209 -0.228430 -0.679405 -0.196949 -0.246670 -0.217565 -0.551867 -0.266905 -0.100697 -0.098665 0.927798 0.017975 -0.906395 -0.028863 0.503620 0.280548 -0.312467 -0.254430 -0.217587 -0.197472 0.054778 0.054449 -0.620546 -0.234647 -0.142125 -0.136441 0.286107 0.241184 -0.35...
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//Chapter-4, Illustration 27, Page 222 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P0=800;//Steam pressure in kPa T0=900;//Steam temperature in K a1=70;//Nozzle angle in degrees ns=0.85;//Steam efficiency m=...
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function root = ridder( f, a, b, tol, NiterMax ) if ~exists("tol", "local") then tol = 1e-9 end if ~exists("NiterMax", "local") then NiterMax = 30 end printf("\nRoot searching via Ridder''s method\n") printf("Initial search interval: [%18.10f,%18.10f]\n", a, b) printf("Tolerance: %18.10e\n", to...
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// Example 9.10 // Repeat the example 9.9 assuming 90 % leading power factor // Determine (a) Excitation voltage (b) Power angle (c) No load voltage, // assuming the field current is not changed (d) Voltage regulation (e) No load // voltage if the field current is reduced to 80% of its value at rated load. // Page 37...
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// Exa 8.1 clc; clear; close; // Given data l=25;// in mm l=l*10^-3;// in meter d=5;// in mm d=d*10^-3;// in meter S= 20;// in cm S= S*10^-2;// in meter Va= 3000;// in volts TraceLength= 10;// in cm TraceLength=TraceLength*10^-2;// in meter y=TraceLength/2; Vd= 2*d*Va*y/(l*S);// in volts Vrms= Vd/sqrt(2...
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//caption:Find input voltage //Ex6.10 clc clear close Vref=5//reference voltage(in V) t1=0.2//coumts when input voltage is applied(in sec) R=100*10^3//resistance(in ohm) C=10^-6//capacitance(in F) t2=R*C Vin=(t2/t1)*Vref disp(Vin,'input voltage(in V)=')