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int f(float); int f(float);int f(float);int f(float);int f(float);int f(float);int f(float); int f(float), f(float), f(float), f(float), f(float); int f(float x) { int x1; } void main(void) { enum A { A1, A2, A3, A4, A5 } a; int x; float y; int *p; { int x; /* не ошибка */ } main(); ...
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clc //Given that D15=0.59// diameter of 15th newton’s ring in cm D5=0.336// diameter of 5th newton’s ring in cm R=100// radius of Plano convex lens in cm //Sample Problem 12 Page No. 51 printf("\n # Problem 12 # \n") p=15-5 printf(" \n Standard formula used \n D_a^2 – D_b^2 = 4*p*R*lambda \n") lambda=(D15^2 ...
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//Example No.6.3 //Page No.186. clc;clear; r = 1.278*10^(-10);//Atomic radius of copper -[m]. A = 63.54;//Atomic weight of copper. n = 4; Na = 6.022*10^(26); a = (2*sqrt(2)*r); printf("\nThe lattice constant for FCC is %3.3e",a); d = ((n*A)/(Na*a^(3)));//for FCCn=4. d = ((n*A)/(Na*(3.61*10^(-10))^(3))); p...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Adjoint stability (Arpack): Channel</description> <executable>IncNavierStokesSolver</executable> <parameters>ChanStability_adj_Ar.xml</parameters> <files> <file description="Session File">ChanStability_adj_Ar.xml</file> <file descriptio...
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--> A=[5 3 -11; 4 -5 4; 3 -13 19] A = 5. 3. -11. 4. -5. 4. 3. -13. 19. --> [L,U,P]=lu(A) L = 1. 0. 0. 0.6 1. 0. 0.8 0.5 1. U = 5. 3. -11. 0. -14.8 25.6 0. 0. 1.421D-15 P = 1. 0. 0. 0. 0. 1....
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PL/SQL Developer Test script 3.0 25 --调用测试脚本自动推送。 DECLARE RECEPT_ID NUMBER; x_return_code VARCHAR2(2000); x_return_msg VARCHAR2(2000); BEGIN for receipt_group in ( select shipment_header_id,receipt_num,order_number,po_header_id from( select rt.transaction_id,rt.attribute1 kk,cux_rcv.*...
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// CÓDIGO PRINCIPAL clearglobal // Limpa as variáveis globais clear // Limpa as variáveis locais xdel(winsid()) // Fecha as janelas ativas clc // Limpa a tela do console winId=progressionbar("Iniciando . . .") exec("A0_PRECOD1_OBJS.sce",-1) // Funções de criar objeto e criar uicontr...
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function[L]=LimitesRaizes(n,c) if(c(1) == 0) then disp("coeficiente c(1) nulo"); return; end t = n + 1; c(t+1) = 0; while c(t) == 0 t = t-1; end for i=1:4 if(i == 2 | i == 4) then for j=1:t/2 Aux = c(j); c(...
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function res = mdaqIsExtMode() res = [] con = mdaqOpen(); result = mlink_set_obj(con, "ext_mode", 1); mdaqClose(con); if result == -25 then res = %F else res = %T end endfunction
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clear;lines(0); disp([1 2],3) deff('[]=%t_p(l)','disp(l(3),l(2))') disp(tlist('t',1,2))
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//Find (a) the final-stage voltage gain Av2  vo=vo1; (b) the final-stage input impedance Zin2; //(c) the initial-stage voltage gain Av1  vo1=vin; (d) the amplifier input impedance Zin1; and //(e) the amplifier voltage gain Av  vo=vi. //Example 6.22 page no 189 clear clc hfe=40 Rc2=20*10^3 //Ω Rc1=10^4 ...
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clc pathname=get_absolute_file_path('5_2_4.sce') filename=pathname+filesep()+'524.sci' exec(filename) //SCFH means ft^3(STP)/h ndot=3.95*10^5/359 printf(" Molar flowrate=%E lb-moles/hr",ndot) V2dot=V1dot*T2*P1/(T1*P2) printf(" \n True volumetric flowrate=%E ft^3/h",V2dot)
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//ques-16.26 //Calculating values of rate constants clc K=0.1;//equilibrium constant R_T=10^-5;//relaxation time (in s) //R_T = 1/(ka+kb) //K=ka/kb ka=1/(11*10^-5); kb=10*ka; printf("The value of ka is %d /s and kb is %d /s.",ka,kb);
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//example 10.5// //resolution// clc //clears the screen// clear //clears all variables// a=2^12; resolution=5000/(a-1); disp(resolution, 'Resolution of 12 bit A/D converter (in mV)=')
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); function HSIColor(H,S,I) { H=H*2*Pi; r=0;g=0;b=0; if ((H>=0) and (H<=2*Pi/3)) then { b=(1-S)/3; r=(1.0+S*cos(H)/cos(2*Pi/6-H))/3; g=1.0-r-b; } if ((H>=2*Pi/3) and (H<=4*Pi/3)) then { r=(1-S)/3; g=(1.0+S*cos(H-2*Pi/3)/co...
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clc;clear; //Example 4.2 //given data d=2180;//density of NaCl M=23.5+35.5;//Molecular weight Na=6.02*10^26;//Avgraodo no. in 1/kg mole n=4;//for f.c.c //calculations a=(n*M/(Na*d))^(1/3); d=a/2; disp((d*10^10),'distance between to adajcent atoms in angstrom')
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// This GUI file is generated by guibuilder version 4.2.1 ////////// f=figure('figure_position',[511,78],'figure_size',[656,582],'auto_resize','on','background',[-2],'figure_name','Graphic window number %d','dockable','off','infobar_visible','off','toolbar_visible','off','menubar_visible','off','default_axes','on','v...
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a a c h a r y a n a n d a n a ஆ ச ா ர ் ய ா ன ா ன ் த ன ா a a c h w a l ஆ ச ் வ ல ் a a d h i r o t i ஆ த ி ர ோ ட ் ட ி a a d i t y a n a n d a n ஆ த ி த ் ய ா ன ன ் த ன ் a a d m i s a d a k k a ஆ த ் ம ி ச த க ் க ா a a g k a g o l a ஆ க ் க ா க ோ ல ா a a g k e s h o l a y ஆ க ் க ே ஷ ோ ல ...
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//find clc //solution //given d=0.05//m l=0.1//m p=1.4//N/mm^2 N=900//rpm //d/c=1000 Z=0.011 to=75//deg C ta=35//deg C t=10//deg C S=1850 u=(33/10^8)*(Z*N/p)*1000+0.002 W=p*d*l*10^6//N V=%pi*d*N/60//m/s Qg=u*W*V///W //(tb-ta)=0.5(75-35)=20//deg C C=280//W/m^2/C Qd=C*l*d*20//J/s printf("headt dessip...
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//Exemplo de regressão linear em dados simulados //Fixando seeds para reprodutibilidade rand("seed",0) grand('setsd',0) //Geração dos dados x = 10*rand(100,1) //x é vetor de 100 pontos aleatório uniforme(0,10) eps = grand(100,1,'nor',0,2) y = 7*x+2+eps //y = 7x+2+e, onde eps é vetor de 100 pts ~ Normal(0,2) //Scatte...
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V=500//applied voltage N1=700//initial speed of motor Ia1=50//armature current Ra=.4//effective armature resistance Eb1=V-Ia1*Ra N2=600//reduced speeed of motor Ia2=Ia1//as torque and flux remains same //back emf is directly proportional to speed R=((V-Ia2*Ra)*N1-Eb1*N2)/(Ia2*N1) mprintf("Additional resistan...
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// Premier script // Définition de la matrice A A = [1:3;-4,5,7;0,6,9] // Transposée de A transA = A' // Calcul du déterminant detA = det(A) // Calcul de l'inverse invA = inv(A) // Vérification checkA = A * invA // Affichage des résultats disp("Matrice : ", A, "Transposée : ", transA, "Déterminant", detA, "Inver...
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clc //Initialization of variables x=0.25 Ps1=96 //mm Ps2=43.9 //mm //calculations P1=x*Ps1 P2=(1-x)*Ps2 P=P1+P2 Xdash=P1/P //results printf("mole fraction of methanol in vapor = %.3f ",Xdash)
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//===================================================================================== //Chapter 12 example 29 clc;clear all; //variable declaration C1 = 95*10^-12; //capacitance in F f1 = 800*10^3; //frequency in Hz f2 = 2.5*10^6; //frequency in Hz //calculations w2 = 2*%pi*f; L ...
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clc; //page no 207 //prob no. 5.11 //A PLL FM generator refering fig.5.25 with f_ref=100*10^3;N=200;kf=50*10^3;//in Hz/V //a)Determination of carrier freq of o/p signal fc=N*f_ref; disp('MHz',fc/10^6,'The carrier freq of o/p signal'); //b)Determination of RMS modulating voltage for 10kHz deviation dev=10*10^3;...
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 3.1 clc; clear; s=%s p=poly([4],'s','coeff') q=poly([0 5 1],'s','coeff') g=p./q disp(g,'the given transfer function is') c=g/(1+g) disp(c,'the closed loop transfer ...
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//Fluid Systems - By - Shiv Kumar //Chapter 11- Centrifugal Pumps //Example 11.2 //To Find the Vane Angle at Outer Periphery of the Impeller. clc clear //Given Data:- N=1470; //Speed, rpm Q=100; //Discharge, litres/s Hm=24; //manometric Head, m Do=240; ...
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//7.5 clc; S=900; P=1.5*10^3; Q=2*10^3; Cs=0.2*10^-6; rx=S*P/Q; printf("Resistance=%.0f ohm",rx) Lx=P*Cs*S; printf("\nInductance=%.2f H",Lx)
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clc T=300//K Na=10**16 //cm^-3 Nd=10**16 //cm^-3 ni=1.5*10**10 //cm^-3 Dn=25 //cm^2/s Dp=10 //cm^2/s taup0=5*10^-7 //s taun0=5*10^-7 //s epsilon=11.7 e=1.6*10**-19 //C //J=(E*D*np0/Ln)+(E*D*pn0/Lp) Js=e*ni^2*[(1/Na)*sqrt(Dn/taun0)+(1/Nd)*sqrt(Dp/taup0)] disp(Js,"reverse saturation current density in A/...
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clc clear // 1 A = [1 6 7 11 12 15] B = [-4:9] C = [] for i = 1:length(B) C(1,i) = ceil(%e^B(1,i)) end // 1 a disp("1.a) Cardinalidade de C: " + string(length(C))) // 1 b u_AB = union(A, B) r_1b = setdiff(union(u_AB, C), intersect(u_AB, C)) disp("1.b) conjunto (A U B) + C: ") disp(r_1b) // 2 cartoes = [...
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clc; //Example 7.3 //Page No 257 disp("Given: An FM modulator with a modulation index m=1, a modulating signal v,(t)=Vmsin(2pi1000t) and an unmodulated carrier vc(t)=10sin(2pi500kt)."); //Solution //(a) disp("(a)From Table 7.3, a modulation index of 1 yields a reduced carrier component and three sets of significant...
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pathname=get_absolute_file_path('4_21.sce') filename=pathname+filesep()+'4_21data.sci' exec(filename) Pstag=Pe*[(y+1)^2*Me^2/((4*y*Me^2)-2*(y-1))]^(y/(y-1))*(1-y+2*y*Me^2)/(y+1) disp(Pstag,"Pstag=","Pstag=Pe*[(y+1)*Me^2/((4*y*Me^2)-2*(y-1))]^(y/(y-1))*(1-y+2*y*Me^2)/(y+1)","the stagnation presure is given by Pstag"...
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//This code plots an involute spur gear. //INPUT n=15;//number of teeth d=100;//pitch diamter phi_d=20;//pressure angle in degrees r_fillet=0.05;//radius of fillet //------------------------------------ pd=n/d;//diametral pitch phi=phi_d*%pi/180;//pressure angle in radians db=d*cos(phi);//diameter of base circ...
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function r=%sp_q_s(a,b) //r=a.\b // Copyright INRIA [ij,v,mn]=spget(a) if size(v,'*')<>mn(1)*mn(2) then error(27) else r=full(a).\b end
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FLAGS='--list' STDIN='' STDOUT='NONE\nUTF-7\nUTF-8\nUTF-16BE\nUTF-16LE\nUTF-32BE\nUTF-32LE\nGB18030\n' STDERR='' EXITVAL='0'
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int successor(int x) { return x + 1; } main { int s; s := successor(); return s; }
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 19 disp("CHAPTER 7"); disp("EXAMPLE 19"); //VARIABLE INITIALIZATION va=10000; //apparent power v1=500; //primary voltage in Volts v2=250; //secondary voltage in Volts f=50; //open circuit ...
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//fiber optic communications by joseph c. palais //example 3.3 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given lambda=1.55e-6*1e9//wave length in nm lambda0=1.3e-6*1e9//Zero dispersion wave length in nm M0=-0.095//slope at zero dispersion wave length ps/(nm^2xKm) //to find M=(M0/4)*(lambda...
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clc V=6; //m^3 %A=0.45; %B=0.55; R_A=0.288; //kJ/kg K R_B=0.295; //kJ/kg K m=2; //kg T=303; //K disp("(i) The partial pressures") m_A=%A*m; m_B=%B*m; p_A=m_A*R_A*10^3*T/V/10^5; //bar disp("p_A=") disp(p_A) disp("bar") p_B=m_B*R_B*10^3*T/V/10^5; //bar disp("p_B=") disp(p_B) disp("bar") disp(...
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//Program to find the Inverse Z transform using the Long Division Method clear; clc; z=%z; num=2*z*(2*z-1) den=(z-1)*(z-2)^2 h=ldiv(num,den,10) disp(h,"Displaying the first ten terms of the inverse z transform")
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clc // given data Co=20000.0 // cost in Rs B=3000.0 // annual benefit in rs n=15.0 // time in years i=15.0/100 // initial guess for rate NPV=zeros(4) NPV(1)=B*(((1+i)**n)-1)/(i*(1+i)**n)-Co x=1 printf( "Iteration no.\t\ti*\t\tNPV(i*)") while NPV(x)<0 x=x+1 i=i-0.01 NPV(x)=B*(((1+i)**n)-1)/...
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; malformed check-sat command (set-logic QF_UF) (check-sat x)
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//Variable declaration rho=1.54*10**-8; //resistivity of metal(ohm m) n=5.8*10**28; //number of free electrons(per m**3) e=1.602*10**-19; //charge(c) m=9.11*10**-31; //mass(kg) E=1*10**2; //electric field(V/m) Kb=1.381*10**-23; //boltzmann constant T=300; //temperature(K) //Calculati...
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// Copyright INRIA eps=100*%eps; // inf if norm([1,2,3,-1,-2,-3],0)<>%inf then pause,end if ~isnan(norm([1,2,3,-1,-2,-3],%nan)) then pause,end if norm([])<>0 then pause,end // vector x=[1,2,3,-4]; if abs(norm(x,1) - sum(abs(x))) > eps then pause,end if abs(norm(x,2) - sqrt(sum(abs(x).*abs(x)))) > eps then pause,end ...
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clc // Given that lambda = 5e-7 // wavelength of light in meter theta = %pi / 6 // half angular width of central maximum in first case in radian theta_ = %pi / 2 // half angular width of central maximum in second case in radian // Sample Problem 17 on page no. 2.44 printf("\n # PROBLEM 17 # \n") m = 1 // for first min...
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disp('To find:factorial of a 6 ') facto2 =2*1; facto3 =3* facto2 facto4 =4* facto3 facto5 =5* facto4 facto6 =6* facto5 k =8*7* factorial (6)/ factorial (6) ; disp (k,'value of 8!/6! is:') j =12*11*10* factorial(9)/factorial(9); disp(j,'value of 12!/9! is:')
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function ydot=f(t, T) ydot= -2.2067 * 10^(-1 * 12) * (T^4 - 300^4); endfunction
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// Copyright INRIA scifuncs=['funcc1','funcc2','funcc3','funcc4']; //Scilab functions files=G_make(['/tmp/ex3cI.o','/tmp/ex3c.o'],'ex3c.dll'); addinter(strcat(files,' '),'testcentry3',scifuncs) //matrix (double) created by C function x1=funcc1(); if norm(x1-matrix((1:5*3),3,5)) > %eps then pause,end //matrix (int)...
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//clc() T = 350;//K P = 1;//bar V1 = 22.4143 * 10^-3;//m^3 (suffix 1 represents at STD) P1 = 1.01325;//bar T1 = 273.15;//K V = P1 * V1 * T/(T1 * P); disp("m^3/mol",V,"Molar volume =")
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clc; clear all; disp("Volatge at burnout point") d=0.001;//m diameter of wire I=190;//amp L=0.4;//m length of wire rhol=958.4;//kg/m^3 rhov=0.5955;//kg/m^3 hfg=2257*10^3;//J/kg s=58.9*10^(-3);// N/m g=9.81;//m/s^2 qsc=0.18*rhov^0.5*hfg*(g*s*(rhol-rhov))^0.25;// at burnout i.e. points of critical flux A=%pi*...
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//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 7 //Scilab version- 6.0.0 //Example 3.3.4 clc; clear; //given N1=1.487;//refractive index delta=1.71; L=5E3;//length of the graded index fiber c=3E8;//velocity of light in m/s b=delta*delta; e=L*N1*b; w=8*c; d...
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function do_export(scs_m,fname) [lhs,rhs]=argn(0) driv='Pos';num=1 dr=driver() wpar=scs_m(1)(1) winc=xget('window'); if rhs==1 then num=x_choose(['Postscript file';.. 'Graphics window'],'How do you want to export?') if num==0 then return;end if num<>2 then fname= xgetfile('*');end end // remove blanks and apostroph...
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//in page no.340,numbering is done wrongly,it should be like ex-8,ex-9,ex-10,ex-11,ex-12,ex-13,ex-14 clc //to calculate average values of intensities of electric and magnetic fields of radiation //energy of lamp=1000 J/s //area illuminated =4*%pi*r^2=16*%pi m^2 //energy radiated per unit area per second =1000/16*%...
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z=%z; x=ldiv(z,2*z^2-3*z+1,5); mprintf('x[n]={0,%.2f,%.2f,%.2f,....}',x(1),x(2),x(3));
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//Checking if function works for different values obpts = [ 1 2 -3; 3.3 1.5 .2; 1.1 2.5 2.4; .2 1.5 3.2; 2.3 -1.5 -.5; -1 -3 5.5; -1.5 -.5 3.5]; impts = [282 274; 397 227; 577 276; 462 378; 270 479; 450 523; 566 476]; camera = [ 1 0 0; 0 1 0; 0 0 1] dist = [0 0 0 0]; iterations = 10; reprojectionError ...
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//Calculations on oil engine clc,clear //Given: n=4 //Number of cylinders d_o=5 //Diameter of orifice in cm Cd=0.6 //Coefficient of discharge for orifice d=10.5,l=12.5 //Bore and stroke in cm N=1200 //Engine speed in rpm T=147 //Brake torque delivered in Nm m_f=5.5 //Fuel consumption in kg/hr CV=43100 //Calor...
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//EX13_3 PG-13.3 clc clear disp("representation of the number 567 in power of 8") disp("N=(5*8^2)+(6*8^1)+(7*8^0)=375") printf(" Therefore decimal equivalent of 567 is: ") N=(5*8^2)+(6*8^1)+(7*8^0) printf("%.0f",N)
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changed #0 changed #1 changed #2 changed #3 changed #4 test for 5 item #6 item #7 test for 8 item #9 stored #10 stored #11 stored #12 stored #13 stored #14 stored #15 stored #16 stored #17 stored #18 stored #19 item #20 item #21 item #22 item #23 item #24 item #25 item #26 item #27 item #28 item #29 item #30 item #31 i...
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//Network Theorem 2 //pg no 3.25 //example 3.21 //Calculation of Vth v=100; r=20; x=v/r; disp("Removing the 20 Ohm resistor from the network"); printf("\nVth = %.f V ",v); //calculation of Rth disp("replacing the voltage source with short circuit and current source by open circuit"); disp("Rth = 0"); //calc...
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//Calculate impedance and quality factor and bandwidth clear; clc; //soltion //given R=10;//ohm L=150*10^-6;//H C=100*10^-12;//F fo=1/(2*%pi*sqrt(L*C)); Zp=L/(C*R); //impedance printf("The impedance Z= %.0f kΩ\n",Zp/1000); Xl=(2*%pi*fo*L); Q=Xl/R; BW=fo/Q; printf("The Quality factor of the circuit...
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// Initilization of variables W=30 // N // Weight of the hammer theta=30 // degree // ref fig.20.12 mu=0.18 // coefficient of friction s=10 // m // distance travelled by the hammer // fig 20.12 g=9.81 // m/s^2 // acc due to gravity // Calculations // The acceleration of the hammer is given as, a=g*((sind(theta)...
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clear close clc s = poly(0,'s'); G1 = 100/((s+100)*(s^2+2*s+2)); Glin1 = syslin('c',G1); G2 = 1/((s^2+2*s+2)); Glin2 = syslin('c',G2); clf(); evans(Glin1,100); evans(Glin2,100) // Post-tuning graphical elements ch = gca().children; curves = ch(2).children; curves.thickness = 2; asymptotes = ch(ch.type=="Segs"); a...
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clear; clc; close; Rf = 240*10^(3); R1 = 10*10^(3); Vi = 0.02; w = 300*10^(3); SR = 0.5; Acl = abs(Rf/R1); K = Acl*Vi; w1 = SR/K; disp(w,'Since this frequency is much less than maximum obtained,hence no distortion will be observed');
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bem vindo ao meu mundo!!
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//Chapter-1,Example1_7_2,pg 1-42 wavelength=6000 //wavelength of light in air u=1.2 //refractive index of transparant material wavelength_1=wavelength/u ...
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//(Springs) Example 10.3 //Maximum force acting on the helical spring P (kN) P = 7.5 //Mean coil diameter D (mm) D = 150 //Spring rate k (N/mm) k = 75 //Ultimate tensile strength of the spring material Sut (N/mm2) Sut = 1250 //Rigidity modulus of the material G (N/mm2) G = 81370 //Array of values C Cval =...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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function y = I(x) y = (x.^20)*exp(x) endfunction function y = SquareMethod(f,a,b,n) s=0; h=(b-a)/n; for i=0:(n-1) s=s+f(a+(i*h)); end y=h*s endfunction // Fonctions supplémentaires pour des tests de précision function S = Simpson(f,a,b,N) h = (b-a)/N pe = a + h*[1:N-1] pm = a + ...
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//example 16.6 //calculate permeability coefficient clc;funcprot(0); //given L=30; //spacing between drans Q=4D-6; //discharge a=8; b=8.3; k=1000000*Q*L/(4*(b^2-a^2)); k=round(k*100)/100; mprintf("permeability coefficient=%fD-6 m/sec.",k);
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//Page Number: 11.16 //Example 11.8 clc; //(a) Channel Matrix //Given PYbyX=[0.9 0.1;0.2 0.8]; PZbyY=[0.9 0.1;0.2 0.8]; //As P(Z/X)=P(Y/X)*P(Z/Y) PZbyX=PYbyX*PZbyY; disp(PZbyX,'Channel Matrix'); //(b)Pz1 and Pz2 //Given Px1=0.5; Px2=Px1; //As P(Z)=P(X)*P(Z/X) //P(X) matrix PX=[Px1 Px2]; PZ=PX*PZb...
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//(Springs) Example 10.4 //Refer Fig.10.17 on page 410 //Axial force on the spring when the valve is open Pmax (N) Pmax = 300 //Axial force on the spring when the valve is closed Pmin (N) Pmin = 150 //Length of the spring when the valve is open lmax (mm) lmax = 30 //Length of the spring when the valve is closed lmin (...
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clc //given d=7//in; central distance k1=2*7*7//T1+t1/(2*7)=7 k2=2*7*5//T2+t2/(2*5)=7 G=9/1 t1=(-(k1+k2)+((k1+k2)^2+4*(G-1)*(k1*k2))^(1/2))/(2*(G-1)) a=ceil(t1) b=floor(t1) T1=k1-a T2=k2-a T3=k2-b G1=T1*T2/(a*a) G2=T1*T3/(a*b) dp=a/d //case b) tb1=23//let t1 = 23 Tb1=k1-tb1 Gb1=Tb1/tb1 Gb2=G/Gb1 t...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/04/fill/Fill.tst load Fill.hack; echo "First, make sure that 'No Animation' is selected. Then, select the Keyboard, click ...
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clc; clear; disp_X=0.05896*10^-3 //displacement of mirror in m n=200 //no of fringes //calculation lambda=(2*disp_X)/n mprintf("The wavelength of the light is = %1.3e m",lambda) //The answer provided in the textbook is wrong.
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clc; VO=0.21; VN=0.79; n=3.5; nO=VO*n; nN=VN*n nC=1; m_O=32; m_N=28; m_C=44; mO=m_O*nO; mN=m_N*nN; mC=m_C*nC; m=mO+mN+mC; disp("total mass is:"); disp("kg",m); //percentage of carbon is mc=12; P=mc*100/m; disp("percentage of carbon is:"); disp("%",P) n=nO+nN+nC; m_=[nO*m_O/n]+[nN*m_N...
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//Determine the incremental cost of recieved power and penalty factor of the plant clear clc; pf=10/8;//penalty factor cost=(.1*10+3)*pf;//Cost of recieved power=dF1/dP1 mprintf("Penalty Factor=%.1f\n",pf); mprintf("Cost of recieved Power=Rs %.1f /MWhr",cost);
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## DO NOT EDIT! Generated automatically from test/atan2.itl ## by the Interval Testing Framework for IEEE 1788. ## https://github.com/nehmeier/ITF1788/tree/92558f7e942665a78f2e883dbe7af52320100fba ## ## Copyright 2015-2016 Oliver Heimlich ## ## This program is free software; you can redistribute it and/or modify ## i...
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//chapter-10 page 490 example 10.11 //============================================================================== clc; clear; D=1;//Assume diameter of the parabolic reflectors in the original system in m w=1;//Assume wavelength in m //CALCULATION D1=2*D;//diameter of the parabolic reflectors in the modifi...
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//clc() P = 100;//kPa T = [273 280 290 300 310 320 330 340]; for i =1:8 Ps(i) = exp(13.8216 - 2697.55/(T(i)-48.78)); end disp((Ps)) for j = 1:8 Ys(j) = Ps(j) * 86.11 / ((P - Ps(j))*28); end disp(Ys) plot(T,Ys,rect=[273,0,333,10]); xtitle('100% saturation line for nitrogen-hexane system','Temperature...
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// to calculate air velocity assuming density of air 1.2kg/m3 clc; gammma=9800 // constant gammma h=4e-3 // height of water in mm pair=1.2 // air velocity of air in kg/m3 deltap=h*gammma V=sqrt((2*deltap)/pair) mprintf('V =%f m/s',V)
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clc pathname=get_absolute_file_path('5_2_1.sce') filename=pathname+filesep()+'521.sci' exec(filename) n=weight/MN2 //mol V=n*R*T*14.7/P //lt printf("assuming ideal gas behaviour, volume=%f litres",V) Vcap=V/n if(Vcap>5) disp("ideal gas equation yields error less than 1 % for diatomic gas") else disp(...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-3, Illustration 3, Page 54 //Title: Calculation of pressure //=====================================================================...
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errcatch(-1,"stop");mode(2);//Caption:Find (a)Voltage per turn (b)Cross sectional area of core (c)Cross sectional area of conductor for h.v (d)Number of turns per phase in h.v winding (e)Cross sectional area of conductor in l.v winding (f)Number of turns in l.v winding (g)Window area (h)Yoke and approx frame size,and (...
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//Chapter 13 //Example 13_35 //Page 350 clear;clc; v=500; ip=800; in=550; io=1500; ra=0.2; //no load current inl=5; tip=io+ip; tin=io+in; cn=ip-in; printf("Total current on positive side = %d A \n", tip); printf("Total current on negative side = %d A \n", tin); printf("Current in nuetral wire = %d A \n\n", cn); e=v...
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//Problem 10.08: //initializing the variables: EA = 150 T = 298; // in K //calculation: DHc = -1580.56 // in cal/gmol //DCp = 14*Cpco2 + 2*Cph2o + 5*Cphcl + 22.5*Cpo2 + 141.05*Cpn2 //DCp = 1318.60 + 0.1899*T - 5.327E6*T^-2 //DHc = 1318.60(T2 - T) + 0.5*0.1899*(T2^2 - T^2) + 5.327E6(T2^-1 - 298^-1) //solvin...
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//Example12.3 //Find the probability that tails shows up at least once. disp('Let A be the event that tail shows atleast once'); disp('Eac toss has two possible outcmes H ,T'); disp(2^3,'Hence the total no of outcomes is 2^3='); disp(1-(1/2^3),'P(A)=1-Probability of getting all head i.e 1/8=');
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// find voltage gain,center frequency,Q // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 21-12, page 827 clear;clc; close; // Given data C=120*10^-9;// capacitance in faraday R1=13*10^3;// resistance in ohms R2=10*10^3;// resistance i...
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//To calculate the susceptibility chi_1 = 2.8*10^-4; //susceptibility T1 = 350; //temperature, K T2 = 300; //temperature, K //chi = C/T where C is curie constant chi_2 = chi_1*T1/T2; //susceptibility at 300 K printf("susceptibility at 300 K is %f",chi_2);
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2+2 2+2,3*4 2+2;3*4 2+2,3*4; // a comment
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clc h1 = 313.93 // Enthalpy of water at heater inlet in kJ/kg h2 = 2676 // Enthalpy of hot water at temperature 100.2 degree Celsius h3 = 419 //Enthalpy of water at heater inlet in kJ/kg w1 = 4.2 // mass flow rate in kg/s printf("\n Example 5.4") w2 = w1*(h3-h1)/(h2-h3)// Steam rate printf("\n The amount of ...
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//Section-10,Example-2,Page no.-CT.31 //To calculate dl_E for the given process. clc; P=4 V_2=25 V_1=5 W=-(P*(V_2-V_1))*(8.314/0.08206) q=500 dl_E=q+W disp(dl_E,'Change in internal energy(J)')
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clear; clc; printf("\t Example 11.10\n"); T1=303; // isothermal temp.,K v=5; //air speed,m/s l=0.05; //length of naphthalene model that is flat, m Mnap=128.2; //molar mass of naphthalene,kg/kmol D=0.86*10^-5; //diffusion coefficient of naphthalene in air,m/s Pv=10^(11.45-3729.3/...
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//Exa 3.8 clc; clear; close; format('v',6); //Given Data : Wdot=200;//W t1=40;//degree centigrade //Q2dot=20*(t1-t2);//W //COP=Q2dot/W2dot=T2/(T1-T2) //(t1-t2)/(W2dot/20)=(t1+273)/(t1-t2) //20*t1^2+20*t2^2-20*2*t1*t2-t1*Wdot-273*Wdot //(t2+273)/(t1-t2)=(t1-t2)/(Wdot/20) //t2^2-(2*t1+(Wdot/20))*t2-273*(Wd...
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// Preview control for walking timer(); // 足の着地時間(s),x方向の位置(m),y方向の位置(m) foot = [0 0 0; 0.6 0.1 0.06; 0.9 0.2 -0.06; 1.2 0.3 0.06; 1.5 0.4 -0.06; 1.8 0.5 0.06; 2.4 0.6 -0.06; 3.0 0.7 0.0; 100 0 0]; forward_period = 1.0; // 予見制御の時間(s) calculate_period = 4.0; // 歩行パターンを生成する期間(s) dt = 0.01; ...
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// This code plot the PDOS calculated from Quantum espresso // change the file browser to working folder. clear; clc; exec(PiLib); xdel(winsid()); // Parameters ========================================================== work_dir=[] // dir where pdos files are stored Ef=10.6726 // Fermi level plot_atom=[-1,13,14,-2,1...
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clc;funcprot(0);//Example 2.12 //Initilisation of Variables L=0.05;....//length of the linear triangular fin in m t=0.01;....//diameter of linear triangular fin in m w=0.25;...//width of the linear triangular fin in m K=175;....//thermal conductivity of rod in W/m*k h=45;....//Convective heat transfer coefficient...
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//chapter 5 //example 5.17 //Calculate percentage of uncertainty in the momentum of electron //page 109 clear; clc; //given K=1; // in KeV (kinetic energy of electron) dx=1; // in Angstrom (uncertainty in the position) h=6.63E-34; // in J-s (Planck's constant) m=9.1E-31; // in Kg (mass of electron) pi=3.14; ...
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clc clear //INPUT t1=288;//inital temperature in K dv=1/2;//ratio of inital to final volume y=1.4;//coefficient of expansion //CALCULATIONS t2=t1*(dv)^(y-1);//final temperature in K //OUTPUT mprintf('the final temperature is %3.1f K',t2)