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19_1.sce
pathname=get_absolute_file_path('19_1.sce') filename=pathname+filesep()+'19_1data.sci' exec(filename) clear Yc=(2*L45^2 +L12^2)/(4*L12 +4*L45); Ixx=((2*L12 +L45)*t*Yc^2) +(L45*t*(L45-Yc)^2)+ (2*t/3)*((2*Yc^3) -((Yc-L45)^3) -((Yc-L12)^3)); P=-Sy/Ixx; function[q1]=q12(s1), q1=P*t*(Yc-L12)*s1 +P*t*0.5*s1^2; e...
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//EXAMPLE 3.2.C clc; Syms s t w=2; laplace(cosh(w*t),t,s)
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load Or16Way.hdl, output-file Or16Way.out, compare-to Or16Way.cmp, output-list in%B2.16.2 out%B2.1.2; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1010101010101010, eval, output; set in %B0011110011000011, eval, output; set in %B0001001000110100, eval, output;
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units SI /LiquidPhases = 2 /RecycleDetails = 1 displayproperties commonproperties VapFrac T P MoleFlow MassFlow VolumeFlow StdLiqVolumeFlow Energy H S MolecularWeight MassDensity Cp ThermalConductivity Viscosity molarV ZFactor SurfaceTension StdLiqMolarVol displayproperties VapFrac T P MoleFlow MassFlow VolumeF...
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/* Questionaire created by optica toolkit Date: Tue Mar 04 16:13:41 1997 */ question(1, 'item 7-1', 'Hoe kan in deze situatie het onscherpe beeld gecorrigeerd worden?', [ 'Door een sterke, negatieve lens tussen het voorwerp en de lens te plaatsen', 'Door een sterke, positieve lens tussen het voorwerp en d...
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get_ejercicio.tst
PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_ejercicio(pejercicio_id => :pejercicio_id); end; 2 result 1 Yoga 5 pejercicio_id 1 1 4 0
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10_3_Condensation_Chimney.sce
clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 10.3 Page 648 \n'); //Example 10.3 // Heat Transfer and Condensation Rates //Operating Conditions Ts = 50+273 ;//[K] Surface Temperature Tsat = 100+273 ;//[K] Saturated Temperature D = .08 ...
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style.displayedLabel="common_source"; pal1_1=xcosPalAddBlock(pal1_1,"common_source",[],style);
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//Example 3.40:resistance and capacitance clc; clear; close; r2=1000;//ohms r4=100;//ohms c4=0.1;//micro farads c3=1000;//pF rs=((c4/(c3*10^-6))*r2);//M-ohm cs=((r4/r2)*(c3*10^-6));//micro farads disp(rs*10^-7,"resistance is,(M-ohm)=") disp(cs*10^6,"capacitance is,(micro-F)")
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tpunc.sce
// // // // // clear all; M = 100; H = @(x,k) x^2*k^2; function [N,L,x,k,dx,dk] = setup_grid(M) // N = 2*M+1; L = sqrt(2*pi*N); dx = L/N; dk = 2*pi/L; x = (-M:1:M)*dx; //x = linspace(-M,M,N)*dx k = (-M:1:M)*dk; //k = linspace(-M,M,N)*dk endfunction function rv = dimGetAndC...
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lab7.sce
N=1420; x0=12; t=0:0.1:30; function g=k(t); //g=0.7;//(первый случай) //g=0.00003;//(второй случай) g=0.57*sin(t);//(третий случай) endfunction function v=p(t); //v=0.000012;//(первый случай) //v=0.5;//(второй случай) v=0.38*cos(13*t);//(третий случай) endfunction function xd=f(t,x); xd=(k...
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//(Threaded Joints) Example 7.19 //Maximum external force Pmax (kN) Pmax = 10 //Minimum external force Pmin (kN) Pmin = 0 //Assume the stiffness of the bolts to be 1N/mm kb kb = 1 //Calculate the stiffness of the parts kc kc = 3 * kb //Overload percentage load (%) load = 50 //Yield tensile strength of 50C4...
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clc; //A circuit is midpoint bised when the Q-point value of Vce is one half of Vcc. //from example and 7.3 Vcc=8; //volt Vbe=0.7; //volt Rb=360000; //ohm Ib=(Vcc-Vbe)/Rb; //Ampere Hfe=100; Ic=Hfe*Ib;//Ampere Rc=2000; //ohm Vce=Vcc-Ic*Rc; //volt disp('V',Vce,"Vce=");//The answers vary due to round off error...
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clc //initialisation of variables P= 200 //mm t= 30 //min k= 2.5*10^-4 //sec^-1 //CALCULATIONS P0= P/(10^(k*t*60/2.303)) P1= P-P0 //RESULTS printf (' Partial Pressure of reactant= %.f mm',P1)
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/MemoryAccess/BasicTest/BasicTest.tst load BasicTest.asm, output-file BasicTest.out, compare-to BasicTest.cmp, output-list RAM[256]%D1.6.1 RAM[300]%D1.6.1 RAM[40...
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//4.12 clc; V=100; R=0.2; L=0.8*10^-3; T=2.4*10^-3; Duty_cycle=1/2.4; E=0; Imax=V/R*((1-exp(-Duty_cycle*T*R/L))/(1-exp(-T*R/L)))-E/R; printf("\nImax = %.2f A", Imax) Imin=V/R*((exp(Duty_cycle*T*R/L)-1)/(exp(T*R/L)-1))-E/R; printf("\nImin = %.2f A", Imin) Vavg=Duty_cycle*V; printf("\nAverage output Voltage ...
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clc clear N1=250; D1=53; D2=32; N2=N1*(D1/D2); printf('Speed of shaft: %2.2f RPM',N2); printf('\n');
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(batch "dftmpcmd.tst") (clear) (batch "dfgblcmd.tst") (clear) (batch "memrycmd.tst") (clear) (batch "miscfnx.tst") (clear) (batch "dfrulcmd.tst") (clear) (batch "seqop.tst") (clear) (batch "tceplace.tst")
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// Exa 1.22.6 clc; clear; close; // Given data d = 5.2;// in gm/cc n = 2; M = 120; N_A = 6.023*10^23; m = M/N_A;//mass of 1 atom in gm m = n*m;//mass of unit cell in gm g = 20;// in gm m = g/m;// in unit cells disp(m,"The number of unit cell in its 20 gm is : ");
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clear clc //Original and new length(m) L1=32;L2=50; sigma1=8; // For small deviaqtion from plug flow,sigma_sqr is directly proportional to L sigma2=sigma1*sqrt(L2/L1); printf("\n No of bottles of rose expected is %f",sigma2)
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//Effects of leakage n1=0:0.005:0.1; n2=0:0.005:0.125; n3=0:0.005:1.125; xt1=(2*cos(20*%pi*n1')+5*cos(100*%pi*n1')); xt2=(2*cos(20*%pi*n2')+5*cos(100*%pi*n2')); xt3=(2*cos(20*%pi*n3')+5*cos(100*%pi*n3')); XDFS1=abs(fft(xt1,-1))/20; XDFS2=abs(fft(xt2,-1))/25; XDFS3=abs(fft(xt3,-1))/225; f1=0:5:100; f2=0:4:100; f3=0:100/...
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//Car on road //refer fig. 19.8 //Consider dynamic equilibrium of car v=sqrt(0.4*9.81*50)*((60*60)/(1000)) //kmph //Limiting speed from the consideration of preventing overturning //Taking moment about point of contact of outer wheel with road and noting that R1=0 when the vehicle is about to overturn //Limiting...
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errcatch(-1,"stop");mode(2);// Example 4.3, page no-210 m=0.005 c=0.7 y=-log(0.01) //printf("y=%.2f",y) t=y*2*m/c printf("t=%.4f Secs",t) exit();
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clc; clear all; lambda = 5206e-10; // Wavelength of ight in meters d = 0.02603e-3; // Distance moved n = (2*d)/lambda; // Condition for interference is disp(' ',n,'The number of fringes shifted across wire is')
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clc disp("Example 2.23") printf("\n") disp("Calculate Average voltage, rectification efficiency & percentage regulation") printf("Given\n") V2=30 RL=100 Rf=10 Vm=sqrt(2)*V2 //Average output voltage Vdc=(((2*Vm)/(%pi))/(1+(Rf/RL))) //Rectification effeiciency nr=0.812/(1+(Rf/RL)) //percentage regulation PR...
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clc C=0.85; //Weight of Carbon present H2=0.06; //Weight of Hydrogen present O2=0.06; //Weight of Oxygen present w_required=C*8/3 + H2*8; //Weight of O2 required w_needed=w_required-O2; //Weight of O2 to be supplied w_air=w_needed*100/23; disp("Weight of air needed=") disp(w_air) disp("kg")
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function p=find_path(i,j,g) [lhs,rhs]=argn(0) if rhs<>3 then error(39), end // check i and j if prod(size(i))<>1 then error('find_path: first argument must be a scalar') end if prod(size(j))<>1 then error('find_path: second argument must be a scalar') end // check g check_graph(g) // compute lp, la and ls n=g('node...
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// Caption: Finding reluctances and flux clear; close; clc; U_r=70000; U_o=4*%pi*10^-7; function [R_c]=reluctance_core(l,A) R_c=l/(U_r*U_o*A); endfunction disp(reluctance_core(.3,9*10^-4),'Reluctance of the core=') function [R_g]=reluctance_gap(g,A) R_g=g/(U_o*A); endfunction disp(reluctance_gap(...
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function y = idst1(x,varargin) //This function computes the inverse type I discrete sine transform. //Calling Sequence //Y = idst(X) //Y = idst(X, N) //Parameters //X: Matrix or integer //N: If N is given, then X is padded or trimmed to length N before computing the transform. //Description //This function computes the...
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clc //initialisation of variables in=630//pound/min T0=460+60//R cp=0.24 J=778 g=32.2//ft/sec^2 g1=1.4 T1=450//R ar=0.262//ft^2 nT1=498//ft/sec R=53.3 nT1=489//R //CALCULATIONS W=in/60 v1=sqrt((T0-T1)*2*g*J*cp) p1=W*R*T1/(144*ar*v1) nv1=sqrt((T0-nT1)*2*g*J*cp) np1=W*R*nT1/(144*ar*nv1) //RESULTS pr...
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// ====================== S-params Converter ==================== // // (Semi)Intelligent Differential S-param Viewer // // Main GUI controls // // (c)2014 L. Rayzman // // GUI interface based on UICONTROL2 GUI demo // // Created : 02/25/2014 // Last Update : 06/23/2014 - Separated GUI control...
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function histogramPrzedzialy(img,ilosc_przedzialow) [h w] = size(img); H = zeros(ilosc_przedzialow,1); Y = zeros(2*ilosc_przedzialow+2,1); dlugoscStopnia = ceil(256/ilosc_przedzialow); pom = [0:dlugoscStopnia:255]; pom = [pom;pom]; X = matrix(pom,1,-1); X = [X 255 255]; ...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute ...
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//Chapter-5,Example5_3_11,pg 5-11 //a proton and alpha particle are accelerated by the same potential difference m_p=1.67*10^-27 //mass of proton m_a=4*m_p //mass of alpha particle (assume mass of alpha particle to be 4 time...
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clc T2=300 T1=1400 Eta=1-(T2/T1) mprintf("Eta=%f\n",Eta)//ans vary due to roundoff error Q1=65 //in kJ/min W=60 //in kJ/min mprintf("efficiency claimed by inventor=%f",W/Q1)//ans vary due to roundoff error
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spLITTer p {} FiLter X { bitAnd ( m, ) OR hM ( ) Not Wmtg << ef } FiLTeR u {nOt Hf Lp } W -> r groUPer a {aGgReGATE KO.W } UNgrOuPEr Im { } gRoUPFiLtEr Q {not bitAND ( 51.122.4.2/25, ) or not bitand ( ) nOT BItor (zC, C, ) bITANd ( 7.2.177.6, ) oR Not 46.183.248.252 Not In lW ( BitANd ( ), ) oR Bit...
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//Chapter 21, Problem 28 clc; n1=500; //primary turns n2=50; //secondary turns v1=2.4e3; //supply voltage Vp=v1/sqrt(3); //primary phase voltage Vp2=Vp*(n2/n1); //secondary phase voltage Vp...
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clear all t=0:1/120:6 x1=exp(-t).*sin(20*%pi*t)+exp(-t/2).*sin(19*%pi*t) subplot(2,1,1) plot(t,x1) xlabel('t') ylabel('x_1(t)') a=gca(); t2=-4:1/120:4 x2=sinc(t2).*cos(20*%pi*t2) subplot(2,1,2) plot(t2,x2) xlabel('t2') ylabel('x_2(t2)') a=gca();
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//chapter-4,Example4_8,pg 490 //enter binary 1-bit values only printf("RS flip-flop truth table\n") S=input("enter value of S") R=input("enter value of R") Qn=input("Enter previous value of Q") En=input("enter enable value") if En==0 then op=Qn printf("op=%.f",op) else if S==0&R==0 then ...
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eg_12_5.sce
clc; clear; disp("For the 4 state machine M4 in PG 397"); disp("IF the four states A,B,C,D are assigned as 00,01,10,11(ta={(AC)(BD)}) and 00,01,11,10(tb={(AD)(BC)})"); disp("And if the output,next state functions of both the assignments are calculated we can find that "); disp("For first assignment "); disp("Y1=x^y1+x...
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cercle.sce
function C = cercle(x,y,r) // trace un cercle de centre (x,y) et de rayon r cpt1 = 1 cpt2 = 1 D = 2*r step = D/100 for i = x-r:step:x+r ind_i = i/step-(x-r)/step+1 C1(ind_i) = sqrt(r^2-(i-x)^2)+y C2(ind_i) = -sqrt(r^2-(i-x)^2)+y if imag(C1(ind_i)) == 0 then //on slct...
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clc //to calculate energy of a neutron //consider nucleus as a cubical box of size 10^-14m //x=y=z=a=10^-14=l //for neutron to be in the lowest energy state nx=ny=nz=1 //formula is E=(%pi^2*h^2/8*%pi^2*m)*((nx/lx)^2+(ny/ly)^2+(nz/lz)^2) h=6.626*10^-34 //planck's constant in Js m=1.6*10^-27 //mass in kg l=10^-1...
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// File name: projects/01/PriorityEncoder83.tst load PriorityEncoder83.hdl, output-file PriorityEncoder83.out, compare-to PriorityEncoder83.cmp, output-list a%B1.8.1 out%B1.3.1 idle%B1.3.1; // example tst command given set a %B00000000, eval, output; set a %B00000001, eval, output; set a %B00000010,...
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function[z]=fx(x,y) z=((x-1)^2)+((y-1)^2)-x*y endfunction x=[­6:0.1:6]; y=x; w=feval(x,y,fx); plot3d(x,x,w)
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Example2_14.sce
//Example 2.14 clear; clc; //2.14(a) Rs=120; Vref=15; imax=20*10^(-3); Vb=2*Rs*imax; Vtap=Vb/2; Vtapch=0.01*Vtap; v1=Vtap+Vtapch; v2=Vtap-Vtapch; v1ch=v1-v2; i=v1ch/((Rs*Rs)/(Rs+Rs)); R1=(Vtap/i)-630; R2=1000; i3=2*imax+(4.8/R2); R3=(2/i3)+6-0.642857 ; R4=((Vref-(R3...
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// Scilab Code Ex2.11: Page:83 (2011) clc;clear; m0 = 1.67e-27;....// Rest mass,in kg a = 1e-14;....// Size of the box h = 6.63e-34;....// Planck's constant,in J-s n = 1; // Quantum number for lowest energy state E_n = n^2*h^2/(8*m0*a^2); printf("\nThe lowest energy of the neutron confined to the nucleus = %4....
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2_3_5.sce
clc //initialisation of variables F= 100 //tonf p= 2000 //lbf/in^2 x= 12 //in x1= 48 //in p1= 40 //lbf/in^2 //CALCULATIONS A3= (F/p)*2240 A2= A3*x/x1 A1= A2*p/p1 //RESULTS printf (' Piston area= %.f in^2',A2) printf (' \n ram area= %.f in^2',A1)
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6_18.sce
clc //initialisation of variables b1= 3.2 //ft b2= 1.3 //ft h1= 1.86 //ft h2= 1.63 //ft g= 32.2 //ft/sec^2 //CALCULATIONS a1= b1*h1 a2= b2*h2 Q= a1*a2*sqrt(2*g)*sqrt(h1-h2)/(sqrt(a1^2-a2^2)) //RESULTS printf ('Discharge = %.1f cuses ',Q)
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clear clc disp('Ex-14.7'); mpc2=938; //rest energy of proton Q=mpc2+mpc2-(4*mpc2); //Q value of reaction Kth=(-Q)*(6*mpc2/(2*mpc2)); // thershold kinetic energy printf('The threshold kinetic energy is %.2f MeV',Kth);
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motor-system-lecture-frequency.sce
clc; // Simply copy&pasted from professor lol // Motor parameters (change at your will) K = 2; Omega_n = 10; Csi = 0.5; // Transfer function s = poly(0, 's'); G = K / (s^2 / Omega_n^2 + 2 * Csi / Omega_n * s + 1); G = syslin('c', G); Dt = 0.1; t = [0:Dt:10]; // Amplitude: A = 2.5; u = [zeros(1, round(1/Dt)), A * o...
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//example-18.6 //page no-550 //given //resistivity of copper , nickel and silver are rhoCu=0.015*10^-6 //ohm m rhoNi=0.012*10^-6 //ohm m rhoAg=0.016*10^-6 //ohm m //atomic percent of nickle and silver CNi=0.25 CAg=0.40 //the resistivity of Cu-Ni-Ag alloy at 300 K rho=rhoCu+(rhoNi*CNi)+(rhoAg*CAg) //ohm m...
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//Example 8.12.2: the field current,Evaluation of alfa,Evaluation of power factor clc; clear; close; //given data : format('v',7) TL=50;// in N-M N=1000;//in rpm Rf=150;//in ohm Ra=.25;// in ohm Kv=0.7032; alfa=0; Vm=230;// in volts Ef=((Vm*sqrt(2))/%pi)*(1+cosd(alfa)); If=Ef/Rf; disp("part (a)") disp(If,"Field current...
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11_7.sce
//chapter 11 //example 11.7 //page 328 clear all; clc ; //given Rl=40;//load resistance in kohm Vcc=14;//supply voltage V Ve1=5;Vce1=3;Vce2=3; Vc1=Ve1+Vce1; Vb2=Vc1; Ve2=Vb2-0.7; VR5=Vcc-Ve2-Vce2; R5=Rl/10; printf("\nR5=%d kohm,use standard value 3.9 kohm ",R5);R5=3.9; Ic2=1000*VR5/R5; R6=1000*Ve2/Ic2; ...
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//chapter 6 Ex 11 clc; clear; close; n=39; avg39=15;//average of 39 students inc=3/12; //months converted to years avg40=avg39+inc; Sum39=avg39*n; Sum40=avg40*(n+1); teacherAge=Sum40-Sum39; mprintf("The age of teacher is %d years",teacherAge);
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Valaquio_MP2.sce
curDir = get_absolute_file_path('Valaquio_MP2.sce') getd(curDir + '/functions') //============================= Number 1 function item = number1() num = [100.0 154.2349 -12.32157 -(2/3)] for i = 1:1:size(num, 2) disp('=========================='); printf("Input: %f\n\n", num(i)) printf("Double Precision: \n")...
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//Chapter-1,Example1_3_2,pg 1-15 As=28.1 //atomic weight of Si Ag=69.7 //atomic weight of Ga Aa=74.9 //atomic weight of As as=5.43*10^-8 //lattice constant of Si aga=5.65*10^-8 ...
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q03.sce
//solve ODE clc; clear; function t=f(x,y) t=(sin(x) - 2*y*tan(x)); endfunction x0=%pi/3; y0=0; x=%pi; y=ode(y0,x0,x,f) //for graph x=[%pi/2:0.1:2*%pi]; y=ode(y0,x0,x,f); plot2d(x,y); xlabel("X Axis") ylabel("Y Axis") title("Solution to ODE")
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clc //initialisation of variables m=1//kg c=1000 T1=273//k T2=50+273//k l=571700//cal/kg //CALCULATIONS ds=m*c*log(T2/T1)+m*l/T2 //results printf(' difference in entropy = % 1f cal per degree c',ds)
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clc(); clear; //To determine the magnetic field k=1.5; //maximum kinetic energy in MeV m=1.67*10^-27; //mass of proton in kg q=1.6*(10^-19); //charge of particle r=0.35; ...
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clc; V=20; //voltage in Volts R1=2; //resisitance in Ohm R2=4; //resistance in Ohm R3=5; //resistance in Ohm Rp=(1/R1)+(1/R2)+(1/R3); //calculating parallel resistance R=1/Rp; //Parallel disp(R,"(a)Equivalent Resisitance in Ohm = "); //displaying result I1=V/R1; //calculating current through R1 ...
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//Example 7.1(c) clear; clc; fL=0.1; fH=1*10^6; enw=20*10^(-9); fce=200; En=enw*sqrt((fce*log(fH/fL))+fH-fL); printf("Estimated RMS input voltage=%.1f uV",En*10^6);
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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//[r]=%ros(l1,l2) //%ros(l1,l2) correspond a l'operation l1==l2 ou l1 est une fraction // rationnelle et l2 une matrice de scalaire //! r=degree(l1(2))==0&degree(l1(3))==0 if r then r=coeff(l1(2))./coeff(l1(3))==l2,end //end
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// sum 20-6 clc; clear; i=2.5; C=4500; N=960; P=20*10^3; Ks=1.15; Kf=1.10; t=8; //let weight density be w w=0.110*10^5; m=w*t/10^6; Fa=8.75; d=200; D=i*d; u=0.4; V=2*%pi*N*d/(2*60*1000); Pd=P*Ks*Kf; Cp=1; Cv=0.6; //to find b T1=Fa*t*Cp*Cv; Tc=m*V^2/9.81; theta=180-(2*asind((D-d)/(2*C))); theta=...
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function ri = moc_randi (bounds, varargin) // Return random integers in a given range // Calling Sequence // ri = moc_randi(imax) // ri = moc_randi(imax,n) // ri = moc_randi(imax,m,n,...) // ri = moc_randi([imin,imax],...) // Description // Additional arguments determine the shape of the return matrix. When no // argu...
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// Element-wise division of threea vectors function vdiv3(V1, V2, V3) R = (V1 ./ V2) ./ V3; endfunction
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clear ; clc; //Page No. 419 // Example 13.8 printf('Example 13.8\n\n'); // Solution fig E13.8 T1c = 15 ;// Temperature of F & P -[degree C] T1 = 273 + T1c ;// Temperature of F & P -[K] P1 = 105 ;// Pressure of F & P -[kPa] // F analysis F_CO2 = 1.2/100 ;// Volume fraction F_odr = 98.8/100 ;// Volume fraction ...
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disp( 'solving for the congruence equation 8x @ 12(mod28),where @ is the sign for congruence') a =8; b =12; m =28; V= int32([a,m]); d= gcd(V); a1= a/d; b1= b/d; m1= m/d; function yd=f(x) yd=(a1*x)-b1 endfunction disp ('k is the unique solution of the equation') for i=0:m1 x=i; p=f(x); if(modulo(p,m1)==0...
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clc; g=0.003; // gap length wp=0.006; // pole width B=0.8; // flux density in air gap uo=4*%pi*10^-7; // free space permeability // after the derivation of expression fe=(B^2*wp*g)/(2*uo); printf('Force tending to bring electromagnets into axial alignment is %f N',fe);
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clc //initialisation of variables v=20//cu ft a=14.7//ft v1=200//psi t=500//F n=30//cu ft n1=120//psi t1=300//F p=12//cu ft t2=200//F B=1545//F p=538//psia //CALCULATIONS O=144*(a+v1)*v/(B*(t+460))//mol N=144*(a+n1)*n/(B*(t1+460))//mol T=(O+N)*B*(v1+460)/12//lb per sq abs P=p*(O/(O+N))//psia P1=p*(N...
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disp("Vbi=(K*T/q)*log(Na*Nd/ni^2)"); k=0.026; //say a=K*T/q Na=10^16; Nd=10^19; ni=1.5*10^10; Vbi=k*log(Na*Nd/ni^2); printf('\n The value of built-in-voltage is %fV',Vbi); disp("Vp=q*Nd*a^2/(2*Єs)"); q=1.6*10^-19; a=10^-8; b=11.9*8.854*10^-14; //say b=Єs Vp=q*Nd*a^2/(2*b); printf('\n The value of pinch-of...
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clc //initialisation of variables p1=140000//Btu per gal h=0.75//percent p2=40000//Btu per gal h1=4.3//ft h2=0.746//ft p3=1.25//ft f=10//cents a gal //CALCULATIONS H=h1*h2*p3//cents per hr B=p2/(p1*h)*f//cents per lb //RESULTS printf('the cost of operating the heat pump is=% f cents per hr',H) printf('the...
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//Scilab Code for Example 5.1 of Signals and systems by //P.Ramakrishna Rao //Discrete Time Fourier Transform of //x[n]= (a^abs(n)) 0<a<1 clear; clc; close; // DTS Signal a = 0.5; //0<a<1 max_limit = 10; n = -max_limit+1:max_limit-1; x = a^abs(n); // Discrete-time Fourier Transform Wmax = 2*%pi; ...
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//Chapter 12 //page no 486 //given clc; clear all; CSO=-59.8; //in dB y=10^(CSO/10); mprintf("AM modulation depth (m) = %e\n",y); asq=3.6*10^-3; Ncso=50; msq=(y/Ncso/asq/asq); mprintf("\n m^2 = %e\n",msq); printf("\n Decrease of AM modulation depth decrease the CSO distortion by = %0.0f percent",sqrt(msq...
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clc; //ex3.3 Vsrms=25; //volt Vspk=Vsrms/0.707; //volt Vf=0.7; //volt VLpk=Vspk-Vf; //volt disp('V',Vspk,"Vspk="); //The answers vary due to round off error disp('V',VLpk,"VLpk="); //The answers vary due to round off error
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Madrasi paralysis even if rebirth square is occupied +---a---b---c---d---e---f---g---h---+ | | 8 . . . . . . . . 8 | | 7 -P . . . . . . . 7 | | 6 . P . . . . . . 6...
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// Given:- // Analysis // State 1 is the same as in Example 8.3, so h1 = 3348.4 // in kj/kg s1 = 6.6586 // in kj/kg.k // State 2 is fixed by p2  2.0 MPa and the specific entropy s2, ...
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clear clc //initialisation of variables l= 1.5 //miles d= 18 //in Q= 12.4 ///cusecs h= 130 //ft r= 169 r1= 338 w= 62.4 //lb/ft^3 g= 32.2 //ft/sec^2 //CALCULATIONS f= h*10*l^5/(l*5280*Q^2) R= sqrt(1.5*r1-r) d= sqrt(l^2/R*144) v= sqrt(h*g*2/(r/R^2+1)) HP= w*0.25*%pi*(d/12)^2*v^3/(550*2*g) //RESULTS prin...
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//bin aufgabe 3 T = 2; t = linspace(0,2*T); a0 = 1; w = 2*%pi/T; p = a0/2; for k = 1:10 p = p + ((1-(-1)^k)/k)*cos(k*w*t) end figure(1); clf(); subplot(2,2,1); plot(t, p, 'black') for k= 1:10 a(k) = sum((1-(-1)^k)/k); b(k) = sum(1/k^2); end c = [a0/2;(a - %i*b)/2]; s...
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//i/p args contain negative values k=[0 0 0 0 0]; v=[0 0 0 0 0]; [num,den] = latc2tf(k,v); disp(num); disp(den); //output // 0. 0. 0. 0. 0. 0. // // 1. 0. 0. 0. 0. 0. //
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g= 9.80665 Ixx = 0.082 Iyy = 0.083 Izz = 0.062 Ixz = 0.000 mass = 0.712 l = 0.137 den = (Ixx*Izz - Ixz^2) ApL = Izz/den ApN = Ixz/den AqM = 1/Iyy ArL = Ixz/den ArN = Ixx/den K1 = 3.321*g K2 = 3.426*g K3 = 3.622*g K4 = 3.454*g KT1 = 0.06329 KT2 = 0.04349 KT3 = 0.02104 KT4 = 0.05735 B31 = -K1/mass B32 = -K2/mass B...
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clc; clear all; disp("Critical radius of insulation") k=0.155;// W/(m*C) t1=65;//degree C tair=20;//degree C r1=10/2;//mm ho=8.5;// W/(m^2*K) rc=1000*k/ho;//mm t=rc-r1; disp("mm",rc,"critical radius of insulation =") disp("mm",t,"thickness upto which rubber insulation is effective in heat dissipation t =") ...
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// Scilab Code Ex9.10: Page-467 (2011) clc;clear; mu1 = 1.52;....// Refractive index of core a = 14.5e-006;....// Radius of the fibre core, m del = 0.0007;....// Fractional index difference lambda = 1.3e-006;....// Operating wavelength of optical fibre, m mu2 = mu1*(1-del); // Refractive index of cladding v...
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//Chapter 3, Prblem 18, clc funcprot(0) // A = p2z(R,Theta) - Convert from polar to rectangular form. // R is a matrix containing the magnitudes // Theta is a matrix containing the phase angles (in degrees). function [A] = p2z(R,Theta) A = R*exp(%i*%pi*Theta/180); endfunction // [R1, Theta1] = z2p(A1)...
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function rtheta=CartToCyl(xy) // Cartésiennes à polaires theta = atan(xy(2), xy(1)) r = norm(xy) rtheta = [r, theta] endfunction function xy=CylToCart(rtheta) // Polaires à cartésiennes x = rtheta(1)*cos(rtheta(2)) y = rtheta(1)*sin(rtheta(2)) xy = [x, y] endfunction
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clc // one value of e is done Gs=2.75 A=30.68 Ms=128 p=1 Hs=Ms/(A*Gs*p) H=2.540 Hv=H-Hs e=Hv/Hs printf('the value of e for give values = %f',e)
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-- VectorCAST 21.sp3 (08/04/21) -- Test Case Script -- -- Environment : TEMPLATE_EXAMPLE -- Unit(s) Under Test: manager -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:REMOVED_CL_PREFIX TEST.S...
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//water// //page 1.87 example 1// clc W1=7.3;//Mg(HCO3)2 in water in mg/L// W2=9.5;//MgCl2 in water in mg/L// W3=16.2;//Ca(HCO3)2 in water in mg/L// W4=13.6;//CaSO4 in water in mg/L// M1=100/146;//multiplication factor of Mg(HCO3)2// M2=100/95;//multiplication factor of MgCl2// M3=100/162;//multiplication fact...
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i=5*10^(-3); v=12; r=v/i; disp("the resistance value (in kΩ) is"); disp(r*10^(-3));
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// Scilab code Ex1.6: Pg 25 (2005) clc; clear; // For simplification assume velocity of light equal to unity c = 1 // Velocity of light, m/s lamda_obs = 474e-09; // Wavelength measured by observer, m lamda_source = 394e-09; // Wavelength measured in the source's rest frame, m v = (...
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clc H=0.07; // average head rate=-0.02/600; // (dH/dt) H1=0.08; // m H2=0.01; // m k=-rate/H^(3/2); t=integrate('-1/k*H^(-3/2)', 'H', H1, H2); disp("Time taken =") disp(t) disp("s")
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//Example 3.3 clc s=%s; syms t; xs=2/(s*(s^2+2*s+2)); disp(xs,'x(s)=') [A]=pfss(xs) F1=ilaplace(A(1),s,t); F2=ilaplace(A(2),s,t); xt=F1+F2; disp(xt,'x(t)=')
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function[fx] = fungsiNormal(mu,sigma,x) konst = 1 / (sigma * sqrt(2 * %pi)) fx = konst * exp(-0.5 * (((x-mu)/sigma)^2)) endfunction function[P_Normal] = PNormal(mu,sigma,a,b) n = 1000 h = (b-a) / n fa = fungsiNormal(mu,sigma,a) fb = fungsiNormal(mu,sigma,b) jum = 0 for i = 1 : (n-1) a = a + h fa1n = fungsiNor...
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'successful test OPEN "B", #1, "mouse.dll" FOR i = 1 TO LOF(1) SEEK #1, i k$ = INPUT$(1, #1) mouse$ = mouse$ + k$ NEXT CLOSE #1 DEF SEG = VARSEG(mouse$) a% = SADD(mouse$) CALL absolute(a%) DEF SEG = &H100 PRINT PEEK(0), PEEK(1)
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//function// A=[-2 1;0 -3] B=[4;1] C=[1 0] [O]=obsv_mat(A,C); disp(O,"Observability Matrix=") //To Check Whether the matrix(Cc)is singular i.e determint of Cc=0 if determ(O)==0; printf("Since the matrix is Singular, the system is not Observable \n"); else; printf("The system is Observable \n") end;
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clear ; clc; // Example 25.2 printf('Example 25.2\n\n'); //page no. 767 // Solution // Given // The main reaction is (1/2)*H2(g) +(1/2)* Cl2(g) --> HCl(g) (A) // Look in Appendix F for heat of formation of H2 ,Cl2 and HCl H_H2 = 0 ;// Standard heat of formation of H2 -[kJ/ g mol H2] ...
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clear; clc; V=400; V_ph=V/sqrt(3); N_s=1000; N=800; a=.7; I_d=110; R=2; k=1-((1-N/N_s)*(2.339*a*V_ph)/(I_d*R)); printf("value of duty cycle=%.3f",k); P=I_d^2*R*(1-k); I1=a*I_d*sqrt(2/3); r1=.1; r2=.08; Pr=3*I1^2*(r1+r2); P_o=20000; P_i=P_o+Pr+P; eff=P_o/P_i*100; printf("\nefficiency=%.2f",eff); ...
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clc(); clear; // To study the effect of adding fins to the cylindrical barrel of an air cooled engine l1= 3/12; // Length of fins in ft l2 = 4/12; h = 50; // Heat transfer coefficient in Btu/hr-ft-F k = 28; ...