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// Example 18.13, page no-467 clear clc c=2*10^-6//F v=1000//V epsr=100 E=(c*v^2)/2 c0=c/epsr e2=(c0*v^2)/2 E1=E-e2 printf("The energy stored in dielectric is %.2f J",E1)
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//Example 16.1 //Outline of Linear Shooting Method //Page no. 572 clc;close;clear; deff('y=f(x)','y=x^2'); h=0.5;X0=0;Y0=1;Z1=[-1,-1.5,-1.1771];i=1;Y1=Y0; for j=1:3 Z0=Z1(i); i=i+1 Y0=1; for n=1:2 printf('\nFor n = %i\n---------------------------\n',n-1) K1(1)=h*Z0; ...
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clc // Given that E = 5.4e6 // energy liberates during dynamite explosion in J/kg c = 3e8 // velocity of photon in meter/sec // Sample Problem 38 on page no. 11.32 printf("\n # PROBLEM 38 # \n") printf(" Standard formula used \n") printf(" E = m*c^2 \n ") E_ = 1 * c^2 // energy liberated by 1 kg content in J f = E / E...
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function [sos,varargout] = tf2sos (b, a) //This function converts direct-form filter coefficients to series second-order sections. //Calling Sequence //[sos] = tf2sos (b, a) //[sos, g] = tf2sos (b, a) //Parameters //b: matrix of real numbers //a: matrix of real numbers //Description //This is an Octave function. //Th...
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// Measure running time of Mult.asm load Mult.asm, output-file MultTime.out, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2 time%S1.5.1; set RAM[0] 2, set RAM[1] 3, set RAM[2] -1; while RAM[2] <> 6 { ticktock; } output; set PC 0, set RAM[0] 17, set RAM[1] 123, set RAM[2] -1; while RAM[2] <...
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function [x,y,typ]=sftreg(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then //** GET INPUTS [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case ...
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PL/SQL Developer Test script 3.0 20 -- Created on 30.06.2018 by V.ZHURAVOV declare -- Local variables here i integer; begin -- Test statements here pdb_pub.unfreeze_(p_pdb_name => 'DEV_CLONE'); pdb_pub.unfreeze_(p_pdb_name => 'DEV'); pdb_pub.unfreeze_(p_pdb_name => 'WEEKLY_NODE'); pdb_pub.open_ro_(p_...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.48(PAGENO 264)"); //given delta_f = 75*10^3//frequency deviation f_M = 15*10^3//modulating frequency //calculations //we have w_m = 2*%pi*f_M where f_M = 15KHz,we get D = delta_f/f_M...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 16") To=(17+273);//temperature of surrounding in K T1=(700+273);//temperature of high temperature reservoir in K T2=(30+273);//temperature of low tempe...
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//Example 4.15. clc format(6) disp("For a Wien bridge oscillator,") disp(" f = 1 / 2*pi*R*C") fm=(1/(2*%pi*(100*10^3)*(50*10^-12)))*10^-3 // in kHz disp(fm,"Therefore, f_max(in kHz) =") fmi=(1/(2*%pi*(100*10^3)*(500*10^-12)))*10^-3 disp(fmi,"and f_min(in kHz) =") fn=31.83+50 disp(fn,"Now f_new(in kHz) = ...
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// Function Name: min/max // Return min/max value // Calculating the min/max inputvec1 = [1, 2, 3]; result = armaVec("min",inputvec1) result = armaVec("max",inputvec1)
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//Attitude Definition and Beta Angle // Authours: Matthieu D. Jessie A. Arvin T. clear; clc; clf; // Remove at implementation function [outx, outy, outz] = xRot(vec,theta) R1 = [1,0,0;0,cos(theta),sin(theta);0,-sin(theta),cos(theta)]; out = vec*R1; outx = out(1); outy = out(2); outz = out(3); endfunction fu...
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// Chapter 4 Additional Example 8 //============================================================================== clc; clear; // input data h = 6.625*10^-34 // plancks constant m = 9.11*10^-31 // mass of electron in Kg c = 3*10^8; // velocity of light in m/s // Calcu...
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# Depeopanizer test (from old Hysim manual) units Field $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + Methane Ethane PROPANE thermo + ISOBUTANE n-BUTANE ISOPENTANE n-PENTANE n-Hexane thermo + n-Heptane n-Octane deprop = Tower.Tower() deprop.Stage_0 + 9 # eleven stages` cd deprop.Stage_0 ...
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N=32 Rkm=1.6 Acell=(3*sqrt(3)/2)*(Rkm^2) TA=N*Acell//total service area Tc=336 n=7 Ncpc=Tc/n//number of channels per cell TSC=Ncpc*N//total sysytem capacity N1=128 Ahex=TA/N1 R=sqrt(Ahex/(1.5*sqrt(2))) NCap=Ncpc*N1 disp(TA,'total service area in kmsqr') disp(Ncpc,'number of channels per cell') disp(TSC,'total sysytem c...
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//Variable declaration A=360*10**-4; //area(m**2) V=15; //voltage(V) C=6*10**-6; //capacitance(farad) epsilonr=8; epsilon0=8.84*10**-12; //Calculation E=V*C/(epsilon0*epsilonr*A); //field strength(V/m) dm=epsilon0*(epsilonr-1)*V*A; //total dipole moment(Cm) //Result printf('field strength...
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//Reference: K. Deep et al.,"A real coded genetic algorithm for solving integer and mixed integer optimization problems", Applied Mathematics and Computation, 212, p 505-518,2009 //===================================================================== // Copyright (C) 2018 - IIT Bombay - FOSSEE // This file must be used...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 2, Example 11") D2= 0.37;//in meters N= 800;//in rpm Q= 0.03; Hgiven = 14; disp("Impeller tip Speed U2 in m/s is :") U2 = %pi *D2*N...
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//example1.6 clc disp("The current distribution using KCL is as shown,") disp("Key Point : KVL should not be applied to the loop consisting current source.") disp("From branch DE,") disp("(i1)=5+3(i2) ...(1)") disp("Applying KVL to the loop BCDEFGB without current source,") disp("-1*(5+3(i2))+5(i2)=0 ...(2)"...
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// Exa 7.6 clc; clear; close; format('v',6) // Given data V_DD = 40;// in V Vt = 5;// in V R_D= 820;// in ohm I_Don = 3;// in mA I_Don = I_Don * 10^-3;// in A V_GSon = 10;// in V K = I_Don/( (V_GSon-Vt)^2 );// in A/V^2 R2 = 18;// in Mohm R2 = R2 * 10^6;// in ohm R1 = 22;// in Mohm R1 = R1 * 10^6;// in ...
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//find.. clc //soltuion //given b=0.100//m t=0.01//m v=16.67//m/s //T1-T2=1.8 *T2 f=1.6//N/mm^2 rho=1000//kg/m^3 //let T1 and T2 be tneion on tight and slag side T=f*b*t*10^6//N//max tension m=0.1*0.01*1000//kg/m Tc=m*v^2//N T1=T-Tc//N T2=T1/2.8//N P=(T1-T2)*v printf("the power transmitted is,%f W\n",...
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//Ex19_9 Pg-960 clc disp("Conversion of decimal number 31.65 base to its binary equivalent ") a=31.65; z=modulo(a,1) x=floor(a);//separating the decimal from the integer part b=0; c=0; d=0; while(x>0) //taking integer part into a matrix and convert to equivalent binary y=modulo(x,2); b=b+(10^c)*y; x=x/2; x=floor(x); c...
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// Scilab code Ex12.3: Pg:467 (2008) clc;clear; n1 = 1.45; // Core refractive index of an fibre d = 0.6; // Core diameter of fiber, m NA = 0.16; // Numerical aperture of fiber lambda_0 = 9e-007; // Wavelength of light, m V = %pi*d*NA/lambda_0; // Normalized frequency (V-number)for the fiber print...
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clc; clear; //Example 3.48 rho=960 //[kh/m^3] mu=2.82*10^-4 //[kg/(m.s)] k=0.68 //[W/(m.K)] lambda=2255 //[kJ/kg] lambda=lambda*10^3 //[J/kg] Ts=373 //Saturation temperature of steam [K] Tw=371 //[K] dT=Ts-Tw //[K] L=0.3 //Dimension [m] g=9.81 //[m/s^2] h=0.943*(rho^2*g*lambda*k^3/(L*mu*dT))^(1...
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// determine head and power output if angular velocity from fig2= // ex 6.2 pgno.142 clc r1=300 // mm inlet radius r2=150 //mm outer radius Q=0.05 // m3/s flow rate a1=30 //degree inlet guide blade a2=80// degree angle v1=6 // m/s velocity v2=3//m/s velocity t=25 // angular velocity n=0.9 n1=0.8 g=9.8 ...
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// Csae study: Chapter-8, Page No:253 // 2.Processing of a customer list CUSTOMERS=10; printf(" Input names and telephone numbers\n"); printf(" [Names must have First,Second and Last_name]\n"); for i=1:CUSTOMERS //Read data [first_name(i),second_name(i),surname(i),...
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clc //to calculate de Broglie wavelength V=100 //potential difference in volts lambda=12.25/sqrt(V) disp("de Broglie wavelength of any electron is lambda="+string(lambda)+"angstrom")
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clc //Given that F = [2.5,4.5,-5] // F is a force vector act through origin // sample Problem 1 Page No. 176 printf("\n\n\n # Problem 1 # \n") F_magnitude = sqrt ( 2.5^2 + 4.5^2 + (-5)^2) theta_x = (180 / %pi ) * acos ( 2.5 / F_magnitude) theta_y = (180 / %pi ) * acos ( 4.5 / F_magnitude) theta_z = (180 / %pi ...
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//Caption: Completely Randomized Design //Example4.1 //Page75 clear; clc; A1 = 23; A2 = 34; A3 = 45; A4 = 34; B1 = 30; B2 = 20; B3 = 30; B4 = 20; C1 = 35; C2 = 29; C3 = 25; C4 = 45; D1 = 28; D2 = 40; D3 = 40; D4 = 34; Yij = [A1,B1,C1,D1;A2,B2,C2,D2;A3,B3,C3,D3;A4,B4,C4,D4]; disp(Yij,'Yij=') [m,n]...
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//Initilization of variables A=80 //lb B=40 //lb C=60 //lb l1=2 //in l2=4 //in l3=6 //in l4=9 //in l5=3 //in l6=7 //in //Calculations P=-(-A*l1+B*l2-C*l2)/l1 By=-(A*l3+P*l3)/l4 Ay=(-A*l5-P*l5)/l4 Bz=-(-C*l1-B*l1)/l4 Az=(C*l6+B*l6)/l4 //Result clc printf('The forces are Ay=%flb By=%flb Az=%flb Bz=%flb'...
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clear // // // //Variable declaration El=10**-2*50 //energy loss(J) H=El*60 //heat produced(J) d=7.7*10**3 //iron rod(kg/m**3) s=0.462*10**-3 //specific heat(J/kg K) //Calculation theta=H/(d*s) //temperature rise(K) //Result printf("\n temperature rise is %0.2f K",theta)
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// Scilab Code Ex1.19: Page-1.19 (2009) clc; clear; m = 9.1e-031; // Mass of the electron, kg h = 6.6e-034; // Planck's constant e = 1.6e-019; // Energy equivalent of 1 eV, J/eV lambda = 9.1e-012; // de-Broglie wavelength of electron, m // We have lambda = h/(m*v), solving for v v = h/(m*lambda); // ...
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//Chapter 3 //Example 3_1 //Page 50 clear;clc; max_dem=100; lf=0.4; //energy generated printf("Energy generated per annum = %.1f kWh\n\n", max_dem*lf*8760*1000);
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// Book - Power System: Analysis & Design 5th Edition // Authors - J. Duncan Glover, Mulukutla S. Sharma, Thomas J. Overbye // Chapter - 5 : Example 5.7 // Scilab Version 6.0.0 : OS - Windows clc; clear; p = 9000; // Power in MW l = 500; ...
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// Ex4_1 clc; //Given: t1=1600;// in year a=11.6*10^17;// atoms // Solution: k=0.693/t1;// year^-1 L=(a*226)/k;// atomic mass of Radon is 226 printf("The value of avagadro constant is = %f atoms per mole",L)
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//Initilization of variables s=4 //m length of sides l=2 //kN load acting on each node r=7 //kN by inspection reaction at A //Calculation //Taking Moment about point G FH=(-r*12+2*10+2*6+2*2)/(2*tand(60)) //kN Compressive //Taking moment about point H GI=(r*14-2*12-2*8-2*4)/(2*tand(30)) //kN Tension //Summing ...
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#************************************************************ # Scenario of Test # # date : Wed Oct 29 12:02:15 2008 #************************************************************ p3d_sel_desc_name P3D_ENV Test p3d_sel_desc_name P3D_ROBOT superman p3d_set_robot_current 0.000000 0.000000 0.000000 0.000000 0.000000 0....
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a b b a א ב א a b d o u l a y e ע ב ד ו ל א י a b r a j א ב ר א ג ' a c u t i f o l i a א ק י ו ט י פ ו ל י א a d a n א ד ן a d i ע ד י a d i d a s א ד י ד ס a d y g e a א ד י ג י א a e r o f l o t א י ר ו פ ל ו ט a k k a d ע ק א ד a l a b a m a א ל א ב א מ א a l a h r a m א ל א ה ר א ם a l b a h r i א ל ב ח ר י a l e ...
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//Chapter-17,Example 9,Page 372 clc(); close(); m1 = 146 //mass of Mg(HCO3)2 m2 = 162 //mass of Ca(HCO3)2 m3 = 111 //mass of CaCl2 m4 = 120 //mass of MgSO4 m5 = 136 //mass of CaSO4 amnt_1 = 12.5 //amount of Mg(HCO3)2 in ppm amnt_2 = 10.5 //amount of Ca(HCO3)2 in ppm amnt...
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//program to generate a PSK modulated waveform function []=PSKmod(data,fc,Ac) t=0:0.001:1 x=Ac*sin(2*%pi*fc*t) y=Ac*sin(2*%pi*fc*t+%pi) z=data mods=[] for i=1:length(data) if(z(i)==1) then mods=[mods,x] else mods=[mods,y] end end ...
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clear //Given Vp=220.0 //V Is=5 //A n=20 //Calculation Vs=Vp*n Ip=(Vs*Is)/Vp P=Vs*Is //Result printf("\n (i) Voltage across secondary is %0.3f V",Vs) printf("\n (ii) The current in primary is %0.3f A",Ip) printf("\n (iii) The power output is %0.3f K W",P*10**-3...
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//程式L2_2.m: 矩陣的直積% A=[1 1;-1 1]; B=[1 2;3 4]; A1=A'; B1=B'; //將矩陣轉置 A2=inv(A); B2=inv(B); //求反矩陣 kron1=kron(A,B); //求右直接乘積 kron2=kron(A1,B1); kron3=kron(A2,B2); kron_left=kron1'; kron_right=kron2; invert_left=inv(kron1); invert_right=kron3; kron_left kron_right invert_left invert_right y...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.246897D+00 ...
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//Example 24.6. perform the binary divisions clc x=bin2dec('110') x1=bin2dec('10') x2=x/x1 x3=dec2bin(x2) disp("(i) 110 / 10") disp(x3," = binary") disp(x2," = decimal") x=bin2dec('1111') x1=bin2dec('110') x2=x/x1 x3=dec2bin(int(x2)); disp("(ii) 1111 / 110") disp(x3," = binary") disp(x2," = decimal")
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//(10.4) Air enters the compressor of an ideal Brayton refrigeration cycle at 1 bar, 270K, with a volumetric flow rate of 1.4 m3/s. If the compressor pressure ratio is 3 and the turbine inlet temperature is 300K, determine (a) the net power input, in kW, (b) the refrigeration capacity, in kW, (c) the coefficient of...
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clc; B=1.6; // flux density between magnetic surfaces a=1; // area of magnetic surfaces uo=4*%pi*10^-7; // free space permeability f=(B^2*a)/(2*uo); printf('Force between two magnetic surfaces is %f N',f);
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// Exa 6.4 clc; clear; close; // Given data R1= 200;// in kohm R1=R1*10^3;// in ohm R2=R1;// in ohm C1= 200;// in pF C1= C1*10^-12;// in F C2=C1;// in F f= 1/(2*%pi*R1*C1);// in Hz disp(f*10^-3,"Frequency of oscilltions in kHz is : ") // Note: Calculation to find the value of f in the book is wrong, so a...
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// to determine the starting torque developed clc; P=180000; V=600; Ia=P/V; Ra=.105; Ea=V-Ia*Ra; n=600; nn=500; Eaa=Ea*nn/n; Iaa=282; //from magnetising curve Iad=Ia-Iaa; Ias=500; //at start k=Iad/Ia^2; Iae=Ias-Iad*k; Eas=590; //from magnetising curve Ts=Eas*Ias/(2*%pi*nn/60);disp(Ts,'T_start(N...
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clc //initialisation of variables h= 2.5 //ft a= 45 //degrees x= 5 //ft Q= 45 //cuses v= 2.6 //ft/sec w= 6.92 //ft C= 120 //CALCULATIONS b= (Q/(v*h))-h p= b+2*(h+sqrt(2)) A= h*w m= A/p i= (v/(C*sqrt(m)))^2 //RESULTS printf ('Width = %.2f ft',b) printf ('\n Slope = %.6f ',i)
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clc;funcprot(0);//EXAMPLE 5.1 // Initialisation of Variables d=10.2;............//Engine bore in cm spo=0.6;............//Spark plug offset in cm vf=15.8;............//Average flame speed in m/s thetas=20;.............//The angle of the crank when spark plug is fired theta=6.5;..........//Angle by which the Engin...
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function [] = microdaq_setup() SETUP_PATH = mdaq_toolbox_path()+'macros'+filesep()+'microdaq_setup_template.sce'; exec(SETUP_PATH,-1); while STATE if findobj('Tag','edit1') == [] then global STATE STATE = 0 sleep(500) end end endfunction
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clc disp("Example 5.65") printf("\n") disp("calculate the Series & parallel resonant frequencies of Crystal") printf("Given\n") //indutance L=3 //Capacitor due to mechanical mounting of crystal Cm=10*10^-12 //electrical equivalent capacitance of crystal compliance Cs=0.05*10^-12 //electrical equivalent resis...
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// Theory and Problems of Thermodynamics // Chapter 12 // Statistical Thermodynamics // Example 6 clear ;clc; //Given data T = 300 // temperature of particles E = 300 // activation energy e1 = 3*E // permissible energy levels e2 = 6*E // permiss...
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clear clc //Example 9.5 TURBULENT BOUNDARY-LAYER PROPERTIES to=0.896; //[lbf/ft^3] rho=1.94; //[slugs/ft^3] uo=sqrt(to/rho) //shear velocity [ft/s] //Logarithmic velocity distribution y=0.0088; //[ft] v=1.22*10^-5; //[ft^2/s] uL=uo*(2.44*log(y*uo/v)+5.56) //velocity of water [ft/s] delta=0.088; //[ft] yn...
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// given 6 samples (c.q. approximations) of a parabola // determine the parameters of the best fitting parabola // i.e. a, b, and c in y = ax^2 + bx + c // using gradient descent // e.g. y=x^2-4x+3 xx = [-1.0, 0.1, 1.1, 1.9, 2.9, 4.1]; yy = [ 8.5, 2.5, -0.2, -0.7, -0.1, 3.2]; function [a, b, c] = update_one_step...
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*Testcase KIMD fc0 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000000 # LA R0,0 R0->function code 0 r 204=4110f500 # LA R1,PB R1->parameter block r 208=41200000 # LA R2,SO R2...
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//Example 2.13 //To determine area of triangle when 2 sides and an angle is given clc,clear c=7 //side oposite to vertex C A=33 //angle at vertex A b=5 //side opposite to vertex B area_K = b*c*sind(A)/2 printf('Area of triangle ABC = %.2f square units',area_K)
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// Scilab Code Ex 10.4 Degeneracy of Energy Level: Page-332 (2010) // Function to find the factorial of a number function[f] = fact(num) f = 1; for i = 1:1:num f = f*i; end endfunction // Fucntion to determine degenerate energy states function[degstates] = degno(a, b, c)// degno takes thr...
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errcatch(-1,"stop");mode(2);//Ex:9.1 ; ; C=10*10^-9; R=10000; f=(1/(2*%pi*sqrt (6)*C*R)); printf("The freq of oscillation = %f Hz",f); exit();
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function hasil=langrange(x,fx,xtaksir); i=0;j=0;L=0; [n,m]=size(x); [ny,my]=size(fx); pi=1; for i=1:m pi=1; for j=1:m if i<> j then pi=pi*( (xtaksir-x(1,j)) / (x(1,i)-x(1,j)) ); disp(pi); end,//end if end,//endfo...
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// A program to directly writing and reading a matrix to/from a file. A = rand (4,3); fprintfMat ("MatrixA.txt", A, "%lg"); B = fscanfMat ("MatrixA.txt", "%lg"); disp(B);
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clc L=335; //kJ/kg h3=1319.22; //kJ/kg h1=100.04; //kJ/kg h4=h1; s_f2=-2.1338; //kJ/kg K s_g2=5.0585; //kJ/kg K s_g3=4.4852; //kJ/kg K h_f2=-54.56; //kJ/kg h_g2=1304.99; //kJ/kg x2=(s_g3-s_f2)/(s_g2-s_f2); h2=h_f2+x2*(h_g2-h_f2); COP_theoritical=(h2-h1)/(h3-h2); COP_actual=0.62*COP_theoritical; RE=COP...
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//chapter 1 //example 1.3 //calculate potential energy //page 15 clear; clc; //given r=2; //in angstrom(distance) e=1.6E-19; // in C (charge of electron) E_o= 8.85E-12;// absolute premittivity //calculate r=2*1E-10; // since r is in angstrom V=-e^2/(4*%pi*E_o*r); // calculate potential printf('\nThe potent...
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clc clear //Initialization of variables k=1.4 R=53.3 //lb-ft/lb R pe=14.7 //psia p0=114.7 //psia T0=524.6 //R g=32.2 //ft/s^2 d=0.5 //in Nm1=1 //calculations pr=pe/p0 Nme=sqrt(2/(k-1) *((1/pr)^((k-1)/k) -1)) Te=T0/(1+ (k-1)/2 *Nme^2) Ve=Nme*sqrt(k*g*R*Te) At=%pi/4 *(d)^2 Ae=Nm1/Nme *((1+ (k-1)/2 *Nme^2...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-3, Illustration 2, Page 54 //Title: Calculation of weight //=======================================================================...
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//Problem 21.21: A 200 V, d.c. shunt-wound motor has an armature resistance of 0.4 ohm and at a certain load has an armature current of 30 A and runs at 1350 rev/min. If the load on the shaft of the motor is increased so that the armature current increases to 45 A, determine the speed of the motor, assuming the flux r...
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clear // //case a //rab=(80+40)||(60+40) rab=(120*100)/(120+100) printf("\n rab= %0.1f ohm",rab) //rab=(80||60)+(40||40) rab=(4800/(140))+(1600/80) printf("\n rab= %0.1f ohm",rab) //case b //(60+80)||(40+40) rcd=(140*80)/(140+80) printf("\n rcd= %0.1f ohm",rcd) //(60||40)+(80||40) rab=(2400/(100))+(3200/(120)) print...
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//check o/p when the i/p is a null vector x=[0 0 0 0 0]; t=1:length(x); s=slewrate(x, t); disp(s) //output // []
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// Scilab code Ex4.34: : Pg:188 (2008) clc;clear; Lambda = 5896e-08; // Wavelength of light, cm d = 0.3; // Path difference between the M1 and M2 mirrors, cm r = 0; // For central bright fringe // Since 2*d*cos(r) = n*Lambda and for r = 0 which gives 2*d = n*Lambda // 2*d*cos_theta = (n-6)*Lambda, solvin...
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function s1=%lss_a_p(s1,d2) //s=%lss_a_p(s1,d2) iff // s=s1+d2 //! // Copyright INRIA s1(5)=s1(5)+d2
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// Example 7.7 clear all; clc; // Given data H = 70; // Height of the cylinder in cm R = H/2; // Diameter of the cylinder in cm a = 1.9; // Radius of black control rod in cm // From Table 6.2, Buckli...
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clc; disp("Example 3.9") d= 0.005 // diameter in metres density= 900 // in kg/m^3 mew=0.5 // kg/ms Q=5e-6 // flow rate in m^3/sec U= (4*Q)/(%pi*d*d) // volumetric flow rate per area of cross section Re= d*U*density/mew disp(" The Reynolds number is ") disp(Re) disp(" . Hence we can apply hagen poiseull...
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//Ex1_14 clc; //Given: H1=241.8; // in KJ/mol H2=887.2; // in KJ/mol // 1 KJ/mol = 0.0104 eV/atom //solution: part (a) e1=H1*0.0104; printf("\n The energy release in part (a) in eV/molecule is = %f ",e1) //solution: part (b) e2=H2*0.0104; printf("\n The energy release in part (b) in eV/molecule is ...
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clc; clear; format('e',11); w=2*%pi*10^9; c=3*10^8; //c=velocity of wave in air. k=w/c; disp(k,"The propagation constant,k(in rad/m)=");
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// Example 5.2: resistance clc, clear // given : l=1; // length in m A=4*10^-4; // area of cross section in m^2 p=0.01*10^-2; // resistivity in ohm-m R=p*(l/A); disp(R,"resistance of wire,R(ohm) = ")
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 6 : SYNCHRONOUS MACHINES // EXAMPLE : 6.5a clear ; clc ; close ; // Clear the work space and console // GIVEN DATA printf("\n EXAMPLE : 6.5a( Data is same as Example 6.4): \n\n ...
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clc m=2.5; //kg p1=6*10^5; //Pa r=2; //r=V2/V1 cv=0.718; //kJ/kg K R=0.287; //kJ/kg K T1=363; //K p2=1*10^5; //Pa T2=278; //K V1=m*R*T1/p1; V2=2*V1; T0=278; //K p0=1*10^5; //Pa Q=0; //adiabatic process disp("(i)The maximum work") dS=m*cv*log(T2/T1) + m*R*log(V2/V1); Wmax=m*[cv*(T1-T2)] + T0*(cv*log(T2...
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clc pathname=get_absolute_file_path('3_3_1.sce') filename=pathname+filesep()+'331.sci' exec(filename) moles=mass/M printf("\n no.of moles=%f",moles) lbmole=moles/453.6 printf("\n no.of lb moles=%f",lbmole) Cmoles=moles printf("\n no.of moles of carbon=%f",Cmoles) Omoles=2*moles printf("\n no.of moles of oxyg...
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let seq = (Seq [(Input ("X")), (Empty ("P")), (Loop (OR (Gt (Var "X") (Const 0)) (Eq (Var "X") (Const 0))) (Seq [(Input ("Y")), (Push ("P") (Var "Y")), (Assign ("X") (Minus (Var "X") (Const 1)))])), (Assign ("S") (Const 0)), (Size ("P") ("L")), (Loop (Gt (Var "L") (Const 0)) (Seq [(Pop ("P") ("Y")), (Assign ("S") (Plus...
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clc //initialisation Rt=13.3//ohms R100=7.0//ohms R0=5.0//ohms t=444.6//celsius RT=9.1//ohms //CALCULATIONS tp=(Rt-R0)*100/(R100-R0) Tp=(RT-R0)*100/(R100-R0) s=(t-tp)*10000/(t*(t-100)) T=Tp+((s*(Tp*(Tp-100)))/10000) Ts=Tp+((s*T*(T-100))/10000) //results printf(' platinum temperature of bath= % 2f C',T) p...
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//Example6_41 // To find the value of resistance R1 for instrumentation amplifier clc; clear; close; A =100 ; R2 = 450*10^3 ; R3 = 1*10^3 ; R4 = 1*10^3 ; // The gain of differential amplifier // A = (R4/R3)*(1+(2R2/R1)) ; //but R3 = R4 then // A = 1+(2R2/R1) ; R1 = 2*R2/(A-1); disp('The value of resi...
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//To convert velocity m/s from km/h conv = 5/18 //Given that v_BA = 52 //in km/hr v_PA = -78 //in km/hr //Sample Problem 4-10a printf("**Sample Problem 4-10a**\n") //using concept of relative velocity v_PB = v_PA - v_BA printf("The velocity of P as measured by Barbara is %d km/hr\n",v_PB) //Sample Pr...
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exec('plates.sci') // Una función que crea la matriz P de orden 6 function [P] = PMatrix() ORDER = 6 // La misma matriz que en el ejercicio e [N, b] = plates(6, 1.25, 1.2) // Resultado P = zeros(ORDER, ORDER) for i = 1:ORDER for j = 1:ORDER if( i == j) P(i,j) = N(i,j) - i*j else P(i,j) = N(7-...
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clc disp("Example 12.4") printf("\n") disp("Continued from Example 12.3") Vmax=120*sqrt(2) Zmag=20;Zph=-30; //Let the line to neutral voltage magnitude be VLN VLN=Vmax/sqrt(3) //From figure 12.14 ILmag=VLN/Zmag ILph=0-Zph printf("\nIL=%3.2f(%d deg)\n",ILmag,ILph); //From fig 12.7(b) //VAN=Vn(-90 deg)...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 5 Example # 5.6 "); //''RPM of shaft'' N = 3; //''Angular velocity, omega=2*pi*N/60 in rad/s'' omega = 0.31; //''Ambient temp in degree C'...
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//Exa 7.4 clc; clear; close; //given data : f=3000;//in MHz f=f*10^6;//in Hz d=20;//in feet d=20*0.3048;//in meter c=3*10^8;//in m/s lambda=c/f;//in meters r=2*d^2/lambda;//in meters disp(r,"Minimum distance between primary and secondary in meters : ");
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.261326D+00 ...
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clear ; clc; // Example 9.9 printf('Example 9.9\n\n'); printf('Page No. 277\n\n'); //given A = 15;// glazing area in m^2 l = 10;// Length of office in m h = 6;// height of office in m w = 3.5;// width of office in m Y_w = 4;// Admittance of wall in W/m^2-K Y_f = 3;// Admittance of floor in W/m^2-K Y_c = 3...
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//null to null beamwidth and the gain power //given clc HPBW=6//degree//half power beamwidth f=6d+9//hertz v=3d+8 NNBW=2*HPBW//degree//null to null beamwidth lemda=v/f//metre Da=70*(lemda/HPBW)//degree//half power beamwidth gp=6.4*(Da/lemda)^2 gp_decibles=10*log10(gp)//changing to decibles gp_decibles=round(...
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Ведение логов.TST
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/*Essa rotina utliza o metodo dos minimos quadrados para gerar os coeficientes das funções. Ela calcula com o método da regressão multipla e aceita tanto funções de uma unica variavel com de grau maior que 1, quanto funções de multiplas variaveis This routine uses the least squares method to generate the coefficients...
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2^4+2^7 // =144 uint8(2^4+2^7) // =144 uint8(2^4+2^7)+uint8(2^4+2^7) // 144+144=32+256 int8(2^4+2^7) //=144-256 int8(2^4+2^7)+int8(2^4+2^7) // =-112-112+256
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//To Compute the Economical Sizes of the Transformer and its Equipment //Page 296 clc; clear; NC=24; //Number Of Customers Per Block //We get the Total Annual Cost from the releveant equations as // TAC = 239.32 + (3.1805*ST) + (3492/ST) + (28170/ST^2) + (0.405*ASL) + (17018/ASL) + (1.134*ASD) + (8273/ASD) ...
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rows = 3; cols = 3; A = zeros(rows, cols); disp("Enter the 3x3 A matrix"); for i = 1:rows for j = 1:cols A(i,j) = input("value for A:"); end end [m,n] = size(A) [v,pivots] = rref(A) r = length(pivots) disp(r,'rank = ') cs = A(:,pivots) disp(cs,'Column space = ') ns = kernel(A) disp(ns,"null space = "...
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//EXAMPLE 5-31 PG NO-326; V=25; R1=50; R2=40; R3=10; I=(V/(R1+((R2*R3)/(R2+R3))))*(R3/(R2+R3)); disp('i) Current (I) is = '+string (I) +' A ');
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clear //Given //Variable declaration b=120 //Width of plate in mm t=20 //Thickness of plate in mm R=10*10**3 //Radius of curvature in mm E=2e5 //Youngs modulus in N/sq.mm //Calculation I=b*t**3/12 //Moment of inertia in mm^4 y_max=t/2 ...