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// Example 34_20 clc;funcprot(0); //Given data P=120;// Plant capacity in MW CC=15000;// The Capital cost in Rs/kW Arc=20*10^6;// Annual running charges in rupees F_al=0.6;// The annual load factor F_ac=0.5;// Annual capacity factor //Calculation MD=(P*F_ac)/F_al;// Maximum demand in MW Rc=P-MD;// Reserve c...
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/* * By: Jatin Kumar Mandav * * Newton - Raphson Method is a method for finding successively * better approximations to the roots of a real-valued function. * It is one example of root finding algorithm. * * Formula: x(n+1) = x(n) - f(x(n))/f'(x(n)) * */ function [] = newton...
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function varargout = frd(varargin) [lhs,rhs] = argn(0) if rhs < 2 || rhs > 4 then errmsg = msprintf(gettext("%s: input arguments must have either two or three input arguments."), "frd"); error(errmsg) end frequency = varargin(1) freqUnit = 'rad/TimeUnit' respData = varargin(2) ...
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clear; clc; //Example - 17.24 //Page number - 631 printf("Example - 17.24 and Page number - 631\n\n"); // Given T = 600 + 273.15;//[K] - Reaction temperature P = 1;//[atm] - Reaction pressure // The Gibbs free energy of formation of various species at 873.15 K are delta_G_CH4_RT = -2.82;// delta_G_CH4/(R...
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//To find the addendum required clc //given t=25 phi=20*%pi/180 //let pitch be 1 R=t/(2*%pi)//R=t*p/(2*%pi) Larc=1.6//1.6*p //AB=Larc*cos(phi) AB=Larc*cos(phi) Ra=(4.47+13.97)^(1/2)//by simplifying AB+2{(Ra^2-R^2*cos(phi)^2)-R*sin(phi)} and using p =1 Addendum=Ra-R //writing p in place of p=1 printf("\nAd...
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// Exa 8.14 clc; clear; close; // Given data V_P = -4;// in V I_DSS = 9;// in mA V_GS = -2;// in V I_D = I_DSS*(( 1-(V_GS/V_P) )^2);// in mA disp(I_D,"The drain current in mA is");
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errcatch(-1,"stop");mode(2);//Ex:3.14 ; ; r=10*10^3;//in ohms t=1*10^-3; c=(10*t/r)*10^6; printf("Capacitor = %d uF",c); exit();
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bit equ $88 dirbit equ $8d direct equ $44 immed equ $55 srcdirect equ $33 acall addr add a, #immed add a, @ r0 add a, @ r1 add a, direct add a, r0 add a, r1 add a, r2 add a, r3 add a, r4 add a, r5 add a, r6 add a, r7 addc a, #immed addc a, @ r0 addc a, @ r1 addc a, direct addc a...
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// Initiliation of variables m_g=3000 // kg // mass of the gun m_s=50 // kg // mass of the shell v_s=300 // m/s // initial velocity of shell s=0.6 // m // distance at which the gun is brought to rest v=0 // m/s // initial velocity of gun // Calculations // On equating eq'n 1 & eq'n 2 we get v_g as, v_g=(m_s*v_s...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 35 clc; disp("CHAPTER 1"); disp("EXAMPLE 35"); //VARIABLE INITIALIZATION I=10; //current source in Amperes v=10; //voltage source in Volts r1=4; //top resistance in Ohms r2=...
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function[x,relres,resvec,it]=richardson(A,b,alpha,tol,maxit) n=size(A,1); x0=zeros(n,1); normb=norm(b); resvec = zeros(maxit,1); res=b-A*x0 relres=norm(res)/normb; Dm1=alpha; it=0; while(relres > tol) & (it < maxit) it=it+1; x=x0+Dm1*res; x...
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// Grob's Basic Electronics 11e // Chapter No. 27 // Example No. 27_7 clc; clear; // Assume the transformer turns ratio Np:Ns = 4:1 in Fig. 27–21 a and 2:1 in Fig. 27–22a. Compare Vripple and Vdc if C = 500 uF and Rl = 250. // Given data A1 = 4/1; // Turns ratio Np:Ns=4:1 B1 = 1/4; ...
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data22_4.sci
//(Cylinders and Pressure Vessels) Example 22.4 //Inner diameter of the cylinder Di (mm) Di = 250 //Gas pressure Pi (MPa) Pi = 15 //Ultimate tensile strength of the cylinder material Sut (N/mm2) Sut = 340 //Poisson's ratio of the material mu mu = 0.27 //Factor of safety fs fs = 5 //Check the behavior of th...
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//(a+b)*(a^2-ab+b^2) clear; clc; close; //on collecting like terms val=string('a^3+b^3')
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example2.sce
clear ; clc; xdel ( winsid ()); // c l o s e a l l windows mode (0) x1 = [1; 2; 3] x2 = [1; 0; 1] x3 = [2; 2; 4] A = [x1 x2 x3 ]; disp (A, ' [ x1 : x2 : x3 ] =' ); disp ( clean ( det (A)), ' de t ( [ x1 : x2 : x3 ] ) =' ); // s i n g u l a r x3 = [2;2;2] A = [x1 x2 x3 ]; disp (A, ' [ x1 : x2 : x3 ] =' ); di...
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clc //initialization of variables T = 32 //F T0 = 10//F Tinf= 80 //F U = 3.6 //Btu/hr-ft^2-F A = 27 //ft^2 d = 8.31 //lb/gal V = 100 //gal Cv = 1//Btu/lb-F //Calculations t = (-log((T-T0)/(Tinf-T0)))*d*V*Cv/(U*A)//hr //Results printf("The time we can wait before the water in the tank starts to freeze is %...
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poly2ac4.sce
//o/p when null matrix is given as i/p a = [0,0,0,0,0,0]; efinal = 0.2; // Step prediction error r = poly2ac(a,efinal); // Autocorrelation sequence disp(r); //Output // !--error 10000 //Input polynomial has to be a 1-dimensional array //at line 35 of function poly2ac called by : //r = poly2ac(a,efi...
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clc //initialization of new variables clear u=25 //km/h t=1 //h S=0.36 //m^2 Cd=0.88 r=1.2 //kg/m^3 //calculations D=Cd*1/2*r*(u/3.6)^2*(S) P=D*u/3.6 E=P*t*3600 //results printf('Drag force = %.2f N',D) printf('\n Power = %.2f W',P) printf('\n Energy spent is %.1f KJ',E/1000)
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//clear// //Caption:Duobinary Encoding //Example6.2: Precoded Duobinary coder and decoder //Page 256 clc; b = [0,0,1,0,1,1,0];//input binary sequence:precoder input a(1) = xor(1,b(1)); if(a(1)==1) a_volts(1) = 1; end for k =2:length(b) a(k) = xor(a(k-1),b(k)); if(a(k)==1) a_volts(k)=1; else ...
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clc clear //Input data Cx=750 //velocity upstream of shock in m/s Px=1 //Pressure upstream of shock in bar Tx=10+273 //Temperature upstream of shock in K k=1.4 //Adiabatic constant R=287 //Specific gas constant in J/kg-K //Calculation Mx=Cx/sqrt(k*R*Tx) //Mach number upstream of shock My=0.545 //Mach nu...
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clc //Intitalisation of variables clear dT= 0.170 //C M2= 60.06 //gms w1= 22.5 //gms w2= 0.45 //gms R= 1.987 //cal T= 100 //C lv= 539.9 //cal g^-1 //CALCULATIONS Kb= dT*M2*w1/(1000*w2) Kb1= R*(273.2+T)^2/(lv*1000) //RESULTS printf ('Eleveation constant of water = %.3f ',Kb) printf ('\n Eleveation constan...
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clc L_A=0.003; //m L_B=0.05; //m L_C=L_A; k_A=46.5; //W/m 0C k_B=0.046; //W/m 0C k_C=k_A; h0=11.6; //W/m^2 0C hi=14.5; //W/m^2 0C t0=25; //0C ti=6; //0C A=0.5*0.5*2+0.5*1*4; //m^2 disp("(i) The rate of removal of heat =") Q=A*(t0-ti)/(1/h0 + L_A/k_A + L_B/k_B + L_C/k_C + 1/hi); disp(Q) disp("W") ...
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//Math Helper function fDeg = r2d(fRad) fDeg = fRad * 180 / %pi endfunction function fRad = d2r(fDeg) fRad = fDeg * %pi / 180; endfunction
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//chapter12 //example12.11 //page248 Vcc=15 // V Re=2 // kilo ohm Rc=1 // kilo ohm gain_beta=100 Vbe=0.7 // V R1=10 // kilo ohm R2=5 // kilo ohm // when Ic=0, Vce=Vcc i.e. Vce=6 and when Vce=0, Ic=Vcc/(Rc+Re) i.e. Ic=15/(1+2) // so equation of load line becomes Ic=-(1/3)*Vce+5 clf() x=linspace(0,15,5...
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clc; funcprot(0); //Example 5.1 Flat Plates Nornmal to Direction to Flow // Initialisation of variables l = 10; h = 8; V = 40; // Calculations A = l*h; F = 0.00327*A*V^2; //Results disp(F,"Force in plate (lb) :");
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// Calculation of maximum temperature clear; clc; printf("\t Example 19.1\n"); To=20; // Room Temperature (degree celsius) sigma=-172; //Mpa Compressive stress E=100*10^3; //Mpa Young's modulus a=20*10^-6; //Celsius^-1 Coefficient of thermal expansion Tf=To-(sigma/(E*a)); printf("\nFinal ...
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clc //initialization of varaibles v2=5.434 //cu ft/lb v1=4.937 //cu ft/lb h1=1227.6 h2=1223.9 A1=%pi/144 //calculations Vratio=v2/v1 V1=sqrt(64.4*(h1-h2)*778/(Vratio^2 -1)) V2=V1*Vratio w=A1*V1/v1 //results printf("Average velocity at 1 = %d fps",V1) printf("\n Average velocity at 2 = %d fps...
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//Normally aspirated and supercharged engine clc,clear //Given: V_s=3300 //Swept volume in cc //For normally aspirated bmep1=9.3 //Brake mean effective pressure in bar N1=4500 //Engine speed in rpm eta_it1=28.5 //Indicated thermal efficiency in percent eta_m1=90 //Mechanical efficiency in percent m1=205 //Mass...
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/////////////////////////////////////////////////////////////////////// /////////////// ROCK, PAPER, SCISSORS /////////////// /////////////////////////////////////////////////////////////////////// print("Rock, paper scissors") let getInput() = print("Type 'rock', 'paper' or 'scissors'. Type 'quit...
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//Chapter 6, Example 6.3 clc //Initialisation pi=3.14 //pi f=100 //frequency in hertz L=25*10**-3 //inductance in henry vl=5 //peak voltage //Calculation w=2*pi*f //angular frequency Xl=w*L ...
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clear all clc // Load SOCKET Toolbox. exec(SCI+'contribsocket_toolbox_2.0.1loader.sce'); SOCKET_init(); // Define Red Pitaya as TCP/IP object IP= '192.168.178.56'; // Input IP of your Red Pitaya... port = 5000; // If you are using WiFi then IP is: tcpipObj='RedPitaya'...
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PL/SQL Developer Test script 3.0 15 -- Created on 14/09/2010 by AGILAR declare -- Local variables here i integer; vResult boolean; MeuCliente pkg_comercial.TCliente; begin vResult:= pkg_comercial.getDadosSegundaViaFatura(vIdCliente => 1, vCliente => MeuCliente); if vResult then dbms_output...
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//Exa 1.13 clc; clear; close; format('v',7); //Given Data : theta1_p1=273.16;//K p_gauge1=32;//mm of Hg p_atm=752;//mm of Hg p_gauge2=76;//mm of Hg P1=p_gauge1+p_atm;//mm of Hg P2=p_gauge2+p_atm;//mm of Hg theta2_p2=theta1_p1*(P2/P1);//in K theta2_p2=theta2_p2-273;//degree C disp(theta2_p2,"Temperature ...
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Nms = input("Enter the frame size in milliseconds: "); Sfms = input("Enter the frame shift in milliseconds: "); FileName = input("Enter the sound file name (Enclose in single quotes): "); [y, Fs, bits] = wavread(FileName); N = Nms * Fs / 1000; // Number of frames for size Sf = Sfms * Fs / 1000; // Number of frames f...
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// Change PAPI path ! exec('/home/quepas/PhD/Tools/sPAPI/loader.sce') // Add array operations and examples getd('.') getd('./array_operations'); getd('./examples'); // Measurement statistics mprintf('@1@ [SCILAB] Measuring Array Operations...\n'); mprintf('\tNum. of measurement repetitions = %d (cutoff first: %d)\n',...
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.ig XMERGE2.TST VERS:- 01.00 DATE:- 09/26/86 TIME:- 09:37:39 PM .. Test file consisting of several CAS abstracts for use in trials .. of xmerger (CAS abstracts are the default option): .. Usage: xmerger <xmerge1.tst xmerge2.tst +results_file * XMERGE2.TST ANSWER 2 OF 8 AN CA94(21):172080h...
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argc:7 Dataset: ../datasets/converted/5powergrid.net Nodes Edges Com Mod NMI Time seq semisync 4941 13188 517 0.797223 -1 0.0369399 par semisync 4941 13188 1119 0.65376 -1 0.16538
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clc; clear all; n = 200; // Number of fringes observed d = 0.589e-3; // Distance moved lambda = (2*d)/n; // Condition for interference is disp('m',lambda,'The wavelength of light used is') lamda=lambda*1e10;//conversion in Angstrome disp('Angstrom',lamda,'The wavelength of light used is ') //rounding off value ...
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// Scilab code Ex4.23 : Pg:159 (2008) clc;clear; a = 1; // Assume amplitude of the wave from coherent sources to be unity D = 1; // The distance between the slits and the screen, m d = 5e-004/2; // Half the separation between two slits, m mu = 1.5; // The refractive index of glass plate t = 1.5e-006; ...
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## Test the rename branch command read <deleteall.fi branch samplebranch rename jabberwocky write -
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//Chapter-4, Illustration 25, Page 218 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P0=100;//Steam pressure in bar T0=773;//Steam temperature in K a1=70;//Nozzle angle in degrees ns=0.78;//Steam efficiency m=...
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//(9.14) A converging nozzle has an exit area of 0.001 m2. Air enters the nozzle with negligible velocity at a pressure of 1.0 MPa and a temperature of 360 K. For isentropic flow of an ideal gas with k = 1.4, determine the mass flow rate, in kg/s, and the exit Mach number for back pressures of (a) 500 kPa and (b) 784...
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//Example 14-14 clc;clear;funcprot(0); // Properties rho=998;//The density of water at 20°C in kg/m^3 //Given values D_a=2.05;//Diameter in m n_a=120;//rpm n_b=120;//rpm omega_a=12.57;//rad/s omega_b=12.57;//rad/s V_a=350;//m^3/s H_a=75.0;//m H_b=104;//m bhp_a=242*10^6;//MW bhp_b=548*10^6 g=9.81;//The ac...
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18 1:0.07142857142857142 43:0.25 92:2.0 161:0.2 175:0.5 1197:1.0 1556:1.0 1584:1.0 1657:1.0 18 16:0.6666666666666666 43:0.25 50:0.07692307692307693 57:0.1 92:1.0 105:1.0 161:0.2 282:0.16666666666666666 1140:1.0 1197:1.0 1928:1.0 18 1:0.14285714285714285 8:0.5 14:0.2 16:0.6666666666666666 43:0.25 57:0.1 89:1.0 105:1.0 1...
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clc clear //input T=100 //rise in temperature i=2.7 //current t=950 //time taken mc=0.15//mass of calorimeter cy=3*10^3//specific heat capacity of y cc=2*10^3//specific heat capacity of calorimeter my=160*10^-3//mass of liquid //calculation v=((my*cy)+(mc*cc))*T/(i*t)//law of conservation of heat //output ...
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clc //Initialization of variables u = 0.04 // lb-s/ft^2 V = 2 //ft/s h = 1/60 // ft //Calculations T = (u*3*V)/h // results printf("The shearing stress is %.1f lb/ft^2",T)
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-- VectorCAST 6.4t (05/31/17) -- Test Case Script -- -- Environment : UT_OCU_OCU -- Unit(s) Under Test: Ocu -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FEATU...
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// Exa 6.4 clc; clear; close; format('v',6) // Given data I_DSS = 8;// in mA I_DSS = I_DSS * 10^-3;// in A V_P =-5;// in V V_GS = -2;// in V V_DSmin = V_GS - V_P;// in V disp(V_DSmin,"The minimum value of V_DS in V is"); I_DS = I_DSS*((1 - (V_GS/V_P))^2);// in A I_DS = I_DS * 10^3;// in mA disp(I_DS,"The ...
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//Chapter-3, Problem 3.3 , Page105 //=========================================================================== clc; clear; //INPUT DATA PRF= 1000;//pulse repetitive frequency in Hz F = 10*10^9;//operating frequency of radar in Hz; Vo = 3*10^8;//velocity in m/s //Calculations lamda = Vo/F; // Blind Fr...
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disp('Лабораторная работа 1: метод Гаусса') Matrix = read("matr.txt", -1, 4); copyMatrix = Matrix; disp(Matrix,"Исходная матрица:") n = length(Matrix(:,1));; j = 1; tic; for i=1:n bla = 1; tmp = Matrix(i,i); while tmp == 0 if bla >= n then disp("Wrong matrix!") exit; ...
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clc disp("Example 3.63") printf("\n") disp("Draw a DC load line for Collector to base bias") printf("Given\n") //given Vcc=20 Vbe=0.7 hFE=50 Rc=1.8*10^3 Rb=39*10^3 //base current Ib=(Vcc-Vbe)/(Rb+(1+hFE)*Rc) //collector current Icq=hFE*Ib //to find Vce Vceq=(Ib*Rb)+Vbe //to draw DC load line Ic1=Vcc/R...
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///////////////// // Général // ///////////////// function ast = calculCentreAstre(astre) for i=1:size(astre, "r") temp = 0; for j=1:size(astre, "c") temp = temp + astre(i, j) end ast(i) = temp/size(astre, "c"); end endfunction ////////...
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[1,4,6,4,1] | [1,2,1] = initial: [1,4,6,4,1] / [1,2,1], rem1=[1,4,6,4,1], div2=[1,2,1], lenq=3, len1=5, len2=3 step end: quot=[0,0,0]/qden=1, rem1=[1,4,6,4,1]/rden=1, div2=[1,2,1], bquot=1, lenq=3, len1=5, len2=3 while end: quot=[0,0,1]/1, rem1=[1,4,5,2]/1 step end: quot=[0,0,1]/qden=1, rem1=[1,4,5,2]/rden=1, di...
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//Example 5-6 Water Discharge from a Large Tank z_1 = 5 //water height in tank [m] g = 9.81 //gravitational acceleration [m/s^2]
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//2.44 clc; e0=8.85*10^-12; A=500*10^-6; d=0.2*10^-3; C=e0*A/d; d1=0.18*10^-3; C_new=e0*A/d1; C_change=C_new-C; Ratio=(C_change/C)/(0.02/0.2); printf("\nratio of per unit change of capacitance to per unit change of diaplacement=%.2f",Ratio) d1=0.19*10^-3; e1=1; d2=0.01*10^-3; e2=8; C=(e0*A)/((d1/e1)+(d2/...
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clc //Initialization of variables n1=10 //mol n2=12 //mol //calculations dn=n1-n2 //results printf("dHp = dEv- %d *RT",dn)
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clear; clc; printf("\t\t\tProblem Number 6.41\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.41 (page no. 304) // Solution //For Methane(CH4,MW=16) p=500; //evaluate specific volume at p pressure //Unit:psia pc=674; //critical temperature //Unit:psia T=50+460; //evaluate specific volume at T temperature ...
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_uncued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds...
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clear;lines(0); x=poly(0,'x'); v=[x*(x+1),x^2*(x+1),(x-2)*(x+1),(3*x^2+2)*(x+1)]; [pg,U]=hrmt(v);U=clean(U) det(U)
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exa_7_4.sce
//Exa 7.4 clc; clear; close; //given data format('v',9); T1=800+273;// in K A= 5*6;// in square meter epsilon=0.45; sigma=5.67*10^-8; q=epsilon*sigma*A*T1^4;//in watt disp(q,"Energy emitted by a grey surface in watt : ");
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// Example 2.3 // Calculation of (a) critical angle (b) numerical aperature and (c) acceptance angle // Page no 38 clc; clear; close; // Given data n1=1.5; // Refractive index of core n2=1.47; // Refractive index of cladding) // (a) Critical angle thea...
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//Example 2.9 clc clear close a=[0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1]; b=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]; c=[0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1]; d=[0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1]; for i=1:16 // finding Y for all 16 cases x=bitor(a(i),b(i)); y=bitor(c(i),d(i)); r(i)=bitand(x,y); x1=bitcmp...
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example12_9.sce
//clc() N = 100;//mol fuel gas Nco = 21; Nh2 = 15.6; Nco2 = 9.0; Nch4 = 2; Nc2h4 = 0.4; Nn2 = 52; Hco = 282.99;//kJ/mol ( heat of combustion ) Hh2 = 285.84;//kJ/mol ( heat of combustion ) Hch4 = 890.4;//kJ/mol ( heat of combustion ) Hc2h4 = 1410.99;//kJ/mol ( heat of combustion ) Hvap = 44.04;//kJ/mol H = ...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <!DOCTYPE AUTOTEST> <AutoTest version="2.0.0" wavetype="2"> <Pulse>Pulse 2b</Pulse> <Title>Pulse 2b</Title> <Organization>GM</Organization> <Standard>GMW3097 2006</Standard> <Item>3.5.2 CI. Transients on Power Lines</Item> <Count>1</Count> ...
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clear clc disp("example10.5") i1=0.8 i2=1.0 l1=complex(0.04,0.12) l2=complex(0.03,0.1) l3=complex(0.03,0.12) vl=1 i3=i1+i2 v1=vl+i3*(l1)+i1*(l2) v2=vl+i3*(l1)+i2*(l3) p1=real(i1*v1) p2=real(i2*v2) cos1=real(v1)/abs(v1) cos2=real(v2)/abs(v2) b11=abs((real(l1)+real(l2))/(v1^2*cos1^2)) b22=abs((real(l1)...
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//example 11.4 //calculate number of siphons units required clc;funcprot(0); //given rl=435; //full reservior level cl=429.6; //level of centre of siphon hfl=435.85; //high flood level hfd=600; //high flood discharge w=4; //width of throat h=2; //heigth of thr...
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7_1_Cooling_rate.sce
clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 7.1 Page 415 \n'); //Example 7.1 // Cooling rate per Unit Width of the Plate //Operating Conditions v = 10; //[m/s] Air velocity p = 6000; //[N/m^2] Air pressure Tsurr = 300+273;...
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//Example 6.24 clc clear x = 1:3:10; F = [500426 329240 175212 40365]; n = length(x); del = %nan*ones(n,4); del(:,1) = F'; for j = 2:4 for i = 1:n-j+1 del(i,j) = del(i+1,j-1) - del(i,j-1); end end del0 = del(1,:); X = 2; x0 = x(1); h = x(2) - x(1); p = (X-x0) / h; F2 = 0; for ...
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//water chemistry// //example 7.15// W1=0.28;//amount of CaCO3 in grams dissolved in 1 litre of water// V1=28;//required EDTA in ml on titration of 100ml of CaCO3 solution// V2=33;//required EDTA in ml for 100ml of unknown hard water sample// V3=10;//required EDTA in ml for 100 ml of unknown sample after boiling a...
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6_20.sce
//example 6.20 //double integration //page 247 clc;clear;close; deff('z=f(x,y)','z=exp(x+y)'); h0=0.5,k0=0.5; h=[0 0.5 1];,k=[0 0.5 1]; for i=1:3 for j=1:3 x(i,j)=f(h(i),k(j)); end end T_area=h0*k0*(x(1,1)+4*x(1,2)+4*x(3,2)+6*x(1,3)+x(3,3))/4//trapezoidal method printf('the integration value ...
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MUX 4-1.sce
ok=open_serial(1,2,115200); if ok~=0 then error('Unable to open serial port, please check'); end for i=1:10000 //input pins i0=cmd_digital_in(1,2) //LSB, reads input i0 i1=cmd_digital_in(1,3) i2=cmd_digital_in(1,4) i3=cmd_digital_in(1,5) //MSB, reads input i3 //select lines a=...
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launcher.sce
function beauty_axes(x_text, y_text) a = gca(); a.x_label.text = x_text; a.x_label.font_size = 4; a.y_label.text = y_text; a.y_label.font_size = 4; endfunction function beauty_legend(text, place) legend(text, place), a = gca(); a.children(1).font_size = 4; endfunction function beauty_p...
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5.sce
//problem 1.5 h1=0.05 h2=0.1 s1=0.8 s2=13.6 w=9810 p=s2*h2*w //pressure at balance line p1=s1*h1*w pf=p-p1 disp(pf, "pressure in pipe(N/m2)")
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Example4_9.sce
//Exa 4.9 clc; clear; close; //Given data : r=4/2;//cm rdash=0.7788*r;//cm d=300;//cm d3=6*100;//cm LA=0.2*[log(d/rdash)+1/2*log(2)-%i*0.866*log(2)];//mH disp(LA,"Inductance per km of phase1(mH)"); LB=0.2*log(d/rdash);//mH disp(LB,"Inductance per km of phase2(mH)"); LC=0.2*[log(d/rdash)+1/2*log(2)+%i*0.866...
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//chapter9 //example9.15 //page158 n=4 Rl=200 // ohm fin=50 // Hz Vp=230 // V rms Vs=Vp/n // V rms Vsm=Vs*2^0.5 // maximum voltage across secondary Idc=2*Vsm/(%pi*Rl) Vdc=Idc*Rl PIV=Vsm // in full wave rectifier, output frequency is twice input frequency since there are two ouput pulses for each cy...
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clc; // page no 127 // prob no 3.11 //Refering the fig. 3.17 //From fig it is clear that thee waveform is made from two sine waves Vp=12.5;//Since Vp-p is 25V from fig hence individual Vp is half of Vp-p Rl=50;//Load resistance is 50 ohm //Determination of average power Vrms=Vp/sqrt(2); P=((Vrms)^2)/Rl; disp...
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clear // // // //Variable declaration v=0.2 //volume(cc) a=1*10**4 //area(cm**2) r=0 n=1 lamda=5.5*10**-5 //wavelength(cm) t=2 //Calculation d=v/a //thickness of film(cm) mew=n*lamda/(2*t*cos(r)) //refractive index of oil //Result printf("\n refractive index of oil is %0.2f *10**-5",mew*...
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14_1.sce
clc //initialisation of variables clear H1=26 //B.Th.U /lb H2= -27.5 //BThU/lb //CALCULATIONS H= H1-H2 t=-83//f s=3.43//ft^3/lb v=224*sqrt(H) //RESULTS printf ('Final temperature= %.f F',t) printf (' \n Final specific volume = %.2f ft^3/Lb',s) printf (' \n Hd = %.1f B.Th.U/lb',H) printf (' \n veloci...
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egalisation.sci
function render=egalisation(img) //This is the script to do an equalization on the image // Calcul of the histogram value (nb of pixel with gray value) imghist=histogramme(img); //disp(imghist) // Calcul normalized histogram // but before, calcul of the total number of pixel [wd,he]=size(img) nbpixels = wd*he imgn...
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errcatch(-1,"stop");mode(2);//Example 2_4_1 ; ; //To calculate the wavelength of light D=150 //units in centimeters d=0.03 //units in centimeters betaa=0.3 //units in centimeters lemda=((betaa*d)/D)*10^8 printf("Wavelength of the light is %.0f angstrom",lem...
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ex2_10.sce
RL=20; //load resistance Zo=50; //intrinsic impedance Rin=50; //input resistance Tin=10^(-RL/20); //reflection coefficient at input Rg1=Rin*(1+Tin)/(1-Tin); Rg2=Rin*(1-Tin)/(1+Tin); disp("Ohms",Rg1,"Source resistance for positive Tin="); disp("Ohms",Rg2,"Source resistance for negative Tin=");
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Name=Clown Flick Practice Small PlayerCharacters=Gamer BotCharacters=GamerBot.bot;GamerBot.bot;GamerBot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Gamer AddedBots=GamerBot.bot;GamerBot.bot;GamerBot.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=2 BotTeams=1;1;1 MapName=hall.map MapScale=3.8125 BlockProjectile...
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Ex24_4.sce
clc; Po=25; G=10*log10(Po/(1*10**-3)); disp('dB',G*1,"G=");
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mdaq_zvsfb.sci
// Generated with MicroDAQ toolbox ver: 1.3.0 function [x,y,typ] = mdaq_zvsfb(job,arg1,arg2) block_desc = ['Set ZVSFB parameters'; 'This block uses PWM1 and PWM2 modules to generate ZVSFB waveform'; 'It allows to set constant PWM period(frequency).'; 'FED/RED waveform poperties can be adjusted by passing va...
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Ex2_3_u1.sce
//Example 2_3_u1 clc(); clear; //To calculate minimum no of lines per centimeter lamda1=5890 //units in armstrongs lamda2=5896 //units in armstrongs dlamda=lamda2-lamda1 //units in armstrongs k=2 n=lamda1/(k*dlamda) width=2.5 //units in cm nooflines=n/width printf("No of lines per cm...
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Ex6_1.sce
clear; clc; //Example 6.1 Vtn=1; //let x= u_n*Cox*1/2 x=20*10^-3; //let y=W/L y=40; I_D=1; Kn=x*y; printf('\nconduction parameter=%.3f mA/V^2\n',Kn) g_m=2*sqrt(Kn*I_D); printf('\ntransconductance=%.3f mA/V\n',g_m)
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isNegative.tst
// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. load isNegative.hdl, output-file isNegative.out, compare-to isNegative.cmp, output-list in%B2.16.2 out%B2.1.2; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval,...
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Ex7_6.sce
clear //Given //we will divide this into two equal parts and other part l = 10.0 // in - The height t = 0.1 // in - The width b = 5.0 //mm- The width of the above part A = t* b //sq.in - area of part y_net = l/2 // The com of the system y_1 = l // The position of teh com of part_2 I_1 = t*(l*...
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taylorwin3.sce
//check o/p when the i/p arguments are n:required order of the filter, nbar: no of constant level sidelobes, and sll: max sidelobe level w = taylorwin(6,4,-40); disp(w); ////output //0.3305716 // 1.019979 // 1.6494495 // 1.6494495 // 1.019979 // 0.3305716
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ExportFixedData.sce
//clf; clc; clear all; Pos = 44; N = 12 num = 1:32; k =1; y = 0:2047; z = dec2bin(y,16); for Ch =1+ (32*Pos):32+ (32*Pos) str = 'chan_' + string(num(k)) + '.txt'; k = k+1; csvWrite(z', str); end clear data;
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ex6_22.sce
// Exa 6.22 clc; clear; close; // Given data V_DD= 20;// in V I_DSS= 9;// in mA V_P= -3;// in V R1= 0.3*10^3;// in kΩ R2= 1.7*10^3;//in kΩ R_D= 3.2;// in kΩ R=1;// in kΩ V_G= V_DD*R1/(R1+R2);// in V //I_D= I_DSS*[1-V_GS/V_P]^2 (i) // V_G= V_GS+I_D*R or I_D= (V_G-V_GS)/R (ii...
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2014-09-29T16:14:00
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dollars.sce
e=input("Bedrag in euros: "); t=input("Wisselkoers: "); d=e*t; disp("Het bedrag in dollar: "+string(d)) printf("Het bedrag is %f dollar",d)
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ex23_1.sce
clc;clear; //Example 23.1 //calculation of relative permittivity //given values E=1000;//electric field in V/m P=4.3*10^-8;//polarization in C/m^2 e=8.85*10^-12;//permittivity in F/m //calculation er=1+(P/(e*E)); disp(er,'relative permittivity of NaCl is ');
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103.sce
clc //initialisation of variables l=20//m e=0.00025//mm E=2000000//kg/cm^2 f=19.6//cm^2 //CALCULATIONS sig=E*e//kg/cm^2 Del=sig*f//kg L=e*l//m //RESULTS printf('the pressure of bearings normal operations=% f m',L)
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7_1.sce
disp("Eg=1.420+(1.087*x)+(0.438*x^2)"); x=800*10^-9; Eg=1.420+(1.087*x)+(0.438*x^2); printf('\n The value of Eg is %feV',Eg); printf('\n'); disp("The corresponding bandgap value for x=800nm from Eg(x) is 0.11");
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WeldedBealGoalProgramming.sce
//Reference: K. Deb,"Solving Goal Programming Problems Using Multi-Objective Genetic Algorithms",Proceeedings of the 1999 Congress on Evolutionary C omputation CEC-99,USA, 1999, p. 77-84 // goal f1(x) = (1.10471*h^2*l + 0.04811*t*b*(14+l))<=5; // goal f2(x) = (2.1952/((t^3)*b))<=0.001; // subjected to // g1(x) = 13,...
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Resta.tst
load Resta.hdl, output-file Resta.out, output-list s%B1.16.1; set al %B1001011010110101, set ah %B1010110101101101, set bl %B0010110100101011, set bh %B0101101010010110, eval;
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Ex7_24.sce
//Example 7.24 // LQR Design for a Tape Drive xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ // State space model for a Tape Drive F=[0 2 0 0 0;-0.10 -0.35 0.1 0.1 0.75; 0 0 0 2 0; 0.4 0.4 -0.4 -1.4 0; 0 -0.03 0 0 -1]; G=[0 0 0 0 1]'...