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clear all; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 2 // Heat Conduction in Solids // Example 2.4 // Page 32 printf("Example 2.4, Page 32 \n\n") Ti = 300; //Internal temp of hot gas in degree Celsius OD = 0.1; //Outer diameter of long metal pipe in meters ID = 0.0...
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clc clear //Input data m=21000//Steam rate in kg/h p1=17//Pressure in bar T1=230+273//Temperature in K P=132.56//Power in kW x2=0.957//Dryness fraction p2=3.5//Pressure in bar Pl=1337.5//Power in l.p turbine in kW p3=0.3//Pressure in bar x3=0.912//Dryness fraction //Calculations h1=2869.7//Enthalpy in k...
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// Scilab Code Ex11.4: Page-250 (2010) lambda = 500e-009; // Wavelength of laser light, m f = 15e-02; // Focal length of the lens, m d = 2e-02; // Diameter of the aperture of source, m a = d/2; // Radius of the aperture of source, m P = 5e-003; // Power of the laser, W A = %pi*lambda^2*f^2/a^2; ...
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//Example 2 Page No:1.83 //given sr=0.000001;//volt/sec freq1=100000;//hz vsat=12;//volt baw=100000;//hz //determine vx vx=2*(1/(sr*2*3.14*freq1)); format(6); disp('maximum peak amplitude at 100khz = '+string(vx)+" volt");
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//Problem 10.17: In a Wheatstone bridge ABCD, a galvanometer is connected between A and C, and a battery between B and D. A resistor of unknown value is connected between A and B. When the bridge is balanced, the resistance between B and C is 100 ohms, that between C and D is 10 ohms and that between D and A is 400 o...
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// Scilab code Ex12.3: Pg 436 (2005) clc; clear; e_V = 1; // Energy applied to diode, eV k_B_T = 0.025; // Product of Boltzmann constant and temperature, eV // For simplicity let (q*V)/(k_B*T) = x x = (e_V/(k_B_T)); I_f_r = (exp(x)-1)/(exp(-x)-1); // Ratio of forward current to reverse current in diode pr...
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clc clear //INPUT b=0.00136;//vanderwaal constant in suv/gm a=0.011;//vanderwaal constant in atm(suv)^2/gm^2 r=0.003696;//universal gas constant in atm(suv)/gm.deg t=423;//temperature of steam in K cp=-0.674/0.024205;//specific heat at 423K in atm(cc)gm(deg) //CALCULATIONS dt=(-b+(2*a/(r*t)))/cp;//change o...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-7 clear; clc; close; // Clear the work space and console. // Given data V = 10 * exp(%i * 0 * (%pi/180)); // Supply voltage of the source 10<0 V R_s = 1000 ; // Res...
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//code for solving 2d steady state conduction pathname=get_absolute_file_path('2d_conduction_gauss_siedel.sce') filename=pathname+filesep()+'2d_conduction_data.sci' exec(filename) T=[]; //Creating empty matrix for temperature //Temperature at the bottom of the plate for j=1:1:nx T(1,j)=T_bottom; end //Temperature a...
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//============================================================================= // Copyright 2020 Allan CORNET (Nelson) // // Licensed under the Apache License, Version 2.0 (the "License"); // you may not use this file except in compliance with the License. // You may obtain a copy of the License at // // http://www...
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//scilab 5.4.1 //Windows 7 operating system //chapter 8 Junction Transistors:Biasing and Amplification clc clear VBE=0.7//VBE=base emitter voltage b=99//b=dc current gain of the common emitter transistor VCC=15//VCC=collector supply voltage RE=7//RE=resistance in kilo ohms connected to the emitter terminal RC=...
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// ALU-nostat.tst é um teste parcial da ALU // ALU-nostat.tst testa somente a parte computacional da ALU. // A saida de 'zr' e 'ng'sao ignoradas. load ALU.hdl, output-file ALU-nostat.out, compare-to ALU-nostat.cmp, output-list x%B1.16.1 y%B1.16.1 zx%B1.1.1 nx%B1.1.1 zy%B1.1.1 ny%B1.1.1 f%B1.1....
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/////////Chapter 10 Properties Of Steam ///Example 10.21 Page No:201 /// Find Final enthalpy of steam //Input data clc; clear; m=4; //Steam in Kg P=13; //Absolute pressure in bar tsup1=450; //Absolute temp in degree celsius deltaH=2.8*10^3; Cps=2...
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// Example 2.12: Calculate Collector current and Collector to emitter voltage Vcc=25;// Colector voltage in volts Vbe=0.7;// Base to emitter voltage in volts Rb= 180;// in KILLO OHMS Beta=80;//Common emitter D.C. Current gain Rc=0.82;// Collector resistance in killo ohms Re=0.2;// Emitter resistance in killo oh...
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clear; clc; //Example13.3[View Factors Associated with a Tetragon] //Given:- //A pyramid with square base and it's sides being isoceles triangle //Solution:= F11=0;//Since base is a flat surface //F12=F13=F14=F15=x x=(1-F11)/4; disp("of total radiation",x,"Each side pf the four surfaces of the pyramid reciev...
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clc; t0=3600; //time in sec t=3601; //time in sec c=3*10^8; //velocity in m/sec v=c*sqrt((1-(t0/t)^2)); //calculating velocity disp(v,"Velocity in m/sec = "); //displaying result
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clc// // // //Variable declaration C=2*10^-6; //capacitance(F) V=1000; //voltage(V) epsilon_r=100; //Calculation W=C*V^2/2; //energy stored in the condenser(J) C0=C/epsilon_r; W0=C0*V^2/2; E=1-W0; //energy stored in the dielectric(J) //Result printf("\n energy stored in the condenser...
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s=%s [A]=pfss((s+2)/(s^2+2*s+1)*(s+3)) disp([A])
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load Comparator.hdl, output-file Comparator.out, compare-to Comparator.cmp, output-list in%B1.16.1 eqz%B2.1.2 ltz%B2.1.2; set in %B0000000000000000, eval, output; set in %B0111111111111111, eval, output; set in %B1000000000000000, eval, output; set in %B1111111111111111, eval, output;
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scenario = "Classifier Training"; response_matching = simple_matching; active_buttons = 2; button_codes = 1,2; default_font = "Calibri"; default_font_size = 18; default_text_color = 100,100,100; default_clear_active_stimuli = false; response_logging = log_all; write_codes = true; pulse_width = 6; response_po...
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function x = sist(L,b) n = size(L,1); x = zeros(n,1); x(1) = b(1)/L(1,1); for i = 2:n x(i) = (b(i) - sum(L(i,1:i-1)*x(1:i-1)))/L(i,i); end endfunction function [x, d, k, r] =GaussSeidel_sist(A, b, x0, E, M, n) L = tril(A); U = triu(A, 1); x = sist(L, -U*x0 + b); k = 0; while((norm(x-x0, n)>=E) && (k<M)) ...
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clc // Given that N = 4000 // Grating lines per cm n = 2 // order lambda = 5000 // wavelength of light in angstrom // Sample Problem 23 on page no. 165 printf("\n # PROBLEM 23 # \n") printf(" Standard formula used \n") printf(" d_theta /d_lambda = n/(e+d)*cos(theta) \n") theta = asin(n*lambda*1e-8*N) ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS // EXAMPLE : 1.18 : // Page number 699-700 clear ; clc ; close ; // Clear the w...
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close(); clear; clc; Vm = 200; w = 377; Im = 8; //A theta = 30; //degree //(a) power factor 'pf' pf = cos(theta*(%pi)/180); mprintf("Power factor, pf = %0.3f\n\n",pf); //(b) true power 'S' S = Vm*Im/2 * pf; //W mprintf("True Power, S = %0.1f W\n\n",S); //(c)Apparant power 'Q' Q = Vm*Im/2; //VA mprint...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 2: HEATING AND WELDING // EXAMPLE : 2.6 : // Page number 732 clear ; clc ; close ; // Clear the work space and console // ...
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clc clear //Input data r=7.8;//Compression ratio p=1;//The pressure at the start of compression in atm T1=335;//The temperature at the start of compression in K //Calculations W1=100;//Isentropic compression function for T1 in J/kg air K W2=W1-(292*log(1/r));//Isentropic compression function in J/kg air K ...
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clc(); clear; // To compute the temprature distribution h=1; // Heat transfer coefficient in Btu/hr-ft^2-degF x=1; // Assumed thickness in ft k=1; // Thermal conductivity in Btu/hr-ft-degF N=h*x/...
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n1 = 9 n2 = 5 n3 = 0 n4 = 5 nodes = 10 + n3 function [matrix] = getMatrix(nodes, n1, n2, n3, n4) n1_str = string(n1); n2_str = string(n2); n3_str = string(n3); n4_str = string(n4); n = strcat([ n1_str, n2_str, n3_str, n4_str ]); rand("seed", strtod(n)); T = rand(nodes, nodes) + rand(nodes, nodes...
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//Network Theorem 2 //pg no 3.7 //example 3.5 disp("When 5-A source is acting alone:"); disp("By current-division formula :"); I1=5*(2/(2+4)); printf("I1=5*(2/(2+4)) = %.2f A (down)", I1); disp("When 2-A source is acting alone:"); disp("By current-division formula :"); I2=2*(2/(2+4)); printf("I2=2*(2/(2+4)) =...
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//Realiza la eliminacion de Gauss para una matriz A y un vector b // Devuelve: B matriz triangular superior resultado de aplicar eliminación // Gaussiana a A. Realiza pivoteo parcial escalado. // Pivoteo Parcial Escalado: Busca el mejor candidato para pivote: // Calcula el mayor valor absoluto de cada fila y en ca...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 7.3 //Caption : Program to Find the Critical Pressure and the Discharge Pressure //Given Values T1=573.15;//[K] R=8314; P1=700;//[KPa] M=18.015; Gamma=...
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// gradiant function [g] = grad2 (im) // on definit une matice N,M full if 0 N=size(im,1) M=size(im,2) g=zeros(N,M,2); g(:,1 :N-1,1)= im(:,2:N)-im(:,1:N-1); g(1:M-1,:,2)= im(2:M,:)-im(1:M-1,:); endfunction
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disp('matrix A corresponding to transformation T is:') A=[-5 9;4 -7]; disp(A) disp('determinant of A is:') disp(det(A)) disp('since det(A) is not equal to zero') disp('by IMT, A is invertible') disp('hence, the inverse of A exists') disp('inverse of A is:') disp(inv(A))
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clc clear //Initalization of variables cp=0.24 h=138.8 t3=1960 //R //calculations t4d=t3-h/cp Qs=cp*(t3-t4d) work=43.9 //Btu/lb etat=work/Qs *100 //results printf("Thermal efficiency of the unit = %.1f percent",etat)
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//example-6.1 //page no-169 //given //molecular weight of CaF2 (calcium fluoride) Mw=0.079 //kg/mol //specific gravity of CaF2 sg=3.17 //density rho=sg*1000 //kg/m^3 //avogadro's number NA=6.023*10^23 //the no of lattice sites is NL=NA*rho/Mw //calcium ions/m^3 //the ionic structure of CaF2 NI=2*NL /...
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//plot log data from ceres test // clear all xdel(winsid()); clear; // CERES ODOM BATCH //load log file data = read('~/Desktop/log_file_2.txt',-1,14); //plot fig1 = figure(0); fig1.background = 8; plot(data(2:$,10),data(2:$,11),"g."); plot(data(2:$,1),data(2:$,2),"b-"); plot(data(2:$,4),data(2:$,5),"r-"); plot(data...
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clear; clc; disp("T(A,B,C,D)=A^C^+ABD+BC^D+AB^D^+ABCD^"); disp("Assume A^=x , C^=y , BD=z"); disp("Now from consensus theorem for the first three terms"); disp("BC^D is the redundant term so it can be removed"); disp("T(A,B,C,D)=A^C^+ABD+AB^D^+ABCD^"); disp("T(A,B,C,D)=A^C^+ABD+AD^(B^+BC)"); disp("we know that ...
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sce1.0 # camera eyepos 1 -3 1.5 eyedir -0.2 1 -0.3 eyeup 0.0 0.0 1.0 wdist 1.0 fovy_deg 45 nx 400 ny 300 #options max_recursion 4 aasample 0 # scene background 0 0 0.6 ca 0.1 0.1 0.1 rotate 36 0 0 1 { #ground cr 0.4 0.5 0.4 cp 0.4 0.4 0.4 triangle -3 -10 0 3 -10 0 3 10 0 triangle -3 -10 0 3 10 0 -...
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load RegisterFile.hdl, output-file RegisterFile.out, compare-to RegisterFile.cmp, output-list time%S1.4.1 rr1%D1.2.1 rr2%D1.2.1 wr%D1.2.1 wd%D1.5.1 load%B2.1.2 rd1%D1.5.1 rd2%D1.5.1; set rr1 0, set rr2 1, set wr 0, set wd 10, set load 1, tick, output; tock, output; set rr1 0, set rr2 1, set wr 1, set wd 11, set ...
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//Example 13.1, Page no 471 clc m=9.11*10^-31//in kg h=6.63*10^-34//in j-s ef=4.72*1.60*10^-19//in J n=%pi*(((8*m)/h**2)^(3/2))*((ef**(3/2))/3) printf("\n The number of electron per unit volume in lithium is %e /m^3",n)
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//Fuels and Combustion// //Example 8.10// C=810;//weight of carbon in 1kg of coal sample in grams// O=80;//weight of oxygen in 1kg of coal sample in grams// S=10;//weight of Sulphur in 1kg of coal sample in grams// N=10;//weight of nytrogen in 1kg of coal sample in grams// H=50;//weight of hydrogen in 1kg of coal...
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clc;funcprot(0);//EXAMPLE 3.9 // Initialisation of Variables p1=1;.....................//Pressure in bar t1=300;......................//Temperature in K Q=1500;.....................//Heat added in kJ/kg r=8;.......................//Compression ratio Cv=0.72;....................//Specific heat at constant volume ...
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gpc_wtc.sce
// Updated(19-7-07) // 12.8 A=[1 -0.44]; dA=1; B=[0.51 1.21]; dB=1; C = [1 -0.44]; dC = 1; k=1; N1 = 0; N2 = 2; Nu = 0; rho = 1; getf gpc_Nc.sci; [K,KH1,KH2,Tc,dTc,Sc,dSc,R1,dR1] = ... gpc_Nc(A,dA,B,dB,C,dC,k,N1,N2,Nu,rho)
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clc // Given that theta = 0.3 // Angle of wedge in degree lambda1 = 6e-5 // Wavelength of light in cm lambda2 = 4.5e-5 // Wavelength of light in cm r = 90 // Radius of curvature in cm // Sample Problem 33 on page no. 120 printf("\n # PROBLEM 33 # \n") printf("\n Standard formula used \n D_m^2 -D_n^2 = 4*p*r*...
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clc; clear all; disp("contact surface temperature") disp("The rate of heat flow at a surface x =0 is given by") disp(" Q = -k*A*delT/(%pi*a*tau)^0.5") disp("Heat received by each unit area of contact surface from the body at a temperature t1 is") disp("Q = -k1*A*(t1-ts)/(%pi*a1*tau)^0.5") disp("Heat received by ...
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clc // initialization of variables clear S_u=1300 //MPa K_C=69 // MPa sqrt(m) SF=2.2 //calculations S_c=S_u/2.2 a=1/%pi*(K_C/S_c)^2 printf('a = %.2f mm',a*10^3)
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2018-07-12T12:35:54
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sce
convmtx1.sce
h=[1 2 3 4 56]; n=6; A=convmtx(h,n); disp(A);
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[ "Apache-2.0" ]
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TaoReiches/Tao
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2021-01-17T18:39:43
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Models.tst
${ // Enable extension methods by adding using Typewriter.Extensions.* using Typewriter.Extensions.Types; Template(Settings settings) { settings.OutputFilenameFactory = file => { var dirIndex = file.FullName.LastIndexOf(file.Name); var dir = file.FullName.Substr...
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pathname=get_absolute_file_path('21_3.sce') filename=pathname+filesep()+'21_3data.sci' exec(filename) clear Lc1=Lc+ 0.1*10^3,Lc2=Lc- 0.1*10^3; Mx1=-Sy*(L-Lc1);//moment at section1 L31=(L1*(L-Lc1)+ L2*Lc1)/L;//leangth of CS1 B31=(B1*(L-Lc1)+ B2*Lc1)/L;//breadth of CS1 Mx2=-Sy*(L-Lc2);//moment at section2 L32=(L...
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2016-09-27T05:12:48
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pmusic5.sce
x=[1 2 3 4 5 6 2 3 7]; p=3; fs=4e6; nfft=6; [S,f] = pmusic(x,p,nfft,fs) disp(S); disp(f); //output // // 6.4454494 // 0.5509978 // 0.2413610 // 0.1686702 // // 0. // 666666.67 // 1333333.3 // 2000000. // //
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maxxonair/BlueBook-Descent-and-Landing-Analysis-Toolkit-DaLAT
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.sci
clear RootFolder='C:\Users\Max Braun\Documents\Max_Braun_2017\05_Tools\LandingSim\LandingSim-3DOF\burst_container\'; filename = fullfile(RootFolder, 'burstres_20.txt'); filename2 = fullfile(RootFolder, 'burstres_30.txt'); BB_ascent_5_6 = csvRead(filename, " "); BB_ascent_6_6 = csvRead(filename2, " "); //-------------...
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3_5.sce
clc //initialisation of variables v= 20 //ft/sec d= 2 //in w= 62.4 //lb/ft^3 g= 32.2 //ft/sec^2 //CLACULATIONS A= (%pi/4)*(d^2/144) hp= (w*A*v^3)/(2*g*550) //RESULTS printf (' horse power = %.3f hp ',hp)
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example8_21.sce
//Chapter 8 //Example 8_21 //Page 192 clear;clc; l=214; vsag=2.35; w=1.125; ww=1.5; area=3.225; bs=2540; wt=sqrt(w^2+ww^2); t=bs*area; s=vsag*wt/w; f=t*8*s/(wt*l^2); printf("Total weight of 1m length of conductor = %.3f kg \n\n", wt); printf("Working tension = %.0f/f kg \n\n",t); printf("Slant sag = %.2f m \n\n", s...
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//Exa Misc 8.1 clc; clear; close; //given data format('v',5); L2=0.4;//in mH C=0.004;//in µF f=120;//in KHz L1=1/(4*%pi^2*(f*10^3)^2*C*10^-6)-L2*10^-3;//in H disp(L1*10^3,"Value of L1(in mH) :");
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//Exa 9.2 clc; clear; close; //given data Vreg=8;//in volts as IC 7808 is given IL=100;//in mA IR=100;//in mA Iq=0;//in mA RL=50;//in ohms // let find the value of resistor to deliver required current R=Vreg/(IR*10^-3);// in ohms; so current must be in amperes disp(R,"Required Resistance in ohms : "); disp...
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clc //initialisation of variables g= 32.2 //ft/sec^2 Cd= 0.62 L= 7.573 //ft H= 1.2 //ft S= 2.85 //ft //CALCULATIONS Q1= 2*Cd*sqrt(2*g)*L*H^1.5/3 Q2= 3.33*L*H^1.5 Q3= sqrt(2*g)*L*H^1.5*(0.405+(0.00984/H)) He= H+0.004 Q4= (3.227+0.435*(He/S))*L*He^1.5 //RESULTS printf ('Q = %.2f cuses ',Q1) printf ('\n Q ...
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//Variable declaration rho=47*10**-2 e=1.6*10**-19 mu_n=0.39 mu_p=0.19 E=10**4 //Calculations ni=1/(rho*e*(mu_n+mu_p)) Dh=mu_p*E De=mu_n*E //Results printf('ni = %0.3f *10**19 /m**3 \n',(ni/10**19)) printf('Drift velocity of holes %0.3f ms**-1 \n',Dh) printf('Drift velocity of electrons= %0....
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OSA -----------------------
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// from fig. 22.18A clc // Three gear ratios between input and intermediate shaft nmax = 1400 // maximum speed in rev/min. i1 = 1/1 i2 = 1/1.26 i3 = 1/(1.26)^2 // The two ratios between intermediate and output shaft i4 = 1/1 i5 = 1/(1.26)^3 // number of teeth for input and intermediate shaft t1 = 27/27 t2 =...
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//Variable declaration n1=1.45; //refractive index of core n2=1.44; //refractive index of cladding //Calculation delta=(n1-n2)/n1; //fractional refractive indices change //Result printf('fractional refractive indices change is %0.3f *10**-3 \n',(delta*10**3))
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//Find the value of RB that just results in saturation if (a) the capacitor is present, and //(b) the capacitor is replaced with a short circuit. //Solved Example Ex3.19 page no 91 clear clc b=50 Vbeq=0.3 //V Vcc=12//v Vs=2//v Rc=4//Kohm Rs=100//Kohm Vce=0.2 Icq=(Vcc-Vce)/Rc printf("\n Icq = %0.2f mA...
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clear // //case a I=12/(2+((12*24)/(36))) //values taken from circuit I1=I*(24/(36)) I2=I*(12/(36)) printf("\n i= %0.1f A",I) printf("\n i1= %0.1f A",I1) printf("\n i2= %0.1f A",I2) //case b power=(I**2)*2 printf("\n power consumed by 2 ohm resistor= %0.1f W",power) power=(I1**2)*12 printf("\n power consumed by 12 ...
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// chapter 9 // example 9.16 // Find the mobility and density // page 279 clear; clc; //given RH=3.66E-4; // in m^3/C (Hall coefficient) rho=8.93E-3; // in ohm-m (resistivity) e=1.6E-19; // in C (charge of electron) // calculate u=RH/rho; // calculation of mobility n=1/(RH*e); // calculation of density pri...
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//Fluid Systems - By Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.3 //To Calculate The Maximum Speed at which pump may be run and Determine Resultant Suction Head at Begining, Middle and End of the Stroke. clc clear //Given Data:- D=150; //Diameter of Plunger, mm L=250; ...
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description = Test SLA with average and group availability for two hosts logfile = average.log global_vars { start_time = 1199200000 end_time = 1199230000 host_name { testhost testhost2 } } test 1: using SLA - Group availability { use_average = 0 correct { TOTAL_TIME_UP = 20000 TOTAL_TIME_DOWN = 10...
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clc; clear; printf("\t\t\tChapter8_example1\n\n\n"); // Determination of the heat transferred to the wall. // air properties at (400+120)/2 =260 degree F = 720 degree R from Appendix Table D1 rou= 0.0551; // density in Ibm/cu.ft cp=0.2420; // specific heat BTU/(lbm-degree Rankine) v= 27.88e-5; // viscosity in sq.ft/s...
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//ex10 //Second-Law Analysis of an Otto Cycle clear clc //In Example 9–2, various quantities of interest were given r=8;//constant ratio T0=290;//temp in K T1=290;//temp at state 1 in K T2=652.4;//temp at state 2 in K T3=1575.1;//temp at state 3 in K P2=179.97;//pressure at state 2 in kPa P3=434.5;//pressur...
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clear;lines(0); F=randpencil([],[1,2],[1,2,3],[]); F=rand(6,6)*F*rand(6,6);[E,A]=pen2ea(F); [Si,Pi,Di]=penlaur(F); [Bfs,Bis,chis]=glever(F); norm(coeff(Bis,1)-Di,1)
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/CPU.tst load CPU.hdl, output-file CPU.out, compare-to CPU.cmp, output-list time%S0.4.0 inM%D0.6.0 instruction%B0.16.0 reset%B2.1.2 outM%D1.6.0 writeM%B3...
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clear; clc; printf("\t\t\tExample Number 5.11\n\n\n"); // high speed heat transfer for a flat plate // Example 5.11 (page no.-257-259) // solution L = 0.7;// [m] length of flat plate W = 1;// [m] width of plate // flow conditions are M = 3; p = 101325/20;// [Pa] T = -40+273;// [degree celsius] Tw = 35;/...
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clc; clear all; V = 120000; // Volume of hall in cubic meters T = 1.5; // Reverberation time TSA = 25000; // Total absorbing surface area in square meters A = (0.163*V)/T TA = A/TSA;//The average absorbing power of the surface disp('Sabine',TA,'The average absorbing power of the surface is ') // Slight variatio...
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//example 2.30// //hexadecimal to binary conversion// clc //clears the screen// clear //clears already existing variables// x=hex2dec('29FA') //hexadecimal to decimal conversion// a=dec2bin(x) //decimal to binary conversion// disp('conversion of hexadecimal given no to its binary form is:') disp(a) //answer...
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// Example 6-2 // Root Locus clear; clc; xdel(winsid()); //close all windows s = %s; H = syslin('c',s + 2, s^2 + 2*s + 3); evans(H,10); xgrid(); a = gca(); a.box = "on"; a.data_bounds = [-6 -3; 2 3]; a.children(1).visible = 'off'; xtitle('Root locus of G(s) = (s + 2)/ (s^2 + 2*s + 3)');
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//chapter12 //example12.8 //page245 V_CC=20 // V R_B=100 // kilo ohm R_C=1 // kilo ohm V_BE=0.7 // V gain_beta=100 // we know that R_B=(V_CC-V_BE-gain_beta*R_C*I_B)/I_B so we get I_B=(V_CC-V_BE)/(R_B+gain_beta*R_C) I_C=gain_beta*I_B V_CE=V_CC-I_C*R_C printf("operating point is %.3f V, %.3f mA \n",...
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clear; clc; //Example 1.1 //Caption : Program to find transistor currents for npn transistor. //Given Values //Silicon Transistor B=100; //Beta Ico=20; //in nA Rc=3; Rb=200; Vbb=5; //in V Vcc=10; //in V Vbe=0.7; //in Active region //Applying KVL to base circuit //Vbb+Rb*Ib+Vbe=0 Ib=(V...
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clc clear //Initialization of variables tin=298 //K tout=273 //K tout2=308 //K tin2=294 //K //calculations eta1=(tin-tout)/tin eta2=abs((tin2-tout2)/tin2) //results printf("Efficiency in case 1 = %.3f",eta1) printf("\n efficiency in case 2 = %.3f",eta2)
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//chapter 16 Ex 3 clc; clear; close; //let pipes be A and B t12=12; //time taken by A and B to fill tank together AB1hour=1/t12; //part filled by both in 1 hour //Let reservoir be filled by pipe 1 in x hours, thus other in (10+x)hours, thus the equation that is formed is (1/x)+1/(10+x)=1/12; on solving we get...
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//example 15.4 //calculate the economical depth of cutting for cross section of channel clc;funcprot(0); //given B=5; //bed width t=2; //top width of banks h=2.92; //heigth of banks from bed n=1.5; //sectional area of digging=sectional area of two banks //B...
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clc apsilen = 11.9*8.85*10^-14 disp("apsilen = "+string(apsilen)+"F/m") //initializing value of relative permitivity phi_b = 0.66 disp("schottky barrier heights(in volts) = phi_b= "+string(phi_b)+"eV")//initializing value of schottky barrier heights(in volts) mo = 9.1*10^-31 disp("mo = "+string(mo)+"kg") //initia...
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//Ex:1.16 clc; clear; close; r=1000;// distance in m l=1;// length in m Irms=5;// current in Amp f=1;// frequency in MHz y=300/f;// Wavelength in m le=(2/%pi)*l;// effective length in m Erms=(120*%pi*le*Irms)/(y*r);// field strength in V/m printf("The field strength = %d mV/m", Erms*1000);
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clc; clear; function y = funcao(valor) y = (valor^2);//formula da funcao endfunction function y2 = derivada(valor) y2 = (2*valor);//formula da derivada endfunction xi = 1; iter = 0; while(iter < 10) x = xi - (funcao(xi) / derivada(xi)); erro = abs(funcao(xi)); iter = iter + 1; xi = x; end disp...
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function dac_info = get_dac_info(hwid) c_params_struct = struct(.. "c_number", [],.. "c_range_desc", [],.. "c_range_value", [],.. "c_range", []); c_params_e1xxx = list(); c_params_e2000 = list(); c_params_e1xxx(1) = struct(.. "c_number", [1;2],.. "c_range_desc", ["0-5...
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//Exa:3.2 clc; clear; close; //Given: //V=12*sin(6*10^8*t+5*sin(1250)*t); //Compairing it with V=A*sin(wc*t+mf*sin(wm)*t); wc=6*10^8; wm=1250; mf=5; A=12; R=10; Vrms=A/sqrt(2); fc=wc/2/%pi; fm=wm/2/%pi; P=Vrms^2/R; printf("\n Fc = %f MHz",fc/10^6); printf("\n Fm = %fHz",fm); printf("\n Power = %fW...
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function [r]=%lns(l1,l2) r=%t
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// Regulation at laggiing leading and unity power factors clc; clear; ol=0.01;// Ohmic loss is 1% of the output // Output = V*I; Ohmic loss =(I^2)*R //(I*R)/V = 0.01 rd=0.05; // Reactance drop is 5% of the output voltage // Power Factors pf1=0.8;// lag pf2=1; // unity pf3=0.8;// lead deff('y=an...
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clc //initialisation of variables p= 0.08 //atm //CALCULATIONS a= (1-p)/(p+1) //RESULTS printf ('fraction = %.2f ',a)
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//Caption:Chi-square Distribution[Sampling Distributions of Variance] //Example7.7 //Page210 clear; clc; n =20; //sample size Sig = 81;//variance of mean annual sales of the population in Lakhs S2 = 125;//Variance of mean annual sales of the population in Lakhs Df = n-1; //degrees of freedom X = ((n-1)*S2)/Sig...
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction j...
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// chapter 7 example 8 //----------------------------------------------------------------------------- clc; clear; // given data S = 5*10^-2; // inter spacing distance lamda = 6*10^-2; // operating wavelength in cms phi_Az = 25 // angle in azimuth direction phi_E = 35 ...
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// SAMPLE PROBLEM 7/6 clc;funcprot(0); // Given data m=70;// The mass of bent plate in kg omega=30;// rad/s x_A=0.125;// m y_A=0.100;// m x_B=0.075;// m y_B=.150;// m d_x=0.0375;// m d_y=0.125;// m d_z=0.075;// m // Calculation // Part A m_A=x_A*y_A*m;// kg m_B=x_B*y_B*m;// kg I_xxA=((m_A/12)*(y_A^2+x...
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//Exa 2.3 clc; clear; close; format('v',7); //Given Data WA=20;//KJ QA=15;//KJ QB=10;//KJ U2subU1=QA-WA;//change in internal energy in KJ disp(U2subU1,"Change in internal energy in KJ : ");
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction j=%i Pout=10D+3//output of the motor at full load e=.85//efficiency at full load P...
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clear// //Variable Declaration d=3*4**-1 //Rivet diameter in inches t=7*8**-1 //Thickness of the plate in inches tau=14000 //Shear stress limit in psi sigma_b=18000 //Normal stress limit in psi //Calculations //Design Shear Stress in Rivets V=tau*(d**2*(%pi/4))*4 //Shear force maximum allowable in lb //De...
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//chapter19 //example19.12 //page424 It=8.93 // A Ic=8 // A // we know that (It/Ic)^2=1+m^2/2 so making m as subject we get m=(2*((It/Ic)^2-1))^0.5 printf("modulation factor = %.3f or %.3f percent \n",m,m*100)
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// Example 6.5 format('v',5) clc; clear; close; // given data R1= 10*10^3;// in Ω R2= 2.2*10^3;// in Ω R_C= 3.6*10^3;// in Ω V_CC= 10;// in V I_C= 1.1*10^-3;// in A // The base voltage V_B= R2*V_CC/(R1+R2);// in V // The collector voltage V_C= V_CC-I_C*R_C;// in V disp(V_B,"The base voltage in V is : "...
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clc; clear all; H=1E6;//magnetic field intensity in A/m X=-0.8e-5;//susceptibility u0 = 4e-7*%pi; M=X*H;//magnetization in A/m B=u0*(M+H);//flux density in Wb/m^2; disp('A/m',M,'magnetization is:') disp('Wb/m^2',B,'flux density is:')
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