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clc clear //INPUT DATA //H2+ 0.5(O2+3.773 N2)= H2O+1.887 N2 ;//CHEMICAL EQUATION //22.3 H2 +18.606 O2 +70.2 N2 = 22.3 H2O+ 7.44 O2+70.2 N2 ;//EXHAUST GASES CHEMICAL EQUATION //CALCULATIONS xs=2*1/(0.5*32+0.5*3.773*28);//air fuel ratio From the combustion equation xa=(1*2)/(0.8343*32+3.148*28);//air fuel ratio ...
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clc V=150+180*%i; //Assigning values to parameters I=5-4*%i; Z=V/I; disp("Ohms",Z,"Impedance"); [Ro,Theta]=polar(Z); P=V*I*cos(Theta); [r,t]=polar(P); disp("Watts",r,"Power consumed");
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disp('To find the eigenvalues of matrix A.') disp('A=') a=[5 3;-4 4] disp(a) disp('Eigen values of A are:') disp(spec(a)) disp('Hence, A has no real eigenvalues.')
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// x=[4]; b=blackman(x); disp(b); //output //- 1.388D-17 // 0.63 // 0.63 // - 1.388D-17 //
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-9,Example 3,Page 318 //Title: Fugacity and fugacity coefficient //================================================================================================================ clear clc //INPUT T=427.85;/...
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//EXAMPLE 3.2.B clc; Syms s t w=2; laplace(cos(w*t),t,s)
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verdelen V;SBJV;SG;PRS verdelen V;IND;SG;2;PST verdelen V;NFIN verdelen V;IND;PL;PRS verdelen V;IMP;SG verdelen V.PTCP;PST verdelen V;IND;SG;3;PRS verdelen V;IND;SG;1;PST verdelen V;SBJV;PL;PST verdelen V;IND;SG;2;PRS verdelen V;IND;PL;PST verdelen V;SBJV;PL;PRS verdelen V;IND;SG;3;PST verdelen V;IMP;PL verdelen V;IND;...
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// Scilab Code Ex7.8: : Page-7.13 (2009) clc; clear; NA = 0.16; // Numerical aperture of the step index fibre n1 = 1.50; // Refractive index of the core material d = 65e-006; // Diameter of the core, m lambda = 0.9e-006; // Wavelength of transmitted light, m V = %pi*d/lambda*NA; // V-number for the...
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clc; clear; lbm=9999; //cm, measured length of bridge lrm=9;//cm, measured length of rivet lbt=10000;//cm, true length of bridge lrt=10;//cm,true length of rivet //calculating true error below; Etb=lbt-lbm;//cm, true error in bridge Etr=lrt-lrm;//cm, true error in rivet //calculating percent relative error bel...
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//Exa 2.1 clc; clear; close; //Given data : n1=1.40;//refractive index delta=1;//relative refractive index difference in % //Formula : n2/n1=1-delta n2=n1*(1-delta/100);//refractive index(unitless) disp(n2,"Refractive index of cladding : ");
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T1=20 //C T2=100 //C T3=90 //C T4=30 //C P=3 //bar V=5 //L R=0.08314 //L.bar/mol.K T=363 //K ndot=100 //mol/min
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//characteristic impedance //given clc Zl=300//ohm Zo=75//ohm//of the line SWR=1//the source impedence is equal to characteristic impedance of the line Zt=sqrt(Zl*Zo) disp(Zt,'the characteristic impedance in ohm')
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//Example 12.1, page 435 clc c=9*10^9 cm=1.6*10^-19 d=2.4*10^-10//in m v=(c*cm*cm)/d e=v/(1.6*10^-19)//in J printf("\n The energy is %e ev",e)
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); #function density(xc,yc,zc) #{ # vl=exp(-0.5*sqrt(xc*xc+yc*yc+zc*zc))*xc; # return(vl); #} function density(xc,yc,zc) { rd=sqrt(xc*xc+yc*yc+zc*zc); f1=(6-rd)*exp(-0.5*rd); vl=f1*(2*sqr(zc)-(sqr(xc)+sqr(yc))); return(vl); } function denscolor(pt) { ...
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//Page Number: 299 //Example 5.14 clc; //Given f=10D+9;//hz v0=600;//V vr=250;//V ebym=1.759D+11; //Repeller space n=1; l=sqrt((ebym*(n+(3/4))^2*(vr+v0)^2)/(8*f^2*v0));//m disp('mm',l*1000,'Repeller space:');
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//ques28 syms s t f=integ(exp(-s*t)*exp(-t),t,0,2); disp('Laplace of given function is'); disp(f);
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clc funcprot(0) //if variables are redefined do nothing format('v',10) function [A,b]=leastsquares(A,b) x=(A'*A)\(A'*b); disp(x,'x = '); C=x(1,1); D=x(2,1); disp(C,'C = '); disp(D,'D = '); disp('the Line of best fit is b=C+Dt'); endfunction function main() disp('Coefficient Matr...
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clc clear //DATA GIVEN IP=35; //power developed by the engine in kW m=284; //flow rate in kg/h p1=15; //steam inlet pressure in bar p2=0.14; //condenser pressure in bar //At 35 bar and 25 deg celsius from steam tables h1=2923.3; /...
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// Example 13.4 //Write a function to insert a given item before a specified node known as //key node. funcprot(0); //Create the list function [List]=create(list1) global List; // Create the current node list1.number=input("Input a number(Type -999 to end); "); if list1.num...
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clc clear //Initialization of variables rpm=60 rho=2 //slugs/ft^3 mu=3.5e-5 //lb-sec/ft^2 D=4/12 //ft r=2 //ft //calcualtions V=rpm*2*%pi/60 *2 Nr=V*D*rho/mu Cd=1.1 Fd=Cd*%pi/4 *(D)^2 *0.5*rho*V^2 T=2*Fd*r w=rpm*2*%pi/60 hp=T*w/550 //results printf("Horsepower required = %.2f hp",hp)
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// Scilab Code Ex4.18: : Page-4.34 (2009) clc; clear; theta = 15.2; // Angle through which plane of polarization is rotated, degrees S = 65; // Specific rotation of sugar solution, degrees l = 15; // Length of sugar, cm // As S = 10*theta/(l*c), solving for c c = 10*theta/(l*S); // Concentration of ...
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//Problem 43.14:The circuit diagram of an air-cored transformer winding is shown in Figure 43.17. The coefficient of coupling between primary and secondary windings is 0.70. Determine for the circuit (a) the mutual inductance M, (b) the primary current I1 and (c) the secondary terminal p.d. //initializing the variable...
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// ############################################################################ // Permite obtener una FT a partir de sus polinomios numerador y denominador // o de la representacion en espacio de estados. // Sintaxis: // sys=zpk(g) : con g un cociente de polinomios o un sistema en espacio de estados. // sys=zpk(num,d...
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SCENARIO_EXTENSION Masterarbeit LAYERID 1 ROAD ROADID 1 LANE LANEID 1 LANETYPE pedestrian ENDLANE LANEID 2 LANETYPE bicycle ENDLANE LANEID 3 LANETYPE car ENDLANE ENDROAD ENDLAYER ENDSCENARIO_EXTENSION
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clc //Initialization of variables wl=256*10^-9 //m t=1 //mm C=0.050 //mol/L T=0.16 t2=2 //mm //calculations E=-log10(T) /(C*t) A1=-log10(T) A2=E*C*t2 Tr=10^(-A2) //results printf("Transmittance = %.3f",Tr)
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//chapter12 //example12.20 //page256 Vcc=8 // V Rb=360 // kilo ohm Rc=2 // kilo ohm gain_beta=100 Vbe=0.7 // V // when Ic=0, Vce=Vcc i.e. Vce=8 and when Vce=0, Ic=Vcc/Rc i.e. Ic=8/2 // so equation of load line becomes Ic=-0.5*Vce+4 clf() x=linspace(0,8,5) y=-0.5*x+4 plot2d(x,y,style=3,rect=[0,0,9,5])...
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//variable initialization c=3*10^8; //Speed of sound (meter/second) M=1.97*10^30; //Mass of sun (kg) R=1.5*10^11; //Mean radius of the earth orbit (meter) sigma=1.4*10^3; //Solar energy...
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//Example 5.1, Page number 5.28 clc;clear;close //variable declaration n1=1.50 //Core refractive index n2=1.47 //Cladding refractive index //Calculations C_a=asin(n2/n1) //Critical angle N_a=(n1**2-n2**2)**(1/2) // Numerical Aperture A_a=asin(N_a) // degree //Results printf("The Crit...
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function t = randExp(n, lambda) t = -log(1 - rand(n,1)) / lambda endfunction
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clear flag=1 clc mode(-1) printf("Example 7 : Show the method of file handling using the od command \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") printf("\nHere all instructions are preloaded in the form of a dem...
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clc clear //Input data Is=230 //Specific Impulse in sec m=1 //Propellent flow in kg/s g=9.81 //Acceleration due to gravity in m/s^2 //Calculation F=m*Is*g //Thrust in N //Output printf('Thrust is %3.1f N',F)
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clc clear //input p=6;//number of poles n=72;//number of slots n1=10;//conductors per slot b=0.01;//flux per pole in weber f=50;//frequency in hertz phi=170;//pitch of coil in electrical degrees kf=1.11;//form factor for sinusoidal forms //calcultions n2=n/p;//number of slots per pole n3=n2/3;//number o...
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clear; function [X,n] = newton(x0,esp,f,df) maxIter = 100 X = [x0] x = x0 n = 1 while (abs(f(x)) >= esp) & (n < maxIter), x = x - f(x)/df(x) X(n+1) = x n = n + 1 end endfunction // define espilon //esp = 0.01 //esp = 0.0001 esp = 0.00000001 // ==== testcase 1 ==== function a = f1(x)...
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errcatch(-1,"stop");mode(2);//23.4 p=40//in cm q=-(2*p) x=(1/p)-(1/q) f=1/x disp(f,"The focal length in cm=") //Answer given in book is wrong exit();
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//example 5.13 //calculate formation constant of acquifer using theis method clc;funcprot(0); //given Q=2500; //discharge(l/min) r=60; //distance of observation well from acquifer tmin=[1 1.5 2 2.5 3 4 5 6 8 10 12 14 18 24 30 40 50 60 80 100 120 150 180 210 240]; //time in minutes s=[0.2 0.26 0....
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clc; x=[1 1 1 1]; h=[1 1 1]; Xz=0; z=poly(0,"z"); for i=1:length(x) Xz=Xz+x(i)*z^(1-i); end Hz=0; for i=1:length(h) Hz=Hz+h(i)*z^(1-i); end Yz=Xz*Hz; y=coeff(numer(Yz)) disp(y,"y[n]=")
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clc;clear; //Example 8.9 //given data um=0.6;//mass adsoption coeffcient in cm^2/g p=2.7;//density of aluminium in g/cm^3 //calculations u=p*um; disp(u,'linear adsorption coefficent of aluminium in 1/cm'); T=0.693/u disp(T,'the hvl in cm'); x=(log(20))*(1/u); disp(x,'the thickness in cm')
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clc //initialisation of variables za= 16 //ft h1= 2 //ft h2= 3 //ft g= 32.2 //ft/sec^2 //CALCULATIONS vc= sqrt(2*g*(za-h1-h2)) vb= vc*(h1/(2*h1))^2 r= -h1-h2-(vb^2/(2*g)) r1= r+34 //RESULTS printf ('pressure head at B= %.1f ft lb',r1)
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// Exa 6.6 format('v',6); clc; clear; close; // Given data L= 15;// in µH L= L*10^-6;// in H C1= .004;// in µF C1= C1*10^-6;// in F C2= .04;// in µF C2= C2*10^-6;// in F C= C1*C2/(C1+C2);// in F f= 1/(2*%pi*sqrt(L*C));// in Hz disp(f*10^-3,"Frequency of oscillations in kHz is : ")
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//We have included all posibilities that can be there for ALU load ALU8.hdl, output-file ALU8.out, compare-to ALU8.cmp, output-list x%B1.8.1 y%B1.8.1 signed%B3.1.3 opcode%B3.3.3 out%B1.8.1 of%B3.1.3 eq%B3.1.3; set opcode %X0, set x %Xaa, set y %Xaa, eval, output; set opcode %X1, set x %Xab, set y %Xba, ev...
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clear; clc; printf("\t Example 6.12\n"); d=.22; //density of dry pulp in g/cc; Ls=1.125*10^-2*.22*10^3; //mass of bone dry solid ais the drying surface A=1.5*1.5*2; //both upper surafce and lower surface are exposed v=1.5*1.5*.5; //volume of...
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//Chapter 4: Radiation //Example 4-4.2 clc; //Variable Initialization v = 3e8 //Speed of light(m/s) f = 10e6 //Frequency (Hz) //Calculation w = 2*%pi*f //Angular frequency(rad/s) r = v/w //Distance (m) //Result mprintf("The distance for the specified condition is %.2f m",r)
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clear // //node eqns are obtained form the figure printf("\n va=8.33V and vb=4.17V") i=8.33/(8) printf("\n current through 8 ohm resistor is= %0.1f A",i)
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//Inilitization of variables Lab=12 //m Mc=40 //kN-m Md=10 //kN-m Me=20 //kN-m Fe=20 //kN //force acting at point E //Calculations Xa=-(Fe) //kN //take sum Fx=0 Rb=(Md+Me-Mc)/Lab //N //take moment at A Ya=-Rb //N //take sum Fy=0 //Results clc printf('The vertical reaction (upwards) at A is %f kN \n',Ya) p...
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i have 18 minutes to tell you what happened over the past six million years all right we all have come from a long way here in africa and converged in this region of africa which is a place where 90 percent of our evolutionary process took place and i say that not because i am african but it s in africa that you find t...
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//Anti Imaging Filter considerations Ap=0.5;//passband attenuation fp=20;//passband edge frequency As=60;//stopband attenuation S=42.1; fs=S-fp;//stopband edge frequency e=sqrt(10^(0.1*Ap)-1); e1=sqrt(10^(0.1*As)-1); n=(log10(e1/e))/(log10(fs/fp)); n=ceil(n)//design of nth order butworth filter //(b)Assuming ...
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A=4*%pi*10^-7;N=300;V=120; R=6;G=5*10^-3;Ag=6*6*10^-4; Lg=2*5*10^-3; Vo=2*6*6*5*10^-7; I=V/R Bg=(A*N*I)/(2*G) Wf=(Bg^2)/(2*A)*(Vo) Fm=(Bg^2)/(2*A)*(2*Ag) L=(N^2*A*Ag)/(Lg) Irms=V/(sqrt(6^2+15.34^2)) Brms=(A*N*Irms)/(2*G) Fm=(Brms^2)/(2*A)*(2*Ag)
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// to calculate ratio of generator speed to motor speed clc; V=220; P=4000; I_a=P/V; r_a=.4; //armature resistance E_ag=V+I_a*r_a; E_am=V-I_a*r_a; a=1.1; //phi_m/phi_g n=(E_ag/E_am)*a; disp(n,'n_g/n_m');
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function [stk,txt,top]=sci_stem() // Copyright INRIA txt=[] if rhs==3|stk(top)(5)=='10' then style=linetype(stk(top)(1)) top=top-1 rhs=rhs-1 else style=-1 end style=sci2exp(style) if rhs==1 then x=gettempvar(1) if isname(stk(top)(1)) then y=stk(top)(1) else y=gettempvar(2) txt=y+' = '+stk(top...
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//Example7.9 // to calculate upper and lower cut-off frequency of the band pass filter clc; clear; close; R1 = 10*10^3 ; //K ohm R2 = 10 ; //K ohm C1 = 0.1*10^-6 ; // uF C2 = 0.001 ; //uF // the lower cut-off frequency of band pass filter is fLC = 1/(2*%pi*R1*C1); disp('The lower cut-off frequency FLC of ...
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Name=Stral's Luck Tester PlayerCharacters=Quaker BotCharacters=Quaker Bot Long Strafes.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Quaker AddedBots=Quaker Bot Long Strafes.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=lucktester.map MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=t...
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clc //initialisation of variables L= 12 //ft Po= 100 //kips e= 2 //ft ys= 42000 //psi A= 11.77 //in^2 rmin= 195 //in Zmin= 11.0 //in^3 lbyr= 74.2 stress= 18 //ksi //CALCULATIONS P= (stress-(Po/A)/((1/A)+((e*12)/Zmin))) //RESULTS printf ('Additional Load= %.2f kips ',P)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//ques-18.30 //Calculating equilibrium constant for the given reaction clc T=278;//temperature (in K) S=-333.3;//entropy change (in J/K/mol) R=8.31;// J/K/mol h1=-110.5;//heat of formation for CO (in kJ/mol) h2=-74.8;//heat of formation for methane (in kJ/mol) h3=-286;//heat of formation for water (in kJ/mol) ...
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/* Créateur: Jinshan GUO et Anais Debureaux */ exec(fullpath(pwd() + '\TP4.sci'),-1); disp("===========Exo1-Factorisation de Cholesky==========="); A1 = [15 10 18 12;10 15 7 13;18 7 27 7;12 13 7 22]; [C]=cholesky(A1); //Exo1_a disp("Resulat_Exo1(a)_C=",C); disp("Si A1 == A1'':", A1 == A1'); disp("Car A1...
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//Determine the control limits for X -R chart. //page no 119 clear clc; USL = 175; LSL = 135; n = 5; K = 50; X1 = 7660; R1=880; X2=X1/K; R2=R1/K; A2 = 0.58; d2 = 2.326; D3 = 0.0; D4 = 2.11; //Control limits for R-chart UCL = D4*R2; mprintf("\UCL = %.2f \n",UCL); LCL = D3*R2; mprintf("\LCL = %.2f \n"...
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function d = distQuat(q1,q2) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: //Outputs the quaternion qOut = q1*q2; //INPUT //q1 : quaternion. Row vector //q2 : quaternion. Row vector //OUTPUT //d : distance between the two quat...
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clc clear printf("Example 1.4 | Page number 10 \n\n"); //find the steam pressure. //Given Data Pg = 12E5 //in N/m^2 //inlet gauge pressure Pvac = 75 / 1000 //in m Hg //exit gauge pressure atmosphericPressure = 760 / 1000 //in m Hg //atmospheric pressure density = 13.6 * 10^3 //kg/m^3 //density of mercury g =...
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function [M,V,CT]=train(Image) I_gray=rgb2gray(Image); seuil=imgraythresh(I_gray); I_bw=~im2bw(I_gray,seuil); str=imcreatese('ellipse',2,2); I_erode=imerode(I_bw,str); I_dilate=imdilate(I_bw,str); M=[]; V=[]; [L,N]=imlabel(I_dilate); [A,BB,CT] = imblobprop(L); for ...
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// z: [y u] (Column matrix) // ---- ---- // | | // | ryy(0) ryy(1) ... ryy(len) | // | | // v = | ruy(0) ruy(1) ... ruy(len) | // | | // | ryu(0) ryu(1) ... ryu(len) | // ...
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a=0.21;//dissociation constant// P=1;//pressure in atm// Kp=(a^2*P)/(1-a^2); printf('\nKp for the reaction=Kp=%f',Kp); printf('\nP=1atm=0.4+PCOCl2+PCO+PCl2\nsum of pressure reactants=0.6atm\nCOCl2=CO+Cl2\nHere P is the total pressure due to all the participants of the reaction and is equal to 0.6atm.'); P1=0.6; a...
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9q1.sce
clc //initialisation of variables Ds= 16.5 //kN/m^3 S= 19.25 //kN/m^3 g= 9.8 //kN/m^3 h1= 6 //m h2= 13 //m //at point A Sa= 0 Ua= 0 Sa1= 0 //at point B Sb= h1*Ds Ub= 0 Sb1= Sb-Ub //at point C Sc= h1*Ds+h2*S Uc= h2*g Sc1= Sc-Uc //results printf ('total pressure at C= % 2f kN/m^3 ',Sc) printf ('pore...
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clear; clc; close; Vcc = 12; Vbe = 0.7; Vce = 4.23; Rb = 240*10^(3); Rc = 2.2*10^(3); Beta = 75; Ic = 3.53*10^(-3); Ibq = (Vcc-Vbe)/Rb; Icq = Beta*Ibq; Vceq = Vcc-Ic*Rc; Vb = Vbe; Vc = Vce; Vbc = Vb-Vc; disp(Ibq,'Ibq(Amperes) is :'); disp(Icq,'Icq(Amperes) is :'); disp(Vceq,'Vceq(volts) is :'); ...
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//Variable Declaration FSL=207 //Free space loss(dB) RFL=1.5 //receiver feeder loss(dB) AA=0.5 //Atmospheric Absorption loss(dB) AML=0.5 //Antenna Alignment loss(dB) //Calculation LOSSES=FSL+RFL+AA+AML //Total link loss (dB) //Results printf("The total link loss is %.1f dB", LOSSES)
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clc //initialisation of variables r= 0.448 R= 0.868 r1= 0.152 R1= 0.807 //CALCULATIONS P= R^3/r^2 U= R/r P1= R1^3/r1^2 U1= R1/r1 //RESULTS printf (' power ratio in case 1= %.2f ',P) printf (' \n velocity ratio in case 1= %.2f ',U) printf (' \n power ratio in case 2= %.2f ',P1) printf (' \n velocity ratio...
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// Example 9.12 clear all; clc; // Given data no_home = 10^6; // Number of houses no_resident = 4; // Number of residents in a home total_time = 50; // Number of years the analysis is carried out radon_concn_old = 1; ...
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scenario = "Stimuli- Rating"; #randomize_trials = true; default_font_size = 36; default_background_color = 128,128,128; active_buttons =10; button_codes =1,2,3,4,5,6,7,8,9,10; begin; ################################################# fixation cross picture { box { height = 10; width = 40; color = 255, 25...
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PL/SQL Developer Test script 3.0 31 -- 测试游标之动态游标(强类型游标) declare -- 动态游标 要先申明类型 在声明变量 -- 使用open for 进行初始化数据 -- 申明类型 type v_cursor_type is ref cursor return emp%rowtype; -- 声明变量 v_cursor v_cursor_type; -- 声明行类型 v_row emp%rowtype; begin -- Test statements here -- 动态游标不能用for循环 -- ...
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disp('Vectors u1 u2 and y are') u1=[1;3;-2] u2=[5;1;4] y=[1;3;5] disp(y,'y=',u2,'u2=',u1,'u1=') disp('u1.u2=') a=u1'*u2 disp(a,'=') disp('Hence, {u1 u2} form an orthogonal basis.') disp('Let W=span{u1 u2}') disp('Therefore, projection of y on W is:') disp('((y.u1)/(u1.u1))*u1+((y.u2)/(u2.u2))*u2') a1=y'*u1 ...
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clc p=140; //bar h=3001.9; //kJ/kg T=400; //0C disp("Temperature=") disp(T) disp("°C") v=0.01722; //m^3/kg disp("The specific volume") disp(v) disp("m^3/kg") u=h-p*v*10^2; disp("specific internal energy=") disp(u) disp("kJ/kg")
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////Given t=10.0**-12 //s h1=1.054*10**-34 h=6.625*10**-34 //Calculation E=h1/t v=E/h //Result printf("\n uncertainity in energy is %e J",E) printf("\n uncertainity in frequency is %e Hz",v)
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); facetypes=list; function getfacetypenr(ptlist) { for i=0 to facetypes.size-1 do { if facetypes(i).ptcount==ptlist.size then return(i); } newfacetype=map("ptcount":(ptlist.size)); facetypes.add(newfacetype); return(facetypes.size-1); } function ...
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// problem 8.5 d=0.05 V=20 y=120 x=180-y g=9.81 p1=1000 w=g*p1 a=3.142*d*d/4 F=(w*a*V*V*(1+cosd(x)))/(g) disp(F,"force in N exerted by the water jet")
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function [z] = ask(question) disp(question); res = input('','string'); if (part(res,1) == 'y') z = %T; else z = %F end endfunction a="Does the conflict involve a Warwaw Pact or other Soviet allied border state?"; b="Does the conflict pose a grave threat to the political existance of the Soviet ally?"...
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// Scilab Code Ex7.6: Isotope Effect in mercury: Page-153 (2010) M1 = 199; // Mass of an isotope of mercury, amu T_C1 = 4.185; // Transition temperature of the isoptope of Hg, K T_C2 = 4.153; // Transition temperature of another isoptope of Hg, K alpha = 0.5; // Isotope coefficient M2 = M1*(T_C1/T_C2)^...
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//Soultion 4-02 WD=get_absolute_file_path('4_02_solution.sce'); datafile=WD+filesep()+'4_02_example.sci'; clc; exec(datafile) //unit conversion Vdot = Vdot / 10**3; //[L/s] to [m^3/s] D_inlet = D_inlet / 100; //[cm] to [m] D_outlet = D_outlet / 100; //[cm] to [m] deltax = deltax / 100; //[cm] to [m] //solution u_inlet ...
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//Example 6.15 //Program to determine filter coefficients obtained by sampling: //N=7,w=pi/2 clear; clc ; close ; N=7; U=1; //Zero Adjust for n=0+U:1:N-1+U h(n)=(1+2*cos(2*%pi*(n-U-3)/7))/N end disp(h,"Filter Coefficients,h(n)=")
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clc sigmayp=340 //MPa tauyp=sigmayp/2 //MPa disp(tauyp,"in MPa is=") a=0.1 //m b=0.15 //m v=0.3 //pi=4*p0 //sigmatheta=(pi*(a^2+b^2)-2*p0*b^2)/(b^2-a^2) //sigmatheta=1.7*pi //sloution a: maxi principal stress theory sigmatheta=1.7 pi=sigmayp/sigmatheta disp(pi,"in MPa is= ") //sloution b: maxi shea...
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//calculates// s=%s; sys1=syslin('c',(s+3)/s); syms u rp k H RL; num2=u*RL*s*(s+2); den2=(rp+RL)*(s+3); sys2=num2/den2; num3=k; den3=s+2; sys3=num3/den3; sys=sys1*sys2*sys3; disp(sys,"G(s)="); RL=10*10^3; rp=4*10^3; sys=eval(sys) sys=float(sys) disp(sys,"sys="); disp(H,"H(s)"); M=sys/.H //G(s)/1+G(s)...
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clc T=300 //K Nn=2.8*10^19 //cm^-3 Np=1.04*10^19 //cm^-3 //a=Ef-Ev an=0.25 //eV ap=0.87 //eV k=8.617*10^-5 //eV/K n0=Nn*exp(-an/(k*T)) disp(n0,"n0 in cm^-3 is=") p0=Np*exp(-ap/(k*T)) disp(p0,"p0 in cm^-3 is=")
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disp("hello"); a= [20,10]; disp(a); b = input("enter 3*3 matrix"); disp(b); c=20; if(c==20) then disp("C is 20"); elseif (c>0) then disp("C is greater than zero."); else disp("C is less than zero"); end for j=2:2:10 disp(c); end
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function [resultado] = float_dec_to_base(number) contador = 1 inteiro = int(number) resultado = dec2hex(inteiro) + '.' fracionario = modulo(number,inteiro) while modulo(fracionario,1) ~= 0 fracionario = fracionario * 16 numero = int(fracionario) numero_s = '0' ...
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// Scilab Code Ex3a.a.4: Page-134 (2008) clc; clear; R = 6.4e+006; // Radius of the earth, m g = 10; // Acceleration due to gravity, m/sec-square T = 2*%pi*sqrt(R/g); // Time period of oscillations of the body, s printf("\nThe time period of oscillations of the body = %4.1f min", T/60); // Result // T...
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// {w,rate}=loadwave(filename); loads a WAV file. // w=loadwave(filename); loads a WAV file. r is saved to defaultrate. // savewave(filename,v[,rate,bits]); saves a WAV file. // analyze(v[,fmin,fmax,rate,points]); plots the frequencies of v // mapsound(w,[,dt,fmin,fmax,simpl,rate]); show the sound history // soundsec(n...
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//Chapter 1 : Wave Optics clear; //Variable declaration D1=1.50 D2=1.30 //Calculation myu=(D1/D2)**2 //Result mprintf("Refractive index of liquid= %.3f",myu)
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clc clear //input v=14 //voltage f=90 //frequency i=0.4 //current t=55 //phase //calculation r=v/(i*sqrt(1+tand(t)^2))// value of resistance l=r*tand(t)/(2*f*%pi)//value of inductance c=1/(4*%pi*%pi*f*f*l)//value of capacitance for resonance to occur //output printf("the value of resistance is %3.3f ohm",r)...
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//find the Thevenin equivalent for the network to the left of terminals a; b. //Solved Example 1.7 //page no 19 clear clc printf("\n find the The´venin equivalent for the network to the left of terminals a; b.") V1=10//V V2=15//V R1=4//ohm R2=6//ohm I=(V1-V2)/(R1+R2) printf("\n The value of I is =%0.2f A"...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 10.1\n\n\n"); // Chapter 10 : Refrigeration // Problem 10.1 (page no. 503) // Solution T1=70+460; //70F=70+460 R //Energy flows into the system at reservoir at constant temperature T1(unit:R) T2=32+460; //32F=32+460 R //Heat is rejected to the constant...
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clear all exec('C:\Users\Julien Guégan\Desktop\PFE\affichage.sce',-1) function alpha = backtracking(f,x,d,grad) alpha = 1 w = 10^-4 cpt = 0 fx = f(x) //une seule evaluation while(f(x+alpha*d)>(fx+alpha*w*(grad'*d))) alpha = alpha/2 cpt = cpt+1 end endfunction function [L,dLx] ...
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//Programming Example 8.12 //calculate Fibonacci number (F=1 for i<3, and F= F1+F2 for i>=3) //Second File function[f]=Fibonacci(count) global f1; global f2; global first; //As in static variables the initialization takes place only once //but static is not available in scilab // hence use of glo...
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/*Equação do Segundo Grau*/ #include <stdio.h> int main (void) { int a, b, c, Delta; float x1, x2; printf("Digitar valor de a="); scanf ("%d, &a"); printf("Digitar valor de b="); scanf ("%d, &b"); printf("Digitar valor de c="); scanf ("%d, &c"); Delta=b*b-4*a*c; if(Delta<0) printf ("Não existem raizes reais")...
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clear clc //initialisation of variables h= 94 //ft w= 62.4 //lb/ft^3 e= 0.58 p= 73.5 //per cent //CALCULATIONS WHP= h*e*w/550 BHP= WHP/(p/100) //RESULTS printf('W.H.P= %.2f h.p',WHP) printf('\n Brake horse power= %.1f',BHP)
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clc;funcprot(0);......//Example 4.8 //Initialization of variables D=0.2*10^-3;.........//Diameter of the wire in m L=1;...........//Length of the wire in m Tw=60;........//Temperature of wire in degrees celcius Ta=20;.............//Temperature under the water in degrees celcius v=16.96*10^-6;.......//Viscosity in...
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clc m = 1000 // Mass of fish in kg T0 = 300 // Ambient temperature in K P0 = 1 // Ambient pressure in bar T1 = 300 // Initial temperature of fish in K T2_ = -20 // Final temperature of fish in degree Celsius Tf_ = -2.2 // Freezing point temperature of fish in degree Celsius Cb = 1.7 // Specific heat of fish bel...
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function xdot=Vtol_NonLinear(u1,u2,u3,u4,u5,u6,u7,u8) // This is nonlinear Pendulum Model // Load the parameters exec('Vtol_Parameters.sce', -1); // state variables x=u1; y=u2; theta=u3; varx=u4; vary=u5; vartheta=u6; // control variables u_1=u7; // fuerza F1 u_2=u8; // u2=F2-mg // Modelo Mo...
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// flow control // the basic form of an if statement is: // if statement1 // elseif statement2 // else // end a = 0 if a > 0 then disp('a is positif'); elseif a < 0 then disp('a is negatif'); else disp('a is nul'); end; //switch // swtich test // cas...
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//Example 1.39://frequency range clc; clear; fn=800;// natural frequency in cps MD=12;//maximum amount of deviation in amplitude ratio M1=1.12;// M2=0.88 r=0.904;//ratio y=0.62;//damping ratio f=fn*r;//excitation frequency in cps //When M=1.12 THE SOLUTION WILL HAVE IMAGINARY ROOTS AND THIS IMLIES THE OUTPUT WOULD NE...
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clc;clear; //Example 2.13 //given values Plamp=80; N=30;//no of lamps t=12; y=250;//days in a year UC=0.07;//unit cost in USD //calculation LP=Plamp * N/1000;//Lighting power in kW OpHrs=t*y;//Operating hours LE=LP * OpHrs;//Lighting energy in kW LC=LE*UC;//Lighting cost disp(LC ,'the annual energy cos...
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Name=Playground Improved PlayerCharacters=FortniteMain BotCharacters=IAFortniteLike.bot;EnemyClose.bot;EnemySniper.bot IsChallenge=false Timelimit=60.0 PlayerProfile= AddedBots= PlayerMaxLives=0 BotMaxLives= PlayerTeam=0 BotTeams= MapName= MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=true I...