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// Chapter9 // Frequency of oscillation // Page.No-310 // Example_9_3 //Figure 9.12-9.14 // Given clear;clc; R=1000; //in Ohm C=0.1*10^-6; //in F f=1/(2*%pi*1.732*R*C); printf("\n The mimimum frequency of oscillation = %.0f Hz\n",f); // Result //Vo=(R+Xc)*I1-R*I2 W=1/((6^0.5)*C*R); ...
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clc //Initialization of variables p1=0 //Pa p2=0 //Pa V1=0 //m/s V2=0 //m/s Zdif=10 //ft z2-z1 f=0.02 D=6/12 //ft l=200 //ft K_L=0.5+1.5+1.0 g=32.2 //ft/s^2 eta=66.5 A=%pi*D^2/4 Q=poly(0,'Q') V=Q/A hp=Zdif + (f*l/D+K_L)*V^2/(2*g) sol=roots(hp-eta) Q=sol(1)*7.48*60 //ft^3/s to gallons/min printf('Q = ...
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// Example 5.7 // Determine expected locked-rotor line current // Page No. 192 clc; clear; close; // Given data Ir1=151; // Rated current V1=230; // Rated voltage V2=220; // Motor starting voltage F1=60; // Rated frequency F2=50;...
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syms t s=%s [A]=pfss((1/(s^2+2*s+5))) disp(A(1))
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Kovasznay Flow variable P, periodic BC</description> <executable>IncNavierStokesSolver</executable> <parameters>KovaFlow_varP_per.xml</parameters> <files> <file description="Session File">KovaFlow_varP_per.xml</file> </files> <me...
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//example 8.7(a)// clc //clears the screen// clear //clears all variables// close //closes all existing files// disp('A positive edge triggered D flip flop, as shown in figure can be used for the purpose. Waveform A is applied to the D input and waveform B is applied to the clock input. If we examine the two wav...
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function [res] = kiks_calculate_gripper(id) // Ouput variables initialisation (not found in input variables) res=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http...
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clc phi_b=0.8 disp("phi_b = "+string(phi_b)+"V") //initializing value of barrierpotential T=300 disp("T = "+string(T)+"K") //initializing value of temperature kBT=0.026 disp("kBT = "+string(kBT)+"eV") //initializing value of multiplication of boltzmann constant and 300K temperature R_star=8 disp("R_star = "+str...
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//Chapter 13 //Example 13_4 //Page 315 clear;clc; Va=250; Ic=15; Id=20; Ib=12; Lab=75; Lcd=50; Lbc=100; area=0.27; p=1.78*1e-6; //single core resistance of the section of 100m length R=p*100*100/area; Rab=R*Lab/100*2; Rbc=R*Lbc/100*2; Rcd=R*Lcd/100*2; Icd=Id; Ibc=Icd+Ic; Iab=Ibc+Ib; Vb=Va-Iab*Rab; Vc=Vb-Ibc*Rbc; V...
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function [sortedStr, ind] = insertName(str1, blk1) if isempty(str1) then sortedStr = blk1; ind = 1; end str = convstr(str1,"l"); blk = convstr(blk1,"l"); indx = find(part(str,1)==part(blk,1)); i = 0; while ~isempty(indx) i = i + 1; indx = find(part(str,1:i)==p...
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// Scilab Code Ex16.1: Page-581(2014) clc; clear; H0 = 22; // Value of Hubble constant, km/s per million ly parsec = 3.26; // The value of 1 parsec, light years printf("\nThe value of Hubble constant = %d km/s per Mpc", ceil(H0*parsec)); // Result // The value of Hubble constant = 72 km/s per Mpc
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//Example 4.8 //Equivalent discrete controller for DC motor speed control. //------------------------------------------------------------------ //NOTE THAT-- The system response (continuous) to sampled control //input depends on //the sampling time set for continuous signal in SIMULATION. //In this example we conside...
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// Resuelve el sistema lineal Ax=b con el método de gauss_seidel // comenzando desde x con una tolerancia de eps // con un máximo de iteraciones maxIter // Además muestra la cantidad de iteraciones realizadas si se llegó a la condición de parada function x = gauss_seidel(A, b, x, eps, maxIter) n = size(A, 1) xN...
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// A => B, k(T) function dy = model(t, y) T = y(1) A = y(2) B = y(3) k0 = 1e11 // L/(mol*s) R = 8.314e-3 // kJ/(mol*K) Ea = 78 // kJ k = k0*exp(-Ea/(R*T)) dAdt = -k*A dBdt = k*A dTdt = 0.1 // <---rate of heating/cooling K/s dy=[dTdt, dAdt, dBdt] endfunction // initial conditions T0 = 300 //K A0 = 2...
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// Theory and Problems of Thermodynamics // Chapter 5 //Second Law of Thermodynamcis // Example 18 clear ;clc; //Given data ms = 5 // mass of steel block in kg mw = 5 // mass of water in kg T1 = 1273.15 // initial temperature of steel block in K T2 = 373.15 ...
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//Finding charge and potential gradient //Example 5.2(pg 193) clc clear C=0.0002*(10^-6)//capacitance in F V=20000//P.D across condenser in V t=2//thickness in mm Q=C*V//charge on each plate in coulomb g=(V/t)*(1/1000)// potential gradient in kV/mm printf('Charge given to condenser is %e Coulombs \n',Q) print...
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clear; clc; disp("a)") disp("Convert: 1) Q=5 m^3/s=10595 cfm") disp("2) rhoa=0.0761lbm/ft^3") disp("3) SP=deltap/(rhow*g)") delta_ps=500 rho_w=1000 g=9.8 SP=delta_ps/(rho_w*g) printf("Hence SP = %0.3f m",SP) disp("Thus SP= 2.01 in.wg.") disp("b)") disp("Calculating the specific speed:Ns") N_s=1500*((10575)^0.5)/(2.0...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 2 : FORCES IN AN ELECTROMAGNETIC SYSTEMS // EXAMPLE : 2.1 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA A = 0.0001; // The Cross-sectional ar...
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clc clear n=15000//Number of lines per inch w=[5890,5896]//Wavelengths of the two sodium lines in Amgstrongs n1=1//Order of diffraction //Calculations N=(n/2.54)*100//Number of lines present per meter q1=asind(N*n1*w(1)*10^-10)//Angle of diffraction for D1 line in degrees q2=asind(N*n1*w(2)*10^-10)//Angle of...
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// TP SCILAB : INTERPOLATION D'IMAGES ET DEFORMATIONS // script scilab à compléter getd('.'); stacksize max; funcprot(0); // I) Interpolation d'images
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clear; clc; V=50*exp(%i*45/(180/%pi));Z1=3;Z2=2+(%i*10);Xl=2; Voc=V*Z2/(Z1+Z2); Zab=1/((1/Z1)+(1/Z2)); Zg=Zab Rl1=Zg-(%i*Xl); Rl=abs(Rl1); Z=Zab+Rl-(%i*Xl); I1=Voc/Z; I=abs(I1); P=I*I*Rl; printf("-Rl = %f ohms\n",round(Rl*100)/100); printf("-Xl = %f ohms\n",Xl); printf("-Maximum power delivered to load = ...
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// Scilab Code Ex5.9: Page-180 (2006) clc; clear; gamma_expt = 7.0e-04; // Experimental value of electronic specific heat, cal/mol/K-square gamma_theory = 3.6e-04; // Theoretical value of electronic specific heat, cal/mol/K-square L = poly(0, 'L'); L = roots(gamma_expt - gamma_theory*(1 + L)); printf("\nThe...
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//Section-10,Example-1,Page no.-CT.29 //To calculate the maximum work done. clc; V_2=50 V_1=5 R=0.08206 T=298 n=10 W=-(n*R*T)*log(V_2/V_1) disp(W,'Maximum work done in(dm^3atm)') W1=W*(8.314/0.08206) disp(W1,'Maximum work done in(J)')
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x=linspace(0,5,101); y=2*0.2^x; plot2d(x,y);
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clear; clc; printf("\t Example 5.11\n"); //air leaves at 19 degree at fully saturated condition T1=30; //temperature at the inlet in degree celcius T2=17; //temperature at the exit in degree celcius f=100000; //flow rate of water in kg/hr hi=.004; //humidity of ...
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v=120; f=60; i=5; p=525; z=v/i; r=p/i^2; x_l=sqrt(z^2-r^2); l=x_l/(2*%pi*f); disp("the inductance (in mH) of the coil is"); disp(l*10^3);
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//1a licznik = log(15)/log(5) mianownik = log(45) licznik/mianownik //1b A = [1,-2,3,0;3,3,0,6;1,-2,5,8;6,3,-1,0] B = [6,-2,0;3,0,6;-2,6,8;8,-1,0] A*B //1c a=22 h=13 Pc=3/2*a*(a*sqrt(3)+2*h) //2 function f = logarytm(x) f = log((x+4)/log(5)) + 2 endfunction function g endfunction
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// Ex3_15 clc; // Given: E2=44;// in keV En=525;// in keV // Solution: n=(En)/E2; // printf("%f",n) printf("\n For the required level of energy 525 keV nearest even integer is = %d & spin is (+)",n+1)
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function ir_plotmodelset(X, y, epsilon, padx) // Plots 2D set of feasible linear models consistent with dataset (X,y,epsilon) // TODO: Add possibility to manage colors if argn(2) < 4 then padx = %t; end if size(X,1) < 2 then error('Not enough data'); end if size(X,2) == 2 & an...
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clear; clc; printf("\t Example 3.5\n"); Kg=2.72*10^-4; //overall gas phase mass transfer coefficient in kmol/m^2*S*atm r_gas=0.85*(1/Kg); //given that gas phase resisitance is 0.85 times overall resistance kg=1/r_gas; m=9.35*10^-3; //henry's law constant in atm*m^3/kmol k...
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//All the quantities are expressed in SI units p0 = 30*101000; //reservoir pressure T0 = 3500; //reservoir temperature R = 520; //specific gas constant gam = 1.22; //ratio of specific heats ...
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clc //solution //given //refer fig 10.16 b=120//mm//width t=15//mm//thickness l1=b-12.5//mm s=15//mm ft1=70//N/mm^2//tensile stress ft2=56//N/mm^2//shear stress //let l2 be length of weld //P=A*ft P=120*15*ft1//N ft11=ft1/1.5//N/mm^2 ft22=ft2/2.7//N/mm^2 P1=0.707*s*l1*ft11//N //P2=0.707*s*l2*ft22=440*l2//N //P=P1+P2//...
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// Example 1.5 // Computation of length of conductor // Page No. 25 clc; clear all; close; // Given data e=2.5; // Voltage generated B=1.2; // Magnetic field v=8.0; // Speed // Length of conductor (e=B*l*v) l=e/(B*v); //Display result on command window...
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//Example 12.19 //Program to estimate the maximum system length for satisfactory //performance clear; clc ; close ; //Given data SNR_dB=17; //dB - REQUIRED SNR L=100*10^3; //metre - INTERVAL SPACING K=4; //FOR AMPLIFIER h= 6.626*10^(-34); //J/K - PLANK's C...
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clc; V=50; // Volume of water in a tank in litres T1=120; // Temperature of water at initial state (1) in degree celcius x1=0.6; // Dryness fraction at initial state (1) T2=-10; // Temperature of water at final state (2) in degree celcius vf1=0.00106; // specific volume of water from steam tables at T1 in m^3/kg ...
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function [Path,path,ok]=whereintree(Tree,xc,yc) [m,k]=mini((Tree('x')-xc).^2+(Tree('y')-yc).^2) ok=%t;path=[];Path=list() if k==1 then return,end O=Tree('orig') path=Tree('paths')(k-1); if size(O,'*')>size(super_path,'*') then message(['Navigator tree doesnt correspond to this' 'diagram']) ok=%f return end...
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//programming Example 9.9 //calculate the average of n numbers, //then compute the deviation of each number aboutthe average. n = 5; List={3, -2, 12, 4.4, 3.5}; function[] = main() Sum = 0; //calculate and display the average for count = 1:1:n Sum=Sum+List(cou...
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//example 8.4 //calculate hydrodynamic pressure on10m,40m and 100m from top clc;funcprot(0); //given H=100; //heigth of dam wb=73; //width of base of dam wt=7; //width of top of dam l=1; //length of dam hw=98; //heigth of water in dam hsu=...
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on rounded; % This is part of ongoing work... the main Reduce sources in arith/rounded.red % define safe!_fp!-plus etc but both CSL and PSL defined their own % "better" versions. The CSL one in cslbase/arith08.c and the PSL one % is packages/support/psl.red. % As at least a temporary measure the CSL code has been adj...
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clear; clc; close; clf; x=linspace(-5,4,10); y=12-x-x^2; plot2d(x,y,5); xtitle("Graph of y=12-x-x^2 ","x axis","y axis"); x=poly(0,'x'); y=12-x-x^2; //"at these points curve cuts the axis of x" x=roots(y) x=-1/2; y=12-x-x^2; //highest point y=[0 2 4 6 8 10 y]; plot(x,y,'b--.pentagram'); legend("y=12-...
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// Exa 4.5 clc; clear; close; // Given data SR= 2;// in V/micro sec del_v_in= 0.5;// in volt del_t=10;//in micro sec del_v_inBYdel_t= del_v_in/del_t;// in V/micro sec // v_out= A_CL*v_in A_CL= SR/del_v_inBYdel_t; disp(A_CL,"Closed-loop gain ") disp(A_CL,"Any closed loop voltage gain of magnitude exceeding 4...
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// scilab-cli -nb -f n=scanf("%d") while n<>0 ma=0;mi=1000;s=0 for i = 1:n x=scanf("%d") if x<mi then mi=x; end if x>ma then ma=x; end s=s+x end printf("%d\n",(s-mi-ma)/(n-2)) n=scanf("%d") end exit
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function [s]=%sclss(d1,s2) // s=[d1,s2] d1 gain, s2 state-space //! // origin s. steer inria 1987 // [a2,b2,c2,d2,x2,dom2]=s2(2:7) [n2,m2]=size(b2);[p1,m1]=size(d1) s=tlist('lss',a2,[0*ones(n2,m1),b2],c2,[d1,d2],x2,dom2)
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//Tested on Windows 7 Ultimate 32-bit //Chapter 3 Semiconductor Diodes and Miscellaneous Devices Pg no. 97 and 98 clear; clc; //Given Data Vin=18;//input voltage in volts Vz=10;//zener breakdown voltage in volts Tr=20;//reference temperature in degree celsius T=40;//given temperature in degree celcius Tc=0...
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function M=%hm_exp(M) // Copyright INRIA M('entries')=exp(M('entries'))
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// Example 10.5 // Computation of no-load speed // Page No. 408 clc; clear; close; // Given data nrated=1750; // Rated speed SR=4; // Speed regulation // No-load speed Snl=nrated*(1+SR/100); // Display result on command window printf("\n No-load speed = %0.0f r/m...
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// Test # 4 : Checking the type for Input Argument #3 exec('./zpklp2xn.sci',-1); [z,p,k,n,d]=zpklp2xn(0.1,2,[2 9],[3 0.4],[0.1,0.6]); // !--error 10000 //K must be a scalar //at line 45 of function zpklp2xn called by : //[z,p,k,n,d]=zpklp2xn(0.1,[2 9],[3 0.4],[0.1,0.6])
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clear// //Variables gmo = 5.0 * 10**-3 //Maximum transconductance (in Siemen) RD = 1.0 * 10**3 //Drain resistance (in ohm) RS = 200.0 //Source resistance (in ohm) ID = 5.0 * 10**-3 //Drain current (in Ampere) ...
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it is a thrill to be here at a conference that s devoted to inspired by nature you can imagine and i m also thrilled to be in the foreplay section did you notice this section is foreplay because i get to talk about one of my favorite critters which is the western grebe you have n t lived until you ve seen these guys do...
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clc clear //INPUT DATA Rc=15;//compression ratio r1=1.84;//cutoff ratio r2=1.98;//cutoff ratio g=1.4;//constant p1=101.325;//Pressure in kN/m^2 Rc3=17;//compression ratio r3=1.84;//cutoff ratio Rc4=18;//compression ratio r4=1.88;//cutoff ratio //CALCULATIONS nd1=(1-(((1/(Rc^(g-1))))*(((r1^g)-1)/((r1-1)*g...
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clear // cutoff frequency fc1 = 2000; // Sampling frequency fs = 48000; // cutoff frequency normalized fc1n = fc1/fs; // Signal size SIZE = 48; pi = %pi; NUM_SIZE = 6; DEN_SIZE = 5; // Signal generation t = 0:(SIZE-1); F1 = 1000; F2 = 4000; x1 = cos(2*pi*F1/fs*t); x2 = cos(2*pi*F2/fs*t); x = (x1...
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//Problem 7.02: //initializing the variables: H200 = 1170; // in Btu/lbmol H2000 = 14970; // in Btu/lbmol n = 20000; // in scfm //calculation: ndt = n*1/379 Q = ndt*(H2000 - H200) printf("\n\nResult\n\n") printf("\n the heat transfer rate is %.2E Btu/min",Q)
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clc //Initialization of variables t=[0 1000 2000 3000 4000] p=[10.20 5.72 3.99 2.78 1.94] lnp=log(p) x=t y=lnp //hence the value differs from textbook a bit. sx=sum(x);sx2=sum(x^2);sy=sum(y);sxy=sum(x.*y);n=length(x); A=[sx,n;sx2,sx];B=[sy;sxy];p=A\B; m=p(1,1);b=p(2,1); k=m plot(x,y) //Since first order re...
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clear; clc; // Example 7.3 printf('Example 7.3\n\n'); printf('Page No. 203\n\n'); // given C = 250*10^3;//Original annual cost of fuel in Pound O_E = 71.5;// Original Efficiency Fl_i = 20;// Initial Flue loss Fl_f = 17.5;// Final Flue loss N_E = O_E + (Fl_i - Fl_f);// New Efficiency F_save = C*((N_E-O_E)...
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clc p=1.3; //bar R0=8.314; M_CO2=44; M_O2=32; M_N2=28; M_CO=28; m_O2=0.1; m_N2=0.7; m_CO2=0.15; m_CO=0.05; //Considering 1 kg of mixture m=1; //kg //let moles be denoted by n n_O2=m_O2/M_O2; n_N2=m_N2/M_N2; n_CO2=m_CO2/M_CO2; n_CO=m_CO/M_CO; M=1/(m_O2/M_O2 + m_N2/M_N2 + m_CO2/M_CO2 + m_CO/...
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// Concentration of holes and electrons // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 1-27 in page 52 clear; clc; close; // Data given sigma=100; // Conductivity of p-type germanium e=1.6*10^-19; // Charge on an electron in eV mu_p=1800; // ...
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//calculation of specific heat clear; clc; printf("\t Example 6.7\n"); //for water m=100;//mass, g s=4.184;//specific heat, J/g C deltaT=23.17-22.5;//change in temp., C qH2O=m*s*deltaT;//heat gained by water, J //for lead qPb=-qH2O;//heat lost by lead, J m=26.47;//mass, g deltaT=23.17-89.98;//change...
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function varargout = rarx(varargin) // Parameters Estimation of ARX model by recursive method // // Calling Sequence // sys = rarx(ioData,[na nb nk],lambda) // Parameters // ioData : iddata or [outputData inputData] ,matrix of nx2 dimensions, type plant data // na : non-negative integer number specified as order ...
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<<<<<<< HEAD ======= function [y, z, opt] = buffer (x, n, p, opt) >>>>>>> 6bbb00d0f0128381ee95194cf7d008fb6504de7d //This function buffers the given data into a matrix of signal frames //Calling Sequence //[y] = buffer (x, n) //[y] = buffer (x, n, p) //[y] = buffer (x, n, p) //[y, z, opt] = buffer (...) //Parameters /...
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// test catenary projection in an image // when the attached points are mobile clear; //close; exec('../../Load.sce'); ////////////////////////////////////////////////////////////////////////////////////////// ////////////////////////////////////////////////////////////////////////////////////////// // USE...
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// Example 2.7.7 page 2.27 clc; clear; n1=1.48; //refractive index of core n2=1.46; //refractive index of cladding NA=sqrt(n1^2-n2^2); //computing Numerical aperture theta=asind(NA); //computing acceptance angle printf("\nNumerical aperture is %.3f.\nAcceptance angle is %.2f degrees.",N...
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clc f = 0.2 // feed in mm/rev. N = 800 // spindle speed in rev./min. d = 10 // doameter of hole in mm mrr = %pi*(d^2)*f*N/4 // metal removal rate in mm^3/min. mrr = mrr/60 // mm^3/s p = 0.5*mrr // cutting power from table 14.2 in watts omega = 2*%pi*N/60 // rpm T = p/omega // torque in N.m printf("\n MRR = %0....
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clc; clear; //----------------- // Question 1 // Part a s = poly(0, 's'); Ga = 1/(s^3 + 4*s^2 + 5*s); Ga = syslin('c', Ga); scf(); evans(Ga, 30); //----------------- // Part b Gb = (s+1) / (s^2 * (s + 3.6)); Gb = syslin('c', Gb); scf(); evans(Gb, 80); //----------------- // Part c Gc = (s+0.4) / (s^2 * (s + 3.6)); Gc =...
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//example 3.5 clc; funcprot(0); e=0.5; B=6; k=e/B; Gamma=110; q=440; disp("get the values of Nqe and Nye from the figure from the value of e/B"); Nye=26.8; Nqe=33.4; Qult=B*1*(q*Nqe+1/2*Gamma*B*Nye); disp(Qult,"ultimate bearing capacity in lb/ft"); disp(Qult/2000,"ultimate bearing capacity in ton/ft");
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//ques2 //Mach Number of Air Entering a Diffuser clear clc //(a) The speed of sound in air at 30°C is determined as k=1.4; R=0.287;//gas constant T=303;//air temperature in K c=sqrt(k*R*T*1000);//speed of light in m/s printf('(a) speed = %.0f m/s \n',c); //(b) Mach Mumber V=200;//speed in m/s Ma=V/c; print...
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//coefficient// s=%s; sys=syslin('c',(9*(1+2*s))/(s^2+0.6*s+9)); disp(sys,"C(s)/R(s)=") //given r(t)=u(t) syms t s; R=laplace('1',t,s); disp(R,"R(s)=") C=R*sys; disp(C,"C(s)=") c=ilaplace(C,s,t) disp(c,"c(t)=") G=9/(s^3+0.6*s^2); disp(G,"G(s)=") H=1; y=1+G*H; syms t s; Kp=limit(s*G/s,s,0) Kv=limit(s*G...
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clear; clc; // Example: 11.7 // Page: 465 printf("Example: 11.7 - Page: 465\n\n"); // Solution //*****Data******// w2 = 0.6;// [g] w3 = 1.8;// [g] Temp = 27 + 273;// [K] V1 = 100;// [cubic cm] M2 = 60;// [g/mol] M3 = 180;// [g/mol] R = 0.082;// [L.atm/mol.K] //****************// V1 = V1/1000;//...
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accident_prone= 0.4; nonaccident_prone= 0.2; pop_accident = 0.3; prob_of_accident = pop_accident*accident_prone + (1-pop_accident)*nonaccident_prone; prob = pop_accident * accident_prone /prob_of_accident; disp(prob, "The required probability is")
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// Exa 3.11 clc; clear; close; format('v',5) //Given data Beta = 100; V_CC = 10;// V R1 = 9.1;// in k ohm R_C = 1;// in k ohm R_E = 560*10^-3;// in k ohm R2 = 4.7;// in k ohm V_BE = 0.7;// in V V_Th = (V_CC/(R1+R2))*R2;// in V R_B = (R1*R2)/(R1+R2);// in k ohm // V_Th - I_B*R_B - V_BE - I_E*R_E = 0 or ...
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get_custos_implantacao.sce
function [custo_MW_instalado] = get_custos_implantacao(parametros,verbose,arquivo_xls) // ------------------------------------------------------------------ // //-----//-----// MODELAGEM DE MASSAS E CUSTOS \\-----\\-----\\ // ------------------------------------------------------------------ // // // Au...
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// Scilab code Exa18.10 : : Page-767 (2011) clc; clear; m_mew = 106; // Mass of mew lepton, mega electron volts per square c m_tau = 1784; // Mass of tau lepton, mega electron volts per square c tau_mew = 2.2e-06; // Mean life of mew lepton, sec R = 16/100; // Branching factor tau_plus = R*(m_...
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//Problem 4.02: A cell has an internal resistance of 0.02 ohms and an e.m.f. of 2.0 V. Calculate its terminal p.d. if it delivers (a) 5 A, (b) 50 A //initializing the variables: r = 0.02; // in ohms e = 2; // in volts I1 = 5; // in Amperes I2 = 50; // in Amperes //calculation: pd1 = e - (I1*r) pd2 = e - (I...
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6_5.sce
//elements in one row of rouths tabulations are all zero s=%s; m=s^5+4*s^4+8*s^3+8*s^2+7*s+4; disp(m) r=coeff(m) n=length(r) routh=routh_t(m) disp(routh,"rouths tabulations=") c=0; for i=1:n if (routh(i,1)<0) c=c+1; end end if(c>=1) printf("system is unstable") else printf("system is marginally stable"...
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clc Pop = 10 disp("Pop= "+string(Pop))//initializing value of amount of optical intensity hw=1.65 disp("hw = "+string(hw)+"eV") //initializing value of energy of incident optical beam (h-bar omega) alpha = 7*10^3 disp("alpha= "+string(alpha)+"cm^-1")//initializing value of absorption coefficient(alpha) for GaAs ...
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clear ; clc; // Example 5.1 printf('Example 5.1\n\n'); //Page no.109 // Solution P = 60 ;//[Gpa] //(a) p_atm = (P*(10^6))/101.3 ;//[atm] printf('(a) Pressure in atmospheres is %.2e atm\n',p_atm); //(b) p_s = (P*(10^6)*14.696)/101.3 ;//[psia] printf(' (b) Pressure in psia is %.2e psia\n',p_s); // (c...
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//Example 7_18 clc(); clear; //To find the numerical aperature and acceptance angle n1=1.6 n2=1.4 n0=1.33 NA=sqrt(n1^2-n2^2)/n0 printf("The numerical aperature is %.3f",NA) theta=asin(NA)*180/%pi printf("\nThe acceptance angle is %.2f degrees",theta)
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// Exa 2.11 format('v',5);clc;clear;close; // Given data At = 8.5;//true value in A Am = 8.3;//measured value in A Absoluteerror = At - Am;//absolute error in A disp(Absoluteerror,"The Absolute error in A is"); // Relative percentage error Per_Error = ((At-Am)/At)*100;// %e in % disp(Per_Error,"The relative p...
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function y=sinexp(x) y=sin(x) + exp(x) endfunction function [p] = bissecao(f, a, b, TOL, N) i = 1 fa = f(a) while (i <= N) //iteracao da bissecao p = a + (b-a)/2 fp = f(p) //condicao de parada if ((fp == 0) | ((b-a)/2 < TOL)) then return end //bissecta ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 9, Example 2") //Steam is condensed at temprature(Tg=100°C) on the outer surafce of a horizontal tube of length(L=3m) and diameter(d)=50mm or .05m Tg=100; L=3; ...
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//Chapter 11 : Free Electron Theory Of Metals clear; //Variable declaration EF=1.1214*10**-18 //fermi energy in J m=9.11*10**-31 //Mass of electron h=6.63*10**-34 //planck's constant //Calculations n=((8*m*EF)/(h**2))**(3/2)*(%pi/3)/10**28 //Result mprintf("No. of free electrons per unit vol...
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// Exa 4.10 clc; clear; close; // Given data R_F = 1.2;// in M ohm R_F = R_F * 10^6;// in ohm C_F = 10;// in nF C_F = C_F * 10^-9;// in F f_a = 1/(2*%pi*R_F*C_F);// in Hz disp(f_a,"The safe frequency in Hz is"); R1 = 120;// in k ohm R1 = R1 * 10^3;// in ohm A = R_F/R1; AindB= 20*log10(A);// in dB disp(Ai...
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JSONParse.sci
// A simple JSON parser function JSON2Struct = JSONParse(JSON) true = "%T" false = "%F" oldnull = null, null = "%Nan" // Backup the null() function and set variable JSON_text_cat = strcat(JSON); // The following section is required to convert multidimensional // arrays into...
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//example 2.22// clc //clears the screen// clear //clears already existing variables// //octal to binary conversion// y=oct2dec('736') //octal to decimal conversion// a=dec2bin(y) //decimal to binary conversion// disp('binary conversion of given no is:') disp(a) //answer in binary form//
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//Exa:2.7 clc; clear; close; //Given: m1=0.55;//modulation percent 1 m2=0.65;//modulation percent 2 Pc=360;// in watts mt=sqrt(m1*m1+m2*m2); printf("\n\n\t total modulation = %f ",mt); Pb=(mt*mt)*Pc/2; printf("\n\n\t total sideband power radiated = %f W",Pb);
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clc; warning('off'); printf("\n\n example2.8 - pg39"); // given delx=0.3-0; //[m] - length d=0.05-0; //[m] - diameter A=(%pi*d^2)/4; //[m^2] - area; R=8.314*10^3; //[N*m/kmol*K] - gas constant xco1=0.15; // mole prcent of co in one tank xco2=0; // mole percent of co in other tank p2=1; //[atm] - pressu...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 2, Example 11") //An electrical resistance wire 2.5mm or 2.5*10^-3m in diameter(D) and L=0.5m long has a measured voltage drop of E=25V for a current flow of I=40A...
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${ using Typewriter.Extensions.WebApi; using Typewriter.Extensions.Types; Template(Settings settings) { settings.IncludeProject("Host"); settings.OutputFilenameFactory = (file) => { return file.Name.Replace("Controller.cs", "Service.ts"); }; } string methodName(Method method){ return method.Name.To...
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EX13_4_1.sce
//Example No. 13.4.1 clc; clear; close; format('v',7); Pr1=0.0297/1000;//W(Recieved power) Pr2=0.0471/1000;//W(Recieved power) Pr3=0.0374/1000;//W(Recieved power) Pt=1;//W(Transmitted power) R=10;//m(Radius) f=980;//MHz(Frequency) f=f*10^6;//Hz(Frequency) c=3*10^8;//m/s(Speed of light) lambda=c/f;//m(Wavel...
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b=200//width, in mm d=300//effective depth, in mm Mu=74//in kN-m top_cover=30//in mm fck=20//in MPa fy=415//in MPa Xc=0.479*d//in mm Mulim=0.138*fck*b*d^2/10^6//in kN-m Ast1=round(0.36*fck*b*Xc/0.87/fy)//in sq mm M1=Mu-Mulim//in kN-m fcc=0.446*fck//in MPa //for d'/d=30/300=0.1 and Fe415 grade steel, fsc=353...
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clear clc warning('off') function phi = binaryMixture(theta, setFrac, phase) x1 = theta(1); P = theta(2); x = [x1; 1 - x1]; y = [setFrac; 1 - setFrac]; T = 307.4; R = 8.3144621e-3; Tc = [305.3; 660]; Pc = [4872; 2750]; omega = [0.1; 0.313]; Tr = T ./ Tc; ki = 0.37464 + (1.54...
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//Chapter 4 Ex 4 clc; clear; close; // from given statement we the equation as (4/21)x-(8/45)x=8 for x=1:700 if ((4/21)*x-(8/45)*x)==8 break; end end half=x/2; mprintf("The required number is %d",half);
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4 2 2 1 7 3 ~~~~~~~~~~~~~~~~~~~~~~~~~~ 5
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OneBitErrorDetection.tst
load OneBitErrorDetection.hdl, output-file OneBitErrorDetection.out, compare-to OneBitErrorDetection.cmp, output-list x0%B3.1.3 x1%B3.1.3 x2%B3.1.3 x3%B3.1.3 x4%B3.1.3 x5%B3.1.3 x6%B3.1.3 x7%B3.1.3 y0%B3.1.3 y1%B3.1.3 y2%B3.1.3 y3%B3.1.3 y4%B3.1.3 y5%B3.1.3 y6%B3.1.3 y7%B3.1.3 pg%B3.1.3 pc%B3.1.3 z%B3.1.3; /*Data Set ...
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// Example 22_14 clc;funcprot(0); //Given data T_1=350;// °C p_1=30;// bar p_2=6;// bar p_3=1;// bar p_4=0.07;// bar P=10;// Power developed by the turbine in MW n_t=80/100;// Isentropic efficiency of each stage // Calculation // From h-s chart: h_1=3106;// kJ/kg h_2=2811;// kJ/kg h_3=2560;// kJ/kg h_4...
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clc //initialisation of variables W= 5 //kJ Q= 23 //kJ Q1= -50 //kJ W1= 0 //kJ //CALCULATIONS E1= Q-W E2= Q1-W1 E3= -(E1+E2) W3= -E3 //RESULTS printf ('energy change in process 1 = %.f kJ',E1) printf ('\n energy change in process 2 = %.f kJ',E2) printf ('\n energy change in process 3 = %.f kJ',E3) printf...
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ATWM1_Working_Memory_MEG_Nonsalient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...