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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc., USA,pp 436. //Chapter-3 Ex3.2.b Pg No. 96 //Title:Heat generation in CSTR in Series //============================================================================================================= clear clc //INPUT // For a first order reac...
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//Reaction at B //refer fig. 8.10 //Applying virtual work principle //(-4-6+RB)*delta(y)=0 //Thus RB=6+4 //kN printf("Reaction at B is RB=%.2f kN",RB)
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exec dgl.sci figure(1); clf; mtlb_axis([0 5 -60 10]) x = 0; //initalisierung y = 3; //initialsierung h = 0.1; //step size while (x<=5) plot(x, y, 'o'); y = y + h*dgl(x, y); x = x + h sleep(100) end
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//猫耳族的太空船 world 0 Space //1111 scene 0 Space cut 0 可乐炭 你很厉害呢! 牛奶酱 这还用你说。不过你还没使出全力吧? 可乐炭 怎么说? 牛奶酱 最终BOSS从来都是要有第二形态的。 可乐炭 好吧,那就如你所愿,moon ***** power! // moon prism power, make up! 可乐炭 怎么没反应? 牛奶酱 废话,你可是月球的敌人啊,怎么可能给你月亮的力量。再说,就算给了你,版权也通不过吧。 可乐炭 那怎么办? 牛奶酱 随便喊个变身就行啦! 可乐炭 我为什么要听你的啊? 牛奶酱 随你便。 boss 可乐炭 我才不会输… 牛奶酱 你还有力气吗? 可乐炭 你不知...
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//Ex 2.2 clc;clear;close; format('v',6); fi=0.015;//Wb(flux) ag=2.5;//mm(airgap) Ae=200;//cm^2(Effective area) FD=fi/(Ae*10^-4);//T(Flux density) mu0=4*%pi*10^-7;//constant H=FD/mu0;//A/m(Magnetic field strength) mmf=H*ag*10^-3;//A(magnetomotive force required) disp(mmf,"Magnetomotive force required(A)"); //...
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//Example No. 14_03 //Eigen Vectors //Pg No. 473 clear ; close ; clc ; A = [8 -4 ; 2 2 ] ; lamd = poly(0,'lamd') p = det(A - lamd*eye()) root = roots(p) mprintf('\n The roots are \n lamda1 = %f \n lamda2 = %f \n ',root(1),root(2)) A1 = A - root(1)*eye() X1 = [-1*A1(1,2)/A1(1,1) ; 1] disp(X1,'X1 = ') A2 = ...
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clc clear //Input data T1=450;//The temperature of the source in k H1=1000;//The amount of heat taken by the engine at T1 in calories T2=350;//The temperature of the sink in K //Calculations H2=(T2/T1)*H1;//The amount of heat rejected to the sink in each cycle in calories n=(1-(T2/T1))*100;//The efficien...
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//Example 6_6_u1 clc(); clear; //To calculate the ratio of stimulated emission to Spontaneous emission h=6.63*10^-34 //units in m^2 kg s^-1 c=3*10^8 //units in meter/sec lamda=694.3 //units in nm lamda=lamda*10^-9 ...
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//Initiization of variables w=1500 //N/m x=4 //m L=4 //m //Calculations k=x^2/w //m^3/N //Solving the intergral we get W=L^3/(3*k) //N x_bar=L^4/(4*k*W) //m //Result clc printf("The resultant is %f N and the line of action of the force is %f m",W,x_bar)
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//Tensions in the strings //refer fig. 17.7 //Case (a)- Initial velocity u=0 t=5 sec //Writing impulse momentum equation for 500 N block and 1500 N block and solving obtained equations v=7.007 //m/sec T=642.86 //N //Case (b)-Initial velocity u=3 m/sec //Writing impulse momentum equation for 500 N block and 150...
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clear clc //to find forces that is scale reading // GIVEN:: //refer to figure 9-22(a) from page no. 189 //mass od beam m = 1.8//in kg //massof block M = 2.7//in kg //acceleration due to gravity g = 9.8//in m/s^2 // SOLUTION: //refer to figure 9-22(b) from page no. 189 //consider our system as ...
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clc; //page 432 //Given T2=600;//lb, Tension from side 2 us=0.25;// Coeffiecient of static friction between pulley and belt bta=(2*%pi)/3;//Co=efficient of kinetic friction between pulley and belt r1=8//in in //Pulley B T1=T2/(exp(us*bta))//N, Tension from side 1 //disp(T1) //Pulley A //Aumming moment ab...
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clc //given data i=12/100.0 // interest rate n=10 // time in years time=100.0 // days geyser is used in year effi=0.9 // efficiency of geyser w=100.0 // weight of water in kg C=4.2 // heat capacity in kJ/kg-degree C theta=60-15 // temperature difference in C cost=4 // cost of electricity per kWh Elec=(1/...
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//Problem 21.12: A 10 kW shunt generator having an armature circuit resistance of 0.75 ohm and a field resistance of 125 ohms , generates a terminal voltage of 250 V at full load. Determine the efficiency of the generator at full load, assuming the iron, friction and windage losses amount to 600 W. //initializing ...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 9 : SYMMETRICAL COMPONENTS AND FAULT ANALYSIS // EXAMPLE : 9.11 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA kv = 230 ; // Line voltage in kV from E...
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clear; clc; //page no. 194 gam = 0.0765;// lb/cuft V1 = 293;//fps hp = 1500; h = 10;//ft V4 = 338;//fps V = 0.5*(V1+V4); Q = hp*550/((V4-V1)*V*gam/32.2); d1 = sqrt(Q/(V1*0.25*%pi)); d4 = sqrt(Q/(V4*0.25*%pi)); F = Q*(gam/32.2)*(V4-V1); eta = V1/V; printf('V4 = %d fps,\n V = %.1f fps,\n d1 = %.1f f...
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clc disp("Example 6.8") printf("Given") disp("R1= 10kohm R2=50kohm Ri=500kohm R0=0") disp("Open loop gain (A)=10^5") A=10^5;R1=10*10^3;R2=50*10^3;Ri=500*10^3; //From figure 6.11 //Applying KCL equation at node B disp("(v1+vd)/10+ (v2+vd)/50+ vd/500=0 (1)") //Since R0=0 disp("v2=A*vd") //Solving for ...
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// 2.14 clc; mo=0.8; sr=250; sm=sr/mo; R=sm*1*10^-3; printf("Resolution of 1mm movement = %.4f degree/mm",R) Rq=300/1000; printf("\nRequired Resolution of 1mm movement = %.3f degree/mm",Rq) disp('Since the resolution of potentiometer is higher than the resolution required so it is suitable for the application'...
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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) then v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution8_4.sce') //Obtain path of data file data...
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//Scilab Code for Example 7.1 of Signals and systems by //P.Ramakrishna Rao clc; clear; a0=2; a1=2; a2=4; x1=[1,3,5,7]; x2=[2,4,6,8]; for t=1:4 y1(1,t)=a0+a1*x1(t)+a2*(x1(t))^2; y2(1,t)=a0+a1*x2(t)+a2*(x2(t))^2; end b1=2; b2=3; x=b1*x1+b2*x2; disp('y(n) does not depend on past inputs'); disp('H...
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function [x]=resolLU(A,b) [L,U] = LU(A) y = solinf(L,b) x = solsup(U,y) endfunction
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//a function to create histograms needed to compute dispersion scores //it also computates associate dispersion scores to videos //scores and histograms are stored in the given file //inputs : // - path : the path to the folder where data are // - filename : the file name containing are (csv format with ';' separati...
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clc;funcprot(0);//EXAMPLE 20.14 // Initialisation of Variables v=14;..........//Volume of air delivered in m^3 p1=1;........//Suction pressure in bar p2=7;........//Delivery pressure in bar N=310;........//Compressor rpm n=1.35;........//Compression index k=0.05;........//Clearance ratio rld=1.5;.........//Rati...
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V1=200//voltage applied to non-inductive load I1=20//current flowing through the load R=V1/I1 V=230//applied voltage to series connection of R and L I=I1 Z=V/I Xl=sqrt(Z^2-R^2) L=Xl/(2*%pi*50) phi=atand(Xl/R) mprintf("Inductance of the reactor=%f H, phase angle between applied voltage and the current is %f d...
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mōhio V;ACT mōhio V;PASS tahi V;ACT tahi V;PASS patu V;PASS patu V;ACT hoe V;ACT hoe V;PASS āmine V;ACT āmine V;PASS oka V;PASS oka V;ACT paki V;PASS paki V;ACT wareware V;ACT wareware V;PASS puta V;ACT puta V;PASS kaukau V;PASS kaukau V;ACT tae V;ACT tae V;PASS tomo V;ACT tomo V;PASS hora V;PASS hora V;ACT waiata V;PA...
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//Fluid Systems- By Shiv Kumar //Chapter 5- Francis Turbine //Example 5.13 //To Determine the Blade Angle at Entry and Exit. clc clear //Given Data:- R=0.6; //Degree ui=15; //Peripheral velocity of Runner at entry, m/s Vfo=3.2; //m/s Vfi=Vfo;...
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//exapple 1.45 clc; funcprot(0); // Initialization of Variable c=90-36-30/60-30/3600;//co latitude p=90-16-12/60-18.4/3600;//co declination z=90-30-12/60-30/3600;//co altitude s=(p+z+c)/2; pi=3.14159; s1=s-c; s2=s-p; s3=s-z; H=2*atan(sqrt(sin(s1*pi/180)*sin(s2*pi/180)/sin(s*pi/180)/sin(s3*pi/180))); H=H...
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clear //Given dia = 15 //mm - The diameter of the rod h = 0.5 //mt - The freely falling height A = 3.14*(dia**2)/4 //sq.mm The area of the crossection E = 200 //GPa -Youngs modulus L = 750 //mm - The total length of the rod G = 80 //gpa - Shear modulus N = 10 ...
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//To Calculate the Charge on each Capacitor //Example 31.4 clear; clc; C1=10*10^-6;//Capacitance of First Capacitor C2=20*10^-6;//Capacitance of Second Capacitor C=C1*C2/(C1+C2);//Equivalent capacitance of C1 and C2 in series V=30;//Apllied Voltage Q=C*V;//Formula for finding the charge on each...
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лобаны V;SG;1;PST;CAUS+INTR кулыны V;PL;3;FUT;INTR огъя ADJ;COMPV утьыны V;SG;LGSPEC_MULT;3;NEG;PRS;CAUS+TR чабыны V;SG;3;PST;TR салон N;NOM;SG;PSS3S;LGSPEC1 жюри N;GEN;SG;LGSPEC1 кылзӥсь N;HUM;ACC;PL;PSS1S зарезь N;IN+ESS;SG;PSS1S детектив N;HUM;NOM;SG;PSS3S;LGSPEC1 мунё N;DAT;PL;PSS3S вкладчик N;HUM;ABL;PL;LGSPEC1 ма...
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errcatch(-1,"stop");mode(2);//Example 3.9.1// multiplier ; ; //given data : Vin=20;//in volts I_fsd=50*10^-6;//in Farad Rm=200;// in ohm Rs=(Vin/I_fsd)-Rm; disp(Rs*10^-3,"the multiplier,Rs(k-ohm) = ") exit();
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// Exa 3.2 clc; clear; close; format('v',6) // Given data R_C = 5;// in k ohm V_CC = 10;// in V I_C = 1;// in mA V_CE = V_CC - (I_C*R_C);// in V disp("Part (i) When Collector load = 5 kohm"); disp("Operating point is : "+string(V_CE)+" V, "+string(I_C)+" mA") disp("The quiescent point 5V and 1mA"); R_C = 6...
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//Example 7_9 clc(); clear; //To find out the angle where it should be banked v=25 //units in meters/sec r=60 //units in meters g=9.8 //units in meters/sec^2 tantheta=v^2/(r*g) //units in radians theta=atan(tantheta)*180/%pi printf("The angle where it should be banked is theta=%d degrees",round(thet...
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// Function Name: cummulativeSum // Returns a matrix containing the cumulative sum of elements in each column (dim=0), or each row (dim=1) of input matrix // Calculating the cummulativeSum. //dim = 1 inputMat = [-1.2, 1, 1.9; -4, 2.6, 5; -2.3, 8, -7]; result = armaMatFunc("cummulativeSum",inputMat,1) //dim = ...
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clc // Given that lambda = 5.89e-7 // wavelength of light in meter d = 1 // distance of screen from slit in meter b = 1e-4 // slit-width in meter // Sample Problem 18 on page no. 2.44 printf("\n # PROBLEM 18 # \n") theta = (asin(lambda / b)) * (180 / %pi) // calculation for angular spread x = (2 * d * lambda) / b// ca...
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// Scilab code Exa4.7.1: To calculate the energy and power released during fission of U-235 : Page 189 (2011) m = 0.001; // Mass of U-235 lost during fission, Kg c = 3e+08; // Velocity of light, m/s E = m*c^2; // Energy released during fission, J E_t = E/(4e+09*1000); // Energy requires TNT, Kt printf("\n Energy...
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//problem 7 pagenumber 2.91 //given format(6); r1=1e3;//ohm r2=100e3;//ohm rf1=90e3;//ohm //determine cmrr ac=(r2-rf1)/(r1+r2); ad=(rf1+((((rf1+r1)/r1)*r2)/(r1+r2)))/r1;format(12); disp( 'CMRR = '+string(ad/(ac)));//no unit
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.482229D+00 ...
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// Test #8 : When output arguments are less than 5 exec('./zpkbpc2bpc.sci',-1); [z,p,k]=zpkbpc2bpc(4,2.2,1,[0.5,0.6],[-0.8,0.34]); disp(k); disp(p); disp(z); // //Scilab Output //k= 1.4967554 + 0.3078635i //p= -0.7456261 + 0.5534776i //z= -0.8709140 + 0.6869281i // //Matlab Output //z=-0.8709 + 0.6869i //...
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load Larc.hdl, // function call NOT set RAM4K[0] %X8AFA, // li R10 -6 1. set RAM4K[1] %X9D08, // lui R13 2048(dec) 2. set RAM4K[2] %X0000, // nop 3. set RAM4K[3] %X0000, // nop 4. set RAM4K[4] %X0000, // nop ...
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// Exa 7.5 clc; clear; close; // given data VSat=13;//in Volt Vut=2;//in Volt Vlt=-1;//in Volt // Assume R1=10 Kohm R1=10;//in Kohm R2=((VSat/Vut)-1)*R1;//in Kohm R3=((-VSat/Vlt)-1)*R1;//in Kohm disp(R1,"Value of R1 in Kohm is :"); disp(R2,"Value of R2 in Kohm is :"); disp(R3,"Value of R1 in Kohm is :");...
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function [d] = cald(T, y) n = length(T); h = T(2:n) - T(1:n-1); c = 1 ./ h(1:n-1); a = [0; c]; b = 2 * ([0 ; c] + [c ; 0]); dy = y(2:n) - y(1:n-1); u1 = dy(1:n-1) .* (c .* c) u = 3 * ([0; u1] + [u1; 0]); d = rich (a, b, c, u); endfunction
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clc N=60; //rpm r2=0.25; //m g=9.8; //m/s^2 w=2*%pi*N/60; dz_12=(w*r2)^2/2/g; // dz_12=z2-z1 c=w*r2^2; dz_23=c^2/2/g/r2^2;// dz_23=z3-z2 dz_13=dz_23+dz_12; disp("Total depression =") disp(dz_13) disp("m")
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// Scilab code Ex7.6: Pg 244 (2005) clc; clear; Z_T = 88; // Atomic number of daughter nucleus E_T = 4.05e+06; // Energy of ejected alphas, eV R = 9.00e-15; // Nuclear radius, m r_o = 7.25e-15; // Bohr radius, m E_o = 0.0993e+06; // Energy analogous to the Rydberg in Atomic Physics T_T = ex...
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//Chapter 2 //Example 2.2 //page 57 //To find reactance of the conductor clear;clc; f=50; //frequency D=5.04; //diameter of the entire ACSR d=1.68; //diameter of each conductor Dsteel=D-2*d; //diameter of steel strand //As shown in fig D12=d; D13=(sqrt(3)*d); D14=2*d; D15=D13; D16=D12; //neglecting the central sttel co...
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Z=2; E2=-(13.6)*(Z^2)/4; b=(-E2); printf('\n The Kinetic energy of the electron is %f',b); m0=(9.1)*(10^-31)*(1.6)*(10^-19); p=sqrt(2*b*m0); h=(6.6); disp("λ=(h)/(p)"); c=h/p; //say c=λ d=c*(10^-25); printf('\n The value of de-Broglie wavelength is %fnm',d);
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//Caption:Calculate breadth of rectangular waveguide //Exa:4.7 clc; clear; close; f=9*10^9;//in Hz c=3*10^10;//in cm/s wl_g=4;//in m wl_o=c/f; wl_c=[sqrt(1-((wl_o/wl_g)^2))/wl_o]^-1; b=wl_c/4; disp(b,'Breadth of rectangular waveguide (in cm) =');
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function frequency = GetFreqAtStageAndNote(stage, note) //function frequency = GetFreqAtStageAndNote(stage, note) //returns the frequency of a note at the given stage and note //stage corresponds to the four stages (0, 1, 2, 3) //stage 0 is the lowest frequency, 3 is the highest //note is an index for th...
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//Chapter-4, Example 4.21, Page 147 //============================================================================= clc clear function [polar] = r2p(x,y)//function to convert rectangular to polar polar = ones(1,2) polar(1) = sqrt ((x ^2) +(y^2)) polar(2) = atan (y/x) polar(2) =(polar (2)*180)/%pi endfunc...
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A=10^-4; q = 1.6*10^-19; kT = 0.0259; Wb = 10^-4; ni = 1.5*10^10; Na = 10^17; Tn = 10^-7; upe=200; une=700; Nd = 10^15; Tp=10^-5; unb=1300; upb=450; Veb = 0.3; Vcb = -40; pn = ni^2/Nd; Dp = upb*kT; Lp = sqrt(Dp*Tp); Ies = q*A*Dp*pn/Lp*(csch(Wb/Lp)+tanh(Wb/Lp)); dpe = pn*exp(Veb/kT); Ib = q*A*Dp*dpe/...
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mode(7); // Polinomios // um polinomio definido pelas raizes p=poly([1 2],'s') // um polinomio definido pelos coeficientes q=poly([1 2],'s','c') // soma de polinomios p+q // multiplicacao de polinomios p*q // divisao de polinomios q/p // polinomio definido pela equacao caracteristica de uma matriz poly([1 ...
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// Find Id,Vds,Vgs,Av // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 7-27 in page 331 clear; clc; close; // Given data Idss=3; // Drain-source current in mA Vp=-2.4; // Pinch off voltage in volts // Calculation printf("Id^2-6.73*Id+5.76=0\...
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clc mode(1) pause //Zadatak 1 //a) //Plotanje i definisanje funkcija deff('res=funct_1(x)','res=cos(x)-x'); x0 = 0; x = linspace(-2,2,51); y=cos(x); plot(x,y,'r-'); plot(x,x,'b-'); pause //Poziv fsolve xsol =fsolve(x0,funct_1) pause //b) //Plotanje i definisanje funkcija deff('res=funct_2(x)',['res(1)=x(2)-(x(1).^2+1)...
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clear;lines(0); A=rand(5,2)*rand(2,5); [Q,M]=fullrf(A); norm(Q*M-A,1) [X,d]=rowcomp(A);Y=X'; svd([A,Y(:,1:d),Q]) //span(Q) = span(A) = span(Y(:,1:2))
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//=========================================================================== //chapter 7 example 18 clc;clear all; //variable declaration VL =400; //voltage in V IL = 10; //current in A //r = W1/W2 //tan(phi) = sqrt(3)*((W1-W2)/(W1+W2)) //tan(phi) = sqrt(3)*((1-(W2/W1))/(1+(W2/W1))) //tan(phi) = sq...
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : FLOAT_W -- Unit(s) Under Test: float_example -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIP...
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// Scilab Code Ex16.6: Page-598(2014) clc; clear; c = 1; // Assume speed of light to be unity clf(); v = [0:0.01:0.92]'; bita = v/c; // Recession velocity ratio for i = 1:1:93 red_shift(i) = sqrt((1+bita(i))/(1-bita(i)))-1; end plot(bita, red_shift); title('The relation between Redshift and...
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// Scilab code: Ex3.24 : Unertainity in the position of an electron:Pg: 94 (2008) m = 9.1e-31; // Mass of an electron, kg v = 300; // Speed of electron, m/s h_bar = 6.6e-034; // Reduced Plancks constant, joule second p = m*v; // Momentum of electron, kgm/s del_p = 1e-04*p; // Minimum uncertainity in...
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//Fluid Systems - By - Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.10 //To Find the Power required to overcome the friction of Delivery pipe when (a)No air vessel is fitted on it , (b)A large air vessel is fitted at the centre line of the pump. clc clear //Given Data:- ...
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Name=Circle Strafes Fast PlayerCharacters=Quaker BotCharacters=Cycle Strafes.rot IsChallenge=true Timelimit=100.0 PlayerProfile=Quaker AddedBots=Cycle Strafes.rot PlayerMaxLives=0 BotMaxLives=6 PlayerTeam=2 BotTeams=1 MapName=circleplats.map MapScale=3.0 BlockProjectilePredictors=true BlockCheats=true In...
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//Example 4 // Young's modulus clc; clear; close; //given data : l=3;// in m n=600;// in Hz p=8.3*10^3;// in kg/m^3 Y=p*n^2*(2*l)^2; disp(Y,"Youngs modulus,Y(N/m^2) = ")
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// Grob's Basic Electronics 11e // Chapter No. I // Example No. I_5 clc; clear; // Express the resistance of 1,000,000-Ohms using the appropriate metric prefix from Table I–2. disp ('First, express 1,000,000-Ohms in engineering notation: 1,000,000-Ohms = 1.0*10^6-Ohms') disp ('Next, replace 10^6 with its corre...
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clear; clc; disp("--------------Example 3.27---------------") ratio=10; // power of signal after amplification/initial power of signal = p2/p1 amp=10*log10(ratio); // formula to calculate amplification or gain of power printf("The amplification is %d dB.",amp); // display result
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function t = taylor(x0 , x , n) t = exp(x0) for i = 2: n t = t+exp(x0)*(x - x0)^(i-1)/factorial(i-1) end endfunction t = taylor(-4.63,3.94,17)
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clc //variable initialization V=380 //line voltage in volts P=8 //number of poles f=50 //frequency in Hz n=1.25 N1=600 //speed in rpm N2=400 //speed in rpm //solution Ns=(120*f/P) s=(Ns-N1)/Ns Vd1=(3*sqrt(6)*s*(V/sqrt(3)))/(%pi*n) m=(3*sqrt(6)*(V/sqrt(3)))/(%pi*Vd1) a=acosd(-(s*(n/m))) s1=(Ns-N2)/Ns s...
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function [summ]=halfsum(m,n) //A=[1,5,9;2,6,10;3,7,11;4,8,12] A = ceil(rand(m,n)*10) disp(A) s = size(A) m = s(1) n = s(2) sumk = 0 if(m >=n) for (i=0:(m-1)) for(j=i:(n-1)) //disp(A($-i,j+1)) sumk= sumk + (A($-i,j+1)) e...
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clear ; clc; // Example 7.3 printf('Example 7.3\n\n'); // Page no. 171 // Solution Fig. E7.3 printf("Drawing as in fig E7.3 is not possible with scilab.")
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#---------------------------------------------------------------------- # STIDP -- Store CPU ID #---------------------------------------------------------------------- # Fixed test values cpuverid AA cpumodel 4444 cpuserial 666666 #--------------------------------------------------------...
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u=-1:0.1:1; y=uencode(u,3); disp(y); //output // column 1 to 19 // // 0 0 0 1 1 2 2 2 3 3 4 4 4 5 5 6 6 6 7 // // column 20 to 21 // // 7 7
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// Scilab code Ex17.16 : Pg:897 (2011) clc;clear; V = 1000; // Operating voltage of the GM counter, volt a = 1e-04' // Radius of GM counter wire, m b = 2e-02; // Radius of cathode, m E = V/(2.3026*a*log10(b/a)); // Maximum radial field at the surface of central wire of GM tube, V/m tau = 1e+09; // ...
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skey370.tst
*Testcase Storage Keys: pure System/370 only mainsize 3 numcpu 1 sysclear archlvl 370 loadcore "$(testpath)/skey370.core" f- 5000 f- 5800 runtest 0.2 *Done
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HOME=getenv("HOME") + "/"; PREMIADIR=HOME + "devel/premia/trunk-dev"; exec(PREMIADIR + '/nsp/libpremia/loader.sce'); premia_init() pb_list = PBLIST; t=cputime(); Lpb=pb_list; for pb=Lpb' printf("job %s\n",pb) load(pb); P.compute[]; end t=t - cputime(); printf ("cpu : %f\n", t);
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clc; N=10000; // Speed of gas turbine in rpm T01=700+273.15; // Total head temperature at nozzle entry in kelvin P01=4.5; //Total head pressure at nozzle entry in bar P02=2.6; // Outlet pressure from nozzle in bar p3=1.5;// Pressure at trbine outlet annulus in bar M=0.5; // Mach number at outlet alpha_2=70; // o...
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//example-21.4 //page no-632 //given //refer to fig-21.6 //width of loop //W=(OA+OB) //so W=80*2 //A/m //height of loop //H=(OC+OD) //wb/m^2 //so H=0.15*2 //Wb/m^2 //area of loop A=W*H //T A/m or J printf ("the energy loss per ubitvolume of the magnetic material during one cycle is %f J",A)
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//Chapter-11 example 45 //============================================================================= clc; clear; //Given data Pt = 100*10^3; // Peak tx. power PRF = 1000; // pulse repetitive freq. in Hz PW = 1.2*10^-6; // Pulse Width in sec //Calculations DC ...
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//Example No. 3_08 //-ve Integer to binary //Pg No. 50 clear ; close ; clc ; negint = -13 posbin = dec2bin(abs(negint)) posbin = strcat(['0',posbin]) compl_1 = strsubst(posbin,'0','d') compl_1 = strsubst(compl_1,'1','0') compl_1 = strsubst(compl_1,'d','1') compl_2 = dec2bin(bin2dec(compl_1) + 1) disp(com...
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function [found, coordinates] = findChessboardCorners(image1,pts_row,pts_col,flags) img1 = mattolist(image1); [found coordinates] = opencv_findChessboardCorners(img1,pts_row,pts_col,flags); endfunction
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@relation yeast-5 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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//Exa2.35 clc; clear; close; //given data Hc=7900;//in A/m d=1;//in mm r=d/2;//in mm r=r*10^-3;//in m Ic=2*%pi*r*Hc; disp("Critical current is : "+string(Ic)+" A");
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errcatch(-1,"stop");mode(2);//Ex:4.15 ; ; N_s=120; V_p=220; N_p=2000; V_s=N_s*V_p/N_p; printf("Secondry voltage = %f V",V_s); exit();
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//Reference: Edgar, Himmelblau and Lasdon,"Optimization of Chemical Processes",2nd Ed,McGraw-Hill Chemical Engineering Series,chapter 6 //The cost of refined oil when shipped via the Malacca Straits to Japan in dollars per kiloliter was given as the linear sum of the crude oil cost, the insurance, customs, freight cos...
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//EXAMPLE 2-80 PG NO-115-16 I=12+%i*0; X2=13.33; R=10+%i*13.33; V=I*R; disp('i) VOLTAGE (V) is in polar form = '+string (V) +' V ') V1=30-%i*27.67; Z1=10.6165+%i*1.5; R1=V1/Z1; disp('i) RESISTANCE (R1) is in polar form = '+string (R1) +' ohm ')
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// Distortion Matrix Examples Q1 = [0. 0. 1.1111 1.0784; 0. -1.5464 -1.7172 -0.1961]; Q2 = [0. 0.3191 1.3542 0.9804; 0. -2.1489 -2.2083 -0.098]; Q3 = [0. -0.5 0.9375 0.7692; 0. -2. -1. 0.1538]; [A1,Q1] = dist_mat(Q1,0.5); [A2,Q2] = dist_mat(Q2,0.7); [A3,Q3] = dist_mat(Q3,1.2);
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(unwatch all) (clear) (load "gnrcprc.clp") (dribble-on "gnrcprc.out") (testit) (dribble-off) (clear) (open "gnrcprc.rsl" gnrcprc "w") (load "compline.clp") (printout gnrcprc "gnrcprc.clp differences are as follows:" crlf) (compare-files gnrcprc.exp gnrcprc.out gnrcprc) (close gnrcprc)
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// Example 7.3 // Power Transfer from an Oscillator V_rms=1.2; Z_s=complex(6,8)*10^3; Z=conj(Z_s); // Matched Load Impedance P_max=V_rms^2/(4*real(Z));// Maximum availble power // If load has a fixed ratio X/R= -7/24 then, c=poly(0,'c'); Z_1= complex(24,-7)*c;// New value of // Since |Z_1|=|Z_s| q=abs(Z_1)-a...
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clc //initialisation of variables r= 3.5 T= 186 //F T1= 60 //F //RESULTS R= (((T+460)/(T1+460))^r-1)*100 //RESULTS printf ('percentage rise = %.1f per cent',R)
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clc clear //Input data Y=(7.25*10^10)//Youngs modulus of silver in N/m^2 K=(11*10^10)//Bulk modulus of silver in N/m^2 //Calculations s=(3*K-Y)/(6*K)//Poissons ratio //Output printf('Poissons ratio for silver is %3.2f',s)
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//Chapter-1,Example1_2_6,pg 1-15 n=8 wavelength=5890*10^-8 //wavelength of light u=1.46 //refractive index of oil i=30 //angle of incidence r=asind(sind(i)/u) //by Snell's law ...
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clc; fs=0.02; // full load slip ir=2; // ratio of starting current to full load current n=5; // number of section R=0.03; // rotor resistance //ir*ifl=(E2/R)*sm where ifl is full load current and E2 is induced voltage in rotor therefore sm=fs*ir; // maximum slip al=sm^(1/n); R1=R/sm; // resistance of whole sec...
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clc clear //Initialization of variables basis= 1 //kmol ammonia P=10^6 //pa a=4.19 b=0.0373 R=8314.3 Tc=405.5 Pc=11.28*10^6 //calculations disp("part b") an=27*R^2*Tc^2 /(64*Pc) bn=R*Tc/(8*Pc) V=3 //results printf("Since an and bn are same as a and b, V is the same = %d m^3/kmol",V)
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 2.9 //evaluation of a integral //given data //function of x=(2*x^2)+(3*x)+5) //limit=3 to 6 //calculation y=integrate('((2*x^2)+(3*x)+5)','x',3,6) disp(y,'value of the given integral is')
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.265035D+00 ...
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//increasing sigma_r src = imread("../images/cow2.jpg"); [output1 output2] = pencilSketch(src,120, 0.8,0.02 ); imshow(output1); //imshow(output2);
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function [B,A] = invfreq(H,F,nB,nA,W,iter,tol, plane) // Calculates inverse frequency vectors // // Calling Sequence //[B,A] = invfreq(H,F,nB,nA) //[B,A] = invfreq(H,F,nB,nA,W) //[B,A] = invfreq(H,F,nB,nA,W,[],[],plane) //[B,A] = invfreq(H,F,nB,nA,W,iter,tol,plane) // // Parameters // H: desired complex frequency resp...
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clc //Initialization of variables y1=[1.5 1.48] V1=[2.22 2.29] d=1.2 //calculations q=y1.*V1 V2=q/d Vm=[2.5 2.56] Rh1=[0.9 0.89] Rh2=[0.88 0.78] Rhm=(Rh1+Rh2)/2 S=(q.*Vm/ Rhm.^(2/3)).^2 dx=[358 226] yavg=(y1(1) + y1(2))/2 qavg=(q(1) + q(2))/2 B=4.5 Q=qavg*B //results printf("Flow rate = %.1f m^3/s",Q...
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clc // Given That r = 1 // distance from lamp in meter power = 100// power radiated by lamp in W mu_not = 1.2566e-6 // universal constant epsilon_not = 8.85e-12 // universal constant //Sample Problem 15 Page No. 87 printf("\n # Problem 15 # \n ") s = power /(4 * %pi * (r^2)) //calculation of intensity at a dist...
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//Example 12.7 clear; clc; SNRmaxmindB=96; SNRmaxminb=16; n=1; m1=((((SNRmaxmindB+3.41)/6.02)-n)/1.5); m1app=m1-0.042193;//Approximation for m1 k1=2^m1app; m2=((((SNRmaxmindB+11.14)/6.02)-n)/2.5) k2=2^m2; printf("k for first order Integrate Difference ADC : k=%.f",k1); printf("\nk f...