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// Exa 3.13 clc; clear; close; // Given data V_F= 0.2;// in V T=300;// in K V_T= T/11600;// in volt Io= 1;// in micro amp Io=Io*10^-6;// in amp Id= Io*(%e^(V_F/V_T)-1) I_F=Id; r_dc= V_F/I_F;// in ohm disp(r_dc,"Dynamic resistance in ohm is : ") r_ac= .026/I_F;// in ohm disp(r_ac,"Static resistance in ohm...
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// Scilab code Ex4.12: Pg:149 (2008) clc;clear; Lambda = 6500e-007; // Wavelength of light, mm Lambda_prime = 5200e-007; // New wavelength of light, mm n = 3; // Order of bright fringe D = 1200; // Distance between the source and the slits, mm d = 2/2; // Separation between teh slits, mm x3 = n*La...
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function [e] = sim1(x0,xn,n) deff("y=f(x)","y=sqrt(x^2+1)") h=(xn-x0)/n s=0 while x0<xn s=s+(h/3)*(f(x0)+4*f(x0+h)+f(x0+2*h)) x0=x0+2*h end e=(abs(s-1.147)/1.147)*100 disp(s) endfunction
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// // "vib-tr.sce" // clear; clf(); function dx = model(t,x) om=1.6; dx(1) = x(2); dx(2) = -0.2*x(2) - x(1) + cos(om*t); endfunction x0 = [0; 0.3]; tt = linspace(0, 100, 800); xx = ode(x0, 0, tt, model); g=gca(); g.data_bounds=[0,-1.5;100,1.5]; //座標軸の設定 plot(tt,xx(1,:),"-"); xtitle("x(t)=a(t)+b(t)"); xgrid(); ...
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//Exa 4.8 clc; clear; close; //Given data : r=(20/2)/10;//cm d1=4*100;//cm d2=5*100;//cm d3=6*100;//cm rdash=0.7788*r;//cm L=0.2*log((d1*d2*d3)^(1/3)/rdash);//mH disp(L,"Inductance per phase(mH)");
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function timeStretchedSignal = timeStretch(timeSignal, timeStretchFactor, ftLength) // timeStretchedSignal = timeStretch(timeSignal, timeStretchFactor, ftLength) Time-stretch a signal to timeStretchFactor times longer with phase vocoder // timeSignal is an input sound. ftLength is the FT size, defaults to 1024. ...
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--> A=[3,4,7,-2;5,4,9,3;1,-1,0,3;1,-1,0,0] A = 3. 4. 7. -2. 5. 4. 9. 3. 1. -1. 0. 3. 1. -1. 0. 0. --> --> [Q,R]=qr(A) Q = -0.5 0.5 -0.7071068 6.245D-17 -0.8333333 -0.0555556 0.5499719 -3.932D-17 -0.1666667 -0.6111111 -0.3142697 -0....
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// Example 8_13 clc;funcprot(0); // Given data T_1=-10;// °C P_3=0.9;// MPa Q_C=300;// kW C=0.07;// $/kWh C_n=0.50;// The cost of operating a furnace in $/therm q=100000;// kJ/therm // Calculation // (a) // From appendix D we find, h_1=183.1;// kJ/kg s_1=0.7014;// kJ/kg.K s_2=s_1;// kJ/kg.K h_3=71.9;//...
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clc;funcprot(0); //Example 6.3 //Initializing the variables d1 = 0.25; //Pipeline diameter d2 = 0.10; //Throat diameter h =0.63; //Difference in height rho = 1000; //Density of water g = 9.81 //Acceleration due to gravity //Calculations rh...
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//Ex3_15 // Image Sharpning using Laplacian // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; close; clear;...
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// Example no 9.6 // To determine the maximum throughput using ALOHA and slotted ALOHA // Page no. 466 clc; clear all; //The maximum throughput using ALOHA Rmax=1/2; //Maximum rate of arrival calculated by equating ALOHA throughput formula derivative to zero T=Rmax*...
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function [t_alpha] = stand_students_t_VarUnkn(alpha) if (alpha ==0.05) then t_alpha = 1.645; elseif (alpha==0.01) then t_alpha = 2.326; end endfunction
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//chapter 31 Ex 5 clc; clear; close; totalBalls=10; white=6; Black=4; random=2; sizeS= factorial(totalBalls)/(factorial(totalBalls-random)*factorial(random)); sizeE=(factorial(white)/(factorial(white-random)*factorial(random)))+(factorial(Black)/(factorial(Black-random)*factorial(random))); prob=sizeE/sizeS;...
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//Exa 1.14 clc; clear; close; //given data : Irms=30;//in A f=1;//in MHz Erms=10;//in mV/m Erms=Erms*10^-3;//in V/m r=50;//in Km r=r*10^3;//in m c=3*10^8;//speed of light i m/s lambda=c/(f*10^6);//in m le=Erms*lambda*r/(120*%pi*Irms);//in m disp(le,"Effetive height of Antenna in meter : ");
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 43 // read it as example 42 in the book on page 2.102 clc; disp("CHAPTER 2"); disp("EXAMPLE 43"); //VARIABLE INITIALIZATION I=5; // max amplitude of wave in Amp f=50; //Hz //wave for...
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clc; clear all; ap = 3; // as = 15; // wp = 2; // Analog Passband Edge ws = 4.828; // Analog Stopband Edge // Low Pass Filter // Order of filter n = 0.5*(log((10^((0.1)*(as)) - 1)/(10^((0.1)*(ap)) - 1))); N = n/(log(ws/wp)); N = ceil(N) disp...
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clc u_p=10; // m/s scale=1/25; // l_m/l_p L=125; // m meu=1.235*10^(-6); // m^2/s meu_p=1.188*10^(-6); // m^2/s rho_p=1025; // kg/m^3 rho_m=1000; // kg/m^3 A=3500; // wetted surface in m^2 u_m=u_p*sqrt(scale); d=L*scale; Re=d*u_m/meu; // Reynolds no. C_F=0.075/(log10(Re)-2)^2; // Skin friction coeffi...
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errcatch(-1,"stop");mode(2);//Example 2.5 : velocity ; ; //given data : n=1; Z=1; k=6.56*10^15; // k is constant fn=k*(Z^2/n^3); disp(fn,"orbital frequency,fn(Hz) = ") exit();
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////Given m=1.672*10**-27 //mass of neutron in kg h=6.60*10**-34 //Js v=1.0*10**-10 //de broglie wavelength in m //Calculation K=(h**2/(2.0*m*v**2))/(1.6*10**-19) //Result printf("\n Kinetic energy of a neutron is %0.2f *10**-2 ev",K...
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//Two bodies hung to rope //refer fig. 16.15 (a) and (b) s=(450+300)*(4*4-2*2)/(2*9.81*150) //m //Let T be the tension in the string //apply work energy principle T=((450*3.058)-((450*12)/(2*9.81)))/3.058 //N printf("\nT=%.0f N\ns=%.3f m",T,s)
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//ques-3.2 //Calculating number of molecules of ethene in sample and number of molecues of polyethene produced clc m=28;//mass of ethene (in g) deg=1000;//average degree of polymerisation //Part (i) n1=(m/28)*6.023;//number of molecules of ethene (x10^23) printf("The number of molecules of ethene in sample are...
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//Ex:4 clc; clear; close; h_p=1000;//perigee height in km h_a=4000;//apogee height in km R_E=6378.14;// radius of earth in km a=(2*R_E+h_p+h_a)/2;//Semi major axis in km u=3.986*10^5//km^3 per sec^2 T_P=(4*%pi^2*a^3/u)^(1/2);//Orbit period in sec printf("Orbital period =%f sec",T_P);
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// Exa 5.6 clc; clear; close; // Given data f_c = 2;// in kHz f_c = f_c * 10^3;// in Hz C2 = 0.033;// in µF C2 = C2 * 10^-6;// in F C3 = C2;// in F C = C2;// in F R2 = 1/(2*%pi*f_c*C);// in ohm R2 = R2 * 10^-3;// in k ohm R3=R2;// in kohm disp(R2,"The value of R2 and R3 in kΩ is : "); //R_F= 0.586*R1 R1...
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EX13_2.sce
//Finding of Boundary layer thickness , Drag Force //Given x=1; L=1.5; b=1.2; vs=0.25; mu=0.001; rho=1000; x2=1.2; L2=1.2; //To Find A=L*b; R=(rho*vs*x)/mu; t=(5.477*x)/sqrt(R); tau=(0.365*mu*vs*sqrt(R))/x; R1=(rho*vs*L)/mu; Cd=1.46/sqrt(R1); Fd=(1/2)*Cd*rho*(vs)^2*A; disp("Boundary Layer Thickness ="...
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//Eg-5.4 //pg-219 clear clc exec graf.sci clc A=[1 2 4;3 1 2;4 2 5]; a1=zeros(3,1); a1(1)=trace(A); A1=A; for k=2:3 A2=A*(A1-a1(k-1)*eye(3,3)); a1(k)=trace(A2)/k; A1=A2; end C=[1; -a1]; for(i = 1:4) c(i) = C(5-i); end ce = poly(c,'x','c'); printf('\nThe expression of...
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*Testcase bfp-004-cvttolog.tst: CLFEBR, CLFDBR, CLFXBR #Testcase bfp-004-cvttolog.tst: IEEE Convert To Logical #..Includes CONVERT TO LOGICAL 32 (3). Tests traps, exceptions, #..rounding modes, and NaN propagation. sysclear archmode esame # # Following suppresses logging of program checks. This test program, as ...
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clc //initialisations h=50//m g=9.8//m/sec2 l=1000 j=4.2//j/cal //calculations q=h*g/j t=q/l //results printf(' difference in temperature of water= % 1f C',t)
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//Solution 5-15 WD=get_absolute_file_path('5_15_solution.sce'); datafile=WD+filesep()+'5_15_example.sci'; clc; exec(datafile) Wdot_shaft = Wdot_shaft * 1000; Wdot_pump = eta_pump * Wdot_shaft / 100; mdot = Wdot_pump / (g * (z_2 + h_L)); //energy equation Vdot = mdot / rho; printf("Discharge rate of water is %1.4e m^3/s...
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//Example 14.6. clc format(6) Ai=1+80 disp(Ai," Ai = 1 + hfe =") Ri=(5*10^3)+((1+80)*(2*10^3)) //in ohm x1=Ri*10^-3 //in k-ohm disp(x1," Ri(k-ohm) = hie + (1+hfe)*RL =") Av=(81*2*10^3)/(167*10^3) disp(Av," Av = Ai*RL / Ri =") Ro=(5000+600)/(1+80) // in ohm disp(Ro," Ro(ohm) = hie+Rs / 1+hfe =") Rof=(69...
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//Example 6.6 clear; clc; //Given delHfus=6.0;//heatoffusion of water in kJ mol^-1 T=298;//temperature in K k=1.38*(10^(-23));//in J K^-1 N=10;//number of molecules //To calculate the probabilty that 10 molecules will be found in half of the container delS=N*k*log(0.5);//entropy change in J mol^-1 K^-1 w=delS/(2.303*...
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[Read-the-docs-example-10] # Read the docs - example 10 user_indice: {'indice_name': 'my_indice', 'calc_operation': 'nb_events', 'calc_operation': 'max_nb_consecutive_events', 'logical_operation': 'gt', 'thresh': 'p85', 'var_type': 'p'} in_files: ['pr_day_CNRM-CM5_historical_r1i1p1_19700101-19741231.nc','pr_day_CNRM-CM...
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clc Vr=10; //Assigning values to parameters Vl=15; Vc=10; V=sqrt(Vr^2+(Vl-Vc)^2); V=10+%i*0+0+%i*15+0-%i*10; [r,t]=polar(V); disp("Volts",r,"Voltage");
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function pkgQuit() f = pkgGetRootHandle(gcbo) btn = messagebox('All modification will be lost.','Exit','warning',['Continue','Cancel'],'modal') if btn==1 then xdel(f.figure_id) end endfunction
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 15") disp("In question no. 15 prove for ideal gas satisfies the cyclic relation is done which cannot be solve using scilab software.")
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//find transfer function of lag network printf("syms R1 R2 C\n ei=(R1+R2+(1/C)*s);\n eo=(R2+(1/C)*s);\n G=eo/ei;\n transfer function Eo(s)/Ei(s)is:G")
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//Example 5_16 clc(); clear; //To find IMA AMA and Efficiency of the system si=3 so=1 IMA=si/so Fo=2000 //units in Newtons Fi=800 //units in Newtons AMA=Fo/Fi effi=AMA/IMA*100 printf("IMA=%.2f\n",IMA) printf("AMA=%.2f\n",AMA) printf("Percentage of efficiency is %d percent",effi)
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// Determine primary and secondary voltages and current clc; clear; R1=100; R2=40; P=2; // Power r=sqrt(R2/R1); // n2/n1 Turns ratio if(r<1) printf(' The turns ratio is 1 : %g \n',(1/r)); else printf('The turns ratio is %g : 1 \n',r); end V1=sqrt(P*(R1)); V2=sqrt(P*(R2)); I1=V1/R1; ...
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Xs=8 Ia=40 V=600 Vt=V/sqrt(3) Ef=V delta=acos((1-(Xs*Ia/V)^2+(Vt/V)^2)/2/Vt*V) theta=-atan((cos(delta)-Vt/V)/sin(delta)) pf=cos(theta) Pout=sqrt(3)*V*pf*Ia disp(Pout) theta=-theta Pin=Pout disp(Pout)
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// Exa 10.14 clc; clear; close; format('v',7) // Given data P = 4; slots = 144; phi = 20;// in mWb phi = phi * 10^-3;// in Wb N = 720;// in rpm A = 4; P =4; n1 = 2;// in coil/slot n2 = 2;// in turns/coil Z = slots*n1*n2;// total number of conductor Eg = (N*P*phi*Z)/(60*A);// in V disp(Eg,"The induced v...
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function st=statgain(sl) //-compat type(sl)<>15 retained for list/tlist compatibility if type(sl)<>15&type(sl)<>16 then error(97,1),end flag=sl(1); select flag(1) case 'lss' dom=sl(7); [m,p]=size(sl(2)); if dom='c' then if rank(sl(2)) <> m then error('singular A matrix'),end st=sl(5)-sl(4)*inv(sl(2...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 7 //Properties of Solutions //Example 13 clear; clc; //Given: P = 20; //pressure in bar //Function for fugacity of component 1 function [y] = f1(x1); y = (50*x1)-(80*x1^2)+(40*x1^3) endfunction //To determine fugacity fugacity coeff...
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clc; Q=200; //heat in Btu(British Thermal Unit) m=50; //mass in lb c=0.5; //specific heat capacity inBtu/lb.F delT=Q/(m*c); //calculating change in temperatur using Q=mc(del T) disp(delT,"Change in Temperature in Farenheit = "); //displaying result. disp(25-delT,"Final Temperature in Farenheit = "); //...
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errcatch(-1,"stop");mode(2);//3.8 ; Sp_constant=10.5*10^-6*%pi/180; deflection=83; Td=Sp_constant*deflection; I1=10; K=0.078; I2=(Td/(K*I1))*10^6; printf("Current in the voltage coil=%.2f uA",I2) exit();
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//Example 5-2, Page No - 160 clear clc max_deviation = 25*10^3 fm =15*10^3 mf =max_deviation/fm printf('The deviation ratio of the TV sound is %.3f',mf)
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C19P4.sce
clear clc //to find speed of sound // GIVEN: //refer figure 19-8 from page no. 436 //frequeny f = 1080//in Hz //distances of water level at resonance x1 = 6.5//in cm x2 = 22.2//in cm x3 = 37.7//in cm // SOLUTION //using equation of sound wave for resonance //from first two resonances half_lambda = x2-...
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//Lendo imagens a = imread('a.jpg'); b = imread('b.jpg'); c = imread('c.jpg'); d = imread('d.jpg'); e = imread('e.jpg'); //Transformando imagem pra matriz de double a=im2double(a); b=im2double(b); c=im2double(c); d=im2double(d); e=im2double(e); a=matrix(a(:), size(a)); b=matrix(b(:), size(b)); c=matrix(c(:), size(c))...
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3.sce
//Variable declaration mew=1.33; //refractive index of soap t=5000*10**-10; //thickness(m) n0=0; n1=1; n2=2; n3=3; //Calculation x=4*mew*t; lamda1=x/((2*n0)+1); //for n=0 lamda2=x/((2*n1)+1); //for n=1 lamda3=x/((2*n2)+1); //for n=2 lamda4=x/((2*n3)+1); //for n=3 //Res...
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2_2.sce
clc //initialisation of variables F= 1 //Pouunda m= 1 //lbm g= 1 //fts^-2 //CALCULATIONS gc= m*g/F //RESULTS printf ('gc= %.2f lbm ft/poundal^2',gc)
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exp_5_3.sce
clear; clc; function [Ecom,Emag]=vcurves(Prtd,Xs,Vt,Phi,K); index=1; if index==1; X= input('percentage load'); Pg=X*Prtd; Vt=Vt/sqrt(3); pfang=Phi*%pi/180; x=pfang:-.005:-pfang; Pg=Pg*ones(1,length(x)); Ia=Pg./(3*abs(Vt)*cos(x)); Iacom=...
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//** ... a very crude temp solution ... exec(EESCI_DSPIC_PATH + "/NativeInteger/NAT_GAINBLK.sci"); exec(EESCI_DSPIC_PATH + "/NativeInteger/NAT_SUMMATION.sci");
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[0,600]x[0,400] S (20,40) (100,50) S (50,30) (100,200) S (10,100) (200,70) S (10,300) (300,370) S (50,5) (70,290) S (60,390) (80,100)
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//pathname=get_absolute_file_path('5.05.sce') //filename=pathname+filesep()+'5.05-data.sci' //exec(filename) //Mass of the block(in kg): m=1 //Temperature of the block(in K): T=27+273 //Height(in m): h=200 //Heat capacity for copper(in kJ/kg.K): s=0.393 //Acceleration due to gravity(in m/s^2): g=9.81 //Ch...
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clc //initialisation of variables h=300//cu ft p1=14.2//psia p2=150//psia w1=74//percent w2=88//percent q=33000//ft g=144//ft t1=0.74//ft t2=0.88//ft //CALCULATIONS I=(-g)*p1*h*log(p2/p1)/q//hp P1=I/t1//hp P2=P1/t2//hp //RESULTS printf('the isothermal horsepower=% f hp',P2)
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//Fuels and Combustion// //Example 8.20// w=1080;//quantity of water taken in grams// W=150;//Water equivalent of calorimeter in grams// m=0.681;//weight of coal taken or mass of fuel in grams// dt=3.61;//rise in temperature of water in degree C// AC=50;//Acid correction in calories// FC=5;//Fuse wire correction...
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clc; ApdB=3; Ap=10^(ApdB/10); disp(' ',Ap,"Ap=");
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[m^2-n^2,2*m*n,m^2+n^2].powerSum(2, 2, 1) = 0
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//Section-5,Example-8,Page no.-D.8 //To calculate rate constant and time taken to complete 80% of the reaction. clc; //k=2.303/t log( r_0/r_t) k=(2.303/50) *log10(1/0.6) disp(k,'Rate constant(min^-1)') t=(2.303/k)*(log10(1/0.2)) disp(t,'Time required when the reaction is 80% complete(min)')
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function G=fod(alpha,f,N,w) wl=w(1); wh=w(2); if f=='o' then exec('C:\Users\SAYAN\Documents\FuzzyFOPID\oustaloup.sci'); G=oustaloup(alpha,N,wl,wh); elseif f=='r' then exec('C:\Users\SAYAN\Documents\FuzzyFOPID\refOustaloup.sci'); G=refOustaloup(alpha,N,wl,wh); elseif f=='m' then exec('C:\Users\SAYAN\Documents\F...
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// Aim:Refer Example 4-8 for Problem Description // Given: // Kinematic viscosity of oil: nu=100; //cS // Diameter of steel pipe: D=1; //in // flow rate: Q=30; //gpm // Diameter of wide open globe valve: D_l=1; //in
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//(8.6) Consider a reheat–regenerative vapor power cycle with two feedwater heaters, a closed feedwater heater and an open feedwater heater. Steam enters the first turbine at 8.0 MPa, 480C and expands to 0.7 MPa. The steam is reheated to 440C before entering the second turbine, where it expands to the condenser pre...
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Example_10_2.sce
clear; clc; printf("Example 10.2\n"); th=[0 0 3 7 22 32 46 55 80 106]; //Time in hours tm=[0 26 5 36 16 38 50 25 22 25]; //Time in min //Conversion to kilo seconds for i=1:10 tm(i)=tm(i)*60; th(i)=th(i)*3600; tim(i)=(tm(i)+th(i))/1000; end L=[0 2.5 12.9 23.2 43.9 54.7 67.0 73.8 9...
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//Chapter-6,Example 6_5,Page 6-27 clc() //Given Values: B=10.9*10^-5 //Horizontal component of B in wb/m^2 u0=4*%pi*10^-7 //Permeability in free space H=B/u0 //Horizontal component of magnetic field printf('Horizontal component of magnetic field is =%.1f Ampere/meter \n',H...
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syms d Wmax=500 Wmin=200 sigmau=900 sigmae=700 FSu=3.5 FSe=4 Kf=1.65 A=(%pi/4)*d^2 Wm=(Wmax+Wmin)/2 sigmam=(Wm*10^3)/A disp(sigmam,"Mean stress=") Wv=(Wmax-Wmin)/2 sigmav=(Wv*10^3)/A disp(sigmav,"Variable stress=") 0=1-((sigmam*Kf)/(sigmau/FSu))-(sigmav/(sigmae/FSe))//according to Soderberg's relation d...
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//EX13_3 PG-13.3 clc clear disp("representation of the number 567 in power of 8") disp("N=(5*8^2)+(6*8^1)+(7*8^0)=375") printf(" Therefore decimal equivalent of 567 is: ") N=(5*8^2)+(6*8^1)+(7*8^0) printf("%.0f",N)
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clear; //clc(); s=15; sa=complex(s,0); s1=40; sb1=complex(s1*0.6,s1*0.8); sb=conj(sb1); s2=25; sc1=complex(s2*0.8,s2*0.6); sc=conj(sc1); st=sa + sb + sc; t_kvar=sqrt((real(st)^2) + (imag(st)^2)); printf("The kVA is:%.2f kVA\n",t_kvar); pf=real(st)/t_kvar; printf("The power factor is:%.4f lagging...
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mahara mahara V;ACT tahi tahia V;PASS mahara maharatia V;PASS whāngai whāngai V;ACT momotu motukia V;PASS hiki hiki V;ACT mutu mutua V;PASS aroha aroha V;ACT mihi mihi V;ACT tomo tomokia V;PASS kī kī V;ACT ako ako V;ACT pātai pātaitia V;PASS tūtaki tūtakitia V;PASS motu motukia V;PASS eke eke V;ACT hora hora V;ACT tuhi...
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Ex3_1.sce
// Problem 3.1,Page no.54 clc;clear; close; P=40 //mm //Force applied to stretch a tape L=30 //m //Length of steel tape A=6*1 //mm //Cross section area E=200*10**9*10**-6 //KN/m**2 //Modulus of Elasticity //Calculations sigma_L=(P*L*10**3)*(A*E)**-1 //mm //Result printf("The Elongation of steel tape is %.1f mm",s...
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exa6_9.sce
// Example 6.9 // AC Network With a Controlled Source // Form figure 6.22(b) V_m=20; // Voltage phasor magnitude phase_v=0; // voltage phasor phase omega=1000; // Radian frequency (rad/s) Z_R1=6; Z_R2=12; C=250*10^-6; // Farad L=8*10^-3; // Henry Z_C=1/(%i*omega*C); Z_L=%i*omega*L; // Using Proportionality ...
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ex6_9.sce
// Exa 6.9 clc; clear; close; format('v',7) // Given data Vout = 12.5;// in V Vin = 0.25;// in V Av = Vout/Vin;// unit less disp(Av,"The voltage gain without feed back is "); Vin = 1.5;// in V Avf = round(Vout/Vin);// unit less // Avf = Av/(1+(Beta*Av)); Beta = ((Av/Avf)-1)/Av;// unit less Beta = Beta*100...
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// Example 1.11 clear; clc; close; format('v',8); // Given data f=50;//in Hz P=4;//no. of poles Pin=50;//in kW N=1440;//in rpm StatorLoss=1000;//in watts FrictionalLoss=650;//in watts //Calculations Ns=120*f/P;//in rpm S=(Ns-N)/Ns;//Slip N=Ns*(1-S);//in rpm P2=Pin-StatorLoss/1000;//in KW //formul...
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//Example 6.10 clc;clear;close; x=[1 1 2 2 3 3]; //Calculation of DFT X=fft(x,-1); X=clean(X); disp(x,'Given Sequence is x(n): '); disp(X,'DFT of the Sequence is X(k): '); subplot(3,1,1); plot2d3(x); title('Given Seqence x[n]:');ylabel('Amplitude--&gt;');xlabel('n--&gt;'); subplot(3,1,2); plot2d3(abs(X)); title('Magni...
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solved_layout_cube.tst
###TStar Version 05 Tree Description File ###USER=Unknown ###TIME=Sat Nov 28 21:46:28 2009 n=0;h=0;d=2; v:op=12;n=1;h=0;d=2; ^ v:op=12;n=2;h=0;d=2; v:op=0;n=3;h=0;d=2; ^ ^ v:op=12;n=4;h=0;d=2; v:op=0;n=5;h=0;d=2; v:op=2;n=6;h=0;d=2; v:op=2;n=7;h=0;d=2; ^ ^ ^ ^ ^
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// calculate output across load resistor // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 10-8, page 333 clear;clc; close; // Given data B=200; re=180;// in ohms R1=10*10^3;// in ohms R2=2.2*10^3;// in ohms Rc=3.6*10^3;// in ohms Vg=1*10^-3;// in v...
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clc; //Example 12.2 //page no 125 printf("Example 12.2 page no 125\n\n"); //to calculate reynolds number L=2.54//diameter of tube in cm rho=1.50//density of liquid in gm/cm^3 v=20//velocity of flow in cm/s meu=0.78e-2//viscosity of liquid in g/cm*s printf("\n diameter of tube L=%f cm\n density rho=%f gm/cm^3\...
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//Fiber Optics Communication Technology, by Djafer K. Mynbaev and Lovell L.scheiner //Windows 8 //Scilab version- 6.0.0 //Example 5.3.2 clc; clear ; //given lambda=1550;//operating wavelength in nm deltalambda=1;//wavelength in nm L=1;//length of fiber in km Dmatlambda=20;//material dispersion in ps/nm.km Dw...
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//Variable declaration: //From figure 16.13, for ideal countercurrent heat exchanger: T1 = 150.0 //Inlet temperature of hot fluid ( F) T2 = 100.0 //Outet temperature of hot fluid ( F) t1 = 50.0 //Inlet temperature of cold fluid ( F) t2 = 80.0 ...
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ppppStrafer6ShooterInvincible.sce
Name=ppppStrafer6ShooterInvincible PlayerCharacters=6Shooter BotCharacters=Quaker Bot Fast Strafes.bot IsChallenge=true Timelimit=60.0 PlayerProfile=6Shooter AddedBots=Quaker Bot Fast Strafes.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=cataIC.map MapScale=3.8125 BlockProjectilePredictors=true Blo...
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// Grob's Basic Electronics 11e // Chapter No. 28 // Example No. 28_14 clc; clear; // For the pnp transistor, solve for Vb, Ve, Ic, Vc, and Vce. // Given data R1 = 33*10^3; // Resistor1=33 kOhms R2 = 6.2*10^3; // Resistor2=6.2 kOhms Rc = 2*10^3; // Collector resistance=2 kOhms Re = 500; ...
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// ================================================================================= // InverseKinem.sci // ================================================================================= function [Ret, Joints] = scrInvKinem (KinemParams, TCP0) // // DESCRIPTION // Solves the Inverse Kinematics problem of a Scara-R...
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// Example 4.4 clc; clear; close; // Given data format('v',6); Vout= '(-2*V1+3*V2+4*V3)';//given expression R3= 10;// in kΩ // Vout= -(Rf/R1*V1+Rf/R2*V2+Rf/R3*V3) (i) // Compare equation(i) with given expression Rf= 4*R3;//in kΩ R2= Rf/3;// in kΩ R1= Rf/2;// in kΩ disp(Rf,"The value of Rf in kΩ is :...
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// Exa 7.2 clc; clear; close; // Given data H1 = 3100;// in kJ/kg H2 = 1950;// in kJ/kg C1 = 20;// in meter/second C2 = 30;// in meter/secon Q = 0;// in kJ/kg Q_desh= 20;// in kJ/kg Vs= 1.1;// in m^3/kg W = H1-H2+(C1^2-C2^2)/(2*1000)+Q-Q_desh;// in kJ/kg m= 2;//mass flow rate in kg/sec Power= m*W;// in kW...
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// Exa7.14 clc; clear; close; // given : phi=5 // HPBW,half power beam width in Degrees phi_not=2*phi // BWFN, null-to-null beam width in degrees Lm=poly(0,'Lm') // defining Lm as lambda // formula : phi=70*(Lm/D_a) // where Lm is wavelength in m and D_a is mouth diameter in m D_a=(70*Lm)/phi G_p=6.4*(D_a/Lm)...
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// calculating the temperature after 1.5 s clc; th0=100; t=1.5; tc=3.5; th=th0*[1-exp(-t/tc)]; disp(th,'temperature after 1.5 s (degree C)')
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 6 Example # 6.4 ") //Temperature of device casing in degree K Ts = 353; //Length of holes in m L = 0.3; //Diameter of holes in m D = 0.0025...
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clc; m=300;//g, mass of each rod mom=1/1000;//given mo/m vo=2000;//m/s, relative velocity wo=60;//rpm wo=wo*2*%pi/60;//rad/s, conversion a=800;//mm, radius of disk a=a/1000;//m, conversion into meter //By theorytical work we get wx=-4/5*mom*vo/a;//rad/s , x component of angular velocity wy=0;//rad/s , y comp...
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//Exa:1.31 clc; clear; close; f=50;//in hertz P1=6;//No. of poles P2=4;//No.of poles N_s1=120*f/P1;//Synchronous Speed of 6-pole motor N_s2=120*f/P2;//Synchronous Speed of 4-pole motor N_sc1=120*f/(P1+P2);//Concantenated Speed of set when cumulatively compounded (in rpm) N_sc2=120*f/(P1-P2);//Concantenated Sp...
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clc;funcprot(0);//Example 8.8 //Initilisation of Variables mh=10;....//Mass flow rate of water in kg/s L=6.7;.....//Lemgth of the tubes in m Do=0.026;....//Diameter of tube in m hi=470;....//Inside heat transfer coefficient in W/m^2 K ho=210;.....//Outside heat transfer coefficient in W/m^2 K Tci=15;......//Inle...
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// ====================== S-params Converter ==================== // // (Semi)Intelligent Differential S-param Viewer // // Diff port mode selection GUI // // (c)2014 L. Rayzman // // GUI interface based on UICONTROL2 GUI demo // // Created : 06/23/2014 // Last Update : // // ==============...
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function y1=formula(u1); y1=-5169*u1*u1+21240*u1+6135; disp(y1); endfunction
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// exa 7.10 Pg 212 clc;clear;close; // Given Data d=35;// mm d2=125;// mm n=6;// factor of safety T=800;// N.m N=350;// rpm tau_s=63;// MPa tau_b=56;// MPa tau_CI=10;// MPa tau_k=46;// MPa // Diameter of bolts: F=2*T*10**3/d2/n;// N //%pi/4*db**2*tau_b=F db=sqrt(F/(%pi/4*tau_b));// mm printf('\n (i) Diameter of bolts...
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// Exa 1.18 clc; clear; close; // Given data V_gamma = 0.7;// in V R1 = 5*10^3;// in ohm R2 = 10*10^3;// in ohm V=5;// in V disp("Part (a)") I_R2 = (V-V_gamma-(-V))/(R1+R2);// in A I_D2 = I_R2;// in A disp(I_D2*10^3,"The value of I_D1 and I_D2 in mA is"); V_o = V - (I_D2 * R1);// in V disp(V_o,"The value ...
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clc //initialisation of variables T1=500 //R T2=2000 //R P1=30 //lbf/in^2 P2=20 //lbf/in^2 M=32.00 //ft S2=11.515*log(T2/T1) s1=2*172*(1/sqrt(T2-1/sqrt(T1))) s=-1530*[(1/T2-1/T1)] s3=-1.986*log(P2/P1) //CALCULATIONS S=S2-s1+s+s3//Btu/lb mole R S2=S/M//Btu/lbm-R //RESULTS printf('The change in entropy p...
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//Exa 5.21 clc; clear; close; //Given data : P=50*10^6;//VA pf=0.8;//power factor cos_fi_r=pf; sin_fi_r=sqrt(1-cos_fi_r^2); A=0.98*expm(%i*%pi/180*3);//parameter of 3-phase line D=0.98*expm(%i*%pi/180*3);//parameter of 3-phase line B=110*expm(%i*%pi/180*75);//parameter of 3-phase line C=0.0005*expm(%i*%pi/1...
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PL/SQL Developer Test script 3.0 21 -- 测试游标更新数据 -- 默认情况 游标是只读的 declare -- 声明游标 -- 用 for update表示用于更新 cursor emp_cursor(l_deptno number) is select * from emp_bak e where e.deptno=l_deptno for update; begin for emp_row in emp_cursor(20) loop -- 更新值到当前的记录 update emp_bak e set e.sal=3...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); sf=T_scene_create; sss=T_getscene; sss.ambientlightcolor=color(0.15,0.15,0.15); #sss.VolumeShadowAdd(0,color(0,0,0,0.5),0.002,20); refframe=sss.addsubframe("refframe"); sf1=sss.addsubframe("sf1"); obj=sf1.add("SolidObject"); cset=Contour(list(point(0,0,0),point(0,1...
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//ex13.4 V_IN1=3; V_IN2=1; V_IN3=8; //all resistors are of equal value so weight of each input is 1 V_OUT=-(V_IN1+V_IN2+V_IN3); disp(V_OUT,'output voltage in volts')
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//[]=tdinit() tit=["bioreactor model initialisation"; "competition model initialisation"; "system with limit cycle "; "linear system "; "quadratic model "; "linear system with a feedback "; "pray predator model initialisation"] ii=x_choose(tit," Systems Initialisation "); k=0; debit=0; x2in=0; ppr=0; ppa=0; pps=...
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sce
EX4_3.sce
clc //code uses userdefined function complexstring function s=complexstring(a) if imag(a)>=0 then s=sprintf('%g+%gi',real(a),imag(a)) else s=sprintf('%g%gi',real(a),imag(a)) end funcprot(0) endfunction //induction machine parameters in ohms r1=0.39 //pr...