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/PresentationFiles_Subjects - Kopie/CONT/NW42UPG/ATWM1_Working_Memory_MEG_NW42UPG_Session1/ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
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ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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example12_14.sce
clc // Given that t = 10 // time in days r = 15 // percentage fraction of sample which remain // Sample Problem 14 on page no. 12.36 printf("\n # PROBLEM 14 # \n") printf("Standard formula used \n") printf(" lambda = 0.693 / t_1/2 (Decay constant) \n N =N_0*e^(-lambda*t) \n") lambda = log(100 / 15) / t T = 0.693 ...
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Ex1_11_2.sce
//Ex 1.11.2 clc;clear;close; format('v',9); //Given : T=300;//K Ao=2.735*10^31;//constant for Si k=86*10^-6;//boltzman constant EGO=1.1;//volt(Bandgap energy) ni=sqrt(Ao*T^3*exp(-EGO/k/T));//per cm^3 disp(ni,"Intrinsic carrier concentration per cm^3 : ");
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Example54.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 5, Example 4") disp("Calculation at mean radius:") disp("Wc = U(Cw2 - Cw1) = U*DeltaCw") disp("or") disp(" Cp(T02 - T01) = CpDeltaT0s...
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2020-09-08T00:02:57.479436
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T2.tst
// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press 2004. Book site: http://www.idc.ac.il/tecs // File name: projects/07/MemoryAccess/StaticTest/StaticTest.tst. // Version: beta 1.4 load T2.asm, output-file T2.out, compare-to T2.cmp, o...
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2020-04-09T02:43:26.499817
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Ex1_48.sce
//Ex:1.48 clc; clear; close; E=60;// electric field strength in V/m n=120*%pi;// efficiency H=E/n;// magnetic field strength in Amp/m printf("The magnetic field strength = %f A/m", H);
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Ex6_5.sce
//caption:Find resolution and voltage //Ex6.5 clc clear close N=3//bit of D/A convertor V=5//full scale voltage(in V) A=0.001//magnitude of accuracy R=1/2^N disp(R,'resolution(in V)=') Ac=A*V disp(Ac,'accuracy(in V)=')
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Ex5_6.sce
//Example 5_6 page no:196 clc V=50; R=10;//resistance in ohm L=0.5;//inductance in henry C=10*10^-6//capacitance in farad f=50//frequency in Hz Xc=1/(2*3.14*f*C) Xl=2*3.14*f*L Z=sqrt(R^2+(Xl-Xc)^2) disp(Z,"the impedence is (in ohm)") I=V/Z disp(I,"current is (in A)") angle=atand((Xl-Xc)/R) disp(angle,"the...
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2020-04-09T02:43:26.499817
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12_5.sce
clear clc //initialisation of variables nm= 360 d= 1.5 //in n= 100 dp= 12 //in vm= 4.8 //ft/sec Tm= 52 //sec T= 16 //lb-ft t= 133 //lb ft //CALCULATIONS vp= n*dp*vm/(nm*d) Tp= Tm*dp^2*vp^2/(d^2*vm^2) N= Tm*vm*6080*100/(T*2*%pi*nm*60) W= Tp*vp*65000/10.67 T1= W/(N*2*%pi*n*60)-t //RESULTS printf ('Spee...
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5_3.sce
clc //initialisation of variables d= 13.6 //gm/cm^3 g= 980 //cm/s^2 D= 0.4 //mm angle= 130 //degrees s= 514 //dyn/cm //CALCULATIONS h= (4*s*cosd(angle))/(d*g*D*10^-1) //RESULTS printf (' Difference in mercury level= %.2f cm (depression)',h)
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/2d_conduction_steady_3by3.sce
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2d_conduction_steady_3by3.sce
//2d conduction with grid of 3*3 points pathname=get_absolute_file_path('2d_conduction.sce') filename=pathname+filesep()+'2d_conduction_data.sci' exec(filename) C=[-(T_left+T_bottom);-T_bottom;-(T_right+T_bottom);-T_left;0;-T_right;-(T_left+T_top);-T_top;-(T_right+T_top)] //matrix of constants A=[-4 1 0 1 0 0 0 0 0 1 -...
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lalabest.sce
Name=lalabest PlayerCharacters=PUBG Char BotCharacters=Pigeon.bot;target.bot;air1F_close_short.bot;Quaker Bot Easy.bot;Tank QC Fast Strafes.bot IsChallenge=false Timelimit=60.0 PlayerProfile=pistol Launchman AddedBots=Pigeon.bot;Pigeon2.bot;Pigeon3.bot;Pigeon4.bot;Pigeon5.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0;0 Play...
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detectAgastFeatures.sci
// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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Chapter5_Example23.sce
//Chapter-5, Example 5.23, Page 215 //============================================================================= clc clear //INPUT DATA N=2000;//Speed of the engine a=0.06;//Thermal diffusivity in m^2/h //CALCULATIONS t=1/(60*N);//Period of on oscillation in h x=(1.6*sqrt(3.14*a*t))*1000;//Depth of pe...
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Example7_4_a.sce
//Example 7.4 (a) //Program to Calculate Value of Rb in the Biasing Circuit clear; clc ; close ; //Given Circuit Data Vcc=6; //V Vbe=0.3; //V Icbo=2*10^(-6); //A Ic=1*10^(-3); //A Beeta=20; //Calculation //Case 1: Considering Icbo and Vbe in the calculations Ib=(Ic-(Beeta+1)*Icbo)/Beeta; Rb1=(Vcc-Vbe)/Ib;...
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test17.tst
1;re;0 4;- 3;- p1,p2;-;-;i;2;0;- blizzard 1 status
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8_6.sce
clear clc disp('Exa-8.6'); disp('The Oxygen atom has a configuration of 1s2,2s2,2p4. 4 electrons in the outer most shell.'); disp('Let us maximize the net spin by assigning a spin of 1/2 to 3 of them but the fourth should have spin of -1/3. Hence S=3/2-1/2=1.'); disp('The consistent values of L for the 3 elec...
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36.sce
clc disp("(i) Air and benzene vapour ") // C6H6(g) + 7.5O2(g) + 7.5*(79/21)N2(g) = 6CO2(g) + 3H2O(g) + 7.5*(79/21)*N2(g) LHVp=3169500; //kJ/mole LHVv=LHVp/((12*6+6*1)+(7.5*32)+7.5*(79/21)*28) disp("LHVv per kg of mixture =") disp(LHVv) disp("kJ/kg") m=54; //kg/kg mole of fuel h_fg=2442; //kJ/kg HHVp...
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Ex_3_4.sce
//Example 3_4 clc; clear;close; //Given data: RL=3;//in ohm V=30;//in V //Solution : Vpeak=4*V/%pi;//V Vrms=Vpeak/sqrt(2);//V disp(Vrms,"(a) RMS value of output voltage in volt : "); //VL=sqrt(2/T*integrate('V^2','t',0,T/2));//V VL=V;//V Pout=VL^2/RL;//W disp(Pout,"(b) Output power(W) : "); Ipeak=VL/...
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//Example 6_1 clc(); clear; //To calculate the Electric field of a laser beam i=10^-3/(3*10^-6) //units in W/mts^2 c=3*10^8 //units in mts/sec u=4*10^-7 //units in SI n=1 E0=sqrt((i*2*c*u)/n) //units in V/mts printf("The electric field is E0=%.2f V/m",E0) //In text book answer is given E0=5...
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//ofprietoc@unal.edu.co function probarAjusteDeCurvas() //Los datos tabulados x = [0.0000000000001 1 2 3 4 5]//El 0.0000001 es para aproximarlo a 0 y poder calcular la aproximación logarítmica y = [2.1 7.7 13.6 27.2 40.9 61.1] //x = [1 4 6 8 13 15 16 20] //y = [21.6 19.8 19.1 26.4 26.1 ] //...
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// particle filter prediction // input params allow_prediction = %T; allow_correction = %T; allow_resampling = %T; x_0 = 1.5; y_0 = 2.5; a_0 = %pi/6; n_p = 200; n_it = 150; dt = 0.1; sigma_x0 = 0.5; // [m] sigma_y0 = 0.5; // [m] sigma_a0 = 0.1; // [rad] sigma_vx = 0.1; // [m/s] (1 cm/s) sigma_vy = 0.1; // [m/s...
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//Example 5.21 clc;clear;close; z=poly(0,'z'); H=(1+z^-1)/(1+3/4*z^-1+1/8*z^-2); pole=roots(numer(H)); zero=roots(denom(H)); disp(H,'System Transfer Function H(z)='); disp(zero,'System zeros are at'); disp(pole,'System poles are at '); plzr(H);
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clc pathname=get_absolute_file_path('9_5_5.sce') filename=pathname+filesep()+'955.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("part 1") Hr=HfSalt+3*HfWater-HfAcid-3*HfBase printf("Hr of the rxn=%f Kj/mol",Hr) dis...
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clear; clc; printf("\t\t\tProblem Number 6.2\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.2 (page no. 241) // Solution P1=10^6; //Pressure at volume V1=2 m^3 //Unit:Pa V1=2; //Unit:m^3 //V1=Volume at 10^6 Pa P2=8*10^6 // Increased Pressure //Unit:Pa //Boyle's law,P1*V1=P2*V2 V2=(P1*V1)/P2; //Volume oc...
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//example6.2 clc disp("The rate of change of inductance with deflection is,") disp("dL/d(theta)=d(12+6(theta)-(theta^2))/d(theta)=6-2(theta) uH/radian= 6-2(theta)*10^-6 H/radians") disp("From the torque equation,") disp("theta=(I^2)dL/(2*K*d(theta))") disp("therefore, theta=(8^2)*[6-2(theta)]*10^-6 /(2*12*10^-6)"...
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clear //Given m=9*10**9// constant q=1.6*10**-19// charge C r=10**-10// distance m //Calculation U=m*q**2/r// potential energy K=U/2.0// Kinetic energy //Result printf("\n Kinetic energy is %e J",K)
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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clear clc l1=100 l2=250 l3=400 r=.25/1000 l=.125/1000 I1=100 I2=120 I3=80 pf1=.7 pf2=1 pf3=.8 phi1=acos(pf1) phi2=acos(pf2) phi3=acos(pf3) Z1=l1 * ((r*cos(phi1))+(l*sin(phi1))) Z2=l2 * ((r*cos(phi2))+(l*sin(phi2))) Z3=l3 * ((r*cos(phi3))+(l*sin(phi3))) V=240 dv=(Z1*I1)+(Z2*I2)+(Z3*I3) ...
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## Tests of selection-set syntax and parser features set echo read <simple.fi set interactive =H resolve Special set resolution 15 resolve Event number resolution =TR resolve Special combination @min(=TR) resolve min operator @max(=TR) resolve max operator 24..97 resolve Range 24..97&=C resolve Range and conjunction 24...
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//reading the imag xdel(winsid()); I =imread('D:\standard_test_images\peppers_color.tif'); //converting image into grayscale I=rgb2gray(I); //plot the grayscale image figure,imshow(I);title("Original image"); I_orig=I; //addition of noise I = imnoise(I,'salt & pepper',0.7) ; figure,imshow(I);title("Noisy(sal...
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//Ex6_12 //Color Image Smoothning by Neighbourhood Averaging. // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; ...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 19.1w //calculation of the angular magnification //given data f=12*10^-2//focal length(in m) of the simple microscope D=25*10^-2//distance(in m) at which the image is formed away from the eye //calculation m=1+(D...
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clc; //Example 3.3 //Page no. 26 printf("Example 3.3 Page no. 26\n\n") //given at 30 degree temerature //properties of water from appendix A.2 density(rho),surface tension(sigma) rho=996 sigma=0.071 printf("rho=%f\kg/m^3\n surface tension (sigma)=%f N/m\n",rho,sigma) theta=0//negligible angle of contact g=9.8...
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Name=Horde Mode PlayerCharacters=Roman BotCharacters=Barbarian.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Roman AddedBots=Barbarian.bot;Barbarian.bot;Barbarian.bot;Barbarian.bot;Barbarian.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0;0 PlayerTeam=2 BotTeams=1;1;1;1;1 MapName=colosseum.map MapScale=6.0 Bl...
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// Scilab Code Ex2.17: Page-72 (2013) clc; clear u = 931.5; // Energy equivalent of 1 amu, MeV/u c = 1; // For simplicity assume speed of light in vacuum to be unity, m/s E_B = 4.24; // The dissociationenergy of the NaCl molecule, MeV M = 58.44*u; // Energy corresponding to molecular mass of NaCl, MeV ...
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clear; clc; // Example: 7.5 // Page: 269 printf("Example: 7.5 - Page: 269\n\n"); // Solution //*****Data******// P1 = 100;// [kPa] T1 = 250;// [K] Q = 0.1;// [cubic m/s] P2 = 500;// [kPa] M = 44;// [g/mol] R = 8.314;// [J/mol K] //****************// // Solution (a) // Work done by reversible ad...
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//Transport Processes and Seperation Process Principles //Chapter 11 //Example 11.1-1 //Vapour Liquid Seperation Processes //given data pa=[116.9 135.5 155.7 179.2 204.2 240] pb=[46 54 63.3 74.3 86 101.32] P=101.32 //eq: paxa+pb(1-xa)=P xa=[]; ya=[]; for i=1:6 xa(i)=(P-pb(1,i))/(pa(1,i)-pb(1,i)) ya...
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clc //initialisation of variables h1= 2.25 //in dh1= 6 //in h2= 4.125 dh2= 3 //in dt1= 107 //sec dt2= 120 //sec Cd= 0.62 g= 32.2 //ft/sec^2 d= 1.5 //in //CALCULATIONS r1= dh1/(dt1*12) r2= dh2/(dt2*12) k= Cd*%pi*(d/12)^2*sqrt(2*g)/4 A= k*(sqrt(h2)-sqrt(h1))/(r1-r2) Q= r1*A+k*sqrt(h1) //RESULTS print...
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//Determine the current in parallel branches and supply current clc; clear; Xl=%i*100; // Inductance R=10; // Resistance V=10; Xco=-%i*100; Q=abs(Xl)/R; Z0=Q*abs(Xco); I0=V/Z0; Ic=V/Xco; Il=V/Xl; Pi=V*I0; // Power Input Pc=(I0^2)*10; // Copper Loss // Frequency reduced to fo/2 Xl1=Xl/2;...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-3, Illustration 9, Page 61 //Title: Calculation of volume change with change in composition //=====================================...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 12 clc; disp("CHAPTER 7"); disp("EXAMPLE 12"); //no load cuurent of transformer ia 10A at pf of 0.25 lagging when connected to 400V, 50 Hz supply //VARIABLE INITIALIZATION v1=400; //primary voltage in Volts f=50; //Hz I...
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//To calculate the Approximate value of Dynamic Resistance of P N Junction under Forward Bias //Example 45.3 clear; clc; //(a)Case-I: Forward Bias of 1 V is applied ///////////////////////////////////////////////////////////////////////////// i1=10*10^-3;//Current in Amperes at 1 Volt i2=15*10^-3;//...
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clc clear printf("Example 3.3 | Page number 74 \n\n"); //find temperature in °C T = 250 //K t = T - 273.15 //°C printf("Temperature in °C = %.2f °C",t)
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction //c...
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//chapter-4 page 146 example 4.7 //============================================================================== clc; clear; //For a rectangular waveguide disp('For a rectangular waveguide the dominant mode is the TE10 mode.TE10 mode can propagate at a lower frequency'); f=9*10^9;//frequency in Hz wg=4;//guid...
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//MÉTODO DE RESOLUÇÃO RETROATIVA //Matriz = Matriz de coeficientes do sistema linear //b = vetor de termos independentes do sistema //x = vetor de soluções do sistema function x = resolucaoRetroativa (Matriz, b) //pegando o tamanho(dimensões) da Matriz [l,c] = size(Matriz); //inicia a resolução retrotiva...
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<!DOCTYPE html> <!--[if IE]><![endif]--> <html> <head> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> <title>Class ReceiveTransitionCondition </title> <meta name="viewport" content="width=device-width"> <meta name="title" content="Class ReceiveTransiti...
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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) then v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution8_18.sce') //Obtain path of data file dat...
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clc //Initialization of variables ps=0.5069 //psia p=20 //psia m1=0.01 m2=1 M1=18 M2=29 //calculations xw= (m1/M1)/(m1/M1+m2/M2) pw=xw*p //results printf("partial pressure of water vapor = %.3f psia",pw)
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//Exa 6.4 clc; clear; close; //Given data Q = 88;// in MJ Q=Q*10^3;// in kJ T1 = 190;// in °C T1 = T1 + 273;// in K T3 = -15;// in °C T3 = T3 + 273;// in K Eta_carnot = (T1 - T3)/T1; Wnet= Eta_carnot * Q;// in kJ CarnotPower= Wnet/3600;// in kWh disp(CarnotPower,"The value of Carnot Power in kWh is : ") ...
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// about the analytical integration for the analytical solution //Eg-13.4 //pg-529 clear clc x(1) = 0; yb(1) = 0; y(1) = 1; //Initial condition h = 0.1; deff('out = func(in1,in2)','out = 0.5*(1+in1)*in2^2') //Taking the exact values using the expression calculated analytically as y = 4/(4-2*x-x^2) ...
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R=210//m.N//kg.K(gas constant)\ T=20//degree celsius P=0.2//MPa(Pressure) V=40//litres(volume)
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 19.6w //calculation of the length of the tube and the angular magnification produced by the telescope //given data fo=200*10^-2//focal length(in m) of the objective lens fe=4*10^-2//focal length(in m) of the eyepiece ...
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errcatch(-1,"stop");mode(2);; ; A=[2 3;7 8]; disp(A,'A='); P=[0 1;1 0]; disp(P,'P(Row exchange matrix)=') disp(P*A,'PA=') //end exit();
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clear; clc; close; disp("Example 10.1") cmap=[14.1,6.50,20.0,0.82;13.5,5.88,18.1,0.84;13,5.32,16.4,0.83;12.5,4.81,14.8,0.83;12,4.36,13.4,0.83;11.5,4,12.2,0.84] disp(cmap,"Compressor map data in table:") Cpc=1004 Cpt=1156 f=0.03 //fuel-to-air ratio em=0.995 //efficiency T=6 //T=Tt4/Tt2 pb=0.95 //burner pressure ratio gm...
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clear; clc; // Example: 6.23 // Page: 239 printf("Example: 6.23 - Page: 239\n\n"); // Solution // *****Data******// T = 298;// [K] P = 10*10^5;// [Pa] Tc = 126.2;// [K] Pc = 34*10^5;// [bar] R = 8.314;// [J/mol K] //****************// a = 27*R^2*Tc^2/(64*Pc);// [Pa.m^6/square mol] b = R*Tc/(8*Pc...
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//Example 1.7<f> //draw the waveform of the signal x1(t)=r(3t+1) clc; clear all; t=-10:.001:10; for i=1:length(t) if t(i)>=-1/3 then x(i)=3*t(i)-1/3; else x(i)=0; end end //figure plot2d(x,t); xtitle('Required figure','t','x(t)')
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clc; T1=288; p2!p1=10; y=1.4; T2s=T1*[(p2!p1)^{(y-1)/y}]; nc=0.82; T2=(T2s-T1)/nc+T1; T3=973; y2=1.333; T4s=T3/[(p2!p1)^{(y2-1)/y2}] nt=0.85; T4=T3-(T3-T4s)*nt cp=1.005; cp2=1.11; Wi=cp*(T2-T1); Wo=cp2*(T3-T4); N=(Wo-Wi); Q=cp2*(T3-T2); Ceff=N/Q disp("$",Ceff*100,"cycle efficiency is:")...
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//example 4.54 //calculate Total rainfall in catchment //run-off by rainfall of 3.3cm in 3hrs clc;funcprot(0); //given A=[36 18 66]; //area of catchment fi=[0.9 1.1 0.5]; //fi index r1=[0.6 0.9 1.0]; //rainfall in first hour r2=[2.4 2.1 2.0]; //rainfall in second hour r3=...
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// 08.08.16 function Out=Sfparadata(varargin) Nargs=length(varargin); Fd=varargin(1); Ndu=25 ; Ndv=25; Np=[50,50]; if Nargs>=3 Ndu=varargin(2); Ndv=varargin(3); end; if Nargs>=4 Np=varargin(4); end; Tmp=Sf3data(Fd,Ndu,Ndv,Np); Out=Projpara(Tmp); endfunction
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Energy = -4.622E+05 Energy = -4.728E+05 Energy = -4.820E+05 Energy = -4.904E+05 Energy = -4.981E+05 Energy = -5.050E+05 Energy = -5.112E+05 Energy = -5.168E+05 Energy = -5.217E+05 Energy = -5.259E+05
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// Example no 6.4 // To design an RLC network that implements an IF quadrature FM detector // Page no. 273 clc; clear all; close; // Given data fc=10.7*10^6; //Cut-off frequency in Hz B=500*10^3; //Bandwidth in Hz...
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//2.3 clc; Vp_sec=230*2^0.5/4; alph=asind(12/Vp_sec); alph1=180-alph; //the diode will conduct from 8.89 degree to 171.51degree Angle_conduction=alph1-alph; printf("Conduction Angle = %.2f degree", Angle_conduction) Idc=4; R=1/(2*Idc*%pi)*(2*Vp_sec*cosd(alph)+(2*12*alph*%pi/180)-12*%pi); printf("\nResistance ...
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//Solutions to Problems In applied mechanics //A N Gobby clear all; //friction of bearings is to to neglected clc //initialisation of variables h=2240//ft g=32.2//ft g1=15//in w=1200//lbf q=12//ft r=1.5//ft t=3.28//tonf ft t1=1.7//tonf ft x=550//ft s=6//ft //CALCULATIONS T=((w*(g1/q)^2)/(h*g))*(3/r)//tonf...
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//Example 24.12. clc disp("(i) A + AB = A(1+B) distributive law") disp(" = A.1 law 2") disp(" = A law 4") disp('') disp("(ii) A + A''B = (A+A'')(A+B) distributive law") disp(" = 1.(A+B) law 6") disp(" ...
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// blkdiag2.sci form a block diagonal matrix from 2 matrices function Z = blkdiag2(X,Y) sizex = size(X); sizey = size(Y); Z = [X zeros(sizex(1),sizey(2)); zeros(sizey(1),sizex(2)) Y]; endfunction
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clear; clc; // Illustration 12.3 // Page: 671 printf('Illustration 12.3 - Page: 671\n\n'); // Solution // ***Data***// SsByA = 40; x1 = 0.25;// [moisture fraction] x2 = 0.06;// [moisture fraction] //***********// X1 = x1/(1-x1);// [kg moisture/kg dry solid] X2 = x2/(1-x2);// [kg moisture/kg dry so...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 6: CIRCUIT BREAKER // EXAMPLE : 6.1 : // Page number 545 clear ; clc ; close ; // Clear the work space and console // Gi...
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////given V1=.82 //volts V2=1.85 //volts lembda1=4.0*10**-7 //m lembda2=3.0*10**-7 e=1.6*10**-19 c=3.0*10**8 //m/s //Calculation lembda=(1/lembda2)-(1/lembda1...
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clear // // //Initilization of Variables sigma=326 //N/mm**2 //stress E=2*10**5 //N/mm**2 //Modulus of Elasticity FOS=2 //Factor of safety a=1*7500**-1 //Rankine's constant D=350 //mm //Overall Depth //Cover plates b1=500 //mm //width t1=10 //mm //Thickness d=220 //mm //Distance between two channels L=6000 //mm ...
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//scilab 5.4.1 //Windows 7 operating system //chapter 20 Cathode Ray Oscilloscope clc clear e=1.6*10^-19//e=charge of an electron Va=1000//Va=potential difference in volts m=9.11*10^-31//m=mass of an electron v=sqrt((2*e*Va)/m)//v=axial velocity of an electron l=2*10^-2//l=axial length of deflecting plates in ...
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//EX9_9 PG-9.24 clc L1=0.5e-3; L2=1e-3; C=0.2e-6; Leq=L1+L2;//total inductance for Hartley oscillator f=1/(2*%pi*sqrt(Leq*C)); printf("\n Therefore frequency of oscillation is %.f Hz \n",f) //there is a slight difference between the answer given in the book //and the and output in the book they have taken the...
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function trainCascadeObjectDetector(outputFolder,positiveInstances,negativeImages,varargin) // It creates trained cascade XML file // // Calling Sequence // trainCascadeObjectDetector(outputFolder,positiveInstances,"negativeImages") // // Parameters // outputFolder: Folder name to store trained cascade (cascade.xml) ...
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errcatch(-1,"stop");mode(2);//Chapter 2, Problem 6 a=2 //attenuation constant l=10 //length in Km //calculation of loss in dB a10=a*l loss=8.686*a10 printf("Loss in dB = %.2f dB",loss) exit();
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clc clear //Page number 495 //Input data m=3;//The rate at which ice melts in kg/hour t=28;//The external temperature in degree centigrade Li=3.3*10^5;//Specific latent heat of ice fusion in Jkg^-1 s=4.2*10^3;//The specific heat in Jkg^-1.C //Calculations Q=(m*Li)+(m*s*t);//The heat taken by the ice to m...
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clc w1=0.009 h1star=64.5 w2=0.029 h2star=109.5 h3=167.45 h4=125.66 mw3=1000 ma=(mw3*(h3-h4))/((h2star-h1star)-((w2-w1)*h4)) mprintf("ma=%fkg/s\n",ma)//ans vary due to roundoff error mprintf("Make up water required=%fkg/s",ma*(w2-w1))//ans vary due to roundoff error
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load MUX8Way16.hdl, output-file MUX8Way16.out, output-list in0%B1.16.1 in1%B1.16.1 in2%B1.16.1 in3%B1.16.1 in4%B1.16.1 in5%B1.16.1 in6%B1.16.1 in7%B1.16.1 select%B1.3.1 out0%B1.16.1; set in0 %XC000, set in1 %X3000, set in2 %X0C00, set in3 %X0300, set in4 %X00C0, set in5 %X0030, set in6 %X000C, set in7 %X0003, set sele...
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function s=%s_l_lss(s1,s2) // //! // Copyright INRIA s=inv(s1)*s2
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clear; clc; disp("--------------Example 30.10----------------") g=7; p=23; printf("\nThe steps are as follows:\n\n"); x=3; y=6; R1=modulo(g^x,p); // formuula R2=modulo(g^y,p); // formula printf("1) Alice chooses x = %d and calculates R1 = %d.\n\n2) Bob chooses y = %d and calculates R2 = %d.\n\n3) Alice sends ...
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clc // Given That lambda1 = 5.9e-5 // wavelength in cm lambda2 = 5.896e-5 //wavelength in cm lambda = 5.89e-5 // wavelength in cm grating_element = 4000 // lines per cm t = 4 // width of grating in cm n = 1 // for first order spectrum //Sample Problem 27 Page No. 58 printf("\n # Problem 27 # \n") printf(" \n...
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// Exa 12.12 clc; clear; close; // Given data n = 8; T_C = 9;//in µsec T_C = T_C * 10^-6;// in sec f_max = 1/(2*%pi*T_C*(2^n));// in Hz disp(f_max,"Maximum frequency in Hz is");
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//Fluid Systems - By - Shiv Kumar //Chapter 11- Centrifugal Pumps //Example 11.10 //To Find (i)Manometric Head (ii)Manometric Efficiency (iii)Overall Efficiency of the Pump. clc clear //Given Data:- Do=480; //External Diameter of the Impeller, mm ...
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${ // Enable extension methods by adding using Typewriter.Extensions.* using Typewriter.Extensions.Types; // Uncomment the constructor to change template settings. //Template(Settings settings) //{ // settings.IncludeProject("Project.Name"); // settings.OutputExtension = ".tsx"; ...
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clc; funcprot(0); //Example 8.4 Power Required by Wing // Initialisation of variables S = 350; V = 80; alpha = 6; Cd = 0.0452; // Value of Cd from fig 8.8 rho = 0.002378; // Calculations D = Cd*rho/2*S*V^2; HP = D*V/550; //Results disp(HP,"Horse power required to move the wing forward(hp) :"...
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// Exa 7.3 clc; clear; close; // Given data H1 = 2940;// in kJ/kg H2 = 2630;// in kJ/kg C = sqrt((H1-H2)*1000*2);// in m/sec disp(C,"Velocity of the steam leaving the nozzle in m/sec is");
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//(b)overlap-save method xn=[1 2 3 3 4 5]; hn=[1 1 1]; xon=[0 0 1 2 3]; x1n=[2 3 3 4 5]; x2n=[4 5 0 0 0]; yon=convol(xon,hn); y1n=convol(x1n,hn); y2n=convol(x2n,hn); yno=yon(3:5); yn1=y1n(3:5); yn2=y2n(3:5); yn=[yno yn1 yn2] YN=convol(xn,hn)
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//3º trabalho de Inteligência Computacional, rede neural //autor: Lais de Fátima Sousa Gomes, Matrícula 504405 clear; clc; //_____Algumas funções auxiliares________________ //função de rosenbrock function [z] = rosenbrock(x, y) z = (1 - x)^2 + 100*(y - x^2)^2; endfunction //converte para o valor real function [...
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function marche = marcheAleatoireReduc(nombre_pas, T, s) alpha = 1; for i=1:T:nombre_pas pas = genererRandBinomiale(1,0.5,1); s = sqrt(alpha * T); if pas == 0 then tabPas(i) = s; elseif pas == 1 then tabPas(i) = -s; end marche(i) = sum...
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//clc() F = 1000;//kg/h H1 = 116.3;//kJ/kg ( enthalpy of feed solution - 10% NaOH, 305 K ) H2 = 560.57;//kJ/kg ( enthalpy of thick liquor - 50% NaOH, 380 K ) Hsteam = 2676;//kJ/kg ( 1atm , 373.15K ) //by doing material balances, P = 200;//kg/h mvap = 800;//kg/h //Enthalpy balance gives, F*H1 + Q = mvap*Hsteam +...
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function [z,p,k] = sos2zp (sos, g) //This function converts series second-order sections to zeros, poles, and gains (pole residues). //Calling Sequence //z = sos2zp (sos) //z = sos2zp (sos, g) //[z, p] = sos2zp (...) //[z, p, k] = sos2zp (...) //Parameters //sos: matrix of real or complex numbers //g: real or complex ...
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//Program to find mean,S.D. and first r moments about mean of given n pairs (x) clc;clear;close; clc printf('\n\n Name - Syeda Reeha Quasar \n Enrolment No. - 14114802719 \n Group - C7 \n\n') n = input('Enter the no.of pairs of values (x.f) to find the mean = ') m = input('Enter the no. r = ') disp('Enter the value...
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// Scilab Code Ex5.9 :: Page-5.39 (2009) clc;clear; m_Ca_41 = 40.962278; // Mass of one Ca-41 nuclei, amu m_Ca_42 = 41.958618; // Mass of one Ca-41 nuclei, amu m_n = 1.008665; // Mass of a neutron, amu delta_m = m_Ca_42 - (m_Ca_41 + m_n); // Difference in the mass of Ca-42 and Ca_41 nuclei, amu E = del...
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clc; clear; lambda=5*10^-5 //wavelength in cm e=1/6000 //No. of lines per centimeter on the grating surface //calculation //1st order theta_1= asind(lambda/e) //angle in degree //3rd order theta_3= asind((3*lambda)/e) //angle in degree angle_of_deviation = theta_3 - theta_1 printf("Difference in the ...
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// Example 4.12 : Midband gain and upper 3dB frequency R_sig= 100*10^3; // (ohm) R_G=4.7*10^6; // (ohm) R_D=15*10^3; // (ohm) R_l=15*10^3; // (ohm) g_m=1*10^-3; // (mho) r_o=150*10^3; // (ohm) C_gs=1*10^-12; // (F) C_gd=0.4*10^-12; // (F) R_L= 1/(1/r_o + 1/R_D + 1/R_l) A_M=R_G/(R_G + R_sig)*g_m*R_L; disp(A_M...
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//A 4-point DFT from a 3-point sequence xn=[1;2;1]; w=exp(-%i*%pi/2); for i=1:4 for j=1:3 WN(i,j)=w^((i-1)*(j-1)); end end XDFT=WN*xn