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//write the time equation for voltage and current Vrms=150 Vm=2*1.414*Vrms f=50 L=0.2 X=2*3.14*f*L Im=Vm/X disp('current equation i=212.132sin(314)t' , 'voltage equation v=3.376sin(314t-90)' , ' Im= '+string(Im)+ ' ')
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function show_nodes(ns,sup) // Copyright INRIA [lhs,rhs]=argn(0) if rhs==1 then sup='pas de sup' else if rhs<>2 then error(39), end end // ns s=size(ns) if s(1)*s(2) == 0 then return end if s(1)<>1 then error('First argument must be a row vector') end // sup if type(sup)<>10|prod(size(sup))<>1 then error('Seco...
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clc //initialisation of variables p=200//ft p1=30//psia p2=90//psia t1=62//f t2=68//F t3=20//f t4=30//F t5=140//F w=250//Btu s=42.4//ft h=42.8//tons h1=82.15//ft h2=96.69//hp h3=95.08//ft h4=22.03//ft h5=23.42//ft h6=80.73//ft //CALCULATIONS W=(h*p)/(h6-h5)//lb per min J=W*(h2-h1)+w//Btu per min ...
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//chapter 10 //example 10.2 //page 290 clear all; clc ; //given gm=3;//in mA/V Rd=2.7;//in Kohm Rs=1; Rl=10; rd=100;//in Kohm Av=-gm*Rd/(1+gm*Rs); Rp=1/rd+1/Rd+1/Rl Av1=-gm*(1/Rp); printf('\nAv=%d for unbypassed series resistor and \nAv=%.1f for bypassed resistor with load resistor',Av,Av1)
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//Example 16.2 clc; syms z n; x1=(2^n); x2=(3^n); X1=symsum(x1*(z^-n),n,0,%inf); X2=symsum(x2*(z^-n),n,-%inf,0); X=X1+X2; disp(X,"ans=")
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//Example 4.16 clc //use of printf function i=2.0; //floating -point number j=3.0; //floating -point number printf("%f %f %f %f" ,i ,j,i+j, sqrt(i+j));
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// Example 6_1 clc;funcprot(0); // Given data V=300;// ft/s D=6/12;// ft R=D/2;// ft Z=15;// ft g=32.174;// ft/s^2 g_c=32.174;// lbm.ft/lbf.s^2 // Calculation // From the superheated steam table, Table C.3a in Thermodynamic Tables to accompany Modern Engineering Thermodynamics, we find that, at 100. psia an...
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// Exa 6.6 clc; clear; close; // given data AF=5;//unitless fc=1;//in KHz disp("To have a roll off rate of 40dB/decade a second order filter is requied."); disp("For flattest passband, butterworth type filter has to be used, hence alfa=1.414"); alfa=1.414;//unitless // assume C2=0.1 uF C2=0.1;//in uF C3=(C...
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clc disp("Example 1.49") printf("\n") disp("find the maximum forward current at 25c and 80c") printf("Given\n") T1=25 //to find maximum forward current at this temperature T2=80 //to find maximum forward current at this temperature VT1=0.65 //forward voltage drop(constant at all tem...
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clear; clc; close; disp("Example 4.2") m=50 //mass flow rate in kg/s ec=0.9 //compressore polytropic efficiency Tt2=288 //inlet total temp in K. pt2=100000 // inlet total pressure in Pa gm=1.4 //gama cp=1004 //specific heat in J/kg.K p=35 //total pressure ratio tr=p^((gm-1)/(gm*ec)) //relation between total ...
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//Chapter 18 //Example 18_16 //Page 450 clear;clc; kv=11; mva=25; X0=%i*0.05; X1=%i*0.2; X2=%i*0.2; Xn=%i*0.3; Er=1; pu_xn=Xn*mva*1000/kv^2/1000; I0=Er/(X0+X1+X2+3*pu_xn); I1=I0; I2=I0; Ir=3*I0; fc=mva*1e6/sqrt(3)/kv/1000*abs(Ir); printf("Per unit value of Xn = %.4f p.u \n\n", imag(pu_xn)); printf("I1=I2=I0=j(%.3f)...
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clear; lines(0); np=100; q=3; msig = 10; // номер строки, отвечающая нужной нам плотности прививки, с которой мы будем считывать j=0; w=190 s0 = '../n=' + string(np) + '/m=' + string(w) + '/zav_q/' ; s = s0 + 'zav_q=' + string(q) + '_' +'np=' + string(np) + '.dat'; s1 = '../n=' + string(np) + '/Re...
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clc; pathname=get_absolute_file_path('4_3_soln.sce') filename=pathname+filesep()+'4_3_data.sci' exec(filename) // Solution: // acceleration due to gravity, g=32.2; //ft/s^2 // Reynolds Number, N_R=(7740*v*D)/nu; // Head loss in pipe, H_L=round((64*L*(v^2))/(N_R*(D/12)*2*g)); //ft ,Hagen-Poiseuille Equation // Head los...
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clc Vacuum_recorded=740; //mm of Hg Barometric_reading=760; //mm of Hg Absolute_pressure=(Barometric_reading-Vacuum_recorded)*133.4; disp("Absolute pressure in the condenser=") disp(Absolute_pressure) disp("Pa")
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// calculates a compress factor to give the desired detail in the waterfall graph compress_factor = 1; while(((end_sample - (start_sample-1))/compress_factor) > 336 | (((end_sample - (start_sample-1))/compress_factor)) ~= int(((end_sample - (start_sample-1))/compress_factor))) compress_factor = comp...
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function titlepage(str,win) //titlepage(str) genere une page de titres graphiques contenant la ma- //trice de chaines de caracteres str ecrite centree dans la page avec //une taille de caractere maximale. //! //origine S Steer INRIA 1989 // Copyright INRIA [lhs,rhs]=argn(0) old=xget('window') if rhs==2 then xset('wind...
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ie=6; ib=120*10^(-3); ic=ie-ib; alpha=ic/ie; disp("the alpha of the transistor is"); disp(alpha);
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--------------------ROOT NODE @ Position (0, 2) ------------ --------------------START TREE ------------------------ Node number 0 Position 0,2 scored 48. BoardState[ --------------------- |O||O||O||O||O||O||O| --------------------- |O||O||O||O||R||R||O| --------------------- |O||O||O||R||R||R||O| ---------------------...
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h=20//inches S=1.9//Specific gravity of liquid
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f=50 w=2*%pi*f Z2=1000 Z3=16800 C=0.38E-6 Xc=1/%i/w/C Z4=833+Xc Z1=Z2*Z3/Z4 Rx=real(Z1) Lx=imag(Z1)/w disp(Rx) disp(Lx)
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// Scilab Code Ex5.20: Page-294 (2008) clc; clear; h = 6.62e-034; // Planck's constant, Js m = 9.11e-031; // Rest mass of a electron, kg delta_x = 1e-009; // Minimum uncertainty in position of the electron, m delta_p_min = h/delta_x; // Minimum uncertainty in electron's momentum, kg-m/s delta_v = delt...
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//Example 3.16.B clc; syms s; I=(8*(s^(2)))/((s+2)*(s+1)^(3)); i=ilaplace(I); disp(i);
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clear // //Given //Variable declaration P=60*10**3 //Load in N d=4*10 //diameter in mm L=5*10**3 //Length of rod in mm E=2e5 //Youngs Modulus in N/sq.mm //Calculation A=(%pi/4)*d**2 //Area in sq.mm V=int(A*L) //Volume of rod in cubic.mm //case (ii):stress in the rod ...
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host("make /tmp/Testc.o"); //Interface host("make /tmp/testcc.o"); //Called routines scifuncs=['funcc1','funcc2','funcc3','funcc4','funcc5']; //Scilab functions addinter(['/tmp/Testc.o','/tmp/testcc.o'],'testcentry',scifuncs) //matrix (double) created by C function funcc1() //matrix (int) created by C function func...
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//============================================================================== // chapter 7 example 6 clc; clear; // Variable declaration I1 = 20; // current in ma V1 = 0.8; // vtg in volts V2 = 0.7; // vtg in volts I2 = 10; // current in ma v3 = -10; I3 = -1*...
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function result= prob(N, M, K) if(N==1 & M==0) if(K >0) result = 1; else result =0; end elseif (N==0 & M==1) if(K <0) result = 0; else result =1; ...
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//Example 4_11 clc(); clear; //To calculate where the radius of the atom is present a=4/sqrt(2) R=a/2-1 printf("The radius of the atom is at R=%.3fr",R)
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clear;lines(0); plot2d([-100,500],[-100,600],[-1,-1],"022") x=0:100:200; xnumb(x,500*ones(x),[10,20,35],1)
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//variable initialization z1=29 //atomic no. of Copper z2=26 //atomic no. of Iron lembda1=193 //wavel...
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clear //Given B=49 Ie=12 //mA Ib=240 //microA //Calculation A=(B/1+B)*10**-2 Ic=A*Ie Ic1=B*Ib //Result printf("\n The value of Ic using A is %0.3f mA",Ic) printf("\n The value of Ic using B is %0.3f mA",Ic1*10**-3)
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clc; clear; function z=f(x,y) z=2*x*y + 2*x - x^2 - 2*y^2 endfunction x=-1; y=1; d2fx=-2; d2fy=-4; d2fxy=2; modH=d2fx*d2fy-(d2fxy)^2; for i=1:25 dfx=2*y+2-2*x; dfy=2*x - 4*y; //the function can thus be expressed along h axis as //f((x+dfx*h),(y+dfy*h)) function d=g(h) d=2*(x+dfx*h)*(y+dfy*h...
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scenario = "Cued_BOSS_1"; scenario_type = trials; active_buttons = 1; # left mouse button default_background_color = 100,100,100; pulse_width = 10; #should be >5 so we don't miss triggers by mistake response_matching = simple_matching; #so we can have hit/miss/fa resp write_codes = true; #Send and Register Codes pcl_...
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clear; clc; // Stoichiometry // Chapter 2 // Basic Chemical Calculations // Example 2.19 // Page 27 printf("Example 2.19, Page 27 \n \n"); // solution m1 = 100 //[kg] TEA solution (basis) m2 = 50 //[kg] TEA M1 = 149 // molar mass of TEA d = 1.05 //[kg/l] V = m1/d // volume of 100 kg sol. n = (m2...
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clear // // // //Variable declaration h=6.6*10^-34; //planck's constant(J-sec) m=9*10^-31; //mass of electron(kg) deltax_max=10*10^-10; //length of box(m) //Calculations deltavx_min=h/(deltax_max*m); //minimum uncertainity in velocity of electron(m/s) //Result printf("\n minimum...
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//Example 1.19.1 //whether the signal is energy signal or power signal clc ; t =0:0.001:10; y= exp (-10*t); E= integrate ( ' ( exp(-10*t)) ^2 ' , ' t ' ,0 ,2* %pi ); disp (E, ' Energy o f the s i g n a l i s ' ); disp ( 'since the energy is finite hence it is energy signal'); figure plot(t,y,'red'); xtit...
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clear // // //Given //Variable declaration Ds=20 //Diameter of steel rod in mm Di_c=40 //Internal diameter of copper tube in mm De_c=50 //External diameter of copper tube in mm Es=200*10**3 //Youngs modulus of steel in N/sq.mm Ec=100*10**3 //Youngs modulus of copper i...
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//Example 1.18 // wavvelength of light clc; //given data : b=.5D-2;//distace between succesive fringes in m u=1.4;//refractive index of cellophane a=10;//angle of wedge in sec a=a*%pi/(60*60*180);//to convert in radian w=2*u*a*b; w=w*1D10;//to convert in A disp(w,"wavelength of light used in A") //note: Pi ...
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function [b, a] = GetNoteIndexCoefficients(noteIndex) //function [b, a] = GetLetterCoefficients(noteIndex) //gets the bandpass filter values for the letter //noteIndex should go from 0 to 11, where 0 is e and 11 is d# //-1 will be D# as well, 12 corresponds to the higher e select noteIndex case -1 then /...
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clc //initialisation of variables clear m= 5.313*10^-23 //g k= 1.38*10^-16 T= 298 //K R= 82.06 //ml-atm /mol K h= 6.624*10^-27 //J /mol //CALCULATIONS Qt= (2*%pi*m*k*T)^1.5*R*T/h^3 //RESULTS printf ('Qt = %.2e ',Qt)
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//Example_a_4_5 page no:177 clc; Vrms=sqrt(5^2+(5^2/2));//the values are taken by comparing the given equation with rms equation disp(Vrms,"the rms value of the waveform is");
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clc,clear printf('Example 4.14\n\n') Ns=250 //Speed in rpm f=50 //frequency I_l=100 Slots=216 Conductors_per_slot=5 Pole=120*f/Ns phi=30*10^-3//flux per pole in weber Z=Slots*Conductors_per_slot //Total Conductors Z_ph=Z/3 //conductors per phase T_ph=Z_ph/2 //turns per phase n=Slots/Pole //slots per pole...
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//DTfT of periodic signals x=[3 2 1 2];//one period of signal n=0:3; k=0:3; x1=x*exp(%i*n'*2*k*%pi/4) dtftx=abs(x1) x=[3 2 1 2 3 2 1 2 3]; n=-4:4; a=gca(); a.y_location="origin"; a.x_location="origin"; plot2d3('gnn',n,x); xtitle('discrete periodic time signal'); x2=[dtftx dtftx 8]; a=gca(); xset('window'...
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//Example1-1 //Given clc; clear all; printf("(i) t1=d/c \n"); printf(" (ii) t2=[(d-5)/c]+[5/v2] \n"); printf(" v2=c/n2 \n"); printf(" t2=(d+2.5)/c\n"); printf(" (iii) delta_t=t2-t1=(d+2.5-d)/c\n"); c=3*10^8; //Speed of light in m/s delta_t=2.5*10^-2/c; //convert...
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//Exa3.23 clc; clear; close; // given data // (i) when I_D=2;// in mA I_D=I_D*10^-3;// in A V_D=0.5;// in V R1=V_D/I_D; disp("Resistace is : "+string(R1)+" ohm"); // (ii) when I_D=20;// in mA I_D=I_D*10^-3;// in A V_D=0.8;// in V R2=V_D/I_D; disp("Resistace is : "+string(R2)+" ohm"); // (ii) when I_D=...
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//Ex11_1 clc tsu=20*10^(-9) disp("tsu= "+string(tsu)+" seconds") // Input set-up time of second flip flop tpd=30*10^(-9) disp("tpd= "+string(tpd)+" seconds") // Input set-up time of first flip flop Tmin=tpd+tsu disp("Tmin=tpd+tsu= "+string(Tmin)+" seconds") // Minimum allowed time interval b/w threshold levels o...
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clear; clc; //Example - 7.27 //Page number - 261 printf("Example - 7.27 and Page number - 261\n\n"); //(a) //This part involves proving a relation in which no numerical components are involved. //For prove refer to this example 7.27 on page number 261 of the book. //(b) //This part involves proving a rel...
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//A pile hammer h=0.6 //m v=sqrt(2*9.81*0.6) //m/sec V=(15*3.431)/(22.5) //m/sec //Applying work energy equation s=(22.5*2.287^2)/(2*9.81*117.5) //m printf("\ns=%.3f m",s)
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//Example 12.14 //Updating Customer Records Date = struct('month',0,'day',0,'year',0); lastpayment = Date; record = struct('Name'," ",'street'," ",'city'," ",'acct_no',0,'acct_type',' ','oldbalance',0,'newbalance',0,'payment',0,'lastpayment',0); customer = record; function[] = main...
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//Problem 44.17: A low-loss transmission line has a mismatched load such that the reflection coefficient at the termination is 0.2/_-120°. The characteristic impedance of the line is 80 ohm. Calculate (a) the standing-wave ratio, (b) the load impedance, and (c) the incident current flowing if the reflected current is 1...
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//Ex13_4 clc C1 = 1*10^-9//capacitance of capacitor 1 C2 = 10*10^-9//capacitance of capacitor 2 L = 110*10^-6//inductance of inductor beta = C1/C2//feedback factor f0 = ((C1+C2)/(C1*C2*L))^.5/(2*%pi)//operating frequency disp("C1 = "+string(C1)+"F") disp("C2 = "+string(C2)+"F") disp("L = "+string(L)+"H") disp...
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# Nanotrav Version #0.12, Release date 2003/12/31 # nanotrav/nanotrav -p 1 -ordering hw -reordering annealing -trav ./nanotrav/s27.blif # CUDD Version 3.0.0 **************READING IN NETWORK*************** Number of inputs: 2 **************GENERATING NETWORK BDD*************** Printing the BDD for f: ptr to the...
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r= 5*(10^(-17)); //radius of spherical electron, m Me= 9.1*(10^(-31)); //mass of electron, kg h= 6.63*(10^(-34)); //Planck's constant, J.s hbar= h/(2*(%pi)); //reduced Planck's constant, J.s v= (5*sqrt(3)/4)*(hbar/(Me*r)); //using Eqn 7.1, Page 230 c= 3*(10^8); //velocity of light, m/s v= v/c; //converting in ...
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// Exa 3.10.18 clc; clear; close; // Given data W = 2 * 10^-4;// in cm W = W * 10^-2;// in m A = 1;// in mm^2 A = A * 10^-6;// in m^2 epsilon_r = 16; epsilon_o = 8.854 * 10^-12;// in F/m epsilon = epsilon_r * epsilon_o; C_T = (epsilon * A)/W;// in F disp(C_T*10^12,"The barrier capacitance in pF is");
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//clear// //Caption:Waveforms of Different Digital Modulation techniques //Figure7.1 //Digital Modulation Techniques //To Plot the ASK, FSK and PSk Waveforms clear; clc; close; f = input('Enter the Analog Carrier Frequency in Hz'); t = 0:1/512:1; x = sin(2*%pi*f*t); I = input('Enter the digital binary data')...
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clear x = rand(1,1000); tic() for i = 1:size(x,2) if x(i) >= 0.5 y(i) = 1; else y(i) = 0; end end y toc() tic() y2 = 1 * (x >= 0.5); y2 toc()
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x=[1 2 3 4 5 6 7 6]; [X,R] = corrmtx(x,3,'prewindowed'); disp(X); disp(R); //output // 1. 0. 0. 0. // 2. 1. 0. 0. // 3. 2. 1. 0. // 4. 3. 2. 1. // 5. 4. 3. 2. // 6. 5. 4. 3. // 7. 6. 5. 4. // 6. 7. 6. 5. // // ...
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clc // Given that v1 = 2.7e8 // velocity of first electron beam in meter/sec v2 = -2.7e8 // velocity of second electron beam in meter/sec // Sample Problem 35 on page no. 11.31 printf("\n # PROBLEM 35 # \n") printf(" Standard formula used \n") printf(" u_x = u_x_ + v / (1+ v*u_x_/c^2) \n ") u = v1 - v2 u_ = (v1 - v2) ...
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function [res]=f1(x) res = sin(x(1, :) + x(2, :)) - x(2, :) - 1.5 endfunction function [res]=f2(x) res = x(1, :) + cos(x(2, :) - 0.5) - 0.5 endfunction function [res]=f(x) res = [f1(x); f2(x)] endfunction function [res]=jacob_exact(x) // "Аналитический" Якобиан функции res = [ cos(x(1, :...
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//Exa 4.7 clc; clear; close; //given data : n=10;//no. of elements //d=lambda/4 separation in meter disp("Do=1.789*4*n*d/lambda"); disp("Putting d=lambda/4 we get D=1.789*n") Do=1.789*n;//directivity : unitless Dodb=10*log10(Do);//in db disp(Dodb,"Do in db = ");
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// Example 6.21.2 page 6.59 clc; clear; tr=30; //radiative recombination lifetime tnr=100; //non-radiative recombination lifetime h=6.624d-34; //plank's constant c=3d8; //speed of light q=1.6d-19; //charge of electron i=40d-3; //current lamda=1310d-9; //wavelength t=tr*tnr/(tr+t...
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//Chapter-3, Example 3.2, Page 48 //============================================================================= clc clear Di=0.05;//Inner diameter of hollow cylinder in m Do=0.1;//Outer diameter of hollow cylinder in m T=[200,100];//Inner and outer surface temperature in degree C k=70;//Thermal conductivity ...
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w=600 R=10 L=10E-3 C=0.5E-3 Xl=w*L*%i Xc=1/(w*C*%i) //Xc value in the book is wrong V1=40 V2=complex(0,-30) //mesh analysis A=[R+Xl,-R;-R,R+Xc] I=inv(A)*[V1;V2] Ir=I(1)-I(2) Vr=R*Ir disp(Vr) //Final answer is different
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// Theory and Problems of Thermodynamics // Chapter 5 //Second Law of Thermodynamcis // Example 11 clear ;clc; //Given data T1 = 300 // Temperature of first reservoir in K T2 = 400 // Temperature of second reservoir in K T3 = 1200 // Temperature of third reservoir in K ...
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clc m=4.4; //kg p=6; //bar t_sup=250; //0C t_w= 30; //0C c_ps=2.2; //kJ/kg c_pw=4.18; // At 6 bar, 250 0C; From steam tables t_s=158.8; //0C h_f=670.4; //kJ/kg h_fg=2085; //kJ/kg h_sup=h_f+h_fg+ c_ps*(t_sup-t_s); disp("Amount of heat added per kg of water, Qw=") Qw=c_pw*(t_w-0); disp(Qw) disp("Net am...
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clc; clear; //example 25.8 //binary multiplication format('v',8);//changing the default precision to 8 a=10101.01;//first number b=110.10;//second number A=bin21dec(a);//converting a in to decimal number B=bin21dec(b);//converting b in to decimal number S=A*B; //multiply the two decimal numbers te...
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clear; clc; printf("\t\t\tExample Number 4.4\n\n\n"); // heat removal from semi-infinite solid // illustration4.4 // solution alpha = 8.4*10^(-5);// [square meter/s] constant Ts = 200;// [degree celsius] initial temperature of of slab x = 0.04;// [m] depth at which temperature is calculated T_x_t = 120;// [d...
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function rep=getsymbol(title) marksIds=['.','+','x','*','diamond fill.','diamond',.. 'triangle up','triangle down','trefle','circle']; fontsSiz=['08' ,'10','12','14','18','24']; mm=xget('mark'); lmid=list('markId',mm(1)+1,marksIds); lmsiz=list('marksize',mm(2)+1,fontsSiz); xch_l = list(lmid,lmsiz); entval=[lmid(2),lms...
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//clear// //Caption:circuit bandwidth of a photodiode //Example6.7 //page 239 clear; clc; close; CP = 3*10^-12;//photodiode capacitance is 3 pico farad CA = 4*10^-12;//amplifier capcitance is 4 pico farad CT = CP+CA; //total capacitance RT1 = 1000; //photodiode load resistance BC1 = 1/(2*%pi*RT1*CT); //circu...
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clc //initialisation of variables clear L2= 6000 //cal v= 3 T= 25 //C T1= 0 //C //CALCULATIONS R= ((L2/(v*4.576))*(T-T1)/((273+T1)*(273+T))) r= 10^((L2/(v*4.576))*(T-T1)/((273+T1)*(273+T))) //RESULTS printf ('Ratio = %.3f ',R) printf ('\n Relative change in mean ionic coefficient = %.2f ',r)
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clc// // // //Variable declaration n1=1;n2=1;n3=1; h=6.62*10^-34; //planck's constant m=9.1*10^-31; //mass(kg) L=0.1*10^-9; //side(m) //Calculation E1=h^2*(n1^2+n2^2+n3^2)/(8*m*1.6*10^-19*L^2); //lowest energy of electron(eV) //Result printf("\n lowest energy of electron is %0.1f eV",E1...
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//Método de Newton para f(x) = x^3 - 4*x^2 + 5*x -2 x = 1.0731000001 for i = 1:1000 x = x - (x^3 - 4*x^2 + 5*x -2)/(3*x^2 - 8*x + 5) end disp(x)
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//Example 2.5 : velocity clc; clear; close; //given data : n=1; Z=1; k=6.56*10^15; // k is constant fn=k*(Z^2/n^3); disp(fn,"orbital frequency,fn(Hz) = ")
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// mode(-1); lines(0); c=[90 0 0 ; 1 9 0]; disp(c, "c ="); disp("[NI,A,Rej,P,R]=confmatrix2ni_mi(c)"); [NI,A,Rej,P,R]=confmatrix2ni_mi(c); disp(NI, "NI =", A, "A = ", Rej, "Rej = ", P, "P = ", R, "R = ")
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clf; plot2d(0,0,0,rect=[0 0 10 10],frameflag=3) xgrid(4), // segments start x1=2*ones(1,5) y1=[1:2:9]; // segments end x2=8*ones(1,5) y2=[1 1 5 9 7]; // drawing the segments X=[x1;x2],Y=[y1;y2] xarrows(X,Y,3,[1:5]) E=gce(); E.thickness=3;
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//Example5.13 // To calculate unity gain bandwidth and maximum close loop gain clc; clear; close; A = 10^3 ; // open loop gain fo = 60 ; // Hz // dominant pole frequency fdb = 12*10^3 ; //Hz // 3-db frequency // the unity gain bandwidth f1 = fo*A ; disp('the unity gain bandwidth is = '+string(f1)+'Hz');...
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//NPSHA and NPSHR// pathname=get_absolute_file_path('10.08.sce') filename=pathname+filesep()+'10.08-data.sci' exec(filename) //Diameter of pipe (in feet): Df= Di/12 //Area of crossection of pipe(in ft^2): A=%pi/4*Df^2 //Velocity of flow(in ft/sec): V=Q/7.48/A/60 //For water at T=80F,viscosity=0.927e-5 ft^2/s...
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//Example 3.22: Reduce expression using k-map clc; //clears the window clear; //clears all existing variables //Mapping the expression// disp('f(a,b,c,d) = summation of minterms(0,1,4,5,10,11,14)') disp('The function f''(a,b,c,d) = summation of minterms(2,3,6,7,8,9,12,13,15)') disp(' a''b'' a''b ab ab''...
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//Chapter-1,Example1_6_2,pg 1-35 //intercept of planeare in proportion a,b/3,2*c //as a,b and c are basic vectors the proportin of intercepts 1:1/3:2 //therefore reciprocal r1=1 r2=3 r3=1/2 //taking LCM v=int32([2,1]) l=double(lcm(v)) m1=(l*r1) m2=(l*r2) m3=(l*r3) printf("miler in...
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//Ex12_2 clc Vo=14 disp("Vo= "+string(Vo)+" volts") // output voltage f=500 disp("f = "+string(f)+" Hz")//frequency IB2=500*10^(-9) disp("IB2= "+string(IB2)+" A") //base- Current B=0.5 disp("B="+string(B))//Feedback factor vf=B*Vo disp("vf=B*Vo= +"+string(vf)+", -"+string(vf)+" volts") // Feedback voltage ...
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load Computer.hdl, output-file test1.out, output-list RAM64[16]%D1.7.1 RAM64[17]%D1.7.1 RAM64[18]%D1.7.1; // loads program written in the Hack language -- c = |a-b| ROM32K load test1.hack, /* case a > b */ set RAM64[16] 30, // a = 30 set RAM64[17] 20, // b = 20 repeat 20 { tick, tock; } output; ...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 5 : INDUCTION MACHINES // EXAMPLE : 5.7 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA f = 50; // Frequency of the 2-pole Induction Motor p ...
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//EXAMPLE 6.30 //PROGRAM REQUIRES MAXIMA SCILAB TOOLBOX //USE Z-TRANSFORM TO EVALUATE CONVOLUTION OF TWO SEQUENCES: clc; clear; syms n z; x = [-2 0 1 -1 3]; h = [1 2 0 -1 0]; for n=0:4 X(n+1) = x(n+1)*z^(-n); H(n+1) = h(n+1)*z^(-n); end disp(X','X = '); disp(H','H = '); for i=1:5 U(i)=0; for j=1:5 ...
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// Variable declaration v1 = 10 // Degree of freedom a corresponding to (a,b) v2 = 20 // Degree of freedom b corresponding to (a,b) // Calculation // we need to find f(0.95) at (10,20) i.e. 1/ f(0.05) at(20,10) f = 1 / 2.77 // Required value f(0.05) at(20,10) = 2.77 from Table-6 // Result pr...
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clc p1 = 1 // Air pressure at compressure inlet in bar t1 = 30 // Air temperature at compressure inlet in degree Celsius p2 = 3.5 // Air pressure at compressure exit in bar t2 = 141 // Air temperature at compressure exit in degree Celsius v = 90 // Air velocity at compressure exit in m/s cp = 1.0035 // Specific h...
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disp("Is=A*R*T*exp(-q*Va/(K*T))"); A=10^-3; R=110; T=300; Va=0.67; Va1=0.3; a=0.026; //say a=K*T/q Is=A*R*T*exp(-Va/a)*10^8; printf('\n The value of Is is %f*10^-8 A',Is*10^2); I=Is*exp(-Va1/a)*10^7; printf('\n The value of I is %f*10^-3 A',I);
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<?xml version="1.0" ?> <TestCase name="bf_db" version="5"> <meta> <create version="10.0.0" buildNumber="10.0.0.431" author="admin" date="02/03/2018" host="inbasdpc10722" /> <lastEdited version="10.0.0" buildNumber="10.0.0.431" author="admin" date="02/03/2018" host="inbasdpc10722" /> </meta> <id>D9F27663071A11E...
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//The step pulley //refer fig. 20.3 theta=20 //radian alpha=2 //rad/sec^2 omega0=0 //Using kinematic relation t=sqrt(20) //sec //Velocity of A vA=8.944 //m/sec vB=0.6*8.944 //m/sec printf("\nt=%.3f sec\nvA=%.3f m/sec\nvB=%.3f m/sec",t,vA,vB)
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errcatch(-1,"stop");mode(2);// Exa 6.4 ; ; // Given data P=100;// in ohm Q=10;// in ohm S=46;// in ohm R= P*S/Q;//in ohm disp(R,"Unknown resistance in ohm") exit();
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x = linspace(0,3,100) y = sin(x) xlfont("reset") xlfont("Times New Roman",10) plot(x,y) xstring(0.5,0.5,"A Text from ffr") figure_entity = gcf(); axes_entity = figure_entity.children title_entity = axes_entity.children title_entity.font_style = 10
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//Finding resistance //Example 15.10(pg 398) clc clear rho=1.7*(10^-6)//resistivity of copper in ohm-cm l=5//length in metres t=0.005//thickness in m D=0.08//external diameter in m d=D-(2*t)//internal diameter in m a=%pi*(D^2-d^2)/4//cross section area in cm^2 R=rho*l/a//resistance of copper tube in ohm R1=R...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// problem 9.7 Hs=5 Ls=10 D=0.15 d=0.1 N=30/60 s=0.15 g=9.81 W=2*3.142*N w=9810 ha=10.3 z=(D/d)^2 H=(Ls*z*W*W*s/g) Ph=Hs+H Phabs=ha-Ph f=0.01 Hfs=(4*f*Ls/(d*2*g))*((z*W*s)^2) H1=Hs+Hfs H1abs=ha-H1 H2=Hs-H H2abs=ha-H2 Hd=15 Ld=25 H11=(Ld*z*W*W*s/g) H12=H11+Hd H12abs=ha+H12 Hfd=(4*f*Ld/(d*2*g))*...
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close_serial.sci
// // This file is part of Arduino toolbox // Copyright (C) 2012-2012 - DEMOSCIENCES - Alain CAIGNOT // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also availa...
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clc //soltuion //given P=2.5//N/mm^2 D=1600//mm ft=75//N/mm^2 T=60//N/mm^2 fc=125//N/mm^2 //design of longitudinal joint t=(P*D)/(2*ft)+1//mm d=6*sqrt(t)//m pi=3.14 //choose standard avlue fromtable 9.3 //let p be pitch //Pt=(p-d)*t*ft//N//tearing resistance of plate //Pt=(p-34.5)*2100//N Ps=4*1.875*(pi/4)*d^2*T+(pi/4...
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// Scilab code Ex8.5: Pg.328 (2008) clc; clear; M = 1; // Atomic weight of hydrogen, u T = 5800; // Temperature at sun's surface, K lamda = 656.3; // Wavelength of H_alpha line, nm delta = 0.72e-06*lamda*sqrt(T/M); // Broadening of spectral lines, nm printf("\nThe broadening of spectral lines = %5.3f ...
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//inductance //given clc A=0.04//cm^2 N=4//no. of turns Lss=8.5*(A^(0.5))*(N^(5/3))*1d+3//PH Lss=round(Lss/10)*10///rounding off decimals disp(Lss*1d-3,'the inductance for the given parameter in nH')//nH
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clear all; clc; //This numerical is Ex 3_1E,page 43. N=800 Q=1750//in gallon per minute r_1=3 b_1=4 r_2=9 b_2=3 omega=N*%pi/30 printf('\n The angular velocity is %g rad/s',omega) omega_r=83.7 disp("After rounding off the value of angular velocity is 83.7 rad/s") U_1=omega_r*r_1/12 printf(' U_1=%g',U_...
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//Example No. 4.3 clc; clear; close; format('v',6); //Given Data : P=30;//KW theta1=54-30;//degree C t1=1;//hour theta2=67-30;//degree C t2=2;//hour(t2=2*t1) disp("theta=theta_f*(1-exp(-t/T))"); //Let exp(-t1/T)=a then exp(-t2/T)=a^2 //theta1/theta2=(1-a)/(1-a^2) //a^2*theta1-a*theta2+theta2-theta1=0 ...