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clear; clc; disp("--------------Example 12.5---------------") bandwidth = 10*10^6; // 10 Mbps Tp=25.6*10^-6; // 25.6 microseconds Tfr=2*Tp; // formula min_frame_size = bandwidth*Tfr; // formula bytes=min_frame_size/8; // 1 byte = 8 bits printf("The minimum frame size is %d bits or %d bytes.\nThis is the minimum...
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//Example 6-18// //Minimise an expression// clc //clears the console// clear //clears all existing variables// //Mapping the expression// disp('Y=m(2,3,4,5,6,7,12,13,14,15,18,19,20,21,22,23,28,29,30,31)') disp(' A'' A ') disp(' D''E'' D''E DE DE'' ...
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ImaipNodB=6 ImaipNo=10^(ImaipNodB/10) NopImai=1/ImaipNo SINRdB=8 SINR=10^(SINRdB/10)//signal to noise ratio Q=128//total spreading factor a=.55//relative intercellular interfernce factor M=Q/((1+a)*(1+NopImai)*SINR) disp(M,'users per cell')
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// Example 7-1 // Steady state sinusoidal output clear; clc; xdel(winsid()); //close all windows // please set the path // cd "/<your code directory>/" // exec("plotresp.sci") s = %s; w = 1; K = 5; T = 0.1; G = syslin('c',K,T*s + 1); t = 0:0.1:20; u = sin(w*t); plotresp(u,t,G,'Response to sinusoidal input'); // a...
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main { var number; number <- 44; } .
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// Ex 20 Page 361 clc;clear;close; // Given //Ia=0.0004*(Va+40*Vg)**(3/2);// mA --eqn(1) Va=250;//V Vg=-3;//V //mu=delVa/delVg //differentiation wrt Vg eqn(1) //(4*10**-6*3/2*(Va+40*Vg))**(1/2)*(mu+40)=0 mu=-40;//constant printf("Amplification factor, mu = %.f",mu) //differentiation wrt Va eqn(1) //delIa/delVa=(4*10**...
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// Example 1.19 clear; clc; close; format('v',8); // Given data P=4;//in poles Pout=37;//in HP f=50;//in Hz N=1425;//in rpm MechLoss=3;//in HP StatorLoss=2500;//in watts VL=500;//in volt cosfi=0.9;//power factor //Calculations Ns=120*f/P;//in rpm S=(Ns-N)/Ns;//slip disp(S,"(i) Slip is : "); Pout=Po...
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//convolution by polynomial method x=[4 1 3]; h=[2 5 0 4]; z=%z; n=length(x)-1:-1:0; X=x*z^n'; n1=length(h)-1:-1:0; H=h*z^n1'; y=X*H //effect of zero insertion on convolution h=[2 0 5 0 0 0 4]; x=[4 0 1 0 3]; y=convol(x,h) //effect of zero padding on convolution h=[2 5 0 4 0 0]; x=[4 1 3 0]; y=convol(x,...
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clc; f_diff=50*1e3 //in Hz v=5000 //in m/s //f1=v/2*t //f2=2v/2t //f2-f1=v/2t t=v/(2*f_diff) disp(+'meter',t,'Thickness of steel plate =')
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//exapple 1.12 clc; funcprot(0); // Initialization of Variable pi=3.14159; alpha=22+36/60;//altitude of star A=42//azimuth angle delta=40;//latitude of observer //in triangle ZPM(figure in book) PZ=(90-delta)*pi/180; A=A*pi/180; ZM=(90-alpha)*pi/180; PM=acos((cos(PZ)*cos(ZM)+sin(ZM)*sin(PZ)*cos(A))); t...
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//example 6.2 clear; clc; //Given: T=500;//Temperature[K] P=100;//Pressure[atm] a=3.61;//van der waals constant for CO2[atm.L^2.mol^-2] b=0.0429;//van der waals constant for CO2[L.mol^-1] R=0.082;//Universal gas constant[atm.K-1.mol^-1] //To find the molar volume of CO2 x=b+(R*T/P); y=a/P; z=a*b/P; p...
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v= 6.12*(10^7); //receding velocity with respect to Earth, m/s c= 3*(10^8); //velocity of light, m/s L0= 500; //initial wavelength of spectral line, nm L= L0*sqrt(((1+(v/c))/(1-(v/c)))); //final wavelength of spectral light, nm Ls= L-L0; //shift in wavelength, nm disp(Ls,"Shift in Green spectral line (in nm) is:...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 6 Single Staje BJT Amplifiers Pg no. 204 clear; clc; //Given Data B=190;//current gain of single transistor //Solution Bac=B^2;//current gain of superbeta transistor if B is the gain of each of the employed transistor printf("Bac = %d",Bac);
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//Example 1.12 // power required clc; clear; close; format('v',10) l=0.5;//length in meter b=0.25;//breadh in meter h=0.02;//in meter t1=25;// temperture °C t2=125;// temperture °C t=10;//time in minutes f=30;//frequency in 30 MHz w=600;//weight of the wood in kg/m^3 sh=1500;//specific heat in J/Kg/°C e=50;//efficiency...
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//Exa 1.36 clc; clear; close; format('v',7); //Given Data : pc=37.7;//bar Tc=132.5;//K vc=0.093;//m^3Kgmol R=287;//Nm/KgK m=10;//Kg T=300;//K V=0.3;//m^3 a=27*R^2*Tc^2/64/pc/10^5; b=R*Tc/8/pc/10^5;// //(p+a/V^2)*(V-b)=R*T p=R*T/(V-b)-a/V^2;//N/m^2 p=p/10^5;//bar disp(p,"Pressure exerted by air in ba...
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// Chapter 5 additional Example 14 //============================================================================== clc; clear; // if a plane cut intercepts of lengths l1,l2,l3 the on three crystal axes ,then // l1 : l2 : l3 = pa : pq :rc // where a,b and c are primitive vectors of the unit cell and p,q and r a...
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clc // Given that w = 25 // Width of mild steel block in mm d= 0.05 // Depth of cut in mm D = 200 // Diameter of the wheel in mm N = 3000 // Rpm of the wheel f =100 // Feed velocity of table in mm/min C = 3 // No of grits in mm^-2 rg = 15 // In mm^-1 // Sample Problem 21 on page no. 248 printf("\n # PROBLEM 4.21 # \n"...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/03/a/DFF.tst load DFF.hdl, output-file DFF.out, compare-to DFF.cmp, output-list time%S1.4.1 in%B2.1.2 out%B2.1.2; set in 0, tick, output; tock, ou...
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clear// //Variable Declaration sigma_w=1000 //Working Stress in Bending in psi tau_w=100 //Working stress in shear in psi //Dimensions b_out=8 //Width in inches h=10 //Depth in inches b_in=6 //Width in inches //Calculations I=((b_out*h**3)-(b_in*b_out**3))*12**-1 //Moment of inertia in in^4 //Design for ...
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//Initilization of variables a=92.9*10^6 //mi G=3.43*10^-8 T=365*24*3600 //s c=5280 //Calculations M=(4*%pi^2*a^3*c^3)/(G*T^2) //slugs //Result clc printf('The mass of the sun is %f slugs',M)
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// Computation of residues // 4.5 // Numerator and denominator coefficients // are passed in decreasing powers of z(say) function [res,pol,q] = respol(num,den) len = length(num); if num(len) == 0 num = num(1:len-1); end [resi,q] = pfe(num,den); res = resi(:,2); res = int(res) + (clean(res - int(res)...
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clear;lines(0); n=8;omega = exp(-2*%pi*%i/n); j=0:n-1;F=omega.^(j'*j); //Fourier matrix x=1:8;x=x(:); F*x fft(x,-1) dft(x,-1) inv(F)*x fft(x,1) dft(x,1)
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// Example 8.1: gm clc, clear IDSS=12; // in mili-amperes Vp=-5; // in volts VGS=-1.5; // in volts gmo=2*IDSS/abs(Vp); // in mili-Siemens gm=gmo*(1-VGS/Vp); // in mili-Siemens disp(gm,"gm (mS) =");
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clc //solution //given b=100//mm//width t=12.5//mm//thickness P=50*10^3//N T=56//N/mm^2 //let l and s be length of wled and size of weld //s=t s=12.5//mm //P=1.414*s*l*T l=P/(1.414*s*T)//mm printf("the value of length of static weld is,%f mm\n",l+12.5) T1=T/2.7//N //P=1.414*s*l*T1 l1=P/(1.414*s*T1)//mm printf("the val...
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//chapter 16 //example 16.5 //page 484 clear all; clc ; //given Vs=15;//dc supply Vref=6; printf("\nSuitable device is 1N753,from datasheet") Vz=6.2;//nominal voltage P=400;//nominal power in mW Izmin=5; Izm=P/Vz;//Izm=Ilmax+Izmin R1=10^3*(Vs-Vz)/Izm; printf("\nseries resistance R1=%d ohm,use standard va...
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// scilab Code Exa 9.4 axial turbine stage 3000 rpm d=1; // mean diameter of the impeller blade in m r=d/2; N=3e3; // rotor Speed in RPM a_r(1)=1; // aspect ratio a_r(2)=2; a_r(3)=3; alpha2=70; // air angle at nozzle exit alpha3=0; beta_2=54; // air angle at rotor entry sigma=0.5*(sind(alpha2)); // blade...
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// Example No.6.10. // Page No.189. clc;clear; h=1;k=0;l=0; d100=1/sqrt(h^2+k^2+l^2); disp('Interplanar spacing for d100 plane = a'); h=1;k=1;l=0; d110=1/sqrt(h^2+k^2+l^2); disp('Interplanar spacing for d110 plane = a/1.414'); h=1;k=1;l=1; d111=1/sqrt(h^2+k^2+l^2); disp('Interplanar spacing for d111 plan...
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clc disp("Example 2.20") printf("\n") disp("Calculate peak,RMS,DC load current, DC in each diode,DC output voltage,% regulation,PIV,RMS current,DC load voltage") printf("Given\n") Rf=500 RL=2000 V2=280 //Secondary voltage is Vm=sqrt(2)*V2 //Peak load current Im=Vm/(Rf+RL) //DC load current Idc=2*Im/(%pi) ...
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//Calculate the midband voltage gain and bandwidth of cascade amplifier clear; clc; //soltion //given Am=8; //midband voltage gain of individual MOSFET BW=500*10^3//Hz f2=BW; n=4; A2m=Am^n; f2_=f2*(sqrt((2^(1/n))-1)); printf("Midband voltage gain = %.0f\n",A2m); printf("Overall Bandwidth= %.1f kHz",...
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function %g=numdiff(%f,%x,tol) // given a function %f from R^n to R^p //computes the matrix g such as // [ d f ] // [ i ] //g = [ ---- ] // ij [ d x ] // [ j ] // using finite difference methods [lhs,rhs]=argn(0) if rhs<3 then tol=sqrt(%eps)*[1 1d-3] end if type(%f)==15 then pa...
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clc //initialisation of variables vw= 0.3 //ft/sec dw= 1 //in da= 12 //in ww= 62.3 //lb/ft^3 wa= 0.075 //lb/ft^3 nw= 0.01 //poise na= 0.00018 //poise //CALCULATIONS va= vw*dw*ww*na/(nw*da*wa) //RESULTS printf ('critical velocity of air = %.3f ft/sec',va)
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//EXAMPLE 2-47 PG NO 92 V=100/sqrt(2); //VOLTAGE F=100; //FREQUENCY L=0.018; //INDUCTANCE XL=2*%pi*F*L; disp('i) INDUCTANCE (XL) is in polar form = '+string (XL) +' ohm '); I=V/[(11.3+%i*11.3)]; //current di...
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s=%s sys=syslin('c',(s+1)*k/(s*(s-1)*(s^2+5*s+20))) evans(sys) //stability [Ki,s]=kpure(sys) disp(Ki)
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//signals and systems //Discrete Time Fourier Transform //x[n]= 1 , abs(n)<=N1 clear; clc; close; // DTS Signal N1 = 2; n = -N1:N1; x = ones(1,length(n)); // Discrete-time Fourier Transform Wmax = 2*%pi; K = 4; k = 0:(K/1000):K; W = k*Wmax/K; XW = x* exp(-sqrt(-1)*n'*W); XW_Mag = real(XW); W = [...
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// Example2_29_pg130.sce // Positive and negative sequence voltages // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 130 clear; clc; close; // Given data V_1 = 1000 + %i*50; V_2 = -800 + %i*100; V...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.443317D+00 ...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.11w //locating image of a dust particle on the surface of water filled in a concave mirror as observed from top //given data R=-40; //radius of curvature(in cm) of the concave mirror u=-5; //object distance(in cm) ...
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clear// //Variables IS = 30.0 //Current (in milli-Ampere) RS = 15.0 //Source resistance (in kilo-ohm) //Calculation RL = RS / 20.0 //Load Resistance (in kilo-ohm) IL = IS * RS/(RL +RS) //Load Current (in Ampere) //Result printf("\n Largest value of load ...
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clc; f=50; // frequency p=10; // number of poles pb=120000; // power dissipated in block rotor test // stator ohmic losses = rotor ohmic losses pr=pb/2; // total rotor loss disp('case a'); ws=(4*%pi*f)/p; // synchronous speed Ts=pr/ws; printf('Starting torque is %f Nm\n',Ts); disp('case b'); pr=pr/3; // to...
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//Fiber-optics communication technology, by Djafer K. Mynbaev and Lowell L. Scheiner //Example 10.1.1 //windows 7 //Scilab version-6.0.0 clc; clear ; //given E=0.712;//the energy gap E=Ec-Ef in eV KBT=0.025;//Boltzman constant temperature product in eV e=1.6E-19;//Electrons value in Coulomb Y=E/KBT; fE= exp...
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clc; clear; printf("\t\t\tChapter4_example4\n\n\n"); hc=6; D=0.105; k=0.431; c=2000; rou=998; Vs=%pi*D^3/6; As=%pi*D^2; // calculating Biot Number for lumped capacitance approach Bi_lumped=hc*Vs/(k*As); printf("\nThe Biot number is %.3f,",Bi_lumped); alpha=k/(rou*c); printf("\nThe value of diffusivity is %.2e sq.m/s",a...
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//Example 7.3 F_app=120;//Applied force (N) F_fr=5;//Opposing friction force(N) d=0.800;//Distance traversed (m) F_net=F_app-F_fr;//Net force (N) W_net=F_net*d;//Net work (J) printf('a.Net work done on the package = %0.1f J',W_net) W_app=F_app*d*cosd(0);//Work done due to applied force in direction of displaceme...
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clear; clf; clc; t1 = 0:0.01:1; t2 = 1.01:0.01:3; t3 = 3.01:0.01:4; t = [t1 t2 t3]; N = length(t); x1 = t1; x2 = -t2+2; x3 = t3-4; x = [x1 x2 x3]; subplot(211); plot(t,x); y = fft(x); yabs = abs(y)/N; k = 0:N-1; subplot(212); plot2d3(k(1:10),yabs(1:10)); disp(yabs(1:10));
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//Section-1,Example-2,Page no.AC-266 //To calculate the amount of lime required for softening of given hard water sample. clc; C_Eq1=144*(100/146) //CaCO3 equi.of Mg(HCO3)2 C_Eq2=25*(100/162) //CaCO3 equi.of Ca(HCO3)2 C_Eq3=95*(100/95) //CaCO3 equi.of MgCl2 V_1=5000 //Given solution of hard wate...
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//Example 7.8, page no-441 clear clc D=80 W=66.5 //(a) printf("(a)\nThe intersection point of DB temperature 80°F and WB temperature 66.5°F \nlines on the relative humidity curve for 50%%.\n RH = 50%% ") //(b) printf("\n(b)\nFrom the point of intersection of the dry and wet bulb curves, move left \nhorizontally...
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clc; clear; printf("\t\t\tChapter7_example8\n\n\n"); // Estimation of force exerted on the pole // properties of air at given conditions from appendix table D1 rou= 0.0735; // density in Ibm/ft^3 v= 16.88e-5; // viscosity in ft^2/s V=20*5280/3600; // flow velocity in ft/s printf("\nThe flow velocity is %.1f ft/s",V);...
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clc //Example 2.18 //Stress in gas turbine //------------------------------------------------------------------------------ //Given data: //Stresses //Radial Stress Sx=20* (10^6) // MPa //Tangential Stress Sy=50* (10^6) // MPa res18=mopen(TMPDIR+'18_stress_in_gas_turbine.txt','wt') mfprintf(res18,'Give...
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//consider wind tunnel model of example 7.3.datas are taken from example 7.3 and 7.4 Hac=0.24;//distance of aerodynamic center from leading edge a=0.08;//lift slope Vh=lt*St/(c*S)//tail volume ratio at=0.1;//tail lift slope per degree de=0.35;//derivative of downwash angle w.r.t angle of attack
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-18 clear; clc; close; // Clear the work space and console. // Given data V_sc = 50 ; // Short circuit voltage in volt V_1 = 2300 ; // Rated primary voltage in volt ...
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//Example 6_1 clc(); clear; //To calculate how large is the average force retarding its motion m=1500 //units in Kg vf=15 //units in meters/sec v0=20 //units in meters/sec t=3 //units in sec f=((m*vf)-(m*v0))/t //Units in Newtons printf("The average retarding force is F=%d Newtons",f)
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clc; clear; p1=1/8; p2=1/8; p3=5/8; p4=1/8; //Quantization Levels //B is the Bandwidth of the signal H=p1*log2(1/p1)+p2*log2(1/p2)+p3*log2(1/p3)+p4*log2(1/p4); disp(H,"The average Information (in bits/message)="); disp("The Information Rate R=rH =2*B(1.55) =3.1B bits/s");
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//------------------------------------------------------------------------------ // Calibration du pas de temps. //------------------------------------------------------------------------------ stacksize(150000000) // Paramètres lambda = 0.52 mu = 0.5 tmax = 2000 N = 50 S = 400 nbSimulations = 200 h = 0.05 // Compar...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <TestCase> <Step> <EventId>e51</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e14</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e79</EventId> <Reaching...
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// 08.10.15 function Out=Cutsf2d(Nvec,GL,Flg) global THETA PHI Theta=THETA; Phi=PHI; Tmp=Rotate3data(GL,Nvec,[-1,0,0]); THETA=%pi/2; PHI=0; Out=Projpara(Tmp); if Flg==1 Windisp(Out); end; THETA=Theta; PHI=Phi; endfunction;
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V1=35; //Assigning values to parameters R1=3; R2=2; R3=4; V2=40; Ra=((R2*R3)/(R2+R3))+R1; // Considering only 35V source I=V1/Ra; IR1=I; IR3=I*(R2)/(R2+R3); IR2=I-IR3; Rb=((R1*R2)/(R1+R2))+R3; //Considering only 40V source I1=V2/Rb; I1R3=I1; I1R1=I1*(R2)/(R2+R3); I1R2=I...
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//Chapter 30 Ex4 clc; clear; close; S={'B','I','H','A','R'}; sizeS=size(S,"c"); reqLetters=sizeS; //since all the letters are required noWords=factorial(sizeS)/factorial(sizeS-reqLetters); mprintf("The required number of words are %.0f",noWords);
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES // EXAMPLE : 2.12 : // Page number 109-110 clear ; clc ; close ; // Clear th...
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14.sce
clc m_N2=2.5; //kg M_N2=28; p_N2=15; //bar p_total=20; //bar n_N2=m_N2/M_N2; p_O2=p_total-p_N2; n_O2=p_O2/p_N2*n_N2; M_O2=32; m_O2=n_O2*M_O2; disp("Mass of O2 added =") disp(m_O2) disp("kg")
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//Example 3.24.a clc; Syms s t; x=laplace(((2+t)*(exp(-3*t)),t,s); disp(x);
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Example10_8.sce
//Example 10.8 clear; clc; vI=10; f=100*10^3; T=1/f; D=25; TH=2.5*10^(-6); C=(TH*1*10^(-3))/7.5; R=vI/(7.5*f*C); delvImax=2.5; C1=(10^(-3)*TH)/delvImax; RA=62; RB=150*10^3; RC=100*10^3; printf("Designed Voltage to Frequency Converter :"); printf("\nR=%.1f kohms",R*10^(-3)...
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//[p,m,x_final,y_final] = ag(75,20,-500,-500,500,500,0.85,0.005,50) //Chamada geral da função, recebe como parâmetro a quantidade de Indivíduos e de bits desejada, os limites em X e Y, as taxas de crossover e mutação, e a quantidade de gerações; retorna a população após todas as gerações, o valor mínimo de cada geração...
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clear // // // //Variable declaration V=2.405; //V-number lamda=8500*10^-10; //wavelength(m) n1=1.48; //core refractive index n2=1.47; //cladding refractive index //Calculations d=V*lamda/(%pi*sqrt(n1^2-n2^2)); //diameter of core(m) //Result printf("\n diameter of core is %0.2f *...
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ex5_12.sce
//Chapter-5, Example 5.12, Page 170 //============================================================================= clc clear //INPUT DATA C=50;//capacitance in uf R=100;//resistance in ohms V=200;//supply voltage in volts f=50;//freq in hz //CALCULATIONS Xc=1/(2*%pi*f*C*10^-6);//capacitive reactance in ohms ...
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6_3.sce
clc //initialisation of variables mus= 0.25 d= 0.5 //in h= 3 //in //CALCULATIONS A=[1 -1;mus mus] b= [0;1] c= A\b Na= c(1,1) Nb= c(2,1) d= -d*mus*Na+h*Na //RESULTS printf ('minimu distance= %.2f in',d)
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// Ex 55 Page 400 clc;clear;close; // Given Edc=250;//V fim=.065;//Wb f=50;//Hz E1=6000;//V P=1500;//kW p=8;//pole pf=0.9 V=400;//V J=3;//A/mm^2 E2=Edc/sqrt(2)//V N2=E2/4.44/f/fim;//no. of turns N1=E1/E2*N2;//no. of turns printf("no. of turns in primary = %d",N1) printf("\n no. of turns in secondary = %d",N2) Idc=P*1...
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//Problem 2.15: A source of e.m.f. of 15 V supplies a current of 2 A for six minutes. How much energy is provided in this time? //initializing the variables: V = 15; // in Volts I = 2; // in ampere t = 360; // in sec //calculation: E = V*I*t printf("\n\nResult\n\n") printf("\nEnergy(E): %.0f Joule(J)\n",E...
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clc //initialisations c=0.58 m=4//gm ms=5//gm t=78//c t1=80//c x1=10//cm x2=8.5//cm c1=0.05 c2=0.048 t2=100//c t3=27//c //CALCULATIONS Hal=m*c*t m1=Hal/t1 m2=m1*x1/x2 Hp=m2*80 H1=ms*(t2-t3)*c1 H2=ms*c2*t3 L=(Hp-H1-H2)/ms //results printf(' latent heat of fusion= % 1f cal/gm',L)
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//to generate standard signals like unit impulse,unit step,unit ramp,parabolic,sinusoidal,triangular pulse,signum,sinc and Gaussian signals clc; clear; t=-15:0.1:15; x=1.*(t==0); subplot(3,3,1) plot(t,x); xtitle('unit impulse signal','time t','signal x(t)'); x=1.*(t>=0); subplot(3,3,2) plot(t,x); xtitle('uni...
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clc,clear printf('Example 2.1\n\n') V=220 I_a=30 //armature currnet R_a=0.75 //Armature resistance E_b=V - I_a*R_a // Since V= E_b+ I_a*R_a printf('Induced EMF or back EMF in the motor is %.1f V',E_b)
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errcatch(-1,"stop");mode(2);//1.17 ; Y=90; X=89; Error_absolute=Y-X; disp(Error_absolute,'absolute Error') Error_relative=(Y-X)*100/Y; disp(Error_relative,'relative Error (percent)=') Accuracy_relative=1-Error_relative; disp(Accuracy_relative,'Accuracy relative=') Accuracy_percentage=100*Accuracy_relative; d...
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// ==================================================================== // Allan CORNET // DIGITEO 2008 - 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== assert_checktrue(xls_NewExcel()); ass...
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clc clear disp('3.') function y = bissexto(ano) y = %f if(pmodulo(ano, 4) == 0) if(pmodulo(ano, 100) == 0 && pmodulo(ano, 400) ~= 0) y = %f else y = %t end end endfunction function y = F(n) if(n == 1 || n == 2) y = 1 else F0=1; ...
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// Chapter 12 // Minimum acceptable frquency range // Page.No-448 // Example_12_3 // Given clear;clc; DR=50; //in dB Bits=DR/6; printf("\n The Bits required are = %.1f \n",Bits); // Result //we cannot have fractional bit so, printf("\n we cannot have fractional bit so, Bits required are = %.0...
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clc //initialisation of variables T = 100 //C T1= 25 //C T2= 150 //C T3= 357 //C T4= 500 //C T5= 2000 //C T6= 5*10^6 T7= 1000 //C //CALCULATIONS e= (T-T1)/(T+273) e1= (T2-T1)/(273+T2) e2= (T3-T)/(273+T3) e3= (T5-T4)/(T5+273) e4= (T6-T7)/T6 //RESULTS printf (' maximum efficiency = %.2f ',e) printf (' \...
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clear //Given n=10 E=1.5 R=4 //ohm r=0.1 a=8 //Calculation Emf=n*E Rt=R+(n*r) I=Emf/Rt Emf1=(a*E)-(2*E) I1=Emf1/Rt I11=I-I1 //Result printf("\n Reduction in current is %0.3f A", I11)
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//Exa 5.2 clc; clear; close; format('v',6); //Given Data : m=2;//Kg T1=300+273;//Kelvin T2=150+273;//Kelvin T0=20+273;//Kelvin Cp=0.45;//KJ/KgK deltaQ=m*Cp*(T1-T2);//KJ deltaS=m*Cp*log(T1/T2);//KJ/K A=deltaQ-T0*deltaS;//KJ disp(A,"Reversible work or Available energy in KJ : "); UA=T0*deltaS;//KJ disp(...
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pathname=get_absolute_file_path('6_4.sce') filename=pathname+filesep()+'6_4data.sci' exec(filename) P=[1 P1(1) P1(2) P1(1)*P1(2); 1 P2(1) P2(2) P2(1)*P2(2); 1 P3(1) P3(2) P3(1)*P3(2); 1 P4(1) P4(2) P4(1)*P4(2)]; alpha1=inv(P)*u; alpha2=inv(P)*v; alpha=[alpha1;alpha2]; deff("[Ex]=f(y)","Ex=alpha(2)+ y...
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R0 = 2.8; // Resistence at t=0 degree in ohm R100 = 3.8; // Resistence at t = 100 degree in ohm a = (R100/R0 - 1)*0.01; // alpha R = 5.8; // Indicated ressistace in ohm t = (R/R0 - 1)/a; // Temperature in degree disp("degree",t,"The temperature when indicated resistance is 5.8 ohm is ")
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load IsZero.hdl, output-file IsZero.out, compare-to IsZero.cmp, output-list in%B1.16.1 out; set in %B0000000000000000, eval, output; set in %B1010101010101010, eval, output;
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//variable initialization lembda_c=0.024 //Compton wavelength of electron (Å) Theta=(45*%pi)/180; //Scattering angle (radian) //Calculation of wavelength of incident photon lembda=lembda_c*...
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// Calculating the kVA output of a single phase transformer clc; disp('Example 5.3, Page No. = 5.78') // Given Data D = 0.4;// Distance between core centres (in meter) f = 50;// Frequency (in Hz) Bm = 1.2;// Flux density of core (in Wb per meter square) Kw = 0.27;// Window space factor s = 2.3;// Current densit...
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//Exa:8.3 clc; clear; close; //Given: Bw=25;//in KHz Nr=2*Bw*1000; printf("\n Nyquist sampling rate = %f samples/seconds",Nr/1000); br=8;//bits Ne=br*Nr; printf("\n Transmitted elements = %f elements",Ne);
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// Example 2.4;Critical Angle clc; clear; close; n1=1.48;//Waveguide Refractive Index n2=1.46;//Cladding Refractive Index Oc=asind(sqrt((1-(n2/n1)^2)));//Critical Angle disp(Oc,"critical angle in degree is")
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// Test # 6 : Input Argument #1 range test exec('./allpassshift.sci',-1); [n,d]=allpassshift(3,0.4); //!--error 10000 //Wo must lie between 0 and 1 //at line 36 of function allpassshift called by : //[n,d]=allpassshift(3,0.4);
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//Funcion edsonj.sce modificada function xdot=edsonj(u1,u2,u3,u4,u5) // Se a modificado para tener el modelo de péndulo no lineal // Cardar datos exec('edsonjParameters.sce', -1); // Variables de estado x=u1; v=u2; theta=u3; vtheta=u4; // Variable de control F=u5; // fuerza // Modelo MoDiCA-X //Estado 1 Posicio...
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//Chapter-5, Example 5.3, Page 5.7 //============================================================================= clc clear //INPUT DATA Eph=(6.6*10^3)/sqrt(3);//Phase voltage in V Isc=145;//Short circuit current in A Ra=1;//Resistance of stator winding in ohm //CALCULATIONS Zs=(Eph/Isc);//Synchronous imp...
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clc clear //input data c =2.25//Chord length of an aerofoil in m l=13.5//Span of the aerofoil in m C=125//Velocity of the aerofoil in m/s Cl=0.465//Lift coefficient Cd=0.022//Drag coefficient d=1.25//Density of the air in kg/m^3 //calculations A=c*l//Area of cross section of the aerofoil in m^2 W=Cl*d*((C^...
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the ADIW (add immediate to word) instruction" ; @Result: "flags.s=1, flags.v=0, flags.n=1, flags.z=0, flags.c=0, r26 = 0, r27 = -64" start: ldi r26, 0b11100000 ldi r27, 0b10111111 adiw r26, 0b00100000 end: break
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clc() clear all function result=f(x,a,b) xd = (b-a)*x/2+(b+a)/2 dx = (b-a)/2 result =dx*( 0.2+25*xd-200*xd^2+675*xd^3-900*xd^4+400*xd^5) endfunction function result=cuadraturaDeGaussLegendre(a,b,funcion) result=funcion(-1/sqrt(3),a,b)+funcion(1/sqrt(3),a,b) endfunction a = 0 b = 0.8 disp("integra...
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//CHAPTER 3 ILLUSRTATION 10 PAGE NO 108 //TITLE:FRICTION clc clear //=========================================================================================== //INPUT DATA PI=3.147 d=2.5// MEAN DIA OF BOLT IN cm p=.6// PITCH IN cm beeta=55/2// VEE ANGLE dc=4// ...
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clc //Initialization of variables ns=70 z1=10 //ft z2=5000 //ft //calculations P1=12.2*144/62.4 P2=0.26*144/62.4 sigmac=0.31 h=(P1-P2-z1)/sigmac //results printf("Max permissible head to assure against cavitation = %d ft",h)
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//Example 8.18 //Cascaded lattice realization of Power-symmetric FIR Transfer Function clear; clc; z=%z; H5z=(1 + 0.3/z + 0.2/z^2 - 0.376/z^3 - 0.06/z^4 + 0.2/z^5); disp(H5z,'FIR filter = '); G5=horner(H5z,-1/z); G5z=G5/z^5; disp(G5z,'FIR filter = '); k5=0.2; H3z=(1/(1+k5^2))*(H5z - k5*G5z); disp(H3z,'Synthesis eqn,H3...
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printf("\t example 18.9 \n"); G=60; // lb/(hr)*(ft^2) De=1/12; // ft theta=6; // hr cs=41.3; // Btu/(ft^3)*(F) c=0.0191; // Btu/(ft^3)*(F) f=0.45; // void fraction T=90; T1=200; t0=50; h=(0.79*(G/De)^0.7); // eq 18.90 printf("\t h is : %.1f \n",h); X=(h*theta/(cs*(1-f))); Y=(T-t0)/(T1-t0); printf("\t X is...
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// Grob's Basic Electronics 11e // Chapter No. 22 // Example No. 22_9 clc; clear; // An RC circuit has a time constant of 3 s. The capacitor is charged to 40 V. Then C is discharged. After 6 s of discharge, how much is Vr? // Given data RC = 3; // RC time constant=3 Sec t = 6; // Discharge time=6 Se...
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function [stk,txt,top]=sci_date() // Copyright INRIA txt=[] stk=list('date()','0','1','1','10')
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//Given that L = 1 //(say) m = 1.8 //in kg M = 2.7 //in kg d = L/4 g = 9.8 //in m/s^2 //Sample Problem 13-1 printf("**Sample Problem 13-1**\n") //From the figure //Balancing torque from A //N2*L = M*g*L/4 + m*g*L/2 N2 = M*g/4 + m*g/2 //similarly N1 = M*g*(3/4) + m*g/2 printf("The Normal from point A...
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//Ex6_2 clc IE = 1.2*10^-3 beta = 60 alpha = beta/(1+beta) disp("beta = "+string(beta))//current gain in CE configuration disp("alpha = beta/(1+beta) = "+string(alpha))//current gain in CB configuraion disp("IE = "+string(IE)+"A")//emitter current IB = IE/(beta+1) IC = beta*IB disp("IB = IE/(beta+1) = "+strin...
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clc //Chapter 5:High Frequency Amplifiers and Automatic Gain Control //example 5.2 page no 148 //given wT=3*10^8//gain bandwidth product w=10*10^6//given frequency Ai=wT/w//short circuit current gain mprintf('the short circuit current gain is %d ',Ai)
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// Exa 3.8 clc; clear; close; // Given data I_by_Io= -0.9; V_T=26;// in mV V_T=V_T*10^-3;//in V n=1; // From Diode equation I= Io*[e^(e*V/(n*V_T))-1] V= n*V_T*log(1+I_by_Io);// in volt disp(V*10^3,"Voltage in mV is ")