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clc //initialisation of variables w=5//m w1=10//m a=60//deg y=9802//N/m^3 //CALCULATIONS h=w+((w/2)*sind(a))//m F=y*h*(w*w1)//kN y2=w+w*sind(a)//m Xp=w*[1-(1/3)*(w1+y2)/(w+y2)]//m hc=w+Xp*sind(a)//m //RESULTS printf('The distance from to the center of pressure is=% f m',hc)
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// Grob's Basic Electronics 11e // Chapter No. 31 // Example No. 31_2 clc; clear; // Claculate the following AC quantities Av, Vout, Pl, Pcc and percent efficiency. Also calculate the endpoints of ac loadline // Given data Icq = 7.91*10^-3; // Collector Currect(Q-point)=7.91 mAmps Rl = 1.5*10^3; ...
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//Example 7.6 //Program to Calculate //(a)Minimum Collector Current //(b)Maximum Collector Current clear; clc ; close ; //Given Circuit Data Vcc=20; //V Rc=2*10^3; //Ohms Rb=200*10^3; //Ohms Beeta1=50; Beeta2=200; //Calculation CASE-1: Minimum Collector Current Ibmin=Vcc/(Rb+Beeta1*Rc); Icmin=Beeta1*Ibmi...
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//scilab 5.4.1 //Windows 7 operating system //chapter 21 Communication Systems clc clear Npe=6*10^10//Npe=peak electron concentration for the E layer in m^-3 Npf=10^12//Npf=peak electron concentration for the F layer in m^-3 fCE=9*sqrt(Npe)//fCE=critical frequency for the E layer format("v",5) disp("MHz",fCE/1...
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m1=1.50 //kg m2=3 //kg Cv1=0.9 //cal/g C Cv2=0.12 //cal/g C Qdot=500 //W T1=250 //C T2=25 //C
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function[image_ret]=cv_Line(image,start,end1,color1) pyImport drawing_file //omitted parameters like thickness, lineType, shift image_ret=drawing_file.myLine(image,start,end1,color1) endfunction
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// Grob's Basic Electronics 11e // Chapter No. I // Example No. I_2 clc; clear; // Express the following numbers in scientific notation: (a) 235,000 (b) 364,000,000 (c) 0.000756 (d) 0.00000000000016. disp ('To express 235,000 in scientific notation, write the number as a number between 1 and 10, which is 2.35 in...
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//Chapter-1,Example1_5_2,pg 1-30 //refer diagram from textbook //in the said arrangement a cation is squeezed into 4 anions in a plane and 5th anion is in upper layer and 6th in bottom layer //join cation anion centres E and B and complete the triangle EBF //in triangle EBF m(angle F)=90 and EF=BF //m(a...
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clear;lines(0); [n,d]=rat(%pi) [n,d]=rat(%pi,1.d-12) n/d-%pi
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//Example 5.3 //Real roots of a Quadratic Equation //read input data printf("a = "); a=scanf("%f"); printf("b = "); b=scanf("%f"); printf("c = "); c=scanf("%f"); //carry out the calculations d=sqrt(b*b - 4*a*c); x1=(-b+d)/(2*a); x2=(-b-d)/(2*a); //In scilab, no error message is genera...
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//signals and systems //fourier analysis of discrete time signals //Example5.5:Discrete Time Fourier Transform:x[n]= sin(nWo) clear; clc; close; N = 0.1; Wo = %pi; W = [-Wo/10,0,Wo/10]; XW =[0.5,0,0.5]; // figure a = gca(); a.y_location ="origin"; a.x_location ="origin"; plot2d3('gnn',W,XW,2); poly1 = a...
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// Variable declaration A = [2.8,0.75,3.7] B = [0.0,-0.1,3.45] C = [1.15,1.75,4.2] D = [1.88,2.65,2.7] n = 12 alpha = 0.05 // Calculation t_thr = 2.201 // t(0.025) at dof = 11 Mean = (sum(A)+sum(B)+sum(C)+sum(D))/n std_dev = 1.417 S_sq = 0.0234 lower = Mean - t_thr*std_dev/sqrt(n) upper = Mean + t_thr*std_dev/sqr...
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// Scilab Code Ex1.2: Page:26 (2011) clc;clear; c = 3e+008; // Speed of light in vacuum, m/s delta_x = 2.45e+03; // Space difference, m delta_t = 5.35e-06; // Time difference, s v = 0.855*c; // Speed of frame S_prime, m/s delta_x_prime = 1/sqrt(1-v^2/c^2)*(delta_x - v*(delta_t))*1e-03; // Distance ...
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clear; clc; printf("\t\t\tExample Number 1.5\n\n\n"); // calculating heat flow from tube to the air flowing across it // solution Tw =110 ;//[degree celsius] temperature of the tube Tf =10 ;//[degree celsius] temperature of the air v=5;//[m/s] velocity of air flow hm=85;//[W/m^2 degree celcius] mean heat t...
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clc clear //INPUT m=5;//mass of air in gm cv=0.172;//specific heat at constant volume cal/gm dt=10;//changi in temperature in K //CALCULATIONS ie=m*cv*dt;//change in internal energy in cal //OUTPUT mprintf('change in internal energy is %3.2f cal',ie)
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//Example 2.12 clear; clc; printf("Example 2.12\n") //Given x1=0.01 //[m] x2=0.15 //[m] x3=0.15 //[m] T1=973 //[K] T2=423 //[K] dT=T1-T2; //Thermal conductivities k1=16.86 //[W/m.K] k2=1.75 //[W/m.K] k3=5.23 //[W/m.K] k_air=0.0337 // [W/m.K] A=1 //[sq m] sigma_R=(x1/(k1*A)+x2/(k2*A)+x3/(k3*A)...
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clc Nd=10**16 //cm^-3 Ne=2.8*10**19 //cm^-3 T=300 //K //(nd/(n0+nd))=z=1/(1+(Ne/2*Nd)*exp(-(Ec-Ed)/kT)) //y=Ec-Ed y=0.045 k=8.617*10^-5 //eV/K z=1/(1+(Ne/(2*Nd))*exp(-y/(k*T))) disp(z,"the donor states is=")
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clc // Given that c = 3e8 // speed of light in m/s u= -1*0.8*c // speed of particle A in m/s v = 0.8*c // speed of particle B in m/s // Sample Problem 20 on page no. 40 printf("\n # PROBLEM 20 # \n") printf(" Standard formula used \n") printf(" u_x = u_x_ + v / (1+ v*u_x_/c^2) \n ") u1 = (u-v) / (1 - ((u * v) / (c)^2...
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//Example 3.3 //Program to compare the threshold optical powers for stimulated //Brillouin and Raman Scattering clear; clc ; close ; //Given data alpha_dB=0.5; //dB/km - ATTENUATION lambda=1.3; //micrometre - OPERATING WAVELENGTH d=6; //micrometre - FIBER CORE DIAMETER nu=0.6...
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//Part A Chapter 5 Example 6 clc; clear; close; T1=35+273;//K T2=-15+273;//K Q2=140.8;//kW Q1BYQ2=T1/T2; Carnot_COP=1/(Q1BYQ2-1); Actual_COP=Carnot_COP/4; W=Q2/Actual_COP;//kW disp("Power required = "+string(W)+" kW"); //Answer is not accurate in the book.
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// CAPTION:Output_Power_of_Four-Cavity_Klystron //chapter_no.-9, page_no.-390 //Example_no.9-3-4 clc; //(a) Calculate_the_plasma_frequency po=5*(10^-5);//dc_electron_beam_current_density wp=((1.759*(10^11)*po)/(8.854*(10^-12)))^(1/2); disp(wp,'the_plasma_frequency(in rad/s)is ='); //(b) Calculate_the_r...
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function polinom=gregoryMundur(x,fx,xTaksir,jmlPol) [n,m]=size(x); [a,b]=size(fx); if ~(n == a) then printf("Ukuran x dan f(x) tidak sama!"); elseif xTaksir < min(x) | xTaksir > max(x) then printf("Nilai interval tidak memenuhi syarat !"); else m=zeros(n,n); ...
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//<s>=%rvlss(s1,s2) //<s>=%rvlss(s1,s2) calcule le bouclage "feedback" du transfert s1 par //le systeme lineaire decrit par sa representation d'etat s2. //Cette macro correspond a l'operation s1/.s2 //! // origine s. steer inria 1988 // [s1,s2]=sysconv(s1,s2);s=s1/.s2; //end
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clc; disp('Enter the matrix:') for i=1:2 for j=1:2 A(i,j)=input('\'); end end b=A(1,1)+A(2,2); c=A(1,1)*A(2,2)-A(1,2)*A(2,1); disp('The characteristic equation is:') disp(['e^2+' string(-b) '*e+' string(c) '=0']) e1=(b+sqrt(b^2-4*c))/2; e2=(b-sqrt(b^2-4*c))/2; if A(1,2)~=0 then v1=[A(1,2);e1-A(1,1)]; v2=[A(1,2)...
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T=4; N=[10,20,50,100,200,350,500,750,950,1500]; //variation du nombre de points //initialisation pas=zeros(10,1); erreur_euler=zeros(10,1); erreur_euler_cauchy=zeros(10,1); erreur_point_milieu=zeros(10,1); erreur_runge_kutta=zeros(10,1); for j=1:10 h=T/N(j); //pas pas(j)=h; t=[0:h:T]; n=length(t); ...
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// problem 10.5 Q=0.03 Hs=18 d=0.1 l=90 n=0.8 w=9810 a=3.142*d*d/4 f=0.04 g=9.81 Vd=Q/a H1=(4*f*l*Vd*Vd)/(d*2*g)+(Vd*Vd/(2*g)) Hm=Hs+H1 P=(w*Q*Hm)/(n*1000) disp(P,"power required to drive the pump")
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function dydt=f1(t,y) dydt = -t*y+t; endfunction function y=point_milieu(y0,t,f) n=length(t); h=t(2)-t(1); y=zeros(1,n); y(1)=y0; for i=1:n-1 k1=f(t(i),y(i)); k2=f(t(i)+h/2,y(i)+h/2*k1); y(i+1)=y(i)+h*k2; end endfunction function y = solution_exacte(t) y = 1-exp(-t^2/2); en...
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//NUMROWS Return number of rows in matrix // // NR = NUMROWS(M) returns the number of rows in the matrix M. // // See also NUMCOLS. function r = numrows(m) [r,x] = size(m); endfunction
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//Find Lattice constant and atomic packing fraction of NaCl having FCC structure //Ex:4.3 clc; clear; close; r_na=0.98;//ionic radius of sodium in angstorm r_cl=1.81;//ionic radius of chlorine in angstorm n=4;//in fcc there are 4 Na and 4 Cl ions a=((2*r_na)+(2*r_cl));//latice constant disp(a,"Lattice constant...
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clc; clear; phi_m=3.20 //in V Na=10^15 //in cm^-3 ni=1.5*10^10 //in cm^-3 x=3.25 Eg=1.11 //in eV e=1.6*10^-19 //in J Const=0.026 //constant for kT/e in V //Calculation phi_pF=Const*log(Na/ni) //in V phi_ms=(phi_m-(x+(Eg/2)+phi_pF)) mprintf("work-function difference= %0.3f V",phi_ms)
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//Exa 2.1 clc; clear; close; //Given data : VL1=220;//Volts VL2=400;//Volts disp("We know, W=I^2*2*R=(P/VL)^2*2*rho*l/a"); disp("a=(P/VL)^2*2*rho*l/(I^2*2*R)"); disp("v=2*(P/VL)^2*2*rho*l/(I1^2*2)*l"); saving=(2/(VL1)^2-2/(VL2)^2)/(2/(VL1)^2)*100;//% disp(saving,"% saving in copper : ");
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//EXAMPLE 5.3 //DETERMINE DFT OF GIVEN SEQUENCE clc; clear; N = input("length of sequence,N = "); M = input("M point DFT = "); if M > N x = [ones(1,N),zeros(1,M-N)]; disp(x,'the sequence is :'); for n=0:M-1 for k=0:M-1 W(n+1,k+1) = exp(-(%i*2*%pi*k/M)*n); end end X = ...
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Date: April 2010 // Description: Linde-Buzo-Gray Vector Quantization Algorithm (LBG Design Algorithm) // // Copyright (C) 2009-2010 OpenPR // All rights reserved. // // Redistribution and use in source an...
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/* * By: Jatin Kumar Mandav * * The Bisection Method in Mathematics is a root-finding method that * repeatedly bisects the interval and then selects a sub-interval in * which a root must lie for further processing. * * X(lower) and X(upper) such that F(X(lower)) * F(X(upper)) < 0. ...
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clear; clc; n=3; m=3; y=zeros(n,m); y(1,2)=(-(%i)*3); y(1,3)=(-(%i)*4); y(2,3)=(-(%i)*5); for i=1:1:n for j=1:1:m y(j,i)=(y(i,j)+y(i,j))/2; end end Y=y; for i=1:1:n for j=1:1:m if (i==j) then for k=1:1:n y(i,i)=y(i,i)+Y(j,k); end ...
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//ques-18.5 //Calculating standard heat of formation of actylene clc h1=-1300;//heat of combustion of acetylene (in kJ) h2=-395;//heat of combustion of graphite(C) (in kJ) h3=-286;//heat of combustion of hydrogen (in kJ) H=2*h2+h3-h1;//heat of formation of actylene (in kJ) printf("Heat of formation of actylene i...
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// to find the output frequency of the circuit 11-8 // example 11-3 in page 326 clc; // Data given Vcc=15;// supply voltage=15 V C1=0.1D-6;// capacitance in farad R1=1e+3; R2=10e+3;// resistances in ohm utp=3; ltp=-3;// upper and lower trigger points in volt //calculation a=['For contact at top of R1' 'For R1...
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//fiber optic communications by joseph c. palais //example 2.6 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given spotsize=1e-3//spot size in m lambda=0.82e-6//wave length in m d1=10//distance in m d2=1e3//distance in m d3=10e3//distance in m //to find theta=2*lambda/(%pi*spotsize)//divergenc...
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear all; //example 6.8 //calculation of output voltage //given data V1=10//voltage(in kV) at primary winding C1=2*10^-6//capacitance(in Farad) on primary side C2=1*10^-9//capacitance(in Farad) on secondary side pern=5//energy efficienc...
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// Example 9.1;//maximum termperature change clc; clear; close; f=0.15;//GHz fc=18;//GHz/degree celsius ta=f/fc;// disp(ta,"maximum temperature change alowed in degree celsius is")
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// Theory and Problems of Thermodynamics // Chapter 10 // Chemical Thermodynamics // Example 2 clear ;clc; //Given data P1 = 10.89 // volumetric composition of CO2 P2 = 3.63 // volumetric composition of CO P3 = 3.63 // volumetric composition of O2 P4 = 81.85 ...
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function [x] = substRetro(U, d) // U= matriz triangular superior // d= vetor de termos independente n = size(U, 1); x(n)=d(n)/U(n,n); for i = n:-1:1 soma = 0; for j = (i +1):n soma = soma + U(i,j)*x(j); end x(i) = (d(i) - soma)/U(i,i); end endfuncti...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 10.1 //Caption : Program to Plot the Graphs of P vs x1,y1 and t vs x1,y1 //Antoinie Equations //ln P1_sat=14.2724-(2945.47/(T-49.15)) [KPa] //ln P2_sat=1...
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//Obtain path of solution file path = get_absolute_file_path('solution5_10.sce') //Obtain path of data file datapath = path + filesep() + 'data5_10.sci' //Obtain path of function file funcpath = path + filesep() + 'functions5_10.sci' //Clear all clc //Execute the data file exec(datapath) exec(funcpath,[-1])...
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clc clear //Page number 498 //Input data R=8.4;//The universal gas constant in J.mol^-1.K^-1 Cv=21;//The spacific heat at constant volume in J.mol^-1.K^-1 P1=2*10^5;//The initial pressure of gas in N/m^2 V1=20;//The initial volume of the gas occupied in litres P2=5*10^5;//The final pressure of the gas in N/...
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clc; // Given data // M_A=r_CA * F relation 3.7 from section 3.5 f=200; // N , Magnitude of Force directed along CD r_CA=[0.3,0, 0.08];//m, vector AC reprecsented in rectangular component //lambda=CD/norm(CD)-m, Unit vector along CD //F=f*lambda;//m, Force CD=[-0.3, 0.24, -0.32];//Vector CD resolved into rectan...
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clear; xdel(winsid()); clc; Ts = 0.1; tfinal = 25; N=round( (tfinal+Ts)/Ts ); t = 0:Ts:N*Ts-Ts; // Discrete-time state space model Ad = [0.9359 0.2428 0.0132 -.0076; -.2136 0.8093 0.0440 -.0252; 0.0018 -.0015 0.971 0.1965; 0.0060 -.0049 -.0960 0.6551]; Bd = [.0628 .0002; .2093 .000...
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//Example 7_11 clc;clear; // Given values L_r=1/100;// (L_r=L_m/L_p) Length scale factor //Properties // For water at atmospheric pressure and at T = 20°C nu_p=1.002*10^-6;// The prototype kinematic viscosity in m^2/s // Calculation nu_m=nu_p*(L_r)^(3/2); printf("Required kinematic viscosity of model liqui...
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//Antennas : example 14-2 : pg(669) c=3*10^8;//velocity of light f=12*10^9;//frequency D=4.5;//diameter of parabolic reflector h=c/f;//wavelength x=D/h; R=(2*D^2)/h; printf("\nThe wavelength, \nh= %.3f m/cycle",h); printf("\nD=4.5 meter \nD/h = %.f",x); printf("\nselect equation, \nR > %.f m",R);
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//chapter 14 //example 14.3 //page 301 Av1=20*log10(100) // db Av2=20*log10(200) // db Av3=20*log10(400) // db Av_total=Av1+Av2+Av3 printf("total voltage gain = %.3f db \n",Av_total)
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// Partial fraction expansion for Example 4.29 // 4.9 // z^2 + 2z // G(z) = -------------------- // (z + 1)^2 (z - 2) exec('respol.sci',-1); exec('flip.sci',-1); num = [1 2 0]; den = convol(convol([1 1],[1 1]),[1 -2]); [res,pol] = respol(num,den)
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//example 3.3 clear; clc; //given: H=29.2;//latent heat of vaporisation[KJ/mol] T=332;//temperature of the system[K] R=8.314;//universal gas constant [J/K/mol] //to find Q,W,U for 1 mole of bromine vaporizes //where Q is heat absorbed or evolved //W is the work done by system //U is the change in inte...
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clc; i=10; //current r=0.005; //radius in metre h1=(i)/(4*2*(%pi)*r); //at half radius H is (1/4)th disp(h1,"H field intensity at one half of radius in A/metre = "); //displaying result h2=(i)/(2*(%pi)*0.01); //calculating H at surface disp(h2,"H field intensity at surface in A/metre = "); //displaying resu...
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expression: 2*n*a(n) +(-23*n+36)*a(n-1) +6*(-2*n+3)*a(n-2)=0 postfix1: ;2;n;*;a(;n;a);*;0;23;n;*;-;36;+;a(;n;1;-;a);*;+;6;0;2;n;*;-;3;+;*;a(;n;2;-;a);*;+;0;= rebuilt1: 2*n*a(n)+(-23*n+36)*a(n-1)+6*(-2*n+3)*a(n-2)=0 postfix2: ;2;n;*;a(;n;a);*;0;23;n;*;-;36;+;a(;n;1;-;a);*;+;6;0;2;n;*;-;3;+;*;a(;n;2;-;a);*;+;0;= rebu...
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% ---------------------------------------------------------------------- % $Id: ofsf.tst 469 2009-11-28 13:58:18Z arthurcnorman $ % ---------------------------------------------------------------------- % Copyright (c) 2006-2009 Andreas Dolzmann and Thomas Sturm % -------------------------------------------------------...
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function output = histogramme(img) hist = zeros(1,256) xmax = size(img,1) ymax = size(img,2) for x=1:xmax for y=1:ymax hist(double(img(x,y))+1) = hist(double(img(x,y))+1)+1 end end output = hist endfunction
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function replace() // Replace values given in to_replace with value. // // Syntax // dfr.replace(input_string) // // Parameters // input_string : String containing the parameters of values to be replaced with the target value. Any additional parameters supported can also be passed // For...
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clc; clear; printf("\n Example 9.31\n"); o_d=10e-3;//outer diameter of the tube i_d=8.2e-3; //inner diameter of the tube h=140;//coeffecient of heat transfer between gas and copper tube k=350;//Thermal conductivity of copper tube L=0.075; b=%pi*o_d;//perimeter of tube A=%pi/4*(o_d^2-i_d^2);//cross sectio...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 1.5\n\n\n"); // Chapter 1: Fundamental Concepts // Problem 1.5 (page no. 25) // Solution //Conversion Problem // 1 inch=0.0254 meter so, 1=0.0254 meter/inch //Eq.1 // 1 ft=12 inch so, 1=12 inch/ft.........//Eq.2 //Multiplying Eq.1 & Eq.2 // We get...
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//Caption:Scilab code to Perform Average Filtering operation //Fig6.18 //page 349 clc; close; a= imread('E:\DIP_JAYARAMAN\Chapter6\lenna.jpg');//SIVP toolbox a=imnoise(a,'salt & pepper', 0.2); //Add salt&pepper noise tothe image a=double(a); [m n]=size(a); N=input('enter the window size='); //The window size...
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clc; //Example 8.5 //page no 81 fig 8.3 printf(" Example 8.5 page no 81 fig 8.3\n\n\n"); //a cylindrical tank filled with water //applying bernoulli equation z1=9//elevation head at section 1 h2=1//height at section 2 D1=3//diameter of cylindrical tank D2=.3//diameter of outlet hole of tank g=9.807//gravitat...
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//Variable declaration: f = 100000 //Flow rate of flue gas (acfm) i = 0.1 //Interest rate //From table 27.4: //For finned preheater: ac1 = 3.1 //Equipment cost ($/acfm) ac2 = 0.8 //Installation cost ($/acfm) ac3 = 0.06 ...
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//Ex3_11 Pg-186 clc Vmin=0.7 //minimum voltage across diode in V V=5 //supply voltage in V V_R1=V-Vmin //voltage across resistor R in V Imin=10^(-3) //minimum current R1=V_R1/Imin printf("Maximum value of R =%.1f kohm \n ",R1*1e-3) I=5*10^(-3) //current through resistance in A V_R2=V-Vmin //voltage acro...
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// Copyright (c) 2015, Embedded Solutions // All rights reserved. // This file is released under the 3-clause BSD license. See COPYING-BSD. function subdemolist = demo_gateway() demopath = get_absolute_file_path("microdaq.dem.gateway.sce"); subdemolist = ["Data acquisition", pathconvert("data_acquisition/micr...
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//Chapter 4 Solutions Nonelectrolytes clc; clear; //Initialisation of Variables m= 92.13 //gms M= 78.11 //gms n= 1 //moles p= 119.6 //mm p1= 36.7 //mm //CALCULATIONS n1= m/M x= n/(n+n1) y= 1-x P= y*p P1= x*p1 P2= P+P1 m1= P/P2 m2= 1-m1 //RESULTS mprintf("Mole fraction of benzene=%.3f",m1) mprintf("\nMole fraction o...
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//chapter 12 //example 12.16 //page 508 printf("\n") printf("given") R1=2.7*10^6;R2=560*10^3;f1=150;Yfs=8000*10^-6;Ie=1.2*10^-3;Rl=80*10^3;R6=8.2*10^3; Zi=(R1*R2)/(R1+R2) Xc1=Zi/10 C1=1/(2*3.14*f1*Xc1) Xc2=.65/Yfs C2=1/(2*3.14*f1*Xc2)//use 15pF as standard value re=26*10^-3/Ie Xc3=.65*re C3=1/(2*3.14*f1*Xc...
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clear; clc; close; Vcc =25; Rl = 4; Po_max = (Vcc^2)/(2*Rl); Pi_max = (2*Vcc^2)/(%pi*Rl); n_max = (Po_max/Pi_max)*100; Vl_p = Vcc; P2q = Pi_max-Po_max; disp(Po_max,'Output power(Watts) = '); disp(Pi_max,'Input power(Watts) = '); disp(P2q,'Power dissipated(Watts) = '); disp(n_max,'Efficiency(Percent...
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clc pathname=get_absolute_file_path('4_6_3.sce') filename=pathname+filesep()+'463.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") n1=(1-conv1)*basis*x n2=conv2*basis*x E1=n2 E2=basis*x - E1-n1 n3=E1-E2 n4=2*E2 n5=basis...
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>>> from room import * >>> my_room = Room('Double', 237, 99.99) >>> str(my_room) 'Room 237,Double,99.99' >>> r = Room("Queen", 105, 80.0) >>> r.set_up_room_availability(['May', 'Jun'], 2021) >>> r.set_up_room_availability(['Feb'], 2020) >>> len(r.availability) 3 >>> len(r.availability[(2021, 6)]) 31 >>> r.availability[...
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//Example 10.9 // Calculations with s-plane Vectors s=%s; num=-6*s; // Numerator of transfer den=s^2+12*s+45; // Denominator X=complex(10,0); // Input signal phasor s_0=complex(-4,3)// complex frequency H_s=(num)/(den)// Transfer-function of the network H_s_0=horner(H_s,s_0); Y=H_s_0*X; // forced response phas...
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clc; v=3300; // rated voltage of motor zs=0.4+%i*5; // synchronous impedance per phase E=4000; // excitation EMF pi=1000; // input power vp=v/sqrt(3); // per phase rated voltage ep=E/sqrt(3); // per phase excitation EMF al=atand(real(zs),imag(zs)); t1=(pi*1000)/3; t2=(vp^2/abs(zs)^2)*real(zs); t3=abs(zs)/(vp*...
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//Ex_2_1 clc; clear; close; format('v',6); //given data : LTsc=1.6;//H(Series cumulative) LTd=0.4;//H(differentially) L1=0.6;//H M=(LTsc-LTd)/4;//H(Mutual Inductance) L2=LTsc-2*M-L1;//H K=M/sqrt(L1*L2);//Coupling Coefficient disp(M,"Mutual Inductance(H)"); disp(K,"Coupling Coefficient");
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//example 3.23<i> //Find the convolution sum clear ; close ; clc ; t= -5:1/100:5; for i =1: length (t) if t(i) <0 then h(i)=0; x(i)=0; else h(i)=2^t(i); x(i)=1; end end y = convol (x,h) ; //figure f=scf(0); plot2d (t,h) xtitle ( ' Input Re spons e ' , ' t ' , ' h ( t ) ' ); xs2jpg(...
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clc; pathname=get_absolute_file_path('13_4_soln.sce') filename=pathname+filesep()+'13_4_data.sci' exec(filename) // Solution: // final pressure in the cylinder, // General Gas Law, p2=((p1+14.7)*V1*(T2+460))/(V2*(T1+460))-14.7; //psig // Results: printf("\n Results: ") printf("\n The final pressure in the cylin...
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utkarsh_experiment_5.sce
clc; xdel(winsid()); x = round(rand(1,10)); nx = length(x); sign = 1; i = 1; while i < nx + 1 t = i:0.001:i + 1 - 0.001; pi = 3.14; if x(i) == 1 then unipolar_nrz = squarewave(t * 2 * pi, 100); unipolar_rz = (1 + squarewave(t * 2 * pi, 50))/2; ami = sign * squarewave (t * 2 * pi, 10...
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clc,clear printf('Example 7.9\n\n') V_L=500 R_a=0.03,X_s=0.3 //armature reactance and synchronous reactance Z_s=complex(R_a,X_s)//synchronous impedance theta=(%pi/180)*phasemag(Z_s) //phasemag returns angle in degrees,not radians phi=acos(0.8) eta=93/100 output_power=100*746 input_power=output_power/eta I_L...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map2303" Width="13" Height="17" CellSize="40" BackgroundSize="1" Background="15plus.png"> <Cell Name="雪块" X="1" Y="1" /> <Cell Name="木箱" X="4" Y="1" /> <Cell Name="雪树" X="5" Y="1" /> <Cell Name="冰块" X="6" Y="1" /> <Cell Name="冰块" X="7" Y="1" /> <Cell Na...
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clc; clear all; E=1000;//applied electrical field P=4.3E-8;//polarisation e0=8.854e-12;//permittivity of vacume er=1+(P/(E*e0));//relative permittivity of NACl disp('',er,'relative permittivity of NACl is:')
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clc //initialisation of variables d= 1 //ft h= 4 //ft h1= 3 //ft p= 25 //percent g= 32.2 //ft/sec^2 //CALCULATIONS h2= ((h/4)-(h1/4))*h*2 w= sqrt(h2*2*g/(d/2)^2) N= w*60/(2*%pi) h3= (h-h1^2/4)*2 w1= sqrt(h3*2*g/(d/2)^2) N1= w1*60/(2*%pi) //RESULTS printf ('original volume= %.1f R.P.M ',N1)
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load AddSub16.hdl, output-file AddSub16.out, compare-to AddSub16.cmp, output-list a%B1.16.1 b%B1.16.1 sel out%B1.16.1; set a %B0000000000000000, set ...
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//calculating required data// //example 12// clc //clears the command window// clear //clears// V=10;//high input voltage// //first part// //digital input is 101001// Vo=(10*2^0+0+0+10*2^3+0+10*2^5)/2^6;//output voltage// printf('output voltage for digital input 101001=%f volt\n',Vo);//displaying the result//...
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clear all; clc; //Value of s differs. The one given in the book is incorrect. On calculation the value is equal to the one provided here. disp("The dynamic pressure at the inlet is calculated from pd1=rho*V1^2/2") Q=220*0.00223//0.00223 is conversion factor D=5 A=%pi*(D^2)/4 V_1=(Q*144)/(A) printf(" V1=Q/A= ...
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function op = verificapar(n) if modulo(n,2)==0 then op = 1 else op = 0 end endfunction
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4_5.sce
clc //initialisation of variables H1= 10//ft H2=2 //ft d= 0.62 so= 3 //in w= 5 //ft g= 32.2 //ft/sec^2 b= 2.5 //ft b1= 7.5 //ft //CALCULATIONS A1= w*b A2= w*b1 a= so^2/144 T= (2*A1*(H1^0.5-H2^0.5))/(d*a*(1+(A1/A2))*sqrt(2*g)) //RESULTS printf (' Time required to lower the level of water = %.1f sec',T...
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10_18.sce
clc //Initialization of variables m=1 //lbm disp("From psychrometric charts,") t1=82 //F phi1=0.4 H1=30 //Btu/lbm dry air w1=65 //grains/lbm dry air w2=250 //grains/lbm dry air //calculations dmf3=(w2-w1)*0.0001427 hf3=68 hf4=43 H2=62.2 H1=30 mf4= (H1-H2+ dmf3*hf3)/(hf4-hf3) per=dmf3/(dmf3+mf4) //resul...
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//Chapter 12 //page no 494 //given clc; clear all; Voutp=20; //in dB Pin=1.2; //in mW m=0.035; Vavg=10^(Voutp/20); //in R=Vavg*sqrt(2)/Pin/m; printf("\n R = %0.1f V/W",R);
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//EX12_13 Pg-12.30 clc clear m1=0.55;//first modulation index m2=0.65;//second modulation index mt=sqrt(m1^2+m2^2); Pc=360;;//power radiated by the carrier signal Psb=Pc*mt^2/2//total sideband power radiated printf("Therefore total sideband power radiated Psb=%.3f W",Psb) //in the question Pc is taken as 360W ...
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//Example 1_36 clc; clear;close; //Given data: dv_by_dt=25/10^-6;//V/s L=0.2*10^-3;//H Vrms=230;//V damping=0.65;//damping factor Vm=sqrt(2)*Vrms;//V C=1/(2*L)*[0.564*Vm/dv_by_dt]^2;//F R=2*damping*sqrt(L/C);//ohm disp(C,"Value of C(F)"); disp(R,"Value of R(ohm)");
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//ques-18.23 //Calculating standard free energy change for the reaction clc //G = free energy (in kJ/mol) G1=-16.8;//ammonia G2=-86.7;//NO G3=-237.2;//water G=G2+G3*(1.5)-G1;//free energy change printf("The free energy change required is %.1f kJ/mol.",G);
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clear //Given P=110 //W P1=100 //W n=5 V=220 //V t=2 //hours n1=4 P2=1120 //W m=1.5 //per KWh //Calculation W=n*P1 W1=V*t W2=n1*P W3=W+W1+W2+P2 E=(W3*t)*10**-3 E2=E*30 B=m*E2 //Result printf("\n...
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clc //initialisation of variables Q= 16 //gpm w= 62.4 //lb/ft^3 d= 1 //in h= 2+(5/12) //ft g= 32.2 //ft/sec^2 x= 11.5 //ft h1= 1.2 //in //CALCULATIONS Cd= Q*10/(60*w*(%pi*(d/12)^2/4)*sqrt(2*g*h)) Cv= sqrt(x^2/(4*(h1/12)*h*12^2)) Cc= Cd/Cv Cr= (1-Cv^2)/Cv^2 //RESULTS printf ('Cr = %.3f ',Cr)
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clc // Variable initialization F=50 //Supply Frequency In Hz Vm=400 //Supply Voltage In Volts Ip=20 //Peak Circulating Current In Ampere A=60 //firing angle // solution Ea=Vm/(sqrt(3)) W=2*%pi*F Lr=[(3*sqrt(2)*Ea)/(W*Ip)]*(1-sind(A)) Lr1=Lr*1000//Inductance in mH printf('\n\n Inductance Value Needed=%0.1...
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//i/p is a matrix x=[-1 0.3 -0.2; 0 0.2 0.3; 1 0.2 0.3]; y=vco(x,150,500); disp(y); ////output // - 0.3090170 0.8443279 0.9297765 // 1. - 0.9510565 - 0.4817537 // - 0.8090170 0.3681246 - 0.1873813 //
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// Example no.5.2 // To calculate (a) the responsivity R and (b) the cutoff wavelength // Page no.198 clc; clear; // Given data neta=0.9; // The quantum efficiency Eg=1.42; // The band-gap energy in eV lambda=1.1; ...