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probXequalsi = 1/6; expecXsquared = 0; for n=1:6 expecXsquared = expecXsquared + (n*n*probXequalsi) end expecX= 3.5 // from eg 4.4a var = expecXsquared - (expecX^2); disp(var, "The variance is")
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clc Z1=14.14-%i*14.14; //Assigning values to parameters Z2=26+%i*15; I=10; Zeq=Z1+Z2; V=I*Zeq; Zeq=(Z1*Z2)/(Z1+Z2); I=V/Zeq; disp("Amperes",polar(I),"Supply current");
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// Exa 6.25 clc; clear; close; format('v',5) // Given data V_CC = 20;// in V R1 = 10;// in k ohm R1 = R1 * 10^3;// in ohm R2 = 10;// in k ohm R2 = R2 * 10^3;// in ohm R_E = 9.3;// in k ohm R_E = R_E * 10^3;// in ohm R_L = 18.6;// in k ohm R_L = R_L * 10^3;// in ohm V2 = (V_CC/(R1+R2))*R2;// in V V_BE = ...
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//kVAr rating of a synchronous condenser clc; clear; P=5000*(10^3); // Power delivered to the load pfo=0.8;// Original Power Factor pfn=0.9;// New Power Factor Pcomo=P+%i*(P*tand(acosd(pfo)));//Original Complex Power Pcomn=P+%i*(P*tand(acosd(pfn)));//New Complex Power Psc=abs(imag(Pcomo-Pcomn)); // Differ...
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clc //initialisation of variables A1= 25 //degrees A2= 80 //degrees H1= 100 //ft H2= 13 //ft g= 32.2 //ft/sec^2 v= 8 //ft/sec d= 3.5 //in de= 15.4 //in b= 1.5 //in w= 62.4 //lb/ft^3 //CALCULATIONS W= H1-H2-(v^2/(2*g)) f= sqrt(W*g/(cotd(A1)*(cotd(A1)-cotd(A2)))) u= f*(cotd(A1)-cotd(A2)) V= d*u/7.7 r= ...
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//lubricants// //example 3.7.9.A// clc wt_oil=1.55//weight f oil saponified(gms)// blank=20//volume blank titration reading(ml)// back=15//volume back titration reading(ml)// volume=blank-back//volume of alcoholic KOH consumed(ml)// normality_KOH=0.5//normality of KOH // S=volume*normality_KOH*56/wt_oil//formul...
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// Scilab Code Ex3.32:: Page-3.50 (2009) clc; clear; // Function to convert theta into degree-minute function[degre, minute]=deg_2_degminsec(theta) degre = floor(theta); minute = (theta-floor(theta))*60; endfunction N = 15000; // No. of lines on the grating per inch, lines/inch a_plus_b = 2.54/N;...
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//Example number 8.5, Page number 171 clc;clear; close; //Variable declaration Is=1.96*10**6; //saturation magnetisation(amp/m) a=3*10**-10; //cube edge(m) mewB=9.27*10**-24; //bohr magneton(amp/m**2) n=2; //number of atoms //Calculation N=n/(a**3); mew_bar=Is/(N*mewB); //average numbe...
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clear; clc; // Illustration 4.8 // Page: 259 printf('Illustration 4.8 - Page: 259\n\n'); // solution// // From Example 4.4, 4.6 and 4.7 Do = 5*10^-3; // [m] rowg = 1.923; // [kg/cubic m] rowl = 986; // [kg/cubic m] g = 9.8; // [square m/s] hl = 0.0173; // [m] vo = 18.48; // [m/s] phie = 0.274; Ks...
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// Scilab Code Ex10.3.3 Mass of deuterium nucleus: Pg: 220 (2008) amu = 1.6e-027; // Mass of a nucleon, kg mp = 1.007895; // Mass of proton, amu mn = 1.008665; // Mass of neutron, amu BE = 2/931; // Binding energy of two nucleons, amu M_D = (mp+mn-BE)*amu; // Mass of a deuterium nucleus, kg printf(...
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// Scilab Code Ex5.34: Page:313 (2011) clc;clear; lambda = 5.89e-07;....// Wavelength of light used, m mu_O = 1.55; // Refractive index of ordinary light mu_E = 1.54; // Refractive index of extraordinary light tQ = lambda/(4*(mu_O-mu_E)); // The thickness of the quarter wave plate, m printf("\nThe thickn...
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// Example 2.3:Numerical Aperture clc; clear; close; v= 26.6;//normalised frequency h=1.3;// Wavelenght in micro meters a=25;//core radius in micro meters NA=(v*h)/(2*%pi*a);// Numerical Aperture disp(NA,"Numerical Aperture of the Fiber is")
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//By Manas,FOSSEE,IITB //function which designs an iir digital filter using analog filter designs and bilinear transformation . hz=iir(3,'bp','butt',[.15 .25],[0 0]); [hzm,fr]=frmag(hz,256); plot2d(fr',hzm') xtitle('Discrete IIR filter band pass 0.15<fr<0.25 ',' ',' '); q=poly(0,'q'); //to express the result...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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//Caption:In a single phase transformer Calculate the secondary terminal voltage at full load. //Exam:3.17 clc; clear; close; V_1=2000;//Primary voltage at no load or full load(in Volts) V_2=400;//Secondary voltage at no load (in Volts) K=V_2/V_1;//Ratio of transformation R_1=5;//Primary resistance(in Ohm) R_2...
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//To Calculate the percentage increase in Magnetic Field //Example 37.3 clear; clc; X=2.1*10^-5;//Susceptibility of Aluminium Bin=X*100;//Percentage increase in Magnetic Field printf("Percentage increase in the Magnetic Field = %.1f*10^-3",Bin*10^3);
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clear flag=1 clc mode(-1) printf("Example 8 : Show the method of comparing files using cmp command \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") printf("\nHere all instructions are preloaded in the form of a demo...
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mode(7); // Primeira sessao no Scilab (parte 1) // define variável a = 1; // define outra variável (case sensitive) A = 2; // soma a + A // dois comandos na mesma linha c = [1 2]; b=1.5 // um comando em diversas linhas u = 1000000*(a*sin(A))^2+... 2000000*a*b*sin(A)*cos(A)+... 1000000*(b*cos(A))^2 // list...
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clear; clc; S=110; ff=.1; sg=.05; f=50; //supplying to infinite work mprintf("since power is supplied to infinite work frequency changes are independent of output\n"); mprintf("Since DelPg(0) is proportional to DelP(ref) therefore turbine generation can be reduced by giving a command to servometer of the speed ...
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prob = 0.95; lim = 0.5; X = cdfnor("X", 0,1, 0.975, 0.025 ) disp(ceil((4*X)^2), "Observations are necessary (atleast)")
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// Speed tachometer example clear Ra=1; Kt=10; J=2; f=0.5; Kb=0.1; Ka=54; Kg=1; num1=poly([1],'s','c'); den1=poly([f,J],'s','c'); num2=poly([Kg*Ka],'s','c'); den2=poly([1],'s','c'); num3=poly([Kb],'s','c'); den3=poly([1],'s','c'); num4=poly([Kt/Ra],'s','c'); den4=poly([1],'s','c'); // defining transfer functions G1...
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clc // Environment T0 = 298.15 // Environment temperature in K P0 = 1 // Atmospheric pressure in atm R = 8.3143// Gas constant xn2 = 0.7567 // mole fraction of nitrogen xo2 = 0.2035 // mole fraction of oxygen xh2o = 0.0312 // mole fraction of water xco2 = 0.0003// mole fraction of carbon dioxide xother = 0....
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clear; clc; // Example: 10.5 // Page: 401 printf("Example: 10.5 - Page: 401\n\n"); // Solution //*****Data******// deff('[P1] = f1(T)','P1 = exp(14.3916 - 2795/(T + 230))'); deff('[P2] = f2(T)','P2 = exp(14.2724 - 2945.47/(T + 224))'); deff('[P3] = f3(T)','P3 = exp(14.2043 - 2972.64/(T + 209))'); //**...
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//Chapter-1, Example 1.19, Page 1.45 //============================================================================= clc clear //INPUT DATA N=(300/60);//Speed of the motor in rps P=4;//Number of poles Z=732;//Number of conductors I=80;//Current through each conductor in A l=0.35;//Length of the conductor in...
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// Exa 11.12 clc; clear; close; format('v',6) // Given data C = 0.01;// in pF C = C * 10^-12;// in F L = 10;// in mH L = L * 10^-3;// in H f_o = 1/(2*%pi*sqrt(L*C));// in Hz f_o = f_o * 10^-6;// in MHz disp(f_o,"The oscillation frequency in MHz is"); R1 = 100;// in k ohm R2 = 5;// in k ohm A = 1 + (R1/R2...
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function xf=dft(x,flag); //xf=dft(x,flag); //macro which computes dft of vector x // x :input vector // flag :indicates dft or idft // xf :output vector //! //author: C. Bunks date: 29 Sept 1988 n=maxi(size(x)); arg=(0:n-1); am=-2*%pi*%i*arg'*arg/n; if flag=1 then, am=-am; end, xf=exp(am)*matrix(x,n,1); if fl...
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fRF=1.89*10^9; //RF frequency BW=20*10^6; //Bandwidth fIF=200*10^6; //Intermediate Frequency flo=fRF+fIF; //Local oscillator frequency Q=fIF/BW; //Quality factotr disp(Q,"Quality Factor");
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PL/SQL Developer Test script 3.0 93 declare -- Non-scalar parameters require additional processing p_ints_1 p_diff.TIntArray; p_ints_2 p_diff.TIntArray; p_intss_1 p_temp.TListInt; p_intss_2 p_temp.TListInt; m_compare p_temp.TCompareRecInt; m_str_1 varchar2(60); m_str_2 varchar2(60); m_ch varchar2(...
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errcatch(-1,"stop");mode(2);//Ex:3.12 ; ; c=150*10^-6;//in farads r=2*10^6;//in ohms V_s=150;//in volts V_c=0.8187*V_s; printf("Capacitor voltage = %f V",V_c); exit();
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// Exa 5.13 clc; clear; close; format('v',6) // Given data V_L = 400;// in V I_L = 10;// in A W2= 1;// assumed W1= 2*W2; phi= atand(sqrt(3)*(W1-W2)/(W1+W2)); W1= V_L*I_L*cosd(30-phi);// in W W2= V_L*I_L*cosd(30+phi);// in W disp(W1,"The reading of first wattmeter in W is : ") disp(W2,"The reading of secon...
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clc //initialisation of variables g= 32.2 //ft/sec^2 d= 3 //in h= 50 //ft w= 6.24 //lb/ft^3 r= 0.5 r1= 16 r2= 9/16 r3= 0.25 r4= 40.5/256 r5= 972/256 r6= 81/256 //CALCULATIONS v=sqrt(h*2*g/(r+r1+r2+r3+r4+r5+r6)) Q= %pi*(d/12)^2*v*60*w/4 //RESULTS printf ('discharge in the pipeline= %.1f gal.min',Q)
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FLAGS='--strip --detect' STDIN='' STDOUT='' STDERR='!USAGE!' EXITVAL='1'
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# @Harness: eventqueue # @Result: 5 A; 10 A; 15 A; 20 A; 25 A # @Purpose: this tests the operation of the delta queue using simple events event A { insert A 5; } main { insert A 5; advance 25; }
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// Exa 2.8 clc; clear; close; // Given data Nsi = 4.9*10^22;// in /cm^3 ni= 2.5*10^12;// in /cm^3 q=1.6*10^-19;// in C miu_n= 1600;// in cm^2/Vs miu_p= 400;// in cm^2/Vs N_D= Nsi/(100*10^6); sigma= q*ni*(miu_n+miu_p);// in (Ωcm)^-1 rho= 1/sigma;// in Ωcm disp(rho,"Resistivity of silicon in Ωcm is :") n=N_...
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//Example 6_2_u2 clc(); clear; //To calculate the atomic polarizability eo=8.85*10^-12 er=1.000435 n=2.7*10^25 alpha=(eo*(er-1))/n //units in met^3 printf("The atomic polarizability is aplha=") disp(alpha) printf("met^3")
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//Chapter 5, Exmaple 9, page 180 //Calculate corona onset voltage clc clear t = 5*5*8.66 // the three side of the trangle in m Deq = nthroot(t,3) dt = 1 //delta = 1 at standard temperature and pressure r = 1 //radius of the conductor En = 27.501 // kVpeak/cm E0 = 30*dt*(1 + 0.3*sqrt(dt*r)) V0peak = E0*log(Deq*10**2) V...
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// Exa 1.17 clc; clear; close; // Given data V1 = 0.7;// in V V2 = 5;// in V V_o = V1-V2;// in V R = 2.2*10^3;// in ohm I_D = -V_o/R; I_D = I_D * 10^3;// in mA disp(V_o,"The output voltage in volts is : ") disp(I_D,"The current through diode in mA is");
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clc Na=10^16 disp("Na = "+string(Na)+"/cm^3") //initializing value of medium p doping concentration. Nd=10^18 disp("Nd = "+string(Nd)+"/cm^3") //initializing value of light n doping . Vbi=0.64 disp("Vbi = "+string(Vbi)+"V") //initializing value of built in voltage. e=1.6*10^-19 disp("e = "+string(e)+"columns") ...
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//Chapter-1,Example 1_4,Page 1-17 clc() //Given Data: B=0.1*10^-2 //fringe spacing lam=5.893*10^-7 //Wavelength of light u=1.52 //Refractive index of wedge //Calculations: //We know, B=lam/(2*u*theta). Here u=1 theta1=lam/(2*u*B) //angle of wedge in radi...
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scenario = "Set Images"; response_matching = simple_matching; active_buttons = 3; button_codes = 1,2,3; default_font = "Calibri"; default_font_size = 24; default_text_color = 100,100,100; response_logging = log_active; begin; #image bitmap {filename = "\\training\\tree_flower_18.png";} flower; #letter ...
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load HalfAdder.hdl, output-file HalfAdder.out, output-list a b carry sum; set a %B0, set b %B0, eval, output; set a %B0, set b %B1, eval, output; set a %B1, set b %B0, eval, output; set a %B1, set b %B1, eval, output;
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clc; // Answer for minimum excitation voltage is given wrong in book v=400; // rated voltage of motor xd=6; // d-axis synchronous reactance xq=4; // q-axis synchronous reactance vt=400/sqrt(3); // rated per phase voltage p=21; // load carried by motor pph=(p/3)*1000; // per phase load carried by motor // As per...
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Multiply Function.sce
function mymultiply=multiply(xn,n0,xm,m0)// Hàm multiply y(n)= x1(n).x2(n) // Tiền xử lí tín hiệu xn và xm // Bổ sung thêm a lần phần tử '0' vào bên trái tín hiệu xm a=abs(m0-n0); if n0>m0 then //xn --> xnnew0 xnnew0=xn; //xm --> xmnew0 ...
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disp('chapter 6 ex6.3') disp('given') disp("current souurce to be designed") disp("constant output current=100mA") Il=.1 disp("maximum load resistance=40ohms") Rlmax=40 disp("available supply voltage=+/-12V") Vcc=12 disp("for P MOSFET Vdsmax=100 Idmax=210mA Rdon=5") Vdsmax=100 Idmax=0.210 Rdon=5 disp("Vdsmax=Vcc=12") ...
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//To Determine phasors and phasor diagrams when loaded with a balanced resistor //Page 154 clc; clear; R=2.77; //Resistance of the balanced load //From Phasor Diagram in Result file Vab=480*exp(%i*0); //Reference Voltage MVn=abs(Vab)/sqrt(3); //Magnitude of line to neutral voltages //Angles of Three phase vol...
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function z=narsimul(x1,x2,x3,x4,x5,x6,x7,x8) //function z=narsimul(a,b,d,sig,u,up,yp,ep) // or // function z=arsimul(ar,u,up,yp,ep) // // Armax simulation using rtitr // A(z)= Id+a1*z+...+a_r*z^r; ( r=0 => A(z)=Id) // B(z)= b0+b1*z+...+b_s z^s; ( s=-1 => B(z)=0) // D(z)= Id+d1*z+...+d_t z^t; ( t=0 => D(...
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//Chapter-4,Example4_6_1,pg 4-7 P=3.147*10^-3 //output power t=60 //time wavelength=632.8*10^-9 //wavelength of He-Ne laser h=6.63*10^-34 //Plancks constant c=3*10^8 ...
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clf; clear; clc; load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps de service index_bool = ( data(:, 3) == 3 ) tabS3 = data(index_bool, :) t_s3 = tabS3(1:$,4); deciles=perctl(t_s3,10:10:90); for i=2:10 ClassesDeciles(i)=deciles(i-1) end ClassesDeciles(1)=min...
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load GameOfLife.asm, output-file me.out, compare-to me.cmp, output-list RAM[100]%D1.8.1 RAM[101]%D1.8.1 RAM[132]%D1.8.1 RAM[133]%D1.8.1; set PC 0, set RAM[99] 1, // set number of generations set RAM[100] 1, // set starting pattern set RAM[101] 1, set RAM[132] 1, repeat 5000000 { ticktock; } output;
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x^2 + y^2 - z^2 - x^2 - y^2 + z^2 equals=false, isEqualTo=true, isEquivalent=false, similiarity=null
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// To determine Rl for which resonance can take place clc; clear; Rl=poly(0,'Rl'); Rc=5; Xc=6; Xl=15; x=(((Rl^2)+(Xl^2))*Xc)-(((Rc^2)+(Xc^2))*Xl); Rl=roots(x); disp(x) printf('The above eqaution must be eqauted to zero to get Rl \n') disp(Rl) printf('The above eqaution leads to imaginary roo...
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// find output voltage // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 24-15, page 984 clear; clc; close; // Given data R1=2.21*10^3;// in ohms R2=2.8*10^3 ;// in ohms Vref=2.21;// in volts // Calculations Vout=((R1+R2)/R1)*Vref;//...
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K=8.62*10^-5; T=300; a=K*T; printf('\n The value of K*T is %fV',a); I0=10^-6; Va=0.15; disp("rac=1/((I0/K*T)*exp(Va/K*T));"); rac=1/((I0/a)*exp(Va/a)); printf('\n The value of rac is %f ohm',rac);
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//Given that R = 8.5*10^-2 //in meter Rb = 0.13 //in T/s r = 5.2*10^-2 //in meter //Sample Problem 31-4a printf("**Sample Problem 31-4a**\n") //Using Faraday's law Rf = Rb*%pi*r^2 E = Rf/(2*%pi*r) printf("The induced electric field is equal to %eV/m\n", E) //Sample Problem 31-4b printf("\n**Sample Pr...
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//example 14.35 //design the distributory using Laecey theory clc;funcprot(0); //given f=0.85; //silt factor AR=3600; //area for rabi AK=1400; //area for kharif delta_r=0.135; //kor depth for rabi delta_k=0.19; //kor depth for kharif tr=4; //kor period for rab...
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//Optoelectronics and Fiber Optics Communication by C.R. Sarkar and D.C. Sarkar //Example 3.7 //OS = Windows 7 //Scilab version 5.5.2 clc; clear; //given C=3*10^8;//speed of light in m/s lamda=0.85*10^-6;//wavelength in m SW=0.003*10^-6;//spectrum width in m Ym=0.021;//material dispersion parameter (ps...
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= Basic Tests 6 basic/ctrl-z_test.py 6 basic/ctrl-c_test.py 6 basic/fg_test.py 6 basic/jobs_test.py 6 basic/stop_test.py 5 basic/bg_test.py 5 basic/kill_test.py
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//Caption:transfer_function_of_generator //example 5.9.7 //page 105 syms E Vf Kg R L s=%s; //generator_field_constant_Kg=delta(e)/delta(If) Kg=50/2; L=2;//field_inductance R=200;//field_resistance //transfer function is given by : E/Vf=(Kg/R+s*L) a=Kg/(R+s*L); disp(a,"E(s)/Vf(s)=");
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//Example 7.7 clc clear function [I] = simp13 (fun,a,b,n) // Integrate the function over the interval using Simpson's 1/3rd rule // simp13 (fun,a,b,n) // fun - function to be integrated // a - lower limit of integration // b - upper limit of integration // n - No. of times simpson's 1/3rd rule needs to be ...
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# answers.tst >>> from xml.etree import ElementTree >>> from ucc.word import answers, xml_access >>> root = ElementTree.fromstring(''' ... <answers> ... <answer name="q1" type="bool" value="True" /> ... <answer name="q2" type="number" value="123" /> ... <answer name="q3" type="int" value="123" repeated="T...
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// problem 10.9 Q=0.05 p=392.4*1000 n=0.65 s=0.8 w1=9810 Hw=p/w1 Hoil=p/(w1*s) Pw=(w1*Q*Hw)/(n*1000) Poil=(w1*s*Q*Hoil)/(n*1000) disp(Pw,Poil,"power in Kw to drive the pump with water and oil of s,p=0.8")
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//=========================================================================== //chapter 3 example 5 clc; clear all; //variable declaration er = 1.5*10^-2; //accuracy A1 = 10; //current in A A2 = 2.5; //current in A //calcu...
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clear; clc; disp(' Example 19.4'); // aim : To determine // (a) the volume of external saturated air // (b) the mass of air // (c) the heat transfer // (d) the heat transfer required by the combind water vapour // given values Vb = 56000;// volume of building, [m^3] T2 = 273+20;// temperature of air in th...
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//Question 1 Rb = 270.833; Tb = 1/Rb; disp(Tb); B = 0.3/Tb; disp(B); //Question 2 Rb = 270.833; c = Rb/0.4; disp(c); b1 = 200; snr = (2^(c/b1)) - 1; disp(snr); //Question 3 b = 200; Rb = 270.833 be = Rb/b disp(be); //Question 4 bc = 1250; rb = 9.6; srmin = 3; sumin_ratio = 10^(srmin/10); disp(sumin_ratio); mm...
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function [mod,fase]=polar2(z) mod = abs(z) fase = atan(imag(z),real(z)) endfunction function [mod,fase]=polard(z) mod = abs(z) fase = atand(imag(z),real(z)) endfunction
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//chapter28 //example28.10 //page607 printf("1) Y = A . B . C` + A . ( B . C )` \n") printf(" Y` = ( A . B . C` + A . ( B . C )` )` \n") printf(" By De Morgan theorem \n") printf(" Y` = ( A . B . C`)` . ( A . ( B . C)` )` \n") printf(" By De Morgan theorem \n") printf(" Y` = ( A` + B` + C ) . ( A` ...
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// (4.12) Steam at a pressure of 15 bar and a temperature of 320C is contained in a large vessel. Connected to the vessel through a valve is a turbine followed by a small initially evacuated tank with a volume of 0.6 m3. When emergency power is required, the valve is opened and the tank fills with steam until the pre...
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//Transport Processes and Seperation Process Principles //Chapter 7 //Example 7.1-1 //Principles of Unsteady state and convective mass transfer //given data //si units c0=0.1;//initial concentration c1=0;//final concentration K=1;//assumed as 1 Dab=4.72/(10^10);//diffusivity t1=10*3600;//time take x1=0; xc...
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A=[0 1;-2 -3]; B=[1;2]; P=[1 1;1 -1]; Ahat= P*A*inv(P) Bhat=P*B disp(Ahat,"A^=") disp(Bhat,"B^=")
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#-- scenario file --# # when mouse have to alternately lick either port (3x) to get water # to motivate exploratory licking, can press spacebar to give free drop of water # pure-tone sounds are also played when reward is delivered, so mouse gets used to cue # modified from MJ phase1_Alternation 2/14/2017 # correct disp...
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// ============================================================================= // loader.sce // ============================================================================= D3R_KINEM_ALG_DIR = get_absolute_file_path( "loader.sce" ); getd( D3R_KINEM_ALG_DIR ); // ====================================================...
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--> zeros(3,4) ans = 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.
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clc //initialization of variables V=1000 //mph P=14.7 //lb/in^2 T=60 //F g=1.4 //calculations V1=V*(88/T) Pratio=(1+ (g-1)*V1^2 /(2*g*32.2*53.3*(T+460)))^(g/(g-1)) eta=1-1/(Pratio)^0.286 //results printf("Theoretical cycle efficiency = %.3f",eta)
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//to calculate starting torque and atarting current,motor performance clc; V_a=110*complex(cosd(90),sind(90)); V_m=220*complex(cosd(0),sind(0)); R_1=3; R_2=2.6; X_1=2.7; X_2=2.7; X=110; V_f=(1/2)*(V_m-imult(V_a)); V_b=(1/2)*(V_m+imult(V_a)); Z_f=(complex(0,X)*complex(R_2,X_2))/(complex(0,X)+complex(R_2,X_2...
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//To find line current and pf and powers of a balanced delta load clc; clear; Z=8+6*%i; // Load V=230; // Voltage supply iR=V/Z; theta= atand(imag(iR)/real(iR)); Il= iR*sqrt(3); // Line current Pa=sqrt(3)*V*abs(Il)*cosd(theta); // Active Power Pr=sqrt(3)*V*abs(Il)*sind(theta); // Reactive Power Pt...
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//Chapter 28 clc //Example 6 //given Z=74 //atomic number of tungsten Eo=13.6 //ground state enenrgy in ev E_K=-(Z-1)^2*(13.6) //Energy of the electron in K shell n=3 Z_eff=Z-n^2 E3=Eo/n^2 E_M=-Z_eff^2*E3 E=E_M-E_K disp(E,"Energy of the characteristic emiited from tungsten target when electron drops from M shell to K s...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 12: POWER,ENERGY,AND EFFICIENCY RELATIONS OF DC AND AC DYNAMOS // Example 12-18 clear; clc; close; // Clear the work space and console. // Given data (Ex.12-16) // code letter = J P = 6 ; // Numb...
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clc; //ex3.6 q=1.60*10**-19; l=0.2*10**-3; a=0.04*10**-6; v=1; i=8*10**-3; mun=0.13; //concentration of free electrons R=v/i;//resistance disp('ohm',R*1,"R="); rho=(R*a)/l; disp('ohm-m',rho*1,"rho="); sigma=1/rho;//conductivity n=sigma/(q*mun);//concentration of free electrons disp('/m^3',n*1,"n=") //Dr...
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clc clear printf("example 8.7 page number 367\n\n") //to find the flow rate in an orifice density_of_water = 1000; //in kg/m3 viscosity = 1*10^-3; //in Pa-s pipe_diameter = 250; //in mm orifice_diameter = 50; // in mm density_of_mercury = 13600; // in mm manometer_height = 242; ...
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// Initilization of variables r=200 // m // radius of the curved road v_1=72*(1000/3600) // m/s // initial speed of the car v_2=36*(1000/3600) // m/s // speed of the car after 10 seconds t=10 // seconds // Calculations A_n=v_1^2/r // m/s^2 // normal component of acceleration A_t=0 // since dv/dt=0 // tangential ...
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// Scilab code: Ex3.23 : Uncertainity in the position of a bullet:Pg: 93 (2008) m = 0.025; // Mass of an bullet, kg v = 400; // Speed of bullet, m/s h_bar = 6.6e-034; // Reduced Plancks constant, joule second p = m*v; // Momentum of bullet, kgm/s del_p = 2e-04*p; // Minimum uncertainity in momentum,...
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//Matemática Discreta - Proposta de resolução da ficha prática 5 //Nota: As resoluções que se seguem apresentam apenas sugestões de resolução dos exercícios propostos. Na maior parte dos casos, existem muitas outras formas de resolver o exercício. function M=um(A) //função equivalente à função bool2s V=size(A)...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 2: Basic Laws // Example 2 - 6 clear; clc; close; // // Given data v1 = -12.00; v2 = -4.00; R1 = 4.00; R2 = 6.00;...
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scenario = "frame"; scenario_type = fMRI_emulation; #scenario_type = fMRI; scan_period = 3000; response_matching = simple_matching; no_logfile = false; sequence_interrupt=false; #default active_buttons = 2; button_codes=0,1; default_font="arial"; default_font_size=30; default_text_color=255,255,255; default_background_...
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//Example 5.50 //Spline Interpolation //Page no. 204 clc;close;clear; xi=[1,2,3]; yi=[-1,4,21]; x=poly(0,'x') deff('y=S(x0,x1)','y=(x-xi(x1))*yi(x0)/(xi(x0)-xi(x1))+(x-xi(x0))*yi(x1)/(xi(x1)-xi(x0))'); S1=S(1,2); S2=S(2,3); printf('\n The required Spline is : \n') disp(S2,'S2 = ',S1,'S1 = ');
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function [y, xm]= rceps(x) //Produce the cepstrum of the signal x, and if desired, the minimum phase reconstruction of the signal x. //Calling Sequence //[y, xm] = rceps(x) //Parameters //x: real or complex vector input //Produce the cepstrum of the signal x, and if desired, the minimum phase reconstruction of the sig...
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function x=%r_rand(a) // Copyright INRIA x=rand(a(2));
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clc; i1=3; //current in Ampere n2=500; //no. of turns n1=100; //no. of turns v1=120; //potential diff in volt v2=(n2*v1)/n1; //calculating v2 i2=(n1*i1)/n2; //calculating i2 disp(v2,"Voltage in volt = "); //diplaying result disp(i2,"Current in Ampere = "); //diplaying result
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// Example 2_12 clc;funcprot(0); // Given data v_0=250;// km/h theta_i=15;// degree a=0.8;// m/s^2 t=60;// seconds s_0=0;// m x=3000;// m // Calculation // (a) v_0=v_0/3.6;// m/s v=v_0+(a*t);// m/s s=s_0+(v_0*t)+((1/2)*a*t^2);// m y=s*cosd(theta_i);// m theta=atand(y/x);// degree r=sqrt(x.^2+y.^2);// ...
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//ques-18.45 //Calculating change in chemical potential of a substance clc P1=1; P2=0.5;//partial pressure (in atm) T=298;//temperature (in K) C_P=8.314*T*log(P2/P1); printf("The change in chemical potential is %.4f kJ/mol.",C_P/1000);
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čagar’ čagarilesai N;TERM;SG saged sagedoihe ADJ;IN+ALL;PL lainduz lainduselesai N;TERM;SG rida ridoilepäi N;PRP;PL kül’menzoitta kül’menzoitta V;NFIN allergine allergižen ADJ;ACC;SG avtozavod avtozavodoin N;FRML;PL konsonant konsonantoihepäi N;PRP;PL pakssil’mäine pakssil’mäiženno ADJ;APPRX;SG armahtuzkäsk armahtuzkäs...
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clc;funcprot(0)//EXAMPLE 7.9 //Initializing the variables etaV1 = 0.81;.........//Volumetric efficiency pi1 = 1.01;.......//Inlet pressure before supercharger pe1= 1.01;...........//Exhaust pressure before supercharger pi2= 1.38;............//Inlet pressure after supercharger pe2 = 1.01;.........//Exhaust press...
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exec("swigtest.start", -1); try initArray(); catch swigtesterror(); end if x_get() <> int32([0,1,2,3,4,5,6,7,8,9]) then swigtesterror(); end if y_get() <> [0/7,1/7,2/7,3/7,4/7,5/7,6/7] then swigtesterror(); end exec("swigtest.quit", -1);
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# - Header - # # - Disc Threshold One - # scenario = "17_March_2015"; $BP = "D"; response_matching = simple_matching; active_buttons=3; # button press button_codes=251,252,253; # - Screen Parameters - # default_font_size = 26 ; default_font = "Arial"; default_text_color = 0, 0, 0; screen_width = 102...
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// Exa 13.16 clc; clear; close; // Given data f = 700;// in Hz D = 0.5; C = 0.1;// in µF C = C * 10^-6;// in F // Formula f= 1.44/((R_A+2*R_B)*C) // R_A+2*R_B= 1.44/(f*C) (i) // D= (R_A+R_B)/(R_A+2*R_B) or // R_A+R_B=D*1.44/(f*C) // From eq (i) and (ii) R_B=round(1.44/(f*C))*(1-D); R_A= ...
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epsilon=8.854D-12 r=sqrt(.1^2+.1^2)//distance b/w A and C Fca=(2D-6)*(4D-6)/(4*%pi*epsilon*r^2)//from A to C Fcb=(4D-6)*(2D-6)/(4*%pi*epsilon*.1^2)//from C to B Fcd=(4D-6)*(4D-6)/(4*%pi*epsilon*.1^2)//from C to D //Fr has horizontal and vertical components as Frx and Fry respectively Frx=Fcd-Fca*cos(45*%pi/180)...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 8.7\n\n\n"); // Chapter 8 : Vapor Power Cycles // Problem 8.7 (page no. 386) // Solution //From problem 8.3, work=1515-1150.5; //Unit:Btu/lbm of steam //pump work is neglected //Useful ideal work //Because of the heat losses, 50 Btu/lbm of the 364.5 B...
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clear // //From the circuit diagram of the figure we can obtain tha following equations based on which the problems are solved //eqn 1..........vl=(i1+i2)*zl....the load voltage //eqn 2..........vl=e1-i1*z1=e2-i2*z2 //eqn 3..........i1=(e1-vl)*y1 and i2=(e2-vl)*y2 //eqn 4..........vl=(e1*y1+e2+y2)/(y1+y2+yl) //load vol...
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//clear// clc clear exec("9.8data.sci"); t = 0:.01:1.5; function w=f(t,Y) w =zeros(4,1); k1a=1.25*exp((9500/1.987)*((1/320)-(1/Y(4)))); k2b=0.08*exp((7000/1.987)*((1/290)-(1/Y(4)))); ra=-k1a*Y(1); V=100+vo*t; rc=3*k2b*Y(2); rb=k1a*(Y(1)/2)-k2b*Y(2); w(1)=ra+(Cao-Y(1))*vo/V; w(2)=rb-Y(2)*vo/V; w(3...