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clc clear printf('Solve the equation y''+y=3X^2, with boundary points (0,0) and (2, 3.5)') printf('\nCompare computed value form The Galerkin Method vs Analytic result') P=0 X(1,1)=0 for i=1:20 X(1,i+1)=0.1+P P=X(1,i+1) end for i=1:21 A(1,i)=(101/152).*X(1,i).*X(1,i).*X(1,i)-(103/228)*X(1,i).*X(1...
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//Example_a_16_9 page no:787 clc; Y11=6; Y22=6; Y21=4; Y12=4; Ys=1; driv_pt_admt=((Y22*Ys)+(Y22*Y11)-(Y21*Y12))/(Ys+Y11); disp(driv_pt_admt,"the driving point admittance is (in mho)");
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function []=process_result(filename) M = csvRead(filename, ";") fontS = 4; disp(filename); M1 = M; M1(isnan(M1)) = 60000; disp("total times:"); disp(sum(M1, 1)/1000/60/60); disp(sum(M1)/1000/60/60); f=gcf(); f.figure_size=[1100, 650] f.background=-2; T=5000...
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//Ex:2.17 clc; clear; close; r_o=40;//resis at 0 degree r_t=44;//at 100 degree t=100;//temperature diff. temp_coeff=(1/t)*((r_t/r_o)-1); printf("Temperature Coefficient = %f per degree centigrade",temp_coeff);
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clc; p1=1.0021; // Initial pressure of the fluid in MPa T1=180; // Initial temperature of the fluid in degree celcius m=0.5; // Mass of the fluid in kg p2=p1; // Constant pressure process // (a).Steam x1=0.8; // Quality of the steam at state 1 // Following are the values taken from steam table vf1=0.001127; ...
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//Chapter-11 example 35 //============================================================================= clc; clear; //input data lamda = 0.03; //wavelength in m RCS = 5; // Radar cross section in m^2 D = 1; // antenna diameter in m F ...
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y^2 = x^3 + c with x = 24*w + 3, y = 54*v + 5, c = - 2 x -> (2976*w + 31104*w^2 + 165888*w^3 + 331776*w^4 + 129) / (2160*v + 11664*v^2 + 100), y -> ( - 9072*w - 492480*w^2 - 6912000*w^3 - 44789760*w^4 - 143327232*w^5 - 191102976*w^6 + 383) / (32400*v + 349920*v^2 + 1259712*v^3 + 1000)
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//Script to solve dY/dx=F(x,Y), Y(x0)=Y0 function [Z] = F(x, Y) Z(1) = Y(2); Z(2) = (2.5 * sin(.5 * x) - 5 * abs(Y(2)) * Y(2) - 6 * Y(1)) / 2; endfunction; x = [0.0:0.25:15]; x0 = 0; Y0 = [1;0]; Y = ode("rk", Y0, x0, x, F); //solve ODE disp("t Displacement Velocity") disp([x' Y']); y1 = Y(1,:); y2 = Y(2,:); /...
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//clc() T1 = 250;//K T = 273.15;//K T2 = 400;//K Cice = 2.037;//kJ/kgK T3 = 373.15;//K Cliq = 75.726;//kJ/kmolK //Cp = 30.475 + 9.652*10^-3*T + 1.189*10^-6*T^2 Hfusion = 6012;//kJ/kmol Hvap = 40608;//kJ/kmol //1 - Heat for raising the temperature of ice, H1 H1 = Cice * (T - T1); //2 - Latent heat of fusion ...
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l=8; r=400; v=20; disp("Part a"); t=l/r; disp("the time constant (in ms) of the circuit is"); disp(t*10^3); disp("Part b"); i=v/r; disp("final value of the current (in mA) is"); disp(i*10^3); disp("Part c"); rate=v/l; disp("the initial rate of rise of current (in A/s) is"); disp(rate); disp("Part d"); t1=i...
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//chapter_no.-6, page_no.-260 //Example_no.6-4-1 clc; //(a) Calculate_the_strong_potential_w(inv)_for_strong_inversion kt=26*(10^-3); Na=3*(10^17); Ni=1.5*(10^10); wsinv=2*kt*log(Na/Ni); disp(wsinv,'the_strong_potential_w(inv)_for_strong_inversion(volts)'); //(b)Calculate_the_insulator_Capacitance eir=4; ei=8.854...
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// ==================================================================== // Allan CORNET // DIGITEO 2008 - 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== r = xls_NewExcel(); assert_checktrue(...
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clear // // //Initilization of Variables L_ED=2 //m //Length of DB & AC L_AC=2 L_DB=2 L_CD=4 //m //Length of CD L_CE=2 //m //Length of CE F_A=40 //KN //Force at C F_B=20 //KN //Force at A E=200*10**6 //KN/mm**2 //Modulus of Elasticity I=50*10**-6 //m**4 //M.I //Calculations //LEt V_C & V_D be the reactions at C & D...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.1\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.1 (page no. 322) // Solution //As the basis of the calculation,assume that we have 1 lbm of mixture.Also,take the molecular weight of oxygen to be 32.00 and nitrogen to be 28.02.(from tabl...
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//4.16 clc; Vav=250; V=150; Toff=1*10^-3; Ton=(Vav/V)*Toff-Toff; printf("Period of conduction = %.6f sec", Ton)
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function [num,den]=%p_simp(num,den) // implement complex case // Copyright INRIA
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//Example 1_27 clc; clear; close; format('v',4); //given data : V1=20;//V V2=4;//V R1=500;//ohm R2=1000;//ohm R3=100;//ohm R4=800;//ohm RL=1000;//ohm //solution VCB=-R2/(R4+R2)*V1;//V //writing KVL equation for the loop I=poly(0,'I'); eqn=V1-R1*I-V2-R3*I;//KVL equation I=roots(eqn);//A VCA=-I*R1;//V ...
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// [ir,r,cl] = cra(z,M,n) // M: No. of lags // n: Order of pre whitening filter // z is of the form: // z = [y u] // y and u are column matrices function [ir,r,cl] = cra(z,varargin) len = length(varargin); if len==0,M = 20;n = 10; elseif len==1,M = varargin(1);n=10; else M = varargin(1);n ...
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clc //initialisation of variables p=1.0//metres p0=0.8//metres p100=1.093//metres //CALCULATIONS t=((p-p0)*100/(p100-p0)) //RESULTS printf(' temperature of hot water= % 1f C',t)
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : VCAST_TIME_W -- Unit(s) Under Test: vcast_time -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCR...
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пуғдай пуғдайзар N;ALL;SG кӱскӱ кӱскӱнің N;GEN;SG алтын алтын N;NOM;SG чайғы чайғылар N;NOM;PL хар харның N;GEN;SG ағас ағастар N;NOM;PL хуча хучаларнаң N;INS;PL кӱскӱ кӱскӱлерзер N;ALL;PL хара хурт хара хурт N;NOM;SG тарбаған тарбағаннарда N;AT;PL иир иирзер N;ALL;SG алтынзарых алтынзарыхтарзар N;ALL;PL інек інектерні...
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// ******************************************************************* // Lagrange Interpolation for the given data: **** // (x1, f1), (x2, f2), (x3, f3), ......(xn, fn) **** // NPDE-TCA UG-Level workshop at IMA Bhubaneshwar **** // By Manas,FOSSEE,IITB ...
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//Exa 1.12 clc; clear; close; //Given data format('v',6); C1=21;//in pF V1=4;//in volt V2=9;//in volt disp("C is proportional to 1/sqrt(V)"); disp("So, C2/C1=sqrt(V1/V2)"); C2=sqrt(V1/V2)*C1;//in pF disp(C2,"At reverse bias 9V, Diode capacitance in pF : ");
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function [fx] = FungsiD(x) M = sum(x); [m, n] = size(x); for i = 1 : n fx(i) = (x(i)) / M end endfunction
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//Bilinear transformation //To convert twin-T notch analog filter to digital filter s=%s; z=%z; HS=(s^2+1)/(s^2+4*s+1); Wo=1; S=240;f=60;//sampling and analog frequencies W=0.5*%pi;//digital frequency C=Wo/tan(0.5*W) HZ=horner(HS,C*(z-1)/(z+1)) f=0:120; HZ1=abs(horner(HZ,exp(-%i*%pi*f'/120))); HS1=abs(horne...
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// Example 8_2 clc;funcprot(0); // Given data Q_solar=100*10^3;// Btu/h T_river=40+459.67;// R T_collector=200+459.67;// R // Calculation W_e_rev=(Q_solar*(1-(T_river/T_collector)))/3412;// kW printf("\nThe maximum steady state electrical power (in kW) that can be produced by this power plant,(W_electrical)_r...
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function [x_q, s_q] = delta_mod(sinal,delta) e(1) = 0; e_q(1) = delta*sign(e(1)); x_q(1) = 0; for k=1:length(sinal) e(k+1) = sinal(k) - x_q(k); e_q(k+1) = delta*sign(e(k)); x_q(k+1) = x_q(k) + e_q(k); end s_q = e_q./delta; endfunction
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clc; funcprot(0); //Example 24.1 //Initializing the variables H_at = 10.3; Hs = 1.5; Hd = 4.5; Ls = 2; Ld = 15; g = 9.81; Ds = 0.4; // Diameter of stroke Db = 0.15; // Diameter of bore Dd = 0.05; // Diameter of discharge and suction pipe nu = 0.2; f = 0.01; abs_pump_pressure = 2.4; //Calcula...
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//chapter 21 Ex 1 clc; clear; close; p=68000; r=50/3; t=9/12; sInterest=(p*r*t)/100; printf("The simple interest is Rs. %d",sInterest);
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//chapter6,Example6_19,pg 148 Ie=1*10^-3 Ib=0.04*10^-3 Ic=Ie-Ib alpha=Ic/Ie printf("current gain\n") printf("alpha=%.2f",alpha)
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// Exa 2.16.5 clc; clear; close; format('e',8) // Given data At = 63.5;// atomic weight d = 8.96;// in gm/cc Miu_e = 43.28;// in cm^2/V.sec N_A = 6.02*10^23;// in /gm mole e = 1.6*10^-19;// in C n = (N_A/At)*d;// in /cc Rho = 1/(n*e*Miu_e);// in ohm-cm disp(Rho,"The resistivity in ohm-cm is");
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 6 : SYNCHRONOUS MACHINES // EXAMPLE : 6.28 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA V = 400; // Operating voltage of the Synchron...
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clc; bore=5;//cm stroke=7.5;//cm V=(%pi/4)*5^2*7.5 V0=21.3; tV=V+V0; rv=tV/V0; y=1.4; eta=1-[rv^(1-y)]; disp("efficiency is:"); disp("%",eta*100)
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//Variable declaration theta=90; //angle(degrees) lamda=1.5; //wavelength(angstrom) d=1.6; //spacing(angstrom) //Calculation theta=theta*%pi/180; //angle(radian) n=2*d*sin(theta)/lamda; //order of diffraction //Result printf('order of diffraction is %0.3f \n',int(n))
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function [AllpassNum,AllpassDen]= allpasslp2bs (Wo,Wt) // Allpass filter for lowpass to bandstop transformation // //Calling Sequence: //[AllpassNum,AllpassDen] = allpasslp2bs(Wo,Wt): returns the numerator, AllpassNum, and the denominator, AllpassDen, of the second-order allpass mapping filter for performing a real low...
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// Scicos // // Copyright (C) INRIA - Masoud Najafi <masoud.najafi@inria.fr> // Serge Steer <serge.steer@inria.fr> 1993 // Habib Jreij 1993 // // This program is free software; you can redistribute it and/or modify // it under the terms ...
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i=0.2; v1=120; f=60; v2=95; disp("Part a"); z1=v1/i; x_l=sqrt(z1^2-r^2); z2=v2/i; x_c=x_l-sqrt(z2^2-r^2); c=1/(2*%pi*f*x_c); disp("the size of capacitance (in μF) needed is"); disp(c*10^6); disp("Part b"); vc=i*x_c; disp("voltage (in V) across capacitor is");disp(vc); disp("Part c"); v=i*z1; disp("volta...
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// Exa 5.10 clc; clear; close; // Given data Vin= 10;// in volt R=2.2;// in k ohm R=R*10^3;//in ohm Ad=10^5;// voltage gain T= 1;// in ms T=T*10^-3;// in second C=1;// in micro F C=C*10^-6;// in F I= Vin/R;// in volt V= I*T/C;// in V disp(V,"The output voltage at the end of the pulse in volt"); RC_desh=...
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clc //initialization of varaibles disp("From psychrometric charts,") e=0.7 phi=0.5 g1=0.0131 //lb water/lb dry air h1=32.36 //B/lb of dry air g3=0.0073 h3=24.26 pg=0.3390 T3=528 //R V3=1000 Rw=85.8 //calculations pw3=phi*pg ww3=pw3*144*V3/(Rw*T3) wa3=ww3/g3 wa1=phi*wa3 wa2=phi*wa3 ww1=g1*wa1 ww2=ww3...
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// Scilab code Exa4.5.8: To determine the threshold energy for given reaction : P.no. 185 (2011) // Na(11,23)+ n > F(9,20)+ He(2,4) is the reaction M_Na_23 = 22.99097; // Mass of Na-23, amu M_n_1 =1.00866 ; // Mass of n-1, amu Q = -5.4; // Q-value, MeV E_th = -Q*(M_Na_23+M_n_1)/M_Na_23; // Threshold energy, M...
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//example 14.34 //calculate concentration at point 10 cm above the bed clc;funcprot(0); //given D=2.8; //depth of flow c_=700; //concentration at 30 cm below water surface y=0.1; a=D-0.3; e=0.4; //exponent in rouse equation; c=c_*(a*(D-y)/(y*(D-a)))^e; mprintf("concentration at po...
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function y=f(x) y=-sin(x^2)/x endfunction x=[0.001:0.02:2*%pi]; clf; plot(x,f,"r")
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function demo_scatterly_sin() x=[0:0.1:2*%pi]; y=2*sin(x); scatterly(x,y) endfunction demo_scatterly_sin(); clear demo_scatterly_sin;
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clc; g1=1.5; // gain factor of amplifier g2=80; // gain factor of generator vo=250; // output voltage at no load s=0.2; // feedback potentiometer setting // for generated voltage= 80V field current is 1 A ifl=vo/g2; // field current for generated voltage= 250V vi=ifl/g1; // amplifier input voltage for field curr...
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// Calculate the value of resistance after 15s clc; R0=29.44; Rs=100; t=15; tc=5.5; R_15=Rs+R0*[1-exp(-t/tc)]; disp(R_15,'value of resistance after 15s(ohm)')
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clc //initialisation of variables clear p1= 10 //atm p2= 1 //atm T1= 25 //C n= 2/5 //CALCULATIONS T2= (p1/p2)^n*(273+T1)-273 //RESULTS printf ('Final temperature = %.f C',T2)
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syms I R C s V1=I*(R+1/(s*C)) V2=I*(1/(s*C)) disp(V2/V1,"V2/V1 = ")
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.26\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.26 (page no. 603) // Solution //From the table 11.7, //For the oil side,a resistance(fouling factor) of 0.005 (hr*F*ft^2)/Btu can be used //and for the water side,a fouling factor of 0.001 (hr...
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r = fscanfMat("/home/joe/programming/ruby/discrete_math/tickets_sold.dat");
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Expanding for base=2, level=6, reasons+features=base,same,similiar invall,norm Refined variables=x,y [0+1x,0+1y]: unknown -> [1] [0,0] x²-y³+3 ---------------- level 0 expanding queue[0]^-1,meter=[2,2]: x²-y³+3 [1+2x,0+2y]: unknown -> [1] [1,0] x+x²-2y³+1 [0+2x,1+2y]: unknown -> [2] [0,1] 2x²-3y-6y²-4y³+1 endexp[0] ---...
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1*a^1 + 1*b^1 > 0; 1*a^1 - 1*b^1 > 0; 1*a^1 > 0 evaluate: failure biased
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clear // //The composite figure is divided into three simple figures and taking A as origin coordinates of their centroids //variable declaration L1=400.0 //length of wire AB,mm L2=150.0*%pi //length of wire BC,mm L3=250.0 //length of wire CD,mm theta=30*%pi/180 //The wire is divided into three s...
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[[-1,2,-1,0,0],[1,2,-1,1,0],[2,-2,1,-1,0],[2,-1,2,0,0]] [0,1,0,1]*3 [-2,15,9,16]*2 [-12,43,38,51]*3 [-12,31,33,40]*12 [-80,171,204,235]*5 [-150,283,365,408]*6 [-84,145,198,217]*21 [[-1,2,1,1,0],[1,2,1,0,0],[2,1,2,0,0],[2,2,1,1,0]] [3,4,5,6] [1,6,8,9]*6 [-5,48,69,76]*3 [-27,100,152,165]*4 [-23,60,95,102]*15 [-137,294,...
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// chapter 7 example 5 //----------------------------------------------------------------------------- clc; clear; // given data Ptot = 100; // certain antenna radiating power Ptot_iso = 10*10^3; // isotropic antenna radiating power // Calculations D = 10*log10(Ptot_iso/Ptot); // Di...
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clear //Given A=10**-3 //m** n=10 I=2 //A B=0.1 //T //Calculation // t=n*I*A*B*cos(0) t1=n*I*A*B*cos(60*3.14/180.0) //Result printf("\n (i) Torque when magnetic field is parallel to the field %0.0f *10**-3 Nm",t*10**3) printf("\n (ii) Torque when magneti...
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clear; clc; close; w=0.4;//in micrometer l=100;//in nanometer Cg=1.6;//in fF/micrometer Ct=Cg*w; Cgs1=0;Cgd1=0;Cgb1=Ct/2;//cutoff Cgs2=Ct/2;Cgd2=Ct/2;Cgb2=0;//linear Cgs3=(2*Ct)/3;Cgb3=0;Cgd3=0;//saturation disp(Cgs1,'Cgs for cutoff region');//units in fF disp(Cgd1,'Cgd for cutoff region'); disp(Cgb1,'Cgb f...
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clc // Given that E = 5e-19 // energy of photon in J h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C // Sample Problem 5 on page no. 14.21 printf("\n # PROBLEM 5 # \n") printf("Standard formula used \n") printf(" E = h*c/lambda \n") lambda = c * h /...
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clear clc disp("example 8.6") mh=205//mean height a=1000*10^6//in miters r=1.25//annual rain fall er=0.8//efficiency lf=0.75//load factor hl=5//head loss et=0.9//efficiency of turbine eg=0.95//efficiency of generator wu=a*r*er/(365*24*3600) printf("\nwater used is \t\t%fm^3/sec",wu) eh=mh-hl printf("\neff...
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V=32 I=1 R1=20 R2=8 R3=2 Voc1=V/(R1+R2+R3)*(R2+R3) ///a,b open Isc1=V/R1 ///a,b short Voc2=I*R2/(R1+R2+R3)*R1 Isc2=I*R2/(R2+R3) ////by superposition Voc=Voc1+Voc2 Isc=Isc1+Isc2 disp(Voc) disp(Isc)
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clc; clear all; //page no 157 //prob no. 5.6 fLO=110; //MHz //for V2(f) f=[0:.01:231+.01]; //x axis function V=pulse() V=[] for i=1:.005:1.5 V=[V i] end endfunction V2=[zeros(0:.01:120-fLO-.01) pulse() zeros(121-fLO+.01:.01:120+fLO-.01) pulse() 0]; //y axis clf; subplot(21...
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function[e,xn,a,b,c]=newton(x) a=(x^3)-(0.165*(x^2))+(3.993*(10^-4)); b=(3*x^2)-(0.33*x); xn=x-(a/b); e=abs((xn-x)/xn)*100; if(e>0) then newton(xn); else disp(xn); disp(e); end endfunction
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//Example 5// Ch 12 clc; clear; close; // given data C2 = 0.75/3;//capacitance between 3 core bunched together and lead sheath in uF/km C3=0.56//in uf/km V=33*10^3; f=50;//in Hz C4=0.5*(C2+C3)*10;//capacitance per km b/w any two cores printf("capacitance per km b/w any two cores %f uF",C4) ChargKVAr=V^2*2*%p...
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// for open loop system // given speed=60km/hr syms R K1 K; (R*K1*K)=60 K1=50; K=1.5; R=60/(K1*K) disp(R,"Input open=") // for closed loop R=60(1+(K1*K))/(K1*K) disp(R,"Input closed=")
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//Chapter 26 clc //Example4 //given c=3*10^8 //velocity of light in m/sec //when the spaceship is at rest x=52 // diatance in x direction in meters y=25 //measurement in y direction v=0.95*c //when the spaceship moves to an observer at rest only x dimension looks contracted gamma=1/sqrt(1-(v^2/c^2)) L=x/gam...
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//example 5.7 //calculate discharge and percent increase in discharge clc; //given k=0.005; //coefficient of permeability r=0.1; //well radius s=4; //drawdown b=10; //thickness R=300; //radius of circle of influence //Part(a) Q1=2.72*b*k*s/...
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clear; clc; disp('Example 4.2'); // aim : To determine // saturation temperature and enthalpy // Given values P = 2.04;// pressure, [MN/m^2] // solution // since in the steam table values of enthalpy and saturation temperature at 2 and 2.1 MN?m^2 are given, so for knowing required values at given ...
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clc D = 12.7 // diameter in mm d = 50 // depth in mm v = 75 // cutting speed in m/min. f = 0.175 // feed in mm/rev l = d + 2*0.29*D // lemgth of drill travel in mm N = (1000*v)/(%pi*D) // r.p.m. tm = l/(f*N) // min printf("\n Time taken to drill hole = %0.3f min." , tm)
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//Tested on Windows 7 Ultimate 32-bit //Chapter 10 Feedback in Amplifiers Pg no. 330 and 331 clear; clc; //Given A=500;//open loop gain B=0.1;//feedback factor beta dA_to_A=10/100;//variation in open loop gain //Solution dAfb_to_Afb=dA_to_A*1/(A*B);//variation in closed loop gain printf("Percentage va...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 51 clc; disp("CHAPTER 2"); disp("EXAMPLE 51"); //VARIABLE INITIALIZATION Y1=0.4+(%i*0.6); //admittance of 1st branch in Siemens Y2=0.1+(%i*0.4); //admittance of 2nd branch in Siemens Y3=0.06+(%i*0.23); //...
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("16*x^4 - 16*y^4 - z^2").isMappableTo("x^4 - y^4 - z^2") = {x=>2*x,y=>2*y,z=>z}
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//chapter 9 example 4a// clc clear //angular velocity=A,llength at which rotating mirror from the photo detector=L,shadow pulse of width=We,shadow velocity=V,outer diametetr=do// L=0.1;//in mts// A=4;//in rad sec-1// V=L*A;//in mts/sec// printf("\n shadow velocity=%f m/sec\n",V) We=250;//in micro seconds// do=...
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//Example number 7.5, Page number 147 clc;clear; close; //Variable declaration A=650*10**-4; //area(m**2) epsilon0=8.85*10**-12; d=4*10**-2; //seperation(m) Q=2*10**-10; //charge(C) epsilonr=3.5; //dielectric constant //Calculation C=A*epsilon0/d; V=Q/C; //voltage(V) //Result printf("voltage ...
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clc //Example 8.7 //Calculate the cross sectional area, pressure, temperature and mach number at a pt in duct where air velocity is 1400ft/s P1=30//psia T1=660//R (Rankine temperature scale) ratio_T=0.83333//dimentionless m=10//lbm/s mass flow rate v1=1400//ft/s R=4.98*10^4//(ft^2/s^2)*(lbm/lbmol.R)^0.5 k=1.4/...
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//Example 3.15.2: shunt resistance clc; clear; close; //given data : Im=1;// in mA Rm=100;// in ohm I=100;// in mA Rsh=(Im*10^-3*Rm)/((I-Im)*10^-3); disp(Rsh,"shunt resistance,Rsh(ohm) = ")
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// Example 5.4 //slope efficiency clc; clear; close; eg=1242;// e=1300;//in nm n=0.1;//efficiency s=((eg/e)*n);// disp(s,"slope efficiency is")
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clc // Given that l = 3e-10 // width of box in m e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg c = 3e8 // speed of light in m/sec h = 6.62e-34 // Planck constant in J-sec // Sample Problem 16 on page no. 15.30 printf("\n # PROBLEM 16 # \n") printf("Standard Formula used \n") printf(" ...
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//Ex:67 clc; clear; close; R_e=6378;// in km H=35786;// in km E_min=5;// min elevation angle in degree x=cos(E_min*3.14/180); R=R_e/(R_e+H); P=2*asin(R*x);// in radian a_max=(P)*180/3.14;// in degree printf("The max coverage angle=%f degree", a_max);
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/07/MemoryAccess/BasicTest/BasicTestVME.tst load BasicTest.vm, output-file BasicTest.out, compare-to BasicTest.cmp, outpu...
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clc //Initialization of variables H=-169182 //Btu/mole s1=1.3609 //Btu/mole R s2=49.003 //Btu/mole R s3=51.061 //Btu/mole R T=537 //R //calculations dG=H-T*(s3-s2-s1) //results printf("Change in Gibbs energy = %d Btu/mole carbon",dG)
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clear; clc; funcprot(0); //Example - 15.16 //Page number - 534 printf("Example - 15.16 and Page number - 534\n\n"); //Given T = 78.15;//[C] P_1_sat = 755;//[mm Hg] P_2_sat = 329;//[mm Hg] z_1 = 0.3; V = 0.5; // log(Y1) = 0.845/(1 + 0.845*(x_1/x_2))^(2) // log(Y2) = 1/(1 + 1.183*(x_2/x_1))^(2) //...
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clear; clc; close; yos = 50*10^(-6); Idss = 10*10^(-3); Vp = -4; Vgsq = -2.2; Idq = 2.03*10^(-3); Rd = 3.6*10^(3); Rs = 1.1*10^(3); Vi = 40*10^(-3); gmo = 2*Idss/abs(Vp); gm = gmo*(1-(Vgsq/Vp)); rd = 1/yos; Zi = Rs*((rd+Rd)/(1+gm*rd))/(Rs+((rd+Rd)/(1+gm*rd))); Zi2 = Rs*gm^(-1)/(Rs+gm^(-1)); Zo = Rd*rd...
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function[x]= descente(A,b) n=size(A) i=1:n j=1:n A=A(i,j) x(1)=b(1)/A(1,1) for k=2:n s=0 for j=1:k-1 s=s+A(k,j)*x(j) end x(k)=(b(k)-s)/A(k,k) end endfunction
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// HW_7 Problem 1 // clear and close everything!!! clear; clc; close; close; close; close; // Independent Parameters ------------------------------------------------ gamma_a = 1.4; gamma_e = 1.3; R = 287; // (j/(kg*K)) M = 1.8; P_a = 12112; // (Pa) T_a = 216.650; // (K) T_m...
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disp('To find:number of mathematics students taking atleast one of the languages French(F),German(G) and Russian(R)') F=65; //number of students studying French G=45; // number of students studying German R=42; //number of students studying Russian FandG=20; //number of students studying French and German FandR...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 45 disp("CHAPTER 2"); disp("EXAMPLE 45"); //VARIABLE INITIALIZATION L=1.405; //inductance in Henry r=40; //resistance in Ohms C=20/(10^6); //capacitance in Farad v=100; ...
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clc clear //Initialization of variables d=8 //in V=3.65 //ft/s u1=4.75 //ft/s r0=4 //in //calculations f=0.0449 Q=V*%pi/4 *(d/12)^2 Vs=(u1-V)/3.75 r0e=10^((u1/Vs - 8.5)/5.75) e=r0/r0e //results printf("Flow rate = %.2f ft^3/s",Q) printf("\n roughness factor = %.3f in",e)
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//Variable declaration N=1.6*10**20; //number of molecules(/m**3) T=300; //temperature(K) E=5*10**5; //electric field(V/m) x=0.25*10**-9; //separation(m) Kb=1.381*10**-23; //boltzmann constant e=1.6*10**-19; //Calculation Pd=N*e**2*x**2*E/(3*Kb*T); //orientational polarization //Re...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>3D Tet Kovasnay solution using DG SVV Kerneal and dealiasing</description> <executable>IncNavierStokesSolver</executable> <parameters>Tet_Kovasnay_SVV_DGKer.xml</parameters> <files> <file description="Session File">Tet_Kovasnay_SVV_DGKer...
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// Scilab code Exa3.7: : Page 125(2011) clc; clear; Z = 82; // Atomic number E = 1; // Energy of the beta paricle, MeV I_l = 800; // Ionisation loss, MeV R = Z*E/I_l; // Ratio of radiation loss to ionisation loss E_1 = I_l/Z; // Energy of the beta particle when radiation radiation loss is equal to ...
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clear; clc; disp('Example 4.19'); // aim : To determine the condition of the steam after // (a) isothermal compression to half its initial volume,heat rejected // (b) hyperbolic compression to half its initial volume // Given values V1 = .3951;// initial volume,[m^3] P1 = 1.5;// initial pressure,[MN/...
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clc; //e.g 28.10 C1=0.1*10**-6; C2=1*10**-6; L=470*10**-6; C=(C1*C2)/(C1+C2) fo=1/(2*%pi*sqrt(L*C)); disp('kHZ',fo*10**-3,"fo=");
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clc //Chapter15 //Example15.1, page no 533 //Given P_A=0.5// probability of producing symbol 'A' P_B=0.25// probability of producing symbol 'B' P_C=0.25// probability of producing symbol 'C' H=P_A*log2(1/P_A)+P_B*log2(1/P_B)+P_C*log2(1/P_C)// the source entropy mprintf('The source entropy is: %f bits/symbol',H)...
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//Fluid system - By - Shiv Kumar //Chapter 2 - Impact of Jet //Example 2.6 clc clear //Given Data:- M=13.5; //Mass of plate, kg d=16; //Diameter of the Jet, mm V=20; //Velocity of the Jet, m/s L=300; //Length of Edge of plate, mm //Data Used:- ...
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// Copyright (C) INRIA 1999-2005 // // This program is free software; you can redistribute it and/or modify it // under the terms of the GNU General Public License version 2 as published // by the Free Software Foundation. // // This program is distributed in the hope that it will be useful, but // WITHOUT ANY WARRAN...
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function ldot = f(t,l) ldot = [sigma*(l(2,1)-l(1,1)); (r-l(3,1))*l(1,1)-l(2,1); l(1,1)*l(2,1)-b*l(3,1)]; endfunction /*x = l(1,1); y = l(2,1); z = l(3,1);*/ sigma = 10; r = 28; b = 2.66; t = [0:0.01:90]; t0 = 0; l0 = [0;1;1]; ls = ode(l0,t0,t,f); title('Auto correlation for lorenz attractor'...
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//mass of an element in a given compound clear; clc; printf("\t Example 3.10\n"); massCuFeS2=3.71*10^3;//given mass of CuFeS2, kg CuFeS2=183.5;//mol. mass of CuFeS2, g Cu=63.55;//mol. mass of Cu, g percentCu=Cu/CuFeS2*100;//percent Cu in CuFeS2 massCu=percentCu*massCuFeS2/100;//mass of Cu in given CuFeS2,...
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//Example 14.10 //Spline Integration Method //Page no. 478 clc;close;clear; deff('y=f(x)','y=sind(%pi*x)') deff('y=f1(x,h)','y=(f(x+h)-f(x))/h') h=0.01; n=2;h=0.5;a=0;b=1; disp(integrate('f(x)','x',0,1),'I = ')
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clc //initialisation of variables clear v= 1 //lit p= 1 //atm h= 76 //cm d= 13.595 //kg/cm^3 g= 980.66 //dunes cm^-2 j= 4.18 //joules //CALCULATIONS W= v*p W1= h*d*g W2= W1*10^-4 W3= W2/j //RESULTS printf ('Work done in lit-atm = %.f lit-atm',W) printf ('\n Work done in dynes = %.2e dynes cm^-2',W1) pr...
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clear; clc; disp("--------------Example 10.16---------------"); x=poly(0,"x"); // a) x+1 g=x^1+1; t=0; // compute t while(%T) q=(x^t+1)/g; if(q == 1) break; end t=t+1; end printf("a. t = %d . This is a very poor choice for a generator. Any two errors next to each other cannot be d...