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function [q]=getMove(x, throw, str, player) q = x + throw; if (player = 1) then printGraph(q, p0, c, s_player, s_ai, c_player); else printGraph(q, c0, p, s_ai, s_player, c_ai); end sf_snake = %f; sf_ladder = %f; while (sf_snake = %f) and (sf_ladder = %f) for i = 1:sizesnake ...
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clc d = 150 // diameter in mm h = 10 // thickness in mm R = d/2 // radius in mm mu = 0.2 // coefficient of friction sigma_0 = 200 // N/mm^2 Rs = R - (h/(2*mu))*log(1/(sqrt(3)*mu)) // sticking radius in mm Ps = sigma_0*exp(2*mu*(R-Rs)/h) // pressure at sticking radius in N/mm^2 function y=f(r) y=2*%pi*r*sig...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Adjoint stability (Arpack): Channel</description> <executable>IncNavierStokesSolver</executable> <parameters>ChanStability_adj_Ar.xml</parameters> <files> <file description="Session File">ChanStability_adj_Ar.xml</file> <file descriptio...
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clear // //values are obtained from the graph i=10 //10t A for 0 to 1 second d=10 //where di/dt is 10 L=2 // at one second v=L*d printf("\n v= %0.1f v",v) //for 1 to 5 seconds d=-5 //at t=3 seconds voltage across the inductor is v=L*d printf("\n v= %0.1f v",v)
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 7 clc; disp("CHAPTER 2"); disp("EXAMPLE 7"); //VARIABLE INITIALIZATION s1=300; //apparent power in kVA pf1=0.65; //power factor(lagging) pf2=0.85; //power factor(lagging) //SO...
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//Section-9,Example-3,Page no.-E.13 //To calculate E0 cell for the given cell. clc; E0_cathode=0.77 E0_anode=0.76 E0=E0_anode+E0_cathode disp(E0,'Emf of the cell')
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clc d = 1 // Assumption l = 1 // Assumption A_ACDB = (%pi/4)*(1/3)*((1.05*d)^2)*10.5*l - (%pi/4)*(1/3)*d^2*10*l // Area of ABCD A_AEFB = (%pi/4)*(1/3)*((1.1*d)^2)*11*l - (%pi/4)*(1/3)*d^2*10*l // Area of AEFB t = 100*(A_ACDB/A_AEFB) printf("\n Example 2.1") printf("\n The straight bore thermometer reading will ...
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//(11.4)Using p–v–T data for saturated water, calculate at 100C (a) hg - hf, (b) ug - uf, (c) sg - sf. Compare with the respective steam table value. //solution //analysis //For comparison, Table A-2 gives at 100C, hgf =2257 //in kj/kg ...
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r1=0.4; r2=1; rl=2; v1=12; v2=15; i1=v1/r1; i2=v2/r2; vx=(i1+i2)/(1/r1+1/r2+1/rl); disp("the load voltage (in V) is");disp(vx);
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clc,clear printf('Example 7.16\n\n') V_L=3300 V_ph=V_L/sqrt(3) E_bph=V_ph Z_s=complex(0.5,5) //synchronous impedance theta=(%pi/180)*phasemag(Z_s) //phasemag returns angle in degrees, not radians P=8,f=50 //pole and frequency delta_mech=3 //mechanical angle in degrees by which rotor is behind delta_elec=(P/2...
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//Chapter 6, Example 6.1 clc //Initialisation w=1000 //angular frequency L=10**-3 //inudctance in henry //Calculation Xl=w*L //reactance in ohm //Results printf("Reactance, Xl = %d Ohm",Xl)
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a a c h a a r y a n a n d a n आ च ा र ् य न ं द न a a d h a d i n a a d h i r a a t आ ध ा द ि न आ ध ी र ा त a a h l a d आ ह ् ल ा द a a h u t i आ ह ु त ी a a k h r i g o l i आ ख ि र ी ग ो ल ी a a n c h a l k e p h o o l आ ँ च ल क े फ ू ल a a n k h o n a n n k h o n m e i n आ ँ ख ो ं आ ँ ख ...
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clc clear //Input data t1=100;//The temperature at steam point in degree centigrade t2=0;//The temperature at ice point in degree centigrade //Calculations T1=t1+273;//The temperature at steam point in K T2=t2+273;//The temperature at ice point in K n=(1-(T2/T1))*100;//The efficiency of the carnots engi...
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//pathname=get_absolute_file_path('4.05.sce') //filename=pathname+filesep()+'4.05-data.sci' //exec(filename) //Temperature inside the house(in K): T1=25+273.15 //Temperature outside the house(in K): T2=-1+273.15 //Heating load(in MJ/h): Q1=125 //COP: COP=1/(1-T2/T1) //Minimum power required(in MJ/h): W=Q1/C...
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clear clc s=50 v=11 x=.15 S=50 V=11 Xe=.15/4 FMVA= round(10000/Xe)/10000 Fault=FMVA * S mprintf("\n(a)fault level = %.3f pu", Fault) sga=.5*Fault sgb=800-sga xb=.15/2 X=(S/sgb)-xb x=X*(V*V/S) mprintf("\n(b)X = %.3f ohms", x)
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PowerSpectra_PAM()
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//Francis Brylle G. Sinco //MS Applied Mathematics //Math 288 //University of the Philippines - Diliman //12 March 2011 //Broyden-Fletcher-Goldfar-Shanno(BFGS) Algorithm with Line Search Algorithm using the Strong Wolfe Conditions applied to minimize the Rosenbrock Function //INITIALIZATION OF QUANTITIES k=1; M=100...
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clc //initialisation of variables G= 2.68 e= 0.52 g= 9.81 //kN/m^3 h1= 0.7 //m h2= 1 //m h3= 1.5 //m h4= 2 //m //calculations //for soil A sa= (G+e)*g/(1+e) //point a Sa= h1*g+h2*sa u= (h2+h1+h3/2)*g Es= Sa-u //point b sb= h1*g+h4*sa ub= (h4+h1+h3)*g Eb= sb-ub i= h3/2 s= i*g //results printf ('ef...
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// Scilab code Ex5.6: Pg:217 (2008) clc;clear; Lambda = 6e-05; // Wavelength of spectral line, cm n = 1; // First order principal maxima aplusb = 1/160; // Grating element where a is the width of slit and b is the width of opaque region in a grating, cm // since the grating equation is given by (a +b)*si...
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clc clear // Utilizaremos la factorización LU de Scilab para resolver el sistema A*x=b A = [0 2 3; 2 0 3; 8 16 -1] b = [7 13 -3]' [L,U,P] = lu(A) disp(P) disp(L) disp(U) // Modificamos el vector b usando la matriz de permutación c = P*b // La solución del sistema A*x=b mediante la factorización L...
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x = -10:100; t = 0:100; y = [zeros(-10:-1),t]; plot(x,y);
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clc //given data F=100000 // final amount in rs i=6 // interest rate in % n=10 // time in years P=F*(1/(1+i/100.0)**n) // initial amount printf("The initial value is Rs %.2f",P)
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clc // Intialization of variables Rw = 1/15 // Ratio of widths Q = 125 // m^3/s t = 24 // hr w = 20 //m //calculations Qm = Q*(Rw)^2.5 tm = t*(Rw)^0.5 wm = w*Rw // results printf(" the required model width is %.3f m",wm) printf(" \nthe required model flow rate is %.3f m^3/s",Qm) printf(" \nthe operating m...
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//Ex6_16 //Edge Detection Vector Space // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; close; clear; xdel(win...
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@relation @attribute 3.61646249686014 real[0.032626572772507245,15.99550170609938] @attribute 11.61879710931984 real[0.01308043209846943,15.989311852037073] @attribute red{red,green} @inputs 3.61646249686014,11.61879710931984 @outputs red @data red green red green red green red green green green green green green gre...
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.5 // Page 356 printf("Example 6.5, Page 356 \n \n"); // solution //(a) printf("(a) \n \n") // basis 50000 m^3/h of gas mix at 295.5K 100kPa v = 24.57 //m^3/kmol sp vol of gas at 295.5K and 100kPa n1 = 5000...
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clc //Intitalisation of variables clear d1= 5.9 //deg d2= 5.3 //deg //CALCULATIONS r= sind(d1)/sind(d2) vr= r^3 //RESULTS printf ('Ratio of inter planar distance = %.2f ',r) printf ('\n Ratio of volumes = %.2f ',vr)
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clc disp("the soln of eg 4.7-->Simultaneous O.D.E.") function dx_dt=fw(t,x,y); dx_dt=x+2*y, endfunction function dy_dt=fq(t,x,y); dy_dt=3*x+2*y endfunction y=4,x=6 //initial values //solving by Runge-Kutta method for t=0:.1:.2, h=.1 ...
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//Chapter 3, Problem 8 clc; R0=100; //resistance at 0◦C T=70; //tempreture in ◦C a=0.0043; //temperature coefficient of resistance at 0◦C Rt=R0*(1+(a*T)); //calculating resistance at 70◦C printf("Resistance at 70◦C = %f ohm",Rt);
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<?xml version="1.0" encoding="utf-8"?> <test> <description>desc P=10</description> <executable>AcousticSolver</executable> <parameters>APE_2DVariableC_WeakDG_MODIFIED.xml</parameters> <files> <file description="Session File">APE_2DVariableC_WeakDG_MODIFIED.xml</file> </files> <metrics> ...
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//Minimum force required //refer fig. 5.13 //Applying Lami's theorem to system of forces on block R1=20*sind(145)/sind(140) //kN R2=20*sind(75)/sind(140) //kN //Applying Lami's theorem to system of forces on wedge P=R2*sind(130)/sind(105) //kN printf("required force is P=%0.2f kN",P)
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clc; clear; close; LEinv=1; LEnor=5/3; LEnand=4/3; Cload=20;//in fF Cin=10;//in fF Pinv=1/2; Pnor=3/2; Pnand=1; path_effort=LEinv*LEnand*LEnor*Cload/Cin; disp(path_effort,'total path effort='); SE=path_effort^(1/4); disp(SE,'optimal stage effort='); delay=(4*SE)+(2*Pinv)+Pnor+Pnand; disp(delay,'normalis...
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// Example 16_10 clc;funcprot(0); // Given data m=5.00*10^-3;// kg T=20.0+273.15;// K p=101.3*10^3;// kg/(m.s^2) R=286;// m^2/(s^2.K) D=3.00*10^-3;// m g=9.81;// m/s^2 g_c=1;// The gravitational constant // Calculation W=(m*g)/g_c;// N rho=p/(R*T);// kg/m^3 V_in=((4*g_c*W)/(rho*%pi*D^2))^(1/2);// m/s pr...
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//Chapter-10,Example10_11,pg10_42 Tsh=190 P=8 f=50 fr=1.5 ML=700 s=fr/f Ns=120*f/P N=Ns*(1-s) Po=Tsh*(2*%pi*N/60) Pm=Po+ML Pc=Pm*s/(1-s) printf("rotor copper loss\n") printf("Pc=%.3f W",Pc)
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//// //Variable Declaration n = 52 //Number of cards in std . pack j = 5 //Number of cards in subset //Calculation C = factorial(n)/(factorial(j)*factorial(n-j)) //Results printf("\n Maximum Possible 5-card combinations are %8d",C)
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// ============================================================================= // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2012 - Scilab Enterprises - Alexandre HERISSE // // This file is distributed under the same license as the Scilab package. // ============================...
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//ex15.7 R4=10^3; C1=0.022*10^-6; R7=R4; C2=C1; R6=R4; R5=100*10^3; f_c=1/(2*%pi*R4*C1); //critical frequency in hertz for each integrator f0=f_c //center frequency Q=(1+(R5/R6))/3; BW=f0/Q; disp(f0,'center frequency in hertz') disp(Q,' value of Q') disp(BW,'bandwidth in hertz')
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clc; p1=1; // Pressure before compression in bar T1=350; // Temperature before compression in kelvin T3=2000; // Temperature after combustion in kelvin rp=1.3; // Pressure ratio Cp=1.005; // Specific heat at constant pressure in kJ/kg K r=1.4; // Specific heat ratio R=287; // Characteristic gas constant in J/kg ...
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s=%s ;// convert to state space TFcont=syslin ('c',20*(4*s+2)/(s^3+5*s^2+8*s+2)) SScont=tf2ss (TFcont ) [Ac ,Bc ,U, ind ]=canon( SScont( 2 ) , SScont( 3 ) ) disp(Ac,"Matrix A=") disp(Bc,"Matrix B=")
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codeblock readtextfile(ScriptDir+"\TOOLS.sci"); id=3; #break; b=Blob; if id==4 then { b.Addtorus(point(-3,0,0),vector(0,1,0),2,0.5,2); b.Addtorus(point( 0,0,0),vector(0,0,1),2,0.5,2); b.Addtorus(point( 3,0,0),vector(0,1,0),2,0.5,2); b.Addtorus(point( 6,0,0),vector(0,0,1),2,0.5,2); } if id==3 then { ...
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//Exa 11.4 clc; clear; close; //Given data : V1=11000;//Volt f=50;//Hz a=0.645;//cm^2 d=sqrt(4*a/%pi);//cm d=d/100;//m D=2.18/100;//m epsilon_r=3.5;//relative permitivity V=V1*sqrt(2)/sqrt(3);//V(assuming 3 phase system) gmax=2*V/d/log(D/d);//V/m gmax=gmax/10^5;//KV/cm disp(gmax,"Maximum electrostatic st...
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errcatch(-1,"stop");mode(2);//Example 4.16 (b) //Program to Evaluate and Compare the 8-point DFT of the given Sequence //x2[n]=1, 0<=n<=6 using DIT-FFT Algorithm. ; ; ; x2=[1,1,1,1,1,1,1,0]; //FFT Computation X2 = fft (x2 , -1); disp(X2,'X2(k) = '); exit();
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clc //Chapter 3:Network noise and intermodulation distortion //example 3.6 page no 82 //given NF=8//noise figure in dB B=2.1*10^3//bandwidth Rs=50//sourse resistance Si_dB=NF-144+log10(B)//available input power in dBm Si_W=(10^(Si_dB/10))/10^3//available input power in W Ei=sqrt(Si_W*4*Rs)//minimum detectable ...
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// Scilab Code Ex2.4 Longest wavelength of incident radiation: Pg:45 (2008) h = 6.624e-034; // Planck's constant, Js c = 3e+08; // Speed of light, m/s e = 1.6e-019; // Energy equivalent of 1 eV, joule/eV phi = 6*e; // Work function of metal, joule f0 = phi/h; // Threshold frequency for metal surf...
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// example 1: Gaussienne " ' //d = rand(1,10000,'normal'); //clf(); // 20 baton //histplot(20,d,leg='rand(1,10000,''normal'')',style=16,rect=[-3,0,3,0.5]); // example 2: Binomiale n = 6, p = 0.5 // fail 6 fois avant success et probabilite de success de 0.5 //d = grand(1000,1,"bin",6,0.5); // creer un vector de -0.5...
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function [d,p]=ecart_pente_frenet(A,B,x) //Le repère de Frenet a A pour origine et B définit l'axe x //x est une position (ou bien une pose 2D) //d= ecart latéral signé //p= pente signée du segment [AB] //PhB nov 2015 M = x(1:2); xa=A(1);ya=A(2); xb=B(1);yb=B(2); alpha=atan(...
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//------------------------------------------------ //■2013.10.09 秋山殿 // 対称化された最終SMC(極配置)+チャタリング除去 //------------------------------------------------ // ▼2自由度機械システムの定義 L=[1 0; 0 1]; //アクチュエータに加わる力を表す行列 k=10; //到達則のスカラ関数 m1=1; m2=10; //質量 k1=1.1; k2=2.2; //ばね定数 d1=1.2; d2=2.1; //減衰定数 M=[m1 0; 0 m2];...
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//example 6.10 //calculate //minimum capacity of reservior //the initial storage storage required to maintain uniform demand clc;funcprot(0); //given in=[2.83 4.25 5.66 18.4 22.64 22.64 19.81 8.49 7.1 7.1 5.66 5.66]; //inflow(x10^5) s=0; for i=1:12 s=s+in(i); end avd=s/12; ...
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plot();F=gcf(); F.type // type of handle F= Figure F.visible // on <=> the figure is visible F.visible="off";// off <=> the figure becomes invisible F.figure_id // figure number 0 F.figure_id=1; // in the graphics window, the number changes to 1 delete(F) //to delete
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clear;clc;close(); // Given martrix A=[3 0 1;2 2 2;4 2 5]; disp(A,'The given matrix is') //Initial vector u0=[1 1 1]; disp(u,'The initial vector is') v=A*u0; a=max(u0); disp(a,'First approximation to eigen value is') while abs(max(v)-a)>0.002 disp(v,'current eigen vector is') a=max(v); disp(a,'...
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* #------------ defsym cmd r #------------ * defsym arch S/370 script $(testpath)/cmd-rv-2K.subtst * defsym arch S/390 script $(testpath)/cmd-rv-4K-32.subtst * defsym arch z/Arch script $(testpath)/cmd-rv-4K-64.subtst * #------------ defsym cmd v #------------ * defsym arch S/370 script $(testpath)/cmd-rv-2K.subtst * d...
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//Example 2.5(b) clear; clc; R1=15*10^3;//From the result of Example 2.4 p=0.001;//For 1% tolerance p=t/100=1/100=0.01 emax=4*p;//imbalace factor Romin=R1/emax; printf("Ro can be anywhere in the range Ro>=%.2f Mohms",Romin*10^(-6));
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//EX12_14 Pg-12.30 clc clear m=0.5;// modulation index It=12;//antenna current when AM transmitter is 50% modulated Ic=It/sqrt(1+m^2/2);//carrier current m=0.9;//when modulation depth is increase to 0.9 It=Ic*sqrt(1+m^2/2) printf("Therefore total antenna current It=%.2f A",It)
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syms t w0 W w=-10:0.1:10; wc=2; for i=1:length(w) if w(i)>-wc & w(i)<wc then Hw(i)=1; else Hw(i)=0; end end a=gca(); plot(w,Hw); poly1=a.children.children; poly1.thickness=3; poly1.foreground=2; xtitle('x(t)','t') disp("we know y(t)=x(t) for w<wc"); Xw=ones(1,length(w))./(2+...
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clear clf clc x = [-1:0.01:6]; y = 2**(x+4)+3; z = (x**3+4*x)/x**2+5; plot(x,y,'LineWidth',3) plot(x,z,'r','LineWidth',3) xgrid title('Plot of 2**(x+4)+3 and (x**3+4*x)/(x**2+5)')
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playerJoin: - command: 'do adm_log allevents::$0:::$1::$2::$3' playerFirstJoin: - command: 'do adm_log allevents::$0:::$1::$2::$3' playerQuit: - command: 'do adm_log allevents::$0:::$1::$2::$3' serverEmpty: - command: 'do adm_log allevents::$0:::$1::$2::$3' serverNotEmpty: - command: 'do adm_log...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.17\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.17 (page no. 578) // Solution //The first step is to check Reynolds number.It will be recalled that the Reynolds number is given by (D*V*rho)/mu and is dimensionless.Therefore,we can use D, ...
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// Chapter8 // Page.No-335, Figure.No-8.25(a) // Example_8_5 // Output voltage // Given clear;clc; vin=100*10^-3; t=0:0.1:2*%pi; i=1; for t=0:0.1:2*%pi; if t<=%pi v(i)=vin*sin(t); else v(i)=0; end i=i+1; end t=0:0.1:2*%pi; plot(t,v)
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// Form the state space model (assume full state output) A = [0 1 0 0;0 -0.0014 0.1271 0;0 0 0 1;0 -0.025 19.1713 0]; B = [0;1.7777;0;3.4296]; C = [1 0 0 0 //dy1 0 0 1 0];//dy2 D=[0;0]; //inputs u and e; outputs dy1 and dy2 P = syslin("c",A, B, C, D); //The compensator weights Q=[800 0 0 0;0 0 0 0;0 0 20...
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clear // //Given //Variable declaration D1=30 //Larger diameter in mm D2=15 //Smaller diameter in mm L=350 //Length of rod in mm P=5.5*10**3 //Axial load in N dL=0.025 //Extension in mm //Calculation E=int((4*P*L)/(%pi*D1*D2*dL)) //Modulus of elasticity in N/sq.mm //Result print...
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//Caption:Determine output voltage when (a)Device is cutoff (b)Device is switched on //Ex4.10 clc; clear; close; Idf=0.25//Drain current at cutoff(in ns) rd=40//Drain resistance at switched on(in ohm) Vdd=15//Drain voltage(in volts) Rd=6.8//Drain resistance(in kilo ohm) Vo=Vdd-(Idf*Rd*10^(-6)) disp(Vo,'Output...
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//Exa:9.9 clc; clear; close; //Given: SNR=32; Actual_snr=10^(SNR/10); w1=300;//in Hz w2=3400;//in Hz w=w2-w1; c=w*log2(1+Actual_snr); printf("\n Capacity=%f bits/sec",c);
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Ex1_40_10.sce
//Ex 1.40.10 clc;clear;close; format('v',9); //Given : rho=9.6*10^-2;//ohm-m mu_n=1300;//cm^2/V-s q=1.6*10^-19;//Coulomb sigma_n=1/rho;//(ohm-m)^-1 ND=sigma_n/q/(mu_n*10^-4);//per m^3 ni=5*10^22*10^6;//per m^3 disp(ND/ni,"Ratio of donor atom to Si atom : ");
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TranspositionSet={[0,1,3,2],[1,0,2,3],[1,0,3,2],[2,3,0,1],[2,3,1,0],[3,2,1,0],[3,2,0,1]} considerNonPrimitive Expanding for base=2, level=2, reasons+features=base,transpose,primitive,same,similiar,evenexp invall,norm Refined variables=a,b,c,d [0+1a,0+1b,0+1c,0+1d]: unknown -> [1] [0,0,0,0] a²+b²-c²-d² -> solution ...
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ex4_4.sce
//ex4.4 V_CE_sat=0.2; V_BE=0.7; V_BB=3; V_CC=10; B_DC=50; R_B=10*10^3; R_C=1*10^3; I_C_sat=(V_CC-V_CE_sat)/R_C; I_B=(V_BB-V_BE)/R_B; I_C=B_DC*I_B; if I_C>I_C_sat then disp('transistor in saturation') else disp('transistor not in saturation') end
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clc,clear printf('Example 4.2\n\n') P=16*1000 //power supplied in watts V=220 //supply voltage e=0.9;k=0.57; //emissivity and radiant efficiency rho=1.09*10^-12//resistivity in ohm-metre l_by_d2 = %pi*V^2/(4*rho*P) //ratio of l and d^2 (i) T1=1170+273; T2=500+273; //temperatures ...
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//program to implement bisection method function []=bisection(r) xl=0 xu=r xm=xl+xu/2 p=poly([3.993*10^-4,0, -0.165,1],'x','coeff') p1=horner(p,xl) p2=horner(p,xu) if p1*p2<0 then xu=xm else xl=xm end xmn=(xl+xu)/2 e=abs((xmn-xm)/xmn)*100 whil...
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Ex15_30.sce
//Initilization of variables rho=490 //lb/ft^3 t=0.02 //in d=4 //in r=d/2 //in g=32.2 //ft/s^2 //Calculations W=(%pi*r^2*t*rho)/1728 //lb //Mass m=W/g //slugs //Momemt of inertia I=(1/4)*m*(r/12)^2 //slug-ft^2 //Result clc printf('the moment of inertia is %fslug-ft^2',I)
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16_9.sci
//16.9 clc; IL=11000; Eph=IL/3^0.5; printf("\nLine to neutral voltage=%.2f V",Eph) E_Each_phase=Eph; printf("\nVoltage induced in Each phase winding=%.2f V",E_Each_phase) T=(242/360)*(1/50)*1000; printf("\nTime interval=%.2f ms",T) IL_peak=(2^0.5)*IL; printf("\nPeak line voltage=%.2f V",IL_peak)
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Chapter5_Exampl4.sce
clc clear //INPUT DATA n=1.35;//for cylinders p1=1;//pressure in bar v1=1;//volume in m^3 p2=7;//pressure in bar nm=0.85;//mechanical efficiency in percentage nt=0.9;//Turbine efficiency in percentage N=300;//speed in rpm //CALCULATIONS //(a)single acting cylinder ip1=((n/(n-1))*p1*10^2*v1*(((p2/p1)^((n-1...
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function res = flowsheet_residuals(x, K_coef, cp1_coef, h_hx_coef, frac) //********************************************************************* // Data Reconciliation Benchmark Problems From Literature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv ...
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UTT.sce
//Marqueur de l'activité du programme on=1; //Blabla d'intro disp(" Ultimate Traveler''s toolbox "); disp(" V 1.0 "); disp(" "); disp(" "); disp(" Ultimate traveller''s toolbox est l''outil idéal pour tous les grands voyageurs soucieux de prépar...
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Ex11_3.sce
//Variable declaration: syms l //Wavelength (mu.m) I = 40*exp(-l**2) //Intensity of radiation (Btu/h.ft^2.mu.m) //Calculation: E = eval(integrate(I, l,0,%inf)) //Total emissive power (Btu/h.ft^2) //Result: printf("The total emissive power is : %.1f...
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Example_3_26.sce
//Example 3.26 The mean of a certain normal distribution is equal to the standard error clc; clear; n=49; disp("Mean = S.E in sample size of 25 i.e s_d=5(m)",49,"Total Sample = "); disp(1-0.9192,"Probab. of P(x<0), when n=40. Since the population is normal = P(x<0)=");
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Example5_9.sce
//Example 5.9 clc disp("The function can be implemented with a 8 to 1 multiplexer, as shown in fig. 5.22. Three variables A, B and C are applied to the select lines. The minterms to be included (1, 3, 5 and 6) are chosen by making their corresponding input lines equal to 1. Mintems 0, 2, 4 and 7 are not included by m...
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7_5.sce
clc //initialisation of variables f=0.01 l=2640 d1=0.5*16 d2=0.25 k1=0.03125 h=100//ft pi=22/7 g=32.2 //CALCULATIONS k2=(4*f*l)/(d1) k3=(4*f*l)/(d2) //results k=k1+k2+k3+0.5+1 v2=sqrt(2*g*h/k) dis=pi*d2*d2*v2*60*6.24/4 //Results printf (' Discharge= %.1f gal/min',dis)
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//**************************** sigmadelta ************************************** if (blk_name.entries(bl) =='sigma_delta') then mputl("# sigmadelta",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) sigma_str= '.subckt sigma_delta_fe in[0]=net' + string(blk(blk_objs(bl),2))+"_"+ string(ss) +" in[1]=net"+stri...
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Chapter7_Example6.sce
clc clear //Input data b1=80//Intensity levelof the sound produced by the electric generator in dB b2=70//Intensity level of the room in dB //Calculations I2=10^(b1/10)*10^-12//Intensity of the sound produced by the electric generator in W/m^2 I4=10^(b2/10)*10^-12//Intensity of the sound existing in the room i...
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mode(2);errcatch(-1,"stop");driver("GIF"); //example 4.42 //calculate mean precipitaion using thiesson polygon method clc;funcprot(0); //given a=4; //dimension of plot sides P1=4.8;P2=13;P3=8;P4=5.4;P5=3.2;P6=9.4; //precipitaion at respective stations A1=a^2/8+a^2/(4*1.73); A2=a^2/8; A3=A2;...
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// Exa 9.3 clc; clear; close; // Given data H2 = 3055;// in kj per kg H3 = 2550;// in kj per kg fie_1 = 7.15;// kj per kg k fie_2 = 7.57;// kj per kg k d_fie= fie_2 - fie_1;// in kj per kg k disp(d_fie,"Change in entropy during throttling process in kJ/kg-K is :"); dH = H2 - H3;// in kj per kg disp(dH,"Chan...
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options([abox_target(allinonefile), tbox_target(allinonefile), indexing(yes)]). options([abox_target(allinonefile), tbox_target(allinonefile), indexing(no)]). %All DB -> indexing doesn't help at all options([indexing(no)]). options([indexing(yes)]). concept('Good'). concept('Patricide'). role(hasChild). equiv(and([som...
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function [x,y,typ]=DELAYV_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then //normal position standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=ar...
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//Exa 5.7 clc; clear; close; //Given Data : format('v',7); I=180;//in Ampere cos_fir=0.8;//unitless R=0.7;//in ohm/phase X=1.2;//in ohm/phase ETA=90;//in % Pdev_BY_VR=3*I*cos_fir;//in KW Psending_BY_VR=Pdev_BY_VR/(ETA/100);//in kW Losses=3*I^2*R;//in watt VR=Losses/(Psending_BY_VR-Pdev_BY_VR);//in volt V...
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// sum 15-5 clc; clear; d=200; r=d/2; N=300; P=5000; D=500; R=D/2; u=0.3; E=205*10^3; G=84*10^3; Ta=60; Kb=1.5; Kt=2; w=2*%pi*N/60; beta1=20*%pi/180; V=r*w; v=R*w; // Let T1-T2 =T T=P/V; x=u*%pi/sin(beta1); T2=T/((exp(x)-1)); T1=T2*exp(x); t=P/v; y=u*%pi; T3=t/((exp(x)-1)); T4=T3*exp(x); T=P...
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//Ex:2.34 clc; clear; close; // For a closed surface, a sphere of radius r is choosen. To find the total radiated power, the radiated component of the power density is integrated over its surface. therefore, // Wt=double integration of (ar.Ao.(sin(x)/r^2))*(ar.r^2.sin(x)) with limits from 0 to 2*pi and from 0 to p...
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@0 op jmp 3 0 @1 op sav 1 0 @2 jmp to 4 0 @4 reg win 1 0 @5 jmp ret 0 1 @5 jmp to 3 0 @3 jmp die 0 0
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//Calculating equivalent impedence referred to primary //Chapter 3 //Example 3.12 //page 216 clear; clc; disp("Example 3.11") f=50; //frequency in hertz r=6; //turns ratio R1=0.90; //primary resistance in ohms R2=0.03; //secondary resistance in ohms X1=...
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clc; warning("off"); printf("\n\n example12.2 - pg562"); p=1.2047*0.06243; //[lb/ft^3] mu=(18.17*10^-6)*(0.6720); //[lb/ft*sec] v=mu/p; x=2; //[ft] U=6; //[ft/sec] Nre=(x*U)/v; disp("The Reynolds number is well within the laminar region",Nre,"Nre="); del=5*x*(Nre)^(-1/2); C1=0.33206; Cd=2*C1*(Nre)^(-1/2...
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exec(INTER_SYS_DIR+'/bin/gl_draw_phy.sci'); exec(INTER_SYS_DIR+'/bin/gl_retrieve_exportlig.sci');
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//pagenumber 287 example 4 clear ib=20*10^-6;//ampere beta1=500; re=10;//ohm correction in the book r1=4.7*10^2;//ohm correction in the book ic=ib*beta1; voltag=ic*r1;//voltage drop at 4.7*10^3ohm vc=(10-voltag); rb=(vc-0.6)/ib; disp("rb = "+string((rb))+"ohm"); //re included voltag=ic*re;//voltage drop...
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Name=FN AK Highground PlayerCharacters=A_air_pistol_frozen BotCharacters=target.bot;target.bot;target.bot;target.bot;target.bot IsChallenge=true Timelimit=30.0 PlayerProfile=A_air_pistol_frozen AddedBots=target.bot;target.bot;target.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=square_1wall...
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clc // Given that E = 3 // kinetic energy of proton in Mev m1 = 1.007276 // mass of H(1) in a.m.u. m2 = 3.016056 // mass of H(3) in a.m.u. m3 = 1.008665 // mass of neutron in a.m.u. m4 = 3.016036 // mass of He(3) in a.m.u. // Sample Problem 22 on page no. 12.39 printf("\n # PROBLEM 22 # \n") printf("Standard law used ...
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//Chapter 6, Example 6.9, page 245 clc //Initialisation d=5 //in dB h=20 //Transmitter initial height //Calculation ht=h*10**(0.25) //Transmitter ultimate antenna height //Results printf("(1) Antenna Heigh...
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//Example 2 // intensity clc; clear; close; I=1;//assume a1=1*I;// a2=4*I;// ph1=0;//degree i1=(a1+a2)+a2*cosd(ph1);// disp("intensity where phase difference is zero is "+string(i1)+"*I") ph2=90;//degree i2=(a1+a2)+a2*cosd(ph2);// disp("intensity where phase difference is pi/2 is "+string(i2)+"*I") ph3=180;//degree i3...
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clc; pathname=get_absolute_file_path('6_3_soln.sce') filename=pathname+filesep()+'6_3_data.sci' exec(filename) // Solution: // Inclination of Weight, theta=(theta*%pi)/180; //rad // Cylinder Force, F=W*sin(theta); //lb // Results: printf("\n Results: ") printf("\n The Cylinder Force at constant velocity is %.0f ...
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load OddCounter.hdl, output-file OddCounter.out, compare-to OddCounter.cmp, output-list time%S1.4.1 reset%D1.3.1 out%B1.16.1; set reset 0, tick,output, tock,output; tick,output, tock,output; tick,output, tock,output; tick,output, tock,output; set reset 1, tick,output, tock,output; tick,output, tock,output; set r...
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//Example 6_2 clc;clear; // Given values m=14;//Water flow rate in kg/s rho=1000;//The density of water in kg/m^3 A_1=0.0113;// The cross sectional area of the elbow at inlet in m^2 A_2=7*10^-4;// The cross sectional area of the elbow at outlet in m^2 z_2=0.3;// m z_1=0;// m g=9.81;// The acceleration due to g...
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clc clear //Input data t=6;//Time taken for a liquid to cool from 80 to 60 degree centigrade in minutes T=10;//To find the temperature after the time in minutes t11=80;//The initial temperature of the liquid in degree centigrade t12=60;//The final temperature of the liquid in degree centigrade ts=30;//The t...
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//Exam:3.29 clc; clear; close; n_1=1;//1st order reflection index angle_1=10;//1st order reflection angle n_3=3;//3rd order reflection index //sind(angle_1)/sind(angle_3)=n_1/n_3 angle_3=asind(n_3*sind(angle_1)/n_1);// disp(angle_3,'3rd order reflection angle=')