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clear clc //to find magnitude and direction of vector indicating location of car // GIVEN:: //distance travelled due east on a level of road //s is represented as ax+by.since b has no x component and a has no y componebt we can write Sx = 32// in km //distance travelled before stopping after taking turn ...
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//Variable declaration chi=0.5*10**-5; //magnetic susceptibility H=10**6; //field strength(ampere/m) mew0=4*%pi*10**-7; //Calculation I=chi*H; //intensity of magnetisation(ampere/m) B=mew0*(I+H); //flux density in material(weber/m**2) //Result printf('intensity of magnetisation is %0.3f ampe...
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EXAMPLE6_9.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 6 //NOISE clear all; clc; printf("EXAMPLE 6.9(PAGENO 302)"); //given R_eq = 2518//equivalent resistance in ohms R_t = 600//input impedence in ohms R_a= 50//output impedencre in ohms //calculations R_eq1 = R_eq - R_t; F = 1 + (R_eq1/R_a)...
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//Chapter 5, Problem 13 clc n1=16 //no of turns on primary n2=8 //no of turns on secondary zs=16 //terminating resistance //calculation of effective resistance zp=zs*(n1/n2)^2 printf("Effective resistance at the primary = %d ohm",zp)...
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clc clear //Initalization of variables J=778 o2=12.5 theo=0.95 N=56.5 R0=1545 T=540 //R p=14 //psia LHV=2368089 //Btu/lb ther=39.4 iep=0.78 ve=0.8 //calculations Ar=o2/0.21 *theo vol=N*R0*T/(144*p) hv=(LHV -17730)/LHV ithep=iep*ther pd=ithep/100 *ve *100.5 mep=J*pd //results printf("Indicated mep ...
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clear; clc; E_ll=110; U=12; V_o=(3*sqrt(2)*E_ll)/%pi; X=0; V_d1=(V_o*(cosd(X)+cosd(U+X)))/2; printf("\nthe dc output voltage when (X=0) = %.3f kV",V_d1); X1=25; V_d2=(V_o*(cosd(X1)+cosd(U+X1)))/2; printf("\nthe dc output voltage when (X1=25) = %.3f kV",V_d2); X2=90; V_d3=(V_o*(cosd(X2)+cosd(U+X2)))/2; prin...
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//Problem 6.06: //initializing the variables: n = 5; // in lbmol T1 = 100; // in degrees F P1 = 1; // in atm T2 = 400; // in degrees F P2 = 10; // in atm Cpg = 5; // Btu/lb.degF R = 1.987; //calculation: T1 = T1 + 460 T2 = T2 + 460 dS = n*R*log(P1/P2) + n*Cpg*log(T2/T1) printf("\n\nResult\n\n") prin...
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// Exa 9.9 clc; clear; close; format('v',7) // Given data Rating = 250*10^3;// in VA Pi = 1.8;// in kW Pi = Pi * 10^3;// in W Pcu_f1 = 2000;// in W phi= acosd(0.8);// in ° Eta = ((Rating*cosd(phi))/((Rating*cosd(phi))+Pi+Pcu_f1))*100;// %Eta in % disp(Eta,"The efficiency at full load in % is"); // The maxi...
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//Example number 4.10, Page number 70 clc;clear; close; //Variable declaration n=1; //order h=1; k=1; l=1; e=1.6*10**-19; //charge(c) V=5000; //voltage(V) m=9.1*10**-31; //mass(kg) H=6.625*10**-34; //plank constant d=0.204*10**-9; //interplanar spacing(m) //Calculation lamda=H/sqrt(2*m*e*V); //wave...
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clear clc disp('Exa-2.8'); w1=600;w2=434; // w1=recorded wavelength;w2=actual wavelength // c/w1 = c/w2 *(sqrt(1-u/c)/(1+u/c)) k=w2/w1; x=(1-k^2)/(1+k^2); //solving for u/c printf('The speed of galaxy wrt earth is %.2f c',x);
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clc clear //input p=4;//number of poles n=48;//number of slots b=0.02;//fulx per pole in weber w=50*(%pi);//angular velocity in rad/sec //calcultions f=(w*(p/2))/(2*%pi);//frequency in hertz phim=360/n;//mechanical angle in degrees phie=phim*(p/2);//electrical angle in degrees phiE=phie*(%pi/180);//elec...
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//finding magnitude and nature of forces //refer fig. 4.14(a) //considering equilibrium if entire truss //taking moment about L0 R2=(200*6+200*12+150*18+100*24+100*30)/36 //kN R1=200+200+150+100+100-R2 //kN //consider equilibrium of right hand side of section (1)-(1) theta1=atand(1/6) //degree theta2=atand(6...
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function sp=g_round(a) // Copyright INRIA [ij,v,mn]=spget(a) sp=sparse(ij,round(v),mn)
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function count = mtlb_fprintf(varargin) [lhs,rhs]=argn() count=0 if type(varargin(1))==10 then //mtlb_fprintf(fmt,...) fmt=varargin(1) nfmt=size(strindex(fmt,'%'),'*') nv=size(varargin)-1 if nv==1 then a=varargin(2) na=size(a,'*') mult=max(na/nfmt,1) fmt=strcat(fmt(ones(1,mult))) // duplicate fo...
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//example 5.7 clc; funcprot(0); // Initialization of Variable Vi=350;//voltage f=100;//frequency Rf=10000;//resistance Ri=520; //calculation Vp=(1+(Rf/Ri))*Vi*2^.5; disp(Vp/1000,"load voltage in V:") clear()
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a b (1,1) (2,2) (1,3) (2,1) (3,3) (2,3)
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//Part A Chapter 7 Example 14 clc; clear; close; rcv=71.5;//cm of Hg(Recorded condenser vaccum) br=76.8;//cm of Hg(Barometer reading) Tc=35;//degree C(Temperature of condensation) Tw=27.6;//degree C(Temperature of hot well) mc=1930;//kg(Mass of condensate/hour) mw=62000;//kg(Mass of cooling water/hour) T1=8.5...
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//Ex:65 clc; clear; close; r=42164;// in km d_m=500;// in km i=d_m/r;// the angle of inclination in rad printf("The angle of inclination=%f rad",i); printf("\n The angle of inclination=%f degree",i*(180/3.14));
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//Example 4.20: clc; clear; close; //given data : format('v',5) A=50;//gain without feedback Af=25;//gain with feedback Beta=(((A/Af)-1)/A);//feed back ratio Ad=40;//new gain after ageing Af1=(Ad/(1+(Beta*Ad)));//new gain with feedback df=Af-Af1;// reduction in gain pdf= (df/Af)*100;//percentage reduction in gain disp...
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// no i/p args are passed to the function y=polyscale(); disp(y); //output // !--error 4 //Undefined variable: a //at line 25 of function polyscale called by : //y=polyscale();
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//pathname=get_absolute_file_path('11.03.sce') //filename=pathname+filesep()+'11.03-data.sci' //exec(filename) //Height of chimney(in m): H=20 //Temperature of burnt gases(in K): Tg=380+273 //Ambient air temperature(in K): Ta=27+273 //Air supplied(in kg air per fuel): m=2*Ta/(Tg-2*Ta) printf("\n RESULT \n") ...
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//Calculate frequency of oscillations clear; clc; //soltion //given L=55*10^-6;//H C=300*10^-12;//F fo=1/(2*%pi*sqrt(L*C)); printf("The frequency of oscillations= %.0f kHz\n",fo/1000);
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//Chapter-4, Example 4.11, Page 137 //============================================================================= clc clear //INPUT DATA I1=5;//current in A I=10;//current in A I2=I/sqrt(2); //CALCULATIONS i3=sqrt(((2*I1)^2)+(I2^2)); mprintf("rms value of current is %1.2f A respectively\n",i3); //=========...
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Expanding for base=3, level=3, reasons+features=base,same,similiar,evenexp norm,showfail Refined variables=k,x,y [0+1k,0+1x,0+1y]: unknown -> [1] [0,0,0] 3k-x²-3y²-1 ---------------- level 0 expanding queue[0]^-1,meter=[1,3,1]: 3k-x²-3y²-1 [0+1k,0+3x,0+1y]: failure constant=-1, vgcd=3 [0,0,0] 3k-9x²-3y²-1 [0+1k,1+3x,0+...
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function C=seriesC(C1,C2) C=C1*C2/(C1+C2) endfunction V=100 Cp=1+2 Ceq=seriesC(Cp,6) q=Ceq*V q1=q*(1/(1+2)) q2=q-q1 disp(q2,q1,q) E6=q*q/2/6/1000 E1=q1*q1/2/1/1000 E2=q2*q2/2/2/1000 Enet=E1+E2+E6 disp(Enet,E6,E2,E1)
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// Case Study:-Chapter 6 // 3.Minimum Cost for p=0:0.1:10 cost=48-8*p+p^2; if(p==0) , cost1=cost; continue; //Use of continue statement end if(cost>=cost1) , break; //Use of break statement end cost1=cost; ...
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function []=tdinit() // Copyright INRIA tit=["bioreactor model (bioreact)"; "competition model (compet)"; "system with limit cycle (cycllim)"; "linear system (linear)"; "quadratic model (linper)"; "linear system with a feedback (lincom)"; "prey predator model (p_p)"] ii=x_choose(tit," Systems Initialisation ");...
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//Ex:2.10 clc; clear; close; n1=1.50;// core refractive index n2=(99/100)*1.50;// cladding refractive index x_c=(asin(n2/n1))*180/%pi;// critical angle in degree n_m=sqrt(n1^2-n2^2);// numerical aperture printf("critical angle = %f degree",x_c); printf("\n numerical aperture = %f",n_m);
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clear; clc; // Example: 1.7 // Page: 9 // Solution printf("Example: 1.7 - Page: 9\n\n"); //*****Data*****// P = 560*10^3;// [Pa] Vinit = 3;// [cubic m] Vfinal = 5;// [cubic m] Wext = 210*10^3;// [J] //*************// W = P*(Vfinal - Vinit);// [J] // Again the system receives 210 kJ of work from t...
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//**************************** Join ******************************** if(blk_name.entries(bl)=='join') then for ss= 1:scs_m.objs(blk_objs(bl)).model.rpar(1) spl_fix=[spl_fix;'net'+ string(blk(blk_objs(bl),ss+1+numofip))+"_",'net'+string(blk(blk_objs(bl),2))+"_"] spl_fix=[spl_fix;'out:net'+ string(b...
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clc clear //Initialization of variables N2=78.1 //Moles of Nitrogen M=29 //Molar mass of Air ba=2.12 //Basis x4=0.3 //Moles of Ch4 x5=3.7 //Moles of H2 x6=14.7 //moles of H2o //calculations O2=N2/3.76 c=14.7 b= x4*4 + x5*2 + x6*2 a=b/ba AF=(O2+N2)*M/(a*12 + b) //results printf("Air fuel ratio = %.1f lbm...
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boardsize 4 play w a1 play b b1 play w a2 play b b2 play w a3 play b b3 1 havannah_winner #? [none] play w a4 2 havannah_winner #? [white]
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//To use these functions make sure the location of the IOME iogs application //is on the path //Linux export IOME_HOME=PATHTOIOME //Linux export PATH=$PATH":$IOME_HOME/bin" //Windows set IOME_HOME=PATHTOIOME //Windows set PATH=%PATH%;$IOME_HOME/bin function [vec]=stringtovec(stringvar, vsize, separator) vec=...
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//(Welded and Riveted Joints) Example 8.17 //Plate thickness d (mm) d = 25 //Reversed axial load acting on the plates P (kN) P = 100 //Throat of the weld t (mm) t = 25 //Ultimate tensile strength of the weld material Sut (N/mm2) Sut = 450 //Factor of safety fs fs = 2 reliability = 90 //Operation //No...
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clc // Given that A = 150*6 // Cross-section of strips in mm^2 w = 150 // Width of the strip in mm ti = 6 // Thickness in mm pA = 0.20 // Reduction in area d = 400 // Diameter of steel rolls in mm Ys = 0.35// Shear Yield stress of the material before rolling in KN/mm^2 Ys_ = 0.4// Shear Yield stress of the material af...
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//Problem 33.10: For the circuit shown in Figure 33.52 determine the current flowing in the inductive branch by using Norton’s theorem. //initializing the variables: V1 = 20; // in volts V2 = 10; // in volts R1 = 2; // in ohm R2 = 1.5; // in ohm R3 = %i*2.95; // in ohm R4 = 3; // in ohm //calculation: //Th...
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//Chapter-7, Example 7.2, Page 275 //============================================================================= clc clear //INPUT DATA Ta=20;//Temperature of air in degree C Tp=134;//Temperature of heated plate in degree C v=3;//Velocity of flow in m/s L=2;//Length of plate in m W=1.5;//Width of plate in ...
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clc //Initialization of variables R=1.986 //B/mol R t2=1100 //R t1=1000 //R //calculations wrev=R*(t2-t1) //results printf("work done = %.1f Btu/mol",wrev)
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//Example 27_1 clc(); clear; //What fraction of atomic mass of Uranium is due to its electrons n=92 //Units in constant mass=0.000549 //Units in u tmass=235 //units in u per=(n*mass)/tmass //Units in fractions printf("The fraction of atomic mass of Uranium is due to its electrons is=%.6f",per...
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Ex9_2.sce
// Example 9_2 clc;funcprot(0); // Given data m=20;// The mass flow rate of air in kg/min P_4=1600;// kPa T_1=20+273;// K P_1=100;// kPa n=0.90;// The efficiency of the compressor c_p=1.00;// kJ/kg.K k=1.4;// The specific heat ratio // Calculation P_2=sqrt(P_1*P_4);// kPa T_3=T_1;// K T_2a=T_1*(P_2/P_1)^...
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Phi_q.1_linux.sce
clear; lines(0); np=100; q=3; //rang=190/300 for w=list(210,220,240,260,280,300) msig = 1 // номер строки, отвечающая нужной нам плотности прививки, с которой мы будем считывать msig1 =2 msig2 =3 msig3 =4 msig4 =5 msig5 =6 msig6 =7 msig7 =8 msig8 =9 msig9 =10 msig10 =11 msig11 =12 msig12 =13 msig13...
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mult.sce
//**************************** MULT ************************************ if (blk_name.entries(bl) =='mult') then mputl("# MULT",fd_w); mputl(".subckt mult in[0]=net"+string(blk(blk_objs(bl),2))+'_'+ string(1)+ " in[1]=net"+string(blk(blk_objs(bl),3))+'_'+ string(1)+ " in[2]=net"+string(blk(blk_objs(bl),4))+'_'+...
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//Exa 3.8 clc; clear; close; format('v',6); //Given Data : Wdot=200;//W t1=40;//degree centigrade //Q2dot=20*(t1-t2);//W //COP=Q2dot/W2dot=T2/(T1-T2) //(t1-t2)/(W2dot/20)=(t1+273)/(t1-t2) //20*t1^2+20*t2^2-20*2*t1*t2-t1*Wdot-273*Wdot //(t2+273)/(t1-t2)=(t1-t2)/(Wdot/20) //t2^2-(2*t1+(Wdot/20))*t2-273*(Wd...
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10_23.sce
clear; clc; //Example - 10.23 //Page number - 366 printf("Example - 10.23 and Page number - 366\n\n"); //Given T = 320 + 273.15;//[K] R = 8.314;//[J/mol*K] - Universal gas constant // For water Tc = 647.1;//[K] Pc = 220.55;//[bar] Pc = Pc*10^(5);//[Pa] // The cubic form of Redlich Kwong equation of ...
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clear //Given l=1.001 A=1.001 //Calculation R=l*A R1=R-1 A=R1*100 //Result printf("\n Percentage change in its resistance is %0.1f percentage",A)
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//f=x^y^z+wxz+xy+v^w^yz^ clc; n=4; k=[0 0 0 0; 1 0 1 1; 0 1 1 0; 1 1 1 0]; k(:,:,2)=[0 0 0 0; 1 0 1 1; 0 1 1 0; 0 1 1 0]; //k=[1 0 0 0; // 0 0 0 0; // 0 0 0 0; // 0 0 1 0]; //k(:,:,2)=[1 0 0 0; // 0 0 0 0; // 0 0 0 0; // 1 0 0 0];...
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2011-01-23T20:52:18
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rom-load SimpleStaticTest.asm, output-file SimpleStaticTest.out, compare-to SimpleStaticTest.cmp, output-list RAM[256]%D1.6.1; set RAM[0] 256, repeat 200 { ticktock; } output;
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7_11.sce
//ill conditioned linear system //example 7.11 //page 277 clc;clear;close; A=[25 24 10;66 78 37;92 -73 -80]; de_A=det(A); for i=1:3 s=0; for j=1:3 s=s+A(i,j)^2 end s=sqrt(s); k=de_A/s; end if k<1 then printf(' the fuction is ill conditioned') end
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fiin.sce
// this is 8 vehicle clc clear rokl=1 x=4 z=15 pop=10 iter=1000 mest=1000*ones(1,pop) a=zeros(pop,z) rag=zeros(iter) ryg=zeros(iter) cap=[288 95 115 133 107 22 34 28 186 190 33 56 100 90 82 143 68 166 44 73 72 60 68 8 20 ] tim=[0 40 1.5 39 6.8 11 16 12 36 20 27 17 51 4.5 17; 40 0 42 9.1 43 38 33 39 51 41 48 45 21 34 3...
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clc clear //Input data D1=15 //Entry diameter in cm D2=30 //Exit diamater in cm P1=0.96 //Inlet pressure in bar T1=340 //Inlet temperature in K C1=185 //INlet velocity in m/s k=1.4 //Adiabatic Constant R=287 //Specific gas constant in J/kg-K //Calculation A1=%pi*D1^2/4 //Entry area in cm^2 A2=%pi*D2^2/...
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Ex9_8.sce
// Example 9_8 clc;funcprot(0); // Given data r=10;// The compression ratio P_1=200;// kPa T_1=100+273;// K T_3=600+273;// K R=0.287;// kJ/kg.K k=1.4;// The specific heat ratio // Calculation v_1=(R*T_1)/P_1;// m^3/kg T_4=T_3;// K v_4=(T_4/T_1)*v_1;// m^3/kg v_2=v_4/r;// m^3/kg T_2=T_1;// K P_2=(R*T_2)...
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clc; //e.g 22.6 IDSS=10*10**-3; VDD=20; IDQ=IDSS/2; disp('mA',IDQ*10**3,"ID="); VDSQ=VDD/2; disp('V',VDSQ*1,"VDS="); VGS=-2.2; RD=(VDD-VDSQ)/IDQ; disp('Kohm',RD*10**-3,"RD="); RS=-VGS/IDQ; disp('ohm',RS*1,"RS=");
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clc; //ex2.2 VD1=0; //Volt//diode is forward bias for ideal diode total Rideal=0 so VD1=IT*Rideal=0V R1=1000; //kilo ohm; VS=5; //Volt //voltage across voltage source IT=(VS/R1)-(VD1/R1);//Ampere;apply kvl in the circuit VR1=IT*R1; //Volt//apply ohms law voltage across resistance disp( 'Volt',VD1*1,"VD1="); dis...
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builder_gateway_c.sce
// ==================================================================== // Allan CORNET // Simon LIPP // INRIA 2008 // This file is released into the public domain // ==================================================================== //if MSDOS then // to manage long pathname // includes_src_c = '-I""' + get_abso...
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particula.sce
// Derivadas na prática: simulação de fenômeno descrito por equação dif. // Autor: Josenalde Oliveira - Matemática Aplicada II // A velocidade do corpo no tempo é associada à taxa de variação do espaço // percorrido em função do tempo, ou seja, v(t) = ds/dt // Problema: tem-se disponível a relação desta taxa de varia...
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zpv.tst
zaka=zĭ săka=zĭ V;POT zaka=zĭ rzaka=zĭ V;HAB zaka=zĭ guzaka=zĭ V;PFV u+tooˀ gútooˀ V;POT u+tooˀ batooˀ V;PFV u+tooˀ rutooˀ V;HAB asa guasa V;PFV asa rasa V;HAB asa gâsa V;POT u+zûˀu=zhibi bazûˀu=zhibi V;PFV u+zûˀu=zhibi gúzûˀu=zhibi V;POT u+zûˀu=zhibi ruzûˀu=zhibi V;HAB u+s+ialda basialda V;PFV u+s+ialda gúsialda V;POT...
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sci
Ex10_2.sci
clear all; t=-%inf:%inf; w=2*%pi*%i K=4 k=0:0.004:4; sigma=0 Wmax=w.*k./K; function x=f(t); x=sign(t).*exp(-sigma.*abs(t)).*exp(-%i.*w.*t) endfunction Y=intg(-10,10,f) // for the CTFS of x(t)=u(t) f=1 // Analog frequency f=1 Hz U=(1/%i*2*%pi*f)+(1/2).*[ones(1,1)] disp(Y,'The CTFS of sgn(t)=')...
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ex_24_13.sce
//find.. clc //solution //given P=30000//W N=750//rpm a=(%pi/180)*12.5 pn=0.1//N/mm62 Kl=1.75 t=42//N/mm^2 //D=6*b T=60*P/(2*%pi*N)*Kl*1000//N-mm //d=(T*16/(%pi*t))^(1/3)//mm printf("dia of shaft is,%f mm\n",(T*16/(%pi*t))^(1/3)) printf("dia of shaft is say,50 mm\n") d=50//mm //T=2*%pi*u*pn*R^2*b //b=R...
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clear; clc; //page no. 83 v = 5;// fps a_t = 0; a_r = v^2 /2;// ft/sec^2 printf('Radial component of acceleration = %.1f ft/sec^2\n Tangential component of acceleration = %d ',a_r,a_t);
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// NR.sci is a scilab file to perform linearization of nonlinear element using Newton-Raphson method. It is developed for a scilab based circuit simulator. It is written by Yogesh Dilip Save (yogessave@gmail.com). // Copyright (C) 2012 Yogesh Dilip Save // This program is free software; you can redistribute it and/or...
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clear; clc; uts=5758; //ultimate tensile strength l=200; wt=.604; h=uts/2; sag=wt*l*l/(8*h); printf("The sag is:%.3f m",sag);
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clc clear //input vht=100;//higher threshold voltage in volts rl1=5;//resistance of load in kiloohms rl2=10;//load resistance in kiloohms //calculations //for rl1 //when va=0 ia1=vht/rl1;//anode current in milliamperes //when va=100 ia2=0;//since va=vht //for rl2 //when va=0 ia3=vht/rl2;//anode curren...
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xdel(winsid());//fechar janelas de figuras clear();//limpar memória clc();//limpar console t0 = 0; delta_t = 0.001; final_time = 20; t = (0:delta_t:final_time); t = t' ifinal=size(t);ifinal=ifinal(1); F = 10*ones(ifinal, 1); m = 40; b = 10; k = 100; s = poly(0, 's'); g = syslin('c', 1/m/(s^2 +b*s/m+ k/m)) y = csim(F',...
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// Example 12.2 Vl=415; // Supply Voltage Vph=Vl/sqrt(3); // Phase Voltage p1=10000; // Load of 10-kW p2=8000; // Load of 8-kW p3=5000; // Load of 5-kW IR=p1/Vph; //Current by ( 10-kW Load ) disp(' Current by ( 10-kW Load ) = '+str...
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//Example 8.19.1 //Use fourier transform to determine the response of the following signal clc; clear all; n=-10:10 for i=1:length(n) if n(i)>=1 then x(i)=(3/4)^n(i); h(i)=(1/2)^n(i); else x(i)=0; h(i)=0; end end subplot(3,2,1) plot(x,n); xtitle('(a)x(n)'); ...
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// Example 3.8 clear; clc; close; format('v',6); // Given data m=4;//phases Beta=1.5;//in degree //Calculations //Formula : Beta=360/m/Nr Nr=360/m/Beta;//no. of rotor teeth disp(Nr,"No. of rotor teeth ; "); Ns=Nr;//no. of stator teeth disp(Ns,"In multi stack motor, Stator teeth = rotor teeth = ");
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//ANSWER GIVEN IN THE BOOK FOR THIS QUESTION IS INCORRECT. clc; //Neglecting armature reaction & magnetic saturation //Assuming rotational losses to remain constant V=230;//Supply voltage P=15000;//power rating of dc series motor in watts Il_1=80;//line current rated Il_2=40;//line current assuming that motor ...
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//332 clear; close; clc; A=[-1 2 2]'; disp(A,'A='); [U diagnol V]=svd(A); disp(U,'U='); disp(diagnol,'diagnol='); disp(V','V''='); disp(U*diagnol*V','A=U*diagnol*V''') //end
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//Example 13.6// C=12.01;//amu //atomic mass of carbon //(From Appendix 1) H=1.008;//amu //atomic mass of hydrogen //(From Appendix 1) O=16.00;//amu //atomic mass of oxygen //(From Appendix 1) a=6;//Number of atoms b=2;//Number of atom mw=((a*C)+(a*H)+O)+1.5*(C+(b*H)+O)-1.5*((b*H)+O) mprintf("mw = %f g (Answer ...
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// page no 484 // example no 15.4 // INSTRUCTIONS TO GENERATE SQUARE WAVE PULSE FROM COUNTER 1 clc; printf('Control Word \n \n'); printf('D7 D6 D5 D4 D3 D2 D1 D0 \n'); printf('0 1 1 1 0 1 1 0 = 76H \n \n'); printf('D7,D6=01 Select counter 1 \n'); printf('D5,D4=11 Load 16 bit count \n...
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clear; //clc(); s3q=10*10^6; vl=10.5*1000; il=s3q/(sqrt(3)*vl); iph=il; zph=5; printf("\n Voltage drop in the line is: %.2f V",zph*iph); //b).using per unit method to soolve sb=10; vlb=11; vpu=vl/vlb; sb3q=12; spu=s3q/sb3q; ipu=spu/vpu; zpu=zph*sb3q/vlb^2; v=zpu*ipu*vlb/sqrt(3); printf("\n voltag...
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clear; //clc(); p1=500; p2=100; q1=acosd(.707); q2=acosd(0.95); lkvar=(p1*tand(q1) - (p1+p2)*tand(q2)); printf("The kVAr is:%.2f kVAr\n",lkvar); kva=sqrt(p2*p2 + lkvar*lkvar); printf("The kVA is:%.2f kVA\n",kva); pf=(p2/kva); printf("The power factor is:%.3f leading\n",pf);
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// Scilab code Ex7.8: Pg:295 (2008) clc;clear; c = 3e+08; // Velocity of light, m/s e = 1.6e-019; // Charge of an electron, coulomb B = 0.5; // Maximum magnetic field at the electron orbit, Weber per meter square D = 1.5; // Diameter of the orbit, meter R = D/2; // Radius of the orbit, meter omeg...
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//Part A Chapter 6 Example 2 clc; clear; close; T1=27+273;//K T2=100+273;//K T3=400+273;//K m=5;//kg cp=4.2;//kJ/kgK cp2=2260;//kJ/kg delta_T=100-27;//degree C Q1=m*cp*delta_T;//kJ/K delta_S1=Q1/T1//kJ/K Q2=m*cp2;//kJ/K delta_S2=Q2/T2//kJ/K R=8.314/34;//kJ/kgK //cp_steam=R*(3.5+1.2*T+0.14*T^2)*10^-3;//k...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 3") T1=(-27+273);//temperature of refrigerator in K W=3*.7457;//work input in KJ/s Q=1*3.5;//refrigeration effect in KJ/s disp("COP=T1/(T2-T1)=Q/W") ...
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// Utility function: takes operator op // op must be a function of a vector, producing a vector // and op must be linear i.e. op(a + b) = op(a) + op(b) // and op(k*a)=k*op(b) // result: matrix m representation of op // i.e op(x) = m * x // simple linear algebra: m consists of columns op(ei) // where ei is a basis vecto...
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clear; clc; // Illustration 10.10 // Page: 552 printf('Illustration 10.10 - Page: 552\n\n'); // Solution //****Data****// B = 1150;// [kg/h] //*******// // x and y are taken in weight ratio. x1_prime = 0.0101;// [Wt. fraction] xF_prime = 0.0101;// [Wt. fraction] y2_prime = 0;// [Wt. fraction] x2_...
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//variable initialization R=109734 //(cm-1) T=24477 //(cm-1) Zeff=1 n=3 //calculation delta=n-(Zeff*sqrt(R/T)); //q...
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figure; sigma = 8.0; e=ones(20,1); C=ones(1,20); Ct=diag(C)/sigma; x=linspace(1,10,20); plot(X,d2,"ro"); //K=1 G=e; for K=0:4 if K > 1 G=[G X.^(K-1)] end m=inv(G'*Ct*G)*G'*Ct*d2; ymod=m' *X.^K end
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//check o/p when matrix containiig single element is passed t=[2]; z=[5]; [k] = rc2poly(t); disp(k); //output //1. 2.
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//Example 3.35:unknown resistance clc; clear; close; P=100.24;//ohms Q=200;//ohms S=100.03;//ohms x=(P/Q)*S*10^-6;//ohms q=200;//ohms r=700;//micro ohms p=100.31;//ohms y=((q*r*10^-6)/(p+q+(r*10^-6)));//ohms z=((P/Q)-(p/q));//ohms R=x+(y*z);//micro ohms disp(R*10^6,"unknown resistance is ,(micro-ohm)=")
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function y = cceps (x,correct) //Return the complex cepstrum of the vector x //Calling Sequence //cceps (x) //cceps(x, correct) //Description //This function return the complex cepstrum of the vector x. If the optional argument correct has the value 1, a correction method is applied. The default is not to do this. func...
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clc; clear all; disp("surface temperature of sun") lmax=0.49;//mu m T=2898/lmax;//mu.m disp("K",T, "surface temperature of sun = ") sigma=5.67*10^(-8); Eb=sigma*T^4;//W/m^2 disp("W/m^2",Eb,"The total rate of energy emmision, Eb =")
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// chapter 13 // example 13.3 // page 278 Vcc=15 // V Re=2 // kilo ohm Rc=1 // kilo ohm Rl=1 // kilo ohm Vbe=0.7 // V // dc load line // when Ic=0, Vce=Vcc i.e. Vce=15 and when Vce=0, Ic=Vcc/(Rc+Re) i.e. Ic=15/3 // so equation of load line becomes Ic=-(1/3)*Vce+15 clf() x=linspace(0,15,5) y=-...
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//Author: Parthasarathi Panda //parthasarathipanda314@gmail.com function [phi, varargout]=phasedelay(varargin) //cas variable is 2 if sos form is involved and 1 if direct rational form is given //(sos,n) or (sos,w) or (sos,'whole')or (b,a) is the input //cas variable is 2 if sos form is involved and 1 if di...
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//C-Exercise22 //Jurain Kahl //Nattawut Phanrattinon funcprot(0); exec("CompFin_2019_SS_BS_Price_Int.sce") //computes the initial price of European call options with identicall maturity T and strikes K = (K1, ..., Kn) function V0 = BS_EuCall_FFT (S0, r, sigma, T, K, R, N, M, kappa1) //model parameters delta and ka...
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function r=%rolss(s1,s2) //%rolss(s1,s2) <=> s1==s2 , s1 rational, s2 state-space //! r=%f
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clc; // page no 447 // prob no 13_5 //signal with bandwidth Bbb=200 kHz & SNR=20 dB spred at chip rate 50:1 Bbb=200*10^3;//Bandwidth Gp=50;//chip rate SNR_in=20;//SNR is 20 dB without spreading //Determination of BW after spreading Brf=Gp*Bbb; disp('MHz',Brf,'The value of BW after spreading'); //Converting in...
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clc clear // 1.a) Re1R = readxls("Material/dados.xls")(1).value exec("Material/funcoes.sce", -1) disp ("Re1R") disp(Re1R) // 1. b) // Equivalência => RST // 143 isR = verifica1(Re1R) isS = verifica4(Re1R) isT = verifica3(Re1R) if isR == %t & isS == %t & isT == %t disp("A matrix Re1R é uma rel...
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clear; clc; //Example - 14.15 //Page number - 485 printf("Example - 14.15 and Page number - 485\n\n") //Given, T = 25 + 273.15;//[K] - Temperature mol_CaCl2 = 0.001;//[mol/kg] - Molality of HCl A = 0.510;//[(kg/mol)^(1/2)] Z_positive = 2;//Stoichiometric coefficient of 'Ca' ion Z_negative = -1;//Stoichiom...
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// Exa 2.8 clc; clear; close; format('v',7) // Given data d = 10.5;// in gm/cc At = 108;// atomic weight N_A = 6.025*10^23;// in /gm mole r = 10^-3;// in m q = 1.6*10^-19;// in C // The number of electrons per unit volume n = (N_A/At)*d;// in /cm^3 n = n * 10^6;// in /m^3 A = %pi*((r)^2);// in m^2 I = 2;...
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clc clear //Input data T1=40+273//Temperature at the beginning of compression in K p1=1//Pressure at the beginning of compression in kg/cm^2 p2=15//Pressure at the end of adabatic compression in kg/cm^2 T3=2000+273//Maximum temperature during the cycle in K Cv=0.17//Specific heat at constant volume in kJ/kg.K g...
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//Example 6_1 clc; clear;close; //Given data: hp=[50 100 150 120 0];//hp t=[20 20 10 20 15];//seconds //Solution : hp_rms_t=0;//initializing for i=1:5 hp_rms_t=hp_rms_t+(hp(i)^2*t(i));//hp end hp_rms=sqrt(hp_rms_t/sum(t));//hp disp(hp_rms,"Required hp(rms)"); disp("Motor size should be 100 hp");
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clear; clc; disp("--------------Example 20.1---------------") // 01000010 - first 8 bits of IP4 packet p="01000010"; s=strsplit(p,4); // split into two v=bin2dec(s(1)); // version d=bin2dec(s(2)); // header length bytes=d*4; // formula if(((bytes > = 20 )&((v == 4) |(v == 6)))) //minimum number of bytes is ...
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//Example 5.15, page no-208 clear clc f1=2.4 //first signal frequency f2=3.2 //2nd signal frequency f3=3.4 //3rd signal frequency //minimum sampling rate for each of the signals would be twice the highest frequency component sr=3*(f3*2) st=10^6/(sr*10^3) printf("Sampling rate of th...
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clear; clf; // clear //scf; // add printf('\n'); printf('************** t demo ****************'); printf('\n'); printf('Enter a File Name of T Unit'); UnitSpaceFile = input('File Name(.xls)?: ',"string"); //printf('./' +UnitSpaceFile+'.xls\n'); T_Mat_Sheets = readxls('./' + UnitSpaceFile + '.xls'); // EX...
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//Initilization of variables //length matrix L1=[0,4,6] //m //Bending moment matrix B=[0,400,0] //N.m //Shear force plotting //Here the left side and right side lengths are considered as close as 4 to keep up with right and left distinctions L=[0,3.999,4,5.99998,6] S=[100,100,-200,-200,0] //Calculations cum Re...