question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
Find the id for the trips that lasted at least as long as the average duration of trips in zip code 94103.
SELECT id FROM trip WHERE duration >= (SELECT AVG(duration) FROM trip WHERE zip_code = 94103)
CREATE TABLE trip (id VARCHAR(255), duration INTEGER, zip_code VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 107 }
What are the dates in which the mean sea level pressure was between 30.3 and 31?
SELECT date FROM weather WHERE mean_sea_level_pressure_inches BETWEEN 30.3 AND 31
CREATE TABLE weather (date VARCHAR(255), mean_sea_level_pressure_inches INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 108 }
Find the day in which the difference between the max temperature and min temperature was the smallest. Also report the difference.
SELECT date, max_temperature_f - min_temperature_f FROM weather ORDER BY max_temperature_f - min_temperature_f LIMIT 1
CREATE TABLE weather (date VARCHAR(255), max_temperature_f VARCHAR(255), min_temperature_f VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 109 }
How many books are there?
SELECT COUNT(*) FROM book
CREATE TABLE book (Id VARCHAR(255), Title VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 115 }
List the writers of the books in ascending alphabetical order.
SELECT Writer FROM book ORDER BY Writer
CREATE TABLE book (Writer VARCHAR(255), Title VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 116 }
List the titles of the books in ascending order of issues.
SELECT Title FROM book ORDER BY Issues
CREATE TABLE book (Title VARCHAR(255), Issues VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 117 }
What are the titles of the books whose writer is not "Elaine Lee"?
SELECT Title FROM book WHERE Writer <> 'Elaine Lee'
CREATE TABLE book (Title VARCHAR(255), Writer VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 118 }
What are the title and issues of the books?
SELECT Title, Issues FROM book
CREATE TABLE book (Title VARCHAR(255), Issues VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 119 }
What are the dates of publications in descending order of price?
SELECT Publication_Date FROM publication ORDER BY Price DESC
CREATE TABLE publication (Publication_Date VARCHAR(255), Price VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 120 }
What are the distinct publishers of publications with price higher than 5000000?
SELECT DISTINCT Publisher FROM publication WHERE Price > 5000000
CREATE TABLE publication (Publisher VARCHAR(255), Price INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 121 }
List the publisher of the publication with the highest price.
SELECT Publisher FROM publication ORDER BY Price DESC LIMIT 1
CREATE TABLE publication (Publisher VARCHAR(255), Price VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 122 }
List the publication dates of publications with 3 lowest prices.
SELECT Publication_Date FROM publication ORDER BY Price LIMIT 3
CREATE TABLE publication (Publication_Date VARCHAR(255), Price VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 123 }
Show the title and publication dates of books.
SELECT T1.Title, T2.Publication_Date FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID
CREATE TABLE book (Title VARCHAR(255), Book_ID VARCHAR(255)); CREATE TABLE publication (Publication_Date VARCHAR(255), Book_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 124 }
Show writers who have published a book with price more than 4000000.
SELECT T1.Writer FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID WHERE T2.Price > 4000000
CREATE TABLE publication (Book_ID VARCHAR(255), Price INTEGER); CREATE TABLE book (Writer VARCHAR(255), Book_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 125 }
Show the titles of books in descending order of publication price.
SELECT T1.Title FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID ORDER BY T2.Price DESC
CREATE TABLE publication (Book_ID VARCHAR(255), Price VARCHAR(255)); CREATE TABLE book (Title VARCHAR(255), Book_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 126 }
Show publishers that have more than one publication.
SELECT Publisher FROM publication GROUP BY Publisher HAVING COUNT(*) > 1
CREATE TABLE publication (Publisher VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 127 }
Show different publishers together with the number of publications they have.
SELECT Publisher, COUNT(*) FROM publication GROUP BY Publisher
CREATE TABLE publication (Publisher VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 128 }
Please show the most common publication date.
SELECT Publication_Date FROM publication GROUP BY Publication_Date ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE publication (Publication_Date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 129 }
List the writers who have written more than one book.
SELECT Writer FROM book GROUP BY Writer HAVING COUNT(*) > 1
CREATE TABLE book (Writer VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 130 }
List the titles of books that are not published.
SELECT Title FROM book WHERE NOT Book_ID IN (SELECT Book_ID FROM publication)
CREATE TABLE book (Title VARCHAR(255), Book_ID VARCHAR(255)); CREATE TABLE publication (Title VARCHAR(255), Book_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 131 }
Show the publishers that have publications with price higher than 10000000 and publications with price lower than 5000000.
SELECT Publisher FROM publication WHERE Price > 10000000 INTERSECT SELECT Publisher FROM publication WHERE Price < 5000000
CREATE TABLE publication (Publisher VARCHAR(255), Price INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 132 }
What is the number of distinct publication dates?
SELECT COUNT(DISTINCT Publication_Date) FROM publication
CREATE TABLE publication (Publication_Date VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 133 }
Show the prices of publications whose publisher is either "Person" or "Wiley"
SELECT Price FROM publication WHERE Publisher = 'Person' OR Publisher = 'Wiley'
CREATE TABLE publication (Price VARCHAR(255), Publisher VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 134 }
How many actors are there?
SELECT COUNT(*) FROM actor
CREATE TABLE actor (Id VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 135 }
List the name of actors in ascending alphabetical order.
SELECT Name FROM actor ORDER BY Name
CREATE TABLE actor (Name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 136 }
What are the characters and duration of actors?
SELECT Character, Duration FROM actor
CREATE TABLE actor (Character VARCHAR(255), Duration VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 137 }
List the name of actors whose age is not 20.
SELECT Name FROM actor WHERE Age <> 20
CREATE TABLE actor (Name VARCHAR(255), Age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 138 }
What are the characters of actors in descending order of age?
SELECT Character FROM actor ORDER BY age DESC
CREATE TABLE actor (Character VARCHAR(255), age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 139 }
What is the duration of the oldest actor?
SELECT Duration FROM actor ORDER BY Age DESC LIMIT 1
CREATE TABLE actor (Duration VARCHAR(255), Age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 140 }
What are the names of musicals with nominee "Bob Fosse"?
SELECT Name FROM musical WHERE Nominee = 'Bob Fosse'
CREATE TABLE musical (Name VARCHAR(255), Nominee VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 141 }
What are the distinct nominees of the musicals with the award that is not "Tony Award"?
SELECT DISTINCT Nominee FROM musical WHERE Award <> 'Tony Award'
CREATE TABLE musical (Nominee VARCHAR(255), Award VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 142 }
Show names of actors and names of musicals they are in.
SELECT T1.Name, T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID
CREATE TABLE actor (Name VARCHAR(255), Musical_ID VARCHAR(255)); CREATE TABLE musical (Name VARCHAR(255), Musical_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 143 }
Show names of actors that have appeared in musical with name "The Phantom of the Opera".
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID WHERE T2.Name = 'The Phantom of the Opera'
CREATE TABLE actor (Name VARCHAR(255), Musical_ID VARCHAR(255)); CREATE TABLE musical (Musical_ID VARCHAR(255), Name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 144 }
Show names of actors in descending order of the year their musical is awarded.
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID ORDER BY T2.Year DESC
CREATE TABLE musical (Musical_ID VARCHAR(255), Year VARCHAR(255)); CREATE TABLE actor (Name VARCHAR(255), Musical_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 145 }
Show names of musicals and the number of actors who have appeared in the musicals.
SELECT T2.Name, COUNT(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID
CREATE TABLE actor (Musical_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE musical (Name VARCHAR(255), Musical_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 146 }
Show names of musicals which have at least three actors.
SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT(*) >= 3
CREATE TABLE actor (Musical_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE musical (Name VARCHAR(255), Musical_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 147 }
Show different nominees and the number of musicals they have been nominated.
SELECT Nominee, COUNT(*) FROM musical GROUP BY Nominee
CREATE TABLE musical (Nominee VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 148 }
Please show the nominee who has been nominated the greatest number of times.
SELECT Nominee FROM musical GROUP BY Nominee ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE musical (Nominee VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 149 }
List the most common result of the musicals.
SELECT RESULT FROM musical GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE musical (RESULT VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 150 }
List the nominees that have been nominated more than two musicals.
SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT(*) > 2
CREATE TABLE musical (Nominee VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 151 }
List the name of musicals that do not have actors.
SELECT Name FROM musical WHERE NOT Musical_ID IN (SELECT Musical_ID FROM actor)
CREATE TABLE actor (Name VARCHAR(255), Musical_ID VARCHAR(255)); CREATE TABLE musical (Name VARCHAR(255), Musical_ID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 152 }
Show the nominees that have nominated musicals for both "Tony Award" and "Drama Desk Award".
SELECT Nominee FROM musical WHERE Award = 'Tony Award' INTERSECT SELECT Nominee FROM musical WHERE Award = 'Drama Desk Award'
CREATE TABLE musical (Nominee VARCHAR(255), Award VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 153 }
Show the musical nominee with award "Bob Fosse" or "Cleavant Derricks".
SELECT Nominee FROM musical WHERE Award = 'Tony Award' OR Award = 'Cleavant Derricks'
CREATE TABLE musical (Nominee VARCHAR(255), Award VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 154 }
Find the emails of the user named "Mary".
SELECT email FROM user_profiles WHERE name = 'Mary'
CREATE TABLE user_profiles (email VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 155 }
What is the partition id of the user named "Iron Man".
SELECT partitionid FROM user_profiles WHERE name = 'Iron Man'
CREATE TABLE user_profiles (partitionid VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 156 }
How many users are there?
SELECT COUNT(*) FROM user_profiles
CREATE TABLE user_profiles (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 157 }
How many followers does each user have?
SELECT COUNT(*) FROM follows
CREATE TABLE follows (Id VARCHAR(255), user_id VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 158 }
Find the number of followers for each user.
SELECT COUNT(*) FROM follows GROUP BY f1
CREATE TABLE follows (f1 VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 159 }
Find the number of tweets in record.
SELECT COUNT(*) FROM tweets
CREATE TABLE tweets (Id VARCHAR(255), content VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 160 }
Find the number of users who posted some tweets.
SELECT COUNT(DISTINCT UID) FROM tweets
CREATE TABLE tweets (UID VARCHAR(255), tweet_text VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 161 }
Find the name and email of the user whose name contains the word ‘Swift’.
SELECT name, email FROM user_profiles WHERE name LIKE '%Swift%'
CREATE TABLE user_profiles (name VARCHAR(255), email VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 162 }
Find the names of users whose emails contain ‘superstar’ or ‘edu’.
SELECT name FROM user_profiles WHERE email LIKE '%superstar%' OR email LIKE '%edu%'
CREATE TABLE user_profiles (name VARCHAR(255), email VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 163 }
Return the text of tweets about the topic 'intern'.
SELECT text FROM tweets WHERE text LIKE '%intern%'
CREATE TABLE tweets (text VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 164 }
Find the name and email of the users who have more than 1000 followers.
SELECT name, email FROM user_profiles WHERE followers > 1000
CREATE TABLE user_profiles (name VARCHAR(255), email VARCHAR(255), followers INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 165 }
Find the names of the users whose number of followers is greater than that of the user named "Tyler Swift".
SELECT T1.name FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT(*) > (SELECT COUNT(*) FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 WHERE T1.name = 'Tyler Swift')
CREATE TABLE follows (f1 VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE user_profiles (name VARCHAR(255), uid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 166 }
Find the name and email for the users who have more than one follower.
SELECT T1.name, T1.email FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT(*) > 1
CREATE TABLE follows (f1 VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE user_profiles (name VARCHAR(255), email VARCHAR(255), uid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 167 }
Find the names of users who have more than one tweet.
SELECT T1.name FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) > 1
CREATE TABLE tweets (uid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE user_profiles (name VARCHAR(255), uid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 168 }
Find the id of users who are followed by Mary and Susan.
SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = 'Mary' INTERSECT SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = 'Susan'
CREATE TABLE follows (f1 VARCHAR(255), f2 VARCHAR(255)); CREATE TABLE user_profiles (uid VARCHAR(255), name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 169 }
Find the id of users who are followed by Mary or Susan.
SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = 'Mary' OR T1.name = 'Susan'
CREATE TABLE follows (f1 VARCHAR(255), f2 VARCHAR(255)); CREATE TABLE user_profiles (uid VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 170 }
Find the name of the user who has the largest number of followers.
SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 1
CREATE TABLE user_profiles (name VARCHAR(255), followers VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 171 }
Find the name and email of the user followed by the least number of people.
SELECT name, email FROM user_profiles ORDER BY followers LIMIT 1
CREATE TABLE user_profiles (name VARCHAR(255), email VARCHAR(255), followers VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 172 }
List the name and number of followers for each user, and sort the results by the number of followers in descending order.
SELECT name, followers FROM user_profiles ORDER BY followers DESC
CREATE TABLE user_profiles (name VARCHAR(255), followers VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 173 }
List the names of 5 users followed by the largest number of other users.
SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 5
CREATE TABLE user_profiles (name VARCHAR(255), followers VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 174 }
List the text of all tweets in the order of date.
SELECT text FROM tweets ORDER BY createdate
CREATE TABLE tweets (text VARCHAR(255), createdate VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 175 }
Find the name of each user and number of tweets tweeted by each of them.
SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid
CREATE TABLE tweets (uid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE user_profiles (name VARCHAR(255), uid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 176 }
Find the name and partition id for users who tweeted less than twice.
SELECT T1.name, T1.partitionid FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) < 2
CREATE TABLE user_profiles (name VARCHAR(255), partitionid VARCHAR(255), uid VARCHAR(255)); CREATE TABLE tweets (uid VARCHAR(255), tweet_text VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 177 }
Find the name of the user who tweeted more than once, and number of tweets tweeted by them.
SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) > 1
CREATE TABLE tweets (uid VARCHAR(255), tweet_text VARCHAR(255)); CREATE TABLE user_profiles (name VARCHAR(255), uid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 178 }
Find the average number of followers for the users who do not have any tweet.
SELECT AVG(followers) FROM user_profiles WHERE NOT UID IN (SELECT UID FROM tweets)
CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR(255)); CREATE TABLE tweets (followers INTEGER, UID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 179 }
Find the average number of followers for the users who had some tweets.
SELECT AVG(followers) FROM user_profiles WHERE UID IN (SELECT UID FROM tweets)
CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR(255)); CREATE TABLE tweets (followers INTEGER, UID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 180 }
Find the maximum and total number of followers of all users.
SELECT MAX(followers), SUM(followers) FROM user_profiles
CREATE TABLE user_profiles (followers INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 181 }
Find the names of all the catalog entries.
SELECT DISTINCT (catalog_entry_name) FROM catalog_contents
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 182 }
Find the list of attribute data types possessed by more than 3 attribute definitions.
SELECT attribute_data_type FROM Attribute_Definitions GROUP BY attribute_data_type HAVING COUNT(*) > 3
CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 183 }
What is the attribute data type of the attribute with name "Green"?
SELECT attribute_data_type FROM Attribute_Definitions WHERE attribute_name = 'Green'
CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR(255), attribute_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 184 }
Find the name and level of catalog structure with level between 5 and 10.
SELECT catalog_level_name, catalog_level_number FROM Catalog_Structure WHERE catalog_level_number BETWEEN 5 AND 10
CREATE TABLE Catalog_Structure (catalog_level_name VARCHAR(255), catalog_level_number INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 185 }
Find all the catalog publishers whose name contains "Murray"
SELECT DISTINCT (catalog_publisher) FROM catalogs WHERE catalog_publisher LIKE '%Murray%'
CREATE TABLE catalogs (catalog_publisher VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 186 }
Which catalog publisher has published the most catalogs?
SELECT catalog_publisher FROM catalogs GROUP BY catalog_publisher ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE catalogs (catalog_publisher VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 187 }
What is the entry name of the most expensive catalog (in USD)?
SELECT catalog_entry_name FROM catalog_contents ORDER BY price_in_dollars DESC LIMIT 1
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), price_in_dollars VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 190 }
What is the level name of the cheapest catalog (in USD)?
SELECT t2.catalog_level_name FROM catalog_contents AS t1 JOIN catalog_structure AS t2 ON t1.catalog_level_number = t2.catalog_level_number ORDER BY t1.price_in_dollars LIMIT 1
CREATE TABLE catalog_structure (catalog_level_name VARCHAR(255), catalog_level_number VARCHAR(255)); CREATE TABLE catalog_contents (catalog_level_number VARCHAR(255), price_in_dollars VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 191 }
What are the average and minimum price (in Euro) of all products?
SELECT AVG(price_in_euros), MIN(price_in_euros) FROM catalog_contents
CREATE TABLE catalog_contents (price_in_euros INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 192 }
What is the product with the highest height? Give me the catalog entry name.
SELECT catalog_entry_name FROM catalog_contents ORDER BY height DESC LIMIT 1
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), height VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 193 }
Find the name of the product that has the smallest capacity.
SELECT catalog_entry_name FROM catalog_contents ORDER BY capacity LIMIT 1
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), capacity VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 194 }
Find the names of all the products whose stock number starts with "2".
SELECT catalog_entry_name FROM catalog_contents WHERE product_stock_number LIKE '2%'
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), product_stock_number VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 195 }
Find the names of catalog entries with level number 8.
SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id = t2.catalog_entry_id WHERE t2.catalog_level_number = '8'
CREATE TABLE Catalog_Contents_Additional_Attributes (catalog_entry_id VARCHAR(255), catalog_level_number VARCHAR(255)); CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR(255), catalog_entry_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 196 }
Find the names of the products with length smaller than 3 or height greater than 5.
SELECT catalog_entry_name FROM catalog_contents WHERE LENGTH < 3 OR width > 5
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), LENGTH VARCHAR(255), width VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 197 }
Find the name and attribute ID of the attribute definitions with attribute value 0.
SELECT t1.attribute_name, t1.attribute_id FROM Attribute_Definitions AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.attribute_id = t2.attribute_id WHERE t2.attribute_value = 0
CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_id VARCHAR(255), attribute_value VARCHAR(255)); CREATE TABLE Attribute_Definitions (attribute_name VARCHAR(255), attribute_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 198 }
Find the name and capacity of products with price greater than 700 (in USD).
SELECT catalog_entry_name, capacity FROM Catalog_Contents WHERE price_in_dollars > 700
CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR(255), capacity VARCHAR(255), price_in_dollars INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 199 }
Find the dates on which more than one revisions were made.
SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING COUNT(*) > 1
CREATE TABLE Catalogs (date_of_latest_revision VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 200 }
How many products are there in the records?
SELECT COUNT(*) FROM catalog_contents
CREATE TABLE catalog_contents (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 201 }
Name all the products with next entry ID greater than 8.
SELECT catalog_entry_name FROM catalog_contents WHERE next_entry_id > 8
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR(255), next_entry_id INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 202 }
How many aircrafts do we have?
SELECT COUNT(*) FROM Aircraft
CREATE TABLE Aircraft (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 203 }
Show name and distance for all aircrafts.
SELECT name, distance FROM Aircraft
CREATE TABLE Aircraft (name VARCHAR(255), distance VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 204 }
Show ids for all aircrafts with more than 1000 distance.
SELECT aid FROM Aircraft WHERE distance > 1000
CREATE TABLE Aircraft (aid VARCHAR(255), distance INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 205 }
How many aircrafts have distance between 1000 and 5000?
SELECT COUNT(*) FROM Aircraft WHERE distance BETWEEN 1000 AND 5000
CREATE TABLE Aircraft (distance INTEGER, aid VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 206 }
What is the name and distance for aircraft with id 12?
SELECT name, distance FROM Aircraft WHERE aid = 12
CREATE TABLE Aircraft (name VARCHAR(255), distance VARCHAR(255), aid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 207 }
What is the minimum, average, and maximum distance of all aircrafts.
SELECT MIN(distance), AVG(distance), MAX(distance) FROM Aircraft
CREATE TABLE Aircraft (distance INTEGER, aid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 208 }
Show the id and name of the aircraft with the maximum distance.
SELECT aid, name FROM Aircraft ORDER BY distance DESC LIMIT 1
CREATE TABLE Aircraft (aid VARCHAR(255), name VARCHAR(255), distance VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 209 }
Show the name of aircrafts with top three lowest distances.
SELECT name FROM Aircraft ORDER BY distance LIMIT 3
CREATE TABLE Aircraft (name VARCHAR(255), distance VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 210 }
Show names for all aircrafts with distances more than the average.
SELECT name FROM Aircraft WHERE distance > (SELECT AVG(distance) FROM Aircraft)
CREATE TABLE Aircraft (name VARCHAR(255), distance INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 211 }
How many employees do we have?
SELECT COUNT(*) FROM Employee
CREATE TABLE Employee (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 212 }
Show name and salary for all employees sorted by salary.
SELECT name, salary FROM Employee ORDER BY salary
CREATE TABLE Employee (name VARCHAR(255), salary VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 213 }