question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
Show ids for all employees with at least 100000 salary.
SELECT eid FROM Employee WHERE salary > 100000
CREATE TABLE Employee (eid VARCHAR(255), salary INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 214 }
How many employees have salary between 100000 and 200000?
SELECT COUNT(*) FROM Employee WHERE salary BETWEEN 100000 AND 200000
CREATE TABLE Employee (salary INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 215 }
What is the name and salary for employee with id 242518965?
SELECT name, salary FROM Employee WHERE eid = 242518965
CREATE TABLE Employee (name VARCHAR(255), salary VARCHAR(255), eid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 216 }
What is average and maximum salary of all employees.
SELECT AVG(salary), MAX(salary) FROM Employee
CREATE TABLE Employee (salary INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 217 }
Show the id and name of the employee with maximum salary.
SELECT eid, name FROM Employee ORDER BY salary DESC LIMIT 1
CREATE TABLE Employee (eid VARCHAR(255), name VARCHAR(255), salary VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 218 }
Show the name of employees with three lowest salaries.
SELECT name FROM Employee ORDER BY salary LIMIT 3
CREATE TABLE Employee (name VARCHAR(255), salary VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 219 }
Show names for all employees with salary more than the average.
SELECT name FROM Employee WHERE salary > (SELECT AVG(salary) FROM Employee)
CREATE TABLE Employee (name VARCHAR(255), salary INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 220 }
Show the id and salary of Mark Young.
SELECT eid, salary FROM Employee WHERE name = 'Mark Young'
CREATE TABLE Employee (eid VARCHAR(255), salary VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 221 }
How many flights do we have?
SELECT COUNT(*) FROM Flight
CREATE TABLE Flight (Id VARCHAR(255), departure_date VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 222 }
Show flight number, origin, destination of all flights in the alphabetical order of the departure cities.
SELECT flno, origin, destination FROM Flight ORDER BY origin
CREATE TABLE Flight (flno VARCHAR(255), origin VARCHAR(255), destination VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 223 }
Show all flight number from Los Angeles.
SELECT flno FROM Flight WHERE origin = 'Los Angeles'
CREATE TABLE Flight (flno VARCHAR(255), origin VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 224 }
Show origins of all flights with destination Honolulu.
SELECT origin FROM Flight WHERE destination = 'Honolulu'
CREATE TABLE Flight (origin VARCHAR(255), destination VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 225 }
Show me the departure date and arrival date for all flights from Los Angeles to Honolulu.
SELECT departure_date, arrival_date FROM Flight WHERE origin = 'Los Angeles' AND destination = 'Honolulu'
CREATE TABLE Flight (departure_date VARCHAR(255), arrival_date VARCHAR(255), origin VARCHAR(255), destination VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 226 }
Show flight number for all flights with more than 2000 distance.
SELECT flno FROM Flight WHERE distance > 2000
CREATE TABLE Flight (flno VARCHAR(255), distance INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 227 }
What is the average price for flights from Los Angeles to Honolulu.
SELECT AVG(price) FROM Flight WHERE origin = 'Los Angeles' AND destination = 'Honolulu'
CREATE TABLE Flight (price INTEGER, origin VARCHAR(255), destination VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 228 }
Show origin and destination for flights with price higher than 300.
SELECT origin, destination FROM Flight WHERE price > 300
CREATE TABLE Flight (origin VARCHAR(255), destination VARCHAR(255), price INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 229 }
Show the flight number and distance of the flight with maximum price.
SELECT flno, distance FROM Flight ORDER BY price DESC LIMIT 1
CREATE TABLE Flight (flno VARCHAR(255), distance VARCHAR(255), price VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 230 }
Show the flight number of flights with three lowest distances.
SELECT flno FROM Flight ORDER BY distance LIMIT 3
CREATE TABLE Flight (flno VARCHAR(255), distance VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 231 }
What is the average distance and average price for flights from Los Angeles.
SELECT AVG(distance), AVG(price) FROM Flight WHERE origin = 'Los Angeles'
CREATE TABLE Flight (distance INTEGER, price INTEGER, origin VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 232 }
Show all origins and the number of flights from each origin.
SELECT origin, COUNT(*) FROM Flight GROUP BY origin
CREATE TABLE Flight (origin VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 233 }
Show all destinations and the number of flights to each destination.
SELECT destination, COUNT(*) FROM Flight GROUP BY destination
CREATE TABLE Flight (destination VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 234 }
Which origin has most number of flights?
SELECT origin FROM Flight GROUP BY origin ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Flight (origin VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 235 }
Which destination has least number of flights?
SELECT destination FROM Flight GROUP BY destination ORDER BY COUNT(*) LIMIT 1
CREATE TABLE Flight (destination VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 236 }
What is the aircraft name for the flight with number 99
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
CREATE TABLE Flight (aid VARCHAR(255), flno VARCHAR(255)); CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 237 }
Show all flight numbers with aircraft Airbus A340-300.
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = 'Airbus A340-300'
CREATE TABLE Flight (flno VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Aircraft (aid VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 238 }
Show aircraft names and number of flights for each aircraft.
SELECT T2.name, COUNT(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Flight (aid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 239 }
Show names for all aircraft with at least two flights.
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING COUNT(*) >= 2
CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Flight (aid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 240 }
How many employees have certificate.
SELECT COUNT(DISTINCT eid) FROM Certificate
CREATE TABLE Certificate (eid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 241 }
Show ids for all employees who don't have a certificate.
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
CREATE TABLE Employee (eid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Certificate (eid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 242 }
Show names for all aircrafts of which John Williams has certificates.
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = 'John Williams'
CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Employee (eid VARCHAR(255), name VARCHAR(255)); CREATE TABLE Certificate (eid VARCHAR(255), aid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 243 }
Show names for all employees who have certificate of Boeing 737-800.
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = 'Boeing 737-800'
CREATE TABLE Employee (name VARCHAR(255), eid VARCHAR(255)); CREATE TABLE Certificate (eid VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Aircraft (aid VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 244 }
Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = 'Boeing 737-800' INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = 'Airbus A340-300'
CREATE TABLE Employee (name VARCHAR(255), eid VARCHAR(255)); CREATE TABLE Certificate (eid VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Aircraft (aid VARCHAR(255), name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 245 }
Show the name of aircraft which fewest people have its certificate.
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Certificate (aid VARCHAR(255), eid VARCHAR(255)); CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 247 }
Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY COUNT(*) >= 5
CREATE TABLE Certificate (aid VARCHAR(255), eid VARCHAR(255)); CREATE TABLE Aircraft (name VARCHAR(255), aid VARCHAR(255), distance INTEGER)
generic
null
extra
extended
valid
valid
valid
[]
[]
[]
[ "Unsupported column expression: COUNT(*) >= 5" ]
[ "validated", "extended", "extended" ]
null
null
null
null
{ "split": "train", "row_index": 248 }
what is the salary and name of the employee who has the most number of aircraft certificates?
SELECT T1.name, T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Certificate (eid VARCHAR(255), aid VARCHAR(255)); CREATE TABLE Employee (name VARCHAR(255), salary VARCHAR(255), eid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 249 }
What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Aircraft (aid VARCHAR(255), distance INTEGER); CREATE TABLE Employee (name VARCHAR(255), eid VARCHAR(255)); CREATE TABLE Certificate (eid VARCHAR(255), aid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
6
0
0
{ "split": "train", "row_index": 250 }
How many allergies are there?
SELECT COUNT(DISTINCT allergy) FROM Allergy_type
CREATE TABLE Allergy_type (allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 251 }
How many different allergy types exist?
SELECT COUNT(DISTINCT allergytype) FROM Allergy_type
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 252 }
Show all allergy types.
SELECT DISTINCT allergytype FROM Allergy_type
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 253 }
Show all allergies and their types.
SELECT allergy, allergytype FROM Allergy_type
CREATE TABLE Allergy_type (allergy VARCHAR(255), allergytype VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 254 }
Show all allergies with type food.
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = 'food'
CREATE TABLE Allergy_type (allergy VARCHAR(255), allergytype VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 255 }
What is the type of allergy Cat?
SELECT allergytype FROM Allergy_type WHERE allergy = 'Cat'
CREATE TABLE Allergy_type (allergytype VARCHAR(255), allergy VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 256 }
How many allergies have type animal?
SELECT COUNT(*) FROM Allergy_type WHERE allergytype = 'animal'
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 257 }
Show all allergy types and the number of allergies in each type.
SELECT allergytype, COUNT(*) FROM Allergy_type GROUP BY allergytype
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 258 }
Which allergy type has most number of allergies?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 259 }
Which allergy type has least number of allergies?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) LIMIT 1
CREATE TABLE Allergy_type (allergytype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 260 }
How many students are there?
SELECT COUNT(*) FROM Student
CREATE TABLE Student (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 261 }
Show first name and last name for all students.
SELECT Fname, Lname FROM Student
CREATE TABLE Student (Fname VARCHAR(255), Lname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 262 }
How many different advisors are listed?
SELECT COUNT(DISTINCT advisor) FROM Student
CREATE TABLE Student (advisor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 263 }
Show all majors.
SELECT DISTINCT Major FROM Student
CREATE TABLE Student (Major VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 264 }
Show all cities where students live.
SELECT DISTINCT city_code FROM Student
CREATE TABLE Student (city_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 265 }
Show first name, last name, age for all female students. Their sex is F.
SELECT Fname, Lname, Age FROM Student WHERE Sex = 'F'
CREATE TABLE Student (Fname VARCHAR(255), Lname VARCHAR(255), Age VARCHAR(255), Sex VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 266 }
Show student ids for all male students.
SELECT StuID FROM Student WHERE Sex = 'M'
CREATE TABLE Student (StuID VARCHAR(255), Sex VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 267 }
How many students are age 18?
SELECT COUNT(*) FROM Student WHERE age = 18
CREATE TABLE Student (age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 268 }
Show all student ids who are older than 20.
SELECT StuID FROM Student WHERE age > 20
CREATE TABLE Student (StuID VARCHAR(255), age INTEGER)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 269 }
Which city does the student whose last name is "Kim" live in?
SELECT city_code FROM Student WHERE LName = 'Kim'
CREATE TABLE Student (city_code VARCHAR(255), LName VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 270 }
Who is the advisor of student with ID 1004?
SELECT Advisor FROM Student WHERE StuID = 1004
CREATE TABLE Student (Advisor VARCHAR(255), StuID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 271 }
How many students live in HKG or CHI?
SELECT COUNT(*) FROM Student WHERE city_code = 'HKG' OR city_code = 'CHI'
CREATE TABLE Student (city_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 272 }
Show the minimum, average, and maximum age of all students.
SELECT MIN(age), AVG(age), MAX(age) FROM Student
CREATE TABLE Student (age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 273 }
What is the last name of the youngest student?
SELECT LName FROM Student WHERE age = (SELECT MIN(age) FROM Student)
CREATE TABLE Student (LName VARCHAR(255), age INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 274 }
Show the student id of the oldest student.
SELECT StuID FROM Student WHERE age = (SELECT MAX(age) FROM Student)
CREATE TABLE Student (StuID VARCHAR(255), age INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 275 }
Show all majors and corresponding number of students.
SELECT major, COUNT(*) FROM Student GROUP BY major
CREATE TABLE Student (major VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 276 }
Which major has most number of students?
SELECT major FROM Student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student (major VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 277 }
Show all ages and corresponding number of students.
SELECT age, COUNT(*) FROM Student GROUP BY age
CREATE TABLE Student (age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 278 }
Show the average age for male and female students.
SELECT AVG(age), sex FROM Student GROUP BY sex
CREATE TABLE Student (sex VARCHAR(255), age INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 279 }
Show all cities and corresponding number of students.
SELECT city_code, COUNT(*) FROM Student GROUP BY city_code
CREATE TABLE Student (city_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 280 }
Show all advisors and corresponding number of students.
SELECT advisor, COUNT(*) FROM Student GROUP BY advisor
CREATE TABLE Student (advisor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 281 }
Which advisor has most number of students?
SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student (advisor VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 282 }
How many students have cat allergies?
SELECT COUNT(*) FROM Has_allergy WHERE Allergy = 'Cat'
CREATE TABLE Has_allergy (Allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 283 }
Show all student IDs who have at least two allergies.
SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2
CREATE TABLE Has_allergy (StuID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 284 }
What are the student ids of students who don't have any allergies?
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
CREATE TABLE Has_allergy (StuID VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), age INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 285 }
How many female students have milk or egg allergies?
SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = 'F' AND T1.allergy = 'Milk' OR T1.allergy = 'Eggs'
CREATE TABLE Student (StuID VARCHAR(255), sex VARCHAR(255)); CREATE TABLE has_allergy (StuID VARCHAR(255), allergy VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 286 }
How many students have a food allergy?
SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = 'food'
CREATE TABLE Has_allergy (allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Allergy_type (allergy VARCHAR(255), allergytype VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 287 }
Which allergy has most number of students affected?
SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Has_allergy (Allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 288 }
Show all allergies with number of students affected.
SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy
CREATE TABLE Has_allergy (Allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 289 }
Show all allergy type with number of students affected.
SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
CREATE TABLE Has_allergy (allergy VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Allergy_type (allergytype VARCHAR(255), allergy VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 290 }
Find the last name and age of the student who has allergy to both milk and cat.
SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat')
CREATE TABLE Has_allergy (lname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Student (lname VARCHAR(255), age VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 291 }
What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = 'Lisa' ORDER BY T1.Allergy
CREATE TABLE Has_allergy (Allergy VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Student (StuID VARCHAR(255), Fname VARCHAR(255)); CREATE TABLE Allergy_type (Allergy VARCHAR(255), AllergyType VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 292 }
Find the first name and gender of the student who has allergy to milk but not cat.
SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat')
CREATE TABLE Student (fname VARCHAR(255), sex VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Has_allergy (fname VARCHAR(255), sex VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 293 }
Find the average age of the students who have allergies with food and animal types.
SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'animal')
CREATE TABLE Student (age INTEGER, StuID VARCHAR(255)); CREATE TABLE Allergy_Type (Allergy VARCHAR(255), allergytype VARCHAR(255)); CREATE TABLE Has_allergy (StuID VARCHAR(255), Allergy VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 294 }
List the first and last name of the students who do not have any food type allergy.
SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food')
CREATE TABLE Student (fname VARCHAR(255), lname VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Allergy_Type (Allergy VARCHAR(255), allergytype VARCHAR(255)); CREATE TABLE Has_allergy (StuID VARCHAR(255), Allergy VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 295 }
Find the number of male (sex is 'M') students who have some food type allery.
SELECT COUNT(*) FROM Student WHERE sex = 'M' AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food')
CREATE TABLE Has_allergy (Allergy VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Allergy_Type (Allergy VARCHAR(255), allergytype VARCHAR(255)); CREATE TABLE Student (sex VARCHAR(255), StuID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 296 }
Find the different first names and cities of the students who have allergy to milk or cat.
SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = 'Milk' OR T2.Allergy = 'Cat'
CREATE TABLE Has_Allergy (stuid VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Student (fname VARCHAR(255), city_code VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 297 }
Find the number of students who are older than 18 and do not have allergy to either food or animal.
SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' OR T2.allergytype = 'animal')
CREATE TABLE Allergy_Type (Allergy VARCHAR(255), allergytype VARCHAR(255)); CREATE TABLE Has_allergy (Allergy VARCHAR(255), StuID VARCHAR(255)); CREATE TABLE Student (age VARCHAR(255), StuID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
2
{ "split": "train", "row_index": 298 }
Find the first name and major of the students who are not allegry to soy.
SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Soy')
CREATE TABLE Has_allergy (fname VARCHAR(255), major VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255)); CREATE TABLE Student (fname VARCHAR(255), major VARCHAR(255), StuID VARCHAR(255), Allergy VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 299 }
A list of the top 5 countries by number of invoices. List country name and number of invoices.
SELECT billing_country, COUNT(*) FROM invoices GROUP BY billing_country ORDER BY COUNT(*) DESC LIMIT 5
CREATE TABLE invoices (billing_country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 300 }
A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.
SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8
CREATE TABLE invoices (billing_country VARCHAR(255), total INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 301 }
A list of the top 10 countries by average invoice size. List country name and average invoice size.
SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10
CREATE TABLE invoices (billing_country VARCHAR(255), total INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 302 }
Find out 5 customers who most recently purchased something. List customers' first and last name.
SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5
CREATE TABLE customers (first_name VARCHAR(255), last_name VARCHAR(255), id VARCHAR(255)); CREATE TABLE invoices (customer_id VARCHAR(255), invoice_date VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 303 }
Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.
SELECT T1.first_name, T1.last_name, COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10
CREATE TABLE customers (first_name VARCHAR(255), last_name VARCHAR(255), id VARCHAR(255)); CREATE TABLE invoices (customer_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 304 }
List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.
SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10
CREATE TABLE invoices (total INTEGER, customer_id VARCHAR(255)); CREATE TABLE customers (first_name VARCHAR(255), last_name VARCHAR(255), id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 305 }
List the top 5 genres by number of tracks. List genres name and total tracks.
SELECT T1.name, COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 5
CREATE TABLE tracks (genre_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE genres (name VARCHAR(255), id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 306 }
List every album's title.
SELECT title FROM albums
CREATE TABLE albums (title VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 307 }
List every album ordered by album title in ascending order.
SELECT title FROM albums ORDER BY title
CREATE TABLE albums (title VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 308 }
List every album whose title starts with A in alphabetical order.
SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title
CREATE TABLE albums (title VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 309 }
List total amount of invoice from Chicago, IL.
SELECT SUM(total) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL'
CREATE TABLE invoices (total INTEGER, billing_city VARCHAR(255), billing_state VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 311 }
List the number of invoices from Chicago, IL.
SELECT COUNT(*) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL'
CREATE TABLE invoices (billing_city VARCHAR(255), billing_state VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 312 }
List the number of invoices from the US, grouped by state.
SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state
CREATE TABLE invoices (billing_state VARCHAR(255), billing_country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 313 }
List the state in the US with the most invoices.
SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE invoices (billing_state VARCHAR(255), billing_country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 314 }
List the number of invoices and the invoice total from California.
SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = 'CA'
CREATE TABLE invoices (billing_state VARCHAR(255), total INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 315 }