question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
How many players born in USA are right-handed batters? That is, have the batter value 'R'.
SELECT COUNT(*) FROM player WHERE birth_country = 'USA' AND bats = 'R'
CREATE TABLE player (birth_country VARCHAR(255), bats VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2145 }
What is the average height of the players from the college named 'Yale University'?
SELECT AVG(T1.height) FROM player AS T1 JOIN player_college AS T2 ON T1.player_id = T2.player_id JOIN college AS T3 ON T3.college_id = T2.college_id WHERE T3.name_full = 'Yale University'
CREATE TABLE player_college (player_id VARCHAR(255), college_id VARCHAR(255)); CREATE TABLE player (height INTEGER, player_id VARCHAR(255)); CREATE TABLE college (college_id VARCHAR(255), name_full VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2146 }
What is the highest salary among each team? List the team name, id and maximum salary.
SELECT T1.name, T1.team_id, MAX(T2.salary) FROM team AS T1 JOIN salary AS T2 ON T1.team_id = T2.team_id GROUP BY T1.team_id
CREATE TABLE salary (salary INTEGER, team_id VARCHAR(255)); CREATE TABLE team (name VARCHAR(255), team_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2147 }
What are the name and id of the team offering the lowest average salary?
SELECT T1.name, T1.team_id FROM team AS T1 JOIN salary AS T2 ON T1.team_id = T2.team_id GROUP BY T1.team_id ORDER BY AVG(T2.salary) LIMIT 1
CREATE TABLE team (name VARCHAR(255), team_id VARCHAR(255)); CREATE TABLE salary (team_id VARCHAR(255), salary INTEGER)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2148 }
Find the players' first name and last name who won award both in 1960 and in 1961.
SELECT T1.name_first, T1.name_last FROM player AS T1 JOIN player_award AS T2 WHERE T2.year = 1960 INTERSECT SELECT T1.name_first, T1.name_last FROM player AS T1 JOIN player_award AS T2 WHERE T2.year = 1961
CREATE TABLE player (name_first VARCHAR(255), name_last VARCHAR(255)); CREATE TABLE player_award (year VARCHAR(255), player_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
1
{ "split": "train", "row_index": 2149 }
List players' first name and last name who have weight greater than 220 or height shorter than 75.
SELECT name_first, name_last FROM player WHERE weight > 220 OR height < 75
CREATE TABLE player (name_first VARCHAR(255), name_last VARCHAR(255), weight VARCHAR(255), height VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2150 }
List the maximum scores of the team Boston Red Stockings when the team won in postseason?
SELECT MAX(T1.wins) FROM postseason AS T1 JOIN team AS T2 ON T1.team_id_winner = T2.team_id_br WHERE T2.name = 'Boston Red Stockings'
CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255)); CREATE TABLE postseason (wins INTEGER, team_id_winner VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2151 }
How many times did Boston Red Stockings lose in 2009 postseason?
SELECT COUNT(*) FROM postseason AS T1 JOIN team AS T2 ON T1.team_id_loser = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year = 2009
CREATE TABLE postseason (team_id_loser VARCHAR(255), year VARCHAR(255)); CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2152 }
What are the name and id of the team with the most victories in 2008 postseason?
SELECT T2.name, T1.team_id_winner FROM postseason AS T1 JOIN team AS T2 ON T1.team_id_winner = T2.team_id_br WHERE T1.year = 2008 GROUP BY T1.team_id_winner ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE postseason (team_id_winner VARCHAR(255), year VARCHAR(255)); CREATE TABLE team (name VARCHAR(255), team_id_br VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
5
0
1
{ "split": "train", "row_index": 2153 }
What is the number of wins the team Boston Red Stockings got in the postseasons each year in history?
SELECT COUNT(*), T1.year FROM postseason AS T1 JOIN team AS T2 ON T1.team_id_winner = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' GROUP BY T1.year
CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255)); CREATE TABLE postseason (year VARCHAR(255), team_id_winner VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2154 }
How many games in 1885 postseason resulted in ties (that is, the value of "ties" is '1')?
SELECT COUNT(*) FROM postseason WHERE YEAR = 1885 AND ties = 1
CREATE TABLE postseason (YEAR VARCHAR(255), ties VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2156 }
What is the total salary paid by team Boston Red Stockings in 2010?
SELECT SUM(T1.salary) FROM salary AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year = 2010
CREATE TABLE salary (salary INTEGER, team_id VARCHAR(255), year VARCHAR(255)); CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2157 }
How many players were in the team Boston Red Stockings in 2000?
SELECT COUNT(*) FROM salary AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year = 2000
CREATE TABLE salary (team_id VARCHAR(255), year VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2158 }
List the 3 highest salaries of the players in 2001?
SELECT salary FROM salary WHERE YEAR = 2001 ORDER BY salary DESC LIMIT 3
CREATE TABLE salary (salary VARCHAR(255), YEAR VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2159 }
What were all the salary values of players in 2010 and 2001?
SELECT salary FROM salary WHERE YEAR = 2010 UNION SELECT salary FROM salary WHERE YEAR = 2001
CREATE TABLE salary (salary VARCHAR(255), YEAR VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2160 }
In which year did the least people enter hall of fame?
SELECT yearid FROM hall_of_fame GROUP BY yearid ORDER BY COUNT(*) LIMIT 1
CREATE TABLE hall_of_fame (yearid VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2161 }
How many parks are there in Atlanta city?
SELECT COUNT(*) FROM park WHERE city = 'Atlanta'
CREATE TABLE park (city VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2162 }
How many games were played in park "Columbia Park" in 1907?
SELECT COUNT(*) FROM home_game AS T1 JOIN park AS T2 ON T1.park_id = T2.park_id WHERE T1.year = 1907 AND T2.park_name = 'Columbia Park'
CREATE TABLE park (park_id VARCHAR(255), park_name VARCHAR(255)); CREATE TABLE home_game (park_id VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2163 }
How many games were played in city Atlanta in 2000?
SELECT COUNT(*) FROM home_game AS T1 JOIN park AS T2 ON T1.park_id = T2.park_id WHERE T1.year = 2000 AND T2.city = 'Atlanta'
CREATE TABLE park (park_id VARCHAR(255), city VARCHAR(255)); CREATE TABLE home_game (park_id VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2164 }
What is the total home game attendance of team Boston Red Stockings from 2000 to 2010?
SELECT SUM(T1.attendance) FROM home_game AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year BETWEEN 2000 AND 2010
CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255)); CREATE TABLE home_game (attendance INTEGER, team_id VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2165 }
How much did the the player with first name Len and last name Barker earn between 1985 to 1990 in total?
SELECT SUM(T1.salary) FROM salary AS T1 JOIN player AS T2 ON T1.player_id = T2.player_id WHERE T2.name_first = 'Len' AND T2.name_last = 'Barker' AND T1.year BETWEEN 1985 AND 1990
CREATE TABLE salary (salary INTEGER, player_id VARCHAR(255), year VARCHAR(255)); CREATE TABLE player (player_id VARCHAR(255), name_first VARCHAR(255), name_last VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2166 }
List players' first name and last name who received salary from team Washington Nationals in both 2005 and 2007.
SELECT T2.name_first, T2.name_last FROM salary AS T1 JOIN player AS T2 ON T1.player_id = T2.player_id JOIN team AS T3 ON T3.team_id_br = T1.team_id WHERE T1.year = 2005 AND T3.name = 'Washington Nationals' INTERSECT SELECT T2.name_first, T2.name_last FROM salary AS T1 JOIN player AS T2 ON T1.player_id = T2.player_id JO...
CREATE TABLE player (name_first VARCHAR(255), name_last VARCHAR(255), player_id VARCHAR(255)); CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255)); CREATE TABLE salary (player_id VARCHAR(255), team_id VARCHAR(255), year VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
2
{ "split": "train", "row_index": 2167 }
How many home games did the team Boston Red Stockings play from 1990 to 2000 in total?
SELECT SUM(T1.games) FROM home_game AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year BETWEEN 1990 AND 2000
CREATE TABLE team (team_id_br VARCHAR(255), name VARCHAR(255)); CREATE TABLE home_game (games INTEGER, team_id VARCHAR(255), year VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2168 }
Which team had the least number of attendances in home games in 1980?
SELECT T2.name FROM home_game AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T1.year = 1980 ORDER BY T1.attendance LIMIT 1
CREATE TABLE home_game (team_id VARCHAR(255), year VARCHAR(255), attendance VARCHAR(255)); CREATE TABLE team (name VARCHAR(255), team_id_br VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2169 }
List the names of states that have more than 2 parks.
SELECT state FROM park GROUP BY state HAVING COUNT(*) > 2
CREATE TABLE park (state VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2170 }
How many team franchises are active, with active value 'Y'?
SELECT COUNT(*) FROM team_franchise WHERE active = 'Y'
CREATE TABLE team_franchise (active VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2171 }
Which cities have 2 to 4 parks?
SELECT city FROM park GROUP BY city HAVING COUNT(*) BETWEEN 2 AND 4
CREATE TABLE park (city VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2172 }
Which park had most attendances in 2008?
SELECT T2.park_name FROM home_game AS T1 JOIN park AS T2 ON T1.park_id = T2.park_id WHERE T1.year = 2008 ORDER BY T1.attendance DESC LIMIT 1
CREATE TABLE park (park_name VARCHAR(255), park_id VARCHAR(255)); CREATE TABLE home_game (park_id VARCHAR(255), year VARCHAR(255), attendance VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2173 }
How many camera lenses have a focal length longer than 15 mm?
SELECT COUNT(*) FROM camera_lens WHERE focal_length_mm > 15
CREATE TABLE camera_lens (focal_length_mm INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2174 }
Find the brand and name for each camera lens, and sort in descending order of maximum aperture.
SELECT brand, name FROM camera_lens ORDER BY max_aperture DESC
CREATE TABLE camera_lens (brand VARCHAR(255), name VARCHAR(255), max_aperture VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2175 }
List the id, color scheme, and name for all the photos.
SELECT id, color, name FROM photos
CREATE TABLE photos (id VARCHAR(255), color VARCHAR(255), name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2176 }
What are the maximum and average height of the mountains?
SELECT MAX(height), AVG(height) FROM mountain
CREATE TABLE mountain (height INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 2177 }
What are the average prominence of the mountains in country 'Morocco'?
SELECT AVG(prominence) FROM mountain WHERE country = 'Morocco'
CREATE TABLE mountain (prominence INTEGER, country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2178 }
What are the name, height and prominence of mountains which do not belong to the range 'Aberdare Range'?
SELECT name, height, prominence FROM mountain WHERE range <> 'Aberdare Range'
CREATE TABLE mountain (name VARCHAR(255), height VARCHAR(255), prominence VARCHAR(255), range VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2179 }
What are the id and name of the photos for mountains?
SELECT T1.id, T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id WHERE T1.height > 4000
CREATE TABLE photos (mountain_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE mountain (id VARCHAR(255), name VARCHAR(255), height INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2180 }
What are the id and name of the mountains that have at least 2 photos?
SELECT T1.id, T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id GROUP BY T1.id HAVING COUNT(*) >= 2
CREATE TABLE mountain (id VARCHAR(255), name VARCHAR(255)); CREATE TABLE photos (mountain_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2181 }
What are the names of the cameras that have taken picture of the most mountains?
SELECT T2.name FROM photos AS T1 JOIN camera_lens AS T2 ON T1.camera_lens_id = T2.id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE camera_lens (name VARCHAR(255), id VARCHAR(255)); CREATE TABLE photos (camera_lens_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2182 }
What are the names of photos taken with the lens brand 'Sigma' or 'Olympus'?
SELECT T1.name FROM camera_lens AS T1 JOIN photos AS T2 ON T2.camera_lens_id = T1.id WHERE T1.brand = 'Sigma' OR T1.brand = 'Olympus'
CREATE TABLE photos (camera_lens_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE camera_lens (name VARCHAR(255), id VARCHAR(255), brand VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2183 }
How many different kinds of lens brands are there?
SELECT COUNT(DISTINCT brand) FROM camera_lens
CREATE TABLE camera_lens (brand VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2184 }
How many camera lenses are not used in taking any photos?
SELECT COUNT(*) FROM camera_lens WHERE NOT id IN (SELECT camera_lens_id FROM photos)
CREATE TABLE photos (id VARCHAR(255), camera_lens_id VARCHAR(255)); CREATE TABLE camera_lens (id VARCHAR(255), camera_lens_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2185 }
How many distinct kinds of camera lenses are used to take photos of mountains in the country 'Ethiopia'?
SELECT COUNT(DISTINCT T2.camera_lens_id) FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id WHERE T1.country = 'Ethiopia'
CREATE TABLE mountain (id VARCHAR(255), country VARCHAR(255)); CREATE TABLE photos (camera_lens_id VARCHAR(255), mountain_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2186 }
List the brands of lenses that took both a picture of mountains with range 'Toubkal Atlas' and a picture of mountains with range 'Lasta Massif'
SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id = T3.id WHERE T1.range = 'Toubkal Atlas' INTERSECT SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id = T3.id WHERE T1.rang...
CREATE TABLE mountain (id VARCHAR(255), range VARCHAR(255)); CREATE TABLE photos (mountain_id VARCHAR(255), camera_lens_id VARCHAR(255)); CREATE TABLE camera_lens (brand VARCHAR(255), id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 2187 }
List the camera lens names containing substring "Digital".
SELECT name FROM camera_lens WHERE name LIKE '%Digital%'
CREATE TABLE camera_lens (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2189 }
What is the name of each camera lens and the number of photos taken by it? Order the result by the count of photos.
SELECT T1.name, COUNT(*) FROM camera_lens AS T1 JOIN photos AS T2 ON T1.id = T2.camera_lens_id GROUP BY T1.id ORDER BY COUNT(*)
CREATE TABLE photos (camera_lens_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE camera_lens (name VARCHAR(255), id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2190 }
Find the names of channels that are not owned by CCTV.
SELECT name FROM channel WHERE OWNER <> 'CCTV'
CREATE TABLE channel (name VARCHAR(255), OWNER VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2191 }
List all channel names ordered by their rating in percent from big to small.
SELECT name FROM channel ORDER BY rating_in_percent DESC
CREATE TABLE channel (name VARCHAR(255), rating_in_percent VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2192 }
What is the owner of the channel that has the highest rating ratio?
SELECT OWNER FROM channel ORDER BY rating_in_percent DESC LIMIT 1
CREATE TABLE channel (OWNER VARCHAR(255), rating_in_percent VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2193 }
how many programs are there?
SELECT COUNT(*) FROM program
CREATE TABLE program (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2194 }
list all the names of programs, ordering by launch time.
SELECT name FROM program ORDER BY launch
CREATE TABLE program (name VARCHAR(255), launch VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2195 }
List the name, origin and owner of each program.
SELECT name, origin, OWNER FROM program
CREATE TABLE program (name VARCHAR(255), origin VARCHAR(255), OWNER VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2196 }
find the name of the program that was launched most recently.
SELECT name FROM program ORDER BY launch DESC LIMIT 1
CREATE TABLE program (name VARCHAR(255), launch VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2197 }
find the total percentage share of all channels owned by CCTV.
SELECT SUM(Share_in_percent) FROM channel WHERE OWNER = 'CCTV'
CREATE TABLE channel (Share_in_percent INTEGER, OWNER VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2198 }
Find the names of the channels that are broadcast in the morning.
SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning'
CREATE TABLE channel (name VARCHAR(255), channel_id VARCHAR(255)); CREATE TABLE broadcast (channel_id VARCHAR(255), time_of_day VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2199 }
what are the names of the channels that broadcast in both morning and night?
SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning' INTERSECT SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Night'
CREATE TABLE channel (name VARCHAR(255), channel_id VARCHAR(255)); CREATE TABLE broadcast (channel_id VARCHAR(255), time_of_day VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 2200 }
how many programs are broadcast in each time section of the day?
SELECT COUNT(*), time_of_day FROM broadcast GROUP BY time_of_day
CREATE TABLE broadcast (time_of_day VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2201 }
find the number of different programs that are broadcast during night time.
SELECT COUNT(DISTINCT program_id) FROM broadcast WHERE time_of_day = 'Night'
CREATE TABLE broadcast (program_id VARCHAR(255), time_of_day VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2202 }
find the program owners that have some programs in both morning and night time.
SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = 'Morning' INTERSECT SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = 'Night'
CREATE TABLE broadcast (program_id VARCHAR(255), Time_of_day VARCHAR(255)); CREATE TABLE program (owner VARCHAR(255), program_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 2204 }
List all program origins in the alphabetical order.
SELECT origin FROM program ORDER BY origin
CREATE TABLE program (origin VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2205 }
what is the number of different channel owners?
SELECT COUNT(DISTINCT OWNER) FROM channel
CREATE TABLE channel (OWNER VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2206 }
find the names of programs whose origin is not in Beijing.
SELECT name FROM program WHERE origin <> 'Beijing'
CREATE TABLE program (name VARCHAR(255), origin VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2207 }
What are the names of the channels owned by CCTV or HBS?
SELECT name FROM channel WHERE OWNER = 'CCTV' OR OWNER = 'HBS'
CREATE TABLE channel (name VARCHAR(255), OWNER VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2208 }
Find the total rating ratio for each channel owner.
SELECT SUM(Rating_in_percent), OWNER FROM channel GROUP BY OWNER
CREATE TABLE channel (OWNER VARCHAR(255), Rating_in_percent INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2209 }
Find the name of the program that is broadcast most frequently.
SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id GROUP BY t2.program_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE program (name VARCHAR(255), program_id VARCHAR(255)); CREATE TABLE broadcast (program_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2210 }
How many courses are there in total?
SELECT COUNT(*) FROM COURSES
CREATE TABLE COURSES (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2211 }
What are the descriptions of the courses with name "database"?
SELECT course_description FROM COURSES WHERE course_name = 'database'
CREATE TABLE COURSES (course_description VARCHAR(255), course_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2212 }
What are the addresses of the course authors or tutors with personal name "Cathrine"
SELECT address_line_1 FROM Course_Authors_and_Tutors WHERE personal_name = 'Cathrine'
CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR(255), personal_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2213 }
List the addresses of all the course authors or tutors.
SELECT address_line_1 FROM Course_Authors_and_Tutors
CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR(255), personal_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2214 }
List all the login names and family names of course author and tutors.
SELECT login_name, family_name FROM Course_Authors_and_Tutors
CREATE TABLE Course_Authors_and_Tutors (login_name VARCHAR(255), family_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2215 }
List all the dates of enrollment and completion of students.
SELECT date_of_enrolment, date_of_completion FROM Student_Course_Enrolment
CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR(255), date_of_completion VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2216 }
How many distinct students are enrolled in courses?
SELECT COUNT(DISTINCT student_id) FROM Student_Course_Enrolment
CREATE TABLE Student_Course_Enrolment (student_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2217 }
How many distinct courses are enrolled in by students?
SELECT COUNT(course_id) FROM Student_Course_Enrolment
CREATE TABLE Student_Course_Enrolment (course_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2218 }
Find the dates of the tests taken with result "Pass".
SELECT date_test_taken FROM Student_Tests_Taken WHERE test_result = 'Pass'
CREATE TABLE Student_Tests_Taken (date_test_taken VARCHAR(255), test_result VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2219 }
How many tests have result "Fail"?
SELECT COUNT(*) FROM Student_Tests_Taken WHERE test_result = 'Fail'
CREATE TABLE Student_Tests_Taken (test_result VARCHAR(255), date_test_taken VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2220 }
What are the login names of the students with family name "Ward"?
SELECT login_name FROM Students WHERE family_name = 'Ward'
CREATE TABLE Students (login_name VARCHAR(255), family_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2221 }
What are the dates of the latest logon of the students with family name "Jaskolski" or "Langosh"?
SELECT date_of_latest_logon FROM Students WHERE family_name = 'Jaskolski' OR family_name = 'Langosh'
CREATE TABLE Students (date_of_latest_logon VARCHAR(255), family_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2222 }
How many students have personal names that contain the word "son"?
SELECT COUNT(*) FROM Students WHERE personal_name LIKE '%son%'
CREATE TABLE Students (personal_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2223 }
List all the subject names.
SELECT subject_name FROM SUBJECTS
CREATE TABLE SUBJECTS (subject_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2224 }
List the personal names and family names of all the students in alphabetical order of family name.
SELECT personal_name, family_name FROM Students ORDER BY family_name
CREATE TABLE Students (personal_name VARCHAR(255), family_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2226 }
List each test result and its count in descending order of count.
SELECT test_result, COUNT(*) FROM Student_Tests_Taken GROUP BY test_result ORDER BY COUNT(*) DESC
CREATE TABLE Student_Tests_Taken (test_result VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2227 }
Find the login name of the course author that teaches the course with name "advanced database".
SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id WHERE T2.course_name = 'advanced database'
CREATE TABLE Courses (author_id VARCHAR(255), course_name VARCHAR(255)); CREATE TABLE Course_Authors_and_Tutors (login_name VARCHAR(255), author_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2228 }
Find the addresses of the course authors who teach the course with name "operating system" or "data structure".
SELECT T1.address_line_1 FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id WHERE T2.course_name = 'operating system' OR T2.course_name = 'data structure'
CREATE TABLE Courses (author_id VARCHAR(255), course_name VARCHAR(255)); CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR(255), author_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2229 }
Find the personal name, family name, and author ID of the course author that teaches the most courses.
SELECT T1.personal_name, T1.family_name, T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Courses (author_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR(255), family_name VARCHAR(255), author_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2230 }
Find the addresses and author IDs of the course authors that teach at least two courses.
SELECT T1.address_line_1, T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id GROUP BY T2.author_id HAVING COUNT(*) >= 2
CREATE TABLE Courses (author_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Course_Authors_and_Tutors (address_line_1 VARCHAR(255), author_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2231 }
Find the names of courses taught by the tutor who has personal name "Julio".
SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id WHERE T1.personal_name = 'Julio'
CREATE TABLE Course_Authors_and_Tutors (author_id VARCHAR(255), personal_name VARCHAR(255)); CREATE TABLE Courses (course_name VARCHAR(255), author_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2232 }
Find the names and descriptions of courses that belong to the subject named "Computer Science".
SELECT T1.course_name, T1.course_description FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id = T2.subject_id WHERE T2.subject_name = 'Computer Science'
CREATE TABLE Courses (course_name VARCHAR(255), course_description VARCHAR(255), subject_id VARCHAR(255)); CREATE TABLE Subjects (subject_id VARCHAR(255), subject_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2233 }
Find the subject ID, subject name, and the corresponding number of available courses for each subject.
SELECT T1.subject_id, T2.subject_name, COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id = T2.subject_id GROUP BY T1.subject_id
CREATE TABLE Courses (subject_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Subjects (subject_name VARCHAR(255), subject_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2234 }
Find the subject ID, name of subject and the corresponding number of courses for each subject, and sort by the course count in ascending order.
SELECT T1.subject_id, T2.subject_name, COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id = T2.subject_id GROUP BY T1.subject_id ORDER BY COUNT(*)
CREATE TABLE Courses (subject_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Subjects (subject_name VARCHAR(255), subject_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2235 }
What is the date of enrollment of the course named "Spanish"?
SELECT T2.date_of_enrolment FROM Courses AS T1 JOIN Student_Course_Enrolment AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = 'Spanish'
CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Courses (course_id VARCHAR(255), course_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2236 }
What is the name of the course that has the most student enrollment?
SELECT T1.course_name FROM Courses AS T1 JOIN Student_Course_Enrolment AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (course_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2237 }
What are the names of the courses that have exactly 1 student enrollment?
SELECT T1.course_name FROM Courses AS T1 JOIN Student_Course_Enrolment AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name HAVING COUNT(*) = 1
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (course_id VARCHAR(255), student_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2238 }
What are the descriptions and names of the courses that have student enrollment bigger than 2?
SELECT T1.course_description, T1.course_name FROM Courses AS T1 JOIN Student_Course_Enrolment AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name HAVING COUNT(*) > 2
CREATE TABLE Student_Course_Enrolment (course_id VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Courses (course_description VARCHAR(255), course_name VARCHAR(255), course_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2239 }
What is the name of each course and the corresponding number of student enrollment?
SELECT T1.course_name, COUNT(*) FROM Courses AS T1 JOIN Student_Course_Enrolment AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name
CREATE TABLE Courses (course_name VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (course_id VARCHAR(255), student_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2240 }
What are the enrollment dates of all the tests that have result "Pass"?
SELECT T1.date_of_enrolment FROM Student_Course_Enrolment AS T1 JOIN Student_Tests_Taken AS T2 ON T1.registration_id = T2.registration_id WHERE T2.test_result = 'Pass'
CREATE TABLE Student_Tests_Taken (registration_id VARCHAR(255), test_result VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR(255), registration_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2241 }
What are the completion dates of all the tests that have result "Fail"?
SELECT T1.date_of_completion FROM Student_Course_Enrolment AS T1 JOIN Student_Tests_Taken AS T2 ON T1.registration_id = T2.registration_id WHERE T2.test_result = 'Fail'
CREATE TABLE Student_Tests_Taken (registration_id VARCHAR(255), test_result VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (date_of_completion VARCHAR(255), registration_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2242 }
List the dates of enrollment and completion of the student with personal name "Karson".
SELECT T1.date_of_enrolment, T1.date_of_completion FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.personal_name = 'Karson'
CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR(255), date_of_completion VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Students (student_id VARCHAR(255), personal_name VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2243 }
List the dates of enrollment and completion of the student with family name "Zieme" and personal name "Bernie".
SELECT T1.date_of_enrolment, T1.date_of_completion FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.family_name = 'Zieme' AND T2.personal_name = 'Bernie'
CREATE TABLE Student_Course_Enrolment (date_of_enrolment VARCHAR(255), date_of_completion VARCHAR(255), student_id VARCHAR(255)); CREATE TABLE Students (student_id VARCHAR(255), family_name VARCHAR(255), personal_name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2244 }
Find the student ID and login name of the student with the most course enrollments
SELECT T1.student_id, T2.login_name FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student_Course_Enrolment (student_id VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Students (login_name VARCHAR(255), student_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2245 }
Find the student ID and personal name of the student with at least two enrollments.
SELECT T1.student_id, T2.personal_name FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) >= 2
CREATE TABLE Student_Course_Enrolment (student_id VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Students (personal_name VARCHAR(255), student_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2246 }
Find the student ID and middle name for all the students with at most two enrollments.
SELECT T1.student_id, T2.middle_name FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) <= 2
CREATE TABLE Student_Course_Enrolment (student_id VARCHAR(255), course_id VARCHAR(255)); CREATE TABLE Students (middle_name VARCHAR(255), student_id VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2247 }
How many students did not have any course enrollment?
SELECT COUNT(*) FROM Students WHERE NOT student_id IN (SELECT student_id FROM Student_Course_Enrolment)
CREATE TABLE Students (student_id VARCHAR(255), name VARCHAR(255)); CREATE TABLE Student_Course_Enrolment (student_id VARCHAR(255), course_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2249 }