question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
Find the common login name of course authors and students.
SELECT login_name FROM Course_Authors_and_Tutors INTERSECT SELECT login_name FROM Students
CREATE TABLE Course_Authors_and_Tutors (login_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Students (login_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 2250 }
Find the common personal name of course authors and students.
SELECT personal_name FROM Course_Authors_and_Tutors INTERSECT SELECT personal_name FROM Students
CREATE TABLE Course_Authors_and_Tutors (personal_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Students (personal_name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 2251 }
List the method, date and amount of all the payments, in ascending order of date.
SELECT Payment_Method_Code, Date_Payment_Made, Amount_Payment FROM Payments ORDER BY Date_Payment_Made
CREATE TABLE Payments (Payment_Method_Code VARCHAR(255), Date_Payment_Made VARCHAR(255), Amount_Payment VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2254 }
Among all the claims, what is the settlement amount of the claim with the largest claim amount? List both the settlement amount and claim amount.
SELECT Amount_Settled, Amount_Claimed FROM Claims ORDER BY Amount_Claimed DESC LIMIT 1
CREATE TABLE Claims (Amount_Settled VARCHAR(255), Amount_Claimed VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2255 }
Among all the claims, what is the amount claimed in the claim with the least amount settled? List both the settlement amount and claim amount.
SELECT Amount_Settled, Amount_Claimed FROM Claims ORDER BY Amount_Settled LIMIT 1
CREATE TABLE Claims (Amount_Settled VARCHAR(255), Amount_Claimed VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2256 }
Among all the claims, which claims have a claimed amount larger than the average? List the date the claim was made and the date it was settled.
SELECT Date_Claim_Made, Date_Claim_Settled FROM Claims WHERE Amount_Claimed > (SELECT AVG(Amount_Claimed) FROM Claims)
CREATE TABLE Claims (Date_Claim_Made VARCHAR(255), Date_Claim_Settled VARCHAR(255), Amount_Claimed INTEGER)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2257 }
Among all the claims, which settlements have a claimed amount that is no more than the average? List the claim start date.
SELECT Date_Claim_Made FROM Claims WHERE Amount_Settled <= (SELECT AVG(Amount_Settled) FROM Claims)
CREATE TABLE Claims (Date_Claim_Made VARCHAR(255), Amount_Settled INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2258 }
Which claim incurred the most number of settlements? List the claim id, the date the claim was made, and the number.
SELECT T1.claim_id, T1.date_claim_made, COUNT(*) FROM Claims AS T1 JOIN Settlements AS T2 ON T1.claim_id = T2.claim_id GROUP BY T1.claim_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Claims (claim_id VARCHAR(255), date_claim_made VARCHAR(255)); CREATE TABLE Settlements (claim_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 2260 }
How many settlements were made on the claim with the most recent claim settlement date? List the number and the claim id.
SELECT COUNT(*), T1.claim_id FROM Claims AS T1 JOIN Settlements AS T2 ON T1.claim_id = T2.claim_id GROUP BY T1.claim_id ORDER BY T1.Date_Claim_Settled DESC LIMIT 1
CREATE TABLE Settlements (claim_id VARCHAR(255)); CREATE TABLE Claims (claim_id VARCHAR(255), Date_Claim_Settled VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2261 }
Of all the claims, what was the earliest date when any claim was made?
SELECT Date_Claim_Made FROM Claims ORDER BY Date_Claim_Made LIMIT 1
CREATE TABLE Claims (Date_Claim_Made VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2262 }
What is the total amount of settlement made for all the settlements?
SELECT SUM(Amount_Settled) FROM Settlements
CREATE TABLE Settlements (Amount_Settled INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2263 }
What are the claim dates and settlement dates of all the settlements?
SELECT Date_Claim_Made, Date_Claim_Settled FROM Settlements
CREATE TABLE Settlements (Date_Claim_Made VARCHAR(255), Date_Claim_Settled VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2265 }
What is the most popular payment method?
SELECT Payment_Method_Code FROM Payments GROUP BY Payment_Method_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Payments (Payment_Method_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2266 }
With which kind of payment method were the least number of payments processed?
SELECT Payment_Method_Code FROM Payments GROUP BY Payment_Method_Code ORDER BY COUNT(*) LIMIT 1
CREATE TABLE Payments (Payment_Method_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2267 }
What is the total amount of payment?
SELECT SUM(Amount_Payment) FROM Payments
CREATE TABLE Payments (Amount_Payment INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2268 }
What are all the distinct details of the customers?
SELECT DISTINCT customer_details FROM Customers
CREATE TABLE Customers (customer_details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2269 }
Which kind of policy type was chosen by the most customers?
SELECT Policy_Type_Code FROM Customer_Policies GROUP BY Policy_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Customer_Policies (Policy_Type_Code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2270 }
How many settlements are there in total?
SELECT COUNT(*) FROM Settlements
CREATE TABLE Settlements (Id VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2271 }
Which Payments were processed with Visa? List the payment Id, the date and the amount.
SELECT Payment_ID, Date_Payment_Made, Amount_Payment FROM Payments WHERE Payment_Method_Code = 'Visa'
CREATE TABLE Payments (Payment_ID VARCHAR(255), Date_Payment_Made VARCHAR(255), Amount_Payment VARCHAR(255), Payment_Method_Code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2272 }
Find the total claimed amount of all the claims.
SELECT SUM(Amount_Claimed) FROM Claims
CREATE TABLE Claims (Amount_Claimed INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2275 }
Which department has the largest number of employees?
SELECT name FROM department GROUP BY departmentID ORDER BY COUNT(departmentID) DESC LIMIT 1
CREATE TABLE department (name VARCHAR(255), departmentID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2276 }
What is the employee id of the head whose department has the least number of employees?
SELECT head FROM department GROUP BY departmentID ORDER BY COUNT(departmentID) LIMIT 1
CREATE TABLE department (head VARCHAR(255), departmentID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2277 }
Find the id of the appointment with the most recent start date?
SELECT appointmentid FROM appointment ORDER BY START DESC LIMIT 1
CREATE TABLE appointment (appointmentid VARCHAR(255), START VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2281 }
List the name of physicians who took some appointment.
SELECT T2.name FROM appointment AS T1 JOIN physician AS T2 ON T1.Physician = T2.EmployeeID
CREATE TABLE appointment (Physician VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE physician (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2282 }
Find the names of all physicians and their primary affiliated departments' names.
SELECT T1.name, T3.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T2.PrimaryAffiliation = 1
CREATE TABLE department (name VARCHAR(255), DepartmentID VARCHAR(255)); CREATE TABLE affiliated_with (physician VARCHAR(255), department VARCHAR(255), PrimaryAffiliation VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2284 }
What is the name of the patient who made the most recent appointment?
SELECT T1.name FROM patient AS T1 JOIN appointment AS T2 ON T1.ssn = T2.patient ORDER BY T2.start DESC LIMIT 1
CREATE TABLE patient (name VARCHAR(255), ssn VARCHAR(255)); CREATE TABLE appointment (patient VARCHAR(255), start VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2285 }
How many patients stay in room 112?
SELECT COUNT(patient) FROM stay WHERE room = 112
CREATE TABLE stay (patient VARCHAR(255), room VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2286 }
How many patients' prescriptions are made by physician John Dorian?
SELECT COUNT(T1.SSN) FROM patient AS T1 JOIN prescribes AS T2 ON T1.SSN = T2.patient JOIN physician AS T3 ON T2.physician = T3.employeeid WHERE T3.name = 'John Dorian'
CREATE TABLE patient (SSN VARCHAR(255), name VARCHAR(255)); CREATE TABLE prescribes (patient VARCHAR(255), physician VARCHAR(255)); CREATE TABLE physician (employeeid VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2287 }
Find the patient who most recently stayed in room 111.
SELECT patient FROM stay WHERE room = 111 ORDER BY staystart DESC LIMIT 1
CREATE TABLE stay (patient VARCHAR(255), room VARCHAR(255), staystart VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2289 }
What is the name of the nurse has the most appointments?
SELECT T1.name FROM nurse AS T1 JOIN appointment AS T2 ON T1.employeeid = T2.prepnurse GROUP BY T1.employeeid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE nurse (name VARCHAR(255), employeeid VARCHAR(255)); CREATE TABLE appointment (prepnurse VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2290 }
How many patients do each physician take care of? List their names and number of patients they take care of.
SELECT T1.name, COUNT(*) FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid
CREATE TABLE patient (PCP VARCHAR(255), SSN VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2291 }
Find the name of physicians who are in charge of more than one patient.
SELECT T1.name FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid HAVING COUNT(*) > 1
CREATE TABLE patient (PCP VARCHAR(255), SSN VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2292 }
Find the number of rooms located on each block floor.
SELECT COUNT(*), T1.blockfloor FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockfloor
CREATE TABLE room (blockfloor VARCHAR(255), blockcode VARCHAR(255)); CREATE TABLE BLOCK (blockfloor VARCHAR(255), blockcode VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2293 }
Find the number of rooms for different block code?
SELECT COUNT(*), T1.blockcode FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockcode
CREATE TABLE room (blockfloor VARCHAR(255), blockcode VARCHAR(255)); CREATE TABLE BLOCK (blockcode VARCHAR(255), blockfloor VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2294 }
What are the unique block codes that have available rooms?
SELECT DISTINCT blockcode FROM room WHERE unavailable = 0
CREATE TABLE room (blockcode VARCHAR(255), unavailable VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2295 }
How many different types of rooms are there?
SELECT COUNT(DISTINCT roomtype) FROM room
CREATE TABLE room (roomtype VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2296 }
What is the names of the physicians who prescribe medication Thesisin?
SELECT DISTINCT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.name = 'Thesisin'
CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255)); CREATE TABLE prescribes (physician VARCHAR(255), medication VARCHAR(255)); CREATE TABLE medication (code VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2297 }
Find the name and position of physicians who prescribe some medication whose brand is X?
SELECT DISTINCT T1.name, T1.position FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.Brand = 'X'
CREATE TABLE medication (code VARCHAR(255), Brand VARCHAR(255)); CREATE TABLE prescribes (physician VARCHAR(255), medication VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), position VARCHAR(255), employeeid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2298 }
Find the number of medications prescribed for each brand.
SELECT COUNT(*), T1.name FROM medication AS T1 JOIN prescribes AS T2 ON T1.code = T2.medication GROUP BY T1.brand
CREATE TABLE medication (name VARCHAR(255), brand VARCHAR(255), code VARCHAR(255)); CREATE TABLE prescribes (medication VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2299 }
Find the name of physicians whose position title contains the word 'senior'.
SELECT name FROM physician WHERE POSITION LIKE '%senior%'
CREATE TABLE physician (name VARCHAR(255), POSITION VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2300 }
Find the patient who has the most recent undergoing treatment?
SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1
CREATE TABLE undergoes (patient VARCHAR(255), dateundergoes VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2301 }
Find the names of all patients who have an undergoing treatment and are staying in room 111.
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111
CREATE TABLE undergoes (patient VARCHAR(255), Stay VARCHAR(255)); CREATE TABLE stay (StayID VARCHAR(255), room VARCHAR(255)); CREATE TABLE patient (name VARCHAR(255), SSN VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2302 }
List the names of all distinct nurses ordered by alphabetical order?
SELECT DISTINCT name FROM nurse ORDER BY name
CREATE TABLE nurse (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2303 }
Find the names of nurses who are nursing an undergoing treatment.
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID
CREATE TABLE undergoes (AssistingNurse VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE nurse (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2304 }
List the names of all distinct medications, ordered in an alphabetical order.
SELECT DISTINCT name FROM medication ORDER BY name
CREATE TABLE medication (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2305 }
What are the names of the physician who prescribed the highest dose?
SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1
CREATE TABLE prescribes (physician VARCHAR(255), dose VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2306 }
List the physicians' employee ids together with their primary affiliation departments' ids.
SELECT physician, department FROM affiliated_with WHERE primaryaffiliation = 1
CREATE TABLE affiliated_with (physician VARCHAR(255), department VARCHAR(255), primaryaffiliation VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2307 }
What nurses are on call with block floor 1 and block code 1? Tell me their names.
SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1
CREATE TABLE on_call (nurse VARCHAR(255), blockfloor VARCHAR(255), blockcode VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2309 }
What are the highest cost, lowest cost and average cost of procedures?
SELECT MAX(cost), MIN(cost), AVG(cost) FROM procedures
CREATE TABLE procedures (cost INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
2
{ "split": "train", "row_index": 2310 }
List the name and cost of all procedures sorted by the cost from the highest to the lowest.
SELECT name, cost FROM procedures ORDER BY cost DESC
CREATE TABLE procedures (name VARCHAR(255), cost VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2311 }
Find the three most expensive procedures.
SELECT name FROM procedures ORDER BY cost LIMIT 3
CREATE TABLE procedures (name VARCHAR(255), cost VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2312 }
Find the physicians who are trained in a procedure that costs more than 5000.
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000
CREATE TABLE trained_in (physician VARCHAR(255), treatment VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255)); CREATE TABLE procedures (code VARCHAR(255), cost INTEGER)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2313 }
Find the physician who was trained in the most expensive procedure?
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1
CREATE TABLE trained_in (physician VARCHAR(255), treatment VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), employeeid VARCHAR(255)); CREATE TABLE procedures (code VARCHAR(255), cost VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2314 }
What is the average cost of procedures that physician John Wen was trained in?
SELECT AVG(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = 'John Wen'
CREATE TABLE trained_in (physician VARCHAR(255), treatment VARCHAR(255)); CREATE TABLE procedures (cost INTEGER, code VARCHAR(255)); CREATE TABLE physician (employeeid VARCHAR(255), name VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2315 }
Find the names of procedures which physician John Wen was trained in.
SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = 'John Wen'
CREATE TABLE trained_in (physician VARCHAR(255), treatment VARCHAR(255)); CREATE TABLE physician (employeeid VARCHAR(255), name VARCHAR(255)); CREATE TABLE procedures (name VARCHAR(255), code VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2316 }
Find the name of physicians who are affiliated with both Surgery and Psychiatry departments.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.departmen...
CREATE TABLE affiliated_with (physician VARCHAR(255), department VARCHAR(255)); CREATE TABLE department (DepartmentID VARCHAR(255), name VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 2320 }
Find the name of physicians who are affiliated with Surgery or Psychiatry department.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'
CREATE TABLE affiliated_with (physician VARCHAR(255), department VARCHAR(255)); CREATE TABLE department (DepartmentID VARCHAR(255), name VARCHAR(255)); CREATE TABLE physician (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2321 }
Find the number of patients who are not using the medication of Procrastin-X.
SELECT COUNT(*) FROM patient WHERE NOT SSN IN (SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X')
CREATE TABLE Prescribes (patient VARCHAR(255), Medication VARCHAR(255)); CREATE TABLE patient (SSN VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Medication (Code VARCHAR(255), name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2323 }
How many appointments are there?
SELECT COUNT(*) FROM appointment
CREATE TABLE appointment (Id VARCHAR(255), details VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2324 }
Find the names of nurses who are on call.
SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse
CREATE TABLE on_call (nurse VARCHAR(255), shift VARCHAR(255)); CREATE TABLE nurse (name VARCHAR(255), EmployeeID VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2325 }
How many ships are there?
SELECT COUNT(*) FROM ship
CREATE TABLE ship (Id VARCHAR(255), Name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2326 }
List the name of ships in ascending order of tonnage.
SELECT Name FROM ship ORDER BY Tonnage
CREATE TABLE ship (Name VARCHAR(255), Tonnage VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2327 }
What are the type and nationality of ships?
SELECT TYPE, Nationality FROM ship
CREATE TABLE ship (TYPE VARCHAR(255), Nationality VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2328 }
List the name of ships whose nationality is not "United States".
SELECT Name FROM ship WHERE Nationality <> 'United States'
CREATE TABLE ship (Name VARCHAR(255), Nationality VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2329 }
Show the name of ships whose nationality is either United States or United Kingdom.
SELECT Name FROM ship WHERE Nationality = 'United States' OR Nationality = 'United Kingdom'
CREATE TABLE ship (Name VARCHAR(255), Nationality VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2330 }
What is the name of the ship with the largest tonnage?
SELECT Name FROM ship ORDER BY Tonnage DESC LIMIT 1
CREATE TABLE ship (Name VARCHAR(255), Tonnage VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2331 }
Show different types of ships and the number of ships of each type.
SELECT TYPE, COUNT(*) FROM ship GROUP BY TYPE
CREATE TABLE ship (TYPE VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2332 }
Please show the most common type of ships.
SELECT TYPE FROM ship GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE ship (TYPE VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2333 }
List the nations that have more than two ships.
SELECT Nationality FROM ship GROUP BY Nationality HAVING COUNT(*) > 2
CREATE TABLE ship (Nationality VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2334 }
Show different types of ships and the average tonnage of ships of each type.
SELECT TYPE, AVG(Tonnage) FROM ship GROUP BY TYPE
CREATE TABLE ship (TYPE VARCHAR(255), Tonnage INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2335 }
Show codes and fates of missions, and names of ships involved.
SELECT T1.Code, T1.Fate, T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID
CREATE TABLE mission (Code VARCHAR(255), Fate VARCHAR(255), Ship_ID VARCHAR(255)); CREATE TABLE ship (Name VARCHAR(255), Ship_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2336 }
Show names of ships involved in a mission launched after 1928.
SELECT T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T1.Launched_Year > 1928
CREATE TABLE mission (Ship_ID VARCHAR(255), Launched_Year INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE ship (Name VARCHAR(255), Ship_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2337 }
Show the distinct fate of missions that involve ships with nationality "United States"
SELECT DISTINCT T1.Fate FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T2.Nationality = 'United States'
CREATE TABLE mission (Fate VARCHAR(255), Ship_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE ship (Ship_ID VARCHAR(255), Nationality VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2338 }
List the name of ships that are not involved in any mission
SELECT Name FROM ship WHERE NOT Ship_ID IN (SELECT Ship_ID FROM mission)
CREATE TABLE mission (Name VARCHAR(255), Ship_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE ship (Name VARCHAR(255), Ship_ID VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2339 }
Show the types of ships that have both ships with tonnage larger than 6000 and ships with tonnage smaller than 4000.
SELECT TYPE FROM ship WHERE Tonnage > 6000 INTERSECT SELECT TYPE FROM ship WHERE Tonnage < 4000
CREATE TABLE ship (TYPE VARCHAR(255), Tonnage INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2340 }
Find the number of students in total.
SELECT COUNT(*) FROM list
CREATE TABLE list (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2341 }
Find the last names of students studying in room 111.
SELECT lastname FROM list WHERE classroom = 111
CREATE TABLE list (lastname VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2342 }
Find the first names of students studying in room 108.
SELECT firstname FROM list WHERE classroom = 108
CREATE TABLE list (firstname VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2343 }
What are the first names of students studying in room 107?
SELECT DISTINCT firstname FROM list WHERE classroom = 107
CREATE TABLE list (firstname VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2344 }
For each classroom report the grade that is taught in it. Report just the classroom number and the grade number.
SELECT DISTINCT classroom, grade FROM list
CREATE TABLE list (classroom VARCHAR(255), grade VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2345 }
Which grade is studying in classroom 103?
SELECT DISTINCT grade FROM list WHERE classroom = 103
CREATE TABLE list (grade VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2346 }
Find the grade studying in room 105.
SELECT DISTINCT grade FROM list WHERE classroom = 105
CREATE TABLE list (grade VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2347 }
Which classrooms are used by grade 4?
SELECT DISTINCT classroom FROM list WHERE grade = 4
CREATE TABLE list (classroom VARCHAR(255), grade VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2348 }
Which classrooms are used by grade 5?
SELECT DISTINCT classroom FROM list WHERE grade = 5
CREATE TABLE list (classroom VARCHAR(255), grade VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2349 }
Find the first names of all the teachers that teach in classroom 110.
SELECT firstname FROM teachers WHERE classroom = 110
CREATE TABLE teachers (firstname VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2352 }
Find the last names of teachers teaching in classroom 109.
SELECT lastname FROM teachers WHERE classroom = 109
CREATE TABLE teachers (lastname VARCHAR(255), classroom VARCHAR(255), firstname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2353 }
Report the first name and last name of all the teachers.
SELECT DISTINCT firstname, lastname FROM teachers
CREATE TABLE teachers (firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2354 }
Report the first name and last name of all the students.
SELECT DISTINCT firstname, lastname FROM list
CREATE TABLE list (firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2355 }
Find all students taught by OTHA MOYER. Output the first and last names of the students.
SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'OTHA' AND T2.lastname = 'MOYER'
CREATE TABLE list (firstname VARCHAR(255), lastname VARCHAR(255), classroom VARCHAR(255)); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2356 }
Find all students taught by MARROTTE KIRK. Output first and last names of students.
SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'MARROTTE' AND T2.lastname = 'KIRK'
CREATE TABLE list (firstname VARCHAR(255), lastname VARCHAR(255), classroom VARCHAR(255)); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2357 }
Find the first and last name of all the teachers that teach EVELINA BROMLEY.
SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = 'EVELINA' AND T1.lastname = 'BROMLEY'
CREATE TABLE teachers (firstname VARCHAR(255), lastname VARCHAR(255), classroom VARCHAR(255)); CREATE TABLE list (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
2
{ "split": "train", "row_index": 2358 }
Find the last names of all the teachers that teach GELL TAMI.
SELECT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = 'GELL' AND T1.lastname = 'TAMI'
CREATE TABLE teachers (lastname VARCHAR(255), classroom VARCHAR(255), firstname VARCHAR(255)); CREATE TABLE list (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2359 }
How many students does LORIA ONDERSMA teaches?
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'LORIA' AND T2.lastname = 'ONDERSMA'
CREATE TABLE list (classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2360 }
How many students does KAWA GORDON teaches?
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'KAWA' AND T2.lastname = 'GORDON'
CREATE TABLE list (classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2361 }
Find the number of students taught by TARRING LEIA.
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'TARRING' AND T2.lastname = 'LEIA'
CREATE TABLE list (classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2362 }
How many teachers does the student named CHRISSY NABOZNY have?
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = 'CHRISSY' AND T1.lastname = 'NABOZNY'
CREATE TABLE teachers (classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE list (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2363 }
How many teachers does the student named MADLOCK RAY have?
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = 'MADLOCK' AND T1.lastname = 'RAY'
CREATE TABLE teachers (classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE list (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2364 }
Find all first-grade students who are NOT taught by OTHA MOYER. Report their first and last names.
SELECT DISTINCT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 1 EXCEPT SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = 'OTHA' AND T2.lastname = 'MOYER'
CREATE TABLE list (firstname VARCHAR(255), lastname VARCHAR(255), classroom VARCHAR(255), grade VARCHAR(255)); CREATE TABLE teachers (classroom VARCHAR(255), firstname VARCHAR(255), lastname VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
1
{ "split": "train", "row_index": 2365 }
Find the last names of the students in third grade that are not taught by COVIN JEROME.
SELECT DISTINCT T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 3 AND T2.firstname <> 'COVIN' AND T2.lastname <> 'JEROME'
CREATE TABLE list (lastname VARCHAR(255), classroom VARCHAR(255), grade VARCHAR(255), firstname VARCHAR(255)); CREATE TABLE teachers (classroom VARCHAR(255), lastname VARCHAR(255), firstname VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2366 }
For each grade, report the grade, the number of classrooms in which it is taught and the total number of students in the grade.
SELECT grade, COUNT(DISTINCT classroom), COUNT(*) FROM list GROUP BY grade
CREATE TABLE list (grade VARCHAR(255), classroom VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
2
{ "split": "train", "row_index": 2367 }