question
string
answer
string
context
string
dialect
string
spider_hardness
string
extended_hardness
string
classification_status
string
syntax_status
string
ddl_syntax_status
string
schema_status
string
syntax_errors
list
ddl_syntax_errors
list
schema_errors
list
classification_errors
list
status_history
list
correction_status
string
component1
int64
component2
int64
others
int64
validation_source
dict
Which club has the most members majoring in "600"?
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = '600' GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE student (stuid VARCHAR(255), major VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
6
0
0
{ "split": "train", "row_index": 2471 }
Find the name of the club that has the most female students.
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = 'F' GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE student (stuid VARCHAR(255), sex VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
6
0
0
{ "split": "train", "row_index": 2472 }
What is the description of the club named "Tennis Club"?
SELECT clubdesc FROM club WHERE clubname = 'Tennis Club'
CREATE TABLE club (clubdesc VARCHAR(255), clubname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2473 }
Find the description of the club "Pen and Paper Gaming".
SELECT clubdesc FROM club WHERE clubname = 'Pen and Paper Gaming'
CREATE TABLE club (clubdesc VARCHAR(255), clubname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2474 }
What is the location of the club named "Tennis Club"?
SELECT clublocation FROM club WHERE clubname = 'Tennis Club'
CREATE TABLE club (clublocation VARCHAR(255), clubname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2475 }
Find the location of the club "Pen and Paper Gaming".
SELECT clublocation FROM club WHERE clubname = 'Pen and Paper Gaming'
CREATE TABLE club (clublocation VARCHAR(255), clubname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2476 }
Where is the club "Hopkins Student Enterprises" located?
SELECT clublocation FROM club WHERE clubname = 'Hopkins Student Enterprises'
CREATE TABLE club (clublocation VARCHAR(255), clubname VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2477 }
Find the name of all the clubs at "AKW".
SELECT clubname FROM club WHERE clublocation = 'AKW'
CREATE TABLE club (clubname VARCHAR(255), clublocation VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2478 }
How many clubs are located at "HHH"?
SELECT COUNT(*) FROM club WHERE clublocation = 'HHH'
CREATE TABLE club (clublocation VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2479 }
What are the first and last name of the president of the club "Bootup Baltimore"?
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Bootup Baltimore' AND t2.position = 'President'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (fname VARCHAR(255), lname VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255), position VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2480 }
Who is the "CTO" of club "Hopkins Student Enterprises"? Show the first name and last name.
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Hopkins Student Enterprises' AND t2.position = 'CTO'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (fname VARCHAR(255), lname VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255), position VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2481 }
How many different roles are there in the club "Bootup Baltimore"?
SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = 'Bootup Baltimore'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE member_of_club (position VARCHAR(255), clubid VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2482 }
How many members of "Bootup Baltimore" are older than 18?
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Bootup Baltimore' AND t3.age > 18
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (stuid VARCHAR(255), age VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2483 }
How many members of club "Bootup Baltimore" are younger than 18?
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Bootup Baltimore' AND t3.age < 18
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (stuid VARCHAR(255), age VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2484 }
Find the names of all the clubs that have at least a member from the city with city code "BAL".
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = 'BAL'
CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255)); CREATE TABLE student (stuid VARCHAR(255), city_code VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2485 }
Find the names of the clubs that have at least a member from the city with city code "HOU".
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = 'HOU'
CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255)); CREATE TABLE student (stuid VARCHAR(255), city_code VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2486 }
How many clubs does the student named "Eric Tai" belong to?
SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = 'Eric' AND t3.lname = 'Tai'
CREATE TABLE student (stuid VARCHAR(255), fname VARCHAR(255), lname VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2487 }
List the clubs having "Davis Steven" as a member.
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = 'Davis' AND t3.lname = 'Steven'
CREATE TABLE student (stuid VARCHAR(255), fname VARCHAR(255), lname VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
1
{ "split": "train", "row_index": 2488 }
List the clubs that have at least a member with advisor "1121".
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121
CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255)); CREATE TABLE club (clubname VARCHAR(255), clubid VARCHAR(255)); CREATE TABLE student (stuid VARCHAR(255), advisor VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2489 }
What is the average age of the members of the club "Bootup Baltimore"?
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Bootup Baltimore'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (age INTEGER, stuid VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2490 }
Find the average age of members of the club "Hopkins Student Enterprises".
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Hopkins Student Enterprises'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (age INTEGER, stuid VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2491 }
Retrieve the average age of members of the club "Tennis Club".
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = 'Tennis Club'
CREATE TABLE club (clubid VARCHAR(255), clubname VARCHAR(255)); CREATE TABLE student (age INTEGER, stuid VARCHAR(255)); CREATE TABLE member_of_club (clubid VARCHAR(255), stuid VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2492 }
List the project details of the project both producing patent and paper as outcomes.
SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent'
CREATE TABLE Project_outcomes (project_id VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
0
{ "split": "train", "row_index": 2494 }
List from which date and to which date these staff work: project staff of the project which hires the most staffs
SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader'
CREATE TABLE Project_Staff (date_from VARCHAR(255), date_to VARCHAR(255), project_id VARCHAR(255), role_code VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
2
1
{ "split": "train", "row_index": 2496 }
Find the organisation ids and details of the organisations which are involved in
SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000
CREATE TABLE Grants (organisation_id VARCHAR(255), grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR(255), organisation_details VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2497 }
What is the organisation type and id of the organisation which has the most number of research staff?
SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Organisations (organisation_type VARCHAR(255), organisation_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2498 }
Which organisation type hires most research staff?
SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Organisations (organisation_type VARCHAR(255), organisation_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2499 }
Find out the send dates of the documents with the grant amount of more than 5000 were granted by organisation type described
SELECT T1.sent_date FROM documents AS T1 JOIN Grants AS T2 ON T1.grant_id = T2.grant_id JOIN Organisations AS T3 ON T2.organisation_id = T3.organisation_id JOIN organisation_Types AS T4 ON T3.organisation_type = T4.organisation_type WHERE T2.grant_amount > 5000 AND T4.organisation_type_description = 'Research'
CREATE TABLE organisation_Types (organisation_type VARCHAR(255), organisation_type_description VARCHAR(255)); CREATE TABLE Grants (grant_id VARCHAR(255), organisation_id VARCHAR(255), grant_amount VARCHAR(255)); CREATE TABLE Organisations (organisation_id VARCHAR(255), organisation_type VARCHAR(255)); CREATE TABLE docu...
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2500 }
What are the response received dates for the documents described as 'Regular' or granted with more than 100?
SELECT T1.response_received_date FROM Documents AS T1 JOIN Document_Types AS T2 ON T1.document_type_code = T2.document_type_code JOIN Grants AS T3 ON T1.grant_id = T3.grant_id WHERE T2.document_description = 'Regular' OR T3.grant_amount > 100
CREATE TABLE Documents (response_received_date VARCHAR(255), document_type_code VARCHAR(255), grant_id VARCHAR(255)); CREATE TABLE Document_Types (document_type_code VARCHAR(255), document_description VARCHAR(255)); CREATE TABLE Grants (grant_id VARCHAR(255), grant_amount VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2501 }
List the project details of the projects which did not hire any staff for a researcher role.
SELECT project_details FROM Projects WHERE NOT project_id IN (SELECT project_id FROM Project_Staff WHERE role_code = 'researcher')
CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255), role_code VARCHAR(255)); CREATE TABLE Project_Staff (project_details VARCHAR(255), project_id VARCHAR(255), role_code VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2502 }
What are the task details, task id and project id for the projects which are detailed as 'omnis' or have more than 2 outcomes?
SELECT T1.task_details, T1.task_id, T2.project_id FROM Tasks AS T1 JOIN Projects AS T2 ON T1.project_id = T2.project_id WHERE T2.project_details = 'omnis' UNION SELECT T1.task_details, T1.task_id, T2.project_id FROM Tasks AS T1 JOIN Projects AS T2 ON T1.project_id = T2.project_id JOIN Project_outcomes AS T3 ON T2.proje...
CREATE TABLE Projects (project_id VARCHAR(255), project_details VARCHAR(255)); CREATE TABLE Project_outcomes (project_id VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Tasks (task_details VARCHAR(255), task_id VARCHAR(255), project_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
1
{ "split": "train", "row_index": 2503 }
When do all the researcher role staff start to work, and when do they stop working?
SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'researcher'
CREATE TABLE Project_Staff (date_from VARCHAR(255), date_to VARCHAR(255), role_code VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2504 }
How many kinds of roles are there for the staff?
SELECT COUNT(DISTINCT role_code) FROM Project_Staff
CREATE TABLE Project_Staff (role_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2505 }
What is the total amount of grants given by each organisations? Also list the organisation id.
SELECT SUM(grant_amount), organisation_id FROM Grants GROUP BY organisation_id
CREATE TABLE Grants (organisation_id VARCHAR(255), grant_amount INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2506 }
List the project details of the projects with the research outcome described with the substring 'Published'.
SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id JOIN Research_outcomes AS T3 ON T2.outcome_code = T3.outcome_code WHERE T3.outcome_description LIKE '%Published%'
CREATE TABLE Research_outcomes (outcome_code VARCHAR(255), outcome_description VARCHAR(255)); CREATE TABLE Project_outcomes (project_id VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
0
{ "split": "train", "row_index": 2507 }
How many staff does each project has? List the project id and the number in an ascending order.
SELECT T1.project_id, COUNT(*) FROM Project_Staff AS T1 JOIN Projects AS T2 ON T1.project_id = T2.project_id GROUP BY T1.project_id ORDER BY COUNT(*)
CREATE TABLE Project_Staff (project_id VARCHAR(255), staff_id VARCHAR(255)); CREATE TABLE Projects (project_id VARCHAR(255), project_details VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2508 }
What is the complete description of the researcher role.
SELECT role_description FROM Staff_Roles WHERE role_code = 'researcher'
CREATE TABLE Staff_Roles (role_description VARCHAR(255), role_code VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2509 }
When did the first staff for the projects started working?
SELECT date_from FROM Project_Staff ORDER BY date_from LIMIT 1
CREATE TABLE Project_Staff (date_from VARCHAR(255), date_to VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2510 }
Which project made the most number of outcomes? List the project details and the project id.
SELECT T1.project_details, T1.project_id FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id GROUP BY T1.project_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Project_outcomes (project_id VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2511 }
Which projects have no outcome? List the project details.
SELECT project_details FROM Projects WHERE NOT project_id IN (SELECT project_id FROM Project_outcomes)
CREATE TABLE Project_outcomes (project_details VARCHAR(255), project_id VARCHAR(255)); CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2512 }
Which organisation hired the most number of research staff? List the organisation id, type and detail.
SELECT T1.organisation_id, T1.organisation_type, T1.organisation_details FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Organisations (organisation_id VARCHAR(255), organisation_type VARCHAR(255), organisation_details VARCHAR(255)); CREATE TABLE Research_Staff (employer_organisation_id VARCHAR(255), staff_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
1
{ "split": "train", "row_index": 2513 }
Show the role description and the id of the project staff involved in most number of project outcomes?
SELECT T1.role_description, T2.staff_id FROM Staff_Roles AS T1 JOIN Project_Staff AS T2 ON T1.role_code = T2.role_code JOIN Project_outcomes AS T3 ON T2.project_id = T3.project_id GROUP BY T2.staff_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Project_outcomes (project_id VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Project_Staff (staff_id VARCHAR(255), role_code VARCHAR(255), project_id VARCHAR(255)); CREATE TABLE Staff_Roles (role_description VARCHAR(255), role_code VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
5
0
1
{ "split": "train", "row_index": 2514 }
Which document type is described with the prefix 'Initial'?
SELECT document_type_code FROM Document_Types WHERE document_description LIKE 'Initial%'
CREATE TABLE Document_Types (document_type_code VARCHAR(255), document_description VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2515 }
For grants with both documents described as 'Regular' and documents described as 'Initial Application', list its start date.
SELECT T1.grant_start_date FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id JOIN Document_Types AS T3 ON T2.document_type_code = T3.document_type_code WHERE T3.document_description = 'Regular' INTERSECT SELECT T1.grant_start_date FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id JOI...
CREATE TABLE Grants (grant_start_date VARCHAR(255), grant_id VARCHAR(255)); CREATE TABLE Document_Types (document_type_code VARCHAR(255), document_description VARCHAR(255)); CREATE TABLE Documents (grant_id VARCHAR(255), document_type_code VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
1
0
{ "split": "train", "row_index": 2516 }
How many documents can one grant have at most? List the grant id and number.
SELECT grant_id, COUNT(*) FROM Documents GROUP BY grant_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Documents (grant_id VARCHAR(255), document_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2517 }
Find the organisation type description of the organisation detailed as 'quo'.
SELECT T1.organisation_type_description FROM organisation_Types AS T1 JOIN Organisations AS T2 ON T1.organisation_type = T2.organisation_type WHERE T2.organisation_details = 'quo'
CREATE TABLE Organisations (organisation_type VARCHAR(255), organisation_details VARCHAR(255)); CREATE TABLE organisation_Types (organisation_type_description VARCHAR(255), organisation_type VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2518 }
How many Patent outcomes are generated from all the projects?
SELECT COUNT(*) FROM Project_outcomes WHERE outcome_code = 'Patent'
CREATE TABLE Project_outcomes (outcome_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2520 }
How many project staff worked as leaders or started working before '1989-04-24 23:51:54'?
SELECT COUNT(*) FROM Project_Staff WHERE role_code = 'leader' OR date_from < '1989-04-24 23:51:54'
CREATE TABLE Project_Staff (role_code VARCHAR(255), date_from VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2521 }
What is the last date of the staff leaving the projects?
SELECT date_to FROM Project_Staff ORDER BY date_to DESC LIMIT 1
CREATE TABLE Project_Staff (date_to VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2522 }
What are the result description of the project whose detail is 'sint'?
SELECT T1.outcome_description FROM Research_outcomes AS T1 JOIN Project_outcomes AS T2 ON T1.outcome_code = T2.outcome_code JOIN Projects AS T3 ON T2.project_id = T3.project_id WHERE T3.project_details = 'sint'
CREATE TABLE Project_outcomes (outcome_code VARCHAR(255), project_id VARCHAR(255)); CREATE TABLE Research_outcomes (outcome_description VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Projects (project_id VARCHAR(255), project_details VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2523 }
List the organisation id with the maximum outcome count, and the count.
SELECT T1.organisation_id, COUNT(*) FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Project_outcomes (project_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE Projects (organisation_id VARCHAR(255), project_id VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 2524 }
List the project details of the projects launched by the organisation
SELECT project_details FROM Projects WHERE organisation_id IN (SELECT organisation_id FROM Projects GROUP BY organisation_id ORDER BY COUNT(*) DESC LIMIT 1)
CREATE TABLE Projects (project_details VARCHAR(255), organisation_id VARCHAR(255))
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
0
{ "split": "train", "row_index": 2525 }
List the research staff details, and order in ascending order.
SELECT staff_details FROM Research_Staff ORDER BY staff_details
CREATE TABLE Research_Staff (staff_details VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2526 }
How many tasks are there in total?
SELECT COUNT(*) FROM Tasks
CREATE TABLE Tasks (Id VARCHAR(255), task_name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2527 }
How many tasks does each project have? List the task count and the project detail.
SELECT COUNT(*), T1.project_details FROM Projects AS T1 JOIN Tasks AS T2 ON T1.project_id = T2.project_id GROUP BY T1.project_id
CREATE TABLE Projects (project_details VARCHAR(255), project_id VARCHAR(255)); CREATE TABLE Tasks (project_id VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2528 }
What are the staff roles of the staff who
SELECT role_code FROM Project_Staff WHERE date_from > '2003-04-19 15:06:20' AND date_to < '2016-03-15 00:33:18'
CREATE TABLE Project_Staff (role_code VARCHAR(255), date_from VARCHAR(255), date_to VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2529 }
What are the descriptions of all the project outcomes?
SELECT T1.outcome_description FROM Research_outcomes AS T1 JOIN Project_outcomes AS T2 ON T1.outcome_code = T2.outcome_code
CREATE TABLE Research_outcomes (outcome_description VARCHAR(255), outcome_code VARCHAR(255)); CREATE TABLE Project_outcomes (outcome_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2530 }
Which role is most common for the staff?
SELECT role_code FROM Project_Staff GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Project_Staff (role_code VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2531 }
How many friends does Dan have?
SELECT COUNT(T2.friend) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Dan'
CREATE TABLE PersonFriend (friend VARCHAR(255), name VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), age INTEGER)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2532 }
How many females does this network has?
SELECT COUNT(*) FROM Person WHERE gender = 'female'
CREATE TABLE Person (gender VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2533 }
What is the average age for all person?
SELECT AVG(age) FROM Person
CREATE TABLE Person (age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2534 }
How many different cities are they from?
SELECT COUNT(DISTINCT city) FROM Person
CREATE TABLE Person (city VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2535 }
How many type of jobs do they have?
SELECT COUNT(DISTINCT job) FROM Person
CREATE TABLE Person (job VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2536 }
How old is the doctor named Zach?
SELECT age FROM Person WHERE job = 'doctor' AND name = 'Zach'
CREATE TABLE Person (age VARCHAR(255), job VARCHAR(255), name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2540 }
Who is the person whose age is below 30?
SELECT name FROM Person WHERE age < 30
CREATE TABLE Person (name VARCHAR(255), age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2541 }
How many people whose age is greater 30 and job is engineer?
SELECT COUNT(*) FROM Person WHERE age > 30 AND job = 'engineer'
CREATE TABLE Person (age VARCHAR(255), job VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2542 }
What is the average age for each gender?
SELECT AVG(age), gender FROM Person GROUP BY gender
CREATE TABLE Person (gender VARCHAR(255), age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2543 }
What is average age for different job title?
SELECT AVG(age), job FROM Person GROUP BY job
CREATE TABLE Person (job VARCHAR(255), age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2544 }
What is average age of male for different job title?
SELECT AVG(age), job FROM Person WHERE gender = 'male' GROUP BY job
CREATE TABLE Person (job VARCHAR(255), age INTEGER, gender VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2545 }
What is minimum age for different job title?
SELECT MIN(age), job FROM Person GROUP BY job
CREATE TABLE Person (job VARCHAR(255), age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2546 }
Find the number of people who is under 40 for each gender.
SELECT COUNT(*), gender FROM Person WHERE age < 40 GROUP BY gender
CREATE TABLE Person (gender VARCHAR(255), age INTEGER, id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2547 }
list the name, job title of all people ordered by their names.
SELECT name, job FROM Person ORDER BY name
CREATE TABLE Person (name VARCHAR(255), job VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2550 }
Find the names of all person sorted in the descending order using age.
SELECT name FROM Person ORDER BY age DESC
CREATE TABLE Person (name VARCHAR(255), age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2551 }
Find the name and age of all males in order of their age.
SELECT name FROM Person WHERE gender = 'male' ORDER BY age
CREATE TABLE Person (name VARCHAR(255), gender VARCHAR(255), age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2552 }
Find the name and age of the person who is a friend of both Dan and Alice.
SELECT T1.name, T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' INTERSECT SELECT T1.name, T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice'
CREATE TABLE Person (name VARCHAR(255), age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
1
1
{ "split": "train", "row_index": 2553 }
Find the name and age of the person who is a friend of Dan or Alice.
SELECT DISTINCT T1.name, T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' OR T2.friend = 'Alice'
CREATE TABLE Person (name VARCHAR(255), age VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
2
{ "split": "train", "row_index": 2554 }
Find the person who has exactly one friend.
SELECT name FROM PersonFriend GROUP BY name HAVING COUNT(*) = 1
CREATE TABLE PersonFriend (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2558 }
Who are the friends of Bob?
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Bob'
CREATE TABLE PersonFriend (friend VARCHAR(255), name VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2559 }
Find the name of persons who are friends with Bob.
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Bob'
CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2560 }
Find the names of females who are friends with Zach
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Zach' AND T1.gender = 'female'
CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), gender VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2561 }
Find the female friends of Alice.
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'female'
CREATE TABLE PersonFriend (friend VARCHAR(255), name VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), gender VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2562 }
Find the male friend of Alice whose job is a doctor?
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'male' AND T1.job = 'doctor'
CREATE TABLE PersonFriend (friend VARCHAR(255), name VARCHAR(255)); CREATE TABLE Person (name VARCHAR(255), job VARCHAR(255), gender VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2563 }
Who has a friend that is from new york city?
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = 'new york city'
CREATE TABLE Person (name VARCHAR(255), city VARCHAR(255)); CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2564 }
Who is the friend of Zach with longest year relationship?
SELECT friend FROM PersonFriend WHERE name = 'Zach' AND YEAR = (SELECT MAX(YEAR) FROM PersonFriend WHERE name = 'Zach')
CREATE TABLE PersonFriend (friend VARCHAR(255), name VARCHAR(255), YEAR INTEGER)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2567 }
Find the name of persons who are friends with Alice for the shortest years.
SELECT name FROM PersonFriend WHERE friend = 'Alice' AND YEAR = (SELECT MIN(YEAR) FROM PersonFriend WHERE friend = 'Alice')
CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255), YEAR INTEGER)
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2569 }
Who is the person that has no friend?
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend
CREATE TABLE PersonFriend (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT); CREATE TABLE person (name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
1
0
{ "split": "train", "row_index": 2571 }
Which person whose friends have the oldest average age?
SELECT T2.name, AVG(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY AVG(T1.age) DESC LIMIT 1
CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255)); CREATE TABLE Person (age INTEGER, name VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
4
0
2
{ "split": "train", "row_index": 2572 }
What is the total number of people who has no friend living in the city of Austin.
SELECT COUNT(DISTINCT name) FROM PersonFriend WHERE NOT friend IN (SELECT name FROM person WHERE city = 'Austin')
CREATE TABLE person (name VARCHAR(255), friend VARCHAR(255), city VARCHAR(255)); CREATE TABLE PersonFriend (name VARCHAR(255), friend VARCHAR(255), city VARCHAR(255))
generic
extra
extra
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
1
1
{ "split": "train", "row_index": 2573 }
How many members are there?
SELECT COUNT(*) FROM member
CREATE TABLE member (Id VARCHAR(255), name VARCHAR(255))
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
0
{ "split": "train", "row_index": 2575 }
List the names of members in ascending alphabetical order.
SELECT Name FROM member ORDER BY Name
CREATE TABLE member (Name VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2576 }
What are the names and countries of members?
SELECT Name, Country FROM member
CREATE TABLE member (Name VARCHAR(255), Country VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2577 }
Show the names of members whose country is "United States" or "Canada".
SELECT Name FROM member WHERE Country = 'United States' OR Country = 'Canada'
CREATE TABLE member (Name VARCHAR(255), Country VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2578 }
Show the different countries and the number of members from each.
SELECT Country, COUNT(*) FROM member GROUP BY Country
CREATE TABLE member (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2579 }
Show the most common country across members.
SELECT Country FROM member GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE member (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
hard
hard
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
3
0
0
{ "split": "train", "row_index": 2580 }
Which countries have more than two members?
SELECT Country FROM member GROUP BY Country HAVING COUNT(*) > 2
CREATE TABLE member (Country VARCHAR(255), id INTEGER PRIMARY KEY AUTO_INCREMENT)
generic
easy
easy
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
0
{ "split": "train", "row_index": 2581 }
Show the leader names and locations of colleges.
SELECT Leader_Name, College_Location FROM college
CREATE TABLE college (Leader_Name VARCHAR(255), College_Location VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
0
0
1
{ "split": "train", "row_index": 2582 }
Show the names of members and names of colleges they go to.
SELECT T2.Name, T1.Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID
CREATE TABLE member (Name VARCHAR(255), College_ID VARCHAR(255)); CREATE TABLE college (Name VARCHAR(255), College_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2583 }
Show the names of members and the locations of colleges they go to in ascending alphabetical order of member names.
SELECT T2.Name, T1.College_Location FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID ORDER BY T2.Name
CREATE TABLE member (Name VARCHAR(255), College_ID VARCHAR(255)); CREATE TABLE college (College_Location VARCHAR(255), College_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
1
{ "split": "train", "row_index": 2584 }
Show the distinct leader names of colleges associated with members from country "Canada".
SELECT DISTINCT T1.Leader_Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID WHERE T2.Country = 'Canada'
CREATE TABLE college (Leader_Name VARCHAR(255), College_ID VARCHAR(255)); CREATE TABLE member (College_ID VARCHAR(255), Country VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
2
0
0
{ "split": "train", "row_index": 2585 }
Show the names of members and the decoration themes they have.
SELECT T1.Name, T2.Decoration_Theme FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID
CREATE TABLE member (Name VARCHAR(255), Member_ID VARCHAR(255)); CREATE TABLE round (Decoration_Theme VARCHAR(255), Member_ID VARCHAR(255))
generic
medium
medium
classified
valid
valid
valid
[]
[]
[]
[]
[ "validated", "extended", "classified" ]
null
1
0
1
{ "split": "train", "row_index": 2586 }