output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T next_num() {
T i = 0;
char c;
while (!isdigit(c = getchar()) && c != '-')
;
bool flag = c == '-';
flag ? (c = getchar()) : 0;
while (i = i * 10 - '0' + c, isdigit(c = getchar()))
;
return flag ? -i : i;
}
long long O;
inline... | ### Prompt
Please create a solution in CPP to the following problem:
A Russian space traveller Alisa Selezneva, like any other schoolgirl of the late 21 century, is interested in science. She has recently visited the MIT (Moscow Institute of Time), where its chairman and the co-inventor of the time machine academicia... |
#include <bits/stdc++.h>
using namespace std;
int X1, Y1, X2, Y2;
long long MOD, pw[20];
long long add(long long x, long long y, long long m) {
x += y;
if (x >= m)
x %= m;
else if (x < 0)
x = ((x % m) + m) % m;
return x;
}
long long mul(long long x, long long y, long long m) {
return ((x * y - (long l... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A Russian space traveller Alisa Selezneva, like any other schoolgirl of the late 21 century, is interested in science. She has recently visited the MIT (Moscow Institute of Time), where its chairman and the co-inventor of the time machine ... |
#include <bits/stdc++.h>
using namespace std;
struct bignum {
long long dig[10];
int len;
long long &operator[](int k) { return dig[k]; }
bignum() {}
bignum(long long x) {
len = 0;
do {
dig[len] = x % 100000000;
x /= 100000000;
len++;
} while (x);
}
void print() {
long lo... | ### Prompt
Generate a Cpp solution to the following problem:
A Russian space traveller Alisa Selezneva, like any other schoolgirl of the late 21 century, is interested in science. She has recently visited the MIT (Moscow Institute of Time), where its chairman and the co-inventor of the time machine academician Petrov... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long int n, k;
cin >> n >> k;
if (k == 1) {
cout << n;
return 0;
}
if (n == 1) {
cout << 1;
return 0;
}
set<long long int> s;
for (long long int i = 0; i < n; ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
priority_queue<int, vector<int>, greater<int> > Q;
const int INF = 1e9 + 9;
struct cmp {
bool operator()(pair<int, int> const &a, pair<int, int> const &b) {
if (a.first == b.first) return a.second > b.second;
return a.first < b.first;
}
};
int main() {
int n, ... | ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
const int N = 100009;
long long a[N];
map<long long, long long> mp;
vector<long long> fi, se;
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> a[i];
mp[a[i]] = 1;
}
sort(a, a + n);
for (int i = 0; i < n; i++) {
if (mp[a[i]])... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int no_of_elements, k;
scanf("%d %d", &no_of_elements, &k);
vector<int> element(no_of_elements);
for (int i = 0; i < no_of_elements; i++) scanf("%d", &element[i]);
sort((element).begin(), (element).end());
int set_size = 0;
vector<int> crossed_out... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
long long n, k;
scanf("%I64d", &n);
;
scanf("%I64d", &k);
;
vector<long long> v;
map<long long, bool> m;
for (int i = 0; i < n; i++) {
long long x;
scanf("%I64d", &x);
;
v.push_back(x... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int numeros[n + 1];
for (int i = 0; i < n; i++) {
int a;
cin >> a;
numeros[i] = a;
}
sort(numeros, numeros + n);
set<int> largo;
for (int i = 0; i < n; ++i) {
int l, m;
l = (abs(numeros[i] % k));
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int a[111111];
bool b[111111];
int binSearch(int x) {
int l = 0, r = n - 1;
while (l <= r) {
int m = (l + r) / 2;
if (a[m] == x) return m;
if (a[m] > x)
r = m - 1;
else
l = m + 1;
}
return -1;
}
int main() {
cin >> n >> k;
f... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long a[100000 + 10], b[100000 + 10];
bool f(int x, int y) {
int l = 1, r = x, mid, ans = 0;
while (l <= r) {
mid = (l + r) >> 1;
if (b[mid] < y)
l = mid + 1;
else {
ans = mid;
r = mid - 1;
}
}
if (b[ans] == y)
return 1;
e... | ### Prompt
Construct a CPP code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int a[111111], b[1111], c[111], p[111][111];
int n, l = 0, m;
const int md = 100000000;
int main() {
int n1 = 0, n2 = 0, p1, p2, j, i, z = 0, x, k;
cin >> n >> m;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
map<int, int> mp;
for (i = 0; i < n; i++) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long l, r, n, i, size1 = 0, w = 1, j, mid;
long long k;
long long m[100005];
int f[100005] = {0}, h[100005] = {0};
scanf("%ld %I64d", &n, &k);
for (i = 0; i < n; i++) {
scanf("%I64d", &m[i]);
}
size1 = n;
sort(&m[0], &m[n]);
if (k == 1) ... | ### Prompt
Your task is to create a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline void ri(T &i) {
bool minus = false;
char c;
for (c = getchar(); (c < '0' || c > '9') && (c != '-'); c = getchar())
;
if (c == '-') {
minus = true;
c = '0';
}
for (i = 0; c >= '0' && c <= '9'; c = getchar())
i = (i << 3) ... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int arr[100001];
bool binary_search(long long a, long long n) {
long long l = 0, r = n - 1, w;
while (l <= r) {
w = (l + r) / 2;
if (arr[w] == a && arr[w] >= 0) {
arr[w] = -1;
return true;
} else if (arr[w] > a) {
r = w - 1;
} else
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d%d", &n, &k);
if (k == 1) {
printf("%d", n);
return 0;
}
map<int, vector<int> > a;
while (n--) {
int x;
scanf("%d", &x);
int y = x;
while (y % k == 0) y /= k;
a[y].push_back(x);
}
int ans = 0;
for... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int a[100005];
int has[100005];
int main() {
int n, k, i, ans;
while (~scanf("%d%d", &n, &k)) {
memset(has, 0, sizeof(has));
for (i = 0; i < n; i++) scanf("%d", &a[i]);
sort(a, a + n);
ans = 0;
for (i = 0; i < n; i++) {
if (has[i]) continue;
... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
int cmp(const void *a, const void *b) { return ((int *)b)[0] - ((int *)a)[0]; }
int a[100001][2];
int main() {
int n, k;
int sum = 0;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d", &a[i][0]);
qsort(a, n, sizeof(int) * 2, cmp);
for (int i = 0; i < n; i++) {
if (a[... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n, k;
cin >> n >> k;
set<long long> myset;
for (int i = 0; i < n; i++) {
int c;
cin >> c;
myset.insert(c);
}
auto it = myset.begin();
int ans = 0;
do {
long long x = (*i... | ### Prompt
Please create a solution in CPP to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 5;
int array1[maxn];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n, k;
cin >> n >> k;
set<int> s;
for (int i = 1; i <= n; i++) {
cin >> array1[i];
}
sort(array1 + 1, array1 + n + 1);
s.inse... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
map<long long, bool> vis;
long long n, k, a[100004];
int ans = 0;
int main() {
cin >> n >> k;
for (long long i = 0; i < n; i++) {
cin >> a[i];
vis[a[i]] = 0;
}
sort(a, a + n);
for (long long i = 0; i < n; i++)
if (!vis[a[i]]) {
ans++;
vis[a... | ### Prompt
Your task is to create a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
#pragma comment(linker, "/STACK:102400000,102400000")
using std::bitset;
using namespace std;
vector<long long> a;
long long n, k, flag[101000];
long long ans;
int main() {
long long i, j, tem;
scanf("%I64d%I64d", &n, &k);
memset(flag, 0, sizeof(flag));
;
a.clear();
for (i = 1; i <=... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1);
const double eps = 1e-9;
int main() {
long long i, j, k, l, p, q, r, x, y, z, n, m, c(0), t, h, mn = pow(2, 62) - 1,
mx = 0;
scanf("%lld", &n), scanf("%lld", &k);
map<long long, bo... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
void read(long long a = 0) {
freopen("in", "r", stdin);
if (a) freopen("out", "w", stdout);
}
long long a[100009];
map<long long, long long> vis, here;
int main() {
long long n, k;
cin >> n >> k;
if (k == 1) {
return cout << n, 0;
}
for (int i = 0; i < n; ... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
int n, ans, k, a[N];
map<long long, int> f;
int main() {
scanf("%d%d", &n, &k);
if (k == 1) return printf("%u\n", n), 0;
for (int i = 1; i <= n; i++) {
scanf("%d", a + i);
f[a[i]]++;
}
sort(a + 1, a + n + 1);
for (int i = 1; i <= n... | ### Prompt
Construct a CPP code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int A[100005];
set<int> s;
int main() {
int n, k, one = 0, ka = 0, q = 0;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> A[i];
sort(A, A + n);
for (int i = 0; i < n; i++) {
int a;
a = A[i];
if (a % k)
s.insert(a);
else if (s.find(a / k) ==... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
long long int power(long long int x, long long int y, long long int z) {
if (y == 0)
return 1;
else {
long long int p = power(x, y / 2, z);
if (y % 2 == 0)
return (p * p) % z;
else
return (x * ((p * p) % z)) % z;
}
}
long long int gcd(long ... | ### Prompt
Please create a solution in CPP to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n;
int k;
long long a[100005];
long long b[100005];
long long c[100005];
long long procurando;
long long atual;
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
sort(a + 1, a + n + 1);
for (int i = 1; i <= n; i++) {
b[i] = a[n]... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
long long n, k;
long long A[100001], B[100001];
bool C[100001];
int bb(long long a) {
int i = 0, f = n, m;
while (f - i > 1) {
m = (i + f) / 2;
if (A[m] <= a)
i = m;
else
f = m;
}
return i;
}
int main() {
cin >> n >> k;
for (int i = 0; i ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
long long a[100005], p;
bool vis[100005];
int main() {
while (scanf("%d %d", &n, &k) != EOF) {
int ans = n;
for (int i = 0; i < n; i++) scanf("%I64d", &a[i]);
memset(vis, 0, sizeof(vis));
sort(a, a + n);
for (int i = 0; i < n; i++) {
if... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); }
long long countDivisor(long long n) {
long long divisor = 0;
for (long long i = 1; i * i <= n; i++) {
if (i * i == n)
divisor += 1;
else if (n % i == 0)
divisor += 2;
}
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const int N = 100000;
int a[N];
int main() {
int n, k, ans = 0;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
map<int, bool> used;
for (int i = 0; i < n; i++)
if (a[i] % k || !used[a[i] / k]) {
ans++;
used[a[i]] = 1;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using db = long double;
using str = string;
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
using vi = vector<int>;
using vb = vector<bool>;
using vl = vector<ll>;
using vd = vector<db>;
using vs = vector<str>;
using vpi = ... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
set<long long> s;
int niz[100005];
int n, k;
int main(void) {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d", &niz[i]);
sort(niz, niz + n);
int ukupno = 0;
for (int i = n - 1; i >= 0; i--)
if (s.find((long long)niz[i] * k) == s.end()) s.insert((... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int num[n + 1];
for (int i = 0; i < n; i++) {
int a;
cin >> a;
num[i] = a;
}
sort(num, num + n);
set<int> largo;
for (int i = 0; i < n; i++) {
int l, m;
l = (abs(num[i] % k));
m = largo.count(num[... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k, a[200005], i, ans = 0;
map<long long, int> m;
cin >> n >> k;
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (i = 0; i < n; i++) {
if (a[i] % k == 0 && m[a[i] / k] == 0) {
m[a[i]]++;
ans++;
} el... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100005;
long long a[maxn];
bool cmp(long long a, long long b) { return a > b; }
int main() {
int n, k;
while (cin >> n >> k) {
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n, cmp);
map<long long, long long> mp;
int ans = 0;
f... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
long long factorial(long long n) {
return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
}
long long gcd(long long a, long long b) {
if (a == 0) return b;
return gcd(b % a, a);
}
long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); }
bool sortByVal(co... | ### Prompt
Construct a CPP code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
long long k;
cin >> n;
cin >> k;
multiset<long long> p;
long long resp = 0;
vector<long long> num(n);
for (int i = 0; i < n; i++) {
cin >> num[i];
}
sort(num.begin(), num.end());
for (int i = 0; i < n; i++) {
long long x = n... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int x, k;
while (cin >> x >> k) {
vector<long long int> ar;
for (long long int i = 0; i < x; i++) {
long long int num;
cin >> num;
ar.push_back(num);
}
sort(ar.begin(), ar.end());
map<long long int, long long ... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
if (k == 1) {
cout << n << endl;
return 0;
}
vector<long long> a(n);
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
long long j = 0, cnt = 0;
vector<bool> ch(n, true);
for (lon... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
const double pi = 2 * acos(0);
const long long mod = 4294967296;
void solve() {
long long n, k;
cin >> n >> k;
vector<long long> a(n);
for (int i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
long long cnt = 0;
map<long long, long long> make_pair;
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
void __print(int x) { cerr << x; }
void __print(long x) { cerr << x; }
void __print(long long x) { cerr << x; }
void __print(unsigned x) { cerr << x; }
void __print(unsigned long x) { cerr << x; }
void __print(unsigned long long x) { cerr << x; }
void __print(float x) { cer... | ### Prompt
Create a solution in CPP for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
long long A[100000];
unsigned char B[100000];
long N, K;
void swap(long long *a, long long *b) {
long tmp = *a;
*a = *b;
*b = tmp;
}
long partition(long long A[], long low, long up) {
long x = A[low], i = low - 1, j = up + 1;
while (1) {
do
;
while (A[++i] < x);
do
... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n, k, a[100100], ans;
bool used[100100];
map<int, bool> m;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i], m[a[i]] = true;
sort(a, a + n);
int mx = a[n - 1];
for (int i = 0; i < n; i++) {
if (!used[i]) {
used[i] = 1;
int l ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
long long n, k;
bool vis[100005];
vector<long long> v, vec, H;
vector<long long>::iterator it;
long long freq[100005];
long long dp[100005];
long long call(int pos) {
if (pos >= H.size()) return 0;
if (dp[pos] != -1) return dp[pos];
long long a = H[pos] + call(pos + 2... | ### Prompt
Develop a solution in CPP to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
map<int, int> mp;
int main() {
int n, k, maximo = 0;
cin >> n >> k;
int v[n];
for (int i = 0; i < n; i++) cin >> v[i];
sort(v, v + n);
for (int i = 0; i < n; i++)
if (v[i] % k || !mp.count(v[i] / k)) {
mp[v[i]] = 1;
maximo++;
}
cout << maxi... | ### Prompt
Create a solution in Cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
long long arr[100010];
bool b[100010] = {0};
bool bins(long long x, int low, int high) {
if (low > high)
return false;
else {
int mid = (high + low) / 2;
if (arr[mid] == x)
if (b[mid])
return false;
else
return true;
else if (... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
bool compare(const pair<int, int> &i, const pair<int, int> &j) {
return i.second > j.second;
}
int n, d;
vector<pair<long long, long long>> a;
int lis(vector<int> const &a, int l, int r) {
int n = a.size();
const int INF = 1e9;
vector<int> d(n + 1, INF);
d[0] = -I... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
vector<string> vec_splitter(string s) {
s += ',';
vector<string> res;
while (!s.empty()) {
res.push_back(s.substr(0, s.find(',')));
s = s.substr(s.find(',') + 1);
}
return res;
}
void debug_out(vector<string> __attribute__((unused)) args,
__... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
const long long MAXN = 100005;
long long n, k;
long long a[MAXN];
int main() {
ios::sync_with_stdio(false);
cin >> n >> k;
for (long long i = 1; i <= n; ++i) cin >> a[i];
sort(a + 1, a + n + 1);
long long ans = 0;
set<long long> del;
for (long long i = 1; i <=... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const double EPS = 1e-9;
const int MXX = 2e5 + 5;
int a[MXX];
int main() {
int tc;
long long int n, k;
cin >> n >> k;
map<long long int, long long int> mp;
for (int i = (0); i < (n); i++) {
cin >> a[i];
mp[a[i]]++;
}
sort(a, a ... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long M = 1e9 + 7, N = 205001;
long long mm(long long x, long long y) {
x %= M, y %= M;
return (x * y) % M;
}
long long po(long long x, long long y) {
if (!y) return 1;
long long a = po(x, y / 2) % M;
if (y % 2) return mm(a, mm(a, x));
return mm(a, a);
}
voi... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 655373;
int a[100005];
vector<int> v[655373];
bool invec(int n) {
int rest = n % mod;
for (int i = 0; i < v[rest].size(); i++)
if (v[rest][i] == n) return 1;
return 0;
}
int main() {
int n, k, i, ans = 0;
scanf("%d%d", &n, &k);
for (i = 0; i ... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int arr[100005];
set<int> st;
int main() {
int n, k;
(scanf("%d%d", &n, &k));
for (int i = 1; i <= n; i++) (scanf("%d", &arr[i]));
sort(arr + 1, arr + n + 1);
for (int i = 1; i <= n; i++) {
if (i == 1)
st.insert(arr[i]);
else {
if (arr[i] % k =... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int v[100009];
map<double, bool> mb;
int main() {
long long n, k, i, j, l, cnt = 0;
cin >> n >> k;
for (i = 0; i < n; i++) {
cin >> v[i];
}
sort(v, v + n);
for (i = 0; i < n; i++) {
double val = (double)(v[i] / (double)k);
if (!mb[val]) {
cnt++... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k, a[100001];
set<int> s;
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> a[i];
sort(a + 1, a + n + 1);
for (int i = 1; i <= n; i++)
if (a[i] % k || !s.count(a[i] / k)) s.insert(a[i]);
cout << s.size();
return 0;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int n, k, a[1 << 19], i, r, u;
map<int, int> s;
int main() {
cin >> n >> k;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (i = 0; i < n; i++)
if ((u = a[i]) % k | !s[u / k]) s[u] = ++r;
cout << r;
}
| ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
const int inf = (int)1e9;
const double EPS = 1e-9, INF = 1e12;
int n, k;
bool u[100000];
long long a[100000];
int main() {
cin >> n >> k;
for (int i = 0; i < (int)n; i++) cin >> a[i];
sort(a, a + n);
int ans = 0;
for (int i = 0; i < (int)n; i++)
if (!u[i]) {
... | ### Prompt
Develop a solution in CPP to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
set<long long int> conjunto;
long long int n, k, a[(long int)1e5 + 5], i, contador = 0;
cin >> n >> k;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (i = 0; i < n; i++) {
if (conjunto.find(a[i]) == conjunto.end()) {
contador++;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e7 + 10;
int n, k, x, ans;
int a[N];
map<int, int> b;
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
std::sort(a + 1, a + 1 + n);
for (int i = 1; i <= n; i++) {
x = a[i];
if (x % k | !b[x / k]) b[x] = ++an... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
bool comp(long long int a, long long int b) { return a > b; }
set<long long int> a;
long long a1[100002];
int main() {
long long int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> a1[i];
}
sort(a1, a1 + n, comp);
for (int i = 0; i < n; i++) {
... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long int n, k;
cin >> n >> k;
set<long long int> s;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
s.insert(x);
}
if (k == 1) {
cout << ((int)(s).size()) << "\n";
return 0... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
long long a[1001001], used[1001001], n, br, k, p;
void read() {
int i;
scanf("%I64d%I64d", &n, &k);
for (i = 1; i <= n; i++) scanf("%I64d", &a[i]);
}
int check(long long x) {
int l = 1, r = p, mid;
while (l <= r) {
mid = (l + r) / 2;
if (used[mid] == x) re... | ### Prompt
Please formulate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, buf;
set<long long> elems;
int main() {
long long res = 0;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> buf;
elems.insert(buf);
}
while (!elems.empty()) {
long long now = *(elems.begin());
elems.erase(elems.begin());
long... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int main() {
map<signed long long int, bool> ss;
int n, k, ans = 0;
signed long long int da[100000 + 5];
cin >> n >> k;
for (int i = 1; i <= n; ++i) cin >> da[i];
sort(da + 1, da + n + 1);
for (int i = 1; i <= n; ++i) {
if (da[i] % k == 0) {
if (ss[d... | ### Prompt
Your task is to create a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
iostream::sync_with_stdio(false);
cin.tie(0);
vector<int> v;
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
v.push_back(x);
}
vector<int> valores;
sort(v.begin(), v.end());
for (int i = 0; i < n; i++) {
... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
long long a[100010];
map<long long, bool> f;
int main() {
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%I64d", a + i);
sort(a + 1, a + 1 + n);
int ret = 0;
for (int i = 1; i <= n; i++) {
if (!f[a[i]]) {
ret++;
f[a[i] * k] = ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
std::vector<std::vector<std::vector<T>>> make_3d_vector(long long z,
long long y,
long long x,
... | ### Prompt
Construct a CPP code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
long long arr[100000 + 5];
bool flag[100000 + 5];
int main() {
long long n, k;
scanf("%I64d %I64d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%I64d", &arr[i]);
}
sort(arr, arr + n);
int cnt = 0;
for (int i = 0; i < n; i++) {
if (flag[i]) continue;
... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long int power(long long int x, long long int y);
long long int gcd(long long int a, long long int b);
vector<long long int> ft = {1};
long long int modInv(long long int i) { return power(i, 1000000007 - 2); }
long long int ncr(long long int n, long long int r) {
ret... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 1e9 + 23;
const int MOD = 1e9 + 9;
const int ARRS = 1e5 + 100;
int arr[ARRS];
map<int, bool> in;
int main() {
ios_base::sync_with_stdio(0);
int n, k;
cin >> n >> k;
for (int i = 0; i < n; ++i) {
cin >> arr[i];
}
sort(arr, arr + n);
int ans ... | ### Prompt
Your task is to create a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int n;
long long int k;
cin >> n >> k;
vector<long long int> arr;
for (int i = 0; i < n; i++) {
long long int inp;
cin >> inp;
arr.push_back(inp);
}
sort(... | ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
const long long MAXN = 1e5 + 5;
long long N, K;
long long v[MAXN];
int main() {
cin >> N >> K;
for (int i = 0; i < N; i++) cin >> v[i];
sort(v, v + N);
long long resp = N;
for (int i = 0; i < N; i++) {
long long value = v[i] * K;
int l = i + 1, r = N - 1;
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t = 1;
while (t--) {
long long int n, k;
cin >> n >> k;
set<long long int> s;
map<long long int, bool> cnt;
long long int temp;
for (int i = 0; i < n; i++) {
cin >> temp;... | ### Prompt
Create a solution in Cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
#pragma comment(linker, "/STACK:268435456")
using namespace std;
template <class T>
T sqr(T a) {
return a * a;
}
int a[100010];
map<int, int> b;
int n, k;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (int i = 0; i < n; i++) {
if (a[i] % ... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int a[100005];
set<int> s;
int main() {
int n, k, cnt;
ios::sync_with_stdio(0);
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n, greater<int>());
cnt = 0;
for (int i = 0; i < n; i++)
if (s.count(a[i]) == 0) {
cnt++;
if (a[... | ### Prompt
Please formulate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
set<long long> a;
int main() {
long long n, k;
cin >> n >> k;
for (long long i = 1; i <= n; i++) {
long long x;
cin >> x;
a.insert(x);
}
if (k == 1) {
cout << a.size() << endl;
return 0;
}
set<long long>::iterator it = a.begin();
while (i... | ### Prompt
Your task is to create a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, k;
cin >> n >> k;
int a[100001];
set<long long int> q;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int ans = 0;
for (int i = 0; i < n; i++) {
if (q.find(a[i]) == q.end()) {
q.insert(a[i] * k);
... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
map<int, int> s;
int main() {
int n, k, i;
int r = 0;
int a[100019];
scanf("%d %d", &n, &k);
for (i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
sort(a, a + n);
for (i = 0; i < n; i++) {
if (a[i] % k || !s[a[i] / k]) {
s[a[i]] = ++r;
}
}
pr... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
long long inp[100003], ans = 0;
map<long long, long long> vis;
map<long long, bool> used;
int main() {
long long n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> inp[i];
sort(inp, inp + n);
for (int i = n - 1; i >= 0; i--) {
vis[inp[i]]++;
if (!used... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const int intmax = 0x3f3f3f3f;
const long long lldmax = 0x3f3f3f3f3f3f3f3fll;
double eps = 1e-6;
template <class T>
inline void checkmin(T &a, T b) {
if (b < a) a = b;
}
template <class T>
inline void checkmax(T &a, T b) {
if (b > a) a = b;... | ### Prompt
Please formulate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long n, k;
cin >> (n);
cin >> (k);
set<long long> s;
long long ar[n + 1];
for (long long i = 1; i <= n; i++) cin >> (ar[i]);
sort(ar + 1, ar + n + 1);
for (long long i = 1; i... | ### Prompt
Develop a solution in CPP to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
struct coo {
long long a, b, c, d;
};
bool comp(struct coo a, struct coo b) { return a.a < b.a; }
int bin_srch(vector<long long> &a, long long n, int h) {
int l = 0;
int mid;
while (l <= h) {
mid = (l + h) / 2;
if (a[mid] > n) {
h = mid - 1;
cont... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
static const double EPS = 1e-10;
int main() {
long long N, K;
cin >> N >> K;
vector<long long> in;
for (int i = 0; i < N; ++i) {
long long tmp;
cin >> tmp;
in.push_back(tmp);
}
if (K == 1) {
cout << N;
return 0;
}
sort(in.begin(), in.end(... | ### Prompt
Please formulate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int MaxN = 1e5;
int N;
long long K;
set<long long> S;
int main() {
ios_base::sync_with_stdio(false);
cin >> N >> K;
for (int i = 0; i < N; i++) {
long long x;
cin >> x;
S.insert(x);
}
int ans = N;
while (!S.empty()) {
long long x = *S.begin... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
set<int> s;
int a[100005];
int main() {
int n, k;
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
sort(a, a + n);
for (int i = 0; i < n; i++) {
if (a[i] / k * k != a[i] || !s.count(a[i] / k)) s.insert(a[i]);
}
cout << s.siz... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long int a[999999];
int b[999999];
int main() {
int n, m;
memset(a, 0, sizeof(a));
memset(b, 0, sizeof(b));
scanf("%d%d", &n, &m);
for (int i = 0; i < n; i++) {
scanf("%lld", &a[i]);
}
sort(a, a + n);
int sum = n;
for (int i = 0; i < n; i++) {
... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
while (cin >> n >> k) {
long long t[n];
for (int i = 0; i < (int)n; i++) cin >> t[i];
sort(t, t + n);
set<long long> S;
long long cnt = 0;
for (int i = 0; i < (int)n; i++) {
if (S.count(t[i])) continue;
cn... | ### Prompt
Generate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d%d", &n, &k);
map<long long, int> st;
int r = 0;
int arr[n];
for (int i = 0; i < n; i++) {
int x;
scanf("%d", &arr[i]);
}
sort(arr, arr + n);
for (int i = 0; i < n; i++) {
int x = arr[i];
if (st.find(1ll * x ... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long n, m, len, l;
map<long long, bool> used;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> m;
int nn[n];
for (int i = 0; i < n && cin >> nn[i]; i++) used[nn[i]] = 1;
for (int i = 0; i < n; i++) {
if (!used[nn[i]]) continu... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int main() {
set<int> xs;
int n, k;
cin >> n >> k;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (int i = 0; i < n; i++) {
if (a[i] % k == 0 && xs.find(a[i] / k) == xs.end()) {
xs.insert(a[i]);
continue;
}... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, v[100005], rez;
multiset<long long> s;
set<long long> nu;
multiset<pair<long long, long long> > z;
map<long long, long long> mp;
int main() {
cin >> n >> k;
for (int i = 0; i < n; ++i) {
cin >> v[i];
s.insert(v[i]);
}
sort(v, v + n);
for (i... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const double EPS = 1e-6;
const int PRECISION = 20;
const int MOD = 1e9 + 7;
struct node {
long long val;
node *next;
node *prev;
bool initialPos;
node(int v) {
val = v;
next = nullptr;
prev = nullptr;
initialPos = true;
}
};
struct group {
long... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const int MAX = 100010;
int n, k;
long long int v[MAX];
map<long long int, int> M, mark;
int main() {
scanf("%d", &(n));
scanf("%d", &(k));
for (int i = 0, _n = (n); i < _n; ++i) {
cin >> v[i];
M[v[i]] = 1;
mark[v[i]] = 1;
}
so... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100010;
bool vis[maxn];
long long num[maxn];
int main() {
int n;
long long k;
scanf("%d%lld", &n, &k);
for (int i = 1; i <= n; ++i) {
scanf("%lld", &num[i]);
}
sort(num + 1, num + n + 1);
memset(vis, false, sizeof(vis));
int ans = n;
f... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long int a[100500];
set<long long int> used;
int main() {
long long int n, k;
cin >> n >> k;
for (long long int i = 0; i < ((long long int)(n)); ++i) cin >> a[i];
sort(a, a + n);
long long int ans = 0;
for (long long int i = 0; i < ((long long int)(n)); ++i... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n, m, a[100005], flag[100005];
int main() {
cin >> n >> m;
for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
sort(a + 1, a + 1 + n);
int ans = 0;
for (int i = 1; i <= n; i++) {
if (!flag[i]) {
ans++;
int pos = lower_bound(a + 1, a + 1 + n, (long... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
vector<long long> vec;
while (n--) {
long long x;
cin >> x;
vec.push_back(x);
}
sort(vec.rbegin(), vec.rend());
int res = 0;
set<long long> st;
for (int i = 0; i < vec.size(); i++) {
long long cur... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, l, p, a[120010], s;
map<long long, long long> mp;
int main() {
scanf("%d %d", &n, &k);
for (int i = 1; i <= n; i++) {
scanf("%d", &a[i]);
}
int ss = 0;
sort(a + 1, a + n + 1);
for (int i = 1; i <= n; i++) {
if (mp[a[i]] == 0) {
ss++... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.