output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
int comp(const void* x, const void* y) { return *(int*)x - *(int*)y; }
int a[100007];
int bad[100007];
bool used[100007];
int main() {
int i;
int n, k;
cin >> n >> k;
for (i = 0; i < n; i++) cin >> a[i];
for (i = 0; i < n; i++) used[i] = false;
if (k == 1) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
#pragma comment(linker, "/STACK:64000000")
const int maxn = 1 << 17;
const int inf = 1000000007;
const int mod = 1000000007;
int n, k;
int a[maxn];
int ans;
map<int, int> mp;
int main() {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
map<long long, bool> mp;
map<long long, bool> if_calculated;
int main() {
int n;
long long k;
cin >> n >> k;
for (int i = 0; i < n; ++i) {
int t;
cin >> t;
mp[t] = 1;
}
int ans = 0;
if (k == 1)
ans = n;
else
for (auto i : mp) {
long... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1000000005;
set<int> s;
map<int, bool> M;
int n, k, x;
int main() {
cin >> n >> k;
for (int i = 0; i < n; ++i) {
cin >> x;
M[x] = 1;
if (k != 1)
while (x % k == 0) x /= k;
s.insert(x);
}
if (k == 1) {
cout << n << endl;
... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
int setBit(int N, int pos) { return N = N | (1 << pos); }
int resetBit(int N, int pos) { return N = N & ~(1 << pos); }
bool checkBit(int N, int pos) { return (bool)(N & (1 << pos)); }
using namespace std;
long long n, k, key, arr[100010], dp[100010], TC, flag[100010];
map<long long, long long> ... | ### Prompt
Your task is to create a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int N, K;
int A[100002], result;
map<int, bool> M;
int main() {
cin >> N >> K;
for (int i = 1; i <= N; ++i) cin >> A[i];
sort(A + 1, A + N + 1);
for (int i = N; i >= 1; --i) {
result += !M[A[i]];
if (A[i] % K == 0 && !M[A[i]]) M[A[i] / K] = true;
}
cout ... | ### Prompt
Create a solution in Cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
vector<int> a(n);
for (int i = 0; i < n; ++i) cin >> a[i];
sort(a.begin(), a.end());
set<int> s;
for (int i = 0; i < n; ++i) {
if (a[i] % k == 0 && s.find(a[i] / k) != s.end()) continue;
s.insert(a[i]);
}
cout ... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long n, a[105000], k;
map<long long, long long> cel;
signed main() {
cin >> n >> k;
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (long long i = 0; i < n; i++) {
if (a[i] % k == 0 && cel[a[i] / k] == 1) continue;
cel[a[i]]++;
a[... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long a[100000], i, n, m, k;
set<int> s;
int main() {
cin >> n >> k;
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
s.insert(a[0]);
for (i = 1; i < n; i++) {
m = s.size();
if (a[i] % k != 0) {
s.insert(a[i]);
} else {
s.... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
int n, m;
int a[100100];
int chk[100100];
int ans;
int main() {
int i, j;
scanf("%d%d", &n, &m);
for (i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
if (m == 1) {
printf("%d", n);
return 0;
}
std::sort(a, a + n);
ans = n;
j = 0;
for (i = 0; i < n; i++) {
while (j... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int a[111111], b[1111], c[111], p[111][111];
int n, l = 0, m;
const int md = 100000000;
int main() {
int n1 = 0, n2 = 0, p1, p2, j, i, z = 0, x, k;
cin >> n >> m;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
map<int, int> mp;
for (i = 0; i < n; i++) {
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")
using namespace std;
long long max(long long a, long long b) {
if (a < b) return b;
return a;
}
long long min(long long a, long long b) {
if (a < b) return a;
return b;
}
long long ... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long int n, m, c, k, cnt, x, y, a, b, s, ans;
vector<long long int> g[1001];
queue<long long int> q;
long long int used[100001];
map<long long int, long long int> mp;
long long int d[1001];
long long int arr[1000001];
long long int INF = 1e18;
int main() {
ios_base::... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, a[100007], c = 0;
map<long long, bool> b;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (int i = 0; i < n; i++) {
if (!b[a[i]]) {
c++;
b[a[i] * k] = true;
}
}
cout << c << endl;
ret... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
const long long maxn = 1e5 + 5;
void c_p_c() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
bool isPrime(long long n) {
if (n <= 1) return false;
if (n <= 3) return true;
if (n % 2 == 0 || n % 3 == 0) return false;
for (long long i = 5; i * i <= n;... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 1e9 + 23;
const int MOD = 1e9 + 7;
const int N = 1e5 + 100;
int arr[N];
set<int> res;
int main() {
ios_base::sync_with_stdio(0);
int n, k;
cin >> n >> k;
for (int i = 0; i < (n); ++i) cin >> arr[i];
sort(arr, arr + n);
for (int i = 0; i < (n); ++... | ### Prompt
Create a solution in CPP for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k, x, res = 0;
set<long long> s;
cin >> n >> x;
for (long long i = 0; i < n; ++i) {
cin >> k;
s.insert(k);
}
for (set<long long>::iterator it = s.begin(); it != s.end(); ++it) {
set<long long>::iterator z = s.find(*it * x);
... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
map<long long, bool> mp;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
long long t;
long long m, n, b, c, d, i, j, k, x, y, z, l, q, r;
string s1, s2, s3, s4;
long long cnt = 0, ans = 0, sum = 0;
cin >> n;
;
cin >> k;
;
lo... | ### Prompt
Create a solution in Cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const double eps = 1e-11;
int main() {
std::ios_base::sync_with_stdio(0);
int ct = 0, n, k, nm, val;
cin >> n >> k;
ct = 0;
vector<int> v;
int vis[n + 11];
memset(vis, 0, sizeof vis);
for (int i = 0; i < n; ++i) {
cin >> nm;... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
;
long long n, k;
cin >> n >> k;
vector<long long> arr;
set<long long> s;
for (long long i = 1; i <= n; i++) {
long long x;
cin >> x;
arr.push_back(x);
s.insert(x);
}
v... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
bool comp(pair<int, int>& a, pair<int, int>& b) {
if (a.first > b.first) return true;
if (a.first == b.first && a.second < b.second) return true;
return false;
}
int main() {
using namespace std;
int n, k;
cin >> n >> k;
set<int> s;
vector<int> vec(n);
for... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int a[100005];
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
set<int> ans;
for (int i = 0; i < n; i++) {
if (a[i] % k)
ans.insert(a[i]);
else if (ans.count(a[i] / k) == 0)
ans.insert(a[i]);
}... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int num[100000];
int chosen[100000];
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> num[i];
}
sort(num, num + n);
int cnt = 0;
for (int i = 0; i < n; i++) {
if (num[i] % k != 0) {
chosen[cnt++] = num[i];
} else {
... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, m, a;
cin >> n >> m;
map<long long, long long> mp;
while (n--) {
cin >> a;
mp[a] = 1;
}
if (m == 1) return cout << mp.size() << endl, 0;
for (auto i : mp) {
if (i.second == 0 || mp.find(i.first * m) == mp.end()) continue;
... | ### Prompt
Generate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1e9 + 7;
const long long N = 1e6 + 10;
long long a[N];
void go() {
long long n, k;
cin >> n >> k;
unordered_map<long long, vector<long long>> M;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (int i = 0; i < n; i++) ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, ans = 0;
long long k;
cin >> n >> k;
map<long long, int> mp;
long long arr[n];
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
for (int i = 0; i < n; i++) {
i... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int a[100100];
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
map<int, int> mp;
int ans = 0;
for (int i = 0; i < n; i++) {
if (a[i] % k == 0 && mp[a... | ### Prompt
Please formulate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 2147483647;
const long long LLINF = 9223372036854775807LL;
const int ST = 100010;
const int ST1 = 1000010;
const long long MOD = 1000000007;
long long ABS(long long a) {
if (a < 0)
return a * (-1);
else
return a;
}
vector<int> mn;
vector<int> pol... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
std::ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long int n, k;
cin >> n >> k;
long long int a[n];
map<long long int, long long int> mpp;
for (long long int(i) = 0; (i) < (n); (i)++) {
cin >> a[i];
mpp[a[i]] = 1;
}
... | ### Prompt
Develop a solution in CPP to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n;
map<long long, int> x;
long long a[100005], k;
int main() {
int i, j;
cin >> n >> k;
for (i = 1; i <= n; i++) {
cin >> a[i];
x[a[i]] = 1;
}
sort(a + 1, a + n + 1);
int g = 0;
for (i = n; i >= 1; i--) {
if (x[a[i]] == 1) {
if (a[i] % k ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
while (cin >> n >> k) {
vector<int> v;
for (int i = 0; i < n; i++) {
int t;
cin >> t;
v.push_back(t);
}
sort((v).begin(), (v).end());
map<int, int> m;
int ans = 0;
for (int i = 0; i < n; i++) {
i... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
vector<long long int> v;
int bs(long long int n) {
int mn = 0, mx = v.size(), mid;
while (mn <= mx) {
mid = (mn + mx) / 2;
if (v[mid] < n)
mn = mid + 1;
else if (v[mid] > n)
mx = mid - 1;
else
break;
}
if (v[mid] < n)
return mid... | ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ii = pair<int, int>;
void in(int &x);
const int N = 2e5;
int n, k;
void work() {
in(n);
in(k);
vector<int> v(n);
int sol = 0;
set<int> s;
for (int i = 0; i < n; i++) {
in(v[i]);
if (v[i] % k != 0) {
sol++;
s.insert... | ### Prompt
Generate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
const int mxN = 5e4 + 1;
int main() {
set<long long> s;
long long n, k, x;
cin >> n >> k;
while (n--) {
cin >> x;
s.insert(x);
}
long long ans = 0;
while (!s.empty()) {
long long a = *s.begin();
long long add = 0;
while (s.count(a)) {
... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = int(1e5) + 256;
int n, k, a[MAXN];
vector<int> v;
int main() {
cin >> n >> k;
for (int i = 1; i <= n; ++i) {
cin >> a[i];
}
sort(a + 1, a + 1 + n);
for (int i = 1; i <= n; ++i) {
if ((a[i] % k) || !(binary_search(v.begin(), v.end(), a[i] /... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
vector<long long> vec;
set<long long> set2;
int main() {
int n;
long long k;
cin >> n >> k;
vec.resize(n);
for (int i = 0; i < (int)n; i++) cin >> vec[i];
sort(vec.begin(), vec.end());
reverse(vec.begin(), vec.end());
set2.clear();
for (int i = 0; i < (int... | ### Prompt
Please provide a cpp coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
long long n, k;
cin >> n >> k;
vector<long long> a(n);
set<long long> s;
for (auto& i : a) cin >> i, s.insert(i);
if (k == 1) return cout << n, 0;
sort((a).begin(), (a).end());
for (auto i : a)
... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
const long double pi = 4 * atan((long double)1);
const long long mod = 1e9 + 7;
const long long inf = 1e9;
const long long llinf = 1e18;
const long long nax = 0;
long long n, k;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> n >... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
bool binary(vector<int>& vec, int lenght, long long int val) {
int left = 0, right = lenght - 1, mid = (left + right) / 2;
while (left <= right) {
if (vec[mid] == val) {
vec[mid] = 0;
return true;
} else if (vec[mid] > val) {
right = mid - 1;
... | ### Prompt
Generate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
set<long long> S;
vector<long long> A(n);
long long tmp;
for (int i = 0; i < n; ++i) {
cin >> tmp;
A[i] = tmp;
}
sort(A.begin(), A.end());
long long ans = 0;
for (int i = 0; i < n; ++i) {
if (S.find... | ### Prompt
Your task is to create a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, a[100001], res, i;
map<long long, long long> was;
int main() {
cin >> n >> k;
for (i = 1; i <= n; i++) cin >> a[i], was[a[i]] = 1;
sort(a + 1, a + n + 1);
res = n;
if (k != 1)
for (i = 1; i <= n; i++)
if (was[a[i] * k] == 1 && was[a[i]] =... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (k == 1) {
cout << n << endl;
return 0;
}
set<int> s;
int x;
for (int i = 0; i < n; i++) {
cin >> x;
s.insert(x);
}
int res = 0;
while (!s.empty()) {
int x = *s.begin();
int t = 0;
whil... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
const long double pie = 3.1415926535;
using namespace std;
long long fpow(long long n, long long p) {
long long m = 1;
while (p) {
if (p % 2) m *= n;
p >>= 1;
n *= n;
}
return m;
}
long long mfpow(long long n, long long p, long long M) {
long long m = 1;
n %= M;
while ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
set<long long int> NUM;
long long int N, K;
bool myfunction(long long int i, long long int j) { return (i < j); }
vector<long long int> a;
int main() {
int i;
long long int x;
cin >> N >> K;
a.resize(N);
for (i = 0; i < N; i++) {
cin >> a[i];
NUM.insert(a[... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
void read(int &x) {
int flag = 1;
char ch;
x = 0;
for (ch = getchar(); (ch < '0' || ch > '9') && ch != '-'; ch = getchar())
;
if (ch == '-') {
flag = -1;
ch = getchar();
}
for (; ch >= '0' && ch <= '9'; x = x * 10 + ch - 48, ch = getchar())
;
... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
int cmp(const void *a, const void *b) { return *(int *)a - *(int *)b; }
int binary_search(int left, int right, int a[], long long target) {
if (left > right) return -1;
int middle = (left + right) / 2;
if (a[middle] == target)
return middle;
else if (a[middle] > target)
return b... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
long long power(long long x, long long y);
long long gcd(long long a, long long b);
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n;
cin >> n;
long long k;
cin >> k;
if (k == 1) {
cout << n << "\n";
return 0;
}
set<long long> s;... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
T inline Abs(const T& x) {
return x < 0 ? -x : x;
}
template <class T>
T inline Sqr(const T& x) {
return x * x;
}
int main(int argc, char* argv[]) {
ios_base::sync_with_stdio(false);
long long n, k;
cin >> n >> k;
vector<long long> a(n);
vec... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
long long mpow(long long a, long long n, long long mod) {
long long ret = 1;
long long b = a;
while (n) {
if (n & 1) ret = (ret * b) % mod;
b = (b * b) % mod;
n >>= 1;
}
return (long long)ret;
}
using namespace std;
vector<int> s;
map<int, int> ma;
int main() {
int i, j,... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long int quant, mul;
scanf("%ld %ld", &quant, &mul);
long int *nums = (long int *)calloc(quant, sizeof(long int));
set<long int> s;
for (long int i = 0; i < quant; i++) {
scanf("%ld", &nums[i]);
}
sort(nums, nums + quant);
for (long int i = ... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, i, j, k, ans = 0, m, l;
cin >> n >> m;
vector<long long> arr(n);
map<long long, long long> mp, vis;
set<long long> s;
set<long long>::iterator it;
for (i = 0; i < n; i++) cin >> arr[i];
for (i = 0; i < n; i++) {
k = arr[i];
... | ### Prompt
Generate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d %d", &n, &k);
vector<int> a(n);
for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
sort(a.begin(), a.end());
set<int> r;
for (int i = 0; i < n; ++i)
if (a[i] % k != 0 || a[i] % k == 0 && !r.count(a[i] / k)) {
r.insert(a[... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
const long long MAX = 1e6 + 7;
long long MOD;
void f_io() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
;
}
int32_t main() {
f_io();
long long n, k;
cin >> n >> k;
map<long long, long long> mp;
long long arr[n];
for (long long i = 0; i < n; i++) ci... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
long long int n, k, x;
cin >> n >> k;
long long int a[n];
for (long long int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
set<long long int> p;
for (long long int i = 0; i < n; i++) {
if (a[i] % k || !p.count(a[i] / k)) {
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int n, k, a[1 << 19], i, r, u;
map<int, int> s;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (int i = 0; i < n; i++)
if ((u = a[i]) % k | !s[u / k]) s[u] = ++r;
cout << r;
return 0;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
long long int n, k, ans = 0;
cin >> n >> k;
map<long long int, long long int> m;
vector<long long int> v(n);
for (long long int i = 0; i < n; i++) {
cin >> v[i];
m[v[i]]++;
}
sort(v.begin(), v.end());
long long int mm = *max_element(v... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
const int maxint = -1u >> 1;
const double pi = 3.14159265358979323;
const double eps = 1e-8;
int n, k, a[100100];
set<long long> vis;
int main() {
scanf("%d%d", &n, &k);
for (int i = (0); i < (n); i++) scanf("%d", &a[i]);
sort(a, a + n);
int ans = 0;
for (int i = ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int n, k, a[1 << 19], i, r, u;
map<int, int> s;
int main() {
cin >> n >> k;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (i = 0; i < n; i++)
if ((u = a[i]) % k | !s[u / k]) s[u] = ++r;
cout << r;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
map<int, int> mm;
const int MAXNUM = 100005;
bool mark[MAXNUM];
int main() {
int n, k;
int nums[MAXNUM];
int length[MAXNUM];
scanf("%d %d", &n, &k);
for (int i = 0; i < n; i++) {
scanf("%d", &nums[i]);
}
sort(nums, nums + n);
if (k == 1) {
printf("%d... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
long long n, m, k, ck, ans;
long long a[100005];
map<long long, long long> yo, oy;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) scanf("%I64d", &a[i]);
for (int i = 0; i < n; i++) yo[a[i]] = 1;
sort(a, a + n);
if (k == 1)
cout << n;
else {
for ... | ### Prompt
Create a solution in CPP for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, k;
cin >> n >> k;
long long int arr[n];
for (long long int i = 0; i < n; i++) cin >> arr[i];
map<long long int, long long int> m;
long long int size = 0;
for (long long int i = 0; i < n; i++) {
m[arr[i]] = 1;
m[k * arr[i]]... | ### Prompt
Please create a solution in CPP to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long s[100010];
set<long long> x;
int main() {
long long n, k;
while (cin >> n >> k) {
x.clear();
for (int i = 1; i <= n; i++) {
cin >> s[i];
x.insert(s[i]);
}
if (k == 1) {
cout << n << endl;
continue;
}
sort(s + 1, ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const int MAX_N = 100000 + 2;
int a[MAX_N];
int n, k;
int mark[MAX_N];
int dfs(int i) {
mark[i] = 1;
if ((long long)a[i] * k > 1000000000) return 1;
int j = lower_bound(a, a + n, a[i] * k) - a;
if (j < n && a[j] == a[i] * k)
return 1 + dfs(j);
else
return ... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long arr[100005];
map<long long, int> m;
int main() {
long long n, k, len;
cin >> n >> k;
len = n;
for (int i = 0; i < n; i++) {
cin >> arr[i];
m[arr[i]] = 1;
}
if (k == 1) {
cout << n;
return 0;
}
sort(arr, arr + n);
for (int i = 0; i... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const long double PI =
3.141592653589793238462643383279502884197169399375105820974944;
inline void io() {}
const long long mod = 1e9 + 7;
const long long maxn = 3e5 + 5;
void solve() {
long long n, k;
cin >> n >> k;
long long a[n];
map<long long, long long> mp;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
T fastPower(T base, T power) {
if (!power) return 1;
T ans = fastPower(base, power / 2);
return power & 1 ? ans * ans * base : ans * ans;
}
int n, k, arr[100005];
bool vis[100005];
int BS(int start, int end, long long target) {
if (start > end)... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int cond = 1;
int main() {
int n, k;
scanf("%d %d", &n, &k);
set<int> S;
for (int i = 0; i < (n); i++) {
int x;
scanf("%d", &x);
S.insert(x);
}
int res = 0;
while (!S.empty()) {
++res;
int v = *S.begin();
S.erase(S.begin());
if (100... | ### Prompt
Please create a solution in CPP to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
vector<int> numbers;
vector<int> s;
int maximo = 0;
void backtracking(int len, int current) {
if (current < n) {
int currentNumber = numbers[current];
if ((currentNumber % k) == 0) {
if (find(s.begin(), s.end(), (currentNumber / k)) != s.end()) {
... | ### Prompt
Your task is to create a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n d... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, cnt;
vector<long long> vit;
vector<long long> num;
void find_(long long l, long long r, long long m) {
if (l > r) return;
long long mid = (r + l) / 2;
if (num[mid] == m) {
cnt++;
vit[mid] = 1;
find_(mid + 1, n - 1, m * k);
} else if (m < ... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
const int INF = (int)(1e9);
const long long INFLL = (long long)(1e18);
const double EPS = 1e-13;
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
int n, k;
cin >> n >> k;
map<long long, int> g;
for (int i = 0; i < n; i++) {
long long x;
cin >> x;
g[x] = ... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int u, r;
int a[100000];
map<int, int> s;
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (int i = 0; i < n; i++) {
if ((u = a[i]) % k | !s[u / k]) {
r++;
s[u] += r;
}
}
cout << r... | ### Prompt
Create a solution in cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
long long a[100010], b[1000], d[10010], p[10010];
long long mn = 1e9, mx = -1e9, ans, cnt, sm = 1, n, m;
bool ok, okk, u[1000010], uu[310][310], uk[1000010];
char ck[510][510], ch[100010];
int dx[4] = {0, 1, 0, -1}, dy[4] = {-1, 0, 1, 0};
vector<int> g[900010];
string s[100... | ### Prompt
Generate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, k, t, c = 0, q = -1;
cin >> n >> k;
vector<long long int> a, b;
map<long long int, int> d;
for (int i = 0; i < n; i++) {
cin >> t;
a.push_back(t);
}
sort(a.begin(), a.end());
for (long long int i = 0; i < n; i++) {
i... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
void solve(istream &in, ostream &out) {
int n, k;
in >> n >> k;
if (k == 1) {
out << n << endl;
return;
}
vector<int> a(n);
map<int, bool> m;
for (int i = 0; i < n; ++i) {
in >> a[i];
m[a[i]] = true;
}
int v = *max_element(a.begin(), a.end(... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
const long long int MOD = 1e9 + 7;
const long double PI = 3.14159265;
long long int powerWithMod(long long int base, long long int exponent,
long long int modulus = LLONG_MAX) {
long long int result = 1;
base %= modulus;
while (exponent > 0)... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007, mod2 = 2e9;
double Pi = 3.141592653589793238;
long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); }
long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); }
unsigned long long FP(unsigned long long b,... | ### Prompt
Please create a solution in CPP to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
vector<int> a(111111);
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.begin() + n);
set<int> s;
for (int i = 0; i < n; i++) {
if (a[i] % k > 0)
s.insert(a[i]);
else {
if (s.find(a[... | ### Prompt
Please formulate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long n, i, j, h, k;
long long a[100005], b[100005];
long long f(long long cc, long long ll, long long rr) {
long long x;
x = (ll + rr) / 2;
if (ll > rr) return -1;
if (cc == a[x]) return x;
if (cc > a[x]) {
return f(cc, x + 1, rr);
}
if (cc < a[x]) {
... | ### Prompt
Create a solution in Cpp for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
bool prime(int n) {
if (n == 2 or n == 3)
return true;
else if (n == 1)
return false;
else if (n % 2 == 0 or n % 3 == 0)
return false;
else {
for (int i = 5; i * i <= n; i += 6) {
if (n % i == 0 or n % (i + 2) == 0) return false;
}
retu... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int v[112345], n, k;
set<int> s[112345];
int buscab(int x) {
int ini = 1, fim = n, meio;
while (ini <= fim) {
meio = (ini + fim) / 2;
if (v[meio] == x) {
return -1;
} else if (v[meio] < x) {
ini = meio + 1;
} else {
fim = meio - 1;
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 200002;
long long h[maxn];
int n, k;
int cmp(long long a, long long b) { return a <= b ? 1 : 0; }
int main() {
while (scanf("%d%d", &n, &k) != EOF) {
int i, j;
set<long long> s;
s.clear();
for (i = 0; i < n; i++) {
cin >> h[i];
}... | ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
long long n, k;
map<long long, long long> m;
long long a[100005];
int main() {
cin >> n >> k;
m.clear();
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int cnt = 0;
for (int i = 0; i < n; i++) {
if (m.count(a[i]) == 0) {
cnt++;
... | ### Prompt
Please formulate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
set<long long> s1, s2;
long long n, k;
cin >> n >> k;
std::vector<long long> a(n);
for (long long int i = 0; i < n; i++) cin >> a[i];
sort((a).begin(), (a).end());
for (long long int... | ### Prompt
Please formulate a CPP solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
set<int> q;
int a[100001];
int main() {
int n, k, x;
cin >> n >> k;
for (int i = 0; i < (n); ++i) {
cin >> a[i];
}
sort(a, a + n);
for (int i = 0; i < (n); ++i) {
if (!(a[i] % k) && q.count(a[i] / k)) continue;
q.insert(a[i]);
}
cout << q.size();... | ### Prompt
Construct a cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
int Get() {
char c;
while (c = getchar(), c < '0' || c > '9')
;
int X = 0;
while (c >= '0' && c <= '9') {
X = X * 10 + c - 48;
c = getchar();
}
return X;
}
int A[100000];
int Find(int Left, int Right, int X) {
while (Left <= Right) {
int Mid = ... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long in[100005];
set<long long> S;
int n, k;
int main() {
cin >> n >> k;
for (int i = 0; i < n; i++) {
scanf("%I64d", &in[i]);
}
int ans = 0;
sort(in, in + n);
for (int i = 0; i < n; i++) {
if (in[i] % k != 0 || (in[i] % k == 0 && S.find(in[i] / k) ... | ### Prompt
Please formulate a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
vector<int> A(100000);
scanf("%d %d", &n, &k);
for (int i = 0; i < (n); ++i) scanf("%d", &A[i]);
sort(A.begin(), A.begin() + n);
set<int> S;
for (int i = 0; i < (n); ++i) {
if (A[i] % k)
S.insert(A[i]);
else if (S.find(A[i]... | ### Prompt
Please provide a CPP coded solution to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
long long a[100000];
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
set<long long> s;
int cnt = 0;
for (int i = 0; i < n; i++) {
if (s.find(a[i]) != s.end()) continue;
cnt++;
s.insert(a[i] * k... | ### Prompt
Develop a solution in Cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int n, k, p, a, b, x, y, i, m[100005];
map<int, int> mp;
int main() {
cin >> n >> k;
while (i < n) {
cin >> m[i];
i++;
}
i = 0;
sort(m, m + n);
while (i < n) {
if (m[i] % k != 0 || (m[i] % k == 0 && mp[m[i] / k] == 0)) {
mp[m[i]]++;
p++;
... | ### Prompt
Create a solution in CPP for the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct posi... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100050;
int n, k, ans, vis[maxn];
long long a[maxn];
int main() {
while (scanf("%d%d", &n, &k) != EOF) {
for (int i = 1; i <= n; i++) scanf("%lld", a + i);
if (k == 1) {
printf("%d\n", n);
continue;
}
sort(a + 1, a + n + 1);
... | ### Prompt
Generate a cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positi... |
#include <bits/stdc++.h>
using namespace std;
set<int> s;
set<int>::iterator it1;
map<int, int>::iterator it;
map<int, int> mp;
pair<int, int> pa;
int main() {
int n, k;
int ar[100008];
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> ar[i];
mp[ar[i]] = 0;
}
s.clear();
sort(ar, ar + n);
for (... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int n, k, i, a[100010];
set<int> r;
int main() {
scanf("%d%d", &n, &k);
for (i = 0; i < n; i++) scanf("%d", &a[i]);
sort(a, a + n);
for (i = 0; i < n; i++) {
if (a[i] % k == 0 && r.count(a[i] / k)) continue;
r.insert(a[i]);
}
printf("%d\n", int(r.size())... | ### Prompt
In cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int a[100005];
set<long long> present;
int ans;
int main() {
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
sort(a, a + n);
for (int i = n - 1; i >= 0; i--) {
if (present.find((long long)a[i] * k) == present.end()) {
ans++... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long N = 100001;
long long mod = 1e9 + 7;
long long min(long long a, long long b) {
if (a < b)
return a;
else
return b;
}
long long max(long long a, long long b) {
if (a > b)
return a;
else
return b;
}
long long power(long long a, long long b) {... | ### Prompt
Develop a solution in cpp to the problem described below:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int arr[1000000];
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
set<int> si;
for (int i = 0; i < n; i++) {
if (arr[i] % k == 0) {
if (si.find(arr[i] / k) == si.end()) si.insert(arr[i]);
} else
... | ### Prompt
In Cpp, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
#include <bits/stdc++.h>
using namespace std;
const int maxint = -1u >> 1;
const double pi = 3.14159265358979323;
const double eps = 1e-8;
int n, k, a[100100];
set<long long> vis;
int main() {
scanf("%d%d", &n, &k);
for (int i = (0); i < (n); i++) scanf("%d", &a[i]);
sort(a, a + n);
int ans = 0;
for (int i = ... | ### Prompt
Please create a solution in cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
long long a[100005], x, k;
int main() {
int n, m, i, j, q, ans = 0;
cin >> n >> k;
for (i = 1; i <= n; i++) cin >> a[i];
sort(a + 1, a + n + 1);
for (q = 1; q <= n; q++) {
if (!a[q]) continue;
x = a[q] * k;
i = 0;
j = n + 1;
while (i < j) {
... | ### Prompt
Please create a solution in Cpp to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
map<long long, int> taken;
int n, k;
cin >> n >> k;
long long ans = 0;
long long array[100100];
for (int i = 0; i < n; i++) {
long long a;
scanf("%lld", array + i);
}
sort(array, array + n);
for (int i = 0; i < n; i++) {
if (array[... | ### Prompt
Construct a Cpp code solution to the problem outlined:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct p... |
#include <bits/stdc++.h>
using namespace std;
long long a[100010], b[100010];
map<long long, long long> mp;
int main() {
long long n, i, n1, j, flag = 0, p, s, k, c = 0, c2 = 0;
long long num;
cin >> n >> k;
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (i = 0; i < n; i++) {
p = a[i... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
map<long long, int> m;
long long a[n + 1];
for (int i = 1; i <= n; ++i) cin >> a[i];
sort(a + 1, a + n + 1);
long long x = 0;
for (int i = 1; i <= n; ++i) {
if (m[a[i]] < 1) m[a[i]] = 1;
long long p = a[i] ... | ### Prompt
In CPP, your task is to solve the following problem:
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct pos... |
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